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Question 1
Correct
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A 33-year old lady presented to the gynaecology clinic with amenorrhoea for 6 months and a recent-onset of milk discharge from her breasts. She was not pregnant or on any medication. On enquiry, she admitted to having frequent headaches the last 4 months. Which of the following findings would you expect to see in her condition?
Your Answer: Hyperprolactinaemia
Explanation:Excessively high levels of prolactin in the blood is called hyperprolactinaemia. Normally, prolactin levels are less than 580 mIU/l in females and less than 450 mIU/l in men. The biologically inactive macroprolactin can lead to a false high reading. However, the patient remains asymptomatic. Dopamine down-regulates prolactin whereas oestrogen upregulates it. Hyperprolactinaemia can be caused due to lack of inhibition (compression of pituitary stalk or low dopamine levels), or increased production due to a pituitary adenoma (prolactinoma). Either of these causes can lead to a prolactin level of 1000-5000 mIU/l. However, levels more than 5000mIU/l are usually associated due to an adenoma and >100,000 mIU/l are seen in macroadenomas (tumours < 1cm in diameter). Increased prolactin causes increased dopamine release from the arcuate nucleus of hypothalamus. This increased dopamine in turn, inhibits the GnRH (Gonadotrophin Releasing Hormone) thus blocking gonadal steroidogenesis resulting in the symptoms of hyperprolactinaemia. In women, it includes hypoestrogenism, anovulatory infertility, decreased or irregular menstruation or complete amenorrhoea. It can even cause production of breast milk, loss of libido, vaginal dryness and osteoporosis. In men, the symptoms include impotence, decreased libido, erectile dysfunction and infertility. In men, treatment can be delayed due to late diagnosis as they have no reliable indicator such as menstruation that might indicate a problem. Most of the male patients seek help only when headaches and visual defects start to surface.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 2
Correct
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A 58-year-old woman has had a headache, fever, lethargy and nausea for the last 10 days. He undergoes a CT scan which reveals a lesion in his frontal lobe, which, after a biopsy, is found to be formed by granulation tissue with collagenisation, gliosis and oedema. What's the most likely diagnosis?
Your Answer: Chronic brain abscess
Explanation:A cerebral abscess can result from direct extension of cranial infections, penetrating head trauma, haematogenous spread, or for unknown causes. An abscess forms when an area of cerebral inflammation becomes necrotic and encapsulated by glial cells and fibroblasts. Oedema around the abscess can increase the intracranial pressure. Symptoms result from increased intracranial pressure and mass effects. In a CT scan, an abscess appears as an oedematous mass with ring enhancement.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 3
Correct
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The wound healing process is documented in patients undergoing laparoscopic procedures. The port incisions are sutured closed and the wounds observed every few weeks for re-epithelialisation and tensile strength. Which substance is mostly likely to be found at a cellular level involved in wound healing?
Your Answer: Tyrosine kinase
Explanation:Cell surface growth factor receptors require intercellular proteins such as tyrosine kinase which are necessary to initiate a series of events that eventually lead to cell division and growth. Tyrosine kinase is an enzyme that transfers a phosphate group to the tyrosine residue in a protein. This phosphorylation will lead to an up regulation of the enzyme activity.
Fibronectin acts in the extracellular matrix to bind macromolecules (such as proteoglycans) via integrin receptors to aid attachment and migration of cells.
Laminin is an extracellular matrix component that is abundant in basement membranes.
Hyaluronic acid is one of the proteoglycans in the extracellular matrix.
Collagen fibres are part of the extracellular matrix that gives strength and stability to connective tissues. -
This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 4
Correct
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A suspected recreational drug user was brought to the Emergency department in an unconscious state, and was found to be hypoventilating. Which of the following set of arterial blood gas analysis report is most consistent with hypoventilation as the primary cause? pH, pa(CO2) (mmHg), pa(O2) (mmHg).
Your Answer: 7.28, 55, 81
Explanation:Hypoventilation (or respiratory depression) causes an increase in carbon dioxide (hypercapnia) and respiratory acidosis. It can result due to drugs such as alcohol, benzodiazepines, barbiturates, opiates, mechanical conditions or holding ones breath. Strong opioids such as heroin and fentanyl are commonly implicated and can lead to respiratory arrest. In recreational drug overdose, acute respiratory acidosis occurs with an increase in p(CO2) over 45 mm Hg and acidaemia (pH < 7.35)
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 5
Correct
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In a study, breast lumps were analysed to determine the characteristic of malignant neoplasm on biopsy. What microscopic findings are suggestive of malignancy?
Your Answer: Invasion
Explanation:Invasion is suggestive of malignancy and an even better option would have been metastasis. Pleomorphism is found in both benign and malignant neoplasms along with atypia and anaplasia. A height nuclear/cytoplasmic ratio is suggestive of malignancy but not the best indicator. Malignant tumours are aggressive and growth rapidly. Necrosis can be seen in benign tumours if they deplete their blood supply.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 6
Correct
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A 73-year-old woman goes to the doctor complaining of pain and stiffness in her shoulders and hips for 4 months, which is worst in the mornings. She has also been suffering from fatigue, weight loss and depression. There were no abnormal findings on physical examination. The erythrocyte sedimentation rate was 110 mm/hour, and serum rheumatoid factor and antinuclear antibody assays were negative. Mild normochromic normocytic anaemia was also found. What is the most likely diagnosis in this case?
Your Answer: Polymyalgia rheumatica
Explanation:Polymyalgia rheumatica (PMR) affects older adults, with an acute or subacute onset. Symptoms include severe pain and stiffness of the neck and pectoral or pelvic girdles, which is worse in the morning or after a period of inactivity and is usually bilateral. Other symptoms can include fatigue, weight loss, depression and fever. The erythrocyte sedimentation rate is usually elevated, and normochromic normocytic anaemia can occur. Other tests are usually normal in this disease.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 7
Correct
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Injury to the supraspinatus muscle will affect:
Your Answer: Initiation of abduction of the humerus
Explanation:This muscle arises from the medial two-thirds of the supraspinatus fossa and from the supraspinatus fascia. It is inserted into the highest impression on the greater tubercle of the humerus after passing over the upper part of the shoulder joint. It works with the deltoid to raise the arm from the side of the trunk and initiate abduction. It also assists in fixation of the head of the humerus in the glenoid cavity.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 8
Correct
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A 33 year old woman presents to the clinic with abdominal pain and a progressively worsening condition. She is admitted with cholangitis. Lab results reveal:Serum bilirubin: 180, Alkaline phosphatase: 348, Serum amylase: 1080. Standard treatment is carried out and her Glasgow score is 3. Which of the following is the most appropriate step in her management?
Your Answer: ERCP
Explanation:ERCP serves as a primary therapeutic modality for management of biliary pancreatitis in specific situations: pancreatitis due to microlithiasis, specific types of sphincter of Oddi dysfunction, pancreas divisum, ascariasis and malignancy. It is important that her coagulation status is normalized prior to performing this procedure.
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This question is part of the following fields:
- Generic Surgical Topics
- Hepatobiliary And Pancreatic Surgery
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Question 9
Correct
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A 45 year old women has a 4 cm non tender mass in her right breast which is fixed to the chest wall. Another 2cm non-tender mass is palpable in the left axilla. Chest x ray reveals multiple nodules ranging from 0.5 - 0.2 cm in both the lungs. What is the stage of her disease?
Your Answer: T4 N1 M1
Explanation:This woman has an invasive primary tumour mass with axillary node and lung metastases, making this stage T4 N1 M1. Looking at the other stems, T1 N1 M0 signifies a small primary cancer with nodal metastases but no distant metastases; T1 N0 M1 signifies a small primary cancer with no lymph node metastases but with distant metastases; T2 N1 M0 signifies a larger primary cancer with nodal metastases but no distant metastases; and T3 N0 M0 indicates a larger primary cancer with no metastases to either lymph nodes or to distant sites.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 10
Correct
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A 40 year old woman has a full thickness burn on her foot after being trapped in a burning building. The limb has no fractures but the burn is well circumscribed. She starts complaining of tingling of her foot which has a dusky look after 3 hours. Which of the following is the best management step?
Your Answer: Escharotomy
Explanation:Answer: Escharotomy
Escharotomy is the surgical division of the nonviable eschar, which allows the cutaneous envelope to become more compliant. Hence, the underlying tissues have an increased available volume to expand into, preventing further tissue injury or functional compromise.
Full-thickness circumferential and near-circumferential skin burns result in the formation of a tough, inelastic mass of burnt tissue (eschar). The eschar, by virtue of this inelasticity, results in the burn-induced compartment syndrome. This is caused by the accumulation of extracellular and extravascular fluid within confined anatomic spaces of the extremities or digits. The excessive fluid causes the intracompartmental pressures to increase, resulting in collapse of the contained vascular and lymphatic structures and, hence, loss of tissue viability. The capillary closure pressure of 30 mm Hg, also measured as the compartment pressure, is accepted as that which requires intervention to prevent tissue death.
The circumferential eschar over the torso can lead to significant compromise of chest wall excursions and can hinder ventilation. Abdominal compartment syndrome with visceral hypoperfusion is associated with severe burns of the abdomen and torso. (A literature review by Strang et al found the prevalence of abdominal compartment syndrome in severely burned patients to be 4.1-16.6%, with the mean mortality rate for this condition in these patients to be 74.8%). Similarly, airway patency and venous return may be compromised by circumferential burns involving the neck.
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This question is part of the following fields:
- Emergency Medicine And Management Of Trauma
- Principles Of Surgery-in-General
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Question 11
Incorrect
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A 36 year old woman who smokes heavily arrives at the clinic complaining of frequent stools and crampy abdominal pain that has been occurring for some time. She undergoes colonoscopy (which is macroscopically normal) and several pan colonic biopsies are taken. Histologic analysis reveals a thickened sub apical collagen layer and increased lymphocytes in the lamina propria. Which of the following diagnosis is most likely?
Your Answer: Crohn's disease
Correct Answer: Microscopic colitis
Explanation:Microscopic colitis is an inflammation of the large intestine (colon) that causes persistent watery diarrhoea. The disorder gets its name from the fact that it’s necessary to examine the colon tissue under a microscope to identify it, since the tissue may appear normal with a colonoscopy or flexible sigmoidoscopy. It is characterised by normal endoscopic appearances, microscopic features of colonic inflammation and thickening of the sub epithelial collagen layer. Features such as granulomas are absent. It is the normal endoscopic appearance that makes the other options less likely.
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This question is part of the following fields:
- Generic Surgical Topics
- The Abdomen
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Question 12
Correct
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What occurs during cellular atrophy?
Your Answer: Cell size decreases
Explanation:Atrophy is the decrease in the size of cells, tissues, or organs. There are several causes including inadequate nutrition, poor circulation, loss of hormonal support or nerve supply, disuse, lack of exercise, or disease. An increase in cell size is termed hypertrophy which is distinguished from hyperplasia, in which the cells remain approximately the same size but increase in number.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 13
Correct
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A 25-year-old intravenous drug user is found to have a femoral abscess. He is also febrile with a temperature of 39°C and has a pansystolic murmur loudest at the left sternal edge in the 4th intercostal space. Which of the following is the most likely underlying lesion?
Your Answer: Tricuspid regurgitation
Explanation:Intravenous drug users are at a high risk of right-sided cardiac valvular endocarditis. The character of the murmur described in the scenario fits with the diagnosis of tricuspid valve endocarditis.
Other listed options are ruled out because:
1. Aortic regurgitation—Early diastolic murmur
2. Mitral regurgitation—Pansystolic murmur
3. Aortic valve stenosis—Ejection systolic murmur
4. Tricuspid valve stenosis—Mid-diastolic murmur -
This question is part of the following fields:
- Generic Surgical Topics
- Vascular
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Question 14
Correct
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A 50-year old lady presented to the clinic with chronic pain in the abdomen. On physical examination, she was found to be pale. Further investigations revealed a decrease in both serum iron and total iron-binding capacity, along with an increase in serum ferritin. These findings are seen in:
Your Answer: Anaemia of chronic disease
Explanation:Anaemia of chronic disease is characterized by low serum iron, iron-binding capacity and saturation with increased ferritin (storage iron). Haemolytic anaemia is characterized by normal iron levels as the haemoglobin released from the haemolysed red blood cells is recycled. Anaemia due to chronic blood loss leads to low serum iron, low ferritin and high total iron-binding capacity (TIBC). Malabsorption, especially with duodenal involvement can also lead to iron deficiency anaemia with low ferritin and high TIBC. Megaloblastic anaemia due to vitamin B12 and folate deficiency is not associated with abnormalities in metabolism of iron.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 15
Incorrect
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A medical student is told a substance is freely filtered but is not metabolised, secreted, or stored in the kidney. It has a plasma concentration of 1000 mg/l and its urine excretion rate is 25 mg/min, and the inulin clearance is 100 ml/min. What is the rate of tubular reabsorption of the substance?
Your Answer: 25 mg/min
Correct Answer: 75 mg/min
Explanation:Reabsorption or tubular reabsorption is the process by which the nephron removes water and solutes from the tubular fluid (pre-urine) and returns them to the circulating blood. To calculate the reabsorption rate of substance Z we use the following equation: excretion = (filtration + secretion) – reabsorption. As this substance is freely filtered, its filtration rate is equal to that of inulin. So 25 = (100 + 0) – reabsorption. Reabsorption = 100 – 25 therefore reabsorption = 75 mg/min.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 16
Correct
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The most likely cause of a low p(O2) in arterial blood is:
Your Answer: Hypoxic hypoxia
Explanation:Hypoxia is when the whole body or a region is deprived of adequate oxygen supply. Different types of hypoxia include the following:
– Hypoxic hypoxia, which occurs due to poor oxygen supply, as a result of low partial pressure of oxygen in arterial blood. This could be due to low partial pressure of atmospheric oxygen (e.g., at high altitude), sleep apnoea, poor ventilation because of chronic obstructive pulmonary disease or respiratory arrest, or shunts. The other types of hypoxia have a normal partial pressure of oxygen.
– Anaemic hypoxia occurs due to low total oxygen content of the blood, with a normal arterial oxygen pressure.
– Hyperaemic hypoxia occurs due to poor delivery of oxygen to target tissues, such as in carbon monoxide poisoning or methemoglobinemia.
– Histotoxic hypoxia results due to inability of the cells to use the delivered oxygen due to disabled oxidative phosphorylation enzymes.
– Ischaemic (or stagnant) hypoxia occurs due to local flow restriction of well-oxygenated blood, seen in cases like cerebral ischaemia, ischaemic heart disease and intrauterine hypoxia. -
This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 17
Correct
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A 30-year-old male is playing tennis when he suddenly collapses and has a GCS of 4 when examined. What is the most likely cause?
Your Answer: Subarachnoid haemorrhage
Explanation:The term subarachnoid haemorrhage (SAH) refers to extravasation of blood into the subarachnoid space between the pial and arachnoid membranes. SAH constitutes half of all spontaneous atraumatic intracranial haemorrhages; the other half consists of bleeding that occurs within the brain parenchyma.
Intracranial saccular aneurysms (“berry aneurysms”) represent the most common aetiology of nontraumatic SAH; about 80% of cases of SAH result from ruptured aneurysms. -
This question is part of the following fields:
- Generic Surgical Topics
- Surgical Disorders Of The Brain
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Question 18
Correct
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The sciatic nerve does NOT supply which of the following muscles?
Your Answer: Obturator externus
Explanation:The sciatic nerve supplies both gemellae, quadratus femoris, semitendinosus, semimembranosus, both heads of the biceps femoris, the hamstring half of abductor magnus and obturator internus. Obturator externus is supplied by the obturator nerve.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 19
Incorrect
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Which of the following associations is correctly matched with the body's defence mechanism in fighting infection?
Your Answer: Non-specific cellular mechanism → B lymphocytes
Correct Answer: Specific cellular mechanism → cytotoxic T cells
Explanation:The immune system has certain levels of defence against pathogens. First line includes simple barriers such as skin, mucosa and stomach acid that prevent the pathogen from entering into the body. If this barrier is breached then the innate immune system is activated which includes leukocytes (macrophages, neutrophils, mast cells, eosinophils, basophils, natural killer cells). If the pathogens invade the second layer of defence then the third layer, adaptive immunity is activated, which includes B and T lymphocytes. B cells provide a humoral response whereas cytotoxic T cells have specific cellular mechanisms. They maintain a memory of past infections and are activated faster following a recurrence.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 20
Incorrect
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A 59 year old woman presents to the hospital with a 2.1cm mobile breast mass. A mammogram is indeterminate (M3), an ultrasound scan shows benign changes (U2), and clinical examination is also indeterminate (P3). What is the next best course of action?
Your Answer: Fine needle aspiration cytology
Correct Answer: Image guided core biopsy
Explanation:Image guided core biopsy (US-directed biopsy) is performed for lesions that are palpable, but also for non-palpable, mammogram-detected lesions with a corresponding abnormality visualized on US. US-guided core biopsy is technically easier than stereotactic-guided biopsy as real-time imaging allows the surgeon to visualize the biopsy as it occurs. Using sterile technique and local anaesthesia, a small puncture is made with an 11-knife blade and the needle is placed near the edge of the lesion and fired, which inserts it into the lesion for a sample to be retrieved. When placed parallel to the needle the position of the needle can be visualized on US.
If the core biopsy result is benign and is concordant with imaging findings, continued surveillance is acceptable. If the result is indeterminate or image-discordant, surgical excision is indicated to rule out malignancy. In order to determine the appropriate management and surveillance of a lesion, the histologic, imaging, and clinical findings must be taken into account for an assessment of concordance to be performed. In addition, surgical excision is indicated for a core biopsy that demonstrates atypical hyperplasia (lobular or ductal) or lobular carcinoma in situ or neoplasia as the incidence of coexisting ductal carcinoma in situ or invasive carcinoma may be as high as 30% due to potential sampling error.
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This question is part of the following fields:
- Breast And Endocrine Surgery
- Generic Surgical Topics
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Question 21
Correct
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Which of the following variables are needed to calculate inspiratory reserve volume of a patient?
Your Answer: Tidal volume, vital capacity and expiratory reserve volume
Explanation:Vital capacity = inspiratory reserve volume + tidal volume + expiratory reserve volume. Thus, inspiratory reserve volume can be calculated if tidal volume, vital capacity and expiratory reserve volume are known.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 22
Correct
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If the blood flow is constant, oxygen extraction by tissues will show the greatest decrease due to which of the following interventions?
Your Answer: Tissue cooling
Explanation:With a constant blood flow to a given tissue bed, there will be an increase in oxygen extraction by the tissue with the following; an increase in tissue metabolism and oxygen requirements: warming (or fever), exercise, catecholamines and thyroxine. With cooling, the demand for oxygen decreases, leading to decreased oxygen extraction.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 23
Correct
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A 45-year old male, who was a chronic smoker presented to the clinic with backache and dry, incessant cough. On examination, he was found to have raised blood pressure, purplish striae on his abdomen, truncal obesity and tenderness over the lower thoracic spine. These findings are suggestive of which condition?
Your Answer: Small-cell anaplastic (oat cell) carcinoma
Explanation:The symptoms suggest Cushing syndrome due to increased glucocorticoid levels. One cause of Cushing syndrome is ectopic production of adrenocorticotrophic hormone from oat cell carcinoma. As oat cell carcinoma is known to be highly metastatic, the tenderness in lower back could represent metastatic involvement.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 24
Correct
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A 54-year-old male presents with central chest pain and vomiting. He has drunk a bottle of vodka. On examination, there is some mild crepitus in the epigastric region. What is the likely diagnosis?
Your Answer: Oesophageal perforation
Explanation:Boerhaave syndrome classically presents as the Mackler triad of chest pain, vomiting, and subcutaneous emphysema due to oesophageal rupture, although these symptoms are not always present.
The classic clinical presentation of Boerhaave syndrome usually consists of repeated episodes of retching and vomiting, typically in a middle-aged man with recent excessive dietary and alcohol intake.
These repeated episodes of retching and vomiting are followed by a sudden onset of severe chest pain in the lower thorax and the upper abdomen. The pain may radiate to the back or to the left shoulder. Swallowing often aggravates the pain.
Typically, hematemesis is not seen after oesophageal rupture, which helps to distinguish it from the more common Mallory-Weiss tear.
Swallowing may precipitate coughing because of the communication between the oesophagus and the pleural cavity. -
This question is part of the following fields:
- Emergency Medicine And Management Of Trauma
- Principles Of Surgery-in-General
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Question 25
Correct
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A 32-year-old male is admitted overnight, following a road traffic accident. He has an open tibial fracture with a 20 cm wound and extensive periosteal stripping. He is neurovascularly intact; IV antibiotics and wound dressing have been administered in the emergency department. What is the most appropriate course of action?
Your Answer: Combined skeletal and soft tissue reconstruction on a scheduled operating list
Explanation:The patient has Gustilo-Anderson Grade IIIb.
Options for wound closure in the treatment of open fractures include primary closure of the skin, split-thickness skin grafting, and the use of either free or local muscle flaps. The timing of open wound closure has proponents in the immediate, early, and delayed categories
Gustilo-Anderson classification
Type I – Open fracture with a wound less than 1 cm in length, and clean
Type II – Open fracture with a laceration more than 1 cm in length, without extensive soft-tissue damage, flaps, or avulsions
Type III – Either an open segmental fracture, an open fracture with extensive soft-tissue damage, or a traumatic amputation
The description of type III fractures was subsequently further refined and described by Gustilo et al in 1984, [6] as follows:
Type IIIa – Severe comminution or segmental fractures, but with adequate coverage of bone and a wound that is closable by simple means
Type IIIb – Extensive soft-tissue damage in association with the open fracture, with significant bone exposure and periosteal stripping, typically requiring tissue rotation or free tissue transfer for closure
Type IIIc – Any open fracture with an arterial injury that requires repair -
This question is part of the following fields:
- Generic Surgical Topics
- Orthopaedics
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Question 26
Incorrect
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During a laparoscopic surgery, the surgeon visualizes the medical umbilical folds on the deep surface of the anterior abdominal wall. What causes the medial umbilical folds?
Your Answer: Round ligaments of the uterus
Correct Answer: Obliterated umbilical arteries
Explanation:The medial umbilical ligament is a structure found on the deep surface of the anterior abdominal wall and is covered by the medial umbilical folds. It is a paired structure that represents the remnants of the fetal umbilical artery. They have no role in humans after birth other than to be used as a landmark for exploring the medial inguinal fossa during laparoscopic inguinal hernia repair.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 27
Correct
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A 33 year old woman presents with a complaint of dysphagia. She has a ten year history of treatment refractory anaemia secondary to menorrhagia. Which of the following is the most likely underlying cause?
Your Answer: Plummer Vinson syndrome
Explanation:Iron deficiency anaemia (IDA) is the most common form of anaemia worldwide and can be due to inadequate intake, decreased absorption (e.g., atrophic gastritis, inflammatory bowel disease), increased demand (e.g., during pregnancy), or increased loss (e.g., gastrointestinal bleeding, menorrhagia) of iron. Prolonged deficiency depletes the iron stores in the body, resulting in decreased erythropoiesis and anaemia.
Symptoms are nonspecific and include fatigue, pallor, lethargy, hair loss, brittle nails, and pica. Diagnostic lab values include low haemoglobin, microcytic, hypochromic red blood cells on peripheral smear, and low ferritin and iron levels. Once diagnosed, the underlying cause should be determined. Patients at risk for underlying gastrointestinal malignancy should also undergo a colonoscopy.
Iron deficiency anaemia is treated with oral (most common) or parenteral iron supplementation. Severe anaemia or those with concomitant cardiac conditions may also require blood transfusions. The underlying cause of IDA should also be corrected. IDA may manifest as Plummer-Vinson syndrome (PVS): triad of postcricoid dysphagia, upper oesophageal webs, and iron deficiency anaemia -
This question is part of the following fields:
- Generic Surgical Topics
- Upper Gastrointestinal Surgery
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Question 28
Correct
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A 62-year-old male smoker, presented with shortness of breath, chronic cough and haemoptysis over the last three months. He has developed a fat pad in the base of his neck, rounded face, acne and osteoporosis. Which of the following is the most likely pulmonary disease that is causing these symptoms and findings?
Your Answer: Small-cell anaplastic carcinoma
Explanation:Small cell lung cancer is a highly aggressive form of lung cancer. It is thought to originate from neuroendocrine cells in the bronchus called Feyrter cells and is often associated to ectopic production of hormones like ADH and ACTH that result in paraneoplastic syndromes and Cushing’s syndrome.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 29
Correct
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A 30-year-old male patient is undergoing an open appendicectomy. The surgeons extend the incision medially and suddenly encounter troublesome bleeding. What should be the best course of action?
Your Answer: Ligate the bleeding vessel
Explanation:Medial extension of an appendicectomy incision carries a risk of injury to the inferior epigastric artery which can bleed briskly. It is best managed by ligation.
Bleeding is a complication encountered in all branches of surgery. The decision as to how best to manage the bleed, depends upon its site, vessel, and circumstances.
1. Superficial dermal bleeding:
This will usually cease spontaneously. If not, then direct use of a monopolar or a bipolar cautery device will usually control the situation. Scalp wounds are a notable exception and bleeding from them may be brisk. In this situation, use of a mattress suture as a wound closure method will usually address the problem.2. Superficial arterial bleeding:
If the vessel can be safely identified in superficial arterial bleeding, then the easiest method is to apply a haemostatic clip and ligate the vessel.3. Major arterial bleeding:
If the vessel can be clearly identified and is accessible, then it may be possible to apply a clip and ligate the vessel. If the vessel is located in a pool of blood, then blind application of haemostatic clips is highly dangerous and may result in collateral injury. In this situation, evacuating the clot and packing the area is often safer. The pack can then be carefully removed when the required instruments are available. Some vessels may retract and bleeding may then be controlled by dissection of surrounding structures or underrunning the bleeding point.4. Major venous bleeding:
The safest initial course of action is to apply digital pressure to the bleeding point. To control the bleeding, thereafter, the surgeon will need a working suction device. Divided veins may require ligation.5. Bleeding from raw surfaces:
This may be mixed bleeding and can be troublesome. Spray diathermy and argon plasma coagulation are both useful agents. Certain topical haemostatic agents, such as surgicel, are useful in encouraging clot formation and may be used in conjunction with, or instead of, the above agents. -
This question is part of the following fields:
- Principles Of Surgery-in-General
- Surgical Technique And Technology
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Question 30
Correct
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Intravenous diazepam was administered to a man who was brought to the emergency department with status epilepticus. He was administered 15 l/min oxygen via a reservoir bag mask. Blood investigations showed sodium = 140 mmol/l, potassium = 4 mmol/l and chloride = 98 mmol/l. His arterial blood gas analysis revealed pH 7.08, p(CO2)= 61.5 mmHg, p(O2) = 111 mmHg and standard bicarbonate = 17 mmol/l. This patient had:
Your Answer: Mixed acidosis
Explanation:Acidosis with high p(CO2) and low standard bicarbonate indicates mixed acidosis. Lower p(O2) is due to breathing of 70% oxygen. The prolonged seizures lead to lactic acidosis and the intravenous diazepam is responsible for the respiratory acidosis. Treatment includes airway manoeuvres and oxygen, assisted ventilation if needed, and treatment with fluids.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 31
Incorrect
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A 32 year old woman with a history of Crohn's disease, presents with a recurrent discharging anal fistula. Examination reveals a low anal fistula with involvement of a small area of the external anal sphincter muscle. Which of the following is the most appropriate management plan?
Your Answer: Insertion of a cutting seton
Correct Answer: Insertion of a loose seton
Explanation:Fistulotomy could achieve good results in terms of wound healing and incontinence in strictly selected patients with Crohn’s disease suffering from low-lying trans-sphincteric fistulae. For more high-lying or complicated fistulae, seton placement is more appropriate. For high transsphincteric fistulae, the only option is placement of loose seton.
Fistulae are classified into four main groups according to anatomical location and the degree of sphincter involvement. Simple uncomplicated fistulae are low and do not involve more than 30% of the external sphincter. Complex fistulae involve the sphincter, have multiple branches or are non cryptoglandular in origin -
This question is part of the following fields:
- Colorectal Surgery
- Generic Surgical Topics
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Question 32
Incorrect
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A patient sustained an iatrogenic injury to one of the structures passing through the deep inguinal ring. This was during an operation to repair an inguinal hernia. Which structure is most likely to be injured?
Your Answer: Ilioinguinal nerve
Correct Answer: Round ligament of the uterus
Explanation:The deep inguinal ring transmits the spermatic cord in the man and the round ligament of the uterus in the female. It is bound below and medially by the inferior epigastric vessels (so these don’t go through it).
The ilioinguinal nerve, although it courses through the inguinal canal, does not pass through it.
The iliohypogastric nerves run between the internal oblique and transversus abdominis in the abdominal wall, piercing the internal oblique at the anterior superior iliac spine to travel just deep to the external oblique.
The inferior epigastric artery runs between the transversus abdominis and the peritoneum forming the lateral umbilical fold.
The medial umbilical ligament is the obliterated umbilical artery that it lies within the medial umbilical fold of peritoneum. -
This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 33
Correct
-
A 35 year old opera singer undergoes a thyroidectomy and post-operatively, he develops stridor and is unable to speak. What is the best explanation for this symptom?
Your Answer: Bilateral recurrent laryngeal nerve injury
Explanation:This patient has aphonia due to bilateral damage to the recurrent laryngeal nerve. Bilateral recurrent laryngeal nerve (RLN) injury is rare for benign thyroid lesions (0.2%). After extubation-stridor, respiratory distress, aphonia occurs due to the closure of the glottic aperture necessitating immediate intervention and emergency intubation or tracheostomy. Intra-operative identification and preservation of the RLN minimizes the risk of injury.
The recurrent laryngeal nerves control all intrinsic muscles of the larynx except for the cricothyroid muscle. These muscles act to open, close, and adjust the tension of the vocal cords, and include the posterior cricoarytenoid muscles, the only muscle to open the vocal cords. The nerves supply muscles on the same side of the body, with the exception of the interarytenoid muscle, which is innervated from both sides.The nerves also carry sensory information from the mucous membranes of the larynx below the lower surface of the vocal fold, as well as sensory, secretory and motor fibres to the cervical segments of the oesophagus and the trachea.
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This question is part of the following fields:
- Generic Surgical Topics
- Head And Neck Surgery
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Question 34
Incorrect
-
A 50-year-old female has a metallic heart valve and requires a paraumbilical hernia repair. Perioperatively, she is receiving intravenous unfractionated heparin. To perform the surgery safely a normal coagulation state is required. Which of the following strategies is a routine standard practice?
Your Answer: Stopping the heparin infusion 6 hours pre operatively and administration of intravenous protamine sulphate on commencing the operation
Correct Answer: Stopping the heparin infusion 6 hours pre operatively
Explanation:In performing noncardiac surgery on patients on anticoagulation, the major concern is when it is safe to perform surgery without increasing the risk of haemorrhage or increasing the risk of thromboembolism (e.g., venous, arterial) after discontinuing treatment.
Any patient who is on long-term anticoagulation and is to undergo a major surgery needs proactive management.
Heparin is discontinued 6-12 hours before surgery and restarted at 200-400 U/h at 4-6 hours after surgery. Coumadin is restarted as soon as tolerated by the patient. Stop oral anticoagulants at least 5 days preoperatively, and do not perform the procedure until the PT is in the reference range. -
This question is part of the following fields:
- Peri-operative Care
- Principles Of Surgery-in-General
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Question 35
Correct
-
A 47-year old-woman diagnosed with pancreatitis presented to the emergency department complaining of a worsening shortness of breath, fever, agitation and cough. Oxygen saturation was 67% in room air. Her respiratory status continued to deteriorate therefore she was intubated. She was admitted to the intensive care unit for management. Chest X-ray demonstrated bilateral perihilar opacities. The patient failed conventional treatment and died several days later. At autopsy, the lung shows growth of type 2 pneumocytes and thickened alveolar walls. What is the most probable diagnosis?
Your Answer: Adult respiratory distress syndrome
Explanation:Acute (or adult) respiratory distress syndrome (ARDS) is a life-threatening lung condition characterised by a non-cardiogenic pulmonary oedema that leads to acute respiratory failure. The most common risk factors for ARDS include trauma with direct lung injury, sepsis, pneumonia, pancreatitis, burns, drug overdose, massive blood transfusion and shock. Acute onset of dyspnoea with hypoxemia, anxiety and agitation is typical. Chest X ray most commonly demonstrates bilateral pulmonary infiltrates. Histological changes include the exudative, proliferative and fibrotic phase. ARDS is mainly a clinical diagnosis.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 36
Correct
-
Congenital anomalies of genitourinary tract are more common than any other system. Which of the following anomalies carries the greatest risk of morbidity?
Your Answer: Bladder exstrophy
Explanation:Bladder exstrophy is the condition where the urinary bladder opens from the anterior aspect suprapubically. The mucosa of the bladder is continuous with the abdominal skin and there is separation of the pubic bones. The function of the upper urinary tract remains normal usually. Treatment consists of surgical reconstruction of the bladder and returning it to the pelvis. There can be a need for continent urinary diversion along with reconstruction of the genitals.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 37
Correct
-
A 39 year old woman is admitted with acute cholecystitis which fails to settle. During a laparoscopic cholecystectomy, the gallbladder has evidence of an empyema and Calots triangle is inflamed. The surgeon suspects that a Mirizzi syndrome has occurred. What is the most appropriate course of action?
Your Answer: Undertake an operative cholecystostomy
Explanation:Mirizzi’s syndrome is a rare complication in which a gallstone becomes impacted in the cystic duct or neck of the gallbladder causing compression of the common hepatic duct, resulting in obstruction and jaundice. The obstructive jaundice can be caused by direct extrinsic compression by the stone or from fibrosis caused by chronic cholecystitis (inflammation).
Type I – No fistula present
Type IA – Presence of the cystic duct
Type IB – Obliteration of the cystic ductTypes II–IV – Fistula present
Type II – Defect smaller than 33% of the CHD diameter
Type III – Defect 33–66% of the CHD diameter
Type IV – Defect larger than 66% of the CHD diameterSimple cholecystectomy is suitable for type I patients. This patient has type I because no fistula is present.
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This question is part of the following fields:
- Generic Surgical Topics
- Hepatobiliary And Pancreatic Surgery
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Question 38
Correct
-
A 64 year old woman received midazolam before a colonoscopy. During the procedure her respiratory rate slows down and she becomes hypoxic. The anaesthetist decides to reverse her sedation. Which of the following drugs should be administered?
Your Answer: Flumazenil
Explanation:Reversal of the central effects of midazolam by intravenous flumazenil after general anaesthesia. Since many benzodiazepines have longer half lives than flumazenil patients still require close monitoring after receiving the drug. Other drugs provided in the options would not characteristically be used for the reversal of midazolam.
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This question is part of the following fields:
- Peri-operative Care
- Principles Of Surgery-in-General
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Question 39
Correct
-
Which of the following substances brings about a dilatation of the gastrointestinal resistance vessels?
Your Answer: Vasoactive intestinal peptide
Explanation:Gastric vasoconstrictors include catecholamines, angiotensin II and vasopressin. Vasodilators include vasoactive intestinal peptide and the hormones; gastrin, cholecystokinin and glucagon.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 40
Incorrect
-
A medical intern wanting to perform her first thoracentesis (remove fluid from the pleural cavity) wishes to be reminded where to insert the needle to aspirate in order to avoid injuring the lung or neurovascular elements. Where is this place?
Your Answer: The bottom of interspace 6 in the midaxillary line
Correct Answer: The bottom of interspace 9 in the midaxillary line
Explanation:Thoracentesis is performed in the costodiaphragmatic recess. The needle needs to be inserted below the level of the lungs to avoid injury to the lungs. At the paravertebral line, is between ribs 10 and 12, at the midaxillary line between ribs 8 and 10 and at the midclavicular line between interspaces 6 and 8. The needle should be inserted at the top of the rib (or the bottom of the interspace) to avoid damage to the neurovascular structures found below the rib running in the costal groove.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 41
Correct
-
A 55-years-old man presented to the emergency department complaining of a squeezing sensation in his chest that has spread to his neck with associated worsening shortness of breath. Which of these laboratory tests would you ask for in this patient:
Your Answer: Creatine kinase-MB
Explanation:Creatine kinase-MB is a test that usually is ordered when the patient has chest pain as a cardiac marker. When a heart attack is suspected and a troponin test (which is more specific for heart damage), is not available CK-MB is ordered. There are 3 forms of CK: CK-MM, CK-BB and CK-MB. CK-MB is commonly found in heart tissue, therefore injured heart muscle cells release CK-MB into the blood. Elevated CK-MB levels indicate that it is probable that a person has recently had a heart attack.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 42
Correct
-
A 20 year old is brought to the A&E after he fell from a moving cart. The boy has sustained blunt abdominal injury, and the there is a possibility of internal bleeding as the boy is in shock. An urgent exploratory laparotomy is done in the A&E theatre. On opening the peritoneal cavity, the operating surgeon notices a torn gastrosplenic ligament with a large clot around the spleen. Which artery is most likely to have been injured in this case?
Your Answer: Short gastric
Explanation:The short gastric arteries branch from the splenic artery near the splenic hilum to travel back in the gastrosplenic ligament to supply the fundus of the stomach. Therefore, these may be injured in this case.
The splenic artery courses deep to the stomach to reach the hilum of the spleen. It doesn’t travel in the gastrosplenic ligament although it does give off branches that do.
The middle colic artery is a branch of the superior mesenteric artery that supplies the transverse colon.
Gastroepiploic artery is the largest branch of the splenic artery that courses between the layers of the greater omentum to anastomose with the right gastroepiploic.
Left gastric artery, a branch of the coeliac trunk. It supplies the left half of the lesser curvature. -
This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 43
Incorrect
-
A 20-year old college student was diagnosed with meningitis that had developed due to an acute cavernous sinus thrombosis from an ear infection. Which of the following superficial venous routes is the usual path that an infected blood clot takes to reach the cavernous sinus?
Your Answer: Retromandibular vein
Correct Answer: Facial vein
Explanation:The facial vein is the usual communication between the cavernous sinus and the pterygoid sinus. It is through this vein that an infected clot can travel to the cavernous sinus and cause infection. The pterygoid plexus is a venous plexus that is situated between the temporalis muscle and lateral pterygoid muscle, and partly between the two pterygoid muscles. The pterygoid plexus is connected to the facial vein by the deep facial vein. This connection is what makes this area where this sinus and the facial vein are located a danger zone. The danger zone or triangle of the face is the area from the corners of the mouth to the nose bridge. The sinus connection in this area makes it possible for infection to reach the cavernous sinus and at times cause meningitis.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 44
Incorrect
-
A 39-year-old man, after radiological evaluation and thoracentesis, was found to have chylothorax. What is the most probable cause of this diagnose?
Your Answer: Amyloidosis
Correct Answer: Mediastinal malignant lymphoma
Explanation:Chylothorax is a potentially lethal condition characterized by fluid (chyle) accumulation in the pleural cavity, resulting from disruption of lymphatic drainage in the thoracic duct. Chyle is a fluid rich in triglycerides and chylomicrons and can originate from the thorax, the abdomen or both. Malignant tumours, especially lymphoma, are the most common causes of nontraumatic chylothorax. Bronchogenic carcinoma and trauma are the most common causes after lymphomas. Other rare causes of chylothorax are; granulomatous diseases, tuberculosis, congenital malformations, nephrotic syndrome, hypothyroidism, cirrhosis, decompensated heart failure and idiopathic chylothorax.
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This question is part of the following fields:
- Basic Sciences
- Pathology
-
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Question 45
Correct
-
A 21 year old lady notices a non-tender, mobile breast lump while doing her breast self-examination. The lump is smooth and not tethered to her skin. What is the diagnosis?
Your Answer: Fibroadenoma
Explanation:Answer: Fibroadenoma
A fibroadenoma is a painless, unilateral, benign (non-cancerous) breast tumour that is a solid, not fluid-filled, lump. It occurs most commonly in women between the age of 14 to 35 years but can be found at any age. Fibroadenomas shrink after menopause, and therefore, are less common in post-menopausal women. Fibroadenomas are often referred to as a breast mouse due to their high mobility. Fibroadenomas are a marble-like mass comprising both epithelial and stromal tissues located under the skin of the breast. These firm, rubbery masses with regular borders are often variable in size.
Fibroadenoma tends to occur in early age. It is most commonly found in adolescents and less commonly found in postmenopausal women. The incidence of fibroadenoma decreases with increasing age and generally found before 30 years of age in females in the general population. It is estimated that 10% of the world’s female population suffers from fibroadenoma once in a lifetime.
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This question is part of the following fields:
- Breast And Endocrine Surgery
- Generic Surgical Topics
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Question 46
Incorrect
-
Calculate the cardiac stroke volume of a patient whose oxygen consumption (measured by analysis of mixed expired gas) is 300 ml/min, arterial O2 content is 20 ml/100 ml blood, pulmonary arterial O2 content is 15 ml/100 ml blood and heart rate is 60/min.
Your Answer: 50 ml
Correct Answer: 100 ml
Explanation:By Fick’s principle, VO2 = Q × (CA (O2) − CV (O2)) where VO2 = O2 consumption, Q = cardiac output and CA(O2) and CV(O2) are arterial and mixed venous O2 content respectively. Thus, in the given problem, 300 ml O2/min = Q × (20−15) ml O2/100 ml. Thus, Q = 6000 ml blood/min. Then, we can calculate stroke volume by dividing the cardiac output with heart rate. Thus, stroke volume = 6000 ml/min divided by 60/min stroke volume = 100 ml.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 47
Correct
-
Which organs would cause pain in a patient who complains of dull pain in her pelvis, along the midline starting from the pubic bone in the front to the sacrum at the back?
Your Answer: Urinary bladder, uterus/cervix/vagina, rectum
Explanation:The pain could have been caused by the urinary bladder, uterus/cervix/vagina or rectum as it involves the pelvic viscera.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 48
Incorrect
-
A man had noticed weakness in his left arm causing flexion of the elbow and supination of the forearm. Which nerve in this case was injured?
Your Answer: Radial
Correct Answer: Musculocutaneous
Explanation:The musculocutaneous nerve supplies the biceps brachii and the brachialis muscles. The first one flexes the elbow and the shoulder. It is also involved in supination. The brachialis muscle flexes the forearm. The injury to the musculocutaneous nerve results in paralysis of these muscles.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 49
Correct
-
A 50 year old lawyer is admitted to the medical ward for an endarterectomy. His CT report confirms a left temporal lobe infarct. Which visual defect is most likely to be encountered?
Your Answer: Right superior quadranopia
Explanation:Quadrantanopia refers to an anopia affecting a quarter of the field of vision. While quadrantanopia can be caused by lesions in the temporal and parietal lobes, it is most commonly associated with lesions in the occipital lobe.
A lesion affecting one side of the temporal lobe may cause damage to the inferior optic radiations (known as the temporal pathway or Meyer’s loop) which can lead to superior quadrantanopia on the contralateral side of both eyes (colloquially referred to as pie in the sky).Therefore, a left temporal lobe infarct will affect the right superior quadrantanopia.
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This question is part of the following fields:
- Generic Surgical Topics
- Surgical Disorders Of The Brain
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Question 50
Correct
-
A diabetic 58-year-old man, after the injection of radiographic contrast, has a decreased urine output and decreased level of consciousness. Which of the following conditions has he most likely developed
Your Answer: Acute tubular necrosis
Explanation:Acute tubular necrosis (ATN) involves damage to the tubule cells of the kidneys and is the most common cause of acute kidney injury. ATN in the majority of the cases is caused by ischaemia of the kidneys due to lack of perfusion and oxygenation but it may also occur due to poison or harmful substance. Contrast used for radiology may cause ATN in patients with several risk factors e.g. diabetic nephropathy. Symptoms may include oliguria, nausea, fluid retention, fatigue and decreased consciousness.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 51
Correct
-
A 17 year old girl presents with enlarged tonsils that meet in the midline. Examination confirms the finding and petechial haemorrhages affecting the oropharynx are observed. Splenomegaly is seen on systemic examination. Which of the following is the most likely cause?
Your Answer: Infection with Epstein Barr virus
Explanation:Answer: Acute Epstein Barr virus infection
The Epstein–Barr virus is one of eight known human herpesvirus types in the herpes family, and is one of the most common viruses in humans. Infection with Epstein-Barr virus (EBV) is common and usually occurs in childhood or early adulthood.
EBV is the cause of infectious mononucleosis, an illness associated with symptoms and signs like:
fever,
fatigue,
swollen tonsils,
headache, and
sweats,
sore throat,
swollen lymph nodes in the neck, and
sometimes an enlarged spleen.
Although EBV can cause mononucleosis, not everyone infected with the virus will get mononucleosis. White blood cells called B cells are the primary targets of EBV infection.
Petechiae on the palate are characteristic of streptococcal pharyngitis but also can be seen in Epstein–Barr virus infection, Arcanobacterium haemolyticum pharyngitis, rubella, roseola, viral haemorrhagic fevers, thrombocytopenia, and palatal trauma. -
This question is part of the following fields:
- Generic Surgical Topics
- Head And Neck Surgery
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Question 52
Correct
-
A 40-year-old woman is suspected to have an ovarian cancer. Which tumour marker should be requested to confirm the diagnosis?
Your Answer: CA-125
Explanation:CA-125 is a protein that is used as a tumour marker. This substance is found in high concentration in patients with ovarian cancer. It is the only tumour marker recommended for clinical use in the diagnosis and management of ovarian cancer.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 53
Incorrect
-
If a catheter is placed in the main pulmonary artery of a healthy 30-year-old woman, which of the following will be its mean pulmonary arterial pressure?
Your Answer: 10 mmHg
Correct Answer: 15 mmHg
Explanation:The pulmonary artery pressure (PA pressure) is a measure of the blood pressure found in the main pulmonary artery. The hydrostatic pressure of the pulmonary circulation refers to the actual pressure inside pulmonary vessels relative to atmospheric pressure. Hydrostatic (blood pressure) in the pulmonary vascular bed is low compared with that of similar systemic vessels. The mean pulmonary arterial pressure is about 15 mmHg (ranging from about 13 to 19 mmHg) and is much lower than the average systemic arterial pressure of 90 mmHg.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 54
Incorrect
-
A 35 year old man presents with venous varicosities which are suspected to have resulted due to Klippel-Trenaunay syndrome. Which of the following would not be associated with this condition?
Your Answer: Arteriovenous fistulae
Correct Answer: Long saphenous vein involvement
Explanation:Klippel-Trenaunay syndrome is a condition that affects the development of blood vessels, soft tissues (such as skin and muscles), and bones. The disorder has three characteristic features: a red birthmark called a port-wine stain, abnormal overgrowth of soft tissues and bones, and vein malformations.
Most people with Klippel-Trenaunay syndrome are born with a port-wine stain. This type of birthmark is caused by swelling of small blood vessels near the surface of the skin. Port-wine stains are typically flat and can vary from pale pink to deep maroon in colour.
Klippel-Trenaunay syndrome is also associated with overgrowth of bones and soft tissues beginning in infancy. Usually this abnormal growth is limited to one limb, most often one leg. However, overgrowth can also affect the arms or, rarely, the torso.
Malformations of veins are the third major feature of Klippel-Trenaunay syndrome. These abnormalities include varicose veins and deep veins in the limbs. Malformations of deep veins increase the risk of a deep vein thrombosis (DVT).
Other complications of Klippel-Trenaunay syndrome can include cellulitis, lymphedema, and internal bleeding from abnormal blood vessels. Less commonly, this condition is also associated with fusion of certain fingers or toes (syndactyly) or the presence of extra digits (polydactyly).
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This question is part of the following fields:
- Generic Surgical Topics
- Vascular
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Question 55
Correct
-
A 49 year old man is admitted with small bowel obstruction after having repeated episodes of abdominal pain. A laparotomy is performed and during surgery, a gallstone ileus is identified. Which of the following is the best course of action?
Your Answer: Remove the gallstone via a proximally sited terminal ileal enterotomy and decompress the small bowel. Leave the gallbladder in situ.
Explanation:Gallstone ileus accounts for 1-4% of all small bowel obstructions, predominantly affecting elderly females. This entity is associated with a mortality approaching 20% due to the associated comorbidities that are often present.
Principles of treatment include stone removal via enterotomy through a site proximal to that of the obstruction.
Decompression using a sucking apparatus with many large openings, inserted through an enterotomy, is a fast and suitable method. The danger of wound infection can be considerably reduced by careful technique and by antibiotics. Nevertheless, open suction should be used only when the peritoneal cavity is already infected, or when closed decompression by retrograde stripping into the stomach is not possible. -
This question is part of the following fields:
- Generic Surgical Topics
- Hepatobiliary And Pancreatic Surgery
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Question 56
Incorrect
-
A 38-year-old man presents to the A&E department after sustaining a single gunshot wound to his left thigh. He complains of paraesthesia in his left foot. On examination, he is noted to have a large haematoma on the medial aspect of his left thigh. There are weak palpable pulses distal to the injury, and the patient is unable to move his foot. What should be the most appropriate initial management of this patient?
Your Answer: Fasciotomy of the anterior compartment
Correct Answer: Immediate exploration and repair
Explanation:The classic presentation of arterial injury include the five Ps: pallor, pain, paraesthesia, paralysis, and pulselessness. In the extremities, the tissues most sensitive to anoxia are the peripheral nerves and striated muscles. Early development of paraesthesia and paralysis indicates that there is significant ischaemia present, and therefore, immediate exploration and repair are warranted. Presence of a palpable pulse does not exclude an arterial injury because this may represent a transmitted pulsation through a blood clot.
When severe ischaemia is present, the repair must be completed within six to eight hours to prevent irreversible muscle ischaemia and loss of limb function. Delay to obtain a conventional angiogram or to observe for change needlessly prolongs the ischaemic time. Fasciotomy may be required but should be done in conjunction with and after re-establishment of arterial flow. Local wound exploration is not recommended because brisk haemorrhage may be encountered without prior securing of vascular control.
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This question is part of the following fields:
- Emergency Medicine And Management Of Trauma
- Principles Of Surgery-in-General
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Question 57
Correct
-
A young lady is rushed to the A&E department after being stabbed on her way home. She coughs up blood and a drain is placed into the left chest which removes 750ml of frank blood. She fails to improve and has been given 4 units of blood. Her CVP is now 13. What is the best course of action?
Your Answer: Thoracotomy in theatre
Explanation:Answer: Thoracotomy in theatre
A high CVP of 13 indicates cardiac tamponade. Cardiac tamponade is a clinical syndrome caused by the accumulation of fluid in the pericardial space, resulting in reduced ventricular filling and subsequent hemodynamic compromise. The condition is a medical emergency, the complications of which include pulmonary oedema, shock, and death.
A pericardiotomy via a thoracotomy is mandatory for lifesaving cardiac decompression in acute traumatic cardiac tamponade in cases of ineffective drainage due to clot formation within the pericardial space. Wherever possible a patient needing surgery for penetrating chest trauma should be moved to an operating theatre where optimal surgical expertise and facilities are available. -
This question is part of the following fields:
- Emergency Medicine And Management Of Trauma
- Principles Of Surgery-in-General
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Question 58
Correct
-
A 35 year old IV drug abuser arrives at the clinic with localized spinal pain. It is worse on movement and has been occurring for the last 2 months. The pain is refractory to analgesic treatment and is felt excruciatingly at rest too. He has no history of tuberculosis. Which of the following is the most likely diagnosis?
Your Answer: Osteomyelitis
Explanation:Complications of intravenous drug abuse, such as subcutaneous abscess, joint infections, osteomyelitis, overdose, hepatitis, and infective endocarditis, account for an increasing number of admissions in accident and emergency departments throughout the UK. The organisms that usually cause chronic osteomyelitis in intravenous drug users are Gram‐negative rods such as Pseudomonas aeruginosa and Gram‐positive cocci such as staphylococci. Early treatment is essential to prevent progressive bone destruction. TB tends to affect the thoracic spine and in other causes of osteomyelitis the lumbar spine is affected.
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This question is part of the following fields:
- Generic Surgical Topics
- Orthopaedics
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Question 59
Correct
-
After having donated a unit of blood. The blood bank will prefer to use which of the following anticoagulants to store the blood?
Your Answer: Citrate
Explanation:Calcium is necessary for coagulation to occur. Citrate being a chelator and combining with calcium ions to form un-ionised compound will prevent coagulation. Following transfusion the citrate is removed by the liver with in a few minutes. Oxalate also works on the same principle but it is toxic to the body.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 60
Correct
-
The primary area involved in the pathology of Parkinson's disease is:
Your Answer: Substantia nigra
Explanation:Parkinson’s disease is a degenerative, movement disorder of the central nervous system, and is typically characterized by muscle rigidity, tremor and bradykinesia (in extreme cases, akinesia). Secondary symptoms include high-level cognitive dysfunction and subtle language problems.
Parkinson’s disease is also called ‘primary Parkinsonism’ or ‘idiopathic Parkinson’s disease and is the most common cause of Parkinsonism, a group of similar symptoms. The disorder is caused due to loss of pigmented dopaminergic cells in the pars compacta region of the substantia nigra. -
This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 61
Incorrect
-
A 57 year old woman arrives at the clinic due to a pathological fracture of the proximal femur. Which of the following primary sites is the most likely source of her disease?
Your Answer: Thyroid
Correct Answer: Breast
Explanation:Breast cancer frequently metastasizes to the skeleton, interrupting the normal bone remodelling process and causing bone degradation. Breast cancer is the commonest cause of lytic bone metastasis in women of this age, especially from amongst those options given.
Osteolytic lesions are the end result of osteoclast activity; however, osteoclast differentiation and activation are mediated by osteoblast production of RANKL (receptor activator for NFκB ligand) and several osteoclastogenic cytokines. Osteoblasts themselves are negatively affected by cancer cells as evidenced by an increase in apoptosis and a decrease in proteins required for new bone formation. Thus, bone loss is due to both increased activation of osteoclasts and suppression of osteoblasts. The clinical outcomes of bone pain, pathologic fractures, nerve compression syndrome, and metabolic disturbances leading to hypercalcemia and acid/base imbalance severely reduce the quality of life.
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This question is part of the following fields:
- Oncology
- Principles Of Surgery-in-General
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Question 62
Correct
-
A 31 year old woman presents to the clinic for assessment of varicose veins that she developed several years ago. Examination reveals marked truncal varicosities with a long tortuous saphenous vein. Which of the following would be the next most appropriate step in her management?
Your Answer: Arrange a venous duplex scan
Explanation:Deep vein thrombosis (DVT) is the formation of a blood clot in a deep vein of the legs, thigh, or pelvis. Thrombosis is most often seen in individuals with a history of immobilization, obesity, malignancy, or hereditary thrombophilia. Vascular endothelial damage, venous stasis, and hypercoagulability, collectively referred to as the Virchow triad, are the main factors contributing to the development of DVT.
Symptoms usually occur unilaterally and include swelling, tenderness, and redness or discoloration. Pulmonary embolism (PE), a severe complication of DVT, should be suspected in patients with dizziness, dyspnoea, and fever. The diagnostic test of choice for DVT is compression ultrasound. In most cases, a negative D-dimer test allows thrombosis or PE to be ruled out, but a positive test is nonspecific.
Initial acute treatment of DVT consists of anticoagulation with heparin and, if the thrombus is large or unresponsive to anticoagulation, may also include thrombolysis or thrombectomy. Secondary prophylaxis is achieved with oral warfarin or direct factor Xa inhibitors and supportive measures such as regular exercise and compression stockings. -
This question is part of the following fields:
- Generic Surgical Topics
- Vascular
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Question 63
Correct
-
A 46-year old lady presents with chief complaints of a large mass in the left breast. Histopathology of the mass revealed a stromal component with an epithelial component. What is the likely lesion?
Your Answer: Phyllodes tumour
Explanation:Phyllodes tumours are large, quickly growing tumours which arise from the periductal stroma of the breast. These are fibroepithelial tumours and account for less than 1% of breast cancers. These tumours can be benign, borderline or malignant based on the histology. The tumour usually affects adult women, mostly between the age of 40 to 50 years. It can be confused with fibroadenoma, which however affects much younger patients.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 64
Incorrect
-
The dilator pupillae muscle is innervated by postganglionic sympathetic fibres. Where do the postganglionic sympathetic fibres originate?
Your Answer: Ciliary ganglion
Correct Answer: Superior cervical ganglion
Explanation:The postganglionic sympathetic axons are derived from the superior cervical ganglion and innervate the eye and lacrimal gland allowing for vasoconstriction of the iris and sclera, pupillary dilation, widening of the palpebral fissure, and a reduction in tear production.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 65
Incorrect
-
A 60 year old patient with a history of carcinoma of the head of the pancreas, and obstructive jaundice presents with a spontaneous nose bleed and easy bruising. What is the most likely reason for this?
Your Answer: Vitamin B6 deficiency
Correct Answer: Vitamin-K-dependent clotting factors deficiency
Explanation:Vitamin K is a fat soluble vitamin requiring fat metabolism to function properly to allow for its absorption. People with obstructive jaundice develop vitamin k deficiency as fat digestion is impaired. Vit K causes carboxylation of glutamate residue and hence regulates blood coagulation including: prothrombin (factor II), factors VII, IX, X, protein C, protein S and protein Z.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 66
Correct
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A 58 year old lady who has had a mastectomy undergoes a breast reconstruction surgery. The breast implant is placed just anterior to her pectoralis major muscle. Which of the following methods of wound closure would be the most appropriate in this case?
Your Answer: Use of a pedicled myocutaneous flap
Explanation:The latissimus dorsi myocutaneous flap (LDMF) is one of the most reliable and versatile flaps used in reconstructive surgery. It is known for its use in chest wall and postmastectomy reconstruction and has also been used effectively for coverage of large soft tissue defects in the head and neck, either as a pedicled flap or as a microvascular free flap.
The latissimus dorsi may be transferred as a myofascial flap, a myocutaneous flap, or as a composite osteomyocutaneous flap when harvested with underlying serratus anterior muscle and rib. For even greater reconstructive flexibility, the latissimus can be harvested for free tissue transfer in combination with any or all of the other flaps based on the subscapular vessels (the so-called subscapular compound flap or “mega-flap”), including serratus anterior, scapular, and parascapular flaps
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This question is part of the following fields:
- Emergency Medicine And Management Of Trauma
- Principles Of Surgery-in-General
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Question 67
Correct
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On exploration of an axillary wound, a branch from the third part of the axillary artery was found to be transected. Which of the following arteries would have been likely injured?
Your Answer: Anterior humeral circumflex
Explanation:The axillary artery gives off many branches from the first, second, or third parts along its course. The third part of the axillary artery gives off two branches: the anterior humeral circumflex artery and the posterior humeral circumflex artery.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 68
Incorrect
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A 40-year-old chef presents to the hospital with profuse bloody diarrhoea. He also complains of frequent urge to defecate and pain before and during defecation. A sigmoidoscopy is arranged which reveals necrosis and ulceration of the descending colon mucosa. What is the most likely underlying cause?
Your Answer: Infection with enterohaemorrhagic E. coli
Correct Answer: Infection with enteroinvasive E. coli
Explanation:Necrosis and ulcers of the colon are a feature of infection with enteroinvasive E. coli (EIEC). It presents with a dysentery-type illness similar to shigellosis.
E. coli have different strains that cause a wide range of conditions. The four main types are:
1. Enteropathogenic E. coli—cause watery diarrhoea, vomiting, and low-grade fever
2. Enteroinvasive E. coli—cause dysentery, large bowel necrosis, and ulcers
3. Enterotoxigenic E. coli—cause traveller’s diarrhoea
4. Enterohaemorrhagic E. coli 0157:H7—cause haemorrhagic colitis, haemolytic uremic syndrome, and thrombotic thrombocytopenic purpura
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This question is part of the following fields:
- Clinical Microbiology
- Principles Of Surgery-in-General
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Question 69
Correct
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Which of the following muscles aid in inspiration?
Your Answer: Diaphragm and external intercostals
Explanation:The diaphragm and external intercostals are muscles of inspiration as they increase the volume of thoracic cavity and reduce the intrathoracic pressure. Muscles of expiration include abdominal muscles and internal intercostals.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 70
Correct
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A 25 year old primi gravida lady was scheduled for a regular antenatal check up. During the vaginal exam of this lady, the registrar discovered a malignant growth on the anterior wall of her vagina. Which of the following structures, adjacent to the vagina, is likely to be involved as well?
Your Answer: Fundus of the bladder
Explanation:The fundus of the bladder is related anatomically to the anterior surface of the vagina and the urethra as well. If there was a malignant growth in the anterior surface of the vagina, then most likely the fundus of the bladder would be involved as well aspotentially the urethra.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 71
Correct
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The anatomical course of the phrenic nerve passes over the following muscle in the neck?
Your Answer: Anterior scalene
Explanation:The phrenic nerve originates in the neck between C3-C5, mostly C4 spinal root. It enters the thoracic cavity past the heart and lungs to the diaphragm. In the neck, this nerve begins at the lateral border of the anterior scalene muscle, its course then continues inferiorly on the anterior aspect of the anterior scalene muscle as it moves towards the diaphragm.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 72
Incorrect
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Which muscle is responsible for directing the gaze downward when the eye is abducted?
Your Answer: Inferior oblique muscle
Correct Answer: Inferior rectus muscle
Explanation:The inferior rectus muscle is a muscle in the orbit. As with most of the muscles of the orbit, it is innervated by the inferior division of oculomotor nerve (Cranial Nerve III). It depresses, adducts, and helps laterally rotate the eye.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 73
Correct
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A 34 year old man is suffering from septic shock and receives an infusion of Dextran 70. Which of the following complications may potentially ensue?
Your Answer: Anaphylaxis
Explanation:Dextran 40 and 70 have a higher rate of causing anaphylaxis than either gelatins or starches.
Dextrans are branched polysaccharide molecules, with dextran 40 and 70 available. The high-molecular-weight dextran 70 may persist for up to eight hours. They inhibit platelet aggregation and leucocyte plugging in the microcirculation, thereby, improving flow through the microcirculation. They are primarily used in sepsis.
Unlike many other intravenous fluids, dextrans are a recognised cause of anaphylaxis. -
This question is part of the following fields:
- Peri-operative Care
- Principles Of Surgery-in-General
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Question 74
Correct
-
Gram positive bacteria differ from gram negative bacteria due to the presence of which of the following structures?
Your Answer: Outer membrane
Explanation:The reason bacteria are either Gram-positive or Gram-negative is due to the structure of their cell envelope (the cell envelope is defined as the cell membrane and cell wall plus an outer membrane, if one is present.) Gram-positive bacteria, for example, retain the crystal violet due to the amount of peptidoglycan in the cell wall. It can be said therefore that the Gram-stain procedure separates bacteria into two broad categories based on structural differences in the cell envelope.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 75
Incorrect
-
Which of the following has the least malignant potential?
Your Answer: Villous adenoma
Correct Answer: Hyperplastic polyp
Explanation:Non-neoplastic (non-adenomatous) colonic polyps include hyperplastic polyps, hamartomas, juvenile polyps, pseudopolyps, lipomas, leiomyomas and others.
An autosomal dominant condition, Peutz–Jeghers syndrome is a disease that is characterized by multiple hamartomatous polyps in the stomach, small bowel and colon. Symptoms of this syndrome include hyperpigmentation of the skin and mucous membranes, especially of the lips and gums.
Juvenile polyps develop in children, and once they outgrow their blood supply, they autoamputate around puberty. In cases of uncontrolled bleeding or intussusception, treatment is needed.
Inflammatory polyps and pseudopolyps occur in chronic ulcerative colitis and Crohn’s disease. There is an increased risk of cancer with multiple juvenile polyps (not with sporadic polyps). -
This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 76
Incorrect
-
Destruction of the ventromedial nucleus of the hypothalamus will result in:
Your Answer: Loss of circadian rhythm
Correct Answer: Loss of satiety
Explanation:The ventromedial nucleus of the hypothalamus is divided into an anterior and a superior part. The anterior part controls the female sexual drive, whereas the superior part is responsible for satiety. Destruction of the superior part of the nucleus will result in overeating, as no signal tells the body that it is satisfied.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 77
Correct
-
A 43-year-old male with no significant medical history is currently being kept nil-by-mouth for an elective bilateral inguinal hernia repair. Which of the following describes the best fluid regimen for this patient over the following 24 hours?
Your Answer: 1 L normal saline with 20 mmol potassium and 2 L 5% dextrose with 20 mmol potassium in each bag
Explanation:If patients need IV fluids for routine maintenance alone, restrict the initial prescription to:
25–30 ml/kg/day of water and
approximately 1 mmol/kg/day of potassium, sodium and chloride and
approximately 50–100 g/day of glucose to limit starvation ketosis.
Weight-based potassium prescriptions should be rounded to the nearest common fluids available (for example, a 67 kg person should have fluids containing 20 mmol and 40 mmol of potassium in 24 hours). Potassium should not be added to intravenous fluid bags as this is dangerous.Sodium chloride 0.9%, with or without additional potassium, is one of the most commonly used IV fluids in UK practice.
Glucose 5% solution provides a useful means of giving free water for, once the glucose is metabolised, the fluid is distributed throughout total body water. It is, therefore, a potentially useful means of correcting or preventing simple dehydration and the glucose content will also help to prevent starvation ketosis, although it is important to recognize that it will not make much of a contribution to covering patients overall nutritional needs. The use of 5% glucose, will increase risks of significant hyponatraemia, particularly in children, the elderly, patients on diuretics and those with excess ADH due to osmotic and non-osmotic stimuli (a problem is seen quite frequently in hospitalized patients). Nevertheless, hyponatremia is likely to be avoided by not exceeding recommended volumes of maintenance IV fluids and by careful monitoring of patients’ clinical volume status and electrolyte measurements.
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This question is part of the following fields:
- Peri-operative Care
- Principles Of Surgery-in-General
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Question 78
Incorrect
-
Investigations in a 40-year old gentleman with splenomegaly reveal the following: haemoglobin 21.5 g/dl, haematocrit 66%, mean corpuscular volume (MCV) 86 fl, mean cell haemoglobin concentration 34 g/dl, mean corpuscular haemoglobin 34.5 pg, platelet count 450 × 109/l, and white blood cell count 12 × 109/l, with 81% polymorphonuclear leukocytes, 4% bands, 3% monocytes, and 7% lymphocytes. What is the likely diagnosis?
Your Answer: Chronic myelogenous leukaemia
Correct Answer: Polycythaemia vera
Explanation:The markedly increased haematocrit, along with thrombocytosis and the leucocytosis suggest a myeloproliferative disorder.
Polycythaemia vera is the commonest myeloproliferative disorders occurring more often in males (about 1.4 to 1). The mean age at diagnosis is 60 years (range 15–90 years) with 5% of patients below 40 years at onset. It involves increased production of all cell lines, including red blood cells (independent of erythropoietin), white blood cells and platelets. If confined only to red blood cells, it is known as ‘primary erythrocytosis’. There is an increase in blood volume and hyperviscosity occurs, predisposing to thrombosis. Increased bleeding occurs due to abnormal functioning of platelets. Patients become hypermetabolic, and increased cell turnover leads to hyperuricaemia.
Usually asymptomatic, occasionally symptoms include weakness, pruritus, headache, light-headedness, visual disturbances, fatigue and dyspnoea. Face appears red with engorged retinal veins. Lower extremities appear red and painful, along with digital ischaemia (erythromelalgia). Hepatomegaly is common and massive splenomegaly is seen in 75% patients. Thrombosis can lead to stroke, deep venous thrombosis, myocardial infarction, retinal artery or vein occlusion, splenic infarction (often with a friction rub) or Budd–Chiari syndrome. Gastrointestinal bleeding is seen in 10-20% patients. Hypermetabolism can lead to low-grade fevers and weight loss. Late features include complications of hyperuricaemia (e.g. gout, renal calculi). 1.5% to 10% cases transform to acute leukaemia. -
This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 79
Incorrect
-
During an anatomy revision session, medical students are told that the posterior wall of the rectus sheath ends in a thin curved margin whose concavity is directed downwards. What is the name of this inferior border of the rectus sheath?
Your Answer: Falx inguinalis
Correct Answer: Arcuate line
Explanation:The rectus sheath is a tendinous sheath that encloses the rectus abdominis muscle. It covers the entire anterior surface however on the posterior surface of the muscle the sheath is incomplete ending inferiorly at the arcuate line. Below the arcuate line, the rectus abdominis is covered by the transversalis fascia. The linea alba is a band of aponeurosis on the midline of the anterior abdominal wall, which extends from the xiphoid process to the pubic symphysis. It is formed by the combined abdominal muscle aponeuroses. This is a useful site for midline incision during abdominal surgery because it does not carry many blood vessels. All of the other answer choices are related to the inguinal canal.
The falx inguinalis (sometimes called the inguinal falx or conjoint tendon), is the inferomedial attachment of the transversus abdominis with some fibres of the internal abdominal oblique – it contributes to the posterior wall of the inguinal canal.
The inguinal ligament is the ligament that connects the anterior superior iliac spine with the pubic tubercle – it makes the floor of the inguinal canal.
The internal (deep) inguinal ring is the entrance to the inguinal canal, where the transversalis fascia pouches out and creates an opening through which structures can leave the abdominal cavity. -
This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 80
Correct
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A gymnast was admitted to hospital for investigation of a weakness in the extension and adduction of his arm. He had a previous penetrating wound in the area of the posterior axillary fold. Which of these muscles is the likely cause?
Your Answer: Latissimus dorsi
Explanation:All the criteria of this case points towards the latissimus dorsi. This muscle is greatly involved in extension, adduction and medial rotation of the arm and forms the posterior axillary fold which in this case was injured.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 81
Correct
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A 55-year-old woman complains of pain in the proximal and distal interphalangeal joins, and back pain which has increased over the last 4 years and worsens after activity. X-rays reveal Heberden’s and Bouchard’s nodes in her interphalangeal joints and the presence of osteophytes in her spine. What is the most likely diagnosis?
Your Answer: Osteoarthritis
Explanation:Osteoarthritis is most common in older adults, predominating in women between the ages of 40 and 70; after this age, men and women are affected equally. It affects an entire joint, with disruption and potential loss of joint cartilage, along with other joint changes, including bone hypertrophy (osteophyte formation). The pain is usually gradual and is worse after activity, with occasional joint swelling. X-ray findings include marginal osteophytes, narrowing of the joint space, increased density of the subchondral bone, subchondral cyst formation, bony remodelling and joint effusions.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 82
Correct
-
A 22-year-old man undergoes incision and drainage of an axillary abscess. How should the wound be managed?
Your Answer: Packing with alginate dressing
Explanation:The wound of this patient should be packed with alginate dressing. Abscess wounds should not undergo primary closure. Moreover, use of gauze is inappropriate and would be difficult to redress.
Alginate dressings are absorbent wound care products that contain sodium and calcium fibres derived from seaweed. An individual dressing is able to absorb up to 20 times its own weight. These dressings, which are easy to use, mold themselves to the shape of the wound, which helps ensure that they absorb wound drainage properly. In abscesses requiring incision and drainage, alginate dressings are well-tolerated and their removal causes minimal pain.
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This question is part of the following fields:
- Principles Of Surgery-in-General
- Surgical Technique And Technology
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Question 83
Correct
-
A biopsy taken from the respiratory passage of a 37 year old male, chronic smoker will mostly likely show which cellular adaptation?
Your Answer: Stratified squamous metaplasia
Explanation:Metaplasia is a change in the cell type caused in part due to an extrinsic stress on the organ. It involves a change in the surface epithelium from one cell type to the another, most commonly squamous to columnar. This is a reversible process, and removal of the stress should theoretically reverse the surface epithelium back to normal morphology. Respiratory tract metaplasia is a classic example, in which the normal pseudostratified columnar epithelium is replaced by stratified squamous epithelium to better cope with the stress. Under continuous stress metaplasia can progress to dysplasia which is a disordered growth of cells eventually leading to the development of carcinoma.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 84
Correct
-
Which of the following organs is most likely to have dendritic cells?
Your Answer: Skin
Explanation:Dendritic cells are part of the immune system and they function mainly as antigen presenting cells. They are present in small quantities in tissues which are in contact in the external environment. Mainly in the skin and to a lesser extent in the lining of the nose, lungs, stomach and intestines. In the skin they are known as Langerhans cells.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 85
Incorrect
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A patient admitted for esophagectomy showed low levels of the lightest plasma protein in terms of weight. Which of the following is the lightest plasma protein:
Your Answer: Gamma-globulin
Correct Answer: Albumin
Explanation:Albumin is the most abundant and the lightest of all the plasma proteins. It maintains osmotic pressure, transports unconjugated bilirubin, thyroid hormones, fatty acids, drugs and acts as a buffer for pH.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 86
Incorrect
-
Which of the following can lead to haemolytic anaemia?
Your Answer: Intrinsic factor deficiency
Correct Answer: Presence of haemoglobin S
Explanation:Haemoglobin S is an abnormal type of haemoglobin seen in sickle cell anaemia. This allows for the haemoglobin to crystalize within the RBC upon exposure to low partial pressures of oxygen. This results in rupture of the RBCs as they pass through microcirculation, especially in the spleen. This can cause blockage of the vessel down stream and ischaemic death of tissues, accompanied by severe pain.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 87
Correct
-
Following a posterolateral thoracotomy, a surgeon may wish to infiltrate local anaesthetic above and below the incision to block the nerves supplying the thoracic wall. This wall is innervated by?
Your Answer: Intercostal nerves
Explanation:Intercostal nerves are the ventral primary rami of spinal nerves T1–T11. They give branches which supply the thoracic wall.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 88
Correct
-
A 46 year old man had an upper gastrointestinal endoscopy and biopsies done which were reported by two gastrointestinal pathologists as being ‘indefinite for dysplasia.’ Repeat endoscopy and biopsies were repeated 6 months after completing treatment with proton pump inhibitors. The results revealed no definite evidence of dysplasia. What is the most appropriate management?
Your Answer: Routine surveillance every 2–3 years
Explanation:This patient had endoscopy and biopsy done by different doctors and proton pump inhibitor therapy followed by repeat endoscopy and biopsy six months later which had no definite evidence of dysplasia.
British Society of Gastroenterology (BSG) guidelines state that for patients with Barrett’s oesophagus (BO) but without dysplasia, the recommended surveillance protocols are two yearly, four quadrant biopsies every 2 cm, but jumbo biopsies are not required.
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This question is part of the following fields:
- Generic Surgical Topics
- Upper Gastrointestinal Surgery
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Question 89
Incorrect
-
A 35 year old patient presenting with haematemesis, heart burn and bloody stool was diagnosed with a duodenal ulcer that had eroded the gastroduodenal artery. The patient was then rushed into theatre for an emergency procedure to control the haemorrhage. If the surgeon decided to ligate the gastroduodenal artery at its origin, which of the following arteries would most likely experience retrograde blood flow from collateral sources as a result of the ligation?
Your Answer: Left hepatic
Correct Answer: Right gastroepiploic
Explanation:In the stomach and around the duodenum, there are many arterial anastomoses. Ligation of the gastroduodenal artery would result in the retrograde flow of blood from the left gastroepiploic artery to the right gastroepiploic artery. The blood flows into the right gastroepiploic artery, a branch of the gastroduodenal artery from the left gastroepiploic artery that branches from the splenic artery. This retrograde blood flow is aimed at providing alternate blood flow to the greater curvature of the stomach.
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This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 90
Correct
-
A patient in the intensive care unit developed hyperphosphatemia. The phosphate level is 160 mmol/L. Which of the following is most likely responsible for this abnormality?
Your Answer: Renal insufficiency
Explanation:Hyperphosphatemia is an electrolyte disturbance in which there is an abnormally elevated level of phosphate in the blood. It is caused by conditions that impair renal phosphate excretion (ex: renal insufficiency, hypoparathyroidism, parathyroid suppression) and conditions with massive extracellular fluid phosphate loads (ex: rapid administration of exogenous phosphate, extensive cellular injury or necrosis, transcellular phosphate shifts).
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 91
Correct
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Biopsy of a neoplastic mass was performed. Histologic examination of the specimen showed spindle shaped cells with high nuclear/cytoplasm ratio on immunohisto chemical staining. These pleomorphic cells were vimentin positive, cytokeratin negative and cd45 negative. This type of neoplasm is most commonly found in which patient?
Your Answer: A 15-year-old boy with a mass in the left femur and lung metastases
Explanation:A histology report that describes spindle shaped cells which are vimentin positive suggests osteosarcoma and hematogenous spread to the lungs.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 92
Correct
-
A 49-year-old man, smoker, complains of a persisting and worsening cough over the past few months. He also has noted blood in his sputum. The patient has no other major health conditions. Which of the following investigative procedures should be done first?
Your Answer: Sputum cytology
Explanation:Sputum cytology is a diagnostic test used for the examination of sputum under a microscope to determine if abnormal cells are present. It may be used as the first diagnostic procedure to help detect a suspected lung cancer or certain non-cancerous lung conditions.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 93
Incorrect
-
A young lady is taken to the A&E department after she falls from the 3rd floor balcony. A chest x-ray shows depression of the left main bronchus and deviation of the trachea to the right. What is the most likely injury that she sustained?
Your Answer: Tension pneumothorax
Correct Answer: Aortic rupture
Explanation:Answer: Aortic rupture
Aortic rupture is typically the result of a blunt aortic injury in the context of rapid deceleration. After traumatic brain injury, blunt aortic rupture is the second leading cause of death following blunt trauma. Thus, this condition is commonly fatal as blood in the aorta is under great pressure and can quickly escape the vessel through a tear, resulting in rapid haemorrhagic shock, exsanguination, and death. Traumatic aortic transection or rupture is associated with a sudden and rapid deceleration of the heart and the aorta within the thoracic cavity.
Features on plain chest radiography that suggest aortic injury and can help guide the further use of angiography include; an abnormal aortic arch contour, left apical cap, loss of the aorticopulmonary window, rightward deviation of the trachea, depression of the left main stem bronchus, and a wide left paravertebral pleural stripe. Also, widening of the mediastinum (greater than 8 cm) has a reported sensitivity of 81% to 100% and a specificity of 60%. -
This question is part of the following fields:
- Emergency Medicine And Management Of Trauma
- Principles Of Surgery-in-General
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Question 94
Correct
-
A 18-year old girl presents to her doctor with an excessively enlarged left breast as compared to the right breast since puberty. The most likely cause for this is:
Your Answer: Virginal breast hypertrophy
Explanation:Virginal breast hypertrophy’ is the term assigned to excessive growth of breasts during puberty and is a common phenomenon. It is also known as ‘juvenile macromastia’ or ‘ juvenile gigantomastia’. The breast hypertrophy often starts with menarche and occasionally occurs in growth spurts. These spurts can cause physical discomfort, red and itchy skin or pain in the breasts. The breasts can also grow continuously over several years and lead to overdevelopment of a normal breast. Nipples also undergo enlargement along with the breasts.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 95
Correct
-
Calculate the total peripheral resistance for a patient with a blood pressure of 130/70 mm HG and cardiac output of 5 litres / min?
Your Answer: 18 mmHg × min/l
Explanation:Total peripheral resistance = Mean arterial pressure/Cardiac output. And the mean arterial pressure = Diastolic pressure + 1/3 (Systolic pressure – Diastolic pressure), i.e., 70 + 1/3 (130-70) = 90 mmHg. Therefore, total peripheral resistance = 90 mmHg/5 l per min = 18 mmHg × min/l.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 96
Incorrect
-
A 13 month old baby was taken to the hospital after his father saw that he had periorbital oedema for two days. He is seen by the doctor and noted to have facial oedema and a tender distended abdomen. His temperature is 39.1 and his blood pressure is 91/46 mmHg. There is also clinical evidence of poor peripheral perfusion. What is the diagnosis?
Your Answer: Sickle cell crisis
Correct Answer: Spontaneous bacterial peritonitis
Explanation:Answer: Spontaneous bacterial peritonitis
The presence of periorbital and facial oedema with normal blood pressure in this toddler indicates that he has nephrotic syndrome. Nephrotic syndrome can be associated with a series of complications that can affect an individual’s health and quality of life:
Spontaneous bacterial peritonitis can develop where there is ascites present. This is a frequent development in children but very rarely found in adults.Spontaneous bacterial peritonitis (SBP) is the development of a bacterial infection in the peritoneum, despite the absence of an obvious source for the infection. It is specifically an infection of the ascitic fluid – an increased volume of peritoneal fluid. Ascites is most commonly a complication of cirrhosis of the liver. It can also occur in patients with nephrotic syndrome. SBP has a high mortality rate.
The diagnosis of SBP requires paracentesis, a sampling of the peritoneal fluid taken from the peritoneal cavity. If the fluid contains large numbers of white blood cells known as neutrophils (>250 cells/µL), infection is confirmed and antibiotics will be given, without waiting for culture results. In addition to antibiotics, infusions of albumin are usually administered.
Signs and symptoms of spontaneous bacterial peritonitis (SBP) include fevers, chills, nausea, vomiting, abdominal pain and tenderness, general malaise, altered mental status, and worsening ascites. Thirteen percent of patients have no signs or symptoms. In cases of acute or chronic liver failure SBP is one of the main triggers for hepatic encephalopathy, and where there is no other clear causal indication for this, SBP may be suspected.
These symptoms can also be the same for a spontaneous fungal peritonitis (SFP) and therefore make a differentiation difficult. Delay of diagnosis can delay antifungal treatment and lead to a higher mortality rate.
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This question is part of the following fields:
- Generic Surgical Topics
- The Abdomen
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Question 97
Incorrect
-
When the pitch of a sound increases, what is the physiological response seen in the listener?
Your Answer: The frequency of action potentials in auditory nerve fibres increases
Correct Answer: The location of maximal basilar membrane displacement moves toward the base of the cochlea
Explanation:An increase in the frequency of sound waves results in a change in the position of maximal displacement of the basilar membrane in the cochlea. Low pitch sound produces maximal displacement towards the cochlear apex and greatest activation of hair cells there. With an increasing pitch, the site of greatest displacement moves towards the cochlear base. However, increased amplitude of displacement, increase in the number of activated hair cells, increased frequency of discharge of units in the auditory nerve and increase in the range of frequencies to which such units respond, are all seen in increases in the intensity or a sound stimulus.
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This question is part of the following fields:
- Basic Sciences
- Physiology
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Question 98
Correct
-
During a clinical rotation in the ENT clinic, you observe a flexible bronchoscopy. As the scope is passed down the trachea, you see a cartilaginous structure that resembles a ship's keel and separates the right and the left main stem bronchi. This structure is the:
Your Answer: Carina
Explanation:The carina (a keel-like cartilage) is found at the bifurcation of the trachea separating the right from the left main stem bronchi. It is a little more to the left than to the right.
The cricoid cartilage is the inferior and posterior cartilage of the larynx.
The costal cartilage on the other hand elongates the ribs anteriorly and contribute to the elasticity of the thoracic cage.
The pulmonary ligament is a fold of pleura located below the root of the lung.
Tracheal rings are rings of cartilage that support the trachea.
Peritracheal fascia is a layer of connective tissue that invests the trachea from the outside and is not visible on bronchoscopy. -
This question is part of the following fields:
- Anatomy
- Basic Sciences
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Question 99
Correct
-
An 18 -year-old female is diagnosed with folliculitis in the left axilla. What is the most likely organism that could cause this condition?
Your Answer: Staphylococcus aureus
Explanation:Folliculitis is the inflammation of the hair follicles. It is usually caused by Staphylococcus infection.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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Question 100
Incorrect
-
Leukotrienes normally function during an asthma attack and work to sustain inflammation. Which of the following enzymes would inhibit their synthesis?
Your Answer: Cyclooxygenase-2
Correct Answer: 5-lipoxygenase
Explanation:Leukotrienes are produced from arachidonic acid with the help of the enzyme 5-lipoxygenase. This takes place in the eosinophils, mast cells, neutrophils, monocytes and basophils. They are eicosanoid lipid mediators and take part in allergic and asthmatic attacks. They are both autocrine as well as paracrine signalling molecules to regulate the body’s response and include: LTA4, LTB4, LTC4, LTD4, LTE4 and LTF4.
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This question is part of the following fields:
- Basic Sciences
- Pathology
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SESSION STATS - PERFORMANCE PER SPECIALTY
