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  • Question 1 - A 39-year-old woman, is scheduled for a thyroidectomy for her previously diagnosed Grave's...

    Incorrect

    • A 39-year-old woman, is scheduled for a thyroidectomy for her previously diagnosed Grave's disease. She is eligible for surgery as medical treatment options have failed to control her symptoms and she is the sole guardian for her young children, so radioiodine treatment is unsuitable. While gaining her consent for the surgery, she is told of possible complications of thyroidectomy, which include damage to the sensory branch of the superior laryngeal nerve. What is the name of the sensory nerve that arises from the superior laryngeal nerve?

      Your Answer: Left recurrent laryngeal nerve

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The superior laryngeal nerve gives off two branches: the sensory branch which is the internal laryngeal nerve, and the motor branch which is the external laryngeal nerve.

      The recurrent laryngeal nerve (RLN) rises from the vagus nerve which supplies the intrinsic muscles of the larynx, except the cricothyroid muscles.

    • This question is part of the following fields:

      • Anatomy
      16.7
      Seconds
  • Question 2 - Which of the following statements is true regarding drug dose and response? ...

    Correct

    • Which of the following statements is true regarding drug dose and response?

      Your Answer: Intrinsic activity determines maximal response

      Explanation:

      There are two types of drug dose-response relationships, namely, the graded dose-response and the quantal dose-response relationships.

      Drug response curves are plotted as percentage response again LOG drug concentration. This graph is sigmoid in shape.

      Agonists are drugs with high affinity and high intrinsic activity. Meanwhile, the antagonist is a drug with high affinity but no intrinsic activity. Intrinsic activity determines the maximal response. The maximal response can be achieved even by activation of a small proportion of receptor sites.

    • This question is part of the following fields:

      • Pharmacology
      4.6
      Seconds
  • Question 3 - A 52-year old man was placed under general anaesthesia for an emergent open...

    Correct

    • A 52-year old man was placed under general anaesthesia for an emergent open cholecystectomy. As part of the induction, suxamethonium was administered at 1.5mg/kg. Post-operatively, there was failure to restore muscle twitch responses over a course of five hours. Clinical chemistry studies were obtained and showed the following results: Butrylcholinesterase (BChE) activity: 49 U/L (Reference range: 3300-10,300 U/L), Dibucaine number: <4% (Reference range: 83-88%). The attending physician gave an initial diagnosis of Suxamethonium Apnoea. What is the most probable phenotype of BChE of the patient?

      Your Answer: S (silent)

      Explanation:

      Silent (S) is the most probable phenotype of the patient. In S phenotype, patients have significantly reduced levels of BChE, the lowest among the four phenotypes. Because of this, individuals with S phenotype are subjected to long periods of apnoea. In addition, their dibucaine number is very low.

      Other BChE phenotypes are the following:

      Usual (U)
      Atypical (A)
      Fluoride-resistant (F).

    • This question is part of the following fields:

      • Pathophysiology
      60.8
      Seconds
  • Question 4 - The following are results of some pulmonary function tests: (Measurement - Predicted result...

    Incorrect

    • The following are results of some pulmonary function tests: (Measurement - Predicted result - Test result). Forced vital capacity (FVC) (btps): 3.21, - 1.94. Forced expiratory volume in 1 second (FEV1) (btps): 2.77, 1.82. FEV1/FVC ratio % (btps): 81.9, 93.5. Peak expiratory flow (PEF) (L/second): 6.55, 3.62. Maximum voluntary ventilation (MVV) (L/minute): 103, 87.1 Which statement applies to the results?

      Your Answer: The patient has a moderate obstructive pulmonary defect

      Correct Answer: The patient has a moderate restrictive pulmonary defect

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (V1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35%

      This patient has a %FVC predicted of 60.4% and this corresponds to a moderate restrictive deficit. V1/FVC ratio is 93.5%.

      FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture.

      FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.

      The integrity of the alveolar-capillary barrier is measured by carbon monoxide transfer factor (TLCO) and carbon monoxide transfer coefficient (KCO). These values are seen to be reduced in emphysema, interstitial lung diseases and in pulmonary vascular pathology. However, the KCO (as % predicted) is high in extrapulmonary restriction (pleural, chest wall and respiratory neuromuscular disease), and in loss of lung units provided the structure of the lung remaining is normal. The KCO distinguishes extrapulmonary (high KCO) causes of 'restriction' from intrapulmonary causes (low KCO).

    • This question is part of the following fields:

      • Clinical Measurement
      81.5
      Seconds
  • Question 5 - Which of the following statements is NOT true regarding the internal jugular vein?...

    Incorrect

    • Which of the following statements is NOT true regarding the internal jugular vein?

      Your Answer: It is the continuation of the sigmoid sinus

      Correct Answer: The terminal part of the thoracic duct crosses anterior to it to insert into the right subclavian vein

      Explanation:

      The internal jugular vein is found on both sides of the neck and collects blood from the brain, superficial regions of the face, and neck. It drains into the right atrium.

      It is a continuation of the sigmoid sinus and begins in the posterior cranial fossa and exits the skull via the jugular foramen.
      It runs within the carotid sheath as it descends in the neck and is accompanied by the vagus nerve posteriorly and the common carotid anteromedially.

      The hypoglossal nerve emerges from the hypoglossal canal medial to the internal carotid artery and the internal jugular vein and ninth, tenth, and eleventh cranial nerves.

      The internal jugular vein crosses anterior to the thoracic duct on the left side.

    • This question is part of the following fields:

      • Anatomy
      13.6
      Seconds
  • Question 6 - A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse...

    Correct

    • A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse on lying flat. The doctor suspects gastroesophageal reflux due to a hiatus hernia. Lifestyle modifications to lose weight and antacids are prescribed to her. At which level of the diaphragm will you find an opening for this problem?

      Your Answer: T10

      Explanation:

      Hiatus is an opening in the diaphragm. A hiatal hernia is a protrusion of the upper part of the stomach through an opening in the diaphragm, the oesophageal hiatus, into the thorax. The oesophageal hiatus occurs at the level of T10 in the right crus of the diaphragm.

      Other important openings in the diaphragm:
      T8: vena cava, terminal branches of the right phrenic nerve
      T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
      T12: descending aorta, thoracic duct, azygous and hemi-azygous vein

      An opening in the diaphragm is called a hiatus. The oesophageal hiatus is at vertebral level T10. A hiatus hernia is where the stomach bulges through the oesophageal hiatus hence the name – hiatus hernia.

    • This question is part of the following fields:

      • Anatomy
      23.4
      Seconds
  • Question 7 - Over the course of 10 minutes, one litre of 0.9% normal saline is...

    Correct

    • Over the course of 10 minutes, one litre of 0.9% normal saline is intravenously infused into a normally fit and well 58-year-old male. A catheter is used to measure urine output before and after the infusion. The patient is 70 kg in weight. The following data on urine output is obtained: 50ml/hour Before the infusion, 200 ml/hour 1 hour following infusion, 90 ml/hour 2 hours after the infusion, 60 ml/hr 3 hours after the infusion. Which of the following physiological responses is most likely to account for the sudden increase in urine output after a fluid bolus?

      Your Answer: Increased glomerular filtration rate

      Explanation:

      The following are some basic assumptions:

      Extracellular fluid (ECF) makes up one-third of total body water (TBW), while intracellular fluid makes up the other two-thirds (ICF).
      One-quarter of ECF is plasma, and three-quarters is interstitial fluid (ISF).
      The volume receptors have a 7-10% blood volume change threshold. The osmoreceptors are sensitive to changes in osmolality of 1-2 percent.
      Prior to the transfusion, the plasma osmolality is normal (between 287 and 290 mOsm/kg).
      [Na+] in 0.9 percent N. saline is 154 mmol/L, which is similar to that of extracellular fluid. When given intravenously, this limits its distribution within the extracellular space, resulting in a plasma compartment:ISF volume ratio of 1:3.
      In this time frame, one litre of 0.9 percent N. saline will increase plasma volume by about 250 mL, which could be the threshold for activation of the volume receptors in the atria, resulting in the release of atrial natriuretic peptide (ANP).

      Because 0.9 percent N. saline is isosmotic, after a 1 L infusion, plasma osmolality will not change. No changes in antidiuretic hormone secretion will be detected by the hypothalamic osmoreceptors.

      Because normal saline is protein-free, the oncotic pressure in the blood is slightly reduced after the saline infusion. As a result, fluid movement into the ISF is favoured (Starling’s hypothesis), and the lower oncotic pressure causes an immediate increase in the glomerular filtration rate (GFR) and a reduction in water reabsorption in the proximal tubule.

      The flow of urine increases. There is no hormonal intermediary in this effect, so it is strictly local. Urine flow immediately increases. The fluid returns to the intravascular compartment, and urine flow continues until all of the transfused fluid has been excreted.

      Blood pressure changes associated with a 1 L fluid infusion are unlikely to affect high-pressure baroreceptors in the carotid sinus.

      The juxta-glomerular cells of the afferent arteriole are adjacent to the specialised cells (macula densa) of distal tubules. The sodium and chloride ions in the tubular fluid are detected by the macula densa. Renin release is inhibited when the tubular fluid contains too much sodium chloride. Hormonal changes take longer to manifest than physical changes that control glomerulotubular balance.
      Hypertonic saline, not 0.9 percent N saline, is an osmotic diuretic.

    • This question is part of the following fields:

      • Pathophysiology
      14.1
      Seconds
  • Question 8 - Regarding a drug whose elimination exhibits first-order kinetics, which of the following statements...

    Correct

    • Regarding a drug whose elimination exhibits first-order kinetics, which of the following statements is correct?

      Your Answer: The rate of elimination is proportional to plasma concentration

      Explanation:

      The elimination of phenytoin follows first order kinetics. Plasma concentrations determine the rate of elimination. The relationship between drug X plasma concentration and time is described by an exponential process in the following equation used to describe the rate of elimination:

      C = C0. e-kt

      C=drug concentration, C0= drug concentration at time zero (extrapolated), k = rate constant and t=time

      As enzyme systems become saturated when phenytoin concentrations are above the usual range, clearance of the medication becomes zero-order. The medication is metabolised at a constant pace, regardless of its plasma levels. Aspirin and ethyl alcohol are two more significant examples of medications that operate in this way.

      A plot of drug concentration with time is a washout exponential curve.

      A graph of concentration with time is a straight line i.e. Zero-order kinetics

      The amount eliminated per unit time is constant defines the point at which zero order kinetics commences.

      Elimination involves a rate-limiting reaction operating at its maximal velocity is incorrect.

      The half life of the drug is proportional to the drug concentration in the plasma corresponds to a definition of first-order kinetics.

    • This question is part of the following fields:

      • Pharmacology
      10.1
      Seconds
  • Question 9 - Given the following values: Expired tidal volume = 800 ml, Plateau pressure =...

    Incorrect

    • Given the following values: Expired tidal volume = 800 ml, Plateau pressure = 50 cmH2O, PEEP = 10 cmH2O. Compute for the static pulmonary compliance.

      Your Answer: 200 ml/cmH2O

      Correct Answer: 20 ml/cmH2O

      Explanation:

      Compliance of the respiratory system describes the expandability of the lungs and chest wall. There are two types of compliance: dynamic and static.

      Dynamic compliance describes the compliance measured during breathing, which involves a combination of lung compliance and airway resistance. Defined as the change in lung volume per unit change in pressure in the presence of flow.

      Static compliance describes pulmonary compliance when there is no airflow, like an inspiratory pause. Defined as the change in lung volume per unit change in pressure in the absence of flow.

      For example, if a person was to fill the lung with pressure and then not move it, the pressure would eventually decrease; this is the static compliance measurement. Dynamic compliance is measured by dividing the tidal volume, the average volume of air in one breath cycle, by the difference between the pressure of the lungs at full inspiration and full expiration. Static compliance is always a higher value than dynamic

      Static compliance can be computed using the formula:

      Cstat = Tidal volume/Plateau pressure – PEEP

      Substituting the values given,

      Cstat = 800/50-10
      Cstat = 20 ml/cmH2O

    • This question is part of the following fields:

      • Physiology
      17.4
      Seconds
  • Question 10 - Which of the following is true regarding a laryngoscope? ...

    Incorrect

    • Which of the following is true regarding a laryngoscope?

      Your Answer: The tip of a Miller blade is designed to be placed into the vallecula

      Correct Answer: The Wisconsin and Seward are examples of straight blade laryngoscopes

      Explanation:

      Direct laryngoscopy are performed using laryngoscopes and they can be classed according to the shape of the blade as curved or straight.

      Miller, Soper, Wisconsin and Seward are examples of straight blade laryngoscopes. Straight blades are commonly used for intubating neonates and infants but can be used in adults too.

      The tip of the miller blade is advanced over the epiglottis to the tracheal entrance then lifted in order to view the vocal cords.

      The RIGHT-SIDED Macintosh blade is used in adults while the left-sided blade may be used in conditions that make intubation with standard blade difficult e.g. facial deformities.

      The McCoy laryngoscope is based on the STANDARD MACINTOSH blade not Robertshaw’s. It has a lever operated hinged tip, which improves the view during laryngoscopy.

      Polio blade is mounted at an angle of 120-135 degrees to the handle. Originally designed for use during the polio epidemic €‹in intubation patients within iron lung ventilators, it is now useful in patients with conditions like breast hypertrophy, barrel chest, and restricted neck mobility.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      9.6
      Seconds
  • Question 11 - What statement about endotoxins is true? ...

    Correct

    • What statement about endotoxins is true?

      Your Answer: Can often survive autoclaving

      Explanation:

      Endotoxins are the lipopolysaccharides found in the outer cell wall of Gram-negative bacteria. They are responsible for providing the structure and stability of the cell wall.

      They cannot be destroyed by normal sterilisation as they are heat stable molecules. They require the use of certain sterilant such as superoxide, peroxide and hypochlorite to be neutralised.

      They stimulate strong immune responses, but can only be destroyed partially by specific antibodies. Repeat infections occur as memory T cells cannot be formed.

      It can cause septicaemia and associated symptoms such as fever, shock, hypotension and nausea.

      It activates the alternative complement pathway and the coagulation pathway using secreted cytokines.

      It is not involved in botulism as clostridium botulinum, the responsible organism, secretes a neurotoxic exotoxin.

    • This question is part of the following fields:

      • Pathophysiology
      11.5
      Seconds
  • Question 12 - A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet....

    Correct

    • A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet. On examination, he was found to be hypertensive. Which of the following correctly explains the cause of his visual field defect?

      Your Answer: Pituitary macroadenoma secreting growth hormone (GH)

      Explanation:

      Pituitary macroadenoma is a benign tumour with growth larger than 10mm (those under 10mm are called microadenoma)

      Compression of optic chiasm by pituitary adenoma is responsible for causing visual field defects like bitemporal hemianopia, optic neuropathy.

    • This question is part of the following fields:

      • Pathophysiology
      8.1
      Seconds
  • Question 13 - Which of the following statements regarding anticholinergic drugs (hyoscine hydrobromide, atropine and glycopyrrolate)...

    Incorrect

    • Which of the following statements regarding anticholinergic drugs (hyoscine hydrobromide, atropine and glycopyrrolate) is true?

      Your Answer: Glycopyrrolate is a naturally occurring ester

      Correct Answer: Hyoscine hydrobromide use may precipitate excitement and ataxia

      Explanation:

      Anticholinergic agents are a group of drugs that blocks the action of the neurotransmitter called acetylcholine at synapses in the central and peripheral nervous system.

      Hyoscine, atropine, and glycopyrrolate are anticholinergic which acts at muscarinic receptors with little activity at the nicotinic receptors.

      Hyoscine and atropine are naturally occurring esters. Since Glycopyrrolate is a synthetic quaternary amine, it does not cross the blood brain barrier. Noteworthy, hyoscine, butylbromide also does not cross the blood brain barrier significantly.

    • This question is part of the following fields:

      • Pharmacology
      11.6
      Seconds
  • Question 14 - The population incidence of a disease is best described by? ...

    Incorrect

    • The population incidence of a disease is best described by?

      Your Answer: The number of cases of a disease in a population over a defined time period

      Correct Answer: The number of new cases of a disease per population in a defined period

      Explanation:

      The incidence of a disease is the number of new cases of the disease in a population over a defined time period.

      The prevalence of a disease is the number of cases of the disease in a population over a defined time period describes. It is NOT the number of new cases.

      The number of new cases of a disease only, has no denominator (time period or population) from which to derive an incidence.

      The number of new cases of a disease seeking medical treatment is the incidence of patients seeking medical treatment NOT the incidence of the disease in a population.

      The death rate from a disease is the number of patients dying from the disease in a population.

    • This question is part of the following fields:

      • Statistical Methods
      7
      Seconds
  • Question 15 - A 60-year-old man, with a history of excessive alcohol intake, presents for the...

    Incorrect

    • A 60-year-old man, with a history of excessive alcohol intake, presents for the first time in the emergency department with acute abdominal pain in the epigastric region. On examination, the man is sweating and has a high-grade fever. His heart rate is 140/min and a BP of 92/59 mmHg. The patient is diagnosed with acute pancreatitis. Which of the following is a complication you are most likely to see in this patient?

      Your Answer: Abdominal distention with shifting dullness

      Correct Answer: Blue discolouration of the flank regions

      Explanation:

      Bulky, greasy stools are associated with improper digestion that can be expected if the pancreas loses its exocrine function. This is common in long-term chronic pancreatitis but since this is the patient’s first presentation with such symptoms, this complication is unlikely.

      Peripheral neuropathy is a common complication of chronic diabetes but has been reported with cases of chronic pancreatitis too.

      Abdominal distention with shifting dullness is a classic symptom of underlying ascites. Ascites is a complication of many diseases but it is not common with the acute first-time presentation of pancreatitis.

      Option E: This points towards abdominal obstruction but in the absence of the more common symptoms, nausea and bilious vomiting, this is unlikely.

      Option A: Grey Turner’s sign is the pooling of blood in the retroperitoneal space between the last rib and the top of the hip. The pancreas is a retroperitoneal organ and inflammation of the pancreas can cause retroperitoneal haemorrhage. The sign takes 24-48 hours to develop and can predict a severe attack of acute pancreatitis. The patient has presented with acute pancreatitis due to his history of high alcohol intake, and acute on chronic is unlikely as this is his first presentation. He also has low blood pressure and an increased heart rate, which suggest blood loss with acute pancreatitis.

    • This question is part of the following fields:

      • Anatomy
      13.5
      Seconds
  • Question 16 - Which of the following can be measured directly using spirometry? ...

    Incorrect

    • Which of the following can be measured directly using spirometry?

      Your Answer: Residual volume

      Correct Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
      7.5
      Seconds
  • Question 17 - An individual who recently moved his residence from the plains to the mountains...

    Correct

    • An individual who recently moved his residence from the plains to the mountains will experience immediately which physiologic response to high altitude and hypoxia?

      Your Answer: Increased cardiac output

      Explanation:

      A person remaining at high altitudes for days, weeks, or years becomes more and more acclimatized to the low PO2, so it causes fewer deleterious effects on the body.

      After acclimatization, it becomes possible for the person to work harder without hypoxic effects or to ascend to still higher altitudes. The principal means by which acclimatization comes about are (1) a great increase in pulmonary ventilation, (2) increased numbers of red blood cells, (3) diffusing capacity of the lungs, (4) increased vascularity of the peripheral tissues, and (5) increased ability of the tissue cells to use oxygen despite low PO2.

      The cardiac output often increases as much as 30% immediately after a person ascends to high altitude but then decreases back toward normal over a period of weeks as the blood haematocrit increases, so the amount of oxygen transported to the peripheral body tissues remains about normal.

    • This question is part of the following fields:

      • Pathophysiology
      9
      Seconds
  • Question 18 - A 30-year-old man has been stabbed in an area of the groin that...

    Correct

    • A 30-year-old man has been stabbed in an area of the groin that contains the femoral triangle. He will undergo explorative surgery. Which of the following makes the lateral wall of the femoral triangle?

      Your Answer: Sartorius

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve.

    • This question is part of the following fields:

      • Anatomy
      6.6
      Seconds
  • Question 19 - Following are some examples of induction agents. Which one has the longest elimination...

    Correct

    • Following are some examples of induction agents. Which one has the longest elimination half-life?

      Your Answer: Thiopental

      Explanation:

      Thiopental has the longest elimination half-life of 6-15 hours.

      Elimination half-life of other drugs are given as:
      – Propofol: 5-12 h
      – Methohexitone: 3-5 h
      – Ketamine: 2 h
      – Etomidate: 1-4 h

    • This question is part of the following fields:

      • Pharmacology
      4.6
      Seconds
  • Question 20 - Which oral hypoglycaemic agent has no effect on insulin sensitivity or secretion? ...

    Correct

    • Which oral hypoglycaemic agent has no effect on insulin sensitivity or secretion?

      Your Answer: Alpha glucosidase inhibitors

      Explanation:

      Because alpha glucosidase inhibitors slow starch digestion in the small intestine, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity.

      Biguanides decrease hepatic glucose output while increasing glucose uptake in peripheral cells.

      The meglitinides are secretagogues that act on a different site of the KATP receptors.

      Insulin secretion is stimulated by sulphonylureas, which stimulate insulin secretion from pancreatic beta cells. The KATP channels are inhibited by these substances.

      Insulin-sensitive genes are influenced by thiazolidinediones, which increase the production of mRNAs for insulin-dependent enzymes. As a result, the cells make better use of glucose.

    • This question is part of the following fields:

      • Pharmacology
      10.5
      Seconds
  • Question 21 - In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five...

    Incorrect

    • In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks. Which of the following indicates the most important reason for using epinephrine?

      Your Answer: Positive inotrope effect

      Correct Answer: Preferential distribution of blood to the coronary and cerebral circulation

      Explanation:

      Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (α1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a β1 and β2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
      – Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
      – Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal.

    • This question is part of the following fields:

      • Pathophysiology
      14.7
      Seconds
  • Question 22 - A 24-year-old female, presents to the emergency department via ambulance. She has just...

    Incorrect

    • A 24-year-old female, presents to the emergency department via ambulance. She has just been involved in a car accident. She is examined and undergoes various diagnostic investigations. Her X-ray report states that a fracture was noted on the surgical neck of her humerus. What structure is most likely to the damaged as a result of a surgical neck fracture of the humerus?

      Your Answer: Axillary artery

      Correct Answer: Axillary nerve

      Explanation:

      Fractures to the surgical neck of the humerus are common place as it is the weakest point of the proximal humerus bone.

      The structures most likely to be damaged are the axillary nerve and the posterior circumflex humeral artery as they surround the surgical neck.

      The radial nerve runs along the radial groove, so injury to it would likely occur with a mid-shaft fracture of the humerus.

      The brachial artery is most likely to be injured as a result of a supracondylar fracture of the humerus which increases the risk of volkmaan’s ischemic contractures.

      Injury to the musculocutaneous nerve is least likely to happen and it very uncommon.

    • This question is part of the following fields:

      • Anatomy
      8.9
      Seconds
  • Question 23 - In the adrenal gland: ...

    Incorrect

    • In the adrenal gland:

      Your Answer: There is a portal system between cortex and medulla

      Correct Answer: Catecholamine release is mediated by cholinergic nicotinic transmission

      Explanation:

      The adrenal (suprarenal) gland is composed of two main parts: the adrenal cortex, which is the largest and outer part of the gland, and the adrenal medulla. The adrenal cortex consists of three zones: 1. Zona glomerulosa (outermost layer) is responsible for the production of mineralocorticoids, mainly aldosterone, which regulates blood pressure and electrolyte balance. 2. Zona fasciculata (middle layer) is responsible for the production of glucocorticoids, predominantly cortisol, which increases blood sugar levels via gluconeogenesis, suppresses the immune system, and aids in metabolism. It also produces 11-deoxycorticosterone and corticosterone in addition to cortisol. 3. Zona reticularis (innermost layer) is responsible for the production of gonadocorticoids, mainly dehydroepiandrosterone (DHEA), which serves as the starting material for many other important hormones produced by the adrenal gland, such as oestrogen, progesterone, testosterone, and cortisol. It is also responsible for administering these hormones to the reproductive regions of the body.

      The adrenal medulla majorly secretes epinephrine (adrenaline), and norepinephrine in small quantity. Both hormones have similar functions and initiate the flight or fight response.

      Catecholamine is mediated by cholinergic nicotinic transmission through changes in sympathetic nervous system (T5 – T11), being increased during stress and hypoglycaemia.

      Blood supply to the adrenal gland is by these three arteries: superior suprarenal arteries, middle suprarenal artery and inferior suprarenal artery. Venous drainage is via the suprarenal vein to the left renal vein or directly to the inferior vena cava on the right side. There is no portal (venous) system between cortex and medulla.

    • This question is part of the following fields:

      • Anatomy
      11.8
      Seconds
  • Question 24 - In an experimental study, a healthy subject was given one litre of 5%...

    Incorrect

    • In an experimental study, a healthy subject was given one litre of 5% dextrose within a 15-minute period. Which of the following mechanisms is expected to affect the urine output?

      Your Answer: Inhibition of renin secretion

      Correct Answer: Inhibition of arginine vasopressin (AVP) secretion

      Explanation:

      Changes in the osmolality of body fluids (changes as minor as 1% are sufficient) play the most important role in regulating AVP secretion. The receptors that monitor changes in osmolality of body fluids (termed osmoreceptors) are distinct from the cells that synthesize and secrete AVP, and are located in the organum vasculosum of the lamina terminalis (OVLT) of the hypothalamus. The osmoreceptors sense changes in body osmolality by either shrinking or swelling. When the effective osmolality of the plasma increases, the osmoreceptors send signals to the AVP synthesizing/secreting cells located in the supraoptic and paraventricular nuclei of the hypothalamus, and AVP synthesis and secretion are stimulated. Conversely, when the effective osmolality of the plasma is reduced, secretion is inhibited. Because AVP is rapidly degraded in the plasma, circulating levels can be reduced to zero within minutes after secretion is inhibited.

      In this scenario, the osmolality of the plasma will decrease to an estimate of 2.5%, hence inhibition of AVP.

      Stimulation of atrial stretch receptors is incorrect because the increase in plasma volume is still below the threshold for its activation.

      Osmotic diuresis is incorrect because 5% dextrose is isotonic, hence osmotic diuresis is not probable.

      Renin is inhibited when an excess of NaCl in the tubular fluid is sensed by the macula densa.

    • This question is part of the following fields:

      • Physiology
      12.3
      Seconds
  • Question 25 - Noradrenaline is used as an infusion to increase blood pressure in a 43-year-old...

    Incorrect

    • Noradrenaline is used as an infusion to increase blood pressure in a 43-year-old woman with pneumonia admitted to ICU. Which of the following statements is true regarding Noradrenaline?

      Your Answer: Sympathomimetic effects mainly through α2 but also involves β receptors

      Correct Answer: Has a short half life about 2 minutes

      Explanation:

      Noradrenaline has a short half-life of about 2 minutes. It is rapidly cleared from plasma by a combination of cellular reuptake and metabolism.

      It acts as sympathomimetics by acting on α1 receptors and also on β receptors.

      It decreases renal and hepatic blood flow.

      Norepinephrine is metabolized by the enzymes monoamine oxidase and catechol-O-methyltransferase to 3-methoxy-4-hydroxymandelic acid and 3-methoxy-4-hydroxyphenylglycol (MHPG).

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

    • This question is part of the following fields:

      • Pharmacology
      5.4
      Seconds
  • Question 26 - Which of the following statements is true regarding alfentanil? ...

    Correct

    • Which of the following statements is true regarding alfentanil?

      Your Answer: Is less lipid soluble than fentanyl

      Explanation:

      Alfentanil is less lipid-soluble than fentanyl and thus is less permeable to the membrane making it less potent.

      Alfentanil is a phenylpiperidine opioid analgesic with rapid onset and shorter duration of action.

      Alfentanil has less volume of distribution due to its high plasma protein binding (92%)

      It can cause respiratory depression and can cause sedation

    • This question is part of the following fields:

      • Pharmacology
      43.9
      Seconds
  • Question 27 - Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit....

    Incorrect

    • Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit. Your consultant has requested that you prescribe maintenance fluids for the next 12 hours. The child is 21 kg in weight. What is the most suitable fluid volume to be prescribed?

      Your Answer: 252 ml

      Correct Answer: 732 ml

      Explanation:

      After a paediatric case, you’ll frequently have to calculate and prescribe maintenance fluids. The ‘4-2-1 rule’ should be used as a guideline:

      1st 10 kg – 4 ml/kg/hr
      2nd 10 kg – 2 ml/kg/hr
      Subsequent kg – 1 ml/kg/hr

      Hence

      1st 10 kg = 4 × 10 = 40 ml
      2nd 10 kg = 2 × 10 = 20 ml
      Subsequent kg = 1 × 1 = 1 ml
      Total = 61 ml/hr

      61 × 12 = 732 ml over 12 hrs.

    • This question is part of the following fields:

      • Physiology
      37.9
      Seconds
  • Question 28 - A 45-year-old woman gives a two-week history of fatigue, muscle cramps, and paraesthesia...

    Incorrect

    • A 45-year-old woman gives a two-week history of fatigue, muscle cramps, and paraesthesia of her fingers and toes. She has low serum calcium and low serum parathyroid hormone levels on investigations. She appears slightly confused, likely due to hypocalcaemia, and cannot give a full account of her past medical history, but can recall that she recently was admitted to the hospital. What is the most likely cause of her hypoparathyroidism?

      Your Answer: Hypocalcaemia

      Correct Answer: Thyroidectomy

      Explanation:

      The most common cause of hypoparathyroidism is injury or removing the parathyroid glands. They can be injured accidentally during surgery to remove the thyroid as they are located posterior to the thyroid gland.

      A result of both low parathyroid hormone and low calcium is likely to mean that the parathyroid glands are not responding to hypocalcaemia. The hypocalcaemia can cause confusion, and the stay in the hospital is likely to refer to her surgery.

      While a parathyroid adenoma is fairly common and can cause hypoparathyroidism, it much more likely causes hyperparathyroidism.

      Chronic kidney disease is likely to cause hypocalcaemia, which would increase parathyroid hormone production in an attempt to increase calcium levels, causing hyperparathyroidism. Vitamin D is activated by the kidneys and then binds to calcium to be absorbed in the terminal ileum so that a deficiency would cause hyperparathyroidism.

    • This question is part of the following fields:

      • Anatomy
      7.9
      Seconds
  • Question 29 - The most sensitive indicator of mild obstructive airway disease is? ...

    Incorrect

    • The most sensitive indicator of mild obstructive airway disease is?

      Your Answer: Forced expiratory volume in one second (FEV1)

      Correct Answer: Forced expiratory flow (FEF25-75%)

      Explanation:

      The volume expired in the first second of maximal expiration after a maximal inspiration is known as forced expiratory volume in one second (FEV1), and it indicates how quickly full lungs can be emptied. It is the most commonly measured parameter for bronchoconstriction assessment.

      The maximum volume of air exhaled after a maximal inspiration is known as the ‘slow’ vital capacity (VC). VC is normally equal to FVC after a forced vital capacity (FVC) or slow vital capacity (VC) manoeuvre, unless there is an airflow obstruction, in which case VC is usually higher than FVC.

      The FEV1/FVC (Tiffeneau index) is a clinically useful index of airflow restriction that can be used to distinguish between restrictive and obstructive respiratory disorders.

      The average expired flow over the middle half (25-75 percent) of the FVC manoeuvre is the forced expiratory volume (FEF25-75). The airflow from the resistance bronchioles corresponds to this. It’s a more sensitive indicator of mild small airway narrowing than FEV1, but it’s difficult to tell if the VC (or FVC) is decreasing or increasing.

      The maximum expiratory flow rate achieved is called the peak expiratory flow (PEF), which is usually 8-14 L/second.

    • This question is part of the following fields:

      • Pathophysiology
      17.9
      Seconds
  • Question 30 - These proprietary preparations of local anaesthetic are available in your hospital: Solution A...

    Incorrect

    • These proprietary preparations of local anaesthetic are available in your hospital: Solution A contains 10 mL 0.5% bupivacaine (plain), and Solution B contains 10 mL 0.5% bupivacaine with adrenaline 1 in 200,000. What is the pharmacokinetic difference between the two solutions?

      Your Answer:

      Correct Answer: The onset of action of solution A is quicker than solution B

      Explanation:

      The reasons for adding adrenaline to a local anaesthetic solution are:

      1. To Increase the duration of block
      2. To reduce absorption of the local anaesthetic into the circulation
      3. To Increase the upper safe limit of local anaesthetic (2.5 mg/kg instead of 2 mg/kg, in this case).

      The addition of adrenaline to bupivacaine does not affect its potency, lipid solubility, protein binding, or pKa(8.1 with or without adrenaline).

      The pH of bupivacaine is between 5-7. Premixed with adrenaline, it is 3.3-5.5.
      The onset of a local anaesthetic and its ability to penetrate membranes depends upon degree of ionisation. Compared with the ionised fraction, unionised local anaesthetic readily penetrates tissue membranes to site of action. The onset of action of solution B is slower. this is because the relationship between pKa(8.1) and pH(3.3-5.5) of the solution results in a greater proportion of ionised local anaesthetic molecules compared with solution A.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Anatomy (3/8) 38%
Pharmacology (6/8) 75%
Pathophysiology (6/7) 86%
Clinical Measurement (0/2) 0%
Physiology (1/2) 50%
Anaesthesia Related Apparatus (0/1) 0%
Statistical Methods (0/1) 0%
Passmed