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  • Question 1 - A 48-year-old man is diagnosed with diffuse large B-cell lymphoma and is started...

    Incorrect

    • A 48-year-old man is diagnosed with diffuse large B-cell lymphoma and is started on chemotherapy. Two days following his first treatment session, he presents to the A&E with nausea, vomiting, and myalgia. On examination, he appears clinically dehydrated. A diagnosis of tumour lysis syndrome (TLS) is suspected. Which of the following would be consistent with the diagnosis of TLS?

      Your Answer: Low phosphate

      Correct Answer: Low corrected calcium

      Explanation:

      Out of the aforementioned markers, low corrected calcium is the only biochemistry result consistent with the diagnosis. All of the other markers are elevated in TLS.

      TLS is a potentially fatal condition occurring as a complication during the treatment of high-grade lymphomas and leukaemias. It occurs from the simultaneous breakdown (lysis) of the tumour cells and subsequent release of chemicals into the bloodstream. This leads to hyperkalaemia and hyperphosphatemia in the presence of hyponatraemia. As phosphate precipitates calcium, the serum concentration of calcium becomes low. TLS can occur in the absence of chemotherapy, but it is usually triggered by the introduction of combination chemotherapy. Awareness of the condition is critical for its prophylactic management.

      Patients at high risk of TLS should be given IV rasburicase or IV allopurinol immediately prior to and during the first few days of chemotherapy. Rasburicase is a recombinant version of urate oxidase which is an enzyme that metabolizes uric acid to allantoin. Allantoin is much more water soluble than uric acid and is therefore more easily excreted by the kidneys. Patients in lower-risk groups
      should be given oral allopurinol during cycles of chemotherapy in an attempt to avoid the condition.

      TLS is graded according to the Cairo-Bishop scoring system as:
      1. Laboratory tumour lysis syndrome
      2. Clinical tumour lysis syndrome

    • This question is part of the following fields:

      • Haematology & Oncology
      26.8
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  • Question 2 - A 66-year-old baker presents to the oncology clinic with six-month history of weight...

    Incorrect

    • A 66-year-old baker presents to the oncology clinic with six-month history of weight loss and anorexia. Tumour marker profile shows an elevated level of bombesin. Out of the following, which is the most likely cancer to account for this result?

      Your Answer: Lymphoma

      Correct Answer: Small cell lung carcinoma

      Explanation:

      Bombesin is a tumour marker elevated in small cell lung carcinomas, as well as in gastric carcinomas and retinoblastomas.

      Tumour markers can be divided into:
      1. Monoclonal antibodies
      CA 125: Ovarian cancer, primary peritoneal cancer
      CA 19-9: Pancreatic cancer
      CA 15-3: Breast cancer

      2. Tumour specific antigens
      Prostate specific antigen (PSA): Prostatic carcinoma
      Alpha-feto protein (AFP): Hepatocellular carcinoma, teratoma
      Carcinoembryonic antigen (CEA): Colorectal cancer
      S-100: Melanoma, schwannomas
      Bombesin: Small cell lung carcinoma, gastric cancer

      3. Enzymes
      Alkaline phosphatase (ALP)
      Neuron specific enolase (NSE)

      4. Hormones
      Calcitonin
      Antidiuretic hormone (ADH)
      Human chorionic gonadotropin (hCG)

    • This question is part of the following fields:

      • Haematology & Oncology
      32.4
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  • Question 3 - A 60-year-old man has been admitted with dehydration following an attack of gastritis....

    Correct

    • A 60-year-old man has been admitted with dehydration following an attack of gastritis. His initial blood results revealed raised calcium and erythrocyte sedimentation rate (ESR). He has a history of hypertension, angina, chronic obstructive pulmonary disease (COPD), and diabetes. His most recent results have arrived on the ward, showing: Hb: 13.8 g/dL, WCC: 7.7 x 10^9/L, Plts: 212 x 10^9/L, Na+: 138 mmol/L, K+: 4.7 mmol/L, Ca+2: 2.4 mmol/L, Urea: 7.2 mmol/L, Creatinine: 104 mmol/L, Albumin: 38 g/L, IgG: 24 g/L (6.0-13.0), IgA: 2.1 g/L (0.8-3.0), IgM: 1.3 g/L (0.4-2.5). Trace amounts of Bence Jones protein have also been detected in the urine. CXR shows normal heart and mediastinal contours, clear lungs bilaterally, osteopenia of the bony skeleton with no lytic lesions. What is the most likely diagnosis?

      Your Answer: Monoclonal gammopathy of undetermined significance

      Explanation:

      Monoclonal gammopathy of undetermined significance (MGUS)—also known as benign paraproteinemia and monoclonal gammopathy—is a pre-malignant condition not necessarily leading to its malignant form—multiple myeloma. MGUS causes increase of a serum monoclonal protein (M protein). It is not associated with ostealgia or increased risk of infections. It is often mistaken for multiple myeloma, differing from the latter in, no immunosuppression, anaemia, hypercalcaemia, lytic bone lesions, or renal failure; normal levels of beta-2 microglobulin; and stable lower levels of paraproteinemia.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 4 - A 25-year-old man having sickle cell anaemia presents with headache, lethargy, and pallor....

    Correct

    • A 25-year-old man having sickle cell anaemia presents with headache, lethargy, and pallor. His blood count shows: Haemoglobin: 4.6 g/dL, Reticulocytes: 3%. Infection with parvovirus is suspected. Out of the following, what is the most likely diagnosis?

      Your Answer: Aplastic crisis

      Explanation:

      Sickle cell anaemia is characterised by periods of good health with intervening crises. One of the main types is aplastic crisis characterised by a sudden fall in haemoglobin without marked reticulocytosis (3%—in this case—is just above the normal range). It usually occurs secondary to parvovirus infection.

      The other main types of sickle cell crises are thrombotic crisis (painful or vaso-occlusive crisis), sequestration crisis, and haemolytic crisis. Thrombotic crisis is precipitated by infection, dehydration, alcohol, change in temperature, and deoxygenation. Sequestration crisis is characterised by acute chest syndrome (i.e. fever, dyspnoea, chest/rib pain, low pO2, and pulmonary infiltrates). In haemolytic crisis, fall in haemoglobin occurs secondary to haemolysis. It is a rare type of sickle cell crises.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 5 - Out of the following, which is not associated with polycythaemia vera? ...

    Incorrect

    • Out of the following, which is not associated with polycythaemia vera?

      Your Answer: Splenomegaly

      Correct Answer: Raised ESR

      Explanation:

      Polycythaemia vera (PV) is associated with a low ESR.

      PV, also known as polycythaemia rubra vera, is a myeloproliferative disorder caused by clonal proliferation of marrow stem cells leading to an increase in red cell volume, often accompanied by overproduction of neutrophils and platelets. It has peak incidence in the sixth decade of life, with typical features including hyperviscosity, pruritus, splenomegaly, haemorrhage (secondary to abnormal platelet function), and plethoric appearance. PV is associated with a low ESR.

      Some management options of PV include lose-dose aspirin, venesection (first-line treatment), hydroxyurea (slightly increased risk of secondary leukaemia), and radioactive phosphorus (P-32) therapy.

      In PV, thrombotic events are a significant cause of morbidity and mortality. 5–15% of the cases progress to myelofibrosis or acute myeloid leukaemia (AML). The risk of having AML is increased with chemotherapy treatment.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 6 - A 25-year-old female presents to the acute medical unit with several lumps in...

    Correct

    • A 25-year-old female presents to the acute medical unit with several lumps in her neck and under her arms, weight loss, vomiting, and low mood. She is investigated and is found to have several areas of suspicious lymphadenopathy including in the neck, both axillae, and mediastinum. She also has multiple lesions in her liver which are confirmed to be the manifestations of Hodgkin lymphoma after biopsy. Which stage of the disease is the patient currently at?

      Your Answer: IV

      Explanation:

      The patient is on stage IV according to the Ann Arbor staging system for Hodgkin lymphoma (HL). The disease has spread beyond the lymph nodes into the liver (involvement of extra lymphatic organ).

      HL is a malignant proliferation of lymphocytes characterised by the presence of distinctive giant cells known as Reed-Sternberg cells. It has a bimodal age distribution being most common in the third and seventh decades of life.

      Staging of HL is done according to the Ann Arbor staging system:
      Stage
      I: Single lymph node region (I) or one extra lymphatic site (IE)

      II: Two or more lymph node regions on same side of the diaphragm (II) or local extra lymphatic extension plus one or more lymph node regions on same side of the diaphragm (IIE)

      III: Lymph node regions on both sides of the diaphragm (III) which may be accompanied by local extra lymphatic extension (IIIE)

      IV: Diffuse involvement of one or more extra lymphatic organs or sites

      Suffix
      A: No B symptoms

      B: Presence of at least one of the following: unexplained weight loss >10% baseline during 6 months before staging; recurrent unexplained fever >38°C; recurrent night sweats

    • This question is part of the following fields:

      • Haematology & Oncology
      37.8
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  • Question 7 - A 33-year-old man presents with recurrent episodes of abdominal pain associated with weakness...

    Incorrect

    • A 33-year-old man presents with recurrent episodes of abdominal pain associated with weakness of his arms and legs. Which one of the following urine tests would best indicate lead toxicity?

      Your Answer: Ham test

      Correct Answer: Coproporphyrin

      Explanation:

      Lead poisoning is characterised by abdominal pain, fatigue, constipation, peripheral neuropathy (mainly motor), and blue lines on gum margin in 20% of the adult patients (very rare in children).

      For diagnosis, the level of lead in blood is usually considered with levels greater than 10 mcg/dL being significant. Furthermore, the blood film shows microcytic anaemia and basophilic stippling of red blood cells. Urinary coproporphyrin is increased (urinary porphobilinogen and uroporphyrin levels are normal to slightly increased). Raised serum and urine levels of delta-aminolaevulinic acid may also be seen, making it sometimes difficult to differentiate from acute intermittent porphyria.

    • This question is part of the following fields:

      • Haematology & Oncology
      66.4
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  • Question 8 - An 86-year-old male patient has been diagnosed with monoclonal gammopathy of undetermined significance....

    Incorrect

    • An 86-year-old male patient has been diagnosed with monoclonal gammopathy of undetermined significance. He is eager to know its relation to his future health. Which of the following statements is correct?

      Your Answer: 60% of patients with MGUS will develop Waldenstrom's macroglobulinaemia during their lifetime

      Correct Answer: 10% of patients with MGUS go on to develop myeloma over 10 years

      Explanation:

      Monoclonal gammopathy of undetermined significance (MGUS, also known as benign paraproteinemia and monoclonal gammopathy) is a pre-malignant condition not necessarily leading to its malignant form—multiple myeloma. Around 10% of patients eventually develop myeloma over 10 years, with 50% at 15 years. MGUS causes paraproteinemia and is usually asymptomatic. It is not associated with ostealgia or increased risk of infections. It is often mistaken for multiple myeloma, differing from the latter in, no immunosuppression, normal levels of beta-2 microglobulin, and stable lower levels of paraproteinemia.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 9 - A 50-year-old female patient is started on cyclophosphamide for vasculitis associated with Wegener's...

    Correct

    • A 50-year-old female patient is started on cyclophosphamide for vasculitis associated with Wegener's granulomatosis. Which of the following adverse effects is most characteristically associated with cyclophosphamide use?

      Your Answer: Haemorrhagic cystitis

      Explanation:

      Cyclophosphamide is a cytotoxic alkylating agent that acts by causing cross-linking of DNA strands. Its major adverse effects include haemorrhagic cystitis, myelosuppression, and transitional cell carcinoma.

      Cardiomyopathy is caused by doxorubicin and ototoxicity is caused by cisplatin. Alopecia and weight gain are associated with a variety of chemotherapeutic agents especially those that treat breast cancers (e.g. paclitaxel).

    • This question is part of the following fields:

      • Haematology & Oncology
      26.8
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  • Question 10 - A 24-year-old smoker with testicular cancer presents with exertional dyspnoea, wheezing, and persistent...

    Correct

    • A 24-year-old smoker with testicular cancer presents with exertional dyspnoea, wheezing, and persistent non-productive cough. He completed a course of chemotherapy comprising of cisplatin, bleomycin, and etoposide three months ago. On examination, there are fine bilateral basal crackles. Which of the following is the most likely diagnosis?

      Your Answer: Bleomycin toxicity

      Explanation:

      The cytotoxic drug bleomycin can cause bleomycin-induced pneumonitis (BIP). It usually occurs during chemotherapy but can also occur up to six months post-therapy.

    • This question is part of the following fields:

      • Haematology & Oncology
      28.7
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  • Question 11 - What is the mechanism of action (MOA) of cisplatin? ...

    Incorrect

    • What is the mechanism of action (MOA) of cisplatin?

      Your Answer: Inhibits formation of microtubules

      Correct Answer: Causes cross-linking in DNA

      Explanation:

      Cisplatin is a cytotoxic agent that acts by causing cross-linking in DNA. Its adverse effects include ototoxicity, peripheral neuropathy, hypomagnesaemia, etc.

      The causative cytotoxic agents acting through the other aforementioned MOAs are as follows:

      1. Doxorubicin: Stabilizes DNA topoisomerase II complex and inhibits DNA and RNA synthesis.

      2. Hydroxyurea (hydroxycarbamide): Inhibits ribonucleotide reductase, decreasing DNA synthesis.

      3. Mercaptopurine (6-MP): Purine analogue that is activated by HGPRTase, decreasing purine synthesis.

      4. Vincristine, vinblastine: Inhibits formation of microtubules.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 12 - A 4-year-old girl is diagnosed with acute lymphoblastic leukaemia after presenting with lethargy...

    Correct

    • A 4-year-old girl is diagnosed with acute lymphoblastic leukaemia after presenting with lethargy and easy bruising. Which of the following is a marker of a bad prognosis in this disease?

      Your Answer: Philadelphia chromosome positive

      Explanation:

      Philadelphia translocation, t(9;22), is a marker of poor prognosis in acute lymphoblastic leukaemia (ALL).

      ALL is the malignancy of lymphoid progenitor cells affecting B or T cell lineage. This results in the arrest of lymphoid cell maturation and proliferation of immature blast cells (lymphoblasts), leading to bone marrow and tissue infiltration.

      ALL is the most common type of childhood cancers. Its peak incidence is between two to three years of age.

      Acute B lymphoblastic leukaemia (B-ALL) is the most common type of ALL, involving overproduction of B-cell lymphoblasts. It is manifested by low initial WCC and is associated with a good prognosis.

      Poor prognostic factors for ALL include:
      1. Pre-B cell or T-cell ALL (T-ALL)
      2. Philadelphia translocation, t(9;22)
      3. Age <2 years or >10 years
      4. Male sex
      5. CNS involvement
      6. High initial WBC (e.g. >100 x 10^9/L)
      7. non-Caucasian

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 13 - A 58-year-old female patient is being investigated for breathlessness, cough, and severe weight...

    Correct

    • A 58-year-old female patient is being investigated for breathlessness, cough, and severe weight loss. On the medical ward round, her CXR is reviewed showing hilar lymphadenopathy and multiple peripheral lung metastases. Which of the following tumours is least likely to be the underlying cause of this lung appearance?

      Your Answer: Brain

      Explanation:

      All of the aforementioned listed tumours, except brain tumours, can metastasise to lungs and produce the typical CXR picture consisting of hilar lymphadenopathy with either diffuse multinodular shadows resembling miliary disease or multiple large well-defined masses (canon balls). Occasionally, cavitation or calcification may also be seen.

      Most brain tumours, however, do not metastasise. Some, derived form neural elements, do so but in these cases, intraparenchymal metastases generally precede distant haematogenous spread.

    • This question is part of the following fields:

      • Haematology & Oncology
      28.2
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  • Question 14 - A 70-year-old male patient presents to the urology clinic with a one-month history...

    Incorrect

    • A 70-year-old male patient presents to the urology clinic with a one-month history of passing frank haematuria. Flexible cystoscopy shows a mass of the bladder wall and biopsy reveals transitional cell carcinoma. Out of the following, which industry has he most likely worked in?

      Your Answer: Rubber industry

      Correct Answer: Dyestuffs and pigment manufacture

      Explanation:

      Exposure to aniline dyes is a risk factor for transitional cell carcinoma. Aniline dyes are used in dyestuffs and pigment manufacturing.

      The other aforementioned options are ruled out because:
      1. Feed production may expose to aflatoxin (hepatocellular carcinoma).

      2. Being a military personnel may expose to mustard gas (lung cancer).

      3. Rubber industry may expose to nitrosamines (oesophageal and gastric cancer).

      4. Refrigerant production before 1974 may expose to vinyl chloride (hepatic angiosarcoma).

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 15 - A 56-year-old man, on the acute oncology ward, is a known case of...

    Correct

    • A 56-year-old man, on the acute oncology ward, is a known case of colorectal cancer. He was diagnosed one month ago after participating in a screening test—faecal occult blood test. Following the positive test result, colonoscopy was performed demonstrating a malignant lesion in the descending colon. CT staging showed lymph node involvement but no distant metastases. The patient has undergone a left hemicolectomy and is due to start adjuvant chemotherapy with a combination of fluorouracil (5-FU) and oxaliplatin. During his work-up, his consultant had explained that he would need to be monitored for disease recurrence. Which of the following is important in monitoring the disease activity in colorectal cancer?

      Your Answer: Carcinoembryonic Antigen (CEA)

      Explanation:

      Carcinoembryonic antigen (CEA) is a known tumour marker for colorectal cancer. It is not used diagnostically, but in patients with a known diagnosis of colorectal cancer associated with raised CEA levels, it can be used to monitor disease activity and help with the early identification of disease recurrence.

      Tumour markers can be divided into:
      1. Monoclonal antibodies
      CA 125: Ovarian cancer, primary peritoneal cancer
      CA 19-9: Pancreatic cancer
      CA 15-3: Breast cancer

      2. Tumour specific antigens
      Prostate specific antigen (PSA): Prostatic carcinoma
      Alpha-feto protein (AFP): Hepatocellular carcinoma, teratoma
      Carcinoembryonic antigen (CEA): Colorectal cancer
      S-100: Melanoma, schwannomas
      Bombesin: Small cell lung carcinoma, gastric cancer

      3. Enzymes
      Alkaline phosphatase (ALP)
      Neuron specific enolase (NSE)

      4. Hormones
      Calcitonin
      Antidiuretic hormone (ADH)
      Human chorionic gonadotropin (hCG)

    • This question is part of the following fields:

      • Haematology & Oncology
      44.5
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  • Question 16 - A 46-year-old nurse presents with a short history of epistaxis and bleeding gums....

    Correct

    • A 46-year-old nurse presents with a short history of epistaxis and bleeding gums. Her complete blood count, coagulation profile, and blood film are requested. The results are as follows: Hb: 8.6 g/dL, WCC: 2.3 x 10^9/L, Plts: 18 x 10^9/L, Coagulation profile: deranged, Blood film: bilobed large mononuclear cells. What is the most likely diagnosis?

      Your Answer: Acute myeloid leukaemia

      Explanation:

      This is a picture of bone marrow failure secondary to acute myeloid leukaemia (AML). AML is the acute expansion of the myeloid stem line, which may occur as a primary disease or follow the secondary transformation of a myeloproliferative disorder. It is more common over the age of 45 and is characterized by signs and symptoms largely related to bone marrow failure such as anaemia (pallor, lethargy), frequent infections due to neutropenia (although the total leucocyte count may be very high), thrombocytopaenia (bleeding), ostealgia, and splenomegaly.

      The disease has poor prognosis if:
      1. Age of the patient >60 years
      2. >20% blasts seen after the first course of chemotherapy
      3. Chromosomal aberration with deletion of part of chromosome 5 or 7.

      Acute promyelocytic leukaemia (APL) is an aggressive form of AML.

      Other listed options are ruled out because:
      1. Von Willebrand disease: may present with epistaxis and bleeding gums in severe cases but rarely with abnormalities on blood results.

      2. Acute lymphoblastic leukaemia: mostly seen in children.

      3. Lymphoma: usually presents with rubbery enlargement of lymph nodes.

      4. Warfarin overdose: no bilobed large mononuclear cells seen on blood film.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 17 - A 65-year-old male patient is found to have an elevated serum paraprotein level...

    Correct

    • A 65-year-old male patient is found to have an elevated serum paraprotein level of 35g/L. Bone marrow aspirate reveals 32% monoclonal plasma cell infiltrate. He has no evidence of anaemia, renal impairment, hypercalcaemia, or lytic lesions. What should be the next step in management?

      Your Answer: Observe and monitor

      Explanation:

      The patient is asymptomatic but matches the diagnostic criteria for multiple myeloma (MM). Therefore, the underlying diagnosis of this condition is smouldering multiple myeloma (SMM). SMM is an early precursor to MM. Its treatment is typically to watch and wait.

      MM is a neoplasm of the bone marrow plasma cells. Peak incidence is in patients aged 60–70 years.

      Clinical features of MM include:
      1. Ostealgia, osteoporosis, pathological fractures (typically vertebral), and osteolytic lesions
      2. Lethargy
      3. Infections
      4. Hypercalcaemia
      5. Renal failure
      6. Other features: amyloidosis e.g. macroglossia, carpal tunnel syndrome; neuropathy; hyperviscosity

      Diagnosis of MM is based on the confirmation of (a) one major criterion and one minor criterion or (b) three minor criteria in an individual who has signs or symptoms of multiple myeloma.

      Major criteria:
      1. >30% plasma cells on bone marrow biopsy
      2. Monoclonal band of paraprotein on electrophoresis: >35g/L for IgG, 20g/L for IgA, or >1g of light chains excreted in the urine per day

      Minor criteria:
      1. 10–30% plasma cells on bone marrow biopsy
      2. Abnormal monoclonal band but levels less than listed above
      3. Lytic bone lesions observed radiographically
      4. Immunosuppression

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 18 - A 51-year-old man was admitted with right-sided hemiparesis and right upper motor neurone...

    Correct

    • A 51-year-old man was admitted with right-sided hemiparesis and right upper motor neurone facial nerve palsy. He was known to be on warfarin for a mitral valve replacement and had been adequately anticoagulated. He was also taking furosemide and had recently been started on St John’s wort for low mood. On examination, his pulse was 90 bpm and regular, and his blood pressure was 150/80 mmHg. Cardiac examination demonstrated normal prosthetic valve sounds with an ejection systolic murmur at the left sternal edge. CT scan showed evidence of a left middle cerebral artery infarction. What is the possible explanation for the presentation?

      Your Answer: St John’s wort reduces the activity of warfarin

      Explanation:

      St John’s wort interferes with warfarin by increasing its breakdown and decreasing its effectiveness. This leads to the need for adjustment in the dose of warfarin and careful attention to monitoring if the patient decides to continue with the drug. Ideally, an alternative antidepressant should also be considered.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 19 - A 62-year-old man presents with haematuria. Cystoscopy is carried out which reveals transitional...

    Correct

    • A 62-year-old man presents with haematuria. Cystoscopy is carried out which reveals transitional cell carcinoma of the bladder. Occupational exposure to which of the following is a recognised risk factor for bladder cancer?

      Your Answer: Aniline dye

      Explanation:

      The risk factors for bladder cancer are:

      1. Smoking
      2. Exposure to aniline dyes in the printing and textile industry
      3. Exposure to rubber manufacturing
      4. Cyclophosphamides
      5. Schistosomiasis.

    • This question is part of the following fields:

      • Haematology & Oncology
      15.2
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  • Question 20 - A 32-year-old woman was diagnosed with Hodgkin disease 8 years ago. She was...

    Incorrect

    • A 32-year-old woman was diagnosed with Hodgkin disease 8 years ago. She was treated with radiotherapy which led to complete remission. What is the most likely long-term risk of radiotherapy?

      Your Answer: Infections

      Correct Answer: Secondary cancer

      Explanation:

      The major delayed problem with radiotherapy is the development of secondary cancers. This risk begins to appear ten years after therapy.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 21 - A 60-year-old woman presents to the oncology clinic with a general feeling of...

    Incorrect

    • A 60-year-old woman presents to the oncology clinic with a general feeling of being unwell and temperature of 38.1°C. She is a known case of neuroendocrine cancer of the cervix, treated with carboplatin and etoposide. Her last treatment was eight days ago. Blood cultures are taken and she is started on neutropenic sepsis protocol. What will gram-staining of the blood cultures most likely show?

      Your Answer: Gram-negative cocci

      Correct Answer: Gram-positive cocci

      Explanation:

      Gram-staining of the blood cultures of this patient will show gram-positive cocci. Gram-negative bacilli used to be the most common pathogen isolated in neutropenic sepsis, but currently, the most common pathogens are gram-positive organisms. Staphylococcus epidermidis is the most frequent causative agent, and following this are other staphylococci and streptococci species.

      Neutropenic sepsis is a relatively common complication of cancer therapy—usually chemotherapy. It most commonly occurs 7-14 days after the treatment and is usually defined as a neutrophil count of <0.5 x 10^9/L in a patient undergoing anticancer treatment and who has either a temperature higher than 38°C or has other features consistent with clinically significant sepsis. Management approach includes starting empirical antibiotic therapy (piperacillin with tazobactam—Tazocin) immediately. Following this initial treatment, the patient is usually assessed by a specialist and risk-stratified to see if outpatient treatment may be possible. However, if the patient remains febrile and unwell after 48 hours, an alternative antibiotic such as meropenem is often prescribed with or without vancomycin. If patient is still not responding after 4-6 days, then an antifungal, such as amphotericin B, is started after carrying out investigations (e.g. HRCT and Aspergillus PCR) to determine the likelihood of systemic fungal infection.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 22 - A 34-year-old woman is admitted to the hospital with a one-week history of...

    Correct

    • A 34-year-old woman is admitted to the hospital with a one-week history of dark urine and fatigue. One day before admission, she developed severe abdominal pain and abdominal distension. On examination, she has pallor, jaundice, an enlarged tender liver, and ascites. Her investigations show: Hb: 7.9 g/dL, WCC: 3.2 x 10^9/L, Plts: 89 x 10^9/L, MCV: 101 fL. Peripheral smear: Mild polychromasia, AST: 144 U/L, ALT: 130 U/L, Bilirubin: 54 μmol/L. Urine hemosiderin: ++, Urine urobilinogen +. Abdominal ultrasound reveals an enlarged liver, ascites, and absent flow in the hepatic veins. Which single test would you request to confirm the underlying diagnosis?

      Your Answer: Flow cytometry for CD55 and CD59 expression

      Explanation:

      The patient has paroxysmal nocturnal haemoglobinuria (PNH) complicated by acute hepatic vein thrombosis (Budd–Chiari syndrome).

      PNH is an acquired clonal disorder of haematopoietic stem cells, characterised by variable combination of intravascular haemolysis, thrombosis, and bone marrow failure. Diagnosis is made by flow cytometric evaluation of blood, which confirms the CD55 and CD59 deficiencies and deficiency of expression of other GPI-linked proteins. This test is replacing older complement-based assays such as the Ham test and sucrose lysis test.

    • This question is part of the following fields:

      • Haematology & Oncology
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  • Question 23 - A 8-year-old boy who recently migrated from Nigeria was seen in A&E department...

    Correct

    • A 8-year-old boy who recently migrated from Nigeria was seen in A&E department with a six-week history of progressive swelling of his jaw, fever, night sweats, and weight loss. His mother reported an episode of sore throat in the past which was treated with antibiotics, but he developed a rash subsequently. Other than that, there was no other significant past medical history. On examination, a painless, nontender 4x3cm mass was found that was fixed and hard. The only other examination finding of note was rubbery symmetrical cervical lymphadenopathy. Which of the following translocation would most likely be found on biopsy karyotyping?

      Your Answer: t(8;14)

      Explanation:

      Burkitt lymphoma is associated with the c-myc gene translocation, usually t(8;14).

      Burkitt lymphoma is a rare high-grade non-Hodgkin lymphoma endemic to west Africa and the mosquito belt. It has a close association with the contraction of Epstein-Barr virus (EBV). Burkitt lymphoma often presents with symmetrical painless lymphadenopathy, systemic B symptoms (fever, sweats, and weight loss), central nervous system involvement, and bone marrow infiltration. Classically in the textbooks, the patient also develops a large jaw tumour.

      Other aforementioned options are ruled out because:
      1. t(9;22)—Chronic myeloid leukaemia
      2. t(15;17)—Acute promyelocytic leukaemia
      3. t(14;18)—Follicular Lymphoma
      4. t(11;14)—Mantle Cell Lymphoma

    • This question is part of the following fields:

      • Haematology & Oncology
      52.7
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  • Question 24 - A 76-year-old lady with known carcinoma of the caecum, was admitted to the...

    Correct

    • A 76-year-old lady with known carcinoma of the caecum, was admitted to the hospital for right hemicolectomy. She had a history of osteoarthritis for which she was taking nonsteroidal anti-inflammatory agents (NSAIDs), intermittently. Two years ago, she had a fibroma removed from her right breast as well. The patient was a non-smoker and drank approximately 8 units of alcohol per week. Investigations carried out pre-operatively showed: Hb: 10.8 g/dL, MCV: 75 fL , WCC: 8.4 x10^9/L, Plts: 402 x10^9/L. The surgery remained uncomplicated, and she was given two units of packed red blood cells postoperatively. Three days later, she has now become jaundiced and complains of fatigue. Her blood count now shows: Hb: 7.2 g/dL, MCV: 110 fL, WCC: 9.5 x10^9/L, Plts: 395 x10^9/L. Which of the following is the best investigation to confirm the diagnosis?

      Your Answer: Direct Coombs test

      Explanation:

      The direct Coombs test will specifically confirm immune-mediated haemolysis occurring post-transfusion in the aforementioned case.

      There are two types of Coombs test used in immunohematology and immunology:

      1. Direct Coombs test—It confirms autoimmune haemolytic anaemia by detecting antibodies or complement proteins attached to the surface of red blood cells.

      2. Indirect Coombs test—It is used in prenatal testing of pregnant women and in testing prior to a blood transfusion. It detects antibodies floating freely in the blood, against foreign red blood cells.

    • This question is part of the following fields:

      • Haematology & Oncology
      51
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  • Question 25 - A 25-year-old woman noticed an episode of passing blood instead of urine in...

    Incorrect

    • A 25-year-old woman noticed an episode of passing blood instead of urine in the morning. She looks anaemic, but rest of the examination is normal. Her GP has arranged for a urological examination, which has come out to be normal as well. What is the most likely diagnosis?

      Your Answer: Fanconi anaemia

      Correct Answer: Paroxysmal nocturnal haemoglobinuria

      Explanation:

      The patient has paroxysmal nocturnal haemoglobinuria (PNH). The classic sign of the disease is red discolouration of the urine due to the presence of haemoglobin and hemosiderin from the breakdown of red blood cells. As the urine is more concentrated in the morning, this is when the colour is most pronounced.

      PNH is an acquired clonal disorder of haematopoietic stem cells, characterised by variable combinations of intravascular haemolysis, thrombosis, and bone marrow failure. Diagnosis is made by flow cytometric evaluation of blood, which confirms the CD55 and CD59 deficiencies and deficiency of expression of other GPI-linked proteins. This test is replacing older complement-based assays such as the Ham test and sucrose lysis test.

    • This question is part of the following fields:

      • Haematology & Oncology
      30.6
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  • Question 26 - A 72-year-old man, following a fall at home, presents to his GP with...

    Correct

    • A 72-year-old man, following a fall at home, presents to his GP with acute localised chest pain, associated chronic postural lower back pain and chronic fatigue. On examination, he appears mildly anaemic and dehydrated, and has bruises over his arms and legs despite denying previous trauma. Furthermore, he has marked tenderness over his left lower rib cage, compatible with injured ribs, and tenderness over his lower lumbar spine. The rest of his clinical examination is normal. In order to establish a diagnosis of multiple myeloma, based on the patient's symptomology, which of the following combination of criteria is required?

      Your Answer: >30% plasma cells on bone marrow biopsy and radiographic survey demonstrating lytic lesions

      Explanation:

      Diagnosis of multiple myeloma (MM) is based on the confirmation of (a) one major criterion and one minor criterion or (b) three minor criteria in an individual who has signs or symptoms of multiple myeloma.

      Major criteria:
      1. >30% plasma cells on bone marrow biopsy
      2. Monoclonal band of paraprotein on electrophoresis: >35g/L for IgG, 20g/L for IgA, or >1g of light chains excreted in the urine per day

      Minor criteria:
      1. 10–30% plasma cells on bone marrow biopsy
      2. Abnormal monoclonal band but levels less than listed above
      3. Lytic bone lesions observed radiographically
      4. Immunosuppression

    • This question is part of the following fields:

      • Haematology & Oncology
      71
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  • Question 27 - Which one of the following is the most common type of Hodgkin lymphoma?...

    Correct

    • Which one of the following is the most common type of Hodgkin lymphoma?

      Your Answer: Nodular sclerosing

      Explanation:

      The most common type of Hodgkin’s lymphoma (HL) is nodular sclerosing.

      HL is a malignant proliferation of lymphocytes characterised by the presence of distinctive giant cells known as Reed-Sternberg cells. It has a bimodal age distribution being most common in the third and seventh decades of life.

      According to the histological classification, there are four types of HL:

      1. Nodular sclerosing: most common (around 70%), more common in women, associated with lacunar cells, good prognosis

      2. Mixed cellularity: Around 20%, associated with a large number of Reed-Sternberg cells, good prognosis

      3. Lymphocyte-predominant: Around 5%, Reed-Sternberg cells with nuclei surrounded by a clear space found, best prognosis

      4. Lymphocyte-depleted: rare, worst prognosis

    • This question is part of the following fields:

      • Haematology & Oncology
      7.5
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  • Question 28 - Which of the following is least likely to cause warm autoimmune haemolytic anaemia?...

    Incorrect

    • Which of the following is least likely to cause warm autoimmune haemolytic anaemia?

      Your Answer: Methyldopa

      Correct Answer: Mycoplasma infection

      Explanation:

      Mycoplasma infection causes cold autoimmune haemolytic anaemia (AIHA). The rest of the aforementioned options cause warm AIHA.

      AIHA may be divided into ‘warm’ and ‘cold’ types, according to the temperature at which the antibodies best cause haemolysis. It is most commonly idiopathic but may be secondary to a lymphoproliferative disorder, infection, or drugs.

      1. Warm AIHA:
      In warm AIHA, the antibody (usually IgG) causes haemolysis best at body temperature and tends to occur in extravascular sites, for example, spleen. Management options include steroids, immunosuppression, and splenectomy. It is caused by autoimmune diseases such as SLE (rarely causes mixed-type AIHA), cancers such as lymphomas and CLL, and drugs such as methyldopa.

      2. Cold AIHA:
      The antibody in cold AIHA is usually IgM and causes haemolysis best at 4°C and occurs more commonly intravascularly. Features may include symptoms of Raynaud’s disease and acrocyanosis. Patients do not respond well to steroids. Cold AIHA is caused by cancers such as lymphomas, and infections such as mycoplasma and EBV.

    • This question is part of the following fields:

      • Haematology & Oncology
      15.7
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  • Question 29 - Out of the following, which malignant tumour has the highest predilection for dissemination...

    Correct

    • Out of the following, which malignant tumour has the highest predilection for dissemination to the bones?

      Your Answer: Prostate

      Explanation:

      Prostate cancer is the most common primary tumour that metastasises to the bone.

      Most common tumours causing bone metastasis (in descending order):
      1. Prostate (32%)
      2. Breast (22%)
      3. Kidneys (16%)
      4. Lungs
      5. Thyroid

      Most common sites of bone metastasis (in descending order):
      1. Spine
      2. Pelvis
      3. Ribs
      4. Skull
      5. Long bones

    • This question is part of the following fields:

      • Haematology & Oncology
      5.5
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  • Question 30 - A woman is prescribed docetaxel as part of her chemotherapy for breast cancer....

    Incorrect

    • A woman is prescribed docetaxel as part of her chemotherapy for breast cancer. What is the mechanism of action of docetaxel?

      Your Answer: Stabilizes DNA topoisomerase II complex

      Correct Answer: Prevents microtubule disassembly

      Explanation:

      The principal mechanism of action of taxanes (e.g. docetaxel) is the prevention of microtubule disassembly.

      Other aforementioned options are ruled out because:

      1. Doxorubicin: stabilizes DNA topoisomerase II complex and inhibits DNA and RNA synthesis.

      2. Vincristine, vinblastine: inhibits formation of microtubules.

      3. Cisplatin: causes cross-linking in DNA.

    • This question is part of the following fields:

      • Haematology & Oncology
      15.4
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