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Question 1
Incorrect
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A 73-year-old male has been diagnosed with Barrett's oesophagus. The histological examination reveals a reversible alteration in the adult cell type. Due to prolonged chemical irritation, a glandular cell replaces a squamous cell. What is the type of cellular alteration demonstrated in this case?
Your Answer: Dysplasia
Correct Answer: Metaplasia
Explanation:Cellular Adaptations: Hypertrophy, Hyperplasia, Metaplasia, and Dysplasia
Cellular adaptations refer to the changes that a cell undergoes in response to external pressures to survive in a different steady state. There are four main types of cellular adaptations: hypertrophy, hyperplasia, metaplasia, and dysplasia.
Hypertrophy is an increase in cell mass without an increase in cell number. This adaptive response is due to an increase in the number of intracellular organelles to maintain cell viability at high levels of aerobic metabolism.
Hyperplasia, on the other hand, is an increase in the number of cells, resulting in an increase in the volume of an organ or tissue. It can occur physiologically, under normal physiological control, or pathologically, due to excessive hormonal stimulation that is not under normal physiological control.
Metaplasia is a reversible change in form and differentiation, where one adult cell type is replaced by another adult cell type due to chronic chemical or physical irritation. This change can result in tissues having a form that they were not designed for.
Dysplasia is abnormal cell growth that is a morphological feature of malignancy, characterized by increased cell proliferation and incomplete differentiation. It can act as an early sign of a tumor, occurring at the epithelium stage where there is no invasion of the basement membrane and surrounding tissues.
In summary, cellular adaptations are essential for cells to survive in different steady states. Understanding the different types of cellular adaptations can help in the diagnosis and treatment of various diseases.
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This question is part of the following fields:
- General Principles
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Question 2
Correct
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A man in his early fifties presents to the GP with hearing loss in his right ear. After conducting a Webber's and Rinne's test, the following results were obtained:
- Webber's test: lateralizes to the left ear
- Rinne's test (left ear): Air > Bone
- Rinne's test (right ear): Air > Bone
What is the probable cause of his hearing loss?Your Answer: Acoustic neuroma
Explanation:Sensorineural hearing loss in the right ear is indicative of an acoustic neuroma, which is the only option listed as a cause for this type of hearing loss. Other options such as otitis media with effusion and otitis externa cause conductive hearing loss, while ossicular fracture is a rare cause of conductive hearing loss. Understanding the Weber and Rinne tests is important in interpreting these results accurately.
Vestibular schwannomas, also known as acoustic neuromas, make up about 5% of intracranial tumors and 90% of cerebellopontine angle tumors. These tumors typically present with a combination of vertigo, hearing loss, tinnitus, and an absent corneal reflex. The specific symptoms can be predicted based on which cranial nerves are affected. For example, cranial nerve VIII involvement can cause vertigo, unilateral sensorineural hearing loss, and unilateral tinnitus. Bilateral vestibular schwannomas are associated with neurofibromatosis type 2.
If a vestibular schwannoma is suspected, it is important to refer the patient to an ear, nose, and throat specialist urgently. However, it is worth noting that these tumors are often benign and slow-growing, so observation may be appropriate initially. The diagnosis is typically confirmed with an MRI of the cerebellopontine angle, and audiometry is also important as most patients will have some degree of hearing loss. Treatment options include surgery, radiotherapy, or continued observation.
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This question is part of the following fields:
- Neurological System
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Question 3
Incorrect
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An 82-year-old woman visits her doctor with a medical history of myocardial infarction that has resulted in permanent damage to the conduction system of her heart. The damage has affected the part of the conduction system with the highest velocities, causing desynchronisation of the ventricles.
What is the part of the heart that conducts the fastest?Your Answer: Atrioventricular node
Correct Answer: Purkinje fibres
Explanation:The Purkinje fibres have the highest conduction velocities in the heart’s electrical conduction system. The process starts with the SA node generating spontaneous action potentials, which are then conducted across both atria through cell to cell conduction at a speed of approximately 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node, which has a slow conduction speed of 0.05ms to allow for complete atrial contraction and ventricular filling. The action potentials are then conducted through the Bundle of His, which splits into the left and right bundle branches, with a conduction speed of approximately 2m/s. Finally, the action potential reaches the Purkinje fibres, which are specialized conducting cells that allow for a faster conduction speed of 2-4m/s. This fast conduction speed is crucial for a synchronized and efficient contraction of the ventricle, generating pressure during systole.
Understanding the Cardiac Action Potential and Conduction Velocity
The cardiac action potential is a series of electrical events that occur in the heart during each heartbeat. It is responsible for the contraction of the heart muscle and the pumping of blood throughout the body. The action potential is divided into five phases, each with a specific mechanism. The first phase is rapid depolarization, which is caused by the influx of sodium ions. The second phase is early repolarization, which is caused by the efflux of potassium ions. The third phase is the plateau phase, which is caused by the slow influx of calcium ions. The fourth phase is final repolarization, which is caused by the efflux of potassium ions. The final phase is the restoration of ionic concentrations, which is achieved by the Na+/K+ ATPase pump.
Conduction velocity is the speed at which the electrical signal travels through the heart. The speed varies depending on the location of the signal. Atrial conduction spreads along ordinary atrial myocardial fibers at a speed of 1 m/sec. AV node conduction is much slower, at 0.05 m/sec. Ventricular conduction is the fastest in the heart, achieved by the large diameter of the Purkinje fibers, which can achieve velocities of 2-4 m/sec. This allows for a rapid and coordinated contraction of the ventricles, which is essential for the proper functioning of the heart. Understanding the cardiac action potential and conduction velocity is crucial for diagnosing and treating heart conditions.
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This question is part of the following fields:
- Cardiovascular System
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Question 4
Incorrect
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A 20-year-old male has recently been diagnosed with an infectious episode that caused a sore throat. The illness was found to be caused by a gram-positive cocci in chains. Two weeks later, he developed teardrop erythematous lesions on his trunk and arms. What is the most probable diagnosis?
Your Answer: Impetigo
Correct Answer: Guttate psoriasis
Explanation:Guttate psoriasis is frequently seen after a streptococcal infection, with group-A streptococcus being the likely culprit. The condition is characterized by the appearance of small, teardrop shaped red lesions. Scarlet fever, which is also caused by group-A streptococcus, presents with a rough rash, fever, swollen lymph nodes, and a red tongue. Pityriasis rosea, on the other hand, typically follows a viral infection and is identified by a single scaly patch followed by a widespread salmon-pink rash. Acne vulgaris and impetigo are not commonly associated with a streptococcal sore throat.
Guttate psoriasis is a type of psoriasis that is more commonly seen in children and adolescents. It is often triggered by a streptococcal infection that occurred 2-4 weeks prior to the appearance of the lesions. The condition is characterized by the presence of tear drop-shaped papules on the trunk and limbs, along with pink, scaly patches or plaques of psoriasis. The onset of guttate psoriasis tends to be acute, occurring over a few days.
In most cases, guttate psoriasis resolves on its own within 2-3 months. There is no clear evidence to support the use of antibiotics to treat streptococcal infections associated with the condition. Treatment options for guttate psoriasis include topical agents commonly used for psoriasis and UVB phototherapy. In cases where the condition recurs, a tonsillectomy may be necessary.
It is important to differentiate guttate psoriasis from pityriasis rosea, which is another skin condition that can present with similar symptoms. Guttate psoriasis is typically preceded by a streptococcal sore throat, while pityriasis rosea may be associated with recent respiratory tract infections. The appearance of guttate psoriasis is characterized by tear drop-shaped, scaly papules on the trunk and limbs, while pityriasis rosea presents with a herald patch followed by multiple erythematous, slightly raised oval lesions with a fine scale. Pityriasis rosea is self-limiting and resolves after around 6 weeks.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 5
Incorrect
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A 54-year-old man was admitted 2 weeks ago for pneumonia and was prescribed oral antibiotics. However, the antibiotics were changed after he developed a Clostridium difficile infection 9 days ago, which he is still recovering from. Fortunately, his pneumonia has improved.
He has no significant medical history and is not taking any long-term medications.
What are the expected results of his arterial blood gas test?Your Answer:
Correct Answer: Normal anion gap metabolic acidosis
Explanation:Diarrhoea caused by a Clostridium difficile infection can result in a normal anion gap metabolic acidosis due to the loss of bicarbonate. The body compensates for this by increasing chloride concentration, which maintains a normal anion gap. Low anion gap metabolic acidosis, normal anion gap metabolic alkalosis, and raised anion gap metabolic acidosis are all incorrect as they do not accurately reflect the compensatory mechanisms in this scenario.
Understanding Metabolic Acidosis
Metabolic acidosis is a condition that can be classified based on the anion gap, which is calculated by subtracting the sum of chloride and bicarbonate from the sum of sodium and potassium. The normal range for anion gap is 10-18 mmol/L. If a question provides the chloride level, it may be an indication to calculate the anion gap.
Hyperchloraemic metabolic acidosis is a type of metabolic acidosis with a normal anion gap. It can be caused by gastrointestinal bicarbonate loss, prolonged diarrhea, ureterosigmoidostomy, fistula, renal tubular acidosis, drugs like acetazolamide, ammonium chloride injection, and Addison’s disease. On the other hand, raised anion gap metabolic acidosis is caused by lactate, ketones, urate, acid poisoning, and other factors.
Lactic acidosis is a type of metabolic acidosis that is caused by high lactate levels. It can be further classified into two types: lactic acidosis type A, which is caused by sepsis, shock, hypoxia, and burns, and lactic acidosis type B, which is caused by metformin. Understanding the different types and causes of metabolic acidosis is important in diagnosing and treating the condition.
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This question is part of the following fields:
- Renal System
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Question 6
Incorrect
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A 35-year-old female patient visits the gastroenterology clinic complaining of abdominal discomfort, bloating, flatulence, and diarrhea that have persisted for 8 months. She reports that her symptoms worsen after consuming meals, particularly those high in carbohydrates. During the examination, the gastroenterologist observes no significant abdominal findings but notices rashes on her elbows and knees. As part of her diagnostic workup, the gastroenterologist is contemplating endoscopy and small bowel biopsy. What is the probable biopsy result?
Your Answer:
Correct Answer: Villous atrophy
Explanation:Coeliac disease can be diagnosed through a biopsy that shows villous atrophy, raised intra-epithelial lymphocytes, and crypt hyperplasia. This condition is likely the cause of the patient’s chronic symptoms, which are triggered by meals containing gluten. Fortunately, adhering to a strict gluten-free diet can reverse the villous atrophy. In some cases, coeliac disease may also present with a vesicular rash called dermatitis herpetiformis. Other pathological findings, such as mucosal defects, irregular gland-like structures, or transmural inflammation with granulomas and lymphoid aggregates, suggest different diseases.
Investigating Coeliac Disease
Coeliac disease is a condition caused by sensitivity to gluten, which leads to villous atrophy and malabsorption. It is often associated with other conditions such as dermatitis herpetiformis and autoimmune disorders. Diagnosis is made through a combination of serology and endoscopic intestinal biopsy, with villous atrophy and immunology typically reversing on a gluten-free diet.
To investigate coeliac disease, NICE guidelines recommend using tissue transglutaminase (TTG) antibodies (IgA) as the first-choice serology test, along with endomyseal antibody (IgA) and testing for selective IgA deficiency. Anti-gliadin antibody (IgA or IgG) tests are not recommended. The ‘gold standard’ for diagnosis is an endoscopic intestinal biopsy, which should be performed in all suspected cases to confirm or exclude the diagnosis. Findings supportive of coeliac disease include villous atrophy, crypt hyperplasia, increase in intraepithelial lymphocytes, and lamina propria infiltration with lymphocytes. Rectal gluten challenge is a less commonly used method.
In summary, investigating coeliac disease involves a combination of serology and endoscopic intestinal biopsy, with NICE guidelines recommending specific tests and the ‘gold standard’ being an intestinal biopsy. Findings supportive of coeliac disease include villous atrophy, crypt hyperplasia, and lymphocyte infiltration.
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This question is part of the following fields:
- Gastrointestinal System
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Question 7
Incorrect
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A 55-year-old man with uncontrolled type 2 diabetes is hospitalized and presents with elevated inflammatory markers, metabolic acidosis, leukocytosis, and an amylase level of 3480 U/L. Which medication is the probable cause?
Your Answer:
Correct Answer: Exenatide
Explanation:Exenatide and Pancreatitis: A Review of the Evidence
Exenatide is a medication that mimics the effects of the hormone GLP-1, which triggers insulin secretion in response to food intake. However, there is a rare but concerning association between exenatide and acute pancreatitis. A recent case-control study found that patients taking GLP-1 mimetics like exenatide had a higher risk of developing pancreatitis compared to those taking other diabetes drugs. As a result, patients starting on exenatide should be informed about the symptoms of pancreatitis and monitored closely for abdominal pain.
While there is some controversy surrounding the association between gliptins and pancreatitis, the British National Formulary recommends discontinuing sitagliptin if acute pancreatitis is suspected. It is important to note that lactic acidosis, a potential side effect of metformin, should not be confused with pancreatitis, which is characterized by elevated levels of amylase. Overall, healthcare providers should be aware of the potential risk of pancreatitis in patients taking exenatide and other GLP-1 mimetics, and take appropriate precautions to monitor and manage this condition.
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This question is part of the following fields:
- Pharmacology
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Question 8
Incorrect
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Samantha, a 32-year-old female, is brought to the emergency department by ambulance following a fall. She complains of pain in her right shoulder.
On examination, the doctor observes drooping of the right shoulder downwards. Samantha is given pain relief and an x-ray is arranged. The report confirms a clavicle fracture.
What is the most frequent site of this type of fracture?Your Answer:
Correct Answer: Middle third of the clavicle
Explanation:Fractures of the clavicle typically occur in the medial third, with the lateral aspect being displaced inferiorly by the weight of the arm and medially by the pull of the pectoralis major muscle. Meanwhile, the medial aspect of the fracture is usually displaced superiorly due to the pull of the sternocleidomastoid muscle.
Anatomy of the Clavicle
The clavicle is a bone that runs from the sternum to the acromion and plays a crucial role in preventing the shoulder from falling forwards and downwards. Its inferior surface is marked by ligaments at each end, including the trapezoid line and conoid tubercle, which provide attachment to the coracoclavicular ligament. The costoclavicular ligament attaches to the irregular surface on the medial part of the inferior surface, while the subclavius muscle attaches to the intermediate portion’s groove.
The superior part of the clavicle medial end has a raised surface that gives attachment to the clavicular head of sternocleidomastoid, while the posterior surface attaches to the sternohyoid. On the lateral end, there is an oval articular facet for the acromion, and a disk lies between the clavicle and acromion. The joint’s capsule attaches to the ridge on the margin of the facet.
In summary, the clavicle is a vital bone that helps stabilize the shoulder joint and provides attachment points for various ligaments and muscles. Its anatomy is marked by distinct features that allow for proper function and movement.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 9
Incorrect
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A 10-year-old girl with no previous medical history presents to the emergency department with vomiting and diarrhea. She also complains of abdominal pain. A venous blood gas test is performed and shows the following results:
Normal range
pH: 7.14 (7.35 - 7.45)
pO2: 11.6 (10 - 14)kPa
pCO2: 3.3 (4.5 - 6.0)kPa
HCO3: 10 (22 - 26)mmol/l
BE: -16 (-2 to +2)mmol/l
Lactate: 4.1 0.6-1.8mmol/l
Potassium: 5.4 3.5-5 mmol/l
A blood glucose finger-prick test is also performed, which reads Glucose = 24. Based on the information provided, what is the most likely diagnosis?Your Answer:
Correct Answer: Diabetic ketoacidosis
Explanation:Diabetic ketoacidosis is depicted in this image. It is a critical condition that requires urgent attention, with a focus on administering insulin, fluid resuscitation, and closely monitoring potassium levels.
Diabetic ketoacidosis (DKA) is a serious complication of type 1 diabetes mellitus, accounting for around 6% of cases. It can also occur in rare cases of extreme stress in patients with type 2 diabetes mellitus. DKA is caused by uncontrolled lipolysis, resulting in an excess of free fatty acids that are converted to ketone bodies. The most common precipitating factors of DKA are infection, missed insulin doses, and myocardial infarction. Symptoms include abdominal pain, polyuria, polydipsia, dehydration, Kussmaul respiration, and breath that smells like acetone. Diagnostic criteria include glucose levels above 11 mmol/l or known diabetes mellitus, pH below 7.3, bicarbonate below 15 mmol/l, and ketones above 3 mmol/l or urine ketones ++ on dipstick.
Management of DKA involves fluid replacement, insulin, and correction of electrolyte disturbance. Fluid replacement is necessary as most patients with DKA are deplete around 5-8 litres. Isotonic saline is used initially, even if the patient is severely acidotic. Insulin is administered through an intravenous infusion, and correction of electrolyte disturbance is necessary. Long-acting insulin should be continued, while short-acting insulin should be stopped. Complications may occur from DKA itself or the treatment, such as gastric stasis, thromboembolism, arrhythmias, acute respiratory distress syndrome, acute kidney injury, and cerebral edema. Children and young adults are particularly vulnerable to cerebral edema following fluid resuscitation in DKA and often need 1:1 nursing to monitor neuro-observations, headache, irritability, visual disturbance, focal neurology, etc.
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This question is part of the following fields:
- Endocrine System
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Question 10
Incorrect
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A woman in her early pregnancy is diagnosed with anaemia during a routine check-up. She is informed that this is a common occurrence. What causes anaemia to develop during pregnancy?
Your Answer:
Correct Answer: Haemodilution by the increased plasma volume
Explanation:Anaemia in pregnancy results from a greater increase in plasma volume compared to haemoglobin concentration, leading to a dilution of haemoglobin levels. It is important to note that haemoglobin levels actually increase during pregnancy. Drinking more water does not cause anaemia, as any excess water would be eliminated by the kidneys. Additionally, reduced secretion of ADH does not occur during pregnancy and would result in diuresis rather than anaemia.
During pregnancy, women are checked for anaemia twice – once at the initial booking visit (usually at 8-10 weeks) and again at 28 weeks. The National Institute for Health and Care Excellence (NICE) has set specific cut-off levels to determine if a woman requires oral iron therapy. For the first trimester, the cut-off is less than 110 g/L, for the second and third trimesters, it is less than 105 g/L, and for the postpartum period, it is less than 100 g/L. If a woman falls below these levels, she should receive oral ferrous sulfate or ferrous fumarate. Treatment should continue for three months after iron deficiency is corrected to allow for the replenishment of iron stores.
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This question is part of the following fields:
- Reproductive System
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Question 11
Incorrect
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A 36-year-old woman has been diagnosed with breast and ovarian cancer. Her mother and sister were also diagnosed with breast and ovarian cancer before the age of 40. She has no other medical history.
During examination, a lump was found in her left breast and palpable axillary lymph nodes.
Which investigation is the most appropriate to confirm the genetic diagnosis underlying this condition, from the options provided?Your Answer:
Correct Answer: Polymerase chain reaction (PCR)
Explanation:Reverse Transcriptase PCR
Reverse transcriptase PCR (RT-PCR) is a molecular genetic technique used to amplify RNA. This technique is useful for analyzing gene expression in the form of mRNA. The process involves converting RNA to DNA using reverse transcriptase. The resulting DNA can then be amplified using PCR.
To begin the process, a sample of RNA is added to a test tube along with two DNA primers and a thermostable DNA polymerase (Taq). The mixture is then heated to almost boiling point, causing denaturing or uncoiling of the RNA. The mixture is then allowed to cool, and the complimentary strands of DNA pair up. As there is an excess of the primer sequences, they preferentially pair with the DNA.
The above cycle is then repeated, with the amount of DNA doubling each time. This process allows for the amplification of the RNA, making it easier to analyze gene expression. RT-PCR is a valuable tool in molecular biology and has many applications in research, including the study of diseases and the development of new treatments.
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This question is part of the following fields:
- General Principles
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Question 12
Incorrect
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Which one of the following is not a direct branch of the facial nerve?
Your Answer:
Correct Answer: Auriculotemporal
Explanation:The mandibular nerve gives rise to several branches, including the auriculotemporal nerve, lingual nerve, inferior alveolar nerve, nerve to the mylohyoid, and mental nerve.
The facial nerve is responsible for supplying the muscles of facial expression, the digastric muscle, and various glandular structures. It also contains a few afferent fibers that originate in the genicular ganglion and are involved in taste. Bilateral facial nerve palsy can be caused by conditions such as sarcoidosis, Guillain-Barre syndrome, Lyme disease, and bilateral acoustic neuromas. Unilateral facial nerve palsy can be caused by these conditions as well as lower motor neuron issues like Bell’s palsy and upper motor neuron issues like stroke.
The upper motor neuron lesion typically spares the upper face, specifically the forehead, while a lower motor neuron lesion affects all facial muscles. The facial nerve’s path includes the subarachnoid path, where it originates in the pons and passes through the petrous temporal bone into the internal auditory meatus with the vestibulocochlear nerve. The facial canal path passes superior to the vestibule of the inner ear and contains the geniculate ganglion at the medial aspect of the middle ear. The stylomastoid foramen is where the nerve passes through the tympanic cavity anteriorly and the mastoid antrum posteriorly, and it also includes the posterior auricular nerve and branch to the posterior belly of the digastric and stylohyoid muscle.
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This question is part of the following fields:
- Neurological System
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Question 13
Incorrect
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A 6-year-old girl is brought to the physician by her mother due to fatigue and lethargy for the past 9 months. Previously, she was very active and was at the 80th percentile for height and weight. Currently, she is also unable to concentrate and lagging academically in school. The family moved to an old house 3 years back. During physical examination, conjunctival pallor and a blue line on her gingiva are observed.
Blood tests reveal:
Hb 100 g/L Male: (119-150)
Female: (119-150)
Platelets 340 * 109/L (150 - 400)
WBC 4 * 109/L (4.0 - 11.0)
Mean corpuscular volume (MCV) 70 fL (80 - 100)
A skeletal survey shows dense opacity at the junction of metaphysis and epiphysis of the long bones.
What is the most probable diagnosis?Your Answer:
Correct Answer: Lead poisoning
Explanation:Lead poisoning can cause the accumulation of lead in the metaphysis of bones, which can be seen as bands of increased density on x-rays. In this case, the child’s recent deterioration in academic and physical performance, along with the history of moving to an old house, suggests the possibility of lead-based paint exposure. The presence of a lead line on the gums further supports this suspicion. While normocytic anemia can have many causes, the addition of radiodense lines in the metaphysis of long bones increases the likelihood of lead poisoning. Cretinism, caused by maternal hypothyroidism, typically presents earlier and has different symptoms. Osteomyelitis, an infection of the bone, has different x-ray findings. Sickle cell anemia and iron deficiency are not associated with the symptoms and x-ray findings in this case.
Lead poisoning is a condition that should be considered when a patient presents with abdominal pain and neurological symptoms, along with acute intermittent porphyria. This condition is caused by defective ferrochelatase and ALA dehydratase function. Symptoms of lead poisoning include abdominal pain, peripheral neuropathy (mainly motor), neuropsychiatric features, fatigue, constipation, and blue lines on the gum margin (which is rare in children and only present in 20% of adult patients).
To diagnose lead poisoning, doctors typically measure the patient’s blood lead level, with levels greater than 10 mcg/dl considered significant. A full blood count may also be performed, which can reveal microcytic anemia and red cell abnormalities such as basophilic stippling and clover-leaf morphology. Additionally, raised serum and urine levels of delta aminolaevulinic acid may be seen, which can sometimes make it difficult to differentiate from acute intermittent porphyria. Urinary coproporphyrin is also increased, while urinary porphobilinogen and uroporphyrin levels are normal to slightly increased. In children, lead can accumulate in the metaphysis of the bones, although x-rays are not typically part of the standard work-up.
Various chelating agents are currently used to manage lead poisoning, including dimercaptosuccinic acid (DMSA), D-penicillamine, EDTA, and dimercaprol. These agents work to remove the lead from the body and can help alleviate symptoms.
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This question is part of the following fields:
- Haematology And Oncology
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Question 14
Incorrect
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A 9-month-old girl is brought to the emergency department by her mother due to difficulty in breathing. The mother reports that her daughter has been restless, with a runny nose, feeling warm and a dry cough for the past 4 days. However, the mother is now quite worried because her daughter has not eaten since last night and her breathing seems to have worsened throughout the morning.
During the examination, the infant has a respiratory rate of 70/min, heart rate of 155/min, oxygen saturation of 92% and a temperature of 37.9ºC. The infant shows signs of nasal flaring and subcostal recession while breathing. On auscultation, widespread wheezing is heard. The infant is admitted, treated with humidified oxygen via nasal cannula and discharged home after 2 days.
What is the probable causative agent of this infant's illness?Your Answer:
Correct Answer: Respiratory syncytial virus
Explanation:Bronchiolitis typically presents with symptoms such as coryza and increased breathing effort, leading to feeding difficulties in children under one year of age. The majority of cases of bronchiolitis are caused by respiratory syncytial virus, while adenovirus is a less frequent culprit. On the other hand, croup is most commonly caused by parainfluenza virus.
Understanding Bronchiolitis
Bronchiolitis is a condition that is characterized by inflammation of the bronchioles. It is a serious lower respiratory tract infection that is most common in children under the age of one year. The pathogen responsible for 75-80% of cases is respiratory syncytial virus (RSV), while other causes include mycoplasma and adenoviruses. Bronchiolitis is more serious in children with bronchopulmonary dysplasia, congenital heart disease, or cystic fibrosis.
The symptoms of bronchiolitis include coryzal symptoms, dry cough, increasing breathlessness, and wheezing. Fine inspiratory crackles may also be present. Children with bronchiolitis may experience feeding difficulties associated with increasing dyspnoea, which is often the reason for hospital admission.
Immediate referral to hospital is recommended if the child has apnoea, looks seriously unwell to a healthcare professional, has severe respiratory distress, central cyanosis, or persistent oxygen saturation of less than 92% when breathing air. Clinicians should consider referring to hospital if the child has a respiratory rate of over 60 breaths/minute, difficulty with breastfeeding or inadequate oral fluid intake, or clinical dehydration.
The investigation for bronchiolitis involves immunofluorescence of nasopharyngeal secretions, which may show RSV. Management of bronchiolitis is largely supportive, with humidified oxygen given via a head box if oxygen saturations are persistently < 92%. Nasogastric feeding may be needed if children cannot take enough fluid/feed by mouth, and suction is sometimes used for excessive upper airway secretions.
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This question is part of the following fields:
- Respiratory System
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Question 15
Incorrect
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An 80-year-old man visits his GP complaining of indigestion that has persisted for the last three months. He has a medical history of hypertension and is a heavy smoker with a 50-pack-year history. He also consumes three glasses of wine on weeknights. Upon referral to a gastroenterologist, a lower oesophageal and stomach biopsy is performed, revealing metaplastic columnar epithelium. What is the primary factor that has contributed to the development of this histological finding?
Your Answer:
Correct Answer: Gastro-oesophageal reflux disease (GORD)
Explanation:Barrett’s oesophagus is diagnosed in this patient based on the presence of metaplastic columnar epithelium in the oesophageal epithelium. The most significant risk factor for the development of Barrett’s oesophagus is gastro-oesophageal reflux disease (GORD). While age is also a risk factor, it is not as strong as GORD. Alcohol consumption is not associated with Barrett’s oesophagus, but it is a risk factor for squamous cell oesophageal carcinoma. Infection with Helicobacter pylori is not linked to Barrett’s oesophagus, and it may even reduce the risk of GORD and Barrett’s oesophagus. Smoking is associated with both GORD and Barrett’s oesophagus, but the strength of this association is not as significant as that of GORD.
Barrett’s oesophagus is a condition where the lower oesophageal mucosa is replaced by columnar epithelium, which increases the risk of oesophageal adenocarcinoma by 50-100 fold. It is usually identified during an endoscopy for upper gastrointestinal symptoms such as dyspepsia, as there are no screening programs for it. The length of the affected segment determines the chances of identifying metaplasia, with short (<3 cm) and long (>3 cm) subtypes. The prevalence of Barrett’s oesophagus is estimated to be around 1 in 20, and it is identified in up to 12% of those undergoing endoscopy for reflux.
The columnar epithelium in Barrett’s oesophagus may resemble that of the cardiac region of the stomach or that of the small intestine, with goblet cells and brush border. The single strongest risk factor for Barrett’s oesophagus is gastro-oesophageal reflux disease (GORD), followed by male gender, smoking, and central obesity. Alcohol is not an independent risk factor for Barrett’s, but it is associated with both GORD and oesophageal cancer. Patients with Barrett’s oesophagus often have coexistent GORD symptoms.
The management of Barrett’s oesophagus involves high-dose proton pump inhibitor, although the evidence base for its effectiveness in reducing the progression to dysplasia or inducing regression of the lesion is limited. Endoscopic surveillance with biopsies is recommended every 3-5 years for patients with metaplasia but not dysplasia. If dysplasia of any grade is identified, endoscopic intervention is offered, such as radiofrequency ablation, which is the preferred first-line treatment, particularly for low-grade dysplasia, or endoscopic mucosal resection.
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This question is part of the following fields:
- Gastrointestinal System
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Question 16
Incorrect
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The Trendelenburg test evaluates the integrity of which muscle?
Your Answer:
Correct Answer: Gluteus medius
Explanation:The Trendelenburg Test: Assessing Gluteal Nerve Function
The Trendelenburg test is a diagnostic tool used to assess the function of the superior gluteal nerve. This nerve is responsible for the contraction of the gluteus medius muscle, which is essential for maintaining balance and stability while standing on one leg.
When the superior gluteal nerve is injured or damaged, the gluteus medius muscle is weakened, resulting in a compensatory shift of the body towards the unaffected side. This shift is characterized by a gravitational shift, which causes the body to be supported on the unaffected limb.
To perform the Trendelenburg test, the patient is asked to stand on one leg while the physician observes the position of the pelvis. In a healthy individual, the gluteus medius muscle contracts as soon as the contralateral leg leaves the floor, preventing the pelvis from dipping towards the unsupported side. However, in a person with paralysis of the superior gluteal nerve, the pelvis on the unsupported side descends, indicating that the gluteus medius on the affected side is weak or non-functional. This is known as a positive Trendelenburg test.
It is important to note that the Trendelenburg test is also used in vascular investigations to determine the presence of saphenofemoral incompetence. In this case, tourniquets are placed around the upper thigh to assess blood flow. However, in the context of assessing gluteal nerve function, the Trendelenburg test is a valuable tool for diagnosing and treating motor deficits and gait abnormalities.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 17
Incorrect
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A 70-year-old male arrives at the emergency department complaining of tearing chest pain that radiates to his back. He has a history of uncontrolled hypertension. During auscultation, a diastolic murmur is heard, which is most audible over the 2nd intercostal space, right sternal border. What chest radiograph findings are expected from this patient's presentation?
Your Answer:
Correct Answer: Widened mediastinum
Explanation:Aortic dissection can cause a widened mediastinum on a chest x-ray. This condition is characterized by tearing chest pain that radiates to the back, hypertension, and aortic regurgitation. It occurs when there is a tear in the tunica intima of the aorta’s wall, creating a false lumen that fills with a large volume of blood.
Calcification of the arch of the aorta, cardiomegaly, displacement of the trachea from the midline, and enlargement of the aortic knob are not commonly associated with aortic dissection. Calcification of the walls of arteries is a chronic process that occurs with age and is more likely in men. Cardiomegaly can be caused by various conditions, including ischaemic heart disease and congenital abnormalities. Displacement of the trachea from the midline can result from other pathologies such as a tension pneumothorax or an aortic aneurysm. Enlargement of the aortic knob is a classical finding of an aortic aneurysm.
Aortic dissection is classified according to the location of the tear in the aorta. The Stanford classification divides it into type A, which affects the ascending aorta in two-thirds of cases, and type B, which affects the descending aorta distal to the left subclavian origin in one-third of cases. The DeBakey classification divides it into type I, which originates in the ascending aorta and propagates to at least the aortic arch and possibly beyond it distally, type II, which originates in and is confined to the ascending aorta, and type III, which originates in the descending aorta and rarely extends proximally but will extend distally.
To diagnose aortic dissection, a chest x-ray may show a widened mediastinum, but CT angiography of the chest, abdomen, and pelvis is the investigation of choice. However, the choice of investigations should take into account the patient’s clinical stability, as they may present acutely and be unstable. Transoesophageal echocardiography (TOE) is more suitable for unstable patients who are too risky to take to the CT scanner.
The management of type A aortic dissection is surgical, but blood pressure should be controlled to a target systolic of 100-120 mmHg while awaiting intervention. On the other hand, type B aortic dissection is managed conservatively with bed rest and IV labetalol to reduce blood pressure and prevent progression. Complications of a backward tear include aortic incompetence/regurgitation and MI, while complications of a forward tear include unequal arm pulses and BP, stroke, and renal failure. Endovascular repair of type B aortic dissection may have a role in the future.
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This question is part of the following fields:
- Cardiovascular System
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Question 18
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A 65-year-old man has recently undergone parotidectomy on his left side due to a malignant parotid gland tumor. He has been back on the surgical ward for a few hours when he reports feeling weakness on the left side of his mouth. Upon examination, you observe facial asymmetry and weakness on the left side. He is unable to hold air under pressure in his mouth and cannot raise his left lip to show his teeth. This complication is likely due to damage to which nerve?
Your Answer:
Correct Answer: Facial nerve
Explanation:The facial nerve is the seventh cranial nerve and innervates the muscles of facial expression. It runs through the parotid gland and can be injured during parotidectomy. The maxillary nerve is the second division of the trigeminal nerve and carries sensory fibres from the lower eyelid, cheeks, upper teeth, palate, nasal cavity, and paranasal sinuses. The glossopharyngeal nerve is the ninth cranial nerve and has various functions, including carrying taste and sensation from the posterior third of the tongue and supplying parasympathetic innervation to the parotid gland. The mandibular nerve is the third division of the trigeminal nerve and carries sensory and motor fibres, supplying motor innervation to the muscles of mastication. The hypoglossal nerve is the twelfth cranial nerve and supplies the intrinsic muscles of the tongue.
The facial nerve is responsible for supplying the muscles of facial expression, the digastric muscle, and various glandular structures. It also contains a few afferent fibers that originate in the genicular ganglion and are involved in taste. Bilateral facial nerve palsy can be caused by conditions such as sarcoidosis, Guillain-Barre syndrome, Lyme disease, and bilateral acoustic neuromas. Unilateral facial nerve palsy can be caused by these conditions as well as lower motor neuron issues like Bell’s palsy and upper motor neuron issues like stroke.
The upper motor neuron lesion typically spares the upper face, specifically the forehead, while a lower motor neuron lesion affects all facial muscles. The facial nerve’s path includes the subarachnoid path, where it originates in the pons and passes through the petrous temporal bone into the internal auditory meatus with the vestibulocochlear nerve. The facial canal path passes superior to the vestibule of the inner ear and contains the geniculate ganglion at the medial aspect of the middle ear. The stylomastoid foramen is where the nerve passes through the tympanic cavity anteriorly and the mastoid antrum posteriorly, and it also includes the posterior auricular nerve and branch to the posterior belly of the digastric and stylohyoid muscle.
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This question is part of the following fields:
- Neurological System
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Question 19
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A 63-year-old woman has been experiencing vomiting for the past day due to food poisoning. What acid-base imbalance is likely to occur?
Your Answer:
Correct Answer: Metabolic alkalosis
Explanation:Acid Loss and Compensation in Vomiting
There are two possible approaches to the effects of vomiting on acid loss and compensation. The first, more simplistic way is to assume that vomiting leads to acid loss since the stomach contents contain acid. However, this overlooks the fact that vomiting also results in the loss of sodium, which can affect the body’s acid-base balance. Specifically, the sodium-/H+ antiporters in the kidneys may retain sodium at the expense of hydrogen ions, leading to metabolic alkalosis.
Regardless of the mechanism, the resulting metabolic alkalosis would trigger compensatory responses in the body. One such response would be a decrease in respiratory rate, which would help retain CO2 and lead to a compensatory respiratory acidosis. Overall, the complex interplay between acid loss and compensation in vomiting requires a more nuanced approach that takes into account the various factors involved.
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This question is part of the following fields:
- Clinical Sciences
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Question 20
Incorrect
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A 57-year-old man comes to see his doctor with concerns about his sexual relationship with his new wife. Upon further inquiry, he discloses that he is experiencing difficulty in achieving physical arousal and is experiencing delayed orgasms. He did not report any such issues during his medication review six weeks ago and believes that the recent change in medication may be responsible for this.
The patient's medical history includes asthma, hypertension, migraine, bilateral hip replacement, and gout.
Which medication is the most likely cause of his recent prescription change?Your Answer:
Correct Answer: Indapamide
Explanation:Thiazide-like diuretics, including indapamide, can cause sexual dysfunction, which is evident in this patient’s history. Before attempting to manage the issue, it is important to rule out any iatrogenic causes. Ramipril, an ACE-inhibitor, is not associated with sexual dysfunction, while losartan, an angiotensin II receptor blocker, and amlodipine, a dihydropyridine calcium channel blocker, are also not known to cause sexual dysfunction and are used in the management of hypertension.
Thiazide diuretics are medications that work by blocking the thiazide-sensitive Na+-Cl− symporter, which inhibits sodium reabsorption at the beginning of the distal convoluted tubule (DCT). This results in the loss of potassium as more sodium reaches the collecting ducts. While thiazide diuretics are useful in treating mild heart failure, loop diuretics are more effective in reducing overload. Bendroflumethiazide was previously used to manage hypertension, but recent NICE guidelines recommend other thiazide-like diuretics such as indapamide and chlorthalidone.
Common side effects of thiazide diuretics include dehydration, postural hypotension, and electrolyte imbalances such as hyponatremia, hypokalemia, and hypercalcemia. Other potential adverse effects include gout, impaired glucose tolerance, and impotence. Rare side effects may include thrombocytopenia, agranulocytosis, photosensitivity rash, and pancreatitis.
It is worth noting that while thiazide diuretics may cause hypercalcemia, they can also reduce the incidence of renal stones by decreasing urinary calcium excretion. According to current NICE guidelines, the management of hypertension involves the use of thiazide-like diuretics, along with other medications and lifestyle changes, to achieve optimal blood pressure control and reduce the risk of cardiovascular disease.
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This question is part of the following fields:
- Cardiovascular System
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