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  • Question 1 - Following an uneventful laparoscopic right hemicolectomy, a previously fit and well 75-year-old male...

    Incorrect

    • Following an uneventful laparoscopic right hemicolectomy, a previously fit and well 75-year-old male is admitted to the critical care unit. You've been summoned to examine the patient because he's become oliguric. Which of the following is most likely to indicate that acute kidney injury is caused by a prerenal cause?

      Your Answer: Urine output less <10 mL/hour

      Correct Answer: Serum urea: creatinine ratio 200

      Explanation:

      Prerenal failure has a serum urea: creatinine ratio of >100, while acute kidney injury has a ratio of 40.
      In prerenal failure, ADH levels are typically high, resulting in water, urea, and sodium resorption. The fractional sodium excretion is less than 1%, but it is greater than 2% in acute tubular necrosis.
      Prerenal azotaemia has higher serum urea nitrogen/serum creatinine ratios (>20), whereas acute tubular necrosis has lower ratios (10-15). The normal range is between 12 and 20.
      Urinary sodium is less than 20 in prerenal failure and greater than 40 in acute tubular necrosis.
      Prerenal failure has a urine osmolality of >500, while acute tubular necrosis has an osmolality of 350.
      Prerenal failure has a urine/serum creatinine ratio of >40, while acute tubular necrosis has a urine/serum creatinine ratio of 20.

      The concentrations of serum urea or creatinine change in inverse proportion to glomerular filtration. Changes in serum creatinine concentrations are more reliable than changes in serum urea concentrations in predicting GFR. Creatinine is produced at a constant rate from creatine, and blood concentrations are almost entirely determined by GFR.

      A number of factors influence urea formation, including liver function, protein intake, and protein catabolism rate. Urea excretion is also influenced by hydration status, the amount of water reabsorption, and GFR.

      A high serum creatinine level, as well as a urine output of less than 10 mL/hour and the production of concentrated looking urine, do not necessarily indicate a specific cause of oliguria.

    • This question is part of the following fields:

      • Pathophysiology
      27.2
      Seconds
  • Question 2 - A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT)...

    Correct

    • A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT) of 20 for the prevention of the primary end-point. These results can be best described as:

      Your Answer: For 1000 patients treated with active therapy, there would be 50 fewer strokes

      Explanation:

      Number needed to treat (NNT) is a time specific epidemiological measure that indicates how many patients would be require for an intervention to prevent one additional bad outcome. A perfect NNT would be 1, where everyone improves with treatment, thus the higher the NNT, the less effective the treatment.

      Thus if you treat 1000 patients then you will expect to have 50 fewer strokes.

    • This question is part of the following fields:

      • Statistical Methods
      57.9
      Seconds
  • Question 3 - A 64-year old male has shortness of breath on exertion and presented to...

    Correct

    • A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart. How can this echo aid in calculating cardiac output?

      Your Answer: (end diastolic LV volume - end systolic LV volume) x heart rate

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      59.3
      Seconds
  • Question 4 - A meta analysis takes into consideration five studies each of which is aimed...

    Incorrect

    • A meta analysis takes into consideration five studies each of which is aimed at finding out the relation between a novel drug and upper gastro intestinal bleeding. The relative risk of getting an upper gastrointestinal bleed matched to a control population is recorded by each study. Which among the following studies provides the most compelling evidence that the bleeding is not caused by the new drug?

      Your Answer: Dennis et al

      Correct Answer: Atkinson et al

      Explanation:

      The research study conducted by Atkinson et al makes the most compelling case for the drug as it indicates the relative risk levels to be lower than 1. Also the study employs large square and a narrow confidence interval that are an indicative of a well performed study.

    • This question is part of the following fields:

      • Statistical Methods
      10.6
      Seconds
  • Question 5 - Which of the following facts about T cells is true? ...

    Correct

    • Which of the following facts about T cells is true?

      Your Answer: Secrete IL-2 when activated

      Explanation:

      T cells function as a part of the body’s adaptive immune system. There are different types of T cells, including:

      Cytotoxic T cells: Function as killer cells by releasing cytotoxic granules into the membrane of targeted cells.

      T-Helper cells: When activated, they function to activate other immune cell types, assist in antibody production with B cells and releasing cytokines including IL-2.

      Memory T cells: Function as to provide immune memory against already encountered antigens.

      T cells possess specific glycoproteins and receptors on their surface.

      T-Helper cells work with HLA class II antigens on the cell surfaces in order to recognise foreign antigens

      T cells survive ranges from a few weeks, to a lifetime depending on the subtype in question.

      Immunoglobulins are expressed on the surface of, and secreted by B-lymphocytes.

      Native antigens are recognised by B cells. T cells only recognise antigens that have been processed by the cells and presented on the surface of the cell.

    • This question is part of the following fields:

      • Pathophysiology
      14.9
      Seconds
  • Question 6 - If a patient is to be placed under general anaesthesia using total intravenous...

    Correct

    • If a patient is to be placed under general anaesthesia using total intravenous technique with target-controlled infusions of propofol and remifentanil, what safety precaution is the most vital in this a scenario?

      Your Answer: Cannula access site clearly visible and regularly checked

      Explanation:

      According to the Safe Anaesthesia Liaison Group, the most important factor to consider the cannula access, and if the patient is properly receiving the total intravenous anaesthesia. The cannula access must be regularly checked for kinks, leaks and disconnections.

      Below are the safety precautions and policies to be followed for total intravenous anaesthesia among children and adults:

      When administering TIVA, a non-return valve must be used on any intravenous fluid line;
      When using equipment, it is essential that clinical staff know its limitations and uses;
      Sites of intravenous infusions should be visible so they may be monitored for disconnection, leaks or perivenous infusion into the subcutaneous tissues; and,
      Organisations must give preference to clearly labelled intravenous connectors and valves.

    • This question is part of the following fields:

      • Pathophysiology
      15.2
      Seconds
  • Question 7 - Risk stratification is done prior to a major cardiac surgery using cardiopulmonary exercise...

    Correct

    • Risk stratification is done prior to a major cardiac surgery using cardiopulmonary exercise testing. Given the following options, which one is most likely to have the highest risk for post-operative cardiac morbidity?

      Your Answer: Anaerobic threshold (AT) of less than 11 mL/kg/minute

      Explanation:

      The ventilatory anaerobic threshold (VAT), formerly referred to as the anaerobic threshold, is an index used to estimate exercise capacity. During the initial (aerobic) phase of CPET, which lasts until 50€“60% of Vo2max is reached, expired ventilation (VE) increases linearly with Vo2 and reflects aerobically produced CO2 in the muscles. Blood lactate levels do not change substantially during this phase, since muscle lactic acid production is minimal.

      During the latter half of exercise, anaerobic metabolism occurs because oxygen supply cannot keep up with the increasing metabolic requirements of exercising muscles. At this time, there is a significant increase in lactic acid production in the muscles and in the blood lactate concentration. The Vo2 at the onset of blood lactate accumulation is called the lactate threshold or the VAT. The VAT is also defined as the point at which minute ventilation increases disproportionately relative to Vo2, a response that is generally seen at 60€“70% of Vo2max.

      The VAT is a useful measure as work below this level encompasses most daily living activities. The ability to achieve the VAT can help distinguish cardiac and non€�cardiac (pulmonary or musculoskeletal) causes of exercise limitation, since patients who fatigue before reaching VAT are likely to have a non€�cardiac problem.

      When VAT is detected, patients with PVo2 of ©½10€…ml/kg/min have a high event rate.

    • This question is part of the following fields:

      • Pathophysiology
      7.1
      Seconds
  • Question 8 - Heights of 100 individuals(adults) who were administered steroids at any stage during childhood...

    Incorrect

    • Heights of 100 individuals(adults) who were administered steroids at any stage during childhood was studied. The mean height was found to be 169cm with the data having a standard deviation of 16cm. What will be the standard error associated with the mean?

      Your Answer: 1.3

      Correct Answer: 1.6

      Explanation:

      Standard error can be calculated by the following formula:
      Standard Error= (Standard Deviation)/ˆš(Sample Size)
      = (16) / ˆš(100)
      = 16 / 10
      = 1.6

    • This question is part of the following fields:

      • Statistical Methods
      53.2
      Seconds
  • Question 9 - The following haemodynamic data is available from a patient with pulmonary artery catheter...

    Correct

    • The following haemodynamic data is available from a patient with pulmonary artery catheter inserted: Pulse rate - 100 beats per minute, Blood pressure - 120/70mmHg, Mean central venous pressure (MCVP) - 10mmHg, Right ventricular pressure (RVP) - 30/4 mmHg, Mean pulmonary artery wedge pressure (MPAWP) - 12mmHg. Which value best approximates the patient's coronary perfusion pressure?

      Your Answer: 58mmHg

      Explanation:

      Coronary perfusion pressure(CPP), the difference between aortic diastolic pressure (Pdiastolic) and the left ventricular end-diastolic pressure (LVEDP), is mainly determined by the formula:

      CPP = Pdiastolic -LVEDP
      where
      Pdiastolic is the lowest pressure in the aorta before left ventricular ejection and
      LVEDP is measured directly during a cardiac catheterisation or indirectly using a pulmonary artery catheter. The pulmonary artery occlusion or wedge pressure approximates best with LVEDP.

      Using this patient’s haemodynamic data:

      CPP = Pdiastolic – MPAWP
      COO = 70 – 12 = 58mmHg.

    • This question is part of the following fields:

      • Clinical Measurement
      28.8
      Seconds
  • Question 10 - A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure,...

    Incorrect

    • A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure, the ileocolic artery is ligated. Which vessel does this artery originate from?

      Your Answer: Coeliac axis

      Correct Answer: Superior mesenteric artery

      Explanation:

      The ileocolic artery is the terminal branch of the superior mesenteric artery. It supplies:
      1. terminal ileum
      2. proximal right colon
      3. cecum
      4. appendix (via its branch of the appendicular artery)

      As veins accompany arteries in the mesentery and are lined by lymphatics, high ligation is the norm in cancer resections€”the ileocolic artery branches off the SMA near the duodenum.

    • This question is part of the following fields:

      • Anatomy
      16.6
      Seconds
  • Question 11 - A 23-year-old man, has just undergone surgery under general anaesthesia. He has experienced...

    Incorrect

    • A 23-year-old man, has just undergone surgery under general anaesthesia. He has experienced a severe reaction to the anaesthetic agent resulting in malignant hyperthermia (MH) for which he has been referred for treatment. What investigation can be conducted to determine a patient's susceptibility to malignant hyperthermia?

      Your Answer: Chromosomal analysis

      Correct Answer: In vitro muscle contraction test using caffeine

      Explanation:

      Malignant hyperthermia (MH) is a autosomal dominant inherited medical condition which predisposes affected individuals to a clinical syndrome of hypermetabolism which involves abnormal ryanodine receptors in skeletal muscle causing a deregulation of calcium in muscle.

      It is a life threatening condition requiring immediate medical intervention. It often lies dormant until triggered in susceptible individuals mostly by volatile inhaled anaesthetic agents and succinylcholine which is a muscle relaxant.

      The signs and symptoms of MH are related to this hypermetabolism, which includes an increase in carbon dioxide production, metabolic and respiratory acidosis, accelerated oxygen consumption, heat production, activation of the sympathetic nervous system, hyperkalaemia, disseminated intravascular coagulation (DIC), and multiple organ dysfunction and failure.

      Early signs of MH to look out for in patients includes an uptick in end-tidal carbon dioxide (even with increasing minute ventilation), tachycardia, muscle rigidity, tachypnoea, and hyperkalaemia. Later signs include fever, myoglobinuria, and multiple organ failure.

      In vitro muscle contracture test (IVCT) is the standard for determining individual susceptibility to MH. It is conducted by measuring the force of muscle contraction after exposing the patient’s muscle sample to halothane and caffeine., the sample is normally taken from the vastus medialis or lateralis under regional anaesthesia.

    • This question is part of the following fields:

      • Clinical Measurement
      19.5
      Seconds
  • Question 12 - Drug X, a new intravenous induction drug, is being administered as a bolus...

    Correct

    • Drug X, a new intravenous induction drug, is being administered as a bolus at regular time intervals, and the following data were observed: Time following injection (hours) vs Plasma concentration of drug X (mcg/mL) 2 / 400 6 / 100 10 / 25 14 / 6.25 Which of the following values estimate the plasma half-life (T½) of drug X?

      Your Answer: 2 hours

      Explanation:

      Half life (T½) is the time required to change the amount of drug in the body by one-half (or 50%) during elimination. The time course of a drug in the body will depend on both the volume of distribution and the clearance.

      Extrapolating the values from the plasma concentration vs time:

      Plasma concentration at 0 hours = 800 mcg/mL
      Plasma concentration at 2 hours = 400 mcg/mL
      Plasma concentration at 4 hours = 200 mcg/mL
      Plasma concentration at 6 hours = 100 mcg/mL
      Plasma concentration at 8 hours = 50 mcg/mL
      Plasma concentration at 10 hours = 25 mcg/mL
      Plasma concentration at 12 hours = 12.5 mcg/mL
      Plasma concentration at 14 hours = 6.25 mcg/mL

    • This question is part of the following fields:

      • Statistical Methods
      35.7
      Seconds
  • Question 13 - Which of the following is true about Calcium? ...

    Incorrect

    • Which of the following is true about Calcium?

      Your Answer: Half of Calcium exists as ionised Calcium in serum

      Correct Answer: Only 1% of total body Calcium is found in the plasma

      Explanation:

      Only 1 percent of the calcium in the human body is found in the plasma where it performs the most critical functions.

      Out of this 1 percent, approximately 15% is complexed calcium bound to organic and inorganic anions, 40% is bound to albumin, and the remaining 45% circulates as free ionized calcium.

      The Chvostek sign is a clinical finding associated with hypocalcaemia, or low levels of calcium in the blood. This clinical sign refers to a twitch of the facial muscles that occurs when gently tapping an individual’s cheek, in front of the ear.

      Prolonged QT interval are associated with hypocalcaemia as reported in multiple studies.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      22.1
      Seconds
  • Question 14 - Post thyroidectomy, a 50-year-old male singer noticed some hoarseness in his voice. Now,...

    Correct

    • Post thyroidectomy, a 50-year-old male singer noticed some hoarseness in his voice. Now, he presents to his general physician as it has been the same for the past few weeks. A complication is noted in the post-thyroidectomy report regarding an injury to the external laryngeal nerve. Which muscle has been affected due to loss of innervation by the damaged nerve, and whose improper functioning can lead to hoarseness in the patient's voice?

      Your Answer: Cricothyroid

      Explanation:

      All of the muscles of the larynx are innervated by the recurrent laryngeal nerve, except the cricothyroid muscle.

      Cricothyroid muscle is located deep in the anterior neck, between the cricoid and thyroid cartilage and is innervated by the external laryngeal nerve. Any injury to this muscle can cause paralysis and lead to hoarseness. When cricothyroid muscle contracts, it leads to tightening, stretching and thinning of the vocal folds. This produces higher-pitched sounds during vocalization.

      A patient experiencing hoarseness due to possible injury to the external laryngeal nerve should be reassured that the hoarseness will resolve in time due to increased compensation from the other muscles.

    • This question is part of the following fields:

      • Anatomy
      17.3
      Seconds
  • Question 15 - The thebesian veins contribute to the venous drainage of the heart. Into which...

    Correct

    • The thebesian veins contribute to the venous drainage of the heart. Into which of the following structures do they primarily drain?

      Your Answer: Atrium

      Explanation:

      The heart has two venous drainage systems:
      1. Greater venous system – it parallels the coronary arterial circulation and provides 70% venous drainage to the heart
      2. Lesser venous system – includes the thebasian veins and provides up to 30% of the venous drainage to the heart

      Thebasian veins (also called venae cordis minimae) are the smallest coronary veins and run in the myocardial layer of the heart. They serve to drain the myocardium and are present in all four heart chambers. They are more abundant on the right side of the heart and, more specifically, are most abundant in the right atrium. Thebesian veins drain the subendocardial myocardium either directly, via connecting intramural arteries and veins, or indirectly, via subendocardial sinusoidal spaces.

    • This question is part of the following fields:

      • Anatomy
      10
      Seconds
  • Question 16 - A double-blinded randomised controlled trial is proposed to assess the effectiveness of a...

    Correct

    • A double-blinded randomised controlled trial is proposed to assess the effectiveness of a new blood pressure medication. Which type of bias can be avoided by ensuring the patient and doctor are blinded?

      Your Answer: Expectation bias

      Explanation:

      Observers may subconsciously measure or report data in a way that favours the expected study outcome. Therefore, by blinding the study we can eliminate expectation bias.

      Recall bias is a systematic error that occurs when the study participants omit details or do not remember previous events or experiences accurately.

      Verification can occur during investigations when there is a difference in testing strategy between groups of individuals, which might lead to biasness due to differing ways of verifying the disease of interest.

      Nonresponse bias is the bias that occurs when the people who respond to a survey differ significantly from the people who do not respond to the survey.

      A distortion that modifies an association between an exposure and an outcome because a factor is independently associated with the exposure and the outcome. Randomization is the best way to reduce the risk of confounding.

    • This question is part of the following fields:

      • Statistical Methods
      13.6
      Seconds
  • Question 17 - Out of the following, which anatomical structure lies within the spiral groove of...

    Correct

    • Out of the following, which anatomical structure lies within the spiral groove of the humerus?

      Your Answer: Radial nerve

      Explanation:

      The shaft of the humerus has two prominent features:
      1. Deltoid tuberosity – attachment for the deltoid muscle
      2. Radial or spiral groove – The radial nerve and profunda brachii artery lie in the groove

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs. The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The following parts of the humerus are in direct contact with the indicated
      nerves:
      Surgical neck: axillary nerve.
      Radial groove: radial nerve.
      Distal end of humerus: median nerve.
      Medial epicondyle: ulnar nerve.

    • This question is part of the following fields:

      • Anatomy
      5.4
      Seconds
  • Question 18 - Which of the following statements is an accurate fact about the vertebral column?...

    Correct

    • Which of the following statements is an accurate fact about the vertebral column?

      Your Answer: Herniation of intervertebral disc between the fifth and sixth cervical vertebrae will compress the sixth cervical nerve root

      Explanation:

      The vertebral (spinal) column is the skeletal central axis made up of approximately 33 bones called the vertebrae.

      Cervical disc herniations occur when some or all of the nucleus pulposus extends through the annulus fibrosus. The most commonly affected discs are the C5-C6 and C6-C7 discs. Each vertebrae has a corresponding nerve root which arises at a level above it. This means that a hernation of the C5-C6 disc will cause a compression of the C6 nerve root.

      The foramen transversarium is a part of the transverse process of each cervical vertebrae, however, the vertebral artery only runs through the C1-C6 foramen transversarium.

      The costal facets are the point of joint formation between a rib and a vertebrae. As such, they are only present on the transverse processes of T1-T10.

      The lumbar vertebrae do not form a joint with the ribs, nor do they possess a foramina in their transverse process.

      Intervertebral discs are thickest in the cervical and lumbar regions of the spinal column. However, there are no discs between C1 and C2.

    • This question is part of the following fields:

      • Pathophysiology
      22.9
      Seconds
  • Question 19 - A young woman presented with a gynaecological related infection and was prescribed a...

    Correct

    • A young woman presented with a gynaecological related infection and was prescribed a cephalosporin. Which of the following is correct about the mechanism of action of this drug?

      Your Answer: Bacterial cell wall synthesis inhibition

      Explanation:

      Cephalosporin belongs to a family of beta-lactam antibiotics. All β-lactam antibiotics interfere with the synthesis of the bacterial cell walls. The β-lactam antibiotics inhibit the transpeptidases so that cross-linking (which maintains the close-knit structure of the cell wall) does not take place i.e. they inhibit bacterial cell wall formation.

    • This question is part of the following fields:

      • Pharmacology
      5.5
      Seconds
  • Question 20 - The statement that best describes lactic acidosis is: ...

    Incorrect

    • The statement that best describes lactic acidosis is:

      Your Answer: An anion gap of > 10 mmol is diagnostic

      Correct Answer: It can be precipitated by intravenous fructose

      Explanation:

      An elevated arterial blood lactate level and an increase anion gap ([Na + K] – [Cl + HCO3]) of >20mmol gives rise to lactic acidosis. It can also be a result of overproduction and/or reduced metabolism of lactic acid.

      The liver and kidney are the main sites of lactate metabolism, not skeletal muscle.

      The two types of lactic acidosis that are known are:

      Type A – due to tissue hypoxia, inadequate tissue perfusion and anaerobic glycolysis. These may be seen in cardiac arrest, shock, hypoxaemia and anaemia. The management of type A lactic acidosis involves reversing the underlying cause of the tissue hypoxia.

      Type B – occurs in the absence of tissue hypoxia. Some of the causes of this include hepatic failure, renal failure, diabetes mellitus, pancreatitis and infection. Some drugs can also cause this lie aspirin, ethanol, methanol, biguanides and intravenous fructose.

      The mainstay of treatment involves:
      1. Optimising tissue oxygen delivery
      2. Correcting the cause
      3. Intravenous sodium bicarbonate

      In resistant cases, peritoneal dialysis can be performed.

    • This question is part of the following fields:

      • Physiology
      15.3
      Seconds
  • Question 21 - An acidic drug with a pKA of 4.3 is injected intravenously into a...

    Incorrect

    • An acidic drug with a pKA of 4.3 is injected intravenously into a patient. At a normal physiological pH, the approximate ratio of ionised to unionised forms of this drug in the plasma is?

      Your Answer: 10,000:1

      Correct Answer: 1000:01:00

      Explanation:

      The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.

      To calculate the proportion of ionised to unionised form of an ACID, use the Henderson-Hasselbalch equation.

      pH = pKa + log ([A-]/[HA])

      or

      pH = pKa + log [(salt)/(acid)]
      pH = pKa + log ([ionised]/[unionised]).

      Hence, if the pKa ˆ’ pH = 0, then 50% of drug is ionised and 50% is unionised.

      In this example:

      7.4 = 4.3 + log ([ionised]/[unionised])
      7.4 ˆ’ 4.3 = log ([ionised]/[unionised])
      log 3.1 = log ([ionised]/[unionised])

      Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:

      y = antilog x = 10x

      Antilog to the base 10 of 0 = 1, 1 = 10, 2 =100, 3 = 1000, and 4 = 10,000.

      If you want to find the antilogarithm of 3.1, for a number between 3 and 4, the antilogarithm will return a value between 1000 and 10,000. The ratio is 1:1 if pKa = pH, that is, pH pKa = log 0. (50 percent ionised and unionised).

      According to the above value, there is only one unionised molecule for every approximately 1000 (1259) ionised molecules of this drug in plasma, implying that this drug is largely ionised in plasma (99.99 percent ).

    • This question is part of the following fields:

      • Pharmacology
      128.9
      Seconds
  • Question 22 - A 27-year-old woman takes part in a study looking into the effects of...

    Correct

    • A 27-year-old woman takes part in a study looking into the effects of different dietary substrates on metabolism. She receives a 24-hour ethyl alcohol infusion. A constant volume, closed system respirometer is used to measure CO2 production and consumption. The production of carbon dioxide is found to be 200 mL/minute. Which of the following values most closely resembles her anticipated O2 consumption at the conclusion of the trial?

      Your Answer: 300 mL/minute

      Explanation:

      The respiratory quotient (RQ) is the ratio of CO2 produced by the body to O2 consumed in a given amount of time.

      CO2 produced / O2 consumed = RQ

      CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.

      The RQ will change depending on the energy substrates consumed in the diet. Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.

      Glucose and other hexose sugars (glucose and other hexose sugars):
      RQ=1

      Fats:
      RQ = 0.7

      Proteins:
      Approximately 0.9 RQ

      Ethyl alcohol is a type of alcohol.

      200/300 = 0.67 RQ

      For complete oxidation, lipids and alcohol require more oxygen than carbohydrates.

      When carbohydrate is converted to fat, the RQ can rise above 1.0. Fat deposition and weight gain are likely to occur in these circumstances.

    • This question is part of the following fields:

      • Physiology
      52
      Seconds
  • Question 23 - You're summoned to the emergency room, where a 39-year-old man has been admitted...

    Correct

    • You're summoned to the emergency room, where a 39-year-old man has been admitted following a cardiac arrest. He was rescued from a river, but little else is known about him. CPR is being performed on the patient, who has been intubated. He's received three DC shocks and is still in VF. A rectal temperature of 29.5°C is taken with a low-reading thermometer. Which of the following statements about his resuscitation is correct?

      Your Answer: No further DC shocks and no drugs should be given until his core temperature is greater than 30°C

      Explanation:

      The guidelines for the management of cardiac arrest in hypothermic patients published by the UK Resuscitation Council differ slightly from the standard algorithm.

      In a patient with a core temperature of less than 30°C, do the following:

      If you’re on the shockable side of the algorithm (VF/VT), you should give three DC shocks.
      Further shocks are not recommended until the patient has been rewarmed to a temperature of more than 30°C because the rhythm is refractory and unlikely to change.
      There should be no drugs given because they will be ineffective.

      In a patient with a core temperature of 30°C to 35°C, do the following:

      DC shocks are used as usual.
      Because they are metabolised much more slowly, the time between drug doses should be doubled.

      Active rewarming and protection against hyperthermia should be given to the patient.

      Option e is false because there is insufficient information to determine whether resuscitation should be stopped.

    • This question is part of the following fields:

      • Physiology
      23.3
      Seconds
  • Question 24 - The solutions that contains the most sodium is? ...

    Incorrect

    • The solutions that contains the most sodium is?

      Your Answer: 500 mL 5% N saline

      Correct Answer: 3500 mL 0.9% N saline

      Explanation:

      Sodium concentration for different fluids
      3% N saline 513 mmol/L
      5% N saline 856 mmol/L
      0.9% N saline 154 mmol/L
      Hartmann’s solution 131 mmol/L
      0.45% N saline with 5% glucose 77 mmol/L

      This means that:

      500 mL 5% N saline contains 428 mmol of sodium
      1000 mL 3% N saline contains 513 mmol of sodium
      3500 mL 0.9% N saline contains 539 mmol of sodium
      4000 mL Hartmann’s contains 524 mmol of sodium
      6000 mL 0.45% N saline with 5% glucose contains 462 mmol of sodium.

    • This question is part of the following fields:

      • Physiology
      100.3
      Seconds
  • Question 25 - Which of the following statements is true about data analysed from a new...

    Incorrect

    • Which of the following statements is true about data analysed from a new drug trial?

      Your Answer: A Student's t test could be used

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      The data is ideal for chi square test evaluation as it will help determine if observed outcomes are in line with expected outcomes, and also if results are significant or due to chance.

      The student’s t test is not ideal as it requires comparison of means from different populations, rather than proportions.

      Pearson’s coefficient of linear regression is not ideal as it requires the plotting of a linear regression.

      The numbers should be analysed before determining if there are any statistical conclusions that can be drawn from the population.

      Statistical analysis is always required to determine the performance of any treatment during a clinical drug trial. Conclusions cannot be drawn simply by looking at the data.

    • This question is part of the following fields:

      • Statistical Methods
      20.9
      Seconds
  • Question 26 - What can you see within the tunica media of a blood vessel on...

    Correct

    • What can you see within the tunica media of a blood vessel on examination?

      Your Answer: Smooth muscle

      Explanation:

      The blood vessel well is divided into 3 parts, namely:

      The tunica intima, which is the deepest layer. It contains endothelial cells separated by gap junctions

      The tunica media, primarily consisting of the involuntary smooth muscle fibres, laid out in spiral layers with elastic fibres and connective tissue.

      The tunica adventitia, which is the most superficial layer. It consists of the vasa vasorum, fibroblast and collagen.

    • This question is part of the following fields:

      • Anatomy
      14.2
      Seconds
  • Question 27 - A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he...

    Incorrect

    • A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he requires a urethral catheter. Where does resistance first occur during the insertion of a catheter?

      Your Answer: Prostatic urethra

      Correct Answer: Membranous urethra

      Explanation:

      The membranous urethra is the shortest part of the urethra and the least dilatable part of it.

      This is as a result of it being surrounded by the external urethral sphincter which is made up of striated muscle and controls voluntary urine flow from the bladder to the urethra.

    • This question is part of the following fields:

      • Anatomy
      22.7
      Seconds
  • Question 28 - Monitoring of which of the following is indicated in the prevention of propofol...

    Correct

    • Monitoring of which of the following is indicated in the prevention of propofol infusion syndrome?

      Your Answer: Blood glucose

      Explanation:

      Propofol infusion syndrome (PRIS) is characterized by lactic acidosis, bradyarrhythmia, rhabdomyolysis, cardiac and renal failure, and often leads to death. So, lactate monitoring is advised inpatients with propofol infusion syndrome.

    • This question is part of the following fields:

      • Pharmacology
      19.4
      Seconds
  • Question 29 - The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised...

    Correct

    • The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?

      Your Answer: Synthesis of ATP is brought about by anaerobic respiration

      Explanation:

      Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.

      Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.

      Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.

      Muscle fibres of type II (fast twitch) are divided into three types:

      Type IIa – aerobic/oxidative metabolism is used.
      Type IIb – anaerobic/glycolytic metabolism is used by these fibres.

      When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.

    • This question is part of the following fields:

      • Pharmacology
      32.6
      Seconds
  • Question 30 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level. Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer: Students t-test

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
      8.5
      Seconds
  • Question 31 - General anaesthesia is administered to a patient in a hospital in Lhasa which...

    Incorrect

    • General anaesthesia is administered to a patient in a hospital in Lhasa which is one of the highest cities in the world (at 11,975 feet). An Anaesthetic rotameter is normally calibrated at 20 C and 1 bar pressure and is known to be underread at altitude. The temperature of the theatre was 10 C. Which one of the following physical properties is responsible for the rotameter inaccuracy in these conditions?

      Your Answer: Pressure in the gas cylinder

      Correct Answer: Density of the gas

      Explanation:

      Since the gas is less dense at higher altitudes, the density of a gas influences flows when passing through the orifice. Due to this reason, for a given flow rate, the bobbin will not be forced as far up the rotameter tube.

      At higher altitudes, the volume of a fixed mass of gas increases, and therefore the molecules of gas are widely spaced resulting in a decrease in density with an increase in altitude.

      Viscosity is simply termed as friction of gas. The viscosity of a gas is important only at low flow rates when the flow characteristic of the gas is laminar.

      Charle’s law stated that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature (T) provided the pressure remains constant.

      Boyle’s law for a fixed amount of gas at constant temperature, the pressure (P) and volume (V) are inversely proportional.

    • This question is part of the following fields:

      • Basic Physics
      33.8
      Seconds
  • Question 32 - A 74-year-old man presents to a hospital for manipulation of Colles fracture. The...

    Correct

    • A 74-year-old man presents to a hospital for manipulation of Colles fracture. The patient is 50 kg and the anaesthetic plan is to perform an intravenous regional (Bier's) block. Which of the following is the appropriate dose of local anaesthetic for the procedure?

      Your Answer: 0.5% prilocaine (40 ml)

      Explanation:

      Prilocaine is the drug of choice for intravenous regional anaesthesia. 0.5% prilocaine (40 ml) is indicated for this condition.
      Lidocaine is another alternative for this condition but volume and dose are likely to be inadequate for the procedure.

    • This question is part of the following fields:

      • Pharmacology
      8.7
      Seconds
  • Question 33 - A 33-year old man was referred to you because of difficulty moving his...

    Incorrect

    • A 33-year old man was referred to you because of difficulty moving his limbs. History revealed that he was placed under anaesthesia for a major surgery 12 hours prior to the referral. Other symptoms were noted such as anxiousness, agitation, and fever of 38°C. Upon physical examination, he was tachycardic at 119 beats per minute. Moreover, his medical history showed that he was on Fluoxetine for clinical depression. The nurses reported that, because of his frequent complaints of axillary pain, he was given tramadol with paracetamol. Which of the following is responsible for his clinical features?

      Your Answer: Neuroleptic malignant syndrome

      Correct Answer: Tramadol

      Explanation:

      Tramadol is weak agonist at the mu receptor. It inhibits the neuronal reuptake of serotonin and norepinephrine, and inhibits pain neurotransmission. It is given for moderate pain, chronic pain syndromes, and neuropathic pain.

      Fluoxetine is a selective serotonin reuptake inhibitor (SSRI). It inhibits the neuronal reuptake of serotonin by inhibiting the serotonin transporter (SERT). It is the drug of choice for major depressive disorder, and is given for other psychiatric disorders such as anxiety, obsessive-compulsive, post-traumatic stress, and phobias.

      When tramadol is given with SSRIs, serotonin syndrome may occur. Serotonin syndrome is characterized by fever, agitation, tremors, clonus, hyperreflexia and diaphoresis. The onset of symptoms may occur within a few hours, and the first-line treatment is sedation, paralysis, intubation and ventilation.

    • This question is part of the following fields:

      • Pharmacology
      23.9
      Seconds
  • Question 34 - When the volume of gas is measured, its value should be supported by...

    Correct

    • When the volume of gas is measured, its value should be supported by a suitable abbreviation. From the following options, what does the STPD stand for?

      Your Answer: Standard Temperature and Pressure, Dry

      Explanation:

      Gas is composed of large numbers of molecules moving in random directions, separated by distances. They undergo perfectly elastic collisions with each other and the walls of a container and transfer kinetic energy in form of heat. These assumptions bring the characteristics of gases within the range and reasonable approximation to a real gas, particularly how any change in temperature and pressure affect the behaviour of gas. According to different theories and laws proposed, mathematical equations are derived to calculate the volume of gas, also different abbreviations are being used according to given conditions. The abbreviations used are ATP, BTPS, and STPD.
      ATP stands for ambient temperature and barometric pressure, it is used to describe the conditions under which volume of gas is measured.
      BTPS stands for body temperature and pressure saturated with water vapor. These are conditions under which volume of gas exist and all results of lung volume determination should be quoted at BTPS.
      STPD stands for standard temperature and pressure, dry (0C and 760 mm Hg). These are the conditions that are used to describe quantities of individual gases exchanged in the lungs.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      4.5
      Seconds
  • Question 35 - A patient is evaluated for persistent dysphonia six months after undergoing a subtotal...

    Correct

    • A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy. Which of the following is the most likely reason for the change in this patient's voice?

      Your Answer: Damage to recurrent laryngeal nerve

      Explanation:

      After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.

      Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.

      On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.

      Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.

      This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.

      The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.

      Vocal cord polyps affect 0.8 percent of people.

    • This question is part of the following fields:

      • Pathophysiology
      16.6
      Seconds
  • Question 36 - Regarding basal metabolic rate (BMR), which of the following is the most efficient...

    Correct

    • Regarding basal metabolic rate (BMR), which of the following is the most efficient regulator of BMR?

      Your Answer: Hypothalamus

      Explanation:

      The hypothalamus is primarily responsible for the regulation of the basal metabolic rate. It releases thyrotropin releasing hormones (TRH) in response to low levels of triiodothyronine (T3) and thyroxine (T4). The TRH acts on the pituitary gland to release thyroid stimulating hormone, which will stimulate the thyroid gland to synthesize more T3 and T4.

      Basal metabolic rate refers to the energy expended by an individual in a resting, post-absorptive state. It represents the energy required to carry out normal body functions, such as respiration.

    • This question is part of the following fields:

      • Pathophysiology
      4.4
      Seconds
  • Question 37 - A single intravenous dose of 100 mg phenytoin was administered to a 70...

    Correct

    • A single intravenous dose of 100 mg phenytoin was administered to a 70 kg patient and plasma concentration monitored. The concentration in plasma over time is recorded as follows: Time (hours): 1, 2, 3, 4, 5, Concentration (mcg/mL) 100, 71, 50, 35.5, 25. From the data available, the drug is likely eliminated by?

      Your Answer: First-order kinetics with a half-life of 2 hours

      Explanation:

      Elimination of phenytoin from the body follows first-order kinetics. This means that the rate of elimination is proportional to plasma concentration.

      The rate of elimination can be described by the equation:

      C = C0·e-kt

      Where:

      C = drug concentration
      C0 = drug concentration at time zero (extrapolated)
      k = Rate constant
      t = Time

      Enzyme systems become saturated when phenytoin concentrations exceed the normal range and elimination of the drug becomes zero-order. At this point, the drug is metabolised at a fixed rate and metabolism is independent of plasma concentration.

      Aspirin and ethyl alcohol are other drugs that behave this way.

    • This question is part of the following fields:

      • Pharmacology
      60.9
      Seconds
  • Question 38 - All of the following statements about cerebrospinal fluid are incorrect except: ...

    Incorrect

    • All of the following statements about cerebrospinal fluid are incorrect except:

      Your Answer: Contains the same concentration of protein as plasma

      Correct Answer: Has a glucose concentration 2/3 that of the plasma glucose

      Explanation:

      The pH of CSF is 7.31 which is lower than plasma.

      Compared to plasma, it has a lower concentration of potassium, calcium, and protein and a higher concentration of sodium, chloride, bicarbonate and magnesium.

      CSF usually has no cells present but if white cells are present, there should be no more than 4/ml.

      The pressure of CSF should be less than 20 cm of water.

      The concentration of glucose is approximately two-thirds of that of plasma, and it has a concentration of approximately 3.3-4 mmol/L.

    • This question is part of the following fields:

      • Physiology
      9.7
      Seconds
  • Question 39 - A strict diet is mandatory for which of the following drugs for mood...

    Incorrect

    • A strict diet is mandatory for which of the following drugs for mood disorders?

      Your Answer: Moclobemide

      Correct Answer: Tranylcypromine

      Explanation:

      Tranylcypromine is a monoamine oxidase inhibitor that binds irreversibly to target enzyme.

      Monoamine oxidase inhibitors are responsible for blocking the monoamine oxidase enzyme. The monoamine oxidase enzyme breaks down different types of neurotransmitters from the brain: norepinephrine, serotonin, dopamine, and tyramine. MAOIs inhibit the breakdown of these neurotransmitters thus, increasing their levels and allowing them to continue to influence the cells that have been affected by depression.

      There are two types of monoamine oxidase, A and B. The MAO A is mostly distributed in the placenta, gut, and liver, but MAO B is present in the brain, liver, and platelets. Serotonin and noradrenaline are substrates of MAO A, but phenylethylamine, methylhistamine, and tryptamine are substrates of MAO B. Dopamine and tyramine are metabolized by both MAO A and B. Selegiline and rasagiline are irreversible and selective inhibitors of MAO type B, but safinamide is a reversible and selective MAO B inhibitor.

      MAOIs prevent the breakdown of tyramine found in the body and certain foods, drinks, and other medications. Patients that take MAOIs and consume tyramine-containing foods or drinks will exhibit high serum tyramine level. A high level of tyramine can cause a sudden increase in blood pressure, called the tyramine pressor response. Even though it is rare, a high tyramine level can trigger a cerebral haemorrhage, which can even result in death.

      Eating foods with high tyramine can trigger a reaction that can have serious consequences. Patients should know that tyramine can increase with the aging of food; they should be encouraged to have fresh foods instead of leftovers or food prepared hours earlier. Examples of high levels of tyramine in food are types of fish and types of meat, including sausage, turkey, liver, and salami. Also, certain fruits can contain tyramine, like overripe fruits, avocados, bananas, raisins, or figs. Further examples are cheeses, alcohol, and fava beans; all of these should be avoided even after two weeks of stopping MAOIs. Anyone taking MAOIs is at risk for an adverse hypertensive reaction, with accompanying morbidity. Patients taking reversible MAOIs have fewer dietary restrictions.

      Amitriptyline is a tricyclic antidepressant, and citalopram and escitalopram are selective serotonin reuptake inhibitors.

    • This question is part of the following fields:

      • Pharmacology
      7.1
      Seconds
  • Question 40 - A patient admitted to the hospital is on oxygen via a venturi mask....

    Incorrect

    • A patient admitted to the hospital is on oxygen via a venturi mask. The air entrainment ratio is 1:9 i.e. 1 litre of 100% oxygen from the source entrains 9 litres of air from the atmosphere). The flow rate of 100% oxygen is 6L/minute. Based on the given data which of the following value approximates the oxygen concentration delivered to the patient?

      Your Answer: 35%

      Correct Answer: 28%

      Explanation:

      The formula for calculating air: oxygen entrainment ratio is given as :
      100% ˆ’ FiO2 = air/oxygen entrainment ratio
      Since FiO2 ˆ’ 21% and the entrainment ratio is already known. Substituting the values in the equation: x = FiO2.

      100 ˆ’ x = 9
      x ˆ’ 21
      100 ˆ’ x = 9(x ˆ’ 21)
      100 ˆ’ x = 9x ˆ’ 189
      10x = 289
      x = 289/10
      x = 28.9%.

    • This question is part of the following fields:

      • Basic Physics
      89.9
      Seconds
  • Question 41 - A 63-year old man has palpitations and goes to the emergency room. An...

    Correct

    • A 63-year old man has palpitations and goes to the emergency room. An ECG shows tall tented T waves, which corresponds to phase 3 of the cardiac action potential. The shape of the T wave is as a result of which of the following?

      Your Answer: Repolarisation due to efflux of potassium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      33.7
      Seconds
  • Question 42 - Concerning the pathway of endothelial nitric oxide (eNO), one of the following best...

    Incorrect

    • Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.

      Your Answer: Stimulation of guanylyl cyclase, decreases cGMP concentration leading to vasodilation

      Correct Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation

      Explanation:

      Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).

      Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.

      Smooth muscle vasodilatation results from:

      1. Light chain phosphatase activation.
      2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
      3. Hyperpolarisation of cells by activation of H+ channels.

    • This question is part of the following fields:

      • Pathophysiology
      13.3
      Seconds
  • Question 43 - A 50-year-old woman's blood pressure readings in the clinic are 170/109 mmHg, 162/100...

    Incorrect

    • A 50-year-old woman's blood pressure readings in the clinic are 170/109 mmHg, 162/100 mmHg and 175/107 mmHg and her routine haematology, biochemistry, and 12-lead ECG are normal. She is assessed on the day of surgery prior to laparoscopic inguinal hernia repair and is found to be normally fit and well. Documentation of previous blood pressure measurements from her general practitioner in the primary healthcare setting are not available. What is your next course of action?

      Your Answer: Refer to the general practitioner for review and treatment

      Correct Answer: Proceed with scheduled surgery without treatment

      Explanation:

      The AAGBI and the British Hypertension Society has published guidelines for the measurement of adult blood pressure and management of hypertension before elective surgery.

      The objective is to ensure that patients admitted for elective surgery have a known systolic blood pressure below 160 mmHg and diastolic blood pressures below 100 mmHg. The primary health care teams, if possible, should ensure that this is the case and provide evidence to the pre-assessment clinic staff or on admission.

      Avoiding cancellation on the day of surgery because of white coat hypertension is a secondary objective.

      Patients with blood pressures below 180 mmHg systolic and 110 mmHg diastolic (measured in the preop assessment clinic), who present to pre-operative assessment clinics without documented evidence of primary care blood pressures should proceed to elective surgery.

      In this question, the history/assessment does not appear to point to obvious end-organ damage so there is no indication for further investigation for secondary causes of hypertension or an echocardiogram at this point. Further review and treatment at this point is not required.

      However, you should write to the patient’s GP and encourage serial blood pressure measurements in the primary health care setting.

    • This question is part of the following fields:

      • Pathophysiology
      34.5
      Seconds
  • Question 44 - A 43-year-old patient was brought to the emergency department with a traumatic amputation...

    Correct

    • A 43-year-old patient was brought to the emergency department with a traumatic amputation of his leg at mid-thigh level. Resuscitation with 1 L gelofusine was done and four units of packed red blood cells were given before theatre. Thirty minutes following blood transfusion, the patient became flushed, breathless, hypotensive, develops haemoglobinuria, and had a fever of 38oC. Which one of the following correctly explains the patient signs and symptoms?

      Your Answer: Activation of classic complement pathway

      Explanation:

      This may be the classical case of blood transfusion reaction due to ABO incompatibility.

      Here red cells are destroyed in the bloodstream with the release of haemoglobin in circulation (causing haemoglobinuria). Here, IgM or IgG anti-A or anti-B antibody can cause rapid activation of complement cascade usually the classical pathway. This is called intravascular haemolysis.

      There may be extravascular haemolysis by cells of the mononuclear phagocyte system situated in the liver and spleen. Extravascular red cell destruction can increase breakdown products of haemoglobin, such as bilirubin and urobilinogen.

    • This question is part of the following fields:

      • Pathophysiology
      15.3
      Seconds
  • Question 45 - When there is a relation between two variables due to the existence of...

    Correct

    • When there is a relation between two variables due to the existence of a confounding factor, this association is termed as:

      Your Answer: Indirect

      Explanation:

      When the association among any two classes of object is defined by the presence of a third entity it is termed as indirect association. For an instance, the age of the employee may affect the rate of pay, which would have implications on job satisfaction. So, in this example, an indirect relationship between age and job satisfaction exists due to a third party i.e. rate of pay.

    • This question is part of the following fields:

      • Statistical Methods
      7.2
      Seconds
  • Question 46 - A 75-year-old man, visits his general practitioner. He complains of changes to his...

    Incorrect

    • A 75-year-old man, visits his general practitioner. He complains of changes to his bowel habit and unexpected weight loss in the last 6 months. He is scheduled for a colonoscopy and biopsy where he is diagnosed with a transverse colon malignancy. The transverse colon is one of many organs tethered to the posterior wall of the abdominal cavity by a double fold of the peritoneum. Which of the listed organs is also tethered to the peritoneum in a similar way?

      Your Answer: The tail of the pancreas

      Correct Answer: The stomach

      Explanation:

      The peritoneal cavity is made up of the omentum, the ligaments and the mesentery.

      The section of the peritoneum responsible for tethering organs to the posterior abdominal wall is the mesentery.

      These tethered organs are classified as intraperitoneal, and these include the stomach, spleen, liver, first and fourth parts of the duodenum, jejunum, ileum, transverse, and sigmoid colon.

      Retroperitoneal organs are located posterior to the peritoneum and include: the rest of the duodenum, the ascending colon, the descending colon, the middle third of the rectum, and the remainder of the pancreas.

    • This question is part of the following fields:

      • Anatomy
      89.4
      Seconds
  • Question 47 - A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise....

    Incorrect

    • A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin. What is the mechanism of resistance to ampicillin?

      Your Answer: Carbapenemase production

      Correct Answer: Beta-lactamase production

      Explanation:

      Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to β-lactamase production which opens the β-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      Resistance to cephalosporins is due to changes in penicillin-binding proteins.

      Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA

      Resistance to fluoroquinolones is due to mutations in DNA gyrase.

    • This question is part of the following fields:

      • Pharmacology
      12.2
      Seconds
  • Question 48 - From the following statements, which is true of humidification? ...

    Correct

    • From the following statements, which is true of humidification?

      Your Answer: Ultrasonic humidifier can achieve greater than 100% relative humidity

      Explanation:

      Increasing temperature increases the amount of water vapour contained in air; for example, at 20°C, air contains about 17 g/m3, and at 37°C, air contains about 44 g/m3. The wet and dry bulb hygrometer, like the hair hygrometer, measures relative humidity.

      Under normal operating conditions, Heat and moisture exchangers (HMEs) allows relative humidity of up to 70% to be achieved. Mucus can impair their performance, and they should not be used for longer than 24 hours.

      Hot water bath humidifiers might cause scalding, condensed water in the tubing can interfere with gas flow, and there is a danger of infection.

      The ultrasonic humidifier operates at roughly 2 MHz and may attain relative humidity levels much above 100%.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      15.1
      Seconds
  • Question 49 - A morbidly obese (BMI=48) patient has the following co-morbidities: type II diabetes mellitus...

    Correct

    • A morbidly obese (BMI=48) patient has the following co-morbidities: type II diabetes mellitus and hypertension. It is recommended for the patient to undergo bariatric surgery. If the patient is laid flat for induction of anaesthesia, what physiologic changes of the respiratory system is the most important to consider?

      Your Answer: Functional residual capacity will decrease

      Explanation:

      A decrease in the functional residual capacity (FRC) is the most important physiologic change to consider for such patients.

      FRC is the sum of the expiratory reserve volume and the residual volume. It is the resting volume of the lung, and is an important marker for lung function. During this time, the alveolar pressure is equal to the atmospheric pressure. When morbidly obese individuals lie supine, the FRC decreases by as much as 40% because the abdominal contents push the diaphragm into the thoracic cavity.

      Chest wall compliance is expected to reduce because of fat deposition surrounding adjacent structures.

      Inspiratory reserve volume (IRV) is expected to increase, and peak expiratory flow is expected to decrease, however the decrease in FRC is more important to consider because of the risk of hypoxia secondary to premature airway closure and ventilation-perfusion mismatch.

    • This question is part of the following fields:

      • Physiology
      13.8
      Seconds
  • Question 50 - During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding....

    Incorrect

    • During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding. The 'Pringle manoeuvre is performed to stop the bleeding where the hepatic artery, portal vein, and common bile duct are clamped. These structures form the anterior boundary of the epiploic foramen. Which of the following vessels also contributes to the boundary of this region?

      Your Answer: Common hepatic artery

      Correct Answer: Inferior vena cava

      Explanation:

      The epiploic foramen (foramen of Winslow or aditus to the lesser sac) is found behind the free right border of the lesser omentum. A short, 3 cm slit serves as the entrance to the lesser sac from the greater sac.

      The epiploic foramen has the following boundaries:
      Anteriorly: hepatoduodenal ligament, the bile duct (anteriorly on the right), the hepatic artery (anteriorly on the left), and the portal vein (posteriorly) together with nerves and lymphatics
      Superiorly: the peritoneum of the posterior layer of the hepatoduodenal ligament runs over the caudate process of the liver
      Posteriorly: inferior vena cava
      Floor: upper border of the first part of the duodenum
      The anterior and posterior walls of the foramen are normally
      apposed, which partly explains why patients can develop large fluid
      collections isolated to the greater or lesser sac

      Rapid control of the hepatic artery and portal vein can be obtained by compression of the free edge of the lesser omentum (a €˜Pringle’ manoeuvre), which is a potentially useful technique in liver trauma and surgery.

    • This question is part of the following fields:

      • Anatomy
      21.9
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Pathophysiology (7/10) 70%
Statistical Methods (4/8) 50%
Physiology And Biochemistry (2/3) 67%
Clinical Measurement (1/2) 50%
Anatomy (4/8) 50%
Pharmacology (5/9) 56%
Physiology (3/6) 50%
Basic Physics (0/2) 0%
Anaesthesia Related Apparatus (2/2) 100%
Passmed