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  • Question 1 - A study can only make confident claims about cause and effect if it...

    Correct

    • A study can only make confident claims about cause and effect if it has what?

      Your Answer: Good internal validity

      Explanation:

      Claims about cause and effect require good internal validity.

      Validity refers to how accurately something measures what it claims to measure. There are two main types of validity: internal and external. Internal validity refers to the confidence we have in the cause and effect relationship in a study. This means we are confident that the independent variable caused the observed change in the dependent variable, rather than other factors. There are several threats to internal validity, such as poor control of extraneous variables and loss of participants over time. External validity refers to the degree to which the conclusions of a study can be applied to other people, places, and times. Threats to external validity include the representativeness of the sample and the artificiality of the research setting. There are also other types of validity, such as face validity and content validity, which refer to the general impression and full content of a test, respectively. Criterion validity compares tests, while construct validity measures the extent to which a test measures the construct it aims to.

    • This question is part of the following fields:

      • General Principles
      14.3
      Seconds
  • Question 2 - A 36-year-old man is admitted to the hospital with sudden onset of tingling...

    Incorrect

    • A 36-year-old man is admitted to the hospital with sudden onset of tingling and pain in his limbs, followed by rapid muscle weakness over the past day. He has not had a fever, but recently experienced diarrhea. After further testing, he is diagnosed with Guillain-Barré syndrome, an autoimmune disorder that causes acute peripheral paralysis. This is caused by antibodies targeting self-antigens on peripheral neuron gangliosides in the Fab region, with the Fc region binding complement proteins and causing damage. What specific domain of the Fc region is responsible for this binding and resulting damage in Guillain-Barré syndrome?

      Your Answer: Variable domains of heavy chains

      Correct Answer: Constant domains of heavy chains

      Explanation:

      The Fc region of immunoglobulins is composed of the constant domains of its heavy chains and varies among classes. The Fab region contains the variable domains and a portion of the constant domains of both heavy and light chains. In Guillain-Barré syndrome, the Fab region of anti-ganglioside antibodies binds to the antigen, while the Fc region mediates the response by activating complement proteins. The Fc domain does not include light chains, and the constant domain of heavy chains is the only part of the antibody found in the Fc region.

      Immunoglobulins, also known as antibodies, are proteins produced by the immune system to help fight off infections and diseases. There are five types of immunoglobulins found in the body, each with their own unique characteristics.

      IgG is the most abundant type of immunoglobulin in blood serum and plays a crucial role in enhancing phagocytosis of bacteria and viruses. It also fixes complement and can be passed to the fetal circulation.

      IgA is the most commonly produced immunoglobulin in the body and is found in the secretions of digestive, respiratory, and urogenital tracts and systems. It provides localized protection on mucous membranes and is transported across the interior of the cell via transcytosis.

      IgM is the first immunoglobulin to be secreted in response to an infection and fixes complement, but does not pass to the fetal circulation. It is also responsible for producing anti-A, B blood antibodies.

      IgD’s role in the immune system is largely unknown, but it is involved in the activation of B cells.

      IgE is the least abundant type of immunoglobulin in blood serum and is responsible for mediating type 1 hypersensitivity reactions. It provides immunity to parasites such as helminths and binds to Fc receptors found on the surface of mast cells and basophils.

    • This question is part of the following fields:

      • General Principles
      41.7
      Seconds
  • Question 3 - An 80-year-old man is brought to the emergency department in respiratory arrest. According...

    Incorrect

    • An 80-year-old man is brought to the emergency department in respiratory arrest. According to his partner, he has a history of congestive heart failure and has recently been battling an infection. After being placed on mechanical ventilation, you observe that the patient has decreased lung compliance.

      What could be the cause of this observation?

      Your Answer: Loss of lung connective tissue with age

      Correct Answer: Pulmonary oedema

      Explanation:

      Reduced lung compliance is a common consequence of pulmonary edema, which occurs when fluid accumulates in the alveoli and exerts mechanical stress on the air-filled alveoli. This can happen in patients with acute decompensation of congestive cardiac failure, often triggered by an infection. On the other hand, emphysema can increase compliance due to long-term damage that reduces the elastic recoil of the lungs. Additionally, lung surfactant produced by type II pneumocytes can increase lung compliance. Finally, aging can also lead to increased compliance as the loss of lung connective tissue can reduce elastic recoil.

      Understanding Lung Compliance in Respiratory Physiology

      Lung compliance refers to the extent of change in lung volume in response to a change in airway pressure. An increase in lung compliance can be caused by factors such as aging and emphysema, which is characterized by the loss of alveolar walls and associated elastic tissue. On the other hand, a decrease in lung compliance can be attributed to conditions such as pulmonary edema, pulmonary fibrosis, pneumonectomy, and kyphosis. These conditions can affect the elasticity of the lungs and make it more difficult for them to expand and contract properly. Understanding lung compliance is important in respiratory physiology as it can help diagnose and manage various respiratory conditions. Proper management of lung compliance can improve lung function and overall respiratory health.

    • This question is part of the following fields:

      • Respiratory System
      40.3
      Seconds
  • Question 4 - A 56-year-old patient visits his primary care physician for a follow-up on his...

    Correct

    • A 56-year-old patient visits his primary care physician for a follow-up on his diabetes treatment. He is currently taking metformin and expresses concern about adding more medications that may lead to hypoglycemia. The patient has a medical history of bladder cancer, which was treated through surgery. On examination, the only notable finding is an elevated body mass index of 32 kg/m².

      Based on recent blood test results, with an HbA1c level of 61 mmol/L (<48), the GP wants to prescribe a medication that does not cause weight gain or hypoglycemia. What is the probable mechanism of action of this drug?

      Your Answer: Reduction of the peripheral breakdown of incretins such as glucagon-like peptide (GLP-1)

      Explanation:

      Diabetes mellitus is a condition that has seen the development of several drugs in recent years. One hormone that has been the focus of much research is glucagon-like peptide-1 (GLP-1), which is released by the small intestine in response to an oral glucose load. In type 2 diabetes mellitus (T2DM), insulin resistance and insufficient B-cell compensation occur, and the incretin effect, which is largely mediated by GLP-1, is decreased. GLP-1 mimetics, such as exenatide and liraglutide, increase insulin secretion and inhibit glucagon secretion, resulting in weight loss, unlike other medications. They are sometimes used in combination with insulin in T2DM to minimize weight gain. Dipeptidyl peptidase-4 (DPP-4) inhibitors, such as vildagliptin and sitagliptin, increase levels of incretins by decreasing their peripheral breakdown, are taken orally, and do not cause weight gain. Nausea and vomiting are the major adverse effects of GLP-1 mimetics, and the Medicines and Healthcare products Regulatory Agency has issued specific warnings on the use of exenatide, reporting that it has been linked to severe pancreatitis in some patients. NICE guidelines suggest that a DPP-4 inhibitor might be preferable to a thiazolidinedione if further weight gain would cause significant problems, a thiazolidinedione is contraindicated, or the person has had a poor response to a thiazolidinedione.

    • This question is part of the following fields:

      • Endocrine System
      60.2
      Seconds
  • Question 5 - A 56-year-old man is sent home following an uneventful left total hip replacement....

    Correct

    • A 56-year-old man is sent home following an uneventful left total hip replacement. He has been prescribed a direct factor Xa inhibitor for thromboprophylaxis.

      What is the probable medication that the patient has been prescribed?

      Your Answer: Apixaban

      Explanation:

      Apixaban directly inhibits factor Xa, while bivalirudin and dabigatran directly inhibit thrombin. On the other hand, enoxaparin is a type of low molecular weight heparin that indirectly inhibits factor Xa by forming a complex with antithrombin III, leading to irreversible inactivation of factor Xa.

      Direct oral anticoagulants (DOACs) are medications used to prevent stroke in non-valvular atrial fibrillation (AF), as well as for the prevention and treatment of venous thromboembolism (VTE). To be prescribed DOACs for stroke prevention, patients must have certain risk factors, such as a prior stroke or transient ischaemic attack, age 75 or older, hypertension, diabetes mellitus, or heart failure. There are four DOACs available, each with a different mechanism of action and method of excretion. Dabigatran is a direct thrombin inhibitor, while rivaroxaban, apixaban, and edoxaban are direct factor Xa inhibitors. The majority of DOACs are excreted either through the kidneys or the liver, with the exception of apixaban and edoxaban, which are excreted through the feces. Reversal agents are available for dabigatran and rivaroxaban, but not for apixaban or edoxaban.

    • This question is part of the following fields:

      • Haematology And Oncology
      24.2
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  • Question 6 - You are evaluating an 80-year-old woman who was admitted last night with symptoms...

    Incorrect

    • You are evaluating an 80-year-old woman who was admitted last night with symptoms suggestive of a stroke. She is suspected to have lateral medullary syndrome.

      During the examination, you observe that she has lost her sense of taste in the posterior third of her tongue and has an absent gag reflex.

      Through which structure does the affected cranial nerve most likely pass?

      Your Answer: Foramen rotundum

      Correct Answer: Jugular foramen

      Explanation:

      The jugular foramen is the pathway through which the glossopharyngeal nerve travels.

      Cranial nerves are a set of 12 nerves that emerge from the brain and control various functions of the head and neck. Each nerve has a specific function, such as smell, sight, eye movement, facial sensation, and tongue movement. Some nerves are sensory, some are motor, and some are both. A useful mnemonic to remember the order of the nerves is Some Say Marry Money But My Brother Says Big Brains Matter Most, with S representing sensory, M representing motor, and B representing both.

      In addition to their specific functions, cranial nerves also play a role in various reflexes. These reflexes involve an afferent limb, which carries sensory information to the brain, and an efferent limb, which carries motor information from the brain to the muscles. Examples of cranial nerve reflexes include the corneal reflex, jaw jerk, gag reflex, carotid sinus reflex, pupillary light reflex, and lacrimation reflex. Understanding the functions and reflexes of the cranial nerves is important in diagnosing and treating neurological disorders.

    • This question is part of the following fields:

      • Neurological System
      30.2
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  • Question 7 - A 35-year-old woman has been diagnosed with gonorrhoeae and prescribed ceftriaxone. She later...

    Incorrect

    • A 35-year-old woman has been diagnosed with gonorrhoeae and prescribed ceftriaxone. She later presents at the emergency department with severe abdominal pain, elevated white blood cell count, and signs of severe colitis. What is the most probable causative organism for these symptoms?

      Your Answer: Escherichia coli

      Correct Answer: Clostridium difficile

      Explanation:

      The correct answer is C. difficile, as it is the causative organism in pseudomembranous colitis that can occur after recent use of broad-spectrum antibiotics like ceftriaxone. These antibiotics can disrupt the gut flora, allowing C. difficile to thrive. Other antibiotics that can cause C. difficile include PPI, clindamycin, and fluoroquinolones.

      Campylobacter, Escherichia coli, and Neisseria gonorrhoeae are incorrect answers. Campylobacter infections are typically caused by undercooked chicken, untreated water, or international travel. E. coli infections are usually caused by contact with infected feces, unwashed foods, or unclean water. Neisseria gonorrhoeae is a sexually transmitted disease that is spread through unprotected sex, not through recent use of broad-spectrum antibiotics. The patient in this case does not have symptoms of gonorrhoeae and there is no indication of unprotected sex after the antibiotic prescription.

      Clostridium difficile is a type of bacteria that is commonly found in hospitals. It produces a toxin that can damage the intestines and cause a condition called pseudomembranous colitis. This bacteria usually develops when the normal gut flora is disrupted by broad-spectrum antibiotics, with second and third generation cephalosporins being the leading cause. Other risk factors include the use of proton pump inhibitors. Symptoms of C. difficile infection include diarrhea, abdominal pain, and a raised white blood cell count. The severity of the infection can be determined using the Public Health England severity scale.

      To diagnose C. difficile infection, a stool sample is tested for the presence of the C. difficile toxin. Treatment involves reviewing current antibiotic therapy and stopping antibiotics if possible. For a first episode of infection, oral vancomycin is the first-line therapy for 10 days, followed by oral fidaxomicin as second-line therapy and oral vancomycin with or without IV metronidazole as third-line therapy. Recurrent infections may require different treatment options, such as oral fidaxomicin within 12 weeks of symptom resolution or oral vancomycin or fidaxomicin after 12 weeks of symptom resolution. In life-threatening cases, oral vancomycin and IV metronidazole may be used, and surgery may be considered with specialist advice. Other therapies, such as bezlotoxumab and fecal microbiota transplant, may also be considered for preventing recurrences in certain cases.

    • This question is part of the following fields:

      • Gastrointestinal System
      8.4
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  • Question 8 - A 70-year-old woman is admitted to the cardiology ward with a 4-day history...

    Incorrect

    • A 70-year-old woman is admitted to the cardiology ward with a 4-day history of increasing shortness of breath and difficulty sleeping due to breathlessness when lying flat. Her medical history includes ischaemic heart disease and chronic heart failure. She was recently started on a new medication by her GP.

      Upon examination, diffuse crackles are heard loudest at the bases. Her JVP is elevated, and there is pitting oedema to the knees bilaterally.

      Brain natriuretic peptide 5500 pg/mL (< 300)

      Which medication is most likely to have caused this presentation?

      Your Answer: Amlodipine

      Correct Answer: Verapamil

      Explanation:

      Calcium channel blockers are a class of drugs commonly used to treat cardiovascular disease. These drugs target voltage-gated calcium channels found in myocardial cells, cells of the conduction system, and vascular smooth muscle. The different types of calcium channel blockers have varying effects on these areas, making it important to differentiate their uses and actions.

      Verapamil is used to treat angina, hypertension, and arrhythmias. It is highly negatively inotropic and should not be given with beta-blockers as it may cause heart block. Side effects include heart failure, constipation, hypotension, bradycardia, and flushing.

      Diltiazem is used to treat angina and hypertension. It is less negatively inotropic than verapamil, but caution should still be exercised when patients have heart failure or are taking beta-blockers. Side effects include hypotension, bradycardia, heart failure, and ankle swelling.

      Nifedipine, amlodipine, and felodipine are dihydropyridines used to treat hypertension, angina, and Raynaud’s. They affect peripheral vascular smooth muscle more than the myocardium, which means they do not worsen heart failure but may cause ankle swelling. Shorter acting dihydropyridines like nifedipine may cause peripheral vasodilation, resulting in reflex tachycardia. Side effects include flushing, headache, and ankle swelling.

      According to current NICE guidelines, the management of hypertension involves a flow chart that takes into account various factors such as age, ethnicity, and comorbidities. Calcium channel blockers may be used as part of the treatment plan depending on the individual patient’s needs.

    • This question is part of the following fields:

      • General Principles
      32
      Seconds
  • Question 9 - A man in his 50s with advanced prostate cancer has come in for...

    Incorrect

    • A man in his 50s with advanced prostate cancer has come in for a consultation to ask you about his prognosis if he chooses to undergo the radiotherapy he is considering. You inform him that it is challenging to predict outcomes for individual patients but decide to utilize a Kaplan-Meier survival plot to assist you in your explanation. Can you describe what a Kaplan-Meier survival plot is?

      Your Answer: An accurate prediction of increasing survival with time after treatment.

      Correct Answer: An estimate of decreasing survival with time after an event.

      Explanation:

      The Kaplan-Meier survival plot, also known as the product limit estimate, illustrates the decreasing survival estimates over time after an event. This method involves calculating the probabilities of an event occurring at a specific time and multiplying them by previously computed probabilities to obtain the final estimate. The survival probability for a population at a particular time on the plot is determined by subtracting the number of deaths from the number of subjects living at the start and dividing by the number of subjects living at the start. However, since it is a statistical estimate, it may not be entirely accurate in predicting outcomes.

      On the other hand, a scatter plot is a graphical representation that uses Cartesian coordinates to display values for more than two variables in a dataset. It is commonly used to identify any potential relationships between two different variables.

      Types of Graphs for Statistical Data Representation

      Graphical representations of statistical data are essential in presenting complex information in a clear and concise manner. There are various types of graphs used to represent statistical data, each with its unique features and applications. One of the most common types of graphs is the box-and-whisker plot, which displays the minimum, lower quartile, median, upper quartile, and maximum values of a sample. This graph is useful in identifying the spread and distribution of data.

      Another type of graph is the funnel plot, which is used to demonstrate publication bias in meta-analyses. This graph displays the effect size of each study against its precision, allowing researchers to identify any asymmetry in the data. The histogram is another graphical display used to categorize continuous data into a number of categories. This graph is useful in identifying the frequency distribution of data.

      The forest plot is a graphical representation of the strength of evidence of constituent trials in meta-analyses. This graph displays the effect size and confidence interval of each study, allowing researchers to identify the overall effect size and heterogeneity of the data. The scatter plot is another graphical representation that displays values for two variables for a set of data using Cartesian coordinates. This graph is useful in identifying the relationship between two variables.

      Finally, the Kaplan-Meier survival plot is a plot of the Kaplan-Meier estimate of the survival function, showing decreasing survival with time. This graph is useful in identifying the survival rate of a population over time. In conclusion, the choice of graph depends on the type of data and the research question being addressed.

    • This question is part of the following fields:

      • General Principles
      68.1
      Seconds
  • Question 10 - A couple in their late 20s comes to your clinic seeking advice regarding...

    Incorrect

    • A couple in their late 20s comes to your clinic seeking advice regarding the possibility of their children inheriting cystic fibrosis. The husband has a confirmed diagnosis of the condition, but the carrier status of the wife is unknown.

      What is the likelihood of any of their offspring being affected by cystic fibrosis?

      Your Answer: 25%

      Correct Answer: 2.50%

      Explanation:

      Cystic Fibrosis Inheritance

      Cystic fibrosis (CF) is a genetic disorder that affects the chloride ion channels, leading to the thickening of respiratory and other secretions. It is an autosomal recessive condition, which means that a person must inherit two copies of the defective gene, one from each parent, to develop the disease. The most common defective allele is carried by approximately 1 in 20 people.

      If a man with CF has children with a woman who does not carry the recessive gene, then none of their children will be affected by the disease. However, they will all be carriers of the CF gene. On the other hand, if the woman is a carrier of the CF gene, there is a 50% chance that each child will inherit one copy of the defective gene from each parent and be affected by the disease. The remaining 50% of the children will inherit one copy of the defective gene and one normal gene, making them carriers of the CF gene but not affected by the disease.

      In summary, the probability of any child being affected by CF is 2.5% if one parent has the defective gene and the other does not. It is important for individuals who are carriers of the CF gene to be aware of their status and seek genetic counseling before planning to have children.

    • This question is part of the following fields:

      • Basic Sciences
      25.9
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  • Question 11 - A 63-year-old man visits the clinic with complaints of palpitations and constipation that...

    Incorrect

    • A 63-year-old man visits the clinic with complaints of palpitations and constipation that has been bothering him for the past 5 days. He reports passing gas but feels uneasy. The patient has a history of hypertension, and you recently prescribed bendroflumethiazide to manage it. To check for signs of hypokalaemia, you conduct an ECG. What is an ECG indication of hypokalaemia?

      Your Answer: Small or absent P waves

      Correct Answer: Prolonged PR interval

      Explanation:

      Hypokalaemia can be identified through a prolonged PR interval on an ECG. However, this same ECG sign may also be present in cases of hyperkalaemia. Additional ECG signs of hypokalaemia include small or absent P waves, tall tented T waves, and broad bizarre QRS complexes. On the other hand, hyperkalaemia can be identified through ECG signs such as long PR intervals, a sine wave pattern, and tall tented T waves, as well as broad bizarre QRS complexes.

      Hypokalaemia, a condition characterized by low levels of potassium in the blood, can be detected through ECG features. These include the presence of U waves, small or absent T waves (which may occasionally be inverted), a prolonged PR interval, ST depression, and a long QT interval. The ECG image provided shows typical U waves and a borderline PR interval. To remember these features, one user suggests the following rhyme: In Hypokalaemia, U have no Pot and no T, but a long PR and a long QT.

    • This question is part of the following fields:

      • Cardiovascular System
      29.8
      Seconds
  • Question 12 - You are requested to assess a patient in the emergency department who has...

    Incorrect

    • You are requested to assess a patient in the emergency department who has experienced abrupt onset chest pain, dyspnoea and diaphoresis. After reviewing the patient's ECG, you identify changes within a specific section and promptly arrange for transfer to the catheterisation laboratory.

      What is the underlying process indicated by the affected section of the ECG?

      Your Answer: Atrioventricular node function

      Correct Answer: Period between ventricular depolarisation and repolarisation

      Explanation:

      The ST segment on an ECG indicates the period when the entire ventricle is depolarized. In the case of a suspected myocardial infarction, it is crucial to examine the ST segment for any elevation or depression, which can indicate a STEMI or NSTEMI, respectively.

      The ECG does not have a specific section that corresponds to the firing of the sino-atrial node, which triggers atrial depolarization (represented by the p wave). The T wave represents ventricular repolarization.

      In atrial fibrillation, the p wave is absent or abnormal due to the irregular firing of the atria.

      Understanding the Normal ECG

      The electrocardiogram (ECG) is a diagnostic tool used to assess the electrical activity of the heart. The normal ECG consists of several waves and intervals that represent different phases of the cardiac cycle. The P wave represents atrial depolarization, while the QRS complex represents ventricular depolarization. The ST segment represents the plateau phase of the ventricular action potential, and the T wave represents ventricular repolarization. The Q-T interval represents the time for both ventricular depolarization and repolarization to occur.

      The P-R interval represents the time between the onset of atrial depolarization and the onset of ventricular depolarization. The duration of the QRS complex is normally 0.06 to 0.1 seconds, while the duration of the P wave is 0.08 to 0.1 seconds. The Q-T interval ranges from 0.2 to 0.4 seconds depending upon heart rate. At high heart rates, the Q-T interval is expressed as a ‘corrected Q-T (QTc)’ by taking the Q-T interval and dividing it by the square root of the R-R interval.

      Understanding the normal ECG is important for healthcare professionals to accurately interpret ECG results and diagnose cardiac conditions. By analyzing the different waves and intervals, healthcare professionals can identify abnormalities in the electrical activity of the heart and provide appropriate treatment.

    • This question is part of the following fields:

      • Cardiovascular System
      45.1
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  • Question 13 - A 55-year-old man visits his general practitioner complaining of pain in the back...

    Incorrect

    • A 55-year-old man visits his general practitioner complaining of pain in the back of his leg. The doctor suspects a sciatic nerve injury.

      During the examination, which reflexes are expected to be absent?

      Your Answer: Patellar (knee) reflex

      Correct Answer: Ankle reflex

      Explanation:

      When the sciatic nerve is damaged, the reflexes in the ankle and plantar areas are lost, but the knee jerk reflex remains intact. This can cause pain and numbness in the back of the leg. If the damage occurs at the pelvic outlet, the ability to flex the knee may be lost, but the knee jerk reflex will still be present. During a neurological examination of the upper limb, the reflexes in the biceps, brachioradialis, and triceps are tested. Additionally, the sural and tibial nerve reflexes are cutaneous reflexes that are activated during walking.

      Understanding Sciatic Nerve Lesion

      The sciatic nerve is a major nerve that is supplied by the L4-5, S1-3 vertebrae and divides into the tibial and common peroneal nerves. It is responsible for supplying the hamstring and adductor muscles. When the sciatic nerve is damaged, it can result in a range of symptoms that affect both motor and sensory functions.

      Motor symptoms of sciatic nerve lesion include paralysis of knee flexion and all movements below the knee. Sensory symptoms include loss of sensation below the knee. Reflexes may also be affected, with ankle and plantar reflexes lost while the knee jerk reflex remains intact.

      There are several causes of sciatic nerve lesion, including fractures of the neck of the femur, posterior hip dislocation, and trauma.

    • This question is part of the following fields:

      • Neurological System
      225.2
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  • Question 14 - A 42-year-old man with schizophrenia undergoes his yearly physical examination. He is currently...

    Incorrect

    • A 42-year-old man with schizophrenia undergoes his yearly physical examination. He is currently taking risperidone as part of his medication regimen.

      What is the most common issue that can be linked to the use of risperidone in this patient?

      Your Answer:

      Correct Answer: Galactorrhoea

      Explanation:

      Risperidone, an atypical antipsychotic, has the potential to increase prolactin levels. This is because it inhibits dopamine, which reduces dopamine-mediated inhibition of prolactin. Although elevated prolactin may not cause any symptoms, it can have adverse effects if persistently elevated. One of the major roles of prolactin is to stimulate milk production in the mammary glands. Therefore, any cause of raised prolactin can result in milk production, which is known as galactorrhoea. This can occur in both males and females due to raised prolactin levels. Galactorrhoea is the most likely side effect caused by risperidone.

      Raised prolactin levels can also lead to reduced libido and infertility in both sexes. However, it is unlikely to result in increased libido. Prolactin can interfere with other hormones, such as oestrogen and progesterone, which can cause irregular periods, but it does not specifically cause painful periods. Elevated levels of prolactin would not result in seizures. Risperidone is more likely to be associated with weight gain rather than weight loss, as it acts on the histamine receptor.

      Understanding Prolactin and Its Functions

      Prolactin is a hormone that is produced by the anterior pituitary gland. Its primary function is to stimulate breast development and milk production in females. During pregnancy, prolactin levels increase to support the growth and development of the mammary glands. It also plays a role in reducing the pulsatility of gonadotropin-releasing hormone (GnRH) at the hypothalamic level, which can block the action of luteinizing hormone (LH) on the ovaries or testes.

      The secretion of prolactin is regulated by dopamine, which constantly inhibits its release. However, certain factors can increase or decrease prolactin secretion. For example, prolactin levels increase during pregnancy, in response to estrogen, and during breastfeeding. Additionally, stress, sleep, and certain drugs like metoclopramide and antipsychotics can also increase prolactin secretion. On the other hand, dopamine and dopaminergic agonists can decrease prolactin secretion.

      Overall, understanding the functions and regulation of prolactin is important for reproductive health and lactation.

    • This question is part of the following fields:

      • Endocrine System
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  • Question 15 - A 19-year-old male presents to the emergency department with complaints of breathing difficulty....

    Incorrect

    • A 19-year-old male presents to the emergency department with complaints of breathing difficulty. Upon examination, his chest appears normal, but his respiratory rate is 32 breaths per minute. The medical team suspects he may be experiencing a panic attack and subsequent hyperventilation. What impact will this have on his blood gas levels?

      Your Answer:

      Correct Answer: Respiratory alkalosis

      Explanation:

      The patient is experiencing a respiratory alkalosis due to their hyperventilation, which is causing a decrease in carbon dioxide levels and resulting in an alkaline state.

      Respiratory Alkalosis: Causes and Examples

      Respiratory alkalosis is a condition that occurs when the blood pH level rises above the normal range due to excessive breathing. This can be caused by various factors, including anxiety, pulmonary embolism, CNS disorders, altitude, and pregnancy. Salicylate poisoning can also lead to respiratory alkalosis, but it may also cause metabolic acidosis in the later stages. In this case, the respiratory centre is stimulated early, leading to respiratory alkalosis, while the direct acid effects of salicylates combined with acute renal failure may cause acidosis later on. It is important to identify the underlying cause of respiratory alkalosis to determine the appropriate treatment. Proper management can help prevent complications and improve the patient’s overall health.

    • This question is part of the following fields:

      • Respiratory System
      0
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  • Question 16 - Which of the following statements is true regarding autosomal recessive inheritance? ...

    Incorrect

    • Which of the following statements is true regarding autosomal recessive inheritance?

      Your Answer:

      Correct Answer: All offspring of an affected individual and a non-affected individual (i.e. not a carrier or affected) will be heterozygote carriers

      Explanation:

      Understanding Autosomal Recessive Inheritance

      Autosomal recessive inheritance is a genetic pattern where a disorder is only expressed when an individual inherits two copies of a mutated gene, one from each parent. This means that only homozygotes, individuals with two copies of the mutated gene, are affected. Both males and females are equally likely to be affected, and the disorder may not manifest in every generation, as it can skip a generation.

      When two heterozygote parents, carriers of the mutated gene, have children, there is a 25% chance of having an affected (homozygote) child, a 50% chance of having a carrier (heterozygote) child, and a 25% chance of having an unaffected child. On the other hand, if one parent is homozygote for the gene and the other is unaffected, all the children will be carriers.

      Autosomal recessive disorders are often metabolic in nature and are generally more life-threatening compared to autosomal dominant conditions. It is important to understand the inheritance pattern of genetic disorders to provide appropriate genetic counseling and medical management.

    • This question is part of the following fields:

      • General Principles
      0
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  • Question 17 - A 36-year-old man with a history of psoriasis presents with pain in his...

    Incorrect

    • A 36-year-old man with a history of psoriasis presents with pain in his left knee, middle finger, and heel. He reports a family history of psoriasis. During examination, red, inflamed, and silvery plaques are observed on his elbows and scalp. Additionally, there is tenderness and swelling in the affected joints. What HLA haplotype is linked to his joint pain?

      Your Answer:

      Correct Answer: HLA-B27

      Explanation:

      Psoriatic arthritis is often observed in individuals who possess the HLA-B27 antigen, as evidenced by the presence of asymmetrical and oligoarticular arthritis with enthesitis in the left heel, along with a history of psoriasis and a familial predisposition to the condition.

      HLA Associations: Diseases and Antigens

      HLA antigens are proteins encoded by genes on chromosome 6. There are two classes of HLA antigens: class I (HLA A, B, and C) and class II (HLA DP, DQ, and DR). Diseases can be strongly associated with certain HLA antigens. For example, HLA-A3 is associated with haemochromatosis, HLA-B51 with Behcet’s disease, and HLA-B27 with ankylosing spondylitis, reactive arthritis, and acute anterior uveitis. Coeliac disease is associated with HLA-DQ2/DQ8, while narcolepsy and Goodpasture’s are associated with HLA-DR2. Dermatitis herpetiformis, Sjogren’s syndrome, and primary biliary cirrhosis are associated with HLA-DR3. Finally, type 1 diabetes mellitus is associated with HLA-DR3 but more strongly associated with HLA-DR4, specifically the DRB1 gene (DRB1*04:01 and DRB1*04:04).

    • This question is part of the following fields:

      • General Principles
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  • Question 18 - A 27-year-old patient arrives at the emergency department complaining of severe abdominal pain...

    Incorrect

    • A 27-year-old patient arrives at the emergency department complaining of severe abdominal pain and vomiting blood. The patient has been taking naproxen for Achilles tendinopathy. Upon examination, the patient is found to be tachycardic with a pulse of 110 and has a blood pressure of 95/60. An urgent endoscopy is performed, revealing a bleeding peptic ulcer. To stop the bleeding definitively, the patient is sent for embolisation of the left gastric artery via angiogram.

      During the angiogram, what vertebral level can be used as a radiological marker for the origin of the artery supplying the left gastric artery?

      Your Answer:

      Correct Answer: T12

      Explanation:

      In cases where initial treatment for upper GI bleeds is ineffective, angiography may be necessary to embolize the affected vessel and halt the bleeding. To perform an angiogram, the radiologist will access the aorta through the femoral artery, ascend to the 12th vertebrae, and then enter the left gastric artery via the coeliac trunk.

      Peptic ulcers in otherwise healthy patients are often caused by non-steroidal anti-inflammatory drugs.

      The coeliac trunk is not located at any vertebral level other than the 12th. The oesophagus passes through the diaphragm with the vagal trunk at the T10 level, while the T11 level has no significant associated structures. The superior mesenteric artery and left renal artery branch off the abdominal aorta at the L1 level.

      The aorta is a major blood vessel that carries oxygenated blood from the heart to the rest of the body. At different levels along the aorta, there are branches that supply blood to specific organs and regions. These branches include the coeliac trunk at the level of T12, which supplies blood to the stomach, liver, and spleen. The left renal artery, at the level of L1, supplies blood to the left kidney. The testicular or ovarian arteries, at the level of L2, supply blood to the reproductive organs. The inferior mesenteric artery, at the level of L3, supplies blood to the lower part of the large intestine. Finally, at the level of L4, the abdominal aorta bifurcates, or splits into two branches, which supply blood to the legs and pelvis.

    • This question is part of the following fields:

      • Cardiovascular System
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  • Question 19 - A 75-year-old woman is admitted for a laparoscopic cholecystectomy. As part of her...

    Incorrect

    • A 75-year-old woman is admitted for a laparoscopic cholecystectomy. As part of her pre-operative evaluation, it is discovered that she is taking furosemide to manage her hypertension. What percentage of the sodium filtered at the glomerulus will be eliminated?

      Your Answer:

      Correct Answer: Up to 25%

      Explanation:

      Loop diuretics cause significant increases in sodium excretion by acting on both the medullary and cortical regions of the thick ascending limb of the loop of Henle. This leads to a reduction in the medullary osmolal gradient and an increase in the excretion of free water, along with sodium loss. Unlike thiazide diuretics, which do not affect urine concentration and are more likely to cause hyponatremia, loop diuretics result in the loss of both sodium and water.

      Diuretic drugs are classified into three major categories based on the location where they inhibit sodium reabsorption. Loop diuretics act on the thick ascending loop of Henle, thiazide diuretics on the distal tubule and connecting segment, and potassium sparing diuretics on the aldosterone-sensitive principal cells in the cortical collecting tubule. Sodium is reabsorbed in the kidney through Na+/K+ ATPase pumps located on the basolateral membrane, which return reabsorbed sodium to the circulation and maintain low intracellular sodium levels. This ensures a constant concentration gradient.

      The physiological effects of commonly used diuretics vary based on their site of action. furosemide, a loop diuretic, inhibits the Na+/K+/2Cl- carrier in the ascending limb of the loop of Henle and can result in up to 25% of filtered sodium being excreted. Thiazide diuretics, which act on the distal tubule and connecting segment, inhibit the Na+Cl- carrier and typically result in between 3 and 5% of filtered sodium being excreted. Finally, spironolactone, a potassium sparing diuretic, inhibits the Na+/K+ ATPase pump in the cortical collecting tubule and typically results in between 1 and 2% of filtered sodium being excreted.

    • This question is part of the following fields:

      • Renal System
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  • Question 20 - You have been asked to review a 63-year-old man on the medical ward...

    Incorrect

    • You have been asked to review a 63-year-old man on the medical ward who was recently treated for an exacerbation of pulmonary oedema. His past medical history includes heart failure. He is currently on a course of antibiotics for prostatitis.

      His blood results from yesterday are shown below:

      Na+ 141 mmol/l
      K+ 4.3 mmol/l
      Urea 6 mmol/l
      Creatinine 60 µmol/l

      His blood results from today are shown below:

      Na+ 140 mmol/l
      K+ 4.6 mmol/l
      Urea 15 mmol/l
      Creatinine 180 µmol/l

      What is the most probable reason for the change in kidney function?

      Your Answer:

      Correct Answer: Concomitant use of furosemide and gentamicin resulting in renal failure

      Explanation:

      The risk of renal failure increases when furosemide and gentamicin are used together. Furosemide is the primary diuretic for treating acute pulmonary edema, but its concurrent use with gentamicin can lead to kidney failure. The patient’s blood test results indicate acute kidney injury, which is likely caused by gentamicin toxicity.

      Acute kidney injury can result from pre-renal causes such as sepsis and dehydration, and in such cases, the blood test would show a significant increase in urea levels disproportionate to the rise in creatinine.

      Bendroflumethiazide is not a commonly used medication for managing acute pulmonary edema.

      Metronidazole is not significantly associated with nephrotoxicity.

      Gentamicin is a type of antibiotic known as an aminoglycoside. It is not easily dissolved in lipids, so it is typically administered through injection or topical application. It is commonly used to treat infections such as infective endocarditis and otitis externa. However, gentamicin can have adverse effects on the body, such as ototoxicity, which can cause damage to the auditory or vestibular nerves. This damage is irreversible. Gentamicin can also cause nephrotoxicity, which can lead to acute tubular necrosis. The risk of toxicity increases when gentamicin is used in conjunction with furosemide. Lower doses and more frequent monitoring are necessary to prevent these adverse effects. Gentamicin is contraindicated in patients with myasthenia gravis. To ensure safe dosing, plasma concentrations of gentamicin are monitored. Peak levels are measured one hour after administration, and trough levels are measured just before the next dose. If the trough level is high, the interval between doses should be increased. If the peak level is high, the dose should be decreased.

    • This question is part of the following fields:

      • General Principles
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  • Question 21 - A 65-year-old man arrives at the Emergency Department after collapsing at home. According...

    Incorrect

    • A 65-year-old man arrives at the Emergency Department after collapsing at home. According to his wife, he had complained of sudden lower back pain just before the collapse. Upon examination, he appears pale and hypotensive, leading you to suspect a ruptured abdominal aortic aneurysm. Can you determine at which level the affected structure terminates?

      Your Answer:

      Correct Answer: L4

      Explanation:

      The section of the aorta that runs through the abdomen, known as the abdominal aorta, extends from the T12 vertebrae to the L4 vertebrae. This area is particularly susceptible to developing an aneurysm, which is most commonly seen in men over the age of 65. Risk factors for abdominal aortic aneurysms include smoking, diabetes, high blood pressure, and high cholesterol levels. Symptoms are often absent until the aneurysm ruptures, causing sudden and severe pain in the lower back or abdomen, as well as a drop in blood pressure and consciousness. To detect potential aneurysms, the NHS offers a one-time ultrasound screening for men over the age of 65 who have not previously been screened.

      The abdominal aorta is a major blood vessel that originates from the 12th thoracic vertebrae and terminates at the fourth lumbar vertebrae. It is located in the abdomen and is surrounded by various organs and structures. The posterior relations of the abdominal aorta include the vertebral bodies of the first to fourth lumbar vertebrae. The anterior relations include the lesser omentum, liver, left renal vein, inferior mesenteric vein, third part of the duodenum, pancreas, parietal peritoneum, and peritoneal cavity. The right lateral relations include the right crus of the diaphragm, cisterna chyli, azygos vein, and inferior vena cava (which becomes posterior distally). The left lateral relations include the fourth part of the duodenum, duodenal-jejunal flexure, and left sympathetic trunk. Overall, the abdominal aorta is an important blood vessel that supplies oxygenated blood to various organs in the abdomen.

    • This question is part of the following fields:

      • Gastrointestinal System
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  • Question 22 - A 78-year-old ex-smoker comes to the clinic complaining of chest discomfort and shortness...

    Incorrect

    • A 78-year-old ex-smoker comes to the clinic complaining of chest discomfort and shortness of breath. He had a history of ST-elevation myocardial infarction 10 days ago, which was treated with thrombolysis. During the examination, a high-pitch holosystolic murmur is heard at the apex. The ECG shows widespread ST elevation. Unfortunately, the patient experiences cardiac arrest and passes away. What is the probable histological finding in his heart?

      Your Answer:

      Correct Answer: Macrophages and granulation tissue at margins

      Explanation:

      The histology findings of a myocardial infarction (MI) vary depending on the time elapsed since the event. Within the first 24 hours, there is evidence of early coagulative necrosis, neutrophils, wavy fibers, and hypercontraction of myofibrils. This stage is associated with a high risk of ventricular arrhythmia, heart failure, and cardiogenic shock.

      Between 1-3 days post-MI, there is extensive coagulative necrosis and an influx of neutrophils, which can lead to fibrinous pericarditis. From 3-14 days post-MI, macrophages and granulation tissue are present at the margins, and there is a high risk of complications such as free wall rupture (which can cause mitral regurgitation), papillary muscle rupture, and left ventricular pseudoaneurysm.

      After 2 weeks to several months, the scar tissue has contracted and is complete. This stage is associated with Dressler syndrome, heart failure, arrhythmias, and mural thrombus. It is important to note that the risk of complications decreases as time passes, but long-term management and monitoring are still necessary for patients who have experienced an MI.

      Myocardial infarction (MI) can lead to various complications, which can occur immediately, early, or late after the event. Cardiac arrest is the most common cause of death following MI, usually due to ventricular fibrillation. Cardiogenic shock may occur if a large part of the ventricular myocardium is damaged, and it is difficult to treat. Chronic heart failure may result from ventricular myocardium dysfunction, which can be managed with loop diuretics, ACE-inhibitors, and beta-blockers. Tachyarrhythmias, such as ventricular fibrillation and ventricular tachycardia, are common complications. Bradyarrhythmias, such as atrioventricular block, are more common following inferior MI. Pericarditis is common in the first 48 hours after a transmural MI, while Dressler’s syndrome may occur 2-6 weeks later. Left ventricular aneurysm and free wall rupture, ventricular septal defect, and acute mitral regurgitation are other complications that may require urgent medical attention.

    • This question is part of the following fields:

      • Cardiovascular System
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  • Question 23 - A 25-year-old woman presents to the Emergency department with sudden onset of difficulty...

    Incorrect

    • A 25-year-old woman presents to the Emergency department with sudden onset of difficulty breathing. She has a history of asthma but is otherwise healthy. Upon admission, she is observed to be breathing rapidly, using her accessory muscles, and is experiencing cold and clammy skin. Upon chest auscultation, widespread wheezing is detected.

      An arterial blood gas analysis reveals:

      pH 7.46
      pO2 13 kPa
      pCO2 2.7 kPa
      HCO3- 23 mmol/l

      Which aspect of the underlying disease is affected in this patient?

      Your Answer:

      Correct Answer: Forced Expiratory Volume

      Explanation:

      It is probable that this individual is experiencing an acute episode of asthma. Asthma is a condition that results in the constriction of the airways, known as an obstructive airway disease. Its distinguishing feature is its ability to be reversed. The forced expiratory volume is the most impacted parameter in asthma and other obstructive airway diseases.

      Understanding Lung Volumes in Respiratory Physiology

      In respiratory physiology, lung volumes can be measured to determine the amount of air that moves in and out of the lungs during breathing. The diagram above shows the different lung volumes that can be measured.

      Tidal volume (TV) refers to the amount of air that is inspired or expired with each breath at rest. In males, the TV is 500ml while in females, it is 350ml.

      Inspiratory reserve volume (IRV) is the maximum volume of air that can be inspired at the end of a normal tidal inspiration. The inspiratory capacity is the sum of TV and IRV. On the other hand, expiratory reserve volume (ERV) is the maximum volume of air that can be expired at the end of a normal tidal expiration.

      Residual volume (RV) is the volume of air that remains in the lungs after maximal expiration. It increases with age and can be calculated by subtracting ERV from FRC. Speaking of FRC, it is the volume in the lungs at the end-expiratory position and is equal to the sum of ERV and RV.

      Vital capacity (VC) is the maximum volume of air that can be expired after a maximal inspiration. It decreases with age and can be calculated by adding inspiratory capacity and ERV. Lastly, total lung capacity (TLC) is the sum of vital capacity and residual volume.

      Physiological dead space (VD) is calculated by multiplying tidal volume by the difference between arterial carbon dioxide pressure (PaCO2) and end-tidal carbon dioxide pressure (PeCO2) and then dividing the result by PaCO2.

    • This question is part of the following fields:

      • Respiratory System
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  • Question 24 - A 10-year-old patient presents with recurrent skin cancer and is diagnosed with xeroderma...

    Incorrect

    • A 10-year-old patient presents with recurrent skin cancer and is diagnosed with xeroderma pigmentosum. What is the defective biochemical mechanism in this disease?

      Your Answer:

      Correct Answer: DNA excision repair

      Explanation:

      Xeroderma Pigmentosum and DNA Repair

      Deoxyribonucleic acid (DNA) found in the skin cells can absorb ultraviolet (UV) light, which can cause the formation of pyrimidine dimers. These dimers are removed through a process called excision repair, where the damaged DNA is cut out and replaced with new DNA. However, if this process fails, it can lead to mutations in genes that suppress tumors or promote their growth, potentially leading to cancer.

      Xeroderma pigmentosum is a genetic disorder that is inherited in an autosomal recessive pattern. This means that an individual must inherit two copies of the mutated gene, one from each parent, to develop the disorder. Generally, disorders that affect metabolism or DNA replication on a cellular or genetic level are inherited in an autosomal recessive pattern. On the other hand, genetic disorders that affect larger structural components are usually inherited in an autosomal dominant pattern. While there are exceptions to these rules, they can serve as a helpful guide for exam preparation.

    • This question is part of the following fields:

      • Basic Sciences
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  • Question 25 - A 70-year-old woman complains of throbbing hip pain that has been gradually developing...

    Incorrect

    • A 70-year-old woman complains of throbbing hip pain that has been gradually developing for 2 months. She had a fall during gardening a year ago that resulted in a fracture of the neck of her right femur.

      During examination, she displays a decent range of motion at the hip, but she is experiencing a considerable amount of pain.

      Based on the probable reason for her persistent pain, which blood vessel is most likely affected?

      Your Answer:

      Correct Answer: Medial femoral circumflex artery

      Explanation:

      The primary supplier of blood to the femoral head is the medial femoral circumflex artery. If this artery is compromised, it can lead to avascular necrosis, a condition where the bone’s blood supply is disrupted, causing ischemic and necrotic changes. This can slow down recovery and increase the risk of arthritis and bone collapse. In children, the artery of ligamentum teres is the main blood supply to the femoral head and is commonly compromised due to dislocations. The internal iliac artery supplies much of the pelvis but is unlikely to be damaged in a neck of femur fracture, while the lateral femoral circumflex artery supplies the muscles of the anterior thigh.

      Anatomy of the Femur: Structure and Blood Supply

      The femur is the longest and strongest bone in the human body, extending from the hip joint to the knee joint. It consists of a rounded head that articulates with the acetabulum and two large condyles at its inferior aspect that articulate with the tibia. The superior aspect of the femur comprises a head and neck that pass inferolaterally to the body and the two trochanters. The neck meets the body of the femur at an angle of 125o and is demarcated from it by a wide rough intertrochanteric crest. The greater trochanter has discernible surfaces that form the site of attachment of the gluteal muscles, while the linea aspera forms part of the origin of the attachments of the thigh adductors.

      The femur has a rich blood supply, with numerous vascular foramina existing throughout its length. The blood supply to the femoral head is clinically important and is provided by the medial circumflex femoral and lateral circumflex femoral arteries, which are branches of the profunda femoris. The inferior gluteal artery also contributes to the blood supply. These arteries form an anastomosis and travel up the femoral neck to supply the head. It is important to note that the neck is covered by synovial membrane up to the intertrochanteric line, and the posterior aspect of the neck is demarcated from the shaft by the intertrochanteric crest. Understanding the anatomy of the femur, including its structure and blood supply, is crucial for medical professionals in diagnosing and treating injuries and conditions related to this bone.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
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  • Question 26 - A 9-year-old child is under investigation for short stature. While taking the medical...

    Incorrect

    • A 9-year-old child is under investigation for short stature. While taking the medical history, you uncover that the child's parents are first cousins who share the same grandmother. What genetic disorders are more likely to occur in the offspring of consanguineous parents?

      Your Answer:

      Correct Answer: Autosomal recessive

      Explanation:

      To answer this question, one must have knowledge of consanguinity, which refers to blood relations. In families where both parents share a common ancestor, such as a grandmother, there is a higher likelihood that they both carry a disease allele that runs in their family lineage. This increases the chances of autosomal recessive conditions occurring.

      X-linked dominant, autosomal dominant, and X-linked recessive conditions are not impacted by consanguinity. However, if a family lineage is associated with a disease recessive allele, it is more likely that two carriers will mate if they are blood relatives. Drawing out a family tree can help illustrate the impact of consanguinity on the likelihood of certain genetic conditions.

      Consanguinity and Inherited Defects

      Consanguinity refers to the practice of marrying within the same family or bloodline. When couples who are related marry, the risk of inherited defects is approximately double that of a non-related couple. This is because the genetic material passed down from both parents is more likely to contain the same harmful mutations. However, when second cousins marry, the risk of inherited defects is reduced to that of a non-related couple. This is because second cousins share a smaller percentage of their genetic material compared to first cousins or closer relatives. It is important for couples who are considering marriage to be aware of the potential risks associated with consanguinity and to seek genetic counseling if necessary. By understanding the risks and taking appropriate measures, couples can make informed decisions about their future together.

    • This question is part of the following fields:

      • General Principles
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  • Question 27 - Which one of the following structures is not closely related to the piriformis...

    Incorrect

    • Which one of the following structures is not closely related to the piriformis muscle?

      Your Answer:

      Correct Answer: Medial femoral circumflex artery

      Explanation:

      The lateral hip rotators have different nerve supplies. The piriformis muscle is supplied by the ventral rami of S1 and S2, while the obturator internus and superior gemellus are supplied by the nerve to obturator internus. The inferior gemellus and quadrator femoris are supplied by the nerve to quadratus femoris.

      The piriformis muscle is an important landmark in the gluteal region and is closely related to the sciatic nerve, inferior gluteal artery and nerve, and superior gluteal artery and nerve.

      The medial femoral circumflex artery runs deep to the quadratus femoris muscle.

      The gluteal region is composed of various muscles and nerves that play a crucial role in hip movement and stability. The gluteal muscles, including the gluteus maximus, medius, and minimis, extend and abduct the hip joint. Meanwhile, the deep lateral hip rotators, such as the piriformis, gemelli, obturator internus, and quadratus femoris, rotate the hip joint externally.

      The nerves that innervate the gluteal muscles are the superior and inferior gluteal nerves. The superior gluteal nerve controls the gluteus medius, gluteus minimis, and tensor fascia lata muscles, while the inferior gluteal nerve controls the gluteus maximus muscle.

      If the superior gluteal nerve is damaged, it can result in a Trendelenburg gait, where the patient is unable to abduct the thigh at the hip joint. This weakness causes the pelvis to tilt down on the opposite side during the stance phase, leading to compensatory movements such as trunk lurching to maintain a level pelvis throughout the gait cycle. As a result, the pelvis sags on the opposite side of the lesioned superior gluteal nerve.

    • This question is part of the following fields:

      • Neurological System
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  • Question 28 - A 46-year-old man comes to the clinic complaining of bilateral sciatica and partial...

    Incorrect

    • A 46-year-old man comes to the clinic complaining of bilateral sciatica and partial urinary incontinence. Upon conducting a comprehensive examination and lumbosacral magnetic resonance imaging, the diagnosis of cauda equina syndrome is confirmed at the L2 level.

      What is the most probable finding to be observed during the examination?

      Your Answer:

      Correct Answer: S2-S4 anaesthesia

      Explanation:

      Lesions in the lower lumbar region cannot result in upper motor neuron signs because the spinal cord terminates at L1.

      The spinal cord is a central structure located within the vertebral column that provides it with structural support. It extends rostrally to the medulla oblongata of the brain and tapers caudally at the L1-2 level, where it is anchored to the first coccygeal vertebrae by the filum terminale. The cord is characterised by cervico-lumbar enlargements that correspond to the brachial and lumbar plexuses. It is incompletely divided into two symmetrical halves by a dorsal median sulcus and ventral median fissure, with grey matter surrounding a central canal that is continuous with the ventricular system of the CNS. Afferent fibres entering through the dorsal roots usually terminate near their point of entry but may travel for varying distances in Lissauer’s tract. The key point to remember is that the anatomy of the cord will dictate the clinical presentation in cases of injury, which can be caused by trauma, neoplasia, inflammatory diseases, vascular issues, or infection.

      One important condition to remember is Brown-Sequard syndrome, which is caused by hemisection of the cord and produces ipsilateral loss of proprioception and upper motor neuron signs, as well as contralateral loss of pain and temperature sensation. Lesions below L1 tend to present with lower motor neuron signs. It is important to keep a clinical perspective in mind when revising CNS anatomy and to understand the ways in which the spinal cord can become injured, as this will help in diagnosing and treating patients with spinal cord injuries.

    • This question is part of the following fields:

      • Neurological System
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  • Question 29 - A 30-year-old man presents with a sore throat and insists on receiving antibiotics....

    Incorrect

    • A 30-year-old man presents with a sore throat and insists on receiving antibiotics. After discussing the limited benefits of antibiotics for viral pharyngitis, it is explained to him that only 2 out of every 100 people treated with antibiotics will experience a reduction in complications. What is the number needed to treat (NNT) in this case?

      Your Answer:

      Correct Answer: 50

      Explanation:

      To determine the number needed to treat (NNT), we divide 1 by the absolute risk reduction (ARR) of 0.02, resulting in an NNT of 50. This means that 50 people need to be treated with antibiotics to prevent one complication. This information can be used to assess the risk-benefit profile of the treatment, especially when compared to the number needed to harm.

      Numbers needed to treat (NNT) is a measure that determines how many patients need to receive a particular intervention to reduce the expected number of outcomes by one. To calculate NNT, you divide 1 by the absolute risk reduction (ARR) and round up to the nearest whole number. ARR can be calculated by finding the absolute difference between the control event rate (CER) and the experimental event rate (EER). There are two ways to calculate ARR, depending on whether the outcome of the study is desirable or undesirable. If the outcome is undesirable, then ARR equals CER minus EER. If the outcome is desirable, then ARR is equal to EER minus CER. It is important to note that ARR may also be referred to as absolute benefit increase.

    • This question is part of the following fields:

      • General Principles
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  • Question 30 - A 14-year-old boy comes to the clinic complaining of ear pain. He mentions...

    Incorrect

    • A 14-year-old boy comes to the clinic complaining of ear pain. He mentions having some crusty discharge at the entrance of his ear canal when he woke up this morning. He denies any hearing loss, dizziness, or other symptoms. He swims twice a week. Upon examination, he has no fever. The auricle of his ear appears red, and pressing on the tragus causes discomfort. Otoscopy reveals an erythematous canal with a small amount of yellow discharge. The superior edge of the tympanic membrane is also red, but there is no bulging or fluid in the middle ear. Which bone articulates with the bone that is typically seen pressing against the tympanic membrane?

      Your Answer:

      Correct Answer: Incus

      Explanation:

      The middle bone of the 3 ossicles is known as the incus. During otoscopy, the malleus can be observed in contact with the tympanic membrane and it connects with the incus medially.

      The ossicles, which are the 3 bones in the middle ear, are arranged from lateral to medial as follows:
      Malleus: This is the most lateral of the ossicles. The handle and lateral process of the malleus attach to the tympanic membrane, making it visible during otoscopy. The head of the malleus connects with the incus. The term ‘malleus’ is derived from the Latin word for ‘hammer’.
      Incus: The incus is positioned between and connects with the other two ossicles. The body of the incus connects with the malleus, while the long limb of the bone connects with the stapes. The term ‘incus’ is derived from the Latin word for ‘anvil’.

      Anatomy of the Ear

      The ear is divided into three distinct regions: the external ear, middle ear, and internal ear. The external ear consists of the auricle and external auditory meatus, which are innervated by the greater auricular nerve and auriculotemporal branch of the trigeminal nerve. The middle ear is the space between the tympanic membrane and cochlea, and is connected to the nasopharynx by the eustachian tube. The tympanic membrane is composed of three layers and is approximately 1 cm in diameter. The middle ear is innervated by the glossopharyngeal nerve. The ossicles, consisting of the malleus, incus, and stapes, transmit sound vibrations from the tympanic membrane to the inner ear. The internal ear contains the cochlea, which houses the organ of corti, the sense organ of hearing. The vestibule accommodates the utricule and saccule, which contain endolymph and are surrounded by perilymph. The semicircular canals, which share a common opening into the vestibule, lie at various angles to the petrous temporal bone.

    • This question is part of the following fields:

      • Respiratory System
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SESSION STATS - PERFORMANCE PER SPECIALTY

General Principles (1/4) 25%
Respiratory System (0/1) 0%
Endocrine System (1/1) 100%
Haematology And Oncology (1/1) 100%
Neurological System (0/2) 0%
Gastrointestinal System (0/1) 0%
Basic Sciences (0/1) 0%
Cardiovascular System (0/2) 0%
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