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  • Question 1 - A 47-year-old woman visits her doctor and reports experiencing night sweats, hot flashes,...

    Incorrect

    • A 47-year-old woman visits her doctor and reports experiencing night sweats, hot flashes, and painful sexual intercourse due to vaginal dryness. The doctor suspects that she may be going through menopause and orders a set of blood tests to check her hormonal levels.

      What hormonal changes are probable in this patient?

      Your Answer: Increase in oestradiol production

      Correct Answer: Cessation of oestradiol and progesterone production

      Explanation:

      The cessation of oestradiol and progesterone production in the ovaries, which can be caused naturally or by medical intervention, leads to menopause. This decrease in hormone production often results in elevated levels of FSH and LH.

      Understanding Menopause and Contraception

      Menopause is a natural biological process that marks the end of a woman’s reproductive years. It typically occurs when a woman reaches the age of 51 in the UK. However, prior to menopause, women may experience a period known as the climacteric. During this time, ovarian function starts to decline, and women may experience symptoms such as hot flashes, mood swings, and vaginal dryness.

      It is important for women to understand that they can still become pregnant during the climacteric period. Therefore, it is recommended to use effective contraception until a certain period of time has passed. Women over the age of 50 should use contraception for 12 months after their last period, while women under the age of 50 should use contraception for 24 months after their last period. By understanding menopause and the importance of contraception during the climacteric period, women can make informed decisions about their reproductive health.

    • This question is part of the following fields:

      • Reproductive System
      195.4
      Seconds
  • Question 2 - In what location can Leydig cells be found? ...

    Correct

    • In what location can Leydig cells be found?

      Your Answer: Between testicular seminiferous tubules

      Explanation:

      Cell Types and Functions in Male Reproductive System

      The male reproductive system is composed of various organs that work together to produce and transport sperm. Two main types of epithelial cells are present in the testes: Sertoli cells and Leydig cells. Leydig cells are located between the seminiferous tubules and produce androgens, including testosterone. On the other hand, Sertoli cells are arranged in tubular structures and have a basal and luminal compartment where spermatogonia divide and spermatids mature, respectively. Testosterone diffuses into Sertoli cells and is converted into a more active form called 5-hydroxytestosterone.

      The epididymis is lined by tall columnar epithelial cells with long microvilli. These cells phagocytose dead spermatozoa and produce substances that aid in sperm maturation. The prostate gland is an exocrine gland composed of acinar and ductal cells. Its secretory products are essential for the stability of spermatozoa. Lastly, the seminal vesicles have a convoluted lining of secretory epithelial cells that produce the majority of the volume of seminal fluid, including fructose, which serves as the energy source for spermatozoa. the functions of these cells and organs is crucial in comprehending the male reproductive system’s overall function.

    • This question is part of the following fields:

      • Histology
      20.4
      Seconds
  • Question 3 - A 26-year-old male presents with yellow discoloration of his skin. He reports having...

    Incorrect

    • A 26-year-old male presents with yellow discoloration of his skin. He reports having had the flu for the past week but is otherwise in good health. He vaguely remembers his uncle experiencing similar episodes of yellow skin. What is the probable diagnosis and what is the mode of inheritance for this condition?

      Your Answer: X linked dominant

      Correct Answer: Autosomal recessive

      Explanation:

      Gilbert’s Syndrome is inherited in an autosomal recessive manner. It causes unconjugated hyperbilirubinaemia during periods of stress, such as fasting or infection.

      Gilbert’s syndrome is a genetic disorder that affects the way bilirubin is processed in the body. It is caused by a deficiency of UDP glucuronosyltransferase, which leads to unconjugated hyperbilirubinemia. This means that bilirubin is not properly broken down and eliminated from the body, resulting in jaundice. However, jaundice may only be visible during certain conditions such as fasting, exercise, or illness. The prevalence of Gilbert’s syndrome is around 1-2% in the general population.

      To diagnose Gilbert’s syndrome, doctors may look for a rise in bilirubin levels after prolonged fasting or the administration of IV nicotinic acid. However, treatment is not necessary for this condition. While the exact mode of inheritance is still debated, it is known to be an autosomal recessive disorder.

    • This question is part of the following fields:

      • Gastrointestinal System
      7.8
      Seconds
  • Question 4 - A 79-year-old male arrives at the emergency department with sudden onset right sided...

    Correct

    • A 79-year-old male arrives at the emergency department with sudden onset right sided hemiparesis. He has a medical history of hypertension and reports no changes to his vision, speech or hearing.

      What is the probable diagnosis?

      Your Answer: Lacunar infarct

      Explanation:

      A lacunar stroke can lead to isolated hemiparesis, hemisensory loss, or hemiparesis with limb ataxia. In this case, the patient is experiencing isolated hemiparesis, which is likely caused by a lacunar infarct. Hypertension is strongly linked to this type of stroke.

      Weber’s syndrome results in CN III palsy on the same side as the stroke and weakness in the opposite limb.

      Nystagmus is a common symptom of Wallenberg syndrome.

      Ipsilateral deafness is a common symptom of lateral pontine syndrome.

      Stroke can affect different parts of the brain depending on which artery is affected. If the anterior cerebral artery is affected, the person may experience weakness and loss of sensation on the opposite side of the body, with the lower extremities being more affected than the upper. If the middle cerebral artery is affected, the person may experience weakness and loss of sensation on the opposite side of the body, with the upper extremities being more affected than the lower. They may also experience vision loss and difficulty with language. If the posterior cerebral artery is affected, the person may experience vision loss and difficulty recognizing objects.

      Lacunar strokes are a type of stroke that are strongly associated with hypertension. They typically present with isolated weakness or loss of sensation on one side of the body, or weakness with difficulty coordinating movements. They often occur in the basal ganglia, thalamus, or internal capsule.

    • This question is part of the following fields:

      • Neurological System
      9.4
      Seconds
  • Question 5 - Which muscles are responsible for flexing the hip joint? ...

    Incorrect

    • Which muscles are responsible for flexing the hip joint?

      Your Answer: Biceps femoris

      Correct Answer: Psoas

      Explanation:

      Muscles and their Functions in Joint Movement

      The hip joint has three main flexors, namely the iliacus, psoas, and rectus femoris muscles. These muscles are responsible for flexing the hip joint, which is the movement of bringing the thigh towards the abdomen. On the other hand, the gluteus maximus and medius muscles are involved in hip extension, which is the movement of bringing the thigh backward.

      Moving on to the elbow joint, the bicep femoris muscle is one of the primary flexors. This muscle is responsible for bending the elbow, which is the movement of bringing the forearm towards the upper arm. Lastly, the adductor brevis muscle is responsible for adducting the leg at the hip joint, which is the movement of bringing the leg towards the midline of the body.

      In summary, muscles play a crucial role in joint movement. the functions of these muscles can help in identifying and addressing issues related to joint movement and mobility.

    • This question is part of the following fields:

      • Clinical Sciences
      6
      Seconds
  • Question 6 - A 12-year-old girl with a complicated medical history, including asthma and epilepsy, is...

    Correct

    • A 12-year-old girl with a complicated medical history, including asthma and epilepsy, is scheduled for a medication review. Upon reviewing her medical records, you notice that she is currently taking a medication that is contraindicated for her age group. Which of the following medications is contraindicated for this patient?

      Your Answer: Doxycycline

      Explanation:

      Doxycycline, a type of tetracycline antibiotic, should not be used in children under 12 years of age.

      Understanding Tetracyclines: Antibiotics Used in Clinical Practice

      Tetracyclines are a group of antibiotics that are commonly used in clinical practice. They work by inhibiting protein synthesis, specifically by binding to the 30S subunit and blocking the binding of aminoacyl-tRNA. However, bacteria can develop resistance to tetracyclines through increased efflux by plasmid-encoded transport pumps or ribosomal protection.

      Tetracyclines are used to treat a variety of conditions such as acne vulgaris, Lyme disease, Chlamydia, and Mycoplasma pneumoniae. However, they should not be given to children under 12 years of age or to pregnant or breastfeeding women due to the risk of discolouration of the infant’s teeth.

      While tetracyclines are generally well-tolerated, they can cause adverse effects such as photosensitivity, angioedema, and black hairy tongue. It is important to be aware of these potential side effects and to use tetracyclines only as prescribed by a healthcare professional.

    • This question is part of the following fields:

      • General Principles
      5.9
      Seconds
  • Question 7 - Sophie presents acutely to the hospital with severe epigastric pain that is radiating...

    Incorrect

    • Sophie presents acutely to the hospital with severe epigastric pain that is radiating to the back, nausea and vomiting. Upon questioning, she has suffered from several episodes of biliary colic in the past. A blood test reveals a lipase level of 1000U/L.

      What is the underlying pathophysiology of Sophie's condition?

      Your Answer: The pancreatic enzymes produced are defective and unable to aid in food digestion

      Correct Answer: Pancreatic enzymes released as a result of inflammation autodigest the pancreatic tissue

      Explanation:

      The cause of acute pancreatitis is the autodigestion of pancreatic tissue by pancreatic enzymes, which results in tissue necrosis. The patient is experiencing typical symptoms of acute pancreatitis, including epigastric pain that radiates to the back, nausea, and vomiting. The presence of elevated lipase levels, which are more than three times the upper limit of normal, is also indicative of acute pancreatitis. The patient’s history of biliary colic suggests that gallstones may be the underlying cause of this condition.

      During acute pancreatitis, inflammation of the pancreas triggers the release and activation of pancreatic enzymes, which then begin to digest the pancreatic tissue. This process is known as autodigestion. Autodigestion of fat can lead to tissue necrosis, while autodigestion of blood vessels can cause retroperitoneal hemorrhage, which can be identified by the presence of Grey Turner’s sign and Cullen’s sign.

      Understanding Acute Pancreatitis

      Acute pancreatitis is a condition that is commonly caused by alcohol or gallstones. It occurs when the pancreatic enzymes start to digest the pancreatic tissue, leading to necrosis. The most common symptom of acute pancreatitis is severe epigastric pain that may radiate through to the back. Vomiting is also common, and examination may reveal epigastric tenderness, ileus, and low-grade fever. Although rare, periumbilical discolouration (Cullen’s sign) and flank discolouration (Grey-Turner’s sign) may also be present.

      To diagnose acute pancreatitis, doctors typically measure the levels of serum amylase and lipase in the blood. While amylase is raised in 75% of patients, it does not correlate with disease severity. Lipase, on the other hand, is more sensitive and specific than amylase and has a longer half-life, making it useful for late presentations. Imaging, such as ultrasound or contrast-enhanced CT, may also be necessary to assess the aetiology of the condition.

      Scoring systems, such as the Ranson score, Glasgow score, and APACHE II, are used to identify cases of severe pancreatitis that may require intensive care management. Factors indicating severe pancreatitis include age over 55 years, hypocalcaemia, hyperglycaemia, hypoxia, neutrophilia, and elevated LDH and AST. However, the actual amylase level is not of prognostic value.

      In summary, acute pancreatitis is a condition that can cause severe pain and discomfort. It is important to diagnose and manage it promptly to prevent complications.

    • This question is part of the following fields:

      • Gastrointestinal System
      5.8
      Seconds
  • Question 8 - A 35-year-old man with a 3 year history of poorly controlled Crohn's disease...

    Incorrect

    • A 35-year-old man with a 3 year history of poorly controlled Crohn's disease presents to the gastroenterology clinic for review. Despite trials of multiple agents, he was referred for an ileocaecal resection 12 months ago, which he reports 'went well', and his symptoms have now largely subsided.

      However, he is now reporting new symptoms of fatigue and decreased ability to exercise.

      What is the most probable reason for these symptoms?

      Your Answer: Anaemia of chronic disease

      Correct Answer: B12 deficiency

      Explanation:

      Vitamin deficiency may occur after an ileocaecal resection.

      Vitamin B12 is essential for the development of red blood cells and the maintenance of the nervous system. It is absorbed through the binding of intrinsic factor, which is secreted by parietal cells in the stomach, and actively absorbed in the terminal ileum. A deficiency in vitamin B12 can be caused by pernicious anaemia, post gastrectomy, a vegan or poor diet, disorders or surgery of the terminal ileum, Crohn’s disease, or metformin use.

      Symptoms of vitamin B12 deficiency include macrocytic anaemia, a sore tongue and mouth, neurological symptoms, and neuropsychiatric symptoms such as mood disturbances. The dorsal column is usually affected first, leading to joint position and vibration issues before distal paraesthesia.

      Management of vitamin B12 deficiency involves administering 1 mg of IM hydroxocobalamin three times a week for two weeks, followed by once every three months if there is no neurological involvement. If a patient is also deficient in folic acid, it is important to treat the B12 deficiency first to avoid subacute combined degeneration of the cord.

    • This question is part of the following fields:

      • Haematology And Oncology
      7.7
      Seconds
  • Question 9 - A 10-year-old girl with type 1 diabetes arrives at the emergency department with...

    Incorrect

    • A 10-year-old girl with type 1 diabetes arrives at the emergency department with vomiting. After a brief history, you discover she had a recent bout of strep throat. Upon examination, you detect ketones in her urine and elevated blood sugar levels, indicating a likely case of diabetic ketoacidosis. What is the primary ketone body implicated in diabetic ketoacidosis?

      Your Answer: Beta-hydroxybutyrate

      Correct Answer: Acetoacetate

      Explanation:

      The liver produces water-soluble molecules called ketone bodies from fatty acids, with acetoacetate being the primary ketone body involved in diabetic ketoacidosis, along with beta-hydroxybutyrate and acetone. Ketone bodies are generated during fasting/starvation, intense exercise, or untreated type 1 diabetes mellitus. These molecules are taken up by extra-hepatic tissues and transformed into acetyl-CoA, which enters the citric acid cycle and is oxidized in the mitochondria to produce energy.

      Diabetic ketoacidosis (DKA) is a serious complication of type 1 diabetes mellitus, accounting for around 6% of cases. It can also occur in rare cases of extreme stress in patients with type 2 diabetes mellitus. DKA is caused by uncontrolled lipolysis, resulting in an excess of free fatty acids that are converted to ketone bodies. The most common precipitating factors of DKA are infection, missed insulin doses, and myocardial infarction. Symptoms include abdominal pain, polyuria, polydipsia, dehydration, Kussmaul respiration, and breath that smells like acetone. Diagnostic criteria include glucose levels above 11 mmol/l or known diabetes mellitus, pH below 7.3, bicarbonate below 15 mmol/l, and ketones above 3 mmol/l or urine ketones ++ on dipstick.

      Management of DKA involves fluid replacement, insulin, and correction of electrolyte disturbance. Fluid replacement is necessary as most patients with DKA are deplete around 5-8 litres. Isotonic saline is used initially, even if the patient is severely acidotic. Insulin is administered through an intravenous infusion, and correction of electrolyte disturbance is necessary. Long-acting insulin should be continued, while short-acting insulin should be stopped. Complications may occur from DKA itself or the treatment, such as gastric stasis, thromboembolism, arrhythmias, acute respiratory distress syndrome, acute kidney injury, and cerebral edema. Children and young adults are particularly vulnerable to cerebral edema following fluid resuscitation in DKA and often need 1:1 nursing to monitor neuro-observations, headache, irritability, visual disturbance, focal neurology, etc.

    • This question is part of the following fields:

      • Endocrine System
      6.9
      Seconds
  • Question 10 - A 87-year-old male with chronic untreated hypertension arrives at the emergency department complaining...

    Correct

    • A 87-year-old male with chronic untreated hypertension arrives at the emergency department complaining of chest pain. Upon examination of his ECG, it is observed that there are tall QRS complexes throughout the entire ECG with elevated R-waves in the left-sided leads. What condition does this suggest?

      Your Answer: Left ventricular hypertrophy (LVF)

      Explanation:

      ST elevation is expected in the leads corresponding to the affected part of the heart in an STEMI, while ST depression, T wave inversion, or no change is expected in an NSTEMI or angina. Dilated cardiomyopathy does not have any classical ECG changes, and it is not commonly associated with hypertension as LVF. LVF, on the other hand, causes left ventricular hypertrophy due to prolonged hypertension, resulting in an increase in R-wave amplitude in leads 1, aVL, and V4-6, as well as an increase in S wave depth in leads III, aVR, and V1-3 on the right side.

      ECG Indicators of Atrial and Ventricular Hypertrophy

      Left ventricular hypertrophy is indicated on an ECG when the sum of the S wave in V1 and the R wave in V5 or V6 exceeds 40 mm. Meanwhile, right ventricular hypertrophy is characterized by a dominant R wave in V1 and a deep S wave in V6. In terms of atrial hypertrophy, left atrial enlargement is indicated by a bifid P wave in lead II with a duration of more than 120 ms, as well as a negative terminal portion in the P wave in V1. On the other hand, right atrial enlargement is characterized by tall P waves in both II and V1 that exceed 0.25 mV. These ECG indicators can help diagnose and monitor patients with atrial and ventricular hypertrophy.

    • This question is part of the following fields:

      • Cardiovascular System
      27.1
      Seconds
  • Question 11 - A 45-year-old man visits his GP complaining of weakness in his right hand...

    Correct

    • A 45-year-old man visits his GP complaining of weakness in his right hand that has been ongoing for 2 months. He reports difficulty gripping objects and writing with his right hand. He denies any changes in sensation. The patient has a history of rheumatoid arthritis.

      During the examination, there are no apparent signs of muscle wasting or fasciculation in the right hand. However, the patient is unable to form an 'OK sign' with his right thumb and index finger upon request.

      Which nerve is the most likely culprit?

      Your Answer: Anterior interosseous nerve

      Explanation:

      The anterior interosseous nerve can be compressed between the heads of pronator teres, leading to an inability to perform a pincer grip with the thumb and index finger (known as the ‘OK sign’).

      The correct answer is the anterior interosseous nerve, which is a branch of the median nerve responsible for innervating pronator quadratus, flexor pollicis longus, and flexor digitorum profundus. Damage to this nerve, such as through compression by pronator teres, can result in the inability to perform a pincer grip. Patients with rheumatoid arthritis may be more susceptible to anterior interosseous nerve entrapment.

      The dorsal digital nerve is a sensory branch of the ulnar nerve and does not cause motor deficits.

      The palmar cutaneous nerve is a sensory branch of the median nerve that provides sensation to the palm of the hand.

      The posterior interosseus nerve supplies muscles in the posterior compartment of the forearm with C7 and C8 fibers. Lesions of this nerve cause pure-motor neuropathy, resulting in finger drop and radial wrist deviation during extension.

      Patients with ulnar nerve lesions can still perform a pincer grip with the thumb and index finger. Ulnar nerve lesions may cause paraesthesia in the fifth finger and hypothenar aspect of the palm.

      The anterior interosseous nerve is a branch of the median nerve that supplies the deep muscles on the front of the forearm, excluding the ulnar half of the flexor digitorum profundus. It runs alongside the anterior interosseous artery along the anterior of the interosseous membrane of the forearm, between the flexor pollicis longus and flexor digitorum profundus. The nerve supplies the whole of the flexor pollicis longus and the radial half of the flexor digitorum profundus, and ends below in the pronator quadratus and wrist joint. The anterior interosseous nerve innervates 2.5 muscles, namely the flexor pollicis longus, pronator quadratus, and the radial half of the flexor digitorum profundus. These muscles are located in the deep level of the anterior compartment of the forearm.

    • This question is part of the following fields:

      • Neurological System
      8.4
      Seconds
  • Question 12 - A 28-year-old woman comes in for her first ultrasound after discovering she is...

    Incorrect

    • A 28-year-old woman comes in for her first ultrasound after discovering she is pregnant. The scan reveals that the placenta is properly implanted. What modifications take place in the endometrium during days 5-13 in response to fetal tissue implantation?

      Your Answer: Trophoblastic induced change

      Correct Answer: Decidualization

      Explanation:

      The blastocyst typically implants in the endometrium around day 6-7 and finishes by day 10, which is during the secretory phase when progesterone from the corpus luteum is present. A woman will only test positive for pregnancy after implantation has occurred. During implantation, the blastodisc is formed.

      Apposition is the process of the blastocyst aligning with the endometrium, which is influenced by signals from both the endometrium and the blastocyst. The endometrium releases COX-2, growth factors, cytokines, and hormones like estrogen and progesterone, while the blastocyst releases EGF, LIF signaling, growth factors, and cytokines. NSAIDs should be avoided during the peri-implantation stage due to the importance of COX-2 in apposition.

      Attachment is the next stage, which occurs when the blastocyst attaches to the endometrium through pinopods and microvilli. The endometrium is only receptive to implantation during a narrow window of the menstrual cycle, but sperm can survive for up to 7 days, leading to unexpected pregnancies.

      Penetration is the final stage, where the blastocyst becomes embedded in the endometrium, and the development of the placenta begins. Haemochorial placentation is characterized by changes in the uterus, including the differentiation of the endometrium into the decidua, enlarged stromal cells, and NK cells, as well as the transformation of the uterine spiral arteries.

      Embryology is the study of the development of an organism from the moment of fertilization to birth. During the first week of embryonic development, the fertilized egg implants itself into the uterine wall. By the second week, the bilaminar disk is formed, consisting of two layers of cells. The primitive streak appears in the third week, marking the beginning of gastrulation and the formation of the notochord.

      As the embryo enters its fourth week, limb buds begin to form, and the neural tube closes. The heart also begins to beat during this time. By week 10, the genitals are differentiated, and the embryo exhibits intermittent breathing movements. These early events in embryonic development are crucial for the formation of the body’s major organs and structures. Understanding the timeline of these events can provide insight into the complex process of human development.

    • This question is part of the following fields:

      • General Principles
      6.9
      Seconds
  • Question 13 - A 12-year-old boy presents to the emergency department with complaints of central abdominal...

    Incorrect

    • A 12-year-old boy presents to the emergency department with complaints of central abdominal pain that has shifted to the right iliac fossa. Upon examination, there are no indications of rebound tenderness or guarding.

      What is the most probable diagnosis, and how would you describe the pathophysiology of the condition?

      Your Answer: Perforated appendicitis

      Correct Answer: Obstruction of the appendiceal lumen due to lymphoid hyperplasia or faecolith

      Explanation:

      The pathophysiology of appendicitis involves obstruction of the appendiceal lumen, which is commonly caused by lymphoid hyperplasia or a faecolith. This condition is most prevalent in young individuals aged 10-20 years and is the most common acute abdominal condition requiring surgery. Blood clots are not a typical cause of appendiceal obstruction, but foreign bodies and worms can also contribute to this condition.

      Pancreatitis can lead to autodigestion in the pancreas, while autoimmune destruction of the pancreas is responsible for type 1 diabetes. Symptoms of type 1 diabetes, which typically develops at a younger age than type 2 diabetes, include polydipsia and polyuria.

      Acute appendicitis is a common condition that requires surgery and can occur at any age, but is most prevalent in young people aged 10-20 years. The pathogenesis of acute appendicitis involves lymphoid hyperplasia or a faecolith, which leads to obstruction of the appendiceal lumen. This obstruction causes gut organisms to invade the appendix wall, resulting in oedema, ischaemia, and possibly perforation.

      The most common symptom of acute appendicitis is abdominal pain, which is typically peri-umbilical and radiates to the right iliac fossa due to localised peritoneal inflammation. Other symptoms include mild pyrexia, anorexia, and nausea. Examination may reveal generalised or localised peritonism, rebound and percussion tenderness, guarding and rigidity, and classical signs such as Rovsing’s sign and psoas sign.

      Diagnosis of acute appendicitis is typically based on raised inflammatory markers and compatible history and examination findings. Imaging may be used in certain cases, such as ultrasound in females where pelvic organ pathology is suspected. Management of acute appendicitis involves appendicectomy, which can be performed via an open or laparoscopic approach. Patients with perforated appendicitis require copious abdominal lavage, while those without peritonitis who have an appendix mass should receive broad-spectrum antibiotics and consideration given to performing an interval appendicectomy. Intravenous antibiotics alone have been trialled as a treatment for appendicitis, but evidence suggests that this is associated with a longer hospital stay and up to 20% of patients go on to have an appendicectomy within 12 months.

    • This question is part of the following fields:

      • Gastrointestinal System
      6
      Seconds
  • Question 14 - Which compound is classified as a ketone? ...

    Incorrect

    • Which compound is classified as a ketone?

      Your Answer: Oxaloacetate

      Correct Answer: Acetoacetate

      Explanation:

      Ketone Bodies and their Production

      Ketone bodies, namely acetoacetate and beta-hydroxybutyrate, are synthesized when the levels of fatty acids in the bloodstream are elevated. This can occur during fasting, starvation, or when following a high-fat, low-carbohydrate diet. When these conditions arise, triglycerides from adipose tissue are broken down into fatty acids and re-enter the bloodstream. The fatty acids then enter liver cells and undergo beta-oxidation in the mitochondria to form acetyl CoA. As acetyl CoA accumulates, two molecules can combine to form acetoacetyl CoA, which is then converted to HMGCoA by the enzyme HMG CoA synthetase. HMGCoA lyase then changes the HMG CoA into acetoacetate, which is a ketone body.

      Ketones are essential as they provide fuel for body cells during times of fasting when glucose may be scarce. Brain cells are particularly able to use ketones as a fuel source.

    • This question is part of the following fields:

      • Clinical Sciences
      6.1
      Seconds
  • Question 15 - After a myocardial infarction (MI), a 65-year-old patient is initiated on a regimen...

    Incorrect

    • After a myocardial infarction (MI), a 65-year-old patient is initiated on a regimen of medications for secondary prevention. The regimen includes aspirin, clopidogrel, perindopril, bisoprolol, and simvastatin. However, the patient experiences poor tolerance to clopidogrel, leading to a prescription of ticagrelor instead.

      Your Answer: Inhibits the formation of thromboxane A2

      Correct Answer: Inhibits ADP binding to platelet receptors

      Explanation:

      Ticagrelor and clopidogrel have a similar mechanism of action in that they both inhibit ADP binding to platelet receptors, thereby preventing platelet aggregation. However, ticagrelor specifically targets the glycoprotein GPIIb/IIIa complex, while clopidogrel inhibits the P2Y12 receptor.

      Aspirin, on the other hand, irreversibly binds to cyclooxygenase (COX), an enzyme that plays a key role in the production of thromboxane A2, a potent vasoconstrictor and platelet aggregator.

      Direct oral anticoagulants (DOACs) like rivaroxaban work by directly inhibiting clotting factor Xa, which is necessary for the formation of thrombin and subsequent clotting. Unlike warfarin, DOACs require less monitoring.

      Warfarin, on the other hand, inhibits the production of vitamin K-dependent clotting factors, including factors II, VII, IX, and X. It also inhibits some pro-thrombotic molecules, which initially increases the risk of thrombosis.

      Dabigatran, another form of DOAC, is a thrombin inhibitor and currently the only one with a reversal agent available.

      ADP receptor inhibitors, such as clopidogrel, prasugrel, ticagrelor, and ticlopidine, work by inhibiting the P2Y12 receptor, which leads to sustained platelet aggregation and stabilization of the platelet plaque. Clinical trials have shown that prasugrel and ticagrelor are more effective than clopidogrel in reducing short- and long-term ischemic events in high-risk patients with acute coronary syndrome or undergoing percutaneous coronary intervention. However, ticagrelor may cause dyspnea due to impaired clearance of adenosine, and there are drug interactions and contraindications to consider for each medication. NICE guidelines recommend dual antiplatelet treatment with aspirin and ticagrelor for 12 months as a secondary prevention strategy for ACS.

    • This question is part of the following fields:

      • Cardiovascular System
      6.3
      Seconds
  • Question 16 - A 45-year-old woman receiving chemotherapy for breast cancer presents to the acute medical...

    Incorrect

    • A 45-year-old woman receiving chemotherapy for breast cancer presents to the acute medical unit with a cough and shortness of breath, accompanied by purulent sputum. Laboratory tests show a decreased white blood cell count. During examination of a blood film under a microscope, which cells can be identified by their multi-lobed nuclei and are the initial white blood cells to be recruited to areas of acute inflammation?

      Your Answer: Eosinophils

      Correct Answer: Neutrophils

      Explanation:

      Neutrophils play a crucial role in innate immunity and are present in large numbers. They possess phagocytic abilities and can produce cytokines. Their nuclei have a distinct multi-lobed appearance when viewed under a microscope. Eosinophils, on the other hand, have nuclei that are bilobed. Macrophages and mast cells have a single nucleus.

      Innate Immune Response: Cells Involved

      The innate immune response is the first line of defense against invading pathogens. It involves a variety of cells that work together to quickly recognize and eliminate foreign invaders. The following cells are primarily involved in the innate immune response:

      Neutrophils are the most common type of white blood cell and are the primary phagocytic cell in acute inflammation. They contain granules that contain myeloperoxidase and lysozyme, which help to break down and destroy pathogens.

      Basophils and mast cells are similar in function and both release histamine during an allergic response. They also contain granules that contain histamine and heparin, and express IgE receptors on their cell surface.

      Eosinophils defend against protozoan and helminthic infections, and have a bi-lobed nucleus.

      Monocytes differentiate into macrophages, which are involved in phagocytosis of cellular debris and pathogens. They also act as antigen-presenting cells and are a major source of IL-1.

      Natural killer cells induce apoptosis in virally infected and tumor cells, while dendritic cells act as antigen-presenting cells.

      Overall, these cells work together to provide a rapid and effective response to invading pathogens, helping to protect the body from infection and disease.

    • This question is part of the following fields:

      • General Principles
      5.8
      Seconds
  • Question 17 - Which statement accurately describes the results of a randomised controlled trial comparing the...

    Incorrect

    • Which statement accurately describes the results of a randomised controlled trial comparing the effectiveness of drug A and drug B in treating diabetes mellitus, where 100 patients were assigned to each group and the HbA1c levels were 72 mmol/mol in group A and 61 mmol/mol in group B with a p-value of 0.08?

      Your Answer: Type II error is 8%

      Correct Answer: The 95% confidence intervals of the HbA1c for group A and group B likely overlapped

      Explanation:

      Statistical Significance and Confidence Intervals

      When conducting statistical analyses, it is important to understand the concepts of statistical significance and confidence intervals. In general, statistical significance refers to the likelihood that the results of a study are not due to chance. This is typically determined by calculating a p value, which represents the probability of obtaining the observed results if the null hypothesis (i.e., no difference between groups) is true. If the p value is below a predetermined level of significance (usually 0.05 or 0.01), the results are considered statistically significant.

      Confidence intervals, on the other hand, provide a range of values within which the true population parameter (e.g., mean, proportion) is likely to fall. The width of the confidence interval is determined by the level of confidence (e.g., 95%, 90%) and the variability of the data. A narrower confidence interval indicates greater precision in the estimate.

      In the given statements, it is suggested that the p value and confidence intervals can provide insight into the likelihood of differences between groups. Specifically, if the p value is above 0.05, it is likely that the confidence intervals of the two groups overlap. Additionally, a 90% confidence interval will generally be narrower than a 95% confidence interval. Finally, if the p value is below 0.1, it is suggested that the 90% confidence intervals did not overlap, indicating a greater likelihood of differences between groups. However, it is important to note that the power of the study (i.e., the ability to detect true differences) is not known, so the possibility of a type II error (i.e., failing to detect a true difference) cannot be ruled out.

    • This question is part of the following fields:

      • Clinical Sciences
      5.4
      Seconds
  • Question 18 - A 28-year-old, gravida 2 para 1, presents to the emergency department with pelvic...

    Incorrect

    • A 28-year-old, gravida 2 para 1, presents to the emergency department with pelvic pain. She delivered a healthy baby at 37 weeks gestation 13 days ago.

      During the examination, it was found that she has right lower quadrant pain and her temperature is 37.8º C. Further tests revealed a left gonadal (ovarian) vein thrombosis. The patient was informed about the risk of the thrombus lodging in the venous system from the left gonadal vein.

      What is the first structure that the thrombus will go through if lodged from the left gonadal vein?

      Your Answer: Superior vena cava

      Correct Answer: Left renal vein

      Explanation:

      The left gonadal veins empty into the left renal vein, meaning that any thrombus originating from the left gonadal veins would travel to the left renal vein. However, if the thrombus originated from the right gonadal vein, it would flow into the inferior vena cava (IVC) since the right gonadal vein directly drains into the IVC.

      The portal vein is typically formed by the merging of the superior mesenteric and splenic veins, and it also receives blood from the inferior mesenteric, gastric, and cystic veins.

      The superior vena cava collects venous drainage from the upper half of the body, specifically above the diaphragm.

      Anatomy of the Inferior Vena Cava

      The inferior vena cava (IVC) originates from the fifth lumbar vertebrae and is formed by the merging of the left and right common iliac veins. It passes to the right of the midline and receives drainage from paired segmental lumbar veins throughout its length. The right gonadal vein empties directly into the cava, while the left gonadal vein usually empties into the left renal vein. The renal veins and hepatic veins are the next major veins that drain into the IVC. The IVC pierces the central tendon of the diaphragm at the level of T8 and empties into the right atrium of the heart.

      The IVC is related anteriorly to the small bowel, the first and third parts of the duodenum, the head of the pancreas, the liver and bile duct, the right common iliac artery, and the right gonadal artery. Posteriorly, it is related to the right renal artery, the right psoas muscle, the right sympathetic chain, and the coeliac ganglion.

      The IVC is divided into different levels based on the veins that drain into it. At the level of T8, it receives drainage from the hepatic vein and inferior phrenic vein before piercing the diaphragm. At the level of L1, it receives drainage from the suprarenal veins and renal vein. At the level of L2, it receives drainage from the gonadal vein, and at the level of L1-5, it receives drainage from the lumbar veins. Finally, at the level of L5, the common iliac vein merges to form the IVC.

    • This question is part of the following fields:

      • Cardiovascular System
      6.1
      Seconds
  • Question 19 - A 65-year-old man presents to his GP with worsening breathlessness. He reports difficulty...

    Incorrect

    • A 65-year-old man presents to his GP with worsening breathlessness. He reports difficulty climbing stairs and sleeping, and finds it easier to sleep in his living room chair. He used to manage stairs fine a year ago, but now has to stop twice on the way up.

      When asked about other symptoms, he reports feeling slightly wheezy and occasionally coughing up white sputum. He denies any weight loss. His medical history includes angina, non-diabetic hyperglycaemia, and hypertension. He has smoked 15 cigarettes per day since he was 25 and drinks around 5 pints of lager every Friday and Saturday night.

      On examination, his oxygen saturations are 96%, respiratory rate 16/min at rest, heart rate 78/min, and blood pressure 141/88 mmHg. Bibasal crackles are heard on auscultation of his lungs.

      What is the most likely diagnosis?

      Your Answer: Occupational asthma

      Correct Answer: Heart failure

      Explanation:

      Orthopnoea is a distinguishing symptom that can help differentiate between heart failure and COPD in patients. While the symptoms may be non-specific, the presence of orthopnoea, or breathlessness when lying down, is a key indicator of heart failure rather than COPD.

      Although the patient has a significant history of smoking, there are no other signs of lung cancer such as weight loss, persistent cough, or coughing up blood. However, it is recommended to conduct an urgent chest X-ray to rule out any serious underlying conditions.

      In cases of occupational asthma, symptoms tend to worsen when exposed to triggers in the workplace and improve during time off. However, in this patient’s case, the symptoms have been gradually worsening over time.

      Features of Chronic Heart Failure

      Chronic heart failure is a condition that affects the heart’s ability to pump blood effectively. It is characterized by several features that can help in its diagnosis. Dyspnoea, or shortness of breath, is a common symptom of chronic heart failure. Patients may also experience coughing, which can be worse at night and accompanied by pink or frothy sputum. Orthopnoea, or difficulty breathing while lying down, and paroxysmal nocturnal dyspnoea, or sudden shortness of breath at night, are also common symptoms.

      Another feature of chronic heart failure is the presence of a wheeze, known as a cardiac wheeze. Patients may also experience weight loss, known as cardiac cachexia, which occurs in up to 15% of patients. However, this may be hidden by weight gained due to oedema. On examination, bibasal crackles may be heard, and signs of right-sided heart failure, such as a raised JVP, ankle oedema, and hepatomegaly, may be present.

      In summary, chronic heart failure is a condition that can be identified by several features, including dyspnoea, coughing, orthopnoea, paroxysmal nocturnal dyspnoea, wheezing, weight loss, bibasal crackles, and signs of right-sided heart failure. Early recognition and management of these symptoms can help improve outcomes for patients with chronic heart failure.

    • This question is part of the following fields:

      • Cardiovascular System
      5.6
      Seconds
  • Question 20 - A 31-year-old female patient visits her GP with complaints of feeling constantly tired,...

    Incorrect

    • A 31-year-old female patient visits her GP with complaints of feeling constantly tired, lacking energy, and experiencing severe headaches. She reports a loss of libido and irregular menstrual cycles. During an eye exam, bitemporal hemianopia is detected, and an MRI scan reveals a non-functional pituitary tumor that is pressing on an artery. Which artery is being compressed by the patient's tumor?

      Your Answer: Ophthalmic artery

      Correct Answer: Internal carotid artery

      Explanation:

      The internal carotid artery originates from the common carotid artery near the upper border of the thyroid cartilage and travels upwards to enter the skull through the carotid canal. It then passes through the cavernous sinus and divides into the anterior and middle cerebral arteries. In the neck, it is surrounded by various structures such as the longus capitis, pre-vertebral fascia, sympathetic chain, and superior laryngeal nerve. It is also closely related to the external carotid artery, the wall of the pharynx, the ascending pharyngeal artery, the internal jugular vein, the vagus nerve, the sternocleidomastoid muscle, the lingual and facial veins, and the hypoglossal nerve. Inside the cranial cavity, the internal carotid artery bends forwards in the cavernous sinus and is closely related to several nerves such as the oculomotor, trochlear, ophthalmic, and maxillary nerves. It terminates below the anterior perforated substance by dividing into the anterior and middle cerebral arteries and gives off several branches such as the ophthalmic artery, posterior communicating artery, anterior choroid artery, meningeal arteries, and hypophyseal arteries.

    • This question is part of the following fields:

      • Neurological System
      10.5
      Seconds
  • Question 21 - A 25-year-old male is getting a routine check-up from his family doctor before...

    Correct

    • A 25-year-old male is getting a routine check-up from his family doctor before starting a new workout regimen at the gym. He has a clean medical history and does not smoke or drink. He is currently pursuing a graduate degree in political science. The doctor orders a CBC and other tests.

      The patient returns to the doctor's office a week later for the test results. The CBC shows that his platelet count is low. However, he does not have any signs of bleeding from his nose or mouth, and there are no rashes on his skin.

      The doctor suspects that this may be due to platelet in vitro agglutination.

      What could have caused this condition?

      Your Answer: Ethylenediaminetetraacetic acid (EDTA)

      Explanation:

      EDTA is known to induce pseudothrombocytopenia, which is a condition where platelet counts are falsely reported as low due to EDTA-dependent platelet aggregation. On the other hand, sodium fluoride inhibits glycolysis and prevents enzymes from functioning, leading to the depletion of substrates like glucose during storage. While sodium citrate, sodium oxalate, and lithium heparin are all anticoagulants commonly found in vacutainers, they are not linked to thrombocytopenia.

      Causes of Thrombocytopenia

      Thrombocytopenia is a medical condition characterized by a low platelet count in the blood. The severity of thrombocytopenia can vary, with some cases being more severe than others. Severe thrombocytopenia can be caused by conditions such as immune thrombocytopenia (ITP), disseminated intravascular coagulation (DIC), thrombotic thrombocytopenic purpura (TTP), and haematological malignancy. On the other hand, moderate thrombocytopenia can be caused by heparin-induced thrombocytopenia (HIT), drug-induced factors such as quinine, diuretics, sulphonamides, aspirin, and thiazides, alcohol, liver disease, hypersplenism, viral infections such as EBV, HIV, and hepatitis, pregnancy, SLE/antiphospholipid syndrome, and vitamin B12 deficiency. It is important to note that pseudothrombocytopenia can also occur as a result of using EDTA as an anticoagulant.

    • This question is part of the following fields:

      • Haematology And Oncology
      5.6
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  • Question 22 - A 9-year-old girl is brought to the emergency department with acute onset pain...

    Correct

    • A 9-year-old girl is brought to the emergency department with acute onset pain in her hands for the past 2 hours. She has a history of recurrent infections. Physical examination shows tender diffuse swelling of her hands bilaterally.

      Her blood tests show:
      Hb 85 g/L Male: (119-150)
      Female: (119-150)
      Platelets 250 * 109/L (150 - 400)
      WBC 6 * 109/L (4.0 - 11.0)
      Mean corpuscular volume (MCV) 90 fL (80-100)

      Peripheral smear examination shows numerous sickled red blood cells (RBC) and Howell-jolly bodies. Haemoglobin electrophoresis confirms sickle cell disease.

      Which of the following is a beneficial prophylactic drug for her?

      Your Answer: Hydroxyurea

      Explanation:

      Hydroxyurea is utilized in the prophylactic management of sickle cell anemia to prevent painful episodes by increasing the levels of HbF. The management of sickle cell disease involves two aspects: acute episodes and chronic management. Acute episodes are treated with adequate hydration and effective analgesia, while chronic management aims to prevent acute episodes and treat complications. Hydroxyurea has been proven to reduce the frequency of painful crises and the need for blood transfusions by increasing HbF levels, which has a higher affinity for oxygen than haemoglobin A. Acetaminophen is an analgesic that inhibits the cyclooxygenase enzyme and is only useful in mild pain cases. Methotrexate is a chemotherapeutic agent that has no role in sickle cell disease management.

      Managing Sickle-Cell Anaemia

      Sickle-cell anaemia is a genetic blood disorder that causes red blood cells to become misshapen and break down, leading to a range of complications. When a crisis occurs, management involves providing analgesia, rehydration, oxygen, and potentially antibiotics if there is evidence of infection. Blood transfusions may also be necessary, and in some cases, an exchange transfusion may be required if there are neurological complications.

      In the longer term, prophylactic management of sickle-cell anaemia involves the use of hydroxyurea, which increases the levels of HbF to prevent painful episodes. Additionally, it is recommended that sickle-cell patients receive the pneumococcal polysaccharide vaccine every five years to reduce the risk of infection. By implementing these management strategies, individuals with sickle-cell anaemia can better manage their condition and improve their quality of life.

    • This question is part of the following fields:

      • Haematology And Oncology
      7.6
      Seconds
  • Question 23 - A young girl comes to the clinic complaining of severe menstrual cramps that...

    Incorrect

    • A young girl comes to the clinic complaining of severe menstrual cramps that occur every month. Her physician assures her that this is a common issue and prescribes mefenamic acid as a pain reliever. What is the mechanism of action of mefenamic acid?

      Your Answer: Blocking dorsal horn sodium channels

      Correct Answer: Inhibiting COX, decreasing prostaglandin production

      Explanation:

      Mefenamic acid is classified as an NSAID because it works by inhibiting COX, which ultimately leads to a decrease in prostaglandin production. Any response indicating an increase or alteration in prostaglandin levels would be inaccurate. The idea of blocking dorsal horn sodium channels is more characteristic of a neuropathic medication rather than an NSAID.

      Understanding Non-Steroidal Anti-Inflammatory Drugs (NSAIDs) and COX-2 Selective NSAIDs

      Non-steroidal anti-inflammatory drugs (NSAIDs) are medications that work by inhibiting the activity of cyclooxygenase enzymes, which are responsible for producing key mediators involved in inflammation such as prostaglandins. By reducing the production of these mediators, NSAIDs can help alleviate pain and reduce inflammation. Examples of NSAIDs include ibuprofen, diclofenac, naproxen, and aspirin.

      However, NSAIDs can also have important and common side-effects, such as peptic ulceration and exacerbation of asthma. To address these concerns, COX-2 selective NSAIDs were developed. These medications were designed to reduce the incidence of side-effects seen with traditional NSAIDs, particularly peptic ulceration. Examples of COX-2 selective NSAIDs include celecoxib and etoricoxib.

      Despite their potential benefits, COX-2 selective NSAIDs are not widely used due to ongoing concerns about cardiovascular safety. This led to the withdrawal of rofecoxib (‘Vioxx’) in 2004. As with any medication, it is important to discuss the potential risks and benefits of NSAIDs and COX-2 selective NSAIDs with a healthcare provider before use.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
      6.3
      Seconds
  • Question 24 - A 67-year-old woman visits her doctor complaining of constant fatigue. She has no...

    Incorrect

    • A 67-year-old woman visits her doctor complaining of constant fatigue. She has no medical history. During the examination, her heart rate is found to be 56 beats per minute and regular. There is thinning of the lateral third of the eyebrows on both sides. Proximal myopathy is evident, with shoulder power of 4+/5. Her body mass index is elevated at 36 kg/m². The doctor prescribes medication, which successfully resolves her symptoms and signs. What type of receptor does this medication target, considering the probable diagnosis?

      Your Answer: Tyrosine kinase receptor

      Correct Answer: Nuclear receptor

      Explanation:

      Levothyroxine exerts its effects through nuclear receptors, which are located inside the cell. This is the correct answer. The patient’s symptoms suggest hypothyroidism, which is commonly associated with fatigue, bradycardia, thinning of the outer third of eyebrows and proximal myopathy, and weight gain. To interact with a nuclear receptor, the substance must be lipid soluble.

      G protein-coupled receptors are not involved in the mechanism of action of levothyroxine. This answer is incorrect. Adrenaline is an example of a substance that acts through this receptor.

      Guanylate cyclase receptors are also not involved in the mechanism of action of levothyroxine. This answer is incorrect. Hormones such as atrial natriuretic peptide (BNP) and brain natriuretic peptide (BNP) act through this receptor by cyclizing guanylate into cyclic GMP.

      Ion channel receptors are not involved in the mechanism of action of levothyroxine. This answer is incorrect. These receptors typically mediate fast responses, such as those mediated by GABA. Zolpidem is an example of a medication that acts through this receptor.

      Pharmacodynamics refers to the effects of drugs on the body, as opposed to pharmacokinetics which is concerned with how the body processes drugs. Drugs typically interact with a target, which can be a protein located either inside or outside of cells. There are four main types of cellular targets: ion channels, G-protein coupled receptors, tyrosine kinase receptors, and nuclear receptors. The type of target determines the mechanism of action of the drug. For example, drugs that work on ion channels cause the channel to open or close, while drugs that activate tyrosine kinase receptors lead to cell growth and differentiation.

      It is also important to consider whether a drug has a positive or negative impact on the receptor. Agonists activate the receptor, while antagonists block the receptor preventing activation. Antagonists can be competitive or non-competitive, depending on whether they bind at the same site as the agonist or at a different site. The binding affinity of a drug refers to how readily it binds to a specific receptor, while efficacy measures how well an agonist produces a response once it has bound to the receptor. Potency is related to the concentration at which a drug is effective, while the therapeutic index is the ratio of the dose of a drug resulting in an undesired effect compared to that at which it produces the desired effect.

      The relationship between the dose of a drug and the response it produces is rarely linear. Many drugs saturate the available receptors, meaning that further increased doses will not cause any more response. Some drugs do not have a significant impact below a certain dose and are considered sub-therapeutic. Dose-response graphs can be used to illustrate the relationship between dose and response, allowing for easy comparison of different drugs. However, it is important to remember that dose-response varies between individuals.

    • This question is part of the following fields:

      • General Principles
      30.2
      Seconds
  • Question 25 - A 12-year-old boy with sickle cell anaemia arrives at the emergency department with...

    Incorrect

    • A 12-year-old boy with sickle cell anaemia arrives at the emergency department with a hot, swollen, erythematous and painful knee. The symptoms developed over a few hours and he is unable to bear weight on the affected leg. Upon joint aspiration, cloudy synovial fluid with neutrophilia is observed. What is the primary mode of transmission for this condition?

      Your Answer: Sexually transmitted

      Correct Answer: Hematogenous spread

      Explanation:

      Septic arthritis is often characterized by sudden joint pain, swelling, and warmth, and is typically caused by hematogenous spread of bacteria. Staphylococcus aureus is the most common causative organism, except in individuals with sickle cell anemia, where Salmonella is more common. While direct introduction or extension from a nearby infection can also cause septic arthritis, hematogenous spread is the most frequent cause. Unlike respiratory diseases, septic arthritis is not spread through respiratory droplets. In sexually active patients, gonococcal arthritis caused by Neisseria gonorrhoeae should be considered as a potential cause.

      Septic Arthritis in Adults: Causes, Symptoms, and Treatment

      Septic arthritis is a condition that occurs when bacteria infect a joint, leading to inflammation and swelling. The most common organism that causes septic arthritis in adults is Staphylococcus aureus, while Neisseria gonorrhoeae is the most common organism in sexually active young adults. The infection is usually spread through the bloodstream, often from distant bacterial infections such as abscesses. The knee is the most commonly affected joint in adults.

      Symptoms of septic arthritis include acute joint swelling, restricted movement, warmth to the touch, and fever. To diagnose the condition, synovial fluid sampling is necessary and should be done before administering antibiotics if needed. Blood cultures and joint imaging may also be necessary.

      Treatment for septic arthritis involves intravenous antibiotics that cover Gram-positive cocci, such as flucloxacillin or clindamycin if the patient is allergic to penicillin. Antibiotics are typically given for several weeks, and patients may be switched to oral antibiotics after two weeks. Needle aspiration is used to decompress the joint, and arthroscopic lavage may be required. Overall, prompt diagnosis and treatment are essential to prevent joint damage and other complications.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
      6.2
      Seconds
  • Question 26 - Which artery are you feeling when you detect an arterial pulsation on the...

    Incorrect

    • Which artery are you feeling when you detect an arterial pulsation on the mandible at the anterior border of the masseter muscle during a routine head and neck examination?

      Your Answer: The maxillary artery

      Correct Answer: The facial artery

      Explanation:

      Arteries of the Face

      The face is supplied with blood by several arteries, each with its own unique path and function. The facial artery, for instance, curves around the mandible before continuing on a winding journey to reach the medial canthus of the eye. Meanwhile, the lingual artery is responsible for supplying blood to the tongue and floor of the mouth. The marginal mandibular artery, on the other hand, provides blood to the depressor labii inferioris and depressor anguli oris. The maxillary artery, which supplies the deep structures of the face including the mandible and pterygoid, is also an important contributor to facial blood flow. Finally, the superficial temporal artery is responsible for supplying the temporalis muscle and the scalp. the unique roles of each of these arteries is crucial for proper diagnosis and treatment of facial injuries and conditions.

    • This question is part of the following fields:

      • Clinical Sciences
      6.1
      Seconds
  • Question 27 - During a challenging femoro-popliteal bypass surgery, the surgeon mistakenly applies a clamp on...

    Correct

    • During a challenging femoro-popliteal bypass surgery, the surgeon mistakenly applies a clamp on the femoral nerve. The clamp remains in place for a significant portion of the procedure. Upon examination after the operation, the nerve is found to be intact but shows signs of compression. What is the most probable outcome in the coming months?

      Your Answer: Wallerian degeneration

      Explanation:

      Despite the nerve remaining intact, a neuronal injury can lead to Wallerian degeneration and potentially the formation of neuromas.

      Nerve injuries can be classified into three types: neuropraxia, axonotmesis, and neurotmesis. Neuropraxia occurs when the nerve is intact but its electrical conduction is affected. However, full recovery is possible, and autonomic function is preserved. Wallerian degeneration, which is the degeneration of axons distal to the site of injury, does not occur. Axonotmesis, on the other hand, happens when the axon is damaged, but the myelin sheath is preserved, and the connective tissue framework is not affected. Wallerian degeneration occurs in this type of injury. Lastly, neurotmesis is the most severe type of nerve injury, where there is a disruption of the axon, myelin sheath, and surrounding connective tissue. Wallerian degeneration also occurs in this type of injury.

      Wallerian degeneration typically begins 24-36 hours following the injury. Axons are excitable before degeneration occurs, and the myelin sheath degenerates and is phagocytosed by tissue macrophages. Neuronal repair may only occur physiologically where nerves are in direct contact. However, nerve regeneration may be hampered when a large defect is present, and it may not occur at all or result in the formation of a neuroma. If nerve regrowth occurs, it typically happens at a rate of 1mm per day.

    • This question is part of the following fields:

      • Neurological System
      7.5
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  • Question 28 - A 90-year-old female arrives at the emergency department after experiencing a brief episode...

    Correct

    • A 90-year-old female arrives at the emergency department after experiencing a brief episode of aphasia. The episode lasted for 15 minutes, according to her daughter, and has never occurred before. She did not lose consciousness or sustain a head injury. The patient is currently taking atorvastatin, amlodipine, and sertraline. What diagnostic measures can be taken to confirm the diagnosis?

      Your Answer: Referral to TIA clinic and consideration for MRI scan

      Explanation:

      The definition of a TIA has changed to be based on tissue rather than time. It is now defined as a temporary episode of neurological dysfunction caused by focal brain, spinal cord, or retinal ischemia without acute infarction. Based on the patient’s symptoms, it is likely that they have experienced a TIA. NICE guidelines recommend urgent referral to a specialist stroke physician within 24 hours for patients who have had a suspected TIA within the last 7 days. An MRI scan may be necessary to confirm the diagnosis. A referral to a TIA clinic is required for patients who have experienced a transient episode of aphasia. CT brain imaging is no longer recommended unless there is a clinical suspicion of an alternative diagnosis that a CT could detect. The ROSIER tool is used to identify patients likely suffering from an acute stroke, not TIA. An ultrasound of the carotids may be appropriate down the line to determine if a carotid endarterectomy is required to reduce the risk of future strokes and TIAs. The diagnosis of TIA is now tissue-based, not time-based, and determining the episode as a TIA based on the duration of symptoms would be inappropriate.

      A transient ischaemic attack (TIA) is a brief period of neurological deficit caused by a vascular issue, lasting less than an hour. The original definition of a TIA was based on time, but it is now recognized that even short periods of ischaemia can result in pathological changes to the brain. Therefore, a new ’tissue-based’ definition is now used. The clinical features of a TIA are similar to those of a stroke, but the symptoms resolve within an hour. Possible features include unilateral weakness or sensory loss, aphasia or dysarthria, ataxia, vertigo, or loss of balance, visual problems, sudden transient loss of vision in one eye (amaurosis fugax), diplopia, and homonymous hemianopia.

      NICE recommends immediate antithrombotic therapy, giving aspirin 300 mg immediately unless the patient has a bleeding disorder or is taking an anticoagulant. If aspirin is contraindicated, management should be discussed urgently with the specialist team. Specialist review is necessary if the patient has had more than one TIA or has a suspected cardioembolic source or severe carotid stenosis. Urgent assessment within 24 hours by a specialist stroke physician is required if the patient has had a suspected TIA in the last 7 days. Referral for specialist assessment should be made as soon as possible within 7 days if the patient has had a suspected TIA more than a week previously. The person should be advised not to drive until they have been seen by a specialist.

      Neuroimaging should be done on the same day as specialist assessment if possible. MRI is preferred to determine the territory of ischaemia or to detect haemorrhage or alternative pathologies. Carotid imaging is necessary as atherosclerosis in the carotid artery may be a source of emboli in some patients. All patients should have an urgent carotid doppler unless they are not a candidate for carotid endarterectomy.

      Antithrombotic therapy is recommended, with clopidogrel being the first-line treatment. Aspirin + dipyridamole should be given to patients who cannot tolerate clopidogrel. Carotid artery endarterectomy should only be considered if the patient has suffered a stroke or TIA in the carotid territory and is not severely disabled. It should only be recommended if carotid stenosis is greater

    • This question is part of the following fields:

      • Neurological System
      74.1
      Seconds
  • Question 29 - A 7-year-old boy is brought to the clinic by his father, who is...

    Incorrect

    • A 7-year-old boy is brought to the clinic by his father, who is worried about his son's hearing. The father has noticed that his son frequently asks him to repeat himself and tends to turn up the volume on the TV. During Weber's test, the patient indicates that the sound is louder on the right side. What conclusion can be drawn from this finding?

      Your Answer: Sensorineural hearing loss of right ear.

      Correct Answer: Can not tell which side is affected.

      Explanation:

      The Weber test alone cannot determine which side of the patient’s hearing is affected. The test involves placing a tuning fork on the forehead and asking the patient to report if the sound is symmetrical or louder on one side. If the sound is louder on the left side, it could indicate a conductive hearing loss on the left or a sensorineural hearing loss on the right. To obtain more information, the Weber test should be performed in conjunction with the Rinne test, which involves comparing air conduction and bone conduction.

      Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness

      Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.

      Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.

      The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.

      Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.

    • This question is part of the following fields:

      • Respiratory System
      8
      Seconds
  • Question 30 - A 60-year-old man is admitted to the hospital with pneumonia. During routine daily...

    Incorrect

    • A 60-year-old man is admitted to the hospital with pneumonia. During routine daily blood tests, the following results are obtained:

      Hb 105 g/L
      WCC 14.2 * 109/l
      CRP 98 mg/l
      Na+ 136 mmol/l
      K+ 6.1 mmol/l
      Glucose 12.8 mmol/l
      Urea 7.8 mmol/l
      eGFR 56 mL/min/1.73m2 (>90 mL/min/1.73m2)

      The patient has a medical history of diabetes mellitus, hypertension, and chronic kidney disease. He is currently taking paracetamol, amlodipine, furosemide, and spironolactone.

      What is the most appropriate modification to his management?

      Your Answer: Stop amlodipine

      Correct Answer: Stop spironolactone

      Explanation:

      To address the hyperkalaemia in this patient, the most appropriate step would be to stop the potassium-sparing diuretic, spironolactone. Starting metformin or erythropoietin, or increasing furosemide, would not be the most appropriate actions at this time.

      Potassium-sparing diuretics are classified into two types: epithelial sodium channel blockers (such as amiloride and triamterene) and aldosterone antagonists (such as spironolactone and eplerenone). However, caution should be exercised when using these drugs in patients taking ACE inhibitors as they can cause hyperkalaemia. Amiloride is a weak diuretic that blocks the epithelial sodium channel in the distal convoluted tubule. It is usually given with thiazides or loop diuretics as an alternative to potassium supplementation since these drugs often cause hypokalaemia. On the other hand, aldosterone antagonists like spironolactone act in the cortical collecting duct and are used to treat conditions such as ascites, heart failure, nephrotic syndrome, and Conn’s syndrome. In patients with cirrhosis, relatively large doses of spironolactone (100 or 200 mg) are often used to manage secondary hyperaldosteronism.

    • This question is part of the following fields:

      • General Principles
      6.7
      Seconds

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General Principles (1/5) 20%
Haematology And Oncology (2/3) 67%
Endocrine System (0/1) 0%
Cardiovascular System (1/4) 25%
Musculoskeletal System And Skin (0/2) 0%
Respiratory System (0/1) 0%
Passmed