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Question 1
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What could be a potential cause of metabolic acidosis?
Your Answer: Poorly controlled diabetes
Explanation:Acid-Base Imbalances in Different Medical Conditions
Poorly controlled diabetes can cause the breakdown of fatty acids, leading to the production of ketones as an alternative energy source. However, an excess of ketones can result in metabolic acidosis due to their acidic nature. On the other hand, chronic obstructive pulmonary disease (COPD) and suffocation can cause the retention of carbon dioxide, leading to respiratory acidosis. In COPD, there may be a compensatory metabolic alkalosis. Voluntary hyperventilation can cause respiratory alkalosis due to the reduction of carbon dioxide. Vomiting can also lead to metabolic alkalosis. Diabetic ketoacidosis is a complication of type 1 diabetes that results in high blood sugar levels, ketone production, and acidosis.
In summary, different medical conditions can cause acid-base imbalances in the body. It is important to identify the underlying cause of the imbalance to provide appropriate treatment.
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This question is part of the following fields:
- Basic Sciences
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Question 2
Correct
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What are the primary constituents of the cytoskeleton in eukaryotic cells?
Your Answer: Microfilaments, intermediate filaments and microtubules
Explanation:The Eukaryotic Cytoskeleton: A Structural Support System
The eukaryotic cytoskeleton is a network of structures that provide structural support to the cell. It helps the cell maintain its shape, protects it from external pressure, and performs intracellular transport. The cytoskeleton is made up of three major structures: microfilaments, intermediate filaments, and microtubules. Microfilaments are thin double helices made up of actin and are involved in pressure resistance and cell motility. Intermediate filaments have a more complex structure and maintain cell shape while bearing tension. Microtubules are hollow cylinders made up of alpha and beta tubulin proteins and are involved in intracellular transport, cell movement, and form the mitotic spindle during cytokinesis.
Cilia, flagella, and lamellipodia are structures that are not part of the cell’s cytoskeleton but are made up of components of it and perform unique functions such as cell movement and extracellular sensing. Kinesin and dynein are motor proteins that support microtubule function. Microfilaments and alpha/beta microtubules are incorrect because they leave out intermediate filaments. Tubulin and actin are proteins of microtubules and microfilaments, respectively, but myosin is a motility protein involved in muscle contraction. The eukaryotic cytoskeleton is an essential component of the cell that provides structural support and enables various cellular functions.
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This question is part of the following fields:
- Basic Sciences
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Question 3
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Which process occurs mainly in the smooth endoplasmic reticulum?
Your Answer: Steroid synthesis
Explanation:The Functions of Endoplasmic Reticulum and Lysosomes
The endoplasmic reticulum (ER) is a complex network of membranes that is divided into two types: rough and smooth. The rough ER is characterized by the presence of ribosomes on its cytosolic side, which makes it an important site for protein production, modification, and transport. On the other hand, the smooth ER is involved in cholesterol and steroid handling, as well as calcium storage in some cells. This type of ER is particularly prominent in cells that produce large amounts of steroid hormones, such as those found in the adrenal cortex.
Lysosomes, on the other hand, are organelles that are responsible for breaking down and recycling cellular waste. They are formed by the Golgi apparatus, which is another complex network of membranes found in eukaryotic cells. Lysosomes contain a variety of enzymes that are capable of breaking down different types of molecules, including proteins, lipids, and carbohydrates.
In summary, the ER and lysosomes are two important organelles in eukaryotic cells that play different roles in cellular metabolism. While the ER is involved in protein production, modification, and transport, the lysosomes are responsible for breaking down and recycling cellular waste.
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This question is part of the following fields:
- Basic Sciences
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Question 4
Correct
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A 70-year-old male smoker complains of calf pain.
The GP performs a clinical test by raising the patient's legs and observing for the angle at which there is blanching. After one minute, the legs are lowered over the side of the couch so that they are fully dependent with feet on the floor. Reactive hyperaemia is observed.
Which clinical test does this describe?Your Answer: Buerger's test
Explanation:Tests for Assessing Arterial and Venous Circulation, Hip Dysfunction, and Meniscal Tear
Buerger’s test is a method used to evaluate the arterial circulation of the lower limb. The test involves observing the angle at which blanching occurs, with a lower angle indicating a higher likelihood of arterial insufficiency. Additionally, the degree of reactive hyperaemia on dependency of the limb after one minute is another positive sign of arterial insufficiency during the test.
Another test used to assess circulation is the Ankle-Brachial Pressure Index (ABPI), which involves using blood pressure cuffs to determine the degree of claudication. McMurray’s test, on the other hand, is used to evaluate for a meniscal tear within the knee joint.
Perthe’s test is a method used to assess the patency of the deep femoral vein prior to varicose vein surgery. Lastly, Trendelenburg’s test is used to evaluate hip dysfunction. These tests are important in diagnosing and treating various conditions related to circulation and joint function.
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This question is part of the following fields:
- Basic Sciences
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Question 5
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What is the primary means of transportation for vitamin D in the human body?
Your Answer: In blood, bound to the group specific component
Explanation:The Role of UV Light and Vitamin D in Calcium and Phosphate Regulation
In order for the body to produce Vitamin D3, UV light at a specific wavelength is required to convert cholesterol in the skin. Vitamin D2 and D3 are then transported in the bloodstream bound to the Vitamin-D Binding Protein and undergo further modifications in the liver and kidney to become the active form, 1,25 (OH)2Vitamin D. This active form plays a crucial role in regulating calcium and phosphate concentrations in the body.
1,25 (OH)2Vitamin D increases calcium absorption in the duodenum and inhibits the secretion and synthesis of PTH, which helps to maintain calcium concentrations. It also increases phosphate absorption in the jejunum and ileum, which is important for maintaining phosphate concentrations. Additionally, 1,25 (OH)2Vitamin D promotes bone turnover by stimulating both osteoblast and osteoclast activity.
Overall, the production and activation of Vitamin D through UV light and dietary sources is essential for proper calcium and phosphate regulation in the body.
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This question is part of the following fields:
- Basic Sciences
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Question 6
Correct
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What role does the nucleolus play in eukaryotic cells?
Your Answer: To transcribe ribosomal RNA and assemble ribosomes
Explanation:The Nucleolus: Structure and Function
The nucleolus is a non-membrane-bound structure that takes up about a quarter of the nuclear volume. It is composed mainly of proteins and nucleic acids and is responsible for transcribing ribosomal RNA (rRNA) and assembling ribosomes in the cell. Nucleoli are formed in nucleolar organizing regions (NORs), which are also the regions of the genes for three of the four eukaryotic rRNAs.
During ribosome assembly, ribosomal proteins enter the nucleolus from the cytoplasm and begin to assemble on an rRNA precursor. As the pre-rRNA is cleaved to produce 5.8S, 18S, and 28S rRNAs, additional ribosomal proteins and the 5S rRNA (which is synthesized elsewhere in the nucleus) assemble to form preribosomal subunits. These subunits then exit the nucleolus into the cytoplasm and combine to produce the final 40S and 60S ribosomal subunits.
Overall, the nucleolus plays a crucial role in protein synthesis by producing the components necessary for ribosome assembly. Its unique structure and function make it an essential component of the cell’s machinery.
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This question is part of the following fields:
- Basic Sciences
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Question 7
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What is the primary factor that increases the risk of thiamine (vitamin B1) deficiency?
Your Answer: Chronic alcohol excess
Explanation:Thiamine: Its Roles, Sources, Deficiency States, and Manifestations
Thiamine is a vital nutrient that plays several roles in the body. It acts as a cofactor to enzymes involved in energy production, metabolism of branched chain amino acids, and regulation of nerve and muscle action potentials. It is found in many foods, including wheat, oats, and yeast-containing products. However, deficiency states can occur in chronic alcohol dependence, renal dialysis, and cultures that mainly consume white rice. The deficiency can manifest as ‘dry’ beriberi, which causes peripheral neuropathy, muscle weakness, fatigue, and reduced concentration, or ‘wet’ beriberi, which also involves heart failure and edema. In severe cases, Wernicke-Korsakoff syndrome can develop, which is an emergency requiring urgent IV replacement of thiamine. If left untreated, it can lead to irreversible amnesia, confabulation, and dementia. Therefore, all patients with alcohol-related admissions should be considered for Pabrinex, a B vitamin infusion.
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This question is part of the following fields:
- Basic Sciences
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Question 8
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Of which cellular structure is the fibrillar centre a component?
Your Answer: The nucleolus
Explanation:The Fibrillar Centre in the Nucleolus
The fibrillar centre is a crucial component of the nucleolus, which is found in most metazoan nucleoli, particularly in higher eukaryotes. Along with the dense fibrillar components and the granular component, it forms the three major components of the nucleolus. During the end of mitosis, the fibrillar centre serves as a storage point for nucleolar ribosomal chromatin and associated ribonucleoprotein transcripts. As the nucleolus becomes active, the ribosomal chromatin and ribonucleoprotein transcripts begin to form the dense fibrillar components, which are more peripherally located and surround the fibrillar centres. The transcription zone for multiple copies of the pre-rRNA genes is the border between these two structures. It is important to note that the fibrillar centre is not a component of any of the cell structures mentioned in the incorrect answer options.
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This question is part of the following fields:
- Basic Sciences
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Question 9
Correct
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What are the potential clinical consequences of a lack of vitamin E?
Your Answer: Ataxia
Explanation:Vitamin E Deficiency
Vitamin E deficiency is a rare condition that is more likely to occur in individuals with problems affecting the absorption of dietary fats. This includes those with a history of bowel surgery, pancreatic insufficiency, and cystic fibrosis. Premature infants are also at a higher risk of developing this deficiency as vitamin E does not easily cross the placenta. However, supplementation with vitamin E can reverse the damage in some cases.
The effects of vitamin E deficiency can be severe and can cause spinocerebellar degeneration, which includes limb ataxia, loss of joint position sense, loss of sensation of vibration, and loss of deep tendon reflexes. Additionally, it can cause degeneration of retinal pigments, leading to blindness. In premature infants, it can cause haemolytic anaemia, thrombocytosis, and oedema.
Overall, vitamin E deficiency is crucial in preventing and treating its effects. It is important to identify individuals who are at a higher risk of developing this deficiency and provide them with appropriate supplementation to prevent any long-term damage.
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This question is part of the following fields:
- Basic Sciences
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Question 10
Correct
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What is the estimated percentage of oxygen in the blood that is attached to haemoglobin?
Your Answer: 100%
Explanation:Calculation of Oxygen in Blood
The majority of oxygen in the blood is bound to haemoglobin, with the exact amount varying based on the oxygen saturation and haemoglobin level. To calculate the amount of oxygen per litre of blood, the formula (13.9 × Hb × sats/100) + (PaO2 × 0.03) can be used. For example, an average man with an Hb of 14, saturations of 98% on room air, and a PaO2 of 12 would have 191 ml of oxygen per litre of blood. It is important to note that only 0.36 ml of this oxygen is dissolved in the blood.
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This question is part of the following fields:
- Basic Sciences
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