-
Question 1
Incorrect
-
A patient is evaluated in the Emergency Department after a paracetamol overdose. Why was prothrombin time chosen to evaluate liver function instead of albumin?
Your Answer: Because prothrombin binds to paracetamol in the blood
Correct Answer: Because prothrombin has a shorter half life
Explanation:Prothrombin is a more suitable indicator of acute liver failure than albumin due to its shorter half-life. In cases of acute liver failure caused by paracetamol overdose, the liver is unable to replace prothrombin, leading to a decrease in its levels. On the other hand, albumin levels remain unchanged as its half-life is relatively long. Although albumin levels may decrease with acute inflammation, this does not provide information about the patient’s liver function. Therefore, prothrombin time/INR remains the preferred diagnostic test for acute liver failure. It is important to note that prothrombin does not bind to paracetamol in the blood, and while albumin does affect oncotic pressure, this does not explain its usefulness in detecting acute liver failure.
Understanding Acute Liver Failure
Acute liver failure is a condition characterized by the sudden onset of liver dysfunction, which can lead to various complications in the body. The causes of acute liver failure include paracetamol overdose, alcohol, viral hepatitis (usually A or B), and acute fatty liver of pregnancy. The symptoms of acute liver failure include jaundice, raised prothrombin time, hypoalbuminaemia, hepatic encephalopathy, and hepatorenal syndrome. It is important to note that liver function tests may not always accurately reflect the synthetic function of the liver, and it is best to assess the prothrombin time and albumin level to determine the severity of the condition. Understanding acute liver failure is crucial in managing and treating this potentially life-threatening condition.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 2
Correct
-
A 49-year-old woman comes to the Emergency Department complaining of colicky abdominal pain. She states that she has been having on-and-off pain in the upper right quadrant for the past few months, especially after consuming fatty foods.
Which cells are accountable for generating the hormone linked to this presentation?Your Answer: I cells
Explanation:The correct answer is I cells, which are located in the upper small intestine. This patient’s symptoms are consistent with biliary colic, which occurs when the gallbladder contracts against an obstruction, typically a gallstone. Fatty foods stimulate the production of cholecystokinin (CCK) from the I cells in the duodenum, which promotes gallbladder contractility and the release of bile into the small intestine to aid in lipid emulsification.
B cells are not involved in promoting gallbladder contractility and are instead part of the adaptive immune response. D cells release somatostatin, which decreases insulin production, and are found in the stomach, small intestine, and pancreas. G cells are located in the stomach and secrete gastrin to promote acid secretion by the parietal cells of the stomach.
Overview of Gastrointestinal Hormones
Gastrointestinal hormones play a crucial role in the digestion and absorption of food. These hormones are secreted by various cells in the stomach and small intestine in response to different stimuli such as the presence of food, pH changes, and neural signals.
One of the major hormones involved in food digestion is gastrin, which is secreted by G cells in the antrum of the stomach. Gastrin increases acid secretion by gastric parietal cells, stimulates the secretion of pepsinogen and intrinsic factor, and increases gastric motility. Another hormone, cholecystokinin (CCK), is secreted by I cells in the upper small intestine in response to partially digested proteins and triglycerides. CCK increases the secretion of enzyme-rich fluid from the pancreas, contraction of the gallbladder, and relaxation of the sphincter of Oddi. It also decreases gastric emptying and induces satiety.
Secretin is another hormone secreted by S cells in the upper small intestine in response to acidic chyme and fatty acids. Secretin increases the secretion of bicarbonate-rich fluid from the pancreas and hepatic duct cells, decreases gastric acid secretion, and has a trophic effect on pancreatic acinar cells. Vasoactive intestinal peptide (VIP) is a neural hormone that stimulates secretion by the pancreas and intestines and inhibits acid secretion.
Finally, somatostatin is secreted by D cells in the pancreas and stomach in response to fat, bile salts, and glucose in the intestinal lumen. Somatostatin decreases acid and pepsin secretion, decreases gastrin secretion, decreases pancreatic enzyme secretion, and decreases insulin and glucagon secretion. It also inhibits the trophic effects of gastrin and stimulates gastric mucous production.
In summary, gastrointestinal hormones play a crucial role in regulating the digestive process and maintaining homeostasis in the gastrointestinal tract.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 3
Incorrect
-
An 80-year-old man who frequently drinks alcohol presents to his doctor with symptoms of productive cough, fever, and chills. Upon examination, a chest x-ray reveals a distinct cavity in the right lower lobe with an air-fluid level. The patient's sputum is sent for culture and sensitivity, and he is prescribed clindamycin.
After ten days, the patient reports experiencing watery diarrhea 3-4 times a day and abdominal pain. He has not experienced any fever or weight loss, and his vital signs are normal. What is the initial medication recommended for his condition?Your Answer: Ceftriaxone
Correct Answer: Vancomycin
Explanation:The preferred antibiotic for treating C. difficile infection is oral vancomycin. However, in the case of a patient with clinical features and radiological findings indicative of a lung abscess, who also has a history of alcohol consumption that increases the risk of aspiration and lung abscesses, clindamycin was used as a treatment. Unfortunately, this led to the development of a C. difficile infection, which can be confusing when considering the antibiotics involved in causing and treating the infection.
Clostridium difficile is a type of bacteria that is commonly found in hospitals. It produces a toxin that can damage the intestines and cause a condition called pseudomembranous colitis. This bacteria usually develops when the normal gut flora is disrupted by broad-spectrum antibiotics, with second and third generation cephalosporins being the leading cause. Other risk factors include the use of proton pump inhibitors. Symptoms of C. difficile infection include diarrhea, abdominal pain, and a raised white blood cell count. The severity of the infection can be determined using the Public Health England severity scale.
To diagnose C. difficile infection, a stool sample is tested for the presence of the C. difficile toxin. Treatment involves reviewing current antibiotic therapy and stopping antibiotics if possible. For a first episode of infection, oral vancomycin is the first-line therapy for 10 days, followed by oral fidaxomicin as second-line therapy and oral vancomycin with or without IV metronidazole as third-line therapy. Recurrent infections may require different treatment options, such as oral fidaxomicin within 12 weeks of symptom resolution or oral vancomycin or fidaxomicin after 12 weeks of symptom resolution. In life-threatening cases, oral vancomycin and IV metronidazole may be used, and surgery may be considered with specialist advice. Other therapies, such as bezlotoxumab and fecal microbiota transplant, may also be considered for preventing recurrences in certain cases.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 4
Correct
-
A 35-year-old woman arrives at the Emergency Department with a sudden onset of painless left-sided facial weakness, along with difficulty speaking and a drooping mouth. She expresses concern about having a stroke, but her medical history is unremarkable. Upon further examination, you rule out a stroke and suspect that she may be experiencing Bell's palsy, an unexplained paralysis of the facial nerve.
What signs would you anticipate discovering during the examination?Your Answer: Taste impairment of the anterior tongue
Explanation:The facial nerve’s chorda tympani branch is responsible for providing taste sensation to the anterior two-thirds of the tongue. Bell’s palsy is a condition characterized by unilateral facial nerve weakness or paralysis, which can result in impaired taste sensation in the anterior tongue.
Upper motor neuron lesions typically spare the forehead, as alternative nerve routes can still provide innervation. In contrast, lower motor neuron lesions like Bell’s palsy can cause forehead paralysis.
While ptosis may occur in Bell’s palsy, it typically presents unilaterally rather than bilaterally.
Although patients with Bell’s palsy may complain of tearing eyes, tear production is actually decreased due to loss of control of the eyelids and facial muscles.
The facial nerve controls the motor aspect of the corneal reflex, so an abnormal corneal reflex may be observed in Bell’s palsy.
Nerve Supply of the Tongue
The tongue is a complex organ that plays a crucial role in speech and taste. It is innervated by three different cranial nerves, each responsible for different functions. The anterior two-thirds of the tongue receive general sensation from the lingual branch of the mandibular division of the trigeminal nerve (CN V3) and taste sensation from the chorda tympani branch of the facial nerve (CN VII). On the other hand, the posterior one-third of the tongue receives both general sensation and taste sensation from the glossopharyngeal nerve (CN IX).
In terms of motor function, the hypoglossal nerve (CN XII) is responsible for controlling the movements of the tongue. It is important to note that the tongue’s nerve supply is essential for proper functioning, and any damage to these nerves can result in speech and taste disorders.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 5
Correct
-
A 14-year-old boy is brought to the hospital due to severe nausea and vomiting. He has been unable to eat or drink for the past 48 hours and has not urinated in the last 24 hours. The doctor prescribes an antiemetic, but which antiemetic should be avoided in this situation?
Your Answer: Metoclopramide
Explanation:The effectiveness of antiemetics depends on their ability to interact with different receptors. Therefore, the selection of an appropriate antiemetic will depend on the patient and the underlying cause of nausea.
Metoclopramide is a dopamine antagonist that also has peripheral 5HT3 agonist and muscarinic antagonist effects, which help to promote gastric emptying. However, it is not recommended for use in children and young adults due to the potential risk of oculogyric crisis.
Understanding the Mechanism and Uses of Metoclopramide
Metoclopramide is a medication primarily used to manage nausea, but it also has other uses such as treating gastro-oesophageal reflux disease and gastroparesis secondary to diabetic neuropathy. It is often combined with analgesics for the treatment of migraines. However, it is important to note that metoclopramide has adverse effects such as extrapyramidal effects, acute dystonia, diarrhoea, hyperprolactinaemia, tardive dyskinesia, and parkinsonism. It should also be avoided in bowel obstruction but may be helpful in paralytic ileus.
The mechanism of action of metoclopramide is quite complicated. It is primarily a D2 receptor antagonist, but it also has mixed 5-HT3 receptor antagonist/5-HT4 receptor agonist activity. Its antiemetic action is due to its antagonist activity at D2 receptors in the chemoreceptor trigger zone, and at higher doses, the 5-HT3 receptor antagonist also has an effect. The gastroprokinetic activity is mediated by D2 receptor antagonist activity and 5-HT4 receptor agonist activity.
In summary, metoclopramide is a medication with multiple uses, but it also has adverse effects that should be considered. Its mechanism of action is complex, involving both D2 receptor antagonist and 5-HT3 receptor antagonist/5-HT4 receptor agonist activity. Understanding the uses and mechanism of action of metoclopramide is important for its safe and effective use.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 6
Correct
-
A 36-year-old female patient presents with persistent dyspepsia of 6 months duration. She failed multiple trials of conservative treatment by her GP, therefore, she was referred for the gastroenterologist for further review.
Investigations were done and her urea breath test was negative for Helicobacter pylori. Gastroscopy revealed multiple gastroduodenal ulcers. What type of cells are affected by the high levels of fasting gastrin detected?Your Answer: Gastric parietal cells
Explanation:The secretion of gastrin hormone from G cells in the antrum of the stomach is responsible for increasing the secretion of H+ by gastric parietal cells. Additionally, chief cells secrete pepsin, which is a proteolytic enzyme, while D cells in the pancreas and stomach secrete somatostatin hormone. Gastrin hormone is released in response to distension of the stomach and vagal stimulation.
Overview of Gastrointestinal Hormones
Gastrointestinal hormones play a crucial role in the digestion and absorption of food. These hormones are secreted by various cells in the stomach and small intestine in response to different stimuli such as the presence of food, pH changes, and neural signals.
One of the major hormones involved in food digestion is gastrin, which is secreted by G cells in the antrum of the stomach. Gastrin increases acid secretion by gastric parietal cells, stimulates the secretion of pepsinogen and intrinsic factor, and increases gastric motility. Another hormone, cholecystokinin (CCK), is secreted by I cells in the upper small intestine in response to partially digested proteins and triglycerides. CCK increases the secretion of enzyme-rich fluid from the pancreas, contraction of the gallbladder, and relaxation of the sphincter of Oddi. It also decreases gastric emptying and induces satiety.
Secretin is another hormone secreted by S cells in the upper small intestine in response to acidic chyme and fatty acids. Secretin increases the secretion of bicarbonate-rich fluid from the pancreas and hepatic duct cells, decreases gastric acid secretion, and has a trophic effect on pancreatic acinar cells. Vasoactive intestinal peptide (VIP) is a neural hormone that stimulates secretion by the pancreas and intestines and inhibits acid secretion.
Finally, somatostatin is secreted by D cells in the pancreas and stomach in response to fat, bile salts, and glucose in the intestinal lumen. Somatostatin decreases acid and pepsin secretion, decreases gastrin secretion, decreases pancreatic enzyme secretion, and decreases insulin and glucagon secretion. It also inhibits the trophic effects of gastrin and stimulates gastric mucous production.
In summary, gastrointestinal hormones play a crucial role in regulating the digestive process and maintaining homeostasis in the gastrointestinal tract.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 7
Correct
-
A 16-year-old presents to the Emergency Department with her father, who has noticed a yellowish tint to her eyes. Upon further inquiry, she reports having a flu-like illness a few days ago, which has since resolved. She has no medical history and is not taking any medications. On examination, scleral icterus is the only significant finding. The following are her blood test results:
Hb 130 g/L Male: (135-180) Female: (115 - 160)
Platelets 320 * 109/L (150 - 400)
WBC 6.0 * 109/L (4.0 - 11.0)
Bilirubin 80 µmol/L (3 - 17)
ALP 42 u/L (30 - 100)
ALT 30 u/L (3 - 40)
γGT 50 u/L (8 - 60)
Albumin 45 g/L (35 - 50)
What is the most probable cause of her symptoms?Your Answer: Gilbert's syndrome
Explanation:Gilbert’s syndrome is characterized by an inherited deficiency of an enzyme used to conjugate bilirubin, resulting in elevated levels of unconjugated bilirubin in the blood. This can lead to isolated jaundice of the sclera or mouth during times of physiological stress.
Crigler Najjar syndrome, on the other hand, is a rare genetic disorder that causes an inability to convert and clear bilirubin from the body, resulting in jaundice shortly after birth.
Gallstones, which can be asymptomatic or present with right upper quadrant pain following a meal, are associated with risk factors such as being overweight, over 40 years old, female, or fertile.
Primary sclerosing cholangitis (PSC) is characterized by scarring and fibrosis of the bile ducts inside and outside the liver, and may occur alone or in combination with inflammatory diseases such as ulcerative colitis. Symptoms of PSC include jaundice, right upper quadrant pain, itching, fatigue, and weight loss.
Gilbert’s syndrome is a genetic disorder that affects the way bilirubin is processed in the body. It is caused by a deficiency of UDP glucuronosyltransferase, which leads to unconjugated hyperbilirubinemia. This means that bilirubin is not properly broken down and eliminated from the body, resulting in jaundice. However, jaundice may only be visible during certain conditions such as fasting, exercise, or illness. The prevalence of Gilbert’s syndrome is around 1-2% in the general population.
To diagnose Gilbert’s syndrome, doctors may look for a rise in bilirubin levels after prolonged fasting or the administration of IV nicotinic acid. However, treatment is not necessary for this condition. While the exact mode of inheritance is still debated, it is known to be an autosomal recessive disorder.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 8
Correct
-
A 32-year-old man has come in for a follow-up appointment after being diagnosed with irritable bowel syndrome. However, his faecal calprotectin was slightly elevated, but not high enough to raise suspicion of inflammatory bowel disease.
He had initially presented with abdominal pain and diarrhoea, along with feelings of discomfort and bloating that were relieved upon defecation. He denied any presence of blood in his stool. You prescribed psyllium husk and scheduled a review in four weeks. He has a medical history of low back pain, migraine, and depression.
Today, his faecal calprotectin has returned to normal levels. What is the most likely cause of the initial abnormal test result?Your Answer: Use of NSAIDs
Explanation:Mallory-Weiss syndrome (MWS) is characterized by a rupture in the mucous membrane at the junction of the stomach and oesophagus.
Faecal Calprotectin: A Screening Tool for Intestinal Inflammation
Faecal calprotectin is a recommended screening tool for inflammatory bowel disease (IBD) by NICE. It is a test that detects intestinal inflammation and can also be used to monitor the response to treatment in IBD patients. The test has a high sensitivity of 93% and specificity of 96% for IBD in adults. However, in children, the specificity falls to around 75%.
Apart from IBD, other conditions that can cause a raised faecal calprotectin include bowel malignancy, coeliac disease, infectious colitis, and the use of NSAIDs. Therefore, faecal calprotectin is a useful diagnostic tool for detecting intestinal inflammation and can aid in the diagnosis and management of various gastrointestinal conditions.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 9
Incorrect
-
A 25-year-old male presents to the emergency department with upper abdominal pain that radiates to the back. This started a few hours previously and has been accompanied by some nausea and vomiting. The patient denies any alcohol intake recently.
On examination, he has tenderness in the epigastric and right upper quadrant regions. He has a fever of 38.9°C. An ultrasound scan reveals no evidence of gallstones. The patient is given a preliminary diagnosis of acute pancreatitis and some blood tests are requested.
What could be the cause of this patient's condition?Your Answer: Peptic ulcer disease
Correct Answer: Mumps
Explanation:Mumps is a known cause of acute pancreatitis, but it has become rare since the introduction of the MMR vaccine. In 2018, there were only 1088 cases of mumps in the UK, which statistically translates to around 54 cases of acute pancreatitis secondary to mumps. Inflammatory bowel disease may also lead to pancreatitis, but it is usually caused by gallstones or medication used to treat IBD. While influenzae and gastroenteritis are not commonly associated with pancreatitis, there have been a few reported cases linking influenzae A to acute pancreatitis, although these occurrences are extremely rare.
Acute pancreatitis is a condition that is primarily caused by gallstones and alcohol consumption in the UK. However, there are other factors that can contribute to the development of this condition. A popular mnemonic used to remember these factors is GET SMASHED, which stands for gallstones, ethanol, trauma, steroids, mumps, autoimmune diseases, scorpion venom, hypertriglyceridaemia, hyperchylomicronaemia, hypercalcaemia, hypothermia, ERCP, and certain drugs. It is important to note that pancreatitis is seven times more common in patients taking mesalazine than sulfasalazine. CT scans can show diffuse parenchymal enlargement with oedema and indistinct margins in patients with acute pancreatitis.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 10
Correct
-
A 75-year-old man has been experiencing abdominal discomfort and distension for the past two days. He has not had a bowel movement in a week and has not passed gas in two days. He seems sluggish and has a temperature of 35.5°C. His pulse is 56 BPM, and his abdomen is not tender. An X-ray of his abdomen reveals enlarged loops of both small and large bowel. What is the most probable diagnosis?
Your Answer: Pseudo-obstruction
Explanation:Pseudo-Obstruction and its Causes
Pseudo-obstruction is a condition that can be caused by various factors, including hypothyroidism, hypokalaemia, diabetes, uraemia, and hypocalcaemia. In the case of hypothyroidism, the slowness and hypothermia of the patient suggest that this may be the underlying cause of the pseudo-obstruction. However, other factors should also be considered.
It is important to note that pseudo-obstruction is a condition that affects the digestive system, specifically the intestines. It is characterized by symptoms that mimic those of a bowel obstruction, such as abdominal pain, bloating, and constipation. However, unlike a true bowel obstruction, there is no physical blockage in the intestines.
To diagnose pseudo-obstruction, doctors may perform various tests, including X-rays, CT scans, and blood tests. Treatment options may include medications to stimulate the intestines, changes in diet, and surgery in severe cases.
Overall, it is important to identify the underlying cause of pseudo-obstruction in order to provide appropriate treatment and management of the condition.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 11
Incorrect
-
A 68-year-old woman presents to the respiratory clinic for a follow-up of her COPD. She informs the healthcare provider that she has quit smoking, resulting in fewer COPD exacerbations, none of which required hospitalization. However, she has observed a slight increase in her weight and swelling in her ankles.
During the physical examination, the patient's weight is noted to be 76kg, up from her previous weight of 72kg. The healthcare provider listens to her heart and lungs and detects normal breath and heart sounds. The patient has bilateral edema that extends up to her mid-calves.
What other examination findings may be evident, given the probable diagnosis?Your Answer: Palpable thrill
Correct Answer: Smooth hepatomegaly
Explanation:The patient’s symptoms suggest that they have developed cor pulmonale due to COPD, resulting in right-sided heart failure. On examination, signs of fluid congestion such as peripheral edema, raised jugular venous pressure (JVP), ascites, and hepatomegaly may be present. Therefore, the most likely finding would be an enlarged liver with a firm, smooth, tender, and pulsatile edge.
Caput medusae, which refers to the swelling of superficial veins in the epigastric area, is unlikely to occur in a new presentation of cor pulmonale.
Narrow pulse pressure is a characteristic of aortic stenosis, which causes left ventricular dysfunction. However, this patient only shows signs of right-sided heart failure.
A palpable thrill, which indicates turbulent flow across a heart valve, may be felt in severe valvular disease that causes left ventricular dysfunction. Murmurs are often present in valvular disease, but not in this patient’s case.
Reverse splitting of the second heart sound may occur in aortic stenosis or left bundle branch block, which can cause left ventricular dysfunction.
Understanding Hepatomegaly and Its Common Causes
Hepatomegaly refers to an enlarged liver, which can be caused by various factors. One of the most common causes is cirrhosis, which can lead to a decrease in liver size in later stages. In this case, the liver is non-tender and firm. Malignancy, such as metastatic spread or primary hepatoma, can also cause hepatomegaly. In this case, the liver edge is hard and irregular. Right heart failure can also lead to an enlarged liver, which is firm, smooth, and tender. It may even be pulsatile.
Aside from these common causes, hepatomegaly can also be caused by viral hepatitis, glandular fever, malaria, abscess (pyogenic or amoebic), hydatid disease, haematological malignancies, haemochromatosis, primary biliary cirrhosis, sarcoidosis, and amyloidosis.
Understanding the causes of hepatomegaly is important in diagnosing and treating the underlying condition. Proper diagnosis and treatment can help prevent further complications and improve overall health.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 12
Incorrect
-
A 33-year-old woman presents to the emergency department with acute illness. Her vital signs are as follows.
Heart rate 96 BPM (60-80)
Respiratory rate 30 per minute (12-20)
Temperature 39.2 ºC (35.5-37.5)
Blood pressure 112/84 mmHg (100-140/60-90)
An infection is suspected, but the source is unknown. Further investigation with a CT scan of the chest and abdomen reveals a retroperitoneal collection, likely caused by leakage from a damaged retroperitoneal structure.
Which of the following structures is most likely affected?Your Answer: First part of the duodenum
Correct Answer: Ureter
Explanation:The ureters are located in the retroperitoneal space and damage to them can result in the accumulation of fluid in this area. This retroperitoneal collection may be caused by leaked fluid from the damaged ureter. It is important to note that the ureter is the only retroperitoneal structure among the provided options, making it the most likely cause of the fluid accumulation in this patient.
To remember the retroperitoneal structures, a helpful mnemonic is SAD PUCKER, which stands for Suprarenal (adrenal) glands, Aorta/inferior vena cava, Duodenum (2nd and 3rd parts), Pancreas (except tail), Ureters, Colon (ascending and descending), Kidneys, Esophagus, and Rectum.
The retroperitoneal structures are those that are located behind the peritoneum, which is the membrane that lines the abdominal cavity. These structures include the duodenum (2nd, 3rd, and 4th parts), ascending and descending colon, kidneys, ureters, aorta, and inferior vena cava. They are situated in the back of the abdominal cavity, close to the spine. In contrast, intraperitoneal structures are those that are located within the peritoneal cavity, such as the stomach, duodenum (1st part), jejunum, ileum, transverse colon, and sigmoid colon. It is important to note that the retroperitoneal structures are not well demonstrated in the diagram as the posterior aspect has been removed, but they are still significant in terms of their location and function.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 13
Incorrect
-
A 67-year-old woman visits her GP after discovering a lump in her groin subsequent to relocating. The patient reports that she can push the lump back in, but it returns when she coughs. During the examination, the GP identifies the lump located superior and medial to the pubic tubercle. The GP reduces the lump, applies pressure to the midpoint of the inguinal ligament, and instructs the patient to cough. The lump reappears, leading the GP to tentatively diagnose the patient with a direct inguinal hernia. Through which anatomical structures will the hernia pass?
Your Answer: Deep inguinal ring and superficial inguinal ring
Correct Answer: Transversalis fascia and superficial inguinal ring
Explanation:The correct structures for a direct inguinal hernia to pass through are the transversalis fascia (which forms the posterior wall of the inguinal canal) and the superficial ring. If the hernia were to pass through other structures, such as the deep inguinal ring, it would reappear upon increased intra-abdominal pressure. In contrast, an indirect inguinal hernia enters the canal through the deep inguinal ring and exits at the superficial ring, so it would not reappear if the deep inguinal ring were blocked.
The inguinal canal is located above the inguinal ligament and measures 4 cm in length. Its superficial ring is situated in front of the pubic tubercle, while the deep ring is found about 1.5-2 cm above the halfway point between the anterior superior iliac spine and the pubic tubercle. The canal is bounded by the external oblique aponeurosis, inguinal ligament, lacunar ligament, internal oblique, transversus abdominis, external ring, and conjoint tendon. In males, the canal contains the spermatic cord and ilioinguinal nerve, while in females, it houses the round ligament of the uterus and ilioinguinal nerve.
The boundaries of Hesselbach’s triangle, which are frequently tested, are located in the inguinal region. Additionally, the inguinal canal is closely related to the vessels of the lower limb, which should be taken into account when repairing hernial defects in this area.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 14
Incorrect
-
A 50-year-old man presents with brisk haematemesis and is taken to the endoscopy department for an upper GI endoscopy. The gastroenterologist identifies an ulcer on the posterior duodenal wall and attempts to control the bleeding with various haemostatic techniques. After an unsuccessful attempt, the surgeon is called for assistance. During the laparotomy and anterior duodenotomy, a vessel is found spurting blood into the duodenal lumen. What is the origin of this vessel?
Your Answer: Splenic artery
Correct Answer: Common hepatic artery
Explanation:The gastroduodenal artery originates from the common hepatic artery.
The Gastroduodenal Artery: Supply and Path
The gastroduodenal artery is responsible for supplying blood to the pylorus, proximal part of the duodenum, and indirectly to the pancreatic head through the anterior and posterior superior pancreaticoduodenal arteries. It commonly arises from the common hepatic artery of the coeliac trunk and terminates by bifurcating into the right gastroepiploic artery and the superior pancreaticoduodenal artery.
To better understand the relationship of the gastroduodenal artery to the first part of the duodenum, the stomach is reflected superiorly in an image sourced from Wikipedia. This artery plays a crucial role in providing oxygenated blood to the digestive system, ensuring proper functioning and health.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 15
Incorrect
-
A 65-year-old man comes to the clinic with a left groin swelling that is identified as a direct inguinal hernia. Can you indicate the position of the ilioinguinal nerve in relation to the spermatic cord within the inguinal canal?
Your Answer: Lateral to the spermatic cord
Correct Answer: Anterior to the spermatic cord
Explanation:The inguinal canal is a crucial anatomical feature that houses the spermatic cord in males, while the ilioinguinal nerve runs in front of it. Both the ilioinguinal and iliohypogastric nerves stem from the L1 nerve root. Unlike the deep (internal) inguinal ring, the ilioinguinal nerve enters the inguinal canal through the abdominal muscles and exits through the superficial (external) inguinal ring.
The inguinal canal is located above the inguinal ligament and measures 4 cm in length. Its superficial ring is situated in front of the pubic tubercle, while the deep ring is found about 1.5-2 cm above the halfway point between the anterior superior iliac spine and the pubic tubercle. The canal is bounded by the external oblique aponeurosis, inguinal ligament, lacunar ligament, internal oblique, transversus abdominis, external ring, and conjoint tendon. In males, the canal contains the spermatic cord and ilioinguinal nerve, while in females, it houses the round ligament of the uterus and ilioinguinal nerve.
The boundaries of Hesselbach’s triangle, which are frequently tested, are located in the inguinal region. Additionally, the inguinal canal is closely related to the vessels of the lower limb, which should be taken into account when repairing hernial defects in this area.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 16
Correct
-
A 65-year-old woman visits her GP complaining of altered bowel habit for the past 2 months. She denies experiencing melaena or fresh rectal blood. The patient has a medical history of type 2 diabetes mellitus and breast cancer, which has been in remission for 2 years. She consumes 14 units of alcohol per week.
During abdominal palpation, the liver edge is palpable and nodular, descending below the right costal margin. There is no presence of shifting dullness.
What is the probable cause of the patient's examination findings?Your Answer: Liver metastases
Explanation:If a patient has hepatomegaly and a history of malignancy, it is likely that they have liver metastases. The nodular edge of the liver, along with the patient’s history of breast cancer, is a cause for concern regarding cancer recurrence. Acute alcoholic hepatitis, Budd-Chiari syndrome, and non-alcoholic steatohepatitis are less likely causes in this scenario.
Understanding Hepatomegaly and Its Common Causes
Hepatomegaly refers to an enlarged liver, which can be caused by various factors. One of the most common causes is cirrhosis, which can lead to a decrease in liver size in later stages. In this case, the liver is non-tender and firm. Malignancy, such as metastatic spread or primary hepatoma, can also cause hepatomegaly. In this case, the liver edge is hard and irregular. Right heart failure can also lead to an enlarged liver, which is firm, smooth, and tender. It may even be pulsatile.
Aside from these common causes, hepatomegaly can also be caused by viral hepatitis, glandular fever, malaria, abscess (pyogenic or amoebic), hydatid disease, haematological malignancies, haemochromatosis, primary biliary cirrhosis, sarcoidosis, and amyloidosis.
Understanding the causes of hepatomegaly is important in diagnosing and treating the underlying condition. Proper diagnosis and treatment can help prevent further complications and improve overall health.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 17
Correct
-
A 67-year-old man comes to the emergency department complaining of abrupt abdominal pain. He reports the pain as cramping, with a severity of 6/10, and spread throughout his abdomen. The patient has a medical history of hypertension and type 2 diabetes mellitus. He used to smoke and has a smoking history of 40 pack years.
What is the most probable part of the colon affected in this patient?Your Answer: Splenic flexure
Explanation:Ischaemic colitis frequently affects the splenic flexure, which is a vulnerable area due to its location at the border of regions supplied by different arteries. Symptoms such as cramping and generalised abdominal pain, along with a history of smoking and hypertension, suggest a diagnosis of ischaemic colitis. While the rectosigmoid junction is also a watershed area, it is less commonly affected than the splenic flexure. Other regions of the large bowel are less susceptible to ischaemic colitis.
Understanding Ischaemic Colitis
Ischaemic colitis is a condition that occurs when there is a temporary reduction in blood flow to the large bowel. This can cause inflammation, ulcers, and bleeding. The condition is more likely to occur in areas of the bowel that are located at the borders of the territory supplied by the superior and inferior mesenteric arteries, such as the splenic flexure.
When investigating ischaemic colitis, doctors may look for a sign called thumbprinting on an abdominal x-ray. This occurs due to mucosal edema and hemorrhage. It is important to diagnose and treat ischaemic colitis promptly to prevent complications and ensure a full recovery.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 18
Incorrect
-
A 67-year-old male is receiving treatment for his colorectal cancer from the oncology team at his nearby hospital. What type of colorectal carcinoma is most frequently encountered?
Your Answer: Squamous cell carcinoma
Correct Answer: Adenocarcinoma
Explanation:The most common type of colorectal cancer is adenocarcinoma, which originates from the mucosal lining of the colon. Initially, it develops as a benign adenoma from glandular cells of the mucosa, which later transforms into a malignant form.
Squamous cell carcinoma arises from squamous cells, which are not present in the colon. Ductal carcinoma is a breast cancer that originates from ductal cells. Basal cell carcinoma is a type of skin cancer, while mesothelioma is a malignancy that affects the mesothelium, commonly found in the lining of the chest wall.
Colorectal cancer is a prevalent type of cancer in the UK, ranking third in terms of frequency and second in terms of cancer-related deaths. Every year, approximately 150,000 new cases are diagnosed, and 50,000 people die from the disease. The cancer can occur in different parts of the colon, with the rectum being the most common location, accounting for 40% of cases. The sigmoid colon follows closely, with 30% of cases, while the descending colon has only 5%. The transverse colon has 10% of cases, and the ascending colon and caecum have 15%.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 19
Correct
-
A 50-year-old male has been diagnosed with carcinoma of the head of the pancreas. He has reported that his stool is sticking to the toilet bowl and not flushing away. Which enzyme deficiency is most likely causing this issue?
Your Answer: Lipase
Explanation:Steatorrhoea, characterized by pale and malodorous stools that are hard to flush, is primarily caused by a deficiency in lipase.
Pancreatic cancer is a type of cancer that is often diagnosed late due to its non-specific symptoms. The majority of pancreatic tumors are adenocarcinomas and are typically found in the head of the pancreas. Risk factors for pancreatic cancer include increasing age, smoking, diabetes, chronic pancreatitis, hereditary non-polyposis colorectal carcinoma, and mutations in the BRCA2 and KRAS genes.
Symptoms of pancreatic cancer can include painless jaundice, pale stools, dark urine, and pruritus. Courvoisier’s law states that a palpable gallbladder is unlikely to be due to gallstones in the presence of painless obstructive jaundice. However, patients often present with non-specific symptoms such as anorexia, weight loss, and epigastric pain. Loss of exocrine and endocrine function can also occur, leading to steatorrhea and diabetes mellitus. Atypical back pain and migratory thrombophlebitis (Trousseau sign) are also common.
Ultrasound has a sensitivity of around 60-90% for detecting pancreatic cancer, but high-resolution CT scanning is the preferred diagnostic tool. The ‘double duct’ sign, which is the simultaneous dilatation of the common bile and pancreatic ducts, may be seen on imaging.
Less than 20% of patients with pancreatic cancer are suitable for surgery at the time of diagnosis. A Whipple’s resection (pancreaticoduodenectomy) may be performed for resectable lesions in the head of the pancreas, but side-effects such as dumping syndrome and peptic ulcer disease can occur. Adjuvant chemotherapy is typically given following surgery, and ERCP with stenting may be used for palliation.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 20
Correct
-
An 80-year-old man visits his GP complaining of indigestion that has persisted for the last three months. He has a medical history of hypertension and is a heavy smoker with a 50-pack-year history. He also consumes three glasses of wine on weeknights. Upon referral to a gastroenterologist, a lower oesophageal and stomach biopsy is performed, revealing metaplastic columnar epithelium. What is the primary factor that has contributed to the development of this histological finding?
Your Answer: Gastro-oesophageal reflux disease (GORD)
Explanation:Barrett’s oesophagus is diagnosed in this patient based on the presence of metaplastic columnar epithelium in the oesophageal epithelium. The most significant risk factor for the development of Barrett’s oesophagus is gastro-oesophageal reflux disease (GORD). While age is also a risk factor, it is not as strong as GORD. Alcohol consumption is not associated with Barrett’s oesophagus, but it is a risk factor for squamous cell oesophageal carcinoma. Infection with Helicobacter pylori is not linked to Barrett’s oesophagus, and it may even reduce the risk of GORD and Barrett’s oesophagus. Smoking is associated with both GORD and Barrett’s oesophagus, but the strength of this association is not as significant as that of GORD.
Barrett’s oesophagus is a condition where the lower oesophageal mucosa is replaced by columnar epithelium, which increases the risk of oesophageal adenocarcinoma by 50-100 fold. It is usually identified during an endoscopy for upper gastrointestinal symptoms such as dyspepsia, as there are no screening programs for it. The length of the affected segment determines the chances of identifying metaplasia, with short (<3 cm) and long (>3 cm) subtypes. The prevalence of Barrett’s oesophagus is estimated to be around 1 in 20, and it is identified in up to 12% of those undergoing endoscopy for reflux.
The columnar epithelium in Barrett’s oesophagus may resemble that of the cardiac region of the stomach or that of the small intestine, with goblet cells and brush border. The single strongest risk factor for Barrett’s oesophagus is gastro-oesophageal reflux disease (GORD), followed by male gender, smoking, and central obesity. Alcohol is not an independent risk factor for Barrett’s, but it is associated with both GORD and oesophageal cancer. Patients with Barrett’s oesophagus often have coexistent GORD symptoms.
The management of Barrett’s oesophagus involves high-dose proton pump inhibitor, although the evidence base for its effectiveness in reducing the progression to dysplasia or inducing regression of the lesion is limited. Endoscopic surveillance with biopsies is recommended every 3-5 years for patients with metaplasia but not dysplasia. If dysplasia of any grade is identified, endoscopic intervention is offered, such as radiofrequency ablation, which is the preferred first-line treatment, particularly for low-grade dysplasia, or endoscopic mucosal resection.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 21
Incorrect
-
Sarah is a 65-year-old patient with decompensated liver cirrhosis. Two years ago she had variceal bleed, for which she has been taking propranolol and received endoscopic variceal ligation. Sarah presents to the emergency department with haematemesis and a recurrent oesophageal variceal bleed is suspected.
What emergency surgery is necessary in this case?Your Answer: Oesophagectomy
Correct Answer: Transjugular intrahepatic portosystemic shunt (TIPS) procedure
Explanation:To address recurrent variceal haemorrhage despite optimal medical therapy, a TIPS procedure may be performed. This involves linking the hepatic vein to the portal vein, which helps to alleviate the complications associated with portal hypertension.
Variceal haemorrhage is a serious condition that requires prompt and effective management. The initial treatment involves resuscitation of the patient, correction of clotting abnormalities, and administration of vasoactive agents such as terlipressin or octreotide. Prophylactic IV antibiotics are also recommended to reduce mortality in patients with liver cirrhosis. Endoscopic variceal band ligation is the preferred method for controlling bleeding, and the use of a Sengstaken-Blakemore tube or Transjugular Intrahepatic Portosystemic Shunt (TIPSS) may be necessary if bleeding cannot be controlled. However, TIPSS can lead to exacerbation of hepatic encephalopathy, which is a common complication.
To prevent variceal haemorrhage, prophylactic measures such as propranolol and endoscopic variceal band ligation (EVL) are recommended. Propranolol has been shown to reduce rebleeding and mortality compared to placebo. EVL is superior to endoscopic sclerotherapy and should be performed at two-weekly intervals until all varices have been eradicated. Proton pump inhibitor cover is given to prevent EVL-induced ulceration. NICE guidelines recommend offering endoscopic variceal band ligation for the primary prevention of bleeding for people with cirrhosis who have medium to large oesophageal varices.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 22
Incorrect
-
A 40-year-old female comes to the clinic complaining of difficulty swallowing both solid and liquid foods for the past 3 months. She denies any hoarseness of voice but reports having had pneumonia a month ago, which resolved with antibiotics. Upon examination, oesophageal manometry reveals absent peristalsis, increased lower sphincter tone, and incomplete relaxation of the lower sphincter during swallowing.
What is the most probable diagnosis for this patient?Your Answer: Oesophageal carcinoma
Correct Answer: Achalasia
Explanation:The classic triad for achalasia includes loss of peristalsis, increased lower sphincter tone, and inadequate relaxation of the lower sphincter, which is evident on manometry. Dysphagia for both solid and liquid is also a common symptom of achalasia.
Unlike achalasia, Barrett’s esophagus does not show any changes on manometry. However, it can be identified through the presence of intestinal metaplasia on endoscopy.
Diffuse esophageal spasm is a motility disorder that does not affect lower esophageal sphincter pressure and relaxation during swallowing. Instead, manometry reveals repetitive high amplitude contractions.
Hiatus hernia is typically associated with gastroesophageal reflux disease and does not show any abnormal findings on manometry.
Understanding Dysphagia and its Causes
Dysphagia, or difficulty in swallowing, can be caused by various conditions affecting the oesophagus, including cancer, oesophagitis, candidiasis, achalasia, pharyngeal pouch, systemic sclerosis, myasthenia gravis, and globus hystericus. These conditions have distinct features that can help in their diagnosis, such as weight loss and anorexia in oesophageal cancer, heartburn in oesophagitis, dysphagia of both liquids and solids in achalasia, and anxiety in globus hystericus. Dysphagia can also be classified as extrinsic, intrinsic, or neurological, depending on the underlying cause.
To diagnose dysphagia, patients usually undergo an upper GI endoscopy, a full blood count, and fluoroscopic swallowing studies. Additional tests, such as ambulatory oesophageal pH and manometry studies, may be needed for specific conditions. It’s important to note that new-onset dysphagia is a red flag symptom that requires urgent endoscopy, regardless of age or other symptoms. By understanding the causes and features of dysphagia, healthcare professionals can provide timely and appropriate management for their patients.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 23
Incorrect
-
A 48-year-old woman complains of fatigue. She has experienced occasional bouts of diarrhea for several years and has recurrent abdominal pain and bloating.
During the abdominal examination, no abnormalities were found, but a blood test revealed anemia due to folate deficiency. The patient tested positive for immunoglobulin A-tissue transglutaminase (IgA-tTG), and an intestinal biopsy showed villous atrophy.
Which serotype is most strongly linked to this condition?Your Answer: HLA-DR4
Correct Answer: HLA-DQ2
Explanation:The incorrect HLA serotypes are HLA-A3, HLA-B27, and HLA-B51. HLA-A3 is associated with haemochromatosis, which can be asymptomatic in early stages and present with non-specific symptoms such as lethargy and arthralgia. HLA-B27 is associated with ankylosing spondylitis, reactive arthritis, and anterior uveitis. Ankylosing spondylitis presents with lower back pain and stiffness that worsens in the morning and improves with exercise. Reactive arthritis is characterized by arthritis following an infection, along with possible symptoms of urethritis and conjunctivitis. Anterior uveitis is inflammation of the iris and ciliary body and is a differential diagnosis for red eye. HLA-B51 is associated with Behçet’s disease, which involves oral and genital ulcers and anterior uveitis.
Understanding Coeliac Disease
Coeliac disease is an autoimmune disorder that affects approximately 1% of the UK population. It is caused by sensitivity to gluten, a protein found in wheat, barley, and rye. Repeated exposure to gluten leads to villous atrophy, which causes malabsorption. Coeliac disease is associated with various conditions, including dermatitis herpetiformis and autoimmune disorders such as type 1 diabetes mellitus and autoimmune hepatitis. It is strongly linked to HLA-DQ2 and HLA-DQ8.
To diagnose coeliac disease, NICE recommends screening patients who exhibit signs and symptoms such as chronic or intermittent diarrhea, failure to thrive or faltering growth in children, persistent or unexplained gastrointestinal symptoms, prolonged fatigue, recurrent abdominal pain, sudden or unexpected weight loss, unexplained anemia, autoimmune thyroid disease, dermatitis herpetiformis, irritable bowel syndrome, type 1 diabetes, and first-degree relatives with coeliac disease.
Complications of coeliac disease include anemia, hyposplenism, osteoporosis, osteomalacia, lactose intolerance, enteropathy-associated T-cell lymphoma of the small intestine, subfertility, and unfavorable pregnancy outcomes. In rare cases, it can lead to esophageal cancer and other malignancies.
The diagnosis of coeliac disease is confirmed through a duodenal biopsy, which shows complete atrophy of the villi with flat mucosa and marked crypt hyperplasia, intraepithelial lymphocytosis, and dense mixed inflammatory infiltrate in the lamina propria. Treatment involves a lifelong gluten-free diet.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 24
Correct
-
A 65-year-old man comes to the emergency department with a significant swelling in his abdomen. He confesses to consuming more alcohol since losing his job five years ago, but he has no other significant medical history.
During the examination, the doctor observes shifting dullness. To confirm the suspicion of portal hypertension, the doctor orders liver function tests and an ascitic tap (paracentesis).
What result from the tests would provide the strongest indication of portal hypertension?Your Answer: Serum-ascites albumin gradient (SAAG) of 13.1 g/L
Explanation:Ascites is a medical condition characterized by the accumulation of abnormal amounts of fluid in the abdominal cavity. The causes of ascites can be classified into two groups based on the serum-ascites albumin gradient (SAAG) level. If the SAAG level is greater than 11g/L, it indicates portal hypertension, which is commonly caused by liver disorders such as cirrhosis, alcoholic liver disease, and liver metastases. Other causes of portal hypertension include cardiac conditions like right heart failure and constrictive pericarditis, as well as infections like tuberculous peritonitis. On the other hand, if the SAAG level is less than 11g/L, ascites may be caused by hypoalbuminaemia, malignancy, pancreatitis, bowel obstruction, and other conditions.
The management of ascites involves reducing dietary sodium and sometimes fluid restriction if the sodium level is less than 125 mmol/L. Aldosterone antagonists like spironolactone are often prescribed, and loop diuretics may be added if necessary. Therapeutic abdominal paracentesis may be performed for tense ascites, and large-volume paracentesis requires albumin cover to reduce the risk of complications. Prophylactic antibiotics may also be given to prevent spontaneous bacterial peritonitis. In some cases, a transjugular intrahepatic portosystemic shunt (TIPS) may be considered.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 25
Incorrect
-
A patient with common bile duct obstruction is undergoing an endoscopic retrograde cholangiopancreatography (ERCP). During the procedure, the Ampulla of Vater, a structure that marks the anatomical transition from the foregut to midgut is encountered.
What two structures combine to form the Ampulla of Vater in a different patient?Your Answer: Common bile duct and second part of the duodenum
Correct Answer: Pancreatic duct and common bile duct
Explanation:The correct anatomy of the biliary and pancreatic ducts is as follows: the common hepatic duct and cystic duct merge to form the common bile duct, which then joins with the pancreatic duct to form the Ampulla of Vater. This structure, also known as the hepatopancreatic duct, enters the second part of the duodenum. The flow of pancreatic enzymes and bile into the duodenum is controlled by the Sphincter of Oddi, a muscular valve also known as Glisson’s sphincter.
Anatomy of the Pancreas
The pancreas is located behind the stomach and is a retroperitoneal organ. It can be accessed surgically by dividing the peritoneal reflection that connects the greater omentum to the transverse colon. The pancreatic head is situated in the curvature of the duodenum, while its tail is close to the hilum of the spleen. The pancreas has various relations with other organs, such as the inferior vena cava, common bile duct, renal veins, superior mesenteric vein and artery, crus of diaphragm, psoas muscle, adrenal gland, kidney, aorta, pylorus, gastroduodenal artery, and splenic hilum.
The arterial supply of the pancreas is through the pancreaticoduodenal artery for the head and the splenic artery for the rest of the organ. The venous drainage for the head is through the superior mesenteric vein, while the body and tail are drained by the splenic vein. The ampulla of Vater is an important landmark that marks the transition from foregut to midgut and is located halfway along the second part of the duodenum. Overall, understanding the anatomy of the pancreas is crucial for surgical procedures and diagnosing pancreatic diseases.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 26
Incorrect
-
Sophie, a 19-year-old girl with type 1 diabetes mellitus, arrives at the emergency department with confusion, vomiting, and abdominal pain. Upon examination, she displays tachycardia and tachypnea. The medical team orders various tests, including an arterial blood gas.
The results are as follows:
pH 7.29 mmol/l
K+ 6.0 mmol/l
Glucose 15mmol/l
The doctors initiate treatment for diabetic ketoacidosis.
What ECG abnormality can be observed in relation to Sophie's potassium level?Your Answer: Tall P waves
Correct Answer: Tall tented T waves and flattened P waves
Explanation:When a person has hyperkalaemia, their blood has an excess of potassium which can lead to cardiac arrhythmias. One of the common ECG abnormalities seen in hyperkalaemia is tall tented T waves. Other possible ECG changes include wide QRS complexes and flattened P waves. In contrast, hypokalaemia can cause T wave depression, U waves, and tall P waves on an ECG. Delta waves are typically seen in patients with Wolfe-Parkinson-White syndrome.
ECG Findings in Hyperkalaemia
Hyperkalaemia is a condition characterized by high levels of potassium in the blood. This condition can have serious consequences on the heart, leading to abnormal ECG findings. The ECG findings in hyperkalaemia include peaked or ‘tall-tented’ T waves, loss of P waves, broad QRS complexes, sinusoidal wave pattern, and ventricular fibrillation.
The first ECG finding in hyperkalaemia is the appearance of peaked or ‘tall-tented’ T waves. This is followed by the loss of P waves, which are the small waves that represent atrial depolarization. The QRS complexes, which represent ventricular depolarization, become broad and prolonged. The sinusoidal wave pattern is a characteristic finding in severe hyperkalaemia, where the ECG tracing appears as a series of undulating waves. Finally, ventricular fibrillation, a life-threatening arrhythmia, can occur in severe hyperkalaemia.
In summary, hyperkalaemia can have serious consequences on the heart, leading to abnormal ECG findings. These findings include peaked or ‘tall-tented’ T waves, loss of P waves, broad QRS complexes, sinusoidal wave pattern, and ventricular fibrillation. It is important to recognize these ECG findings in hyperkalaemia as they can guide appropriate management and prevent life-threatening complications.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 27
Incorrect
-
A 20-year-old woman currently completing her exams presents to her GP with fatigue and generalised weakness. She has also noted that her skin and the whites of her eyes appear yellow. The GP suspects the patient may have Gilbert’s syndrome and orders liver function tests to determine the patient’s baseline liver function. The GP advises the patient that no treatment is necessary for this condition.
Reference range
Bilirubin 3 - 17 µmol/L
ALP 30 - 100 u/L
ALT 3 - 40 u/L
γGT 8 - 60 u/L
Albumin 35 - 50 g/L
LDH 100 - 190 U/L
What set of results would be expected from this patient?Your Answer: Bilirubin 10 umol/l, ALT 15 U/L, LDH 160 U/L, GGT 250 U/L
Correct Answer: Bilirubin 40 umol/l, ALT 15 U/L, LDH 160 U/L, GGT 25 U/L
Explanation:Jaundice becomes visible when bilirubin levels exceed 35 umol/l. Therefore, the correct option is the one with a bilirubin level of 40 umol/l, as this is typically the range where jaundice becomes visible. Furthermore, all other liver function values in this option are within the normal range. The other options are incorrect because they have bilirubin levels that are too low to cause visible jaundice, and the liver function results are usually normal in cases of Gilbert’s syndrome.
Understanding Bilirubin and Its Role in Jaundice
Bilirubin is a chemical by-product that is produced when red blood cells break down heme, a component found in these cells. This chemical is also found in other hepatic heme-containing proteins like myoglobin. The heme is processed within macrophages and oxidized to form biliverdin and iron. Biliverdin is then reduced to form unconjugated bilirubin, which is released into the bloodstream.
Unconjugated bilirubin is bound to albumin in the blood and then taken up by hepatocytes, where it is conjugated to make it water-soluble. From there, it is excreted into bile and enters the intestines to be broken down by intestinal bacteria. Bacterial proteases produce urobilinogen from bilirubin within the intestinal lumen, which is further processed by intestinal bacteria to form urobilin and stercobilin and excreted via the faeces. A small amount of bilirubin re-enters the portal circulation to be finally excreted via the kidneys in urine.
Jaundice occurs when bilirubin levels exceed 35 umol/l. Raised levels of unconjugated bilirubin may occur due to haemolysis, while hepatocyte defects, such as a compromised hepatocyte uptake of unconjugated bilirubin and/or defective conjugation, may occur in liver disease or deficiency of glucuronyl transferase. Raised levels of conjugated bilirubin can result from defective excretion of bilirubin, for example, Dubin-Johnson Syndrome, or cholestasis.
Cholestasis can result from a wide range of pathologies, which can be largely divided into physical causes, for example, gallstones, pancreatic and cholangiocarcinoma, or functional causes, for example, drug-induced, pregnancy-related and postoperative cholestasis. Understanding bilirubin and its role in jaundice is important in diagnosing and treating various liver and blood disorders.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 28
Correct
-
A 15-year-old girl comes to the clinic with her father. She has lost 10kg in the last 2 months. Recently, her father found her vomiting in the bathroom. The girl admits to struggling with her self-esteem and body image, and has been inducing vomiting after meals. She feels anxious in social situations. During the examination, you observe swelling above the angle of the mandible, indicating parotid gland enlargement. Which nerve supplies the parasympathetic fibers to the parotid gland?
Your Answer: Glossopharyngeal nerve
Explanation:The correct answer is the glossopharyngeal nerve, which is the ninth cranial nerve. It provides parasympathetic innervation to the parotid gland and carries taste and sensation from the posterior third of the tongue, pharyngeal wall, tonsils, middle ear, external auditory canal, and auricle. It also supplies baroreceptors and chemoreceptors of the carotid sinus.
The facial nerve, the seventh cranial nerve, supplies the muscles of facial expression, taste from the anterior two-thirds of the tongue, and sensation from parts of the external acoustic meatus, auricle, and retro-auricular area. It also provides parasympathetic fibers to the submandibular gland, sublingual gland, nasal glands, and lacrimal glands.
The hypoglossal nerve, the twelfth cranial nerve, supplies the intrinsic muscles of the tongue and all but one of the extrinsic muscles of the tongue.
The greater auricular nerve is a superficial cutaneous branch of the cervical plexus that supplies sensation to the capsule of the parotid gland, skin overlying the gland, and skin over the mastoid process and outer ear.
The mandibular nerve, the third division of the trigeminal nerve, carries sensory and motor fibers. It carries sensation from the lower lip, lower teeth and gingivae, chin, and jaw. It also supplies motor innervation to the muscles of mastication, mylohyoid, the anterior belly of digastric, tensor veli palatini, and tensor tympani.
The patient in the question has sialadenosis, a benign, non-inflammatory enlargement of a salivary gland, in the parotid glands, which can be caused by bulimia nervosa.
The parotid gland is located in front of and below the ear, overlying the mandibular ramus. Its salivary duct crosses the masseter muscle, pierces the buccinator muscle, and drains adjacent to the second upper molar tooth. The gland is traversed by several structures, including the facial nerve, external carotid artery, retromandibular vein, and auriculotemporal nerve. The gland is related to the masseter muscle, medial pterygoid muscle, superficial temporal and maxillary artery, facial nerve, stylomandibular ligament, posterior belly of the digastric muscle, sternocleidomastoid muscle, stylohyoid muscle, internal carotid artery, mastoid process, and styloid process. The gland is supplied by branches of the external carotid artery and drained by the retromandibular vein. Its lymphatic drainage is to the deep cervical nodes. The gland is innervated by the parasympathetic-secretomotor, sympathetic-superior cervical ganglion, and sensory-greater auricular nerve. Parasympathetic stimulation produces a water-rich, serous saliva, while sympathetic stimulation leads to the production of a low volume, enzyme-rich saliva.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 29
Correct
-
A 50-year-old woman presents with an unknown cause of jaundice. She noticed the yellowing of her skin and eyes in the mirror that morning. Upon examination, a palpable mass is found in the right upper quadrant of her abdomen. Her lab results show a total bilirubin level of 124 umol/L and high levels of conjugated bilirubin in her urine. What is the most probable diagnosis?
Your Answer: Cholangiocarcinoma
Explanation:To correctly diagnose this patient, knowledge of Courvoisier’s sign is necessary. This sign indicates that a palpable gallbladder in the presence of painless jaundice is unlikely to be caused by gallstones. Therefore, biliary colic is an incorrect answer as it is a painful condition. Haemolytic anaemia is also an incorrect answer as the blood test results would differ from this patient’s results. The correct answer is cholangiocarcinoma, which is a cancer of the biliary tree that can cause painless obstructive jaundice. Gilbert’s syndrome is not the most appropriate answer as it only presents with a raised bilirubin and does not cause an increase in ALP.
Understanding Cholangiocarcinoma
Cholangiocarcinoma, also known as bile duct cancer, is a serious medical condition that can be caused by primary sclerosing cholangitis. This disease is characterized by persistent biliary colic symptoms, which can be accompanied by anorexia, jaundice, and weight loss. In some cases, a palpable mass in the right upper quadrant may be present, which is known as the Courvoisier sign. Additionally, periumbilical lymphadenopathy (Sister Mary Joseph nodes) and left supraclavicular adenopathy (Virchow node) may be seen.
One of the main risk factors for cholangiocarcinoma is primary sclerosing cholangitis. This condition can cause inflammation and scarring of the bile ducts, which can lead to the development of cancer over time. To detect cholangiocarcinoma in patients with primary sclerosing cholangitis, doctors often use a blood test to measure CA 19-9 levels.
-
This question is part of the following fields:
- Gastrointestinal System
-
-
Question 30
Incorrect
-
A 67-year-old woman is currently admitted to the female orthopedic ward following a left total hip replacement after a femoral neck fracture. The surgery was uncomplicated, and the patient is expected to be discharged in four days. However, in the evening, the patient complains of feeling unwell and experiencing pain in the left hip area. The nurse records her vital signs, which include a pulse rate of 94 beats per minute, a respiratory rate of 20 breaths per minute, a blood pressure of 105/63 mmHg, and a temperature of 38.1ºC (100.6 degrees Fahrenheit). The ward doctor suspects a bone infection around the hip prosthesis and initiates treatment with clindamycin while awaiting review by the orthopedic surgeon. The patient's pain and suspected bone infection eventually subside, but after two days, the patient develops severe abdominal pain and diarrhea. What is the most likely causative organism responsible for this patient's condition?
Your Answer: Gram-negative, maltose-utilising diplococci
Correct Answer: Gram-positive anaerobic bacilli
Explanation:Pseudomembranous colitis is caused by the gram-positive bacillus Clostridium difficile, which can overgrow in the intestine following broad-spectrum antibiotic use. A patient recovering from a total hip replacement who develops signs of infection and is treated with clindamycin may develop severe abdominal pain and diarrhea, indicating a diagnosis of pseudomembranous colitis. Treatment options include metronidazole or oral vancomycin for more severe cases. Staphylococcus bacteria are gram-positive, catalase-positive cocci that can be differentiated based on coagulase positivity and novobiocin sensitivity. Listeria, Bacillus, and Corynebacterium are gram-positive aerobic bacilli, while Campylobacter jejuni, Vibrio cholerae, and Helicobacter pylori are gram-negative, oxidase-positive comma-shaped rods with specific growth characteristics.
Clostridium difficile is a type of bacteria that is commonly found in hospitals. It produces a toxin that can damage the intestines and cause a condition called pseudomembranous colitis. This bacteria usually develops when the normal gut flora is disrupted by broad-spectrum antibiotics, with second and third generation cephalosporins being the leading cause. Other risk factors include the use of proton pump inhibitors. Symptoms of C. difficile infection include diarrhea, abdominal pain, and a raised white blood cell count. The severity of the infection can be determined using the Public Health England severity scale.
To diagnose C. difficile infection, a stool sample is tested for the presence of the C. difficile toxin. Treatment involves reviewing current antibiotic therapy and stopping antibiotics if possible. For a first episode of infection, oral vancomycin is the first-line therapy for 10 days, followed by oral fidaxomicin as second-line therapy and oral vancomycin with or without IV metronidazole as third-line therapy. Recurrent infections may require different treatment options, such as oral fidaxomicin within 12 weeks of symptom resolution or oral vancomycin or fidaxomicin after 12 weeks of symptom resolution. In life-threatening cases, oral vancomycin and IV metronidazole may be used, and surgery may be considered with specialist advice. Other therapies, such as bezlotoxumab and fecal microbiota transplant, may also be considered for preventing recurrences in certain cases.
-
This question is part of the following fields:
- Gastrointestinal System
-
00
Correct
00
Incorrect
00
:
00
:
0
00
Session Time
00
:
00
Average Question Time (
Secs)