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  • Question 1 - A 55-year-old man visits his general practitioner complaining of pain in the back...

    Incorrect

    • A 55-year-old man visits his general practitioner complaining of pain in the back of his leg. The doctor suspects a sciatic nerve injury.

      During the examination, which reflexes are expected to be absent?

      Your Answer: Tibial nerve reflex

      Correct Answer: Ankle reflex

      Explanation:

      When the sciatic nerve is damaged, the reflexes in the ankle and plantar areas are lost, but the knee jerk reflex remains intact. This can cause pain and numbness in the back of the leg. If the damage occurs at the pelvic outlet, the ability to flex the knee may be lost, but the knee jerk reflex will still be present. During a neurological examination of the upper limb, the reflexes in the biceps, brachioradialis, and triceps are tested. Additionally, the sural and tibial nerve reflexes are cutaneous reflexes that are activated during walking.

      Understanding Sciatic Nerve Lesion

      The sciatic nerve is a major nerve that is supplied by the L4-5, S1-3 vertebrae and divides into the tibial and common peroneal nerves. It is responsible for supplying the hamstring and adductor muscles. When the sciatic nerve is damaged, it can result in a range of symptoms that affect both motor and sensory functions.

      Motor symptoms of sciatic nerve lesion include paralysis of knee flexion and all movements below the knee. Sensory symptoms include loss of sensation below the knee. Reflexes may also be affected, with ankle and plantar reflexes lost while the knee jerk reflex remains intact.

      There are several causes of sciatic nerve lesion, including fractures of the neck of the femur, posterior hip dislocation, and trauma.

    • This question is part of the following fields:

      • Neurological System
      12.5
      Seconds
  • Question 2 - A 25-year-old male is brought in after a possible heroin overdose. His friend...

    Correct

    • A 25-year-old male is brought in after a possible heroin overdose. His friend discovered him on the floor of his apartment, where he may have been for a full day. The patient is groggy but responsive and reports experiencing muscle soreness. The medical team suspects rhabdomyolysis and wants to conduct a blood test to assess muscle damage. What specific blood test would be helpful in this evaluation?

      Your Answer: Creatine kinase

      Explanation:

      Rhabdomyolysis: Causes and Consequences

      Rhabdomyolysis is a serious medical condition that occurs when muscle cells break down and release their contents into the interstitial space. This can lead to a range of symptoms, including muscle pain and weakness, hyperkalemia, hyperphosphatemia, hypocalcemia, hyperuricemia, and brown discoloration of the urine. In severe cases, rhabdomyolysis can cause cardiac arrhythmias, renal failure, and disseminated intravascular coagulation (DIC).

      There are many different factors that can trigger rhabdomyolysis, including crush injuries, toxic damage, drugs and medications, severe electrolyte disturbances, reduced blood supply, ischemia, electric shock, heat stroke, and burns. One of the key diagnostic markers for rhabdomyolysis is elevated levels of creatine kinase in the blood.

      Treatment may involve addressing the underlying cause of the muscle breakdown, managing electrolyte imbalances, and providing supportive care to prevent complications. By the causes and consequences of rhabdomyolysis, individuals can take steps to protect their health and seek prompt medical attention if necessary.

    • This question is part of the following fields:

      • Clinical Sciences
      5.6
      Seconds
  • Question 3 - What is the name of the protozoal infection that results in chronic diarrhoea,...

    Incorrect

    • What is the name of the protozoal infection that results in chronic diarrhoea, bloating, and weight loss, and is treated with metronidazole?

      Your Answer: Cryptosporidium sp.

      Correct Answer: Giardia lamblia

      Explanation:

      Protozoan Infections of the Gastrointestinal Tract

      Giardiasis is a gastrointestinal condition caused by the ingestion of water contaminated with cysts of the protozoan Giardia lamblia. This protozoan can exist in two forms, an inactive cyst form used for transmission and an active trophozoite form. Once ingested, Giardia invades the duodenal enterocytes and resides there, occasionally shedding cysts into the stool. The symptoms of giardiasis can mimic many other gastrointestinal conditions, including Coeliac disease, and may only be diagnosed by biopsy during endoscopy. Treatment for giardiasis involves the use of metronidazole.

      Cryptosporidium is another protozoan that can cause gastrointestinal symptoms, but only in immunocompromised individuals. Entamoeba histolytica, on the other hand, causes colitis with bloody diarrhoea and can lead to liver abscesses if it invades through to the portal vein. Treatment for Entamoeba histolytica involves the use of metronidazole and iodoquinol to clear colonisation in the liver.

      Schistosoma species are not protozoa, but rather helminths that cause schistosomiasis. This condition can manifest in various ways, including intestinal, liver, and pulmonary symptoms.

    • This question is part of the following fields:

      • Microbiology
      7
      Seconds
  • Question 4 - A 35-year-old woman is 16 weeks pregnant and is considering prenatal testing. Due...

    Correct

    • A 35-year-old woman is 16 weeks pregnant and is considering prenatal testing. Due to her age, she is concerned about the possibility of her child having Down syndrome. She undergoes chorionic villus sampling and the sample of chorionic villi is sent to the lab. They use PCR to aid analysis.

      Which of these techniques would be used?

      Your Answer: Denaturation, annealing and elongation of DNA

      Explanation:

      To amplify desired fragments of DNA, Polymerase Chain Reaction (PCR) utilizes denaturation, annealing, and elongation. The process involves heating to denature the double helix, primer hybridization, and elongation by polymerase enzymes for analysis. Reverse transcriptase PCR is a technique used to amplify RNA segments, which involves converting RNA to DNA using reverse transcriptase enzymes before analysis. Gene probe creation is a technique used for tests like fluorescence in situ hybridization (FISH) to view changes within chromosomes by causing gene segments to fluoresce when bound to a special probe. However, it is not typically used for Down syndrome testing, which is better suited for PCR. Foetal cell culture is another technique used for prenatal diagnosis in some cases.

      Reverse Transcriptase PCR

      Reverse transcriptase PCR (RT-PCR) is a molecular genetic technique used to amplify RNA. This technique is useful for analyzing gene expression in the form of mRNA. The process involves converting RNA to DNA using reverse transcriptase. The resulting DNA can then be amplified using PCR.

      To begin the process, a sample of RNA is added to a test tube along with two DNA primers and a thermostable DNA polymerase (Taq). The mixture is then heated to almost boiling point, causing denaturing or uncoiling of the RNA. The mixture is then allowed to cool, and the complimentary strands of DNA pair up. As there is an excess of the primer sequences, they preferentially pair with the DNA.

      The above cycle is then repeated, with the amount of DNA doubling each time. This process allows for the amplification of the RNA, making it easier to analyze gene expression. RT-PCR is a valuable tool in molecular biology and has many applications in research, including the study of diseases and the development of new treatments.

    • This question is part of the following fields:

      • General Principles
      16.3
      Seconds
  • Question 5 - A 25-year-old fitness enthusiast visits his doctor to inquire about the effectiveness of...

    Correct

    • A 25-year-old fitness enthusiast visits his doctor to inquire about the effectiveness of arachidonic acid supplements in promoting muscle growth. He is a gym trainer and participates in national bodybuilding competitions. He has been researching the benefits of arachidonic acid supplementation in increasing lean body mass, strength, and endurance. He asks his doctor to provide more information about arachidonic acid and whether there is enough scientific evidence to support its use.

      The doctor explains that arachidonic acid is a polyunsaturated omega-6 fatty acid that is produced from phospholipase. Can you identify the enzyme that catalyzes the conversion of phospholipase to arachidonic acid?

      Your Answer: Phospholipase A2

      Explanation:

      Phospholipase A2 is responsible for the transformation of phospholipids into arachidonic acid.

      The conversion of lecithin to lysolecithin is facilitated by Phospholipase A1.

      Leukotrienes are produced from arachidonic acid through the action of Lipoxygenase.

      Protein kinase is an enzyme that adds phosphate groups to other proteins through a chemical process known as phosphorylation.

      Phospholipase plays a crucial role in the production of phosphatidic acid.

      Arachidonic Acid Metabolism: The Role of Leukotrienes and Endoperoxides

      Arachidonic acid is a fatty acid that plays a crucial role in the body’s inflammatory response. The metabolism of arachidonic acid involves the production of various compounds, including leukotrienes and endoperoxides. Leukotrienes are produced by leukocytes and can cause constriction of the lungs. LTB4 is produced before leukocytes arrive, while the rest of the leukotrienes (A, C, D, and E) cause lung constriction.

      Endoperoxides, on the other hand, are produced by the cyclooxygenase enzyme and can lead to the formation of thromboxane and prostacyclin. Thromboxane is associated with platelet aggregation and vasoconstriction, which can lead to thrombosis. Prostacyclin, on the other hand, has the opposite effect and can cause vasodilation and inhibit platelet aggregation.

      Understanding the metabolism of arachidonic acid and the role of these compounds can help in the development of treatments for inflammatory conditions and cardiovascular diseases.

    • This question is part of the following fields:

      • General Principles
      19.7
      Seconds
  • Question 6 - A 50-year-old male is admitted to the burns unit after being involved in...

    Incorrect

    • A 50-year-old male is admitted to the burns unit after being involved in a house fire. He presents with hypoxia, hypotension, and flushed red skin. The suspicion of cyanide toxicity arises, and treatment with intravenous hydroxocobalamin is initiated.

      What causes cyanide toxicity?

      Your Answer: Carboxyhemoglobinemia

      Correct Answer: Inhibits the mitochondrial enzyme cytochrome c oxidase

      Explanation:

      The inhibition of cytochrome c oxidase by cyanide can cause the mitochondrial electron transfer chain to stop functioning, leading to histotoxic hypoxia. Plastic fires can result in cyanide toxicity.

      Carbon monoxide poisoning can cause carboxyhemoglobinemia, which hinders the delivery of oxygen to the body by forming carboxyhemoglobin more readily than oxyhaemoglobin.

      Methemoglobinemia is a type of haemoglobin that contains ferric iron, which impairs the affinity for oxygen and can result in tissue hypoxia. It can be caused by genetic or acquired factors, such as the use of drugs like amyl nitrite.

      Paracetamol toxicity can lead to a depletion of glutathione stores.

      Fomepizole is a competitive inhibitor of alcohol dehydrogenase and can be used to treat methanol and ethylene glycol toxicity.

      Understanding Cyanide Poisoning

      Cyanide is a toxic substance that can be found in insecticides, photograph development, and metal production. When ingested, cyanide can inhibit the enzyme cytochrome c oxidase, which can lead to the cessation of the mitochondrial electron transfer chain. This can result in a range of symptoms, depending on the severity and duration of exposure.

      The presentation of cyanide poisoning can vary, but some classical features include brick-red skin and a smell of bitter almonds. Acute symptoms may include hypoxia, hypotension, headache, and confusion. Chronic exposure can lead to ataxia, peripheral neuropathy, and dermatitis.

      If someone is suspected of cyanide poisoning, supportive measures such as administering 100% oxygen should be taken immediately. Definitive treatment involves the use of hydroxocobalamin, which is given intravenously. A combination of inhaled amyl nitrite, intravenous sodium nitrite, and intravenous sodium thiosulfate may also be used.

      It is important to seek medical attention immediately if cyanide poisoning is suspected, as prompt treatment can be life-saving.

    • This question is part of the following fields:

      • General Principles
      7.6
      Seconds
  • Question 7 - A 23-year-old man is brought to the emergency department by his roommate after...

    Incorrect

    • A 23-year-old man is brought to the emergency department by his roommate after experiencing difficulty speaking and breathing for the past hour. The man had recently returned from a one-week vacation and had been feeling well. Before heading out for his regular Saturday football game, he had some homemade pineapple jam. The man has no significant medical history and has not been hospitalized recently. There is no significant family history. The attending physician recognizes the condition and begins treatment immediately. The emergency medicine resident explains the situation to the roommate. What is the most likely mechanism that has been affected in this patient?

      Your Answer: Formation of synaptic vesicles

      Correct Answer: Release of the acetylcholine at the neuromuscular junction

      Explanation:

      The symptoms presented by this man are consistent with a diagnosis of Clostridium botulinum toxicity, which occurs when contaminated food is ingested. The bacteria responsible for this condition, Clostridium botulinum, thrive in the anaerobic environment of home-canned food. The toxin produced by these bacteria prevents the release of acetylcholine at the neuromuscular junction, resulting in neuromuscular impairment.

      1: The Clostridium botulinum toxin does not affect the muscarinic or nicotinic acetylcholine receptors. Autoantibodies to the muscarinic receptors are responsible for the destruction of these receptors in myasthenia gravis.
      2: The spread of depolarization along the myelinated axon at the nodes of Ranvier is not affected by the Clostridium botulinum toxin.
      3: The influx of calcium ions into the presynaptic terminal through voltage-gated calcium channels triggers the release of neurotransmitter into the synaptic cleft. Autoantibodies to these calcium channels are responsible for the Lambert-Eaton myasthenic syndrome.
      4: The Clostridium botulinum toxin prevents the release of acetylcholine by cleaving the SNARE protein complex, which is necessary for the fusion of the pre-formed synaptic vesicles with the presynaptic membrane.
      5: The process of loading, docking, priming, fusion, and endocytosis of synaptic vesicles is not affected by the Clostridium botulinum toxin.

      Understanding Botulism: Causes, Symptoms, and Treatment

      Botulism is a rare but serious illness caused by the bacterium Clostridium botulinum. This gram-positive anaerobic bacillus produces botulinum toxin, a neurotoxin that blocks the release of acetylcholine, leading to flaccid paralysis and other symptoms. There are seven serotypes of the bacterium, labeled A-G. Botulism can result from eating contaminated food, particularly tinned food, or from intravenous drug use.

      The neurotoxin produced by Clostridium botulinum often affects bulbar muscles and the autonomic nervous system. Symptoms of botulism include diplopia, ataxia, and bulbar palsy. Patients are usually fully conscious with no sensory disturbance, but they experience flaccid paralysis.

      Treatment for botulism involves administering botulism antitoxin and providing supportive care. However, the antitoxin is only effective if given early, as once the toxin has bound, its actions cannot be reversed. Therefore, it is important to seek medical attention immediately if botulism is suspected.

    • This question is part of the following fields:

      • General Principles
      5.5
      Seconds
  • Question 8 - A 59-year-old man presents to the emergency department with pleuritic thoracic pain and...

    Incorrect

    • A 59-year-old man presents to the emergency department with pleuritic thoracic pain and fever. His medical history includes an inferior STEMI that occurred 3 weeks ago. During auscultation, a pericardial rub is detected, and his ECG shows diffuse ST segment elevation and PR segment depression. What is the complication of myocardial infarction that the patient is experiencing?

      Your Answer: Ventricular septal defect

      Correct Answer: Dressler syndrome

      Explanation:

      The patient’s symptoms strongly suggest Dressler syndrome, which is an autoimmune-related inflammation of the pericardium that typically occurs 2-6 weeks after a heart attack. This condition is characterized by fever, pleuritic pain, and diffuse ST elevation and PR depression on an electrocardiogram. A pleural friction rub can also be heard during a physical exam.

      While another heart attack is a possibility, the absence of diffuse ST elevation and the presence of a pleural friction rub make this diagnosis less likely.

      A left ventricular aneurysm would present with persistent ST elevation but no chest pain.

      Ventricular free wall rupture typically occurs 1-2 weeks after a heart attack and would present with acute heart failure due to cardiac tamponade, which is characterized by raised jugular venous pressure, pulsus paradoxus, and diminished heart sounds.

      A ventricular septal defect usually occurs within the first week and would present with acute heart failure and a pansystolic murmur.

      Myocardial infarction (MI) can lead to various complications, which can occur immediately, early, or late after the event. Cardiac arrest is the most common cause of death following MI, usually due to ventricular fibrillation. Cardiogenic shock may occur if a large part of the ventricular myocardium is damaged, and it is difficult to treat. Chronic heart failure may result from ventricular myocardium dysfunction, which can be managed with loop diuretics, ACE-inhibitors, and beta-blockers. Tachyarrhythmias, such as ventricular fibrillation and ventricular tachycardia, are common complications. Bradyarrhythmias, such as atrioventricular block, are more common following inferior MI. Pericarditis is common in the first 48 hours after a transmural MI, while Dressler’s syndrome may occur 2-6 weeks later. Left ventricular aneurysm and free wall rupture, ventricular septal defect, and acute mitral regurgitation are other complications that may require urgent medical attention.

    • This question is part of the following fields:

      • Cardiovascular System
      6.2
      Seconds
  • Question 9 - A 6-year-old girl presents to the emergency department with her parents, who are...

    Incorrect

    • A 6-year-old girl presents to the emergency department with her parents, who are concerned about her extremely swollen legs. The patient reports feeling fine and has no significant medical history.

      Upon examination, there is pitting edema that extends to the lower abdominal wall. Laboratory tests confirm hypoalbuminemia.

      A urine dipstick reveals ++++ proteinuria and no red blood cells.

      What is the probable result of electron microscopy of a renal biopsy?

      Your Answer: Thickening of the basement membrane

      Correct Answer: Effacement of podocyte foot processes

      Explanation:

      Effacement of podocyte foot processes is observed in minimal change disease on electron microscopy, indicating fusion of podocytes. This condition is the most common cause of nephrotic syndrome in children, which is characterized by hypoalbuminemia, edema, and marked proteinuria. Although normal glomerular architecture may be observed in minimal change disease when viewed with a light microscope, electron microscopy is necessary to detect the effacement of podocyte foot processes. Kimmelstiel-Wilson lesions are not a feature of minimal change disease, as they are commonly observed in diabetic nephropathy. Similarly, mesangial cell proliferation is not a hallmark of minimal change disease, as it is typically observed in membranoproliferative glomerulonephritis, which presents as a nephritic syndrome and is not consistent with the patient’s symptoms. Overall, minimal change disease is typically responsive to steroid treatment and has a favorable prognosis.

      Minimal change disease is a condition that typically presents as nephrotic syndrome, with children accounting for 75% of cases and adults accounting for 25%. While most cases are idiopathic, a cause can be found in around 10-20% of cases, such as drugs like NSAIDs and rifampicin, Hodgkin’s lymphoma, thymoma, or infectious mononucleosis. The pathophysiology of the disease involves T-cell and cytokine-mediated damage to the glomerular basement membrane, resulting in polyanion loss and a reduction of electrostatic charge, which increases glomerular permeability to serum albumin.

      The features of minimal change disease include nephrotic syndrome, normotension (hypertension is rare), and highly selective proteinuria, where only intermediate-sized proteins like albumin and transferrin leak through the glomerulus. Renal biopsy shows normal glomeruli on light microscopy, while electron microscopy shows fusion of podocytes and effacement of foot processes.

      Management of minimal change disease involves oral corticosteroids, which are effective in 80% of cases. For steroid-resistant cases, cyclophosphamide is the next step. The prognosis for the disease is generally good, although relapse is common. Roughly one-third of patients have just one episode, one-third have infrequent relapses, and one-third have frequent relapses that stop before adulthood.

    • This question is part of the following fields:

      • Renal System
      6.4
      Seconds
  • Question 10 - A 44-year-old heavy smoker presents with a productive cough and progressively worsening shortness...

    Incorrect

    • A 44-year-old heavy smoker presents with a productive cough and progressively worsening shortness of breath on exertion. The patient's spirometry results are forwarded to you in clinic for review.

      Tidal volume (TV) = 400 mL.
      Vital capacity (VC) = 3,300 mL.
      Inspiratory capacity (IC) = 2,600 mL.
      FEV1/FVC = 60%

      Body plethysmography is undertaken, demonstrating a residual volume (RV) of 1,200 mL.

      What is this patient's total lung capacity (TLC)?

      Your Answer: 3,300 mL

      Correct Answer: 4,500 mL

      Explanation:

      To calculate the total lung capacity, one can add the vital capacity and residual volume. For example, if the vital capacity is 3300 mL and the residual volume is 1200 mL, the total lung capacity would be 4500 mL. It is important to note that tidal volume, inspiratory capacity, and the FEV1/FVC ratio are other measurements related to lung function. Residual volume refers to the amount of air left in the lungs after a maximal exhalation, while total lung capacity refers to the volume of air in the lungs after a maximal inhalation.

      Understanding Lung Volumes in Respiratory Physiology

      In respiratory physiology, lung volumes can be measured to determine the amount of air that moves in and out of the lungs during breathing. The diagram above shows the different lung volumes that can be measured.

      Tidal volume (TV) refers to the amount of air that is inspired or expired with each breath at rest. In males, the TV is 500ml while in females, it is 350ml.

      Inspiratory reserve volume (IRV) is the maximum volume of air that can be inspired at the end of a normal tidal inspiration. The inspiratory capacity is the sum of TV and IRV. On the other hand, expiratory reserve volume (ERV) is the maximum volume of air that can be expired at the end of a normal tidal expiration.

      Residual volume (RV) is the volume of air that remains in the lungs after maximal expiration. It increases with age and can be calculated by subtracting ERV from FRC. Speaking of FRC, it is the volume in the lungs at the end-expiratory position and is equal to the sum of ERV and RV.

      Vital capacity (VC) is the maximum volume of air that can be expired after a maximal inspiration. It decreases with age and can be calculated by adding inspiratory capacity and ERV. Lastly, total lung capacity (TLC) is the sum of vital capacity and residual volume.

      Physiological dead space (VD) is calculated by multiplying tidal volume by the difference between arterial carbon dioxide pressure (PaCO2) and end-tidal carbon dioxide pressure (PeCO2) and then dividing the result by PaCO2.

    • This question is part of the following fields:

      • Respiratory System
      6.2
      Seconds
  • Question 11 - What is the most frequent reason for mesenteric infarction to occur? ...

    Incorrect

    • What is the most frequent reason for mesenteric infarction to occur?

      Your Answer: Acute on chronic thrombus of the superior mesenteric artery

      Correct Answer: Acute embolism affecting the superior mesenteric artery

      Explanation:

      Mesenteric infarcts can be caused by various factors such as prolonged atrial fibrillation, ventricular aneurysms, and post myocardial infarction.

      Understanding Mesenteric Vessel Disease

      Mesenteric vessel disease is a condition that affects the blood vessels supplying the intestines. It is primarily caused by arterial embolism, which can result in infarction of the colon. The most common type of mesenteric vessel disease is acute mesenteric embolus, which is characterized by sudden onset abdominal pain followed by profuse diarrhea. Other types include acute on chronic mesenteric ischemia, mesenteric vein thrombosis, and low flow mesenteric infarction.

      Diagnosis of mesenteric vessel disease involves serological tests such as WCC, lactate, CRP, and amylase, as well as CT angiography scanning in the arterial phase with thin slices. Management of the condition depends on the severity of symptoms, with overt signs of peritonism requiring laparotomy and mesenteric vein thrombosis being treated with medical management using IV heparin. In cases where surgery is necessary, limited resection of necrotic bowel may be performed with the aim of relooking laparotomy at 24-48 hours.

      The prognosis for mesenteric vessel disease is generally poor, with the best outlook being for acute ischaemia from an embolic event where surgery occurs within 12 hours. Survival rates may be as high as 50%, but this falls to 30% with treatment delay. It is important to seek medical attention promptly if symptoms of mesenteric vessel disease are present.

    • This question is part of the following fields:

      • Gastrointestinal System
      6.2
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  • Question 12 - A 30-year-old patient presents with complaints of recurrent bloody diarrhoea and symptoms of...

    Incorrect

    • A 30-year-old patient presents with complaints of recurrent bloody diarrhoea and symptoms of iritis. On examination, there is a painful nodular erythematous eruption on the shin and anal tags are observed. What diagnostic test would you recommend to confirm the diagnosis?

      Your Answer: Barium enema

      Correct Answer: Colonoscopy

      Explanation:

      Inflammatory Bowel Disease with Crohn’s Disease Suggestion

      The patient’s symptoms and physical examination suggest inflammatory bowel disease, with anal skin tags indicating a possible diagnosis of Crohn’s disease. Other symptoms consistent with this diagnosis include iritis and a skin rash that may be erythema nodosum. To confirm the diagnosis, a colonoscopy with biopsies would be the initial investigation. While serum ACE levels can aid in diagnosis, they are often elevated in conditions other than sarcoidosis.

      Overall, the patient’s symptoms and physical examination point towards inflammatory bowel disease, with Crohn’s disease as a possible subtype. Further testing is necessary to confirm the diagnosis and rule out other conditions.

    • This question is part of the following fields:

      • Rheumatology
      5.6
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  • Question 13 - Where is the area postrema located in the brain? A 16-year-old girl was...

    Incorrect

    • Where is the area postrema located in the brain? A 16-year-old girl was prescribed erythromycin for her severe acne, but after three days, she had to stop taking it due to severe nausea that made her unable to function.

      Your Answer: Cerebellum

      Correct Answer: Floor of the 4th ventricle

      Explanation:

      The vomiting process is initiated by the chemoreceptor trigger zone, which receives signals from various sources such as the gastrointestinal tract, hormones, and drugs. This zone is located in the area postrema, which is situated on the floor of the 4th ventricle in the medulla. It is noteworthy that the area postrema is located outside the blood-brain barrier. The nucleus of tractus solitarius, which is also located in the medulla, contains autonomic centres that play a role in the vomiting reflex. This nucleus receives signals from the chemoreceptor trigger zone. The vomiting centres in the brain receive inputs from different areas, including the gastrointestinal tract and the vestibular system of the inner ear.

      Vomiting is the involuntary act of expelling the contents of the stomach and sometimes the intestines. This is caused by a reverse peristalsis and abdominal contraction. The vomiting center is located in the medulla oblongata and is activated by receptors in various parts of the body. These include the labyrinthine receptors in the ear, which can cause motion sickness, the over distention receptors in the duodenum and stomach, the trigger zone in the central nervous system, which can be affected by drugs such as opiates, and the touch receptors in the throat. Overall, vomiting is a reflex action that is triggered by various stimuli and is controlled by the vomiting center in the brainstem.

    • This question is part of the following fields:

      • Neurological System
      5.5
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  • Question 14 - A 67-year-old female is hospitalized with acute pancreatitis. What factor would indicate a...

    Incorrect

    • A 67-year-old female is hospitalized with acute pancreatitis. What factor would indicate a poor prognosis?

      Your Answer: Calcium 2.8mmol/l

      Correct Answer: Glucose 15.8mmol/l

      Explanation:

      The Glasgow Prognostic Score is a useful tool for assessing the severity of acute pancreatitis. If three or more of the following criteria are present within the first 48 hours, it is likely that the patient is experiencing severe pancreatitis and should be referred to the High Dependency Unit or Intensive Care Unit. Conversely, if the score is less than three, severe pancreatitis is unlikely. The criteria include: age over 55 years, white blood cell count over 15 x 109/L, urea over 16 mmol/L, glucose over 10 mmol/L, pO2 less than 8 kPa (60 mm Hg), albumin less than 32 g/L, calcium less than 2 mmol/L, LDH over 600 units/L, and AST/ALT over 200 units. Based on these criteria, the only option that meets the threshold for severe pancreatitis is a glucose level of 15.8 mmol/L.

      Acute pancreatitis is a condition that is primarily caused by gallstones and alcohol consumption in the UK. However, there are other factors that can contribute to the development of this condition. A popular mnemonic used to remember these factors is GET SMASHED, which stands for gallstones, ethanol, trauma, steroids, mumps, autoimmune diseases, scorpion venom, hypertriglyceridaemia, hyperchylomicronaemia, hypercalcaemia, hypothermia, ERCP, and certain drugs. It is important to note that pancreatitis is seven times more common in patients taking mesalazine than sulfasalazine. CT scans can show diffuse parenchymal enlargement with oedema and indistinct margins in patients with acute pancreatitis.

    • This question is part of the following fields:

      • Gastrointestinal System
      7.3
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  • Question 15 - A 28-year-old athlete visits her GP with complaints of amenorrhea. She hasn't had...

    Correct

    • A 28-year-old athlete visits her GP with complaints of amenorrhea. She hasn't had her period for the past 6 months, and her pregnancy test came back negative. She had regular periods before and started menstruating at the age of 12. The patient has been undergoing rigorous training for marathons for the last 8 months. She doesn't have any fever or diarrhea, and there are no signs of hirsutism on examination.

      The blood test results show:

      - TSH: 2 mU/L (normal range: 0.4 – 4)
      - Free T4: 15 pmol/L (normal range: 9 – 25)
      - Free T3: 5.2 nmol/L (normal range: 3.5 – 7.8)
      - LH: <1 IU/L (normal range: 1-12)
      - FSH: <1 IU/L (normal range: 1-9)

      What is the most likely cause of her amenorrhea?

      Your Answer: Hypothalamic amenorrhoea

      Explanation:

      The patient is experiencing secondary amenorrhoea, which is indicative of hypothalamic amenorrhoea due to low-level gonadotrophins. This could be caused by the patient’s intensive training for marathons, as well as other risk factors such as stress and anorexia nervosa. Hyperthyroidism is unlikely as the patient does not exhibit any symptoms or abnormal thyroid function test results. Polycystic ovarian syndrome (PCOS) can be ruled out as the patient does not have hirsutism, a high BMI, or elevated LH and FSH levels. Pregnancy is also not a possibility as the patient’s test was negative and she does not exhibit any signs of pregnancy.

      Understanding Amenorrhoea: Causes, Investigations, and Management

      Amenorrhoea is a condition characterized by the absence of menstrual periods. It can be classified into two types: primary and secondary. Primary amenorrhoea occurs when menstruation fails to start by the age of 15 in girls with normal secondary sexual characteristics or by the age of 13 in girls with no secondary sexual characteristics. On the other hand, secondary amenorrhoea is the cessation of menstruation for 3-6 months in women with previously normal and regular menses or 6-12 months in women with previous oligomenorrhoea.

      The causes of amenorrhoea vary depending on the type. Primary amenorrhoea may be caused by gonadal dysgenesis, testicular feminization, congenital malformations of the genital tract, functional hypothalamic amenorrhoea, congenital adrenal hyperplasia, imperforate hymen, hypothalamic amenorrhoea, polycystic ovarian syndrome, hyperprolactinemia, premature ovarian failure, and thyrotoxicosis. Meanwhile, secondary amenorrhoea may be caused by stress, excessive exercise, PCOS, Sheehan’s syndrome, Asherman’s syndrome, and other underlying medical conditions.

      To diagnose amenorrhoea, initial investigations may include pregnancy tests, full blood count, urea & electrolytes, coeliac screen, thyroid function tests, gonadotrophins, prolactin, and androgen levels. Management of amenorrhoea involves treating the underlying cause. For primary amenorrhoea, it is important to investigate and treat any underlying cause. For secondary amenorrhoea, it is important to exclude pregnancy, lactation, and menopause and treat the underlying cause accordingly. Women with primary ovarian insufficiency due to gonadal dysgenesis may benefit from hormone replacement therapy to prevent osteoporosis and other complications.

      In conclusion, amenorrhoea is a condition that requires proper diagnosis and management. Understanding the causes and appropriate investigations can help in providing the necessary treatment and care for women experiencing this condition.

    • This question is part of the following fields:

      • Reproductive System
      5.9
      Seconds
  • Question 16 - A 67-year-old man is attending the urology clinic and receiving goserelin for his...

    Correct

    • A 67-year-old man is attending the urology clinic and receiving goserelin for his metastatic prostate cancer. Can you explain the drug's mechanism of action?

      Your Answer: Overstimulation of GnRH receptors

      Explanation:

      GnRH agonists used in the treatment of prostate cancer can paradoxically lead to lower LH levels in the long term. This is because chronic use of these agonists can result in overstimulation of GnRH receptors, which in turn disrupts endogenous hormonal feedback systems. While initially stimulating the production of LH/FSH and subsequent androgen production, chronic use of GnRH agonists can cause negative feedback to suppress the release of gonadotropins, resulting in a significant decrease in serum testosterone levels. This mechanism can be thought of as switching on to switch off. It is important to note that inhibiting the 5 alpha-reductase enzyme and relaxing prostatic smooth muscle are not mechanisms of action for GnRH agonists, but rather for other medications used in the treatment of prostate conditions.

      Prostate cancer management varies depending on the stage of the disease and the patient’s life expectancy and preferences. For localized prostate cancer (T1/T2), treatment options include active monitoring, watchful waiting, radical prostatectomy, and radiotherapy (external beam and brachytherapy). For localized advanced prostate cancer (T3/T4), options include hormonal therapy, radical prostatectomy, and radiotherapy. Patients may develop proctitis and are at increased risk of bladder, colon, and rectal cancer following radiotherapy for prostate cancer.

      In cases of metastatic prostate cancer, reducing androgen levels is a key aim of treatment. A combination of approaches is often used, including anti-androgen therapy, synthetic GnRH agonist or antagonists, bicalutamide, cyproterone acetate, abiraterone, and bilateral orchidectomy. GnRH agonists, such as Goserelin (Zoladex), initially cause a rise in testosterone levels before falling to castration levels. To prevent a rise in testosterone, anti-androgens are often used to cover the initial therapy. GnRH antagonists, such as degarelix, are being evaluated to suppress testosterone while avoiding the flare phenomenon. Chemotherapy with docetaxel is also an option for the treatment of hormone-relapsed metastatic prostate cancer in patients who have no or mild symptoms after androgen deprivation therapy has failed, and before chemotherapy is indicated.

    • This question is part of the following fields:

      • Renal System
      6.6
      Seconds
  • Question 17 - What could be a potential cause of metabolic acidosis? ...

    Incorrect

    • What could be a potential cause of metabolic acidosis?

      Your Answer: Vomiting

      Correct Answer: Poorly controlled diabetes

      Explanation:

      Acid-Base Imbalances in Different Medical Conditions

      Poorly controlled diabetes can cause the breakdown of fatty acids, leading to the production of ketones as an alternative energy source. However, an excess of ketones can result in metabolic acidosis due to their acidic nature. On the other hand, chronic obstructive pulmonary disease (COPD) and suffocation can cause the retention of carbon dioxide, leading to respiratory acidosis. In COPD, there may be a compensatory metabolic alkalosis. Voluntary hyperventilation can cause respiratory alkalosis due to the reduction of carbon dioxide. Vomiting can also lead to metabolic alkalosis. Diabetic ketoacidosis is a complication of type 1 diabetes that results in high blood sugar levels, ketone production, and acidosis.

      In summary, different medical conditions can cause acid-base imbalances in the body. It is important to identify the underlying cause of the imbalance to provide appropriate treatment.

    • This question is part of the following fields:

      • Basic Sciences
      6.2
      Seconds
  • Question 18 - A 75-year-old woman presents to the respiratory clinic with an 8-week history of...

    Correct

    • A 75-year-old woman presents to the respiratory clinic with an 8-week history of progressive dyspnoea and dry cough with occasional haemoptysis. She has been a heavy smoker for the past 30 years, smoking 50 cigarettes per day.

      During the examination, reduced air entry is noted in the right upper lung field. The patient appears cachectic with a BMI of 18kg/m². A chest x-ray is ordered, which reveals a rounded opacity in the apical region of the right lung.

      What are the most indicative ocular signs of this diagnosis?

      Your Answer: Partial ptosis and constricted pupil

      Explanation:

      The patient’s presentation of partial ptosis and constricted pupil is consistent with Horner’s syndrome. This is likely due to a Pancoast tumor in the apical region of the right lung, which can compress the sympathetic chain and cause a lack of sympathetic innervation. This results in partial ptosis, pupillary constriction, and anhidrosis. Complete ptosis and dilated pupil would be seen in traumatic oculomotor nerve palsy, while exophthalmos and dilated pupil are associated with Grave’s eye disease. Lid lag and normal pupil size are commonly seen in hyperthyroidism, but should not be confused with ptosis and Horner’s syndrome.

      Horner’s syndrome is a condition characterized by several features, including a small pupil (miosis), drooping of the upper eyelid (ptosis), a sunken eye (enophthalmos), and loss of sweating on one side of the face (anhidrosis). The cause of Horner’s syndrome can be determined by examining additional symptoms. For example, congenital Horner’s syndrome may be identified by a difference in iris color (heterochromia), while anhidrosis may be present in central or preganglionic lesions. Pharmacologic tests, such as the use of apraclonidine drops, can also be helpful in confirming the diagnosis and identifying the location of the lesion. Central lesions may be caused by conditions such as stroke or multiple sclerosis, while postganglionic lesions may be due to factors like carotid artery dissection or cluster headaches. It is important to note that the appearance of enophthalmos in Horner’s syndrome is actually due to a narrow palpebral aperture rather than true enophthalmos.

    • This question is part of the following fields:

      • Neurological System
      17.3
      Seconds
  • Question 19 - A 75-year-old man sustains a scaphoid bone fracture that is displaced. The medical...

    Incorrect

    • A 75-year-old man sustains a scaphoid bone fracture that is displaced. The medical team decides to use a screw to fix the fracture. What structure is located directly medial to the scaphoid?

      Your Answer: Pisiform

      Correct Answer: Lunate

      Explanation:

      The lunate is positioned towards the middle in the anatomical plane. Injuries that involve high velocity and result in scaphoid fractures may also lead to dislocation of the lunate.

      The scaphoid bone has various articular surfaces for different bones in the wrist. It has a concave surface for the head of the capitate and a crescentic surface for the lunate. The proximal end has a wide convex surface for the radius, while the distal end has a tubercle that can be felt. The remaining articular surface faces laterally and is associated with the trapezium and trapezoid bones. The narrow strip between the radial and trapezial surfaces and the tubercle gives rise to the radial collateral carpal ligament. The tubercle also receives part of the flexor retinaculum and is the only part of the scaphoid bone that allows for the entry of blood vessels. However, this area is commonly fractured and can lead to avascular necrosis.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
      7.5
      Seconds
  • Question 20 - A 65-year-old woman is admitted to the ICU with a multidrug-resistant urinary tract...

    Incorrect

    • A 65-year-old woman is admitted to the ICU with a multidrug-resistant urinary tract infection. She has a medical history of type 2 diabetes, hypertension, and a previous cerebrovascular accident. After three days, she experiences an altered sensorium and her urine output has been 100 ml over the past 12 hours. Her creatinine level has increased from 1 mg/dl to almost 5 mg/dl, and her blood pressure is currently 180/100 mmHg. The patient is currently taking amikacin, insulin, atorvastatin, atenolol, ramipril, and clopidogrel.

      Which medication, other than ramipril, should be discontinued for this patient?

      Your Answer: Insulin

      Correct Answer: Amikacin

      Explanation:

      The patient’s symptoms suggest that they may be experiencing acute kidney injury (AKI) as a result of a severe urinary tract infection and potential sepsis. It is important to note that ACE inhibitors such as ramipril should not be used in cases of AKI, and aminoglycosides like amikacin should also be discontinued. Beta-blockers like atenolol, on the other hand, are generally safe to use in AKI patients and may be preferred over ACE inhibitors and ARBs as antihypertensives. While statins like atorvastatin are generally safe in AKI, they can rarely cause rhabdomyolysis, which can worsen renal function and lead to renal failure. Therefore, patients who experience muscle pain should be evaluated further to rule out the possibility of rhabdomyolysis.

      Acute kidney injury (AKI) is a condition where there is a reduction in renal function following an insult to the kidneys. It was previously known as acute renal failure and can result in long-term impaired kidney function or even death. AKI can be caused by prerenal, intrinsic, or postrenal factors. Patients with chronic kidney disease, other organ failure/chronic disease, a history of AKI, or who have used drugs with nephrotoxic potential are at an increased risk of developing AKI. To prevent AKI, patients at risk may be given IV fluids or have certain medications temporarily stopped.

      The kidneys are responsible for maintaining fluid balance and homeostasis, so a reduced urine output or fluid overload may indicate AKI. Symptoms may not be present in early stages, but as renal failure progresses, patients may experience arrhythmias, pulmonary and peripheral edema, or features of uraemia. Blood tests such as urea and electrolytes can be used to detect AKI, and urinalysis and imaging may also be necessary.

      Management of AKI is largely supportive, with careful fluid balance and medication review. Loop diuretics and low-dose dopamine are not recommended, but hyperkalaemia needs prompt treatment to avoid life-threatening arrhythmias. Renal replacement therapy may be necessary in severe cases. Patients with suspected AKI secondary to urinary obstruction require prompt review by a urologist, and specialist input from a nephrologist is required for cases where the cause is unknown or the AKI is severe.

    • This question is part of the following fields:

      • Renal System
      7.6
      Seconds
  • Question 21 - A 56-year-old woman presents to the emergency department with colicky right upper quadrant...

    Incorrect

    • A 56-year-old woman presents to the emergency department with colicky right upper quadrant pain after consuming a fatty meal. She has a high body mass index (32 kg/m²) and no significant medical history. On examination, she exhibits tenderness in the right upper quadrant, but she is not feverish. The following laboratory results were obtained: Hb 136 g/L, Platelets 412* 109/L, WBC 8.9 * 109/L, Na+ 138 mmol/L, K+ 4.2 mmol/L, Urea 5.4 mmol/L, Creatinine 88 µmol/L, CRP 4 mg/L, Bilirubin 12 µmol/L, ALP 44 u/L, and ALT 34 u/L. Which cells are responsible for producing the hormone that is implicated in the development of the underlying condition?

      Your Answer: G cells

      Correct Answer: I cells

      Explanation:

      The correct answer is I cells, which are located in the upper small intestine. The patient is experiencing colicky pain in the right upper quadrant after consuming a fatty meal and has a high body mass index, suggesting a diagnosis of biliary colic. CCK is the primary hormone responsible for stimulating biliary contraction in response to a fatty meal, and it is secreted by I cells.

      Beta cells are an incorrect answer because they secrete insulin, which does not cause gallbladder contraction.

      D cells are also an incorrect answer because they secrete somatostatin, which inhibits various digestive processes but does not stimulate gallbladder contraction.

      G cells are another incorrect answer because they are located in the stomach and secrete gastrin, which can increase gastric motility but does not cause gallbladder contraction.

      Overview of Gastrointestinal Hormones

      Gastrointestinal hormones play a crucial role in the digestion and absorption of food. These hormones are secreted by various cells in the stomach and small intestine in response to different stimuli such as the presence of food, pH changes, and neural signals.

      One of the major hormones involved in food digestion is gastrin, which is secreted by G cells in the antrum of the stomach. Gastrin increases acid secretion by gastric parietal cells, stimulates the secretion of pepsinogen and intrinsic factor, and increases gastric motility. Another hormone, cholecystokinin (CCK), is secreted by I cells in the upper small intestine in response to partially digested proteins and triglycerides. CCK increases the secretion of enzyme-rich fluid from the pancreas, contraction of the gallbladder, and relaxation of the sphincter of Oddi. It also decreases gastric emptying and induces satiety.

      Secretin is another hormone secreted by S cells in the upper small intestine in response to acidic chyme and fatty acids. Secretin increases the secretion of bicarbonate-rich fluid from the pancreas and hepatic duct cells, decreases gastric acid secretion, and has a trophic effect on pancreatic acinar cells. Vasoactive intestinal peptide (VIP) is a neural hormone that stimulates secretion by the pancreas and intestines and inhibits acid secretion.

      Finally, somatostatin is secreted by D cells in the pancreas and stomach in response to fat, bile salts, and glucose in the intestinal lumen. Somatostatin decreases acid and pepsin secretion, decreases gastrin secretion, decreases pancreatic enzyme secretion, and decreases insulin and glucagon secretion. It also inhibits the trophic effects of gastrin and stimulates gastric mucous production.

      In summary, gastrointestinal hormones play a crucial role in regulating the digestive process and maintaining homeostasis in the gastrointestinal tract.

    • This question is part of the following fields:

      • Gastrointestinal System
      5.8
      Seconds
  • Question 22 - A 72-year-old retiree visits his doctor with a skin lesion on the back...

    Incorrect

    • A 72-year-old retiree visits his doctor with a skin lesion on the back of his right hand. The lesion appears as a red papulo-nodule with scaling and ulceration. After a biopsy, the diagnosis of cutaneous squamous cell carcinoma is confirmed.

      What histological findings are expected from the biopsy examination?

      Your Answer: Central invagination with a keratotic core

      Correct Answer: Keratin pearls

      Explanation:

      Keratin pearls are a characteristic finding in cutaneous squamous cell carcinomas on biopsy. Atypical melanocytes are typically found in melanomas, not squamous cell carcinoma. Central invagination with a keratotic core is more commonly seen in keratoacanthomas. Basal cell carcinomas are characterized by the proliferation of basaloid cells parallel to the long axis of the epidermis. Seborrheic keratosis, a benign proliferation of immature keratinocytes, is typically identified by small keratin-filled cysts and a well-demarcated lesion with a stuck-on appearance.

      Understanding Squamous Cell Carcinoma of the Skin

      Squamous cell carcinoma is a type of skin cancer that is commonly seen in individuals who have had excessive exposure to sunlight or have undergone psoralen UVA therapy. Other risk factors include actinic keratoses and Bowen’s disease, immunosuppression, smoking, long-standing leg ulcers, and genetic conditions. While metastases are rare, they may occur in 2-5% of patients.

      This type of cancer typically appears on sun-exposed areas such as the head and neck or dorsum of the hands and arms. The nodules are painless, rapidly expanding, and may have a cauliflower-like appearance. Bleeding may also occur in some cases.

      Treatment for squamous cell carcinoma involves surgical excision with margins of 4mm for lesions less than 20 mm in diameter and 6mm for larger tumors. Mohs micrographic surgery may be used in high-risk patients and in cosmetically important sites. Prognosis is generally good for well-differentiated tumors that are less than 20 mm in diameter and less than 2mm deep. However, poorly differentiated tumors that are larger than 20 mm in diameter and deeper than 4mm, as well as those associated with immunosuppression, have a poorer prognosis.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
      6.4
      Seconds
  • Question 23 - A 20-year-old man has a tonsillectomy due to recurrent acute tonsillitis. During recovery,...

    Correct

    • A 20-year-old man has a tonsillectomy due to recurrent acute tonsillitis. During recovery, he experiences a postoperative bleeding. Which vessel is the most probable cause of the bleeding?

      Your Answer: External palatine vein

      Explanation:

      If the external palatine vein is harmed during tonsillectomy, it can result in reactionary bleeding and is located adjacent to the tonsil.

      Tonsil Anatomy and Tonsillitis

      The tonsils are located in the pharynx and have two surfaces, a medial and lateral surface. They vary in size and are usually supplied by the tonsillar artery and drained by the jugulodigastric and deep cervical nodes. Tonsillitis is a common condition that is usually caused by bacteria, with group A Streptococcus being the most common culprit. It can also be caused by viruses. In some cases, tonsillitis can lead to the development of an abscess, which can distort the uvula. Tonsillectomy is recommended for patients with recurrent acute tonsillitis, suspected malignancy, or enlargement causing sleep apnea. The preferred technique for tonsillectomy is dissection, but it can be complicated by hemorrhage, which is the most common complication. Delayed otalgia may also occur due to irritation of the glossopharyngeal nerve.

    • This question is part of the following fields:

      • Cardiovascular System
      5.9
      Seconds
  • Question 24 - A 25-year-old male is undergoing treatment for a complex skin infection that has...

    Incorrect

    • A 25-year-old male is undergoing treatment for a complex skin infection that has not improved with flucloxacillin and vancomycin. You contact microbiology for advice on the best antimicrobial therapy, and they suggest daptomycin due to its effective coverage against gram-positive bacteria.

      What is the mechanism of action of this medication?

      Your Answer: Interferes with protein synthesis in gram positive bacteria

      Correct Answer: Interferes with the outer membrane of gram positive bacteria resulting in cell death

      Explanation:

      Daptomycin causes cell death in gram-positive bacteria by interfering with their outer membrane. Aminoglycosides are bactericidal antibiotics that bind to the 30s ribosome subunit, leading to the misreading of mRNA and the synthesis of abnormal peptides that accumulate intracellularly, ultimately resulting in cell death. Quinolones inhibit bacterial DNA from unwinding and duplicating by blocking DNA topoisomerase. Trimethoprim inhibits bacterial DNA synthesis by binding to dihydrofolate reductase and preventing the reduction of dihydrofolic acid (DHF) to tetrahydrofolic acid (THF), which is an essential precursor in the thymidine synthesis pathway. Terbinafine blocks the biosynthesis of ergosterol, a crucial component of fungal cell membranes, by inhibiting squalene epoxidase.

      The mechanism of action of antibiotics can be categorized into inhibiting cell wall formation, protein synthesis, DNA synthesis, and RNA synthesis. Beta-lactams such as penicillins and cephalosporins inhibit cell wall formation by blocking cross-linking of peptidoglycan cell walls. Antibiotics that inhibit protein synthesis include aminoglycosides, chloramphenicol, macrolides, tetracyclines, and fusidic acid. Quinolones, metronidazole, sulphonamides, and trimethoprim inhibit DNA synthesis, while rifampicin inhibits RNA synthesis.

    • This question is part of the following fields:

      • General Principles
      6.1
      Seconds
  • Question 25 - A 22-year-old man arrives at the emergency department with a stab wound on...

    Incorrect

    • A 22-year-old man arrives at the emergency department with a stab wound on the left side of his neck above the clavicle. Upon examination, there is no indication of damage to the pleura or any major blood vessels. However, a winged scapula is observed on the left side of his back, with the scapula protruding from the chest wall and the inferior angle pointing towards the midline. What nerve is responsible for this condition?

      Your Answer: Suprascapular nerve

      Correct Answer: Long thoracic nerve

      Explanation:

      The nerve responsible for a winged scapula is the long thoracic nerve, which originates from C5-7 and travels along the thorax to reach the serratus anterior muscle. Damage to this nerve can cause the scapula to lift off the thoracic wall and limit shoulder movement. Other nerves that can cause a winged scapula include the accessory nerve and dorsal scapular nerve. The transverse cervical nerve supplies the neck, the phrenic nerve supplies the diaphragm, the greater auricular nerve supplies the mandible and ear, and the suprascapular nerve supplies the shoulder muscles and joints.

      The Long Thoracic Nerve and its Role in Scapular Winging

      The long thoracic nerve is derived from the ventral rami of C5, C6, and C7, which are located close to their emergence from intervertebral foramina. It runs downward and passes either anterior or posterior to the middle scalene muscle before reaching the upper tip of the serratus anterior muscle. From there, it descends on the outer surface of this muscle, giving branches into it.

      One of the most common symptoms of long thoracic nerve injury is scapular winging, which occurs when the serratus anterior muscle is weakened or paralyzed. This can happen due to a variety of reasons, including trauma, surgery, or nerve damage. In addition to long thoracic nerve injury, scapular winging can also be caused by spinal accessory nerve injury (which denervates the trapezius) or a dorsal scapular nerve injury.

      Overall, the long thoracic nerve plays an important role in the function of the serratus anterior muscle and the stability of the scapula. Understanding its anatomy and function can help healthcare professionals diagnose and treat conditions that affect the nerve and its associated muscles.

    • This question is part of the following fields:

      • Neurological System
      6.6
      Seconds
  • Question 26 - A 27-year-old patient with anorexia nervosa has been admitted from home for nutritional...

    Correct

    • A 27-year-old patient with anorexia nervosa has been admitted from home for nutritional support. Following her initial oral feed, her phosphate level has decreased from 0.5 mmol/L to 0.1 mmol/L (reference range 0.7-1.4). What could be the reason for her hypophosphataemia?

      Your Answer: Phosphate enters the body's cells

      Explanation:

      Refeeding Syndrome

      Refeeding syndrome is a potentially fatal condition that can occur after a prolonged period of fasting or poor nutritional intake followed by a meal high in carbohydrates. It is characterized by a rapid decrease in the serum levels of phosphate, potassium, and magnesium, all of which are already depleted in the body. This happens because glucose availability within the blood causes insulin secretion while glucagon secretion is reduced. Insulin stimulates glycogen, adipose and protein synthesis and enhances the action of the Na-K-ATPase pump in cell membranes, which draws glucose into the cells. Many minerals and cofactors are also drawn into the cells to support these metabolic processes.

      The condition is particularly dangerous for patients with starvation, anorexia nervosa, gastrointestinal conditions that impede adequate nutrition, and poor nutrition due to severe illness such as cancer cachexia. In healthy patients, phosphate ions enter the body’s cells under the influence of insulin after a meal, and the phosphate concentration in blood remains within the reference range. However, in patients with refeeding syndrome, a meal can stimulate marked phosphate entry into cells, causing profound hypophosphataemia. This can lead to cardiac arrhythmias and other life-threatening complications. Therefore, it is important to monitor patients at risk of refeeding syndrome closely and provide appropriate nutritional support to prevent this condition.

    • This question is part of the following fields:

      • Clinical Sciences
      5.4
      Seconds
  • Question 27 - A 12-year-old boy is brought to the emergency department by his mother after...

    Incorrect

    • A 12-year-old boy is brought to the emergency department by his mother after she found him having seizures. She reports that he has not eaten anything all day. The child is hyperventilating.

      Blood results reveal:
      - Low fasting glucose
      - High urea
      - Normal sodium
      - Normal potassium
      - High triglycerides
      - pH of 7.29

      Upon palpation of his abdomen, hepatomegaly is noted.

      An ultrasound scan of the abdomen shows enlarged kidneys.

      Based on these findings, what is the most likely diagnosis and underlying cause of this child's presentation?

      Your Answer: Lysosomal acid alpha-glucosidase deficiency

      Correct Answer: A defect in glucose-6-phosphatase

      Explanation:

      Glucose-6-phosphatase deficiency is the cause of Von Gierke’s disease. This condition is characterized by an inability to maintain adequate blood glucose levels during the post-absorptive hours of each day, which can lead to seizures due to hypoglycemia. Excessive lactate and urate generation also occur, resulting in hyperuricemia and organ damage. Children are typically diagnosed at 2 years of age and may present with hepatomegaly, hyperventilation, respiratory distress, vomiting, and other manifestations of hypoglycemia. Other enzyme deficiencies and their associated conditions include galactocerebrosidase deficiency in Krabbe’s disease, alpha-L iduronidase deficiency in Hurler’s disease, N-acetylglucosamine-1-phosphate transferase deficiency in Inclusion cell disease, lysosomal acid alpha-glucosidase deficiency in Pompe disease, Hexosaminidase A deficiency in Tay-Sachs disease, and alpha-galactosidase deficiency in Fabry’s disease.

      Inherited Metabolic Disorders: Types and Deficiencies

      Inherited metabolic disorders are a group of genetic disorders that affect the body’s ability to process certain substances. These disorders can be categorized into different types based on the specific substance that is affected. One type is glycogen storage disease, which is caused by deficiencies in enzymes involved in glycogen metabolism. This can lead to the accumulation of glycogen in various organs, resulting in symptoms such as hypoglycemia, lactic acidosis, and hepatomegaly.

      Another type is lysosomal storage disease, which is caused by deficiencies in enzymes involved in lysosomal metabolism. This can lead to the accumulation of various substances within lysosomes, resulting in symptoms such as hepatosplenomegaly, developmental delay, and optic atrophy. Examples of lysosomal storage diseases include Gaucher’s disease, Tay-Sachs disease, and Fabry disease.

      Finally, mucopolysaccharidoses are a group of disorders caused by deficiencies in enzymes involved in the breakdown of glycosaminoglycans. This can lead to the accumulation of these substances in various organs, resulting in symptoms such as coarse facial features, short stature, and corneal clouding. Examples of mucopolysaccharidoses include Hurler syndrome and Hunter syndrome.

      Overall, inherited metabolic disorders can have a wide range of symptoms and can affect various organs and systems in the body. Early diagnosis and treatment are important in managing these disorders and preventing complications.

    • This question is part of the following fields:

      • General Principles
      6.7
      Seconds
  • Question 28 - A 42-year-old man has been released from the hospital after receiving a liver...

    Incorrect

    • A 42-year-old man has been released from the hospital after receiving a liver transplant. As a preventive measure against graft-versus-host disease, he has been prescribed an immunosuppressant that forms a complex with FK506 binding protein (FKBP) and inhibits calcineurin phosphatase. What is the name of the medication that this patient is likely taking?

      Your Answer: Ciclosporin

      Correct Answer: Tacrolimus

      Explanation:

      Tacrolimus: An Immunosuppressant for Transplant Rejection Prevention

      Tacrolimus is an immunosuppressant drug that is commonly used to prevent transplant rejection. It belongs to the calcineurin inhibitor class of drugs and has a similar action to ciclosporin. The drug works by reducing the clonal proliferation of T cells by decreasing the release of IL-2. It binds to FKBP, forming a complex that inhibits calcineurin, a phosphatase that activates various transcription factors in T cells. This is different from ciclosporin, which binds to cyclophilin instead of FKBP.

      Compared to ciclosporin, tacrolimus is more potent, resulting in a lower incidence of organ rejection. However, it is also associated with a higher risk of nephrotoxicity and impaired glucose tolerance. Despite these potential side effects, tacrolimus remains an important drug in preventing transplant rejection and improving the success of organ transplantation.

    • This question is part of the following fields:

      • General Principles
      6.1
      Seconds
  • Question 29 - A 23-year-old female presents to the Emergency department with significant pain in her...

    Incorrect

    • A 23-year-old female presents to the Emergency department with significant pain in her right iliac region and slight vaginal bleeding. She reports having missed her period for the past seven weeks, despite previously having regular 28-day cycles. Upon examination, tenderness is noted in her lower abdomen near the site of pain. A quantitative urine pregnancy test is ordered to detect which hormone?

      Your Answer: Progesterone

      Correct Answer: β- human chorionic gonadotrophin

      Explanation:

      Pregnancy can be detected through urine tests that identify the beta subunit of the human chorionic gonadotrophin. This hormone increases during the first trimester of pregnancy to support progesterone production by the corpus luteum. Although the alpha subunit of this hormone is identical to that of other hormones, such as luteinising hormone, follicle stimulating hormone, and thyroid stimulating hormone, it is the beta subunit that is recognized and used as a marker for pregnancy. The pituitary gland secretes luteinising hormone and follicle stimulating hormone in all humans, but these hormones are not indicative of pregnancy.

      Understanding Ectopic Pregnancy: The Pathophysiology

      Ectopic pregnancy occurs when the fertilized egg implants outside the uterus, most commonly in the fallopian tube. In fact, 97% of ectopic pregnancies occur in the tubal region, with the majority in the ampulla. However, if the implantation occurs in the isthmus, it can be more dangerous. The remaining 3% of ectopic pregnancies can occur in the ovary, cervix, or peritoneum.

      During ectopic pregnancy, the trophoblast, which is the outer layer of cells that forms the placenta, invades the tubal wall. This invasion can cause bleeding, which may dislodge the embryo. The natural history of ectopic pregnancy includes absorption and tubal abortion, with the latter being the most common. In tubal abortion, the embryo is expelled from the tube, resulting in bleeding and pain. In tubal absorption, the tube may not rupture, and the blood and embryo may be shed or converted into a tubal mole and absorbed. However, if the tube ruptures, it can lead to severe bleeding and potentially life-threatening complications.

      In summary, understanding the pathophysiology of ectopic pregnancy is crucial in identifying and managing this potentially life-threatening condition. Early diagnosis and prompt treatment can help prevent complications and improve outcomes for affected individuals.

    • This question is part of the following fields:

      • Reproductive System
      7.2
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  • Question 30 - Which one of the following is not a tumor-inducing gene? ...

    Incorrect

    • Which one of the following is not a tumor-inducing gene?

      Your Answer: sis

      Correct Answer: Ki 67

      Explanation:

      Ki 67 is an immunohistochemical marker that indicates nuclear proliferation. While Ki67 positivity is indicative of malignancy, it is not an oncogene in and of itself.

      Oncogenes are genes that promote cancer and are derived from normal genes called proto-oncogenes. Proto-oncogenes play a crucial role in cellular growth and differentiation. However, a gain of function in oncogenes increases the risk of cancer. Only one mutated copy of the gene is needed for cancer to occur, making it a dominant effect. Oncogenes are responsible for up to 20% of human cancers and can become oncogenes through mutation, chromosomal translocation, or increased protein expression.

      In contrast, tumor suppressor genes restrict or repress cellular proliferation in normal cells. Their inactivation through mutation or germ line incorporation is implicated in various cancers, including renal, colonic, breast, and bladder cancer. Tumor suppressor genes, such as p53, offer protection by causing apoptosis of damaged cells. Other well-known genes include BRCA1 and BRCA2. Loss of function in tumor suppressor genes results in an increased risk of cancer, while gain of function in oncogenes increases the risk of cancer.

    • This question is part of the following fields:

      • General Principles
      8
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SESSION STATS - PERFORMANCE PER SPECIALTY

Neurological System (1/4) 25%
Clinical Sciences (2/2) 100%
Microbiology (0/1) 0%
General Principles (2/8) 25%
Cardiovascular System (1/2) 50%
Renal System (1/3) 33%
Respiratory System (0/1) 0%
Gastrointestinal System (0/3) 0%
Rheumatology (0/1) 0%
Reproductive System (1/2) 50%
Basic Sciences (0/1) 0%
Musculoskeletal System And Skin (0/2) 0%
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