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  • Question 1 - A caudal epidural block is planned for a 6-year-old child scheduled for an...

    Correct

    • A caudal epidural block is planned for a 6-year-old child scheduled for an inguinoscrotal hernia repair under general anaesthesia. The weight of the child is 20kg. The most important safety aspect the anaesthetist must keep in mind while performing the block is?

      Your Answer: Limiting the bupivacaine dose to no more than 40 mg

      Explanation:

      Choosing an appropriate dose of local anaesthetic to reduce the chance of toxicity is the most important safety aspect in performing a caudal block.

      The caudal will have to be inserted following induction of anaesthesia as performing it in an awake child is not a viable option.

      The patient is placed in the lateral position and the sacral hiatus is identified. Under strict asepsis, a needle ( usually a 21-23FG needle) is advanced at an angle of approximately 55-65° to the coronal plane at the apex of the sacrococcygeal membrane. When there is loss of resistance, thats the endpoint. The needle must first be aspirated before anaesthetic agent is injected because there is a risk (1 in 2000) of perforating the dura or vascular puncture.

      Alternatively, a 22-gauge plastic cannula can be used. Following perforation of the sacrococcygeal membrane, the stilette is removed and only the blunter plastic cannula is advanced. This reduces the risk of intravascular perforation.

      Eliciting an appropriate end motor response at an appropriate current strength when the caudal and epidural spaces are stimulated helps in improving the efficacy and safety of neural blockade. A 22G insulated needle is advanced in the caudal canal until a pop is felt. If the needle is placed correctly, an anal sphincter contractions (S2 to S4) is seen when an electrical stimulation of 1-10 mA is applied.

      The application of ultrasound guidance in identification of the caudal epidural space has been shown to prevent inadvertent dural puncture and to increase the safety and efficacy of the block in children.

    • This question is part of the following fields:

      • Pharmacology
      26.5
      Seconds
  • Question 2 - Which of the following statements is true about oxygen face masks? ...

    Incorrect

    • Which of the following statements is true about oxygen face masks?

      Your Answer: In healthy patients, the peak inspiratory flow rate rarely exceeds 15 litres per minute during normal tidal ventilation

      Correct Answer: The oxygen concentration delivered by high air flow oxygen enrichment devices is not dependent on the respiratory pattern of the patient

      Explanation:

      The normal peak inspiratory flow in healthy individuals is 20-30 L/min during each normal tidal ventilation. This is expected to increase with greater respiratory rate and deeper inspiration.

      Face masks are used to facilitate the delivery of oxygen from a breathing system to a patient. Face masks can be divided into two types: fixed performance or variable performance devices.

      In fixed performance devices (also known as high air flow oxygen enrichment or HAFOE), fixed inspired oxygen concentration is delivered to the patent, independent and greater than that of the patient’s peak inspiratory flow rate (PIFR). No random entrainment is expected to occur at the time of PIFR, hence, the oxygen concentration in HAFOE devices is not dependent on the patient’s respiratory pattern.

      Moreover, in HAFOE masks, the concentration of oxygen at a given oxygen flow rate is determined by the size of the constriction; a device with a greater entrainment aperture delivers a lower oxygen concentration. Therefore, a 40% Venturi device will have lesser entrainment aperture when compared to a 31% Venturi. Venturi masks allow relatively fixed concentrations of supplemental oxygen to be inspired e.g. 24%, 28%, 31%, 35%, 40% and 60% oxygen. These are colour coded and marked with the recommended oxygen flow rate.

      Variable performance devices deliver variable inspired oxygen concentration to the patient, and is dependent on the PIFR. The PIFR can often exceed the flow rate at which oxygen or an oxygen/air mixture is supplied by the device, depending on a patient’s inspiratory effort. In addition, these masks allow expired air to be released through the holes in the sides of the mask. Thus, with increased respiratory rate, rebreathing of alveolar gas from inside the mask may occur.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      52.5
      Seconds
  • Question 3 - The equipment used for patient monitoring in theatre and intensive care settings have...

    Correct

    • The equipment used for patient monitoring in theatre and intensive care settings have electrical safety requirements for the protection of hospital staff and patients. Of the different classes of electrical equipment listed, which is least likely to cause a patient to suffer a microshock?

      Your Answer: II (CF)

      Explanation:

      Microshock refers to ventricular fibrillation caused by miniscule amounts of currents or voltages (100-150 microamperes) passing through the myocardial tissue from external cables arising from electrical components within the cardiac muscle, for example, pacemaker electrodes or saline filled venous catheters.
      The risk of shock changes with the construction of electrical equipment in question. The main classes of electrical equipment include: I: Appliances have a protective earth connected to an outer casing which prevents live elements from coming in contact with conductive elements. A fault in this equipment class will result in live elements coming in contact with the outer casing and allowing electrical flow into the protective earth. This triggers the protective fuse to disconnect the electric supply to the appliance.
      II: These appliances have reinforced insulation. In the event of a fault which causes the first layer of insulation to fail, the second layer is able to prevent contact of live elements with outer casing.
      III: These appliances have no insulation to provide safety, and rely solely on the use of separated extra low voltage source (SELV) which limits voltage to 25V AC or 60V DC allowing for a person to come in contact with it without risk of a shock under normal dry conditions. Under wet conditions, voltage supply should be lowered to reduce risk of shock. These devices have no risk of macroshocks, but some risk of microshocks.
      Class I and II electrical appliances are further divided into subtypes developed to limit current leakage in the event of a singular fault:
      B (body): Upper limit of current leakage is 500 µA. This current can cause skin tingling and microshocks, but is not sufficient to cause injury.
      BF (body floating): These appliances have an isolating capacitor or transformer which separate the secondary circuit from the protective earth. The upper limit of current leakage is the same as type B.
      CF (cardiac floating): Upper limit of leakage current during a singular fault is 50 microamps. It is least likely to result in a microshock.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      3.9
      Seconds
  • Question 4 - Arrythmias can develop from abnormal conduction, which may be as a result of...

    Correct

    • Arrythmias can develop from abnormal conduction, which may be as a result of impaired blood flow in the coronary arteries which causes hypoxia. Phase 0 depolarisation can be slowed, and this leads to slower conduction speeds. Rapid depolarisation in the cardiac action potential is caused by which movement of ions?

      Your Answer: Sodium influx

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      19.5
      Seconds
  • Question 5 - Which of the statements below best describe the total cerebral flow (CBF) in...

    Incorrect

    • Which of the statements below best describe the total cerebral flow (CBF) in an adult?

      Your Answer: Below a mean arterial pressure of 60 mmHg the cerebral blood flow is proportional to the systolic blood pressure

      Correct Answer: Accounts for 15% of the cardiac output

      Explanation:

      While the brain only weighs 3% of the body weight, 15% of the cardiac output goes towards the brain.

      Between mean arterial pressures (MAP) of 60-130 mmHg, autoregulation of cerebral blood flow (CBF) occurs. Exceeding this, the CBF is maintained at a constant level. This is controlled mainly by the PaCO2 level, and the autonomic nervous system has minimal role.

      Beyond these limits, the CBF is directly proportional to the MAP, not the systolic blood pressure.

    • This question is part of the following fields:

      • Physiology
      44
      Seconds
  • Question 6 - Which of the following statements is correct about a characteristic that is normally...

    Correct

    • Which of the following statements is correct about a characteristic that is normally distributed in a population?

      Your Answer: There will be approximately equal numbers who have more or less of the characteristic than the mean

      Explanation:

      68% of the population will be found in one standard deviation (SD) above plus one SD below the mean. Two SDs above plus two SDs below the mean will include 95% of the population.

      The median can be greater or less than the mean as it is simply the mid point of the data after the data is arranged. Half the data are above and half below the median .

      The mode is a true score, unlike the mean or the median. It is the most common score or the score obtained from the largest number of subjects in any given data.

    • This question is part of the following fields:

      • Statistical Methods
      14.7
      Seconds
  • Question 7 - A 72-year-old female is diagnosed with acute mesenteric ischemia. On CT angiogram, the...

    Correct

    • A 72-year-old female is diagnosed with acute mesenteric ischemia. On CT angiogram, the origin of the superior mesenteric artery is stenosed. At which vertebra level does the superior mesenteric artery branch from the aorta?

      Your Answer: L1

      Explanation:

      The superior mesenteric artery branches from the abdominal aorta just 1-2 cm below the origin of the celiac trunk. It lies posterior to the body of the pancreas and splenic vein and is separated from the aorta by the left renal vein. It passes forwards and inferiorly, anterior to the uncinate process of the pancreas and the third part of the duodenum, to enter the root of the small bowel mesentery and supply the midgut.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T10 – oesophageal opening in the diaphragm

      T12 – Coeliac trunk, aortic hiatus in the diaphragm

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta.

    • This question is part of the following fields:

      • Anatomy
      12.9
      Seconds
  • Question 8 - An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a...

    Correct

    • An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a bottle of sugared orange squash at anaesthetic assessment . He appears to have consumed 120 mL of the bottle's contents. What is the minimal safe fasting time prior to proceeding with a general anaesthetic in this patient?

      Your Answer: 1 hour

      Explanation:

      The incidence of Pulmonary aspiration in children is about 0.07%€�0.1%.

      The Association of Paediatric Anaesthetists of Great Britain and Ireland, The European Society of Paediatric Anaesthetists and L’Association Des Anesthésistes€�Réanimateurs Pédiatriques d’Expression Française produced a consensus statement in April 2018 with revised starvation times in children prior to elective surgery.

      The preoperative fasting for elective procedures for children aged 0-16 years of age are:

      Solid food/formula milk – 6 hours
      Breast milk – 4 hours
      Clear fluid – 1 hour

      A liberal clear fluid fasting regime does not affect the incidence of pulmonary aspiration in children as long as there are no specific contraindications (e.g. gastro-oesophageal reflux, cerebral palsy). Prolonged periods of fasting in children are associated with increase thirst and irritability and can lead to other adverse physiological and metabolic effects.

      Clear fluids are defined as water, clear (nonopaque) fruit juice or squash/cordial, ready diluted drinks, and non-fizzy sports drinks.

    • This question is part of the following fields:

      • Pathophysiology
      11.4
      Seconds
  • Question 9 - The external laryngeal nerve is responsible for the innervation of which of the...

    Incorrect

    • The external laryngeal nerve is responsible for the innervation of which of the following muscles?

      Your Answer: Thyro-arytenoid

      Correct Answer: Cricothyroid

      Explanation:

      The external laryngeal nerve arises from the superior laryngeal nerve and provides innervation to the cricothyroid muscle.

      The other muscles mentioned receive their innervations from the recurrent laryngeal nerve.

    • This question is part of the following fields:

      • Anatomy
      9.2
      Seconds
  • Question 10 - From the following electromagnetic waves, which one has the shortest wavelength? ...

    Correct

    • From the following electromagnetic waves, which one has the shortest wavelength?

      Your Answer: X rays

      Explanation:

      Electromagnetic waves are categorized according to their frequency or equivalently according to their wavelength. Visible light makes up a small part of the full electromagnetic spectrum.

      Electromagnetic waves with shorter wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays. Electromagnetic waves with longer wavelengths and lower frequencies include infrared light, microwaves, and radio and televisions waves.

      Different electromagnetic waves according to their wavelength from shorter to longer are X-rays, ultraviolet radiations, visible light, infrared radiation, radio waves. X-ray among electromagnetic waves has the shortest wavelength and higher frequency with wavelengths ranging from 10*-8 to 10* -12 and corresponding frequencies.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      9.4
      Seconds
  • Question 11 - A 70-year-old man presents with central crushing chest pain that radiates to the...

    Correct

    • A 70-year-old man presents with central crushing chest pain that radiates to the jaw in the emergency department. He has associated symptoms of nausea and diaphoresis. A 12 lead ECG is performed. ST-elevation is observed in leads V2-V4. The diagnosis of anteroseptal ST-elevation myocardial infarction is made. Which coronary vessel is responsible for this condition and runs in the interventricular septum on the anterior surface of the heart to reach the apex?

      Your Answer: Left anterior descending artery

      Explanation:

      The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.

      The left main coronary artery branches into:
      1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
      2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septum

      The left anterior descending coronary artery is the largest coronary artery. It courses anterior to the interventricular septum in the anterior interventricular groove, extending from the base of the heart to its apex. Around the apex, the LAD anastomosis with the terminal branches of the posterior descending artery (branch of the right coronary artery).
      Atherosclerosis or thrombotic occlusion of LAD causes myocardial infarction in large areas of the anterior, septal, and apical portions of the heart muscle. It can lead to a serious deterioration in heart performance.

      Occlusion of the LAD causes anteroseptal myocardial infarction, which is evident on the ECG with changes in leads V1-V4. Occlusion of the left circumflex artery causes lateral, posterior, or anterolateral MI. However, as it does not run towards the apex in the interventricular septum of the heart, it is not the correct answer for this question.

      The right coronary artery branches into:
      1. Right marginal artery
      2. Posterior descending artery

      The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. Occlusion of the right coronary artery causes inferior MI, which is indicated on ECG with changes in leads II, III, and aVF.

    • This question is part of the following fields:

      • Anatomy
      16
      Seconds
  • Question 12 - How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?...

    Correct

    • How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?

      Your Answer: Three

      Explanation:

      The abdominal arteries are divided into 3 branches;
      – 3 main unpaired trunks (celiac trunk, superior mesenteric, inferior mesenteric arteries)
      – 6 paired branches
      – unpaired median sacral artery.

      We can group the abdominal aorta as follows;
      -Ventral which includes: Coeliac trunk, superior mesenteric and inferior mesenteric arteries
      -Lateral: Inferior phrenic, middle suprarenal, renal and gonadal arteries
      -Dorsal: Lumbar and median sacral arteries
      -Terminal : Right and left common iliac arteries

      The celiac trunk (L1) takes blood the foregut and its found posterior to the stomach. The unpaired superior mesenteric artery supplies blood to the mid-gut.

      The paired renal arteries form the inferior suprarenal arteries. The renal arteries arise around L1/L2 and takes blood to either side of the kidneys.

      The median sacral artery supplies blood to the lumbar vertebrae the L4 and L5.

    • This question is part of the following fields:

      • Anatomy
      19.2
      Seconds
  • Question 13 - Given the following values: Expired tidal volume = 800 ml, Plateau pressure =...

    Correct

    • Given the following values: Expired tidal volume = 800 ml, Plateau pressure = 50 cmH2O, PEEP = 10 cmH2O. Compute for the static pulmonary compliance.

      Your Answer: 20 ml/cmH2O

      Explanation:

      Compliance of the respiratory system describes the expandability of the lungs and chest wall. There are two types of compliance: dynamic and static.

      Dynamic compliance describes the compliance measured during breathing, which involves a combination of lung compliance and airway resistance. Defined as the change in lung volume per unit change in pressure in the presence of flow.

      Static compliance describes pulmonary compliance when there is no airflow, like an inspiratory pause. Defined as the change in lung volume per unit change in pressure in the absence of flow.

      For example, if a person was to fill the lung with pressure and then not move it, the pressure would eventually decrease; this is the static compliance measurement. Dynamic compliance is measured by dividing the tidal volume, the average volume of air in one breath cycle, by the difference between the pressure of the lungs at full inspiration and full expiration. Static compliance is always a higher value than dynamic

      Static compliance can be computed using the formula:

      Cstat = Tidal volume/Plateau pressure – PEEP

      Substituting the values given,

      Cstat = 800/50-10
      Cstat = 20 ml/cmH2O

    • This question is part of the following fields:

      • Physiology
      73.5
      Seconds
  • Question 14 - Drug A has a 1 L/kg volume of distribution and a 0.1 elimination...

    Incorrect

    • Drug A has a 1 L/kg volume of distribution and a 0.1 elimination rate constant (k). Drug B has a 2 L/kg volume of distribution and a 0.2 elimination rate constant (k). Which of the following statements best describes the pharmacokinetics of drug A in a single compartment?

      Your Answer: Drug A has a shorter half life than drug B

      Correct Answer: Drug A has a lower clearance than drug B

      Explanation:

      The fall in plasma concentration of a drug with time decreases exponentially in a single compartment pharmacokinetic model (wash-out curve).

      A straight line is produced when the logarithm (ln) of a drug’s plasma concentration is plotted against time because a constant proportion of the drug is removed from the plasma per unit time. The line’s gradient or slope can be expressed mathematically as k. (the rate constant). The gradient is related to the half life (T1/2) because it can be used to predict a drug’s plasma concentration at any time.

      According to the following formula, clearance (CL), volume of distribution (Vd), and elimination rate constant (k) are mathematically related.

      CL = Vd x k

      For drug A, CL = 1 x 0.1 = 0.1units per minute

      For drug B, Cl = 2 x 0.2 = 0.4 units per minute

      Hence, it is proved that Drug A has a lower clearance than drug B.

    • This question is part of the following fields:

      • Pharmacology
      101.4
      Seconds
  • Question 15 - A survey aimed at finding out mean glucose level in individuals that took...

    Incorrect

    • A survey aimed at finding out mean glucose level in individuals that took antipsychotics medicines was conducted. The results were as follows: Mean Value: 7mmol/L, Standard Deviation: 6mmol/L, Sample Size: 9, Standard Error: 2mmol/L. For a confidence interval of 95%, which of the option presents the correct range up to the nearest value?

      Your Answer: 5-9 mmol/L

      Correct Answer: 3-11 mmol/L

      Explanation:

      Key Point: While finding out confidence intervals, standard errors are used. Standard error and Standard deviation are two distinct entities and should not be confused.

      For 99.7% confidence interval, you can find the range as follows:

      Multiply the standard error by 3.

      Subtract the answer from mean value to get the lower limit.

      Add the answer obtained in step 1 from the mean value to get the upper limit.

      The range turns out to be 1-13 mmol/L.

      For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. The range found for this interval is 3-11 mmol/L.

      For a 95% confidence interval. Standard Error is multiplied by 1.96 which gives us the limit ranging from 3.08 to 10.92 mmol/L which could be approximated to 3-11 mmol/L.

    • This question is part of the following fields:

      • Statistical Methods
      71
      Seconds
  • Question 16 - An arterial pressure transducer is supposedly in direct correlation to change, thus it...

    Correct

    • An arterial pressure transducer is supposedly in direct correlation to change, thus it is dependent on zero gradient drift and zero offset. Which of the following values will best compensate for the gradient drift?

      Your Answer: 0 mmHg and 200 mmHg

      Explanation:

      Since an arterial pressure transducer, and every other measuring apparatus, is prone to errors due to offset and gradient drifts, regular calibration is required to maintain accuracy of the instrument. The two-point calibration pressure values of 0 mmHg and 200 mmHg are within the physiologic range and can best compensate for the gradient drift.

    • This question is part of the following fields:

      • Clinical Measurement
      13.8
      Seconds
  • Question 17 - An 82-year old male has shortness of breath which is made worse when...

    Correct

    • An 82-year old male has shortness of breath which is made worse when he lies down but investigations have revealed a normal ejection fraction. Why might this be?

      Your Answer: He has diastolic dysfunction

      Explanation:

      Decreased stroke volume causes decreased ejection fraction which results in diastolic dysfunction.
      Ejection fraction is not a useful measure in someone with diastolic dysfunction because stroke volume may be reduced whilst end-diastolic volume may be reduced.
      Diastolic dysfunction may arise with reduced heart compliance.

      Ejection fraction measures of the proportion of blood leaving the ventricles with each beat and is calculated as follows:
      Stroke volume / end-diastolic volume.

      A healthy ejection fraction is usually taken as 60% (based on a stroke volume of 70ml and end-diastolic volume of 120ml).

      Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.

      Sitting up decreases venous because of the action of gravity on blood in the venous system.
      Hypotension also decreases venous return.
      A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.

      Systemic vascular resistance = mean arterial pressure / cardiac output.
      Increased vascular resistance impedes the flow of blood back to the heart.

      Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      18.7
      Seconds
  • Question 18 - Using a negative feedback loop, Haem production is controlled by which of these...

    Correct

    • Using a negative feedback loop, Haem production is controlled by which of these enzymes?

      Your Answer: ALA synthetase

      Explanation:

      Heme a exists in cytochrome a and heme c in cytochrome c; they are both involved in the process of oxidative phosphorylation. 5′-Aminolevulinic acid synthase (ALA-S) is the regulated enzyme for heme synthesis in the liver and erythroid cells.

      There are two forms of ALA Synthase, ALAS1, and ALAS2.

    • This question is part of the following fields:

      • Physiology
      11.7
      Seconds
  • Question 19 - It is safe to perform a central neuraxial block without an increased risk...

    Correct

    • It is safe to perform a central neuraxial block without an increased risk of developing a vertebral canal haematoma in?

      Your Answer: A patient on clopidogrel 7 days after last dose

      Explanation:

      The incidence of vertebral canal haematoma following neuraxial blockade was reported (third National Audit Project (NAP3)) as 0.85 per 100 000 (95% CI 0-1.8 per 100 000). The incidence following neuraxial blockade in coagulopathic patients is likely to be higher hence coagulopathy remains a relative contraindication for conducting a spinal or epidural. When indicate, risk and benefits are weighed, and it is only performed by experienced personnel in this case.

      Acceptable time to perform a block after the last dose of rivaroxaban in a patient with a creatinine clearance of greater than 30mL/minute is 18 hours.

      Acceptable time to perform a block after the last dose of subcutaneous LMWH as prophylaxis is 12 hours.

      Acceptable time to perform a block after the last dose of subcutaneous UFH as prophylaxis is 4 hours.

      Acceptable time to perform a block after the last dose of thrombolytic therapy (streptokinase or alteplase) is 10 days.

      Clopidogrel should be stopped 7 days prior to surgery, particularly if a central neuraxial procedure is considered.

    • This question is part of the following fields:

      • Pathophysiology
      25.5
      Seconds
  • Question 20 - The cardiac muscle will primarily utilize which metabolic substrate to produce energy when...

    Correct

    • The cardiac muscle will primarily utilize which metabolic substrate to produce energy when at rest?

      Your Answer: Fatty acids

      Explanation:

      Approximately 70% of the heart’s ATP requirement is met by cardiac mitochondria through beta-oxidation of fatty acids at rest. The remaining 30% is supplied by glucose.

      Amino acids and ketones, in the presence of ketoacidosis, may supply at most 10% of the ATP requirement. And, when in high levels, lactate may also contribute to the ATP requirement of the heart, particularly during moments of high muscular activity.

    • This question is part of the following fields:

      • Pathophysiology
      9.3
      Seconds
  • Question 21 - The following statements concern the sensory innervation of the nasal passage: ...

    Correct

    • The following statements concern the sensory innervation of the nasal passage:

      Your Answer: the infraorbital branch of the maxillary nerve supplies the vestibule

      Explanation:

      The walls of the anterior nasal passage are supplied by the anterior ethmoidal branch of the nasociliary nerve, and the floor is innervated by the superior dental nerve (not the sphenopalatine nerves).

      The walls and floor of the posterior nasal passage are innervated by the long and short sphenopalatine nerves and the great palatine nerve (not the superior dental nerves and the nasociliary nerve).

      The vestibule is innervated by small branches of the infraorbital branch of the maxillary nerve.

      The nasopharynx is innervated by the sensory branches of the trigeminal nerve (not the great palatine nerve).

    • This question is part of the following fields:

      • Anatomy
      19.4
      Seconds
  • Question 22 - A 240 volt alternating current (AC) socket from a wall is used to...

    Incorrect

    • A 240 volt alternating current (AC) socket from a wall is used to charge a direct current (DC) cardiac defibrillator. Name the electrical component that converts AC to DC.

      Your Answer: Step-down transformer

      Correct Answer: Rectifier

      Explanation:

      There are two types of defibrillators
      AC defibrillator
      DC defibrillator

      AC defibrillator,
      consists of a step-up transformer with primary and secondary winding and two switches. Since secondary coil consists of more turns of wire than the primary coil, it induces larger voltage. A voltage value ranging between 250V to 750V is applied for AC external defibrillator. And used to enable the charging of a capacitor.

      DC defibrillator,
      consists of auto transformer T1 that acts as primary of the high voltage transformer T2. Is an iron core that transfers energy between 2 circuits by electromagnetic induction. Transformers are used to isolate circuits, change impedance and alter voltage output. transformers do not convert AC to DC.

      Diode rectifier composed of 4 diodes made of semiconductor material allows current to flow only in one direction. Alternating current (AC) passing through these diodes produces direct current (DC). Capacitor stores the charge in the form of an electrostatic field.

      Capacitor is used to convert the rectified AC voltage to produce DC voltage but capacitors do not directly convert AC to DC.

      Inductor induces a counter electromotive force(emf) that reduces the capacitor discharge value.

      In step-down transformer primary coils has more turns of wire than secondary coil, so induced voltage is smaller in the secondary coil.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      14.7
      Seconds
  • Question 23 - Which of the following is correct for gas pipeline pressure? ...

    Correct

    • Which of the following is correct for gas pipeline pressure?

      Your Answer: 4 bar for oxygen

      Explanation:

      Pipeline gases (in the UK this includes: Oxygen, Nitrous oxide, Medical air, and Entonox) are supplied at 4 bar (or 400 kPa), and compressed air is supplied at 7 bar for power tools.

      Carbon dioxide and nitric oxide are usually only supplied in cylinders.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      9.7
      Seconds
  • Question 24 - A 61-year-old woman with myasthenia gravis is admitted to the ER with type...

    Incorrect

    • A 61-year-old woman with myasthenia gravis is admitted to the ER with type II respiratory failure. There is a suspicion of myasthenic crisis. She is in a semiconscious state. Her blood pressure is 160/90 mmHg, pulse is 110 beats per minute, temperature is 37°C, and oxygen saturation is 84 percent. With a PaCO2 of 75 mmHg (10 kPa) breathing air, blood gas analysis confirms she is hypoventilating. Which of the following values is the most accurate representation of her alveolar oxygen tension (PAO2)?

      Your Answer: 9

      Correct Answer: 7.3

      Explanation:

      The following is the alveolar gas equation:

      PAO2 = PiO2 ˆ’ PaCO2/R

      Where:

      PAO2 is the partial pressure of oxygen in the alveoli.
      PiO2 is the partial pressure of oxygen inhaled.
      PaCO2 stands for partial pressure of carbon dioxide in the arteries.
      The amount of carbon dioxide produced (200 mL/minute) divided by the amount of oxygen consumed (250 mL/minute) equals R = respiratory quotient. With a normal diet, the value is 0.8.

      By subtracting the partial pressure exerted by water vapour at body temperature, the PiO2 can be calculated:

      PiO2 = 0.21 × (100 kPa ˆ’ 6.3 kPa)
      PiO2 = 19.8

      Substituting:
      PAO2 = 19.8 ˆ’ 10/0.8
      PAO2 = 19.8 ˆ’ 12.5
      PAO2 = 7.3k Pa

    • This question is part of the following fields:

      • Physiology
      209.2
      Seconds
  • Question 25 - In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five...

    Incorrect

    • In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks. Which of the following indicates the most important reason for using epinephrine?

      Your Answer: There is good evidence that the use of epinephrine decreases the mortality from VF cardiac arrest

      Correct Answer: Preferential distribution of blood to the coronary and cerebral circulation

      Explanation:

      Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (α1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a β1 and β2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
      – Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
      – Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal.

    • This question is part of the following fields:

      • Pathophysiology
      33.2
      Seconds
  • Question 26 - Which of the following statements about the central venous pressure (CVP) waveform is...

    Correct

    • Which of the following statements about the central venous pressure (CVP) waveform is true?

      Your Answer: Third degree heart block causes canon A waves

      Explanation:

      The central venous pressure (CVP) waveform depicts changes of pressure within the right atrium. Different parts of the waveform are:

      A wave: which represents atrial contraction. It is synonymous with the P wave seen during an ECG. It is often eliminated in the presence of atrial fibrillation, and increased tricuspid stenosis, pulmonary stenosis and pulmonary hypertension.

      C wave: which represents right ventricle contraction at the point where the tricuspid valve bulges into the right atrium. It is synonymous with the QRS complex seen on ECG.

      X descent: which represents relaxation of the atrial diastole and a decrease in atrial pressure, due to the downward movement of the right ventricle as it contracts. It is synonymous with the point before the T wave on ECG.

      V wave: which represents an increase in atrial pressure just before the opening of the tricuspid valve. It is synonymous with the point after the T wave on ECG. It is increased in the background of a tricuspid regurgitation.

      Y descent: which represents the emptying of the atrium as the tricuspid valve opens to allow for blood flow into the ventricle in early diastole.

      Canon waves: which refer to large waves present on the trace that do not correspond to the A, V or C waves. They usually occur in a background of complete heart blocks or junctional arrythmias.

    • This question is part of the following fields:

      • Clinical Measurement
      29.3
      Seconds
  • Question 27 - Prior to rapid sequence induction of anaesthesia, a man with a BMI of...

    Correct

    • Prior to rapid sequence induction of anaesthesia, a man with a BMI of 35 is pre-oxygenated. Which method of pre-oxygenation with a tight-fitting face mask is the most effective?

      Your Answer: Oxygen 6 litres per minute via a Mapleson A breathing system, with patient sitting up at 30 degrees breathing four vital capacity breaths

      Explanation:

      This patient is morbidly obese and has a high risk of developing hypoxia. This will be exacerbated by the patient’s supine position, as a result of:

      Functional residual capacity has been reduced (FRC)
      Increased closing capacity (CC)
      Reduced tidal volume due to increased airway resistance, decreased thoracic cage compliance, and decreased respiratory muscle strength and endurance
      Following induction of general anaesthesia, there is a tendency for atelectasis and increased O2 consumption due to the increased workload of respiratory muscles and the overall increase in metabolism.

      Pre-oxygenation with 100 percent oxygen via a tight-fitting mask can be done using either tidal volume breaths for three to five minutes or four vital capacity breaths in normal circumstances. In the head-up position, this patient is much more likely to be adequately pre-oxygenated, maximising the FRC and minimising the CC. In spontaneously breathing patients, the Mapleson A and circle systems are both effective, but the Mapleson D requires 160-200 ml/kg/minute to prevent rebreathing.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      19.3
      Seconds
  • Question 28 - Regarding the classification of breathing systems, which of the following is true? ...

    Correct

    • Regarding the classification of breathing systems, which of the following is true?

      Your Answer: The Conway classification describes a functional classification based on whether a CO2 absorber is required

      Explanation:

      Breathing system is an assembly of components which connects patient’s airway to anaesthesia machine through which controlled composition of gas mixture is dispensed. It delivers gas to the patient, removes expired gas and controls the temperature and humidity of the inspired mixture. It allows spontaneous, controlled, or assisted respiration. It may also provide ports for gas sampling, airway pressure, flow and volume monitoring.

      Breathing systems have been classified by Conway and Mapleson.
      Conway suggested a functional classification:
      – Circuits requiring a CO2 absorber
      – Circuits not requiring a CO2 absorber

      William Mapleson designated varying arrangements of breathing system components (masks, breathing tubes, fresh gas flow inlets, adjustable pressure-limiting valves, and reservoir bags) as Mapleson A-E circuits.
      Mapleson A: Arranged as FGF inlet, reservoir bag, APL valve, mask.
      In this circuit, because the reservoir bag is between the FGF inlet valve and the APL valve, expired gas from the patient may re-enter the system and fill the reservoir bag during controlled ventilation. This is the most efficient system for spontaneous breathing as the FGF must only be equal to a patient’s minute ventilation to prevent rebreathing.

      Mapleson B: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the FGF inlet is closer to the APL valve, which helps prevent the rebreathing concern in the Mapleson A circuit as above during controlled ventilation.

      Mapleson C: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the arrangement is the same as the Mapleson B circuit. However, this circuit is shorter as it does not contain elongated corrugated tubing. This circuit also has the FGF inlet close to the APL valve to aid in preventing rebreathing.

      Mapleson D: Arranged as reservoir bag, APL valve, FGF inlet, and mask.
      In this circuit, the arrangement interchanges the FGF inlet and APL valve of the Mapleson A circuit. This system prevents rebreathing by directing FGF towards the APL valve rather than towards the patient during exhalation.

      Mapleson E: Arranged as corrugated tubing, FGF inlet, and mask.
      In this circuit, there is no reservoir bag and no APL valve. Given the inability to alter the pressure of the circuit, this is ideal for spontaneously ventilating neonates or paediatric patients where low-pressure ventilation is desired. The system prevents rebreathing, similar to the Mapleson D circuit.

      Jackson Rees later modified the Mapleson E by adding an open ended bag, which has since become known as the Mapleson F.
      Mapleson F: Arranged as APL valve directly connected to reservoir bag, corrugated tubing, FGF inlet, and mask.
      The system prevents rebreathing similarly to Mapleson D by directing FGF towards the APL valve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      20
      Seconds
  • Question 29 - What is the order of the anatomical components of the tracheobronchial tree from...

    Correct

    • What is the order of the anatomical components of the tracheobronchial tree from proximal to distal?

      Your Answer: Bronchioles, terminal bronchioles, respiratory bronchioles, alveolar ducts, alveolar sacs

      Explanation:

      The tracheobronchial tree is subdivided into the conducting and the respiratory zones.

      The zones from proximal to distal are:

      Trachea
      Bronchi
      Bronchioles
      Terminal bronchioles
      Respiratory bronchioles
      Alveolar ducts
      Alveolar sacs

      from the trachea to terminal bronchioles are the conducting zone while the respiratory zone is from the respiratory bronchioles to the alveola sacs.

    • This question is part of the following fields:

      • Anatomy
      24.8
      Seconds
  • Question 30 - Which of the following is not used in the treatment of Neuroleptic Malignant...

    Incorrect

    • Which of the following is not used in the treatment of Neuroleptic Malignant Syndrome?

      Your Answer: Bromocriptine

      Correct Answer: Olanzapine

      Explanation:

      The neuroleptic malignant syndrome (NMS) is a rare complication in response to neuroleptic or antipsychotic medication.

      The main features are:
      – Elevated creatinine kinase
      – Hyperthermia and tachycardia
      – Altered mental state
      – Increased white cell count
      – Insidious onset over 1-3 days
      – Extrapyramidal dysfunction (muscle rigidity, tremor, dystonia)
      – Autonomic dysfunction (Labile blood pressure, sweating, salivation, urinary incontinence)

      Management is supportive of ICU care, anticholinergic drugs, increasing dopaminergic activity with Amantadine, L-dopa, and dantrolene, and non- depolarising neuromuscular blockade drugs.

      Since Olanzapine is a potential cause of NMS it is not a treatment.

    • This question is part of the following fields:

      • Pharmacology
      9.8
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Pharmacology (1/3) 33%
Anaesthesia Related Apparatus (5/7) 71%
Physiology And Biochemistry (2/2) 100%
Physiology (2/4) 50%
Statistical Methods (1/2) 50%
Anatomy (5/6) 83%
Pathophysiology (3/4) 75%
Clinical Measurement (2/2) 100%
Passmed