-
Question 1
Correct
-
A 10-year-old patient presents with recurrent skin cancer and is diagnosed with xeroderma pigmentosum. What is the defective biochemical mechanism in this disease?
Your Answer: DNA excision repair
Explanation:Xeroderma Pigmentosum and DNA Repair
Deoxyribonucleic acid (DNA) found in the skin cells can absorb ultraviolet (UV) light, which can cause the formation of pyrimidine dimers. These dimers are removed through a process called excision repair, where the damaged DNA is cut out and replaced with new DNA. However, if this process fails, it can lead to mutations in genes that suppress tumors or promote their growth, potentially leading to cancer.
Xeroderma pigmentosum is a genetic disorder that is inherited in an autosomal recessive pattern. This means that an individual must inherit two copies of the mutated gene, one from each parent, to develop the disorder. Generally, disorders that affect metabolism or DNA replication on a cellular or genetic level are inherited in an autosomal recessive pattern. On the other hand, genetic disorders that affect larger structural components are usually inherited in an autosomal dominant pattern. While there are exceptions to these rules, they can serve as a helpful guide for exam preparation.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 2
Correct
-
A couple in their early 30s come to your clinic seeking advice. The husband has a history of haemophilia B and they are worried about the possibility of passing it on to their children. Can you determine which of their offspring will be affected by the disease?
Your Answer: All daughters will be carriers; no sons will be affected
Explanation:The inheritance of Haemophilia A and B is crucial in identifying individuals who are at risk of developing the condition. Haemophilia A and B are genetic disorders that are inherited in an X-linked recessive manner. Haemophilia A is caused by a deficiency in clotting factor VIII, while haemophilia B is caused by a deficiency in clotting factor IX.
On the other hand, haemophilia C, which is caused by a deficiency in clotting factor XI, is primarily inherited in an autosomal recessive manner. In X-linked recessive conditions like haemophilia B, males are more likely to be affected than females. This is because males only need one abnormal copy of the gene, which is carried on the X chromosome, to be affected.
Females, on the other hand, can be carriers of the condition if they carry one normal and one abnormal copy of the gene. While carriers can have clotting abnormalities, these are usually milder than those seen in affected individuals. Men cannot pass the condition to their sons, but they will pass on the abnormal X chromosome to all their daughters, who will be carriers.
Female carriers can pass on the condition to around half their sons, and half their daughters will be carriers. Females can only be affected if they are the offspring of an affected male and a carrier female. In summary, the inheritance of haemophilia A and B is crucial in identifying individuals who are at risk of developing the condition. It also helps in providing appropriate genetic counseling and management for affected individuals and their families.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 3
Correct
-
What is the final product of glycolysis besides ATP?
Your Answer: Pyruvate
Explanation:Glycolysis: The Energy-Producing Reaction
Glycolysis is a crucial energy-producing reaction that converts glucose into pyruvate while releasing energy to create ATP and NADH+. It is one of the three major carbohydrate reactions, along with the citric acid cycle and the electron transport chain. The reaction involves ten enzymatic steps that provide entry points to glycolysis, allowing for a variety of starting points. The most common starting point is glucose or glycogen, which produces glucose-6-phosphate.
Glycolysis occurs in two phases: the preparatory (or investment) phase and the pay-off phase. In the preparatory phase, ATP is consumed to start the reaction, while in the pay-off phase, ATP is produced. Glycolysis can be either aerobic or anaerobic, but it does not require nor consume oxygen.
Although other molecules are involved in glycolysis at some stage, none of them form its end product. Lactic acid is associated with anaerobic glycolysis. glycolysis is essential for how the body produces energy from carbohydrates.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 4
Correct
-
A premature baby is born and the anaesthetists are struggling to ventilate the lungs because of insufficient surfactant. How does Laplace's law explain the force pushing inwards on the walls of the alveolus caused by surface tension between two static fluids, such as air and water in the alveolus?
Your Answer: Inversely proportional to the radius of the alveolus
Explanation:The Relationship between Alveolar Size and Surface Tension in Respiratory Physiology
In respiratory physiology, the alveolus is often represented as a perfect sphere to apply Laplace’s law. According to this law, there is an inverse relationship between the size of the alveolus and the surface tension. This means that smaller alveoli experience greater force than larger alveoli for a given surface tension, causing them to collapse first. This phenomenon is similar to what happens when two balloons of different sizes are attached together, with the smaller balloon emptying into the larger one.
In the lungs, this collapse of smaller alveoli can lead to atelectasis and collapse if surfactant is not present. Surfactant is a substance that reduces surface tension, making it easier to expand the alveoli and preventing smaller alveoli from collapsing. this relationship between alveolar size and surface tension is crucial in respiratory physiology, as it helps explain the importance of surfactant in maintaining proper lung function.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 5
Correct
-
What type of molecule does haemoglobin belong to?
Your Answer: Quaternary protein structure
Explanation:The Structure and Functions of Proteins
Proteins are complex molecules that can vary in structure from single amino acids to large, folded molecules. Amino acids are joined together by peptide bonds to form dipeptides and polypeptides. More complex molecules can also have disulphide bonds and ionic bonds. The primary structure of a protein is a simple amino acid chain, while the secondary structure is a specific shape such as a helix or pleated sheet. The tertiary structure is a more globular shape, arranged by ionic, hydrogen, and disulphide bonds, and hydrophobic interactions. The quaternary structure is a complex protein containing several polypeptide chains held together by interactions.
Proteins have multiple roles within the human body, including as hormones, food substrates, enzymes, receptor molecules, muscles, cell membrane constituents, carrier molecules in blood, and determinants of oncotic/osmotic pressures. However, proteins can be easily damaged by denaturation, which is the loss of the specific three-dimensional shape of a molecule. Denaturation can be caused by heat, salts, heavy metals, solvents, detergents, and extremes of pH.
In summary, proteins are essential molecules with a diverse range of structures and functions within the human body. their structure and potential for denaturation is crucial for maintaining their proper function.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 6
Correct
-
A 29-year-old woman visits your clinic with concerns about a possible pregnancy.
Can you explain the mechanism behind a urinary pregnancy test?Your Answer: ELISA
Explanation:Techniques in Biochemistry
Over-the-counter urine pregnancy tests use ELISA to detect beta-HCG in a woman’s urine. The test stick contains antibodies that react with beta-HCG, producing a color change that confirms pregnancy. The urinary pregnancy test is a solid-phase ELISA, where the antibody is immobilized on a specialized filter paper. The fluid travels laterally across the paper to bind with the antibody, and if beta-HCG is present, the line turns blue. Electrophoresis characterizes the electrical charge and size of substances, while PCR identifies specific sequences of DNA or RNA. Radioimmunoassay uses radioactivity to identify specific proteins. Enzymatic degradation breaks down large proteins into smaller subunits for which target antibodies may already exist. This method is used to characterize large proteins for which the structure has not yet been described.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 7
Correct
-
What RNA base pairs with adenine when synthesizing a complementary RNA strand from DNA, using RNA polymerase to split the helix at specific points?
Your Answer: Uracil
Explanation:Differences between DNA and RNA
DNA and RNA differ in several ways. The primary sugar in DNA is deoxyribose, while in RNA it is ribose. Additionally, DNA is double stranded, while RNA is single stranded. This single stranded structure with un-paired bases allows for transcription to occur when the DNA bases are freed. Each base has a specific pairing, with guanine always binding to cytosine and adenine always binding to thymine in the DNA strand. During transcription, the same complementary RNA bases assemble with the DNA bases, except for thymine, which is not an RNA base. Instead, uracil serves as the RNA pyrimidine base equivalent of thymine. Finally, lysine is an amino acid coded for by the RNA base triplet AAA, where A represents adenine.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 8
Incorrect
-
As part of your general practice placement, you have been tasked with conducting an audit on the duration of solid food introduction in the practice population. You review the data for the last six infants born within the practice:
6 months, 7 months, 8 months, 9 months, 10 months, 11 months.
What is the variance value for the duration of solid food introduction in the practice population?Your Answer: 8.6
Correct Answer: 74.9
Explanation:Variance and Standard Deviation in Breast Feeding Duration
Variance is a statistical measure that indicates how spread out a set of data is. In the case of breast feeding duration, variance can help us understand how much the duration varies from the mean. The formula for variance involves squaring the difference between each data point and the mean, then dividing the sum by n-1, where n is the total number of data points. In a sample population, n-1 is a better estimate of variance than n because it accounts for the variability within the sample.
For example, if the variance of breast feeding duration is 74.9 months, this indicates that the duration is widely distributed from the mean of 17.6 months. A smaller variance, such as 4.5 months, would indicate that the duration varies less and is closer to the mean. The standard deviation, which is the square root of the variance, is also important in the spread of data. In a normal distribution, 95% of observations will fall within two standard deviations of the mean.
In the case of breast feeding duration, the mean is 17.6 months, indicating that babies are breast fed for an average of 15 and a half months. The median, which is the middle number in the data set, is 15 months, meaning that half of the babies were breast fed for 15 months. variance and standard deviation can help us better understand the distribution of breast feeding duration and other medical measurements.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 9
Incorrect
-
A 65-year-old patient with suspected spinal cord compression has been admitted to the neurosurgical team for an urgent MRI of the spine. Which particle's magnetic properties does magnetic resonance imaging rely predominantly upon?
Your Answer: Injected radioactive isotopes, for example, technetium-99
Correct Answer: Hydrogen ion (proton)
Explanation:How MRI Scanners Use Hydrogen Ions to Create Images
MRI scanners use the magnetic properties of hydrogen ions, also known as protons, to create images of the human body. These protons have nuclear spin, which means they have magnetic vectors that can be aligned in an electromagnet. The scanner bombards the protons with radiofrequency radiation, causing them to release energy when they return to their resting state. This energy release is recorded and used to construct the MRI image.
While other nuclei, such as carbon 13, also have nuclear spin and could be used in MRI imaging, hydrogen ions are much more abundant in human tissues. This makes them the preferred choice for creating images of the body. The process of aligning the magnetic vectors of the protons and then recording their energy release is repeated many times to create a detailed image of the body’s internal structures.
Overall, MRI scanners use the magnetic properties of hydrogen ions to create detailed images of the human body. This non-invasive imaging technique has revolutionized medical diagnosis and treatment, allowing doctors to see inside the body without the need for surgery.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 10
Correct
-
What occurs during metaphase II of meiosis?
Your Answer: The cell's chromosomes attach to the meiotic spindle to divide into chromatids
Explanation:The Process of Meiosis
Meiosis is a complex process that involves two major cycles. The first cycle, meiosis I, condenses the reproductive cell’s DNA into chromosomes that are then replicated, creating two pairs of each original chromosome. These pairs are then separated, and the cell divides with one chromosome in each daughter cell. The second cycle, meiosis II, splits the chromosomes into individual chromatids, which are then separated as in meiosis I. This separation is facilitated by a spindle, a set of parallel fibers that attach to the center of each chromosome and split into two, making the chromatids travel on the polar opposite sides of the cell. The cell then divides again, giving rise to four haploid daughter cells.
During meiosis II, the chromosomes align on the spindle in metaphase II. Tetrads separate during anaphase I and line up during metaphase I. Sister chromatids separate on the meiotic spindle during anaphase II. Finally, chromosomes uncoil and lengthen at the end of meiosis, in telophase II. This process is essential for the production of gametes and the continuation of sexual reproduction in many organisms.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 11
Correct
-
A premature baby is born and the anaesthetists are struggling to ventilate the lungs because of insufficient surfactant. How does Laplace's law explain the force pushing inwards on the walls of the alveolus caused by surface tension between two static fluids, such as air and water in the alveolus?
Your Answer: Inversely proportional to the radius of the alveolus
Explanation:The Relationship between Alveolar Size and Surface Tension in Respiratory Physiology
In respiratory physiology, the alveolus is often represented as a perfect sphere to apply Laplace’s law. According to this law, there is an inverse relationship between the size of the alveolus and the surface tension. This means that smaller alveoli experience greater force than larger alveoli for a given surface tension, and they will collapse first. This phenomenon explains why, when two balloons are attached together by their ends, the smaller balloon will empty into the bigger balloon.
In the lungs, this same principle applies to lung units, causing atelectasis and collapse when surfactant is not present. Surfactant is a substance that reduces surface tension, making it easier to expand the alveoli and preventing smaller alveoli from collapsing. Therefore, surfactant plays a crucial role in maintaining the proper functioning of the lungs and preventing respiratory distress. the relationship between alveolar size and surface tension is essential in respiratory physiology and can help in the development of treatments for lung diseases.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 12
Incorrect
-
In which part of the cell are the electron transport chain carriers situated?
Your Answer: Mitochondria matrix
Correct Answer: Mitochondrial cristae
Explanation:The Electron Transport Chain in Mitochondria
The electron transport chain (ETC) is a crucial process in cellular aerobic respiration that occurs in the mitochondrial cristae. These are folded membranes inside the organelle. During respiration, NADH and FADH produced from other parts of the process, such as glycolysis, transfer electrons from electron donors to electron acceptors through redox reactions. This electron transfer is coupled with proton transfer across the mitochondrial membrane, creating an electrochemical proton gradient. This gradient induces the production of ATP, which is used as an energy currency by the cell.
ATP is produced through a mechanism called chemiosmotic phosphorylation. The structure of the mitochondrion is essential for this process to occur. The cristae provide a large surface area for the ETC to take place, and the mitochondrial membrane is impermeable to protons, allowing for the creation of the proton gradient. The inner membrane also contains ATP synthase, the enzyme responsible for producing ATP through chemiosmotic phosphorylation.
In summary, the electron transport chain in mitochondria is a complex process that involves the transfer of electrons and protons across the mitochondrial membrane to create a proton gradient. This gradient is then used to produce ATP through chemiosmotic phosphorylation. The structure of the mitochondrion is crucial for this process to occur efficiently.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 13
Incorrect
-
What could be a potential cause of metabolic acidosis?
Your Answer: Chronic obstructive pulmonary disease (COPD)
Correct Answer: Poorly controlled diabetes
Explanation:Acid-Base Imbalances in Different Medical Conditions
Poorly controlled diabetes can cause the breakdown of fatty acids, leading to the production of ketones as an alternative energy source. However, an excess of ketones can result in metabolic acidosis due to their acidic nature. On the other hand, chronic obstructive pulmonary disease (COPD) and suffocation can cause the retention of carbon dioxide, leading to respiratory acidosis. In COPD, there may be a compensatory metabolic alkalosis. Voluntary hyperventilation can cause respiratory alkalosis due to the reduction of carbon dioxide. Vomiting can also lead to metabolic alkalosis. Diabetic ketoacidosis is a complication of type 1 diabetes that results in high blood sugar levels, ketone production, and acidosis.
In summary, different medical conditions can cause acid-base imbalances in the body. It is important to identify the underlying cause of the imbalance to provide appropriate treatment.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 14
Incorrect
-
What role does vitamin K play in the body?
Your Answer: Maintaining healthy liver function
Correct Answer: Activation of clotting factors II, VII, IX, X
Explanation:The Roles of Vitamin K in the Body
Vitamin K plays several important roles in the body. One of its main functions is to modify clotting factors II, VII, IX, and X through a process called carboxylation. This modification allows calcium to bind to the factors, which is necessary for them to participate in the clotting pathway. This principle is used in full blood counts to prevent clotting by adding EDTA, which chelates the calcium. Vitamin K also modifies osteocalcin and matrix proteins in bone, as well as nephrocalcin in the kidney, in a similar way.
In addition to its role in blood clotting and bone health, vitamin K is also important for nervous tissue development and growth. However, vitamin K antagonists such as warfarin are sometimes used as anticoagulants to prevent blood clots. It is important to follow guidelines and instructions carefully when using these medications. Overall, vitamin K plays a crucial role in maintaining the health and function of various systems in the body.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 15
Incorrect
-
What are the typical clinical manifestations of a deficiency in vitamin B6 (pyridoxine)?
Your Answer: Renal impairment
Correct Answer: Sensory neuropathy
Explanation:The Importance of Pyridoxine in the Body
Pyridoxine is a group of B-vitamins that are crucial in various bodily functions. They act as essential cofactors in many reactions, particularly in the metabolism of amino acids and neurotransmitters. Pyridoxine also plays a role in regulating gene transcription and controlling steroid hormones.
The body can produce pyridoxine through bacterial flora in the gut, and it is also present in many dietary sources. However, overheating certain foods can destroy pyridoxine, and some medications can alter its metabolism. Pyridoxine is also used therapeutically to prevent neuropathy in the treatment of tuberculosis.
Deficiency in pyridoxine can lead to sensory neuropathy, skin changes, and damage to mucous membranes. On the other hand, deficiency in vitamin C can cause gingivitis and increased bleeding, while vitamin K deficiency can also lead to bleeding. Sleep disturbance is rarely attributed to vitamin B3 (niacin) deficiency.
In summary, pyridoxine is a vital nutrient that plays a crucial role in various bodily functions. Its deficiency can lead to various health problems, highlighting the importance of maintaining adequate levels of this vitamin in the body.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 16
Incorrect
-
What are the clinical consequences of a lack of vitamin A?
Your Answer: Bleeding gums
Correct Answer: Dry conjunctiva
Explanation:The Devastating Effects of Vitamin A Deficiency
Vitamin A deficiency is a serious health concern that can lead to a range of devastating effects. One of the most common consequences is blindness, particularly in children. Poor night vision is often an early sign of this deficiency, which can progress to complete blindness if left untreated.
In addition to blindness, vitamin A deficiency can also cause dry conjunctiva, a condition known as conjunctival xerosis. This occurs when the normally moist and fine conjunctiva becomes thickened and dysfunctional, leading to the formation of white plaques known as Bitot’s spots. Corneal ulceration can also occur as a result of this condition.
The respiratory and gastrointestinal epithelia can also be affected by vitamin A deficiency, leading to reduced resistance to infection. This deficiency is a major public health issue in some parts of the world and is the single most common preventable cause of blindness. It is crucial to address this issue through education and access to vitamin A-rich foods and supplements.
Overall, the devastating effects of vitamin A deficiency highlight the importance of proper nutrition and access to essential vitamins and minerals. By addressing this issue, we can help prevent blindness and improve overall health outcomes for individuals and communities around the world.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 17
Correct
-
What controls the specific stages of the cell cycle?
Your Answer: Cyclins and cyclin-dependent kinases
Explanation:Regulation of the Cell Cycle by Cyclins and Cyclin-Dependent Kinases
The cell cycle is controlled by the activity of proteins known as cyclins and phosphorylating enzymes called cyclin-dependent kinases (CDKs). Cyclins and CDKs combine to form an activated heterodimer, where cyclins act as the regulatory subunits and CDKs act as the catalytic subunits. Neither of these molecules is active on their own. When a cyclin binds to a CDK, the CDK phosphorylates other target proteins, either activating or deactivating them. This coordination leads to the entry into the next phase of the cell cycle. The specific proteins that are activated depend on the different combinations of cyclin-CDK. Additionally, CDKs are always present in cells, while cyclins are produced at specific points in the cell cycle in response to other signaling pathways.
In summary, the cell cycle is regulated by the interaction between cyclins and CDKs. This interaction leads to the phosphorylation of target proteins, which ultimately controls the progression of the cell cycle.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 18
Correct
-
What is the apoptotic event that occurs just before the formation of an apoptosome?
Your Answer: Release of cytochrome c from mitochondria
Explanation:Apoptosis and the Role of the Apoptosome
Apoptosis, also known as programmed cell death, is a natural process that occurs in all multicellular organisms. It involves a series of changes in cell morphology, including membrane blebbing, cell shrinkage, nuclear fragmentation, chromatin condensation, and chromosomal DNA fragmentation. The formation of the apoptosome is a crucial part of the apoptosis cascade. It is a large protein structure that is triggered by the release of cytochrome c from the mitochondria in response to various stimuli, such as DNA damage, infections, or developmental signals.
The apoptosome is formed when cytochrome c binds to Apaf-1, a cytosolic protein, in a 1:1 ratio. This triggers the recruitment and activation of the initiator pro-caspase-9, which then activates effector caspases, a family of apoptotic proteases, to initiate the apoptotic cascade. It is important to note that the activation of caspase-9 occurs only after the formation of the apoptosome.
In summary, apoptosis is a natural process that occurs in multicellular organisms, and the apoptosome plays a crucial role in triggering the apoptotic cascade. the mechanisms behind apoptosis and the formation of the apoptosome can provide insights into various diseases and developmental processes.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 19
Incorrect
-
What is the primary means of transportation for vitamin D in the human body?
Your Answer: In blood, bound to albumin
Correct Answer: In blood, bound to the group specific component
Explanation:The Role of UV Light and Vitamin D in Calcium and Phosphate Regulation
In order for the body to produce Vitamin D3, UV light at a specific wavelength is required to convert cholesterol in the skin. Vitamin D2 and D3 are then transported in the bloodstream bound to the Vitamin-D Binding Protein and undergo further modifications in the liver and kidney to become the active form, 1,25 (OH)2Vitamin D. This active form plays a crucial role in regulating calcium and phosphate concentrations in the body.
1,25 (OH)2Vitamin D increases calcium absorption in the duodenum and inhibits the secretion and synthesis of PTH, which helps to maintain calcium concentrations. It also increases phosphate absorption in the jejunum and ileum, which is important for maintaining phosphate concentrations. Additionally, 1,25 (OH)2Vitamin D promotes bone turnover by stimulating both osteoblast and osteoclast activity.
Overall, the production and activation of Vitamin D through UV light and dietary sources is essential for proper calcium and phosphate regulation in the body.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 20
Correct
-
What occurs in eukaryotic prophase?
Your Answer: Chromatin condenses into chromosomes
Explanation:The Stages of Prophase in Eukaryotic Mitosis
Prophase is the first stage of eukaryotic mitosis, except for plant cells which have a preprophase stage. During prophase, the cell’s chromatin, which is made up of DNA and associated proteins, condenses into double rod-shaped structures called chromosomes. This process is facilitated by the condensin protein I and/or II complexes. As the chromosomes form, the nuclear membrane and nucleoli disintegrate and disappear, making the chromatin visible.
Before prophase, the cell’s DNA is replicated during interphase, resulting in identical pairs of chromosomes called chromatids. These chromatids attach to each other at a DNA element called the centromere. DNA and centrosome duplication occur during interphase, while chromosome alignment takes place during metaphase. The nuclear membrane and nucleoli re-form during telophase, and the sister chromatids separate during anaphase.
In summary, prophase is the initial stage of eukaryotic mitosis where chromatin condenses into chromosomes, and the nuclear membrane and nucleoli disappear. Chromosome alignment, DNA and centrosome duplication, and re-formation of the nuclear membrane and nucleoli occur in subsequent stages.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 21
Incorrect
-
A 32-year-old snowboarder presents to the Emergency department complaining of pain and swelling around the first metacarpophalangeal joint (MCP joint) following a fall during practice.
Upon examination, there is significant swelling and bruising on the ulnar side of the joint.
What is the most probable injury that the patient has sustained?Your Answer: Scaphoid bone
Correct Answer: Ulnar collateral ligament
Explanation:Skier’s Thumb: A Common Injury in Winter Sports
Skier’s thumb, also known as gamekeeper’s thumb, is a common injury that occurs in winter sports. It is caused by damage or rupture of the ulnar collateral ligament, which is located at the base of the thumb. This injury can result in acute swelling and gross instability of the thumb. In severe cases where a complete tear of the ligament is suspected, an MRI may be necessary to confirm the diagnosis, and surgical repair may be required.
Once the acute swelling has subsided, treatment for skier’s thumb typically involves immobilization in a thumb spica. This is the standard therapy for cases of partial rupture.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 22
Correct
-
What is the term for the process described below in laboratory testing?
Enzymes are immobilised on a solid surface, such as a bead or well, and allowed to come into contact with the sample. After washing, another enzyme is added with a label allowing quantitation of the analyte.Your Answer: Enzyme-linked immunosorbent assay
Explanation:ELISA: A Common Immunoassay in Medical Diagnostic Testing
An enzyme-linked immunosorbent assay (ELISA) is a type of immunoassay that is widely used in medical diagnostic testing. This method uses antibodies to identify and/or quantify the analyte being tested. The ELISA process involves several steps, including coating a plate with the antigen, adding the patient’s sample, washing the plate to remove any unbound material, adding an enzyme-linked antibody, washing the plate again, and adding a substrate to produce a measurable signal.
Over time, many modifications have been made to the ELISA, making it a versatile tool in the laboratory for measuring various analytes. Some of the substances that can be measured using immunoassays include thyroid hormone, testosterone, oestrogen, troponin, and vitamin D. The ELISA has been around for a long time and is still widely used today due to its accuracy, sensitivity, and specificity.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 23
Incorrect
-
What role does the nucleolus play in eukaryotic cells?
Your Answer: To produce RNA polymerases for ribosomal RNA transcription
Correct Answer: To transcribe ribosomal RNA and assemble ribosomes
Explanation:The Nucleolus: Structure and Function
The nucleolus is a non-membrane-bound structure that takes up about a quarter of the nuclear volume. It is composed mainly of proteins and nucleic acids and is responsible for transcribing ribosomal RNA (rRNA) and assembling ribosomes in the cell. Nucleoli are formed in nucleolar organizing regions (NORs), which are also the regions of the genes for three of the four eukaryotic rRNAs.
During ribosome assembly, ribosomal proteins enter the nucleolus from the cytoplasm and begin to assemble on an rRNA precursor. As the pre-rRNA is cleaved to produce 5.8S, 18S, and 28S rRNAs, additional ribosomal proteins and the 5S rRNA (which is synthesized elsewhere in the nucleus) assemble to form preribosomal subunits. These subunits then exit the nucleolus into the cytoplasm and combine to produce the final 40S and 60S ribosomal subunits.
Overall, the nucleolus plays a crucial role in protein synthesis by producing the components necessary for ribosome assembly. Its unique structure and function make it an essential component of the cell’s machinery.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 24
Incorrect
-
Of which cellular structure is the fibrillar centre a component?
Your Answer: The endoplasmic reticulum
Correct Answer: The nucleolus
Explanation:The Fibrillar Centre in the Nucleolus
The fibrillar centre is a crucial component of the nucleolus, which is found in most metazoan nucleoli, particularly in higher eukaryotes. Along with the dense fibrillar components and the granular component, it forms the three major components of the nucleolus. During the end of mitosis, the fibrillar centre serves as a storage point for nucleolar ribosomal chromatin and associated ribonucleoprotein transcripts. As the nucleolus becomes active, the ribosomal chromatin and ribonucleoprotein transcripts begin to form the dense fibrillar components, which are more peripherally located and surround the fibrillar centres. The transcription zone for multiple copies of the pre-rRNA genes is the border between these two structures. It is important to note that the fibrillar centre is not a component of any of the cell structures mentioned in the incorrect answer options.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 25
Incorrect
-
What is the statement of Henry's law?
Your Answer: The rate of diffusion of a gas is in inverse proportion to its weight
Correct Answer: The concentration of a gas when dissolved in liquid is proportional to its partial pressure
Explanation:Gas Laws
Gas laws are a set of scientific principles that describe the behavior of gases under different conditions. One of these laws is Avogadro’s law, which states that equal volumes of gases at a standardized temperature and pressure contain the same number of molecules. Another law is Boyle’s law, which explains that gases expand when the temperature is increased. Charles’ law, on the other hand, states that the pressure of a gas is inversely proportional to its volume at a standardized temperature. Lastly, Graham’s law explains that the rate of diffusion of a gas is in inverse proportion to its weight. The specific gas laws that you need to know may vary depending on your syllabus, but you should be able to recognize and apply them if given the formulae. It is unlikely that you will be expected to know the correct formula.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 26
Incorrect
-
What is the primary function of riboflavin in the B vitamin group?
Your Answer: Visual acuity
Correct Answer: Mopping up free radicals
Explanation:The Role of Riboflavin in the Body
Riboflavin, also known as vitamin B2, is a B-vitamin that plays a crucial role in the body. One of its functions is to act as an antioxidant, mopping up free radicals that can cause damage to cells. However, if the metabolites formed during this process are not excreted promptly, the free radicals can be generated again. Riboflavin is also involved in the production of blue-light sensitive pigments in the eye, which help establish the circadian rhythm. This function is not related to visual acuity.
Riboflavin is found in a variety of foods, including milk and offal. Deficiency of this vitamin is rare, but when it does occur, it can cause non-specific effects on the skin and mucous membranes. There is no evidence of clear long-lasting damage from riboflavin deficiency. Overall, riboflavin is an important nutrient that plays a vital role in maintaining good health.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 27
Incorrect
-
A couple in their late 30s come to the clinic seeking information about the risk of their three children inheriting Huntington's disease. The husband has recently been diagnosed with the disease, while the wife is not affected. What is the likelihood, expressed as a percentage, that their children will inherit the disease?
Your Answer: 25%
Correct Answer: 50%
Explanation:Huntington’s Disease
Huntington’s disease is a genetic disorder that typically appears later in life and is characterized by symptoms such as chorea, cognitive decline, and personality changes. It is an autosomal dominant disease, meaning that there is a 50% chance of passing it on to offspring. If the gene is inherited from an unaffected parent, the child will not be affected. This is different from autosomal recessive inheritance, where both parents must pass on the gene for it to affect their children.
The disease is caused by an increase in the length of a repeating trinucleotide sequence (CAG) in the Huntington protein. This sequence can change in length through generations, and longer sequences are associated with earlier onset of symptoms (genetic anticipation). Since Huntington’s disease usually presents itself after people have already started their families, there are many issues associated with genetic testing.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 28
Incorrect
-
What is the most common method of assessing nutritional status in adults?
Your Answer: Albumin on blood testing
Correct Answer: Body mass index
Explanation:The Body Mass Index as a Measure of Nutritional Status
The measurement and assessment of nutritional status can be challenging, and there is no single test that can provide a complete picture. However, the body mass index (BMI) is a commonly used measurement in clinical practice. The BMI is calculated by dividing a person’s weight in kilograms by their height in meters squared. This measure is used to assess adiposity and nutritional status, and it is simple and quick to calculate and interpret.
Although the BMI is a convenient measure, it has limitations for assessing obesity in individual patients. It is best used to track trends in an individual patient’s BMI over time. In some cases, the BMI may overestimate fat mass in patients who are very tall or have a high proportion of lean tissue due to an active lifestyle. Additionally, the BMI may not be accurate for athletes and children.
Other measurements, such as skin fold thickness and weight, can also be useful, but the BMI is generally considered the better option. The ponderal index is used specifically for children. It is important to note that albumin is not a reliable marker of nutritional status, as it can also be affected by inflammation.
Overall, the BMI is a widely used measure of nutritional status and is recommended by the World Health Organization. However, it is important to consider its limitations and use it in conjunction with other measurements to obtain a more complete picture of a patient’s nutritional status.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 29
Correct
-
Which food is a rich source of vitamin D in the diet?
Your Answer: Oily fish
Explanation:Sources of Vitamin D
Vitamin D is a type of fat-soluble vitamin that can be found in certain foods such as cheese, butter, eggs, and oily fish. However, vegetable sources of vitamin D are limited, although some foods are fortified with this vitamin. For instance, 100 grams of sundried shiitake mushrooms contain 1600 IU of vitamin D, while one egg contains 20 IU. Wild salmon is also a good source of vitamin D, with 100 grams containing 800 IU, while farmed salmon contains 200 IU.
Aside from food sources, sunlight is also a good source of vitamin D. Exposure of arms and legs to sunlight for 10-15 minutes can provide 3000 IU of vitamin D. However, it is difficult to obtain the daily requirement of 25-50 IU of vitamin D through sunlight alone, especially for people living in temperate climates. As a result, many people may have insufficient vitamin D levels. It is important to ensure that we get enough vitamin D through a combination of food sources and sunlight exposure.
-
This question is part of the following fields:
- Basic Sciences
-
-
Question 30
Incorrect
-
What is the composition of enzymes found in lysosomes?
Your Answer: Peroxidases
Correct Answer: Acid hydrolases
Explanation:Lysosomes: The Digestive System of the Cell
Lysosomes are organelles that come from the Golgi apparatus and are enclosed by a membrane. They are responsible for breaking down various biological macromolecules such as proteins, nucleic acids, carbohydrates, and lipids. Lysosomes contain acid hydrolases, which are enzymes that cleave chemical bonds by adding water and function at an acidic pH of around 5. They are involved in digesting foreign agents that are internalized by the cell and breaking down other cellular organelles like mitochondria, allowing for their components to be recycled.
The acidic pH within lysosomes is maintained by a proton pump in the lysosomal membrane, which imports protons from the cytosol coupled to ATP hydrolysis. This acidic environment is necessary for the activity of the acid hydrolases. D-amino acid oxidases and peroxidases are not found in lysosomes but in peroxisomes. Alcohol dehydrogenases and ATPases are not involved in digestion but in other cellular functions. Alcohol dehydrogenases catalyze the interconversion between alcohols and aldehydes or ketones with the reduction of NAD+ to NADH, while ATPases catalyze the breakdown of ATP into ADP and a phosphate ion, releasing energy for the cell’s functions.
-
This question is part of the following fields:
- Basic Sciences
-
00
Correct
00
Incorrect
00
:
00
:
00
Session Time
00
:
00
Average Question Time (
Secs)