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Question 1
Incorrect
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A 55-year-old man is hospitalized after experiencing haematemesis. Upon examination, his prothrombin time is found to be elevated. What could be a possible reason for this anomaly?
Your Answer: Systemic lupus erythematosus
Correct Answer: Chronic liver disease
Explanation:The inheritance of Haemophilia A and B is crucial in identifying individuals who are at risk of developing the condition. Haemophilia A and B are genetic disorders that are inherited in an X-linked recessive manner. Haemophilia A is caused by a deficiency in clotting factor VIII, while haemophilia B is caused by a deficiency in clotting factor IX.
On the other hand, haemophilia C, which is caused by a deficiency in clotting factor XI, is primarily inherited in an autosomal recessive manner. In X-linked recessive conditions like haemophilia B, males are more likely to be affected than females. This is because males only need one abnormal copy of the gene, which is carried on the X chromosome, to be affected.
Females, on the other hand, can be carriers of the condition if they carry one normal and one abnormal copy of the gene. While carriers can have clotting abnormalities, these are usually milder than those seen in affected individuals. Men cannot pass the condition to their sons, but they will pass on the abnormal X chromosome to all their daughters, who will be carriers.
Female carriers can pass on the condition to around half their sons, and half their daughters will be carriers. Females can only be affected if they are the offspring of an affected male and a carrier female. In summary, the inheritance of haemophilia A and B is crucial in identifying individuals who are at risk of developing the condition. It also helps in providing appropriate genetic counseling and management for affected individuals and their families.
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This question is part of the following fields:
- Haematology And Oncology
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Question 2
Correct
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A 60-year-old male visits his doctor complaining of a lump on the side of his neck. He reports feeling exhausted and experiencing night sweats. Following a needle core biopsy, the patient is diagnosed with follicular lymphoma. Which chromosomes are linked to this condition through translocation?
Your Answer: 14 and 18
Explanation:The translocation of chromosomes is associated with various types of lymphoma and leukaemia. For example, the t(14;18) translocation causes follicular lymphoma by increasing BCL-2 transcription. Similarly, the t(8;14) translocation causes Burkitt lymphoma, while the t(9;22) translocation leads to the Philadelphia chromosome and chronic myeloid leukaemia. Mantle cell lymphoma is associated with the t(11;14) translocation. These translocations can help diagnose and classify these haematological malignancies.
Genetics of Haematological Malignancies
Haematological malignancies are cancers that affect the blood, bone marrow, and lymphatic system. These cancers are often associated with specific genetic abnormalities, such as translocations. Here are some common translocations and their associated haematological malignancies:
– Philadelphia chromosome (t(9;22)): This translocation is present in more than 95% of patients with chronic myeloid leukaemia (CML). It results in the fusion of the Abelson proto-oncogene with the BCR gene on chromosome 22, creating the BCR-ABL gene. This gene codes for a fusion protein with excessive tyrosine kinase activity, which is a poor prognostic indicator in acute lymphoblastic leukaemia (ALL).
– t(15;17): This translocation is seen in acute promyelocytic leukaemia (M3) and involves the fusion of the PML and RAR-alpha genes.
– t(8;14): Burkitt’s lymphoma is associated with this translocation, which involves the translocation of the MYC oncogene to an immunoglobulin gene.
– t(11;14): Mantle cell lymphoma is associated with the deregulation of the cyclin D1 (BCL-1) gene.
– t(14;18): Follicular lymphoma is associated with increased BCL-2 transcription due to this translocation.
Understanding the genetic abnormalities associated with haematological malignancies is important for diagnosis, prognosis, and treatment.
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This question is part of the following fields:
- Haematology And Oncology
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Question 3
Incorrect
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You are currently interested in the outcome of a clinical trial comparing a new medication for non-valvular atrial fibrillation against the four currently existing direct oral anti-coagulants with the primary outcome measure being the reduction in stroke events.
The trial is being conducted across multiple regions and includes a total of 5000 enrolled patients.
What phase is this clinical trial currently in?Your Answer: Phase 4
Correct Answer: Phase 3
Explanation:Phase 3 studies involve a larger number of actual patients and compare the new treatment with currently available treatments. These studies typically involve around 500-5000 patients. In contrast, Phase 0 studies involve very few people and are primarily focused on testing low doses of treatment to ensure safety. Phase 1 studies involve around 100 healthy volunteers and are used to assess pharmacodynamics and pharmacokinetics. Phase 2 studies involve around 100-300 actual patients and aim to examine efficacy and identify any adverse effects.
Stages of Drug Development
Drug development is a complex process that involves several stages before a drug can be approved for marketing. The process begins with Phase 1, which involves small studies on healthy volunteers to assess the pharmacodynamics and pharmacokinetics of the drug. This phase typically involves around 100 participants.
Phase 2 follows, which involves small studies on actual patients to examine the drug’s efficacy and adverse effects. This phase typically involves between 100-300 patients.
Phase 3 is the largest phase and involves larger studies of between 500-5,000 patients. This phase examines the drug’s efficacy and adverse effects and may compare it with existing treatments. Special groups such as the elderly or those with renal issues may also be studied during this phase.
If the drug is shown to be safe and effective, it may be approved for marketing. However, Phase 4, also known as post-marketing surveillance, is still necessary. This phase involves monitoring the drug’s safety and effectiveness in a larger population over a longer period of time.
In summary, drug development involves several stages, each with its own specific purpose and participant size. The process is rigorous to ensure that drugs are safe and effective before they are marketed to the public.
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This question is part of the following fields:
- General Principles
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Question 4
Correct
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A 36-year-old woman presents to her GP with a history of long-standing fatigue, dyspnea, and chest discomfort that has recently worsened. Despite being physically active, she has been experiencing these symptoms. She is a social drinker and does not smoke. Her family history is unremarkable except for her mother who died of 'chest disease' at the age of 50. During examination, her observations are as follows:
Blood pressure: 135/85mmHg
Pulse: 95 beats/min
Respiration: 25 breaths/min
An ECG shows no abnormalities, and cardiac enzymes are within normal ranges. She is referred for echocardiography, which reveals a right pulmonary artery pressure of 35 mmhg.
What substance is elevated in this patient, underlying the disease process?Your Answer: Endothelin
Explanation:Understanding Endothelin and Its Role in Various Diseases
Endothelin is a potent vasoconstrictor and bronchoconstrictor that is secreted by the vascular endothelium. Initially, it is produced as a prohormone and later converted to ET-1 by the action of endothelin converting enzyme. Endothelin interacts with a G-protein linked to phospholipase C, leading to calcium release. This interaction is thought to be important in the pathogenesis of many diseases, including primary pulmonary hypertension, cardiac failure, hepatorenal syndrome, and Raynaud’s.
Endothelin is known to promote the release of angiotensin II, ADH, hypoxia, and mechanical shearing forces. On the other hand, it inhibits the release of nitric oxide and prostacyclin. Raised levels of endothelin are observed in primary pulmonary hypertension, myocardial infarction, heart failure, acute kidney injury, and asthma.
In recent years, endothelin antagonists have been used to treat primary pulmonary hypertension. Understanding the role of endothelin in various diseases can help in the development of new treatments and therapies.
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This question is part of the following fields:
- Cardiovascular System
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Question 5
Correct
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A 4-month-old child presents with a cleft palate, recurrent infections, and hypocalcemia. On chest x-ray, there is a decreased thymic shadow. The diagnosis is a primary immunodeficiency disorder. Which embryological structure abnormal development is most likely responsible for this condition?
Your Answer: 3rd and 4th branchial pouches
Explanation:Abnormal development of the 3rd and 4th branchial pouches is the underlying cause of 22q11 deletion syndromes, including DiGeorge syndrome. This patient exhibits clinical symptoms consistent with DiGeorge syndrome, which is characterized by the improper formation of these pouches.
The 3rd branchial pouch typically develops into the thymus and inferior parathyroids, while the 4th branchial pouch gives rise to the superior parathyroids. When the thymus fails to develop properly, it can result in a deficiency of T cells and recurrent infections. Additionally, inadequate parathyroid development can lead to hypocalcemia.
DiGeorge syndrome, also known as velocardiofacial syndrome and 22q11.2 deletion syndrome, is a primary immunodeficiency disorder that results from a microdeletion of a section of chromosome 22. This autosomal dominant condition is characterized by T-cell deficiency and dysfunction, which puts individuals at risk of viral and fungal infections. Other features of DiGeorge syndrome include hypoplasia of the parathyroid gland, which can lead to hypocalcaemic tetany, and thymic hypoplasia.
The presentation of DiGeorge syndrome can vary, but it can be remembered using the mnemonic CATCH22. This stands for cardiac abnormalities, abnormal facies, thymic aplasia, cleft palate, hypocalcaemia/hypoparathyroidism, and the fact that it is caused by a deletion on chromosome 22. Overall, DiGeorge syndrome is a complex disorder that affects multiple systems in the body and requires careful management and monitoring.
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This question is part of the following fields:
- General Principles
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Question 6
Correct
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A 54-year-old man comes to the emergency department complaining of difficulty breathing. The results of his pulmonary function tests are as follows:
Reference Range
FVC (% predicted) 102 80-120
FEV1 (% predicted) 62 80-120
FEV1/FVC (%) 60.1 >70
TCLO (% predicted) 140 60-120
What is the probable reason for his symptoms?Your Answer: Asthma exacerbation
Explanation:The raised transfer factor suggests that the patient is experiencing an exacerbation of asthma. This condition can cause obstructive patterns on pulmonary function tests, leading to reduced FEV1 and FEV1/FVC, as well as hypoxia and wheezing. However, other conditions such as COPD exacerbation, idiopathic pulmonary fibrosis, and pulmonary embolism would result in a low transfer factor, and are therefore unlikely explanations for the patient’s symptoms.
Understanding Transfer Factor in Lung Function Testing
The transfer factor is a measure of how quickly a gas diffuses from the alveoli into the bloodstream. This is typically tested using carbon monoxide, and the results can be given as either the total gas transfer (TLCO) or the transfer coefficient corrected for lung volume (KCO). A raised TLCO may be caused by conditions such as asthma, pulmonary haemorrhage, left-to-right cardiac shunts, polycythaemia, hyperkinetic states, male gender, or exercise. On the other hand, a lower TLCO may be indicative of pulmonary fibrosis, pneumonia, pulmonary emboli, pulmonary oedema, emphysema, anaemia, or low cardiac output.
KCO tends to increase with age, and certain conditions may cause an increased KCO with a normal or reduced TLCO. These conditions include pneumonectomy/lobectomy, scoliosis/kyphosis, neuromuscular weakness, and ankylosis of costovertebral joints (such as in ankylosing spondylitis). Understanding transfer factor is important in lung function testing, as it can provide valuable information about a patient’s respiratory health and help guide treatment decisions.
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This question is part of the following fields:
- Respiratory System
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Question 7
Correct
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Which one of the following is not well absorbed after a gastrectomy?
Your Answer: Vitamin B12
Explanation:The absorption of Vitamin B12 is affected by post gastrectomy syndrome, while the absorption of other vitamins remains unaffected. This syndrome is characterized by the rapid emptying of food from the stomach into the duodenum, leading to symptoms such as abdominal pain, diarrhoea, and hypoglycaemia. Complications of this syndrome include malabsorption of Vitamin B12 and iron, as well as osteoporosis. Treatment involves following a diet that is high in protein and low in carbohydrates, and replacing any deficiencies in Vitamin B12, iron, and calcium.
Understanding Gastric Emptying and Its Controlling Factors
The stomach plays a crucial role in both mechanical and immunological functions. It retains solid and liquid materials, which undergo peristaltic activity against a closed pyloric sphincter, leading to fragmentation of food bolus material. Gastric acid helps neutralize any pathogens present. The time material spends in the stomach depends on its composition and volume, with amino acids and fat delaying gastric emptying.
Gastric emptying is controlled by neuronal stimulation mediated via the vagus and the parasympathetic nervous system, which favors an increase in gastric motility. Hormonal factors such as gastric inhibitory peptide, cholecystokinin, and enteroglucagon also play a role in delaying or increasing gastric emptying.
Diseases affecting gastric emptying can lead to bacterial overgrowth, retained food, and the formation of bezoars that may occlude the pylorus and worsen gastric emptying. Gastric surgery can also have profound effects on gastric emptying, with vagal disruption causing delayed emptying.
Diabetic gastroparesis is predominantly due to neuropathy affecting the vagus nerve, leading to poor stomach emptying and repeated vomiting. Malignancies such as distal gastric cancer and pancreatic cancer may also obstruct the pylorus and delay emptying. Congenital hypertrophic pyloric stenosis is a disease of infancy that presents with projectile non-bile stained vomiting and is treated with pyloromyotomy.
In summary, understanding gastric emptying and its controlling factors is crucial in diagnosing and treating various diseases that affect the stomach’s function.
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This question is part of the following fields:
- Gastrointestinal System
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Question 8
Correct
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A 60-year-old male presents with increasing fatigue.
Three months ago, he was diagnosed with bronchial carcinoma and has undergone chemotherapy. Upon admission, his electrolyte levels were measured as follows:
- Sodium: 118 mmol/L (137-144)
- Potassium: 3.5 mmol/L (3.5-4.9)
- Urea: 3.2 mmol/L (2.5-7.5)
- Creatinine: 65 µmol/L (60-110)
What would be the most appropriate initial investigation for this patient?Your Answer: Urine osmolality and sodium concentration
Explanation:Hyponatraemia in Bronchial Carcinoma Patients
Hyponatraemia is a common condition in patients with bronchial carcinoma. It is characterized by a marked decrease in sodium levels, which appears to be dilutional based on other test results that fall within the lower end of the normal range. The most likely cause of this condition is the syndrome of inappropriate ADH secretion (SIADH), which occurs when the tumour produces ADH in an ectopic manner. However, the diagnosis of SIADH is one of exclusion, and other possibilities such as hypoadrenalism due to metastatic disease to the adrenals should also be considered.
To determine the cause of hyponatraemia, initial tests such as urine sodium and osmolality are recommended. These tests can help rule out other possible causes and confirm the diagnosis of SIADH. Treatment for this condition typically involves fluid restriction. It is important to note that measuring ADH concentrations is not a reliable diagnostic tool as it is not widely available and does not provide any useful information.
In summary, hyponatraemia is a common condition in bronchial carcinoma patients, and SIADH is the most likely cause. Initial tests such as urine sodium and osmolality can help confirm the diagnosis, and treatment involves fluid restriction.
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This question is part of the following fields:
- Endocrine System
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Question 9
Incorrect
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Which one of the following structures lies posterior to the femoral nerve in the femoral triangle?
Your Answer: Adductor longus
Correct Answer: Iliacus
Explanation:The femoral nerve is located in front of the iliacus muscle within the femoral triangle. Meanwhile, the iliacus and pectineus muscles are situated behind the femoral sheath.
The femoral nerve is a nerve that originates from the spinal roots L2, L3, and L4. It provides innervation to several muscles in the thigh, including the pectineus, sartorius, quadriceps femoris, and vastus lateralis, medialis, and intermedius. Additionally, it branches off into the medial cutaneous nerve of the thigh, saphenous nerve, and intermediate cutaneous nerve of the thigh. The femoral nerve passes through the psoas major muscle and exits the pelvis by going under the inguinal ligament. It then enters the femoral triangle, which is located lateral to the femoral artery and vein.
To remember the femoral nerve’s supply, a helpful mnemonic is don’t MISVQ scan for PE. This stands for the medial cutaneous nerve of the thigh, intermediate cutaneous nerve of the thigh, saphenous nerve, vastus, quadriceps femoris, and sartorius, with the addition of the pectineus muscle. Overall, the femoral nerve plays an important role in the motor and sensory functions of the thigh.
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This question is part of the following fields:
- Neurological System
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Question 10
Correct
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A 65-year-old patient presents at the lung cancer clinic for their initial assessment. Their general practitioner referred them due to a persistent cough lasting 5 months and a weight loss of one stone in a month. The patient has quit smoking recently but used to smoke 20-30 cigarettes daily for 30 years. No asbestos exposure is reported.
A circular lesion was detected in the right upper lobe during a recent chest x-ray. A subsequent computed tomography (CT) scan indicated that this lung lesion is indicative of a primary lesion.
What is the most probable sub-type of lung cancer in this case?Your Answer: Adenocarcinoma
Explanation:Adenocarcinoma has become the most prevalent form of lung cancer, as per the given scenario. This type of cancer accounts for approximately one-third of all cases and can occur in both smokers and non-smokers. Therefore, the most probable answer to the question is adenocarcinoma. Mesothelioma, on the other hand, is a rare and incurable cancer that is almost exclusively linked to asbestos exposure and affects the pleura. It would not present as an upper lobe mass, but rather as a loss of lung volume or pleural opacity. Alveolar cell carcinoma, which is less common than adenocarcinoma, would likely cause significant sputum production.
Lung cancer can be classified into two main types: small cell lung cancer (SCLC) and non-small cell lung cancer (NSCLC). SCLC is less common, accounting for only 15% of cases, but has a worse prognosis. NSCLC, on the other hand, is more prevalent and can be further broken down into different subtypes. Adenocarcinoma is now the most common type of lung cancer, likely due to the increased use of low-tar cigarettes. It is often seen in non-smokers and accounts for 62% of cases in ‘never’ smokers. Squamous cell carcinoma is another subtype, and cavitating lesions are more common in this type of lung cancer. Large cell carcinoma, alveolar cell carcinoma, bronchial adenoma, and carcinoid are other subtypes of NSCLC. Differentiating between these subtypes is crucial as different drugs are available to treat each subtype.
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This question is part of the following fields:
- Respiratory System
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Question 11
Correct
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A 28-year-old woman with a three week history of abdominal pain, diarrhoea and weight loss undergoes a colonoscopy. Biopsies are taken and a diagnosis of Crohn's disease is made.
What microscopic changes are expected to be observed in this case?Your Answer: Increased goblet cells
Explanation:Crohn’s disease is characterized by an increase in goblet cells on microscopic examination. Unlike ulcerative colitis, Crohn’s disease may have skip lesions and transmural inflammation. Pseudopolyps and shortening of crypts are more commonly seen in ulcerative colitis.
Inflammatory bowel disease (IBD) is a condition that includes two main types: Crohn’s disease and ulcerative colitis. Although they share many similarities in terms of symptoms, diagnosis, and treatment, there are some key differences between the two. Crohn’s disease is characterized by non-bloody diarrhea, weight loss, upper gastrointestinal symptoms, mouth ulcers, perianal disease, and a palpable abdominal mass in the right iliac fossa. On the other hand, ulcerative colitis is characterized by bloody diarrhea, abdominal pain in the left lower quadrant, tenesmus, gallstones, and primary sclerosing cholangitis. Complications of Crohn’s disease include obstruction, fistula, and colorectal cancer, while ulcerative colitis has a higher risk of colorectal cancer than Crohn’s disease. Pathologically, Crohn’s disease lesions can be seen anywhere from the mouth to anus, while ulcerative colitis inflammation always starts at the rectum and never spreads beyond the ileocaecal valve. Endoscopy and radiology can help diagnose and differentiate between the two types of IBD.
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This question is part of the following fields:
- Gastrointestinal System
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Question 12
Incorrect
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Which bone is not part of the carpal bones?
Your Answer: Trapezoid
Correct Answer: Trapezius
Explanation:Trapezius is not related to the mnemonic for the carpal bones.
Carpal Bones: The Wrist’s Building Blocks
The wrist is composed of eight carpal bones, which are arranged in two rows of four. These bones are convex from side to side posteriorly and concave anteriorly. The trapezium is located at the base of the first metacarpal bone, which is the base of the thumb. The scaphoid, lunate, and triquetrum bones do not have any tendons attached to them, but they are stabilized by ligaments.
In summary, the carpal bones are the building blocks of the wrist, and they play a crucial role in the wrist’s movement and stability. The trapezium bone is located at the base of the thumb, while the scaphoid, lunate, and triquetrum bones are stabilized by ligaments. Understanding the anatomy of the wrist is essential for diagnosing and treating wrist injuries and conditions.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 13
Incorrect
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John Smith, a 81-year-old man, arrives at the emergency department after falling down a few steps. He complains of 7/10 groin pain and is administered pain relief.
During the assessment, the doctor conducts a neurovascular examination and observes decreased sensation in the right medial thigh, indicating a possible nerve injury.
Further investigations reveal a pubic rami fracture.
Which nerve is likely to be affected in this situation, and which muscle compartment of the thigh does it supply?Your Answer: Femoral nerve, adductor compartment of the thigh
Correct Answer: Obturator nerve, ADductor compartment of the thigh
Explanation:The adductor compartment of the thigh is innervated by the obturator nerve, which enters the thigh through the obturator canal after running laterally along the pelvic wall towards the obturator foramen. The muscles innervated by the obturator nerve include the adductor brevis, adductor longus, adductor magnus, gracilis, and obturator externus. The sciatic nerve also innervates the adductor magnus, while the femoral nerve innervates the anterior compartment of the thigh and the sciatic nerve innervates the posterior compartment of the thigh.
Anatomy of the Obturator Nerve
The obturator nerve is formed by branches from the ventral divisions of L2, L3, and L4 nerve roots, with L3 being the main contributor. It descends vertically in the posterior part of the psoas major muscle and emerges from its medial border at the lateral margin of the sacrum. After crossing the sacroiliac joint, it enters the lesser pelvis and descends on the obturator internus muscle to enter the obturator groove. The nerve lies lateral to the internal iliac vessels and ureter in the lesser pelvis and is joined by the obturator vessels lateral to the ovary or ductus deferens.
The obturator nerve supplies the muscles of the medial compartment of the thigh, including the external obturator, adductor longus, adductor brevis, adductor magnus (except for the lower part supplied by the sciatic nerve), and gracilis. The cutaneous branch, which is often absent, supplies the skin and fascia of the distal two-thirds of the medial aspect of the thigh when present.
The obturator canal connects the pelvis and thigh and contains the obturator artery, vein, and nerve, which divides into anterior and posterior branches. Understanding the anatomy of the obturator nerve is important in diagnosing and treating conditions that affect the medial thigh and pelvic region.
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This question is part of the following fields:
- Neurological System
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Question 14
Correct
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What are the clinical effects that can occur due to acute or chronic over-administration of multivitamins leading to Vitamin A toxicity?
Your Answer: Nausea, vomiting and headaches
Explanation:The Importance and Risks of Vitamin A
Vitamin A is an essential nutrient that plays a crucial role in various bodily functions such as growth and development, vision, enzyme signalling pathways, and the maintenance of epithelial membranes. However, excessive intake of vitamin A can lead to toxicity, which can cause several adverse effects. These include raised intracranial pressure resulting in headaches, nausea, vomiting, and visual loss, increased bone resorption leading to osteoporosis and hypercalcaemia, liver damage, hair loss, and skin changes. Moreover, there is a possible increased risk of malignancy, particularly among smokers. Pregnant women are also advised to avoid foods rich in vitamin A, such as liver and fish oils, due to the teratogenicity of vitamin A-derived drugs. Therefore, it is crucial to maintain a balanced intake of vitamin A to avoid the risks associated with its toxicity.
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This question is part of the following fields:
- Basic Sciences
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Question 15
Correct
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A 30-year-old male presents to his general practitioner complaining of jaundice and fatigue that has been present for the past 2 days. He mentions that he has experienced similar symptoms in the past but has never sought medical attention until now. He reports having a severe case of the flu recently. The patient has no significant medical history and leads a healthy lifestyle, abstaining from alcohol and smoking.
What enzyme deficiency is likely responsible for this condition?Your Answer: UDP glucuronosyltransferase
Explanation:Individuals with Gilbert’s syndrome exhibit a decrease in the amount of UDP glucuronosyltransferase, an enzyme responsible for conjugating bilirubin in the liver. This deficiency leads to an accumulation of unconjugated bilirubin, which cannot be eliminated through urine, resulting in jaundice. Although symptoms may arise during periods of stress, the condition is generally not clinically significant.
HMG-CoA reductase is an enzyme involved in cholesterol synthesis, while lipoprotein lipase plays a central role in lipid metabolism and is associated with various conditions such as hypertriglyceridemia. G6PD deficiency, on the other hand, affects the pentose phosphate pathway by reducing the production of NADPH.
Gilbert’s syndrome is a genetic disorder that affects the way bilirubin is processed in the body. It is caused by a deficiency of UDP glucuronosyltransferase, which leads to unconjugated hyperbilirubinemia. This means that bilirubin is not properly broken down and eliminated from the body, resulting in jaundice. However, jaundice may only be visible during certain conditions such as fasting, exercise, or illness. The prevalence of Gilbert’s syndrome is around 1-2% in the general population.
To diagnose Gilbert’s syndrome, doctors may look for a rise in bilirubin levels after prolonged fasting or the administration of IV nicotinic acid. However, treatment is not necessary for this condition. While the exact mode of inheritance is still debated, it is known to be an autosomal recessive disorder.
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This question is part of the following fields:
- Gastrointestinal System
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Question 16
Correct
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A 75-year-old man is brought to the hospital with a urinary tract infection. He has a history of hypertension and mild cognitive impairment.
The medical team observes that he has had recurrent urinary tract infections caused by Escherichia coli in the past year.
Which culture medium is required for the growth of this microorganism?Your Answer: MacConkey agar
Explanation:The correct medium for culturing Escherichia coli and obtaining pink colonies is MacConkey agar. This is because E. coli is a lactose-fermenting bacteria, and MacConkey’s agar contains lactose that is utilized by such bacteria to produce acid, resulting in the formation of pink colonies. Charcoal-yeast agar, chocolate agar, and Lowenstein-Jensen agar are not appropriate for culturing E. coli as they are used for isolating other bacteria that cause different illnesses.
Culture Requirements for Common Organisms
Different microorganisms require specific culture conditions to grow and thrive. The table above lists some of the culture requirements for the more common organisms. For instance, Neisseria gonorrhoeae requires Thayer-Martin agar, which is a variant of chocolate agar, and the addition of Vancomycin, Polymyxin, and Nystatin to inhibit Gram-positive, Gram-negative, and fungal growth, respectively. Haemophilus influenzae, on the other hand, grows on chocolate agar with factors V (NAD+) and X (hematin).
To remember the culture requirements for some of these organisms, some mnemonics can be used. For example, Nice Homes have chocolate can help recall that Neisseria and Haemophilus grow on chocolate agar. If I Tell-U the Corny joke Right, you’ll Laugh can be used to remember that Corynebacterium diphtheriae grows on tellurite agar or Loeffler’s media. Lactating pink monkeys can help recall that lactose fermenting bacteria, such as Escherichia coli, grow on MacConkey agar resulting in pink colonies. Finally, BORDETella pertussis can be used to remember that Bordetella pertussis grows on Bordet-Gengou (potato) agar.
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This question is part of the following fields:
- General Principles
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Question 17
Correct
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A 56-year-old man is hospitalized due to heart failure and is given IV furosemide. What is the percentage of bioavailability for intravenous administration of furosemide?
Your Answer: 100%
Explanation:A drug administered through an intravenous route has
Bioavailability refers to the amount of a drug that enters the bloodstream after it is ingested. This means that an intravenous (IV) drug has 100% bioavailability since it is directly administered into the bloodstream. The bioavailability of a drug can be affected by various factors such as the speed at which the stomach empties, the acidity of the stomach, the way the liver metabolizes the drug, the specific formulation of the drug, and how susceptible the drug is to hydrolysis. However, it is important to note that renal function does not have an impact on bioavailability.
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This question is part of the following fields:
- General Principles
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Question 18
Correct
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A 26-year-old gardener presents to her GP with a two week history of elbow swelling. She reports a gradual onset of the swelling, with no apparent triggers, and experiences pain and warmth upon touch. She denies any swelling in other areas and is generally in good health.
The patient has a medical history of well-managed rheumatoid arthritis and is currently taking methotrexate. There are no other known medical conditions.
During the physical examination, a tender, soft, fluctuant mass is palpated on the posterior aspect of the patient's elbow.
Based on the above information, what is the most probable diagnosis?Your Answer: Olecranon bursitis
Explanation:Understanding Olecranon Bursitis
Olecranon bursitis is a condition that occurs when the olecranon bursa, a fluid-filled sac located over the olecranon process at the proximal end of the ulna, becomes inflamed. This bursa serves to reduce friction between the elbow joint and the surrounding soft tissues. The inflammation can be caused by trauma, infection, or systemic conditions such as rheumatoid arthritis or gout. It is also commonly known as student’s elbow due to the repetitive mild trauma of leaning on a desk using the elbows.
The condition is more common in men and typically presents between the ages of 30 and 60. Causes of olecranon bursitis include repetitive trauma, direct trauma, infection, gout, rheumatoid arthritis, and idiopathic reasons. Patients with non-septic olecranon bursitis typically present with swelling over the olecranon process, which is often the only symptom. Some patients may also experience tenderness and erythema over the bursa. On the other hand, patients with septic bursitis are more likely to have pain and fever.
Signs of olecranon bursitis include swelling over the posterior aspect of the elbow, tenderness on palpation of the swollen area, redness and warmth of the overlying skin, fever, skin abrasion overlying the bursa, effusions in other joints if associated with rheumatoid arthritis, and tophi if associated with gout. Movement at the elbow joint should be painless until the swollen bursa is compressed in full flexion.
Investigations are not always needed if a clinical diagnosis can be made and there is no concern about septic arthritis. However, if septic bursitis is suspected, aspiration of bursal fluid for microscopy and culture is essential. Purulent fluid suggests infection, while straw-coloured bursal fluid favours a non-infective cause. Understanding the causes, symptoms, and signs of olecranon bursitis can help in its diagnosis and management.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 19
Incorrect
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On examining the caecum, what structure is most likely to be detected at the point where all the tenia coli converge?
Your Answer: Ileocolic artery
Correct Answer: Appendix base
Explanation:The tenia coli come together at the bottom of the appendix.
The Caecum: Location, Relations, and Functions
The caecum is a part of the colon located in the proximal right colon below the ileocaecal valve. It is an intraperitoneal structure that has posterior relations with the psoas, iliacus, femoral nerve, genitofemoral nerve, and gonadal vessels. Its anterior relations include the greater omentum. The caecum is supplied by the ileocolic artery and its lymphatic drainage is through the mesenteric nodes that accompany the venous drainage.
The caecum is known for its distensibility, making it the most distensible part of the colon. However, in cases of complete large bowel obstruction with a competent ileocaecal valve, the caecum is the most likely site of eventual perforation. Despite this potential complication, the caecum plays an important role in the digestive system. It is responsible for the absorption of fluids and electrolytes, as well as the fermentation of indigestible carbohydrates. Additionally, the caecum is a site for the growth and proliferation of beneficial bacteria that aid in digestion and immune function.
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This question is part of the following fields:
- Gastrointestinal System
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Question 20
Correct
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A 3-day-old baby was brought to the emergency department by their 35-year-old mother due to difficulty breathing. The mother reports that the baby has been feeding poorly since birth, appeared lethargic, and has slightly yellow skin. The baby was born at 37 weeks' gestation and is the younger of a pair of twins. They were delivered via normal vaginal delivery with no complications and had a birth weight of 3.8 kg. The baby has been exclusively breastfed since birth. The mother did not regularly attend antenatal checkups and is unsure of her group B Streptococcus status.
During examination, the baby is observed to be tachypnoeic with expiratory grunting and nasal flaring. The baby is visibly jaundiced up to the chest, with a temperature of 38.9ºC, a heart rate of 200 beats per minute (normal heart rate for newborn: 120 - 160 beats per minute), and a respiratory rate of 60 breaths per minute (normal respiratory rate: 40 - 60 breaths per minute).
What is a potential risk factor for the current presentation of this 3-day-old baby?Your Answer: Maternal group B Streptococcus colonisation
Explanation:Early-onset neonatal sepsis in a two-day-old infant may be caused by maternal group B Streptococcus (GBS) colonisation, which is a common coloniser of the vaginal tract and can be transmitted to the newborn during delivery. This can lead to symptoms such as lethargy, jaundice, dyspnoea, tachycardia, and poor capillary refill time, which may indicate septic shock.
However, being large for gestational age, advanced maternal age, or having multiple gestations are not known risk factors for neonatal sepsis. Instead, they are associated with other complications such as shoulder dystocia, neonatal hypoglycaemia, spontaneous abortions, chromosomal abnormalities, congenital malformations, IUGR, and twin-to-twin transfusion syndrome.
Neonatal sepsis is a serious bacterial or viral infection in the blood that affects babies within the first 28 days of life. It is categorized into early-onset (EOS) and late-onset (LOS) sepsis, with each category having distinct causes and presentations. The most common causes of neonatal sepsis are group B streptococcus (GBS) and Escherichia coli. Premature and low birth weight babies are at higher risk, as well as those born to mothers with GBS colonization or infection during pregnancy. Symptoms can range from subtle signs of illness to clear septic shock, and may include respiratory distress, jaundice, seizures, and poor feeding. Diagnosis is usually established through blood culture, and treatment involves early identification and use of intravenous antibiotics. Other important management factors include maintaining adequate oxygenation and fluid/electrolyte status, and preventing or managing hypoglycemia and metabolic acidosis.
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This question is part of the following fields:
- General Principles
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Question 21
Incorrect
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In pediatric patients with sickle cell disease, what is the most common causative organism of osteomyelitis?
Your Answer: Staphylococcus aureus
Correct Answer: Salmonella species
Explanation:Salmonella is the most common infecting organism in children with osteomyelitis worldwide.
Understanding Osteomyelitis: Types, Causes, and Treatment
Osteomyelitis is a bone infection that can be classified into two types: haematogenous and non-haematogenous. Haematogenous osteomyelitis is caused by bacteria in the bloodstream and is usually monomicrobial. It is more common in children and can be caused by risk factors such as sickle cell anaemia, intravenous drug use, immunosuppression, and infective endocarditis. On the other hand, non-haematogenous osteomyelitis is caused by the spread of infection from adjacent soft tissues or direct injury to the bone. It is often polymicrobial and more common in adults, with risk factors such as diabetic foot ulcers, pressure sores, diabetes mellitus, and peripheral arterial disease.
Staphylococcus aureus is the most common cause of osteomyelitis, except in patients with sickle-cell anaemia where Salmonella species are more prevalent. To diagnose osteomyelitis, MRI is the imaging modality of choice, with a sensitivity of 90-100%.
The treatment for osteomyelitis involves a course of antibiotics for six weeks. Flucloxacillin is the preferred antibiotic, but clindamycin can be used for patients who are allergic to penicillin. Understanding the types, causes, and treatment of osteomyelitis is crucial in managing this bone infection.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 22
Incorrect
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A 14-year-old female presents to her GP with worries about never having had a menstrual period. She notes that she is noticeably shorter than her peers, despite her parents being of average height.
After ruling out pregnancy, the GP orders additional tests, which show:
FSH 15 IU/L (1-9)
LH 14 IU/L (1-12)
What is the most probable diagnosis in this scenario?Your Answer: Premature ovarian failure
Correct Answer: Turner's syndrome
Explanation:If a patient with primary amenorrhea has elevated FSH/LH levels, it may indicate the presence of gonadal dysgenesis.
Understanding Amenorrhoea: Causes, Investigations, and Management
Amenorrhoea is a condition characterized by the absence of menstrual periods. It can be classified into two types: primary and secondary. Primary amenorrhoea occurs when menstruation fails to start by the age of 15 in girls with normal secondary sexual characteristics or by the age of 13 in girls with no secondary sexual characteristics. On the other hand, secondary amenorrhoea is the cessation of menstruation for 3-6 months in women with previously normal and regular menses or 6-12 months in women with previous oligomenorrhoea.
The causes of amenorrhoea vary depending on the type. Primary amenorrhoea may be caused by gonadal dysgenesis, testicular feminization, congenital malformations of the genital tract, functional hypothalamic amenorrhoea, congenital adrenal hyperplasia, imperforate hymen, hypothalamic amenorrhoea, polycystic ovarian syndrome, hyperprolactinemia, premature ovarian failure, and thyrotoxicosis. Meanwhile, secondary amenorrhoea may be caused by stress, excessive exercise, PCOS, Sheehan’s syndrome, Asherman’s syndrome, and other underlying medical conditions.
To diagnose amenorrhoea, initial investigations may include pregnancy tests, full blood count, urea & electrolytes, coeliac screen, thyroid function tests, gonadotrophins, prolactin, and androgen levels. Management of amenorrhoea involves treating the underlying cause. For primary amenorrhoea, it is important to investigate and treat any underlying cause. For secondary amenorrhoea, it is important to exclude pregnancy, lactation, and menopause and treat the underlying cause accordingly. Women with primary ovarian insufficiency due to gonadal dysgenesis may benefit from hormone replacement therapy to prevent osteoporosis and other complications.
In conclusion, amenorrhoea is a condition that requires proper diagnosis and management. Understanding the causes and appropriate investigations can help in providing the necessary treatment and care for women experiencing this condition.
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This question is part of the following fields:
- Reproductive System
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Question 23
Incorrect
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A 70-year-old male arrives at the emergency department complaining of tearing chest pain that radiates to his back. He has a history of uncontrolled hypertension. During auscultation, a diastolic murmur is heard, which is most audible over the 2nd intercostal space, right sternal border. What chest radiograph findings are expected from this patient's presentation?
Your Answer: Calcification of the arch of the aorta
Correct Answer: Widened mediastinum
Explanation:Aortic dissection can cause a widened mediastinum on a chest x-ray. This condition is characterized by tearing chest pain that radiates to the back, hypertension, and aortic regurgitation. It occurs when there is a tear in the tunica intima of the aorta’s wall, creating a false lumen that fills with a large volume of blood.
Calcification of the arch of the aorta, cardiomegaly, displacement of the trachea from the midline, and enlargement of the aortic knob are not commonly associated with aortic dissection. Calcification of the walls of arteries is a chronic process that occurs with age and is more likely in men. Cardiomegaly can be caused by various conditions, including ischaemic heart disease and congenital abnormalities. Displacement of the trachea from the midline can result from other pathologies such as a tension pneumothorax or an aortic aneurysm. Enlargement of the aortic knob is a classical finding of an aortic aneurysm.
Aortic dissection is classified according to the location of the tear in the aorta. The Stanford classification divides it into type A, which affects the ascending aorta in two-thirds of cases, and type B, which affects the descending aorta distal to the left subclavian origin in one-third of cases. The DeBakey classification divides it into type I, which originates in the ascending aorta and propagates to at least the aortic arch and possibly beyond it distally, type II, which originates in and is confined to the ascending aorta, and type III, which originates in the descending aorta and rarely extends proximally but will extend distally.
To diagnose aortic dissection, a chest x-ray may show a widened mediastinum, but CT angiography of the chest, abdomen, and pelvis is the investigation of choice. However, the choice of investigations should take into account the patient’s clinical stability, as they may present acutely and be unstable. Transoesophageal echocardiography (TOE) is more suitable for unstable patients who are too risky to take to the CT scanner.
The management of type A aortic dissection is surgical, but blood pressure should be controlled to a target systolic of 100-120 mmHg while awaiting intervention. On the other hand, type B aortic dissection is managed conservatively with bed rest and IV labetalol to reduce blood pressure and prevent progression. Complications of a backward tear include aortic incompetence/regurgitation and MI, while complications of a forward tear include unequal arm pulses and BP, stroke, and renal failure. Endovascular repair of type B aortic dissection may have a role in the future.
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This question is part of the following fields:
- Cardiovascular System
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Question 24
Incorrect
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A 25-year-old patient comes in for her routine check-up at the psychiatric outpatient clinic. She has been diagnosed with borderline personality disorder. During the consultation, she discloses that she hears voices in her head instructing her to harm herself. Additionally, she sees apparitions of her deceased mother and cat. However, she is not frightened by these occurrences as she recognizes that they are not real. How would you characterize her atypical perceptions?
Your Answer: Organic hallucinosis
Correct Answer: Pseudohallucination
Explanation:Pseudohallucinations in Personality Disorders
Pseudohallucinations are hallucinations that patients recognize as not being real. These hallucinations can occur spontaneously and are different from true perception. Patients can stop them willingly. Patients with personality disorders, especially borderline personality disorder, may experience semi-psychotic and pseudohallucinatory episodes that are challenging to treat with medication. Psycho-social interventions and a strong therapeutic alliance are the primary therapeutic techniques, with medication as a secondary option.
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This question is part of the following fields:
- Psychiatry
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Question 25
Incorrect
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A 32-year-old woman presents to the medical unit with fevers, rigors, and night sweats. She has been experiencing increased fatigue and nausea for the past 72 hours before developing fevers.
Upon examination, she appears lethargic and diaphoretic.
Initial vital signs are as follows:
Temperature 39ºC
Blood pressure 90/60 mmHg
Heart rate 120 beats per minute
Respiratory rate 22 breaths per minute
Oxygen saturations 97% on room air
The medical team initiates empirical antibiotic therapy and intravenous fluids while performing an infection screen and blood cultures.
After 48 hours, the patient's condition has improved. The provisional report from the blood cultures indicates the growth of gram-negative bacilli.
What is the most likely organism causing the patient's infection?Your Answer: Clostridium difficile
Correct Answer: Escherichia coli
Explanation:The patient is exhibiting symptoms of sepsis, but the source of the infection is unknown. Therefore, general measures for managing sepsis are necessary, including taking urine and blood cultures, providing blood pressure support, conducting screening investigations, and administering empirical antibiotic therapy.
It is important to have some knowledge of bacteria as blood culture results typically take 48 hours to become available and come with a provisional report. In this case, the provisional description fits with Escherichia coli, an aerobic gram-negative rod that is often associated with severe systemic features and corresponds to the patient’s initial presentation of Escherichia coli bacteraemia.
Other bacteria, such as Clostridium difficile, Pseudomonas aeruginosa, Streptococcus, and Staphylococcus species, do not match the description provided. Clostridium difficile is a gram-positive bacillus that causes healthcare-associated infections and colitis, while Pseudomonas aeruginosa is more commonly associated with infections in immunocompromised patients and medical devices. Streptococcus and Staphylococcus species are gram-positive cocci and do not correspond to the description given.
Classification of Bacteria Made Easy
Bacteria are classified based on their shape, staining properties, and other characteristics. One way to simplify the classification process is to remember that Gram-positive cocci include staphylococci and streptococci, while Gram-negative cocci include Neisseria meningitidis, Neisseria gonorrhoeae, and Moraxella catarrhalis. To categorize all bacteria, only a few Gram-positive rods or bacilli need to be memorized, which can be remembered using the mnemonic ABCD L: Actinomyces, Bacillus anthracis (anthrax), Clostridium, Diphtheria (Corynebacterium diphtheriae), and Listeria monocytogenes.
The remaining organisms are Gram-negative rods, such as Escherichia coli, Haemophilus influenzae, Pseudomonas aeruginosa, Salmonella sp., Shigella sp., and Campylobacter jejuni. By keeping these classifications in mind, it becomes easier to identify and differentiate between different types of bacteria.
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This question is part of the following fields:
- General Principles
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Question 26
Incorrect
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A 45-year-old man presents to the physician complaining of fatigue, dark urine, and swelling in his lower extremities that has been ongoing for the past two weeks. He has no significant medical history and is not taking any medications. He denies using tobacco, alcohol, or drugs. During the physical examination, symmetric pitting oedema is observed in his lower extremities, and his blood pressure is 132/83 mmHg with a pulse of 84/min.
Laboratory results reveal a urea level of 4mmol/L (2.0 - 7.0) and a creatinine level of 83 µmol/L (55 - 120). Urinalysis shows 4+ proteinuria and microscopic hematuria. Electron microscopy of the kidney biopsy specimen reveals dense deposits within the glomerular basement membrane, and immunofluorescence microscopy is positive for C3, not immunoglobulins.
What is the most likely pathophysiologic mechanism underlying this patient's condition?Your Answer: Anti- GBM antibodies
Correct Answer: Persistent activation of alternate complement pathway
Explanation:The cause of membranoproliferative glomerulonephritis, type 2, is persistent activation of the alternative complement pathway, which leads to kidney damage. This condition is characterized by IgG antibodies, known as C3 nephritic factor, that target C3 convertase. In contrast, Goodpasture’s syndrome is associated with anti-GBM antibodies, while rapidly progressive glomerulonephritis may involve cell-mediated injury. Immune complex-mediated glomerulopathies, such as SLE and post-streptococcal glomerulonephritis, are caused by circulating immune complexes, while non-immunologic kidney damage is seen in diabetic nephropathy and hypertensive nephropathy.
Understanding Membranoproliferative Glomerulonephritis
Membranoproliferative glomerulonephritis, also known as mesangiocapillary glomerulonephritis, is a kidney disease that can present as nephrotic syndrome, haematuria, or proteinuria. Unfortunately, it has a poor prognosis. There are three types of this disease, with type 1 accounting for 90% of cases. It is caused by cryoglobulinaemia and hepatitis C, and can be diagnosed through a renal biopsy that shows subendothelial and mesangium immune deposits of electron-dense material resulting in a ‘tram-track’ appearance under electron microscopy.
Type 2, also known as ‘dense deposit disease’, is caused by partial lipodystrophy and factor H deficiency. It is characterized by persistent activation of the alternative complement pathway, low circulating levels of C3, and the presence of C3b nephritic factor in 70% of cases. This factor is an antibody to alternative-pathway C3 convertase (C3bBb) that stabilizes C3 convertase. A renal biopsy for type 2 shows intramembranous immune complex deposits with ‘dense deposits’ under electron microscopy.
Type 3 is caused by hepatitis B and C. While steroids may be effective in managing this disease, it is important to note that the prognosis for all types of membranoproliferative glomerulonephritis is poor. Understanding the different types and their causes can help with diagnosis and management of this serious kidney disease.
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This question is part of the following fields:
- Renal System
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Question 27
Incorrect
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A premature baby is born and the anaesthetists are struggling to ventilate the lungs because of insufficient surfactant. How does Laplace's law explain the force pushing inwards on the walls of the alveolus caused by surface tension between two static fluids, such as air and water in the alveolus?
Your Answer: Directly proportional to the radius of the alveolus
Correct Answer: Inversely proportional to the radius of the alveolus
Explanation:The Relationship between Alveolar Size and Surface Tension in Respiratory Physiology
In respiratory physiology, the alveolus is often represented as a perfect sphere to apply Laplace’s law. According to this law, there is an inverse relationship between the size of the alveolus and the surface tension. This means that smaller alveoli experience greater force than larger alveoli for a given surface tension, and they will collapse first. This phenomenon explains why, when two balloons are attached together by their ends, the smaller balloon will empty into the bigger balloon.
In the lungs, this same principle applies to lung units, causing atelectasis and collapse when surfactant is not present. Surfactant is a substance that reduces surface tension, making it easier to expand the alveoli and preventing smaller alveoli from collapsing. Therefore, surfactant plays a crucial role in maintaining the proper functioning of the lungs and preventing respiratory distress. the relationship between alveolar size and surface tension is essential in respiratory physiology and can help in the development of treatments for lung diseases.
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This question is part of the following fields:
- Basic Sciences
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Question 28
Correct
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A 75-year-old man arrives at the emergency department complaining of a squeezing pain from his loin to groin area and blood in his urine. After diagnosis, he is found to have a kidney stone measuring approximately 2mm in diameter in his left ureter. What anatomical structure must the stone pass through for conservative management?
Your Answer: Trigone of the bladder
Explanation:The trigone of the bladder is a sensitive area located at the base of the bladder, which is formed by the two ureteric orifices and the internal urethral orifice. This area plays a crucial role in sending signals to the brain for micturition as the bladder fills. When managing ureteric stones conservatively, the stone must pass through the ureteric and urethral orifice to be expelled from the body.
The corpus cavernosa refers to the tissue on either side of the penis that fills with blood during an erection.
The fascia-iliaca compartment is a theoretical space that contains the lateral femoral cutaneous nerve and femoral nerve. It is utilized when conducting a fascia-iliaca nerve block in a fractured neck of femur.
The inguinal canal is a structure formed by the muscles, aponeuroses, ligaments, and tendons of the anterior abdominal wall. In males, it contains blood vessels supplying the testicles and scrotum, the ductus deferens, as well as the nerves supplying these areas.
The pouch of Douglas is an anatomical area found only in women, specifically the recto-uterine area, and is not required for the passing of a ureteric stone.
Bladder Anatomy and Innervation
The bladder is a three-sided pyramid-shaped organ located in the pelvic cavity. Its apex points towards the symphysis pubis, while the base lies anterior to the rectum or vagina. The bladder’s inferior aspect is retroperitoneal, while the superior aspect is covered by peritoneum. The trigone, the least mobile part of the bladder, contains the ureteric orifices and internal urethral orifice. The bladder’s blood supply comes from the superior and inferior vesical arteries, while venous drainage occurs through the vesicoprostatic or vesicouterine venous plexus. Lymphatic drainage occurs mainly to the external iliac and internal iliac nodes, with the obturator nodes also playing a role. The bladder is innervated by parasympathetic nerve fibers from the pelvic splanchnic nerves and sympathetic nerve fibers from L1 and L2 via the hypogastric nerve plexuses. The parasympathetic fibers cause detrusor muscle contraction, while the sympathetic fibers innervate the trigone muscle. The external urethral sphincter is under conscious control, and voiding occurs when the rate of neuronal firing to the detrusor muscle increases.
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This question is part of the following fields:
- Renal System
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Question 29
Incorrect
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A study is proposed to determine if adolescent obesity in girls increases the likelihood of developing polycystic ovarian syndrome. What study design would be most suitable?
Your Answer: Randomised controlled trial
Correct Answer: Cohort study
Explanation:A cohort study is a more reliable source of evidence compared to a case-control study as it involves selecting two groups based on their exposure to a specific agent and monitoring their development of a disease or outcome.
There are different types of studies that researchers can use to investigate various phenomena. One of the most rigorous types of study is the randomised controlled trial, where participants are randomly assigned to either an intervention or control group. However, practical or ethical issues may limit the use of this type of study. Another type of study is the cohort study, which is observational and prospective. Researchers select two or more groups based on their exposure to a particular agent and follow them up to see how many develop a disease or other outcome. The usual outcome measure is the relative risk. Examples of cohort studies include the Framingham Heart Study.
On the other hand, case-control studies are observational and retrospective. Researchers identify patients with a particular condition (cases) and match them with controls. Data is then collected on past exposure to a possible causal agent for the condition. The usual outcome measure is the odds ratio. Case-control studies are inexpensive and produce quick results, making them useful for studying rare conditions. However, they are prone to confounding. Lastly, cross-sectional surveys provide a snapshot of a population and are sometimes called prevalence studies. They provide weak evidence of cause and effect.
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This question is part of the following fields:
- General Principles
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Question 30
Correct
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A 7-year-old girl is brought to the General Practitioner (GP) by her father. The girl has distinct ‘elfin’ facies and is well known for her friendliness to all the practice staff. On examination, an ejection systolic murmur is heard. A Fluorescent in-situ hybridisation study confirms the diagnosis.
What is the most probable cause of her condition?Your Answer: Microdeletion on chromosome 7
Explanation:William’s syndrome is caused by a microdeletion on chromosome 7 and is characterised by distinct facial features and extreme friendliness. Trinucleotide repeats are associated with Fragile X, Huntington’s, and Myotonic Dystrophy, while chromosomal trisomy can cause Down syndrome, Edwards syndrome, and Patau syndrome. Turner syndrome is caused by a karyotype of 46 XO. Viral infections at birth are not specifically associated with these conditions. Diagnosis for William’s syndrome is made with a FISH study.
Understanding William’s Syndrome
William’s syndrome is a genetic disorder that affects neurodevelopment and is caused by a microdeletion on chromosome 7. The condition is characterized by a range of physical and cognitive symptoms, including elfin-like facial features, short stature, learning difficulties, and transient neonatal hypercalcaemia. One of the most notable features of William’s syndrome is the individual’s friendly and social demeanor, which is often described as characteristic-like affect. Additionally, many individuals with William’s syndrome may also experience supravalvular aortic stenosis, a narrowing of the aorta that can lead to heart problems.
Diagnosis of William’s syndrome is typically made through FISH studies, which can detect the microdeletion on chromosome 7. While there is no cure for William’s syndrome, early intervention and support can help individuals with the condition to manage their symptoms and lead fulfilling lives. With proper care and attention, individuals with William’s syndrome can thrive and make meaningful contributions to their communities.
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This question is part of the following fields:
- General Principles
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Question 31
Incorrect
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A 70-year-old male with a 50 pack year history of smoking complains of dyspnoea, cough and facial swelling that has been worsening for the past 8 weeks. The symptoms are aggravated by leaning forward. Venous collaterals are observed on the anterior chest wall during examination.
What is the probable diagnosis?Your Answer: Restrictive cardiomyopathy
Correct Answer: Superior vena cava obstruction
Explanation:When bronchogenic carcinoma leads to SVC obstruction, patients usually experience dyspnea, cough, and swelling of the face.
Understanding Superior Vena Cava Obstruction
Superior vena cava obstruction is a medical emergency that occurs when the superior vena cava, a large vein that carries blood from the upper body to the heart, is compressed. This condition is commonly associated with lung cancer, but it can also be caused by other malignancies, aortic aneurysm, mediastinal fibrosis, goitre, and SVC thrombosis. The most common symptom of SVC obstruction is dyspnoea, but patients may also experience swelling of the face, neck, and arms, headache, visual disturbance, and pulseless jugular venous distension.
The management of SVC obstruction depends on the underlying cause and the patient’s individual circumstances. Endovascular stenting is often the preferred treatment to relieve symptoms, but certain malignancies may require radical chemotherapy or chemo-radiotherapy instead. Glucocorticoids may also be given, although the evidence supporting their use is weak. It is important to seek advice from an oncology team to determine the best course of action for each patient.
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This question is part of the following fields:
- Haematology And Oncology
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Question 32
Incorrect
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A 78-year-old woman is diagnosed with a femoral hernia and requires surgery. What structure forms the posterior wall of the femoral canal?
Your Answer: Inguinal ligament
Correct Answer: Pectineal ligament
Explanation:Understanding the Femoral Canal
The femoral canal is a fascial tunnel located at the medial aspect of the femoral sheath. It contains both the femoral artery and femoral vein, with the canal lying medial to the vein. The borders of the femoral canal include the femoral vein laterally, the lacunar ligament medially, the inguinal ligament anteriorly, and the pectineal ligament posteriorly.
The femoral canal plays a significant role in allowing the femoral vein to expand, which facilitates increased venous return to the lower limbs. However, it can also be a site of femoral hernias, which occur when abdominal contents protrude through the femoral canal. The relatively tight neck of the femoral canal places these hernias at high risk of strangulation, making it important to understand the anatomy and function of this structure. Overall, understanding the femoral canal is crucial for medical professionals in diagnosing and treating potential issues related to this area.
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This question is part of the following fields:
- Gastrointestinal System
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Question 33
Correct
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A 50-year-old woman arrives at the emergency department complaining of abrupt abdominal pain. She has a 35-pack-year smoking history and has been managing polycythemia vera for 10 years with intermittent phlebotomy. Upon initial evaluation, she appears alert and has a distended abdomen with shifting dullness and tender hepatomegaly. What is the probable diagnosis based on these observations?
Your Answer: Budd-Chiari syndrome
Explanation:Budd-Chiari syndrome is the correct diagnosis for this patient, as it is caused by hepatic vein thrombosis. The patient has significant risk factors for thrombophilia and is presenting with the classic triad of right upper quadrant abdominal pain, ascites (as evidenced by shifting dullness on examination), and hepatomegaly.
While decompensated cirrhosis can also cause ascites and hepatomegaly, it is unlikely to cause an acute abdomen and is more likely to present with associated jaundice and encephalopathy. Therefore, this option is incorrect.
Right-sided heart failure can also lead to ascites due to raised portosystemic pressure, but this option is incorrect as the patient does not have risk factors for heart failure apart from smoking and does not have other typical findings of heart failure such as dyspnea and peripheral edema.
Nephrotic syndrome can also cause ascites due to hypoalbuminemia-related fluid retention, but there is no mention of proteinuria or hypoalbuminemia, which typically causes peri-orbital edema. Therefore, this option is also incorrect.
Understanding Budd-Chiari Syndrome
Budd-Chiari syndrome, also known as hepatic vein thrombosis, is a condition that is often associated with an underlying hematological disease or another procoagulant condition. The causes of this syndrome include polycythemia rubra vera, thrombophilia, pregnancy, and the use of combined oral contraceptive pills. The symptoms of Budd-Chiari syndrome typically include sudden onset and severe abdominal pain, ascites leading to abdominal distension, and tender hepatomegaly.
To diagnose Budd-Chiari syndrome, an ultrasound with Doppler flow studies is usually the initial radiological investigation. This test is highly sensitive and can help identify the presence of the condition. It is important to diagnose and treat Budd-Chiari syndrome promptly to prevent complications such as liver failure and portal hypertension.
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This question is part of the following fields:
- Gastrointestinal System
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Question 34
Correct
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An 80-year-old man visits his GP for a follow up appointment after starting trimethoprim for a urinary tract infection 7 days ago. He mentions that his urinary symptoms have gone but that he has been feeling generally tired and weak for the last 4 weeks (before the urinary tract infection). He asks if this could be related to the new medication he started 5 weeks ago. Upon reviewing his medical history, you see that he was started on ramipril 5 weeks ago. He also mentions that his osteoarthritic pain has been quite bad recently, which caused him to miss his most recent medication review appointment, but he has been taking more paracetamol and ibuprofen than usual. Due to the combination of medication and his vague symptoms, you decide to perform an ECG. The ECG shows tall, tented T waves, prolonged PR interval, and bradycardia. What is the underlying cause of these ECG changes?
Your Answer: Hyperkalaemia
Explanation:The patient is most likely suffering from hyperkalaemia, as evidenced by their medication history which includes an increase in potassium-raising drugs such as trimethoprim, ramipril, and ibuprofen. The ECG results also show classic signs of hyperkalaemia, including tall tented T waves, bradycardia, and a prolonged PR interval.
Hyperkalaemia is a condition where there is an excess of potassium in the blood. The levels of potassium in the plasma are regulated by various factors such as aldosterone, insulin levels, and acid-base balance. When there is metabolic acidosis, hyperkalaemia can occur as hydrogen and potassium ions compete with each other for exchange with sodium ions across cell membranes and in the distal tubule. The ECG changes that can be seen in hyperkalaemia include tall-tented T waves, small P waves, widened QRS leading to a sinusoidal pattern, and asystole.
There are several causes of hyperkalaemia, including acute kidney injury, drugs such as potassium sparing diuretics, ACE inhibitors, angiotensin 2 receptor blockers, spironolactone, ciclosporin, and heparin, metabolic acidosis, Addison’s disease, rhabdomyolysis, and massive blood transfusion. Foods that are high in potassium include salt substitutes, bananas, oranges, kiwi fruit, avocado, spinach, and tomatoes.
It is important to note that beta-blockers can interfere with potassium transport into cells and potentially cause hyperkalaemia in renal failure patients. In contrast, beta-agonists such as Salbutamol are sometimes used as emergency treatment. Additionally, both unfractionated and low-molecular weight heparin can cause hyperkalaemia by inhibiting aldosterone secretion.
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This question is part of the following fields:
- Renal System
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Question 35
Incorrect
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During a block dissection of the thigh, the sartorius muscle is identified. What is the nerve supply to this muscle?
Your Answer: Posterior division of the femoral nerve
Correct Answer: Anterior division of the femoral nerve
Explanation:The superficial femoral nerve primarily provides cutaneous branches, but it also innervates the sartorius muscle.
The Sartorius Muscle: Anatomy and Function
The sartorius muscle is the longest strap muscle in the human body and is located in the anterior compartment of the thigh. It is the most superficial muscle in this region and has a unique origin and insertion. The muscle originates from the anterior superior iliac spine and inserts on the medial surface of the body of the tibia, anterior to the gracilis and semitendinosus muscles. The sartorius muscle is innervated by the femoral nerve (L2,3).
The primary action of the sartorius muscle is to flex the hip and knee, while also slightly abducting the thigh and rotating it laterally. It also assists with medial rotation of the tibia on the femur, which is important for movements such as crossing one leg over the other. The middle third of the muscle, along with its strong underlying fascia, forms the roof of the adductor canal. This canal contains important structures such as the femoral vessels, the saphenous nerve, and the nerve to vastus medialis.
In summary, the sartorius muscle is a unique muscle in the anterior compartment of the thigh that plays an important role in hip and knee flexion, thigh abduction, and lateral rotation. Its location and relationship to the adductor canal make it an important landmark for surgical procedures in the thigh region.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 36
Incorrect
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A 50-year-old man with laryngeal cancer is undergoing a challenging laryngectomy. During the procedure, the surgeons cut the thyrocervical trunk. What vessel does this structure typically originate from?
Your Answer: Common carotid artery
Correct Answer: Subclavian artery
Explanation:The subclavian artery gives rise to the thyrocervical trunk, which emerges from the first part of the artery located between the inner border of scalenus anterior and the subclavian artery. The thyrocervical trunk branches off from the subclavian artery after the vertebral artery.
Thoracic Outlet: Where the Subclavian Artery and Vein and Brachial Plexus Exit the Thorax
The thoracic outlet is the area where the subclavian artery and vein and the brachial plexus exit the thorax and enter the arm. This passage occurs over the first rib and under the clavicle. The subclavian vein is the most anterior structure and is located immediately in front of scalenus anterior and its attachment to the first rib. Scalenus anterior has two parts, and the subclavian artery leaves the thorax by passing over the first rib and between these two portions of the muscle. At the level of the first rib, the lower cervical nerve roots combine to form the three trunks of the brachial plexus. The lowest trunk is formed by the union of C8 and T1, and this trunk lies directly posterior to the artery and is in contact with the superior surface of the first rib.
Thoracic outlet obstruction can cause neurovascular compromise.
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This question is part of the following fields:
- Respiratory System
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Question 37
Incorrect
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In a confrontation, a 35-year-old woman was stabbed in the medial aspect of her left thigh. Upon examination, there is a noticeable decrease in knee extension. Additionally, there is a reduction in sensation over the anterior thigh.
Which anatomical structure has been affected by the stabbing?Your Answer: Superior gluteal nerve
Correct Answer: Femoral nerve
Explanation:The femoral nerve is responsible for loss of knee extension and sensory loss to the anterior and medial aspect of the thigh following a stab injury. The muscles innervated by the femoral nerve are responsible for hip flexion and knee extension, while the nerve is responsible for sensation over the anterior thigh. Injury to the inferior gluteal nerve would result in loss of hip extension, while injury to the obturator nerve would result in a loss of sensation to the medial thigh and impaired hip adduction. Although the quadriceps tendon is vital to knee extension, it would not explain the sensory deficit and the location of the injury.
Lower limb anatomy is an important topic that often appears in examinations. One aspect of this topic is the nerves that control motor and sensory functions in the lower limb. The femoral nerve controls knee extension and thigh flexion, and provides sensation to the anterior and medial aspect of the thigh and lower leg. It is commonly injured in cases of hip and pelvic fractures, as well as stab or gunshot wounds. The obturator nerve controls thigh adduction and provides sensation to the medial thigh. It can be injured in cases of anterior hip dislocation. The lateral cutaneous nerve of the thigh provides sensory function to the lateral and posterior surfaces of the thigh, and can be compressed near the ASIS, resulting in a condition called meralgia paraesthetica. The tibial nerve controls foot plantarflexion and inversion, and provides sensation to the sole of the foot. It is not commonly injured as it is deep and well protected, but can be affected by popliteral lacerations or posterior knee dislocation. The common peroneal nerve controls foot dorsiflexion and eversion, and can be injured at the neck of the fibula, resulting in foot drop. The superior gluteal nerve controls hip abduction and can be injured in cases of misplaced intramuscular injection, hip surgery, pelvic fracture, or posterior hip dislocation. Injury to this nerve can result in a positive Trendelenburg sign. The inferior gluteal nerve controls hip extension and lateral rotation, and is generally injured in association with the sciatic nerve. Injury to this nerve can result in difficulty rising from a seated position, as well as difficulty jumping or climbing stairs.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 38
Correct
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A 60-year-old male undergoes a bladder biopsy due to ongoing investigations into haematuria. The pathologist report reveals:
Localized transitional epithelium has been replaced by squamous epithelium in the bladder wall.
What term can be used to describe the observed alteration in the biopsy?Your Answer: Metaplasia
Explanation:Metaplasia is the process where one type of cell transforms into another type of cell.
The pathologist’s observation is most indicative of metaplasia, as there is a transformation from one mature epithelium to another mature epithelium.
1. Incorrect. Anaplasia is characterized by a lack of structural differentiation and is typically observed in malignant changes.
2. Incorrect. Dysplasia is a condition where epithelial cells lose their maturity and is caused by incomplete cellular differentiation.
3. Incorrect. This refers to an increase in the number of cells.
4. Correct.
5. Incorrect. This refers to abnormal and excessive tissue growth.
Cellular Adaptations: Hypertrophy, Hyperplasia, Metaplasia, and Dysplasia
Cellular adaptations refer to the changes that a cell undergoes in response to external pressures to survive in a different steady state. There are four main types of cellular adaptations: hypertrophy, hyperplasia, metaplasia, and dysplasia.
Hypertrophy is an increase in cell mass without an increase in cell number. This adaptive response is due to an increase in the number of intracellular organelles to maintain cell viability at high levels of aerobic metabolism.
Hyperplasia, on the other hand, is an increase in the number of cells, resulting in an increase in the volume of an organ or tissue. It can occur physiologically, under normal physiological control, or pathologically, due to excessive hormonal stimulation that is not under normal physiological control.
Metaplasia is a reversible change in form and differentiation, where one adult cell type is replaced by another adult cell type due to chronic chemical or physical irritation. This change can result in tissues having a form that they were not designed for.
Dysplasia is abnormal cell growth that is a morphological feature of malignancy, characterized by increased cell proliferation and incomplete differentiation. It can act as an early sign of a tumor, occurring at the epithelium stage where there is no invasion of the basement membrane and surrounding tissues.
In summary, cellular adaptations are essential for cells to survive in different steady states. Understanding the different types of cellular adaptations can help in the diagnosis and treatment of various diseases.
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This question is part of the following fields:
- General Principles
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Question 39
Correct
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A researcher is studying Chronic Myeloid Leukaemia (CML). She creates a fluorescent DNA probe that can attach to the BCR-ABL fusion gene to observe the Philadelphia translocation directly.
What is the molecular method employed by the scientist?Your Answer: Fluorescence In Situ Hybridisation (FISH)
Explanation:The technique of fluorescence in situ hybridization involves the use of fluorescent DNA or RNA probes that attach to particular gene locations of interest, allowing for the direct observation of chromosomal abnormalities.
Overview of Molecular Biology Techniques
Molecular biology techniques are essential tools used in the study of biological molecules such as DNA, RNA, and proteins. These techniques are used to detect and analyze these molecules in various biological samples. The most commonly used techniques include Southern blotting, Northern blotting, Western blotting, and enzyme-linked immunosorbent assay (ELISA).
Southern blotting is a technique used to detect DNA, while Northern blotting is used to detect RNA. Western blotting, on the other hand, is used to detect proteins. This technique involves the use of gel electrophoresis to separate native proteins based on their 3-D structure. It is commonly used in the confirmatory HIV test.
ELISA is a biochemical assay used to detect antigens and antibodies. This technique involves attaching a colour-changing enzyme to the antibody or antigen being detected. If the antigen or antibody is present in the sample, the sample changes colour, indicating a positive result. ELISA is commonly used in the initial HIV test.
In summary, molecular biology techniques are essential tools used in the study of biological molecules. These techniques include Southern blotting, Northern blotting, Western blotting, and ELISA. Each technique is used to detect specific molecules in biological samples and is commonly used in various diagnostic tests.
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This question is part of the following fields:
- General Principles
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Question 40
Correct
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Sophie, a 27-year-old female, is brought to the Emergency Department by ambulance after being involved in a car accident. Upon examination, it is discovered that she has a surgical neck fracture of the humerus on X-ray.
What is the structure that is most commonly at risk of damage with a surgical neck fracture of the humerus?Your Answer: Axillary nerve
Explanation:The most frequently occurring nerve injury in a surgical neck fracture of the humerus is damage to the axillary nerve. The radial nerve is at risk of injury in a mid shaft fracture of the humerus, as it passes through the radial groove. A supracondylar fracture of the humerus increases the likelihood of injury to the brachial artery, which can lead to volkmaan’s ischemic contractures.
The humerus is a long bone that runs from the shoulder blade to the elbow joint. It is mostly covered by muscle but can be felt throughout its length. The head of the humerus is a smooth, rounded surface that connects to the body of the bone through the anatomical neck. The surgical neck, located below the head and tubercles, is the most common site of fracture. The greater and lesser tubercles are prominences on the upper end of the bone, with the supraspinatus and infraspinatus tendons inserted into the greater tubercle. The intertubercular groove runs between the two tubercles and holds the biceps tendon. The posterior surface of the body has a spiral groove for the radial nerve and brachial vessels. The lower end of the humerus is wide and flattened, with the trochlea, coronoid fossa, and olecranon fossa located on the distal edge. The medial epicondyle is prominent and has a sulcus for the ulnar nerve and collateral vessels.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 41
Incorrect
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A 50-year-old man has been diagnosed with a gastrointestinal stromal tumour in his stomach. What is the typical cell type that gives rise to these tumours?
Your Answer: Brunner's glands
Correct Answer: Interstitial cells of Cajal
Explanation:Gastrointestinal stromal tumors (GISTs) originate from Cajal’s interstitial pacemaker cells, which are typically found outside the mucosal layer and cause minimal damage to it.
Gastrointestinal Stromal Tumours: Characteristics and Treatment Options
Gastrointestinal stromal tumours (GISTs) are rare tumours that originate from the interstitial pacemaker cells of Cajal. These tumours are primarily found in the stomach (70%), with the remainder occurring in the small intestine (20%) and colon/rectum (5%). Most GISTs are solitary lesions and are sporadic in nature. The majority of GISTs express CD117, a transmembrane tyrosine kinase receptor, and have a mutation of the c-KIT gene.
The main goal of surgery for GISTs is to resect the tumour with a 1-2 cm margin of normal tissue. Extensive resections are not usually required. However, there is a high local recurrence rate, which is related to the site of the tumour, incomplete resections, and high mitotic count. Salvage surgery for recurrent disease is associated with a median survival of 15 months.
In high-risk patients, the use of imatinib has greatly improved prognosis. In the ACOSOG trial, imatinib reduced relapse rates from 17% to 2%. In the UK, imatinib is recommended by NICE for use in patients with metastatic disease or locally unresectable disease.
Overall, GISTs are rare tumours that require careful management. Surgery with a margin of normal tissue is the mainstay of treatment, but the risk of recurrence is high. Imatinib has shown promise in improving prognosis for high-risk patients.
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This question is part of the following fields:
- Gastrointestinal System
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Question 42
Incorrect
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What is the cause of the tubercle bacillus' pathogenicity?
Your Answer: Necrosis caused by expanding granulomas
Correct Answer: Delayed hypersensitivity reaction against bacteria
Explanation:The cell mediated immunity response to mycobacteria is targeted and effective in reducing infection, but it also causes tissue damage through delayed hypersensitivity. Although necrosis can occur in tuberculosis, it typically occurs within the granuloma.
Understanding Tuberculosis: The Pathophysiology and Risk Factors
Tuberculosis is a bacterial infection caused by Mycobacterium tuberculosis. The pathophysiology of tuberculosis involves the migration of macrophages to regional lymph nodes, forming a Ghon complex. This complex leads to the formation of a granuloma, which is a collection of epithelioid histiocytes with caseous necrosis in the center. The inflammatory response is mediated by a type 4 hypersensitivity reaction. While healthy individuals can contain the disease, immunocompromised individuals are at risk of developing disseminated (miliary) TB.
Several risk factors increase the likelihood of developing tuberculosis. These include having lived in Asia, Latin America, Eastern Europe, or Africa for years, exposure to an infectious TB case, and being infected with HIV. Immunocompromised individuals, such as diabetics, patients on immunosuppressive therapy, malnourished individuals, or those with haematological malignancies, are also at risk. Additionally, silicosis and apical fibrosis increase the likelihood of developing tuberculosis. Understanding the pathophysiology and risk factors of tuberculosis is crucial in preventing and treating this infectious disease.
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This question is part of the following fields:
- General Principles
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Question 43
Incorrect
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A 65-year-old woman comes to the clinic complaining of a severe headache on both sides of her temples. Upon further inquiry, she reports a temporary loss of vision in one eye and pain in her jaw. What is the probable diagnosis?
Your Answer: Cluster headache
Correct Answer: Temporal/giant cell arteritis
Explanation:Temporal arteritis, space occupying lesions, migraines, and tension headaches all cause headaches, but they differ in their specific symptoms and causes. Temporal arteritis causes pain in the inflamed temporal artery, which can also lead to jaw pain and temporary vision loss. Space occupying lesions can cause severe morning headaches with vomiting. Migraines are characterized by hours-long headache attacks preceded by an aura and changes in mood, appetite, and sleepiness. Tension headaches cause a band-like pain around the head and are often associated with stress.
Temporal arteritis is a type of large vessel vasculitis that often occurs in patients over the age of 60 and is commonly associated with polymyalgia rheumatica. This condition is characterized by changes in the affected artery that skip certain sections while damaging others. Symptoms of temporal arteritis include headache, jaw claudication, and visual disturbances, with anterior ischemic optic neuropathy being the most common ocular complication. A tender, palpable temporal artery is also often present, and around 50% of patients may experience symptoms of PMR, such as muscle aches and morning stiffness.
To diagnose temporal arteritis, doctors will typically look for elevated inflammatory markers, such as an ESR greater than 50 mm/hr or elevated CRP levels. A temporal artery biopsy may also be performed to confirm the diagnosis, with skip lesions often being present. Treatment for temporal arteritis involves urgent high-dose glucocorticoids, which should be given as soon as the diagnosis is suspected and before the temporal artery biopsy. If there is no visual loss, high-dose prednisolone is typically used, while IV methylprednisolone is usually given if there is evolving visual loss. Patients with visual symptoms should be seen by an ophthalmologist on the same day, as visual damage is often irreversible. Other treatments may include bone protection with bisphosphonates and low-dose aspirin, although the evidence supporting the latter is weak.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 44
Correct
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Which nerve is in danger during removal of the submandibular gland?
Your Answer: Marginal mandibular nerve
Explanation:The depressor anguli oris and depressor labii inferioris muscles are supplied by the marginal mandibular nerve, which is located beneath the platysma muscle. Damage to this nerve can result in facial asymmetry and drooling.
Anatomy of the Submandibular Gland
The submandibular gland is located beneath the mandible and is surrounded by the superficial platysma, deep fascia, and mandible. It is also in close proximity to various structures such as the submandibular lymph nodes, facial vein, marginal mandibular nerve, cervical branch of the facial nerve, deep facial artery, mylohyoid muscle, hyoglossus muscle, lingual nerve, submandibular ganglion, and hypoglossal nerve.
The submandibular duct, also known as Wharton’s duct, is responsible for draining saliva from the gland. It opens laterally to the lingual frenulum on the anterior floor of the mouth and is approximately 5 cm in length. The lingual nerve wraps around the duct, and as it passes forward, it crosses medial to the nerve to lie above it before crossing back, lateral to it, to reach a position below the nerve.
The submandibular gland receives sympathetic innervation from the superior cervical ganglion and parasympathetic innervation from the submandibular ganglion via the lingual nerve. Its arterial supply comes from a branch of the facial artery, which passes through the gland to groove its deep surface before emerging onto the face by passing between the gland and the mandible. The anterior facial vein provides venous drainage, and the gland’s lymphatic drainage goes to the deep cervical and jugular chains of nodes.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 45
Incorrect
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A young woman comes in with a sudden and severe headache at the back of her head, which quickly leads to seizures. Upon examination, doctors discover an aneurysm. During the assessment, they observe that her right eye is displaced downwards and to the side. What could be the probable reason for this?
Your Answer: Superior rectus damage
Correct Answer: Oculomotor nerve palsy
Explanation:When someone has oculomotor nerve palsy, their medial rectus muscle is disabled, which causes the lateral rectus muscle to move the eye uncontrollably to the side. Additionally, the superior rectus, inferior rectus, and inferior oblique muscles are also affected, causing the eye to move downwards due to the unopposed action of the superior oblique muscle. This condition also results in ptosis, or drooping of the eyelid, due to paralysis of the levator palpebrae superioris muscle, and mydriasis, or dilation of the pupil, due to damage to the parasympathetic fibers.
Disorders of the Oculomotor System: Nerve Path and Palsy Features
The oculomotor system is responsible for controlling eye movements and pupil size. Disorders of this system can result in various nerve path and palsy features. The oculomotor nerve has a large nucleus at the midbrain and its fibers pass through the red nucleus and the pyramidal tract, as well as through the cavernous sinus into the orbit. When this nerve is affected, patients may experience ptosis, eye down and out, and an inability to move the eye superiorly, inferiorly, or medially. The pupil may also become fixed and dilated.
The trochlear nerve has the longest intracranial course and is the only nerve to exit the dorsal aspect of the brainstem. Its nucleus is located at the midbrain and it passes between the posterior cerebral and superior cerebellar arteries, as well as through the cavernous sinus into the orbit. When this nerve is affected, patients may experience vertical diplopia (diplopia on descending the stairs) and an inability to look down and in.
The abducens nerve has its nucleus in the mid pons and is responsible for the convergence of eyes in primary position. When this nerve is affected, patients may experience lateral diplopia towards the side of the lesion and the eye may deviate medially. Understanding the nerve path and palsy features of the oculomotor system can aid in the diagnosis and treatment of disorders affecting this important system.
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This question is part of the following fields:
- Neurological System
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Question 46
Correct
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In 2015, The New England Journal of Medicine published a study on the effects of empagliflozin, a sodium-glucose co-transporter 2 inhibitor, on patients with type 2 diabetes over the age of 60 who were at high risk of cardiovascular events. The study found that empagliflozin reduced the incidence of cardiovascular deaths, non-fatal myocardial infarction, and non-fatal stroke compared to a placebo. The event rate for empagliflozin was 37.3/1000 patient years, while the event rate for the placebo was 43.9/1000 patient years. Based on this information, how many patients over the age of 60 and at high risk of adverse cardiovascular outcomes need to be treated with empagliflozin to prevent one cardiovascular death, non-fatal myocardial infarction, or non-fatal stroke?
Your Answer: 150
Explanation:Numbers needed to treat (NNT) is a measure that determines how many patients need to receive a particular intervention to reduce the expected number of outcomes by one. To calculate NNT, you divide 1 by the absolute risk reduction (ARR) and round up to the nearest whole number. ARR can be calculated by finding the absolute difference between the control event rate (CER) and the experimental event rate (EER). There are two ways to calculate ARR, depending on whether the outcome of the study is desirable or undesirable. If the outcome is undesirable, then ARR equals CER minus EER. If the outcome is desirable, then ARR is equal to EER minus CER. It is important to note that ARR may also be referred to as absolute benefit increase.
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This question is part of the following fields:
- General Principles
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Question 47
Incorrect
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A study is conducted for a new anti-aging cream that aims to improve skin elasticity. 200 volunteers are recruited and split into two groups - cream or placebo - without being told which group they are put into. 120 are put in the cream group and 80 in the control (placebo) group. They are asked to apply their cream, not knowing if it is the anti-aging cream or a placebo, and to record whether or not they achieve an acceptable level of improvement in skin elasticity.
Out of the 120 in the cream group, 90 report successfully achieving adequate improvement in skin elasticity. Out of the 80 in the control group, 20 report achieving adequate improvement in skin elasticity.
What are the odds of achieving adequate improvement in skin elasticity with the new anti-aging cream?Your Answer: 0.25
Correct Answer: 3
Explanation:Understanding Odds and Odds Ratio
When analyzing data, it is important to understand the difference between odds and probability. Odds are a ratio of the number of people who experience a particular outcome to those who do not. On the other hand, probability is the fraction of times an event is expected to occur in many trials. While probability is always between 0 and 1, odds can be any positive number.
In case-control studies, odds ratios are the usual reported measure. This ratio compares the odds of a particular outcome with experimental treatment to that of a control group. It is important to note that odds ratios approximate to relative risk if the outcome of interest is rare.
For example, in a trial comparing the use of paracetamol for dysmenorrhoea compared to placebo, the odds of achieving significant pain relief with paracetamol were 2, while the odds of achieving significant pain relief with placebo were 0.5. Therefore, the odds ratio was 4.
Understanding odds and odds ratio is crucial in interpreting data and making informed decisions. By knowing the difference between odds and probability and how to calculate odds ratios, researchers can accurately analyze and report their findings.
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This question is part of the following fields:
- General Principles
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Question 48
Correct
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A 7-year-old boy is brought to the clinic by his father, who is worried about his son's hearing. The father has noticed that his son frequently asks him to repeat himself and tends to turn up the volume on the TV. During Weber's test, the patient indicates that the sound is louder on the right side. What conclusion can be drawn from this finding?
Your Answer: Can not tell which side is affected.
Explanation:The Weber test alone cannot determine which side of the patient’s hearing is affected. The test involves placing a tuning fork on the forehead and asking the patient to report if the sound is symmetrical or louder on one side. If the sound is louder on the left side, it could indicate a conductive hearing loss on the left or a sensorineural hearing loss on the right. To obtain more information, the Weber test should be performed in conjunction with the Rinne test, which involves comparing air conduction and bone conduction.
Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness
Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.
Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.
The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.
Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.
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This question is part of the following fields:
- Respiratory System
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Question 49
Correct
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A 28-year-old man visits his GP complaining of weight loss, fevers, and night sweats that have persisted for several months. Upon examination, he has non-tender lymphadenopathy. He is referred to a specialist and eventually diagnosed with Hodgkin's lymphoma. At the haematological cancer multidisciplinary team meeting, it is decided to initiate vincristine treatment.
At what stage of the cell cycle does this medication take effect?Your Answer: Metaphase
Explanation:Vincristine disrupts the metaphase stage of the cell cycle. This is when chromosomes align in the middle of the cell and begin to separate. By binding to the tubulin protein, Vincristine prevents the formation of microtubules, which stops the initiation of chromosome separation. As a result, the cell undergoes apoptosis. Vincristine does not act during anaphase, cytokinesis, or prophase.
Mitosis: The Process of Somatic Cell Division
Mitosis is a type of cell division that occurs in somatic cells during the M phase of the cell cycle. This process allows for the replication and growth of tissues by producing genetically identical diploid daughter cells. Before mitosis begins, the cell prepares itself during the S phase by duplicating its chromosomes. The phases of mitosis include prophase, prometaphase, metaphase, anaphase, telophase, and cytokinesis. During prophase, the chromatin in the nucleus condenses, and during prometaphase, the nuclear membrane breaks down, allowing microtubules to attach to the chromosomes. In metaphase, the chromosomes align at the middle of the cell, and in anaphase, the paired chromosomes separate at the kinetochores and move to opposite sides of the cell. Telophase occurs when chromatids arrive at opposite poles of the cell, and cytokinesis is the final stage where an actin-myosin complex in the center of the cell contacts, resulting in it being pinched into two daughter cells.
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This question is part of the following fields:
- General Principles
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Question 50
Incorrect
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You perform venepuncture on the basilic vein in the cubital fossa.
At which point does this vein pass deep under muscle?Your Answer: At the medial epicondyle
Correct Answer: Midway up the humerus
Explanation:When the basilic vein is located halfway up the humerus, it travels beneath muscle. At the cubital fossa, the basilic vein connects with the median cubital vein, which in turn interacts with the cephalic vein. Contrary to popular belief, the basilic vein does not pass through the medial epicondyle. Meanwhile, the cephalic vein can be found in the deltopectoral groove.
The Basilic Vein: A Major Pathway of Venous Drainage for the Arm and Hand
The basilic vein is one of the two main pathways of venous drainage for the arm and hand, alongside the cephalic vein. It begins on the medial side of the dorsal venous network of the hand and travels up the forearm and arm. Most of its course is superficial, but it passes deep under the muscles midway up the humerus. Near the region anterior to the cubital fossa, the basilic vein joins the cephalic vein.
At the lower border of the teres major muscle, the anterior and posterior circumflex humeral veins feed into the basilic vein. It is often joined by the medial brachial vein before draining into the axillary vein. The basilic vein is continuous with the palmar venous arch distally and the axillary vein proximally. Understanding the path and function of the basilic vein is important for medical professionals in diagnosing and treating conditions related to venous drainage in the arm and hand.
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This question is part of the following fields:
- Cardiovascular System
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