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Question 1
Incorrect
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During which stage of the cell cycle does the replication of DNA occur?
Your Answer: M phase
Correct Answer: S phase
Explanation:The Five Phases of the Cell Cycle
The cell cycle is a complex process that is divided into five main phases, each with its unique cellular events. The first phase is the G0 phase, which is a resting phase where the cell has stopped dividing and is out of the cell cycle. The second phase is the G1 phase, also known as interphase Gap 1, where cells increase in size, and a checkpoint control mechanism prepares the cell for DNA synthesis.
The third phase is the S phase, where DNA replication occurs. The fourth phase is the G2 phase, also known as Gap 2, which is a gap between DNA synthesis and the onset of mitosis. During this phase, the cell continues to grow until it is ready to enter mitosis. Finally, the fifth phase is the M phase, also known as mitosis, where cell growth stops, and the cell focuses its energy to divide into two daughter cells.
A checkpoint in the middle of mitosis, known as the metaphase checkpoint, ensures that the cell is prepared to complete division. the five phases of the cell cycle is crucial in how cells divide and grow.
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This question is part of the following fields:
- Basic Sciences
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Question 2
Correct
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Which statement regarding microtubules is accurate in relation to Chédiak-Higashi syndrome?
Your Answer: They are arranged in a 9+2 formation in cilia
Explanation:Microtubules and Chédiak-Higashi Syndrome
Microtubules are made up of alpha and beta tubulin dimers that are arranged in a helix and can be added or removed to change the length. They are found in structures such as flagella, mitotic spindles, and cilia, where they have a 9+2 arrangement. These structures are important for cell movement and division. Chemotherapy agents, such as taxanes, target microtubules and are used in breast cancer treatment.
Chédiak-Higashi syndrome is a rare inherited immunodeficiency disorder caused by mutations in the LYST gene. This condition is characterized by neutrophil inclusions, albinism, recurrent infections, and peripheral neuropathy. The neutrophil inclusions are thought to be caused by abnormal microtubule function, which affects the immune system’s ability to fight infections. While there is no cure for Chédiak-Higashi syndrome, treatment focuses on managing symptoms and preventing infections.
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This question is part of the following fields:
- Basic Sciences
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Question 3
Correct
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You are evaluating a geriatric patient in the emergency department who has fallen and needs a venous cannula for fluid resuscitation. To ensure maximum flow into the vein, you plan to apply the Hagen-Poiseuille equation to select an appropriate cannula size. Which of the following statements is true according to this law?
Your Answer: Flow will be faster through a shorter cannula
Explanation:Poiseuille’s Equation and Fluid Flow in Cylinders
Poiseuille’s equation is used to describe the flow of non-pulsatile laminar fluids through a cylinder. The equation states that the flow rate is directly proportional to the pressure driving the fluid and the fourth power of the radius. Additionally, it is inversely proportional to the viscosity of the fluid and the length of the tube. This means that a short, wide cannula with pressure on the bag will deliver fluids more rapidly than a long, narrow one.
It is important to note that even small changes in the radius of a tube can greatly affect the flow rate. This is because the fourth power of the radius is used in the equation. Therefore, any changes in the radius will have a significant impact on the flow rate. Poiseuille’s equation is crucial in determining the optimal conditions for fluid delivery in medical settings.
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This question is part of the following fields:
- Basic Sciences
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Question 4
Incorrect
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At what stage of eukaryotic mitosis do the centromeres of chromosomes separate?
Your Answer: Prometaphase
Correct Answer: Anaphase
Explanation:Chromosome Division during Anaphase
Chromosomes are joined together in an X shape at the centromere. During anaphase, the centromeres break down and the chromosomes divide into two identical pairs called sister chromatids. These sister chromatids then move to opposite sides of the cell along a network of spindle fibres. When the cell divides during telophase, each daughter cell receives one sister chromatid from the parent cell. This ensures the accurate copying and propagation of genes. The process of chromosome division during anaphase is crucial for the proper distribution of genetic material in cells.
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This question is part of the following fields:
- Basic Sciences
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Question 5
Incorrect
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What is the primary reason for malnutrition?
Your Answer: Inadequate intake of multiple vitamins
Correct Answer: Inadequate intake of calories in any form
Explanation:Malnutrition
Malnutrition refers to a state where the dietary intake is insufficient to maintain a healthy state and stable weight. It can be caused by over- or under-nutrition, but it is commonly used to describe under-nutrition. Malnutrition can be defined as a state of nutrition where a deficiency, excess, or imbalance of energy, protein, and other nutrients causes measurable adverse effects on tissue, function, and clinical outcome. Protein malnutrition is the most severe form of malnutrition, causing significant mortality and clinical effects such as kwashiorkor. Carbohydrate malnutrition is less common as carbohydrate sources are widely grown and cheap. Fat malnutrition rarely results in problems if there is adequate dietary protein and carbohydrate. Deficiencies of fat-soluble vitamins can result in various clinical effects. Body size can give some indication of nutritional status, but many obese patients may have nutritional deficiencies due to their faddy diets.
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This question is part of the following fields:
- Basic Sciences
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Question 6
Correct
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What stage of cellular respiration is responsible for the production of pyruvic acid?
Your Answer: Glycolysis
Explanation:The Versatility of Pyruvic Acid in Cellular Metabolism
Pyruvic acid is a simple alpha-keto acid that plays a crucial role in several metabolic pathways within the cell. It serves as a central intersection where different pathways converge and diverge. One of the primary ways pyruvic acid is produced is through glycolysis, where glucose is broken down into pyruvic acid. Depending on the cell’s needs, pyruvic acid can be converted back into glucose through gluconeogenesis or used to synthesize fatty acids through the acetyl-CoA pathway. Additionally, pyruvic acid can be used to produce the amino acid alanine.
Pyruvic acid is also involved in respiration, where it enters the Krebs cycle under aerobic conditions. This cycle produces energy in the form of ATP, which is used by the cell for various functions. Under anaerobic conditions, pyruvic acid can ferment into lactic acid, which is used by some organisms as a source of energy.
In summary, pyruvic acid is a versatile molecule that plays a critical role in cellular metabolism. Its ability to be converted into different molecules depending on the cell’s needs makes it an essential component of many metabolic pathways.
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This question is part of the following fields:
- Basic Sciences
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Question 7
Correct
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What role does the nucleolus play in eukaryotic cells?
Your Answer: To transcribe ribosomal RNA and assemble ribosomes
Explanation:The Nucleolus: Structure and Function
The nucleolus is a non-membrane-bound structure that takes up about a quarter of the nuclear volume. It is composed mainly of proteins and nucleic acids and is responsible for transcribing ribosomal RNA (rRNA) and assembling ribosomes in the cell. Nucleoli are formed in nucleolar organizing regions (NORs), which are also the regions of the genes for three of the four eukaryotic rRNAs.
During ribosome assembly, ribosomal proteins enter the nucleolus from the cytoplasm and begin to assemble on an rRNA precursor. As the pre-rRNA is cleaved to produce 5.8S, 18S, and 28S rRNAs, additional ribosomal proteins and the 5S rRNA (which is synthesized elsewhere in the nucleus) assemble to form preribosomal subunits. These subunits then exit the nucleolus into the cytoplasm and combine to produce the final 40S and 60S ribosomal subunits.
Overall, the nucleolus plays a crucial role in protein synthesis by producing the components necessary for ribosome assembly. Its unique structure and function make it an essential component of the cell’s machinery.
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This question is part of the following fields:
- Basic Sciences
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Question 8
Correct
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What is a primary function of vitamin A?
Your Answer: Vision
Explanation:Vitamin A: Forms, Sources, and Functions
Vitamin A is a crucial nutrient that exists in various forms in nature. The primary dietary form of vitamin A is retinol, also known as pre-formed vitamin A, which is stored in animal liver tissue as retinyl esters. The body can also produce its own vitamin A from carotenoids, with beta-carotene being the most common precursor molecule.
The richest sources of vitamin A include liver and fish liver oils, dark green leafy vegetables, carrots, and mangoes. Vitamin A can also be added to certain foods like cereals and margarines.
Vitamin A plays several essential roles in the body, including supporting vision by being a component of rhodopsin, a pigment required by the rod cells of the retina. It also contributes to the growth and development of various types of tissue, regulates gene transcription, and aids in the synthesis of hydrophobic glycoproteins and parts of the protein kinase enzyme pathways.
In summary, the different forms and sources of vitamin A and its vital functions in the body is crucial for maintaining optimal health.
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This question is part of the following fields:
- Basic Sciences
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Question 9
Correct
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Of which cellular structure is the fibrillar centre a component?
Your Answer: The nucleolus
Explanation:The Fibrillar Centre in the Nucleolus
The fibrillar centre is a crucial component of the nucleolus, which is found in most metazoan nucleoli, particularly in higher eukaryotes. Along with the dense fibrillar components and the granular component, it forms the three major components of the nucleolus. During the end of mitosis, the fibrillar centre serves as a storage point for nucleolar ribosomal chromatin and associated ribonucleoprotein transcripts. As the nucleolus becomes active, the ribosomal chromatin and ribonucleoprotein transcripts begin to form the dense fibrillar components, which are more peripherally located and surround the fibrillar centres. The transcription zone for multiple copies of the pre-rRNA genes is the border between these two structures. It is important to note that the fibrillar centre is not a component of any of the cell structures mentioned in the incorrect answer options.
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This question is part of the following fields:
- Basic Sciences
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Question 10
Correct
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Over the last five years, the total number of patients admitted and deaths in the East and North Hertfordshire NHS Trust have been recorded. In the year 2010/2011, there were 95,071 patients admitted and 1,912 deaths. What is the crude mortality ratio for this group in that year (per 100 admissions)?
Your Answer: 2
Explanation:In this scenario, the crude mortality ratio is established by comparing the number of deaths occurring within the hospital in a given year to the total number of admissions, disregarding age or gender-specific mortality rates. For instance, with 1,912 deaths out of 95,071 admissions, the ratio computes to 0.02, or 2.0% when calculated per 100 admissions (1,912/95,071 = 0.02/100= 2.0%. When recalculated per 1,000 admissions, the crude admission rate would be 20 per 1,000.
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This question is part of the following fields:
- Basic Sciences
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Question 11
Incorrect
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During which phase of aerobic respiration is FADH2 generated?
Your Answer: Oxidative phosphorylation
Correct Answer: Krebs cycle
Explanation:The Krebs Cycle and the Role of FADH2
The Krebs cycle is a crucial part of aerobic respiration in cells. It involves a series of reactions that convert acetate, derived from carbohydrates, fats, and proteins, into carbon dioxide and energy in the form of ATP. Additionally, the Krebs cycle produces precursors for some amino acids and reducing agents like NADH and FADH2 that are involved in other metabolic pathways.
FAD is a redox cofactor that plays a vital role in the Krebs cycle. It receives two electrons from the sixth reaction of the cycle, where succinate dehydrogenase converts succinate into fumarate by removing two hydrogen atoms and attaching them onto FAD. This process results in FAD gaining two electrons and reducing into FADH2.
FADH2 then donates the electrons to the electron transport chain, which is another part of cellular respiration. This mechanism helps compensate for the relatively low amount of ATP produced by the Krebs cycle (2.5 molecules of ATP per turn) compared to the electron transport chain (26-28 molecules of ATP). Overall, the Krebs cycle and the role of FADH2 are essential for generating energy in cells.
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This question is part of the following fields:
- Basic Sciences
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Question 12
Incorrect
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What controls the specific stages of the cell cycle?
Your Answer: The on/off activity of cyclases and cyclase-dependent kinases
Correct Answer: Cyclins and cyclin-dependent kinases
Explanation:Regulation of the Cell Cycle by Cyclins and Cyclin-Dependent Kinases
The cell cycle is controlled by the activity of proteins known as cyclins and phosphorylating enzymes called cyclin-dependent kinases (CDKs). Cyclins and CDKs combine to form an activated heterodimer, where cyclins act as the regulatory subunits and CDKs act as the catalytic subunits. Neither of these molecules is active on their own. When a cyclin binds to a CDK, the CDK phosphorylates other target proteins, either activating or deactivating them. This coordination leads to the entry into the next phase of the cell cycle. The specific proteins that are activated depend on the different combinations of cyclin-CDK. Additionally, CDKs are always present in cells, while cyclins are produced at specific points in the cell cycle in response to other signaling pathways.
In summary, the cell cycle is regulated by the interaction between cyclins and CDKs. This interaction leads to the phosphorylation of target proteins, which ultimately controls the progression of the cell cycle.
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This question is part of the following fields:
- Basic Sciences
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Question 13
Correct
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A 10-year-old patient presents with recurrent skin cancer and is diagnosed with xeroderma pigmentosum. What is the defective biochemical mechanism in this disease?
Your Answer: DNA excision repair
Explanation:Xeroderma Pigmentosum and DNA Repair
Deoxyribonucleic acid (DNA) found in the skin cells can absorb ultraviolet (UV) light, which can cause the formation of pyrimidine dimers. These dimers are removed through a process called excision repair, where the damaged DNA is cut out and replaced with new DNA. However, if this process fails, it can lead to mutations in genes that suppress tumors or promote their growth, potentially leading to cancer.
Xeroderma pigmentosum is a genetic disorder that is inherited in an autosomal recessive pattern. This means that an individual must inherit two copies of the mutated gene, one from each parent, to develop the disorder. Generally, disorders that affect metabolism or DNA replication on a cellular or genetic level are inherited in an autosomal recessive pattern. On the other hand, genetic disorders that affect larger structural components are usually inherited in an autosomal dominant pattern. While there are exceptions to these rules, they can serve as a helpful guide for exam preparation.
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This question is part of the following fields:
- Basic Sciences
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Question 14
Incorrect
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What is the apoptotic event that occurs just before the formation of an apoptosome?
Your Answer: Activation of caspase-9
Correct Answer: Release of cytochrome c from mitochondria
Explanation:Apoptosis and the Role of the Apoptosome
Apoptosis, also known as programmed cell death, is a natural process that occurs in all multicellular organisms. It involves a series of changes in cell morphology, including membrane blebbing, cell shrinkage, nuclear fragmentation, chromatin condensation, and chromosomal DNA fragmentation. The formation of the apoptosome is a crucial part of the apoptosis cascade. It is a large protein structure that is triggered by the release of cytochrome c from the mitochondria in response to various stimuli, such as DNA damage, infections, or developmental signals.
The apoptosome is formed when cytochrome c binds to Apaf-1, a cytosolic protein, in a 1:1 ratio. This triggers the recruitment and activation of the initiator pro-caspase-9, which then activates effector caspases, a family of apoptotic proteases, to initiate the apoptotic cascade. It is important to note that the activation of caspase-9 occurs only after the formation of the apoptosome.
In summary, apoptosis is a natural process that occurs in multicellular organisms, and the apoptosome plays a crucial role in triggering the apoptotic cascade. the mechanisms behind apoptosis and the formation of the apoptosome can provide insights into various diseases and developmental processes.
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This question is part of the following fields:
- Basic Sciences
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Question 15
Incorrect
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As part of your general practice placement, you have been tasked with conducting an audit on the duration of solid food introduction in the practice population. You review the data for the last six infants born within the practice:
6 months, 7 months, 8 months, 9 months, 10 months, 11 months.
What is the variance value for the duration of solid food introduction in the practice population?Your Answer: 17.6
Correct Answer: 74.9
Explanation:Variance and Standard Deviation in Breast Feeding Duration
Variance is a statistical measure that indicates how spread out a set of data is. In the case of breast feeding duration, variance can help us understand how much the duration varies from the mean. The formula for variance involves squaring the difference between each data point and the mean, then dividing the sum by n-1, where n is the total number of data points. In a sample population, n-1 is a better estimate of variance than n because it accounts for the variability within the sample.
For example, if the variance of breast feeding duration is 74.9 months, this indicates that the duration is widely distributed from the mean of 17.6 months. A smaller variance, such as 4.5 months, would indicate that the duration varies less and is closer to the mean. The standard deviation, which is the square root of the variance, is also important in the spread of data. In a normal distribution, 95% of observations will fall within two standard deviations of the mean.
In the case of breast feeding duration, the mean is 17.6 months, indicating that babies are breast fed for an average of 15 and a half months. The median, which is the middle number in the data set, is 15 months, meaning that half of the babies were breast fed for 15 months. variance and standard deviation can help us better understand the distribution of breast feeding duration and other medical measurements.
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This question is part of the following fields:
- Basic Sciences
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Question 16
Correct
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Which food is a rich source of vitamin D in the diet?
Your Answer: Oily fish
Explanation:Sources of Vitamin D
Vitamin D is a type of fat-soluble vitamin that can be found in certain foods such as cheese, butter, eggs, and oily fish. However, vegetable sources of vitamin D are limited, although some foods are fortified with this vitamin. For instance, 100 grams of sundried shiitake mushrooms contain 1600 IU of vitamin D, while one egg contains 20 IU. Wild salmon is also a good source of vitamin D, with 100 grams containing 800 IU, while farmed salmon contains 200 IU.
Aside from food sources, sunlight is also a good source of vitamin D. Exposure of arms and legs to sunlight for 10-15 minutes can provide 3000 IU of vitamin D. However, it is difficult to obtain the daily requirement of 25-50 IU of vitamin D through sunlight alone, especially for people living in temperate climates. As a result, many people may have insufficient vitamin D levels. It is important to ensure that we get enough vitamin D through a combination of food sources and sunlight exposure.
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This question is part of the following fields:
- Basic Sciences
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Question 17
Correct
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What is the main role of the Golgi apparatus in eukaryotic cells?
Your Answer: Process of proteins
Explanation:The Golgi Apparatus, Cell Division, and Homeostasis
The Golgi apparatus is a structure found in eukaryotic cells that consists of flattened membrane stacks. Its primary function is to modify proteins that have been synthesized in the rough endoplasmic reticulum, preparing them for secretion or transport within the cell. However, the Golgi apparatus is not directly involved in cell division, which is controlled by the nucleus.
Cell homeostasis, on the other hand, is primarily maintained by membrane-embedded channels or proteins such as the sodium-potassium pump. This mechanism ensures that the cell’s internal environment remains stable. The sodium-potassium pump is an active transport mechanism that involves the binding of three intracellular sodium ions to the protein. Adenosine triphosphate (ATP) donates a phosphate group to the protein, which causes it to change shape and release the sodium ions out of the cell.
The protein then accepts two extracellular potassium ions, and the donated phosphate group detaches, causing the protein to revert to its original shape. This allows the potassium ions to enter the cell, increasing the intracellular potassium concentration and decreasing the intracellular sodium concentration. This process is in contrast to the extracellular conditions.
In summary, the Golgi apparatus modifies proteins for secretion or transport, while cell division is controlled by the nucleus. Cell homeostasis is maintained by membrane-embedded channels or proteins such as the sodium-potassium pump, which actively transports ions to stabilize the cell’s internal environment.
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This question is part of the following fields:
- Basic Sciences
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Question 18
Correct
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A 70-year-old male smoker complains of calf pain.
The GP performs a clinical test by raising the patient's legs and observing for the angle at which there is blanching. After one minute, the legs are lowered over the side of the couch so that they are fully dependent with feet on the floor. Reactive hyperaemia is observed.
Which clinical test does this describe?Your Answer: Buerger's test
Explanation:Tests for Assessing Arterial and Venous Circulation, Hip Dysfunction, and Meniscal Tear
Buerger’s test is a method used to evaluate the arterial circulation of the lower limb. The test involves observing the angle at which blanching occurs, with a lower angle indicating a higher likelihood of arterial insufficiency. Additionally, the degree of reactive hyperaemia on dependency of the limb after one minute is another positive sign of arterial insufficiency during the test.
Another test used to assess circulation is the Ankle-Brachial Pressure Index (ABPI), which involves using blood pressure cuffs to determine the degree of claudication. McMurray’s test, on the other hand, is used to evaluate for a meniscal tear within the knee joint.
Perthe’s test is a method used to assess the patency of the deep femoral vein prior to varicose vein surgery. Lastly, Trendelenburg’s test is used to evaluate hip dysfunction. These tests are important in diagnosing and treating various conditions related to circulation and joint function.
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This question is part of the following fields:
- Basic Sciences
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Question 19
Correct
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What occurs in eukaryotic prometaphase?
Your Answer: The nuclear membrane and the nucleoli disintegrate and kinetochores appear
Explanation:The Significance of Prometaphase in Cell Division
Prometaphase is a crucial phase in cell division that marks the transition from prophase to metaphase. Although it is often considered as a part of these two phases, it has distinct events that make it an individual phase. During prometaphase, the nuclear membrane disintegrates, and the nucleoli are no longer visible. Additionally, each chromosome forms two kinetochores near the centromere, which serve as attachment points for spindle fibers. These fibers connect to the opposite poles of the cell, forming travelling lines that will separate the sister chromatids during anaphase.
Prophase is characterized by chromatin condensation, while DNA and centrosome duplication occur during interphase. Chromosome alignment takes place during metaphase, and the sister chromatids separate during anaphase. Prometaphase, therefore, plays a crucial role in preparing the chromosomes for separation during anaphase. Its distinct events make it an essential phase in cell division, and its proper execution is necessary for successful cell division.
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This question is part of the following fields:
- Basic Sciences
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Question 20
Correct
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What role does vitamin K play in the body?
Your Answer: Activation of clotting factors II, VII, IX, X
Explanation:The Roles of Vitamin K in the Body
Vitamin K plays several important roles in the body. One of its main functions is to modify clotting factors II, VII, IX, and X through a process called carboxylation. This modification allows calcium to bind to the factors, which is necessary for them to participate in the clotting pathway. This principle is used in full blood counts to prevent clotting by adding EDTA, which chelates the calcium. Vitamin K also modifies osteocalcin and matrix proteins in bone, as well as nephrocalcin in the kidney, in a similar way.
In addition to its role in blood clotting and bone health, vitamin K is also important for nervous tissue development and growth. However, vitamin K antagonists such as warfarin are sometimes used as anticoagulants to prevent blood clots. It is important to follow guidelines and instructions carefully when using these medications. Overall, vitamin K plays a crucial role in maintaining the health and function of various systems in the body.
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This question is part of the following fields:
- Basic Sciences
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Question 21
Incorrect
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What is the fundamental meaning of carbohydrate?
Your Answer: A compound containing carbon, hydrogen and oxygen in any proportion.
Correct Answer: A compound following the formula Cx(H2O)y
Explanation:Carbohydrates: Building Blocks of Energy and Storage
Carbohydrates are organic compounds made up of carbon, hydrogen, and oxygen, with a general formula of Cx(H2O)y. They can be classified as either aldehydes or ketones and contain multiple hydroxyl groups. Monosaccharides are the simplest form of carbohydrates, consisting of a single unit. They are categorized based on the number of carbon atoms they contain, with trioses having three, pentoses having five, and hexoses having six carbon atoms. These monosaccharides are essential for energy production and building larger carbohydrate structures.
Disaccharides are formed when two monosaccharides are joined together through a condensation reaction, releasing a water molecule. The most common disaccharides are lactose, maltose, and sucrose. Polysaccharides, on the other hand, are long, branched polymers made up of multiple single units. They serve as convenient storage molecules for energy reserves, such as glycogen in humans and starch in plants.
In summary, carbohydrates are vital building blocks for energy production and storage in living organisms. Monosaccharides, disaccharides, and polysaccharides all play important roles in maintaining the body’s energy balance and overall health.
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This question is part of the following fields:
- Basic Sciences
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Question 22
Correct
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What is the most common method of assessing nutritional status in adults?
Your Answer: Body mass index
Explanation:The Body Mass Index as a Measure of Nutritional Status
The measurement and assessment of nutritional status can be challenging, and there is no single test that can provide a complete picture. However, the body mass index (BMI) is a commonly used measurement in clinical practice. The BMI is calculated by dividing a person’s weight in kilograms by their height in meters squared. This measure is used to assess adiposity and nutritional status, and it is simple and quick to calculate and interpret.
Although the BMI is a convenient measure, it has limitations for assessing obesity in individual patients. It is best used to track trends in an individual patient’s BMI over time. In some cases, the BMI may overestimate fat mass in patients who are very tall or have a high proportion of lean tissue due to an active lifestyle. Additionally, the BMI may not be accurate for athletes and children.
Other measurements, such as skin fold thickness and weight, can also be useful, but the BMI is generally considered the better option. The ponderal index is used specifically for children. It is important to note that albumin is not a reliable marker of nutritional status, as it can also be affected by inflammation.
Overall, the BMI is a widely used measure of nutritional status and is recommended by the World Health Organization. However, it is important to consider its limitations and use it in conjunction with other measurements to obtain a more complete picture of a patient’s nutritional status.
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This question is part of the following fields:
- Basic Sciences
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Question 23
Correct
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What could be a potential cause of metabolic acidosis?
Your Answer: Poorly controlled diabetes
Explanation:Acid-Base Imbalances in Different Medical Conditions
Poorly controlled diabetes can cause the breakdown of fatty acids, leading to the production of ketones as an alternative energy source. However, an excess of ketones can result in metabolic acidosis due to their acidic nature. On the other hand, chronic obstructive pulmonary disease (COPD) and suffocation can cause the retention of carbon dioxide, leading to respiratory acidosis. In COPD, there may be a compensatory metabolic alkalosis. Voluntary hyperventilation can cause respiratory alkalosis due to the reduction of carbon dioxide. Vomiting can also lead to metabolic alkalosis. Diabetic ketoacidosis is a complication of type 1 diabetes that results in high blood sugar levels, ketone production, and acidosis.
In summary, different medical conditions can cause acid-base imbalances in the body. It is important to identify the underlying cause of the imbalance to provide appropriate treatment.
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This question is part of the following fields:
- Basic Sciences
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Question 24
Incorrect
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A 29-year-old woman visits your clinic with concerns about a possible pregnancy.
Can you explain the mechanism behind a urinary pregnancy test?Your Answer: Radioimmunoassay
Correct Answer: ELISA
Explanation:Techniques in Biochemistry
Over-the-counter urine pregnancy tests use ELISA to detect beta-HCG in a woman’s urine. The test stick contains antibodies that react with beta-HCG, producing a color change that confirms pregnancy. The urinary pregnancy test is a solid-phase ELISA, where the antibody is immobilized on a specialized filter paper. The fluid travels laterally across the paper to bind with the antibody, and if beta-HCG is present, the line turns blue. Electrophoresis characterizes the electrical charge and size of substances, while PCR identifies specific sequences of DNA or RNA. Radioimmunoassay uses radioactivity to identify specific proteins. Enzymatic degradation breaks down large proteins into smaller subunits for which target antibodies may already exist. This method is used to characterize large proteins for which the structure has not yet been described.
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This question is part of the following fields:
- Basic Sciences
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Question 25
Correct
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A premature baby is born and the anaesthetists are struggling to ventilate the lungs because of insufficient surfactant. How does Laplace's law explain the force pushing inwards on the walls of the alveolus caused by surface tension between two static fluids, such as air and water in the alveolus?
Your Answer: Inversely proportional to the radius of the alveolus
Explanation:The Relationship between Alveolar Size and Surface Tension in Respiratory Physiology
In respiratory physiology, the alveolus is often represented as a perfect sphere to apply Laplace’s law. According to this law, there is an inverse relationship between the size of the alveolus and the surface tension. This means that smaller alveoli experience greater force than larger alveoli for a given surface tension, causing them to collapse first. This phenomenon is similar to what happens when two balloons of different sizes are attached together, with the smaller balloon emptying into the larger one.
In the lungs, this collapse of smaller alveoli can lead to atelectasis and collapse if surfactant is not present. Surfactant is a substance that reduces surface tension, making it easier to expand the alveoli and preventing smaller alveoli from collapsing. this relationship between alveolar size and surface tension is crucial in respiratory physiology, as it helps explain the importance of surfactant in maintaining proper lung function.
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This question is part of the following fields:
- Basic Sciences
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Question 26
Incorrect
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A 50-year-old female patient with varicose veins presents to the vascular clinic for evaluation.
During the assessment, a test is conducted to determine the location of incompetence. The patient is instructed to lie down, and the veins are emptied by elevating her legs off the couch. The examiner then identifies the site of the sapheno-femoral junction and applies pressure with their fingers. The patient is then asked to stand up to evaluate vein filling.
What is the name of this test?Your Answer: Tourniquet test
Correct Answer: Trendelenburg's test
Explanation:Assessing Varicose Vein Site of Incompetence
The Trendelenburg and tourniquet tests are both used to evaluate the site of incompetence in varicose veins at the sapheno-femoral junction. During the Trendelenburg test, the examiner applies pressure with their fingers over the junction site, while in the tourniquet test, a tourniquet is placed just below the junction level.
If the veins fill quickly upon standing, it indicates that the sapheno-femoral junction is not the source of the incompetence. These tests are essential in determining the location of the varicose vein site of incompetence, which is crucial in planning the appropriate treatment. By identifying the site of incompetence, physicians can perform targeted interventions to improve venous function and alleviate symptoms. Therefore, the Trendelenburg and tourniquet tests are valuable tools in the diagnosis and management of varicose veins.
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This question is part of the following fields:
- Basic Sciences
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Question 27
Incorrect
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A man in his forties comes in with chest pain resembling a heart attack and is diagnosed with a myocardial infarction. During his hospitalization, it is discovered that he has familial hypercholesterolemia but his triglyceride levels are normal. What is the underlying biochemical abnormality?
Your Answer: Hepatic overproduction of VLDL
Correct Answer: Defective LDL receptors
Explanation:Lipid Metabolism and Transport in the Body
The breakdown of triglycerides in the small intestine is facilitated by pancreatic lipase. These triglycerides are then transported to the liver and other parts of the body through chylomicrons.
Very low-density lipoprotein (VLDL) is responsible for carrying triglycerides from the liver to peripheral tissues. When there is an overproduction of VLDL in the liver, it can lead to high levels of triglycerides in the body.
Pure hypercholesterolaemia is a condition that arises due to a defect in the process of cholesterol uptake into cells. This process relies on apolipoprotein B-100 binding to LDL receptors and facilitating endocytosis. When this process is disrupted, it can lead to high levels of cholesterol in the body.
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This question is part of the following fields:
- Basic Sciences
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Question 28
Correct
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What occurs during metaphase II of meiosis?
Your Answer: The cell's chromosomes attach to the meiotic spindle to divide into chromatids
Explanation:The Process of Meiosis
Meiosis is a complex process that involves two major cycles. The first cycle, meiosis I, condenses the reproductive cell’s DNA into chromosomes that are then replicated, creating two pairs of each original chromosome. These pairs are then separated, and the cell divides with one chromosome in each daughter cell. The second cycle, meiosis II, splits the chromosomes into individual chromatids, which are then separated as in meiosis I. This separation is facilitated by a spindle, a set of parallel fibers that attach to the center of each chromosome and split into two, making the chromatids travel on the polar opposite sides of the cell. The cell then divides again, giving rise to four haploid daughter cells.
During meiosis II, the chromosomes align on the spindle in metaphase II. Tetrads separate during anaphase I and line up during metaphase I. Sister chromatids separate on the meiotic spindle during anaphase II. Finally, chromosomes uncoil and lengthen at the end of meiosis, in telophase II. This process is essential for the production of gametes and the continuation of sexual reproduction in many organisms.
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This question is part of the following fields:
- Basic Sciences
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Question 29
Correct
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What is the statement of Henry's law?
Your Answer: The concentration of a gas when dissolved in liquid is proportional to its partial pressure
Explanation:Gas Laws
Gas laws are a set of scientific principles that describe the behavior of gases under different conditions. One of these laws is Avogadro’s law, which states that equal volumes of gases at a standardized temperature and pressure contain the same number of molecules. Another law is Boyle’s law, which explains that gases expand when the temperature is increased. Charles’ law, on the other hand, states that the pressure of a gas is inversely proportional to its volume at a standardized temperature. Lastly, Graham’s law explains that the rate of diffusion of a gas is in inverse proportion to its weight. The specific gas laws that you need to know may vary depending on your syllabus, but you should be able to recognize and apply them if given the formulae. It is unlikely that you will be expected to know the correct formula.
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This question is part of the following fields:
- Basic Sciences
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Question 30
Incorrect
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What RNA base pairs with adenine when synthesizing a complementary RNA strand from DNA, using RNA polymerase to split the helix at specific points?
Your Answer: Cytosine
Correct Answer: Uracil
Explanation:Differences between DNA and RNA
DNA and RNA differ in several ways. The primary sugar in DNA is deoxyribose, while in RNA it is ribose. Additionally, DNA is double stranded, while RNA is single stranded. This single stranded structure with un-paired bases allows for transcription to occur when the DNA bases are freed. Each base has a specific pairing, with guanine always binding to cytosine and adenine always binding to thymine in the DNA strand. During transcription, the same complementary RNA bases assemble with the DNA bases, except for thymine, which is not an RNA base. Instead, uracil serves as the RNA pyrimidine base equivalent of thymine. Finally, lysine is an amino acid coded for by the RNA base triplet AAA, where A represents adenine.
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This question is part of the following fields:
- Basic Sciences
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