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  • Question 1 - A 16-year-old female was admitted to the paediatric unit with a history of...

    Incorrect

    • A 16-year-old female was admitted to the paediatric unit with a history of anorexia nervosa and a body mass index of 16kg/m². Despite being uncooperative initially, she has shown improvement in her willingness to participate with the team. However, she now presents with complaints of abdominal pain and weakness. Upon blood testing, the following results were obtained:

      Hb 125 g/L Male: (135-180) Female: (115 - 160)
      Platelets 180 * 109/L (150 - 400)
      WBC 4.5 * 109/L (4.0 - 11.0)

      Na+ 138 mmol/L (135 - 145)
      K+ 3.2 mmol/L (3.5 - 5.0)
      Bicarbonate 26 mmol/L (22 - 29)
      Urea 5 mmol/L (2.0 - 7.0)
      Creatinine 70 µmol/L (55 - 120)

      Calcium 2.1 mmol/L (2.1-2.6)
      Phosphate 0.5 mmol/L (0.8-1.4)
      Magnesium 0.6 mmol/L (0.7-1.0)

      What is the likely cause of the patient's abnormal blood results?

      Your Answer: Extended period of low calories and vitamins

      Correct Answer: Extended period of low calories then high carbohydrate intake

      Explanation:

      Refeeding syndrome can occur in patients who have experienced prolonged catabolism and then suddenly switch to carbohydrate metabolism. This can lead to a rapid uptake of phosphate, potassium, and magnesium into the cells, caused by spikes in insulin and glucose. Patients with low BMI and poor nutritional intake over a long period of time are at a higher risk. Taking vitamin tablets would not affect blood results, but excessive intake can result in hypervitaminosis. While exogenous insulin could also cause this syndrome, there is no indication that the patient has taken it. To reduce the risk of refeeding syndrome, some patients may be advised to follow initial high-fat, low-carbohydrate diets.

      Understanding Refeeding Syndrome

      Refeeding syndrome is a condition that occurs when a person who has been starved for an extended period suddenly begins to eat again. This metabolic abnormality is caused by the abrupt switch from catabolism to carbohydrate metabolism. The consequences of refeeding syndrome include hypophosphataemia, hypokalaemia, hypomagnesaemia, and abnormal fluid balance, which can lead to organ failure.

      To prevent refeeding syndrome, it is important to identify patients who are at high risk of developing the condition. According to guidelines produced by NICE in 2006, patients are considered high-risk if they have a BMI of less than 16 kg/m2, have experienced unintentional weight loss of more than 15% over 3-6 months, have had little nutritional intake for more than 10 days, or have hypokalaemia, hypophosphataemia, or hypomagnesaemia prior to feeding (unless high).

      If a patient has two or more of the following risk factors, they are also considered high-risk: a BMI of less than 18.5 kg/m2, unintentional weight loss of more than 10% over 3-6 months, little nutritional intake for more than 5 days, or a history of alcohol abuse, drug therapy (including insulin, chemotherapy, diuretics, and antacids).

      To prevent refeeding syndrome, NICE recommends that patients who haven’t eaten for more than 5 days should be re-fed at no more than 50% of their requirements for the first 2 days. By following these guidelines, healthcare professionals can help prevent the potentially life-threatening consequences of refeeding syndrome.

    • This question is part of the following fields:

      • Gastrointestinal System
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  • Question 2 - A 55-year-old man undergoes a total knee replacement for severe osteoarthritis. He is...

    Incorrect

    • A 55-year-old man undergoes a total knee replacement for severe osteoarthritis. He is seen two weeks later for a wound check and it is found that the surgical incision is healing poorly, however it is not painful or inflamed. He has been feeling generally unwell and has had some bleeding from his gums.

      What could be the possible reason for his symptoms?

      Your Answer:

      Correct Answer: Defective collagen synthesis

      Explanation:

      Vitamin C plays a crucial role as a cofactor for enzymes involved in the synthesis of collagen. A man displaying symptoms of poor wound healing, capillary fragility resulting in bleeding gums, and general malaise is likely suffering from a deficiency of this vitamin. In contrast, a deficiency of vitamin B12 would cause macrocytic, megaloblastic anemia and peripheral neuropathy, while a deficiency of vitamin A would lead to night blindness. Although infection can also impair wound healing and cause malaise, there is no evidence of inflammation at the wound site, and it does not explain the bleeding gums.

      Vitamin C: A Water Soluble Vitamin with Essential Functions

      Vitamin C, also known as ascorbic acid, is a water soluble vitamin that plays a crucial role in various bodily functions. One of its primary functions is acting as an antioxidant, which helps protect cells from damage caused by free radicals. Additionally, vitamin C is essential for collagen synthesis, as it acts as a cofactor for enzymes required for the hydroxylation of proline and lysine in the synthesis of collagen. This vitamin also facilitates iron absorption and serves as a cofactor for norepinephrine synthesis.

      However, a deficiency in vitamin C, also known as scurvy, can lead to defective collagen synthesis, resulting in capillary fragility and poor wound healing. Some of the features of vitamin C deficiency include gingivitis, loose teeth, poor wound healing, bleeding from gums, haematuria, epistaxis, and general malaise. Therefore, it is important to ensure adequate intake of vitamin C through a balanced diet or supplements to maintain optimal health.

    • This question is part of the following fields:

      • General Principles
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  • Question 3 - A pharmaceutical representative visits your clinic and informs you about a new medication...

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    • A pharmaceutical representative visits your clinic and informs you about a new medication that is currently undergoing a trial to determine its appropriate dosage and potential side effects. What categories of patients would you recommend for the trial, and at which stage of the trial is the drug currently in?

      Your Answer:

      Correct Answer: Healthy participants, Phase 1

      Explanation:

      Experimental drugs must pass through several phases of testing before they can be approved for use. Phase 0 trials involve microdosing and are used to speed up drug development by testing how the drug behaves in humans. However, no therapeutic effect or safety and efficacy data can be measured from these trials. Phase 2 trials, on the other hand, aim to determine the best dosage and evaluate the drug’s effectiveness by testing it on patients with the targeted disease.

      Phases of Clinical Trials

      Clinical trials are conducted to determine the safety and efficacy of new treatments or drugs. These trials are commonly classified into four phases. The first phase involves determining the pharmacokinetics and pharmacodynamics of the drug, as well as any potential side effects. This phase is conducted on healthy volunteers.

      The second phase assesses the efficacy and dosage of the drug. It involves a small number of patients affected by a particular disease. This phase may be further subdivided into IIa, which assesses optimal dosing, and IIb, which assesses efficacy.

      The third phase involves assessing the effectiveness of the drug. This phase typically involves a larger number of people, often as part of a randomized controlled trial, comparing the new treatment with established treatments.

      The fourth and final phase is postmarketing surveillance. This phase monitors the long-term effectiveness and side effects of the drug after it has been approved and is on the market.

      Overall, the phases of clinical trials are crucial in determining the safety and efficacy of new treatments and drugs. They provide valuable information that can help improve patient outcomes and advance medical research.

    • This question is part of the following fields:

      • General Principles
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  • Question 4 - A 72-year-old man presents to his GP for a routine check-up and is...

    Incorrect

    • A 72-year-old man presents to his GP for a routine check-up and is found to have a systolic murmur. The murmur is loudest in the aortic region, increases with deep inspiration, and does not radiate. What is the most probable abnormality in this patient?

      Your Answer:

      Correct Answer: Pulmonary stenosis

      Explanation:

      Systolic Valvular Murmurs

      A systolic valvular murmur can be caused by either aortic/pulmonary stenosis or mitral/tricuspid regurgitation. However, the location where the murmur is heard loudest can be misleading. For instance, if it were aortic stenosis, the murmur would typically radiate to the carotids.

      One crucial factor to consider is that the murmur’s intensity can be affected by inspiration or expiration. During inspiration, venous return to the heart increases, exacerbating right-sided murmurs. Conversely, expiration reduces venous return, exacerbating left-sided murmurs. To remember this useful fact, the mnemonic RILE (Right on Inspiration, Left on Expiration) can be used.

      If a systolic murmur is enhanced on inspiration, it must be a right-sided murmur, indicating pulmonary stenosis or tricuspid regurgitation. However, in this case, pulmonary stenosis is the only possible option. systolic valvular murmurs and their characteristics can aid in proper diagnosis and treatment.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 5 - What features are evaluated for grading breast cancer, except for tumor necrosis, according...

    Incorrect

    • What features are evaluated for grading breast cancer, except for tumor necrosis, according to the Bloom-Richardson grading model?

      Your Answer:

      Correct Answer: Tumour necrosis

      Explanation:

      The presence of necrosis in a tumour may indicate that it has become too large for its blood supply, suggesting a high grade tumour. However, when grading breast cancer using the Bloom-Richardson model, nuclear features such as mitoses, coarse chromatin, and pleomorphism are given more weight. The formation of tubular structures is a key indicator of the level of differentiation, with well differentiated tumours showing the presence of tubules.

      Tumour Grading and Differentiation

      Tumours can be classified based on their degree of differentiation, mitotic activity, and other characteristics. The grading system ranges from grade 1, which is the most differentiated, to grade 3 or 4, which is the least. The evaluation is subjective, but generally, high-grade tumours indicate a poor prognosis or rapid growth.

      Glandular epithelium tumours tend to form acinar structures with a central lumen. Well-differentiated tumours exhibit excellent acinar formation, while poorly differentiated tumours appear as clumps of cells around a desmoplastic stroma. Some tumours produce mucous without acinar formation, and these are referred to as mucinous adenocarcinomas. Squamous cell tumours produce structures resembling epithelial cell components, and well-differentiated tumours may also produce keratin, depending on the tissue of origin.

    • This question is part of the following fields:

      • Haematology And Oncology
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  • Question 6 - A woman is advised to start taking folic acid supplements before getting pregnant...

    Incorrect

    • A woman is advised to start taking folic acid supplements before getting pregnant to prevent neural tube defects. At what stage of pregnancy are these defects most likely to occur?

      Your Answer:

      Correct Answer: Week 4

      Explanation:

      The closure of the neural tube takes place in the 4th week of embryonic development. Prior to this, during the first three weeks of pregnancy, the trilaminar disc has not yet formed, making it too early for neural tube closure to occur. The neural tube originates from a specialized part of the ectoderm.

      During the fourth week, the embryo becomes a trilaminar germ disc, marking the beginning of primary neurulation. At this stage, folds develop at the lateral edges of the neural plate, which then rise and fold at hinge points, ultimately meeting and fusing in the midline.

      In the fifth week, secondary neurulation occurs at the caudal end of the embryo. This process is distinct from neural tube closure and involves a rearrangement of cells and canalisation.

      Embryology is the study of the development of an organism from the moment of fertilization to birth. During the first week of embryonic development, the fertilized egg implants itself into the uterine wall. By the second week, the bilaminar disk is formed, consisting of two layers of cells. The primitive streak appears in the third week, marking the beginning of gastrulation and the formation of the notochord.

      As the embryo enters its fourth week, limb buds begin to form, and the neural tube closes. The heart also begins to beat during this time. By week 10, the genitals are differentiated, and the embryo exhibits intermittent breathing movements. These early events in embryonic development are crucial for the formation of the body’s major organs and structures. Understanding the timeline of these events can provide insight into the complex process of human development.

    • This question is part of the following fields:

      • General Principles
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  • Question 7 - A 27-year-old Afro-Caribbean woman visits her GP with concerns about well-defined patches of...

    Incorrect

    • A 27-year-old Afro-Caribbean woman visits her GP with concerns about well-defined patches of significantly lighter skin. At first, this was only on her hands, but she has recently noticed similar patches on her face. She has a medical history of Hashimoto's thyroid disease and takes levothyroxine.

      During the examination, the GP observes well-demarcated areas of hypopigmentation on her hands, arms, and face. Based on the most probable diagnosis, which layer of the epidermis is affected?

      Your Answer:

      Correct Answer: Stratum germinativum

      Explanation:

      The deepest layer of the epidermis is called the stratum germinativum, which is responsible for producing keratinocytes and contains melanocytes. Vitiligo, a condition characterized by depigmented patches, affects this layer by causing the loss of melanocytes.

      The stratum corneum is the topmost layer of the epidermis, consisting of dead cells filled with keratin.

      The stratum granulosum is where keratin production occurs in the epidermis.

      The stratum lucidum is only present in the palms of the hands and soles of the feet.

      The Layers of the Epidermis

      The epidermis is the outermost layer of the skin and is made up of a stratified squamous epithelium with a basal lamina underneath. It can be divided into five layers, each with its own unique characteristics. The first layer is the stratum corneum, which is made up of flat, dead, scale-like cells filled with keratin. These cells are continually shed and replaced with new ones. The second layer, the stratum lucidum, is only present in thick skin and is a clear layer. The third layer, the stratum granulosum, is where cells form links with their neighbors. The fourth layer, the stratum spinosum, is the thickest layer of the epidermis and is where squamous cells begin keratin synthesis. Finally, the fifth layer is the stratum germinativum, which is the basement membrane and is made up of a single layer of columnar epithelial cells. This layer gives rise to keratinocytes and contains melanocytes. Understanding the layers of the epidermis is important for understanding the structure and function of the skin.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
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  • Question 8 - What is the primary means of transportation for vitamin D in the human...

    Incorrect

    • What is the primary means of transportation for vitamin D in the human body?

      Your Answer:

      Correct Answer: In blood, bound to the group specific component

      Explanation:

      The Role of UV Light and Vitamin D in Calcium and Phosphate Regulation

      In order for the body to produce Vitamin D3, UV light at a specific wavelength is required to convert cholesterol in the skin. Vitamin D2 and D3 are then transported in the bloodstream bound to the Vitamin-D Binding Protein and undergo further modifications in the liver and kidney to become the active form, 1,25 (OH)2Vitamin D. This active form plays a crucial role in regulating calcium and phosphate concentrations in the body.

      1,25 (OH)2Vitamin D increases calcium absorption in the duodenum and inhibits the secretion and synthesis of PTH, which helps to maintain calcium concentrations. It also increases phosphate absorption in the jejunum and ileum, which is important for maintaining phosphate concentrations. Additionally, 1,25 (OH)2Vitamin D promotes bone turnover by stimulating both osteoblast and osteoclast activity.

      Overall, the production and activation of Vitamin D through UV light and dietary sources is essential for proper calcium and phosphate regulation in the body.

    • This question is part of the following fields:

      • Basic Sciences
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  • Question 9 - A young athlete preparing for the Olympics decides to train at high altitude....

    Incorrect

    • A young athlete preparing for the Olympics decides to train at high altitude. What are the physiological adaptations that occur during altitude training?

      Your Answer:

      Correct Answer: Vasoconstriction of pulmonary arterioles

      Explanation:

      Physiological Changes during Exercise at Altitude

      Exercising at high altitudes can lead to a number of physiological changes in the body. One of the most significant changes is the vasoconstriction of pulmonary arterioles, which occurs in response to the decrease in PaO2. This can result in an increase in pulmonary artery pressure, leading to pulmonary hypertension and right ventricular hypertrophy if prolonged. Additionally, exercising at altitude can cause an increase in cerebral blood flow, as well as an initial fall in blood volume, which triggers the production of renin and aldosterone.

      Another notable change is the increase in the rate and depth of respiration, which is necessary to compensate for the lower oxygen levels at high altitudes. This increase in respiration also causes the oxygen dissociation curve to shift to the left, resulting in increased oxygen saturation at any given PaO2 value. Furthermore, the kidneys respond to the lower oxygen levels by producing more erythropoietin, which leads to an increase in red blood cell mass.

      Finally, exercising at altitude can cause an increase in arterial pH due to the high respiratory rate, which causes an increase in the excretion of CO2. This results in a respiratory alkalosis, which the kidneys compensate for by retaining H+ ions. Overall, these physiological changes are necessary for the body to adapt to the lower oxygen levels at high altitudes and maintain proper functioning during exercise.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 10 - A 29-year-old man comes to the doctor complaining of a fever that has...

    Incorrect

    • A 29-year-old man comes to the doctor complaining of a fever that has been gradually increasing over the past three days. He has also experienced multiple episodes of diarrhea. He recently returned from a one-month trip to rural villages in India, where he frequently played with stray dogs and helped with farming activities. During his trip, he spent a few days hiking in the forest and swimming in a lake. He mainly drank water from wells. His vital signs are as follows: blood pressure 102/80 mmHg, pulse 50 beats per minute, and temperature 39.6ºC. Blood cultures reveal Salmonella typhi, and he was treated with ciprofloxacin. From which activity could he have contracted the organism?

      Your Answer:

      Correct Answer: Drinking water from wells

      Explanation:

      Typhoid is most commonly transmitted through contaminated food and water, as it is spread via the faecal-oral route. In rural villages where sanitation may be lacking, drinking water from wells can be a major source of transmission.

      Burkholderia pseudomallei is typically associated with soil exposure, which is more commonly found in farming environments than Salmonella typhi.

      Rabies, a virus transmitted through the saliva of infected animals, is a risk for those who come into contact with stray dogs.

      Depending on the species of mosquito, bites can transmit diseases such as malaria or dengue fever, which are both viral haemorrhagic fevers.

      Enteric fever, also known as typhoid or paratyphoid, is caused by Salmonella typhi and Salmonella paratyphi respectively. These bacteria are not normally found in the gut and are transmitted through contaminated food and water or the faecal-oral route. The symptoms of enteric fever include headache, fever, and joint pain, as well as abdominal pain and distension. Constipation is more common in typhoid than diarrhoea, and rose spots may appear on the trunk in 40% of patients with paratyphoid. Possible complications of enteric fever include osteomyelitis, gastrointestinal bleeding or perforation, meningitis, cholecystitis, and chronic carriage. Chronic carriage is more likely in adult females and occurs in 1% of cases.

    • This question is part of the following fields:

      • General Principles
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  • Question 11 - What is the primary mechanism of action of the combined oral contraceptive pill?...

    Incorrect

    • What is the primary mechanism of action of the combined oral contraceptive pill?

      Your Answer:

      Correct Answer: Inhibition of ovulation

      Explanation:

      How does the Combined Oral Contraceptive Pill work?

      The Combined Oral Contraceptive Pill (COC) is a widely used method of contraception in the UK. It works by preventing ovulation, which means that an egg is not released from the ovaries. In addition to this, the COC also thickens the cervical mucus, making it more difficult for sperm to enter the uterus, and thins the endometrial lining, reducing the chance of implantation.

      By combining these three actions, the COC is highly effective at preventing pregnancy. It is important to note that the COC does not protect against sexually transmitted infections (STIs), so additional protection such as condoms should be used if there is a risk of STIs.

    • This question is part of the following fields:

      • Reproductive System
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  • Question 12 - A 50-year-old patient who has a history of three heart attacks in the...

    Incorrect

    • A 50-year-old patient who has a history of three heart attacks in the past five years visits you with a newspaper article in hand. The headline claims that olive oil reduces the risk of heart attacks by 50%. Upon reading the article, you discover that the study was a cohort study involving 15,000 participants, half of whom used olive oil in cooking while the other half used animal fat. What is one disadvantage of conducting a cohort study?

      Your Answer:

      Correct Answer: When the outcome of interest is rare a very large sample size is needed

      Explanation:

      A cohort study involves tracking a group of people over a period of time to investigate whether a specific cause has an impact on the occurrence of a disease. These studies can be costly and time-consuming, but they offer the advantage of being able to examine rare exposure factors and being less prone to recall bias than case-control studies. Additionally, they can determine the incidence or risk of a disease. Typically, the findings are presented as the relative risk of developing the disease due to exposure to the cause.

      There are different types of studies that researchers can use to investigate various phenomena. One of the most rigorous types of study is the randomised controlled trial, where participants are randomly assigned to either an intervention or control group. However, practical or ethical issues may limit the use of this type of study. Another type of study is the cohort study, which is observational and prospective. Researchers select two or more groups based on their exposure to a particular agent and follow them up to see how many develop a disease or other outcome. The usual outcome measure is the relative risk. Examples of cohort studies include the Framingham Heart Study.

      On the other hand, case-control studies are observational and retrospective. Researchers identify patients with a particular condition (cases) and match them with controls. Data is then collected on past exposure to a possible causal agent for the condition. The usual outcome measure is the odds ratio. Case-control studies are inexpensive and produce quick results, making them useful for studying rare conditions. However, they are prone to confounding. Lastly, cross-sectional surveys provide a snapshot of a population and are sometimes called prevalence studies. They provide weak evidence of cause and effect.

    • This question is part of the following fields:

      • General Principles
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  • Question 13 - A 65-year-old man visited his family doctor with a persistent cough that has...

    Incorrect

    • A 65-year-old man visited his family doctor with a persistent cough that has been bothering him for the last six months. He complains of coughing up clear sputum and how it has been affecting his daily life. He has also noticed that he gets short of breath more easily and cannot keep up with his grandchildren. He has a medical history of well-controlled diabetes and dyslipidemia. He attended a smoking cessation program a few months ago, but he finds it challenging to quit smoking after smoking a pack of cigarettes a day for the past 40 years. During the examination, the doctor hears bilateral wheezing with some crackles. The doctor expresses concerns about a possible lung disease due to his long history of smoking and refers him for a pulmonary function test. What is likely to be found during the test?

      Your Answer:

      Correct Answer: The FEV1/FVC ratio is lower than normal as there is a larger decrease in FEV1 than FVC

      Explanation:

      The patient’s prolonged smoking history and current symptoms suggest a diagnosis of chronic bronchitis and possibly emphysema, both of which are obstructive lung diseases. These conditions cause air to become trapped in the lungs, making it difficult to breathe out. Pulmonary function tests typically show a greater decrease in FEV1 than FVC in obstructive lung diseases, resulting in a lower FEV1/FVC ratio (also known as the Tiffeneau-Pinelli index). This is different from restrictive lung diseases, which may sometimes show an increase in the FEV1/FVC ratio due to a larger decrease in FVC than FEV1. Chest X-rays may reveal hyperinflated lungs in patients with obstructive lung diseases. An increase in FEV1 may occur in healthy individuals after exercise training or in patients with conditions like asthma after taking medication. Restrictive lung diseases, such as pneumoconioses, hypersensitivity pneumonitis, and idiopathic pulmonary fibrosis, are typically associated with a decrease in the FEV1/FVC ratio.

      Understanding Pulmonary Function Tests

      Pulmonary function tests are a useful tool in determining whether a respiratory disease is obstructive or restrictive. These tests measure various aspects of lung function, such as forced expiratory volume in one second (FEV1) and forced vital capacity (FVC). By analyzing the results of these tests, doctors can diagnose and monitor conditions such as asthma, COPD, pulmonary fibrosis, and neuromuscular disorders.

      In obstructive lung diseases, such as asthma and COPD, the FEV1 is significantly reduced, while the FVC may be reduced or normal. The FEV1% (FEV1/FVC) is also reduced. On the other hand, in restrictive lung diseases, such as pulmonary fibrosis and asbestosis, the FEV1 is reduced, but the FVC is significantly reduced. The FEV1% (FEV1/FVC) may be normal or increased.

      It is important to note that there are many conditions that can affect lung function, and pulmonary function tests are just one tool in diagnosing and managing respiratory diseases. However, understanding the results of these tests can provide valuable information for both patients and healthcare providers.

    • This question is part of the following fields:

      • Respiratory System
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  • Question 14 - A 67-year-old man is attending the urology clinic and receiving goserelin for his...

    Incorrect

    • A 67-year-old man is attending the urology clinic and receiving goserelin for his metastatic prostate cancer. Can you explain the drug's mechanism of action?

      Your Answer:

      Correct Answer: Overstimulation of GnRH receptors

      Explanation:

      GnRH agonists used in the treatment of prostate cancer can paradoxically lead to lower LH levels in the long term. This is because chronic use of these agonists can result in overstimulation of GnRH receptors, which in turn disrupts endogenous hormonal feedback systems. While initially stimulating the production of LH/FSH and subsequent androgen production, chronic use of GnRH agonists can cause negative feedback to suppress the release of gonadotropins, resulting in a significant decrease in serum testosterone levels. This mechanism can be thought of as switching on to switch off. It is important to note that inhibiting the 5 alpha-reductase enzyme and relaxing prostatic smooth muscle are not mechanisms of action for GnRH agonists, but rather for other medications used in the treatment of prostate conditions.

      Prostate cancer management varies depending on the stage of the disease and the patient’s life expectancy and preferences. For localized prostate cancer (T1/T2), treatment options include active monitoring, watchful waiting, radical prostatectomy, and radiotherapy (external beam and brachytherapy). For localized advanced prostate cancer (T3/T4), options include hormonal therapy, radical prostatectomy, and radiotherapy. Patients may develop proctitis and are at increased risk of bladder, colon, and rectal cancer following radiotherapy for prostate cancer.

      In cases of metastatic prostate cancer, reducing androgen levels is a key aim of treatment. A combination of approaches is often used, including anti-androgen therapy, synthetic GnRH agonist or antagonists, bicalutamide, cyproterone acetate, abiraterone, and bilateral orchidectomy. GnRH agonists, such as Goserelin (Zoladex), initially cause a rise in testosterone levels before falling to castration levels. To prevent a rise in testosterone, anti-androgens are often used to cover the initial therapy. GnRH antagonists, such as degarelix, are being evaluated to suppress testosterone while avoiding the flare phenomenon. Chemotherapy with docetaxel is also an option for the treatment of hormone-relapsed metastatic prostate cancer in patients who have no or mild symptoms after androgen deprivation therapy has failed, and before chemotherapy is indicated.

    • This question is part of the following fields:

      • Renal System
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  • Question 15 - A 65-year-old man is undergoing assessment for polycythemia and has no history of...

    Incorrect

    • A 65-year-old man is undergoing assessment for polycythemia and has no history of smoking. What type of solid-organ cancer could be a possible cause?

      Your Answer:

      Correct Answer: Renal cell carcinoma

      Explanation:

      Renal cell carcinoma has the potential to secrete various hormones such as erythropoietin, PTHrP, renin, or ACTH. This can lead to secondary polycythemia, hypercalcemia, or other related conditions. On the other hand, small cell lung cancer can cause ectopic secretion of ACTH or ADH, but not erythropoietin. Pituitary tumors, on the other hand, may secrete prolactin.

      Renal cell cancer, also known as hypernephroma, is a primary renal neoplasm that accounts for 85% of cases. It originates from the proximal renal tubular epithelium and is commonly associated with smoking and conditions such as von Hippel-Lindau syndrome and tuberous sclerosis. The clear cell subtype is the most prevalent, comprising 75-85% of tumors.

      Renal cell cancer is more common in middle-aged men and may present with classical symptoms such as haematuria, loin pain, and an abdominal mass. Other features include endocrine effects, such as the secretion of erythropoietin, parathyroid hormone-related protein, renin, and ACTH. Metastases are present in 25% of cases at presentation, and paraneoplastic syndromes such as Stauffer syndrome may also occur.

      The T category criteria for renal cell cancer are based on tumor size and extent of invasion. Management options include partial or total nephrectomy, depending on the tumor size and extent of disease. Patients with a T1 tumor are typically offered a partial nephrectomy, while alpha-interferon and interleukin-2 may be used to reduce tumor size and treat metastases. Receptor tyrosine kinase inhibitors such as sorafenib and sunitinib have shown superior efficacy compared to interferon-alpha.

      In summary, renal cell cancer is a common primary renal neoplasm that is associated with various risk factors and may present with classical symptoms and endocrine effects. Management options depend on the extent of disease and may include surgery and targeted therapies.

    • This question is part of the following fields:

      • Renal System
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  • Question 16 - A 50-year-old patient presents for a routine checkup. During a neurological assessment, it...

    Incorrect

    • A 50-year-old patient presents for a routine checkup. During a neurological assessment, it is discovered that the patient has sensory loss in their middle finger. Which specific dermatome is responsible for this sensory loss?

      Your Answer:

      Correct Answer: C7

      Explanation:

      The middle finger is where the C7 dermatome is located.

      Understanding Dermatomes: Major Landmarks and Mnemonics

      Dermatomes are areas of skin that are innervated by a single spinal nerve. Understanding dermatomes is important in diagnosing and treating various neurological conditions. The major dermatome landmarks are listed in the table above, along with helpful mnemonics to aid in memorization.

      Starting at the top of the body, the C2 dermatome covers the posterior half of the skull, resembling a cap. Moving down to C3, it covers the area of a high turtleneck shirt, while C4 covers the area of a low-collar shirt. The C5 dermatome runs along the ventral axial line of the upper limb, while C6 covers the thumb and index finger. To remember this, make a 6 with your left hand by touching the tip of your thumb and index finger together.

      Moving down to the middle finger and palm of the hand, the C7 dermatome is located here, while the C8 dermatome covers the ring and little finger. The T4 dermatome is located at the nipples, while T5 covers the inframammary fold. The T6 dermatome is located at the xiphoid process, and T10 covers the umbilicus. To remember this, think of BellybuT-TEN.

      The L1 dermatome covers the inguinal ligament, while L4 covers the knee caps. To remember this, think of being Down on aLL fours with the number 4 representing the knee caps. The L5 dermatome covers the big toe and dorsum of the foot (except the lateral aspect), while the S1 dermatome covers the lateral foot and small toe. To remember this, think of S1 as the smallest one. Finally, the S2 and S3 dermatomes cover the genitalia.

      Understanding dermatomes and their landmarks can aid in diagnosing and treating various neurological conditions. The mnemonics provided can help in memorizing these important landmarks.

    • This question is part of the following fields:

      • Neurological System
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  • Question 17 - Following a car crash, a 25-year-old male is brought to the hospital and...

    Incorrect

    • Following a car crash, a 25-year-old male is brought to the hospital and needs a blood transfusion. He has B negative blood type. Which of the following blood types would be the best match?

      Your Answer:

      Correct Answer: O rhesus negative

      Explanation:

      The ideal blood type for the patient would be B rhesus negative, but it is not available. Among the available options, rhesus positive blood is not recommended for a woman of reproductive age as it may lead to haemolytic disease in newborns. A-type blood would also cause hemolysis in this patient. The only suitable option is O rhesus negative, which is the universal donor.

      Blood product transfusion complications can be categorized into immunological, infective, and other complications. Immunological complications include acute haemolytic reactions, non-haemolytic febrile reactions, and allergic/anaphylaxis reactions. Infective complications may arise due to transmission of vCJD, although measures have been taken to minimize this risk. Other complications include transfusion-related acute lung injury (TRALI), transfusion-associated circulatory overload (TACO), hyperkalaemia, iron overload, and clotting.

      Non-haemolytic febrile reactions are thought to be caused by antibodies reacting with white cell fragments in the blood product and cytokines that have leaked from the blood cell during storage. These reactions may occur in 1-2% of red cell transfusions and 10-30% of platelet transfusions. Minor allergic reactions may also occur due to foreign plasma proteins, while anaphylaxis may be caused by patients with IgA deficiency who have anti-IgA antibodies.

      Acute haemolytic transfusion reaction is a serious complication that results from a mismatch of blood group (ABO) which causes massive intravascular haemolysis. Symptoms begin minutes after the transfusion is started and include a fever, abdominal and chest pain, agitation, and hypotension. Treatment should include immediate transfusion termination, generous fluid resuscitation with saline solution, and informing the lab. Complications include disseminated intravascular coagulation and renal failure.

      TRALI is a rare but potentially fatal complication of blood transfusion that is characterized by the development of hypoxaemia/acute respiratory distress syndrome within 6 hours of transfusion. On the other hand, TACO is a relatively common reaction due to fluid overload resulting in pulmonary oedema. As well as features of pulmonary oedema, the patient may also be hypertensive, a key difference from patients with TRALI.

    • This question is part of the following fields:

      • Haematology And Oncology
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  • Question 18 - A young farmer suffers an accident with crop-spraying equipment and is drenched with...

    Incorrect

    • A young farmer suffers an accident with crop-spraying equipment and is drenched with insecticide. Upon arrival at the emergency department, he presents with severe bradycardia, shortness of breath, and excessive salivation. What are the possible mechanisms of poisoning in this case?

      Your Answer:

      Correct Answer: Acetylcholinesterase inhibition

      Explanation:

      Excessive salivation, dyspnea, and bradycardia are some of the symptoms that may result from anticholinesterase poisoning.

      Organophosphorus insecticides are potent and long-acting anticholinesterases that cause overactivity at parasympathetic receptors, leading to clinical features. Bronchospasm may cause breathlessness. Respiratory muscle paralysis and coma are the main acute effects of massive exposure.

      To counteract excessive acetylcholinergic activity in the autonomic nervous system, atropine is used. Pralidoxime is used to regenerate acetylcholinesterase.

      Salicylate poisoning occurs due to an overdose of aspirin. Symptoms after drug ingestion include abdominal pain, nausea, tinnitus, deafness, vertigo, and hyperpnea. Rehydration is crucial for general care. In severe cases, drug elimination can be enhanced by hemodialysis.

      Lithium is a mood stabilizing drug commonly used in bipolar depression. Acute lithium toxicity results in various neurological effects, progressing from confusion and motor impairment to coma, convulsions, and death. As lithium is excreted renally, fluid therapy is the mainstay of treatment.

      Paracetamol poisoning results in glutathione depletion. N-acetylcysteine, a glutathione precursor, is used as an antidote.

      Cholinergic receptors are proteins found in the body that are activated by the neurotransmitter acetylcholine. They are present in both the central and peripheral nervous systems and can be divided into two groups: nicotinic and muscarinic receptors. Nicotinic receptors are ligand-gated ion channels that allow the movement of sodium into the cell and potassium out, resulting in an inward flow of positive ions. Muscarinic receptors, on the other hand, are G-protein coupled receptors that exert their downstream effect by linking with different G-proteins.

      Nicotinic receptors are named after their binding capacity for nicotine, but they respond to acetylcholine. They are found in preganglionic neurons of the autonomic nervous system and at neuromuscular junctions. At preganglionic neurons, they create a local membrane depolarization through the movement of sodium into the cell, while at neuromuscular junctions, they initiate a wave of depolarization across the muscle cell. Muscarinic receptors are found in effector organs of the parasympathetic autonomic nervous system and are divided into five classes. They mediate various effects through different G-protein systems.

      Cholinergic receptors can be targeted pharmacologically using agonists and antagonists. For example, muscarinic antagonist ipratropium can be used to induce bronchodilation in asthma or chronic obstructive pulmonary disease. In myasthenia gravis, an autoimmune disease, antibodies are directed against the nicotinic receptor on the neuromuscular junction, resulting in skeletal muscle weakness. Understanding the effects associated with each type of cholinergic receptor is important in understanding physiological responses to drugs and disease.

    • This question is part of the following fields:

      • General Principles
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  • Question 19 - Which tumour is most frequently found in children who are less than one...

    Incorrect

    • Which tumour is most frequently found in children who are less than one year old?

      Your Answer:

      Correct Answer: Neuroblastoma

      Explanation:

      Common Tumours in Children Under 1 Year Old

      Embryonal ‘-blastoma’ tumours are frequently found in children under 1 year old. These tumours include retinoblastoma, neuroblastoma, nephroblastoma, medulloblastoma, and hepatoblastoma. Among these, neuroblastoma is the most common and typically affects infants under 1 year old. It originates from neural crest cells in the adrenal medulla and often presents as a large abdominal mass in an otherwise healthy child.

      Acute lymphoblastic leukaemia (ALL) is the most common cancer in children overall, but it is less common in infants under 1 year old. Unfortunately, the prognosis for those who develop ALL before their first birthday is poorer. Astrocytomas, the most common type of CNS tumour, tend to affect slightly older children.

      Retinoblastomas are embryonal tumours of the retina, with half being spontaneous and the other half being familial due to an inherited mutation in the pRB tumour suppressor gene. Wilms’ tumour, also known as nephroblastoma, is another embryonal tumour that affects the kidneys and may present as an abdominal mass in infants.

      In summary, embryonal ‘-blastoma’ tumours are common in children under 1 year old, with neuroblastoma being the most prevalent. Other tumours, such as ALL and astrocytomas, tend to affect slightly older children. Early detection and treatment are crucial for improving outcomes in these young patients.

    • This question is part of the following fields:

      • Paediatrics
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  • Question 20 - A follow-up study is conducted to examine the weight of 100 adults who...

    Incorrect

    • A follow-up study is conducted to examine the weight of 100 adults who were given steroids during their teenage years. The average weight of the adults is 70kg, with a standard deviation of 8 kg. What is the standard error of the mean?

      Your Answer:

      Correct Answer: 1.6

      Explanation:

      To calculate the standard error of the mean, divide the standard deviation by the square root of the number of patients. For example, if the standard deviation is 16 and there are 100 patients, the standard error of the mean would be 1.6.

      Understanding Confidence Interval and Standard Error of the Mean

      The confidence interval is a widely used concept in medical statistics, but it can be confusing to understand. In simple terms, it is a range of values that is likely to contain the true effect of an intervention. The likelihood of the true effect lying within the confidence interval is determined by the confidence level, which is the specified probability of including the true value of the variable. For instance, a 95% confidence interval means that the range of values should contain the true effect of intervention 95% of the time.

      To calculate the confidence interval, we use the standard error of the mean (SEM), which measures the spread expected for the mean of the observations. The SEM is calculated by dividing the standard deviation (SD) by the square root of the sample size (n). As the sample size increases, the SEM gets smaller, indicating a more accurate sample mean from the true population mean.

      A 95% confidence interval is calculated by subtracting and adding 1.96 times the SEM from the mean value. However, if the sample size is small (n < 100), a 'Student's T critical value' look-up table should be used instead of 1.96. Similarly, if a different confidence level is required, such as 90%, the value used in the formula should be adjusted accordingly. In summary, the confidence interval is a range of values that is likely to contain the true effect of an intervention, and its calculation involves using the standard error of the mean. Understanding these concepts is crucial in interpreting statistical results in medical research.

    • This question is part of the following fields:

      • General Principles
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  • Question 21 - Which of the structures listed below lies posterior to the carotid sheath at...

    Incorrect

    • Which of the structures listed below lies posterior to the carotid sheath at the level of the 6th cervical vertebrae?

      Your Answer:

      Correct Answer: Cervical sympathetic chain

      Explanation:

      The hypoglossal nerves and the ansa cervicalis cross the carotid sheath from the front, while the vagus nerve is located inside it. The cervical sympathetic chain is positioned at the back, between the sheath and the prevertebral fascia.

      The common carotid artery is a major blood vessel that supplies the head and neck with oxygenated blood. It has two branches, the left and right common carotid arteries, which arise from different locations. The left common carotid artery originates from the arch of the aorta, while the right common carotid artery arises from the brachiocephalic trunk. Both arteries terminate at the upper border of the thyroid cartilage by dividing into the internal and external carotid arteries.

      The left common carotid artery runs superolaterally to the sternoclavicular joint and is in contact with various structures in the thorax, including the trachea, left recurrent laryngeal nerve, and left margin of the esophagus. In the neck, it passes deep to the sternocleidomastoid muscle and enters the carotid sheath with the vagus nerve and internal jugular vein. The right common carotid artery has a similar path to the cervical portion of the left common carotid artery, but with fewer closely related structures.

      Overall, the common carotid artery is an important blood vessel with complex anatomical relationships in both the thorax and neck. Understanding its path and relations is crucial for medical professionals to diagnose and treat various conditions related to this artery.

    • This question is part of the following fields:

      • Neurological System
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  • Question 22 - A 40-year-old man from Kenya visits your clinic complaining of feeling constantly fatigued....

    Incorrect

    • A 40-year-old man from Kenya visits your clinic complaining of feeling constantly fatigued. He reports having a persistent cough for the past 6 weeks, which has been keeping him up at night. He also mentions coughing up blood on occasion. Additionally, he has been experiencing night sweats, causing his sheets to become drenched. His wife notes that he appears to be at his worst during the evenings and often has a temperature around that time. Upon examination, he appears tired and has a mild fever of 37.9ºC. A sputum sample is taken, which fails to take up a Gram stain but reveals acid-fast bacilli with the Ziehl-Neelsen test. A chest X-ray shows hilar lymphadenopathy and a cavitating lesion in the right apex. If a lung biopsy were to be taken of the surrounding tissues, what histological finding would be observed?

      Your Answer:

      Correct Answer: Epitheliod histiocytes

      Explanation:

      The presence of epithelioid histiocytes in a granuloma is a common histological finding in patients with Tuberculosis. This is consistent with the patient’s history and geographical origin. Epithelioid histiocytes are elongated macrophages that resemble epithelial cells. In cases where there is necrosis, it is referred to as a Caseating granuloma due to its resemblance to casein in cheese.

      Keratin pearl is a histological finding in squamous cell carcinoma of the lung, which may also present as a cavitating lesion. However, it would not grow acid-fast bacilli, unlike TB.

      Psammoma bodies are typically found in papillary thyroid carcinoma.

      Owls-eye nucleus is a characteristic finding in a CMV infection.

      Reed-Sternberg cells are commonly found in Hodgkin’s lymphoma, which typically presents with B symptoms such as fever, night sweats, and weight loss. However, based on the other findings, this diagnosis is unlikely.

      Types of Tuberculosis

      Tuberculosis (TB) is a disease caused by Mycobacterium tuberculosis that primarily affects the lungs. There are two types of TB: primary and secondary. Primary TB occurs when a non-immune host is exposed to the bacteria and develops a small lung lesion called a Ghon focus. This focus is made up of macrophages containing tubercles and is accompanied by hilar lymph nodes, forming a Ghon complex. In immunocompetent individuals, the lesion usually heals through fibrosis. However, those who are immunocompromised may develop disseminated disease, also known as miliary tuberculosis.

      Secondary TB, also called post-primary TB, occurs when the initial infection becomes reactivated in an immunocompromised host. Reactivation typically occurs in the apex of the lungs and can spread locally or to other parts of the body. Factors that can cause immunocompromise include immunosuppressive drugs, HIV, and malnutrition. While the lungs are still the most common site for secondary TB, it can also affect other areas such as the central nervous system, vertebral bodies, cervical lymph nodes, renal system, and gastrointestinal tract. Tuberculous meningitis is the most serious complication of extra-pulmonary TB. Understanding the differences between primary and secondary TB is crucial in diagnosing and treating the disease.

    • This question is part of the following fields:

      • General Principles
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  • Question 23 - A 45-year-old woman visits her doctor complaining of muscle cramps and fatigue. Upon...

    Incorrect

    • A 45-year-old woman visits her doctor complaining of muscle cramps and fatigue. Upon ruling out any musculoskeletal issues, a blood test is conducted which reveals hyperparathyroidism and low serum phosphate levels. It is suspected that the low phosphate levels are due to the inhibitory effect of parathyroid hormone on renal phosphate reabsorption. Which site in the kidney is most likely affected by parathyroid hormone to cause these blood results?

      Your Answer:

      Correct Answer: Proximal convoluted tubule

      Explanation:

      The proximal convoluted tubule is responsible for the majority of renal phosphate reabsorption. This occurs through co-transport with sodium and up to two thirds of filtered water. The thin ascending limb of the Loop of Henle is impermeable to water but highly permeable to sodium and chloride, while reabsorption of these ions occurs in the thick ascending limb. Parathyroid hormone is most effective at the proximal convoluted tubule due to its role in regulating phosphate reabsorption.

      The Loop of Henle and its Role in Renal Physiology

      The Loop of Henle is a crucial component of the renal system, located in the juxtamedullary nephrons and running deep into the medulla. Approximately 60 litres of water containing 9000 mmol sodium enters the descending limb of the loop of Henle in 24 hours. The osmolarity of fluid changes and is greatest at the tip of the papilla. The thin ascending limb is impermeable to water, but highly permeable to sodium and chloride ions. This loss means that at the beginning of the thick ascending limb the fluid is hypo osmotic compared with adjacent interstitial fluid. In the thick ascending limb, the reabsorption of sodium and chloride ions occurs by both facilitated and passive diffusion pathways. The loops of Henle are co-located with vasa recta, which have similar solute compositions to the surrounding extracellular fluid, preventing the diffusion and subsequent removal of this hypertonic fluid. The energy-dependent reabsorption of sodium and chloride in the thick ascending limb helps to maintain this osmotic gradient. Overall, the Loop of Henle plays a crucial role in regulating the concentration of solutes in the renal system.

    • This question is part of the following fields:

      • Renal System
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  • Question 24 - A 14-year-old boy is brought to the clinic by his mother due to...

    Incorrect

    • A 14-year-old boy is brought to the clinic by his mother due to concerns about his height compared to other boys his age. The boy also shares that he often receives comments about his appearance, with some likening him to a toy doll. What can be inferred about the pattern of hormone release that he may be lacking?

      Your Answer:

      Correct Answer: It is released in a pulsatile manner

      Explanation:

      The doll-like appearance of the boy in his presentation suggests that he may be suffering from growth hormone deficiency, which can cause short stature, forehead prominence, and maxillary hypoplasia. The hypothalamus controls the release of growth hormone through the pulsatile release of growth hormone releasing hormone. Therefore, measuring GHRH levels is not a useful method for investigating growth hormone deficiency.

      Understanding Growth Hormone and Its Functions

      Growth hormone (GH) is a hormone produced by the somatotroph cells in the anterior pituitary gland. It plays a crucial role in postnatal growth and development, as well as in regulating protein, lipid, and carbohydrate metabolism. GH acts on a transmembrane receptor for growth factor, leading to receptor dimerization and direct or indirect effects on tissues via insulin-like growth factor 1 (IGF-1), which is primarily secreted by the liver.

      GH secretion is regulated by various factors, including growth hormone releasing hormone (GHRH), fasting, exercise, and sleep. Conversely, glucose and somatostatin can decrease GH secretion. Disorders associated with GH include acromegaly, which results from excess GH, and GH deficiency, which can lead to short stature.

      In summary, GH is a vital hormone that plays a significant role in growth and metabolism. Understanding its functions and regulation can help in the diagnosis and treatment of GH-related disorders.

    • This question is part of the following fields:

      • Endocrine System
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  • Question 25 - A 35-year-old woman is referred to the endocrine clinic due to missed periods...

    Incorrect

    • A 35-year-old woman is referred to the endocrine clinic due to missed periods and lactation. She has also gained weight and experiences vaginal dryness. The endocrinologist decides to measure her prolactin levels. What hormone is responsible for suppressing the release of prolactin from the pituitary gland?

      Your Answer:

      Correct Answer: Dopamine

      Explanation:

      Dopamine consistently prevents the release of prolactin.

      Understanding Prolactin and Its Functions

      Prolactin is a hormone that is produced by the anterior pituitary gland. Its primary function is to stimulate breast development and milk production in females. During pregnancy, prolactin levels increase to support the growth and development of the mammary glands. It also plays a role in reducing the pulsatility of gonadotropin-releasing hormone (GnRH) at the hypothalamic level, which can block the action of luteinizing hormone (LH) on the ovaries or testes.

      The secretion of prolactin is regulated by dopamine, which constantly inhibits its release. However, certain factors can increase or decrease prolactin secretion. For example, prolactin levels increase during pregnancy, in response to estrogen, and during breastfeeding. Additionally, stress, sleep, and certain drugs like metoclopramide and antipsychotics can also increase prolactin secretion. On the other hand, dopamine and dopaminergic agonists can decrease prolactin secretion.

      Overall, understanding the functions and regulation of prolactin is important for reproductive health and lactation.

    • This question is part of the following fields:

      • Endocrine System
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  • Question 26 - A 28-year-old man has a glomerular filtration rate of 110ml / minute at...

    Incorrect

    • A 28-year-old man has a glomerular filtration rate of 110ml / minute at a systolic blood pressure of 120/80. If his blood pressure were to decrease to 100/70, what would be his glomerular filtration rate?

      Your Answer:

      Correct Answer: 110ml / minute

      Explanation:

      The suggested decrease in blood pressure is within the kidney’s autoregulatory range for blood supply, so the GFR will remain unaffected.

      The Loop of Henle and its Role in Renal Physiology

      The Loop of Henle is a crucial component of the renal system, located in the juxtamedullary nephrons and running deep into the medulla. Approximately 60 litres of water containing 9000 mmol sodium enters the descending limb of the loop of Henle in 24 hours. The osmolarity of fluid changes and is greatest at the tip of the papilla. The thin ascending limb is impermeable to water, but highly permeable to sodium and chloride ions. This loss means that at the beginning of the thick ascending limb the fluid is hypo osmotic compared with adjacent interstitial fluid. In the thick ascending limb, the reabsorption of sodium and chloride ions occurs by both facilitated and passive diffusion pathways. The loops of Henle are co-located with vasa recta, which have similar solute compositions to the surrounding extracellular fluid, preventing the diffusion and subsequent removal of this hypertonic fluid. The energy-dependent reabsorption of sodium and chloride in the thick ascending limb helps to maintain this osmotic gradient. Overall, the Loop of Henle plays a crucial role in regulating the concentration of solutes in the renal system.

    • This question is part of the following fields:

      • Renal System
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  • Question 27 - A 30-year-old man visits the sexual health clinic with complaints of dysuria and...

    Incorrect

    • A 30-year-old man visits the sexual health clinic with complaints of dysuria and penile discharge. He is concerned about having a sexually transmitted infection due to engaging in unprotected sex with multiple partners in the past month. During the examination, the clinician takes an urethral swab, smears it on a slide, and performs a gram stain. Upon examining the slide under the microscope, the clinician informs the man that he has probably contracted gonorrhoeae.

      What would be the appearance of this organism when viewed under the microscope?

      Your Answer:

      Correct Answer: Gram-negative diplococci

      Explanation:

      Gram-negative diplococci can be used to identify Neisseria gonorrhoeae on gram staining.

      Streptococcus pneumonia is a type of bacterium that appears as gram-positive diplococci.

      Gram-positive cocci in clusters are characteristic of Staphylococcus aureus.

      The Acinetobacter group and the Haemophilus group are examples of gram-negative coccobacilli.

      Understanding gonorrhoeae: Causes, Symptoms, and Treatment

      gonorrhoeae is a sexually transmitted infection caused by the Gram-negative diplococcus Neisseria gonorrhoeae. It can occur on any mucous membrane surface, including the genitourinary tract, rectum, and pharynx. Symptoms in males include urethral discharge and dysuria, while females may experience cervicitis leading to vaginal discharge. However, rectal and pharyngeal infections are usually asymptomatic. Unfortunately, immunisation is not possible, and reinfection is common due to antigen variation of type IV pili and Opa proteins.

      If left untreated, gonorrhoeae can lead to local complications such as urethral strictures, epididymitis, and salpingitis, which may result in infertility. Disseminated infection may also occur, with gonococcal infection being the most common cause of septic arthritis in young adults. The pathophysiology of disseminated gonococcal infection is not fully understood but is thought to be due to haematogenous spread from mucosal infection.

      Management of gonorrhoeae involves the use of antibiotics. Ciprofloxacin used to be the treatment of choice, but there is now increased resistance to it. Cephalosporins are now more widely used, with a single dose of IM ceftriaxone 1g being the new first-line treatment. If sensitivities are known, a single dose of oral ciprofloxacin 500mg may be given. Disseminated gonococcal infection and gonococcal arthritis may also occur, with symptoms including tenosynovitis, migratory polyarthritis, and dermatitis.

    • This question is part of the following fields:

      • General Principles
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  • Question 28 - A 14-year-old boy visits the GP clinic with his father, complaining of lower...

    Incorrect

    • A 14-year-old boy visits the GP clinic with his father, complaining of lower abdominal pain. He has a fever and has vomited twice in the last 24 hours. The GP suspects appendicitis and recommends further evaluation at the hospital. However, the patient refuses, becoming emotional and stating that he has an important sports game coming up. Despite the GP's attempts to explain the potential risks of refusing treatment, the patient continues to shake his head and refuses to discuss the matter further. His father becomes agitated, insisting that his son needs to go to the hospital for treatment. What is the most appropriate next step in managing this situation?

      Your Answer:

      Correct Answer: Ask the mother to consent to further treatment - as a parent in this instance, her decision overrides that of her daughter

      Explanation:

      The General Medical Council (GMC) has provided guidance for doctors on the ethical principles surrounding consent to treatment in children in their publication ‘0-18 years: guidance for all doctors’ (2007). According to this guidance, if a child lacks capacity, their parents can provide consent for investigations and treatment that are deemed to be in the child’s best interests.

      In this scenario, the patient is not displaying a sufficient level of maturity to comprehend the risks associated with refusing treatment. As the patient is under 16 years old, it can be assumed that they lack the capacity to make such a decision. Therefore, the responsibility of making a decision in the patient’s best interests falls to their mother.

      The options of allowing the patient to go home or return the following day are not appropriate as appendicitis can become a serious and potentially life-threatening condition if left untreated. Asking the mother to leave would also not be a suitable course of action as her reaction is understandable given the circumstances and it is not in the patient’s best interests.

      References:

      General Medical Council. 0-18 years: guidance for all doctors. London: General Medical Council, 2007. p. 11-13.

      Guidelines for Obtaining Consent in Children

      When it comes to obtaining consent in children, the General Medical Council has provided guidelines. For children aged 16 and above, they can be treated as adults and are presumed to have the capacity to decide. However, for those under 16, their ability to understand what is involved determines their capacity to decide. If a competent child refuses treatment, a person with parental responsibility or the court may authorize investigation or treatment that is in the child’s best interests.

      In terms of providing contraceptives to patients under 16, the Fraser Guidelines must be followed. These guidelines state that the young person must understand the professional’s advice, cannot be persuaded to inform their parents, is likely to begin or continue having sexual intercourse with or without contraceptive treatment, and their physical or mental health is likely to suffer without contraceptive treatment. Additionally, the young person’s best interests require them to receive contraceptive advice or treatment with or without parental consent.

      Some doctors use the term Fraser competency for contraception and Gillick competency for general issues of consent in children. However, rumors that Victoria Gillick removed her permission to use her name or applied copyright have been debunked. It is important to note that in Scotland, those with parental responsibility cannot authorize procedures that a competent child has refused. For consistency over competence in children, it is crucial to follow these guidelines when obtaining consent.

    • This question is part of the following fields:

      • General Principles
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  • Question 29 - A 15-year-old girl arrives at the emergency department complaining of difficulty breathing, facial...

    Incorrect

    • A 15-year-old girl arrives at the emergency department complaining of difficulty breathing, facial swelling, and a rash that appeared after consuming a curry. An anaphylactic reaction is suspected, and IM adrenaline is administered.

      On which class of receptors does this medication act?

      Your Answer:

      Correct Answer: G-protein coupled receptors

      Explanation:

      Adrenaline exerts its effects through G protein-coupled receptors, which are responsible for slow transmission and metabolic processes. The adrenergic (sympathetic) receptors that are activated by G proteins include alpha, beta-1, and beta-2 receptors. Alpha-receptors, found in arteries, cause arterial constriction when stimulated by adrenaline, leading to an increase in blood pressure. Beta-1 receptors, located in the heart, increase heart rate and contractility when stimulated. Beta-2 receptors, found in the bronchioles of the lungs, promote bronchodilation when stimulated.

      In the case of anaphylaxis treatment, adrenaline acts on alpha, beta-1, and beta-2 receptors, which helps to reverse the peripheral vasodilation and angioedema seen in anaphylaxis by increasing blood pressure, heart rate, and contractility. Additionally, it reverses bronchoconstriction.

      On the other hand, ligand-gated ion channel receptors are associated with fast responses and include nicotinic acetylcholine, GABA-A & GABA-C, and glutamate receptors.

      Membrane receptors are proteins located on the surface of cells that receive signals from outside the cell and transmit them inside. There are four main types of membrane receptors: ligand-gated ion channel receptors, tyrosine kinase receptors, guanylate cyclase receptors, and G protein-coupled receptors. Ligand-gated ion channel receptors mediate fast responses and include nicotinic acetylcholine, GABA-A & GABA-C, and glutamate receptors. Tyrosine kinase receptors include receptor tyrosine kinase such as insulin, insulin-like growth factor (IGF), and epidermal growth factor (EGF), and non-receptor tyrosine kinase such as PIGG(L)ET, which stands for Prolactin, Immunomodulators (cytokines IL-2, Il-6, IFN), GH, G-CSF, Erythropoietin, and Thrombopoietin.

      Guanylate cyclase receptors contain intrinsic enzyme activity and include atrial natriuretic factor and brain natriuretic peptide. G protein-coupled receptors generally mediate slow transmission and affect metabolic processes. They are activated by a wide variety of extracellular signals such as peptide hormones, biogenic amines (e.g. adrenaline), lipophilic hormones, and light. These receptors have 7-helix membrane-spanning domains and consist of 3 main subunits: alpha, beta, and gamma. The alpha subunit is linked to GDP. Ligand binding causes conformational changes to the receptor, GDP is phosphorylated to GTP, and the alpha subunit is activated. G proteins are named according to the alpha subunit (Gs, Gi, Gq).

      The mechanism of G protein-coupled receptors varies depending on the type of G protein involved. Gs stimulates adenylate cyclase, which increases cAMP and activates protein kinase A. Gi inhibits adenylate cyclase, which decreases cAMP and inhibits protein kinase A. Gq activates phospholipase C, which splits PIP2 to IP3 and DAG and activates protein kinase C. Examples of G protein-coupled receptors include beta-1 receptors (epinephrine, norepinephrine, dobutamine), beta-2 receptors (epinephrine, salbuterol), H2 receptors (histamine), D1 receptors (dopamine), V2 receptors (vas

    • This question is part of the following fields:

      • General Principles
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  • Question 30 - A 50-year-old woman is referred to the clinic with symptoms of fatigue, constipation,...

    Incorrect

    • A 50-year-old woman is referred to the clinic with symptoms of fatigue, constipation, weight gain, and cold intolerance. Thyroid function testing reveals overt hypothyroidism, and the recommended treatment is levothyroxine. What receptors does this medication act on?

      Your Answer:

      Correct Answer: Nuclear receptors

      Explanation:

      Levothyroxine exerts its therapeutic effect by interacting with nuclear receptors found within cells. Unlike G protein-coupled receptors, which are activated by a variety of extracellular signals, levothyroxine does not bind to these receptors. Ligand-gated ion channel receptors, which allow ions to pass through in response to ligand binding, are also not affected by levothyroxine. Similarly, levothyroxine does not interact with serine/threonine kinase receptors, which are bound by the ligand transforming growth factor beta. Instead, levothyroxine controls DNA transcription and protein synthesis, resulting in the regulation of metabolic processes.

      Pharmacodynamics refers to the effects of drugs on the body, as opposed to pharmacokinetics which is concerned with how the body processes drugs. Drugs typically interact with a target, which can be a protein located either inside or outside of cells. There are four main types of cellular targets: ion channels, G-protein coupled receptors, tyrosine kinase receptors, and nuclear receptors. The type of target determines the mechanism of action of the drug. For example, drugs that work on ion channels cause the channel to open or close, while drugs that activate tyrosine kinase receptors lead to cell growth and differentiation.

      It is also important to consider whether a drug has a positive or negative impact on the receptor. Agonists activate the receptor, while antagonists block the receptor preventing activation. Antagonists can be competitive or non-competitive, depending on whether they bind at the same site as the agonist or at a different site. The binding affinity of a drug refers to how readily it binds to a specific receptor, while efficacy measures how well an agonist produces a response once it has bound to the receptor. Potency is related to the concentration at which a drug is effective, while the therapeutic index is the ratio of the dose of a drug resulting in an undesired effect compared to that at which it produces the desired effect.

      The relationship between the dose of a drug and the response it produces is rarely linear. Many drugs saturate the available receptors, meaning that further increased doses will not cause any more response. Some drugs do not have a significant impact below a certain dose and are considered sub-therapeutic. Dose-response graphs can be used to illustrate the relationship between dose and response, allowing for easy comparison of different drugs. However, it is important to remember that dose-response varies between individuals.

    • This question is part of the following fields:

      • General Principles
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  • Question 31 - A 67-year-old male presents with a 3-week history of deteriorating vision in his...

    Incorrect

    • A 67-year-old male presents with a 3-week history of deteriorating vision in his left eye. During examination of the cranial nerves, it is observed that the left pupil is more constricted than the right. The patient experiences slight ptosis of the left eyelid. The patient reports dryness on the left side of the face with decreased sweating. There are no reports of reduced sweating elsewhere. The patient has no known medical history and lives independently with his family. He drinks 6 units per week and has a smoking history of 35 pack-years. Based on the neurological symptoms and history, where is the lesion most likely located?

      Your Answer:

      Correct Answer: Sympathetic chain

      Explanation:

      Horner’s syndrome is a condition that can be categorized into three types based on the location of the lesion. The first type is a central lesion that can occur anywhere from the hypothalamus to the synapse at T1. The second type is a preganglionic lesion that occurs between the synapse in the spinal cord to the superior cervical ganglion. The third type is a postganglionic lesion that occurs above the superior cervical ganglion.

      The level of anhidrosis, or lack of sweating, can help determine the location of the lesion. Anhidrosis is only seen in the first and second types of lesions. In first-type lesions, it affects the entire sympathetic region, while in second-type lesions, it only affects the face after the ganglion.

      In this case, the patient has anhidrosis of the face, suggesting a second-type lesion. The patient’s smoking history increases the likelihood of a Pancoast’s tumor, which compresses the sympathetic chain.

      Lesions in the medulla can present more dramatically, with more cranial nerve abnormalities and peripheral neurological signs. Lesions in the nerve fibers after the superior cervical ganglion typically present with ptosis and meiosis but without anhidrosis. Carotid artery dissection is a common cause of these types of lesions. Lesions in the cervical spine or hypothalamus would result in a more extensive disruption of peripheral neurology.

      Horner’s syndrome is a condition characterized by several features, including a small pupil (miosis), drooping of the upper eyelid (ptosis), a sunken eye (enophthalmos), and loss of sweating on one side of the face (anhidrosis). The cause of Horner’s syndrome can be determined by examining additional symptoms. For example, congenital Horner’s syndrome may be identified by a difference in iris color (heterochromia), while anhidrosis may be present in central or preganglionic lesions. Pharmacologic tests, such as the use of apraclonidine drops, can also be helpful in confirming the diagnosis and identifying the location of the lesion. Central lesions may be caused by conditions such as stroke or multiple sclerosis, while postganglionic lesions may be due to factors like carotid artery dissection or cluster headaches. It is important to note that the appearance of enophthalmos in Horner’s syndrome is actually due to a narrow palpebral aperture rather than true enophthalmos.

    • This question is part of the following fields:

      • Neurological System
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  • Question 32 - A 55-year-old chronic smoker presents to the cardiology clinic with worsening chest pain...

    Incorrect

    • A 55-year-old chronic smoker presents to the cardiology clinic with worsening chest pain during physical activity. After initial investigations, an outpatient coronary angiography is performed which reveals severe stenosis/atheroma in multiple vessels. The patient is informed that this condition is a result of various factors, including the detrimental effects of smoking on the blood vessels.

      What is the ultimate stage in the development of this patient's condition?

      Your Answer:

      Correct Answer: Smooth muscle proliferation and migration from the tunica media into the intima

      Explanation:

      Understanding Atherosclerosis and its Complications

      Atherosclerosis is a complex process that occurs over several years. It begins with endothelial dysfunction triggered by factors such as smoking, hypertension, and hyperglycemia. This leads to changes in the endothelium, including inflammation, oxidation, proliferation, and reduced nitric oxide bioavailability. As a result, low-density lipoprotein (LDL) particles infiltrate the subendothelial space, and monocytes migrate from the blood and differentiate into macrophages. These macrophages then phagocytose oxidized LDL, slowly turning into large ‘foam cells’. Smooth muscle proliferation and migration from the tunica media into the intima result in the formation of a fibrous capsule covering the fatty plaque.

      Once a plaque has formed, it can cause several complications. For example, it can form a physical blockage in the lumen of the coronary artery, leading to reduced blood flow and oxygen to the myocardium, resulting in angina. Alternatively, the plaque may rupture, potentially causing a complete occlusion of the coronary artery and resulting in a myocardial infarction. It is essential to understand the process of atherosclerosis and its complications to prevent and manage cardiovascular diseases effectively.

    • This question is part of the following fields:

      • Cardiovascular System
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  • Question 33 - A 42-year-old male comes to the general physician with a painless lump. He...

    Incorrect

    • A 42-year-old male comes to the general physician with a painless lump. He is referred to urology and subsequent scans reveal a testicular seminoma with metastasis to the lymph nodes that receive lymphatic drainage from the scrotum.

      What are the lymph nodes that receive drainage from the scrotum?

      Your Answer:

      Correct Answer: Superficial inguinal nodes

      Explanation:

      The scrotum’s lymph drainage is received by the superficial inguinal nodes, which serve as the primary lymph node drainage site for this area.

      Lymphatic drainage is the process by which lymphatic vessels carry lymph, a clear fluid containing white blood cells, away from tissues and organs and towards lymph nodes. The lymphatic vessels that drain the skin and follow venous drainage are called superficial lymphatic vessels, while those that drain internal organs and structures follow the arteries and are called deep lymphatic vessels. These vessels eventually lead to lymph nodes, which filter and remove harmful substances from the lymph before it is returned to the bloodstream.

      The lymphatic system is divided into two main ducts: the right lymphatic duct and the thoracic duct. The right lymphatic duct drains the right side of the head and right arm, while the thoracic duct drains everything else. Both ducts eventually drain into the venous system.

      Different areas of the body have specific primary lymph node drainage sites. For example, the superficial inguinal lymph nodes drain the anal canal below the pectinate line, perineum, skin of the thigh, penis, scrotum, and vagina. The deep inguinal lymph nodes drain the glans penis, while the para-aortic lymph nodes drain the testes, ovaries, kidney, and adrenal gland. The axillary lymph nodes drain the lateral breast and upper limb, while the internal iliac lymph nodes drain the anal canal above the pectinate line, lower part of the rectum, and pelvic structures including the cervix and inferior part of the uterus. The superior mesenteric lymph nodes drain the duodenum and jejunum, while the inferior mesenteric lymph nodes drain the descending colon, sigmoid colon, and upper part of the rectum. Finally, the coeliac lymph nodes drain the stomach.

    • This question is part of the following fields:

      • Haematology And Oncology
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  • Question 34 - Look at the following DNA sequence and identify the mutation that has occurred:

    DNA...

    Incorrect

    • Look at the following DNA sequence and identify the mutation that has occurred:

      DNA sequence Amino Acid Sequence
      Original AAA GCC AAA lys, ala, lys
      Mutation AAA ACC ATT lys, thr, lys,

      Has the mutation occurred due to a genetic error?

      Your Answer:

      Correct Answer: Missense

      Explanation:

      Missense mutations are point mutations that result in a change in the amino acid sequence, potentially rendering the protein non-functional. Deletions involve the loss of at least one base, while insertions involve the addition of at least one base. Inversions reverse a section of the genetic code. Missense mutations occur when a single base is changed, resulting in the production of a different amino acid than in the original sequence. Nonsense mutations code for a stop codon, halting the production of amino acids beyond that point.

      Types of DNA Mutations

      There are different types of DNA mutations that can occur in an organism’s genetic material. One type is called a silent mutation, which does not change the amino acid sequence of a protein. This type of mutation often occurs in the third position of a codon, where the change in the DNA base does not affect the final amino acid produced.

      Another type of mutation is called a nonsense mutation, which results in the formation of a stop codon. This means that the protein being produced is truncated and may not function properly.

      A missense mutation is a point mutation that changes the amino acid sequence of a protein. This can have significant effects on the protein’s function, as the altered amino acid may not be able to perform its intended role.

      Finally, a frameshift mutation occurs when a number of nucleotides are inserted or deleted from the DNA sequence. This can cause a shift in the reading frame of the DNA, resulting in a completely different amino acid sequence downstream. These mutations can have serious consequences for the organism, as the resulting protein may be non-functional or even harmful.

    • This question is part of the following fields:

      • General Principles
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  • Question 35 - A 72-year-old patient presents to the Emergency Room with central crushing chest pain...

    Incorrect

    • A 72-year-old patient presents to the Emergency Room with central crushing chest pain that radiates to their jaw and left arm. They have a medical history of hypertension, type 2 diabetes mellitus, and hypercholesterolemia. The patient receives percutaneous coronary intervention but unfortunately experiences ventricular fibrillation and passes away 3 days later. What is the probable histological discovery in their heart?

      Your Answer:

      Correct Answer: Extensive coagulative necrosis, neutrophils

      Explanation:

      Myocardial infarction (MI) can lead to various complications, which can occur immediately, early, or late after the event. Cardiac arrest is the most common cause of death following MI, usually due to ventricular fibrillation. Cardiogenic shock may occur if a large part of the ventricular myocardium is damaged, and it is difficult to treat. Chronic heart failure may result from ventricular myocardium dysfunction, which can be managed with loop diuretics, ACE-inhibitors, and beta-blockers. Tachyarrhythmias, such as ventricular fibrillation and ventricular tachycardia, are common complications. Bradyarrhythmias, such as atrioventricular block, are more common following inferior MI. Pericarditis is common in the first 48 hours after a transmural MI, while Dressler’s syndrome may occur 2-6 weeks later. Left ventricular aneurysm and free wall rupture, ventricular septal defect, and acute mitral regurgitation are other complications that may require urgent medical attention.

    • This question is part of the following fields:

      • Cardiovascular System
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  • Question 36 - A 10-year-old boy is prescribed erythromycin for a lower respiratory tract infection. What...

    Incorrect

    • A 10-year-old boy is prescribed erythromycin for a lower respiratory tract infection. What is the mechanism of action of this medication?

      Your Answer:

      Correct Answer: Inhibition of protein synthesis

      Explanation:

      Macrolides work by inhibiting protein synthesis through their action on the 50S subunit of ribosomes. This class of antibiotics, which includes erythromycin, does not inhibit cell wall synthesis, topoisomerase IV enzyme, or disrupt the cell membrane, which are mechanisms of action for other types of antibiotics.

      Antibiotics work in different ways to kill or inhibit the growth of bacteria. The commonly used antibiotics can be classified based on their gross mechanism of action. The first group inhibits cell wall formation by either preventing peptidoglycan cross-linking (penicillins, cephalosporins, carbapenems) or peptidoglycan synthesis (glycopeptides like vancomycin). The second group inhibits protein synthesis by acting on either the 50S subunit (macrolides, chloramphenicol, clindamycin, linezolid, streptogrammins) or the 30S subunit (aminoglycosides, tetracyclines) of the bacterial ribosome. The third group inhibits DNA synthesis (quinolones like ciprofloxacin) or damages DNA (metronidazole). The fourth group inhibits folic acid formation (sulphonamides and trimethoprim), while the fifth group inhibits RNA synthesis (rifampicin). Understanding the mechanism of action of antibiotics is important in selecting the appropriate drug for a particular bacterial infection.

    • This question is part of the following fields:

      • General Principles
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  • Question 37 - Which bone is not part of the carpal bones? ...

    Incorrect

    • Which bone is not part of the carpal bones?

      Your Answer:

      Correct Answer: Trapezius

      Explanation:

      Trapezius is not related to the mnemonic for the carpal bones.

      Carpal Bones: The Wrist’s Building Blocks

      The wrist is composed of eight carpal bones, which are arranged in two rows of four. These bones are convex from side to side posteriorly and concave anteriorly. The trapezium is located at the base of the first metacarpal bone, which is the base of the thumb. The scaphoid, lunate, and triquetrum bones do not have any tendons attached to them, but they are stabilized by ligaments.

      In summary, the carpal bones are the building blocks of the wrist, and they play a crucial role in the wrist’s movement and stability. The trapezium bone is located at the base of the thumb, while the scaphoid, lunate, and triquetrum bones are stabilized by ligaments. Understanding the anatomy of the wrist is essential for diagnosing and treating wrist injuries and conditions.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
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  • Question 38 - A 35-year-old woman presents to the Emergency Department with a stab wound to...

    Incorrect

    • A 35-year-old woman presents to the Emergency Department with a stab wound to her forearm following a robbery. Upon examination, there is numbness observed in the thenar eminence and weakness in finger and wrist flexion. Which nerve is the most probable to have been damaged?

      Your Answer:

      Correct Answer: Median nerve

      Explanation:

      The median nerve is responsible for providing sensation to the thenar eminence and controlling finger and wrist flexion. Its palmar cutaneous branch supplies sensation to the skin on the lateral side of the palm, including the thenar eminence. The median nerve directly innervates the flexor carpi radialis and palmaris longus muscles, which are responsible for wrist flexion, as well as the flexor digitorum superficialis and lateral half of the flexor digitorum profundus muscles via the anterior interosseous nerve, which control finger flexion. Damage to the median nerve can result in weakness in these movements.

      Anatomy and Function of the Median Nerve

      The median nerve is a nerve that originates from the lateral and medial cords of the brachial plexus. It descends lateral to the brachial artery and passes deep to the bicipital aponeurosis and the median cubital vein at the elbow. The nerve then passes between the two heads of the pronator teres muscle and runs on the deep surface of flexor digitorum superficialis. Near the wrist, it becomes superficial between the tendons of flexor digitorum superficialis and flexor carpi radialis, passing deep to the flexor retinaculum to enter the palm.

      The median nerve has several branches that supply the upper arm, forearm, and hand. These branches include the pronator teres, flexor carpi radialis, palmaris longus, flexor digitorum superficialis, flexor pollicis longus, and palmar cutaneous branch. The nerve also provides motor supply to the lateral two lumbricals, opponens pollicis, abductor pollicis brevis, and flexor pollicis brevis muscles, as well as sensory supply to the palmar aspect of the lateral 2 ½ fingers.

      Damage to the median nerve can occur at the wrist or elbow, resulting in various symptoms such as paralysis and wasting of thenar eminence muscles, weakness of wrist flexion, and sensory loss to the palmar aspect of the fingers. Additionally, damage to the anterior interosseous nerve, a branch of the median nerve, can result in loss of pronation of the forearm and weakness of long flexors of the thumb and index finger. Understanding the anatomy and function of the median nerve is important in diagnosing and treating conditions that affect this nerve.

    • This question is part of the following fields:

      • Neurological System
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  • Question 39 - A 65-year-old male presented with a headache, feeling unwell, and muscle aches for...

    Incorrect

    • A 65-year-old male presented with a headache, feeling unwell, and muscle aches for the past 6 days. He also reported feeling feverish but says it comes and goes over a period of about 3 days. He suspects it's the flu but decided to get checked as he recently returned from a 4-week holiday in Kenya. He mentioned taking prophylaxis while he was there but stopped after a few days due to feeling sick.

      Upon admission, the man had a fever (38.5º) and was slightly tachycardic (110 bpm), but the rest of the initial examination was unremarkable. Initial blood tests, including full blood count, urea and electrolytes, liver function tests, and chest x-ray, were all normal. However, the blood film revealed trophozoites and schizonts of plasmodium falciparum with a parasitaemia of 3.2%.

      After five hours of admission, the man became drowsy and confused. Despite initial management, he was diagnosed with severe malaria and transferred to the intensive care unit where IV artesunate was initiated.

      What is the target of IV artesunate in the malaria parasite?

      Your Answer:

      Correct Answer: Blood schizonts and gametocytes

      Explanation:

      Artesunate is a potent treatment for eliminating blood schizonts and gametocytes in malaria, but it is not effective against liver parasites. Different antimalarial drugs target specific stages of the parasite’s life cycle, with artemisinins, quinoline derivatives, and antibiotics being effective against blood schizonts, while primaquine and atovaquone-proguanil are used to target liver schizonts.

      Understanding Malaria: Causes, Types, and Protective Factors

      Malaria is a disease caused by Plasmodium protozoa, which is transmitted through the bite of a female Anopheles mosquito. There are four different species of Plasmodium that can cause malaria in humans, with Plasmodium falciparum being the most severe. The other three types, including Plasmodium vivax, cause a milder form of the disease known as benign malaria.

      Several protective factors against malaria have been identified, including sickle-cell trait, G6PD deficiency, HLA-B53, and the absence of Duffy antigens. These factors can help reduce the risk of contracting the disease.

      To better understand the life cycle of the malaria parasite, an illustration is provided by the National Institute of Allergy and Infectious Diseases (NIAID). By understanding the causes, types, and protective factors of malaria, we can work towards preventing and treating this deadly disease.

    • This question is part of the following fields:

      • General Principles
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  • Question 40 - A study investigated the association between consuming a low-fibre diet and the risk...

    Incorrect

    • A study investigated the association between consuming a low-fibre diet and the risk of developing bowel cancer in individuals aged 50 and above.

      This cohort study followed 624 participants, out of which 268 consumed a low-fibre diet while the remaining consumed a high-fibre diet. The objective of the study was to determine the attributable risk of developing bowel cancer in each group over a period of 10 years.

      Among the group that consumed a high-fibre diet, 33 individuals developed bowel cancer during the study period. On the other hand, 81 participants in the low-fibre diet group developed bowel cancer.

      What is the attributable risk of developing bowel cancer in the group that consumed a low-fibre diet?

      Your Answer:

      Correct Answer: 0.2095

      Explanation:

      The attributable risk is the proportion of disease in the exposed group that can be attributed to the exposure, calculated as the rate in the exposed group minus the rate in the unexposed group. This measure is useful in determining the significance of a risk factor for a particular disease. For the given data, the attributable risk is 0.2095, calculated by subtracting the rate of disease in the unexposed group from the rate in the exposed group. The incorrect answers of 0.3949 and 3.2605 result from adding the rates and calculating the relative risk, respectively.

      Understanding Disease Rates and Relative Risk

      Disease rates are measurements used to monitor and establish causation of diseases, as well as to evaluate interventions. These rates are calculated by comparing the number of individuals with a disease to the total population. The attributable risk is a measure of the proportion of deaths in the exposed group that were caused by the exposure. It is calculated by subtracting the rate of the disease in the unexposed group from the rate in the exposed group.

      The relative risk, also known as the risk ratio, is a measure of the risk of an event relative to exposure. It is calculated by dividing the rate of the disease in the exposed group by the rate in the unexposed group. A relative risk of 1 indicates no difference between the two groups, while a relative risk of less than 1 means that the event is less likely to occur in the exposed group, and a relative risk of greater than 1 means that the event is more likely to occur in the exposed group.

      The population attributable risk is a measure of the reduction in incidence that would be observed if the population were entirely unexposed. It is calculated by multiplying the attributable risk by the prevalence of exposure in the population. The attributable proportion is the proportion of the disease that would be eliminated in a population if its disease rate were reduced to that of the unexposed group. Understanding these measures is important for evaluating the effectiveness of interventions and identifying risk factors for diseases.

    • This question is part of the following fields:

      • General Principles
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  • Question 41 - A 75-year-old woman is involved in a car accident resulting in a complex...

    Incorrect

    • A 75-year-old woman is involved in a car accident resulting in a complex fracture of the distal part of her humerus and damage to the radial nerve. Which movement is likely to be the most affected?

      Your Answer:

      Correct Answer: Wrist extension

      Explanation:

      Elbow extension will remain unaffected as the triceps are not impacted. However, the most noticeable consequence will be the loss of wrist extension.

      The Radial Nerve: Anatomy, Innervation, and Patterns of Damage

      The radial nerve is a continuation of the posterior cord of the brachial plexus, with root values ranging from C5 to T1. It travels through the axilla, posterior to the axillary artery, and enters the arm between the brachial artery and the long head of triceps. From there, it spirals around the posterior surface of the humerus in the groove for the radial nerve before piercing the intermuscular septum and descending in front of the lateral epicondyle. At the lateral epicondyle, it divides into a superficial and deep terminal branch, with the deep branch crossing the supinator to become the posterior interosseous nerve.

      The radial nerve innervates several muscles, including triceps, anconeus, brachioradialis, and extensor carpi radialis. The posterior interosseous branch innervates supinator, extensor carpi ulnaris, extensor digitorum, and other muscles. Denervation of these muscles can lead to weakness or paralysis, with effects ranging from minor effects on shoulder stability to loss of elbow extension and weakening of supination of prone hand and elbow flexion in mid prone position.

      Damage to the radial nerve can result in wrist drop and sensory loss to a small area between the dorsal aspect of the 1st and 2nd metacarpals. Axillary damage can also cause paralysis of triceps. Understanding the anatomy, innervation, and patterns of damage of the radial nerve is important for diagnosing and treating conditions that affect this nerve.

    • This question is part of the following fields:

      • Neurological System
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  • Question 42 - A 63-year-old man with a history of alcohol abuse presents with recurrent epigastric...

    Incorrect

    • A 63-year-old man with a history of alcohol abuse presents with recurrent epigastric pain. An OGD reveals the presence of varices in the lower esophagus. To prevent variceal bleeding, which medication would be the most suitable prophylactic option?

      Your Answer:

      Correct Answer: Propranolol

      Explanation:

      A non-cardioselective β blocker (NSBB) is the appropriate medication for prophylaxis against oesophageal bleeding in patients with varices. NSBBs work by causing splanchnic vasoconstriction, which reduces portal blood flow. Omeprazole, warfarin, and unfractionated heparin are not suitable options for this purpose.

      Variceal haemorrhage is a serious condition that requires prompt and effective management. The initial treatment involves resuscitation of the patient, correction of clotting abnormalities, and administration of vasoactive agents such as terlipressin or octreotide. Prophylactic IV antibiotics are also recommended to reduce mortality in patients with liver cirrhosis. Endoscopic variceal band ligation is the preferred method for controlling bleeding, and the use of a Sengstaken-Blakemore tube or Transjugular Intrahepatic Portosystemic Shunt (TIPSS) may be necessary if bleeding cannot be controlled. However, TIPSS can lead to exacerbation of hepatic encephalopathy, which is a common complication.

      To prevent variceal haemorrhage, prophylactic measures such as propranolol and endoscopic variceal band ligation (EVL) are recommended. Propranolol has been shown to reduce rebleeding and mortality compared to placebo. EVL is superior to endoscopic sclerotherapy and should be performed at two-weekly intervals until all varices have been eradicated. Proton pump inhibitor cover is given to prevent EVL-induced ulceration. NICE guidelines recommend offering endoscopic variceal band ligation for the primary prevention of bleeding for people with cirrhosis who have medium to large oesophageal varices.

    • This question is part of the following fields:

      • Gastrointestinal System
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  • Question 43 - A 55-year-old man complains of dyspepsia and undergoes an upper GI endoscopy, which...

    Incorrect

    • A 55-year-old man complains of dyspepsia and undergoes an upper GI endoscopy, which reveals the presence of Helicobacter pylori. A duodenal ulcer is found in the first part of the duodenum, and biopsies are taken. The biopsies show epithelium that resembles cells of the gastric antrum. What is the most probable cause of this condition?

      Your Answer:

      Correct Answer: Duodenal metaplasia

      Explanation:

      Metaplasia refers to the conversion of one cell type to another. Although metaplasia itself does not directly cause cancer, prolonged exposure to factors that trigger metaplasia can eventually lead to malignant transformations in cells. In cases of H-Pylori induced ulcers, metaplastic changes in the duodenal cap are commonly observed. However, these changes usually disappear after the ulcer has healed and eradication therapy has been administered.

      Metaplasia is a reversible process where differentiated cells transform into another cell type. This change may occur as an adaptive response to stress, where cells sensitive to adverse conditions are replaced by more resilient cell types. Metaplasia can be a normal physiological response, such as the transformation of cartilage into bone. The most common type of epithelial metaplasia involves the conversion of columnar cells to squamous cells, which can be caused by smoking or Schistosomiasis. In contrast, metaplasia from squamous to columnar cells occurs in Barrett’s esophagus. If the metaplastic stimulus is removed, the cells will revert to their original differentiation pattern. However, if the stimulus persists, dysplasia may develop. Although metaplasia is not directly carcinogenic, factors that predispose to metaplasia may induce malignant transformation. The pathogenesis of metaplasia involves the reprogramming of stem cells or undifferentiated mesenchymal cells present in connective tissue, which differentiate along a new pathway.

    • This question is part of the following fields:

      • Gastrointestinal System
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  • Question 44 - A 28-year-old woman visits her doctor with complaints of fatigue. Upon further inquiry,...

    Incorrect

    • A 28-year-old woman visits her doctor with complaints of fatigue. Upon further inquiry, the doctor learns that she has been experiencing heavy menstrual bleeding for the past 8 months. To investigate further, the doctor orders a complete blood count and iron level test. What is the typical lifespan of a red blood cell?

      Your Answer:

      Correct Answer: 120 days

      Explanation:

      The bone marrow in large bones is responsible for the production of human red blood cells through erythropoiesis. Stem cells undergo a 7-day development process to become red blood cells, which then circulate for around 120 days before being eliminated by the spleen. Eryptosis, or programmed red cell death, occurs at the same rate as production.

      However, certain diseases can increase the rate of eryptosis, resulting in a shorter lifespan for red blood cells. These diseases include haemolytic uraemic syndrome, sepsis, malaria, sickle cell disease, thalassaemia, iron deficiency, and Wilson’s disease.

      Iron deficiency anaemia is a prevalent condition worldwide, with preschool-age children being the most affected. The lack of iron in the body leads to a decrease in red blood cells and haemoglobin, resulting in anaemia. The primary causes of iron deficiency anaemia are excessive blood loss, inadequate dietary intake, poor intestinal absorption, and increased iron requirements. Menorrhagia is the most common cause of blood loss in pre-menopausal women, while gastrointestinal bleeding is the most common cause in men and postmenopausal women. Vegans and vegetarians are more likely to develop iron deficiency anaemia due to the lack of meat in their diet. Coeliac disease and other conditions affecting the small intestine can prevent sufficient iron absorption. Children and pregnant women have increased iron demands, and the latter may experience dilution due to an increase in plasma volume.

      The symptoms of iron deficiency anaemia include fatigue, shortness of breath on exertion, palpitations, pallor, nail changes, hair loss, atrophic glossitis, post-cricoid webs, and angular stomatitis. To diagnose iron deficiency anaemia, a full blood count, serum ferritin, total iron-binding capacity, transferrin, and blood film tests are performed. Endoscopy may be necessary to rule out malignancy, especially in males and postmenopausal females with unexplained iron-deficiency anaemia.

      The management of iron deficiency anaemia involves identifying and treating the underlying cause. Oral ferrous sulfate is commonly prescribed, and patients should continue taking iron supplements for three months after the iron deficiency has been corrected to replenish iron stores. Iron-rich foods such as dark-green leafy vegetables, meat, and iron-fortified bread can also help. It is crucial to exclude malignancy by taking an adequate history and appropriate investigations if warranted.

    • This question is part of the following fields:

      • Haematology And Oncology
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  • Question 45 - A 25-year-old female comes to the GP complaining of sudden eye pain and...

    Incorrect

    • A 25-year-old female comes to the GP complaining of sudden eye pain and vision changes. During the examination, the GP observes a significant relative afferent pupillary defect (RAPD) in her right eye. What will occur when the GP shines a penlight into her right eye?

      Your Answer:

      Correct Answer: No pupillary constriction in both eyes

      Explanation:

      The process of transmitting light through the afferent pathway begins with the retina receiving the light. An action potential is then generated in the optic nerve, which travels through the left and right lateral geniculate bodies. Finally, axons synapse at the left and right pre-tectal nuclei.

      When there is a defect in the afferent pathway, a relative afferent pupillary defect (RAPD) can occur. This is characterized by the absence of constriction in both pupils when a light is shined in the affected eye. For example, if there is a RAPD in the left eye, shining the light in the left eye will result in absent constriction in both pupils, while shining the light in the right eye will result in constriction of both pupils.

      In this question, there is a RAPD in the right eye. Therefore, shining the light in the right eye will result in absent constriction in both eyes. Any answers indicating full or partial constriction in one or both pupils are incorrect.

      A relative afferent pupillary defect, also known as the Marcus-Gunn pupil, can be identified through the swinging light test. This condition is caused by a lesion that is located anterior to the optic chiasm, which can be found in the optic nerve or retina. When light is shone on the affected eye, it appears to dilate while the normal eye remains unchanged.

      The causes of a relative afferent pupillary defect can vary. For instance, it may be caused by a detachment of the retina or optic neuritis, which is often associated with multiple sclerosis. The pupillary light reflex pathway involves the afferent pathway, which starts from the retina and goes through the optic nerve, lateral geniculate body, and midbrain. The efferent pathway, on the other hand, starts from the Edinger-Westphal nucleus in the midbrain and goes through the oculomotor nerve.

    • This question is part of the following fields:

      • Neurological System
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  • Question 46 - A 62-year-old patient with multiple comorbidities, including atrial fibrillation, type 2 diabetes mellitus,...

    Incorrect

    • A 62-year-old patient with multiple comorbidities, including atrial fibrillation, type 2 diabetes mellitus, mild arthritis of the knees, gastric oesophageal reflux disease and high cholesterol, is on several medications. The patient underwent a kidney transplant a few weeks ago and is now visiting the general practitioner with concerns about a persistent rise in blood sugar levels, blurry vision, increased thirst, and fatigue. Which medication is most likely responsible for these symptoms?

      Your Answer:

      Correct Answer: Tacrolimus

      Explanation:

      Tacrolimus: An Immunosuppressant for Transplant Rejection Prevention

      Tacrolimus is an immunosuppressant drug that is commonly used to prevent transplant rejection. It belongs to the calcineurin inhibitor class of drugs and has a similar action to ciclosporin. The drug works by reducing the clonal proliferation of T cells by decreasing the release of IL-2. It binds to FKBP, forming a complex that inhibits calcineurin, a phosphatase that activates various transcription factors in T cells. This is different from ciclosporin, which binds to cyclophilin instead of FKBP.

      Compared to ciclosporin, tacrolimus is more potent, resulting in a lower incidence of organ rejection. However, it is also associated with a higher risk of nephrotoxicity and impaired glucose tolerance. Despite these potential side effects, tacrolimus remains an important drug in preventing transplant rejection and improving the success of organ transplantation.

    • This question is part of the following fields:

      • General Principles
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  • Question 47 - A 12-year-old boy comes to the GP after experiencing unusual behavior. His mother...

    Incorrect

    • A 12-year-old boy comes to the GP after experiencing unusual behavior. His mother accompanies him and reports that her son suddenly started smacking his lips together for a brief period. She adds that he then complained of smelling a foul odor that she couldn't detect. Given the family history of epilepsy, you suspect that he may have had a seizure. What type of seizure is typically associated with these symptoms?

      Your Answer:

      Correct Answer: Temporal lobe seizure

      Explanation:

      Temporal lobe seizures can lead to hallucinations, including olfactory hallucinations, which is likely the cause of this patient’s presentation.

      Flashes and floaters are a common symptom of occipital lobe seizures.

      Juvenile myoclonic epilepsy can cause occasional generalized seizures and daytime absences.

      Parietal lobe seizures can result in paraesthesia.

      Localising Features of Focal Seizures in Epilepsy

      Focal seizures in epilepsy can be localised based on the specific location of the brain where they occur. Temporal lobe seizures are common and may occur with or without impairment of consciousness or awareness. Most patients experience an aura, which is typically a rising epigastric sensation, along with psychic or experiential phenomena such as déjà vu or jamais vu. Less commonly, hallucinations may occur, such as auditory, gustatory, or olfactory hallucinations. These seizures typically last around one minute and are often accompanied by automatisms, such as lip smacking, grabbing, or plucking.

      On the other hand, frontal lobe seizures are characterised by motor symptoms such as head or leg movements, posturing, postictal weakness, and Jacksonian march. Parietal lobe seizures, on the other hand, are sensory in nature and may cause paraesthesia. Finally, occipital lobe seizures may cause visual symptoms such as floaters or flashes. By identifying the specific location and type of seizure, doctors can better diagnose and treat epilepsy in patients.

    • This question is part of the following fields:

      • Neurological System
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  • Question 48 - An 77-year-old woman visits her doctor complaining of loose teeth and mucosal ulcers...

    Incorrect

    • An 77-year-old woman visits her doctor complaining of loose teeth and mucosal ulcers that won't heal. She has a medical history of asthma, diabetes, and recurrent falls, as well as having undergone bilateral hip replacement surgery. Upon examination, the doctor notes periodontal disease, while radiology reports reveal sclerotic lesions in the mandible and maxilla that are indicative of osteonecrosis. Which medication could be responsible for her symptoms?

      Your Answer:

      Correct Answer: Alendronate

      Explanation:

      Osteonecrosis of the jaw is a potential side effect of bisphosphonates, particularly alendronate, and the risk increases with prolonged use. However, the other options listed are not associated with this condition. While denosumab is also linked to osteonecrosis of the jaw, it is less common than with bisphosphonates. It is unlikely that the patient is taking denosumab as there is no mention of any contraindications to bisphosphonates, and alendronate is the first-line drug for bone protection. Additionally, denosumab is significantly more expensive than alendronate.

      Bisphosphonates: Uses, Adverse Effects, and Patient Counselling

      Bisphosphonates are drugs that mimic the action of pyrophosphate, a molecule that helps prevent bone demineralization. They work by inhibiting osteoclasts, the cells responsible for breaking down bone tissue. Bisphosphonates are commonly used to prevent and treat osteoporosis, hypercalcemia, Paget’s disease, and pain from bone metastases.

      However, bisphosphonates can cause adverse effects such as oesophageal reactions, osteonecrosis of the jaw, and an increased risk of atypical stress fractures of the proximal femoral shaft in patients taking alendronate. Patients may also experience an acute phase response, which includes fever, myalgia, and arthralgia following administration. Hypocalcemia may also occur due to reduced calcium efflux from bone, but this is usually clinically unimportant.

      To minimize the risk of adverse effects, patients taking oral bisphosphonates should swallow the tablets whole with plenty of water while sitting or standing. They should take the medication on an empty stomach at least 30 minutes before breakfast or another oral medication and remain upright for at least 30 minutes after taking the tablet. Hypocalcemia and vitamin D deficiency should be corrected before starting bisphosphonate treatment. However, calcium supplements should only be prescribed if dietary intake is inadequate when starting bisphosphonate treatment for osteoporosis. Vitamin D supplements are usually given.

      The duration of bisphosphonate treatment varies depending on the level of risk. Some experts recommend stopping bisphosphonates after five years if the patient is under 75 years old, has a femoral neck T-score of more than -2.5, and is at low risk according to FRAX/NOGG.

    • This question is part of the following fields:

      • Musculoskeletal System And Skin
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  • Question 49 - A builder in his 40s falls off a ladder while laying roof tiles...

    Incorrect

    • A builder in his 40s falls off a ladder while laying roof tiles and suffers a burst fracture of L3. The MRI scan reveals complete nerve transection at this level due to the injury. What clinical sign will be absent in the beginning?

      Your Answer:

      Correct Answer: Extensor plantar response

      Explanation:

      In cases of lower motor neuron lesions, there is a reduction in various features such as muscle strength, muscle size, reflexes, and the occurrence of muscle fasciculation.

      The spinal cord is a central structure located within the vertebral column that provides it with structural support. It extends rostrally to the medulla oblongata of the brain and tapers caudally at the L1-2 level, where it is anchored to the first coccygeal vertebrae by the filum terminale. The cord is characterised by cervico-lumbar enlargements that correspond to the brachial and lumbar plexuses. It is incompletely divided into two symmetrical halves by a dorsal median sulcus and ventral median fissure, with grey matter surrounding a central canal that is continuous with the ventricular system of the CNS. Afferent fibres entering through the dorsal roots usually terminate near their point of entry but may travel for varying distances in Lissauer’s tract. The key point to remember is that the anatomy of the cord will dictate the clinical presentation in cases of injury, which can be caused by trauma, neoplasia, inflammatory diseases, vascular issues, or infection.

      One important condition to remember is Brown-Sequard syndrome, which is caused by hemisection of the cord and produces ipsilateral loss of proprioception and upper motor neuron signs, as well as contralateral loss of pain and temperature sensation. Lesions below L1 tend to present with lower motor neuron signs. It is important to keep a clinical perspective in mind when revising CNS anatomy and to understand the ways in which the spinal cord can become injured, as this will help in diagnosing and treating patients with spinal cord injuries.

    • This question is part of the following fields:

      • Neurological System
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  • Question 50 - Which type of cell makes up the majority of yellow bone marrow? ...

    Incorrect

    • Which type of cell makes up the majority of yellow bone marrow?

      Your Answer:

      Correct Answer: Adipocytes

      Explanation:

      Anatomy of Bones and Bone Marrow

      Bones are composed of two types of bone tissue: compact bone and cancellous bone. The medullary cavity is located within the cancellous bone and contains trabeculae. Blood vessels and bone marrow are also present within the cavity. The bone marrow is responsible for producing blood cells, with red marrow being the site of active haematopoiesis. Yellow marrow, on the other hand, is predominantly made up of adipocytes and fibroblasts.

      Chondrocytes are specialized cells found in cartilage that secrete the collagen matrix. Fibroblasts also contribute to the extracellular matrix by secreting collagen. Haematopoietic stem cells are found in bone marrow and are the common ancestor of all haematologic cells. Megakaryocytes, which are also found in bone marrow, are the precursor to platelets. the anatomy of bones and bone marrow is crucial in their functions and the processes that occur within them.

    • This question is part of the following fields:

      • Clinical Sciences
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