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Question 1
Correct
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A 20-year old male was involved in an accident and has presented to the Emergency Department with a pelvic crush injury. The clinical exam according to ATLS protocol revealed the following: Airway-patent, Breathing - respiratory rate 25 breaths per minute. Breath sounds are vesicular and there are no added sounds. Circulation - Capillary refill time - 4 seconds. Peripheries are cool. Pulse 125 beats/min. BP - 125/95 mmHg. Disability - GSC 15, anxious and in pain. Secondary survey reveals no other injuries. The patient is administered high flow oxygen and IV access is established. The most appropriate IV fluid regimen in this case will be which of the following?
Your Answer: Judicious infusion of Hartmann's solution to maintain a systolic blood pressure greater than 90mmHg
Explanation:These clinical signs suggest that 15-30% of circulating blood volume has been lost.
Pelvic fractures are associated with significant haemorrhage (>2000 ml) that can be concealed. This may require aggressive fluid resuscitation which is initially with crystalloids and then blood. What is also important is including stabilisation of the fracture(s) and pain relief.
The Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock is as follows:
Class I haemorrhage (blood loss up to 15%):
40% blood volume loss):
Preterminal event patient will die in minutes
Marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure (or unobtainable diastolic pressure)
Mental state is markedly depressed
Skin cold and pale.
Needs rapid transfusion and immediate surgical intervention.A blood loss of >50% results in loss of consciousness, pulse and blood pressure.
Fluid resuscitation following trauma is a controversial area.
This clinical scenario points to a 15-30% blood loss. However, further crystalloid and blood replacement may be required after assessing the clinical situation. There is increasing evidence to suggest that transfusion of large volumes of crystalloid in the hospital setting are likely to be deleterious to the patient and hypotensive resuscitation and judicious blood and blood product resuscitation is a more appropriate option. A ratio of 1 unit of plasma to 1 unit of red blood cells is used to replace fluid volume in adults.
This patient does not require immediate transfusion of O negative blood and there is time for a formal crossmatch. The argument about colloids versus crystalloids has existed for decades. However, while they have a role in fluid resuscitation, they are not first line.
There is a risk of anaphylaxis, Hypernatraemia, and acute renal injury with colloidal solutions.
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This question is part of the following fields:
- Physiology
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Question 2
Correct
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A 16-year-old female presented to the hospital with a chief complaint of headache, photophobia, fever, and confusion. She is treated empirically with antibiotics. Which of the following represents the correct mechanism of action of the most commonly used first-line antibiotic class?
Your Answer: Inhibition of cell wall synthesis
Explanation:Based on the presenting symptoms, this is the case of bacterial meningitis. The treatment of choice for bacterial meningitis is a cephalosporin. Cephalosporin acts by inhibiting bacterial cell wall synthesis.
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This question is part of the following fields:
- Pharmacology
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Question 3
Incorrect
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What structure is most posterior at the porta hepatis?
Your Answer: Common bile duct
Correct Answer: Portal vein
Explanation:The structures in the porta hepatis from anterior to posterior are:
The ducts: Most anterior are the left and right hepatic ducts.
The arteries: Next are the left and right hepatic arteries
The veins: Next is the portal vein
The epiploic foramen of Winslow lies most posterior at the porta hepatis.
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This question is part of the following fields:
- Anatomy
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Question 4
Incorrect
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Provided below is an abstract of a study conducted recently. A consensus was developed among international experts. A total of 27 experts were invited. 91% of them decided to show up. A systematic review was performed. This comprised of open ended questions and the participants were encouraged to provide suggestions by e-mail. In the second phase google forms were used. Participants were asked to rate survey items on a scale of 5 points. Items that were rated critical by no less than 80% of the experts were included. Items that were rendered important by 65-79% of experts were inducted in the next survey for re rating. Items that were rated below 65% were rejected. Which of the following methods was used in the study from which the abstract has been taken?
Your Answer: Multi-modal method
Correct Answer: The Delphi method
Explanation:The process used in the study is Delphi method. This method kicks off with an open ended questionnaire and uses its responses as a survey instrument for the next round in which each of the participants is asked to rate the items that the investigators have summarized on the basis of the data collected in the first round.
Any disagreement is further discussed in phases to come on the basis of information obtained from previous phases.
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This question is part of the following fields:
- Statistical Methods
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Question 5
Correct
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In which of the following situations will a regional fall in cerebral blood flow occur, suppose there is no changes in the mean arterial pressure (MAP)?
Your Answer: Hyperoxia
Explanation:The response of cerebral blood flow (CBF) to hyperoxia (PaO2 >15 kPa, 113 mmHg), the cerebral oxygen vasoreactivity is less well defined. A study originally described, using a nitrous oxide washout technique, a reduction in CBF of 13% and a moderate increase in cerebrovascular resistance in subjects inhaling 85-100% oxygen. Subsequent human studies, using a variety of differing methods, have also shown CBF reductions with hyperoxia, although the reported extent of this change is variable. Another study assessed how supra-atmospheric pressures influenced CBF, as estimated by changes in middle cerebral artery flow velocity (MCAFV) in healthy individuals. Atmospheric pressure alone had no effect on MCAFV if PaO2 was kept constant. Increases in PaO2 did lead to a significant reduction in MCAFV; however, there were no further reductions in MCAFV when oxygen was increased from 100% at 1 atmosphere of pressure to 100% oxygen at 2 atmospheres of pressure. This suggests that the ability of cerebral vasculature to constrict in response to increasing partial pressure of oxygen is limited.
Increases in arterial blood CO2 tension (PaCO2) elicit marked cerebral vasodilation.
CBF increases with general anaesthesia, ketamine anaesthesia, and hypoviscosity.
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This question is part of the following fields:
- Physiology
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Question 6
Incorrect
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With a 10-day history of severe vomiting, a 71-year-old man with a gastric outlet obstruction is admitted to the surgical ward. The serum biochemical results listed below are available: Sodium 128 mmol/L (137-144), Potassium 2.6 mmol/L (3.5-4.9), Chloride 50 mmol/L (95-107), Urea 12 mmol/L (2.5-7.5), Creatinine 180 µmol/L (60-110). Which of the following do you think you are most likely to encounter?
Your Answer: pH 7.4-7.45
Correct Answer: The standard base excess will be higher than actual base excess
Explanation:Hydrochloric acid is lost when you vomit for a long time (HCl). As a result, the following can be expected, in varying degrees of severity:
Hypokalaemia
Hypochloraemia
Increased bicarbonate to compensate for chloride loss and metabolic alkalosisThe alkalosis causes potassium to move from the intracellular to the extracellular compartment at first. Long-term vomiting and dehydration cause potassium to be excreted by the kidneys in order to conserve sodium. Dehydration can cause urea and creatinine levels to rise.
The actual base excess is always greater than the standard base excess.
The actual base excess (BE) is a measurement of a base’s contribution to a blood gas picture’s metabolic component. It’s the amount of base that needs to be added to a blood sample to bring the pH back to 7.4 after the respiratory component of a blood gas picture has been corrected (PaCO2 of 40 mmHg or 5.3 kPa). The BE has a normal range of +2 to 2. A large positive BE indicates a severe metabolic alkalosis, while a large negative BE indicates a severe metabolic acidosis. As a result, the actual BE in vitro is unaffected by CO2.
In vivo, however, standard BE is not independent of pCO2 because blood with haemoglobin acts as a better buffer than total ECF.
As a result, it is impossible to tell the difference between compensating for a respiratory disorder and compensating for the presence of a primary metabolic disorder.
The differences between in vitro and in vivo behaviour can be mostly eliminated if the BE is calculated for a haemoglobin concentration of 50 g/L (the ‘effective’ or virtual value of Hb if it was distributed throughout the extracellular space) rather than the actual haemoglobin. Because haemoglobin has a lower buffering capacity, the standard BE is higher than the actual BE. It reflects the BE better in the extracellular space rather than just the intravascular compartment.
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This question is part of the following fields:
- Pathophysiology
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Question 7
Incorrect
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Which of the following statements is true regarding Adrenaline or Epinephrine?
Your Answer: Acts on dopaminergic receptors
Correct Answer: Stimulates ACTH secretion
Explanation:Adrenaline is released by the adrenal glands, acts on α 1 and 2, β 1 and 2 receptors, and is responsible for fight or flight response.
It acts on β 2 receptors in skeletal muscle vessels-causing vasodilation.
It acts on α adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.
It acts on β adrenergic receptors to stimulate glucagon secretion in the pancreas
It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue -
This question is part of the following fields:
- Pharmacology
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Question 8
Incorrect
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What structure is most critical in providing support for the duodenojejunal flexure?
Your Answer: Ligament of Treves
Correct Answer: Ligament of Treitz
Explanation:The duodenojejunal flexure is the point where the duodenum becomes the jejunum.
The ligament of Treitz, which arises from the right crus of diaphragm, provides suspension for support.
Between the ileum and the caecum is the ligament of Treves.
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This question is part of the following fields:
- Anatomy
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Question 9
Correct
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Regarding metal wires, which of the following is the most important determinant of their resistance?
Your Answer: Resistivity
Explanation:Electrical resistivity is a measure of a material’s property to oppose the flow of electric current. This is expressed in Ohm-meters (Ω‹…m). The symbol of resistivity is usually the Greek letter Ï� (rho). A high resistivity means that a material does not conduct electric charge well.
Electrical resistivity is defined as the relation between the electric field inside a material, and the electric current through it as a consequence:
� = E/J
in which Ï� is the resistivity of the material (Ω‹…m),
E is the magnitude of the electrical field in the material (V/m),
J is the magnitude of the electric current density in the material (A/m2)If the electric field (E) through a material is very large and the flow of current (J) is very small, it means that the material has a high resistivity.
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This question is part of the following fields:
- Basic Physics
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Question 10
Correct
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A new proton pump inhibitor (PPI) is being evaluated in elderly patients who are taking aspiring. Study designed has 120 patients receiving the PPI, while a control group of 240 individuals is given the standard PPI. Over a span of 6 years, 24 of the group receiving the new PPI had an upper GI bleed compared to 60 individuals who received the standard PPI. How would you calculate the absolute risk reduction?
Your Answer: 5%
Explanation:Absolute risk reduction = (Control event rate) – (Experimental event rate)
Experimental event rate = 24 / 120 = 0.2
Control event rate = 60 / 240 = 0.25
Absolute risk reduction = 0.25 – 0.2 = 0.05 = 5% reduction
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This question is part of the following fields:
- Statistical Methods
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Question 11
Correct
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You decide to conduct research on the normal rates of gastric emptying in healthy people. The strategy is to give a drug orally and measure plasma concentrations at predetermined intervals. Which of the following drugs would you choose to use?
Your Answer: Paracetamol
Explanation:Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is approaching 100%. As a result, measuring paracetamol levels in plasma after an oral paracetamol dose has been used as a surrogate marker of gastric emptying. This method has been used to investigate the effects of drugs on gastric emptying. At clinically used doses, paracetamol is ideal because it has very few side effects.
Scintigraphic imaging is the gold standard for determining gastric emptying.
Although aspirin (acetyl salicylic acid) is absorbed primarily in the small intestine, some may also be absorbed in the stomach. The oral bioavailability ranges from 70 to 100 percent, making it less reliable than paracetamol.
Propranolol is a lipophilic drug that is rapidly absorbed after administration. However, it is highly metabolised by the liver in the first pass, and only about 25% of propranolol reaches the systemic circulation. It’s not the best indicator of gastric emptying.
Oral bioavailability of gentamicin and vancomycin is low. Only antibiotic-induced pseudomembranous colitis is treated with oral vancomycin.
Erythromycin is a pro-kinetic agent that acts as a motilin receptor agonist.
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This question is part of the following fields:
- Pharmacology
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Question 12
Incorrect
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Which of the following is the smallest value of pressure?
Your Answer: 1,520 mmHg
Correct Answer: 14.69 psi
Explanation:The SI unit of pressure is the pascal (Pa) and it is equal to one newton (N) per square meter (m2) or N/m2.
1 atmosphere (atm) is the equivalent of:
101325 Pa760 mmHg
1.01325 bar
1033.23 cmH2O.
14.69 pounds per square inch (psi)
1013.25 millibar (mbar) or hectopascals (hPa), and14.69 psi is equal to one atmosphere. The other values are equal to two atmospheres of pressure.
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This question is part of the following fields:
- Basic Physics
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Question 13
Correct
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Which of the following is correct about the action of bile salts?
Your Answer: Emulsification of lipids
Explanation:The emulsification and absorption of fats requires Bile salts.
Absorption of fats is associated with the activation of lipases in the intestine.
Bile salts are involved in fat soluble vitamin absorption and are reabsorbed in the terminal ileum (B12 is NOT fat soluble).
Although Vitamin B12 is also absorbed in the terminal ileum, it is a water soluble vitamin (as are B1, nicotinic acid, folic acid and vitamin C) .
The gastric parietal cells secretes Intrinsic factor that is essential for the absorption of B12.
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This question is part of the following fields:
- Pathophysiology
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Question 14
Incorrect
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The population incidence of a disease is best described by?
Your Answer: The number of cases of a disease in a population over a defined time period
Correct Answer: The number of new cases of a disease per population in a defined period
Explanation:The incidence of a disease is the number of new cases of the disease in a population over a defined time period.
The prevalence of a disease is the number of cases of the disease in a population over a defined time period describes. It is NOT the number of new cases.
The number of new cases of a disease only, has no denominator (time period or population) from which to derive an incidence.
The number of new cases of a disease seeking medical treatment is the incidence of patients seeking medical treatment NOT the incidence of the disease in a population.
The death rate from a disease is the number of patients dying from the disease in a population.
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This question is part of the following fields:
- Statistical Methods
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Question 15
Correct
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Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.
Your Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation
Explanation:Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).
Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.
Smooth muscle vasodilatation results from:
1. Light chain phosphatase activation.
2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
3. Hyperpolarisation of cells by activation of H+ channels. -
This question is part of the following fields:
- Pathophysiology
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Question 16
Correct
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Which of the following is the best associated option with Kaplan-Meier survival plot?
Your Answer: An estimate of decreasing survival with time after an event.
Explanation:Also known as the €œproduct limit estimate”, the Kaplan-Meier survival plot is used to estimate the true survival function from the collected data.
Using this plot, probabilities of occurrence of an event at a certain point in time can be computed. The successive probabilities are multiplied by any earlier computed probabilities to get the final estimate. For a given population, the survival probability at any particular time on the plot = (number of subjects living at the start – number of subjects who died)/number of subjects living at the start.
The description of a scatter plot is a graphical representation using Cartesian coordinates to display values for more than two variables for data set. It is used for to assess the relationship between 2 different variables.
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This question is part of the following fields:
- Statistical Methods
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Question 17
Correct
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Where should you insert a needle to obtain a femoral artery sample to be used for an arterial blood gas?
Your Answer: Mid inguinal point
Explanation:The needle should be inserted just below the skin at the mid inguinal point which is the surface indicator for the femoral artery.
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This question is part of the following fields:
- Anatomy
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Question 18
Correct
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The right coronary artery supplies blood to all the following, except which?
Your Answer: The circumflex artery
Explanation:The right coronary artery supplies the right ventricle, the right atrium, the sinoatrial (SA) node and the atrioventricular (AV) node.
The circumflex artery originates from the left coronary artery and is supplied by it.
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This question is part of the following fields:
- Anatomy
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Question 19
Incorrect
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A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated with mitral valve repair. What is true regarding the mitral valve?
Your Answer: It has two anterior cusps
Correct Answer: Its closure is marked by the first heart sound
Explanation:The mitral valve is the valve between the left atrium and left ventricle. It opens when the heart is in diastole (relaxation) which allows blood to flow from the left atrium to the left ventricle. In systole (contraction), the mitral valve closes to prevent the backflow of blood from the left ventricle to the left atrium.
The mitral valve is located posterior to the sternum at the level of the 4th costal cartilage. It is best auscultated over the cardiac apex, where its closure marks the first heart sound.
The mitral valve anatomy is composed of five main structures:
1. Left atrial wall – the myocardium of the left atrial wall extends over the posterior leaflet of the mitral valve. (left atrial enlargement is one of the causes for mitral regurgitation)
2. Mitral annulus – a fibrous ring that connects with the anterior and posterior leaflets. It functions as a sphincter that contracts and reduces the surface area of the valve during systole (Annular dilatation can also lead to mitral regurgitation)
3. Mitral valve leaflets (cusps) – The mitral valve is the only valve in the heart with two cusps or leaflets. One anterior and one posterior.
i. The anterior leaflet is located posterior to the aortic root and is also anchored to the aortic root.
ii. The posterior leaflet is located posterior to the two commissural areas.
4. Chordae tendinae – The chordae tendinae connects both the cusps to the papillary muscles.
5. Papillary muscles – These muscles and their cords support the mitral valve, allowing the cusps to resist the pressure developed during contractions (pumping) of the left ventricleThe anterior and posterior cusps are attached to the chordae tendinae which itself is attached to the left ventricle via papillary muscle.
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This question is part of the following fields:
- Anatomy
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Question 20
Incorrect
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Many of the processes we deal with in anaesthesia entail a relationship between two or more variables. Which of the following relationships is a linear relationship?
Your Answer: The relationship between a decrease in plasma concentration of an intravenous bolus of a drug with time for a single compartment model
Correct Answer: The relationship between the junction potential and temperature in a thermocouple
Explanation:Two bonded wires of dissimilar metals, iron/constantan or copper/constantan, make up a thermocouple (constantan is an alloy of copper and nickel). At the tip, a thermojunction voltage is generated that is proportional to temperature (Seebeck effect).
All of the other connections are non-linear.
For a single compartment model, the relationship between a decrease in plasma concentration of an intravenous bolus of a drug and time is a washout exponential.
A sine wave is the relationship between current and degrees or time from a mains power source.
A sigmoid curve represents the relationship between efficacy and log-dose of a pure agonist on mu receptors.
The pressure of a fixed mass of gas and its volume (Boyle’s law) at a fixed temperature are inversely proportional, resulting in a hyperbolic curve.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 21
Incorrect
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A 31-year old Caucasian female came into the emergency department due to difficulty of breathing. History revealed exposure to room odorizes that are rich in alkyl nitrites. Upon physical examination, patient is tachypnoeic at 32 breaths per minute, desaturated at 88% while on a non-rebreather mask at 15 litres per minute oxygen. She was also noted to be cyanotic, however with clear breath sounds. Considering the history, what is the most probable cause of her difficulty of breathing?
Your Answer: Low arterial oxygen tension
Correct Answer: Increased affinity of bound oxygen to haemoglobin
Explanation:Amyl nitrate is part of the treatment of cyanide poisoning. The short acting nitrate causes oxidation of Fe2+ in haemoglobin to Fe3+ in methaemoglobin. Methaemoglobin combines with cyanide (cyanmethemoglobin), which reacts with sodium thiosulfate to convert nontoxic thiocyanate and methaemoglobin.
Methaemoglobin is formed when the iron in haemoglobin is converted from the reduced state (Fe2+) to the oxidized state (Fe3+). The oxidized form of haemoglobin (Fe3+) does not bind oxygen as readily as Fe2+, but has high affinity for cyanide. It also results to high affinity of bound oxygen to haemoglobin, thus leading to tissue hypoxia. Arterial oxygen tension is normal despite observations of cyanosis and dyspnoea. Methemoglobinemia can be treated with methylene blue and vitamin C.
Carboxyhaemoglobin can be due to carbon monoxide poisoning. In such cases, patients experience headache and dizziness, but do not develop cyanosis.
2,3-diphosphoglycerate causes a shift in the oxygen dissociation curve to the right, decreasing haemoglobin’s affinity to oxygen to facilitate unloading of oxygen to the tissues.
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This question is part of the following fields:
- Pathophysiology
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Question 22
Correct
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A 55-year-old woman presents for transsphenoidal surgery following a diagnosis of pituitary macroadenoma. Which of the following is the most common visual field defect caused by such lesions?
Your Answer: Bitemporal hemianopia
Explanation:Pituitary tumours that compress the optic chiasma primarily affect the neurones that decussate at this location. Bitemporal hemianopia is caused by neurones that emerge from the nasal half of the retina and transmit the temporal half of the visual field.
The axons of ganglion cells in the retina form the optic nerve.
It exits the orbit through the optic foramen and projects to the thalamic lateral geniculate body. The optic chiasma forms above the sella turcica as the nasal fibres decussate along the way. The optic radiation travels from the lateral geniculate body to the occipital cortex.
Lesions at various points along this pathway cause the following visual field defects:
Scotoma implies partial retinal or optic nerve damage.
Monocular vision loss occurs when the optic nerve is completely damaged.
Pathology at the optic chiasma causes bitemporal hemianopia.
Cortical blindness with occipital cortex pathology and homonymous hemianopia with lesions compromising the optic radiation. -
This question is part of the following fields:
- Pathophysiology
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Question 23
Incorrect
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Which of the following derived SI units is correctly expressed as their base units?
Your Answer: Joule: m.kg.s-2
Correct Answer: Volt: m2.kg.s-3.A-1
Explanation:The following units are derived SI units of measurement.
Energy or work: kg.m2.s-2
The Joule (J) is the energy transferred to an object when a force of one newton acts on that object in the direction of its motion through a distance of one meter or N.m.Power: kg.m2.s-3
The Watt (W) = rate of transfer of energy or Joule per second J/s.Force: kg.m.s-2
One Newton (N) which is the international unit of measure for force = 1 kilogram meter per second squared. 1 Newton of force is the force required to accelerate an object with a mass of 1 kilogram 1 meter per second per second.Volt: kg.m2.s-3.A-1
The volt (V) is defined as the potential difference across a conductor when a current of one ampere dissipates one watt of power or W/A.Pressure: kg.m-1.s-2
A pascal (Pa) is force per unit area or N/m2. -
This question is part of the following fields:
- Basic Physics
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Question 24
Incorrect
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The SI unit of measurement is kgm2s-2 in the System international d'unités (SI). Which of the following derived units of measurement has this format?
Your Answer: Force
Correct Answer: Energy
Explanation:The derived SI unit of force is Newton.
F = m·a (where a is acceleration)
F = 1 kg·m/s2The joule (J) is a converted unit of energy, work, or heat. When a force of one newton (N) is applied over a distance of one metre (Nm), the following amount of energy is expended:
J = 1 kg·m/s2·m =
J = 1 kg·m2/s2 or 1 kg·m2·s-2The unit of velocity is metres per second (m/s or ms-1).
The watt (W), or number of joules expended per second, is the SI unit of power:
J/s = kg·m2·s-2/s
J/s = kg·m2·s-3Pressure is measured in pascal (Pa) and is defined as force (N) per unit area (m2):
Pa = kg·m·s-2/m2
Pa = kg·m-1·s-2 -
This question is part of the following fields:
- Physiology
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Question 25
Incorrect
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A 56-year-old man, presents to his general practitioner with a lump in his groin area. He is diagnosed with an indirect inguinal hernia and is scheduled for a laparoscopic inguinal hernia repair. During the repair, the surgeon sees several structures surrounding the inguinal canal. Name the structure that forms the anterior borders of the inguinal canal.
Your Answer: Inguinal ligament
Correct Answer: Aponeurosis of external oblique
Explanation:The inguinal canal is the pathway leading from the wall of the abdomen to the external genitalia.
The borders of the inguinal canal are:
Anterior wall: formed by the aponeurosis of the external oblique, supported by the internal oblique muscle laterally.
Posterior wall: formed laterally by the transversalis fascia, and medially by the conjoint tendon
Roof: formed by the internal oblique and transversus abdominis muscles
Floor: formed by the inguinal ligament and supported medially by the lacunar ligament.
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This question is part of the following fields:
- Anatomy
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Question 26
Correct
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During the design phase of a study, which among the given is aimed at addressing confounding factors?
Your Answer: Randomisation
Explanation:Randomisation allows for performance of experimental trials in a random order. Using this method gives us control over the confounding variables that are not supposed to be held constant.
For an instance, by employing randomisation we get to control biological differences among individual human beings during experimental trials.
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This question is part of the following fields:
- Statistical Methods
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Question 27
Incorrect
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A study of blood pressure measurements is being performed in patients with chronic kidney disease. Considering that the results are normally distributed, what percentage of values lie within two standard deviations of the mean blood pressure reading?
Your Answer: 97.50%
Correct Answer: 95.40%
Explanation:Normal distribution, also called Gaussian distribution, the most common distribution function for independent, randomly generated variables, and describes the spread for many biological and clinical measurements.
Properties of the Normal distribution
symmetrical i.e. Mean = mode = median
68.3% of values lie within 1 SD of the mean
95.4% of values lie within 2 SD of the mean
99.7% of values lie within 3 SD of the mean
The empirical rule, or the 68-95-99.7 rule, tells you where most of the values lie in a normal distribution: Around 68% of values are within 1 standard deviation of the mean.
Around 95% of values are within 2 standard deviations of the mean. Around 99.7% of values are within 3 standard deviations of the mean.
the standard deviation (SD) is a measure of how much dispersion exists from the mean.SD = square root (variance)
The empirical rule, or the 68-95-99.7 rule states where most of the values lie in a normal distribution. Around 68% of values fall within 1 S.D of the mean, about 95% within 2 S.D of the mean, and about 99.7% of values within 3 S.D of the mean. Therefore, 95.4% is the most reasonable answer if results are normally distributed.
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This question is part of the following fields:
- Statistical Methods
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Question 28
Correct
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After a bariatric surgery, average weight loss observed in patients is 18 kg. The standard deviation was found to be 3 kg. What is the percentage of patients that lie between 9 and 27 kg? Note: Assume that the curve is normally distributed.
Your Answer: 99.70%
Explanation:9 & 27 can be obtained by subtracting and adding 9 from the mean. 9 is three times the standard deviation and we know that 99.7% values lie within 3 standard deviations from the mean. We can find the interval for 99.7% to verify in the following way:
For 99.7% confidence interval, you can find the range as follows:
1. Multiply the standard error by 3.
2. Subtract the answer from mean value to get the lower limit.
3. Add the answer obtained in step 1 from the mean value to get the upper limit.
4. The range turns out to be 9-27 kg.
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This question is part of the following fields:
- Statistical Methods
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Question 29
Incorrect
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Which of the following is true regarding the mechanism of action of daptomycin?
Your Answer: DNA topoisomerase inhibitor
Correct Answer: Interferes with the outer membrane of gram positive bacteria resulting in cell death
Explanation:Daptomycin alters the curvature of the membrane, which creates holes that leak ions. This causes rapid depolarization, resulting in loss of membrane potential. Thus it interferes with the outer membrane of gram-positive bacteria resulting in cell death.
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This question is part of the following fields:
- Pharmacology
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Question 30
Incorrect
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During a fight, a 20-year-old male is stabbed in the thigh with a bottle. He is admitted for treatment. Which feature, if present, suggests an injury to the femoral nerve?
Your Answer: Loss of sensation over lateral aspect of thigh
Correct Answer: Loss of knee reflex
Explanation:Femoral nerve lesion (L2,L3 and L4) is characterised by weakness of the quadriceps femoris muscle. This results in weakness of extension of the knee, loss of sensation over the front of the thigh, and loss of the knee jerk reflex.
The skin over the lateral aspect of the thigh and knee, and the lower lateral quadrant of the buttock is supplied by the lateral cutaneous nerve of the thigh (L1,2).
The adductors of the hip are supplied by the obturator nerve (L2-4). This nerve also supplies sensation to the inner thigh.
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This question is part of the following fields:
- Anatomy
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