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Question 1
Correct
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Which of the following statements is true about an acute pulmonary embolism?
Your Answer: Thrombolysis administered through a peripheral vein is as effective as through a pulmonary artery catheter
Explanation:Acute pulmonary embolism occurs when a blood clot becomes embedded in a pulmonary artery and restricts lung blood flow.
Thrombolysis is recommended in patients with extremely compromised circulation rather than reduced oxygen in the blood. It is effective when administered via a peripheral vein or a pulmonary artery catheter.
Anticoagulant therapy (heparin use) decreases the risk of further embolic evens and decreases constriction of pulmonary vessels.
An ECG may be normal in patients with an acute pulmonary embolism.
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This question is part of the following fields:
- Pathophysiology
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Question 2
Incorrect
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All the following statements are false regarding nitrous oxide except:
Your Answer: Decreases the cerebral metabolic rate of oxygen consumption (CMRO2)
Correct Answer: Maintains carbon dioxide reactivity
Explanation:Nitrous oxide increases cerebral blood flow by direct cerebral stimulation and tends to elevate intracranial pressure (ICP)
It increases the cerebral metabolic rate of oxygen consumption (CMRO2)
It is not an NMDA agonist as it antagonizes NMDA receptors.
Cerebral autoregulation is impaired with the use of nitrous oxide but when used with propofol, it is maintained.
Carbon dioxide reactivity is not affected by it.
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This question is part of the following fields:
- Pharmacology
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Question 3
Incorrect
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The statement that best describes the classification of theatre equipment in terms of electrical safety is:
Your Answer: Class II equipment does need connection to earth
Correct Answer: A floating circuit is equipment applied to patient that is isolated from all its other parts
Explanation:There are different classes of electrical equipment that can be classified in the table below:
Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply
Class II – provides double insulation for all equipment. It does not require an earth.
Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.
Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)
Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.
Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF).
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This question is part of the following fields:
- Clinical Measurement
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Question 4
Correct
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Which compound is secreted only from the adrenal medulla?
Your Answer: Adrenaline
Explanation:The adrenal medulla comprises chromaffin cells (pheochromocytes), which are functionally equivalent to postganglionic sympathetic neurons. They synthesize, store and release the catecholamines noradrenaline (norepinephrine) and adrenaline (epinephrine) into the venous sinusoids.
The majority of the chromaffin cells synthesize adrenaline. -
This question is part of the following fields:
- Anatomy
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Question 5
Correct
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After consuming 12 g of paracetamol, a 37-year-old man is admitted to the medical admissions unit. He has hepatocellular necrosis in both clinical and biochemical aspects. The most significant reason for paracetamol causing toxicity is?
Your Answer: Glutathione is rapidly exhausted
Explanation:Phase I and phase II metabolism are used by the liver to break down paracetamol.
1st Phase:
Prostaglandin synthetase and cytochrome P450 (CYP1A2, CYP2E2, CYP3A4 and CYP2D6) to N-acetyl-p-benzoquinoneimine (NAPQI) and N-acetylbenzo-semiquinoneimine. NAPQI is a toxic metabolite that binds to the sulfhydryl groups of cellular proteins in hepatocytes, making it toxic. This can result in centrilobular necrosis.
Glutathione and glutathione transferases prevent NAPQI from binding to hepatocytes at low paracetamol doses by preferentially binding to these toxic metabolites. The cysteine and mercapturic acid conjugates are then excreted in the urine. Depletion of glutathione occurs at higher doses of paracetamol, resulting in high levels of NAPQI and the risk of hepatocellular damage. Hepatotoxicity would not be an issue if the body’s glutathione stores were sufficient.
N-acetylcysteine is a precursor for glutathione synthesis and is the drug of choice for the treatment of paracetamol overdose.
Phase II:
Conjugation with glucuronic acid to paracetamol glucuronide is the most common method of metabolism and excretion, accounting for 60% of renally excreted metabolites. Paracetamol sulphate (35%), unchanged paracetamol (5%), and mercapturic acid are among the other renally excreted metabolites (3 percent ). The capacity of conjugation pathways is limited. The capacity of the sulphate conjugation pathway is lower than that of the glucuronidation pathway.
Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is extremely high, approaching 100%.
As a result, measuring paracetamol levels in plasma after an injury is important. Peak plasma concentrations are reached after 30-60 minutes, with a volume of distribution of 0.95 L/kg. It binds to plasma proteins at a rate of 10% to 25%.
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This question is part of the following fields:
- Pharmacology
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Question 6
Incorrect
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The mandibular division of the trigeminal nerve passes through which anatomic structure?
Your Answer: Stylomastoid foramen
Correct Answer: Foramen ovale
Explanation:The mandibular branch of the trigeminal nerve passes through the foramen ovale. Other structures that pass through this foramen are the accessory meningeal artery, and occasionally, the lesser petrosal nerve.
These are the structures that pass through the other openings in the cranial fossa:
Foramen rotundum – Maxillary branch of the trigeminal nerve
Foramen lacerum – Greater petrosal nerve, traversed by the internal carotid artery
Superior orbital fissure – Oculomotor nerve; trochlear nerve; lacrimal, frontal and nasociliary branches of the ophthalmic branch of the trigeminal nerve; abducens nerve, superior ophthalmic vein
Stylomastoid foramen – facial nerve.
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This question is part of the following fields:
- Anatomy
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Question 7
Correct
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Which of the following statements is not correct regarding dopamine?
Your Answer: Crosses the blood brain barrier
Explanation:Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic α and β1 (but not β2 ) agonist.
The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.
Moderately high doses produce a positive inotropic (direct β1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.
Vasoconstriction (α1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular α and β receptors; does not penetrate the blood-brain barrier€”no CNS effects.
Dopamine is used in patients with cardiogenic or septic shock and severe CHF wherein it increases BP and urine outflow.
It is administered by i.v. infusion (0.2€“1 mg/min) which is regulated by monitoring BP and rate of urine formation
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This question is part of the following fields:
- Pharmacology
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Question 8
Incorrect
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Regarding the Valsalva manoeuvre, which of the following describes the cardiovascular changes in phase III in a normal patient?
Your Answer: Increased intrathoracic pressure, decrease in blood pressure, and increase in heart rate
Correct Answer: Normal intrathoracic pressure, decrease in blood pressure, and increase in heart rate
Explanation:When a person forcefully expires against a closed glottis, changes occur in intrathoracic pressure that dramatically affect venous return, cardiac output, arterial pressure, and heart rate. This forced expiratory effort is called a Valsalva maneuver.
Initially during a Valsalva, intrathoracic (intrapleural) pressure becomes very positive due to compression of the thoracic organs by the contracting rib cage. This increased external pressure on the heart and thoracic blood vessels compresses the vessels and cardiac chambers by decreasing the transmural pressure across their walls. Venous compression, and the accompanying large increase in right atrial pressure, impedes venous return into the thorax. This reduced venous return, and along with compression of the cardiac chambers, reduces cardiac filling and preload despite a large increase in intrachamber pressures. Reduced filling and preload leads to a fall in cardiac output by the Frank-Starling mechanism. At the same time, compression of the thoracic aorta transiently increases aortic pressure (phase I); however, aortic pressure begins to fall (phase II) after a few seconds because cardiac output falls. Changes in heart rate are reciprocal to the changes in aortic pressure due to the operation of the baroreceptor reflex. During phase I, heart rate decreases because aortic pressure is elevated; during phase II, heart rate increases as the aortic pressure falls.
When the person starts to breathe normally again, the intrathoracic pressure declines to normal levels, the aortic pressure briefly decreases as the external compression on the aorta is removed, and heart rate briefly increases reflexively (phase III). This is followed by an increase in aortic pressure (and reflex decrease in heart rate) as the cardiac output suddenly increases in response to a rapid increase in cardiac filling (phase IV). Aortic pressure also rises above normal because of a baroreceptor, sympathetic-mediated increase in systemic vascular resistance that occurred during the Valsava.
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This question is part of the following fields:
- Pathophysiology
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Question 9
Correct
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What makes the ultrasound nebulizer efficient?
Your Answer: Reduction in gas flow resistance
Explanation:Smallest drops reach not only the upper but also the lower respiratory tracks. As a result, the ultrasonic nebulizer is most efficient for the therapy of pulmonary diseases and stands out as a robust and reliable support within the clinical setting.
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This question is part of the following fields:
- Basic Physics
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Question 10
Correct
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Regarding the plateau phase of the cardiac potential, which electrolyte is the main determinant?
Your Answer: Ca2+
Explanation:The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology
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Question 11
Correct
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A 25-year old man needs an emergency appendicectomy and has gone to the operating room. During general anaesthesia, ventilation is achieved using a circle system with a fresh gas flow (FGF) of 1L/min, with and air/oxygen and sevoflurane combination. The capnograph trace is normal. Changes to the end tidal and baseline CO2 measurements at 10 and 20 mins respectively are seen on the capnograph below: (10 minutes and 20 minutes). End-tidal CO2 4.9 kPa, 8.4 kPa. Baseline end-tidal CO2 0.2 kPa, 2.4 kPa. The other vitals were as follows: Pulse 100-105 beats per minute, Systolic blood pressure 120-133 mmHg, O2 saturation 99%. The next most important immediate step is which of the following?
Your Answer: Increase the FGF
Explanation:This scenario describes rebreathing management.
Changes is exhaustion of the soda lime and a progressive rise in circuit deadspace is the most likely explanation for the capnograph.
It is important that the soda lime canister is inspected for a change in colour of the granules. Initially fresh gas flow should be increased and then if necessary, replace the soda lime granules. Other strategies include changing to another circuit or bypassing the soda lime canister after the fresh gas flow is increased.
Any other causes of increased equipment deadspace should be excluded.
Intraoperative hypercarbia can be caused by:
1. Hypoventilation – Breathing spontaneously; drugs which include anaesthetic agents, opioids, residual neuromuscular blockade, pre-existing respiratory or neuromuscular disease and cerebrovascular accident.
2. Controlled ventilation- circuit leaks, disconnection, miscalculation of patient’s minute volume.
3. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits, increased breathing system deadspace.
4. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
5. Exogenous source – Absorption of CO2 absorption from the pneumoperitoneum. -
This question is part of the following fields:
- Physiology
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Question 12
Correct
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Risk stratification is done prior to a major cardiac surgery using cardiopulmonary exercise testing. Given the following options, which one is most likely to have the highest risk for post-operative cardiac morbidity?
Your Answer: Anaerobic threshold (AT) of less than 11 mL/kg/minute
Explanation:The ventilatory anaerobic threshold (VAT), formerly referred to as the anaerobic threshold, is an index used to estimate exercise capacity. During the initial (aerobic) phase of CPET, which lasts until 50€“60% of Vo2max is reached, expired ventilation (VE) increases linearly with Vo2 and reflects aerobically produced CO2 in the muscles. Blood lactate levels do not change substantially during this phase, since muscle lactic acid production is minimal.
During the latter half of exercise, anaerobic metabolism occurs because oxygen supply cannot keep up with the increasing metabolic requirements of exercising muscles. At this time, there is a significant increase in lactic acid production in the muscles and in the blood lactate concentration. The Vo2 at the onset of blood lactate accumulation is called the lactate threshold or the VAT. The VAT is also defined as the point at which minute ventilation increases disproportionately relative to Vo2, a response that is generally seen at 60€“70% of Vo2max.
The VAT is a useful measure as work below this level encompasses most daily living activities. The ability to achieve the VAT can help distinguish cardiac and non€�cardiac (pulmonary or musculoskeletal) causes of exercise limitation, since patients who fatigue before reaching VAT are likely to have a non€�cardiac problem.
When VAT is detected, patients with PVo2 of ©½10€…ml/kg/min have a high event rate.
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This question is part of the following fields:
- Pathophysiology
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Question 13
Correct
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A 50-year-old woman is brought into the emergency department in an ambulance. She was found collapsed on the street. She has visual and oculomotor deficits on examination, but her motor function is intact. A digital subtraction angiography is performed that shows occlusion of the basilar artery at the site where the vertebral arteries fuse to form the basilar artery. Which anatomical landmark corresponds to this site of occlusion?
Your Answer: The base of the pons
Explanation:The basilar artery is a large vessel that is formed by the union of the vertebral arteries at the junction of the medulla and pons. It lies in the pontine cistern and follows a shallow groove on the ventral pontine surface, extending to the upper border of the pons.
The basilar artery then bifurcates into the two posterior cerebral arteries that form part of the Circle of Willis.
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This question is part of the following fields:
- Anatomy
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Question 14
Correct
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Which of the following is true about the bispectral index (BIS)?
Your Answer: Sevoflurane lowers BIS more than ketamine
Explanation:The bispectral index (BIS) monitors works to determine the level of consciousness of a patient by processing electroencephalographic (EEG) signals to obtain a value between 0 and 100, where 0 reflects no brain activity, and 100 reflects a patient is completely awake.
The general meaning of BIS values are:
>95: Patient is in an awake state.
65-85: Patient is in a sedated state.
40-65: Patient is in a state that is optimal for general surgery.
<40: Patient is in a deep hypnotic stateIt is important in measuring the depths of anaesthesia to prevent haemodynamic changes or patient awareness during surgery.
The nature of anaesthetic agent used is a determinant factor in resultant BIS values. Intravenous agents, such as propofol, thiopental and midazolam, result in a deeper hypnotic state, whilst inhalation agents have a lesser hypnotic effect at the same BIS values. Certain agents result in inaccurate BIS values such as ketamine and nitrous oxide (NO). These two agents appear to increase the BIS value, whilst putting the patient in a deeper hypnotic state, and should therefore not be used with BIS monitoring.
Hypothermia also affects the BIS value as it causes a 1.12 per °C decrease in body temperature.
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This question is part of the following fields:
- Clinical Measurement
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Question 15
Incorrect
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An 80-year-old female suffered a TIA 2 weeks ago. She has been admitted to the vascular ward as she will be undergoing carotid endarterectomy tomorrow morning. To explain the procedure and its complications, the surgeon gives her information about the procedure, telling her the artery will be tied during the operation. She inquires about the areas supplied by the different arteries. You explain that the internal carotid artery supplies the brain while the external carotid artery ascends the neck and bifurcates into two arteries. One of these arteries is the superficial temporal artery. Which of the following is the second branch?
Your Answer: Facial artery
Correct Answer: Maxillary artery
Explanation:Carotid endarterectomy is the procedure to relieve an obstruction in the carotid artery by opening the artery at its origin and stripping off the atherosclerotic plaque with the intima. This procedure is performed to prevent further episodes, especially in patients who have suffered ischemic strokes or transient ischemic attacks.
The external carotid artery terminates by dividing into the superficial temporal and maxillary branches. The maxillary artery is the larger of the two terminal branches and arises posterior to the neck of the mandible.
The other arteries mentioned in the answer options branch off from the following:
Temporal arteries from the maxillary artery
Middle meningeal artery from the maxillary artery
Lingual artery from the anterior aspect of the external carotid artery
Facial artery from the anterior aspect of the external carotid artery. -
This question is part of the following fields:
- Anatomy
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Question 16
Correct
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In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks. Which of the following indicates the most important reason for using epinephrine?
Your Answer: Preferential distribution of blood to the coronary and cerebral circulation
Explanation:Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (α1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a β1 and β2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
– Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
– Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal. -
This question is part of the following fields:
- Pathophysiology
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Question 17
Correct
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Which of the following is not used in the treatment of Neuroleptic Malignant Syndrome?
Your Answer: Olanzapine
Explanation:The neuroleptic malignant syndrome (NMS) is a rare complication in response to neuroleptic or antipsychotic medication.
The main features are:
– Elevated creatinine kinase
– Hyperthermia and tachycardia
– Altered mental state
– Increased white cell count
– Insidious onset over 1-3 days
– Extrapyramidal dysfunction (muscle rigidity, tremor, dystonia)
– Autonomic dysfunction (Labile blood pressure, sweating, salivation, urinary incontinence)Management is supportive of ICU care, anticholinergic drugs, increasing dopaminergic activity with Amantadine, L-dopa, and dantrolene, and non- depolarising neuromuscular blockade drugs.
Since Olanzapine is a potential cause of NMS it is not a treatment.
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This question is part of the following fields:
- Pharmacology
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Question 18
Correct
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Following a traumatic head injury, you are summoned to the emergency department to transfer a patient to the CT scanner. With a Glasgow coma score of 3, he has already been intubated and ventilated. It is important to ensure that cerebral protection strategies are implemented during the transfer. Which of the following methods is the most effective for reducing venous obstruction?
Your Answer: Position with a head-up tilt of 30°
Explanation:ICP is significant because it influences cerebral perfusion pressure and cerebral blood flow. The normal ICP ranges from 5 to 13 mmHg.
The components within the skull include the brain (80%/1400 ml), blood (10%/150 ml), and cerebrospinal fluid (CSF) (10%/150 ml).
Because the skull is a rigid box, if one of the three components increases in volume, one or more of the remaining components must decrease in volume to compensate, or the ICP will rise (Monroe-Kellie hypothesis).
Primary brain injury occurs as a result of a head injury and is unavoidable unless precautions are taken to reduce the risk of head injury. A reduction in oxygen delivery due to hypoxemia (low arterial PaO2) or anaemia, a reduction in cerebral blood flow due to hypotension or reduced cardiac output, and factors that cause a raised ICP and reduced CPP are all causes of secondary brain injury. Secondary brain injury can be avoided with proper management.
The most important initial management task is to make certain that:
There is protection of the airway and the cervical spine
There is proper ventilation and oxygenation
Blood pressure and cerebral perfusion pressure are both adequate (CPP).Following the implementation of these management principles, additional strategies to reduce ICP and preserve cerebral perfusion are required. The volume of one or more of the contents of the skull can be reduced using techniques that can be used to reduce ICP.
Reduce the volume of brain tissue
Blood volume should be reduced.
CSF volume should be reduced.The following are some methods for reducing the volume of brain tissue:
Abscess removal or tumour resection
Steroids (especially dexamethasone) are used to treat oedema in the brain.
To reduce intracellular volume, use mannitol/furosemide or hypertonic saline.
To increase intracranial volume, a decompressive craniectomy is performed.The following are some methods for reducing blood volume:
Haematomas must be evacuated.
Barbiturate coma reduces cerebral metabolic rate and oxygen consumption, lowering cerebral blood volume as a result.
Hypoxemia, hypercarbia, hyperthermia, vasodilator drugs, and hypotension should all be avoided in the arterial system.
PEEP/airway obstruction/CVP lines in neck: patient positioning with 30° head up, avoid neck compression with ties/excessive rotation, avoid PEEP/airway obstruction/CVP lines in neckThe following are some methods for reducing CSF volume:
To reduce CSF volume, an external ventricular drain or a ventriculoperitoneal shunt is inserted (although more a long term measure).
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This question is part of the following fields:
- Pathophysiology
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Question 19
Incorrect
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Obeying Boyle's law and Charles's law is a characteristic feature of an ideal gas. The gas which is most ideal out of the following options is?
Your Answer: Xenon
Correct Answer: Helium
Explanation:The ideal gas equation makes the following assumptions:
The gas particles have a small volume in comparison to the volume occupied by the gas.
Between the gas particles, there are no forces of interaction.
Individual gas particle collisions, as well as gas particle collisions with container walls, are elastic, meaning momentum is conserved.
PV = nRT
Where:P = pressure
V = volume
n = moles of gas
T = temperature
R = universal gas constantHelium is a monoatomic gas with a small helium atom. The attractive forces between helium atoms are small because the helium atom is spherical and has no dipole moment. Because helium atoms are spherical, collisions between them approach the ideal state of elasticity.
Most real gases behave qualitatively like ideal gases at standard temperatures and pressures. When intermolecular forces and molecular size become important, the ideal gas model tends to fail at lower temperatures or higher pressures. It also fails to work with the majority of heavy gases.
Helium, argon, neon, and xenon are noble or inert gases that behave the most like an ideal gas. Xenon is a noble gas with a much larger atomic size than helium.
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This question is part of the following fields:
- Pharmacology
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Question 20
Correct
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A 70-year-old man collapsed at home. He was brought into the emergency department in an ambulance. His wife tells you that he complained of sudden lower back pain just before he collapsed. He is pale and hypotensive. You suspect a ruptured abdominal aortic aneurysm. What vertebral level does this affected vessel terminate?
Your Answer: L4
Explanation:The abdominal aorta begins at the level of the body of T12 near the midline, as a continuation of the thoracic aorta. It descends and bifurcates at the level of L4 into the common iliac arteries.
An abdominal aortic aneurysm is a swelling in the abdominal aorta. It most commonly occurs in men over 65 years old of age. Smoking, diabetes, hypertension, and hypercholesterolemia are other risk factors contributing to the disease.
The NHS screening program for abdominal aortic aneurysms involves an ultrasound test for men aged 65 or over if they have not undergone screening for a one-off screening test.
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This question is part of the following fields:
- Anatomy
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Question 21
Correct
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A 27-year-old woman takes part in a study looking into the effects of different dietary substrates on metabolism. She receives a 24-hour ethyl alcohol infusion. A constant volume, closed system respirometer is used to measure CO2 production and consumption. The production of carbon dioxide is found to be 200 mL/minute. Which of the following values most closely resembles her anticipated O2 consumption at the conclusion of the trial?
Your Answer: 300 mL/minute
Explanation:The respiratory quotient (RQ) is the ratio of CO2 produced by the body to O2 consumed in a given amount of time.
CO2 produced / O2 consumed = RQ
CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.
The RQ will change depending on the energy substrates consumed in the diet. Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.
Glucose and other hexose sugars (glucose and other hexose sugars):
RQ=1Fats:
RQ = 0.7Proteins:
Approximately 0.9 RQEthyl alcohol is a type of alcohol.
200/300 = 0.67 RQ
For complete oxidation, lipids and alcohol require more oxygen than carbohydrates.
When carbohydrate is converted to fat, the RQ can rise above 1.0. Fat deposition and weight gain are likely to occur in these circumstances.
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This question is part of the following fields:
- Physiology
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Question 22
Correct
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A 35-year-old female, presents to the emergency department via ambulance. The paramedics have noted the patient's symptoms as unilateral left-sided weakness of the upper and lower limbs, homonymous hemianopia and dysphasia. She has previous personal and family history of deep vein thromboses. The report of her CT scan suggests a stroke involving the middle cerebral artery. Post recovery, she undergoes further diagnostic investigations to determine the cause of a stroke at her young age. She is eventually diagnosed with a hypercoagulable state disease called Factor V Leiden thrombophilia. An emboli in the middle cerebral artery results in dysfunction of which areas of the brain?
Your Answer: Frontal, temporal and parietal lobes
Explanation:The middle cerebral artery is a part of the circle of Willis system of anastomosis within the brain, and the most often affected by brain pathology.
The primary function of the middle cerebral artery is providing oxygenated blood to related regions of the brain. It achieves this by giving off different branches to supply different brain regions, namely:
The cortical branches: which supplies the primary motor and somatosensory cortical areas of some parts of the face, trunk and upper limbs.
The small central branches: which supply the basal ganglia and internal capsule via the lenticulostriate vessels.
The superior division: which supplies the lateral inferior frontal lobe, including the Broca area which is responsible for production of speech, language comprehension, and writing.
The inferior division: which supplies the superior temporal gyrus, including Wernicke’s area which controls speech comprehension and language development.
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This question is part of the following fields:
- Anatomy
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Question 23
Correct
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Which of the following best describes the phenomenon of higher partial pressures of oxygen in the alveoli (PAO2) in the lung apices when in the upright position?
Your Answer: The ventilation/perfusion (V/Q) ratio is greater than in the basal units
Explanation:The ventilation/perfusion ratio varies in different areas of the lung. In an upright individual, although both ventilation and perfusion increase from the apex to the base of the lung, the increase in ventilation is less than the increase in blood flow. As a result, the normal V̇ /Q̇ ratio at the apex of the lung is much greater than 1 (ventilation exceeds perfusion), whereas the V̇ /Q̇ ratio at the base of the lung is much less than 1 (perfusion exceeds ventilation).
There is more volume in the alveoli found in the apices than in the bases of the lungs. This is due to the weight of the lung stretching the apical alveoli to the maximum size. Also, the weight of the lungs pull themselves away from the chest wall, creating a negative intrapleural pressure. These factors, however, do not directly affect the PAO2.
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This question is part of the following fields:
- Pathophysiology
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Question 24
Correct
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Regarding the emergency oxygen flush, which is true?
Your Answer: May lead to awareness if used inappropriately
Explanation:When the emergency oxygen flush is pressed, 100% oxygen is supplied from the common gas outlet. This gas bypasses BOTH flowmeters and vaporisers. The flow of oxygen is usually 45 l/min at a PRESSURE OF 400 kPa.
There is an increased risk of pulmonary barotrauma when the emergency flush is pressed, especially when anaesthetising paediatric patients.
The inappropriate use of the flush causes dilution of anaesthetic gases and this increases the possibility of anaesthetic awareness.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 25
Incorrect
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A 50-year-old male is planned for elective parotidectomy for pleomorphic adenoma. The surgeon intends to use a nerve integrity monitor thus avoiding neuromuscular blockade. Which of the following nerves is liable to injury in parotidectomy?
Your Answer: Vagus nerve
Correct Answer: Facial nerve
Explanation:Parotidectomy is basically an anatomical dissection. Identification of the facial nerve trunk is essential during parotid gland surgery because facial nerve injury is the most daunting potential complication of parotid gland surgery owing to the close relation between the gland and the extratemporal course of the facial nerve. After exiting the stylomastoid foramen, the facial nerve enters the substance of the parotid gland and then gives off five terminal branches:
From superior to inferior, these are the:
– Temporal branch supplying the extrinsic ear muscles, occipitofrontalis and orbicularis oculi
– Zygomatic branch supplying orbicularis oculi
– Buccal branch supplying buccinator and the lip muscles
– Mandibular branch supplying the muscles of the lower lip and chin
– Cervical branch supplying platysma.There are two approaches to identify the facial nerve trunk during parotidectomy€”conventional antegrade dissection of the facial nerve, and retrograde dissection. Numerous soft tissue and bony landmarks have been proposed to assist the surgeon in the early identification of this nerve. Most commonly used anatomical landmarks to identify facial nerve trunk are stylomastoid foramen, tympanomastoid suture (TMS), posterior belly of digastric (PBD), tragal pointer (TP), mastoid process and peripheral branches of the facial nerve.
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This question is part of the following fields:
- Anatomy
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Question 26
Incorrect
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Regarding the information about kidney, which of the following is true?
Your Answer: The kidneys receive 10% of cardiac output at rest
Correct Answer: Each kidney contains approximately 1.2 million nephrons
Explanation:Each kidney is composed of about 1.2 million uriniferous tubules. Each tubule consists of two parts that are embryologically distinct from each other. They are as follows:
a) Excretory part, called the nephron, which elaborates urine
b) Collecting part which begins as a junctional tubule from the distal convoluted tubule.There are two types of nephrons in the kidney:
The cortical nephron comprises 80% of the total nephron and its major function is the excretion of waste products in urine whereas the juxtamedullary nephron comprises 20% of the total nephron and its major function is the concentration of urine by counter current mechanism.
In the superficial (cortical) nephrons, peritubular capillaries branch off the efferent arterioles and deliver nutrients to epithelial cells as well as serve as a blood supply for reabsorption and secretion. In juxtamedullary nephrons, the peritubular capillaries have a specialization called the vasa recta, which are long, hairpin-shaped blood vessels that follow the same course as a loop of Henle. The vasa recta serve as osmotic exchangers for the production of concentrated urine.The kidney receives about 25% of cardiac output and about 20% of this is filtered at the glomeruli of the kidney. Thus, renal blood flow is 1200 ml/minute and renal plasma flow is 650 ml/minute.
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This question is part of the following fields:
- Anatomy
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Question 27
Correct
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Which of the following options will cause an artificial increase in pulse oximeter (SpO2) readings?
Your Answer: Heavy smoker
Explanation:A pulse oximeter is a piece of medical equipment used as a non-invasive method of measuring the oxygen saturation of blood.
It works by measuring the ratio of absorption of red and infrared light in a section of blood flow, as red light is largely absorbed by deoxygenated blood, and infrared light is largely absorbed by oxygenated blood.
Pulse oximetry relies on photoplethysmography (PPG) waveforms. The oximeter has 2 sides, with different functions. One side houses light-emitting diodes which are responsible for transmitting 2 light wavelengths, 660nm for red light and 940nm for near infrared light. The other side is a photodetector. The light emitted travels through the body and the amount that is not absorbed is measured by the photodetector.
Smokers often have increased levels of carboxy haemoglobin (COHb). This leads to artificial increases in pulse oximeter readings as it is unable to differentiate between COHb and oxyhaemoglobin (O2HB) as they both absorb red light at 660nm. Every 1% increase of circulating carboxyhaemoglobin, results in a correlative 1% increase in oximeter readings.
Prilocaine toxicity will cause an artificial decrease in oximeter readings. This is because prilocaine metabolites cause methemoglobinemia (MetHB), which are dysfunctional haemoglobins unable to properly transport oxygen. In this case, a laboratory multiwavelength co-oximeter is recommended for a more accurate reading.
Anaemia will not affect oximeter readings as long as haemoglobins in the blood are normal.
Sickle cell disease does not affect oximeter readings despite its ability to cause hypoxia and shift the oxygen dissociation curve to the right.
Brown-red fingernail polish will cause an underestimation of pulse oximeter readings.
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This question is part of the following fields:
- Clinical Measurement
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Question 28
Correct
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Prior to an urgent appendicectomy, a 49-year-old man requires a rapid sequence induction. His BMI is equal to 50. Which of the following formulas is the most appropriate for calculating a suxamethonium dose in order to achieve optimal intubating conditions?
Your Answer: 1-1.5 × actual body weight (mg)
Explanation:The usual method of calculating the dose of a drug to be given to patients of normal weight is to use total body weight (TBW). This is because the lean body weight (LBW) and ideal body weight (IBW) dosing scalars are similar in these patients.
Because the LBW and fat mass do not increase in proportion in patients with morbid obesity, this is not the case. Drugs that are lipid soluble, such as propofol or thiopentone, can cause a relative overdose. Lean body mass is a better scalar in these situations.
Suxamethonium has a small volume of distribution, so the dose is best calculated using the TBW to ensure optimal and deep intubating conditions. The higher dose was justified because these patients’ plasma cholinesterase activity was elevated.
Other scalars include:
The dose of highly lipid soluble drugs like benzodiazepines, thiopentone, and propofol can be calculated using lean body weight (LBW). The formula LBW = IBW + 20% can be used on occasion.
Fentanyl, rocuronium, atracurium, vecuronium, morphine, paracetamol, bupivacaine, and lidocaine are all administered with LBW.
Formulas can be used to calculate the ideal body weight (IBW). There are a number of drawbacks, including the fact that patients of the same height receive the same dose, and the formulae do not account for changes in body composition associated with obesity. Because IBW is typically lower than LBW, administering a drug based on IBW may result in underdosing. The body mass index (BMI) isn’t used to calculate drug dosage directly.
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This question is part of the following fields:
- Pharmacology
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Question 29
Correct
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A 39-year old man came to the Out-Patient department for symptoms of gastroesophageal reflux disease. Medical history revealed he is on anti-epileptic medication Phenytoin. His plasma phenytoin levels are maintained between 10-12 mcg/mL (Therapeutic range: 10-20 mcg/mL). He is given a H2 antagonist receptor agent (Cimetidine) for his GERD symptoms. Upon follow-up, his plasma phenytoin levels increased to 38 mcg/mL. Regarding metabolism and elimination, which of the following best explains the pharmacokinetics of phenytoin at higher plasma levels?
Your Answer: Plasma concentration plotted against time is linear
Explanation:Drug elimination is the termination of drug action, and may involve metabolism into inactive state and excretion out of the body. Duration of drug action is determined by the dose administered and the rate of elimination following the last dose.
There are two types of elimination: first-order and zero-order elimination.
In first-order elimination, the rate of elimination is proportionate to the concentration; the concentration decreases exponentially over time. It observes the characteristic half-life elimination, where the concentration decreases by 50% for every half-life.
In zero-order elimination, the rate of elimination is constant regardless of concentration; the concentration decreases linearly over time. A constant amount of the drug being excreted over time, and it occurs when drugs have saturated their elimination mechanisms.
Since phenytoin is observed in elevated levels, the elimination mechanisms for it has been saturated and, thus, will have to undergo zero-order elimination.
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This question is part of the following fields:
- Pharmacology
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Question 30
Correct
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A strain gauge operates on which of the following principles?
Your Answer: Varying resistance of a wire when stretched
Explanation:The principle by which a strain gauge works is that when a wire is stretched, it becomes longer and thinner, and as a result, its resistance increases.
A strain gauge, which is used in pressure transducers, acts as a resistor. When the pressure in a pressure transducer changes, the diaphragm moves, changing the tension in the resistance wire and thus changing the resistance.
Changes in current flow through the resistor are amplified and displayed as a pressure change measure.
A Wheatstone bridge, on the other hand, is frequently used to measure or monitor these changes in resistance.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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