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  • Question 1 - Which of the following is a correct match for reflex and their root...

    Incorrect

    • Which of the following is a correct match for reflex and their root value?

      Your Answer: Triceps reflex: C5/C6

      Correct Answer: Knee reflex: L3/L4

      Explanation:

      Reflexes are a routine part of clinical examination. Hyperreflexia (abnormally brisk reflexes) is the sign of upper motor neuron damage whereas diminished or absent jerks are most commonly due to lower motor neuron lesions. Reflexes may be Monosynaptic (deep tendon reflexes) or polysynaptic (superficial reflexes)

      Here are deep tendon reflexes with their nerve root
      Biceps = C5, C6
      Supinator (Brachioradialis) = C5, C6
      Triceps = C6, C7
      Knee reflex = L3,L4
      Ankle reflex = S1

      Polysynaptic superficial reflexes with their nerve root are listed below
      Planter response = S1-2
      Abdominal reflexes = T8-12
      Cremasteric reflex = L1-2.

    • This question is part of the following fields:

      • Anatomy
      9.1
      Seconds
  • Question 2 - What makes the ultrasound nebulizer efficient? ...

    Incorrect

    • What makes the ultrasound nebulizer efficient?

      Your Answer: Humidification of inspired gas by up to 100%

      Correct Answer: Reduction in gas flow resistance

      Explanation:

      Smallest drops reach not only the upper but also the lower respiratory tracks. As a result, the ultrasonic nebulizer is most efficient for the therapy of pulmonary diseases and stands out as a robust and reliable support within the clinical setting.

    • This question is part of the following fields:

      • Basic Physics
      8
      Seconds
  • Question 3 - A 5-year old male has ingested a peanut and has developed urticaria, vomiting...

    Incorrect

    • A 5-year old male has ingested a peanut and has developed urticaria, vomiting and hypotension. The pathogenesis of this condition is derived from predominant cells of which cell line?

      Your Answer: Megakaryocyte

      Correct Answer: Common myeloid progenitor

      Explanation:

      A is correct. Common myeloid progenitor cells are involved in the anaphylaxis reaction.
      B is incorrect. The common lymphoid lineage gives rise to T-cells, B-cell and NK cells.
      C is incorrect as megakaryocytes give rise to platelets.
      D is incorrect – Neural crest cells give rise to various cells throughout the body, including melanocytes, enterochromaffin cells and Schwann cells. However, they do not give rise to mast cells.
      E is incorrect. Reticulocytes give rise to erythrocytes.

      This is a classic case of anaphylaxis. In this situation, IgE previously raised against antigens (in this case peanut antigen) bind to mast cells, and this causes them to degranulate.
      There is release of vasoactive substances like histamine into the blood, and this is responsible for the symptoms seen. Therefore, the main type of cells involved in the pathogenesis of the disease is mast cells.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      15.4
      Seconds
  • Question 4 - In the United Kingdom, a new breast cancer screening test is being conducted...

    Incorrect

    • In the United Kingdom, a new breast cancer screening test is being conducted compared to the conventional use of mammography. This test predicts that if the breast cancer is diagnosed at an earlier stage, it could improve the survival rate but the overall results remains constant. This is an example of what kind of bias?

      Your Answer: Length time bias

      Correct Answer: Lead time bias

      Explanation:

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.

      In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically.

      Self Selection or volunteer bias occur when those subjects are selected to participate in the study who are not the representative of the entire target population. those subjects may be from high socio-economic status and practice those activities or lifestyle that improves their health.

      Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.

    • This question is part of the following fields:

      • Statistical Methods
      24.3
      Seconds
  • Question 5 - Which of the following statements is true regarding the Wrights Respirometer? ...

    Incorrect

    • Which of the following statements is true regarding the Wrights Respirometer?

      Your Answer: May over-read at low flows

      Correct Answer: Measures the minute volume to within an accuracy of +/- 10%

      Explanation:

      A Wrights Respirometer measures the volume of air exhaled over the course of one minute of normal breathing

      It is unidirectional and measures tidal volume and minute volume of gas flow in one direction. It is placed at the expiratory side (lower pressure than inspiratory side therefore lower chances of gas leaks)

      Slits are arranged such that incoming gas will rotate the vane at a rate of 150 revolutions per litre of flowing gas

      The Wright respirometer tends to over-read at high flow rates and under-read at low flows because of mechanical causes like friction and inertia and the accumulation of water vapour

      The ideal flow for accurate readings is 2 L/min for the respirometer. The respirometer reads the tidal volume and minute volume with a ±5€“10% accuracy within the range of 4€“24 L/min.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      15
      Seconds
  • Question 6 - Which of the following statements is NOT true regarding the internal jugular vein?...

    Incorrect

    • Which of the following statements is NOT true regarding the internal jugular vein?

      Your Answer: It is the continuation of the sigmoid sinus

      Correct Answer: The terminal part of the thoracic duct crosses anterior to it to insert into the right subclavian vein

      Explanation:

      The internal jugular vein is found on both sides of the neck and collects blood from the brain, superficial regions of the face, and neck. It drains into the right atrium.

      It is a continuation of the sigmoid sinus and begins in the posterior cranial fossa and exits the skull via the jugular foramen.
      It runs within the carotid sheath as it descends in the neck and is accompanied by the vagus nerve posteriorly and the common carotid anteromedially.

      The hypoglossal nerve emerges from the hypoglossal canal medial to the internal carotid artery and the internal jugular vein and ninth, tenth, and eleventh cranial nerves.

      The internal jugular vein crosses anterior to the thoracic duct on the left side.

    • This question is part of the following fields:

      • Anatomy
      38.5
      Seconds
  • Question 7 - Which of the following options will likely play a major role in falling...

    Incorrect

    • Which of the following options will likely play a major role in falling coronary blood flow?

      Your Answer: Peripheral venous infusion of glyceryl trinitrate (GTN)

      Correct Answer: Intracoronary artery infusion of endothelin-1

      Explanation:

      Endothelin-1 is considered as a powerful coronary vasoconstrictor, produced by the endothelium. It acts to counter the effects of Nitric oxide (NO).
      Neuropeptide-Y, angiotensin1, cocaine, vasopressin, and nicotine are some other coronary vasoconstrictors.

      Chronotrophy and inotrophy occur after the activation of sympathetic nerve fibres, which in turn results in increasing the myocardial oxygen consumption, leading to increased coronary blood flow via local metabolic processes.

      An alpha-receptor mediated coronary vasoconstrictor effect is also initiated that usually competes with vasodilation, resulting in decreased coronary vascular resistance. Some of the other dilators include hydrogen ions, CO2, potassium, and lactic acid. The action of endothelial NO synthase (eNOS) on L-arginine results in the formation of NO. This messenger also plays a vital role in the regulation of coronary blood flow via vasodilation, inhibition of platelet aggression, and decreasing vascular resistance.
      Adenosine is considered as purine nucleoside that forms after the breakdown of adenosine triphosphate (ATP). Adenosine binds to adenosine type 2A (A2A) receptors in coronary vascular smooth muscles. These are coupled to the Gs protein. This mechanism leads to hyperpolarisation of muscle cells, resulting in relaxation and increased coronary blood flow.

      GTN is an veno and arteriolar dilator, which behaves as pro-drug with NO.

    • This question is part of the following fields:

      • Pathophysiology
      40.9
      Seconds
  • Question 8 - A new intravenous neuromuscular blocking agent has been developed. It has a hepatic...

    Incorrect

    • A new intravenous neuromuscular blocking agent has been developed. It has a hepatic extraction ratio of 0.25 and three quaternary nitrogen atoms in its structure. It has been discovered that it has a half-life of fifteen minutes in healthy volunteers. Which of the following elimination mechanisms is the most likely to explain this pharmacological behaviour?

      Your Answer: It is eliminated through the lungs

      Correct Answer: It is filtered and not reabsorbed by the renal tubules

      Explanation:

      The neuromuscular blocking agent is likely to be filtered and not reabsorbed by the renal tubules due to an exclusion process.

      Neuromuscular blocking agents that contain one or more quaternary nitrogen atoms are polar and ionised. As a result, the molecules have low lipid solubility, low membrane diffusion capacity, and low distribution volume.

      It’s unlikely that a compound with three quaternary nitrogen atoms is an ester. Its high polarity would prevent molecules from moving quickly into tissues.

      When drugs have a low hepatic extraction ratio (0.3), the venous and arterial drug concentrations are nearly identical. The liver is not the primary site of drug metabolism.

      Therefore:

      Changes in liver blood flow have no effect on clearance.
      Protein binding, intrinsic metabolism, and excretion are all very sensitive to changes in clearance.
      When taken orally, there is no first-pass metabolism.

      There is no reason for the lungs to eliminate any neuromuscular blocking agent.

    • This question is part of the following fields:

      • Pharmacology
      42.1
      Seconds
  • Question 9 - Activation of which of the following GABA A receptor subunit leads to anxiolytic...

    Correct

    • Activation of which of the following GABA A receptor subunit leads to anxiolytic effects of Benzodiazepines?

      Your Answer: Alpha

      Explanation:

      The GABAA-BZD (Gamma Aminobutyric acid- Benzodiazepine) receptor-Cl (chloride)€“ channel complex is composed
      of five α, β, γ, and in some cases δ, ε, θ or π subunits as well.
      Based on studies conducted in genetically mutated mice, it has been suggested that BZD receptor isoforms containing the α1
      Subunits are involved in mediating sedative, hypnotic, and amnesic actions of BZDs, while those containing α2 subunits mediate anxiolytic and muscle relaxant actions. Diazepam has a similar affinity for BZD receptor containing different (α1 or α2, or α3 or α5 ) subunits, and has broad-spectrum action.

    • This question is part of the following fields:

      • Pharmacology
      25.4
      Seconds
  • Question 10 - A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh...

    Incorrect

    • A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh and erectile dysfunction in a vascular clinic. The left femoral pulse is not palpable on examination, and the right is weakly palpable. Leriche syndrome is diagnosed as the blood flow at the abdominal aortic bifurcation is blocked due to atherosclerosis. He is prepared for aortoiliac bypass surgery. Which vertebral level will you find the affected artery that requires bypassing?

      Your Answer: L1

      Correct Answer: L4

      Explanation:

      The bifurcation of the abdominal aorta into common iliac arteries occurs at the level of L4. The bifurcation is a common site for atherosclerotic plaques as it is an area of high turbulence.

      Leriche Syndrome is an aortoiliac occlusive disease and affects the distal abdominal aorta, iliac arteries, and femoropopliteal vessels. It has a triad of symptoms:
      1. Claudication (cramping lower extremities pain that is reproducible by exercise)
      2. Impotence (reduced penile arterial flow)
      3. Absent/weak femoral pulses (hallmark)

      T12 – aorta enters the diaphragm with the thoracic duct and azygous veins

      L2 – testicular or ovarian arteries branch off the aorta

      L3 – inferior mesenteric artery.

    • This question is part of the following fields:

      • Anatomy
      47.5
      Seconds
  • Question 11 - The following is true about the extracellular fluid (ECF) in a normal adult...

    Incorrect

    • The following is true about the extracellular fluid (ECF) in a normal adult woman weighing 60 kg.

      Your Answer: Contains no protein

      Correct Answer: Has a total volume of about 12 litres

      Explanation:

      Total body water (TBW) is about 50% to 70% in adults depending on how much fat is present. ECF is relatively contracted in an obese person.

      The simple rule is 60-40-20. (60% of weight = total body water, 40% of body weight is ICF and 20% is ECF)

      For this woman, the total body water is 36 litres (0.6 × 60). ECF is 12 litres (1/3 of TBW) and 24 litres (2/3 of TBW) is intracellular fluid .

      Sodium concentration is approximately 135-145 mmol/L in the ECF.

      The ECF is made up of both intravascular and extravascular fluid and plasma proteins is found in both.

    • This question is part of the following fields:

      • Physiology
      35.6
      Seconds
  • Question 12 - A 24-year old female is brought to the emergency room due to urticarial...

    Incorrect

    • A 24-year old female is brought to the emergency room due to urticarial rash and shortness of breath. Her mother reported that, prior to the symptoms, she took Co-amoxiclav (Augmentin) for her present ear infection. She also reported that she had no previous exposure to penicillin or any other related antibiotics. Which of the following can help to differentiate between type 1 and type II hypersensitivity reaction in this case?

      Your Answer: Radio-allergosorbent test (RAST)

      Correct Answer: IgE assay specific for amoxycilloyl

      Explanation:

      Serum specific IgE assays against allergen sources/molecules are the most commonly used in vitro diagnostic approach. The measurement of specific IgE recognizing allergenic epitopes can be achieved both through the usage of single reagents (singleplex) or with a pre-defined panel of a number of molecules to be tested simultaneously (multiplex).

      Several clinical entities have been described and those occurring immediately after drug exposure are immunoglobulin E (IgE)-mediated and explored by skin testing and by the in vitro measurement of serum-specific IgE. The sensitivity of these tests is not 100% and even for patients with a clear positive history, a drug provocation test may be required in order to confirm the diagnosis. The advantages of the in vitro determination of specific IgE antibodies when compared with in vivo testing are that the former poses no direct risk to the patient and does not require personnel with expertise. Even though in vitro tests are recommended in immediate hypersensitivity reactions, their exact place in the diagnostic procedure is not clear and certain authors do not use this method in daily practice. In one study, in terms of sensitivity, 11 of 26 patients (42%) with negative skin tests and a positive drug provocation challenge (or repeated clinical history) had specific IgE to benzylpenicilloyl or amoxicilloyl (4). The specificity of the test was 95€“100%. Therefore, IgE measurements can avoid a potentially harmful drug provocation test.

      An elevated serum tryptase does not differentiate between type 1 and type 2 hypersensitivity reaction. It indicates mast cell degranulation.

      RAST is a useful aid to improve the overall diagnosis of drug allergies by using radioactive detection. This, however, is now rarely used.

      Quantification of basophil activation by CD63 expression can be done by flow cytometry, which forms the basis of experimental drug-induced basophil stimulation tests.

    • This question is part of the following fields:

      • Pathophysiology
      8.1
      Seconds
  • Question 13 - A morbidly obese (BMI=48) patient has the following co-morbidities: type II diabetes mellitus...

    Incorrect

    • A morbidly obese (BMI=48) patient has the following co-morbidities: type II diabetes mellitus and hypertension. It is recommended for the patient to undergo bariatric surgery. If the patient is laid flat for induction of anaesthesia, what physiologic changes of the respiratory system is the most important to consider?

      Your Answer: Peak expiratory flow rate will decrease

      Correct Answer: Functional residual capacity will decrease

      Explanation:

      A decrease in the functional residual capacity (FRC) is the most important physiologic change to consider for such patients.

      FRC is the sum of the expiratory reserve volume and the residual volume. It is the resting volume of the lung, and is an important marker for lung function. During this time, the alveolar pressure is equal to the atmospheric pressure. When morbidly obese individuals lie supine, the FRC decreases by as much as 40% because the abdominal contents push the diaphragm into the thoracic cavity.

      Chest wall compliance is expected to reduce because of fat deposition surrounding adjacent structures.

      Inspiratory reserve volume (IRV) is expected to increase, and peak expiratory flow is expected to decrease, however the decrease in FRC is more important to consider because of the risk of hypoxia secondary to premature airway closure and ventilation-perfusion mismatch.

    • This question is part of the following fields:

      • Physiology
      11.2
      Seconds
  • Question 14 - A 71-year-old woman will undergo surgery for a fractured femur neck. 1 mg...

    Correct

    • A 71-year-old woman will undergo surgery for a fractured femur neck. 1 mg midazolam is used to induce anaesthesia, followed by 75 mg propofol. Which of the following options best describes how these two drugs interact pharmacologically?

      Your Answer: Synergism

      Explanation:

      Drug interactions can be seen in the following examples:

      Additive interaction (summation).

      Additive effects are described for intravenous drug combinations such as ketamine and thiopentone or ketamine and midazolam. Different mechanisms of action are used by them. Thiopentone and midazolam are GABAA receptor agonists, whereas ketamine is an NMDA receptor antagonist. Nitrous oxide and halothane are two other examples.

      Synergism is a supra-additive interaction.

      Refers to the administration of two drugs with similar pharmacological properties and closely related sites of action, resulting in a combined effect that is greater than the sum of the contributions of each component. The construction of an isobologram can be used to interpret and understand these. The best example is the hypnotic effect of benzodiazepines and intravenous induction agents like propofol. As part of a co-induction technique, midazolam is frequently given before propofol.

      Potentiation

      In a dose-dependent manner, volatile agents enhance the effects of neuromuscular blocking agents. Electrolyte disturbance (hypomagnesaemia), Penicillin, and probenecid can all increase the effects of neuromuscular blocking agents (the latter has no similar pharmacological activity).

      Infra-additive interaction (antagonism).

      This can be subdivided into the following categories:

      -Pharmacokinetic interference occurs when one drug affects the absorption of another through the gastrointestinal tract or when hepatic microsomal enzyme induction influences metabolism.
      -Heparin and protamine, for example, or heavy metals and chelating agents, are examples of chemical antagonists.
      -Competitive reversible antagonistic antagonism of receptors, such as opioids and naloxone, and irreversible antagonistic antagonism of receptors

    • This question is part of the following fields:

      • Pharmacology
      72.1
      Seconds
  • Question 15 - The following are results of some pulmonary function tests: (Measurement - Predicted result...

    Incorrect

    • The following are results of some pulmonary function tests: (Measurement - Predicted result - Test result). Forced vital capacity (FVC) (btps): 3.21, - 1.94. Forced expiratory volume in 1 second (FEV1) (btps): 2.77, 1.82. FEV1/FVC ratio % (btps): 81.9, 93.5. Peak expiratory flow (PEF) (L/second): 6.55, 3.62. Maximum voluntary ventilation (MVV) (L/minute): 103, 87.1 Which statement applies to the results?

      Your Answer: The carbon monoxide transfer factor (TLCO) is likely to be high

      Correct Answer: The patient has a moderate restrictive pulmonary defect

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (V1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35%

      This patient has a %FVC predicted of 60.4% and this corresponds to a moderate restrictive deficit. V1/FVC ratio is 93.5%.

      FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture.

      FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.

      The integrity of the alveolar-capillary barrier is measured by carbon monoxide transfer factor (TLCO) and carbon monoxide transfer coefficient (KCO). These values are seen to be reduced in emphysema, interstitial lung diseases and in pulmonary vascular pathology. However, the KCO (as % predicted) is high in extrapulmonary restriction (pleural, chest wall and respiratory neuromuscular disease), and in loss of lung units provided the structure of the lung remaining is normal. The KCO distinguishes extrapulmonary (high KCO) causes of 'restriction' from intrapulmonary causes (low KCO).

    • This question is part of the following fields:

      • Clinical Measurement
      52.4
      Seconds
  • Question 16 - A 60-year-old man had previously been diagnosed with Type 2 diabetes. He had...

    Incorrect

    • A 60-year-old man had previously been diagnosed with Type 2 diabetes. He had recently started gliclazide, a sulphonyl urea, as his diabetes was not controlled by metformin alone. Now, he presents to his physician with complaints of anxiety, sweating, and palpitations since the morning. On physical examination, he is pale and clammy and has mydriasis and increased bowel sounds. Which biological site primarily synthesizes the hormone responsible for this patient's condition?

      Your Answer: Post-ganglionic neurones of the sympathetic nervous system

      Correct Answer: Chromaffin cells of the adrenal medulla

      Explanation:

      This patient has been shifted to a sulfonylurea drug whose most common side effect is hypoglycaemia. Similar symptoms can arise in a patient on insulin too. The signs and symptoms are consistent with a hypoglycaemic attack and include tachycardia, altered consciousness, and behaviour. This needs to be treated as an emergency with rapid correction of the blood glucose level using glucose or IV 20% dextrose.

      In a hypoglycaemic attack, the body undergoes stress and releases hormones to increase blood glucose levels. These include:
      Glucagon
      Cortisol
      Adrenaline

      Adrenaline or epinephrine is the hormone responsible for this patient’s condition and is primarily produced in the medulla of the adrenal gland. It functions primarily to raise cardiac output and raise blood glucose levels in the blood.

      Alpha-cells of the islets of Langerhans produce the hormone glucagon, which has opposing effects to insulin.

      Follicular cells of the thyroid gland produce and secrete thyroid hormones. Thyroid hormones can cause similar symptoms, but it is unlikely with the patient’s medical history.

      Post-ganglionic neurons of the sympathetic nervous system use norepinephrine as a neurotransmitter. Adrenaline can be made in these cells, but it is not their primary production site.

      Zona fasciculata of the adrenal cortex is the main site for the production of cortisol.

    • This question is part of the following fields:

      • Anatomy
      24.1
      Seconds
  • Question 17 - Weight of all of your patients in the ICU is analysed, and shows...

    Incorrect

    • Weight of all of your patients in the ICU is analysed, and shows that your date set is skewed. Which of the following will correctly show the average weight of your patients?

      Your Answer: Mode

      Correct Answer: Median

      Explanation:

      The question mentions a quantitative, ratio scale data set. The use of mean would be ideal under normal circumstances, however, in this situation median is preferred as it is less sensitive to the skewness of data. The median is usually preferred to other measures of central tendency when your data set is skewed (i.e., forms a skewed distribution)

    • This question is part of the following fields:

      • Statistical Methods
      21.3
      Seconds
  • Question 18 - A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT)...

    Incorrect

    • A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT) of 20 for the prevention of the primary end-point. These results can be best described as:

      Your Answer: For every 1000 patients treated with active therapy there would be 100 fewer strokes

      Correct Answer: For 1000 patients treated with active therapy, there would be 50 fewer strokes

      Explanation:

      Number needed to treat (NNT) is a time specific epidemiological measure that indicates how many patients would be require for an intervention to prevent one additional bad outcome. A perfect NNT would be 1, where everyone improves with treatment, thus the higher the NNT, the less effective the treatment.

      Thus if you treat 1000 patients then you will expect to have 50 fewer strokes.

    • This question is part of the following fields:

      • Statistical Methods
      8.6
      Seconds
  • Question 19 - A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought...

    Incorrect

    • A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought to the emergency department and undergoes investigations and treatment. On X-ray of the humerus, she has a mid-shaft fracture. What structure is at the highest risk of damage with a mid-shaft humeral fracture?

      Your Answer: Axillary artery

      Correct Answer: Radial nerve

      Explanation:

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs.
      The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The humeral shaft has two compartments:
      1. Anterior:
      Brachial artery and vein
      Biceps brachii, brachialis, coracobrachialis
      Musculocutaneous, median, and ulnar nerves
      2. Posterior:
      Radial nerve
      Triceps

      Other significant nerve injuries are:
      1. Axillary nerve – surgical neck fracture of the humerus
      2. Brachial Artery – supracondylar fracture of the humerus
      3. Axillary artery – surgical neck fracture of the humerus, but is relatively uncommon.

    • This question is part of the following fields:

      • Anatomy
      35.9
      Seconds
  • Question 20 - A 31-year old Caucasian female came into the emergency department due to difficulty...

    Incorrect

    • A 31-year old Caucasian female came into the emergency department due to difficulty of breathing. History revealed exposure to room odorizes that are rich in alkyl nitrites. Upon physical examination, patient is tachypnoeic at 32 breaths per minute, desaturated at 88% while on a non-rebreather mask at 15 litres per minute oxygen. She was also noted to be cyanotic, however with clear breath sounds. Considering the history, what is the most probable cause of her difficulty of breathing?

      Your Answer: High levels of 2,3-diphosphoglycerate

      Correct Answer: Increased affinity of bound oxygen to haemoglobin

      Explanation:

      Amyl nitrate is part of the treatment of cyanide poisoning. The short acting nitrate causes oxidation of Fe2+ in haemoglobin to Fe3+ in methaemoglobin. Methaemoglobin combines with cyanide (cyanmethemoglobin), which reacts with sodium thiosulfate to convert nontoxic thiocyanate and methaemoglobin.

      Methaemoglobin is formed when the iron in haemoglobin is converted from the reduced state (Fe2+) to the oxidized state (Fe3+). The oxidized form of haemoglobin (Fe3+) does not bind oxygen as readily as Fe2+, but has high affinity for cyanide. It also results to high affinity of bound oxygen to haemoglobin, thus leading to tissue hypoxia. Arterial oxygen tension is normal despite observations of cyanosis and dyspnoea. Methemoglobinemia can be treated with methylene blue and vitamin C.

      Carboxyhaemoglobin can be due to carbon monoxide poisoning. In such cases, patients experience headache and dizziness, but do not develop cyanosis.

      2,3-diphosphoglycerate causes a shift in the oxygen dissociation curve to the right, decreasing haemoglobin’s affinity to oxygen to facilitate unloading of oxygen to the tissues.

    • This question is part of the following fields:

      • Pathophysiology
      4.6
      Seconds
  • Question 21 - The cardiac tissue type that that has the highest conduction velocity is: ...

    Incorrect

    • The cardiac tissue type that that has the highest conduction velocity is:

      Your Answer: Ventricular myocardial tissue

      Correct Answer: Purkinje fibres

      Explanation:

      Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:

      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms.

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
      48.5
      Seconds
  • Question 22 - A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath...

    Correct

    • A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her. Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter. What is true regarding the organ where the filter is placed for this patient's condition?

      Your Answer: It is located posteriorly to the peritoneum

      Explanation:

      The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.

      The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.

      The IVC is a retroperitoneal organ.

    • This question is part of the following fields:

      • Anatomy
      21.4
      Seconds
  • Question 23 - Which of the following drugs is safe to be used in porphyria? ...

    Incorrect

    • Which of the following drugs is safe to be used in porphyria?

      Your Answer: Phenytoin

      Correct Answer: Chloral hydrate

      Explanation:

      Porphyria is a group of disorders in which there is excess production and excess excretion of porphyrins and their precursors. They are usually genetic and are caused due to defects in the haem metabolic pathway. However, other factors like infection, pregnancy, mensuration, starvation may precipitate the attack.

      Sulphonamides, barbiturates (methohexitone and thiopental), and phenytoin are considered to be precipitants so are not safe to use
      Chloral hydrate is thought to be safe to use.
      Etomidate lacks proper studies and may be used with caution but it is generally advised not to use this drug especially if other alternatives are available.

    • This question is part of the following fields:

      • Pharmacology
      15.1
      Seconds
  • Question 24 - Regarding amide local anaesthetics, which one factor has the most significant effect on...

    Incorrect

    • Regarding amide local anaesthetics, which one factor has the most significant effect on its duration of action?

      Your Answer: Tissue pH

      Correct Answer: Protein binding

      Explanation:

      When drugs are bound to proteins, drugs cannot cross membranes and exert their effect. Only the free (unbound) drug can be absorbed, distributed, metabolized, excreted and exert pharmacologic effect. Thus, when amide local anaesthetics are bound to α1-glycoproteins, their duration of action are reduced.

      The potency of local anaesthetics are affected by lipid solubility. Solubility influences the concentration of the drug in the extracellular fluid surrounding blood vessels. The brain, which is high in lipid content, will dissolve high concentration of lipid soluble drugs. When drugs are non-ionized and non-polarized, they are more lipid-soluble and undergo more extensive distribution. Hence allowing these drugs to penetrate the membrane of the target cells and exert their effect.

      Tissue pKa and pH will determine the degree of ionization.

    • This question is part of the following fields:

      • Physiology
      11.5
      Seconds
  • Question 25 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level. Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer: Chi squared test

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
      19.6
      Seconds
  • Question 26 - Regarding the information about kidney, which of the following is true? ...

    Incorrect

    • Regarding the information about kidney, which of the following is true?

      Your Answer: Cortical nephrons supply venous loops (vasa recta)

      Correct Answer: Each kidney contains approximately 1.2 million nephrons

      Explanation:

      Each kidney is composed of about 1.2 million uriniferous tubules. Each tubule consists of two parts that are embryologically distinct from each other. They are as follows:
      a) Excretory part, called the nephron, which elaborates urine
      b) Collecting part which begins as a junctional tubule from the distal convoluted tubule.

      There are two types of nephrons in the kidney:
      The cortical nephron comprises 80% of the total nephron and its major function is the excretion of waste products in urine whereas the juxtamedullary nephron comprises 20% of the total nephron and its major function is the concentration of urine by counter current mechanism.
      In the superficial (cortical) nephrons, peritubular capillaries branch off the efferent arterioles and deliver nutrients to epithelial cells as well as serve as a blood supply for reabsorption and secretion. In juxtamedullary nephrons, the peritubular capillaries have a specialization called the vasa recta, which are long, hairpin-shaped blood vessels that follow the same course as a loop of Henle. The vasa recta serve as osmotic exchangers for the production of concentrated urine.

      The kidney receives about 25% of cardiac output and about 20% of this is filtered at the glomeruli of the kidney. Thus, renal blood flow is 1200 ml/minute and renal plasma flow is 650 ml/minute.

    • This question is part of the following fields:

      • Anatomy
      21.1
      Seconds
  • Question 27 - The following results were obtained In a new drug trial: (Improved:Not improved) Placebo...

    Correct

    • The following results were obtained In a new drug trial: (Improved:Not improved) Placebo group 36: 26, Treatment group 44: 16. Regarding the statistical analysis or interpretation of the trial, one of these is true

      Your Answer: The data could be evaluated using the chi square test

      Explanation:

      This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.

      Since we are comparing proportions not means, the Student’s t test CANNOT be used.

      There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.

      Nothing is so obvious that no statistical analysis is needed.

    • This question is part of the following fields:

      • Statistical Methods
      20.1
      Seconds
  • Question 28 - Which of the following is true about number needed to harm? ...

    Incorrect

    • Which of the following is true about number needed to harm?

      Your Answer: The number of patients that must receive a particular treatment for one patient in that group to receive a positive outcome

      Correct Answer: The number of patients that must receive a particular treatment for one additional patient to experience an adverse outcome.

      Explanation:

      Number needed to harm are a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death). It is calculated as the inverse of the absolute risk reduction. It can equally well be applied to harmful outcomes as well as beneficial ones, where it becomes numbers needed to treat (NNT) instead.

      In this way, they are both calculated the same but NNT usually refers to a therapeutic treatment whereas NNH refers to a risk-factor for disease.

    • This question is part of the following fields:

      • Statistical Methods
      24.7
      Seconds
  • Question 29 - A 26-year old male patient was admitted to the surgery department for appendectomy....

    Correct

    • A 26-year old male patient was admitted to the surgery department for appendectomy. Medical history revealed that he has major depressive disorder and was on Phenelzine. Aside from abdominal pain, initial assessment was unremarkable. However, thirty minutes after, the patient was referred to you for generalized seizures. He was given an analgesic and it was noted that, during the first 15 minutes of administration, he became anxious, with profuse sweating, which later developed into seizures. Upon physical examination, he was febrile at 38.3°C. Which of the following statements is the best explanation for the patient's symptoms?

      Your Answer: Drug interaction with pethidine

      Explanation:

      The clinical picture best describes a probable drug interaction with pethidine.

      Phenelzine, a monoamine oxidase (MAO) inhibitor, when given with pethidine, an opioid analgesic, may lead to episodes of hypertension, rigidity, excitation, hyperpyrexia, seizures, coma and death. Studies have shown that pethidine reacts more significantly with MAO inhibitors than morphine.

      When pethidine is metabolised to normeperidine, it acts as a serotonin reuptake inhibitor and cause an increase in serotonin levels in the brain. MAO inhibitors can also lead to elevated levels of serotonin because of its mechanism of action by inhibiting the enzyme monoamine oxidase that degrades serotonin.

      The excess serotonin levels may lead to serotonin syndrome, of which some of the common precipitating drugs are selective serotonin reuptake inhibitors, MAO inhibitors, tricyclic antidepressants, meperidine, and St. John’s Wort. Onset of symptoms is within hours, which includes fever, agitation, tremor, clonus, hyperreflexia and diaphoresis.

      Drug interaction between phenelzine and paracetamol do not commonly precipitate serotonin syndrome.

      Neuroleptic malignant syndrome is due to dopamine antagonism, precipitated commonly by antipsychotics. Its onset of symptoms occur in 1 to 3 days, and is characterized by fever, encephalopathy, unstable vitals signs, elevated CPK, and rigidity.

      Altered mental status is the most common manifestation of sepsis-associated encephalopathy. Patient also exhibit confusional states and inappropriate behaviour. In some cases, this may lead to coma and death.

    • This question is part of the following fields:

      • Pharmacology
      124.5
      Seconds
  • Question 30 - All the following statements are false regarding local anaesthetic except ...

    Incorrect

    • All the following statements are false regarding local anaesthetic except

      Your Answer:

      Correct Answer: Potency is directly related to lipid solubility

      Explanation:

      The potency of local anaesthetics is directly proportional to lipid solubility because they need to penetrate the lipid-soluble membrane to enter the cell.

      Protein binding has a direct relationship with the duration of action because the higher the ability of the drug to bind with membrane protein, the higher is the duration of action.

      Higher the pKa of a drug, slower the onset of action. Because a drug with higher pKa will be more ionized than the one with lower pKa at a given pH. Local anaesthetics are weak bases, and unionized form diffuses more rapidly across the nerve membrane than the protonated form. As a result drugs with higher pKa will be more ionized will diffuse less across the nerve membrane.

    • This question is part of the following fields:

      • Pharmacology
      0
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SESSION STATS - PERFORMANCE PER SPECIALTY

Anatomy (3/7) 43%
Basic Physics (0/1) 0%
Physiology And Biochemistry (1/2) 50%
Statistical Methods (1/6) 17%
Anaesthesia Related Apparatus (0/1) 0%
Pathophysiology (1/3) 33%
Pharmacology (4/5) 80%
Physiology (2/3) 67%
Clinical Measurement (1/1) 100%
Passmed