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  • Question 1 - An 85-year-old woman visits her doctor with a complaint of worsening breathlessness in...

    Correct

    • An 85-year-old woman visits her doctor with a complaint of worsening breathlessness in the past 6 months. She has been smoking 10 cigarettes a day for the last 40 years. The doctor suspects that she may have chronic obstructive pulmonary disease. What is one of the mechanisms by which smoking damages the lungs and leads to emphysema?

      Your Answer: Inactivation of alpha-1 antitrypsin

      Explanation:

      The function of alpha-1 antitrypsin is to inhibit elastase. However, smoke has a negative impact on this protein in the lungs, resulting in increased activity of elastases and the breakdown of elastic tissue, which leads to emphysema.

      Contrary to popular belief, smoke actually activates polymorphonuclear leucocytes, which contributes to the development of emphysema.

      Mucous gland hyperplasia, basal cell metaplasia, and basement membrane thickening are all examples of how smoke affects the lungs to cause chronic bronchitis, not emphysema.

      COPD, or chronic obstructive pulmonary disease, can be caused by a variety of factors. The most common cause is smoking, which can lead to inflammation and damage in the lungs over time. Another potential cause is alpha-1 antitrypsin deficiency, a genetic condition that can result in lung damage. Additionally, exposure to certain substances such as cadmium (used in smelting), coal, cotton, cement, and grain can also contribute to the development of COPD. It is important to identify and address these underlying causes in order to effectively manage and treat COPD.

    • This question is part of the following fields:

      • Respiratory System
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  • Question 2 - A 24-year-old man is admitted to the emergency department after a car accident....

    Incorrect

    • A 24-year-old man is admitted to the emergency department after a car accident. During the initial evaluation, he complains of difficulty breathing. A portable chest X-ray shows a 3 cm gap between the right lung margin and the chest wall, indicating a significant traumatic pneumothorax. The medical team administers high-flow oxygen and performs a right-sided chest drain insertion to drain the pneumothorax.

      What is a potential negative outcome that could arise from the insertion of a chest drain?

      Your Answer: Hospital-acquired pneumonia

      Correct Answer: Winging of the scapula

      Explanation:

      Insertion of a chest drain poses a risk of damaging the long thoracic nerve, which runs from the neck to the serratus anterior muscle. This can result in weakness or paralysis of the muscle, causing a winged scapula that is noticeable along the medial border of the scapula. It is important to use aseptic technique during the procedure to prevent hospital-acquired pleural infection. Chylothorax, pneumothorax, and pyothorax are all conditions that may require chest drain insertion, but they are not known complications of the procedure. Therefore, these options are not applicable.

      Anatomy of Chest Drain Insertion

      Chest drain insertion is necessary for various medical conditions such as trauma, haemothorax, pneumothorax, and pleural effusion. The size of the chest drain used depends on the specific condition being treated. While ultrasound guidance is an option, the anatomical method is typically tested in exams.

      It is recommended that chest drains are placed in the safe triangle, which is located in the mid axillary line of the 5th intercostal space. This triangle is bordered by the anterior edge of the latissimus dorsi, the lateral border of pectoralis major, a line superior to the horizontal level of the nipple, and the apex below the axilla. Another triangle, known as the triangle of auscultation, is situated behind the scapula and is bounded by the trapezius, latissimus dorsi, and vertebral border of the scapula. By folding the arms across the chest and bending forward, parts of the sixth and seventh ribs and the interspace between them become subcutaneous and available for auscultation.

      References:
      – Prof Harold Ellis. The applied anatomy of chest drains insertions. British Journal of hospital medicine 2007; (68): 44-45.
      – Laws D, Neville E, Duffy J. BTS guidelines for insertion of chest drains. Thorax, 2003; (58): 53-59.

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      • Respiratory System
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  • Question 3 - A 16-year-old male presents to the emergency department with a 48-hour history of...

    Correct

    • A 16-year-old male presents to the emergency department with a 48-hour history of tachypnea and tachycardia. His blood glucose level is 18mmol/l. While breathing 40% oxygen, an arterial blood sample is taken. The results show a PaO2 of 22kPa, pH of 7.35, PaCO2 of 3.5kPa, and HCO3- of 18.6 mmol/l. How should these blood gas results be interpreted?

      Your Answer: Metabolic acidosis with full respiratory compensation

      Explanation:

      The patient’s blood gas analysis shows a lower oxygen pressure by about 10kPa than the percentage of oxygen. The PaCo2 level is 3.5, indicating respiratory alkalosis or compensation for metabolic acidosis. The HCO3- level is 18.6, which suggests metabolic acidosis or metabolic compensation for respiratory alkalosis. These results indicate that the patient has metabolic acidosis with complete respiratory compensation. Additionally, the patient’s high blood glucose level suggests that the metabolic acidosis is due to diabetic ketoacidosis.

      Arterial Blood Gas Interpretation: A 5-Step Approach

      Arterial blood gas interpretation is a crucial aspect of patient care, particularly in critical care settings. The Resuscitation Council (UK) recommends a 5-step approach to interpreting arterial blood gas results. The first step is to assess the patient’s overall condition. The second step is to determine if the patient is hypoxaemic, with a PaO2 on air of less than 10 kPa. The third step is to assess if the patient is acidaemic (pH <7.35) or alkalaemic (pH >7.45).

      The fourth step is to evaluate the respiratory component of the arterial blood gas results. A PaCO2 level greater than 6.0 kPa suggests respiratory acidosis, while a PaCO2 level less than 4.7 kPa suggests respiratory alkalosis. The fifth step is to assess the metabolic component of the arterial blood gas results. A bicarbonate level less than 22 mmol/l or a base excess less than -2mmol/l suggests metabolic acidosis, while a bicarbonate level greater than 26 mmol/l or a base excess greater than +2mmol/l suggests metabolic alkalosis.

      To remember the relationship between pH, PaCO2, and bicarbonate, the acronym ROME can be used. Respiratory acidosis or alkalosis is opposite to the pH level, while metabolic acidosis or alkalosis is equal to the pH level. This 5-step approach and the ROME acronym can aid healthcare professionals in interpreting arterial blood gas results accurately and efficiently.

    • This question is part of the following fields:

      • Respiratory System
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  • Question 4 - A 55-year-old man visits his GP complaining of shortness of breath, haemoptysis, and...

    Incorrect

    • A 55-year-old man visits his GP complaining of shortness of breath, haemoptysis, and unintentional weight loss over the past 3 months. The GP refers him to the respiratory clinic for suspected lung cancer, and further investigations reveal a stage 2 squamous cell carcinoma of the lung. What is the most frequently associated paraneoplastic phenomenon with this type of cancer?

      Your Answer: Syndrome of inappropriate ADH secretion (SIADH)

      Correct Answer: Parathyroid hormone-related protein (PTHrP)

      Explanation:

      The correct answer is PTHrP, which is a paraneoplastic syndrome often associated with squamous cell lung cancer. PTHrP is a protein that functions similarly to parathyroid hormone and can cause hypercalcaemia when secreted by cancer cells.

      Acanthosis nigricans is another paraneoplastic phenomenon that is commonly associated with gastric adenocarcinoma. This condition causes hyperpigmentation of skin folds, such as the armpits.

      The syndrome of inappropriate ADH secretion is often linked to small cell lung cancer. This condition involves the hypersecretion of ADH, which leads to dilutional hyponatraemia and its associated symptoms.

      Carcinoid syndrome is a paraneoplastic syndrome that is typically associated with neuroendocrine tumours that have metastasised to the liver. This condition causes hypersecretion of serotonin and other substances, resulting in facial flushing, palpitations, and gastrointestinal upset.

      Lung cancer can present with paraneoplastic features, which are symptoms caused by the cancer but not directly related to the tumor itself. Small cell lung cancer can cause the secretion of ADH and, less commonly, ACTH, which can lead to hypertension, hyperglycemia, hypokalemia, alkalosis, and muscle weakness. Lambert-Eaton syndrome is also associated with small cell lung cancer. Squamous cell lung cancer can cause the secretion of parathyroid hormone-related protein, leading to hypercalcemia, as well as clubbing and hypertrophic pulmonary osteoarthropathy. Adenocarcinoma can cause gynecomastia and hypertrophic pulmonary osteoarthropathy. Hypertrophic pulmonary osteoarthropathy is a painful condition involving the proliferation of periosteum in the long bones. Although traditionally associated with squamous cell carcinoma, some studies suggest that adenocarcinoma is the most common cause.

    • This question is part of the following fields:

      • Respiratory System
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  • Question 5 - A senior woman with a history of chronic obstructive pulmonary disease (COPD) arrives...

    Incorrect

    • A senior woman with a history of chronic obstructive pulmonary disease (COPD) arrives at the hospital complaining of worsening shortness of breath and a productive cough. As part of the initial evaluation, a chest X-ray is requested.

      What radiographic feature would you anticipate observing on her chest X-ray?

      Your Answer: Pleural effusion

      Correct Answer: Flattened diaphragm

      Explanation:

      The diaphragm of patients with COPD often appears flattened on a chest X-ray due to the chronic expiratory airflow obstruction causing dynamic hyperinflation of the lungs. Pleural effusions are commonly associated with infection, malignancy, or heart failure, while empyema is a result of pus accumulation in the pleural space caused by an infection.

      Understanding COPD: Symptoms and Diagnosis

      Chronic obstructive pulmonary disease (COPD) is a common medical condition that includes chronic bronchitis and emphysema. Smoking is the leading cause of COPD, and patients with mild disease may only need occasional use of a bronchodilator, while severe cases may result in frequent hospital admissions due to exacerbations. Symptoms of COPD include a productive cough, dyspnea, wheezing, and in severe cases, right-sided heart failure leading to peripheral edema.

      To diagnose COPD, doctors may recommend post-bronchodilator spirometry to demonstrate airflow obstruction, a chest x-ray to check for hyperinflation, bullae, and flat hemidiaphragm, and to exclude lung cancer. A full blood count may also be necessary to exclude secondary polycythemia, and body mass index (BMI) calculation is important. The severity of COPD is categorized using the FEV1, with a ratio of less than 70% indicating airflow obstruction. The grading system has changed following the 2010 NICE guidelines, with Stage 1 – mild now including patients with an FEV1 greater than 80% predicted but with a post-bronchodilator FEV1/FVC ratio of less than 0.7. Measuring peak expiratory flow is of limited value in COPD, as it may underestimate the degree of airflow obstruction.

      In summary, COPD is a common condition caused by smoking that can result in a range of symptoms and severity. Diagnosis involves various tests to check for airflow obstruction, exclude lung cancer, and determine the severity of the disease.

    • This question is part of the following fields:

      • Respiratory System
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  • Question 6 - Brenda is a 36-year-old woman who presents with tachypnoea. This occurred whilst she...

    Incorrect

    • Brenda is a 36-year-old woman who presents with tachypnoea. This occurred whilst she was seated. Her only medical history is asthma for which she takes salbutamol. On examination, her respiratory rate is 28 breaths/minute, heart rate 100bpm, Her chest is resonant on percussion and lung sounds are normal. Her chest X-ray is normal. You obtain her arterial blood gas sample results which show the following:

      pH 7.55
      PaCO2 4.2 kPa
      PaO2 10 kPa
      HCO3 24 mmol/l

      What could have caused the acid-base imbalance in Brenda's case?

      Your Answer:

      Correct Answer: Panic attack

      Explanation:

      Although panic attacks can cause tachypnea and a decrease in partial pressure of carbon dioxide, the acid-base disturbance that would result from this situation is not included as one of the answer choices.

      Respiratory Alkalosis: Causes and Examples

      Respiratory alkalosis is a condition that occurs when the blood pH level rises above the normal range due to excessive breathing. This can be caused by various factors, including anxiety, pulmonary embolism, CNS disorders, altitude, and pregnancy. Salicylate poisoning can also lead to respiratory alkalosis, but it may also cause metabolic acidosis in the later stages. In this case, the respiratory centre is stimulated early, leading to respiratory alkalosis, while the direct acid effects of salicylates combined with acute renal failure may cause acidosis later on. It is important to identify the underlying cause of respiratory alkalosis to determine the appropriate treatment. Proper management can help prevent complications and improve the patient’s overall health.

    • This question is part of the following fields:

      • Respiratory System
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  • Question 7 - A 15-year-old boy presents to his GP with a painless swelling in his...

    Incorrect

    • A 15-year-old boy presents to his GP with a painless swelling in his neck. The mass is located centrally just below the hyoid bone and does not cause any difficulty in swallowing or breathing. Upon examination, the GP notes that the mass moves with protrusion of the tongue and with swallowing. The GP diagnoses the boy with a benign thyroglossal cyst, which is caused by a persistent thyroglossal duct, and advises surgical removal. Where is the thyroglossal duct attached to the tongue?

      Your Answer:

      Correct Answer: Foramen cecum

      Explanation:

      The thyroglossal duct connects the thyroid gland to the tongue via the foramen caecum during embryonic development. The terminal sulcus, median sulcus, palatoglossal arch, and epiglottis are not connected to the thyroid gland.

      Understanding Thyroglossal Cysts

      Thyroglossal cysts are named after the thyroid and tongue, which are the two structures involved in their development. During embryology, the thyroid gland develops from the floor of the pharynx and descends into the neck, connected to the tongue by the thyroglossal duct. The foramen cecum is the point of attachment of the thyroglossal duct to the tongue. Normally, the thyroglossal duct atrophies, but in some people, it may persist and give rise to a thyroglossal duct cyst.

      Thyroglossal cysts are more common in patients under 20 years old and are usually midline, between the isthmus of the thyroid and the hyoid bone. They move upwards with protrusion of the tongue and may be painful if infected. Understanding the embryology and presentation of thyroglossal cysts is important for proper diagnosis and treatment.

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      • Respiratory System
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  • Question 8 - A 48-year-old male presents for a preoperative evaluation for an inguinal hernia repair....

    Incorrect

    • A 48-year-old male presents for a preoperative evaluation for an inguinal hernia repair. During the assessment, you observe a loculated left pleural effusion on his chest x-ray. Upon further inquiry, the patient discloses that he worked as a builder three decades ago. What is the probable reason for the effusion?

      Your Answer:

      Correct Answer: Mesothelioma

      Explanation:

      Due to his profession as a builder, this individual is at risk of being exposed to asbestos. Given the 30-year latent period and the presence of a complex effusion, it is highly probable that the underlying cause is mesothelioma.

      Understanding Mesothelioma

      Mesothelioma is a type of cancer that affects the mesothelial layer of the pleural cavity, which is commonly linked to asbestos exposure. Although it is rare, other mesothelial layers in the abdomen may also be affected. Symptoms of mesothelioma include dyspnoea, weight loss, chest wall pain, and clubbing. In some cases, patients may present with painless pleural effusion. It is important to note that only 20% of patients have pre-existing asbestosis, but 85-90% have a history of asbestos exposure, with a latent period of 30-40 years.

      Diagnosis of mesothelioma is typically made through a chest x-ray, which may show pleural effusion or pleural thickening. A pleural CT is then performed to confirm the diagnosis. If a pleural effusion is present, fluid is sent for MC&S, biochemistry, and cytology. However, cytology is only helpful in 20-30% of cases. Local anaesthetic thoracoscopy is increasingly used to investigate cytology negative exudative effusions as it has a high diagnostic yield of around 95%. If an area of pleural nodularity is seen on CT, an image-guided pleural biopsy may be used.

      Management of mesothelioma is mainly symptomatic, with industrial compensation available for those who have been exposed to asbestos. Chemotherapy and surgery may be options for those who are operable. Unfortunately, the prognosis for mesothelioma is poor, with a median survival of only 12 months.

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      • Respiratory System
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  • Question 9 - A 24-year-old female arrives at the emergency department in a state of panic...

    Incorrect

    • A 24-year-old female arrives at the emergency department in a state of panic following a recent breakup with her partner. She complains of chest tightness and dizziness, fearing that she may be experiencing a heart attack. Upon examination, her vital signs are stable except for a respiratory rate of 34 breaths per minute. What compensatory mechanism is expected in response to the change in her oxyhaemoglobin dissociation curve, and what is the underlying cause?

      Your Answer:

      Correct Answer: Left shift, respiratory alkalosis

      Explanation:

      The patient’s oxygen dissociation curve has shifted to the left, indicating respiratory alkalosis. This is likely due to the patient experiencing a panic attack and hyperventilating, leading to a decrease in carbon dioxide levels and an increase in the affinity of haemoglobin for oxygen. Respiratory acidosis, hypercapnia, and a right shift of the curve are not appropriate explanations for this patient’s condition.

      Understanding the Oxygen Dissociation Curve

      The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.

      The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.

      Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.

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  • Question 10 - A father brings his 9-year-old daughter to your general practice, as he is...

    Incorrect

    • A father brings his 9-year-old daughter to your general practice, as he is worried about her hearing. He notices that he has to repeat himself when talking to her, and thinks she is often 'in her own little world'. During the examination, the Rinne test is positive on the left and negative on the right. What conclusions can be drawn from this?

      Your Answer:

      Correct Answer: Can not tell if both sides are affected.

      Explanation:

      The Rinne and Weber tests are used to diagnose hearing loss. The Rinne test involves comparing air and bone conduction, with a positive result indicating a healthy or sensorineural loss and a negative result indicating a conductive loss. The Weber test involves placing a tuning fork on the forehead and determining if the sound is symmetrical or louder on one side, with a conductive loss resulting in louder sound on the affected side and a sensorineural loss resulting in louder sound on the non-affected side. When used together, these tests can provide more information about the type and affected side of hearing loss.

      Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness

      Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.

      Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.

      The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.

      Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.

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  • Question 11 - A man in his early fifties comes in with a painful rash caused...

    Incorrect

    • A man in his early fifties comes in with a painful rash caused by herpes on the external auditory meatus. He also has facial palsy on the same side, along with deafness, tinnitus, and vertigo. What is the probable diagnosis?

      Your Answer:

      Correct Answer: Ramsay Hunt syndrome

      Explanation:

      Ramsay Hunt syndrome is characterized by a combination of Bell’s palsy facial paralysis, along with symptoms such as a herpetic rash, deafness, tinnitus, and vertigo. It is important to note that the rash may not always be visible, despite being present.

      While Bell’s palsy may present with facial paralysis, it does not typically involve the presence of herpetic rashes.

      Understanding Ramsay Hunt Syndrome

      Ramsay Hunt syndrome, also known as herpes zoster oticus, is a condition that occurs when the varicella zoster virus reactivates in the geniculate ganglion of the seventh cranial nerve. The first symptom of this syndrome is often auricular pain, followed by facial nerve palsy and a vesicular rash around the ear. Other symptoms may include vertigo and tinnitus.

      To manage Ramsay Hunt syndrome, doctors typically prescribe oral acyclovir and corticosteroids. These medications can help reduce the severity of symptoms and prevent complications.

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      • Respiratory System
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  • Question 12 - A 25-year-old woman presents to the Emergency department with sudden onset of difficulty...

    Incorrect

    • A 25-year-old woman presents to the Emergency department with sudden onset of difficulty breathing. She has a history of asthma but is otherwise healthy. Upon admission, she is observed to be breathing rapidly, using her accessory muscles, and is experiencing cold and clammy skin. Upon chest auscultation, widespread wheezing is detected.

      An arterial blood gas analysis reveals:

      pH 7.46
      pO2 13 kPa
      pCO2 2.7 kPa
      HCO3- 23 mmol/l

      Which aspect of the underlying disease is affected in this patient?

      Your Answer:

      Correct Answer: Forced Expiratory Volume

      Explanation:

      It is probable that this individual is experiencing an acute episode of asthma. Asthma is a condition that results in the constriction of the airways, known as an obstructive airway disease. Its distinguishing feature is its ability to be reversed. The forced expiratory volume is the most impacted parameter in asthma and other obstructive airway diseases.

      Understanding Lung Volumes in Respiratory Physiology

      In respiratory physiology, lung volumes can be measured to determine the amount of air that moves in and out of the lungs during breathing. The diagram above shows the different lung volumes that can be measured.

      Tidal volume (TV) refers to the amount of air that is inspired or expired with each breath at rest. In males, the TV is 500ml while in females, it is 350ml.

      Inspiratory reserve volume (IRV) is the maximum volume of air that can be inspired at the end of a normal tidal inspiration. The inspiratory capacity is the sum of TV and IRV. On the other hand, expiratory reserve volume (ERV) is the maximum volume of air that can be expired at the end of a normal tidal expiration.

      Residual volume (RV) is the volume of air that remains in the lungs after maximal expiration. It increases with age and can be calculated by subtracting ERV from FRC. Speaking of FRC, it is the volume in the lungs at the end-expiratory position and is equal to the sum of ERV and RV.

      Vital capacity (VC) is the maximum volume of air that can be expired after a maximal inspiration. It decreases with age and can be calculated by adding inspiratory capacity and ERV. Lastly, total lung capacity (TLC) is the sum of vital capacity and residual volume.

      Physiological dead space (VD) is calculated by multiplying tidal volume by the difference between arterial carbon dioxide pressure (PaCO2) and end-tidal carbon dioxide pressure (PeCO2) and then dividing the result by PaCO2.

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      • Respiratory System
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  • Question 13 - A 25-year-old man presents to the Emergency department with acute onset of shortness...

    Incorrect

    • A 25-year-old man presents to the Emergency department with acute onset of shortness of breath during a basketball game. He reports no history of trauma and is typically healthy. Upon examination, he appears tall and lean, and respiratory assessment reveals reduced breath sounds and hyper-resonant percussion notes on the right side. The trachea remains centrally located. A chest x-ray confirms a diagnosis of a collapsed lung due to a right-sided pneumothorax. What is the reason for the lung's failure to re-expand?

      Your Answer:

      Correct Answer: Increase in intrapleural pressure

      Explanation:

      The process of lung expansion relies on the negative pressure in the intrapleural space between the visceral and parietal pleura, which is present throughout respiration. This negative pressure pulls the lung towards the chest wall, allowing it to expand. However, if air enters the intrapleural space, the negative pressure is lost and the lung cannot fully reinflate. It is important to note that the intrapleural space is a potential space between the pleural surfaces, and there is typically no actual space present under normal circumstances.

      Management of Pneumothorax: BTS Guidelines

      Pneumothorax is a condition where air accumulates in the pleural space, causing the lung to collapse. The British Thoracic Society (BTS) has published guidelines for the management of spontaneous pneumothorax, which can be primary or secondary. Primary pneumothorax occurs without any underlying lung disease, while secondary pneumothorax is associated with lung disease.

      The BTS recommends that patients with a rim of air less than 2 cm and no shortness of breath may be discharged, while those with a larger rim of air or shortness of breath should undergo aspiration or chest drain insertion. For secondary pneumothorax, patients over 50 years old with a rim of air greater than 2 cm or shortness of breath should undergo chest drain insertion. Aspiration may be attempted for those with a rim of air between 1-2 cm, but chest drain insertion is recommended if aspiration fails.

      Patients with iatrogenic pneumothorax, which is caused by medical procedures, have a lower likelihood of recurrence than those with spontaneous pneumothorax. Observation is usually sufficient, but chest drain insertion may be required in some cases. Ventilated patients and those with chronic obstructive pulmonary disease (COPD) may require chest drain insertion.

      Patients with pneumothorax should be advised to avoid smoking to reduce the risk of further episodes. They should also be aware of restrictions on air travel and scuba diving. The CAA recommends a waiting period of two weeks after successful drainage before air travel, while the BTS advises against scuba diving unless the patient has undergone bilateral surgical pleurectomy and has normal lung function and chest CT scan postoperatively.

      In summary, the BTS guidelines provide a comprehensive approach to the management of pneumothorax, taking into account the type of pneumothorax and the patient’s individual circumstances. Early intervention and appropriate follow-up can help prevent complications and improve outcomes.

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  • Question 14 - A 60-year-old diabetic patient presents to the clinic with a chief complaint of...

    Incorrect

    • A 60-year-old diabetic patient presents to the clinic with a chief complaint of hearing loss. After conducting a Webber’s and Rinne’s test, the following results were obtained:

      - Webber’s test: lateralizes to the left ear
      - Rinne’s test (left ear): bone conduction > air conduction
      - Rinne’s test (right ear): air conduction > bone conduction

      Based on these findings, what is the probable cause of the patient's hearing loss?

      Your Answer:

      Correct Answer: Otitis media with effusion

      Explanation:

      The Weber test lateralises to the side with bone conduction > air conduction, indicating conductive hearing loss on that side. The options given include acoustic neuroma (sensorineural hearing loss), otitis media with effusion (conductive hearing loss), temporal lobe epilepsy (no conductive hearing loss), and Meniere’s disease (vertigo, tinnitus, and fluctuating hearing loss). The correct answer is otitis media with effusion.

      Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness

      Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.

      Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.

      The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.

      Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.

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  • Question 15 - A 29-year-old man comes to your clinic with a complaint of ear pain...

    Incorrect

    • A 29-year-old man comes to your clinic with a complaint of ear pain that has been bothering him for the past 2 days. He reports no hearing loss or discharge and feels generally healthy. During the physical examination, you observe that he has no fever. When you palpate the tragus of the affected ear, he experiences pain. Upon otoscopy, you notice that the external auditory canal is red. The tympanic membrane is not bulging, and there is no visible fluid level. Which bone can you see pressing against the tympanic membrane?

      Your Answer:

      Correct Answer: Malleus

      Explanation:

      The ossicle that is in contact with the tympanic membrane is called the malleus. The middle ear contains three bones known as ossicles, which are arranged from lateral to medial. The malleus is the most lateral ossicle and its handle and lateral process attach to the tympanic membrane, making it visible during otoscopy. The head of the malleus articulates with the incus. The incus is located between the other two ossicles and articulates with both. The body of the incus articulates with the malleus, while the long limb of the bone articulates with the stapes. The Latin word for ‘hammer’ is used to describe the malleus, while the Latin word for ‘anvil’ is used to describe the incus.

      Anatomy of the Ear

      The ear is divided into three distinct regions: the external ear, middle ear, and internal ear. The external ear consists of the auricle and external auditory meatus, which are innervated by the greater auricular nerve and auriculotemporal branch of the trigeminal nerve. The middle ear is the space between the tympanic membrane and cochlea, and is connected to the nasopharynx by the eustachian tube. The tympanic membrane is composed of three layers and is approximately 1 cm in diameter. The middle ear is innervated by the glossopharyngeal nerve. The ossicles, consisting of the malleus, incus, and stapes, transmit sound vibrations from the tympanic membrane to the inner ear. The internal ear contains the cochlea, which houses the organ of corti, the sense organ of hearing. The vestibule accommodates the utricule and saccule, which contain endolymph and are surrounded by perilymph. The semicircular canals, which share a common opening into the vestibule, lie at various angles to the petrous temporal bone.

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  • Question 16 - A premature baby is born and the anaesthetists are struggling to ventilate the...

    Incorrect

    • A premature baby is born and the anaesthetists are struggling to ventilate the lungs because of insufficient surfactant. How does Laplace's law explain the force pushing inwards on the walls of the alveolus caused by surface tension between two static fluids, such as air and water in the alveolus?

      Your Answer:

      Correct Answer: Inversely proportional to the radius of the alveolus

      Explanation:

      The Relationship between Alveolar Size and Surface Tension in Respiratory Physiology

      In respiratory physiology, the alveolus is often represented as a perfect sphere to apply Laplace’s law. According to this law, there is an inverse relationship between the size of the alveolus and the surface tension. This means that smaller alveoli experience greater force than larger alveoli for a given surface tension, and they will collapse first. This phenomenon explains why, when two balloons are attached together by their ends, the smaller balloon will empty into the bigger balloon.

      In the lungs, this same principle applies to lung units, causing atelectasis and collapse when surfactant is not present. Surfactant is a substance that reduces surface tension, making it easier to expand the alveoli and preventing smaller alveoli from collapsing. Therefore, surfactant plays a crucial role in maintaining the proper functioning of the lungs and preventing respiratory distress. the relationship between alveolar size and surface tension is essential in respiratory physiology and can help in the development of treatments for lung diseases.

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  • Question 17 - A 35-year-old female patient presents to the GP with complaints of headaches, nasal...

    Incorrect

    • A 35-year-old female patient presents to the GP with complaints of headaches, nasal congestion, and facial pain that worsens upon leaning forward. Sinusitis is suspected. Which sinus is typically affected in this condition?

      Your Answer:

      Correct Answer: Maxillary

      Explanation:

      The maxillary sinus is susceptible to infections due to its drainage from the top. This sinus is the most frequently affected in cases of sinusitis. While frontal sinusitis can lead to intracranial complications, it is still less common than maxillary sinusitis.

      The petrosal sinus is not a bone cavity, but rather a venous structure situated beneath the brain.

      Acute sinusitis is a condition where the mucous membranes of the paranasal sinuses become inflamed. This inflammation is usually caused by infectious agents such as Streptococcus pneumoniae, Haemophilus influenzae, and rhinoviruses. Certain factors can predispose individuals to this condition, including nasal obstruction, recent local infections, swimming/diving, and smoking. Symptoms of acute sinusitis include facial pain, nasal discharge, and nasal obstruction. Treatment options include analgesia, intranasal decongestants or nasal saline, and intranasal corticosteroids. Oral antibiotics may be necessary for severe presentations, but they are not typically required. In some cases, an initial viral sinusitis can worsen due to secondary bacterial infection, which is known as double-sickening.

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  • Question 18 - A 27-year-old man with a history of epilepsy is admitted to the hospital...

    Incorrect

    • A 27-year-old man with a history of epilepsy is admitted to the hospital after experiencing a tonic-clonic seizure. He is currently taking sodium valproate as his only medication. A venous blood gas is obtained immediately.

      What are the expected venous blood gas results for this patient?

      Your Answer:

      Correct Answer: Low pH, high lactate, low SaO2

      Explanation:

      Acidosis shifts the oxygen dissociation curve to the right, which enhances oxygen delivery to the tissues by causing more oxygen to dissociate from Hb. postictal lactic acidosis is a common occurrence in patients with tonic-clonic seizures, and it is typically managed by monitoring for spontaneous resolution. During a seizure, tissue hypoxia can cause lactic acidosis. Therefore, a venous blood gas test for this patient should show low pH, high lactate, and low SaO2.

      If the venous blood gas test shows a high pH, normal lactate, and low SaO2, it would not be consistent with postictal lactic acidosis. This result indicates alkalosis, which can be caused by gastrointestinal losses, renal losses, or Cushing syndrome.

      A high pH, normal lactate, and normal SaO2 would also be inconsistent with postictal lactic acidosis because tissue hypoxia would cause an increase in lactate levels.

      Similarly, low pH, high lactate, and normal SaO2 would not be expected in postictal lactic acidosis because acidosis would shift the oxygen dissociation curve to the right, decreasing the oxygen saturation of haemoglobin.

      Finally, normal pH, normal lactate, and normal SaO2 are unlikely to be found in this patient shortly after a seizure. However, if the venous blood gas test was taken days after the seizure following an uncomplicated clinical course, these findings would be more plausible.

      Understanding the Oxygen Dissociation Curve

      The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.

      The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.

      Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.

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  • Question 19 - A 75-year-old man presents to the Emergency Department with acute shortness of breath...

    Incorrect

    • A 75-year-old man presents to the Emergency Department with acute shortness of breath following a 4-day febrile illness. On initial assessment, his oxygen saturation is 70% on room air with a PaO2 of 4.2kpa on an arterial blood gas.

      What would be the anticipated physiological response in this patient?

      Your Answer:

      Correct Answer: Pulmonary artery vasoconstriction

      Explanation:

      When faced with hypoxia, the pulmonary arteries undergo vasoconstriction, which redirects blood flow away from poorly oxygenated areas of the lungs and towards well-oxygenated regions. In cases where patients remain hypoxic despite optimal mechanical ventilation, inhaled nitric oxide can be used to induce pulmonary vasodilation and reverse this response.

      The statement that increased tidal volume with decreased respiratory rate is a response to hypoxia is incorrect. While an increase in tidal volume may occur, it is typically accompanied by an increase in respiratory rate.

      Pulmonary artery vasodilation is also incorrect. Hypoxia actually induces vasoconstriction in the pulmonary vasculature, as explained above.

      Similarly, reduced tidal volume with increased respiratory rate is not a direct response to hypoxia. While respiratory rate may increase, tidal volumes typically increase in response to hypoxia.

      In contrast to the pulmonary vessels, the systemic vasculature vasodilates in response to hypoxia.

      The Effects of Hypoxia on Pulmonary Arteries

      When the partial pressure of oxygen in the blood decreases, the pulmonary arteries undergo vasoconstriction. This means that the blood vessels narrow, allowing blood to be redirected to areas of the lung that are better aerated. This response is a natural mechanism that helps to improve the efficiency of gaseous exchange in the lungs. By diverting blood to areas with more oxygen, the body can ensure that the tissues receive the oxygen they need to function properly. Overall, hypoxia triggers a physiological response that helps to maintain homeostasis in the body.

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  • Question 20 - A 65-year-old man is undergoing an upper GI endoscopy due to difficulty swallowing....

    Incorrect

    • A 65-year-old man is undergoing an upper GI endoscopy due to difficulty swallowing. During the procedure, a suspicious-looking blockage is found at 33 cm from the incisors. The endoscopist tries to widen the area with a balloon, but the tumor causes a rupture in the oesophageal wall. Where will the contents of the oesophagus now drain?

      Your Answer:

      Correct Answer: Posterior mediastinum

      Explanation:

      The oesophagus is expected to remain within the thoracic cavity and situated in the posterior mediastinum at this point.

      The mediastinum is the area located between the two pulmonary cavities and is covered by the mediastinal pleura. It extends from the thoracic inlet at the top to the diaphragm at the bottom. The mediastinum is divided into four regions: the superior mediastinum, middle mediastinum, posterior mediastinum, and anterior mediastinum.

      The superior mediastinum is the area between the manubriosternal angle and T4/5. It contains important structures such as the superior vena cava, brachiocephalic veins, arch of aorta, thoracic duct, trachea, oesophagus, thymus, vagus nerve, left recurrent laryngeal nerve, and phrenic nerve. The anterior mediastinum contains thymic remnants, lymph nodes, and fat. The middle mediastinum contains the pericardium, heart, aortic root, arch of azygos vein, and main bronchi. The posterior mediastinum contains the oesophagus, thoracic aorta, azygos vein, thoracic duct, vagus nerve, sympathetic nerve trunks, and splanchnic nerves.

      In summary, the mediastinum is a crucial area in the thorax that contains many important structures and is divided into four regions. Each region contains different structures that are essential for the proper functioning of the body.

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  • Question 21 - A 75-year-old man presents with a 2-month history of progressive shortness of breath...

    Incorrect

    • A 75-year-old man presents with a 2-month history of progressive shortness of breath and a recent episode of coughing up blood in the morning. He has also experienced significant weight loss of over 12 lbs and loss of appetite. Upon physical examination, conjunctival pallor is noted. The patient has a 30 pack year history of smoking. A chest x-ray reveals a mediastinal mass and ipsilateral elevation of the right diaphragm. What structure is being compressed by the mediastinal mass to explain these findings?

      Your Answer:

      Correct Answer: Phrenic nerve

      Explanation:

      Lung cancer can cause the hemidiaphragm on the same side to rise due to pressure on the phrenic nerve. Haemoptysis is a common symptom of lung cancer, along with significant weight loss and a history of smoking. A chest x-ray can confirm the presence of a mediastinal mass, which is likely to be lung cancer.

      A rapidly expanding lung mass can cause compression of surrounding structures, leading to complications. For example, an apical tumor can compress the brachial plexus, causing sensory symptoms in the arms or Erb’s or Klumpke’s palsies. Compression of the cervical sympathetic chain can cause Horner’s syndrome, which includes meiosis, anhidrosis, ptosis, and enophthalmos.

      A mediastinal mass can also compress the recurrent laryngeal nerve as it winds around the aortic arch, resulting in hoarseness of voice or aphonia. Superior vena caval syndrome is a medical emergency that can cause swelling of the face, neck, upper chest, and arms, as well as the development of collaterals on the chest wall. Malignancy is the most common cause, but non-malignant causes can include an aortic aneurysm, fibrosing mediastinitis, or iatrogenic factors.

      The Phrenic Nerve: Origin, Path, and Supplies

      The phrenic nerve is a crucial nerve that originates from the cervical spinal nerves C3, C4, and C5. It supplies the diaphragm and provides sensation to the central diaphragm and pericardium. The nerve passes with the internal jugular vein across scalenus anterior and deep to the prevertebral fascia of the deep cervical fascia.

      The right phrenic nerve runs anterior to the first part of the subclavian artery in the superior mediastinum and laterally to the superior vena cava. In the middle mediastinum, it is located to the right of the pericardium and passes over the right atrium to exit the diaphragm at T8. On the other hand, the left phrenic nerve passes lateral to the left subclavian artery, aortic arch, and left ventricle. It passes anterior to the root of the lung and pierces the diaphragm alone.

      Understanding the origin, path, and supplies of the phrenic nerve is essential in diagnosing and treating conditions that affect the diaphragm and pericardium.

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  • Question 22 - A 65-year-old male with a diagnosis of lung cancer presents with fatigue and...

    Incorrect

    • A 65-year-old male with a diagnosis of lung cancer presents with fatigue and lightheadedness. Upon examination, the following results are obtained:

      Plasma sodium concentration 115 mmol/L (137-144)
      Potassium 3.5 mmol/L (3.5-4.9)
      Urea 3.2 mmol/L (2.5-7.5)
      Creatinine 67 µmol/L (60-110)

      What is the probable reason for his symptoms based on these findings?

      Your Answer:

      Correct Answer: Syndrome of inappropriate ADH secretion

      Explanation:

      Syndrome of Inappropriate ADH Secretion

      Syndrome of inappropriate ADH secretion (SIADH) is a condition characterized by low levels of sodium in the blood. This is caused by the overproduction of antidiuretic hormone (ADH) by the posterior pituitary gland. Tumors such as bronchial carcinoma can cause the ectopic elaboration of ADH, leading to dilutional hyponatremia. The diagnosis of SIADH is one of exclusion, but it can be supported by a high urine sodium concentration with high urine osmolality.

      Hypoadrenalism is less likely to cause hyponatremia, as it is usually associated with hyperkalemia and mild hyperuricemia. On the other hand, diabetes insipidus is a condition where the kidneys are unable to reabsorb water, leading to excessive thirst and urination.

      It is important to diagnose and treat SIADH promptly to prevent complications such as seizures, coma, and even death. Treatment options include fluid restriction, medications to block the effects of ADH, and addressing the underlying cause of the condition.

      In conclusion, SIADH is a condition that can cause low levels of sodium in the blood due to the overproduction of ADH. It is important to differentiate it from other conditions that can cause hyponatremia and to treat it promptly to prevent complications.

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  • Question 23 - A 65-year-old woman comes to the COPD clinic complaining of increasing breathlessness over...

    Incorrect

    • A 65-year-old woman comes to the COPD clinic complaining of increasing breathlessness over the past 3 months. She is currently receiving long-term oxygen therapy at home.

      During the examination, the patient's face appears plethoric, but there is no evidence of dyspnea at rest.

      The patient's FEV1/FVC ratio remains unchanged at 0.4, and her peak flow is 50% of the predicted value. However, her transfer factor is unexpectedly elevated.

      What could be the possible cause of this unexpected finding?

      Your Answer:

      Correct Answer: Polycythaemia

      Explanation:

      The transfer factor is typically low in most conditions that impair alveolar diffusion, except for polycythaemia, asthma, haemorrhage, and left-to-right shunts, which can cause an increased transfer of carbon monoxide. In this case, the patient’s plethoric facies suggest polycythaemia as the cause of their increased transfer factor. It’s important to note that exacerbations of COPD, pneumonia, and pulmonary fibrosis typically result in a low transfer factor, not an increased one.

      Understanding Transfer Factor in Lung Function Testing

      The transfer factor is a measure of how quickly a gas diffuses from the alveoli into the bloodstream. This is typically tested using carbon monoxide, and the results can be given as either the total gas transfer (TLCO) or the transfer coefficient corrected for lung volume (KCO). A raised TLCO may be caused by conditions such as asthma, pulmonary haemorrhage, left-to-right cardiac shunts, polycythaemia, hyperkinetic states, male gender, or exercise. On the other hand, a lower TLCO may be indicative of pulmonary fibrosis, pneumonia, pulmonary emboli, pulmonary oedema, emphysema, anaemia, or low cardiac output.

      KCO tends to increase with age, and certain conditions may cause an increased KCO with a normal or reduced TLCO. These conditions include pneumonectomy/lobectomy, scoliosis/kyphosis, neuromuscular weakness, and ankylosis of costovertebral joints (such as in ankylosing spondylitis). Understanding transfer factor is important in lung function testing, as it can provide valuable information about a patient’s respiratory health and help guide treatment decisions.

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  • Question 24 - A 55-year-old woman comes to your clinic seeking help to quit smoking. She...

    Incorrect

    • A 55-year-old woman comes to your clinic seeking help to quit smoking. She has been using nicotine patches for 6 months but has not been successful in her attempts. You decide to prescribe bupropion.

      What is a typical side effect of bupropion?

      Your Answer:

      Correct Answer: Gastrointestinal disturbance

      Explanation:

      Side Effects of Buproprion

      Buproprion is a medication that can cause aggression and hallucination in some patients. However, the more common side effects are gastrointestinal disturbances such as diarrhoea, nausea, and dry mouth. These side effects are often experienced by patients taking buproprion. It is important to be aware of the potential side effects of any medication and to speak with a healthcare provider if any concerns arise. Additional information on buproprion and its potential side effects can be found in the electronic Medicines Compendium and Medicines Complete.

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  • Question 25 - A 4-year-old girl with a known diagnosis of cystic fibrosis presents to her...

    Incorrect

    • A 4-year-old girl with a known diagnosis of cystic fibrosis presents to her pediatrician with a 2-day history of left-ear pain. Her mother reports that she has been frequently tugging at her left ear and had a fever this morning. Apart from this, she has been healthy. On examination, a red, bulging eardrum is observed. The pediatrician suspects bacterial otitis media. What is the probable causative organism responsible for this patient's symptoms?

      Your Answer:

      Correct Answer: Haemophilus influenzae

      Explanation:

      Haemophilus influenzae, Streptococcus pneumoniae, and Moraxella catarrhalis are common bacterial organisms that can cause bacterial otitis media. Pseudomonas aeruginosa can also be a common cause in patients with cystic fibrosis.

      The patient’s symptoms are typical of acute otitis media (AOM), which can cause ear pain, fever, and temporary hearing loss. AOM is more common in children due to their short, horizontal eustachian tubes that allow for easier movement of organisms from the upper respiratory tract to the middle ear.

      AOM can be caused by either bacteria or viruses, and it can be difficult to distinguish between the two. However, features that may suggest a bacterial cause include the absence of upper respiratory tract infection symptoms and conditions that predispose to bacterial infections. In some cases, viral AOM can increase the risk of bacterial superinfection. Antibiotics may be prescribed for prolonged cases of AOM that do not appear to be resolving within a few days or in patients with immunosuppression.

      Escherichia coli and Enterococcus faecalis are not the correct answers as they are not commonly associated with AOM. Haemophilus influenzae is more likely due to the proximity of the middle ear to the upper respiratory tract. Staphylococcus aureus is also an unlikely cause of bacterial AOM.

      Acute otitis media is a common condition in young children, often caused by bacterial infections following viral upper respiratory tract infections. Symptoms include ear pain, fever, and hearing loss, and diagnosis is based on criteria such as the presence of a middle ear effusion and inflammation of the tympanic membrane. Antibiotics may be prescribed in certain cases, and complications can include perforation of the tympanic membrane, hearing loss, and more serious conditions such as meningitis and brain abscess.

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  • Question 26 - A 35-year-old woman presents to the medical assessment unit with sudden onset shortness...

    Incorrect

    • A 35-year-old woman presents to the medical assessment unit with sudden onset shortness of breath. She reports no cough or fever and has no other associated symptoms. She recently returned from a hiking trip in France and takes the oral contraceptive pill but no other regular medications. She smokes 10 cigarettes a day but drinks no alcohol. On examination, she is tachypnoeic and tachycardic with an elevated JVP. Her calves are soft and non-tender with no pitting oedema. Initial blood tests show a positive D-dimer and elevated CRP. What is the appropriate treatment for this patient?

      Your Answer:

      Correct Answer: Low molecular weight heparin

      Explanation:

      Treatment for Suspected Pulmonary Embolism

      When a patient presents with risk factors for pulmonary embolism (PE) such as recent travel and oral contraceptive pill use, along with symptoms like tachypnea, tachycardia, and hypoxia, it is important to consider the possibility of a significant PE. In such cases, treatment with low molecular weight heparin should be given promptly to prevent further complications. A low-grade fever is also common in venothromboembolic disease. Elevated JVP signifies significant right heart strain due to a significant PE, but maintained blood pressure is a positive sign.

      The most common ECG finding in PE is an isolated sinus tachycardia, while the CXR may be clear, but prominent pulmonary arteries reflect pulmonary hypertension due to clot load in the pulmonary tree. A D-dimer test is recommended if the Wells score for PE is less than 4.

      According to NICE guidelines on venous thromboembolic diseases, low molecular weight heparin is the appropriate initial treatment for suspected PE. It is important not to delay treatment to await CTPA unless it can be performed immediately. There is no evidence of pneumonia to warrant IV antibiotics. Unfractionated heparin may be considered for patients with an eGFR of less than 30, high risk of bleeding, or those undergoing thrombolysis, but this is not the case with this patient. Thrombolysis is not indicated unless there is haemodynamic instability, even in suspected large PEs.

      In summary, prompt treatment with low molecular weight heparin is crucial in suspected cases of PE, and other treatment options should be considered based on individual patient factors.

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  • Question 27 - Cystic fibrosis is caused by a mutation in the CFTR gene. On which...

    Incorrect

    • Cystic fibrosis is caused by a mutation in the CFTR gene. On which chromosome is this gene located?

      Your Answer:

      Correct Answer: Chromosome 7

      Explanation:

      Understanding Cystic Fibrosis

      Cystic fibrosis is a genetic disorder that causes thickened secretions in the lungs and pancreas. It is an autosomal recessive condition that occurs due to a defect in the cystic fibrosis transmembrane conductance regulator gene (CFTR), which regulates a chloride channel. In the UK, 80% of CF cases are caused by delta F508 on chromosome 7, and the carrier rate is approximately 1 in 25.

      CF patients are at risk of colonization by certain organisms, including Staphylococcus aureus, Pseudomonas aeruginosa, Burkholderia cepacia (previously known as Pseudomonas cepacia), and Aspergillus. These organisms can cause infections and exacerbate symptoms in CF patients. It is important for healthcare providers to monitor and manage these infections to prevent further complications.

      Overall, understanding cystic fibrosis and its associated risks can help healthcare providers provide better care for patients with this condition.

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  • Question 28 - Sophie is a 15-year-old girl who has been brought to your GP clinic...

    Incorrect

    • Sophie is a 15-year-old girl who has been brought to your GP clinic by her father. She has not yet started to develop breasts or have her first period. She does not seem worried, but her father is concerned. Sophie has a history of eczema and has been using topical steroids for several years. When her father leaves the room, she also admits to occasionally using tanning beds.

      What could be a possible cause of delayed puberty in Sophie?

      Your Answer:

      Correct Answer: Cystic fibrosis

      Explanation:

      Delayed puberty can be caused by various factors, with constitutional delay being the most common cause. However, other causes must be ruled out before diagnosing constitutional delay. Some of these causes include chronic illnesses like kidney disease and Crohn’s disease, malnutrition from conditions such as anorexia nervosa, cystic fibrosis, and coeliac disease, excessive physical exercise, psychosocial deprivation, steroid therapy, hypothyroidism, tumours near the hypothalamo-pituitary axis, congenital anomalies like septo-optic dysplasia and congenital panhypopituitarism, irradiation treatment, and trauma such as surgery or head injury.

      Understanding Cystic Fibrosis: Symptoms and Other Features

      Cystic fibrosis is a genetic disorder that affects various organs in the body, particularly the lungs and digestive system. The symptoms of cystic fibrosis can vary from person to person, but some common presenting features include recurrent chest infections, malabsorption, and liver disease. In some cases, infants may experience meconium ileus or prolonged jaundice. It is important to note that while many patients are diagnosed during newborn screening or early childhood, some may not be diagnosed until adulthood.

      Aside from the presenting features, there are other symptoms and features associated with cystic fibrosis. These include short stature, diabetes mellitus, delayed puberty, rectal prolapse, nasal polyps, and infertility. It is important for individuals with cystic fibrosis to receive proper medical care and management to address these symptoms and improve their quality of life.

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  • Question 29 - A 16-year-old girl presents to the Emergency department with her mother. The mother...

    Incorrect

    • A 16-year-old girl presents to the Emergency department with her mother. The mother reports that her daughter has been experiencing worsening breathlessness and facial puffiness for the past 30 minutes. Apart from eczema, the girl has been healthy and is currently taking oral contraceptives. On examination, the girl appears to be in distress, with laboured breathing and stridor but no wheezing. What is the probable cause of her breathlessness?

      Your Answer:

      Correct Answer: Angio-oedema

      Explanation:

      Noisy Breathing and Atopy in Adolescents

      The presence of noisy breathing in an adolescent may indicate the possibility of stridor, which can be caused by an allergic reaction even in an otherwise healthy individual. The history of atopy, or a tendency to develop allergic reactions, further supports the diagnosis of angio-oedema. The sudden onset of symptoms also adds to the likelihood of this diagnosis.

      While asthma is a possible differential diagnosis, it typically presents with expiratory wheezing. However, if the chest is silent, it may indicate a severe and life-threatening form of asthma. Therefore, it is important to consider all possible causes of noisy breathing and atopy in adolescents to ensure prompt and appropriate treatment.

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  • Question 30 - A patient with a body mass index (BMI) of 40kg/m² presents to the...

    Incorrect

    • A patient with a body mass index (BMI) of 40kg/m² presents to the GP describing apnoeic episodes during sleep. He is referred to the hospital's respiratory team where he receives an initial spirometry test which is shown below.

      Forced expiratory volume in 1 sec (FEV1) 2.00 48% of predicted
      Vital capacity (VC) 2.35 43% of predicted
      Total lung capacity (TLC) 4.09 51% of predicted
      Residual volume (RV) 1.74 75% of predicted
      Total lung coefficient (TLCO) 5.37 47% of predicted
      Transfer coefficient (KCO) 1.83 120% of predicted

      What type of lung disease pattern is shown in a patient with a body mass index (BMI) of 30kg/m² who presents to the GP with similar symptoms?

      Your Answer:

      Correct Answer: Extrapulmonary

      Explanation:

      Understanding Pulmonary Function Tests

      Pulmonary function tests are a useful tool in determining whether a respiratory disease is obstructive or restrictive. These tests measure various aspects of lung function, such as forced expiratory volume in one second (FEV1) and forced vital capacity (FVC). By analyzing the results of these tests, doctors can diagnose and monitor conditions such as asthma, COPD, pulmonary fibrosis, and neuromuscular disorders.

      In obstructive lung diseases, such as asthma and COPD, the FEV1 is significantly reduced, while the FVC may be reduced or normal. The FEV1% (FEV1/FVC) is also reduced. On the other hand, in restrictive lung diseases, such as pulmonary fibrosis and asbestosis, the FEV1 is reduced, but the FVC is significantly reduced. The FEV1% (FEV1/FVC) may be normal or increased.

      It is important to note that there are many conditions that can affect lung function, and pulmonary function tests are just one tool in diagnosing and managing respiratory diseases. However, understanding the results of these tests can provide valuable information for both patients and healthcare providers.

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SESSION STATS - PERFORMANCE PER SPECIALTY

Respiratory System (2/5) 40%
Passmed