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Question 1
Incorrect
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A 17-year-old female comes to the doctor's office. She had unprotected sex five days ago and is now five days into her pregnancy. At what stage is the fertilized tissue?
Your Answer: Trophoblast
Correct Answer: Blastocyst
Explanation:After the sperm penetrates the secondary oocyte, the germinal vesicle breakdown is stimulated by the LH surge, leading to the completion of meiosis and the formation of the first polar body. Following fertilization, pronuclear and zygote formation occur, followed by rapid cleavage, compaction, and polarization.
Around day 5, the blastocyst is formed, and implantation occurs between days 5 and 6. On day 1, the zygote is formed, and by late day 1, it reaches the 2-cell stage. The 4-cell stage is reached early on day 2, the 8-cell stage early on day 3, and the 16-cell stage late on day 3. The morula is formed on day 4, and the blastocyst is formed on day 5.
Embryology is the study of the development of an organism from the moment of fertilization to birth. During the first week of embryonic development, the fertilized egg implants itself into the uterine wall. By the second week, the bilaminar disk is formed, consisting of two layers of cells. The primitive streak appears in the third week, marking the beginning of gastrulation and the formation of the notochord.
As the embryo enters its fourth week, limb buds begin to form, and the neural tube closes. The heart also begins to beat during this time. By week 10, the genitals are differentiated, and the embryo exhibits intermittent breathing movements. These early events in embryonic development are crucial for the formation of the body’s major organs and structures. Understanding the timeline of these events can provide insight into the complex process of human development.
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This question is part of the following fields:
- General Principles
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Question 2
Correct
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A 32-year-old woman is 24 weeks pregnant and comes in for a routine check-up. She expresses her worries about how her pregnancy might impact her renal function, given her history of autosomal dominant polycystic kidney disease. Her baseline eGFR is 100 ml/min/1.73m2. What is the expected eGFR measurement at present?
Your Answer: 150ml/min/1.73m2
Explanation:During pregnancy, a woman’s body undergoes various physiological changes. The cardiovascular system experiences an increase in stroke volume, heart rate, and cardiac output, while systolic blood pressure remains unchanged and diastolic blood pressure decreases in the first and second trimesters before returning to normal levels by term. The enlarged uterus may cause issues with venous return, leading to ankle swelling, supine hypotension, and varicose veins.
The respiratory system sees an increase in pulmonary ventilation and tidal volume, with oxygen requirements only increasing by 20%. This can lead to a sense of dyspnea due to over-breathing and a fall in pCO2. The basal metabolic rate also increases, potentially due to increased thyroxine and adrenocortical hormones.
Maternal blood volume increases by 30%, with red blood cells increasing by 20% and plasma increasing by 50%, leading to a decrease in hemoglobin levels. Coagulant activity increases slightly, while fibrinolytic activity decreases. Platelet count falls, and white blood cell count and erythrocyte sedimentation rate rise.
The urinary system experiences an increase in blood flow and glomerular filtration rate, with elevated sex steroid levels leading to increased salt and water reabsorption and urinary protein losses. Trace glycosuria may also occur.
Calcium requirements increase during pregnancy, with gut absorption increasing substantially due to increased 1,25 dihydroxy vitamin D. Serum levels of calcium and phosphate may fall, but ionized calcium levels remain stable. The liver experiences an increase in alkaline phosphatase and a decrease in albumin levels.
The uterus undergoes significant changes, increasing in weight from 100g to 1100g and transitioning from hyperplasia to hypertrophy. Cervical ectropion and discharge may increase, and Braxton-Hicks contractions may occur in late pregnancy. Retroversion may lead to retention in the first trimester but usually self-corrects.
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This question is part of the following fields:
- Reproductive System
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Question 3
Incorrect
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Which type of cell makes up the majority of yellow bone marrow?
Your Answer: Megakaryocytes
Correct Answer: Adipocytes
Explanation:Anatomy of Bones and Bone Marrow
Bones are composed of two types of bone tissue: compact bone and cancellous bone. The medullary cavity is located within the cancellous bone and contains trabeculae. Blood vessels and bone marrow are also present within the cavity. The bone marrow is responsible for producing blood cells, with red marrow being the site of active haematopoiesis. Yellow marrow, on the other hand, is predominantly made up of adipocytes and fibroblasts.
Chondrocytes are specialized cells found in cartilage that secrete the collagen matrix. Fibroblasts also contribute to the extracellular matrix by secreting collagen. Haematopoietic stem cells are found in bone marrow and are the common ancestor of all haematologic cells. Megakaryocytes, which are also found in bone marrow, are the precursor to platelets. the anatomy of bones and bone marrow is crucial in their functions and the processes that occur within them.
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This question is part of the following fields:
- Clinical Sciences
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Question 4
Correct
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A 58-year-old male patient visits the gastroenterology clinic complaining of abdominal pain, weight loss, and diarrhoea for the past 6 months. During gastroscopy, a gastrinoma is discovered in the antrum of his stomach. What is the purpose of the hormone produced by this tumor?
Your Answer: It increases HCL production and increases gastric motility
Explanation:A tumor that secretes gastrin is known as a gastrinoma, which leads to an increase in both gastrointestinal motility and HCL production. It should be noted that while gastrin does increase gastric motility, it does not have an effect on the secretion of pancreatic fluid. This is instead regulated by hormones such as VIP, CCK, and secretin.
Overview of Gastrointestinal Hormones
Gastrointestinal hormones play a crucial role in the digestion and absorption of food. These hormones are secreted by various cells in the stomach and small intestine in response to different stimuli such as the presence of food, pH changes, and neural signals.
One of the major hormones involved in food digestion is gastrin, which is secreted by G cells in the antrum of the stomach. Gastrin increases acid secretion by gastric parietal cells, stimulates the secretion of pepsinogen and intrinsic factor, and increases gastric motility. Another hormone, cholecystokinin (CCK), is secreted by I cells in the upper small intestine in response to partially digested proteins and triglycerides. CCK increases the secretion of enzyme-rich fluid from the pancreas, contraction of the gallbladder, and relaxation of the sphincter of Oddi. It also decreases gastric emptying and induces satiety.
Secretin is another hormone secreted by S cells in the upper small intestine in response to acidic chyme and fatty acids. Secretin increases the secretion of bicarbonate-rich fluid from the pancreas and hepatic duct cells, decreases gastric acid secretion, and has a trophic effect on pancreatic acinar cells. Vasoactive intestinal peptide (VIP) is a neural hormone that stimulates secretion by the pancreas and intestines and inhibits acid secretion.
Finally, somatostatin is secreted by D cells in the pancreas and stomach in response to fat, bile salts, and glucose in the intestinal lumen. Somatostatin decreases acid and pepsin secretion, decreases gastrin secretion, decreases pancreatic enzyme secretion, and decreases insulin and glucagon secretion. It also inhibits the trophic effects of gastrin and stimulates gastric mucous production.
In summary, gastrointestinal hormones play a crucial role in regulating the digestive process and maintaining homeostasis in the gastrointestinal tract.
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This question is part of the following fields:
- Gastrointestinal System
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Question 5
Incorrect
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A 38-year-old man presents for a routine occupational health evaluation. He consumes 38 cans of 4% lager per week and has a history of Wernicke-Korsakoff syndrome 6 months ago. Which vitamin deficiency is most likely in this patient?
Your Answer: C
Correct Answer: B1
Explanation:The Importance of Vitamin B1 (Thiamine) in the Body
Vitamin B1, also known as thiamine, is a water-soluble vitamin that belongs to the B complex group. It plays a crucial role in the body as one of its phosphate derivatives, thiamine pyrophosphate (TPP), acts as a coenzyme in various enzymatic reactions. These reactions include the catabolism of sugars and amino acids, such as pyruvate dehydrogenase complex, alpha-ketoglutarate dehydrogenase complex, and branched-chain amino acid dehydrogenase complex.
Thiamine deficiency can lead to clinical consequences, particularly in highly aerobic tissues like the brain and heart. The brain can develop Wernicke-Korsakoff syndrome, which presents symptoms such as nystagmus, ophthalmoplegia, and ataxia. Meanwhile, the heart can develop wet beriberi, which causes dilated cardiomyopathy. Other conditions associated with thiamine deficiency include dry beriberi, which leads to peripheral neuropathy, and Korsakoff’s syndrome, which causes amnesia and confabulation.
The primary causes of thiamine deficiency are alcohol excess and malnutrition. Alcoholics are routinely recommended to take thiamine supplements to prevent deficiency. Overall, thiamine is an essential vitamin that plays a vital role in the body’s metabolic processes.
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This question is part of the following fields:
- General Principles
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Question 6
Incorrect
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A 64-year-old man comes in for a follow-up of his type 2 diabetes. Despite being on metformin therapy, his HbA1c levels are at 62mmol/mol. To address this, you plan to initiate sitagliptin for dual hypoglycemic therapy.
What is the mechanism of action of sitagliptin?Your Answer: Increases insulin secretion from the pancreas
Correct Answer: Decreases GLP-1 breakdown
Explanation:Sitagliptin, a DPP-4 inhibitor, reduces the breakdown of GLP-1 and GIP incretins, leading to increased levels of these hormones and potentiation of the incretin effect, which is typically reduced in diabetes.
Diabetes mellitus is a condition that has seen the development of several drugs in recent years. One hormone that has been the focus of much research is glucagon-like peptide-1 (GLP-1), which is released by the small intestine in response to an oral glucose load. In type 2 diabetes mellitus (T2DM), insulin resistance and insufficient B-cell compensation occur, and the incretin effect, which is largely mediated by GLP-1, is decreased. GLP-1 mimetics, such as exenatide and liraglutide, increase insulin secretion and inhibit glucagon secretion, resulting in weight loss, unlike other medications. They are sometimes used in combination with insulin in T2DM to minimize weight gain. Dipeptidyl peptidase-4 (DPP-4) inhibitors, such as vildagliptin and sitagliptin, increase levels of incretins by decreasing their peripheral breakdown, are taken orally, and do not cause weight gain. Nausea and vomiting are the major adverse effects of GLP-1 mimetics, and the Medicines and Healthcare products Regulatory Agency has issued specific warnings on the use of exenatide, reporting that it has been linked to severe pancreatitis in some patients. NICE guidelines suggest that a DPP-4 inhibitor might be preferable to a thiazolidinedione if further weight gain would cause significant problems, a thiazolidinedione is contraindicated, or the person has had a poor response to a thiazolidinedione.
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This question is part of the following fields:
- Endocrine System
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Question 7
Incorrect
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A 48-year-old man comes to a specialized medical center half a year after receiving a liver transplant. He has been feeling unwell for the past two weeks, experiencing chills, body aches, and discomfort. Additionally, he has noticed that his urine has become darker during this time. Upon examination, he appears to be visibly jaundiced.
Which type of cell is the primary culprit for his symptoms?Your Answer: Neutrophils
Correct Answer: Helper T cells
Explanation:Chronic organ rejection post-liver transplant is being experienced by this patient, which can be clinically diagnosed and is defined by the onset of symptoms six months after the transplant. The responsible cells for mediating acute and chronic organ rejection are Helper T cells, making it the correct answer. Cytotoxic T cells also play a role in mediating acute and chronic organ rejection.
B cells, on the other hand, mediate hyperacute organ rejection, which is not applicable to this patient as they are experiencing chronic organ rejection. Hyperacute organ rejection occurs within minutes of transplant and is caused by the presence of anti-donor antibodies in the recipient.
Macrophages do not have a role in organ rejection. Their functions include detecting, phagocytosing, and destroying bacteria and other pathogens.
Neutrophils are part of the innate immune response to bacterial and fungal pathogens, and their function is antimicrobial. They do not play a role in organ rejection.
The adaptive immune response involves several types of cells, including helper T cells, cytotoxic T cells, B cells, and plasma cells. Helper T cells are responsible for the cell-mediated immune response and recognize antigens presented by MHC class II molecules. They express CD4, CD3, TCR, and CD28 and are a major source of IL-2. Cytotoxic T cells also participate in the cell-mediated immune response and recognize antigens presented by MHC class I molecules. They induce apoptosis in virally infected and tumor cells and express CD8 and CD3. Both helper T cells and cytotoxic T cells mediate acute and chronic organ rejection.
B cells are the primary cells of the humoral immune response and act as antigen-presenting cells. They also mediate hyperacute organ rejection. Plasma cells are differentiated from B cells and produce large amounts of antibody specific to a particular antigen. Overall, these cells work together to mount a targeted and specific immune response to invading pathogens or abnormal cells.
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This question is part of the following fields:
- General Principles
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Question 8
Incorrect
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A 54-year-old woman has been diagnosed with hypertension following ABPM which showed her blood pressure to be 152/91 mmHg. She is curious about her condition and asks her GP to explain the physiology of blood pressure. Can you tell me where the baroreceptors that detect blood pressure are located in the body?
Your Answer: Hypothalamus
Correct Answer: Carotid sinus
Explanation:The carotid sinus, located just above the point where the internal and external carotid arteries divide, houses baroreceptors that sense the stretching of the artery wall. These baroreceptors are connected to the glossopharyngeal nerve (cranial nerve IX). The nerve fibers then synapse in the solitary nucleus of the medulla, which regulates the activity of sympathetic and parasympathetic neurons. This, in turn, affects the heart and blood vessels, leading to changes in blood pressure.
Similarly, the aortic arch also has baroreceptors that are connected to the aortic nerve. This nerve combines with the vagus nerve (X) and travels to the solitary nucleus.
In contrast, the carotid body, located near the carotid sinus, contains chemoreceptors that detect changes in the levels of oxygen and carbon dioxide in the blood.
The heart has four chambers and generates pressures of 0-25 mmHg on the right side and 0-120 mmHg on the left. The cardiac output is the product of heart rate and stroke volume, typically 5-6L per minute. The cardiac impulse is generated in the sino atrial node and conveyed to the ventricles via the atrioventricular node. Parasympathetic and sympathetic fibers project to the heart via the vagus and release acetylcholine and noradrenaline, respectively. The cardiac cycle includes mid diastole, late diastole, early systole, late systole, and early diastole. Preload is the end diastolic volume and afterload is the aortic pressure. Laplace’s law explains the rise in ventricular pressure during the ejection phase and why a dilated diseased heart will have impaired systolic function. Starling’s law states that an increase in end-diastolic volume will produce a larger stroke volume up to a point beyond which stroke volume will fall. Baroreceptor reflexes and atrial stretch receptors are involved in regulating cardiac output.
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This question is part of the following fields:
- Cardiovascular System
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Question 9
Incorrect
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Ella, a 69-year-old female, arrives at the emergency department with abrupt tearing abdominal pain that radiates to her back.
Ella has a medical history of hypertension, hypercholesterolemia, and diabetes. Her body mass index is 31 kg/m². She smokes 10 cigarettes a day.
The emergency physician orders an ECG and MRI, which confirm the diagnosis of an aortic dissection.
Which layer or layers of the aorta are impacted?Your Answer: Tear in tunica externa
Correct Answer: Tear in tunica intima
Explanation:An aortic dissection occurs when there is a tear in the innermost layer (tunica intima) of the aorta’s wall. This tear allows blood to flow into the space between the tunica intima and the middle layer (tunica media), causing pooling. The tear only affects the tunica intima layer and does not involve the outermost layer (tunica externa) or all three layers of the aortic wall.
Aortic dissection is a serious condition that can cause chest pain. It occurs when there is a tear in the inner layer of the aorta’s wall. Hypertension is the most significant risk factor, but it can also be associated with trauma, bicuspid aortic valve, and certain genetic disorders. Symptoms of aortic dissection include severe and sharp chest or back pain, weak or absent pulses, hypertension, and aortic regurgitation. Specific arteries’ involvement can cause other symptoms such as angina, paraplegia, or limb ischemia. The Stanford classification divides aortic dissection into type A, which affects the ascending aorta, and type B, which affects the descending aorta. The DeBakey classification further divides type A into type I, which extends to the aortic arch and beyond, and type II, which is confined to the ascending aorta. Type III originates in the descending aorta and rarely extends proximally.
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This question is part of the following fields:
- Cardiovascular System
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Question 10
Correct
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A 79-year-old male arrives at the emergency department with sudden onset right sided hemiparesis. He has a medical history of hypertension and reports no changes to his vision, speech or hearing.
What is the probable diagnosis?Your Answer: Lacunar infarct
Explanation:A lacunar stroke can lead to isolated hemiparesis, hemisensory loss, or hemiparesis with limb ataxia. In this case, the patient is experiencing isolated hemiparesis, which is likely caused by a lacunar infarct. Hypertension is strongly linked to this type of stroke.
Weber’s syndrome results in CN III palsy on the same side as the stroke and weakness in the opposite limb.
Nystagmus is a common symptom of Wallenberg syndrome.
Ipsilateral deafness is a common symptom of lateral pontine syndrome.
Stroke can affect different parts of the brain depending on which artery is affected. If the anterior cerebral artery is affected, the person may experience weakness and loss of sensation on the opposite side of the body, with the lower extremities being more affected than the upper. If the middle cerebral artery is affected, the person may experience weakness and loss of sensation on the opposite side of the body, with the upper extremities being more affected than the lower. They may also experience vision loss and difficulty with language. If the posterior cerebral artery is affected, the person may experience vision loss and difficulty recognizing objects.
Lacunar strokes are a type of stroke that are strongly associated with hypertension. They typically present with isolated weakness or loss of sensation on one side of the body, or weakness with difficulty coordinating movements. They often occur in the basal ganglia, thalamus, or internal capsule.
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This question is part of the following fields:
- Neurological System
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Question 11
Incorrect
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Which statement about agonists and antagonists is accurate?
Your Answer: A competitive antagonist leads to reduced binding of agonist, independent of the concentration of agonist
Correct Answer: A partial agonist has affinity but reduced efficacy
Explanation:Affinity and Efficacy in Pharmacology
In pharmacology, the terms affinity and efficacy are used to describe the relationship between a drug and its target receptor. Affinity refers to the strength of the binding between the drug and the receptor, while efficacy refers to the ability of the drug to activate the receptor and produce a response.
An agonist is a drug that binds to a receptor and activates it, producing a response. An agonist has both high affinity and high efficacy, meaning it binds strongly to the receptor and produces a strong response.
An antagonist, on the other hand, binds to the receptor but does not activate it, blocking the action of other agonists. An antagonist has high affinity but no efficacy, meaning it binds strongly to the receptor but does not produce a response.
A partial agonist is a drug that binds to the receptor and produces a response, but the response is weaker than that produced by a full agonist. A partial agonist has high affinity but reduced efficacy, meaning it binds strongly to the receptor but produces a weaker response.
the concepts of affinity and efficacy is important in drug development and in the effects of drugs on the body. By manipulating these properties, researchers can develop drugs that selectively target specific receptors and produce desired effects with minimal side effects.
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This question is part of the following fields:
- Pharmacology
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Question 12
Correct
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You are employed at a medical clinic. A 56-year-old male patient complains of a painful lump in the vicinity of his groin. After inspecting the lump, it is found to be situated superior and medial to the pubic tubercle.
What kind of hernia is probable in this case?Your Answer: Inguinal
Explanation:Inguinal hernias are situated above and towards the middle of the pubic tubercle. They are distinct from epigastric hernias, which occur in the epigastric region and not in the groin area. Femoral hernias, on the other hand, are located below and to the side of the pubic tubercle, unlike inguinal hernias. Hiatal hernias are found in the stomach and can cause symptoms such as heartburn. If there is a soft swelling near the belly button, it is more likely to be an umbilical hernia than a painful lump near the groin.
Understanding Inguinal Hernias
Inguinal hernias are the most common type of abdominal wall hernias, with 75% of cases falling under this category. They are more prevalent in men, with a 25% lifetime risk of developing one. The main symptom is a lump in the groin area, which disappears when pressure is applied or when the patient lies down. Discomfort and aching are also common, especially during physical activity. However, severe pain is rare, and strangulation is even rarer.
The traditional classification of inguinal hernias into indirect and direct types is no longer relevant in clinical management. Instead, the current consensus is to treat medically fit patients, even if they are asymptomatic. A hernia truss may be an option for those who are not fit for surgery, but it has limited use in other patients. Mesh repair is the preferred method, as it has the lowest recurrence rate. Unilateral hernias are usually repaired through an open approach, while bilateral and recurrent hernias are repaired laparoscopically.
After surgery, patients are advised to return to non-manual work after 2-3 weeks for open repair and 1-2 weeks for laparoscopic repair. Complications may include early bruising and wound infection, as well as late chronic pain and recurrence. It is important to seek medical attention if any of these symptoms occur.
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This question is part of the following fields:
- Gastrointestinal System
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Question 13
Incorrect
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As a junior doctor in a GP surgery, you are requested to examine an 82-year-old man who has reported a tremor in his left hand. What additional symptoms could indicate the presence of Parkinson's disease?
Your Answer: Reduced tone and ataxia
Correct Answer: Bradykinesia and rigidity
Explanation:Parkinson’s disease is characterized by three main symptoms: tremor at rest, bradykinesia, and rigidity. Nystagmus is not a typical feature of Parkinson’s disease, while chorea is more commonly associated with Huntington’s disease. Although ataxia may be present in Parkinson’s disease, it is more frequently seen in cases of cerebellar lesions.
Parkinson’s disease is a progressive neurodegenerative disorder that occurs due to the degeneration of dopaminergic neurons in the substantia nigra. This leads to a classic triad of symptoms, including bradykinesia, tremor, and rigidity, which are typically asymmetrical. The disease is more common in men and is usually diagnosed around the age of 65. Bradykinesia is characterized by a poverty of movement, shuffling steps, and difficulty initiating movement. Tremors are most noticeable at rest and typically occur in the thumb and index finger. Rigidity can be either lead pipe or cogwheel, and other features include mask-like facies, flexed posture, and drooling of saliva. Psychiatric features such as depression, dementia, and sleep disturbances may also occur. Diagnosis is usually clinical, but if there is difficulty differentiating between essential tremor and Parkinson’s disease, 123I‑FP‑CIT single photon emission computed tomography (SPECT) may be considered.
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This question is part of the following fields:
- Neurological System
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Question 14
Correct
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A 20-year-old man is admitted to the emergency department after being stabbed in the back. The knife has penetrated his spinal column at a perpendicular angle, causing damage to the termination of his spinal cord.
Which spinal level has been affected by the knife's penetration?Your Answer: L1
Explanation:In adults, the level of L1 is where the spinal cord usually ends.
Lumbar Puncture Procedure
Lumbar puncture is a medical procedure that involves obtaining cerebrospinal fluid. In adults, the procedure is typically performed at the L3/L4 or L4/5 interspace, which is located below the spinal cord’s terminates at L1.
During the procedure, the needle passes through several layers. First, it penetrates the supraspinous ligament, which connects the tips of spinous processes. Then, it passes through the interspinous ligaments between adjacent borders of spinous processes. Next, the needle penetrates the ligamentum flavum, which may cause a give. Finally, the needle passes through the dura mater into the subarachnoid space, which is marked by a second give. At this point, clear cerebrospinal fluid should be obtained.
Overall, the lumbar puncture procedure is a complex process that requires careful attention to detail. By following the proper steps and guidelines, medical professionals can obtain cerebrospinal fluid safely and effectively.
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This question is part of the following fields:
- Neurological System
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Question 15
Correct
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A 68-year-old man presents to an orthopedic surgeon with a two-month history of dull pain in his left knee that is worse at night and unresponsive to over-the-counter pain relievers. Both knees appear normal with no swelling, tendon or ligament abnormalities, and no limited range of motion. The patient has a history of Paget disease of the bone and takes alendronic acid. The orthopedic surgeon notes a Codman triangle on knee X-ray due to periosteum elevation. What is the most likely condition affecting this patient?
Your Answer: Osteosarcoma
Explanation:The presence of a Codman triangle on an X-ray is a strong indication of osteosarcoma, a bone tumor that can cause night pain and is unresponsive to analgesics. This condition is often associated with Paget disease of the bone, which increases the risk of developing osteosarcoma. Giant cell tumor is another bone tumor that can occur in young adults and has a characteristic ‘soap bubble’ appearance on X-ray. Osteochondroma is a common benign bone tumor that can rarely transform into a malignant chondrosarcoma. Osteoarthritis is a painful joint condition caused by mechanical destruction of the cartilage, often worsened by factors such as obesity and age. Treatment options for osteoarthritis include pain relief medication and joint replacement surgery.
Types of Bone Tumours
Benign and malignant bone tumours are two types of bone tumours. Benign bone tumours are non-cancerous and do not spread to other parts of the body. Osteoma is a benign overgrowth of bone that usually occurs on the skull and is associated with Gardner’s syndrome. Osteochondroma, the most common benign bone tumour, is a cartilage-capped bony projection on the external surface of a bone. Giant cell tumour is a tumour of multinucleated giant cells within a fibrous stroma that occurs most frequently in the epiphyses of long bones.
Malignant bone tumours are cancerous and can spread to other parts of the body. Osteosarcoma is the most common primary malignant bone tumour that mainly affects children and adolescents. It occurs most frequently in the metaphyseal region of long bones prior to epiphyseal closure. Ewing’s sarcoma is a small round blue cell tumour that mainly affects children and adolescents. It occurs most frequently in the pelvis and long bones and is associated with t(11;22) translocation. Chondrosarcoma is a malignant tumour of cartilage that most commonly affects the axial skeleton and is more common in middle-age.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 16
Incorrect
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A 27-year-old male presents to the neurology clinic with worsening epilepsy despite being on levetiracetam and sodium valproate. He has had 6 seizures in the past 2 weeks, with one requiring hospitalization. The neurology consultant suggests adding vigabatrin to his treatment regimen.
What is the mechanism of action of vigabatrin?Your Answer: Dopamine receptor antagonist
Correct Answer: Irreversible inhibitor of GABA transaminase
Explanation:Vigabatrin works by irreversibly inhibiting GABA transaminase, while haloperidol acts as a dopamine (D2) receptor antagonist. Cabergoline, on the other hand, is a dopamine receptor agonist, while benzodiazepines function as GABA receptor agonists. Flumazenil has not been specified in terms of its mechanism of action.
Vigabatrin and its potential impact on visual fields
Vigabatrin is a medication used to treat epilepsy and other seizure disorders. However, it is important to note that approximately 40% of patients who take this medication may develop visual field defects, which can potentially be irreversible. Therefore, it is crucial for patients taking vigabatrin to have their visual fields checked every six months to monitor any changes or potential damage. This precautionary measure can help ensure that any visual field defects are caught early and appropriate action can be taken to prevent further damage. It is important for patients to discuss any concerns or questions about vigabatrin and its potential impact on their vision with their healthcare provider.
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This question is part of the following fields:
- Neurological System
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Question 17
Incorrect
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A 19-year-old man presents to the acute medical team with symptoms of nausea and vomiting. He has a history of type 1 diabetes and has been feeling ill lately. Laboratory tests reveal diabetic ketoacidosis, and he is initiated on an insulin infusion. What is the receptor type targeted by this therapy?
Your Answer: Guanylate cyclase receptors
Correct Answer: Tyrosine kinase receptors
Explanation:The receptor tyrosine kinase in the cell membrane is bound by insulin.
Membrane receptors are proteins located on the surface of cells that receive signals from outside the cell and transmit them inside. There are four main types of membrane receptors: ligand-gated ion channel receptors, tyrosine kinase receptors, guanylate cyclase receptors, and G protein-coupled receptors. Ligand-gated ion channel receptors mediate fast responses and include nicotinic acetylcholine, GABA-A & GABA-C, and glutamate receptors. Tyrosine kinase receptors include receptor tyrosine kinase such as insulin, insulin-like growth factor (IGF), and epidermal growth factor (EGF), and non-receptor tyrosine kinase such as PIGG(L)ET, which stands for Prolactin, Immunomodulators (cytokines IL-2, Il-6, IFN), GH, G-CSF, Erythropoietin, and Thrombopoietin.
Guanylate cyclase receptors contain intrinsic enzyme activity and include atrial natriuretic factor and brain natriuretic peptide. G protein-coupled receptors generally mediate slow transmission and affect metabolic processes. They are activated by a wide variety of extracellular signals such as peptide hormones, biogenic amines (e.g. adrenaline), lipophilic hormones, and light. These receptors have 7-helix membrane-spanning domains and consist of 3 main subunits: alpha, beta, and gamma. The alpha subunit is linked to GDP. Ligand binding causes conformational changes to the receptor, GDP is phosphorylated to GTP, and the alpha subunit is activated. G proteins are named according to the alpha subunit (Gs, Gi, Gq).
The mechanism of G protein-coupled receptors varies depending on the type of G protein involved. Gs stimulates adenylate cyclase, which increases cAMP and activates protein kinase A. Gi inhibits adenylate cyclase, which decreases cAMP and inhibits protein kinase A. Gq activates phospholipase C, which splits PIP2 to IP3 and DAG and activates protein kinase C. Examples of G protein-coupled receptors include beta-1 receptors (epinephrine, norepinephrine, dobutamine), beta-2 receptors (epinephrine, salbuterol), H2 receptors (histamine), D1 receptors (dopamine), V2 receptors (vas
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This question is part of the following fields:
- General Principles
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Question 18
Incorrect
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A 10-year-old boy is recuperating the day after a tonsillectomy. His parents report that he hasn't had anything to eat for 6 hours prior to the surgery and he is feeling famished. However, he is declining any attempts to consume food or water. There are no prescribed medications or known drug allergies listed on his medical records.
What would be the most appropriate first step to take?Your Answer: Wait and review in 2 hours time
Correct Answer: Prescribe analgesia and encourage oral intake
Explanation:Effective pain management is crucial after a tonsillectomy to promote the consumption of food and fluids.
Prescribing analgesics and encouraging oral intake is the best course of action. This will alleviate pain and enable the patient to eat and drink, which is essential for a speedy recovery.
Starting maintenance fluids or partial nutritional feeds, obtaining IV access, or waiting for two hours before reviewing the patient are not the most appropriate options. Analgesia should be the primary consideration to facilitate oral fluid therapy and promote healing.
Tonsillitis and Tonsillectomy: Complications and Indications
Tonsillitis is a condition that can lead to various complications, including otitis media, peritonsillar abscess, and, in rare cases, rheumatic fever and glomerulonephritis. Tonsillectomy, the surgical removal of the tonsils, is a controversial procedure that should only be considered if the person meets specific criteria. According to NICE, surgery should only be considered if the person experiences sore throats due to tonsillitis, has five or more episodes of sore throat per year, has been experiencing symptoms for at least a year, and the episodes of sore throat are disabling and prevent normal functioning. Other established indications for a tonsillectomy include recurrent febrile convulsions, obstructive sleep apnoea, stridor, dysphagia, and peritonsillar abscess if unresponsive to standard treatment.
Despite the benefits of tonsillectomy, the procedure also carries some risks. Primary complications, which occur within 24 hours of the surgery, include haemorrhage and pain. Secondary complications, which occur between 24 hours to 10 days after the surgery, include haemorrhage (most commonly due to infection) and pain. Therefore, it is essential to weigh the benefits and risks of tonsillectomy before deciding to undergo the procedure.
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This question is part of the following fields:
- Respiratory System
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Question 19
Incorrect
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A 42-year-old man is found to have a right-sided colon cancer and a significant family history of colorectal and ovarian cancer. Upon genetic testing, he is diagnosed with hereditary non-polyposis colorectal cancer (HNPCC) caused by a mutation in the MSH2 gene. What is the role of this gene?
Your Answer: Apoptosis regulation
Correct Answer: DNA mismatch repair
Explanation:Colorectal cancer can be classified into three types: sporadic, hereditary non-polyposis colorectal carcinoma (HNPCC), and familial adenomatous polyposis (FAP). Sporadic colon cancer is believed to be caused by a series of genetic mutations, including allelic loss of the APC gene, activation of the K-ras oncogene, and deletion of p53 and DCC tumor suppressor genes. HNPCC, which is an autosomal dominant condition, is the most common form of inherited colon cancer. It is caused by mutations in genes involved in DNA mismatch repair, leading to microsatellite instability. The most common genes affected are MSH2 and MLH1. Patients with HNPCC are also at a higher risk of other cancers, such as endometrial cancer. The Amsterdam criteria are sometimes used to aid diagnosis of HNPCC. FAP is a rare autosomal dominant condition that leads to the formation of hundreds of polyps by the age of 30-40 years. It is caused by a mutation in the APC gene. Patients with FAP are also at risk of duodenal tumors. A variant of FAP called Gardner’s syndrome can also feature osteomas of the skull and mandible, retinal pigmentation, thyroid carcinoma, and epidermoid cysts on the skin. Genetic testing can be done to diagnose HNPCC and FAP, and patients with FAP generally have a total colectomy with ileo-anal pouch formation in their twenties.
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This question is part of the following fields:
- Gastrointestinal System
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Question 20
Correct
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A 27-year-old female patient complains of lower abdominal pain and dysuria for the past 5 days. Upon examination, her GP orders cultures which reveal visible organism growth on Thayer-Martin agar plate. What is the probable pathogen responsible for her symptoms?
Your Answer: Neisseria gonorrhoeae
Explanation:Neisseria gonorrhoeae is the correct answer. The growth of this organism on Thayer-Martin agar, a heated blood agar plate that inhibits the growth of contaminating bacteria and fungi, is indicative of a possible infection. Escherichia coli, Proteus mirabilis, and Pseudomonas aeruginosa are all potential causes of urinary symptoms, but they are not cultured using Thayer-Martin agar. Escherichia coli is cultured using MacConkey’s agar, while Proteus mirabilis and Pseudomonas aeruginosa are cultured using other types of agar.
Culture Requirements for Common Organisms
Different microorganisms require specific culture conditions to grow and thrive. The table above lists some of the culture requirements for the more common organisms. For instance, Neisseria gonorrhoeae requires Thayer-Martin agar, which is a variant of chocolate agar, and the addition of Vancomycin, Polymyxin, and Nystatin to inhibit Gram-positive, Gram-negative, and fungal growth, respectively. Haemophilus influenzae, on the other hand, grows on chocolate agar with factors V (NAD+) and X (hematin).
To remember the culture requirements for some of these organisms, some mnemonics can be used. For example, Nice Homes have chocolate can help recall that Neisseria and Haemophilus grow on chocolate agar. If I Tell-U the Corny joke Right, you’ll Laugh can be used to remember that Corynebacterium diphtheriae grows on tellurite agar or Loeffler’s media. Lactating pink monkeys can help recall that lactose fermenting bacteria, such as Escherichia coli, grow on MacConkey agar resulting in pink colonies. Finally, BORDETella pertussis can be used to remember that Bordetella pertussis grows on Bordet-Gengou (potato) agar.
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This question is part of the following fields:
- General Principles
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Question 21
Correct
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A 21-year-old patient visits the clinic after injuring their knee during a soccer game. During the examination, the physician flexes the knee to a 90-degree angle with the foot resting on the exam table. Using both hands to grasp the proximal tibia, the doctor applies an anterior force followed by a posterior force. The physician detects laxity during the anterior movement, indicating possible damage to the anterior cruciate ligament. What is the test called?
Your Answer: Drawer test
Explanation:The drawer test is used to check for cruciate ligament rupture in the knee. The examiner flexes the hip and knee, holds the tibia, and attempts to pull it forward or backward. Excessive displacement indicates a rupture of the anterior or posterior cruciate ligament.
Knee Injuries and Common Causes
Knee injuries can be caused by a variety of factors, including twisting injuries, dashboard injuries, skiing accidents, and lateral blows to the knee. One common knee injury is the unhappy triad, which involves damage to the anterior cruciate ligament, medial collateral ligament, and meniscus. While the medial meniscus is classically associated with this injury, recent evidence suggests that the lateral meniscus is actually more commonly affected.
When the anterior cruciate ligament is damaged, it may be the result of twisting injuries. Tests such as the anterior drawer test and Lachman test may be positive if this ligament is damaged. On the other hand, dashboard injuries may cause damage to the posterior cruciate ligament. Damage to the medial collateral ligament is often caused by skiing accidents or valgus stress, and can result in abnormal passive abduction of the knee. Isolated injury to the lateral collateral ligament is uncommon.
Finally, damage to the menisci can also occur from twisting injuries. Common symptoms of meniscus damage include locking and giving way. Overall, understanding the common causes and symptoms of knee injuries can help individuals seek appropriate treatment and prevent further damage.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 22
Correct
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A 94-year-old male, previously diagnosed with Parkinson's disease, passed away due to aspirational pneumonia and underwent a post-mortem examination. As part of the examination, a histological analysis of the basal ganglia was conducted. What types of inclusion bodies are anticipated to be observed?
Your Answer: Lewy bodies
Explanation:Lewy bodies are commonly associated with Parkinson’s disease, but they can also be present in other conditions. These bodies are characterized by the presence of neuromelanin pigment and are typically found in the remaining Dopaminergic neurons in the substantia nigra pars compacta (SNc). They can be identified through staining for various proteins, including a-synuclein and ubiquitin. While their exact function is not yet fully understood, it is believed that Lewy bodies may play a role in managing proteins that are not properly broken down due to protein dysfunction.
Parkinson’s disease is a progressive neurodegenerative disorder that occurs due to the degeneration of dopaminergic neurons in the substantia nigra. This leads to a classic triad of symptoms, including bradykinesia, tremor, and rigidity, which are typically asymmetrical. The disease is more common in men and is usually diagnosed around the age of 65. Bradykinesia is characterized by a poverty of movement, shuffling steps, and difficulty initiating movement. Tremors are most noticeable at rest and typically occur in the thumb and index finger. Rigidity can be either lead pipe or cogwheel, and other features include mask-like facies, flexed posture, and drooling of saliva. Psychiatric features such as depression, dementia, and sleep disturbances may also occur. Diagnosis is usually clinical, but if there is difficulty differentiating between essential tremor and Parkinson’s disease, 123I‑FP‑CIT single photon emission computed tomography (SPECT) may be considered.
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This question is part of the following fields:
- Neurological System
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Question 23
Incorrect
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In a 70 Kg person, what percentage of the entire body fluid will be provided by plasma?
Your Answer: 35%
Correct Answer: 5%
Explanation:Understanding the Physiology of Body Fluid Compartments
Body fluid compartments are essential components of the human body, consisting of intracellular and extracellular compartments. The extracellular compartment is further divided into interstitial fluid, plasma, and transcellular fluid. In a typical 70 Kg male, the intracellular compartment comprises 60-65% of the total body fluid volume, while the extracellular compartment comprises 35-40%. The plasma volume is approximately 5%, while the interstitial fluid volume is 24%. The transcellular fluid volume is approximately 3%. These figures are only approximate and may vary depending on the individual’s weight and other factors. Understanding the physiology of body fluid compartments is crucial in maintaining proper fluid balance and overall health.
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This question is part of the following fields:
- Renal System
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Question 24
Incorrect
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A 16-year-old boy presents to his GP with a 5-month history of passing frequent watery diarrhoea, up to 6 times a day. He reports occasional passage of mucus mixed with his stool and has experienced a weight loss of around 9kg. An endoscopy and biopsy are performed, revealing evidence of granuloma formation.
What is the probable diagnosis?Your Answer: Ulcerative colitis
Correct Answer: Crohn’s disease
Explanation:The presence of granulomas in the gastrointestinal tract is a key feature of Crohn’s disease, which is a chronic inflammatory condition that can affect any part of the digestive system. The combination of granulomas and clinical history is highly indicative of this condition.
Coeliac disease, on the other hand, is an autoimmune disorder triggered by gluten consumption that causes villous atrophy and malabsorption. However, it does not involve the formation of granulomas.
Colonic tuberculosis, caused by Mycobacterium tuberculosis, is another granulomatous condition that affects the ileocaecal valve. However, the granulomas in this case are caseating with necrosis, and colonic tuberculosis is much less common than Crohn’s disease.
Endoscopy and biopsy are not necessary for diagnosing irritable bowel syndrome, as they are primarily used to rule out other conditions. Biopsies in irritable bowel syndrome would not reveal granuloma formation.
Ulcerative colitis, another inflammatory bowel disease, is characterized by crypt abscesses, pseudopolyps, and mucosal ulceration that can cause rectal bleeding. However, granulomas are not present in this condition.
Inflammatory bowel disease (IBD) is a condition that includes two main types: Crohn’s disease and ulcerative colitis. Although they share many similarities in terms of symptoms, diagnosis, and treatment, there are some key differences between the two. Crohn’s disease is characterized by non-bloody diarrhea, weight loss, upper gastrointestinal symptoms, mouth ulcers, perianal disease, and a palpable abdominal mass in the right iliac fossa. On the other hand, ulcerative colitis is characterized by bloody diarrhea, abdominal pain in the left lower quadrant, tenesmus, gallstones, and primary sclerosing cholangitis. Complications of Crohn’s disease include obstruction, fistula, and colorectal cancer, while ulcerative colitis has a higher risk of colorectal cancer than Crohn’s disease. Pathologically, Crohn’s disease lesions can be seen anywhere from the mouth to anus, while ulcerative colitis inflammation always starts at the rectum and never spreads beyond the ileocaecal valve. Endoscopy and radiology can help diagnose and differentiate between the two types of IBD.
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This question is part of the following fields:
- Gastrointestinal System
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Question 25
Correct
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A 42-year-old woman visits her GP complaining of a hot and painful leg. Upon examination, the lower right limb shows a distinct area of erythema that is warm to the touch. The patient has no significant medical history and is not taking any medications, but has a penicillin allergy. The GP decides to prescribe clindamycin. What is the mechanism of action of this antibiotic?
Your Answer: Binds to the 50S subunit of the ribosome
Explanation:Clindamycin hinders bacterial protein synthesis by binding to the 50S subunit of the ribosome, leading to the eventual death of bacterial cells. Quinolone antibiotics, such as ciprofloxacin, prevent bacterial replication by inhibiting bacterial DNA gyrase, which is responsible for unwinding and duplicating bacterial DNA. Beta-lactam antibiotics, like penicillins and cephalosporins, impair the bacterial cell wall, causing damage that ultimately results in bacterial cell death. Trimethoprim inhibits bacterial dihydrofolate reductase, which reduces the amount of purines available for DNA synthesis within the bacteria, thereby reducing bacterial replication. Tetracyclines, on the other hand, inhibit the 30S subunit of bacterial ribosomes, which has a similar effect to inhibiting the 50S subunit, leading to reduced protein synthesis.
Antibiotics work in different ways to kill or inhibit the growth of bacteria. The commonly used antibiotics can be classified based on their gross mechanism of action. The first group inhibits cell wall formation by either preventing peptidoglycan cross-linking (penicillins, cephalosporins, carbapenems) or peptidoglycan synthesis (glycopeptides like vancomycin). The second group inhibits protein synthesis by acting on either the 50S subunit (macrolides, chloramphenicol, clindamycin, linezolid, streptogrammins) or the 30S subunit (aminoglycosides, tetracyclines) of the bacterial ribosome. The third group inhibits DNA synthesis (quinolones like ciprofloxacin) or damages DNA (metronidazole). The fourth group inhibits folic acid formation (sulphonamides and trimethoprim), while the fifth group inhibits RNA synthesis (rifampicin). Understanding the mechanism of action of antibiotics is important in selecting the appropriate drug for a particular bacterial infection.
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This question is part of the following fields:
- General Principles
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Question 26
Incorrect
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Which of the following explains the mechanism by which PTH increases serum calcium levels?
Your Answer: Vasospasm of the afferent renal arteriole thereby reducing GFR and calcium urinary loss.
Correct Answer: Activation of vitamin D to increase absorption of calcium from the small intestine.
Explanation:The activity of the 1-α-hydroxylase enzyme, which converts 25-hydroxycholecalciferol to 1,25-dihydroxycholecalciferol (the active form of vitamin D), is increased by PTH. Osteoblasts mediate the effects of PTH on osteoclasts, as osteoclasts do not have a PTH receptor.
Understanding Parathyroid Hormone and Its Effects
Parathyroid hormone is a hormone produced by the chief cells of the parathyroid glands. Its main function is to increase the concentration of calcium in the blood by stimulating the PTH receptors in the kidney and bone. This hormone has a short half-life of only 4 minutes.
The effects of parathyroid hormone are mainly seen in the bone, kidney, and intestine. In the bone, PTH binds to osteoblasts, which then signal to osteoclasts to resorb bone and release calcium. In the kidney, PTH promotes the active reabsorption of calcium and magnesium from the distal convoluted tubule, while decreasing the reabsorption of phosphate. In the intestine, PTH indirectly increases calcium absorption by increasing the activation of vitamin D, which in turn increases calcium absorption.
Overall, understanding the role of parathyroid hormone is important in maintaining proper calcium levels in the body. Any imbalances in PTH secretion can lead to various disorders such as hyperparathyroidism or hypoparathyroidism.
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This question is part of the following fields:
- Endocrine System
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Question 27
Incorrect
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A 45-year-old male has been diagnosed with Cushing's disease due to a pituitary adenoma, resulting in elevated plasma cortisol levels. Which part of the adrenal gland is responsible for producing cortisol hormone?
Your Answer: Adrenal chromaffin cells
Correct Answer: Zona fasciculata
Explanation:The adrenal gland comprises two primary parts: the cortex and medulla.
The adrenal medulla is accountable for the production of adrenaline and noradrenaline, which are catecholamines.
The adrenal cortex is divided into three layers: glomerulosa, fasciculata, and reticularis. The glomerulosa primarily produces mineralocorticoids, while the reticularis mainly produces sex steroids. As a result, the Zona fasciculata is the primary source of glucocorticosteroids.
Cortisol: Functions and Regulation
Cortisol is a hormone produced in the zona fasciculata of the adrenal cortex. It plays a crucial role in various bodily functions and is essential for life. Cortisol increases blood pressure by up-regulating alpha-1 receptors on arterioles, allowing for a normal response to angiotensin II and catecholamines. However, it inhibits bone formation by decreasing osteoblasts, type 1 collagen, and absorption of calcium from the gut, while increasing osteoclastic activity. Cortisol also increases insulin resistance and metabolism by increasing gluconeogenesis, lipolysis, and proteolysis. It inhibits inflammatory and immune responses, but maintains the function of skeletal and cardiac muscle.
The regulation of cortisol secretion is controlled by the hypothalamic-pituitary-adrenal (HPA) axis. The pituitary gland secretes adrenocorticotropic hormone (ACTH), which stimulates the adrenal cortex to produce cortisol. The hypothalamus releases corticotrophin-releasing hormone (CRH), which stimulates the pituitary gland to release ACTH. Stress can also increase cortisol secretion.
Excess cortisol in the body can lead to Cushing’s syndrome, which can cause a range of symptoms such as weight gain, muscle weakness, and high blood pressure. Understanding the functions and regulation of cortisol is important for maintaining overall health and preventing hormonal imbalances.
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This question is part of the following fields:
- Endocrine System
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Question 28
Incorrect
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A 30-year-old male refugee arrives at the emergency department complaining of night sweats and a productive cough that has been ongoing for 2 weeks. Upon performing a chest X-ray, signs of tuberculosis are detected. The patient is prescribed a combination of antibiotics, including rifampicin. How does rifampicin work to combat the bacteria's protein synthesis?
Your Answer: Inhibits 50s subunit
Correct Answer: Inhibits RNA polymerase
Explanation:Rifampin causes cell death by inhibiting DNA-dependent RNA polymerase, which leads to the suppression of RNA synthesis.
Rifampicin disrupts DNA synthesis by halting the action of RNA polymerase, resulting in the suppression of RNA synthesis and cell death.
Quinolones inhibit DNA gyrase to function.
Tetracyclines and aminoglycosides inhibit the 30s subunit to work.
Macrolides work by inhibiting the 50s subunit of bacteria, leading to their death.
Beta lactams, such as penicillin, disrupt cell wall synthesis to function.
Understanding Rifampicin: An Antibiotic for Treating Infections
Rifampicin is an antibiotic that is commonly used to treat various infections, including tuberculosis. It is often prescribed in combination with other medications to effectively combat the disease. Rifampicin can also be used as a prophylactic treatment for individuals who have been in close contact with tuberculosis or meningitis.
The mechanism of action of Rifampicin involves inhibiting bacterial DNA-dependent RNA polymerase, which prevents the transcription of DNA into mRNA. This action helps to stop the growth and spread of bacteria in the body.
However, Rifampicin is known to be a potent CYP450 liver enzyme inducer, which can cause hepatitis in some individuals. Additionally, it can cause orange secretions and flu-like symptoms. Therefore, it is important to use Rifampicin only as prescribed by a healthcare professional and to monitor any adverse effects that may occur.
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This question is part of the following fields:
- General Principles
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Question 29
Correct
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A 6-year-old boy arrives at the paediatric emergency department with a non-blanching rash. He is limping and complaining of abdominal pain. He had a recent bout of tonsillitis but is typically healthy. Upon examination, there are numerous palpable purpura in a symmetrical pattern, mainly on his buttocks and the backs of his legs. A urine dipstick reveals mild proteinuria and 2+ blood.
What is the probable underlying pathophysiology of this presentation?Your Answer: IgA mediated small vessel vasculitis
Explanation:The correct answer is IgA mediated small vessel vasculitis, specifically Henoch-Schonlein purpura (HSP). This condition is characterized by palpable purpura, arthralgia, abdominal pain, and haematuria, and typically affects children aged 4-6 years. HSP is often triggered by infections such as streptococcal pharyngitis, but can also be caused by other infections like Mycoplasma pneumoniae, Epstein-Barr virus, and adenovirus.
The other options are incorrect. ANCA-associated vasculitis typically involves the respiratory and ENT systems, which this child does not have. Cryoglobulinaemic vasculitis is associated with hepatitis C, haematological malignancies, and autoimmune disease, none of which are present in this case. Deficiency of von Willebrand factor cleaving protein is a feature of TTP, which is rare in children and typically presents with a low platelet count. ITP is another autoimmune condition that can present similarly to HSP, but can be differentiated by a low platelet count.
Understanding Henoch-Schonlein Purpura
Henoch-Schonlein purpura (HSP) is a type of small vessel vasculitis that is mediated by IgA. It is often associated with IgA nephropathy, also known as Berger’s disease. HSP is commonly observed in children following an infection.
The condition is characterized by a palpable purpuric rash, which is accompanied by localized oedema over the buttocks and extensor surfaces of the arms and legs. Other symptoms include abdominal pain and polyarthritis. In some cases, patients may also experience haematuria and renal failure, which are indicative of IgA nephropathy.
Treatment for HSP typically involves analgesia for arthralgia. While there is inconsistent evidence for the use of steroids and immunosuppressants, supportive care is generally recommended for patients with nephropathy. The prognosis for HSP is usually excellent, particularly in children without renal involvement. However, it is important to monitor blood pressure and urinalysis to detect any signs of progressive renal involvement. Approximately one-third of patients may experience a relapse.
In summary, Henoch-Schonlein purpura is a self-limiting condition that is often seen in children following an infection. While the symptoms can be uncomfortable, the prognosis is generally good. However, it is important to monitor patients for any signs of renal involvement and provide appropriate supportive care.
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This question is part of the following fields:
- Renal System
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Question 30
Incorrect
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A 9-year-old boy comes to the GP after experiencing bloody diarrhoea for the past 6 days. He complains of abdominal pain and has been urinating very little. His mother has also noticed multiple bruises on his body without any known cause. What is the most probable organism responsible for his symptoms?
Your Answer: Leptospirosis spp
Correct Answer: E. coli
Explanation:The patient’s symptoms suggest that they may be suffering from haemolytic uraemic syndrome (HUS), which is often caused by an infection with E.coli 0157:H7.
HUS is characterized by a combination of haemolytic anaemia, thrombocytopaenia, and acute kidney injury, which can ultimately lead to renal failure.
The presence of bloody diarrhoea in the patient’s medical history is a significant indicator of HUS. Additionally, the reduced urine output is likely due to the acute kidney injury, while the bruising may be a result of the thrombocytopaenia associated with HUS.
Understanding Haemolytic Uraemic Syndrome
Haemolytic uraemic syndrome (HUS) is a condition that primarily affects young children and is characterized by a triad of symptoms, including acute kidney injury, microangiopathic haemolytic anaemia, and thrombocytopenia. The most common cause of HUS in children is Shiga toxin-producing Escherichia coli (STEC) 0157:H7, which accounts for over 90% of cases. Other causes of HUS include pneumococcal infection, HIV, systemic lupus erythematosus, drugs, and cancer.
To diagnose HUS, doctors may perform a full blood count, check for evidence of STEC infection in stool culture, and conduct PCR for Shiga toxins. Treatment for HUS is supportive and may include fluids, blood transfusion, and dialysis if required. Antibiotics are not recommended, despite the preceding diarrhoeal illness in many patients. The indications for plasma exchange in HUS are complicated, and as a general rule, plasma exchange is reserved for severe cases of HUS not associated with diarrhoea. Eculizumab, a C5 inhibitor monoclonal antibody, has shown greater efficiency than plasma exchange alone in the treatment of adult atypical HUS.
In summary, HUS is a serious condition that primarily affects young children and is characterized by a triad of symptoms. The most common cause of HUS in children is STEC 0157:H7, and diagnosis may involve various tests. Treatment is supportive, and antibiotics are not recommended. The indications for plasma exchange are complicated, and eculizumab may be more effective in treating adult atypical HUS.
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This question is part of the following fields:
- Renal System
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