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Question 1
Correct
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A 28-year-old male presents to the emergency department with a swelling over his left elbow after a fall on an outstretched hand. On examination, he has tenderness over the proximal part of his forearm and has severely restricted supination and pronation movements. What is the most likely injury?
Your Answer: Fracture of the radial head
Explanation:The patient has an injury due to falling on outstretched hands (FOOSH). Putting his clinical picture into consideration, he is most likely to have a fracture of the radial head.
Radial head fractures often occur with FOOSH injuries. Patients will complain of wrist pain, as well as elbow pain, and be hesitant to perform a range of motion. However, pain with supination and pronation at the elbow is imperative for diagnosis. Palpation at the lateral aspect of the elbow will elicit pain; you also may feel crepitus at the radial head with supination pronation. X-rays should be ordered, with a minimum of two views (AP and lateral). Radial head fractures can be difficult to recognize on x-ray. Assess for a sail sign or effusion on the image. A positive fat pad sign aids in diagnosis, as well. If the image is inconclusive, but the exam is consistent, treat until proven otherwise.
Management should include intensive patient education. Compression wrapping for comfort and stability may be used along with a sling. Please note, early light motion is imperative for these patients, as elbow contracture and stiffness are very common after injury, possibly leading to long-term complications. These patients need to be seen by an orthopaedic specialist as soon as possible to begin management. Be aware that if displacement or step-off of the radial head is present, this may require surgical intervention, and motion could worsen alignment if not managed meticulously.
Other INJURIES TO THE UPPER EXTREMITY DUE TO (FOOSH):
Radial Styloid Fracture
Distal Radius Fracture
Scaphoid Fracture
Scapholunate Tear
Distal Radioulnar Joint
Cellulitis
Synovitis -
This question is part of the following fields:
- Generic Surgical Topics
- Orthopaedics
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Question 2
Correct
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A elderly patient with bulbar palsy is bed ridden. While swallowing he aspirates one of his tablets into his lungs. In which bronchopulmonary segments is it most likely to end up?
Your Answer: Superior segmental bronchus of the right inferior lobe
Explanation:Inhaled objects are more likely to enter the right lung for several reasons. First the right bronchus is shorter, wider and more vertical than the left bronchus. Also, the carina (a ridge-like structure at the point of tracheal bifurcation) is set a little towards the left. The superior segmental bronchus branches posteriorly off the intermediate bronchus or the inferior lobe bronchus and is thus more likely to receive the foreign body that enters the right main bronchus. The lingula is only found on the left lung. The terminal bronchiole is a very small space almost impossible for the tablet to lodge here.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 3
Correct
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A patient underwent surgical excision of mass in the right carotid triangle. One day after the surgery patient complained of numbness of the skin over the right side of the neck. Injury to the cervical plexus of nerves is suspected. What is the possible nerve affected in this patient?
Your Answer: Transverse cervical
Explanation:The transverse cervical nerve (superficial cervical or cutaneous cervical) arises from the second and third spinal nerves, turns around the posterior border of the sternocleidomastoid and, passing obliquely forward beneath the external jugular vein to the anterior border of the muscle, it perforates the deep cervical fascia, and divides beneath the platysma into the ascending and descending branches. It provides cutaneous innervation to this area.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 4
Incorrect
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What is a major source of fuel being oxidised by the skeletal muscles of a man who has undergone starvation for 7 days?
Your Answer: Muscle creatine phosphate
Correct Answer: Serum fatty acids
Explanation:Starvation is the most extreme form of malnutrition. Prolonged starvation can lead to permanent organ damage and can be fatal. Starved individuals eventually lose significant fat and muscle mass as the body uses these for energy.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 5
Correct
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A patient came into the emergency in a state of shock. His blood group is not known, but on testing it clotted with anti B antibodies when mixed with A +ve blood. Which blood should be transfused?
Your Answer: B +ve
Explanation:Group A – has only the A antigen on red cells (and B antibody in the plasma)
Group B – has only the B antigen on red cells (and A antibody in the plasma)
Group AB – has both A and B antigens on red cells (but neither A nor B antibody in the plasma)
Group O – has neither A nor B antigens on red cells (but both A and B antibody are in the plasma). Many people also have a Rh factor on the red blood cell’s surface. This is also an antigen and those who have it are called Rh+. Those who have not are called Rh–. A person with Rh– blood does not have Rh antibodies naturally in the blood plasma (as one can have A or B antibodies, for instance) but they can develop Rh antibodies in the blood plasma if they receive blood from a person with Rh+ blood, whose Rh antigens can trigger the production of Rh antibodies. A person with Rh+ blood can receive blood from a person with Rh– blood without any problems. The patient’s blood group is B positive as he has antigen B, antibody A and Rh antigens -
This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 6
Correct
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A medical student is asked to calculate the net pressure difference in a capillary wall, considering: Interstitial fluid hydrostatic pressure = –3 mmHg, Plasma colloid osmotic pressure = 28 mmHg, Capillary hydrostatic pressure = 17 mmHg, Interstitial fluid colloid osmotic pressure = 8 mmHg, and Filtration coefficient = 1. Which is the correct answer?
Your Answer: 0 mmHg
Explanation:The rate of filtration at any point along a capillary depends on a balance of forces sometimes called Starling’s forces after the physiologist who first described their operation in detail. The Starling principle of fluid exchange is key to understanding how plasma fluid (solvent) within the bloodstream (intravascular fluid) moves to the space outside the bloodstream (extravascular space). Fluid movement = k[(pc– pi)–(Πc– Πi)] where k = capillary filtration coefficient, pc = capillary hydrostatic pressure, pi= interstitial hydrostatic pressure, Πc = capillary colloid osmotic pressure, Πi = interstitial colloid osmotic pressure. Therefore: 1 × [capillary hydrostatic pressure (17) – interstitial fluid hydrostatic pressure (–3)] – [plasma colloid osmotic pressure (28) – interstitial fluid colloid osmotic pressure (8)] = 0 mmHg
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 7
Incorrect
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Whipple's procedure involves mobilizing the head of the pancreas. As the surgeon does this, he must be careful to avoid injury to a key structure that is found lying behind the head of the pancreas. Which vital structure is this?
Your Answer: Portal vein
Correct Answer: Common bile duct
Explanation:The posterior relations of the head of the pancreas include: the inferior vena cava, the common bile duct, the renal veins, the right crus of the diaphragm and the aorta.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 8
Correct
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A 46-year old lady presents with chief complaints of a large mass in the left breast. Histopathology of the mass revealed a stromal component with an epithelial component. What is the likely lesion?
Your Answer: Phyllodes tumour
Explanation:Phyllodes tumours are large, quickly growing tumours which arise from the periductal stroma of the breast. These are fibroepithelial tumours and account for less than 1% of breast cancers. These tumours can be benign, borderline or malignant based on the histology. The tumour usually affects adult women, mostly between the age of 40 to 50 years. It can be confused with fibroadenoma, which however affects much younger patients.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 9
Correct
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A 65 year old man with a history of carcinoma of the distal oesophagus undergoes an Ivor-Lewis oesophagogastrectomy. The next day a pale opalescent liquid is noticed in the right chest drain. Which of the following is the most likely explanation of this finding?
Your Answer: Chyle leak
Explanation:Chyle leakage is one of the most challenging complications following an esophagectomy and can lead to hypovolemia, metabolic and nutritional depletion, infection, and even death. The leakage occurs in 1.1 to 3.7% of esophagectomy patients; mortality occurs in excess of 50% of patients. Surgeons administer a lipid rich material prior to surgery to facilitate its identification if it occurs.
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This question is part of the following fields:
- Peri-operative Care
- Principles Of Surgery-in-General
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Question 10
Incorrect
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A 20-year-old woman presents with a posteriorly-sited anal fissure. Treatment with stool softeners and topical GTN have failed to improve the condition. Which of the following would be the most appropriate next step of management?
Your Answer: Lateral internal sphincterotomy
Correct Answer: Injection of botulinum toxin
Explanation:The most appropriate management option to consider, after GTN or other topical nitrates have failed, is botulinum toxin injection. In males, a lateral internal sphincterotomy would be an acceptable alternative. In a female who has yet to conceive, this may predispose to an increased risk of sphincter dysfunction. Moreover, division of the external sphincter would result in faecal incontinence and is not a justified treatment for anal fissure.
Anal fissures are a common cause of painful, bright red rectal bleeding. Most fissures are idiopathic and present as a painful mucocutaneous defect in the posterior midline (90% cases). Fissures are more likely to be anteriorly located in females, particularly if they are multiparous. Diseases associated with fissure-in-ano include:
1. Crohn’s disease
2. Tuberculosis
3. Internal rectal prolapseDiagnostic options are as follows:
In most cases, the defect can be visualised as a posterior midline epithelial defect. Where symptoms are highly suggestive of the condition and examination findings are unclear, an examination under anaesthesia may be helpful. Atypical disease presentation should be investigated by colonoscopy and EUA, with biopsies of the area.For management of anal fissure:
1. Stool softeners are important as hard stools may tear the epithelium and result in recurrent symptoms. The most effective first-line agents are topically applied GTN (0.2%) or Diltiazem (2%) paste.
2. Resistant cases may benefit from injection of botulinum toxin or lateral internal sphincterotomy. Advancement flaps may be used to treat resistant cases. -
This question is part of the following fields:
- Colorectal Surgery
- Generic Surgical Topics
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Question 11
Correct
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Skeletal muscle fibres are divided into two basic types, type I (slow-twitch fibres) and type II (fast-twitch fibres). Fast muscle fibres do which of the following:
Your Answer: Use anaerobic metabolism
Explanation:Skeletal muscles are divided into two types:
1) type I also known as the slow twitch fibres. They use oxygen for their metabolism and as a result they have a high endurance potential. To support this they have abundant mitochondria and myoglobin, so they appear red/dark.
2) type II fibres also called fast twitch fibres, are low endurance fibres used during anaerobic metabolism. They are required for short bursts of strength and cannot sustain contractions for long periods of time. -
This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 12
Incorrect
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A 45-year-old man has a long history of ulcerative colitis. His symptoms are well-controlled with steroids. However, attempts at steroid weaning and use of steroid-sparing drugs have repeatedly failed. He wishes to avoid a permanent stoma. Which of the following should be the best operative strategy?
Your Answer: Pan-proctocolectomy and construction of an ileo anal pouch
Correct Answer:
Explanation:In patients with ulcerative colitis (UC) where medical management is not successful, surgical resection (pan-proctocolectomy) may offer a chance of cure. Those patients wishing to avoid a permanent stoma may be considered for an ileoanal pouch. However, this procedure is only offered in the elective setting.
Patients with inflammatory bowel disease (UC and Crohn’s disease) frequently present in surgical practice. Elective indications for surgery in UC include disease that requires maximal therapy or prolonged courses of steroids.
Long-standing UC is associated with a risk of malignant transformation. Dysplastic transformation of the colonic epithelium with associated mass lesions is an absolute indication for a proctocolectomy. Restorative options in UC include an ileoanal pouch. Complications of such a pouch include anastomotic dehiscence, pouchitis, and poor physiological function with seepage and soiling.
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Emergency presentation of poorly-controlled colitis that fails to respond to medical therapy should usually be managed with a subtotal colectomy. Excision of the rectum is a procedure with a higher morbidity and is not generally performed in the emergency setting. -
This question is part of the following fields:
- Colorectal Surgery
- Generic Surgical Topics
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Question 13
Correct
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Which of the following will show decreased hearing when tested by air conduction but normal hearing when tested by bone conduction?
Your Answer: Fibrosis causing fixation of the ossicles
Explanation:As the cochlea is embedded into bone, the vibrations from the bone are transmitted directly to the fluid in the cochlea. Hence, any damage to the ossicles or tympanic membrane will not show an abnormal result on bone conduction test.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 14
Correct
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A 33-year-old man is brought to the A&E department following a road traffic accident. He complains of lower abdominal pain. On examination, a fracture of the pelvis along with distended, tender bladder is observed. What should be the best step of management for distended bladder?
Your Answer: Suprapubic catheter
Explanation:This patient has possible urethral injury based on the history. Urethral catheterisation is contraindicated in this situation.
Up to 10% of male pelvic fractures are associated with urethral or bladder injuries. Urethral injury occurs mainly in males. It has two types.
1.Bulbar rupture:
a. most common
b. mostly associated with straddle-type injury, e.g. from bicycles
c. presentation with a triad of urinary retention, perineal haematoma, and blood at the meatus2. Membranous rupture:
a. can be extra- or intraperitoneal
b. occurs commonly due to pelvic fracture
c. symptomology may include penile or perineal oedema/haematoma
d. prostate displaced upwards (high-riding prostate)Ascending urethrogram is carried out in patients of suspected urethral injury. Suprapubic catheter is surgically placed and is indicated in:
1. External genitalia injuries (i.e. the penis and the scrotum)
2. Injury to the urethra caused by penetration, blunt trauma, continence- or sexual pleasure–enhancing devices, and mutilation. -
This question is part of the following fields:
- Generic Surgical Topics
- Urology
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Question 15
Correct
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From which source does the lingual artery originate?
Your Answer: External carotid
Explanation:The lingual artery arises from the external carotid between the superior thyroid artery and facial artery. It can be located easily on the lower surface of the tongue. The terminal branch of the lingual artery is the deep lingual artery. On its course the lingual artery gives off side branches: dorsal lingual branches that supply the dorsum of the tongue till the epiglottis; sublingual artery that supplies the sublingual gland.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 16
Correct
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A 27 year-old male patient was admitted to the hospital due to recurrent fever for the past 2 weeks. The patient claimed that he is an intravenous drug user. Following work up, the patient was diagnosed with infective endocarditis. Which is the most likely organism responsible for this diagnosis?
Your Answer: Staphylococcus aureus
Explanation:Acute bacterial endocarditis is a fulminant illness lasting over days to weeks (<2weeks). It is most likely due to Staphylococcus aureus especially in intravenous drug abusers.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 17
Correct
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A 39-year-old homosexual is admitted with diarrhoea of three-month duration. He is found to be HIV positive with a CD4 cell count <50/μL. Which of the following organisms is most likely to be responsible?
Your Answer: Cryptosporidium
Explanation:Based on the history and findings, the most likely causative organism is cryptosporidium. It can cause severe, chronic, and possibly fatal diarrhoea in immunocompromised patients.
In patients with HIV/AIDS, clinical manifestations of cryptosporidiosis vary with the degree of immune compromise. Those with CD4 cell counts above 180–200/μL may be asymptomatic or develop self-limiting diarrhoeal illness. However, patients with advanced AIDS (CD4 cell counts <50/μL) can have severe diarrhoea that can persist for several months, resulting in severe dehydration, weight loss and malnutrition, extended hospitalizations, and mortality. In addition, patients with advanced AIDS are at greater risk of developing extraintestinal infection, particularly of the biliary, pancreatic, and respiratory tracts.
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This question is part of the following fields:
- Clinical Microbiology
- Principles Of Surgery-in-General
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Question 18
Correct
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A 50-year-old man presents with unilateral facial paralysis after being hit on the head. On examination, he has a right-sided facial nerve palsy and watery discharge from the nose. What is the most likely underlying cause?
Your Answer: Petrous temporal fracture
Explanation:Nasal discharge of clear fluid and a recent head injury makes basal skull fracture the most likely underlying cause for facial nerve palsy.
Facial palsy is a neurological condition in which function of the facial nerve (cranial nerve VII) is partially or completely lost. It is often idiopathic (Bell’s palsy) but in some cases, specific causes such as trauma (e.g. temporal bone fracture), infections, or metabolic disorders can be identified. Two major types are distinguished:
1. Central facial palsy—lesion occurs between cortex and nuclei in the brainstem
2. Peripheral facial palsy—lesion occurs between nuclei in the brainstem and peripheral organsDiagnosis can usually be made clinically while patient’s history often helps in evaluating the underlying aetiology.
Patients with basal skull fracture following head injury (as in this case) exhibit Battle’s sign on examination. It is an indication of fracture of middle cranial fossa of the skull and consists of bruising over the mastoid process as a result of extravasation of blood along the path of the posterior auricular artery. Clinical presence of CSF leak further supports the diagnosis.Assessment options for basal skull fracture include CT and MRI scan. Idiopathic facial nerve palsy is treated with oral glucocorticoids and, in severe cases, with antivirals. Treatment of the other types depends on the underlying cause. Prophylactic antibiotics are given in cases of CSF leak.
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This question is part of the following fields:
- Generic Surgical Topics
- Head And Neck Surgery
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Question 19
Correct
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Risk factors for hepatocellular carcinoma do NOT include:
Your Answer: Heptitis E
Explanation:Risk factors for hepatocellular carcinoma include hepatitis B and C, aflatoxin, anabolic steroids, alcohol cirrhosis and primary liver disease.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 20
Correct
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A 20-year-old woman is admitted with right upper quadrant pain. On examination, there is tenderness in the right upper quadrant region. Imaging shows signs of acute cholecystitis due to gallstones. The common bile duct appears normal and liver function tests are normal as well. What should be the most appropriate course of action?
Your Answer: Laparoscopic cholecystectomy during the next 24–48 hours
Explanation:In most cases, the treatment of choice for acute cholecystitis is cholecystectomy performed early in the illness. The procedure can be carried out laparoscopically even when acute inflammation is present. Delayed surgery particularly around five to seven days after presentation is much more technically challenging and is often best deferred.
Up to 24% of women and 12% of men may have gallstones. Of these, up to 30% may develop local infection and cholecystitis. The classical symptom of cholecystitis is colicky right upper quadrant pain that occurs postprandially. Others include swinging pyrexia, and general feeling of being unwell. They are usually worst following a fatty meal when cholecystokinin levels are highest and gallbladder contraction is maximal.
Murphy’s sign is positive on examination. The standard diagnostic work-up consists of abdominal ultrasound and liver function tests. For management, cholecystectomy should ideally be done within 48 hours of presentation. In patients unfit for surgery, percutaneous drainage may be considered.
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This question is part of the following fields:
- Generic Surgical Topics
- Hepatobiliary And Pancreatic Surgery
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Question 21
Correct
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A 60 year-old patient being treated for hypertension presents to the ED with swelling of the left upper limb due to poor venous return. On examination, it is found that an aneurysm of the ascending aorta is impinging on a large vein lying immediately anterosuperior to it. Which vein is it likely to be?
Your Answer: Left brachiocephalic
Explanation:Among the veins listed, only the left brachiocephalic vein is anterosuperior to the ascending aorta. The right brachiocephalic vein being on the right side would not be affected by the aortic aneurysm.
The azygos vein lies deep in the chest on the right side.
The internal thoracic vein lies interior to the anterior wall of the chest.
The left superior intercostal vein is close to the aortic arch, crossing it laterally. This vein drains the 2nd to 4th interspaces on the left side.
The Right internal jugular vein joins the right brachiocephalic vein which would not be affected by the aneurysm. -
This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 22
Correct
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A 29-year-old pregnant woman suffering from hyperemesis gravidarum is prescribed metoclopramide. What is the mechanism of action of metoclopramide?
Your Answer: Dopamine antagonist
Explanation:Metoclopramide is a potent dopamine-receptor antagonist with anti-emetic and prokinetic properties. It is therefore commonly used to treat nausea and vomiting, and to facilitate gastric emptying in patients with gastric stasis. The anti-emetic action of metoclopramide is due to its antagonist activity at D2 receptors in the chemoreceptor trigger zone (CTZ) in the central nervous system. Common adverse drug reactions associated with metoclopramide include restlessness (akathisia), and focal dystonia.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 23
Correct
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A patient is diagnosed with a tumour of the parotid gland. During surgical removal of the gland, which artery is vulnerable to injury?
Your Answer: External carotid artery
Explanation:The external carotid artery is a major artery of the head and neck. It arises from the common carotid artery when it splits into the external and internal carotid artery. It supplies blood to the face and neck. The external carotid artery begins opposite the upper border of the thyroid cartilage and, taking a slightly curved course, passes upward and forward and then inclines backward to the space behind the neck of the mandible, where it divides into the superficial temporal and internal maxillary arteries. It rapidly diminishes in size in its course up the neck, owing to the number and large size of the branches given off from it. At its origin, this artery is more superficial and placed nearer the midline than the internal carotid and is contained within the carotid triangle. The external carotid artery is covered by the skin, superficial fascia, platysma, deep fascia and anterior margin of the sternocleidomastoid. It is crossed by the hypoglossal nerve, by the lingual, ranine, common facial and superior thyroid veins; and by the digastric and stylohyoid; higher up it passes deeply into the substance of the parotid gland, where it lies deep to the facial nerve and the junction of the temporal and internal maxillary veins. It is here that it is in danger during surgery of the parotid gland.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 24
Correct
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Atrial septal defect (ASD) is most likely to be due to incomplete closure of which one of the following structures:
Your Answer: Foramen ovale
Explanation:Atrial septal defect is a congenital heart defect that results in a communication between the right and left atria of the heart and may involve the interatrial septum. It results from incomplete closure of the foramen ovale which is normally open during fetal life and closes just after birth.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 25
Correct
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Which of the following organs of the abdominal cavity is completely covered by the peritoneum?
Your Answer: Spleen
Explanation:Of the organs listed, the spleen is the only organ that is completely intraperitoneal, that is entirely in the peritoneum. Other completely intraperitoneal organs include the stomach, liver, appendix and the small intestines. The kidney, Inferior vena cava, aorta and the suprarenal glands are all retroperitoneal organs. The pancreas and the duodenum are partially retroperitoneal, with the tail of the pancreas in the peritoneum found in the splenorenal ligament while only the first part of the duodenum is intraperitoneal. For the intraperitoneal organs remember SALTD SPRSS
S = Stomach
A = Appendix
L = Liver
T = Transverse colon
D = Duodenum (only the 1st part)S = Small intestines
P = Pancreas (only the tail)
R = Rectum (only the upper 3rd)
S = Sigmoid colon
S = SpleenFor retroperitoneal, just remember SADPUCKER:
S = suprarenal glands
A = Aorta and IVC
D = Duodenum (all but the 1st part)
P = Pancreas (all but the tail)
U = Ureter and bladder
C = Colon (ascending and descending)
K = Kidneys
E = Oesophagus
R = Rectum (Lower two-thirds)For secondarily retroperitoneal remember ‘Pussy Cat Dolls“:
P = Pancreas
C = Colon (only ascending and descending)
D = Duodenum (only parts 2-4) -
This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 26
Correct
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A 20-year old cyclist falls off a speeding bike and fractures a structure that articulates with the tubercle of the 7th rib. Which structure is fractured?
Your Answer: Transverse process of vertebra T7
Explanation:A rib tubercle is a projection that is postero-inferior and lateral to the neck of a rib which articulates with the transverse process of the corresponding vertebra i.e. of the same number. Therefore, the tubercle of rib 7 articulates with the transverse process of T7 vertebra. The head of the rib 7, on the other hand, articulates with the 6th vertebra superiorly and the 7th vertebra inferiorly.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 27
Incorrect
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A 34 year old mechanic suffers from a Gustilo and Anderson type IIIA fracture of the femoral shaft after being hit by a fork lift truck. What would be the most suitable step in the management of this patient?
Your Answer: Debridement and placement of intramedullary nail
Correct Answer: Debridement and external fixation
Explanation:Perhaps the most important aspect in the treatment of open fractures is the initial surgical intervention with irrigation and meticulous debridement of the injury zone. Irrigation, along with debridement, is absolutely crucial in the management of open fractures.
Early stabilization of open fractures provides many benefits to the injured patient. It protects the soft tissues around the zone of injury by preventing further damage from mobile fracture fragments. It also restores length, alignment, and rotation—all vital principles of fracture fixation. Skeletal traction and external fixation are the quickest fixation constructs to employ. The use of skeletal traction should be reserved only for selected open fracture types (i.e., pelvis fractures and very proximal femur fractures) and if used, it should only be for a short selected time. External fixation is a valuable tool in the surgeon’s arsenal for acute open fracture management. Indications for external fixation are grossly contaminated open fractures with extensive soft-tissue compromise, the Type IIIA-C injuries, and when immediate fixation is needed for physiologically unstable patients. -
This question is part of the following fields:
- Generic Surgical Topics
- Orthopaedics
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Question 28
Correct
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What principal artery that supplies the meninges is susceptible to rupture following trauma to the side of the head over the temporal region:
Your Answer: Middle meningeal artery
Explanation:The middle meningeal artery normally arises from the first or mandibular segment of the maxillary artery. The artery runs in a groove on the inside of the cranium, this can clearly be seen on a lateral skull X-ray. An injured middle meningeal artery is the most common cause of an epidural hematoma.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 29
Correct
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A 35 year old biker is rushed to the A&E department after he is knocked off his bike by a van. He has a 10cm open fracture of his tibia where no peripheral pulses are palpable. Intravenous antibiotics have been administered in the emergency department and the wound has been dressed. What is the most appropriate course of action?
Your Answer: Immediate vascular shunting, followed by temporary skeletal stabilisation and vascular reconstruction
Explanation:The Gustilo open fracture classification system is the most commonly used classification system for open fractures.
This system uses the amount of energy, the extent of soft-tissue injury and the extent of contamination for determination of fracture severity. Progression from grade 1 to 3C implies a higher degree of energy involved in the injury, higher soft tissue and bone damage and higher potential for complications.
Grade Injury
1 Low energy wound <1cm
2 Greater than 1cm wound with moderate soft tissue damage
3 High energy wound > 1cm with extensive soft tissue damage
3 A (sub group of 3) Adequate soft tissue coverage
3 B (sub group of 3) Inadequate soft tissue coverage
3 C (sub group of 3) Associated arterial injuryIt is important to recognize that a Gustilo score of grade 3C implies vascular injury as well as bone and connective-tissue damage. Grade 3C is defined as an open fracture associated with an arterial injury requiring repair, irrespective of degree of soft-tissue injury. The lack of peripheral pulses indicate arterial injury.
A less morbid damage control approach (compared with ligation) for patients with extremity vascular injury is vascular shunting, a technique that has been available for over 50 years. A vascular shunt is a synthetic tube that is inserted into the vessel and secured proximally and distally. Shunts were placed in the context of damage control to allow stabilization of Gustilo 3C fractures or limb replantation. Vascular shunts are typically used for larger, more proximal arteries and veins such as the femoral and popliteal arteries. Shunts can remain in place up to six hours, but definitive vascular reconstruction should be performed as soon as the patient is sufficiently stable to undergo the procedure. Once a fracture is identified, it is reduced as much as possible and splinted. If an open fracture is suspected, the patient should be taken to the operating room to debride and stabilize the fracture (usually with external fixation) either after life-threatening injuries have been managed or concurrently while less emergency chest, abdominal, or head injuries are being addressed. Revascularization — Ischemia due to vascular injury is a major risk factor for amputation, and, ideally, the injury will be identified and treated within six hours to minimize ischemic nerve and muscle damage. -
This question is part of the following fields:
- Generic Surgical Topics
- Orthopaedics
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Question 30
Correct
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A 5-year-old child presents with fever and otalgia. Greenish pustular discharge was seen in his left ear during physical examination. The patient is diagnosed with otitis externa. Which of the following organisms most likely caused the infection?
Your Answer: Pseudomonas aeruginosa
Explanation:P. aeruginosa is a multidrug resistant pathogen recognised for its ubiquity, its advanced antibiotic resistance mechanisms and its association with serious illnesses – especially hospital-acquired infections such as ventilator-associated pneumonia and various septic syndromes. The species name aeruginosa is a Latin word meaning verdigris (copper rust), referring to the blue-green colour of laboratory cultures of the species. This blue-green pigment is a combination of two metabolites of P. aeruginosa, pyocyanin (blue) and pyoverdine (green), which impart the blue-green characteristic colour of cultures.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 31
Correct
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A 30 year old man is diagnosed on oesophageal biopsies to have loss of ganglion cells in the myenteric plexus. Which of the following would be the most appropriate diagnosis?
Your Answer: Achalasia
Explanation:Achalasia is an oesophageal motor disorder characterized by aperistalsis of the oesophageal body and lack of relaxation of the lower sphincter in response to swallows.
Achalasia cardia is one of the common causes of motor dysphagia. Pathophysiologically, achalasia cardia is caused by loss of inhibitory ganglion in the myenteric plexus of the oesophagus. In the initial stage, degeneration of inhibitory nerves in the oesophagus results in unopposed action of excitatory neurotransmitters such as acetylcholine, resulting in high amplitude non-peristaltic contractions (vigorous achalasia); progressive loss of cholinergic neurons over time results in dilation and low amplitude simultaneous contractions in the oesophageal body (classic achalasia). -
This question is part of the following fields:
- Generic Surgical Topics
- Upper Gastrointestinal Surgery
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Question 32
Correct
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A pedestrian sustained a left fibula fractured following a hit-and-run. X-rays showed that there was a transverse fracture of the upper end of the fibula. It was manifested clinically by inability to flex his foot at the ankle joint plus weak extension of the phalanges. What nerve is suspected to be injured in such a case?
Your Answer: Deep peroneal
Explanation:The deep peroneal nerve supplies the muscles allowing for flexion of the foot at the ankle joint, namely the tibialis anterior and peroneus tertius muscles. The peroneus tertius, peroneus brevis, and peroneus longus evert the foot, whereas the tibialis anterior and tibialis posterior invert the foot. Fibres of the deep peroneal nerve originate from L4, L5, and S1.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 33
Correct
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A 23 year old woman is Rh -ve and she delivered a baby with a Rh+ blood group. What measure can be performed to prevent Rh incompatibility in the next pregnancy?
Your Answer: Immunoglobulin D
Explanation:Rh disease is also known as erythroblastosis fetalis and is a disease of the new-born. In mild states it can cause anaemia with reticulocytosis and in severe forms causes severe anaemia, morbus hemolytcus new-born and hydrops fetalis. RBCs of the Rh+ baby can cross the placenta and enter into the maternal blood. As she is Rh- her body will form antibodies against the D antigen which will pass through the placenta in subsequent pregnancies.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 34
Correct
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A 27-year-old male is admitted with left-sided loin pain that radiates to his groin. His investigations demonstrate a 9mm left-sided calculus within the proximal ureter. What is the most appropriate course of action?
Your Answer: Arrange a percutaneous extra corporeal shock wave lithotripsy
Explanation:EAU Guidelines on Urolithiasis recommend that
Proximal Ureteral Stone:
< 10 mm: shock wave lithotripsy (SWL) or ureterorenoscopy (URS)
> 10 mm: 1. URS (ante- or retrograde) 2. SWLContraindications of extracorporeal shock wave lithotripsy:
– Pregnancy, due to the potential effects on the foetus.
– Bleeding diatheses, which should be compensated for at least 24 hours before and 48 hours after
treatment.
– Uncontrolled UTIs
– Severe skeletal malformations and severe obesity, which prevent targeting of the stone.
– Arterial aneurysm in the vicinity of the stone.
– Anatomical obstruction distal to the stone.Lowering shock wave frequency from 120 to 60-90 shock waves/min improves SFRs.
The number of shock waves that can be delivered at each session depends on the type of lithotripter and shock wave power. There is no consensus on the maximum number of shock waves.
Starting SWL on a lower energy setting with stepwise power (and SWL sequence) ramping can achieve vasoconstriction during treatment, which prevents renal injury. -
This question is part of the following fields:
- Generic Surgical Topics
- Urology
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Question 35
Correct
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A gymnast was admitted to hospital for investigation of a weakness in the extension and adduction of his arm. He had a previous penetrating wound in the area of the posterior axillary fold. Which of these muscles is the likely cause?
Your Answer: Latissimus dorsi
Explanation:All the criteria of this case points towards the latissimus dorsi. This muscle is greatly involved in extension, adduction and medial rotation of the arm and forms the posterior axillary fold which in this case was injured.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 36
Correct
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A 53 year old women with a history of atrial fibrillation developed an acute abdomen. On laparoscopic examination her bowels appeared to be dusky to red-purple in colour and her mesenteric veins appeared to be patent. Which of the following is most likely to occur in this situation?
Your Answer: Wet gangrene
Explanation:Infarction of the small bowel following a sudden and complete occlusion of the mesenteric artery can involve any portion of the bowel, whether small or a large. The splenic flexure is at most risk for infarction as it is the watershed area between the superior and inferior mesenteric vessels. Regardless of whether the arterial or the venous blood vessels are occluded, because of the blood reflow into the damaged portion, it will appear haemorrhagic. The bowel appearing congested at first and then becoming oedematous. If the artery is occluded then there will be a clear cut demarcation and in venous occlusion the dusky colour fades with the rest of the normal bowel. Wet gangrene is characteristic of ischaemic injury to the gut.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 37
Incorrect
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A 31 year old construction worker visits his doctor after having painful rectal bleeding and he is found to have an anal fissure. Which of the following is least associated with this condition?
Your Answer: Tuberculosis
Correct Answer: Sickle cell disease
Explanation:Answer: Sickle cell disease
An anal fissure is a painful linear tear or crack in the distal anal canal, which, in the short term, usually involves only the epithelium and, in the long term, involves the full thickness of the anal mucosa. Anal fissures develop with equal frequency in both sexes; they tend to occur in younger and middle-aged persons.
The exact aetiology of anal fissures is unknown, but the initiating factor is thought to be trauma from the passage of a particularly hard or painful bowel movement. Low-fibre diets (e.g., those lacking in raw fruits and vegetables) are associated with the development of anal fissures. No occupations are associated with a higher risk for the development of anal fissures. Prior anal surgery is a predisposing factor because scarring from the surgery may cause either stenosis or tethering of the anal canal, which makes it more susceptible to trauma from hard stool.
In rare cases, an anal fissure may develop due to:
-anal cancer
-HIV
-tuberculosis
-syphilis
-herpesA study showed that a patient may exhibit severe, disabling, anorectal symptoms which are disproportionate to physical findings. Rarely leukaemia may be the cause, and the first signs of blood dyscrasia may appear in the anorectum. The diagnosis may not be suggested by the history, physical examination or routine laboratory data.
Crohn’s disease can also cause problems around the anus. These may include tiny but painful cracks in the skin known as anal fissures. Tunnelling sores called fistulas cause abnormal connections between the bowel and the skin; or an abscess, a pocket of inflamed or dead tissue that is usually very painful.
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This question is part of the following fields:
- Colorectal Surgery
- Generic Surgical Topics
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Question 38
Correct
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Calculate the cardiac output in an adult male with the following parameters: Heart rate 70 beats/min, Arterial [O2] 0.24 ml O2/min, Venous [O2] 0.16 ml O2/min, Whole body O2 consumption 500 ml/min, Pulmonary diastolic pressure 15 mmHg, Pulmonary systolic pressure 25 mmHg, Wedge pressure 5 mmHg.
Your Answer: 6.25 l/min
Explanation:As per Fick’s principle, VO2 = (CO × CAO2) – (CO × CVO2) where VO2 = oxygen consumption, CO = cardiac output, CAO2 = oxygen concentration of arterial blood and CVO2 = oxygen concentration of venous blood. Thus, CO = VO2/CAO2– CVO2, CO = 500/0.24 – 0.16, CO = 500/0.8, CO = 6.25 l/min.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 39
Correct
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Electrophoresis is used to detect antibodies (immunoglobulins) in a blood sample from the umbilical artery of a new born. Which antibodies have the highest percentage in a new-born?
Your Answer: IgG
Explanation:IgG is a monomeric immunoglobulin. It is formed by two heavy chains and two light chains and has two binding sites. Its is the most abundant antibody that is equally distributed in the blood and the tissues. It is the only antibody that can pass through the placenta and thus the only antibody present in the baby after it is born. There are four subclasses: IgG1 (66%), IgG2 (23%), IgG3 (7%) and IgG4 (4%). IgG1, IgG3 and IgG4 cross the placenta easily
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 40
Correct
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The parasympathetic fibres of the oculomotor nerve was impinged due to a growing tumour. The function of which of the following structures will be affected?
Your Answer: Ciliary muscle
Explanation:The oculomotor nerve is the third cranial nerve (CNIII). It offers motor and parasympathetic innervation to many of the ocular structures. The motor fibres innervate a number of the extraocular muscles. While the parasympathetic fibres supply the sphincter pupillae and the ciliary muscles of the eye, and the sympathetic fibres innervates the superior tarsal muscles.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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