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Question 1
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What is the mechanism of action of rifampicin?
Your Answer: Inhibits RNA synthesis
Explanation:Rifampicin hinders the process of RNA synthesis.
Antibiotics work in different ways to kill or inhibit the growth of bacteria. The commonly used antibiotics can be classified based on their gross mechanism of action. The first group inhibits cell wall formation by either preventing peptidoglycan cross-linking (penicillins, cephalosporins, carbapenems) or peptidoglycan synthesis (glycopeptides like vancomycin). The second group inhibits protein synthesis by acting on either the 50S subunit (macrolides, chloramphenicol, clindamycin, linezolid, streptogrammins) or the 30S subunit (aminoglycosides, tetracyclines) of the bacterial ribosome. The third group inhibits DNA synthesis (quinolones like ciprofloxacin) or damages DNA (metronidazole). The fourth group inhibits folic acid formation (sulphonamides and trimethoprim), while the fifth group inhibits RNA synthesis (rifampicin). Understanding the mechanism of action of antibiotics is important in selecting the appropriate drug for a particular bacterial infection.
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This question is part of the following fields:
- General Principles
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Question 2
Correct
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An 80-year-old man is brought to the hospital due to acute delirium. Upon assessment, he appears disoriented to time and place, and is exhibiting responses to unseen stimuli. His family reports that he has been experiencing increased confusion over the past week, as well as complaining of stomach pains and constipation.
The patient has not been prescribed any new medications, but is regularly taking atorvastatin and ramipril. It is important to note that he is currently receiving palliative treatment for lung adenocarcinoma. The suspected cause of his delirium is paraneoplastic production of parathyroid hormone-related protein.
Which set of blood test results would best match the patient's clinical presentation?Your Answer: Low parathyroid hormone, high calcium and low phosphate
Explanation:The patient is exhibiting symptoms of hypercalcemia caused by a paraneoplastic syndrome associated with lung cancer, specifically squamous cell, adenocarcinoma, and small cell. Paraneoplastic syndromes occur when cancer cells produce hormones that disrupt the body’s normal balance. In this case, the cancer cells are producing a parathyroid-like hormone, which increases bone turnover and releases calcium, resulting in elevated serum calcium and decreased phosphate levels. The malignancy is producing an ectopic form of parathyroid hormone, which suppresses the body’s natural supply. If the patient had elevated parathyroid hormone levels, it would suggest primary hyperparathyroidism, which typically causes high calcium and low phosphate levels. Normal parathyroid hormone levels would indicate that the body’s homeostatic mechanisms are functioning properly, resulting in normal calcium and phosphate levels. Low parathyroid hormone levels, along with low calcium and high phosphate levels, may indicate primary hypoparathyroidism.
Hormones Controlling Calcium Metabolism
Calcium metabolism is primarily controlled by two hormones, parathyroid hormone (PTH) and 1,25-dihydroxycholecalciferol (calcitriol). Other hormones such as calcitonin, thyroxine, and growth hormone also play a role. PTH increases plasma calcium levels and decreases plasma phosphate levels. It also increases renal tubular reabsorption of calcium, osteoclastic activity, and renal conversion of 25-hydroxycholecalciferol to 1,25-dihydroxycholecalciferol. On the other hand, 1,25-dihydroxycholecalciferol increases plasma calcium and plasma phosphate levels, renal tubular reabsorption and gut absorption of calcium, osteoclastic activity, and renal phosphate reabsorption. It is important to note that osteoclastic activity is increased indirectly by PTH as osteoclasts do not have PTH receptors. Understanding the actions of these hormones is crucial in maintaining proper calcium metabolism in the body.
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This question is part of the following fields:
- General Principles
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Question 3
Incorrect
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A 44-year-old man with active hepatitis B infection is found to have transitional cell carcinoma of the bladder. After a multidisciplinary assessment, it is determined that his cancer is a non-muscle-invasive tumour of intermediate risk. He undergoes a successful transurethral resection of the carcinoma. However, due to his high risk of recurrence, he is being considered for postoperative intravesical chemotherapy or intravesical bacillus Calmette-Guérin (BCG).
Despite having a BCG vaccination scar on his shoulder, he was treated for pulmonary tuberculosis 22 years ago. He has been on antiretroviral therapy for HIV for the past six years.
What is the factor in this patient's medical history that makes intravesical BCG administration contraindicated?Your Answer: Previously treated tuberculosis
Correct Answer: HIV positive
Explanation:BCG vaccine cannot be given to individuals who have compromised immune systems, such as those with HIV infection, as it is a live vaccine. It is also contraindicated in pregnant women and those with existing tuberculosis infection. Intravesical BCG is not recommended for individuals with active urinary tract infection, traumatic catheterisation, gross haematuria, or recent bladder surgery. However, having hepatitis B or previous BCG vaccination does not prevent an individual from receiving the BCG vaccine. Additionally, intravesical BCG is indicated for reducing the risk of recurrence in non-muscle-invasive papillary carcinoma cases.
The BCG vaccine is a form of immunization that provides limited protection against tuberculosis (TB). In the UK, it is typically given to high-risk infants and was previously administered to children at the age of 13 years until 2005. The Greenbook recommends that the vaccine be given to infants living in areas with an annual incidence of TB of 40/100,000 or greater, as well as infants with a parent or grandparent born in a country with a similar incidence rate. Other groups that should receive the vaccine include previously unvaccinated contacts of respiratory TB cases, healthcare workers, prison staff, and those who work with homeless people.
The vaccine contains live attenuated Mycobacterium bovis and also offers limited protection against leprosy. Before receiving the BCG vaccine, individuals must undergo a tuberculin skin test, with the exception of children under six years old who have had no contact with tuberculosis. The vaccine is administered intradermally to the lateral aspect of the left upper arm and can be given at the same time as other live vaccines, with a four-week interval if not administered simultaneously.
There are several contraindications for the BCG vaccine, including previous vaccination, a history of tuberculosis, HIV, pregnancy, and a positive tuberculin test. It is not recommended for individuals over the age of 35, as there is no evidence that it is effective for this age group.
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This question is part of the following fields:
- General Principles
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Question 4
Incorrect
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A 32-year-old woman is being seen in the Oncology department for evaluation. She has been diagnosed with osteosarcoma of the left femur. Her medical history reveals a previous diagnosis of rhabdomyosarcoma, which was effectively treated when she was eleven years old.
What is the typical biological function of the protein impacted in the patient's underlying genetic disorder?Your Answer: Mismatch repair of single-strand DNA breaks
Correct Answer: Holding the cell cycle at the G1/S phase checkpoint to allow detection and repair of DNA damage
Explanation:The TP53 gene, which encodes the protein p53, is crucial in preventing the cell cycle from entering the S phase until DNA has been checked and repaired. This is particularly important in individuals with Li-Fraumeni syndrome (LFS), an inherited susceptibility to cancer that often results in the development of multiple sarcomas from a young age. LFS is caused by a mutation in one allele of the TP53 gene. One of the key functions of p53 is to hold the cell cycle at the G1/S checkpoint, allowing for the detection and repair of any DNA damage before replication occurs.
The identification of double-strand DNA breaks is not a function of p53. This is typically carried out by the MRN protein complex, which acts upstream of DNA repair proteins such as BRCA1 and BRCA2.
Inhibition of apoptosis is also not a primary function of p53. While p53 can promote apoptosis if cell cycle checkpoints are not satisfied, its primary role is in regulating the cell cycle.
Similarly, mismatch repair of single-strand DNA breaks is not a function of p53. This is typically carried out by mismatch repair proteins such as MLH-1 and MSH-2, which may be mutated in the familial cancer syndrome Lynch syndrome.
Understanding p53 and its Role in Cancer
p53 is a gene that helps suppress tumours and is located on chromosome 17p. It is frequently mutated in breast, colon, and lung cancer. The gene is believed to be essential in regulating the cell cycle, preventing cells from entering the S phase until DNA has been checked and repaired. Additionally, p53 may play a crucial role in apoptosis, the process of programmed cell death.
Li-Fraumeni syndrome is a rare genetic disorder that is inherited in an autosomal dominant pattern. It is characterised by the early onset of various cancers, including sarcoma, breast cancer, and leukaemia. The condition is caused by mutations in the p53 gene, which can lead to a loss of its tumour-suppressing function. Understanding the role of p53 in cancer can help researchers develop new treatments and therapies for those affected by the disease.
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This question is part of the following fields:
- General Principles
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Question 5
Incorrect
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A 4-year-old girl is brought to her pediatrician by her father who is concerned that his daughter seems to be very weak compared to what he had previously experienced with his elder daughter who had a normal development. The father also reports that he noticed that his daughter is always hungry and her constant craving for food has resulted in a significant weight gain. The girl is not being breastfed anymore but the father does confirm her sucking seemed to be very weak at the time. The girl was born via a cesarean section and there were no complications at birth. Upon examination, the pediatrician confirms that the girl has poor muscle tone as well as undeveloped genitals. The pediatrician makes a referral to the pediatrician geneticist and upon genetic testing, the girl is diagnosed with a condition which often leads to significant obesity as one of the main features of the disease. What is the main genetic mechanism of inheritance for this disease?
Your Answer: Autosomal recessive
Correct Answer: Imprinting
Explanation:The individual exhibited indications and manifestations that strongly suggest the presence of Prader-Willi syndrome, a hereditary disorder that typically manifests in early childhood and is characterized by hypotonia, hyperphagia, and obesity. Additionally, cognitive impairment leading to intellectual disability may also be observed.
Understanding Prader-Willi Syndrome
Prader-Willi syndrome is a genetic disorder that is caused by the absence of the active Prader-Willi gene on chromosome 15. This disorder is an example of genetic imprinting, where the phenotype depends on whether the deletion occurs on a gene inherited from the mother or father. If the gene is deleted from the father, it results in Prader-Willi syndrome, while if it is deleted from the mother, it results in Angelman syndrome.
There are two main causes of Prader-Willi syndrome. The first is a microdeletion of paternal 15q11-13, which accounts for 70% of cases. The second is maternal uniparental disomy of chromosome 15. This means that both copies of chromosome 15 are inherited from the mother, and there is no active Prader-Willi gene from the father.
The features of Prader-Willi syndrome include hypotonia during infancy, dysmorphic features, short stature, hypogonadism and infertility, learning difficulties, childhood obesity, and behavioral problems in adolescence. These symptoms can vary in severity and may require lifelong management.
In conclusion, Prader-Willi syndrome is a complex genetic disorder that affects multiple aspects of an individual’s health and development. Understanding the causes and features of this syndrome is crucial for early diagnosis and effective management.
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This question is part of the following fields:
- General Principles
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Question 6
Incorrect
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A new screening test for breast cancer is in development. The following table shows the results of a recent trial.
Breast cancer present Breast cancer absent
Test positive 120 30
Test negative 10 840
What is the negative predictive value of the screening test to 1 decimal place?Your Answer: 93.8%
Correct Answer: 96.0%
Explanation:The negative predictive value refers to the probability that the patient does not possess the condition in case the diagnostic test yields a negative result.
Precision refers to the consistency of a test in producing the same results when repeated multiple times. It is an important aspect of test reliability and can impact the accuracy of the results. In order to assess precision, multiple tests are performed on the same sample and the results are compared. A test with high precision will produce similar results each time it is performed, while a test with low precision will produce inconsistent results. It is important to consider precision when interpreting test results and making clinical decisions.
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This question is part of the following fields:
- General Principles
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Question 7
Incorrect
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A 30-year-old man comes in with an anterior dislocation of his shoulder that occurred during a football game. He reports numbness in the 'regimental badge' area of the shoulder, suggesting axillary nerve injury. During which stage of the cell cycle is a mature neuron cell most likely to be found?
Your Answer: G2
Correct Answer: Quiescent stage
Explanation:Mature neuron cells are in a state of cell cycle arrest and do not undergo division, remaining in the G0 phase.
The Cell Cycle and its Regulation
The cell cycle is a process that regulates the growth and division of cells. It is controlled by proteins called cyclins, which in turn regulate cyclin-dependent kinase (CDK) enzymes. The cycle is divided into four phases: G0, G1, S, G2, and M. During the G0 phase, cells are in a resting state, while in G1, cells increase in size and determine the length of the cell cycle. Cyclin D/CDK4, Cyclin D/CDK6, and Cyclin E/CDK2 regulate the transition from G1 to S phase. In the S phase, DNA, RNA, and histones are synthesized, and centrosome duplication occurs. Cyclin A/CDK2 is active during this phase. In G2, cells continue to increase in size, and Cyclin B/CDK1 regulates the transition from G2 to M phase. Finally, in the M phase, mitosis occurs, which is the shortest phase of the cell cycle. The cell cycle is regulated by various proteins, including p53, which plays a crucial role in the G1 phase. Understanding the regulation of the cell cycle is essential for the development of new treatments for diseases such as cancer.
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This question is part of the following fields:
- General Principles
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Question 8
Incorrect
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A 3-year-old male is brought to the clinician for evaluation of recurrent seizures. He has a history of frequent infections. During chest examination, a heart murmur is detected on the left sternal edge and he presents with abnormal facial features. Laboratory tests show hypocalcemia, hyperphosphatemia, and low levels of parathyroid hormone. The diagnosis is DiGeorge syndrome. Which pharyngeal pouch gives rise to the thymus in this condition?
Your Answer: Fourth pharyngeal pouch
Correct Answer: Third pharyngeal pouch
Explanation:The 3rd pharyngeal pouch gives rise to the thymus. Other structures derived from different pharyngeal pouches include the Eustachian tube, middle ear cavity, and mastoid antrum from the 1st pouch, the Palatine tonsils from the 2nd pouch, the superior parathyroid glands from the 4th pouch, and the thyroid C-cells from the 5th pouch which eventually becomes part of the 4th pouch.
Embryology of Branchial (Pharyngeal) Pouches
During embryonic development, the branchial (pharyngeal) pouches give rise to various structures in the head and neck region. The first pharyngeal pouch forms the Eustachian tube, middle ear cavity, and mastoid antrum. The second pharyngeal pouch gives rise to the palatine tonsils. The third pharyngeal pouch divides into dorsal and ventral wings, with the dorsal wings forming the inferior parathyroid glands and the ventral wings forming the thymus. Finally, the fourth pharyngeal pouch gives rise to the superior parathyroid glands.
Understanding the embryology of the branchial pouches is important in the diagnosis and treatment of certain congenital abnormalities and diseases affecting these structures. By knowing which structures arise from which pouches, healthcare professionals can better understand the underlying pathophysiology and develop appropriate management strategies. Additionally, knowledge of the embryology of these structures can aid in the development of new treatments and therapies for related conditions.
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This question is part of the following fields:
- General Principles
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Question 9
Correct
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A 2-year-old girl is brought to a pediatrician by her mother due to a persistent runny nose and cough for the past six months. Despite being treated with antibiotics for an upper respiratory tract infection, the symptoms have not improved. During the examination, the pediatrician observes that the girl has frontal bossing, a flattened nasal bridge, and a protruding tongue. The child's growth is also below average, but there is no corneal clouding. Further investigation reveals low levels of iduronate sulfatase enzyme activity, confirming the diagnosis. The pediatrician informs the mother that this is a genetically inherited condition and that treatment will involve replacing the defective enzyme. What is the correct name of the condition that this girl is suffering from?
Your Answer: This disease is transmitted by carrier mothers to half of their sons but not daughters
Explanation:The patient’s symptoms suggest a metabolic disease, specifically one of the lysosomal storage diseases such as Hurler syndrome or Hunter syndrome. Hurler syndrome is inherited in an autosomal recessive pattern and is characterized by corneal clouding due to low alpha-L-iduronidase activity. Hunter syndrome, on the other hand, does not involve corneal clouding and is diagnosed through low iduronate sulfatase activity.
1: This transmission pattern is seen in mitochondrial myopathies, a group of genetically inherited diseases with a mitochondrial pattern of inheritance.
2: Autosomal dominant diseases only require one affected parent to transmit the disease, examples include Huntington disease, Marfan syndrome, Li-Fraumeni syndrome, and tuberous sclerosis.
3: X-linked dominant diseases are transmitted by affected mothers to half of their sons and daughters, but not by fathers. Examples include fragile X syndrome, Alport syndrome, and vitamin D-resistant rickets.
4: X-linked recessive diseases are transmitted by carrier mothers to half of their sons, but not their daughters. Examples include Hunter syndrome, ocular albinism, G6PD deficiency, and Lesch-Nyhan syndrome.
5: Autosomal recessive diseases require both parents to be carriers of the defective gene for the disease to be transmitted. Examples include cystic fibrosis, Kartagener syndrome, sickle cell anemia, and Hunter syndrome.Inherited Metabolic Disorders: Types and Deficiencies
Inherited metabolic disorders are a group of genetic disorders that affect the body’s ability to process certain substances. These disorders can be categorized into different types based on the specific substance that is affected. One type is glycogen storage disease, which is caused by deficiencies in enzymes involved in glycogen metabolism. This can lead to the accumulation of glycogen in various organs, resulting in symptoms such as hypoglycemia, lactic acidosis, and hepatomegaly.
Another type is lysosomal storage disease, which is caused by deficiencies in enzymes involved in lysosomal metabolism. This can lead to the accumulation of various substances within lysosomes, resulting in symptoms such as hepatosplenomegaly, developmental delay, and optic atrophy. Examples of lysosomal storage diseases include Gaucher’s disease, Tay-Sachs disease, and Fabry disease.
Finally, mucopolysaccharidoses are a group of disorders caused by deficiencies in enzymes involved in the breakdown of glycosaminoglycans. This can lead to the accumulation of these substances in various organs, resulting in symptoms such as coarse facial features, short stature, and corneal clouding. Examples of mucopolysaccharidoses include Hurler syndrome and Hunter syndrome.
Overall, inherited metabolic disorders can have a wide range of symptoms and can affect various organs and systems in the body. Early diagnosis and treatment are important in managing these disorders and preventing complications.
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This question is part of the following fields:
- General Principles
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Question 10
Incorrect
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During a rotation in the pediatric genetics department, you spend an afternoon observing a list of patients with genetic disorders. Many of the patients who come during the afternoon are children with Down syndrome who are being screened for potential health issues associated with their condition.
You know that individuals with Down syndrome have a higher risk of developing certain health conditions, such as heart defects and leukemia, due to the presence of an extra chromosome.
What is the medical term used to describe the increased risk of health issues associated with Down syndrome?Your Answer: Heterogenicity
Correct Answer: Penetrance
Explanation:Penetrance is a term used in genetics to indicate the percentage of individuals in a population who carry a disease-causing allele and exhibit the related disease phenotype. It is important to note that not all patients with the same gene mutation display the same degree of observable characteristics. Genetic heterogeneity refers to the existence of two different loci of genes that can mutate to produce a similar phenotype. Prevalence is the total number of individuals living with a particular condition at a given time. A punnet diagram is a useful tool for determining the genotypes resulting from a specific cross-breeding experiment.
Understanding Penetrance and Expressivity in Genetic Disorders
Penetrance and expressivity are two important concepts in genetics that help explain why individuals with the same gene mutation may exhibit different degrees of observable characteristics. Penetrance refers to the proportion of individuals in a population who carry a disease-causing allele and express the related disease phenotype. In contrast, expressivity describes the extent to which a genotype shows its phenotypic expression in an individual.
There are several factors that can influence penetrance and expressivity, including modifier genes, environmental factors, and allelic variation. For example, some genetic disorders, such as retinoblastoma and Huntington’s disease, exhibit incomplete penetrance, meaning that not all individuals with the disease-causing allele will develop the condition. On the other hand, achondroplasia shows complete penetrance, meaning that all individuals with the disease-causing allele will develop the condition.
Expressivity, on the other hand, describes the severity of the phenotype. Some genetic disorders, such as neurofibromatosis, exhibit a high level of expressivity, meaning that the phenotype is more severe in affected individuals. Understanding penetrance and expressivity is important in genetic counseling and can help predict the likelihood and severity of a genetic disorder in individuals and their families.
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This question is part of the following fields:
- General Principles
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Question 11
Incorrect
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A 54-year-old dentist has been practicing for many years. Recently, she has started to observe that her hands are developing blisters and becoming weepy. After diagnosis, it is found that she has a latex allergy. What pathological process is responsible for this situation?
Your Answer: Type 2 hypersensitivity reaction
Correct Answer: Type 4 hypersensitivity reaction
Explanation:ACID is an acronym for the four types of hypersensitivity reactions. These include type 1, which is anaphylactic; type 2, which is cytotoxic; type 3, which is immune complex; and type 4, which is delayed hypersensitivity. Unlike the other types, type 4 hypersensitivity reactions are cell mediated rather than antibody mediated. An example of this type of reaction is chronic contact dermatitis.
Classification of Hypersensitivity Reactions
Hypersensitivity reactions are classified into four types according to the Gell and Coombs classification. Type I, also known as anaphylactic hypersensitivity, occurs when an antigen reacts with IgE bound to mast cells. This type of reaction is commonly seen in atopic conditions such as asthma, eczema, and hay fever. Type II hypersensitivity occurs when cell-bound IgG or IgM binds to an antigen on the cell surface, leading to autoimmune conditions such as autoimmune hemolytic anemia, ITP, and Goodpasture’s syndrome. Type III hypersensitivity occurs when free antigen and antibody (IgG, IgA) combine to form immune complexes, leading to conditions such as serum sickness, systemic lupus erythematosus, and post-streptococcal glomerulonephritis. Type IV hypersensitivity is T-cell mediated and includes conditions such as tuberculosis, graft versus host disease, and allergic contact dermatitis.
In recent times, a fifth category has been added to the classification of hypersensitivity reactions. Type V hypersensitivity occurs when antibodies recognize and bind to cell surface receptors, either stimulating them or blocking ligand binding. This type of reaction is seen in conditions such as Graves’ disease and myasthenia gravis. Understanding the classification of hypersensitivity reactions is important in the diagnosis and management of these conditions.
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This question is part of the following fields:
- General Principles
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Question 12
Incorrect
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A 50-year-old male presents with yellow discoloration of his nails. Upon examination, he has thickened yellow toenails. Your plan of action is to treat him with terbinafine.
What is the mechanism of action for terbinafine?Your Answer: Converted to 5-fluorouracil
Correct Answer: Inhibits the fungal enzyme squalene epoxidase
Explanation:Terbinafine causes cellular death by inhibiting the fungal enzyme squalene epoxidase and is used to treat fungal nail infections, ringworm, and pityriasis versicolor.
Griseofulvin disrupts the mitotic spindle by interacting with microtubules.
Amphotericin B forms a transmembrane channel by binding with ergosterol.
Flucytosine is converted to 5-fluorouracil by cytosine deaminase, which disrupts fungal protein synthesis by inhibiting thymidylate synthase.
Caspofungin inhibits the synthesis of beta-glucan, a major component of the fungal cell wall.
Antifungal agents are drugs used to treat fungal infections. There are several types of antifungal agents, each with a unique mechanism of action and potential adverse effects. Azoles work by inhibiting 14α-demethylase, an enzyme that produces ergosterol, a component of fungal cell membranes. However, they can also inhibit the P450 system in the liver, leading to potential liver toxicity. Amphotericin B binds with ergosterol to form a transmembrane channel that causes leakage of monovalent ions, but it can also cause nephrotoxicity and flu-like symptoms. Terbinafine inhibits squalene epoxidase, while griseofulvin interacts with microtubules to disrupt mitotic spindle. However, griseofulvin can induce the P450 system and is teratogenic. Flucytosine is converted by cytosine deaminase to 5-fluorouracil, which inhibits thymidylate synthase and disrupts fungal protein synthesis, but it can cause vomiting. Caspofungin inhibits the synthesis of beta-glucan, a major fungal cell wall component, and can cause flushing. Nystatin binds with ergosterol to form a transmembrane channel that causes leakage of monovalent ions, but it is very toxic and can only be used topically, such as for oral thrush.
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This question is part of the following fields:
- General Principles
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Question 13
Incorrect
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An academic clinician is investigating whether the use of clot retrieval after thrombolysis provides significant improvements in patient outcomes compared to using thrombolysis alone in elderly patients with recent ischaemic stroke. She is testing the null hypothesis that there is no significant difference in patient outcomes between the two treatment methods.
Your Answer: Clot retrieval is no more dangerous than thrombolysis
Correct Answer: The use of clot retrieval in addition to thrombolysis provides no additional benefit
Explanation:The null hypothesis for this study is that the addition of clot retrieval to thrombolysis does not result in a significant improvement in patient outcomes compared to thrombolysis alone.
Significance tests are used to determine the likelihood of a null hypothesis being true. The null hypothesis states that two treatments are equally effective, while the alternative hypothesis suggests that there is a difference between the two treatments. The p value is the probability of obtaining a result by chance that is at least as extreme as the observed result, assuming the null hypothesis is true. Two types of errors can occur during significance testing: type I, where the null hypothesis is rejected when it is true, and type II, where the null hypothesis is accepted when it is false. The power of a study is the probability of correctly rejecting the null hypothesis when it is false, and it can be increased by increasing the sample size.
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This question is part of the following fields:
- General Principles
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Question 14
Incorrect
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A 15-year-old patient is brought into GP by her mother with concerns that she has not yet entered puberty. The patient reports experiencing bullying amongst her peers due to her appearance, short height, and recent weight gain despite eating very little. She also reports feeling low and no longer enjoying activities she used to like. The patient is worried about being the only girl in her class who has not yet experienced periods and the lack of breast development with widely spaced nipples.
During examination, the patient is found to have a webbed neck and a high-arched palate. The patient is referred to a paediatrician who then refers her to the genetics team. As part of their assessment, the genetics team orders a karyotype.
What results would be expected from the karyotype given the likely diagnosis?Your Answer: Trisomy 21
Correct Answer: 45,X0
Explanation:This patient’s clinical presentation is consistent with Turner syndrome, which is typically caused by a karyotype of 45,XO. Symptoms may include short stature, widely spaced nipples, webbed neck, and high-arched palate. Patients with Turner syndrome are also at higher risk for hypothyroidism, which can cause weight gain, lethargy, and depressive symptoms. Down syndrome (trisomy 21) and Edwards’ syndrome (trisomy 18) have distinct clinical features that differ from those seen in Turner syndrome. Klinefelter syndrome is not relevant to this patient’s presentation.
Understanding Turner’s Syndrome
Turner’s syndrome is a genetic condition that affects approximately 1 in 2,500 females. It is caused by the absence of one sex chromosome (X) or a deletion of the short arm of one of the X chromosomes. This condition is identified as 45,XO or 45,X.
The features of Turner’s syndrome include short stature, a shield chest with widely spaced nipples, a webbed neck, a bicuspid aortic valve (present in 15% of cases), coarctation of the aorta (present in 5-10% of cases), primary amenorrhea, cystic hygroma (often diagnosed prenatally), a high-arched palate, a short fourth metacarpal, multiple pigmented naevi, lymphoedema in neonates (especially in the feet), and elevated gonadotrophin levels. Hypothyroidism is also more common in individuals with Turner’s syndrome, as well as an increased incidence of autoimmune diseases such as autoimmune thyroiditis and Crohn’s disease.
In summary, Turner’s syndrome is a chromosomal disorder that affects females and is characterized by various physical features and health conditions. Early diagnosis and management can help individuals with Turner’s syndrome lead healthy and fulfilling lives.
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This question is part of the following fields:
- General Principles
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Question 15
Incorrect
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A 50-year-old woman visits her physician complaining of a persistent productive cough and night sweats. The physician orders a chest x-ray, which reveals upper lobe consolidation consistent with granulomas. To confirm the likely diagnosis, the patient is referred to a hospital where an interferon-gamma release assay (QuantiFERON) is ordered.
What are the main immune cells responsible for producing the cytokine measured by this test?Your Answer: B cells
Correct Answer: T helper cells
Explanation:Understanding Interferons
Interferons are a type of cytokine that the body produces in response to viral infections and neoplasia. They are categorized based on the type of receptor they bind to and their cellular origin. IFN-alpha and IFN-beta bind to type 1 receptors, while IFN-gamma binds only to type 2 receptors.
IFN-alpha is produced by leucocytes and has antiviral properties. It is commonly used to treat hepatitis B and C, Kaposi’s sarcoma, metastatic renal cell cancer, and hairy cell leukemia. However, it can cause flu-like symptoms and depression as side effects.
IFN-beta is produced by fibroblasts and also has antiviral properties. It is particularly useful in reducing the frequency of exacerbations in patients with relapsing-remitting multiple sclerosis.
IFN-gamma is mainly produced by natural killer cells and T helper cells. It has weaker antiviral properties but plays a significant role in immunomodulation, particularly in macrophage activation. It may be beneficial in treating chronic granulomatous disease and osteopetrosis.
Understanding the different types of interferons and their functions can help in the development of targeted treatments for various diseases.
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This question is part of the following fields:
- General Principles
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Question 16
Incorrect
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A new clinical trial is currently being designed by one of the research students in the hospital. As part of this design, the student wants to calculate the probability of correctly rejecting the null hypothesis when it is in fact false. They understand that the calculation of this will improve the reliability of the results.
Which of the following best describes the calculation above if the research student wants to calculate the probability of correctly rejecting the null hypothesis?Your Answer: Standard error
Correct Answer: Statistical power
Explanation:The probability of a type II error is inversely related to power, which is the probability of correctly rejecting the null hypothesis when it is false. Type I errors, or false positives, occur when the null hypothesis is wrongly rejected, while type II errors, or false negatives, occur when the null hypothesis is wrongly accepted. Hypothesis testing involves using statistical tests to determine whether the null hypothesis should be accepted or rejected. The standard error is a statistical measure of the accuracy of a sample distribution in representing a population, calculated using the standard deviation.
Significance tests are used to determine the likelihood of a null hypothesis being true. The null hypothesis states that two treatments are equally effective, while the alternative hypothesis suggests that there is a difference between the two treatments. The p value is the probability of obtaining a result by chance that is at least as extreme as the observed result, assuming the null hypothesis is true. Two types of errors can occur during significance testing: type I, where the null hypothesis is rejected when it is true, and type II, where the null hypothesis is accepted when it is false. The power of a study is the probability of correctly rejecting the null hypothesis when it is false, and it can be increased by increasing the sample size.
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This question is part of the following fields:
- General Principles
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Question 17
Incorrect
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You are assessing a 68-year-old female patient in your general practice. She complains of muscle pain and stiffness in her shoulders and hips for the past two weeks. Her creatine kinase levels are normal, but her erythrocyte sedimentation rate (ESR) is 60 mm/hr. You diagnose her with polymyalgia rheumatica (PMR) and initiate a one-week trial of prednisolone 15mg once daily. Which receptor does this medication target?
Your Answer: Tyrosine kinase receptor
Correct Answer: Nuclear receptor
Explanation:Prednisolone decreases inflammation and leukocyte migration by acting on nuclear receptors, making it the correct answer.
Lidocaine and amlodipine are examples of common medications that act on ion channels.
Adenosine and oxymetazoline are examples of common medications that act on GPCR.
Insulin and levothyroxine are examples of common medications that act on tyrosine kinase receptors.
Pharmacodynamics refers to the effects of drugs on the body, as opposed to pharmacokinetics which is concerned with how the body processes drugs. Drugs typically interact with a target, which can be a protein located either inside or outside of cells. There are four main types of cellular targets: ion channels, G-protein coupled receptors, tyrosine kinase receptors, and nuclear receptors. The type of target determines the mechanism of action of the drug. For example, drugs that work on ion channels cause the channel to open or close, while drugs that activate tyrosine kinase receptors lead to cell growth and differentiation.
It is also important to consider whether a drug has a positive or negative impact on the receptor. Agonists activate the receptor, while antagonists block the receptor preventing activation. Antagonists can be competitive or non-competitive, depending on whether they bind at the same site as the agonist or at a different site. The binding affinity of a drug refers to how readily it binds to a specific receptor, while efficacy measures how well an agonist produces a response once it has bound to the receptor. Potency is related to the concentration at which a drug is effective, while the therapeutic index is the ratio of the dose of a drug resulting in an undesired effect compared to that at which it produces the desired effect.
The relationship between the dose of a drug and the response it produces is rarely linear. Many drugs saturate the available receptors, meaning that further increased doses will not cause any more response. Some drugs do not have a significant impact below a certain dose and are considered sub-therapeutic. Dose-response graphs can be used to illustrate the relationship between dose and response, allowing for easy comparison of different drugs. However, it is important to remember that dose-response varies between individuals.
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- General Principles
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Question 18
Correct
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A 55-year-old man presents to the ENT clinic with a 10-week history of progressive dysphagia and a persistent sore throat. He reports no fever or cough, but has lost around 5kg in weight over the past 8 weeks.
During the examination, non-tender palpable cervical lymphadenopathy is observed. Upon oropharyngeal examination, an ill-defined ulcerated lesion is found at the back of the mouth. Biopsies are taken.
What is the most significant risk factor for the likely presentation of this patient?Your Answer: Human papillomavirus 16/18
Explanation:Understanding Oncoviruses and Their Associated Cancers
Oncoviruses are viruses that have the potential to cause cancer. These viruses can be detected through blood tests and prevented through vaccination. There are several types of oncoviruses, each associated with a specific type of cancer.
The Epstein-Barr virus, for example, is linked to Burkitt’s lymphoma, Hodgkin’s lymphoma, post-transplant lymphoma, and nasopharyngeal carcinoma. Human papillomavirus 16/18 is associated with cervical cancer, anal cancer, penile cancer, vulval cancer, and oropharyngeal cancer. Human herpes virus 8 is linked to Kaposi’s sarcoma, while hepatitis B and C viruses are associated with hepatocellular carcinoma. Finally, human T-lymphotropic virus 1 is linked to tropical spastic paraparesis and adult T cell leukemia.
It is important to understand the link between oncoviruses and cancer so that appropriate measures can be taken to prevent and treat these diseases. Vaccination against certain oncoviruses, such as HPV, can significantly reduce the risk of developing associated cancers. Regular screening and early detection can also improve outcomes for those who do develop cancer as a result of an oncovirus.
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This question is part of the following fields:
- General Principles
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Question 19
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What is the characteristic finding on a blood film after a splenectomy?
Your Answer: Howell-Jolly bodies
Explanation:In cases of hyposplenism, the blood film may show the presence of Howell-Jolly bodies, Pappenheimer bodies, poikilocytes (specifically target cells), erythrocytes containing siderotic granules, and Heinz bodies.
Splenectomy and its Management
Splenectomy is a surgical procedure that involves the removal of the spleen. After the operation, patients are at a higher risk of infections caused by pneumococcus, Haemophilus, meningococcus, and Capnocytophaga canimorsus. To prevent these infections, patients should receive vaccinations such as Hib, meningitis A & C, annual influenzae, and pneumococcal vaccines. Antibiotic prophylaxis with penicillin V is also recommended for at least two years and until the patient is 16 years old, although some patients may require lifelong prophylaxis.
Splenectomy is indicated for various reasons such as trauma, spontaneous rupture, hypersplenism, malignancy, splenic cysts, hydatid cysts, and splenic abscesses. Elective splenectomy is different from emergency splenectomy, and it is usually performed laparoscopically. Complications of splenectomy include haemorrhage, pancreatic fistula, and thrombocytosis. Post-splenectomy changes include an increase in platelets, Howell-Jolly bodies, target cells, and Pappenheimer bodies. Patients are at an increased risk of post-splenectomy sepsis, which typically occurs with encapsulated organisms. Therefore, prophylactic antibiotics and pneumococcal vaccines are essential to prevent infections.
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This question is part of the following fields:
- General Principles
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Question 20
Incorrect
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A 30-year-old male comes to your clinic with a three-month history of abdominal pain that is relieved by eating. You suspect a duodenal ulcer and plan to test for Helicobacter pylori infection using a urea breath test. He has no history of NSAID use and lives in a city where the prevalence of H. pylori is 40%. The sensitivity of the test is 96%, and the specificity is 92%. What is the likelihood ratio for a positive test result?
Your Answer: 20
Correct Answer: 12
Explanation:The positive likelihood ratio of a test can be calculated using the formula: sensitivity divided by (1 minus specificity). This ratio is not affected by the prevalence of the disease. For example, if the sensitivity of a test is 0.96 and the specificity is 0.92, the positive likelihood ratio would be 12.
Precision refers to the consistency of a test in producing the same results when repeated multiple times. It is an important aspect of test reliability and can impact the accuracy of the results. In order to assess precision, multiple tests are performed on the same sample and the results are compared. A test with high precision will produce similar results each time it is performed, while a test with low precision will produce inconsistent results. It is important to consider precision when interpreting test results and making clinical decisions.
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This question is part of the following fields:
- General Principles
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Question 21
Incorrect
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A 50-year-old woman presents to the Emergency Department with a several-hour history of excruciating pain in the left knee. Her medical history is significant for hypertension and a previous episode of gout. She takes amlodipine.
On examination, she is in severe pain and the left knee is swollen, red, warm and tender. Arthroscopic evaluation of the synovial fluid aspirate showed monosodium crystals that are negatively birefringent under polarized light. A diagnosis of recurrent gout is made and ultimately the patient is commenced on prophylaxis using allopurinol.
What is the mechanism of action of allopurinol?Your Answer: Inhibits dihydrofolate reductase
Correct Answer: Inhibits xanthine oxidase
Explanation:Allopurinol is a medication that inhibits xanthine oxidase, which is used for gout prophylaxis. By blocking the conversion of hypoxanthine to xanthine and xanthine to uric acid, it reduces the levels of uric acid in the blood. The other options, such as inhibition of dihydrofolate reductase, ribonucleotide reductase, and thymidylate synthase, are not related to gout prophylaxis. Rasburicase, which oxidizes urate to allantoin, is also used for gout prophylaxis, but it works differently than allopurinol.
Allopurinol can interact with other medications such as azathioprine, cyclophosphamide, and theophylline. It can lead to high levels of 6-mercaptopurine when used with azathioprine, reduced renal clearance when used with cyclophosphamide, and an increase in plasma concentration of theophylline. Patients at a high risk of severe cutaneous adverse reaction should be screened for the HLA-B *5801 allele.
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This question is part of the following fields:
- General Principles
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Question 22
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A 65-year-old woman comes to your clinic with symptoms of depression, weight gain, and dry skin. You suspect that she might be experiencing hypothyroidism.
What is the origin of the organ responsible for her symptoms, from an embryological perspective?Your Answer: Endoderm
Explanation:The thyroid, parathyroid, and thymus glands are all derived from the endodermal layer of the germ layer. Conversely, the ectoderm gives rise to the nails and lens of the eye, while the neural crest tissue is responsible for the development of the nervous system. Finally, the mesoderm is responsible for the formation of muscle and connective tissues.
Embryological Layers and Their Derivatives
Embryonic development involves the formation of three primary germ layers: ectoderm, mesoderm, and endoderm. Each layer gives rise to specific tissues and organs in the developing embryo. The ectoderm forms the surface ectoderm, which gives rise to the epidermis, mammary glands, and lens of the eye, as well as the neural tube, which gives rise to the central nervous system (CNS) and associated structures such as the posterior pituitary and retina. The neural crest, which arises from the neural tube, gives rise to a variety of structures including autonomic nerves, cranial nerves, facial and skull bones, and adrenal cortex. The mesoderm gives rise to connective tissue, muscle, bones (except facial and skull), and organs such as the kidneys, ureters, gonads, and spleen. The endoderm gives rise to the epithelial lining of the gastrointestinal tract, liver, pancreas, thyroid, parathyroid, and thymus.
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This question is part of the following fields:
- General Principles
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Question 23
Incorrect
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Can you reorder the different types of research studies in their correct hierarchy according to their level of evidence, starting with the highest level on top and the lowest level at the bottom? Many individuals can easily remember that the top of the hierarchy is the systematic review and the bottom is the case-series, but it can be difficult to recall the order of the middle levels.
Your Answer: Systematic review of RCTs, RCTs, case-control, cross-sectional, cohort, case-series
Correct Answer: Systematic review of RCTs, RCTs, cohort, case-control, cross-sectional, case-series
Explanation:Levels and Grades of Evidence in Evidence-Based Medicine
In order to evaluate the quality of evidence in evidence-based medicine, levels or grades are often used to organize the evidence. Traditional hierarchies placed systematic reviews or randomized control trials at the top and case-series/report at the bottom. However, this approach is overly simplistic as certain research questions cannot be answered using RCTs. To address this, the Oxford Centre for Evidence-Based Medicine introduced their 2011 Levels of Evidence system which separates the type of study questions and gives a hierarchy for each. On the other hand, the GRADE system is a grading approach that classifies the quality of evidence as high, moderate, low, or very low. The process begins by formulating a study question and identifying specific outcomes. Outcomes are then graded as critical or important, and the evidence is gathered and criteria are used to grade the evidence. Evidence can be promoted or downgraded based on certain circumstances. The use of levels and grades of evidence helps to evaluate the quality of evidence and make informed decisions in evidence-based medicine.
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This question is part of the following fields:
- General Principles
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Question 24
Incorrect
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A 19-year-old male is hospitalized due to haemoptysis and reports a recent change in urine color to brown. Upon examination, his blood pressure is found to be 170/110. A kidney biopsy confirms the diagnosis of Goodpasture's syndrome through positive staining for autoantibodies. What type of collagen is targeted by the patient's autoantibodies?
Your Answer: Collagen type 3
Correct Answer: Collagen type 4
Explanation:Autoantibodies against collagen type IV are responsible for the development of Goodpasture’s syndrome, which is characterized by defective collagen IV. Meanwhile, Ehlers-Danlos syndrome is primarily caused by a genetic defect in collagen type III, with a less common variant affecting collagen type V. Osteogenesis imperfecta, on the other hand, is characterized by defective collagen type I.
Understanding Collagen and its Associated Disorders
Collagen is a vital protein found in connective tissue and is the most abundant protein in the human body. Although there are over 20 types of collagen, the most important ones are types I, II, III, IV, and V. Collagen is composed of three polypeptide strands that are woven into a helix, with numerous hydrogen bonds providing additional strength. Vitamin C plays a crucial role in establishing cross-links, and fibroblasts synthesize collagen.
Disorders of collagen can range from acquired defects due to aging to rare congenital disorders. Osteogenesis imperfecta is a congenital disorder that has eight subtypes and is caused by a defect in type I collagen. Patients with this disorder have bones that fracture easily, loose joints, and other defects depending on the subtype. Ehlers Danlos syndrome is another congenital disorder that has multiple subtypes and is caused by an abnormality in types 1 and 3 collagen. Patients with this disorder have features of hypermobility and are prone to joint dislocations and pelvic organ prolapse, among other connective tissue defects.
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This question is part of the following fields:
- General Principles
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Question 25
Incorrect
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A team of researchers conducts a study to assess the safety of a new medication for lowering cholesterol levels. One thousand participants are randomly divided into two groups, with 500 individuals in each group, and given either the medication or a placebo. The researchers find that acute myositis is more common in those who received the medication than in those who received the placebo, and the difference is statistically significant (p = 0.03).
What is the most precise interpretation of these findings?Your Answer: The study has insufficient power to reach any conclusion
Correct Answer: There is a 3% probability that the result is obtained by chance
Explanation:The study found a significant difference between the groups and concluded that the new hypolipidaemic drug increases the risk of developing acute myositis. However, it is unclear what the incidence of this side effect is with the drug as the question did not provide information on how many patients developed acute myositis in each group. The p value of 0.03 indicates that there is a three percent probability of obtaining the observed result by chance, assuming the null hypothesis is true.
Significance tests are used to determine the likelihood of a null hypothesis being true. The null hypothesis states that two treatments are equally effective, while the alternative hypothesis suggests that there is a difference between the two treatments. The p value is the probability of obtaining a result by chance that is at least as extreme as the observed result, assuming the null hypothesis is true. Two types of errors can occur during significance testing: type I, where the null hypothesis is rejected when it is true, and type II, where the null hypothesis is accepted when it is false. The power of a study is the probability of correctly rejecting the null hypothesis when it is false, and it can be increased by increasing the sample size.
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This question is part of the following fields:
- General Principles
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Question 26
Incorrect
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Which statistical measure would be most helpful in order to reassure a 60-year-old patient who has received a negative test result?
Your Answer: Sensitivity
Correct Answer: Negative predictive value
Explanation:Precision refers to the consistency of a test in producing the same results when repeated multiple times. It is an important aspect of test reliability and can impact the accuracy of the results. In order to assess precision, multiple tests are performed on the same sample and the results are compared. A test with high precision will produce similar results each time it is performed, while a test with low precision will produce inconsistent results. It is important to consider precision when interpreting test results and making clinical decisions.
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This question is part of the following fields:
- General Principles
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Question 27
Incorrect
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A 30-year-old man with a history of HIV and intravenous drug use presents with abnormal liver function tests. PCR testing confirms chronic hepatitis C virus infection. How would you describe this virus?
Your Answer: Positive (+) sense single-stranded RNA (ssRNA) hepatovirus
Correct Answer: Positive (+) sense single-stranded RNA (ssRNA) flavivirus
Explanation:Hepatitis C is a virus that is expected to become a significant public health issue in the UK in the coming years, with around 200,000 people believed to be chronically infected. Those at risk include intravenous drug users and individuals who received a blood transfusion before 1991, such as haemophiliacs. The virus is an RNA flavivirus with an incubation period of 6-9 weeks. Transmission can occur through needle stick injuries, vertical transmission from mother to child, and sexual intercourse, although the risk is relatively low. There is currently no vaccine for hepatitis C.
After exposure to the virus, only around 30% of patients will develop symptoms such as a transient rise in serum aminotransferases, jaundice, fatigue, and arthralgia. HCV RNA is the preferred diagnostic test for acute infection, although patients who spontaneously clear the virus will continue to have anti-HCV antibodies. Chronic hepatitis C is defined as the persistence of HCV RNA in the blood for 6 months and can lead to complications such as rheumatological problems, cirrhosis, hepatocellular cancer, and cryoglobulinaemia.
The management of chronic hepatitis C depends on the viral genotype and aims to achieve sustained virological response (SVR), defined as undetectable serum HCV RNA six months after the end of therapy. Interferon-based treatments are no longer recommended, and a combination of protease inhibitors with or without ribavirin is currently used. However, these treatments can have side effects such as haemolytic anaemia, cough, flu-like symptoms, depression, fatigue, leukopenia, and thrombocytopenia. Women should not become pregnant within 6 months of stopping ribavirin as it is teratogenic.
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This question is part of the following fields:
- General Principles
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Question 28
Incorrect
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You are preparing a presentation on cell cycle for the biology students allocated to you. You have created a table to compare the different stages of the cell cycle. A template of the table is shown below:
Stage Important points to note
G0
G1
S
G2
Mitosis
Which one of the following notes should be added to the notes section for mitosis?Your Answer: Resting phase of the cycle
Correct Answer: Shortest phase of the cell cycle
Explanation:The cell cycle consists of various stages, with mitosis being the briefest. The resting phase is known as G0, while the length of the cycle is determined by G1. The interphase is the longest phase, and centrosome duplication takes place during DNA synthesis.
The Cell Cycle and its Regulation
The cell cycle is a process that regulates the growth and division of cells. It is controlled by proteins called cyclins, which in turn regulate cyclin-dependent kinase (CDK) enzymes. The cycle is divided into four phases: G0, G1, S, G2, and M. During the G0 phase, cells are in a resting state, while in G1, cells increase in size and determine the length of the cell cycle. Cyclin D/CDK4, Cyclin D/CDK6, and Cyclin E/CDK2 regulate the transition from G1 to S phase. In the S phase, DNA, RNA, and histones are synthesized, and centrosome duplication occurs. Cyclin A/CDK2 is active during this phase. In G2, cells continue to increase in size, and Cyclin B/CDK1 regulates the transition from G2 to M phase. Finally, in the M phase, mitosis occurs, which is the shortest phase of the cell cycle. The cell cycle is regulated by various proteins, including p53, which plays a crucial role in the G1 phase. Understanding the regulation of the cell cycle is essential for the development of new treatments for diseases such as cancer.
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This question is part of the following fields:
- General Principles
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Question 29
Incorrect
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A 32-year-old woman visits her primary care physician complaining of dysuria and frequency that has been getting worse over the past 4 days. She reports an unusual odor in her urine but denies experiencing any flank pain, nausea, or vomiting. The physician performs a urine dip and finds leukocyte++ and nitrite++. A urine culture is ordered to ensure appropriate antibiotic treatment in accordance with good microbiological stewardship. What is accurate regarding the probable causative agent?
Your Answer: Diplococci
Correct Answer: Gram negative
Explanation:The symptoms exhibited by this woman are indicative of a typical urinary tract infection.
Enteric bacteria, particularly E. coli, are the most frequent culprits behind UTIs.
Escherichia coli: A Common Gut Commensal with Various Disease Manifestations
Escherichia coli is a type of Gram-negative rod that is commonly found in the gut as a normal commensal. It is a facultative anaerobe and can ferment lactose. However, E. coli infections can lead to various diseases in humans, including diarrhoeal illnesses, urinary tract infections (UTIs), and neonatal meningitis. The classification of E. coli is based on the antigens that can trigger an immune response. These antigens include the lipopolysaccharide layer (O), capsule (K), and flagellin (H). For instance, neonatal meningitis caused by E. coli is usually due to a serotype that contains the capsular antigen K-1.
One particular strain of E. coli, O157:H7, is associated with severe, haemorrhagic, watery diarrhoea. It has a high mortality rate and can lead to haemolytic uraemic syndrome. This strain is often transmitted through contaminated ground beef. Despite being a common gut commensal, E. coli can cause various diseases that can be life-threatening. Therefore, proper hygiene and food safety practices are essential in preventing E. coli infections.
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This question is part of the following fields:
- General Principles
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Question 30
Incorrect
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A 23-year-old man is brought to the emergency department by his roommate after experiencing difficulty speaking and breathing for the past hour. The man had recently returned from a one-week vacation and had been feeling well. Before heading out for his regular Saturday football game, he had some homemade pineapple jam. The man has no significant medical history and has not been hospitalized recently. There is no significant family history. The attending physician recognizes the condition and begins treatment immediately. The emergency medicine resident explains the situation to the roommate. What is the most likely mechanism that has been affected in this patient?
Your Answer: Opening of voltage-gated calcium channels
Correct Answer: Release of the acetylcholine at the neuromuscular junction
Explanation:The symptoms presented by this man are consistent with a diagnosis of Clostridium botulinum toxicity, which occurs when contaminated food is ingested. The bacteria responsible for this condition, Clostridium botulinum, thrive in the anaerobic environment of home-canned food. The toxin produced by these bacteria prevents the release of acetylcholine at the neuromuscular junction, resulting in neuromuscular impairment.
1: The Clostridium botulinum toxin does not affect the muscarinic or nicotinic acetylcholine receptors. Autoantibodies to the muscarinic receptors are responsible for the destruction of these receptors in myasthenia gravis.
2: The spread of depolarization along the myelinated axon at the nodes of Ranvier is not affected by the Clostridium botulinum toxin.
3: The influx of calcium ions into the presynaptic terminal through voltage-gated calcium channels triggers the release of neurotransmitter into the synaptic cleft. Autoantibodies to these calcium channels are responsible for the Lambert-Eaton myasthenic syndrome.
4: The Clostridium botulinum toxin prevents the release of acetylcholine by cleaving the SNARE protein complex, which is necessary for the fusion of the pre-formed synaptic vesicles with the presynaptic membrane.
5: The process of loading, docking, priming, fusion, and endocytosis of synaptic vesicles is not affected by the Clostridium botulinum toxin.Understanding Botulism: Causes, Symptoms, and Treatment
Botulism is a rare but serious illness caused by the bacterium Clostridium botulinum. This gram-positive anaerobic bacillus produces botulinum toxin, a neurotoxin that blocks the release of acetylcholine, leading to flaccid paralysis and other symptoms. There are seven serotypes of the bacterium, labeled A-G. Botulism can result from eating contaminated food, particularly tinned food, or from intravenous drug use.
The neurotoxin produced by Clostridium botulinum often affects bulbar muscles and the autonomic nervous system. Symptoms of botulism include diplopia, ataxia, and bulbar palsy. Patients are usually fully conscious with no sensory disturbance, but they experience flaccid paralysis.
Treatment for botulism involves administering botulism antitoxin and providing supportive care. However, the antitoxin is only effective if given early, as once the toxin has bound, its actions cannot be reversed. Therefore, it is important to seek medical attention immediately if botulism is suspected.
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