-
Question 1
Incorrect
-
The most common site of ectopic pregnancy is?
Your Answer: Infundibulum of Fallopian tube
Correct Answer: Ampulla of Fallopian tube
Explanation:Nearly 95% of ectopic pregnancies are implanted in the various segments of the fallopian tube and give rise to fimbrial, ampullary, isthmic, or interstitial tubal pregnancies. The ampulla is the most frequent site, followed by the isthmus. The remaining 5% of non tubal ectopic pregnancies implant in the ovary, peritoneal cavity, cervix, or prior caesarean scar.
-
This question is part of the following fields:
- Abdomen And Pelvis
- Anatomy
-
-
Question 2
Incorrect
-
Regarding aspirin at analgesic doses, which of the following statements is CORRECT:
Your Answer: The increased production of prostaglandins can irritate gastric mucosa.
Correct Answer: It is contraindicated in patients with severe heart failure.
Explanation:Aspirin (at analgesic doses) is contraindicated in severe heart failure. Aspirin irreversibly inhibits cyclooxygenase (COX) enzymes resulting in decreased production of prostaglandins (which can lead to irritation of the gastric mucosa). The analgesic dose is greater than the antiplatelet dose, and taken orally it has a duration of action of about 4 hours. Clinical features of salicylate toxicity in overdose include hyperventilation, tinnitus, deafness, vasodilatation, and sweating.
-
This question is part of the following fields:
- Central Nervous System
- Pharmacology
-
-
Question 3
Correct
-
A 62-year-old woman presents with cold sensitivity, tiredness, and weight gain. A series of blood tests done shows a grossly elevated TSH level and a diagnosis of hypothyroidism is made.What is the commonest cause of hypothyroidism worldwide?
Your Answer: Iodine deficiency
Explanation:Hypothyroidism occurs when there is a deficiency of circulating thyroid hormones. It is commoner in women and is most frequently seen in the age over 60.Iodine deficiency is the commonest cause of hypothyroidism worldwide.In the UK and other developed countries, iodine deficiency is not a problem and autoimmune thyroiditis is the commonest cause.
-
This question is part of the following fields:
- Endocrine Physiology
- Physiology
-
-
Question 4
Incorrect
-
Among the following infectious diseases, which is typically considered to have an incubation period of less than 3 weeks?
Your Answer: Infectious mononucleosis
Correct Answer: Diphtheria
Explanation:C. diphtheriae, which is the causative agent of diphtheria, is carried in the upper respiratory tract and spread by droplet infection or hand-to-mouth contact. The incubation period averages 2 to 5 days.Infectious mononucleosis is caused by Epstein-Barr virus (EBV). The incubation period for EBV varies from 2 weeks to 2 months.The incubation for Hepatitis A virus is approximately 1 month.The incubation period for Hepatitis C ranges from 2 weeks to 6 months.The period from infection to development of anti-HIV antibodies is usually less than 1 month but may be up to 3 months.
-
This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
-
-
Question 5
Correct
-
Regarding hepatitis B, which of the following statements is CORRECT:
Your Answer: Chronic hepatitis B infection is indicated by the persistence of HBsAg for more than 6 months.
Explanation:Chronic hepatitis B infection is indicated by the persistence of HBsAg for more than 6 months. Hepatitis B has a long incubation period of about 2 – 6 months. Hepatitis B vaccine has recently been introduced to the routine childhood immunisation schedule – given at 2, 3 and 4 months. It is also given to babies born to hepatitis B infected mothers at birth, four weeks and 12 months old. Treatment of acute hepatitis is supportive. Treatment with antivirals should be considered in chronic infection as responders have a reduced risk of liver damage and liver cancer in the long term.
-
This question is part of the following fields:
- Microbiology
- Pathogens
-
-
Question 6
Incorrect
-
You are instructed by a senior to administer Mannitol to an RTA patient with increased intracranial pressure. Mannitol is a low molecular weight compound that freely filters at the glomerulus and is not reabsorbed.Out of the following, which is a contraindication to the use of mannitol?
Your Answer: Rhabdomyolysis
Correct Answer: Severe pulmonary oedema
Explanation:Mannitol is the most widely used osmotic diuretic that is most commonly used to reduce cerebral oedema and intracranial pressure. It is recommended to use mannitol for the reduction of CSF pressure/cerebral oedema in a dose of 0.25-2 g/kg as an intravenous infusion over 30-60 minutes. This can be repeated 1-2 times after 4-8 hours if needed.Mannitol has several contraindications and some of them are listed below:1. Anuria due to renal disease2. Acute intracranial bleeding (except during craniotomy)3. Severe cardiac failure4. Severe dehydration5. Severe pulmonary oedema or congestion6. Known hypersensitivity to mannitol
-
This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
-
-
Question 7
Correct
-
Which of the following is considered the best source of information if a research on the national hospital MRSA rates is being done?
Your Answer: Hospital Episode Statistics
Explanation:Hospital Episode Statistics (HES) is a data warehouse containing details of all admissions, outpatient appointments and A and E attendances at NHS hospitals in England.Each HES record contains a wide range of information about an individual patient admitted to an NHS hospital, including:- clinical information about diagnoses and operations- patient information, such as age group, gender and ethnicity- administrative information, such as dates and methods of admission and discharge- geographical information such as where patients are treated and the area where they liveSome benefits of HES include:- monitor trends and patterns in NHS hospital activity- assess effective delivery of care- support local service planning- reveal health trends over time- determine fair access to health care
-
This question is part of the following fields:
- Evidence Based Medicine
-
-
Question 8
Incorrect
-
A 58-year-old man with a traumatic brain injury is brought into the ER. A medical student asks you about the processes that occur in the brain following a traumatic injury.One of these best describes the central nervous systems response to injury.
Your Answer: Microglia undergo reactive gliosis to leave behind firm translucent tissue
Correct Answer: Degeneration of the axon occurs proximally before it occurs distally
Explanation:Following neuronal injury, as seen in traumatic brain injury, the axon undergoes anterograde degeneration. Degradation starts from the cell body (proximally) and progresses distally. The axon becomes fragmented and degenerates. The brain shows no reactive changes to injury is incorrect. Following major injury such as stroke, the brain undergoes a process of liquefactive degeneration, which leaves cystic spaces within the brain.Axonal regeneration does not occur to any significant extent within the central nervous system unlike what is seen in the peripheral nervous system. Astrocytes undergo reactive gliosis, leaving behind a firm translucent tissue around sites of damage.
-
This question is part of the following fields:
- General Pathology
- Pathology
-
-
Question 9
Correct
-
Vitamin D is a group of secosteroids that play a role in calcium and phosphate control. Vitamin D's hormonally active metabolite is 1,25-dihydroxycholecalciferol.Which of the following actions of 1,25-dihydroxycholecalciferol is a direct action?
Your Answer: Increases renal phosphate reabsorption
Explanation:The hormone-active metabolite of vitamin D is 1,25-dihydroxycholecalciferol (commonly known as calcitriol). Its activities raise calcium and phosphate levels in the bloodstream.The following are the primary effects of 1,25-dihydroxycholecalciferol:Calcium and phosphate absorption in the small intestine is increased.Calcium reabsorption in the kidneys is increased.Increases phosphate reabsorption in the kidneys.Increases the action of osteoclastic bacteria (increasing calcium and phosphate resorption from bone)Inhibits the action of 1-alpha-hydroxylase in the kidneys (negative feedback)Thyroid hormone (parathyroid hormone) Calcium reabsorption in the tubules of the kidneys is increased, but renal phosphate reabsorption is decreased.
-
This question is part of the following fields:
- Endocrine Physiology
- Physiology
-
-
Question 10
Incorrect
-
A 36-year-old man presented to the emergency room with a two-week history of shortness of breath, fevers, and malaise. A chest X-ray was ordered and the results confirmed the diagnosis of a right middle lobe pneumonia. Which of the following structures of the heart lies closest to the consolidation?
Your Answer: Right ventricle
Correct Answer: Right atrium
Explanation:In its typical anatomical orientation, the heart has 5 surfaces formed by different internal divisions of the heart:Anterior (or sternocostal) – Right ventriclePosterior (or base) – Left atriumInferior (or diaphragmatic) – Left and right ventriclesRight pulmonary – Right atriumLeft pulmonary – Left ventricleThe silhouette sign of Felson is with respect to the right middle lobe. The right heart border should have a distinct appearance due to the right atrium abutting aerated right middle lobe. The consolidation in the right middle lobe has resulted in loss of this silhouette.
-
This question is part of the following fields:
- Anatomy
- Thorax
-
-
Question 11
Incorrect
-
A 64-year-old man presents with an acute episode of gout. He has a history of chronic heart failure and hypertension. His current medications include ramipril and furosemide.Which of the following statements regarding the treatment of gout is true? Select ONE answer only.
Your Answer: NSAIDs are the treatment of choice for patients with a history of heart failure
Correct Answer: Colchicine has a role in prophylactic treatment
Explanation:In the absence of any contra-indications, high-dose NSAIDs are the first-line treatment for acute gout. Naproxen 750 mg as a stat dose followed by 250 mg TDS is a commonly used and effective regime.Aspirin should not be used in gout as it reduces the urinary clearance of urate and interferes with the action of uricosuric agents. Naproxen, Diclofenac or Indomethacin are more appropriate choices.Allopurinol is used prophylactically, preventing future attacks by reducing serum uric acid levels. It should not be started in the acute phase as it increases the severity and duration of symptoms.Colchicine acts on the neutrophils, binding to tubulin to prevent neutrophil migration into the joint. It is as effective as NSAIDs in relieving acute attacks. It also has a role in prophylactic treatment if Allopurinol is not tolerated.NSAIDs are contra-indicated in heart failure as they can cause fluid retention and congestive cardiac failure. Colchicine is the preferred treatment in patients with heart failure or those who are intolerant of NSAIDs.
-
This question is part of the following fields:
- Musculoskeletal Pharmacology
- Pharmacology
-
-
Question 12
Incorrect
-
Gastric emptying is increased by all of the following EXCEPT for:
Your Answer: Parasympathetic stimulation
Correct Answer: Secretin
Explanation:Gastric emptying is increased by:Distension of the pyloric antrumA fall in the pH of chyme in the stomachParasympathetic stimulation (via vagus)GastrinThe hormones secretin, cholecystokinin and gastric inhibitory polypeptide (GIP) inhibit gastric emptying.
-
This question is part of the following fields:
- Gastrointestinal
- Physiology
-
-
Question 13
Correct
-
Which of the following statements accurately describes the flexor digitorum superficialis muscle?
Your Answer: It flexes the middle phalanges of the medial four fingers at the proximal interphalangeal joints
Explanation:Flexor digitorum superficialis is the largest muscle of the anterior compartment of the forearm. It belongs to the superficial flexors of the forearm, together with pronator teres, flexor carpi radialis, flexor carpi ulnaris and palmaris longus. Some sources alternatively classify this muscle as an independent middle/intermediate layer of the anterior forearm, found between the superficial and deep groups.Flexor digitorum superficialis is innervated by muscular branches of the median nerve, derived from roots C8 and T1 that arises from the medial and lateral cords of the brachial plexus. The skin that overlies the muscle is supplied by roots C6-8 and T1.The primary arterial blood supply to the flexor digitorum superficialis is derived from the ulnar artery and its anterior recurrent branch. In addition to branches of the ulnar artery, the anterior and lateral surfaces of the muscle are supplied by branches of the radial artery; and its posterior surface also receives branches from the median artery.The main function of flexor digitorum superficialis is flexion of the digits 2-5 at the proximal interphalangeal and metacarpophalangeal joints. Unlike the flexor digitorum profundus, flexor digitorum superficialis has independent muscle slips for all four digits. This allows it to flex the digits individually at their proximal interphalangeal joints. In addition, flexor digitorum superficialis aids the aids flexion of the wrist.
-
This question is part of the following fields:
- Anatomy
- Upper Limb
-
-
Question 14
Incorrect
-
During quiet respiration, position of the right oblique fissure can be marked by a line drawn on the thoracic wall that:
Your Answer: Begins at the spinous process of T6, crosses the fifth intercostal space laterally and follows the contour of rib 7 anteriorly.
Correct Answer: Begins at the spinous process of T4, crosses the fifth intercostal space laterally and follows the contour of rib 6 anteriorly.
Explanation:During quiet respiration, the approximate position of the right oblique fissure can be marked by a line on the thoracic wall that begins at the spinous process of vertebra T4, crosses the fifth intercostal space laterally and then follows the contour of rib 6 anteriorly.
-
This question is part of the following fields:
- Anatomy
- Thorax
-
-
Question 15
Correct
-
When treating diabetic ketoacidosis (DKA), glucose should be given together with insulin as soon as the blood glucose concentration falls below 14 mmol/L in the form of:
Your Answer: 10% glucose intravenous infusion at a rate of 125 mL/hour
Explanation:In addition to the sodium chloride 0.9 percent infusion, glucose 10% should be given intravenously (into a large vein with a large-gauge needle) at a rate of 125 mL/hour once blood glucose concentration falls below 14 mmol/litre.
-
This question is part of the following fields:
- Endocrine
- Pharmacology
-
-
Question 16
Correct
-
A 5-year-old girl presents in a paediatric clinic with symptoms of viral gastroenteritis. You encourage the mother to treat the child at home with oral rehydration therapy (ORT), e.g. dioralyte.Out of the following, which statement is FALSE regarding the use of ORT in the management of gastroenteritis?
Your Answer: ORT is sugar-free
Explanation:One of the major complications of gastroenteritis is dehydration. Choosing the correct fluid replacement therapy is essential according to a patient’s hydration status. Oral rehydration therapy (ORT) refers to the restitution of water and electrolyte deficits in dehydrated patients using an oral rehydration salt (ORS) solution. It is a fluid replacement strategy that is less invasive than other strategies for fluid replacement and has successfully lowered the mortality rate of diarrhoea in developing countries. Some characteristics of Oral rehydration solutions are:- slightly hypo-osmolar (about 250 mmol/litre) to prevent the possible induction of osmotic diarrhoea.- contain glucose (e.g. 90 mmol/L in dioralyte). The addition of glucose improves sodium and water absorption in the bowel and prevents hypoglycaemia. – also contains essential mineral saltsCurrent NICE guidance recommends that 50 ml/kg is given over 4 hours to treat mild dehydration.Once rehydrated, a child should continue with their usual daily fluid intake plus 200 ml ORT after each loose stool. In an infant, give ORT at 1-1.5 x the normal feed volume and in an adult, give 200-400 ml after each loose stool.
-
This question is part of the following fields:
- Fluids & Electrolytes
- Pharmacology
-
-
Question 17
Incorrect
-
A patient with a stab wound to the axilla arrives to the emergency department. You notice weakness in elbow flexion and forearm supination during your assessment. Which of these nerves has been affected:
Your Answer: Long thoracic nerve
Correct Answer: Musculocutaneous nerve
Explanation:The musculocutaneous nerve is relatively protected in the axilla, hence injury to it is uncommon. A stab wound in the axilla is the most prevalent source of damage. Because of the activities of the pectoralis major and deltoid, the brachioradialis, and the supinator muscles, arm flexion and forearm flexion and supination are diminished but not completely lost. Over the lateral part of the forearm, there is a lack of sensation.
-
This question is part of the following fields:
- Anatomy
- Upper Limb
-
-
Question 18
Correct
-
An 85-year-old woman is brought in from her nursing home. She arrives in the Emergency Department and appears confused. The staff member from the nursing home accompanying her informs you that she takes a water tablet.From her past medical history and records, you deduce that the water tablet is a loop diuretic. Which of the following parts of a nephron does a loop diuretic act on?
Your Answer: Ascending loop of Henlé
Explanation:Loop diuretics are drugs used to manage and treat fluid overload associated with CHF, liver cirrhosis, and renal disease. The drugs commonly used are:FurosemideBumetanideTorsemideEthacrynic AcidLoop diuretics act on the apical membrane of the thick ascending loop of Henle and inhibit the Na-K-Cl cotransporter. This blocks the reabsorption of sodium and chloride and results in salt-water excretion. This relieves congestion and reduces oedema. Other diuretics act on the following part of the nephron:1. Thiazide diuretics – Na/Cl co-transporter in the distal convoluted tubule2. Osmotic diuretics – PCT and the loop of Henle3. Aldosterone antagonists – distal convoluted tubule 4. Carbonic anhydrase inhibitors – inhibit the carbonic anhydrase and act on proximal tubular cells
-
This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
-
-
Question 19
Correct
-
Question 20
Incorrect
-
A 20-year-old male receives a small cut over his hand while climbing a fence causing it to bleed. Upon applying pressure for a few minutes, the bleeding stops. Which one of the following physiological components of the blood is responsible for the primary haemostasis reaction, such as in this case?
Your Answer: Tissue thromboplastin release
Correct Answer: Platelet plug formation
Explanation:Haemostasis is your body’s defence against an injury that causes bleeding. It stops bleeding in three main steps: 1) Primary haemostasis – formation of a weak platelet plug- The primary reaction of the body is to cause local vasoconstriction at the site of injury and decrease blood flow to the affected area- the release of cytokines and inflammatory markers lead to adhesion of platelets and aggregation at the site of injury forming a platelet plug- the injured vessel wall has exposed subendothelial collagen that releases von Willebrand factor Any damage to the vessel wall causes the release of the Von Willebrand factor, which is necessary for platelet adhesion. Tissue Thromboplastin is also released, which activates the coagulation pathway, a component of secondary haemostasis. The coagulation cascade ultimately results in the conversion of fibrinogen to fibrin.2) Secondary haemostasis 3) Fibrinolysis
-
This question is part of the following fields:
- General Pathology
- Pathology
-
-
Question 21
Correct
-
A 12-year old boy is taken to the emergency room after accidentally falling off the monkey bars. Witnesses of the accident reported that, when the patient fell, he hit his right hand on a bar and a loud thump was heard. On examination, the hand is oedematous, tender and erythematous. On ultrasound, a rupture of the flexor carpi ulnaris is noted.Which of the following statements is true regarding the flexor carpi ulnaris?
Your Answer: It acts to adduct the hand at the wrist joint
Explanation:Flexor carpi ulnaris is a fusiform muscle located in the anterior compartment of the forearm. It belongs to the superficial flexors of the forearm, along with pronator teres, palmaris longus, flexor digitorum superficialis and flexor carpi radialis. Flexor carpi ulnaris is the most medial of the superficial flexors.Innervation of the flexor carpi ulnaris muscle is from the brachial plexus via the ulnar nerve (C7-T1).Flexor carpi ulnaris receives its arterial blood supply via three different routes. Proximally, a branch of the posterior ulnar recurrent artery supplies the muscle as it passes between the humeral and ulnar heads. Branches of the ulnar artery supply the middle and distal parts of the muscle, with an accessory supply also present distally via the inferior ulnar collateral artery.Due to its position and direction in the forearm, flexor carpi ulnaris can move the hand sideways as well as flexing it. Contracting with flexor carpi radialis and palmaris longus, flexor carpi ulnaris produces flexion of the hand at the wrist joint. However, when it contracts alongside the extensor carpi ulnaris muscle in the posterior compartment, their counteracting forces produce adduction of the hand at the wrist, otherwise known as ulnar deviation or ulnar flexion
-
This question is part of the following fields:
- Anatomy
- Upper Limb
-
-
Question 22
Correct
-
In the foetus at 4 months gestation, where does haematopoiesis mainly occur?
Your Answer: Liver and spleen
Explanation:The first place that haematopoiesis occurs in the foetus is in the yolk sac. Later on, it occurs in the liver and spleen, which are the major hematopoietic organs from about 6 weeks until 6 – 7 months gestation. At this point, the bone marrow becomes the most important site. Haemopoiesis is restricted to the bone marrow in normal childhood and adult life.
-
This question is part of the following fields:
- Basic Cellular
- Physiology
-
-
Question 23
Incorrect
-
A 38-year-old woman is investigated for Addison's disease. She had low blood pressure, weakness, weight loss, and skin discoloration. An adrenocorticotropic hormone (ACTH) stimulation test is scheduled as part of her treatment.Which of the following statements about ACTH is correct?Â
Your Answer: It is secreted by the posterior pituitary
Correct Answer: It is released in response to the release of CRH
Explanation:The anterior pituitary gland produces and secretes a peptide hormone called adrenocorticotropic hormone (ACTH) (adenohypophysis). It is secreted in response to the hypothalamus’s secretion of the hormone corticotropin-releasing hormone (CRH).ACTH promotes cortisol secretion via binding to cell surface ACTH receptors in the zona fasciculata of the adrenal cortex.ACTH also promotes the production of beta-endorphin, which is a precursor to melanocyte-releasing hormone (MRH).
-
This question is part of the following fields:
- Endocrine Physiology
- Physiology
-
-
Question 24
Incorrect
-
Due to a traffic accident, a male patient was unable to flex his arm at the glenohumeral joint. Based on the patient’s current condition, which nerve is most likely damaged?
Your Answer: Pectoral nerves
Correct Answer: Axillary and suprascapular nerve
Explanation:A suprascapular nerve injury causes numbness in the shoulder, as well as weakness in abduction and external rotation. Damage to the axillary nerve can result in shoulder or arm muscle weakness, as well as difficulty lifting the arm. This is because the deltoid and supraspinatus muscles, which are innervated by the axillary and suprascapular nerves, are responsible for abduction of the arm at the shoulder joint.
-
This question is part of the following fields:
- Anatomy
- Upper Limb
-
-
Question 25
Correct
-
You are examining the lower limbs of a 54 year old man who presented after falling from a ladder at home. During your neurological assessment you note a weakness of hip flexion. Which of the following nerves is the most important for flexion of the thigh at the hip joint:
Your Answer: Femoral nerve
Explanation:Flexion of the thigh at the hip joint is produced by the sartorius, psoas major, iliacus and pectineus muscles, assisted by the rectus femoris muscle, all innervated by the femoral nerve (except for the psoas major, innervated by the anterior rami of L1 – 3).
-
This question is part of the following fields:
- Anatomy
- Lower Limb
-
-
Question 26
Incorrect
-
Ipratropium bromide should be used with caution in patients with which of the following conditions:
Your Answer: Hypokalaemia
Correct Answer: Prostatic hyperplasia
Explanation:Ipratropium bromide is an antimuscarinic drug used in the management of acute asthma and COPD. It can provide short-term relief in chronic asthma, but short-acting β2agonists act more quickly and are preferred.The BTS guidelines recommend that nebulised ipratropium bromide (0.5 mg 4-6 hourly) can be added to β2agonist treatment for patients with acute severe or life-threatening asthma or those with a poor initial response to β2 agonist therapy.The aerosol inhalation of ipratropium can be used for short-term relief in mild chronic obstructive pulmonary disease in patients who are not already using a long-acting antimuscarinic drug (e.g. tiotropium).Its maximum effect occurs 30-60 minutes after use; its duration of action is 3-6 hours, and bronchodilation can usually be maintained with treatment three times per day.The commonest side effect of ipratropium bromide is dry mouth. It can also trigger acute closed-angle glaucoma in susceptible patients. Tremor is commonly seen with β2agonists but not with antimuscarinics. Ipratropium bromide should be used with caution in: Men with prostatic hyperplasia and bladder-outflow obstruction (worsened urinary retention has been reported in elderly men), People with chronic kidney disease (CKD) stages 3 and above (because of the risk of drug toxicity), People with angle-closure glaucoma (nebulised mist of antimuscarinic drugs can precipitate or worsen acute angle-closure glaucoma)
-
This question is part of the following fields:
- Pharmacology
- Respiratory
-
-
Question 27
Correct
-
Question 28
Incorrect
-
Carbamazepine is indicated for all of the following EXCEPT for:
Your Answer: Complex focal seizures
Correct Answer: Myoclonic seizures
Explanation:Carbamazepine is a drug of choice for simple and complex focal seizures and is a first-line treatment option for generalised tonic-clonic seizures. It is also used in trigeminal neuralgia and diabetic neuropathy. Carbamazepine may exacerbate tonic, atonic, myoclonic and absence seizures and is therefore not recommended if these seizures are present.
-
This question is part of the following fields:
- Central Nervous System
- Pharmacology
-
-
Question 29
Correct
-
Which of the following globin chains makes up normal adult haemoglobin (HbA)?
Your Answer: Two alpha and two beta chains
Explanation:Total adult haemoglobin comprises about 96 – 98 % of normal adult haemoglobin (HbA). It consists of two alpha (α) and two beta (β) globin chains.
-
This question is part of the following fields:
- Basic Cellular
- Physiology
-
-
Question 30
Incorrect
-
Which coronary artery is mostly likely affected if an ECG shows ST segment elevation in leads II, III and aVF, and ST segment depression in V1-V3?
Your Answer: Left anterior descending artery
Correct Answer: Right coronary artery
Explanation:A posterior wall MI occurs when posterior myocardial tissue (now termed inferobasilar), usually supplied by the posterior descending artery — a branch of the right coronary artery in 80% of individuals — acutely loses blood supply due to intracoronary thrombosis in that vessel. This frequently coincides with an inferior wall MI due to the shared blood supply.The ECG findings of an acute posterior wall MI include the following:1. ST segment depression (not elevation) in the septal and anterior precordial leads (V1-V4). This occurs because these ECG leads will see the MI backwards; the leads are placed anteriorly, but the myocardial injury is posterior.2. A R/S wave ratio greater than 1 in leads V1 or V2.3. ST elevation in the posterior leads of a posterior ECG (leads V7-V9). Suspicion for a posterior MI must remain high, especially if inferior ST segment elevation is also present.4. ST segment elevation in the inferior leads (II, III and aVF) if an inferior MI is also present.The following ECG leads determine the location and vessels involved in myocardial infarction:ECG Leads Location Vessel involvedV1-V2 Septal wall Left anterior descendingV3-V4 Anterior wall Left anterior descendingV5-V6 Lateral wall Left circumflex arteryII, III, aVF Inferior wall Right coronary artery (80%) or Left circumflex artery (20%)I, aVL High lateral wall Left circumflex arteryV1, V4R Right ventricle Right coronary arteryV7-V9 Posterior wall Right coronary artery
-
This question is part of the following fields:
- Anatomy
- Thorax
-
-
Question 31
Incorrect
-
An 80-year-old male has presented with chest pain characteristic of angina pectoris. Before initiating treatment with Glyceryl nitrate, you examine the patient and find a murmur. The patient reveals that he has a heart valve disorder, and you immediately put a hold on the GTN order.Which of the following valve disorders is an absolute contraindication to the use of GTN?
Your Answer: Aortic regurgitation
Correct Answer: Mitral stenosis
Explanation:Angina pectoris is the most common symptom of ischemic heart disease and presents with chest pain relieved by rest and nitro-glycerine. Nitrates are the first-line treatment to relieve chest pain caused by angina. The commonly used nitrates are: 1. Nitro-glycerine (NTG) – angina pectoris (treatment/prophylaxis), acute coronary syndrome, heart failure, hypertension2. Isosorbide mononitrate (ISMN) – chronic angina pectoris (treatment)3. Isosorbide dinitrate (ISDN) – angina pectoris (treatment/prophylaxis)The nitrate drugs cause vasodilation via the action of nitric oxide. The contraindications to the use of nitrate are the following: 1. Allergy to nitrates2. Concomitant use of phosphodiesterases (PDE) inhibitors such as tadalafil and sildenafil3. Right ventricular infarction4. Hypertrophic cardiomyopathy5. Cardiac tamponade6. Constrictive pericarditis7. Hypotensive conditions8. Hypovolaemia9. Marked anaemia10. Mitral stenosis11. Raised intracranial pressure due to cerebral haemorrhage or head trauma12. Toxic pulmonary oedema
-
This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
-
-
Question 32
Incorrect
-
Regarding the tongue, which of the following statements is CORRECT:
Your Answer: Sensation from the tongue is carried by the hypoglossal nerve.
Correct Answer: The lymphatic supply of the tongue drains to the jugulo-omohyoid node of the deep cervical chain.
Explanation:All lymphatics from the tongue ultimately drain into the deep cervical chain of nodes along the internal jugular vein, particularly the jugulo-omohyoid lymph node.
-
This question is part of the following fields:
- Anatomy
- Head And Neck
-
-
Question 33
Incorrect
-
A 70-year-old patient diagnosed with Cushing's syndrome, has a history of weight gain, hypertension, and easy bruising.Which of the following statements about Cushing's syndrome is NOTÂ true?Â
Your Answer: Acanthosis nigricans can occur
Correct Answer: Menorrhagia is a common feature
Explanation:Cushing’s syndrome is a group of symptoms and signs brought on by long-term exposure to high amounts of endogenous or exogenous glucocorticoids.Iatrogenic corticosteroid injection is the most prevalent cause of Cushing’s syndrome.Cortisol levels fluctuate throughout the day, with the greatest levels occurring around 0900 hours and the lowest occurring at 2400 hrs during sleep. The diurnal swing of cortisol levels is lost in Cushing’s syndrome, and levels are greater throughout the 24-hour period. In the morning, levels may be normal, but they may be high at night-time, when they are generally repressed.Insulin resistance causes hyperglycaemia, which is a frequent symptom. Insulin resistance can produce acanthosis nigricans in the axilla and around the neck, as well as other skin abnormalities.In contrast to menorrhagia, elevated testosterone levels are more likely to produce amenorrhoea or oligomenorrhoea. Infertility in women of reproductive age can also be caused by high androgen levels.A dexamethasone suppression test or a 24-hour urine free cortisol collection can both be used to establish the existence of Cushing’s syndrome.
-
This question is part of the following fields:
- Endocrine Physiology
- Physiology
-
-
Question 34
Correct
-
A 72-year-old woman presents to your clinic with worsening oedema. She is a known case of ischaemic heart disease and heart failure.You decide to add a loop diuretic to her current drug regime to control the oedema. Of the following, what is a contraindication to using a loop diuretic?
Your Answer: Anuria
Explanation:Loop diuretics are drugs used to manage and treat fluid overload associated with CHF, liver cirrhosis, and renal disease. The drugs commonly used are:FurosemideBumetanideTorsemideEthacrynic AcidLoop diuretics inhibit the Na-K-Cl pump in the ascending loop of Henle, resulting in salt-water excretion. This relieves congestion and reduces oedema. The contra-indications to the use of loop diuretics are:1. Anuria2. Comatose and precomatose states associated with liver cirrhosis3. Renal failure due to nephrotoxic or hepatotoxic drugs4. Severe hypokalaemia5. Severe hyponatremia6. History of hypersensitivity to furosemide, bumetanide, or torsemide (or sulphonamides)The following conditions or states are not contraindications, but loop diuretics needs to be used cautiously in these conditions:1. Diabetes (but hyperglycaemia less likely than with thiazides)2. Gout3. Hypotension (correct before initiation of treatment)4. Hypovolaemia (Correct before initiation of treatment)
-
This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
-
-
Question 35
Incorrect
-
A 70-year-old man has severe diarrhoea one week after taking co-amoxiclav for a chest infection. The diarrhoea is yellow in colour and smell is offensive.What is the SINGLE MOST likely causative organism?
Your Answer: Norovirus
Correct Answer: Clostridium difficile
Explanation:Clostridium difficile, a Gram-positive, anaerobic, spore forming bacteria is present in the gut of approximately 3% of healthy adults (2012 UK HPA estimates). Following use of broad spectrum antibiotics, which alter normal gut flora, Clostridium difficile associated diarrhoea (CDAD) occurs.About 80% of Clostridium difficile infections are seen in people over the age of 65 and its main clinical features are:Abdominal cramps, severe bloody and/or watery diarrhoea, offensive smelling diarrhoea, and fever.
-
This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
-
-
Question 36
Correct
-
Adenosine is primarily indicated for which of the following:
Your Answer: Paroxysmal supraventricular tachycardia
Explanation:Adenosine is usually the treatment of choice for terminating paroxysmal supraventricular tachycardia including those associated with accessory conduction pathways e.g. Wolff-Parkinson-White syndrome.
-
This question is part of the following fields:
- Cardiovascular
- Pharmacology
-
-
Question 37
Incorrect
-
Vitamin D is a group of secosteroids that play a role in calcium and phosphate control. Vitamin D's hormonally active metabolite is 1,25-dihydroxycholecalciferol.Which enzyme hydroxylates 25-hydroxycholecalciferol to form 1,25-dihydroxycholecalciferol?Â
Your Answer: 1-beta-hydroxylase
Correct Answer: 1-alpha-hydroxylase
Explanation:The hormone-active metabolite of vitamin D is 1,25-dihydroxycholecalciferol (commonly known as calcitriol). Its activities raise calcium and phosphate levels in the bloodstream.In the presence of UVB light, 7-dehydrocholesterol is converted to cholecalciferol in the epidermal layer of the skin, resulting in 1,25-dihydroxycholecalciferol.Cholecalciferol is then converted to 25-hydroxycholecalciferol in the endoplasmic reticulum of liver hepatocytes by 25-hydroxylase (calcifediol).Finally, 1-alpha-hydroxylase converts 25-hydroxycholecalciferol to 1,25-dihydroxycholecalciferol in the kidney. The key regulatory point in the formation of 1,25-dihydroxycholecalciferol is 1-alpha-hydroxylase, which is induced by parathyroid hormone or hypophosphatemia.The following are the primary effects of 1,25-dihydroxycholecalciferol:Calcium and phosphate absorption in the small intestine is increased.Calcium reabsorption in the kidneys is increased.Increases phosphate reabsorption in the kidneys.Increases the action of osteoclastic bacteria (increasing calcium and phosphate resorption from bone)Inhibits the action of 1-alpha-hydroxylase in the kidneys (negative feedback)
-
This question is part of the following fields:
- Endocrine Physiology
- Physiology
-
-
Question 38
Incorrect
-
You examine a resuscitated patient who has been diagnosed with ventricular tachycardia. The patient's hemodynamics are normal. You intended to prescribe amiodarone to him, but you can't because he has a contraindication.In these circumstances, which of the following is a contraindication to using amiodarone?
Your Answer: Long QT syndrome
Correct Answer: Sinus node disease
Explanation:Amiodarone is an anti-arrhythmic medication that can be used to treat both ventricular and atrial arrhythmias.The use of amiodarone is contraindicated in the following situations:Conduction disturbances that are severe (unless pacemaker fitted)Sinus node disease is a condition that affects the lymph nodes in (unless pacemaker fitted)Sensitivity to iodineBlockage of the Sino-atrial heart valve (except in cardiac arrest)Bradycardia in the sinuses (except in cardiac arrest)Thyroid disorders
-
This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
-
-
Question 39
Incorrect
-
Which extraocular muscle is entrapped in a patient with a blowout fracture?
Your Answer: Superior rectus
Correct Answer: Inferior rectus
Explanation:A blowout fracture is an isolated fracture of the orbital walls without compromise of the orbital rims. The common mechanisms are falls, high-velocity ball-related sports, traffic accidents, and interpersonal violence.The frontal, ethmoidal, sphenoid, zygomatic, and lacrimal bones form the bony structures of the orbit. Medially, the maxillary and the lacrimal bone form the lacrimal fossa. Together with the lamina papyracea of the ethmoid bone, they form the medial wall. The sphenoid bone forms the posterior wall and houses the orbital canal. Lateral to the orbital canal lies the superior orbital fissure housing cranial nerves III, IV, V, and VI. The zygomatic bone forms the lateral wall. Superior and inferior borders are the frontal and maxillary bones. Located around the globe of the eye and attached to it are 6 extraocular muscles; the 4 rectus muscles and the superior and inferior oblique muscles. The fat and connective tissue around the globe help to reduce the pressure exerted by the extraocular muscles.The goal of treatment is to restore aesthetics and physiological function. The problem with orbital blowout fractures is that the volume of the orbit can be increased, resulting in enophthalmos and hypoglobus. In addition, the orbital tissue and inferior rectus muscle can become trapped by the bony fragments leading to diplopia, limitation of gaze, and tethering. Finally, the orbital injury can lead to retinal oedema, hyphema, and significant loss of vision.While some cases may be managed with conservative care, others may require some type of surgical intervention.
-
This question is part of the following fields:
- Anatomy
- Head And Neck
-
-
Question 40
Correct
-
What is the mechanism of action of captopril:
Your Answer: Angiotensin-converting enzyme inhibitor
Explanation:Captopril is an angiotensin-converting enzyme (ACE) inhibitor, which inhibits the conversion of angiotensin I to angiotensin II.
-
This question is part of the following fields:
- Cardiovascular
- Pharmacology
-
-
Question 41
Incorrect
-
A 52-year-old patient requires procedural sedation for DC cardioversion of atrial fibrillation. You plan on using propofol as the sedative agent.Propofol works as a result of action on what type of receptor? Select ONE answer only.
Your Answer: Dopamine
Correct Answer: Gamma-aminobutyric acid (GABA)
Explanation:Propofol (2,6-diisopropylphenol) is a short-acting phenol derivative that is primarily used for the induction of anaesthesia.Its mechanism of action is unclear but is thought to act by potentiating the inhibitory neurotransmitters GABA and glycine, which enhances spinal inhibition during anaesthesia.The dose for induction of anaesthesia is 1.5-2.5mg/kg. The dose for maintenance of anaesthesia is 4-12 mg/kg/hour. Following intravenous injection, propofol acts within 30 seconds and its duration of action is 5-10 minutes.Propofol produces a 15-25% decrease in blood pressure and systemic vascular resistance without a compensatory increase in heart rate. It is negatively inotropic and decreases cardiac output by approximately 20%.The main side effects of propofol are:Pain on injection (in up to 30%)HypotensionTransient apnoeaHyperventilationCoughing and hiccoughHeadacheThrombosis and phlebitis
-
This question is part of the following fields:
- Anaesthesia
- Pharmacology
-
-
Question 42
Correct
-
A 34-year-old woman was diagnosed with multiple sclerosis two years ago. Her symptoms have been steadily deteriorating, with no intervals of remission in sight.Which of the following aspects of nerve conduction is disrupted by multiple sclerosis?
Your Answer: Saltatory conduction
Explanation:Local currents propagate action potentials down the axons of neurons. This local current flow following depolarisation results in the depolarisation of the neighbouring axonal membrane, and when this region approaches the threshold, more action potentials are generated and so forth. Due to the refractory period, portions of the membrane that have recently depolarized will not depolarize again, resulting in the action potential only being able to go in one direction.The square root of axonal diameter determines the velocity of the action potential; the axons with the biggest diameter have the quickest conduction velocities. When a neuron is myelinated, the speed of the action potential rises as well.The myelin sheath is an insulating coating that surrounds certain neural axons. By increasing membrane resistance and decreasing membrane capacitance, the myelin sheath improves conduction. This enables faster electrical signal transmission via a neuron, making them more energy-efficient than non-myelinated neuronal axons.Electrical impulses are quickly transmitted from one node to the next, causing depolarization of the membrane above the threshold and triggering another action potential, which is then transmitted to the next node. An action potential is rapidly conducted down a neuron in this manner. Saltatory conduction is the term for this.Multiple sclerosis is an example of a clinical disorder in which the myelin sheath is affected. It is an immune-mediated disorder in which certain nerve cells in the brain and spinal cord become demyelinated. The ability of some areas of the nervous system to properly transmit action potentials is disrupted by demyelination, resulting in a variety of neurological symptoms and indications.
-
This question is part of the following fields:
- Basic Cellular Physiology
- Physiology
-
-
Question 43
Incorrect
-
A 30-year old male is brought to the emergency room after a terrible fall during a photoshoot. The patient reported falling on his right forearm. There is evident swelling and tenderness on the affected area, with notable weakness of the flexor pollicis longus muscle. Radiographic imaging showed a fracture on the midshaft of the right radius.Which of the following nerves is most likely injured in the case above?
Your Answer: The radial nerve
Correct Answer: The anterior interosseous nerve
Explanation:Flexor pollicis longus receives nervous supply from the anterior interosseous branch of median nerve, derived from spinal roots C7 and C8.
-
This question is part of the following fields:
- Anatomy
- Upper Limb
-
-
Question 44
Correct
-
The correct statement about the glomerular filtration barrier is which of the following?
Your Answer: The basement membrane is negatively charged, restricting filtration of negatively charged molecules.
Explanation:The main factor in determining whether a substance is filtered or not is molecular weight. Molecules < 7 kDa in molecular weight e.g. glucose, amino acids, urea, ions are filtered freely, but larger molecules are increasingly restricted up to 70 kDa, and there is very little filtration for anything above this. There is further restriction of negatively charged molecules because they are repelled by negative charges, particularly in the basement membrane. Albumin, which has a molecular weight of 69 kDa and is negatively charged, is filtered but only in very small amounts. All of the filtered albumin is reabsorbed in the proximal tubule. Small molecules such as ions, glucose, amino acids and urea pass the filter without hindrance. Other than the ultrafiltrate being essentially protein free, it has an otherwise identical composition of plasma. Bowman's capsule consists of:- an epithelial lining which consists of a single layer of cells called podocytes- endothelium which is perforated by pores or fenestrations – this allows plasma components with a molecular weight of < 70 kDa to pass freely.
-
This question is part of the following fields:
- Physiology
- Renal
-
-
Question 45
Correct
-
A study investigating the risk of suffering a stroke in patients with atrial fibrillation taking the new antiplatelet drug ticagrelor, compared with standard treatment with warfarin is done over a 2-year time period. 30 of the 300 patients taking ticagrelor and 20 of the 500 patients taking warfarin suffered a stroke over the 2-year period. One of these statements is true regarding the outcomes of this study.
Your Answer: Ticagrelor increases the risk of stroke
Explanation:Absolute risk and relative risk are used to assess the strength of a relationship between a disease and a factor that may affect it.Absolute risk (AR) is the risk of developing a disease over a time period:AR = the number of events that occur in a group / number of people in that groupThe absolute risk reduction (ARR) is the difference between the absolute risk in the control group (ARC) and the absolute risk in the treated group (ART). ARR = ARC – ARTThe control group is the warfarin group, therefore the ARC is 20/500 (0.04). Treatment group is the ticagrelor group and ART = 30/300 (0.1). ARR = 0.04 – 0.1 = -0.06. This shows that treatment with ticagrelor increases risk of developing stroke. This is also termed a relative risk increase.Relative risk, or risk ratio, (RR) is used to compare the risk in the two different groups. It is the ratio of the absolute risks of the disease in the treatment group (ART) to the absolute risk of the disease in the control group (ARC):RR=ART /ARCTherefore RR = 0.1 / 0.04 = 2.5RR < 1 means the intervention reduces the risk of the outcome being studiedRR = 1 means the treatment has no effect on the outcome being studiedRR > 1 means the intervention increased the risk of the outcome being studiedSince RR is 2.5, ticagrelor increases the risk of stroke.SUMMARYAbsolute risk reduction is -0.06Absolute risk in warfarin group = 0.04Relative risk = 2.5Ticagrelor has no effect on stroke is incorrect because RR is not =1
-
This question is part of the following fields:
- Evidence Based Medicine
-
-
Question 46
Incorrect
-
Cryptococcus neoformans is primarily transmitted by which of the following routes:
Your Answer: Respiratory droplet spread
Correct Answer: Inhalation of spores
Explanation:Cryptococcus neoformans is found in bird droppings and transmission is by inhalation of spores, thus the lung is the primary site of infection.
-
This question is part of the following fields:
- Microbiology
- Pathogens
-
-
Question 47
Correct
-
A 18-year-old man returns from a trip to Ibiza with a severely painful left eye. He has copious mucopurulent discharge, is febrile and has left-sided tender preauricular lymphadenopathy. He attends the local eye casualty and is diagnosed with hyperacute conjunctivitis.What is the SINGLE most likely causatiave organism?
Your Answer: Neisseria gonorrhoeae
Explanation:Hyperacute bacterial conjunctivitis is a severe, sight-threatening ocular infection that warrants immediate ophthalmic work-up and management. The infection has an abrupt onset and is characterized by a copious yellow-green purulent discharge that reaccumulates after being wiped away. Typically caused by infection with Neisseria gonorrhoeae.
-
This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
-
-
Question 48
Incorrect
-
A 69-year-old man presents with a painful groin swelling on the right side. The suspected diagnosis is an inguinal hernia.Which of the following examination features make it more likely to be an indirect inguinal hernia?
Your Answer: It can be reduced superiorly then posteriorly
Correct Answer: It can be controlled by pressure over the deep inguinal ring
Explanation:The reduced indirect inguinal hernia can be controlled by pressure over the internal ring; a direct inguinal hernia cannot.An indirect inguinal hernia can be reduced superiorly then superolaterally, while a direct inguinal hernia can be reduced superiorly then posteriorly.An indirect inguinal hernia takes time to reach full size, but a direct inguinal hernia appears immediately upon standing.Indirect inguinal hernias are seen as elliptical swelling, while direct inguinal hernias appear as symmetric, circular swelling.
-
This question is part of the following fields:
- Abdomen And Pelvis
- Anatomy
-
-
Question 49
Incorrect
-
Regarding flow through a tube, which of the following statements is CORRECT:
Your Answer: Resistance to flow is dependent on the length and the diameter of the tube alone.
Correct Answer: Polycythaemia will decrease the rate of blood flow through a vessel.
Explanation:Darcy’s law states that flow through a tube is dependent on the pressure differences across the ends of the tube (P1 – P2) and the resistance to flow provided by the tube (R). Resistance is due to frictional forces and is determined by the length of the tube (L), the radius of the tube (r) and the viscosity of the fluid flowing down that tube (V). The radius of the tube has the largest effect on resistance and therefore flow – this explains why smaller gauge cannulas with larger diameters have a faster rate of flow. Increased viscosity, as seen in polycythemia, will slow the rate of blood flow through a vessel.
-
This question is part of the following fields:
- Basic Cellular
- Physiology
-
-
Question 50
Incorrect
-
A 29-year-old male presents with a 3-day history of bloody diarrhoea and abdominal pain.All the following are causes of infectious bloody diarrhoea EXCEPT?
Your Answer: Schistosoma mansoni
Correct Answer: Enterotoxigenic Escherichia coli
Explanation:Infective causes of bloody diarrhoea include:Salmonella sppCampylobacter sppSchistosomiasisEntamoeba histolytica (Amoebiasis )Shigella sppClostridium difficileYersinia sppEnteroinvasive Escherichia coliEnterotoxigenic Escherichia coli is non-invasive and does not cause inflammation of the gut and bloody diarrhoea. It presents with copious watery diarrhoea and usually are not associated with abdominal cramping.
-
This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
-
SESSION STATS - PERFORMANCE PER SPECIALTY
