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  • Question 1 - A patient visits the radiology department for a magnetic resonance imaging (MRI) scan...

    Incorrect

    • A patient visits the radiology department for a magnetic resonance imaging (MRI) scan (MRI). The presence of metal implants must be ruled out prior to the scan. In a strong magnetic field, which of the following metals is the safest?

      Your Answer: Neodymium

      Correct Answer: Chromium

      Explanation:

      Ferromagnetism is the property of a substance that is magnetically attracted and can be magnetised indefinitely. A material is said to be paramagnetic if it is attracted to a magnetic field. A substance is said to be diamagnetic if it is repelled by a magnetic field.

      Cobalt, iron, gadolinium, neodymium, and nickel are ferromagnetic.

      Gadolinium is a ferromagnetic rare earth metal that is ferromagnetic below 20 degrees Celsius (its Curie temperature). MRI scans are enhanced with gadolinium-based contrast media.

      When ferromagnetic materials are exposed to a magnetic field, they can cause a variety of issues like magnetic field interactions, heating, and image artefacts.

      Titanium, lead, chromium, copper, aluminium, silver, gold, and tin are non ferromagnetic.

    • This question is part of the following fields:

      • Clinical Measurement
      22.7
      Seconds
  • Question 2 - Which of the following is a true statement about invasive arterial pressure monitoring?...

    Incorrect

    • Which of the following is a true statement about invasive arterial pressure monitoring?

      Your Answer: The natural frequency is indirectly related to the catheter diameter

      Correct Answer: Increased resonance elevates the systolic and lower the diastolic pressures

      Explanation:

      The arterial cannula inserted should have parallel walls in order to reduce the risk of interruption of blood flow to distal limbs.

      It is essential that the monitor used to display the arterial pressure waves has a frequency capacity of 0.5-40Hz. This is because the pressure waves are a combination of different sine waves of varying frequencies and amplitudes.

      The diameter of the catheter is directly proportional to the natural frequency which is the frequency at which the system responsible for monitoring the waves resonates and amplifies the signals. This should be at least ten fold in comparison to the fundamental frequency. The diameter of the catheter is also inversely proportional to the square root of the system compliance, the tubing length and the fluid density within the system.

      The presence of an air bubble, a clot or an easily malleable diaphragm and tube can result in wave damping. Increased damping will cause a reduction in the systolic pressure, and an increase in diastolic pressure. The maximum damping value of an appropriate monitoring system would be 0.64.

      A rigid, non-malleable diaphragm and tubing can cause a resonance within the system. This resonance will result in an increase in the systolic pressure and a reduction in the diastolic pressure.

    • This question is part of the following fields:

      • Clinical Measurement
      59
      Seconds
  • Question 3 - Which of the following is true about the bispectral index (BIS)? ...

    Correct

    • Which of the following is true about the bispectral index (BIS)?

      Your Answer: Sevoflurane lowers BIS more than ketamine

      Explanation:

      The bispectral index (BIS) monitors works to determine the level of consciousness of a patient by processing electroencephalographic (EEG) signals to obtain a value between 0 and 100, where 0 reflects no brain activity, and 100 reflects a patient is completely awake.

      The general meaning of BIS values are:

      >95: Patient is in an awake state.
      65-85: Patient is in a sedated state.
      40-65: Patient is in a state that is optimal for general surgery.
      <40: Patient is in a deep hypnotic state

      It is important in measuring the depths of anaesthesia to prevent haemodynamic changes or patient awareness during surgery.

      The nature of anaesthetic agent used is a determinant factor in resultant BIS values. Intravenous agents, such as propofol, thiopental and midazolam, result in a deeper hypnotic state, whilst inhalation agents have a lesser hypnotic effect at the same BIS values. Certain agents result in inaccurate BIS values such as ketamine and nitrous oxide (NO). These two agents appear to increase the BIS value, whilst putting the patient in a deeper hypnotic state, and should therefore not be used with BIS monitoring.

      Hypothermia also affects the BIS value as it causes a 1.12 per °C decrease in body temperature.

    • This question is part of the following fields:

      • Clinical Measurement
      41
      Seconds
  • Question 4 - The statement that best describes temperature management is: ...

    Incorrect

    • The statement that best describes temperature management is:

      Your Answer: Thermistors use the Seebeck effect to measure temperature

      Correct Answer: Gauge thermometers use coils of different metals with different co-efficients of expansion which either tighten or relax with changes in temperature

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      60.4
      Seconds
  • Question 5 - The diaphragm is a muscle that is relatively resistant to non-depolarizing neuromuscular blockade's...

    Incorrect

    • The diaphragm is a muscle that is relatively resistant to non-depolarizing neuromuscular blockade's effects. When these muscle relaxants are used, which of the following peripheral nerve stimulator twitch patterns is best for monitoring the return of diaphragmatic function?

      Your Answer: Train-of-four stimulation

      Correct Answer: Post-tetanic count stimulation

      Explanation:

      Certain skeletal muscles are more resistant to the effects of neuromuscular blocking agents, both non-depolarizing and depolarizing. The diaphragm is the most resistant. The muscles of the larynx and the corrugator supercilii are less resistant. The abdominal, orbicularis oris, and limb peripheral muscles are the most sensitive muscles.

      Twitch stimulation patterns:

      Supramaximal single stimulus:

      The frequency ranges from 1 Hz to 0.1 Hz (one every second to one every 10 seconds)
      The response is proportional to the frequency of the event.
      It has limited clinical utility because it only tells you whether or not a patient is paralysed (no information on degree of paralysis).

      Over the course of 0.5 seconds (2 Hz), four supramaximal stimulate were applied:

      It is possible to see ‘fade’ and use it as a basis for evaluation.
      This stimulation pattern is used to determine the degree of blockade (1-2 twitches is appropriate for abdominal surgery)
      If the train of four (TOF) count is 1-2, reversal agents can be used in conjunction with medium-acting neuromuscular blocking agents.

      Ratio of TOF:

      This is the ratio of the 4th twitch amplitude to the 1st twitch amplitude.
      The ratio decreases with non-depolarising block and is inversely proportional to the degree of block, allowing objective measurement of residual neuromuscular blockade.
      To achieve adequate reversal, the ratio (as measured by accelerography) must be between 0.7 and 0.9.

      Count of twitches after a tetanic experience(PTC):

      50 Hz for 5 seconds, then a 3 second pause, followed by a single 1 Hz twitch stimulus.
      When the TOF count is zero, this stimulation pattern is used to assess deep blockade (that is, in neurosurgery, microsurgery or ophthalmic surgery when even small movements of a patient will disturb the surgical field)
      It gives an estimate of how long it will take for the response to return to single twitches, allowing assessment of blocks that are too deep for any other technique.
      A palpable post-tetanic count (PTC) of 2 indicates no twitch response for about 20-30 minutes, and a PTC of 5 indicates no twitch response for about 10-15 minutes.

      This is without a doubt the best way to keep track of paralysis in patients who need to avoid diaphragmatic movement. It’s best to use drug infusions and aim for a PTC of 2. After a tetanic stimulus, acetylcholine is mobilised, causing post-tetanic potentiation.

      Stimulation in Two Bursts:

      750 milliseconds between two short bursts of 50 Hz
      This stimulation pattern is used to assess small amounts of residual blockade manually (tactile).

    • This question is part of the following fields:

      • Clinical Measurement
      22.1
      Seconds
  • Question 6 - Regarding sine wave damping, which one would approach equilibrium the fastest at zero...

    Incorrect

    • Regarding sine wave damping, which one would approach equilibrium the fastest at zero amplitude, without overshoot?

      Your Answer:

      Correct Answer: Critical damping

      Explanation:

      A damped sine wave is a smooth, periodic oscillation with an amplitude that approaches zero as time goes to infinity. In other words, the wave gets flatter as the x-values become larger.

      Critical damping is defined as the threshold between overdamping and underdamping. In the case of critical damping, the oscillator returns to the equilibrium position as quickly as possible, without oscillating, and passes it once at most.

      In overdamping, the system moves slowly towards the equilibrium. An underdamped system moves quickly to equilibrium, but will oscillate about the equilibrium point as it does so.

      Optimal damping has a damping coefficient of around 0.64-0.7. It maximizes frequency response, minimizes overshoot of oscillations, and minimizes phase and amplitude distortion.

      In an undamped system, the amplitude of the waves that are being generated remain unchanged and constant over time.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 7 - A pulmonary function tests results are: (Measurement, Predicted result, Test result). Forced vital...

    Incorrect

    • A pulmonary function tests results are: (Measurement, Predicted result, Test result). Forced vital capacity (FVC) (btps): 3.85, 2.36 Forced expiratory volume in 1 second (FEV1) (btps): 3.34, 0.97. FEV1/FVC ratio % (btps): 85.1, 39.9. Peak expiratory flow (PEF) (L/second): 7.33, 2.11. Maximum voluntary ventilation (MVV) (L/minute): 116, 44.4. What does this indicate?

      Your Answer:

      Correct Answer: Moderate restrictive and severe obstructive picture

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (V1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35%

      This patient has a mixed deficit with a severe obstructive deficit as V1/FVC predicted is 46.9% and a moderate restrictive deficit as %FVC of predicted is 61.3

      FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture.

      FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 8 - A 50-year-old man is admitted in hospital. Over four hours, he produces 240...

    Incorrect

    • A 50-year-old man is admitted in hospital. Over four hours, he produces 240 mL of urine and has a plasma creatinine concentration is 10 mcg/mL. The normal concentration of creatinine in urine is 1.25 mg/mL. Calculate his approximate creatinine clearance.

      Your Answer:

      Correct Answer: 125 ml/minute

      Explanation:

      Creatinine clearance is a test used to approximate the glomerular filtration rate (GFR) as an assessment of kidney function.

      Creatinine is formed during the breakdown of dietary sources of meat and skeletal muscle. It is secreted at a consistent concentration and pace into the body’s circulation, and is easily filtered across the glomerulus without being reabsorbed or metabolized by the kidney.

      It is represented mathematically as:
      Creatinine clearance (CL) = U x V/P
      where,
      U: Urinary creatinine concentration (mg/mL)
      V: Volume of urine (mL/min)
      P: Plasma creatinine concentration (mg/mL)

      Therefore, in this case:
      CL: 1.25 x 1 = 125mL/min.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 9 - A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck...

    Incorrect

    • A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck circumference of 44 cm. He is troubled by intermittent nasal obstruction which causes his partner sleeps in a separate bedroom because of snoring. He currently on ramipril for hypertension. Which of the following best approximates to his STOP-BANG score from the information above?

      Your Answer:

      Correct Answer: 5

      Explanation:

      The STOP-BANG questionnaire is used to screen patients for obstructive sleep apnoea (OSA).

      The scoring system assigns one point for each feature.

      S: Snoring (louder than talking or loud enough to be heard through closed doors)
      T: Feeling tired, fatigued, or sleepy during daytime
      O: Observed apnoeas during sleep
      P: Hypertension
      B: BMI more than 35 kg/m2
      A: Age 50-years of age or greater
      N: Neck circumference (male 17 inches / 43cm or greater and female 16 inches / 41 or greater)
      G: Gender: Male

      Our patient has a score of 5 ( O, P, A, N, G)

      The score helps clinicians stratify patients for unrecognized OSA and target appropriate clinical management. It can also help triage patients for further investigation. A STOP-BANG score of 5-8 will identify patients with high probability of moderate to severe OSA in the surgical population.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 10 - All of the following options describes a thermistor for the measurement of temperature...

    Incorrect

    • All of the following options describes a thermistor for the measurement of temperature except:

      Your Answer:

      Correct Answer: Resistance of the bead increases exponentially as the temperature increases

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 11 - With regards to devices for temperature management, all of these are used EXCEPT:...

    Incorrect

    • With regards to devices for temperature management, all of these are used EXCEPT:

      Your Answer:

      Correct Answer: Thermistors use the resistance of a semiconductor bead which increases exponentially as the temperature increases

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 12 - A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia....

    Incorrect

    • A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia. She has no cardiac or respiratory problems. Lisinopril is being used to treat her hypertension, which is under control. Which of the following preoperative investigations are the most appropriate for this patient?

      Your Answer:

      Correct Answer: No investigations

      Explanation:

      Because the patient has mild systemic disease, he is ASA 2 and the procedure will be performed under local anaesthesia.

      The following factors should be considered when requesting preoperative investigations:

      Indications derived from a preliminary clinical examination
      Whether or not a general anaesthetic will be used, the possibility of asymptomatic abnormalities, and the scope of the surgery.

      No special investigations are needed if the patient has no history of significant systemic disease and no abnormal findings on examination during the nurse-led assessment.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 13 - A 30 year old male was the victim of an electrocution injury and...

    Incorrect

    • A 30 year old male was the victim of an electrocution injury and has been treated. The option that best describes the current levels for this injury is:

      Your Answer:

      Correct Answer: Tonic muscle contraction - 15 mA

      Explanation:

      There are different effects of electrocution and these can be shown in the table below.

      Current Effect
      1 mA Tingling
      5 mA Pain
      15 mA Tonic muscle contraction
      50 mA Respiratory arrest
      100 mA Ventricular fibrillation and cardiac arrest.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 14 - Which statement is the most accurate when describing electrical equipment and shock? ...

    Incorrect

    • Which statement is the most accurate when describing electrical equipment and shock?

      Your Answer:

      Correct Answer: Type CF is considered to safe for direct connection with the heart

      Explanation:

      There are different classes of electrical equipment that can be classified in the table below:

      Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply

      Class II – provides double insulation for all equipment. It does not require an earth.

      Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.

      Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)

      Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.

      Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF).

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 15 - A patient has a myocardial infarction with anterior ST elevation. There are the...

    Incorrect

    • A patient has a myocardial infarction with anterior ST elevation. There are the following observations: Cardiac output 2.0 L/min, Blood pressure 80/60 mmHg, CVP 20 mmHg, SpO2 91% on 4 L/min oxygen. What is the most logical physiological explanation for these findings?

      Your Answer:

      Correct Answer: Biventricular failure

      Explanation:

      The occlusion of the left anterior descending (LAD) coronary artery causes anterior ST elevation myocardial infarction (STEMI). It has the worst prognosis of all the infarct locations due to its larger infarct size. It has a higher rate of total mortality (27 percent versus 11 percent), heart failure (41 percent versus 15 percent), and a lower ejection fraction on admission than an inferior myocardial infarction (38 percent versus 55 percent ).

      The LAD artery supplies the majority of the interventricular septum, as well as the anterior, lateral, and apical walls of the left ventricle, as well as the majority of the right and left bundle branches and the bicuspid valve’s anterior papillary muscle (left ventricle).

      The left or right ventricle’s end-diastolic volume (EDV) is the volume of blood in each chamber at the end of diastole before systole. Preload is synonymous with the EDV.

      120 mL is a typical left ventricular EDV (range 65-240 mL). The EDV of the right ventricle in a typical range is (100-160 mL).

      With an ejection fraction (EF) of less than 45 percent, the patient is most likely suffering from systolic dysfunction. Increases in right and left ventricular end-diastolic pressures and volumes are likely with a reduced EF because the ventricles are not adequately emptied. The left atrium and the pulmonary vasculature are affected by the increased pressures on the left side of the heart.

      By causing an imbalance of the Starling forces acting across the capillaries, increased hydrostatic pressure in the pulmonary circulation favours the development of pulmonary oedema. With cardiogenic pulmonary oedema, capillary permeability is likely to remain unchanged.

      Biventricular failure will result as a result of the pressure changes being transmitted to the right side of the circulation. The patient’s systemic vascular resistance is likely to be elevated as well, but it is not the most likely cause of his symptoms. The patient is suffering from cardiogenic shock as a result of biventricular failure. The patient has low cardiac output and is hypotensive. Right ventricular filling pressures are elevated, indicating right ventricular dysfunction.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 16 - The following are results of some pulmonary function tests: (Measurement - Predicted result...

    Incorrect

    • The following are results of some pulmonary function tests: (Measurement - Predicted result - Test result). Forced vital capacity (FVC) (btps): 3.21, - 1.94. Forced expiratory volume in 1 second (FEV1) (btps): 2.77, 1.82. FEV1/FVC ratio % (btps): 81.9, 93.5. Peak expiratory flow (PEF) (L/second): 6.55, 3.62. Maximum voluntary ventilation (MVV) (L/minute): 103, 87.1 Which statement applies to the results?

      Your Answer:

      Correct Answer: The patient has a moderate restrictive pulmonary defect

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (V1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35%

      This patient has a %FVC predicted of 60.4% and this corresponds to a moderate restrictive deficit. V1/FVC ratio is 93.5%.

      FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture.

      FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.

      The integrity of the alveolar-capillary barrier is measured by carbon monoxide transfer factor (TLCO) and carbon monoxide transfer coefficient (KCO). These values are seen to be reduced in emphysema, interstitial lung diseases and in pulmonary vascular pathology. However, the KCO (as % predicted) is high in extrapulmonary restriction (pleural, chest wall and respiratory neuromuscular disease), and in loss of lung units provided the structure of the lung remaining is normal. The KCO distinguishes extrapulmonary (high KCO) causes of 'restriction' from intrapulmonary causes (low KCO).

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 17 - Which of the following can be measured directly using spirometry? ...

    Incorrect

    • Which of the following can be measured directly using spirometry?

      Your Answer:

      Correct Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 18 - Which measurements is the most accurate for predicting fluid responsiveness? ...

    Incorrect

    • Which measurements is the most accurate for predicting fluid responsiveness?

      Your Answer:

      Correct Answer: Change in stroke volume following passive straight leg raise

      Explanation:

      The passive leg raising (PLR) manoeuvre is a method of altering left and right ventricular preload and it is done with real-time measurement of stroke volume. It is a simple, quick, relatively unbiased, and accurate bedside test to guide fluid management and avoid fluid overload.

      Pulse pressure variation (PPV), Stroke volume variation (SVV), superior vena cava diameter variation (threshold 36%) and end-expiratory occlusion test are used for dynamic tests of fluid responsiveness.

      PPV is derived peripherally from the arterial pressure waveform.

      Stroke volume variation (SVV) can be derived peripherally through pulse contour analysis of the arterial waveform. PPV and SVV have a threshold of 12% but since they are not used in patients who have cardiac arrhythmias, are spontaneous breathing, and in ventilated patients with low lung compliance and tidal volumes, they are of limited value.

      The tests of fluid responsiveness’ accuracy is determined by calculating the area under the receiver operating characteristic curve (UROC) obtained by plotting the sensitivity of the parameter in predicting fluid responsiveness vs. 1-specificity.

      Under optimal conditions, the ability to determine the need for fluid is best with PPV>SVV>LVEDA>CVP.

      Central venous pressure (CVP) is a static test of preload (not preload responsiveness) and a key determinant of cardiac function. The left ventricular end-diastolic area (LVEDA) a static test of fluid responsiveness, is derived using echocardiography.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 19 - Arterial pressure waveforms give an indication of the operation of the heart and...

    Incorrect

    • Arterial pressure waveforms give an indication of the operation of the heart and the patient's clinical state. Which of the following listed characteristics of arterial waveforms is most indicative of myocardial contractility?

      Your Answer:

      Correct Answer: Slope of the upstroke of the curve.

      Explanation:

      Arterial pressure waveforms is an invasive form of monitoring cardiac parameters. It provides a lot of information on the performance of the heart from different sections, including:

      Cardiac measurements:

      Heart rate
      Systolic pressure
      Diastolic pressure
      Mean arterial pressure
      Pulse pressure
      Change in pulse amplitude corresponding to respiratory changes
      Slope of anacrotic limb associated with aortic stenosis

      From the shape of the arterial waveform displayed:

      Slope of anacrotic limb represents aortic valve and LVOT flow
      Indications of aortic stenosis (AS): Slurred wave, collapsing wave
      Rapid systolic decline in LVOTO
      Bisferiens wave in HOCM
      Low dicrotic notch in states with poor peripheral resistance
      Position and quality of dicrotic notch as a reflection of the damping coefficient

      For this question, the upstroke slope of the pressure wave is indicative of myocardial contractility and is mathematically represented as:

      dP/dt, which represents a change of pressure with regards to time.

    • This question is part of the following fields:

      • Clinical Measurement
      0
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  • Question 20 - A 27-year-old woman arrives at the emergency room after intentionally ingesting 2 g...

    Incorrect

    • A 27-year-old woman arrives at the emergency room after intentionally ingesting 2 g of amitriptyline. A Glasgow coma score of 6 was discovered, as well as a pulse rate of 140 beats per minute and a blood pressure of 80/50 mmHg. Which of the following ECG changes is most likely to indicate the onset of life-threatening arrhythmias?

      Your Answer:

      Correct Answer: Prolongation of the QRS complex

      Explanation:

      Arrhythmias and/or hypotension are the most common causes of death from tricyclic antidepressant (TCA) overdose.

      The quinidine-like actions of tricyclic antidepressants on cardiac tissues are primarily responsible for their toxicity. Conduction through the His-Purkinje system and the myocardium slows as phase 0 depolarisation of the action potential slows. QRS prolongation and atrioventricular block are caused by slowed impulse conduction, which also contributes to ventricular arrhythmias and hypotension.

      Arrhythmias can also be caused by abnormal repolarization, impaired automaticity, cholinergic blockade, and inhibition of neuronal catecholamine uptake, among other things.

      Acidaemia, hypotension, and hyperthermia can all exacerbate toxicity.

      The anticholinergic effects of tricyclic antidepressants, as well as the blockade of neuronal catecholamine reuptake, cause sinus tachycardia. Sinus tachycardia is usually well tolerated and does not require treatment. It can be difficult to tell the difference between sinus tachycardia and ventricular tachycardia with QRS prolongation.

      A QRS duration of more than 100 milliseconds indicates a higher risk of arrhythmia and should be treated with systemic sodium bicarbonate.

      The tricyclic is dissociated from myocardial sodium channels by serum alkalinization, and the extracellular sodium load improves sodium channel function.

    • This question is part of the following fields:

      • Clinical Measurement
      0
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  • Question 21 - If the speed of an ultrasound in soft tissue is 1540 meters per...

    Incorrect

    • If the speed of an ultrasound in soft tissue is 1540 meters per second, what is the estimated wavelength produced if the frequency of a generated ultrasound is 10 megahertz?

      Your Answer:

      Correct Answer: 0.15 millimetre

      Explanation:

      Wavelength can be computed as follows:

      Wavelength = velocity/frequency

      In the given problem, the values stated are:

      Frequency = 10 x 10^6
      Velocity = 1540 meters per second

      Wavelength = 1540/(10×10^6)
      Wavelength = 1540/10,000,000 meters
      Wavelength = 0.15 millimetres.

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      • Clinical Measurement
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  • Question 22 - The following haemodynamic data is available from a patient with pulmonary artery catheter...

    Incorrect

    • The following haemodynamic data is available from a patient with pulmonary artery catheter inserted: Pulse rate - 100 beats per minute, Blood pressure - 120/70mmHg, Mean central venous pressure (MCVP) - 10mmHg, Right ventricular pressure (RVP) - 30/4 mmHg, Mean pulmonary artery wedge pressure (MPAWP) - 12mmHg. Which value best approximates the patient's coronary perfusion pressure?

      Your Answer:

      Correct Answer: 58mmHg

      Explanation:

      Coronary perfusion pressure(CPP), the difference between aortic diastolic pressure (Pdiastolic) and the left ventricular end-diastolic pressure (LVEDP), is mainly determined by the formula:

      CPP = Pdiastolic -LVEDP
      where
      Pdiastolic is the lowest pressure in the aorta before left ventricular ejection and
      LVEDP is measured directly during a cardiac catheterisation or indirectly using a pulmonary artery catheter. The pulmonary artery occlusion or wedge pressure approximates best with LVEDP.

      Using this patient’s haemodynamic data:

      CPP = Pdiastolic – MPAWP
      COO = 70 – 12 = 58mmHg.

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  • Question 23 - A 64-year-old man is admitted to the critical care unit. He has a...

    Incorrect

    • A 64-year-old man is admitted to the critical care unit. He has a recent medical history of faecal peritonitis for which a laparotomy was performed. His vitals have been monitored using an invasive pulmonary artery flotation catheter. His vital readings are: Temperature: 38.1°C. Blood pressure: 79/51 mmHg (mean 58 mmHg), Pulmonary artery pressure: 19/6 mmHg (mean 10 mmHg). Pulmonary capillary occlusion pressure: 5 mmHg, Central venous pressure: 12 mmHg, Cardiac output: 5 L/min, Mixed venous oxygen saturation: 82%. Calculate his approximate pulmonary vascular resistance. Note: A correction factor of 80 is require to convert mmHg to dynes·s·cm-5

      Your Answer:

      Correct Answer: 80 dynes·s·cm-5

      Explanation:

      Pulmonary vascular resistance (PVR) refers to the resistance to blood flow to the left atrium from the pulmonary artery.
      It is derived mathematically by:

      PVR = MPAP – PCWP
      CO
      where,
      MPAP: Mean pulmonary artery pressure
      PCWP: Pulmonary capillary occlusion pressure
      CO: Cardiac output

      For this patient:
      PVR = 10 – 5 = 1mmHg
      5

      Remember, multiply by correction factor 80 to change units:

      PVR = 1mmHg x 80 = 80 dynes·s·cm-5

      Normal values range between 20-130 dynes·s·cm-5.

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  • Question 24 - Blood pressure monitoring is a requirement for in-patient care. Different factors can result...

    Incorrect

    • Blood pressure monitoring is a requirement for in-patient care. Different factors can result in an inaccurate blood pressure reading, including the damping of an arterial waveform. How does a damped arterial waveform affect blood pressure measurements?

      Your Answer:

      Correct Answer: The systolic pressure is lower and the diastolic pressure higher with the same mean

      Explanation:

      Damping is the reduction of energy in a system achieved by reducing the amplitude of oscillations. It is necessary to some degree to prevent wave overshoots.

      Critical damping usually causes the system to be slow, so optimal damping is normally applied to provide a balance between speed and distortion.

      Damping can cause errors if excessive (overdamping) or inadequate (Underdamping). The amount of damping in a system can be determined using the damping coefficient (D), where:

      Undamped: 0
      Critically damped: 1
      Optimally damped: 0.64

      An overdamped system will cause an artificial decrease in the systolic blood pressure, and an artificial increase in the diastolic blood pressure.

      An underdamped system will cause an artificial increase in systolic blood pressure and an artificial decrease in diastolic blood pressure.

      Damping can be caused by a number of factors affecting different parts of the system, including:

      The tubing/cannula: The presence of air bubbles, increased blood viscosity or formation of blood clots.
      The diaphragm/tubing: Increased malleability/compliance
      The tubing: Presence of kinks, narrowing or too many ports of injection.

      The answer here is a damped system will have a low systolic pressure, a high diastolic pressure with a normal mean pressure.

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  • Question 25 - Which of the following statements is false when considering the electrical safety of...

    Incorrect

    • Which of the following statements is false when considering the electrical safety of equipment?

      Your Answer:

      Correct Answer: The low leakage currents limit is 0.01mA for Class I CF

      Explanation:

      There are different classes of electrical equipment that can be classified in the table below:

      Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply

      Class II – provides double insulation for all equipment. It does not require an earth.

      Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.

      Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)

      Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.

      Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF).

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  • Question 26 - A 77-year-old man is admitted to hospital for colorectal surgery. He is scheduled...

    Incorrect

    • A 77-year-old man is admitted to hospital for colorectal surgery. He is scheduled to undergo a preoperative assessment, which includes cardiopulmonary exercise test (CPX). During the CPX, his maximum oxygen consumption (VO2 max) is determined to be 2,100 mL/minute. His weight is measured to be 100 kg. Calculate the metabolic equivalent (MET) that is the best estimate for his VO2 max.

      Your Answer:

      Correct Answer: 6 METs

      Explanation:

      Metabolic equivalent (MET) measures the energy expenditure of an individual.

      It is calculated mathematically by:

      MET = (VO2 max/weight)/3.5 = 21/3.5 = 6 METs

      Where 1 MET = 3.5 mL O2/kg/minute is utilized by the body.

      Note:

      1 MET Eating
      Dressing
      Use toilet
      Walking slowly on level ground at 2-3 mph
      2 METs Playing a musical instrument
      Walking indoors around house
      Light housework
      4 METs Climbing a flight of stairs
      Walking up hill
      Running a short distance
      Heavy housework, scrubbing floors, moving heavy furniture
      Walking on level ground at 4 mph
      Recreational activity, e.g. golf, bowling, dancing, tennis
      6 METs Leisurely swimming
      Leisurely cycling along the flat (8-10 mph)
      8 METs Cycling along the flat (10-14 mph)
      Basketball game
      10 METs Moderate to hard swimming
      Competitive football
      Fast cycling (14-16 mph).

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  • Question 27 - Of the following statements, which is true about the measurements of cardiac output...

    Incorrect

    • Of the following statements, which is true about the measurements of cardiac output using thermodilution?

      Your Answer:

      Correct Answer: Cardiac output should be measured during the end-expiratory pause

      Explanation:

      Thermodilution is the most common dilution method used to measure cardiac output (CO) in a hospital setting.

      During the procedure, a Swan-Ganz catheter, which is a specialized catheter with a thermistor-tip, is inserted into the pulmonary artery via the peripheral vein. 5-10mL of a cold saline solution with a known temperature and volume is injected into the right atrium via a proximal catheter port. The solution is cooled as it mixes with the blood during its travel to the pulmonary artery. The temperature of the blood is the measured by the catheter and is profiled using a computer.

      The computer also uses the profile to measure cardiac output from the right ventricle, over several measurements until an average is selected.

      Cardiac output changes at each point of respiration, therefore to get an accurate measurement, the same point during respiration must be used at each procedure, this is usually the end of expiration, that is the end-expiratory pause.

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  • Question 28 - An 84-year-old woman has a fall. She fractures the neck of her femur...

    Incorrect

    • An 84-year-old woman has a fall. She fractures the neck of her femur and requires emergency surgery. On history and examination, she appears to also have a possible heart failure for which an echocardiogram is scheduled. Her measurements are: End-diastolic volume: 40mL (70-240), End-systolic volume: 30mL (16-140). Calculate her approximate ejection fraction.

      Your Answer:

      Correct Answer: 25%

      Explanation:

      An echocardiogram provides real-time visualisation of cardiac structures. The ejection fraction (EF) is normally measured using this system.

      The ejection fraction (EF) can be deduced mathematically if the patient’s end-diastolic volume (EDV), end-systolic volume (ESV) and stroke volume (SV) are known, as:

      SV = EDV – ESV, and

      EF = SV/EDV x 100

      The normal range for EF is >55-70%.

      For this patient,

      SV= 40 – 30 = 10 mL, therefore

      EF = 10/40 x 100 = 25%.

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  • Question 29 - A 32-year-old male is admitted to the critical care unit. He has suffered...

    Incorrect

    • A 32-year-old male is admitted to the critical care unit. He has suffered a heroin overdose and requires intubation and ventilatory support. What would be his predicted total static compliance (lung and chest wall) measurements.

      Your Answer:

      Correct Answer: 100 ml/cmH2O

      Explanation:

      Static lung compliance refers to the change in volume within the lung per given change in unit pressure. It is usually measured when air flow is absent, such as during pauses in inhalation and exhalation.

      It is a combination of:

      Chest wall compliance: normal value is 200 mL/cmH2O
      Lung tissue compliance: normal value is 200 mL/ cmH2O

      It is represented mathematically as:

      1/Crs = 1/Cl + 1/Ccw

      Where,

      Crs = total compliance of the respiratory system
      Cl = compliance of the lung
      Ccw = compliance of the chest wall

      Therefore in this case:

      1/Crs = 1/200 + 1/200

      1/Crs = 0.005 + 0.005 = 0.01

      1/Ct = 0.01

      Rearranging equation gives:

      Ct = 1/0.01 = 100 mL/cmH2O.

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  • Question 30 - A 23-year-old man, has just undergone surgery under general anaesthesia. He has experienced...

    Incorrect

    • A 23-year-old man, has just undergone surgery under general anaesthesia. He has experienced a severe reaction to the anaesthetic agent resulting in malignant hyperthermia (MH) for which he has been referred for treatment. What investigation can be conducted to determine a patient's susceptibility to malignant hyperthermia?

      Your Answer:

      Correct Answer: In vitro muscle contraction test using caffeine

      Explanation:

      Malignant hyperthermia (MH) is a autosomal dominant inherited medical condition which predisposes affected individuals to a clinical syndrome of hypermetabolism which involves abnormal ryanodine receptors in skeletal muscle causing a deregulation of calcium in muscle.

      It is a life threatening condition requiring immediate medical intervention. It often lies dormant until triggered in susceptible individuals mostly by volatile inhaled anaesthetic agents and succinylcholine which is a muscle relaxant.

      The signs and symptoms of MH are related to this hypermetabolism, which includes an increase in carbon dioxide production, metabolic and respiratory acidosis, accelerated oxygen consumption, heat production, activation of the sympathetic nervous system, hyperkalaemia, disseminated intravascular coagulation (DIC), and multiple organ dysfunction and failure.

      Early signs of MH to look out for in patients includes an uptick in end-tidal carbon dioxide (even with increasing minute ventilation), tachycardia, muscle rigidity, tachypnoea, and hyperkalaemia. Later signs include fever, myoglobinuria, and multiple organ failure.

      In vitro muscle contracture test (IVCT) is the standard for determining individual susceptibility to MH. It is conducted by measuring the force of muscle contraction after exposing the patient’s muscle sample to halothane and caffeine., the sample is normally taken from the vastus medialis or lateralis under regional anaesthesia.

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SESSION STATS - PERFORMANCE PER SPECIALTY

Clinical Measurement (1/5) 20%
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