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Question 1
Incorrect
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A health-conscious 45-year-old presents with an unexplained acute kidney injury (AKI) and a kidney biopsy reveals the presence of calcium oxalate crystals in the renal tubules. The patient's calcium levels are normal, oxalate levels are elevated, and vitamin D levels are within normal range. Which vitamin overdose could potentially account for this condition?
Your Answer: Vitamin E
Correct Answer: Vitamin C
Explanation:The deposition of calcium oxalate in the renal tubules indicates that the patient is experiencing oxalate nephropathy, which is commonly caused by an overdose of vitamin C. Therefore, the correct answer is vitamin C overdose. It should be noted that elevated calcium levels are associated with vitamin D overdose, which is not applicable in this case.
Understanding Oxalate Nephropathy
Oxalate nephropathy is a type of sudden kidney damage that occurs when calcium oxalate crystals accumulate in the renal tubules. This condition can be caused by various factors, including the ingestion of ethylene glycol or an overdose of vitamin C. When these crystals build up in the renal tubules, they can cause damage to the tubular epithelium, leading to kidney dysfunction.
To better understand oxalate nephropathy, it is important to note that the renal tubules are responsible for filtering waste products from the blood and excreting them in the urine. When calcium oxalate crystals accumulate in these tubules, they can disrupt this process and cause damage to the tubular epithelium. This can lead to a range of symptoms, including decreased urine output, swelling in the legs and feet, and fatigue.
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This question is part of the following fields:
- Renal System
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Question 2
Incorrect
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A 68-year-old male visits his doctor complaining of weight loss and difficulty breathing for the past 8 months. Upon physical examination, no abnormalities are found, but the doctor orders a chest x-ray.
The radiograph reveals: 'Central trachea. Bilateral hilar lymph nodes are visible, along with a lesion in the left middle zone. The mass measures approximately 5cm in diameter and has a center of caseation. No other clinical findings are present.'
What is the probable diagnosis for this patient?Your Answer: Mesothelioma
Correct Answer: Tuberculosis
Explanation:The presence of caseating granulomatous inflammation in the lungs is a clear indication of tuberculosis (TB). If a radiograph shows a caseating lesion in the middle zone, it should raise suspicion of TB. It is important to note that mesothelioma, Pancoast tumors, and renal cell carcinoma lung metastases have their own distinct radiographic features and are not associated with caseating granulomas. Sarcoidosis, on the other hand, is a condition characterized by non-caseating granulomas and is not related to TB.
Types of Tuberculosis
Tuberculosis (TB) is a disease caused by Mycobacterium tuberculosis that primarily affects the lungs. There are two types of TB: primary and secondary. Primary TB occurs when a non-immune host is exposed to the bacteria and develops a small lung lesion called a Ghon focus. This focus is made up of macrophages containing tubercles and is accompanied by hilar lymph nodes, forming a Ghon complex. In immunocompetent individuals, the lesion usually heals through fibrosis. However, those who are immunocompromised may develop disseminated disease, also known as miliary tuberculosis.
Secondary TB, also called post-primary TB, occurs when the initial infection becomes reactivated in an immunocompromised host. Reactivation typically occurs in the apex of the lungs and can spread locally or to other parts of the body. Factors that can cause immunocompromise include immunosuppressive drugs, HIV, and malnutrition. While the lungs are still the most common site for secondary TB, it can also affect other areas such as the central nervous system, vertebral bodies, cervical lymph nodes, renal system, and gastrointestinal tract. Tuberculous meningitis is the most serious complication of extra-pulmonary TB. Understanding the differences between primary and secondary TB is crucial in diagnosing and treating the disease.
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This question is part of the following fields:
- General Principles
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Question 3
Incorrect
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A 50-year-old man comes to surgical outpatients complaining of recurrent abdominal pain and vomiting. During examination, a peripheral motor neuropathy is observed. What is the probable diagnosis?
Your Answer: Huntington's disease
Correct Answer: Acute intermittent porphyria
Explanation:Unless proven otherwise, the presence of neurological symptoms along with abdominal pain may indicate either acute intermittent porphyria or lead poisoning.
Understanding Acute Intermittent Porphyria
Acute intermittent porphyria (AIP) is a rare genetic disorder that affects the biosynthesis of haem due to a defect in the porphobilinogen deaminase enzyme. This results in the accumulation of delta aminolaevulinic acid and porphobilinogen, leading to a range of symptoms. AIP typically presents in individuals aged 20-40 years, with females being more commonly affected.
The condition is characterized by a combination of abdominal, neurological, and psychiatric symptoms. Abdominal symptoms include pain and vomiting, while neurological symptoms may manifest as motor neuropathy. Psychiatric symptoms may include depression. Hypertension and tachycardia are also common.
Diagnosis of AIP involves a range of tests, including urine analysis, assay of red cells for porphobilinogen deaminase, and measurement of serum levels of delta aminolaevulinic acid and porphobilinogen. A classic sign of AIP is the deep red color of urine on standing.
Management of AIP involves avoiding triggers and treating acute attacks with IV haematin/haem arginate. In cases where these treatments are not immediately available, IV glucose may be used. With proper management, individuals with AIP can lead healthy and fulfilling lives.
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This question is part of the following fields:
- Haematology And Oncology
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Question 4
Incorrect
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A 4-year-old boy visits the doctor complaining of occasional vomiting. He appears to be unstable while walking and his mother reports that he frequently complains of headaches. What is the probable diagnosis?
Your Answer: Acute myeloid leukaemia
Correct Answer: Medulloblastoma
Explanation:Diagnosis of a Posterior Fossa Tumor in a Young Girl
This young girl is showing symptoms of a posterior fossa tumor, which affects the cerebellar function. Ataxia, slurred speech, and double vision are common symptoms of this type of tumor. Additionally, headaches and vomiting are signs of increased intracranial pressure. The most likely diagnosis for this young girl is medulloblastoma, which is the most frequent posterior fossa tumor in children.
Craniopharyngioma is an anterior fossa tumor that arises from the floor of the pituitary, making it an unlikely diagnosis for this young girl. Acute myeloid leukemia is rare in children and has a low rate of CNS involvement, unlike acute lymphoblastic leukemia. Ataxia telangiectasia is a hereditary condition that causes degeneration of multiple spinal cord tracts, but it would not present with features of a space-occupying lesion. Becker’s muscular dystrophy is an X-linked condition that causes weakness in boys.
In summary, this young girl’s symptoms suggest a posterior fossa tumor, with medulloblastoma being the most likely diagnosis. It is important to accurately diagnose and treat this condition to ensure the best possible outcome for the patient.
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This question is part of the following fields:
- Haematology And Oncology
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Question 5
Incorrect
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A woman in her 40s is undergoing investigation for bowel cancer. During a colonoscopy, numerous small growths are found throughout her bowel, indicating the presence of an autosomal dominant familial condition that the clinician had suspected.
Which gene mutation is commonly associated with this diagnosis?Your Answer: BCR-ABL
Correct Answer: APC
Explanation:While a majority of human cancers are linked to p53 malfunction, it should be noted that the APC gene is specifically associated with FAP and not p53.
Colorectal cancer can be classified into three types: sporadic, hereditary non-polyposis colorectal carcinoma (HNPCC), and familial adenomatous polyposis (FAP). Sporadic colon cancer is believed to be caused by a series of genetic mutations, including allelic loss of the APC gene, activation of the K-ras oncogene, and deletion of p53 and DCC tumor suppressor genes. HNPCC, which is an autosomal dominant condition, is the most common form of inherited colon cancer. It is caused by mutations in genes involved in DNA mismatch repair, leading to microsatellite instability. The most common genes affected are MSH2 and MLH1. Patients with HNPCC are also at a higher risk of other cancers, such as endometrial cancer. The Amsterdam criteria are sometimes used to aid diagnosis of HNPCC. FAP is a rare autosomal dominant condition that leads to the formation of hundreds of polyps by the age of 30-40 years. It is caused by a mutation in the APC gene. Patients with FAP are also at risk of duodenal tumors. A variant of FAP called Gardner’s syndrome can also feature osteomas of the skull and mandible, retinal pigmentation, thyroid carcinoma, and epidermoid cysts on the skin. Genetic testing can be done to diagnose HNPCC and FAP, and patients with FAP generally have a total colectomy with ileo-anal pouch formation in their twenties.
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This question is part of the following fields:
- Gastrointestinal System
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Question 6
Incorrect
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A 40-year-old male visits his doctor with concerns about his family history. His father and paternal grandmother both developed Alzheimer's disease at the age of 68 and 75 respectively. Which allele is associated with an elevated risk, but not a guaranteed factor, for the onset of the disease?
Your Answer: E3
Correct Answer: E4
Explanation:The primary genetic determinant of sporadic Alzheimer’s disease risk is the presence of polymorphic alleles in the APOE gene. Those who carry the ε4 allele are at the greatest risk.
Alzheimer’s disease is a type of dementia that gradually worsens over time and is caused by the degeneration of the brain. There are several risk factors associated with Alzheimer’s disease, including increasing age, family history, and certain genetic mutations. The disease is also more common in individuals of Caucasian ethnicity and those with Down’s syndrome.
The pathological changes associated with Alzheimer’s disease include widespread cerebral atrophy, particularly in the cortex and hippocampus. Microscopically, there are cortical plaques caused by the deposition of type A-Beta-amyloid protein and intraneuronal neurofibrillary tangles caused by abnormal aggregation of the tau protein. The hyperphosphorylation of the tau protein has been linked to Alzheimer’s disease. Additionally, there is a deficit of acetylcholine due to damage to an ascending forebrain projection.
Neurofibrillary tangles are a hallmark of Alzheimer’s disease and are partly made from a protein called tau. Tau is a protein that interacts with tubulin to stabilize microtubules and promote tubulin assembly into microtubules. In Alzheimer’s disease, tau proteins are excessively phosphorylated, impairing their function.
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This question is part of the following fields:
- Neurological System
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Question 7
Correct
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A 75-year-old woman complains of faecal incontinence and displays weakened anal sphincter muscles upon examination. What are the primary nerve root values for the nerves that provide the external anal sphincter?
Your Answer: S2,3,4
Explanation:To prevent fecal matter from reaching the floor, the external anal sphincter receives nerve supply from the pudendal nerve’s inferior rectal branch, which originates from S2, S3, and S4 root values.
Anatomy of the Anal Sphincter
The anal sphincter is composed of two muscles: the internal anal sphincter and the external anal sphincter. The internal anal sphincter is made up of smooth muscle and is continuous with the circular muscle of the rectum. It surrounds the upper two-thirds of the anal canal and is supplied by sympathetic nerves. On the other hand, the external anal sphincter is composed of striated muscle and surrounds the internal sphincter but extends more distally. It is supplied by the inferior rectal branch of the pudendal nerve (S2 and S3) and the perineal branch of the S4 nerve roots.
In summary, the anal sphincter is a complex structure that plays a crucial role in maintaining continence. The internal and external anal sphincters work together to control the passage of feces and gas through the anus. Understanding the anatomy of the anal sphincter is important for diagnosing and treating conditions that affect bowel function.
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This question is part of the following fields:
- Neurological System
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Question 8
Incorrect
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A 70-year-old man visits the endocrinology clinic complaining of muscle cramps, headaches, and lethargy. During the clinic visit, his vital signs are heart rate 80/min, respiratory rate 18/min, blood pressure 150/100 mmHg, temperature 36.5ºC, and saturations 99% on air. Recent blood tests reveal:
- Na+ 147 mmol/L (135 - 145)
- K+ 3.2 mmol/L (3.5 - 5.0)
- Bicarbonate 28 mmol/L (22 - 29)
- Urea 6.0 mmol/L (2.0 - 7.0)
- Creatinine 95 µmol/L (55 - 120)
An adrenal mass is detected on his abdominal CT scan. Can you identify where the hormone responsible for his symptoms is produced?Your Answer: Zona fasciculata
Correct Answer: Zona glomerulosa
Explanation:The correct answer is the zona glomerulosa. This patient is experiencing symptoms of hyperaldosteronism, which is likely caused by an adenoma in the zona glomerulosa, as indicated by the mass seen on CT scan (also known as Conn’s syndrome). The adenoma stimulates the production of aldosterone, leading to hypertension and hypokalemia.
The adrenal medulla produces catecholamines, such as adrenaline and noradrenaline.
The juxtaglomerular apparatus is located in the kidney and produces renin in response to decreased renal perfusion.
The zona fasciculata is the middle layer of the adrenal cortex and is responsible for producing glucocorticoids, such as cortisol.
The zona reticularis is the innermost layer of the adrenal cortex and produces androgens, such as dehydroepiandrosterone (DHEA).
The renin-angiotensin-aldosterone system is a complex system that regulates blood pressure and fluid balance in the body. The adrenal cortex is divided into three zones, each producing different hormones. The zona glomerulosa produces mineralocorticoids, mainly aldosterone, which helps regulate sodium and potassium levels in the body. Renin is an enzyme released by the renal juxtaglomerular cells in response to reduced renal perfusion, hyponatremia, and sympathetic nerve stimulation. It hydrolyses angiotensinogen to form angiotensin I, which is then converted to angiotensin II by angiotensin-converting enzyme in the lungs. Angiotensin II has various actions, including causing vasoconstriction, stimulating thirst, and increasing proximal tubule Na+/H+ activity. It also stimulates aldosterone and ADH release, which causes retention of Na+ in exchange for K+/H+ in the distal tubule.
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This question is part of the following fields:
- Renal System
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Question 9
Correct
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An 80-year-old man is undergoing investigation for haematuria, with no other urinary symptoms reported. He has no significant medical history and previously worked in the textiles industry. During a flexible cystoscopy, a sizable mass is discovered in the lower part of his bladder, raising suspicion of bladder cancer. A PET scan is planned to check for any nodal metastasis. Which lymph nodes are most likely to be affected?
Your Answer: External and internal iliac lymph nodes
Explanation:The bladder’s lymphatic drainage is mainly to the external and internal iliac nodes. A man with haematuria and a history of working with dye is found to have a bladder tumour. To stage the tumour, nodal metastasis should be investigated, and the correct lymph nodes to check are the external and internal iliac nodes. Other options such as deep inguinal, para-aortic, and superficial inguinal nodes are incorrect.
Bladder Anatomy and Innervation
The bladder is a three-sided pyramid-shaped organ located in the pelvic cavity. Its apex points towards the symphysis pubis, while the base lies anterior to the rectum or vagina. The bladder’s inferior aspect is retroperitoneal, while the superior aspect is covered by peritoneum. The trigone, the least mobile part of the bladder, contains the ureteric orifices and internal urethral orifice. The bladder’s blood supply comes from the superior and inferior vesical arteries, while venous drainage occurs through the vesicoprostatic or vesicouterine venous plexus. Lymphatic drainage occurs mainly to the external iliac and internal iliac nodes, with the obturator nodes also playing a role. The bladder is innervated by parasympathetic nerve fibers from the pelvic splanchnic nerves and sympathetic nerve fibers from L1 and L2 via the hypogastric nerve plexuses. The parasympathetic fibers cause detrusor muscle contraction, while the sympathetic fibers innervate the trigone muscle. The external urethral sphincter is under conscious control, and voiding occurs when the rate of neuronal firing to the detrusor muscle increases.
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This question is part of the following fields:
- Renal System
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Question 10
Incorrect
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A 43-year-old man is admitted to the hospital after the nursing staff reported a sudden deterioration in his vital signs. Upon assessment, it is discovered that he is suffering from elevated intracranial pressure due to hydrocephalus. The medical team decides to administer mannitol, an osmotic diuretic, to alleviate the condition.
What is the primary site of action for mannitol in reducing intracranial pressure?Your Answer: Distal convoluted tubule
Correct Answer: Tip of the papilla of the Loop of Henle
Explanation:Where is the osmolarity highest in the nephrons of the kidneys, and why is this relevant to the effectiveness of mannitol as an osmotic diuretic?
The Loop of Henle and its Role in Renal Physiology
The Loop of Henle is a crucial component of the renal system, located in the juxtamedullary nephrons and running deep into the medulla. Approximately 60 litres of water containing 9000 mmol sodium enters the descending limb of the loop of Henle in 24 hours. The osmolarity of fluid changes and is greatest at the tip of the papilla. The thin ascending limb is impermeable to water, but highly permeable to sodium and chloride ions. This loss means that at the beginning of the thick ascending limb the fluid is hypo osmotic compared with adjacent interstitial fluid. In the thick ascending limb, the reabsorption of sodium and chloride ions occurs by both facilitated and passive diffusion pathways. The loops of Henle are co-located with vasa recta, which have similar solute compositions to the surrounding extracellular fluid, preventing the diffusion and subsequent removal of this hypertonic fluid. The energy-dependent reabsorption of sodium and chloride in the thick ascending limb helps to maintain this osmotic gradient. Overall, the Loop of Henle plays a crucial role in regulating the concentration of solutes in the renal system.
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This question is part of the following fields:
- Renal System
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Question 11
Incorrect
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A 35-year-old woman arrives at the emergency department complaining of worsening bone pain in her left hip over the past few days. She mentions feeling ill and feverish, but attributes it to a recent cold. The patient is a known IV drug user and has not traveled recently.
During the examination, the left hip appears red and tender, and multiple track marks are visible.
Which organism is most likely responsible for her symptoms?Your Answer: Salmonella enterica
Correct Answer: Staphylococcus aureus
Explanation:Osteomyelitis is most commonly caused by Staphylococcus aureus in both adults and children. IV drug use is a known risk factor for this condition as it can introduce microorganisms directly into the bloodstream. While Escherichia coli can also cause osteomyelitis, it is more prevalent in children than adults. Mycobacterium tuberculosis can also lead to osteomyelitis, but it is less common than Staphylococcus aureus. Bone introduction typically occurs via the circulatory system from pulmonary tuberculosis. However, antitubercular therapy has reduced the incidence of tuberculosis, making bone introduction less likely than with Staphylococcus aureus, which is part of the normal skin flora. Salmonella enterica is the most common cause of osteomyelitis in individuals with sickle cell disease. As the patient is not known to have sickle cell, Staphylococcus aureus remains the most probable cause.
Understanding Osteomyelitis: Types, Causes, and Treatment
Osteomyelitis is a bone infection that can be classified into two types: haematogenous and non-haematogenous. Haematogenous osteomyelitis is caused by bacteria in the bloodstream and is usually monomicrobial. It is more common in children and can be caused by risk factors such as sickle cell anaemia, intravenous drug use, immunosuppression, and infective endocarditis. On the other hand, non-haematogenous osteomyelitis is caused by the spread of infection from adjacent soft tissues or direct injury to the bone. It is often polymicrobial and more common in adults, with risk factors such as diabetic foot ulcers, pressure sores, diabetes mellitus, and peripheral arterial disease.
Staphylococcus aureus is the most common cause of osteomyelitis, except in patients with sickle-cell anaemia where Salmonella species are more prevalent. To diagnose osteomyelitis, MRI is the imaging modality of choice, with a sensitivity of 90-100%.
The treatment for osteomyelitis involves a course of antibiotics for six weeks. Flucloxacillin is the preferred antibiotic, but clindamycin can be used for patients who are allergic to penicillin. Understanding the types, causes, and treatment of osteomyelitis is crucial in managing this bone infection.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 12
Incorrect
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A middle-aged woman presents with collapse and weakness on her left side. Her husband reports that she has a medical history of hyperthyroidism, diabetes, and autosomal dominant polycystic kidney disease, but no known drug allergies. A CT scan of her head reveals a significant intracerebral bleed on the left side. What is the probable cause of the bleed?
Your Answer: Atherosclerotic disease
Correct Answer: Ruptured berry aneurysm
Explanation:Autosomal dominant polycystic kidney disease increases the risk of brain haemorrhage due to ruptured berry aneurysms.
Autosomal dominant polycystic kidney disease (ADPKD) is a commonly inherited kidney disease that affects 1 in 1,000 Caucasians. The disease is caused by mutations in two genes, PKD1 and PKD2, which produce polycystin-1 and polycystin-2 respectively. ADPKD type 1 accounts for 85% of cases, while ADPKD type 2 accounts for 15% of cases. ADPKD type 1 is caused by a mutation in the PKD1 gene on chromosome 16, while ADPKD type 2 is caused by a mutation in the PKD2 gene on chromosome 4. ADPKD type 1 tends to present with renal failure earlier than ADPKD type 2.
To screen for ADPKD in relatives of affected individuals, an abdominal ultrasound is recommended. The diagnostic criteria for ultrasound include the presence of two cysts, either unilateral or bilateral, if the individual is under 30 years old. If the individual is between 30-59 years old, two cysts in both kidneys are required for diagnosis. If the individual is over 60 years old, four cysts in both kidneys are necessary for diagnosis.
For some patients with ADPKD, tolvaptan, a vasopressin receptor 2 antagonist, may be an option to slow the progression of cyst development and renal insufficiency. However, NICE recommends tolvaptan only for adults with ADPKD who have chronic kidney disease stage 2 or 3 at the start of treatment, evidence of rapidly progressing disease, and if the company provides it with the agreed discount in the patient access scheme.
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This question is part of the following fields:
- Renal System
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Question 13
Correct
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Sophie, a 19-year-old girl with type 1 diabetes mellitus, arrives at the emergency department with confusion, vomiting, and abdominal pain. Upon examination, she displays tachycardia and tachypnea. The medical team orders various tests, including an arterial blood gas.
The results are as follows:
pH 7.29 mmol/l
K+ 6.0 mmol/l
Glucose 15mmol/l
The doctors initiate treatment for diabetic ketoacidosis.
What ECG abnormality can be observed in relation to Sophie's potassium level?Your Answer: Tall tented T waves and flattened P waves
Explanation:When a person has hyperkalaemia, their blood has an excess of potassium which can lead to cardiac arrhythmias. One of the common ECG abnormalities seen in hyperkalaemia is tall tented T waves. Other possible ECG changes include wide QRS complexes and flattened P waves. In contrast, hypokalaemia can cause T wave depression, U waves, and tall P waves on an ECG. Delta waves are typically seen in patients with Wolfe-Parkinson-White syndrome.
ECG Findings in Hyperkalaemia
Hyperkalaemia is a condition characterized by high levels of potassium in the blood. This condition can have serious consequences on the heart, leading to abnormal ECG findings. The ECG findings in hyperkalaemia include peaked or ‘tall-tented’ T waves, loss of P waves, broad QRS complexes, sinusoidal wave pattern, and ventricular fibrillation.
The first ECG finding in hyperkalaemia is the appearance of peaked or ‘tall-tented’ T waves. This is followed by the loss of P waves, which are the small waves that represent atrial depolarization. The QRS complexes, which represent ventricular depolarization, become broad and prolonged. The sinusoidal wave pattern is a characteristic finding in severe hyperkalaemia, where the ECG tracing appears as a series of undulating waves. Finally, ventricular fibrillation, a life-threatening arrhythmia, can occur in severe hyperkalaemia.
In summary, hyperkalaemia can have serious consequences on the heart, leading to abnormal ECG findings. These findings include peaked or ‘tall-tented’ T waves, loss of P waves, broad QRS complexes, sinusoidal wave pattern, and ventricular fibrillation. It is important to recognize these ECG findings in hyperkalaemia as they can guide appropriate management and prevent life-threatening complications.
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This question is part of the following fields:
- Gastrointestinal System
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Question 14
Incorrect
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A 29-year-old male is admitted after a car accident. During examination, his heart rate is found to be 125 beats/min, and his blood pressure is 120/105 mmHg. Upon palpation, his abdomen is tense and tender. The diagnosis is hypovolemic shock. Which receptor stimulation has led to compensation for the blood loss?
Your Answer: Alpha 2 adrenergic
Correct Answer: Alpha 1 adrenergic
Explanation:Activation of alpha 1 adrenergic receptors leads to the contraction of smooth muscles. This causes vasoconstriction in the skin, gut, and kidney arterioles, increasing total peripheral resistance and mean arterial pressure. It also helps to improve perfusion of vital organs such as the brain, heart, and lungs during the fight or flight response.
On the other hand, activation of beta 2 adrenergic receptors results in the dilation of smooth muscles, such as bronchodilation. Activation of beta 3 adrenergic receptors enhances lipolysis in adipose tissue. Activation of alpha 2 adrenergic receptors inhibits the release of noradrenaline, providing negative feedback.
Activation of the muscarinic M2 acetylcholine receptor decreases heart rate, which could worsen compensation.
Adrenergic receptors are a type of G protein-coupled receptors that respond to the catecholamines epinephrine and norepinephrine. These receptors are primarily involved in the sympathetic nervous system. There are four types of adrenergic receptors: α1, α2, β1, and β2. Each receptor has a different potency order and primary action. The α1 receptor responds equally to norepinephrine and epinephrine, causing smooth muscle contraction. The α2 receptor has mixed effects and responds equally to both catecholamines. The β1 receptor responds equally to epinephrine and norepinephrine, causing cardiac muscle contraction. The β2 receptor responds much more strongly to epinephrine than norepinephrine, causing smooth muscle relaxation.
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This question is part of the following fields:
- General Principles
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Question 15
Correct
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A 29-year-old Turkish woman comes to your clinic complaining of growing fatigue and exhaustion. During the clinical examination, you observe pale conjunctiva and peripheral cyanosis. Her complete blood count and haematinics indicate iron deficiency anaemia. You prescribe a course of ferrous fumarate (iron supplement) and advise her to steer clear of certain things that could hinder its absorption. What is one of the things you tell her to avoid?
Your Answer: Tea
Explanation:The absorption of iron in the intestine may be reduced by tannin, which is present in tea.
Iron is abundant in fava beans.
Iron Metabolism: Absorption, Distribution, Transport, Storage, and Excretion
Iron is an essential mineral that plays a crucial role in various physiological processes. The absorption of iron occurs mainly in the upper small intestine, particularly the duodenum. Only about 10% of dietary iron is absorbed, and ferrous iron (Fe2+) is much better absorbed than ferric iron (Fe3+). The absorption of iron is regulated according to the body’s need and can be increased by vitamin C and gastric acid. However, it can be decreased by proton pump inhibitors, tetracycline, gastric achlorhydria, and tannin found in tea.
The total body iron is approximately 4g, with 70% of it being present in hemoglobin, 25% in ferritin and haemosiderin, 4% in myoglobin, and 0.1% in plasma iron. Iron is transported in the plasma as Fe3+ bound to transferrin. It is stored in tissues as ferritin, and the lost iron is excreted via the intestinal tract following desquamation.
In summary, iron metabolism involves the absorption, distribution, transport, storage, and excretion of iron in the body. Understanding these processes is crucial in maintaining iron homeostasis and preventing iron-related disorders.
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This question is part of the following fields:
- General Principles
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Question 16
Incorrect
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What is the term used to describe the recurring thoughts of harming one's own family, even though the person does not want to act on them?
Your Answer: Compulsions
Correct Answer: Obsessional thoughts
Explanation:Possession of Thought
Possession of thought can be understood through the concepts of ego-syntonicity and ego-dystonicity. Ego-syntonic experiences are consistent with an individual’s self-image, while ego-dystonic experiences are not. Obsessional thoughts are unwanted and distressing thoughts, ideas, or images that are recognized as the individual’s own, making them ego-dystonic.
Thought broadcast is a passivity experience where the individual believes their thoughts are taken away from their head and widely broadcast. On the other hand, thought insertion is a phenomenon where the individual believes that their thoughts have been placed inside their head from outside. Both thought broadcasting and insertion are thought alienation experiences and are first rank symptoms of schizophrenia.
In the case of thought alienation experiences, the division between ego-syntonicity and ego-dystonicity is less clear. Although initially ego-syntonic, as the individual recovers from psychosis, they may recognize thought alienation experiences as more distressing and therefore more ego-dystonic in nature.
Compulsions are obsessional motor acts that the patient recognizes as unnecessary but cannot resist performing. possession of thought and its various experiences can aid in the diagnosis and treatment of mental health disorders.
Overall, possession of thought is a complex phenomenon that can have significant impacts on an individual’s mental health and well-being. By the different experiences and their relationship to ego-syntonicity and ego-dystonicity, mental health professionals can provide more effective treatment and support to those experiencing these symptoms.
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This question is part of the following fields:
- Psychiatry
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Question 17
Incorrect
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A research lab is exploring a novel therapy for beta thalassaemia that involves manipulating the RNA splicing process within the cells of affected individuals.
Where does this process primarily occur within the organelles?Your Answer: Smooth endoplasmic reticulum
Correct Answer: Nucleus
Explanation:RNA splicing occurs primarily within the nucleus.
The nucleus is where RNA splicing takes place, which involves removing non-coding introns from pre-mRNA and joining coding exons to form mRNA. Alternative splicing can also occur, resulting in different configurations of exons and the ability for a single gene to code for multiple proteins.
Proteasomes are organelles found in eukaryotic cells that break down large proteins.
Ribosomes are responsible for translating mRNA into peptide structures.
Proteins are folded into their proper shape within the rough endoplasmic reticulum.
The smooth endoplasmic reticulum is involved in the synthesis of steroids and lipids.
Functions of Cell Organelles
The functions of major cell organelles can be summarized in a table. The rough endoplasmic reticulum (RER) is responsible for the translation and folding of new proteins, as well as the manufacture of lysosomal enzymes. It is also the site of N-linked glycosylation. Cells such as pancreatic cells, goblet cells, and plasma cells have extensive RER. On the other hand, the smooth endoplasmic reticulum (SER) is involved in steroid and lipid synthesis. Cells of the adrenal cortex, hepatocytes, and reproductive organs have extensive SER.
The Golgi apparatus modifies, sorts, and packages molecules that are destined for cell secretion. The addition of mannose-6-phosphate to proteins designates transport to lysosome. The mitochondrion is responsible for aerobic respiration and contains mitochondrial genome as circular DNA. The nucleus is involved in DNA maintenance, RNA transcription, and RNA splicing, which removes the non-coding sequences of genes (introns) from pre-mRNA and joins the protein-coding sequences (exons).
The lysosome is responsible for the breakdown of large molecules such as proteins and polysaccharides. The nucleolus produces ribosomes, while the ribosome translates RNA into proteins. The peroxisome is involved in the catabolism of very long chain fatty acids and amino acids, resulting in the formation of hydrogen peroxide. Lastly, the proteasome, along with the lysosome pathway, is involved in the degradation of protein molecules that have been tagged with ubiquitin.
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This question is part of the following fields:
- General Principles
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Question 18
Incorrect
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A 78-year-old man is admitted to the care of the elderly ward with urosepsis and an acute kidney injury stage 2. His medical history includes type 2 diabetes, ischaemic heart disease and prostate cancer.
Assessing his risk of venous thromboembolism (VTE), you determine that he is at high risk. To prevent VTE, you initiate subcutaneous enoxaparin, a low molecular weight heparin. What is the mechanism of action of this medication?Your Answer: Activates antithrombin III and forms a complex that inhibits thrombin, factors Xa, IXa, XIa and XIIa
Correct Answer: Activates antithrombin III and forms a complex that inhibits factor Xa
Explanation:The activation of antithrombin III (ATIII) is the mechanism by which low-molecular weight heparins (LMWH) produce an anti-coagulant effect. ATIII is a glycoprotein that inhibits several enzymes involved in the clotting cascade, including thrombin, factor Xa, and factor IXa. All heparins work to enhance the effect of ATIII, but LMWH specifically binds to ATIII and produces a conformational change that accelerates its inhibition of factor Xa.
In contrast, unfractionated heparin also produces a conformational change in ATIII, but due to its larger size, it can also inhibit other clotting factors such as thrombin, factors IXa, XIa, and XIIa.
Direct oral anticoagulants such as apixaban and rivaroxaban directly inhibit factor Xa, while dabigatran is a direct thrombin inhibitor. Aspirin, on the other hand, inhibits the production of thromboxane A2 by inhibiting COX-1 and COX-2, resulting in reduced platelet aggregation.
Heparin is a type of anticoagulant medication that comes in two main forms: unfractionated heparin and low molecular weight heparin (LMWH). Both types work by activating antithrombin III, but unfractionated heparin forms a complex that inhibits thrombin, factors Xa, IXa, XIa, and XIIa, while LMWH only increases the action of antithrombin III on factor Xa. Adverse effects of heparins include bleeding, thrombocytopenia, osteoporosis, and hyperkalemia. LMWH has a lower risk of causing heparin-induced thrombocytopenia (HIT) and osteoporosis compared to unfractionated heparin. HIT is an immune-mediated condition where antibodies form against complexes of platelet factor 4 (PF4) and heparin, leading to platelet activation and a prothrombotic state. Treatment for HIT includes direct thrombin inhibitors or danaparoid. Heparin overdose can be partially reversed by protamine sulfate.
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This question is part of the following fields:
- General Principles
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Question 19
Incorrect
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A 32-year-old woman who is 34 weeks pregnant with her first baby is worried about the possibility of her child having a congenital heart defect. She was born with patent ductus arteriosus (PDA) herself and wants to know what treatment options are available for this condition.
What treatment will you recommend if her baby is diagnosed with PDA?Your Answer: Nothing, patent ductus arteriosus mostly close spontaneously
Correct Answer: The baby receives indomethacin as a neonate
Explanation:The preferred treatment for patent ductus arteriosus (PDA) in neonates is indomethacin or ibuprofen, administered after birth. While PDA is more common in premature infants, a family history of heart defects can increase the risk. Diagnosis typically occurs during postnatal baby checks, often due to the presence of a murmur or symptoms of heart failure. Doing nothing is not a recommended approach, as spontaneous closure is rare. Surgery may be necessary if medical management is unsuccessful. Prostaglandin E1 is not the best answer, as it is typically used in cases where PDA is associated with another congenital heart defect. Indomethacin or ibuprofen are not given to the mother during the antenatal period.
Understanding Patent Ductus Arteriosus
Patent ductus arteriosus is a type of congenital heart defect that is generally classified as ‘acyanotic’. However, if left uncorrected, it can eventually result in late cyanosis in the lower extremities, which is termed differential cyanosis. This condition is caused by a connection between the pulmonary trunk and descending aorta. Normally, the ductus arteriosus closes with the first breaths due to increased pulmonary flow, which enhances prostaglandins clearance. However, in some cases, this connection remains open, leading to patent ductus arteriosus.
This condition is more common in premature babies, those born at high altitude, or those whose mothers had rubella infection in the first trimester. The features of patent ductus arteriosus include a left subclavicular thrill, continuous ‘machinery’ murmur, large volume, bounding, collapsing pulse, wide pulse pressure, and heaving apex beat.
The management of patent ductus arteriosus involves the use of indomethacin or ibuprofen, which are given to the neonate. These medications inhibit prostaglandin synthesis and close the connection in the majority of cases. If patent ductus arteriosus is associated with another congenital heart defect amenable to surgery, then prostaglandin E1 is useful to keep the duct open until after surgical repair. Understanding patent ductus arteriosus is important for early diagnosis and management of this condition.
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This question is part of the following fields:
- Cardiovascular System
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Question 20
Incorrect
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You are administering lidocaine to numb the skin of a young patient before a minor procedure. What is a true statement about this medication?
Your Answer: Has a longer half life than bupivacaine
Correct Answer: Can be used to treat ventricular tachycardia
Explanation:Lidocaine: Characteristics and Uses
Lidocaine is a medication that is quickly broken down by the liver, making it unsuitable for oral administration. Its effects last for only 20 minutes, but this can be extended to approximately 90 minutes when combined with the vasoconstrictor adrenaline. However, this combination should not be used in areas where there is a risk of ischaemia.
Lidocaine is a potent antiarrhythmic drug that falls under class I, as it prolongs the action potential. It can be used to treat ventricular tachycardia, although it is not included in the ALS algorithm and should only be administered by a specialist.
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This question is part of the following fields:
- Pharmacology
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Question 21
Correct
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Which of the following indicates a verbal response score of 1 on the Glasgow Coma Scale?
Your Answer: No response
Explanation:The Glasgow coma scale is a widely used tool to assess the severity of brain injuries. It is scored between 3 and 15, with 3 being the worst and 15 the best. The scale comprises three parameters: best eye response, best verbal response, and best motor response. The verbal response is scored from 1 to 5, with 1 indicating no response and 5 indicating orientation.
A score of 13 or higher on the Glasgow coma scale indicates a mild brain injury, while a score of 9 to 12 indicates a moderate injury. A score of 8 or less indicates a severe brain injury.
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This question is part of the following fields:
- Neurological System
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Question 22
Incorrect
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A 67-year-old patient is being evaluated after being admitted for treatment of a persistent Clostridium difficile infection. The patient had received treatment for a previous infection three weeks ago, but the symptoms did not subside, and she continued to experience diarrhoea. The patient was hospitalized three days ago due to a life-threatening Clostridium difficile infection.
The patient has been receiving oral vancomycin and IV metronidazole for the past few days, but there has been no improvement in her symptoms. What would be the venous blood gas results in this case?Your Answer: Metabolic acidosis + hyperkalaemia
Correct Answer: Metabolic acidosis + hypokalaemia
Explanation:If a patient experiences prolonged diarrhoea, they may develop metabolic acidosis and hypokalaemia. This is likely the case for a patient with a history of prolonged Clostridium difficile infection, as the loss of bicarbonate ions from the GI tract during diarrhoea can lead to metabolic acidosis. Prolonged diarrhoea can also result in hypokalaemia due to the direct loss of potassium from the GI tract, which the body may be unable to compensate for. Therefore, metabolic acidosis and hypokalaemia are the expected outcomes in this scenario.
Understanding Metabolic Acidosis
Metabolic acidosis is a condition that can be classified based on the anion gap, which is calculated by subtracting the sum of chloride and bicarbonate from the sum of sodium and potassium. The normal range for anion gap is 10-18 mmol/L. If a question provides the chloride level, it may be an indication to calculate the anion gap.
Hyperchloraemic metabolic acidosis is a type of metabolic acidosis with a normal anion gap. It can be caused by gastrointestinal bicarbonate loss, prolonged diarrhea, ureterosigmoidostomy, fistula, renal tubular acidosis, drugs like acetazolamide, ammonium chloride injection, and Addison’s disease. On the other hand, raised anion gap metabolic acidosis is caused by lactate, ketones, urate, acid poisoning, and other factors.
Lactic acidosis is a type of metabolic acidosis that is caused by high lactate levels. It can be further classified into two types: lactic acidosis type A, which is caused by sepsis, shock, hypoxia, and burns, and lactic acidosis type B, which is caused by metformin. Understanding the different types and causes of metabolic acidosis is important in diagnosing and treating the condition.
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This question is part of the following fields:
- Renal System
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Question 23
Incorrect
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A 39-year-old patient visits the doctor with complaints of occasional pain in the upper right quadrant of the abdomen. The patient reports that the pain worsens after meals, particularly after a heavy dinner. There are no other accompanying symptoms, and all vital signs are within normal limits.
What is the most probable diagnosis?Your Answer: Appendicitis
Correct Answer: Biliary colic
Explanation:Biliary colic can cause pain after eating a meal.
Biliary colic occurs when the gallbladder contracts to release bile after a meal, but the presence of gallstones in the gallbladder causes pain during this process. The pain is typically worse after a fatty meal compared to a low-fat meal, as bile is needed to break down fat.
In contrast, duodenal ulcers cause pain that is worse on an empty stomach and relieved by eating, as food acts as a buffer between the ulcer and stomach acid. The pain from an ulcer is typically described as a burning sensation, while biliary colic causes a sharp pain.
Autoimmune hepatitis pain is unlikely to fluctuate as the patient described.
Appendicitis pain typically starts in the center of the abdomen and then moves to the lower right quadrant, known as McBurney’s point.
Ascending cholangitis is characterized by a triad of fever, pain, and jaundice, known as Charcot’s triad.
Understanding Biliary Colic and Gallstone-Related Disease
Biliary colic is a condition that occurs when gallstones pass through the biliary tree. It is more common in women, especially those who are obese, fertile, or over the age of 40. Other risk factors include diabetes, Crohn’s disease, rapid weight loss, and certain medications. Biliary colic is caused by an increase in cholesterol, a decrease in bile salts, and biliary stasis. The pain is due to the gallbladder contracting against a stone lodged in the cystic duct. Symptoms include colicky right upper quadrant abdominal pain, nausea, and vomiting. Unlike other gallstone-related conditions, there is no fever or abnormal liver function tests.
Ultrasound is the preferred diagnostic tool for biliary colic. Elective laparoscopic cholecystectomy is the recommended treatment. However, around 15% of patients may have gallstones in the common bile duct at the time of surgery, which can lead to obstructive jaundice. Other complications of gallstone-related disease include acute cholecystitis, ascending cholangitis, acute pancreatitis, gallstone ileus, and gallbladder cancer. It is important to understand the risk factors, pathophysiology, and management of biliary colic and gallstone-related disease to ensure prompt diagnosis and appropriate treatment.
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This question is part of the following fields:
- Gastrointestinal System
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Question 24
Incorrect
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A 17-year-old boy is out on a movie date with his girlfriend. During the film, he keeps his arm over her seat. However, when the movie ends, he realizes that he has limited wrist movement. Upon examination, he is unable to extend his wrist and has reduced sensation in his anatomical snuff box. Which nerve did he damage while at the cinema?
Your Answer: Musculoskeletal
Correct Answer: Radial
Explanation:Saturday night syndrome is a condition where the brachial plexus is compressed due to sleeping with the arm over the back of a chair. This can result in a radial nerve palsy, commonly known as wrist drop, where the patient is unable to extend their wrist and it hangs flaccidly.
Upper limb anatomy is a common topic in examinations, and it is important to know certain facts about the nerves and muscles involved. The musculocutaneous nerve is responsible for elbow flexion and supination, and typically only injured as part of a brachial plexus injury. The axillary nerve controls shoulder abduction and can be damaged in cases of humeral neck fracture or dislocation, resulting in a flattened deltoid. The radial nerve is responsible for extension in the forearm, wrist, fingers, and thumb, and can be damaged in cases of humeral midshaft fracture, resulting in wrist drop. The median nerve controls the LOAF muscles and can be damaged in cases of carpal tunnel syndrome or elbow injury. The ulnar nerve controls wrist flexion and can be damaged in cases of medial epicondyle fracture, resulting in a claw hand. The long thoracic nerve controls the serratus anterior and can be damaged during sports or as a complication of mastectomy, resulting in a winged scapula. The brachial plexus can also be damaged, resulting in Erb-Duchenne palsy or Klumpke injury, which can cause the arm to hang by the side and be internally rotated or associated with Horner’s syndrome, respectively.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 25
Incorrect
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A 49-year-old man with a history of uncontrolled HIV presents with dyspnea and hemoptysis. Diagnostic tests reveal invasive aspergillosis, and he is prescribed amphotericin B. What is the mode of action of amphotericin B?
Your Answer: Inhibits DNA polymerase
Correct Answer: Binds with ergosterol
Explanation:The mechanism of action of Amphotericin B involves binding with ergosterol, a key component of fungal cell membranes. This binding results in the formation of pores that cause the cell wall to lyse, ultimately leading to fungal cell death.
Flucytosine, on the other hand, is converted by cytosine deaminase to 5-fluorouracil. This compound inhibits thymidylate synthase, which in turn disrupts fungal protein synthesis.
Caspofungin works by inhibiting the synthesis of beta-glucan, a major component of the fungal cell wall.
Griseofulvin interacts with microtubules, leading to the disruption of the mitotic spindle.
Anti-viral agents like acyclovir function by inhibiting viral DNA polymerase.
Antifungal agents are drugs used to treat fungal infections. There are several types of antifungal agents, each with a unique mechanism of action and potential adverse effects. Azoles work by inhibiting 14α-demethylase, an enzyme that produces ergosterol, a component of fungal cell membranes. However, they can also inhibit the P450 system in the liver, leading to potential liver toxicity. Amphotericin B binds with ergosterol to form a transmembrane channel that causes leakage of monovalent ions, but it can also cause nephrotoxicity and flu-like symptoms. Terbinafine inhibits squalene epoxidase, while griseofulvin interacts with microtubules to disrupt mitotic spindle. However, griseofulvin can induce the P450 system and is teratogenic. Flucytosine is converted by cytosine deaminase to 5-fluorouracil, which inhibits thymidylate synthase and disrupts fungal protein synthesis, but it can cause vomiting. Caspofungin inhibits the synthesis of beta-glucan, a major fungal cell wall component, and can cause flushing. Nystatin binds with ergosterol to form a transmembrane channel that causes leakage of monovalent ions, but it is very toxic and can only be used topically, such as for oral thrush.
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This question is part of the following fields:
- General Principles
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Question 26
Incorrect
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A 47-year-old male patient presented with complaints of fatigue and lethargy. He is health-conscious and likes to maintain his fitness.
Upon examination, his blood work revealed a deficiency in vitamin D, for which he was prescribed calcitriol. He was advised to return for a follow-up appointment in two weeks to monitor his blood results.
During his follow-up appointment, his blood work showed normal results, except for an electrolyte abnormality.
What is the most likely electrolyte abnormality seen in his blood results?Your Answer: Low calcium
Correct Answer: High phosphate
Explanation:The action of calcitriol on the body results in an increase in the reabsorption of phosphate by the kidneys, leading to an increase in plasma phosphate levels. Additionally, calcitriol promotes osteoclast activity, which further contributes to an increase in plasma calcium levels through bone resorption. It should be noted that calcitriol does not have any significant effect on potassium and magnesium levels. On the other hand, the hormone PTH has the opposite effect on plasma phosphate levels, causing a decrease in its concentration.
Hormones Controlling Calcium Metabolism
Calcium metabolism is primarily controlled by two hormones, parathyroid hormone (PTH) and 1,25-dihydroxycholecalciferol (calcitriol). Other hormones such as calcitonin, thyroxine, and growth hormone also play a role. PTH increases plasma calcium levels and decreases plasma phosphate levels. It also increases renal tubular reabsorption of calcium, osteoclastic activity, and renal conversion of 25-hydroxycholecalciferol to 1,25-dihydroxycholecalciferol. On the other hand, 1,25-dihydroxycholecalciferol increases plasma calcium and plasma phosphate levels, renal tubular reabsorption and gut absorption of calcium, osteoclastic activity, and renal phosphate reabsorption. It is important to note that osteoclastic activity is increased indirectly by PTH as osteoclasts do not have PTH receptors. Understanding the actions of these hormones is crucial in maintaining proper calcium metabolism in the body.
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This question is part of the following fields:
- General Principles
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Question 27
Incorrect
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Which type of bias are cohort studies particularly prone to?
Your Answer: Publication bias
Correct Answer: Recall bias
Explanation:Understanding Bias in Clinical Trials
Bias refers to the systematic favoring of one outcome over another in a clinical trial. There are various types of bias, including selection bias, recall bias, publication bias, work-up bias, expectation bias, Hawthorne effect, late-look bias, procedure bias, and lead-time bias. Selection bias occurs when individuals are assigned to groups in a way that may influence the outcome. Sampling bias, volunteer bias, and non-responder bias are subtypes of selection bias. Recall bias refers to the difference in accuracy of recollections retrieved by study participants, which may be influenced by whether they have a disorder or not. Publication bias occurs when valid studies are not published, often because they showed negative or uninteresting results. Work-up bias is an issue in studies comparing new diagnostic tests with gold standard tests, where clinicians may be reluctant to order the gold standard test unless the new test is positive. Expectation bias occurs when observers subconsciously measure or report data in a way that favors the expected study outcome. The Hawthorne effect describes a group changing its behavior due to the knowledge that it is being studied. Late-look bias occurs when information is gathered at an inappropriate time, and procedure bias occurs when subjects in different groups receive different treatment. Finally, lead-time bias occurs when two tests for a disease are compared, and the new test diagnoses the disease earlier, but there is no effect on the outcome of the disease. Understanding these types of bias is crucial in designing and interpreting clinical trials.
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This question is part of the following fields:
- General Principles
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Question 28
Correct
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A 55-year-old man arrives at the emergency department complaining of central chest pain that started 15 minutes ago. An ECG is conducted and reveals ST elevation in leads I, aVL, and V6. Which coronary artery is the most probable cause of obstruction?
Your Answer: Left circumflex artery
Explanation:The presence of ischaemic changes in leads I, aVL, and V5-6 suggests a possible issue with the left circumflex artery, which supplies blood to the lateral area of the heart. Complete blockage of this artery can lead to ST elevation, while partial blockage may result in non-ST elevation myocardial infarction. Other areas of the heart and their corresponding coronary arteries are listed in the table below.
The following table displays the relationship between ECG changes and the affected coronary artery territories. Anteroseptal changes in V1-V4 indicate involvement of the left anterior descending artery, while inferior changes in II, III, and aVF suggest the right coronary artery is affected. Anterolateral changes in V4-6, I, and aVL may indicate involvement of either the left anterior descending or left circumflex artery, while lateral changes in I, aVL, and possibly V5-6 suggest the left circumflex artery is affected. Posterior changes in V1-3 may indicate a posterior infarction, which is typically caused by the left circumflex artery but can also be caused by the right coronary artery. Reciprocal changes of STEMI are often seen as horizontal ST depression, tall R waves, upright T waves, and a dominant R wave in V2. Posterior infarction is confirmed by ST elevation and Q waves in posterior leads (V7-9), usually caused by the left circumflex artery but also possibly the right coronary artery. It is important to note that a new LBBB may indicate acute coronary syndrome.
Diagram showing the correlation between ECG changes and coronary territories in acute coronary syndrome.
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This question is part of the following fields:
- Cardiovascular System
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Question 29
Incorrect
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A father brings his 9-year-old daughter to your general practice, as he is worried about her hearing. He notices that he has to repeat himself when talking to her, and thinks she is often 'in her own little world'. During the examination, the Rinne test is positive on the left and negative on the right. What conclusions can be drawn from this?
Your Answer: Sensorineural hearing loss on the right.
Correct Answer: Can not tell if both sides are affected.
Explanation:The Rinne and Weber tests are used to diagnose hearing loss. The Rinne test involves comparing air and bone conduction, with a positive result indicating a healthy or sensorineural loss and a negative result indicating a conductive loss. The Weber test involves placing a tuning fork on the forehead and determining if the sound is symmetrical or louder on one side, with a conductive loss resulting in louder sound on the affected side and a sensorineural loss resulting in louder sound on the non-affected side. When used together, these tests can provide more information about the type and affected side of hearing loss.
Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness
Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.
Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.
The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.
Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.
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This question is part of the following fields:
- Respiratory System
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Question 30
Correct
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A nephrologist is evaluating a 12-year-old boy who presented with general malaise and was found to have proteinuria and haematuria on urine dipstick by his primary care physician. Following a comprehensive assessment, the nephrologist orders a renal biopsy. The biopsy report reveals that the immunofluorescence of the sample showed a granular appearance. What is the probable diagnosis?
Your Answer: Post-streptococcal glomerulonephritis
Explanation:Post-streptococcal glomerulonephritis is a condition that typically occurs 7-14 days after an infection caused by group A beta-haemolytic Streptococcus, usually Streptococcus pyogenes. It is more common in young children and is caused by the deposition of immune complexes (IgG, IgM, and C3) in the glomeruli. Symptoms include headache, malaise, visible haematuria, proteinuria, oedema, hypertension, and oliguria. Blood tests may show a raised anti-streptolysin O titre and low C3, which confirms a recent streptococcal infection.
It is important to note that IgA nephropathy and post-streptococcal glomerulonephritis are often confused as they both can cause renal disease following an upper respiratory tract infection. Renal biopsy features of post-streptococcal glomerulonephritis include acute, diffuse proliferative glomerulonephritis with endothelial proliferation and neutrophils. Electron microscopy may show subepithelial ‘humps’ caused by lumpy immune complex deposits, while immunofluorescence may show a granular or ‘starry sky’ appearance.
Despite its severity, post-streptococcal glomerulonephritis carries a good prognosis.
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This question is part of the following fields:
- Renal System
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