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Question 1
Incorrect
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A 20-year-old male who migrated from Ghana during childhood presents with an intermittent painful morning erection that has lasted for the past 4 hours. He has never experienced this problem before and is typically healthy. On examination, he has mild splenomegaly. Laboratory investigations reveal:
- Hemoglobin (Hb) level of 115 g/L (normal range for males: 135-180 g/L; females: 115-160 g/L)
- Mean corpuscular volume (MCV) of 76 fL (normal range: 80-95 fL)
The peripheral blood film shows multiple small red blood cells, a few sickle cells, and target cells. Based on these findings, what is the most probable genotype for his condition?Your Answer: HbSS
Correct Answer: HbSC
Explanation:Hb SC is a less severe variant of sickle cell disease that can be detected early through screening of children in the UK. This condition is characterized by the presence of both the sickle mutation and the HbC mutation, which results in a lysine substitution for glutamic acid on position 6 of the beta chain. While HbSC shares similarities with sickle cell disease, its symptoms are less frequent and severe. The severity of the disease can vary depending on the specific genotype, with HbAA being normal, HbAS being asymptomatic, HbSC/Sβ+ being moderately affected, and HbSS/Sβ0 being severely affected due to the absence of normal haemoglobin.
Understanding Sickle-Cell Anaemia
Sickle-cell anaemia is a genetic disorder that occurs when an abnormal haemoglobin chain, known as HbS, is synthesized due to an autosomal recessive condition. This condition is more common in people of African descent, as the heterozygous condition offers some protection against malaria. In the UK, around 10% of Afro-Caribbean individuals are carriers of HbS. Symptoms in homozygotes typically do not develop until 4-6 months when the abnormal HbSS molecules take over from fetal haemoglobin.
The pathophysiology of sickle-cell anaemia involves the substitution of the polar amino acid glutamate with the non-polar valine in each of the two beta chains (codon 6) of haemoglobin. This substitution decreases the water solubility of deoxy-Hb, causing HbS molecules to polymerize and sickle in the deoxygenated state. HbAS patients sickle at p02 2.5 – 4 kPa, while HbSS patients sickle at p02 5 – 6 kPa. Sickle cells are fragile and can cause haemolysis, block small blood vessels, and lead to infarction.
To diagnose sickle-cell anaemia, haemoglobin electrophoresis is the definitive test. It is essential to understand the pathophysiology and symptoms of sickle-cell anaemia to provide appropriate care and management for affected individuals.
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This question is part of the following fields:
- Haematology And Oncology
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Question 2
Correct
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You are asked to see a 4-year-old girl with severe chronic malnutrition.
You are concerned about kwashiorkor.
What clinical feature is typical in cases of kwashiorkor?Your Answer: Abdominal swelling
Explanation:Protein-Energy Malnutrition
Protein-energy malnutrition (PEM) or protein energy undernutrition (PEU) occurs when the body’s intake of energy and protein is insufficient to meet its requirements. This can happen due to inadequate intake or an increase in requirements without a corresponding increase in intake. The result is a range of health problems, including undernutrition, which is sadly common in many parts of the world.
Undernutrition can take different forms, including kwashiorkor and marasmus. Kwashiorkor is characterized by inadequate protein intake, leading to oedema, abdominal swelling, and fat accumulation in the liver. Marasmus, on the other hand, involves inadequate consumption of both energy and protein, resulting in emaciation without oedema or abdominal swelling. The term ‘protein-energy undernutrition’ encompasses both of these scenarios.
It’s worth noting that malnutrition can refer to both overnutrition (obesity) and undernutrition, both of which have negative effects on the body’s health. However, in common usage, malnutrition typically refers to undernutrition. Additionally, malnutrition can also result from isolated deficiencies in vitamins or minerals. Overall, protein-energy malnutrition is crucial for promoting and preserving good health.
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This question is part of the following fields:
- Clinical Sciences
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Question 3
Incorrect
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A 15-year-old boy fell from a height of 2 meters while climbing a tree and caught himself with his right arm on a branch just before hitting the ground. He immediately felt pain in his hand and lower neck. Despite the pain, he managed to lower himself to the ground and make his way to the hospital.
Upon examination, there are no visible wounds or fractures, but there is a noticeable reduction in movement and power of the intrinsic hand muscles. All other joints in the upper limb appear to be normal.
What nerve root injury pattern did the boy sustain?Your Answer: C7
Correct Answer: T1
Explanation:Brachial Plexus Injuries: Erb-Duchenne and Klumpke’s Paralysis
Erb-Duchenne paralysis is a type of brachial plexus injury that results from damage to the C5 and C6 roots. This can occur during a breech presentation, where the baby’s head and neck are pulled to the side during delivery. Symptoms of Erb-Duchenne paralysis include weakness or paralysis of the arm, shoulder, and hand, as well as a winged scapula.
On the other hand, Klumpke’s paralysis is caused by damage to the T1 root of the brachial plexus. This type of injury typically occurs due to traction, such as when a baby’s arm is pulled during delivery. Klumpke’s paralysis can result in a loss of intrinsic hand muscles, which can affect fine motor skills and grip strength.
It is important to note that brachial plexus injuries can have long-term effects on a person’s mobility and quality of life. Treatment options may include physical therapy, surgery, or a combination of both. Early intervention is key to improving outcomes and minimizing the impact of these injuries.
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This question is part of the following fields:
- Neurological System
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Question 4
Correct
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A 60-year-old male patient comes in for a routine colonoscopy. He had stage I colon cancer that was treated successfully ten years ago. During the discussion of his thoughts, concerns, and expectations, he mentions that he hasn't thought about the potential results until now and that worrying won't change anything.
What ego defense mechanism is he displaying?Your Answer: Suppression
Explanation:Understanding Ego Defenses
Ego defenses are psychological mechanisms that individuals use to protect themselves from unpleasant emotions or thoughts. These defenses are classified into four levels, each with its own set of defense mechanisms. The first level, psychotic defenses, is considered pathological as it distorts reality to avoid dealing with it. The second level, immature defenses, includes projection, acting out, and projective identification. The third level, neurotic defenses, has short-term benefits but can lead to problems in the long run. These defenses include repression, rationalization, and regression. The fourth and most advanced level, mature defenses, includes altruism, sublimation, and humor.
Despite the usefulness of understanding ego defenses, their classification and definitions can be inconsistent and frustrating to learn for exams. It is important to note that these defenses are not necessarily good or bad, but rather a natural part of human behavior. By recognizing and understanding our own ego defenses, we can better manage our emotions and thoughts in a healthy way.
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This question is part of the following fields:
- Psychiatry
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Question 5
Incorrect
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A 47-year-old man is seen in the emergency department by an emergency doctor and a medical student. The patient is HIV positive. The doctor tells the patient that his chest x-ray and blood results show that he has aspergillosis. He prescribes a course of amphotericin
The emergency doctor then asks you to explain the medication to the patient and answer any questions they may have.
Which one of the following pieces of information must you tell the patient?Your Answer: Amphotericin can cause hyperkalaemia
Correct Answer: Amphotericin is a nephrotoxic drug
Explanation:Amphotericin is known to cause nephrotoxicity, which is an adverse effect. Additionally, hypokalaemia, hypomagnesaemia, and flu-like symptoms are other potential adverse effects. It should be noted that among antifungal agents, azoles are known to be toxic to the liver, while amphotericin is specifically associated with nephrotoxicity.
Antifungal agents are drugs used to treat fungal infections. There are several types of antifungal agents, each with a unique mechanism of action and potential adverse effects. Azoles work by inhibiting 14α-demethylase, an enzyme that produces ergosterol, a component of fungal cell membranes. However, they can also inhibit the P450 system in the liver, leading to potential liver toxicity. Amphotericin B binds with ergosterol to form a transmembrane channel that causes leakage of monovalent ions, but it can also cause nephrotoxicity and flu-like symptoms. Terbinafine inhibits squalene epoxidase, while griseofulvin interacts with microtubules to disrupt mitotic spindle. However, griseofulvin can induce the P450 system and is teratogenic. Flucytosine is converted by cytosine deaminase to 5-fluorouracil, which inhibits thymidylate synthase and disrupts fungal protein synthesis, but it can cause vomiting. Caspofungin inhibits the synthesis of beta-glucan, a major fungal cell wall component, and can cause flushing. Nystatin binds with ergosterol to form a transmembrane channel that causes leakage of monovalent ions, but it is very toxic and can only be used topically, such as for oral thrush.
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This question is part of the following fields:
- General Principles
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Question 6
Incorrect
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A 70-year-old man presents to his GP complaining of a severe throbbing headache on one side of his head. He reports that it started two weeks ago and has now progressed to affect his vision. Additionally, he experiences discomfort in his jaw while chewing, which has made it difficult for him to eat. The patient has a medical history of hypertension and is currently taking ramipril.
During the examination, the GP notes a tender temporal artery that is palpable. Fundoscopy reveals a swollen pale optic disc with blurred margins.
Which artery is responsible for the patient's visual symptoms?Your Answer: Central retinal artery
Correct Answer: Posterior ciliary artery
Explanation:The correct answer is posterior ciliary artery. When a patient presents with temporal arteritis, they may experience a headache, jaw claudication, and visual symptoms that can progress to anterior ischemic optic neuropathy. This occurs due to occlusion of the posterior ciliary artery, which is a branch of the ophthalmic artery. When this artery is blocked, it can result in retinal ischemia and necrosis, leading to visual loss.
The answer of anterior ciliary artery is incorrect because it does not have a direct supply to the retina. Instead, it supplies the conjunctiva, sclera, and rectus muscles. Therefore, it would not show a pale swollen optic disc on fundoscopy, which suggests retinal ischemia.
Central retinal artery is also an incorrect answer because it is not typically affected in temporal arteritis. When this artery is occluded, it results in a cherry red spot on fundoscopy without associated mastication symptoms.
Finally, the lacrimal artery is an incorrect answer because it supplies the lacrimal gland, conjunctiva, and eyelids, but not the retina. Therefore, it would not show a pale optic disc on fundoscopy.
Temporal arteritis is a type of large vessel vasculitis that often occurs in patients over the age of 60 and is commonly associated with polymyalgia rheumatica. This condition is characterized by changes in the affected artery that skip certain sections while damaging others. Symptoms of temporal arteritis include headache, jaw claudication, and visual disturbances, with anterior ischemic optic neuropathy being the most common ocular complication. A tender, palpable temporal artery is also often present, and around 50% of patients may experience symptoms of PMR, such as muscle aches and morning stiffness.
To diagnose temporal arteritis, doctors will typically look for elevated inflammatory markers, such as an ESR greater than 50 mm/hr or elevated CRP levels. A temporal artery biopsy may also be performed to confirm the diagnosis, with skip lesions often being present. Treatment for temporal arteritis involves urgent high-dose glucocorticoids, which should be given as soon as the diagnosis is suspected and before the temporal artery biopsy. If there is no visual loss, high-dose prednisolone is typically used, while IV methylprednisolone is usually given if there is evolving visual loss. Patients with visual symptoms should be seen by an ophthalmologist on the same day, as visual damage is often irreversible. Other treatments may include bone protection with bisphosphonates and low-dose aspirin, although the evidence supporting the latter is weak.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 7
Incorrect
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Which of the following poses the most significant threat to the external validity of a research?
Your Answer: Experimental mortality
Correct Answer: Representativeness of the sample
Explanation:Validity refers to how accurately something measures what it claims to measure. There are two main types of validity: internal and external. Internal validity refers to the confidence we have in the cause and effect relationship in a study. This means we are confident that the independent variable caused the observed change in the dependent variable, rather than other factors. There are several threats to internal validity, such as poor control of extraneous variables and loss of participants over time. External validity refers to the degree to which the conclusions of a study can be applied to other people, places, and times. Threats to external validity include the representativeness of the sample and the artificiality of the research setting. There are also other types of validity, such as face validity and content validity, which refer to the general impression and full content of a test, respectively. Criterion validity compares tests, while construct validity measures the extent to which a test measures the construct it aims to.
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This question is part of the following fields:
- General Principles
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Question 8
Correct
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Emergency medical services are summoned to attend to a 44-year-old motorcyclist who collided with a vehicle. The patient is alert but has sustained a fracture to the shaft of his right humerus. He is experiencing difficulty with extending his wrist and elbow. Which nerve is most likely to have been affected?
Your Answer: Radial
Explanation:The radial nerve is the most probable nerve to have been affected.
Understanding the anatomical pathway of the major nerves in the upper limb is crucial. The radial nerve originates from the axilla, travels down the arm through the radial groove of the humerus, and then moves anteriorly to the lateral epicondyle in the forearm. It primarily supplies motor innervation to the posterior compartments of the arm and forearm, which are responsible for extension.
The radial nerve is commonly damaged due to mid-humeral shaft fractures, shoulder dislocation, and lateral elbow injuries.
The Radial Nerve: Anatomy, Innervation, and Patterns of Damage
The radial nerve is a continuation of the posterior cord of the brachial plexus, with root values ranging from C5 to T1. It travels through the axilla, posterior to the axillary artery, and enters the arm between the brachial artery and the long head of triceps. From there, it spirals around the posterior surface of the humerus in the groove for the radial nerve before piercing the intermuscular septum and descending in front of the lateral epicondyle. At the lateral epicondyle, it divides into a superficial and deep terminal branch, with the deep branch crossing the supinator to become the posterior interosseous nerve.
The radial nerve innervates several muscles, including triceps, anconeus, brachioradialis, and extensor carpi radialis. The posterior interosseous branch innervates supinator, extensor carpi ulnaris, extensor digitorum, and other muscles. Denervation of these muscles can lead to weakness or paralysis, with effects ranging from minor effects on shoulder stability to loss of elbow extension and weakening of supination of prone hand and elbow flexion in mid prone position.
Damage to the radial nerve can result in wrist drop and sensory loss to a small area between the dorsal aspect of the 1st and 2nd metacarpals. Axillary damage can also cause paralysis of triceps. Understanding the anatomy, innervation, and patterns of damage of the radial nerve is important for diagnosing and treating conditions that affect this nerve.
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This question is part of the following fields:
- Neurological System
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Question 9
Incorrect
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A 29-year-old female patient complains of dysuria and frequent urination for the past 3 days. She denies experiencing any vaginal discharge or heavy menstrual bleeding. Upon urine dipstick examination, leukocytes and nitrites are detected. A urine culture reveals the presence of a urease-producing bacteria identified as Proteus mirabilis. The patient is prescribed antibiotics for treatment.
What type of renal stones are patients at risk for developing with chronic and recurrent infections caused by this bacteria?Your Answer: Uric acid
Correct Answer: Ammonium magnesium phosphate (struvite)
Explanation:The formation of kidney stones is a common condition that involves the accumulation of mineral deposits in the kidneys. This condition is influenced by various risk factors such as low urine volume, dry weather conditions, and acidic pH levels. It is also closely linked to hyperuricemia, which is commonly associated with gout, as well as diseases that involve high cell turnover, such as leukemia.
Renal stones can be classified into different types based on their composition. Calcium oxalate stones are the most common, accounting for 85% of all calculi. These stones are formed due to hypercalciuria, hyperoxaluria, and hypocitraturia. They are radio-opaque and may also bind with uric acid stones. Cystine stones are rare and occur due to an inherited recessive disorder of transmembrane cystine transport. Uric acid stones are formed due to purine metabolism and may precipitate when urinary pH is low. Calcium phosphate stones are associated with renal tubular acidosis and high urinary pH. Struvite stones are formed from magnesium, ammonium, and phosphate and are associated with chronic infections. The pH of urine can help determine the type of stone present, with calcium phosphate stones forming in normal to alkaline urine, uric acid stones forming in acidic urine, and struvate stones forming in alkaline urine. Cystine stones form in normal urine pH.
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This question is part of the following fields:
- Renal System
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Question 10
Correct
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An 78-year-old man with a history of hypertension, ischaemic heart disease and peripheral vascular disease presents with palpitations and syncope. His ECG reveals an irregularly irregular pulse of 124 beats/min. What factor in his medical history will be given the most consideration when deciding whether or not to administer anticoagulation?
Your Answer: Age
Explanation:To determine the need for anticoagulation in patients with atrial fibrillation, it is necessary to conduct a CHA2DS2-VASc score assessment. This involves considering various factors, including age (which is weighted heaviest, with 2 points given for those aged 75 and over), hypertension (1 point), and congestive heart disease (1 point). Palpitations, however, are not included in the CHA2DS2-VASc tool.
Atrial fibrillation (AF) is a condition that requires careful management, including the use of anticoagulation therapy. The latest guidelines from NICE recommend assessing the need for anticoagulation in all patients with a history of AF, regardless of whether they are currently experiencing symptoms. The CHA2DS2-VASc scoring system is used to determine the most appropriate anticoagulation strategy, with a score of 2 or more indicating the need for anticoagulation. However, it is important to ensure a transthoracic echocardiogram has been done to exclude valvular heart disease, which is an absolute indication for anticoagulation.
When considering anticoagulation therapy, doctors must also assess the patient’s bleeding risk. NICE recommends using the ORBIT scoring system to formalize this risk assessment, taking into account factors such as haemoglobin levels, age, bleeding history, renal impairment, and treatment with antiplatelet agents. While there are no formal rules on how to act on the ORBIT score, individual patient factors should be considered. The risk of bleeding increases with a higher ORBIT score, with a score of 4-7 indicating a high risk of bleeding.
For many years, warfarin was the anticoagulant of choice for AF. However, the development of direct oral anticoagulants (DOACs) has changed this. DOACs have the advantage of not requiring regular blood tests to check the INR and are now recommended as the first-line anticoagulant for patients with AF. The recommended DOACs for reducing stroke risk in AF are apixaban, dabigatran, edoxaban, and rivaroxaban. Warfarin is now used second-line, in patients where a DOAC is contraindicated or not tolerated. Aspirin is not recommended for reducing stroke risk in patients with AF.
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This question is part of the following fields:
- Cardiovascular System
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Question 11
Correct
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As the pregnancy progresses, at what stage does the foetus typically begin producing surfactant?
A mother has been informed that she will have to deliver her baby prematurely due to complications in the pregnancy. To decrease the chances of neonatal distress syndrome, doctors have administered steroids to stimulate surfactant production in the foetus. They clarify that the foetus is already generating its own surfactant, and these steroids will enhance the process.Your Answer: Week 22
Explanation:Lung development in humans begins at week 4 with the formation of the respiratory diverticulum. By week 10, the lungs start to grow as tertiary bronchial buds form. Terminal bronchioles begin to form around week 18. The saccular stage of lung development, which marks the earliest viability for a human fetus, occurs at around 22-24 weeks when type 2 alveolar cells start producing surfactant. By week 30, the primary alveoli form as the mesenchyme surrounding the lungs becomes highly vascular.
The Importance of Pulmonary Surfactant in Breathing
Pulmonary surfactant is a substance composed of phospholipids, carbohydrates, and proteins that is released by type 2 pneumocytes. Its main component, dipalmitoyl phosphatidylcholine (DPPC), plays a crucial role in reducing alveolar surface tension. This substance is first detectable around 28 weeks and increases in concentration as the alveoli decrease in size. This helps prevent the alveoli from collapsing and reduces the muscular force needed to expand the lungs, ultimately decreasing the work of breathing. Additionally, pulmonary surfactant lowers the elastic recoil at low lung volumes, preventing the alveoli from collapsing at the end of each expiration. Overall, pulmonary surfactant is essential in maintaining proper lung function and preventing respiratory distress.
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This question is part of the following fields:
- Respiratory System
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Question 12
Incorrect
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Lila, a 7-year-old girl, undergoes surgery to correct an inguinal hernia. During the operation, how can the surgeon confirm that Lila has an indirect hernia?
Your Answer: Indirect hernia is anterior to the epigastric vessels
Correct Answer: Indirect hernia is lateral to the epigastric vessels
Explanation:An indirect inguinal hernia is situated on the lateral side of the epigastric vessels. This type of hernia occurs when the processus vaginalis fails to close properly, causing a protrusion through the deep inguinal ring and into the inguinal canal. In males, the hernia may extend into the scrotum, while in females, it may extend into the labia. On the other hand, a direct inguinal hernia is caused by weakened abdominal muscles, typically occurring in older individuals. The protrusion enters the inguinal canal through the posterior wall, which is located on the medial side of the epigastric vessels. It may then exit through the superficial inguinal ring.
Understanding Inguinal Hernias
Inguinal hernias are the most common type of abdominal wall hernias, with 75% of cases falling under this category. They are more prevalent in men, with a 25% lifetime risk of developing one. The main symptom is a lump in the groin area, which disappears when pressure is applied or when the patient lies down. Discomfort and aching are also common, especially during physical activity. However, severe pain is rare, and strangulation is even rarer.
The traditional classification of inguinal hernias into indirect and direct types is no longer relevant in clinical management. Instead, the current consensus is to treat medically fit patients, even if they are asymptomatic. A hernia truss may be an option for those who are not fit for surgery, but it has limited use in other patients. Mesh repair is the preferred method, as it has the lowest recurrence rate. Unilateral hernias are usually repaired through an open approach, while bilateral and recurrent hernias are repaired laparoscopically.
After surgery, patients are advised to return to non-manual work after 2-3 weeks for open repair and 1-2 weeks for laparoscopic repair. Complications may include early bruising and wound infection, as well as late chronic pain and recurrence. It is important to seek medical attention if any of these symptoms occur.
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This question is part of the following fields:
- Gastrointestinal System
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Question 13
Correct
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Evelyn is a 92-year-old woman who arrives at the hospital with severe chest pain, shortness of breath, and palpitations. Given her medical history of angina and diabetes mellitus, doctors suspect acute coronary syndrome. They order several tests, including a troponin I blood test. What is the function of this biomarker in the body?
Your Answer: Binds to actin to hold the troponin-tropomyosin complex in place
Explanation:Troponin I plays a crucial role in muscle contraction by binding to actin and holding the troponin-tropomyosin complex in place. This prevents the myosin-binding site on the actin from being exposed, thereby preventing muscle contraction. Troponin I is also used as a marker for myocardial muscle injury.
Unlike troponin C, troponin I does not bind to calcium. Instead, troponin C has several calcium-binding sites that, when occupied, cause a conformational change in the troponin-tropomyosin complex. This change exposes the myosin-binding site on the actin filament, allowing myosin to bind and initiate muscle contraction.
Although troponin I binds to actin, it does not perform the power stroke that shortens muscle fibers. This is the role of the myosin head, which uses energy from ATP.
It is troponin T, not troponin I, that binds with tropomyosin to form the troponin-tropomyosin complex. This complex allows tropomyosin to move in response to the conformational change induced by calcium binding to troponin C.
Finally, it is tropomyosin, not troponin I, that directly inhibits myosin-binding sites. Tropomyosin is a long fiber that runs along the side of actin filaments, blocking all myosin binding sites. When calcium concentrations within the cell increase, the conformational change in troponin moves tropomyosin, exposing these sites and allowing muscle contraction to occur.
Understanding Troponin: The Proteins Involved in Muscle Contraction
Troponin is a group of three proteins that play a crucial role in the contraction of skeletal and cardiac muscles. These proteins work together to regulate the interaction between actin and myosin, which is essential for muscle contraction. The three subunits of troponin are troponin C, troponin T, and troponin I.
Troponin C is responsible for binding to calcium ions, which triggers the contraction of muscle fibers. Troponin T binds to tropomyosin, forming a complex that helps regulate the interaction between actin and myosin. Finally, troponin I binds to actin, holding the troponin-tropomyosin complex in place and preventing muscle contraction when it is not needed.
Understanding the role of troponin is essential for understanding how muscles work and how they can be affected by various diseases and conditions. By regulating the interaction between actin and myosin, troponin plays a critical role in muscle contraction and is a key target for drugs used to treat conditions such as heart failure and skeletal muscle disorders.
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This question is part of the following fields:
- Cardiovascular System
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Question 14
Incorrect
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A 55-year-old man is hospitalized after experiencing haematemesis. Upon examination, his prothrombin time is found to be elevated. What could be a possible reason for this anomaly?
Your Answer: Aspirin therapy
Correct Answer: Chronic liver disease
Explanation:The inheritance of Haemophilia A and B is crucial in identifying individuals who are at risk of developing the condition. Haemophilia A and B are genetic disorders that are inherited in an X-linked recessive manner. Haemophilia A is caused by a deficiency in clotting factor VIII, while haemophilia B is caused by a deficiency in clotting factor IX.
On the other hand, haemophilia C, which is caused by a deficiency in clotting factor XI, is primarily inherited in an autosomal recessive manner. In X-linked recessive conditions like haemophilia B, males are more likely to be affected than females. This is because males only need one abnormal copy of the gene, which is carried on the X chromosome, to be affected.
Females, on the other hand, can be carriers of the condition if they carry one normal and one abnormal copy of the gene. While carriers can have clotting abnormalities, these are usually milder than those seen in affected individuals. Men cannot pass the condition to their sons, but they will pass on the abnormal X chromosome to all their daughters, who will be carriers.
Female carriers can pass on the condition to around half their sons, and half their daughters will be carriers. Females can only be affected if they are the offspring of an affected male and a carrier female. In summary, the inheritance of haemophilia A and B is crucial in identifying individuals who are at risk of developing the condition. It also helps in providing appropriate genetic counseling and management for affected individuals and their families.
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This question is part of the following fields:
- Haematology And Oncology
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Question 15
Incorrect
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A father brings his 14-year-old son into the Emergency Department, who he witnessed having a 'fit' 30 minutes ago. This occurred as his son was getting up from his chair. The father noticed some shaking of his son's arms, lasting approximately 10 minutes.
His son has been very stressed with school projects over the past week, staying up late and often missing meals. His son's past medical and developmental history is non-significant.
On examination, the son is alert and responsive.
What are the associated factors with this condition?Your Answer: Incontinence is common
Correct Answer: Short postictal period
Explanation:The recovery from syncopal episodes is rapid and the postictal period is short. In contrast, seizures have a much longer postictal period. The stem suggests that the syncope may be due to exam stress and poor nutrition habits. One way to differentiate between seizures and syncope is by the length of the postictal period, with syncope having a quick recovery. Lip smacking is not associated with syncope, but rather with focal seizures of the temporal lobe. The 10-minute postictal period described in the stem is not consistent with a seizure.
Epilepsy is a neurological condition that causes recurrent seizures. In the UK, around 500,000 people have epilepsy, and two-thirds of them can control their seizures with antiepileptic medication. While epilepsy usually occurs in isolation, certain conditions like cerebral palsy, tuberous sclerosis, and mitochondrial diseases have an association with epilepsy. It’s important to note that seizures can also occur due to other reasons like infection, trauma, or metabolic disturbance.
Seizures can be classified into focal seizures, which start in a specific area of the brain, and generalised seizures, which involve networks on both sides of the brain. Patients who have had generalised seizures may experience biting their tongue or incontinence of urine. Following a seizure, patients typically have a postictal phase where they feel drowsy and tired for around 15 minutes.
Patients who have had their first seizure generally undergo an electroencephalogram (EEG) and neuroimaging (usually a MRI). Most neurologists start antiepileptics following a second epileptic seizure. Antiepileptics are one of the few drugs where it is recommended that we prescribe by brand, rather than generically, due to the risk of slightly different bioavailability resulting in a lowered seizure threshold.
Patients who drive, take other medications, wish to get pregnant, or take contraception need to consider the possible interactions of the antiepileptic medication. Some commonly used antiepileptics include sodium valproate, carbamazepine, lamotrigine, and phenytoin. In case of a seizure that doesn’t terminate after 5-10 minutes, medication like benzodiazepines may be administered to terminate the seizure. If a patient continues to fit despite such measures, they are said to have status epilepticus, which is a medical emergency requiring hospital treatment.
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This question is part of the following fields:
- Neurological System
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Question 16
Correct
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A 58-year-old woman visits her primary care physician for a routine check-up. She has a medical history of type 2 diabetes mellitus, hypertension, atrial fibrillation, and osteoarthritis. During the appointment, the doctor inquires about her management of these conditions and evaluates her adherence to prescribed medications. Towards the end of the consultation, the physician invites the patient to participate in a randomized study comparing the efficacy of a new anticoagulant with the current one in preventing stroke in patients with atrial fibrillation. The patient consents and is assigned to the treatment group. After one year, the trial results reveal that 165 out of 1050 individuals on the current treatment experienced a stroke, while 132 out of 1044 individuals on the new anticoagulant had a stroke during the study period. Using this information, what is the number of patients that need to be treated to prevent one stroke case?
Your Answer: 33
Explanation:To determine the number needed to treat (NNT) for preventing one case of stroke, the absolute risk reduction (ARR) must first be calculated. This involves subtracting the risk of stroke in the group receiving the new anticoagulant from the risk in the group receiving the current treatment. For example, if the risk of stroke in the new anticoagulant group is 165 out of 1050 patients and the risk in the current treatment group is 132 out of 1044 patients, the ARR would be 0.0307. The NNT can then be calculated by taking the reciprocal of the ARR, which in this case would be 33. This means that 33 patients would need to be treated with the new anticoagulant drug to prevent one case of stroke.
Numbers needed to treat (NNT) is a measure that determines how many patients need to receive a particular intervention to reduce the expected number of outcomes by one. To calculate NNT, you divide 1 by the absolute risk reduction (ARR) and round up to the nearest whole number. ARR can be calculated by finding the absolute difference between the control event rate (CER) and the experimental event rate (EER). There are two ways to calculate ARR, depending on whether the outcome of the study is desirable or undesirable. If the outcome is undesirable, then ARR equals CER minus EER. If the outcome is desirable, then ARR is equal to EER minus CER. It is important to note that ARR may also be referred to as absolute benefit increase.
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This question is part of the following fields:
- General Principles
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Question 17
Incorrect
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Eve, a 67-year-old female, is undergoing endovascular surgery to repair an abdominal aortic aneurysm. The surgeon places the stent in the aorta and common iliac arteries, as the aneurysm is located just above the aortic bifurcation. What is the level of the bifurcation?
Your Answer: S2
Correct Answer: L4
Explanation:The point at which the aorta divides into the common iliac arteries is located at the level of the fourth lumbar vertebrae (L4). The renal arteries originate at the level of the second lumbar vertebrae (L2), while the inferior mesenteric artery originates at the level of the third lumbar vertebrae (L3). The posterior superior iliac spines are located at the level of the second sacral vertebrae (S2).
Anatomical Planes and Levels in the Human Body
The human body can be divided into different planes and levels to aid in anatomical study and medical procedures. One such plane is the transpyloric plane, which runs horizontally through the body of L1 and intersects with various organs such as the pylorus of the stomach, left kidney hilum, and duodenojejunal flexure. Another way to identify planes is by using common level landmarks, such as the inferior mesenteric artery at L3 or the formation of the IVC at L5.
In addition to planes and levels, there are also diaphragm apertures located at specific levels in the body. These include the vena cava at T8, the esophagus at T10, and the aortic hiatus at T12. By understanding these planes, levels, and apertures, medical professionals can better navigate the human body during procedures and accurately diagnose and treat various conditions.
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This question is part of the following fields:
- Neurological System
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Question 18
Correct
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A 78-year-old woman has recently been diagnosed with heart failure following 10 months of progressive breathlessness and swelling in her ankles. She has been prescribed several medications and provided with lifestyle recommendations. What are the two types of infections that she is most susceptible to due to her recent diagnosis?
Your Answer: Chest infections and ulcerated cellulitic legs
Explanation:As a result of the volume overload caused by heart failure, she will have a higher susceptibility to chest infections due to pulmonary edema and leg infections due to peripheral edema.
Chronic heart failure can be managed through drug treatment, according to updated guidelines issued by NICE in 2018. While loop diuretics are useful in managing fluid overload, they do not reduce mortality in the long term. The first-line treatment for all patients is a combination of an ACE-inhibitor and a beta-blocker, with clinical judgement used to determine which one to start first. Aldosterone antagonists are recommended as second-line treatment, but potassium levels should be monitored as both ACE inhibitors and aldosterone antagonists can cause hyperkalaemia. Third-line treatment should be initiated by a specialist and may include ivabradine, sacubitril-valsartan, hydralazine in combination with nitrate, digoxin, and cardiac resynchronisation therapy. Other treatments include annual influenzae and one-off pneumococcal vaccines. Those with asplenia, splenic dysfunction, or chronic kidney disease may require a booster every 5 years.
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This question is part of the following fields:
- Cardiovascular System
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Question 19
Incorrect
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A 14-year-old arrives at the Emergency Department complaining of abdominal pains, nausea, and vomiting. Upon conducting blood tests, the following results are obtained:
- Glucose: 24 mmol/L (4.0-11.0)
- Ketones: 4.6 mmol/L (<0.6)
- Na+: 138 mmol/L (135 - 145)
- K+: 4.7 mmol/L (3.5 - 5.0)
Based on these findings, the patient is started on a fixed insulin regimen and given intravenous fluids. After repeating the blood tests, it is observed that the K+ level has dropped to 3.3 mmol/L (3.5 - 5.0). What mechanism is responsible for this effect caused by insulin?Your Answer: Inhibition of the ATP-sensitive K+ channel
Correct Answer: Stimulation of the Na+/K+ ATPase pump
Explanation:Insulin is a hormone produced by the pancreas that plays a crucial role in regulating the metabolism of carbohydrates and fats in the body. It works by causing cells in the liver, muscles, and fat tissue to absorb glucose from the bloodstream, which is then stored as glycogen in the liver and muscles or as triglycerides in fat cells. The human insulin protein is made up of 51 amino acids and is a dimer of an A-chain and a B-chain linked together by disulfide bonds. Pro-insulin is first formed in the rough endoplasmic reticulum of pancreatic beta cells and then cleaved to form insulin and C-peptide. Insulin is stored in secretory granules and released in response to high levels of glucose in the blood. In addition to its role in glucose metabolism, insulin also inhibits lipolysis, reduces muscle protein loss, and increases cellular uptake of potassium through stimulation of the Na+/K+ ATPase pump.
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This question is part of the following fields:
- Endocrine System
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Question 20
Incorrect
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A 60-year-old man visits his GP with worries about his hearing in recent months. He has difficulty understanding conversations in noisy environments and his spouse has commented on his need for the television to be turned up to maximum volume.
During the examination, the GP conducts some basic tests and finds:
Rinne's Test - Air conduction > bone conduction in both ears
Weber's Test - Lateralises to the left ear
What can be inferred from these test results?Your Answer: Right sensorineural hearing loss
Correct Answer: Left sensorineural hearing loss
Explanation:The patient has left sensorineural hearing loss, as indicated by the normal Rinne result (air conduction > bone conduction bilaterally) and abnormal Weber result (lateralising to the unaffected ear). In contrast, if the patient had conductive hearing loss, Rinne’s test would show bone conduction > air conduction, and Weber’s test would localise to the worse ear in bilateral conductive hearing loss or the affected ear in unilateral conductive hearing loss. For right sensorineural hearing loss, Rinne’s test would be normal, but Weber’s test would localise to the left ear.
Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness
Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.
Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.
The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.
Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.
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This question is part of the following fields:
- Respiratory System
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