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Question 1
Correct
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The spinal cord in a neonate terminates at the lower border of:
Your Answer: L3
Explanation:The spinal cord and the vertebral canal are as long as each other in early fetal life. The length of the cord increases faster than the growth of the vertebrae during development. By the time of birth, the spinal cord is at the level of the lower border of the 3rd lumbar vertebra, compared to its original position at the level of the 2nd coccygeal vertebra.
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This question is part of the following fields:
- Anatomy
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Question 2
Correct
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The SI unit of energy is the joule. Energy can be kinetic, potential, electrical or chemical energy. Which of these correlates with the most energy?
Your Answer: Energy released when 1 kg fat is metabolised to CO2 and water (the energy content of fat is 37 kJ/g)
Explanation:The derived unit of energy, work or amount of heat is joule (J). It is defined as the amount of energy expended if a force of one newton (N) is applied through a distance of one metre (N·m)
J = 1 kg·m/s2·m = 1 kg·m2/s2 or 1 kg·m2·s-2
Kinetic energy (KE) = ½ MV2
An object with a mass of 1500 kg moving at 30 m/s correlates to 675 kJ:
KE = ½ (1500) × (30)2 = 750 × 900 = 675 kJ
Total energy released when 1 kg fat is metabolised to CO2 and water is 37 MJ. 1 g fat produces 37 kJ/g, therefore 1 kg fat produces 37,000 × 1000 = 37 MJ.
Raising the temperature of 1 kg water from 0°C to 100°C correlates to 420 kJ. The amount of energy needed to change the temperature of 1 kg of the substance by 1°C is the specific heat capacity. We have 1 kg water therefore:
4,200 J × 100 = 420,000 J = 420 kJ
In order to calculate the energy involved in raising a 100 kg mass to a height of 1 km against gravity, we need to calculate the potential energy (PE) of the mass:
PE = mass × height attained × acceleration due to gravity
PE = 100 kg × 1000 m × 10 m/s2 = 1 MJThe heat generated when a direct current of 10 amps flows through a heating element for 10 seconds when the potential difference across the element is 1000 volts can be calculated by applying Joule’s law of heating:
Work done (WD) = V (potential difference) × I (current) × t (time)
WD = 10 × 10 × 1000 = 100 kJ -
This question is part of the following fields:
- Physiology
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Question 3
Correct
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A 25-year old man needs an emergency appendicectomy and has gone to the operating room. During general anaesthesia, ventilation is achieved using a circle system with a fresh gas flow (FGF) of 1L/min, with and air/oxygen and sevoflurane combination. The capnograph trace is normal. Changes to the end tidal and baseline CO2 measurements at 10 and 20 mins respectively are seen on the capnograph below: (10 minutes and 20 minutes). End-tidal CO2 4.9 kPa, 8.4 kPa. Baseline end-tidal CO2 0.2 kPa, 2.4 kPa. The other vitals were as follows: Pulse 100-105 beats per minute, Systolic blood pressure 120-133 mmHg, O2 saturation 99%. The next most important immediate step is which of the following?
Your Answer: Increase the FGF
Explanation:This scenario describes rebreathing management.
Changes is exhaustion of the soda lime and a progressive rise in circuit deadspace is the most likely explanation for the capnograph.
It is important that the soda lime canister is inspected for a change in colour of the granules. Initially fresh gas flow should be increased and then if necessary, replace the soda lime granules. Other strategies include changing to another circuit or bypassing the soda lime canister after the fresh gas flow is increased.
Any other causes of increased equipment deadspace should be excluded.
Intraoperative hypercarbia can be caused by:
1. Hypoventilation – Breathing spontaneously; drugs which include anaesthetic agents, opioids, residual neuromuscular blockade, pre-existing respiratory or neuromuscular disease and cerebrovascular accident.
2. Controlled ventilation- circuit leaks, disconnection, miscalculation of patient’s minute volume.
3. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits, increased breathing system deadspace.
4. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
5. Exogenous source – Absorption of CO2 absorption from the pneumoperitoneum. -
This question is part of the following fields:
- Physiology
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Question 4
Incorrect
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All the following statements are false regarding nitrous oxide except:
Your Answer: Is an NMDA agonist
Correct Answer: Maintains carbon dioxide reactivity
Explanation:Nitrous oxide increases cerebral blood flow by direct cerebral stimulation and tends to elevate intracranial pressure (ICP)
It increases the cerebral metabolic rate of oxygen consumption (CMRO2)
It is not an NMDA agonist as it antagonizes NMDA receptors.
Cerebral autoregulation is impaired with the use of nitrous oxide but when used with propofol, it is maintained.
Carbon dioxide reactivity is not affected by it.
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This question is part of the following fields:
- Pharmacology
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Question 5
Incorrect
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The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?
Your Answer: Ainsley's viewing fallacy
Correct Answer: Hawthorne effect
Explanation:Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.The remaining terms are made up.
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This question is part of the following fields:
- Statistical Methods
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Question 6
Correct
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A 28-year-old woman who is 36 weeks pregnant presented with significant proteinuria and severe headache. On examination, the blood pressure recorded was consistently raised at 190/110. Subsequently, she was admitted to the labour ward as a case of pre-eclampsia. A loading dose of IV magnesium sulphate 4g is given, followed by a 1g/hour infusion. The most suitable parameter to access magnesium toxicity is?
Your Answer: Tendon reflexes
Explanation:Magnesium is a very important cation due to its various physiological roles in the body. This includes:
– playing the role of a cofactor in many enzymatic reactions
– influencing hormone receptor binding
– affecting calcium channels
– impact on cardiac, vascular and neural cellsMagnesium sulphate is used as first line in the treatment of eclampsia. Moreover, it has some preventive role in patients with severe pre-eclampsia. All the clinical effects of magnesium are in line with its plasma concentration.
The first sign of magnesium toxicity in obstetric patients is the loss of patellar reflex, which is regularly monitored during treatment. The other options are all late signs of magnesium toxicity.
Whenever there is a doubt, serum magnesium levels should always be monitored.
The table below correlates the effects of increased levels of magnesium on the body:
Plasma Concentration
(mmol/L) Effect
0.7-1.2 Normal
4-8 Decreased deep tendon reflexes, nausea, headache, weakness, malaise, lethargy and facial flushing
5-10 ECG changes (prolonged PR, prolonged QT, and widened QRS)
10 Muscle weakness, loss of deep tendon reflexes, hypotension
15 SA/AV nodal block, respiratory paralysis and depression
20 Cardiac arrest. -
This question is part of the following fields:
- Pathophysiology
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Question 7
Incorrect
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While administering a general anaesthetic to a 65-year-old man booked for a hip hemiarthroplasty, with a weight 70 kg, and an ASA 1 score, you give 1 g of paracetamol IV but notice that he had received the same dose on the ward one hour prior. What is the most appropriate subsequent management of this patient?
Your Answer: Avoid paracetamol for the next 12 hours and monitor the patient clinically
Correct Answer: Do nothing and give the next doses of paracetamol at standard 6 hour intervals
Explanation:After ingestion of more than 150 mg/kg paracetamol within 24 hours, hepatotoxicity can occur but can also develop rarely after ingestion of doses as low as 75 mg/kg within 24 hours. Hepatocellular damage will not occur in this patient and therefore no need to engage management pathway for paracetamol overdose. If his weight was <33 kg or he already had a history of impaired liver function, then the management would bde different.
Subsequent post-operative doses will be a standard dose of 1 g 6 hourly.
This is a drug administration error and should be reported as an incident even though the patient will not be harmed.
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This question is part of the following fields:
- Pharmacology
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Question 8
Correct
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Among the following, which statement is true regarding electrical safety in an operation theatre?
Your Answer: The higher the frequency of the current the less risk to the patient
Explanation:The operating theatre is an unusual place with several applications of electrical equipment to the human body. This can lead to potential dangers associated with it that need to be prevented. Electrical safety in the operation theatre is the understanding of how these potential dangers can occur and how they can be prevented.
Electricity can cause morbidity or mortality by one of the following ways:
(i) electrocution
(ii) burns
(iii) ignition of a flammable material, causing a fire or explosion.Electrocution is dependant on factors like duration of contact with electric current, the current pathway and the frequency and size of current.
Option A: The higher the frequency, the less effects of electrocution on the body.
Option B & D: Equipment can be classified in classes and types.
The class designation describes the method used for protection against electrocution. Class I is basic protection, class II is double insulation and class III is safety extra low voltage.
The type designation describes the degree of protection based on the maximum permissible leakage currents under normal and fault conditions.
Type B:
can be class I, II or III but the maximum leakage current must not exceed 100 µA. It is therefore not suitable for direct connection to the heart.
Type BF
Similar to type B, but uses an isolated (or floating) circuit.
Type CF
Only type CF protect against microshock as they allow leakage currents of 0.05 mA per electrode for class I and 0.01 mA for class II. Microshock is a small leakage current that can cause harm because of direct connection to the heart via transvenous lines or wires, bypassing the impedance of the skin, leading to ventricular fibrillation. Microshock current of 100 μA is sufficient to cause VF.Option C: A 75mA electrocution can cause ventricular fibrillation. Use the following as a general guide to understand the effect of current size on the body.
1 mA – tingling pain
5 mA – pain
15 mA – tonic muscular contraction
50 mA – respiratory muscle paralysis
75 mA – ventricular fibrillation.Option E: Wet skin reduces the resistance to current flow and therefore increases the effects of electrocution.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 9
Correct
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Which statement is correct concerning breathing systems?
Your Answer: The reservoir bag can limit the pressure in the breathing system to about 40 cm of water
Explanation:Mapleson classified breathing systems into A, B, C, D and E. Jackson-Rees subsequently modified the Mapleson E by adding a double-ended bag to the end of the reservoir tubing, creating the Mapleson F. A Mapleson E or T-piece does not have a reservoir bag.
A Mapleson A system is a very efficient system for use during spontaneous ventilation. However, it is not suitable for use with patients less than 25 kg, due to the increased dead space at the distal / patient end. This system can be modified into a Lack system or coaxial Mapleson A, where the fresh gas flows through an outer tube (30 mm) and exhaled gases flow through the inner tube (14 mm).
The adjustable pressure limiting valve (APL) or expiratory valve allows exhaled gas and excess fresh gas to leave the breathing system. It is a one-way, adjustable spring-loaded valve, and gases escape when the pressure in the system exceeds the valve opening pressure. During spontaneous ventilation a pressure of less than 1 cm of water (0.1 kPa) is needed when the valve is in the open position (not 2 cm of H2O).
The reservoir bag is highly compliant and when over inflated, the rubber bag can limit the pressure in the system to about 40 cm of H2O.
This is due to the law of Laplace, which states that the pressure will fall as the radius of the bag increases:
Pressure = 2 x tension/radius.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 10
Incorrect
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A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he requires a urethral catheter. Where does resistance first occur during the insertion of a catheter?
Your Answer: Prostatic urethra
Correct Answer: Membranous urethra
Explanation:The membranous urethra is the shortest part of the urethra and the least dilatable part of it.
This is as a result of it being surrounded by the external urethral sphincter which is made up of striated muscle and controls voluntary urine flow from the bladder to the urethra.
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This question is part of the following fields:
- Anatomy
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Question 11
Correct
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The lung volume that is commonly measured indirectly is?
Your Answer: Functional residual capacity
Explanation:The functional residual capacity (FRC) is the volume in the lungs at the end of passive expiration. It is determined by opposing forces of the expanding chest wall and the elastic recoil of the lung. A normal FRC = 1.7 to 3.5 L. It a marker for lung function, and, during this time, the alveolar pressure is equal to the atmospheric pressure.
FRC cannot be measured by spirometry because it contains the residual volume.
Tidal volume, inspiratory reserve volume, forced expiratory volume in 1 second, and vital capacity can be measured directly.
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This question is part of the following fields:
- Pathophysiology
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Question 12
Correct
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Which of the following statements is not correct regarding dopamine?
Your Answer: Crosses the blood brain barrier
Explanation:Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic α and β1 (but not β2 ) agonist.
The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.
Moderately high doses produce a positive inotropic (direct β1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.
Vasoconstriction (α1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular α and β receptors; does not penetrate the blood-brain barrier€”no CNS effects.
Dopamine is used in patients with cardiogenic or septic shock and severe CHF wherein it increases BP and urine outflow.
It is administered by i.v. infusion (0.2€“1 mg/min) which is regulated by monitoring BP and rate of urine formation
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This question is part of the following fields:
- Pharmacology
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Question 13
Correct
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One litre of water at 0°C and a pressure of 1 bar is in a water-bath. A 1 kW element is used in heating it. Given that the specific heat capacity of water is 4181 J/(kg°C) or J/(kg K), how long will it take to raise the temperature of the water by 10°C?
Your Answer: 42 seconds
Explanation:The amount of energy required to change the temperature of 1 kg of a substance by 1°C is its specific heat capacity.
Energy required to increase the temperature of any object is given by the equation:
E = m × c × θ
Where:
E = energy required to heat an object
m = mass of object
c = specific heat capacity of the substance
θ = temperature changeThe specific heat capacity of water is 4181 J/(kg°C)
Therefore the energy required to raise 1kg of water by 10°C is:
1 kg × 4181 J/(kg°C) × 10°C = 41810 J
A 1 kW or 1000 W heater would be expected to supply 1000 J/s.
The approximate time it would take the 1 kW heater to raise the temperature of one Litre of water by 10°C is:
41810/1000 = 41.8 seconds.
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This question is part of the following fields:
- Physiology
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Question 14
Incorrect
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Concerning the trachea, which of these is true?
Your Answer: Is made up of 12 C-shaped cartilaginous rings
Correct Answer: In an adult is approximately 15 cm long
Explanation:In an adult, the trachea is approximately 15 cm long. It extends at the level of the 6th cervical vertebra, from the lower border of the cricoid cartilage.
The trachea terminates between T4 and T6 at the carina or bronchial bifurcation. This variation is because of changes during respiration.
The trachea has 16-20 C-shaped cartilaginous rings that maintain its patency.
The trachea is first of the 23 generations of air passages in the tracheobronchial tree (not 25), from the trachea to the alveoli..
The inferior thyroid arteries which are branches of the thyrocervical trunk, arise from the first part of the subclavian artery and supplies the trachea.
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This question is part of the following fields:
- Anatomy
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Question 15
Incorrect
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Drug A has a 1 L/kg volume of distribution and a 0.1 elimination rate constant (k). Drug B has a 2 L/kg volume of distribution and a 0.2 elimination rate constant (k). Which of the following statements best describes the pharmacokinetics of drug A in a single compartment?
Your Answer: Drug A has the same half life than drug B
Correct Answer: Drug A has a lower clearance than drug B
Explanation:The fall in plasma concentration of a drug with time decreases exponentially in a single compartment pharmacokinetic model (wash-out curve).
A straight line is produced when the logarithm (ln) of a drug’s plasma concentration is plotted against time because a constant proportion of the drug is removed from the plasma per unit time. The line’s gradient or slope can be expressed mathematically as k. (the rate constant). The gradient is related to the half life (T1/2) because it can be used to predict a drug’s plasma concentration at any time.
According to the following formula, clearance (CL), volume of distribution (Vd), and elimination rate constant (k) are mathematically related.
CL = Vd x k
For drug A, CL = 1 x 0.1 = 0.1units per minute
For drug B, Cl = 2 x 0.2 = 0.4 units per minute
Hence, it is proved that Drug A has a lower clearance than drug B.
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This question is part of the following fields:
- Pharmacology
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Question 16
Correct
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Which of the following molecule is closely related to the structure of Oxytocin?
Your Answer: ADH
Explanation:Oxytocin is structurally similar to Antidiuretic Hormone (ADH) and thus oxytocin cause water intoxication (due to ADH like action)
Oxytocin is secreted by the posterior pituitary along with ADH. It increases the uterine contractions with complete relaxation in between. It increases the contraction of the upper segment (fundus and body) of the uterus whereas the lower segment is relaxed facilitating the expulsion of the foetus
Antidiuretic hormone (ADH) also called vasopressin is released from the posterior pituitary in response to hypertonicity and increases fluid reabsorption from the kidney.
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This question is part of the following fields:
- Pharmacology
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Question 17
Incorrect
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The leading cause of perioperative anaphylaxis per hundred thousand administrations currently in the UK is?
Your Answer: Suxamethonium
Correct Answer: Teicoplanin
Explanation:The leading cause of perioperative anaphylaxis in the UK currently are antibiotics. They account for 46% of cases with identified causative agents. Co-amoxiclav and teicoplanin between them account for 89% of antibiotic-induced perioperative anaphylaxis
Neuromuscular blocking agents (NMBAs) are the second leading cause and account for 33% of case.
Chlorhexidine (0.78/100,000 administrations)
Co-amoxiclav (8.7/100,000 administrations)Suxamethonium (11.1/100,000 administrations)
Patent blue dye (14.6/100,000 administrations)
Teicoplanin (16.4/100,000 administrations)Anaphylaxis to chlorhexidine periop poses a significant risk in the healthcare setting because of its widespread use with some being fatal.
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This question is part of the following fields:
- Pharmacology
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Question 18
Correct
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An 82-year old male has shortness of breath which is made worse when he lies down but investigations have revealed a normal ejection fraction. Why might this be?
Your Answer: He has diastolic dysfunction
Explanation:Decreased stroke volume causes decreased ejection fraction which results in diastolic dysfunction.
Ejection fraction is not a useful measure in someone with diastolic dysfunction because stroke volume may be reduced whilst end-diastolic volume may be reduced.
Diastolic dysfunction may arise with reduced heart compliance.Ejection fraction measures of the proportion of blood leaving the ventricles with each beat and is calculated as follows:
Stroke volume / end-diastolic volume.A healthy ejection fraction is usually taken as 60% (based on a stroke volume of 70ml and end-diastolic volume of 120ml).
Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.
Sitting up decreases venous because of the action of gravity on blood in the venous system.
Hypotension also decreases venous return.
A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.Systemic vascular resistance = mean arterial pressure / cardiac output.
Increased vascular resistance impedes the flow of blood back to the heart.Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 19
Incorrect
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Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary vasoconstriction)?
Your Answer: Sevoflurane 1 MAC
Correct Answer: Desflurane 2 MAC
Explanation:Resistance pulmonary arteries constrict in response to alveolar and airway hypoxia, diverting blood to better-oxygenated alveoli.
In atelectasis, pneumonia, asthma, and adult respiratory distress syndrome, hypoxic pulmonary vasoconstriction optimises O2 uptake. Hypoxic pulmonary vasoconstriction helps maintain systemic oxygenation during single-lung anaesthesia.
A redox-based O2 sensor within pulmonary artery smooth muscle cells is involved in hypoxic pulmonary vasoconstriction. The production of reactive oxygen species by smooth muscle cells in the pulmonary artery varies in proportion to PaO2. Hypoxic removal of these redox second messengers inhibits voltage-gated potassium channels, depolarizing smooth muscle cells in the pulmonary artery.
L-type calcium channels are activated by depolarization, which raises cytosolic calcium and causes hypoxic pulmonary vasoconstriction. Some anaesthetics suppress this response, increasing the risk of further deterioration in ventilation perfusion mismatch.
Agents that inhibit HPV are ether, halothane, and desflurane (>1.6 MAC).
Agents with no effect on HPV include thiopentone, fentanyl, desflurane (1MAC), isoflurane (<1.5MAC), sevoflurane(1MAC), and propofol. -
This question is part of the following fields:
- Pharmacology
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Question 20
Correct
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What vessel is NOT considered a major branch of the descending thoracic aorta?
Your Answer: Inferior thyroid artery
Explanation:The descending thoracic aorta begins at the lower border of T4 near the midline as a continuation of the arch of the aorta. It descends and ends at the level of T12 at the aortic hiatus in the diaphragm, where it becomes the abdominal aorta.
The aorta gives off the following branches: (descending order)
1. Bronchial arteries
2. Mediastinal arteries
3. Oesophageal arteries
4. Pericardial arteries
5. Superior phrenic arteriesThe posterior intercostal arteries are branches that originate throughout the length of the posterior aspect of the descending thoracic aorta.
The inferior thyroid artery is usually derived from the thyrocervical trunk, a branch of the subclavian artery.
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This question is part of the following fields:
- Anatomy
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Question 21
Incorrect
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In a study lasting over a period of two years, in which the mean age of 800 patients was 82 years, the efficacy of hip protectors in reducing femoral neck fractures was discussed. Both experimental and control group had 400 members. Instances of fractures reported over the two year time duration were 10 for the control group (that were prescribed hip protector) and 20 for the control group. What is the value of Absolute Risk Reduction?
Your Answer: 0.5
Correct Answer: 0.025
Explanation:ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)
So,
ARR= (10/400)-(20/400)
ARR= 0.025-0.05
ARR= 0.025 (Numerical Value)
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This question is part of the following fields:
- Statistical Methods
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Question 22
Correct
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Which of the following statement is true regarding the mechanism of action of rifampicin?
Your Answer: Inhibit RNA synthesis
Explanation:Rifampicin is a derivative of a rifamycin (other derivatives are rifabutin and rifapentine). It is bactericidal against both dividing and non-dividing mycobacterium and acts by inhibiting DNA-dependent RNA polymerase. Thus this drug inhibits RNA synthesis.
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This question is part of the following fields:
- Pharmacology
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Question 23
Incorrect
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Concerning drug dose and response, one of the following statements is correct?
Your Answer: Partial agonism implies low receptor affinity
Correct Answer: Intrinsic activity determines maximal response
Explanation:Dose response curves are plotted as % response to drug against Logarithm of drug concentration. The graph is usually sigmoid shaped.
Any drug that has high affinity and high intrinsic activity is likely an agonist. A drug with high affinity but no intrinsic activity will act as an antagonist. Displacement of an agonist also depends on the relative concentrations of the two drugs at the receptor sites.
Maximal response may be achieved by activation of a small proportion of receptor sites.
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This question is part of the following fields:
- Pharmacology
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Question 24
Correct
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A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems. A macroadenoma compressing the optic chiasm is visible on MRI. What is the most likely visual field defect to be discovered during an examination?
Your Answer: Bitemporal hemianopia
Explanation:The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.
Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.
Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.
The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.
Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.
A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.
A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.
Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.
Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.
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This question is part of the following fields:
- Pathophysiology
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Question 25
Correct
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It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers. Which form of potential bias can be associated with this particular study?
Your Answer: Confounding bias
Explanation:Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.
Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.
Measurement bias can be characterized by gathering of information in a manner that is distorted.
When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.
Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.
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This question is part of the following fields:
- Statistical Methods
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Question 26
Incorrect
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The equipment used for patient monitoring in theatre and intensive care settings have electrical safety requirements for the protection of hospital staff and patients. Of the different classes of electrical equipment listed, which is least likely to cause a patient to suffer a microshock?
Your Answer: III
Correct Answer: II (CF)
Explanation:Microshock refers to ventricular fibrillation caused by miniscule amounts of currents or voltages (100-150 microamperes) passing through the myocardial tissue from external cables arising from electrical components within the cardiac muscle, for example, pacemaker electrodes or saline filled venous catheters.
The risk of shock changes with the construction of electrical equipment in question. The main classes of electrical equipment include: I: Appliances have a protective earth connected to an outer casing which prevents live elements from coming in contact with conductive elements. A fault in this equipment class will result in live elements coming in contact with the outer casing and allowing electrical flow into the protective earth. This triggers the protective fuse to disconnect the electric supply to the appliance.
II: These appliances have reinforced insulation. In the event of a fault which causes the first layer of insulation to fail, the second layer is able to prevent contact of live elements with outer casing.
III: These appliances have no insulation to provide safety, and rely solely on the use of separated extra low voltage source (SELV) which limits voltage to 25V AC or 60V DC allowing for a person to come in contact with it without risk of a shock under normal dry conditions. Under wet conditions, voltage supply should be lowered to reduce risk of shock. These devices have no risk of macroshocks, but some risk of microshocks.
Class I and II electrical appliances are further divided into subtypes developed to limit current leakage in the event of a singular fault:
B (body): Upper limit of current leakage is 500 µA. This current can cause skin tingling and microshocks, but is not sufficient to cause injury.
BF (body floating): These appliances have an isolating capacitor or transformer which separate the secondary circuit from the protective earth. The upper limit of current leakage is the same as type B.
CF (cardiac floating): Upper limit of leakage current during a singular fault is 50 microamps. It is least likely to result in a microshock. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 27
Incorrect
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Which of the following statements is true about the in-hospital management of ventricular fibrillation?
Your Answer: Calcium gluconate has a role in the management of hyperkalaemia.
Correct Answer: Amiodarone may be administered following a third DC shock
Explanation:Ventricular fibrillation (VT) is an arrhythmia caused by a distortion in the organized contraction of the ventricles leading to an inability to pump blood out into the body.
Amiodarone is an anti arrhythmic drug used for the treatment of ventricular and atrial fibrillations. It is the gold standard of treatment for refractory pulseless ventricular tachycardia (VT) and ventricular fibrillation (VF).
Guidelines for emergency treatment state that only the rescuer carrying out chest compressions on the patient may stand near the defibrillator as it charges.
Cardio-pulmonary resuscitation (CPR) during cardiac arrest is required for 2 minute cycles.
Hypovolaemia is as a cause of pulseless electrical activity (PEA) can be reversed using fluid resuscitation, whereas hypotension during cardiac arrest is either persistent or undetectable and is therefore irreversible.
Hyperkalaemia and hypocalcaemia are treated using calcium salts, but calcium chloride is often preferred over calcium gluconate.
During a pulseless VT or VF, a single precordial thump will be effective if administered within the first seconds of the occurrence of a shockable rhythm.
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This question is part of the following fields:
- Pathophysiology
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Question 28
Incorrect
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A mercury barometer can be used to determine absolute pressure. A mercury manometer can be used to check blood pressure. The SI units of length(mm) are used to measure pressure. Why is pressure expressed in millimetres of mercury (mmHg)?
Your Answer: Pressure is directly proportional to the force exerted by the mercury column
Correct Answer: Pressure is directly proportional to length of the mercury column and is variable
Explanation:A mercury barometer can be used to determine absolute pressure. A glass tube with one closed end serves as the barometer. The open end is inserted into a mercury-filled open vessel. The mercury in the container is pushed into the tube by atmospheric pressure exerted on its surface. Absolute pressure is the distance between the tube’s meniscus and the mercury surface.
Pressure is defined as force in newtons per unit area (F) (A).
Mass of mercury = area (A) × density (�) × length (L)
Pressure = ((A × � × L) × 9.8 m/s2)/A
Pressure = � × L x 9.8
Pressure is proportional to LThe numerator and denominator of the above equation, area (A), cancel out. The constants are density and the gravitational acceleration value.
The length is proportional to the applied pressure.
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This question is part of the following fields:
- Physiology
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Question 29
Correct
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The whole water content of the body is calculated by multiplying body mass with 0.6. This water is diffused into distinct compartments. Which fluid compartment can be measured indirectly?
Your Answer: Intracellular volume
Explanation:The total body water content of a 70kg man is (70 × 0.6) = 42 litres. For a woman, the calculation is (70 × 0.55) = 38.5 litres.
For a man, it is subdivided into:
Extracellular fluid (ECF) = 14L (1/3)
Intracellular fluid (ICF) = 28L (2/3).The ECF volume is further divided into:
Interstitial fluid = 10.5 litres
Plasma = 3 litres
Transcellular fluid (CSF/synovial fluid) = 0.5 litres.Directly measured fluid compartments:
Heavy water (deuterium) can be used to measure total body water content, which is freely distributed.
Albumin labelled with a radioactive isotope or using a dye called Evans blue can be used to measure Plasma volume . They do not diffuse into red blood cells.
Radiolabelled (Cr-51) red blood cells can be used to measure total erythrocyte volume.
Inulin as the tracer can be used to measure ECF volume as it circulate freely in the interstitial and plasma volumes.Indirectly measured fluid compartments:
Total blood volume can be calculated with the level of haematocrit and the volume of total circulating red blood cells.
ICF volume can be calculated by subtracting ECF volume from total blood volume. -
This question is part of the following fields:
- Basic Physics
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Question 30
Correct
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A study was concerned with finding out the normal reference range of IgE levels in adults was conducted. Presuming that the curve follows a normal distribution, what is the percentage of individuals having IgE levels greater than 2 standard deviations from mean?
Your Answer: 2.30%
Explanation:Since the data is normally distributed, 95.4% of the values lie with in 2 standard deviations from mean. The rest of the 4.6% are distributed symmetrically outside of that range which means 2.3% of the values lie above 2 standard deviations of the mean.
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This question is part of the following fields:
- Statistical Methods
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