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Question 1
Correct
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A 65-year-old male with a history of chronic obstructive pulmonary disease (COPD) has been admitted and treated for infective exacerbations of COPD three times in the past year. Despite his respiratory issues, he continues to smoke. He is currently receiving only short-acting beta2-agonist therapy. During his COPD patient review with the nurse practitioner at his local general practice, spirometry results reveal a drop in his FEV1 from 65% to 58%.
What is the most effective approach to manage his condition and prevent further decline in his FEV1?Your Answer: Smoking cessation
Explanation:The most effective intervention to slow the decrease in FEV1 experienced by patients with COPD is to stop smoking. If the patient has no asthmatic/steroid-responsive features, the next step in management would be to add a long-acting beta2-agonist (LABA) and a long-acting muscarinic antagonist. If the patient has asthmatic/steroid-responsive features, the next step would be to add a LABA and an inhaled corticosteroid. Oral theophylline is only considered if inhaled therapy is not possible, and oral prednisolone is only used during acute infective exacerbations of COPD to help with inflammation and is not a long-term solution to slow the reduction of FEV1.
The National Institute for Health and Care Excellence (NICE) updated its guidelines on the management of chronic obstructive pulmonary disease (COPD) in 2018. The guidelines recommend general management strategies such as smoking cessation advice, annual influenzae vaccination, and one-off pneumococcal vaccination. Pulmonary rehabilitation is also recommended for patients who view themselves as functionally disabled by COPD.
Bronchodilator therapy is the first-line treatment for patients who remain breathless or have exacerbations despite using short-acting bronchodilators. The next step is determined by whether the patient has asthmatic features or features suggesting steroid responsiveness. NICE suggests several criteria to determine this, including a previous diagnosis of asthma or atopy, a higher blood eosinophil count, substantial variation in FEV1 over time, and substantial diurnal variation in peak expiratory flow.
If the patient does not have asthmatic features or features suggesting steroid responsiveness, a long-acting beta2-agonist (LABA) and long-acting muscarinic antagonist (LAMA) should be added. If the patient is already taking a short-acting muscarinic antagonist (SAMA), it should be discontinued and switched to a short-acting beta2-agonist (SABA). If the patient has asthmatic features or features suggesting steroid responsiveness, a LABA and inhaled corticosteroid (ICS) should be added. If the patient remains breathless or has exacerbations, triple therapy (LAMA + LABA + ICS) should be offered.
NICE only recommends theophylline after trials of short and long-acting bronchodilators or to people who cannot use inhaled therapy. Azithromycin prophylaxis is recommended in select patients who have optimised standard treatments and continue to have exacerbations. Mucolytics should be considered in patients with a chronic productive cough and continued if symptoms improve.
Cor pulmonale features include peripheral oedema, raised jugular venous pressure, systolic parasternal heave, and loud P2. Loop diuretics should be used for oedema, and long-term oxygen therapy should be considered. Smoking cessation, long-term oxygen therapy in eligible patients, and lung volume reduction surgery in selected patients may improve survival in patients with stable COPD. NICE does not recommend the use of ACE-inhibitors, calcium channel blockers, or alpha blockers
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This question is part of the following fields:
- Respiratory System
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Question 2
Incorrect
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A 55-year-old Caucasian man presents to the ENT clinic with complaints of gradual hearing loss over the past year. He reports having to turn up the volume on his television to the maximum to hear it comfortably. There are no associated symptoms such as tinnitus or dizziness, and the patient has no significant medical history.
Upon examination, a Weber and Rinne test reveal conductive hearing loss in the left ear. Otoscope examination shows no signs of middle ear effusion or tympanic membrane involvement in either ear. A pure tone audiometry confirms conductive hearing loss in the left ear, with a Carhart's notch present.
The physician diagnoses the patient with otosclerosis and discusses treatment options.
What is the underlying pathology of otosclerosis?Your Answer: Accumulation of desquamated, stratified squamous epithelium within the middle ear, causing erosion of the ossicles
Correct Answer: Replacement of normal bone by vascular spongy bone
Explanation:Otosclerosis is a condition where normal bone is replaced by spongy bone with a high vascularity. This leads to progressive conductive hearing loss, without any other neurological impairments. The replacement of the normal endochondral layer of the bony labyrinth by spongy bone affects the ability of the stapes to act as a piston, resulting in the conduction of sound from the middle ear to the inner ear being affected. Caucasians are most commonly affected by this condition.
Benign paroxysmal positional vertigo (BPPV) is caused by the dislodgement of otoliths into the semicircular canals. This condition results in vertiginous dizziness upon positional changes, but does not affect auditory function.
Meniere’s disease is caused by endolymphatic hydrops, which is the accumulation of fluid in the inner ear. The pathophysiology of this condition is not well understood, but it leads to vertigo, tinnitus, hearing loss, and aural fullness.
Cholesteatoma is caused by the accumulation of desquamated, stratified squamous epithelium. This leads to the formation of a mass that can gradually enlarge and erode the ossicle chain, resulting in conductive hearing loss.
Presbycusis is a type of sensorineural hearing loss that occurs as a result of aging. The degeneration of the organ of Corti is one of the underlying pathological mechanisms that causes this condition. This leads to the destruction of outer hair cells and a decrease in hearing sensitivity.
Understanding Otosclerosis: A Progressive Conductive Deafness
Otosclerosis is a medical condition that occurs when normal bone is replaced by vascular spongy bone. This condition leads to a progressive conductive deafness due to the fixation of the stapes at the oval window. It is an autosomal dominant condition that typically affects young adults, with onset usually occurring between the ages of 20-40 years.
The main features of otosclerosis include conductive deafness, tinnitus, a normal tympanic membrane, and a positive family history. In some cases, patients may also experience a flamingo tinge, which is caused by hyperemia and affects around 10% of patients.
Management of otosclerosis typically involves the use of a hearing aid or stapedectomy. A hearing aid can help to improve hearing, while a stapedectomy involves the surgical removal of the stapes bone and replacement with a prosthesis.
Overall, understanding otosclerosis is important for individuals who may be at risk of developing this condition. Early diagnosis and management can help to improve hearing and prevent further complications.
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This question is part of the following fields:
- Respiratory System
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Question 3
Incorrect
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A 14-year-old girl presents to her GP with complaints of earache and hearing difficulty in her left ear. Upon examination, her GP observes a bulging tympanic membrane and diagnoses her with acute otitis media. The GP prescribes a course of oral antibiotics.
However, after a few days, the girl's fever persists and her pain worsens, prompting her to visit the emergency department. Upon examination, the girl has a tender and erythematous retro-auricular swelling with a temperature of 38.9ºC. She has no ear discharge, and the rest of her examination is unremarkable.
What complication has developed in this case?Your Answer: Meningitis
Correct Answer: Mastoiditis
Explanation:Mastoiditis is a potential complication of acute otitis media, which can cause pain and swelling behind the ear over the mastoid bone. However, there is no evidence of tympanic membrane perforation, neurological symptoms or signs of meningitis or brain abscess, or facial nerve injury in this case.
Acute otitis media is a common condition in young children, often caused by bacterial infections following viral upper respiratory tract infections. Symptoms include ear pain, fever, and hearing loss, and diagnosis is based on criteria such as the presence of a middle ear effusion and inflammation of the tympanic membrane. Antibiotics may be prescribed in certain cases, and complications can include perforation of the tympanic membrane, hearing loss, and more serious conditions such as meningitis and brain abscess.
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This question is part of the following fields:
- Respiratory System
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Question 4
Incorrect
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A 19-year-old male is admitted with acute asthma. He has been treated with steroid, bronchodilators and 15 l/min of oxygen.
His pulse rate is 125/min, oxygen saturation 89%, respiratory rate 24/min, blood pressure 140/88 mmHg and he has a peak flow rate of 150 l/min. On auscultation of his chest, he has bilateral wheezes.
Arterial blood gas (ABG) result taken on 15 l/min oxygen shows:
pH 7.42 (7.36-7.44)
PaO2 8.4 kPa (11.3-12.6)
PaCO2 5.3 kPa (4.7-6.0)
Standard HCO3 19 mmol/L (20-28)
Base excess −4 (+/-2)
Oxygen saturation 89%
What is the most appropriate action for this man?Your Answer: Start enoxaparin 1.5 mg/kg
Correct Answer: Call ITU to consider intubation
Explanation:Urgent Need for Ventilation in Life-Threatening Asthma
This patient is experiencing life-threatening asthma with a dangerously low oxygen saturation level of less than 92%. Despite having a normal PaCO2 level, the degree of hypoxia is inappropriate and requires immediate consideration for ventilation. The arterial blood gas (ABG) result is consistent with the clinical presentation, making a venous blood sample unnecessary. Additionally, the ABG and bedside oxygen saturation readings are identical, indicating an arterialised sample.
It is crucial to note that in cases of acute asthma, reducing the amount of oxygen below the maximum available is not recommended. Hypoxia can be fatal and must be addressed promptly. Therefore, urgent intervention is necessary to ensure the patient’s safety and well-being.
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This question is part of the following fields:
- Respiratory System
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Question 5
Incorrect
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A 72-year-old man with thyroid cancer is hospitalized for dyspnea. What is the most appropriate test to evaluate potential compression of the upper respiratory tract?
Your Answer: Peak expiratory flow rate
Correct Answer: Flow volume loop
Explanation:Understanding Flow Volume Loops
A flow volume loop is a graphical representation of the amount of air that a person can inhale and exhale over time. It is often described as a triangle on top of a semi-circle. This loop is useful in assessing the compression of the upper airway, which can be caused by various conditions such as asthma, chronic obstructive pulmonary disease (COPD), and sleep apnea.
To interpret a flow volume loop, the vertical axis represents the flow rate, while the horizontal axis represents the volume of air. The loop starts at the bottom left corner, where the person begins to inhale. As the person inhales, the flow rate increases, creating the upward slope of the triangle. At the top of the triangle, the person reaches their maximum inhalation volume.
The person then begins to exhale, creating the downward slope of the triangle. The flow rate decreases as the person exhales, until they reach their maximum exhalation volume, represented by the semi-circle. The loop then returns to the starting point, completing one full cycle.
Overall, flow volume loops are a valuable tool in diagnosing and monitoring respiratory conditions. By analyzing the shape and size of the loop, healthcare professionals can identify abnormalities in lung function and determine the appropriate treatment plan.
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This question is part of the following fields:
- Respiratory System
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Question 6
Incorrect
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Sophie, a 4-year-old patient with Down's syndrome, is brought to the general practitioner by her father. He is worried as Sophie has been crying more than usual and has started holding her right ear. She is diagnosed with acute bacterial otitis media.
What is the most probable bacteria responsible for this infection?Your Answer: Staphylococcus aureus
Correct Answer: Haemophilus influenzae
Explanation:Haemophilus influenzae is a frequent culprit behind bacterial otitis media, a common ear infection.
The majority of cases of acute bacterial otitis media are caused by Streptococcus pneumoniae, Haemophilus influenzae, or Moraxella.
Genital gonorrhoeae is caused by N. gonorrhoeae, a sexually transmitted infection that presents with discharge and painful urination.
Meningococcal sepsis, a life-threatening condition, is caused by N. meningitides.
Staph. aureus is responsible for superficial skin infections like impetigo.
Syphilis, which typically manifests as a painless genital sore called a chancre, is caused by T. pallidum.
Acute otitis media is a common condition in young children, often caused by bacterial infections following viral upper respiratory tract infections. Symptoms include ear pain, fever, and hearing loss, and diagnosis is based on criteria such as the presence of a middle ear effusion and inflammation of the tympanic membrane. Antibiotics may be prescribed in certain cases, and complications can include perforation of the tympanic membrane, hearing loss, and more serious conditions such as meningitis and brain abscess.
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This question is part of the following fields:
- Respiratory System
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Question 7
Incorrect
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A 28-year-old female patient presents to your clinic seeking help to quit smoking. Despite several attempts in the past, she has been unsuccessful. She has a medical history of bipolar disorder and well-managed epilepsy, for which she takes lamotrigine. She currently smokes 15 cigarettes per day and is especially interested in the health benefits of quitting smoking since she has recently found out that she is pregnant. As her physician, you decide to prescribe a suitable medication to assist her in her efforts. What would be the most appropriate treatment option?
Your Answer: Amitriptyline
Correct Answer: Nicotine gum
Explanation:Standard treatments for nicotine dependence do not include amitriptyline, fluoxetine, or gabapentin. Nicotine replacement therapy (NRT) can be helpful for motivated patients, but it is not a cure for addiction and may require multiple attempts. Bupropion and varenicline are other smoking cessation aids, but they have multiple side effects and may not be suitable for all patients. NICE guidelines recommend discussing the best method of smoking cessation with the patient, but NRT is considered safer in pregnancy.
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This question is part of the following fields:
- Respiratory System
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Question 8
Incorrect
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An 83-year-old man is on the stroke ward after suffering a total anterior circulation stroke of the left hemisphere. He is receiving assistance from the physiotherapists to mobilize, but the speech and language team has determined that he has an unsafe swallow. On the 6th day of his hospital stay, he begins to feel unwell.
Upon examination, his temperature is 38.4ºC, heart rate of 112/min, respiratory rate of 18, and his blood pressure is 100/76 mmHg. Aspiration pneumonia is suspected. Which area of the body is most likely affected?Your Answer: Left upper lobe
Correct Answer: Right middle lobe
Explanation:Aspiration pneumonia is a common occurrence in stroke patients during the recovery phase, with a higher likelihood of affecting the right lung due to the steeper course of the right bronchus. This type of pneumonia is often caused by unsafe swallowing and can lead to prolonged hospital stays and increased mortality rates. The right middle and lower lobes are the most susceptible to aspirated gastric contents, while the right upper lobe is less likely due to gravity. It’s important to consider aspiration pneumonia as a differential diagnosis when assessing stroke patients, especially those with severe pathology.
Aspiration pneumonia is a type of pneumonia that occurs when foreign substances, such as food or saliva, enter the bronchial tree. This can lead to inflammation and a chemical pneumonitis, as well as the introduction of bacterial pathogens. The condition is often caused by an impaired swallowing mechanism, which can be a result of neurological disease or injury, intoxication, or medical procedures such as intubation. Risk factors for aspiration pneumonia include poor dental hygiene, swallowing difficulties, prolonged hospitalization or surgery, impaired consciousness, and impaired mucociliary clearance. The right middle and lower lung lobes are typically the most affected areas. The bacteria involved in aspiration pneumonia can be aerobic or anaerobic, with examples including Streptococcus pneumoniae, Staphylococcus aureus, Haemophilus influenzae, Pseudomonas aeruginosa, Klebsiella, Bacteroides, Prevotella, Fusobacterium, and Peptostreptococcus.
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This question is part of the following fields:
- Respiratory System
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Question 9
Incorrect
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A 57-year-old man comes to his GP complaining of worsening shortness of breath during physical activity over the past year. He has never smoked and reports no history of occupational exposure to asbestos, dust, or fumes. His BMI is calculated to be 40 kg/m². Upon examination, there is decreased chest expansion bilaterally, but the lungs are clear upon auscultation. The GP orders spirometry, which reveals a decreased expiratory reserve volume.
Can you provide the definition of this particular lung volume?Your Answer: The volume remaining in the lungs at the end of a normal tidal expiration
Correct Answer: Maximum volume of air that can be expired at the end of a normal tidal expiration
Explanation:The expiratory reserve volume refers to the maximum amount of air that can be exhaled after a normal breath out. It is important to note that this volume can be reduced in conditions that limit lung expansion, such as obesity and ascites. Obesity, in particular, can cause a restrictive pattern on spirometry, where the FEV1/FVC ratio is ≥0.8. Other restrictive lung conditions include idiopathic pulmonary fibrosis, pleural effusion, ascites, and neuromuscular disorders that limit chest expansion. On the other hand, obstructive disorders like asthma and COPD lead to a FEV1/FVC ratio of <0.7, limiting the amount of air that can be exhaled in one second. It is essential to understand the different lung volumes and capacities, including inspiratory reserve volume, tidal volume, expiratory reserve volume, residual volume, inspiratory capacity, vital capacity, functional residual capacity, and total lung capacity. Understanding Lung Volumes in Respiratory Physiology In respiratory physiology, lung volumes can be measured to determine the amount of air that moves in and out of the lungs during breathing. The diagram above shows the different lung volumes that can be measured. Tidal volume (TV) refers to the amount of air that is inspired or expired with each breath at rest. In males, the TV is 500ml while in females, it is 350ml. Inspiratory reserve volume (IRV) is the maximum volume of air that can be inspired at the end of a normal tidal inspiration. The inspiratory capacity is the sum of TV and IRV. On the other hand, expiratory reserve volume (ERV) is the maximum volume of air that can be expired at the end of a normal tidal expiration. Residual volume (RV) is the volume of air that remains in the lungs after maximal expiration. It increases with age and can be calculated by subtracting ERV from FRC. Speaking of FRC, it is the volume in the lungs at the end-expiratory position and is equal to the sum of ERV and RV. Vital capacity (VC) is the maximum volume of air that can be expired after a maximal inspiration. It decreases with age and can be calculated by adding inspiratory capacity and ERV. Lastly, total lung capacity (TLC) is the sum of vital capacity and residual volume. Physiological dead space (VD) is calculated by multiplying tidal volume by the difference between arterial carbon dioxide pressure (PaCO2) and end-tidal carbon dioxide pressure (PeCO2) and then dividing the result by PaCO2.
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This question is part of the following fields:
- Respiratory System
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Question 10
Correct
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A 24-year-old female arrives at the emergency department in a state of panic following a recent breakup with her partner. She complains of chest tightness and dizziness, fearing that she may be experiencing a heart attack. Upon examination, her vital signs are stable except for a respiratory rate of 34 breaths per minute. What compensatory mechanism is expected in response to the change in her oxyhaemoglobin dissociation curve, and what is the underlying cause?
Your Answer: Left shift, respiratory alkalosis
Explanation:The patient’s oxygen dissociation curve has shifted to the left, indicating respiratory alkalosis. This is likely due to the patient experiencing a panic attack and hyperventilating, leading to a decrease in carbon dioxide levels and an increase in the affinity of haemoglobin for oxygen. Respiratory acidosis, hypercapnia, and a right shift of the curve are not appropriate explanations for this patient’s condition.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 11
Incorrect
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As the pregnancy progresses, at what stage does the foetus typically begin producing surfactant?
A mother has been informed that she will have to deliver her baby prematurely due to complications in the pregnancy. To decrease the chances of neonatal distress syndrome, doctors have administered steroids to stimulate surfactant production in the foetus. They clarify that the foetus is already generating its own surfactant, and these steroids will enhance the process.Your Answer: Week 30
Correct Answer: Week 22
Explanation:Lung development in humans begins at week 4 with the formation of the respiratory diverticulum. By week 10, the lungs start to grow as tertiary bronchial buds form. Terminal bronchioles begin to form around week 18. The saccular stage of lung development, which marks the earliest viability for a human fetus, occurs at around 22-24 weeks when type 2 alveolar cells start producing surfactant. By week 30, the primary alveoli form as the mesenchyme surrounding the lungs becomes highly vascular.
The Importance of Pulmonary Surfactant in Breathing
Pulmonary surfactant is a substance composed of phospholipids, carbohydrates, and proteins that is released by type 2 pneumocytes. Its main component, dipalmitoyl phosphatidylcholine (DPPC), plays a crucial role in reducing alveolar surface tension. This substance is first detectable around 28 weeks and increases in concentration as the alveoli decrease in size. This helps prevent the alveoli from collapsing and reduces the muscular force needed to expand the lungs, ultimately decreasing the work of breathing. Additionally, pulmonary surfactant lowers the elastic recoil at low lung volumes, preventing the alveoli from collapsing at the end of each expiration. Overall, pulmonary surfactant is essential in maintaining proper lung function and preventing respiratory distress.
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This question is part of the following fields:
- Respiratory System
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Question 12
Correct
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A 26-year-old man is brought to the emergency department after being rescued at sea following a sailing accident. He is currently unresponsive with a Glasgow Coma Score of 9 (E2 V3 M4).
His vital signs include a heart rate of 110 beats per minute, blood pressure of 110/76 mmHg, oxygen saturation of 93%, and temperature of 34.8 ºC. An ECG is unremarkable and venous blood indicates type 2 respiratory failure. The patient's oxygen dissociation curve shows a leftward shift.
What is the cause of the leftward shift in this 26-year-old patient's oxygen dissociation curve?Your Answer: Hypothermia
Explanation:The only answer that causes a leftward shift in the oxygen dissociation curve is hypothermia. When tissues undergo aerobic respiration, they generate heat, which changes the shape of the haemoglobin molecule and reduces its affinity for oxygen. This results in the release of oxygen at respiring tissues. In contrast, lower temperatures in the lungs cause a leftward shift in the oxygen dissociation curve, which increases the binding of oxygen to haemoglobin.
Hypercapnia is not the correct answer because it causes a rightward shift in the oxygen dissociation curve. Hypercapnia lowers blood pH, which changes the shape of haemoglobin and reduces its affinity for oxygen.
Hypoxaemia is not the correct answer because the partial pressure of oxygen does not affect the oxygen dissociation curve. The partial pressure of oxygen does not change the affinity of haemoglobin for oxygen.
Increased concentration of 2,3-diphosphoglycerate (2,3-DPG) is not the correct answer because higher concentrations of 2,3-DPG reduce haemoglobin’s affinity for oxygen, causing a right shift in the oxygen dissociation curve.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 13
Incorrect
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A 25-year-old patient is undergoing routine pulmonary function testing to assess her chronic condition. The results are compared to a standardised predicted value and presented in the table below:
FEV1 75% of predicted
FVC 70% of predicted
FEV1/FVC 105%
What is the probable condition that this patient is suffering from, which can account for the above findings?Your Answer: Asthma
Correct Answer: Neuromuscular disorder
Explanation:The patient’s pulmonary function tests indicate a restrictive pattern, as both FEV1 and FVC are reduced. This suggests a possible neuromuscular disorder, as all other options would result in an obstructive pattern on the tests. Asthma, bronchiectasis, and COPD are unlikely diagnoses for a 20-year-old and would not match the test results. Pneumonia may affect the patient’s ability to perform the tests, but it is typically an acute condition that requires immediate treatment with antibiotics.
Understanding Pulmonary Function Tests
Pulmonary function tests are a useful tool in determining whether a respiratory disease is obstructive or restrictive. These tests measure various aspects of lung function, such as forced expiratory volume in one second (FEV1) and forced vital capacity (FVC). By analyzing the results of these tests, doctors can diagnose and monitor conditions such as asthma, COPD, pulmonary fibrosis, and neuromuscular disorders.
In obstructive lung diseases, such as asthma and COPD, the FEV1 is significantly reduced, while the FVC may be reduced or normal. The FEV1% (FEV1/FVC) is also reduced. On the other hand, in restrictive lung diseases, such as pulmonary fibrosis and asbestosis, the FEV1 is reduced, but the FVC is significantly reduced. The FEV1% (FEV1/FVC) may be normal or increased.
It is important to note that there are many conditions that can affect lung function, and pulmonary function tests are just one tool in diagnosing and managing respiratory diseases. However, understanding the results of these tests can provide valuable information for both patients and healthcare providers.
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This question is part of the following fields:
- Respiratory System
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Question 14
Incorrect
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A 58-year-old man comes to the GP complaining of wheezing, coughing, and shortness of breath. He has a smoking history of 35 pack-years but has reduced his smoking recently.
The GP orders spirometry, which confirms a diagnosis of chronic obstructive pulmonary disease. The results also show an elevated functional residual capacity.
What is the method used to calculate this metric?Your Answer: Expiratory reserve volume + tidal volume + inspiratory reserve volume
Correct Answer: Expiratory reserve volume + residual volume
Explanation:Understanding Lung Volumes in Respiratory Physiology
In respiratory physiology, lung volumes can be measured to determine the amount of air that moves in and out of the lungs during breathing. The diagram above shows the different lung volumes that can be measured.
Tidal volume (TV) refers to the amount of air that is inspired or expired with each breath at rest. In males, the TV is 500ml while in females, it is 350ml.
Inspiratory reserve volume (IRV) is the maximum volume of air that can be inspired at the end of a normal tidal inspiration. The inspiratory capacity is the sum of TV and IRV. On the other hand, expiratory reserve volume (ERV) is the maximum volume of air that can be expired at the end of a normal tidal expiration.
Residual volume (RV) is the volume of air that remains in the lungs after maximal expiration. It increases with age and can be calculated by subtracting ERV from FRC. Speaking of FRC, it is the volume in the lungs at the end-expiratory position and is equal to the sum of ERV and RV.
Vital capacity (VC) is the maximum volume of air that can be expired after a maximal inspiration. It decreases with age and can be calculated by adding inspiratory capacity and ERV. Lastly, total lung capacity (TLC) is the sum of vital capacity and residual volume.
Physiological dead space (VD) is calculated by multiplying tidal volume by the difference between arterial carbon dioxide pressure (PaCO2) and end-tidal carbon dioxide pressure (PeCO2) and then dividing the result by PaCO2.
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This question is part of the following fields:
- Respiratory System
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Question 15
Correct
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A 67-year-old man is admitted to the acute stroke unit following a haemorrhagic stroke. Three days after admission he complains of pain and swelling in the left calf. A Doppler ultrasound shows large DVT with extension into the upper leg. Given his recent stroke, anticoagulation is contraindicated, however, there is a significant risk of him developing a pulmonary embolus. The decision is made to insert an inferior vena cava (IVC) filter. The registrar inserting the filter is fairly junior, he plans to insert this just above the renal veins, however, asks the consultant if there are any landmarks he can use to guide him. The consultant advises him if he reaches the diaphragm he has gone too far!
At which vertebral level would the diaphragm be encountered when inserting an IVC filter?Your Answer: T8
Explanation:The point at which the inferior vena cava passes through the diaphragm is being asked in this question. The correct answer is T8, which is where the IVC crosses the diaphragm through the caval opening. The IVC is formed by the joining of the left and right common iliac veins at around L5.
In patients who are at high risk of pulmonary embolus and for whom anticoagulation is not effective or contraindicated, an IVC filter can be used. This filter is usually inserted above the renal veins, but it can be placed at any level, including the superior vena cava, if necessary.
The other options provided in the question, T6, T10, and T11, are not associated with any significant structures. The oesophagus passes through the diaphragm with the vagal trunk at T10.
Structures Perforating the Diaphragm
The diaphragm is a dome-shaped muscle that separates the thoracic and abdominal cavities. It plays a crucial role in breathing by contracting and relaxing to create negative pressure in the lungs. However, there are certain structures that perforate the diaphragm, allowing them to pass through from the thoracic to the abdominal cavity. These structures include the inferior vena cava at the level of T8, the esophagus and vagal trunk at T10, and the aorta, thoracic duct, and azygous vein at T12.
To remember these structures and their corresponding levels, a helpful mnemonic is I 8(ate) 10 EGGS AT 12. This means that the inferior vena cava is at T8, the esophagus and vagal trunk are at T10, and the aorta, thoracic duct, and azygous vein are at T12. Knowing these structures and their locations is important for medical professionals, as they may need to access or treat them during surgical procedures or diagnose issues related to them.
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This question is part of the following fields:
- Respiratory System
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Question 16
Incorrect
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An 80-year-old man with metastatic lung cancer arrives at the acute medical unit with sudden shortness of breath. A chest x-ray shows a malignant pleural effusion encasing the right lung. The medical registrar intends to perform a pleural tap to drain the effusion and send a sample to the lab. The registrar takes into account the effusion's position around the lung. What is the minimum level of the effusion in the mid-axillary line?
Your Answer: 8th rib
Correct Answer: 10th rib
Explanation:The parietal pleura can be found at the 10th rib in the mid-axillary line, while the visceral pleura is closely attached to the lung tissue and can be considered as one. The location of the parietal pleura is more inferior than that of the visceral pleura, with the former being at the 8th rib in the midclavicular line and the 10th rib in the midaxillary line. The location of the parietal pleura in the scapular line is not specified.
Anatomy of the Lungs
The lungs are a pair of organs located in the chest cavity that play a vital role in respiration. The right lung is composed of three lobes, while the left lung has two lobes. The apex of both lungs is approximately 4 cm superior to the sternocostal joint of the first rib. The base of the lungs is in contact with the diaphragm, while the costal surface corresponds to the cavity of the chest. The mediastinal surface contacts the mediastinal pleura and has the cardiac impression. The hilum is a triangular depression above and behind the concavity, where the structures that form the root of the lung enter and leave the viscus. The right main bronchus is shorter, wider, and more vertical than the left main bronchus. The inferior borders of both lungs are at the 6th rib in the mid clavicular line, 8th rib in the mid axillary line, and 10th rib posteriorly. The pleura runs two ribs lower than the corresponding lung level. The bronchopulmonary segments of the lungs are divided into ten segments, each with a specific function.
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This question is part of the following fields:
- Respiratory System
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Question 17
Correct
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A 57-year-old woman arrives at the emergency department complaining of difficulty breathing. She has a medical history of idiopathic interstitial lung disease. Upon examination, her temperature is 37.1ºC, oxygen saturation is 76% on air, heart rate is 106 beats per minute, respiratory rate is 26 breaths per minute, and blood pressure is 116/60 mmHg.
What pulmonary alteration would take place in response to her low oxygen saturation?Your Answer: Pulmonary artery vasoconstriction
Explanation:Hypoxia causes vasoconstriction in the pulmonary arteries, which can lead to pulmonary artery hypertension in patients with chronic lung disease and chronic hypoxia. Diffuse bronchoconstriction is not a response to hypoxia, but may cause hypoxia in conditions such as acute asthma exacerbation. Hypersecretion of mucus from goblet cells is a characteristic finding in chronic inflammatory lung diseases, but is not a response to hypoxia. Pulmonary artery vasodilation occurs around well-ventilated alveoli to optimize oxygen uptake into the blood.
The Effects of Hypoxia on Pulmonary Arteries
When the partial pressure of oxygen in the blood decreases, the pulmonary arteries undergo vasoconstriction. This means that the blood vessels narrow, allowing blood to be redirected to areas of the lung that are better aerated. This response is a natural mechanism that helps to improve the efficiency of gaseous exchange in the lungs. By diverting blood to areas with more oxygen, the body can ensure that the tissues receive the oxygen they need to function properly. Overall, hypoxia triggers a physiological response that helps to maintain homeostasis in the body.
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This question is part of the following fields:
- Respiratory System
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Question 18
Correct
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What is the carrier rate of cystic fibrosis in the United Kingdom?
Your Answer: 1 in 25
Explanation:Understanding Cystic Fibrosis
Cystic fibrosis is a genetic disorder that causes thickened secretions in the lungs and pancreas. It is an autosomal recessive condition that occurs due to a defect in the cystic fibrosis transmembrane conductance regulator gene (CFTR), which regulates a chloride channel. In the UK, 80% of CF cases are caused by delta F508 on chromosome 7, and the carrier rate is approximately 1 in 25.
CF patients are at risk of colonization by certain organisms, including Staphylococcus aureus, Pseudomonas aeruginosa, Burkholderia cepacia (previously known as Pseudomonas cepacia), and Aspergillus. These organisms can cause infections and exacerbate symptoms in CF patients. It is important for healthcare providers to monitor and manage these infections to prevent further complications.
Overall, understanding cystic fibrosis and its associated risks can help healthcare providers provide better care for patients with this condition.
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This question is part of the following fields:
- Respiratory System
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Question 19
Correct
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A 49-year-old patient presents to the rheumatology clinic with weight loss, fever, and night sweats. The individual is also experiencing shortness of breath. The following blood test results are obtained:
- Hemoglobin (Hb): 140 g/l
- Platelets: 192 * 109/l
- White cell count (WCC): 5.3 * 109/l
- Creatinine: 154 umol/l
- Urea: 9 mmol/l
- cANCA positive
The white cell differential count is reported as normal. What is the most likely diagnosis?Your Answer: Granulomatosis with polyangiitis
Explanation:The most likely diagnosis for this patient is granulomatosis with polyangiitis, as indicated by the presence of cANCA and the involvement of multiple organs including the lungs, skin, kidneys, and upper respiratory tract. This condition is known to cause inflammation in the glomeruli, leading to renal impairment. Churg-Strauss disease and Alport’s syndrome are unlikely due to normal eosinophil levels and cANCA positivity, respectively. Goodpasture’s syndrome is also unlikely as the patient does not present with haematuria or haemoptysis.
Granulomatosis with Polyangiitis: An Autoimmune Condition
Granulomatosis with polyangiitis, previously known as Wegener’s granulomatosis, is an autoimmune condition that affects the upper and lower respiratory tract as well as the kidneys. It is characterized by a necrotizing granulomatous vasculitis. The condition presents with various symptoms such as epistaxis, sinusitis, nasal crusting, dyspnoea, haemoptysis, and rapidly progressive glomerulonephritis. Other symptoms include a saddle-shape nose deformity, vasculitic rash, eye involvement, and cranial nerve lesions.
To diagnose granulomatosis with polyangiitis, doctors perform various investigations such as cANCA and pANCA tests, chest x-rays, and renal biopsies. The cANCA test is positive in more than 90% of cases, while the pANCA test is positive in 25% of cases. Chest x-rays show a wide variety of presentations, including cavitating lesions. Renal biopsies reveal epithelial crescents in Bowman’s capsule.
The management of granulomatosis with polyangiitis involves the use of steroids, cyclophosphamide, and plasma exchange. Cyclophosphamide has a 90% response rate. The median survival rate for patients with this condition is 8-9 years.
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This question is part of the following fields:
- Respiratory System
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Question 20
Incorrect
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A 56-year-old man has been diagnosed with small cell lung carcinoma. The tumor measures 4 centimeters in its largest dimension and is not invading any surrounding structures. However, there are metastases in the ipsilateral hilar lymph nodes, and no distant metastases have been found. What is the TNM score for this patient, considering the primary tumor (T), regional lymph nodes (N), and distant metastases (M)?
Your Answer: T2 N2 M0
Correct Answer: T2 N1 M0
Explanation:It is crucial to have knowledge about the TNM system for staging lung cancer. The absence of distant metastases eliminates one of the options immediately (as M must be 0).
The size and invasion of the tumor are significant factors:
– T1 is less than 3 cm
– T2 is between 3 cm and 7 cm
– T3 is more than 7 cm and/or involves invasion of the chest wall, parietal pleura, diaphragm, phrenic nerve, mediastinal pleura, or parietal pericardium
– T4 can be any size but involves invasion of other structuresTo differentiate between N1 and N2, remember that N1 involves ipsilateral hilar or peribronchial lymph nodes, while N2 involves ipsilateral mediastinal and/or subcarinal lymph nodes.
Small Cell Lung Cancer: Characteristics and Management
Small cell lung cancer is a type of lung cancer that usually develops in the central part of the lungs and arises from APUD cells. This type of cancer is often associated with the secretion of hormones such as ADH and ACTH, which can cause hyponatremia and Cushing’s syndrome, respectively. In addition, ACTH secretion can lead to bilateral adrenal hyperplasia and hypokalemic alkalosis due to high levels of cortisol. Patients with small cell lung cancer may also experience Lambert-Eaton syndrome, which is characterized by antibodies to voltage-gated calcium channels causing a myasthenic-like syndrome.
Management of small cell lung cancer depends on the stage of the disease. Patients with very early stage disease may be considered for surgery, while those with limited disease typically receive a combination of chemotherapy and radiotherapy. Patients with more extensive disease are offered palliative chemotherapy. Unfortunately, most patients with small cell lung cancer are diagnosed with metastatic disease, making treatment more challenging.
Overall, small cell lung cancer is a complex disease that requires careful management and monitoring. Early detection and treatment can improve outcomes, but more research is needed to better understand the underlying mechanisms of this type of cancer.
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This question is part of the following fields:
- Respiratory System
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Question 21
Incorrect
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A 50-year-old man with laryngeal cancer is undergoing a challenging laryngectomy. During the procedure, the surgeons cut the thyrocervical trunk. What vessel does this structure typically originate from?
Your Answer: Internal carotid artery
Correct Answer: Subclavian artery
Explanation:The subclavian artery gives rise to the thyrocervical trunk, which emerges from the first part of the artery located between the inner border of scalenus anterior and the subclavian artery. The thyrocervical trunk branches off from the subclavian artery after the vertebral artery.
Thoracic Outlet: Where the Subclavian Artery and Vein and Brachial Plexus Exit the Thorax
The thoracic outlet is the area where the subclavian artery and vein and the brachial plexus exit the thorax and enter the arm. This passage occurs over the first rib and under the clavicle. The subclavian vein is the most anterior structure and is located immediately in front of scalenus anterior and its attachment to the first rib. Scalenus anterior has two parts, and the subclavian artery leaves the thorax by passing over the first rib and between these two portions of the muscle. At the level of the first rib, the lower cervical nerve roots combine to form the three trunks of the brachial plexus. The lowest trunk is formed by the union of C8 and T1, and this trunk lies directly posterior to the artery and is in contact with the superior surface of the first rib.
Thoracic outlet obstruction can cause neurovascular compromise.
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This question is part of the following fields:
- Respiratory System
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Question 22
Incorrect
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What is the anatomical level of the transpyloric plane?
Your Answer: T10
Correct Answer: L1
Explanation:The Transpyloric Plane and its Anatomical Landmarks
The transpyloric plane is an imaginary horizontal line that passes through the body of the first lumbar vertebrae (L1) and the pylorus of the stomach. It is an important anatomical landmark used in clinical practice to locate various organs and structures in the abdomen.
Some of the structures that lie on the transpyloric plane include the left and right kidney hilum (with the left one being at the same level as L1), the fundus of the gallbladder, the neck of the pancreas, the duodenojejunal flexure, the superior mesenteric artery, and the portal vein. The left and right colic flexure, the root of the transverse mesocolon, and the second part of the duodenum also lie on this plane.
In addition, the upper part of the conus medullaris (the tapered end of the spinal cord) and the spleen are also located on the transpyloric plane. Knowing the location of these structures is important for various medical procedures, such as abdominal surgeries and diagnostic imaging.
Overall, the transpyloric plane serves as a useful reference point for clinicians to locate important anatomical structures in the abdomen.
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This question is part of the following fields:
- Respiratory System
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Question 23
Incorrect
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An 80-year-old man has been referred to the respiratory clinic due to a persistent dry cough and hoarse voice for the last 5 months. He reports feeling like he has lost some weight as his clothes feel loose. Although he has no significant past medical history, he has a 30-pack-year smoking history. During the examination, left-sided miosis and ptosis are noted. What is the probable location of the lung lesion?
Your Answer: In the pleura
Correct Answer: Lung apex
Explanation:The patient’s persistent cough, significant smoking history, and weight loss are red flag symptoms of lung cancer. Additionally, the hoarseness of voice suggests that the recurrent laryngeal nerve is being suppressed, likely due to a Pancoast tumor located in the apex of the lung. The presence of Horner’s syndrome further supports this diagnosis. Mesothelioma, which is more common in patients with a history of asbestos exposure, typically presents with shortness of breath, chest wall pain, and finger clubbing. A hamartoma, a benign tumor made up of tissue such as cartilage, connective tissue, and fat, is unlikely given the patient’s red flags for malignant disease. Small cell carcinomas, typically found in the center of the lungs, may present with a perihilar mass and paraneoplastic syndromes due to ectopic hormone secretion. Lung cancers within the bronchi can obstruct airways and cause respiratory symptoms such as cough and shortness of breath, but not hoarseness.
Lung Cancer Symptoms and Complications
Lung cancer is a serious condition that can cause a range of symptoms and complications. Some of the most common symptoms include a persistent cough, haemoptysis (coughing up blood), dyspnoea (shortness of breath), chest pain, weight loss and anorexia, and hoarseness. In some cases, patients may also experience supraclavicular lymphadenopathy or persistent cervical lymphadenopathy, as well as clubbing and a fixed, monophonic wheeze.
In addition to these symptoms, lung cancer can also cause a range of paraneoplastic features. These may include the secretion of ADH, ACTH, or parathyroid hormone-related protein (PTH-rp), which can cause hypercalcaemia, hypertension, hyperglycaemia, hypokalaemia, alkalosis, muscle weakness, and other complications. Other paraneoplastic features may include Lambert-Eaton syndrome, hypertrophic pulmonary osteoarthropathy (HPOA), hyperthyroidism due to ectopic TSH, and gynaecomastia.
Complications of lung cancer may include hoarseness, stridor, and superior vena cava syndrome. Patients may also experience a thrombocytosis, which can be detected through blood tests. Overall, it is important to be aware of the symptoms and complications of lung cancer in order to seek prompt medical attention and receive appropriate treatment.
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This question is part of the following fields:
- Respiratory System
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Question 24
Correct
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A senior citizen who has been a lifelong smoker visits the respiratory clinic for a check-up on his emphysema. What alterations in his lung function test results would you anticipate?
Your Answer: Increased residual volume and reduced vital capacity
Explanation:Emphysema causes an increase in residual volume, leading to a decrease in vital capacity. This is due to damage to the alveolar walls, which results in the formation of large air sacs called bullae. The lungs lose their compliance, making it difficult to fully exhale and causing air to become trapped in the bullae. As a result, the total volume that can be exhaled is reduced, leading to a decrease in vital capacity.
Understanding Lung Volumes in Respiratory Physiology
In respiratory physiology, lung volumes can be measured to determine the amount of air that moves in and out of the lungs during breathing. The diagram above shows the different lung volumes that can be measured.
Tidal volume (TV) refers to the amount of air that is inspired or expired with each breath at rest. In males, the TV is 500ml while in females, it is 350ml.
Inspiratory reserve volume (IRV) is the maximum volume of air that can be inspired at the end of a normal tidal inspiration. The inspiratory capacity is the sum of TV and IRV. On the other hand, expiratory reserve volume (ERV) is the maximum volume of air that can be expired at the end of a normal tidal expiration.
Residual volume (RV) is the volume of air that remains in the lungs after maximal expiration. It increases with age and can be calculated by subtracting ERV from FRC. Speaking of FRC, it is the volume in the lungs at the end-expiratory position and is equal to the sum of ERV and RV.
Vital capacity (VC) is the maximum volume of air that can be expired after a maximal inspiration. It decreases with age and can be calculated by adding inspiratory capacity and ERV. Lastly, total lung capacity (TLC) is the sum of vital capacity and residual volume.
Physiological dead space (VD) is calculated by multiplying tidal volume by the difference between arterial carbon dioxide pressure (PaCO2) and end-tidal carbon dioxide pressure (PeCO2) and then dividing the result by PaCO2.
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This question is part of the following fields:
- Respiratory System
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Question 25
Incorrect
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A 23-year-old woman comes to your clinic with a complaint of ear pain and difficulty hearing on one side. During the examination, you observe that she has a fever and a bulging tympanic membrane. What nerve transmits pain from the middle ear?
Your Answer: Vestibulocochlear nerve
Correct Answer: Glossopharyngeal nerve
Explanation:The correct answer is the glossopharyngeal nerve, which is responsible for carrying sensation from the middle ear.
The ninth cranial nerve, or glossopharyngeal nerve, carries taste and sensation from the posterior one-third of the tongue, as well as sensation from various areas such as the pharyngeal wall, tonsils, pharyngotympanic tube, middle ear, tympanic membrane, external auditory canal, and auricle. It also provides motor fibers to the stylopharyngeus and parasympathetic fibers to the parotid gland. Additionally, it carries information from the baroreceptors and chemoreceptors of the carotid sinus.
On the other hand, the seventh cranial nerve, or facial nerve, innervates the muscles of facial expression, stylohyoid, stapedius, and the posterior belly of digastric. It carries sensation from part of the external acoustic meatus, auricle, and behind the auricle, and taste from the anterior two-thirds of the tongue. It also provides parasympathetic fibers to the submandibular, sublingual, nasal, and lacrimal glands.
The eighth cranial nerve, or vestibulocochlear nerve, has a vestibular component that carries balance information from the labyrinths of the inner ear and a cochlear component that carries hearing information from the cochlea of the inner ear.
The twelfth cranial nerve, or hypoglossal nerve, supplies motor innervation to all of the intrinsic muscles of the tongue and all of the extrinsic muscles of the tongue except for palatoglossus.
Lastly, the maxillary nerve is the second division of the trigeminal nerve, the fifth cranial nerve, which carries sensation from the upper teeth and gingivae, the nasal cavity, and skin across the lower eyelids and cheeks.
Based on the patient’s symptoms of ear pain, the most likely diagnosis is otitis media, as indicated by her fever and the presence of a bulging tympanic membrane on otoscopy.
Anatomy of the Ear
The ear is divided into three distinct regions: the external ear, middle ear, and internal ear. The external ear consists of the auricle and external auditory meatus, which are innervated by the greater auricular nerve and auriculotemporal branch of the trigeminal nerve. The middle ear is the space between the tympanic membrane and cochlea, and is connected to the nasopharynx by the eustachian tube. The tympanic membrane is composed of three layers and is approximately 1 cm in diameter. The middle ear is innervated by the glossopharyngeal nerve. The ossicles, consisting of the malleus, incus, and stapes, transmit sound vibrations from the tympanic membrane to the inner ear. The internal ear contains the cochlea, which houses the organ of corti, the sense organ of hearing. The vestibule accommodates the utricule and saccule, which contain endolymph and are surrounded by perilymph. The semicircular canals, which share a common opening into the vestibule, lie at various angles to the petrous temporal bone.
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This question is part of the following fields:
- Respiratory System
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Question 26
Incorrect
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A 70-year-old man with lung cancer is having a left pneumonectomy. The left main bronchus is being divided. Which thoracic vertebrae is located behind this structure?
Your Answer: T3
Correct Answer: T6
Explanation:Anatomy of the Lungs
The lungs are a pair of organs located in the chest cavity that play a vital role in respiration. The right lung is composed of three lobes, while the left lung has two lobes. The apex of both lungs is approximately 4 cm superior to the sternocostal joint of the first rib. The base of the lungs is in contact with the diaphragm, while the costal surface corresponds to the cavity of the chest. The mediastinal surface contacts the mediastinal pleura and has the cardiac impression. The hilum is a triangular depression above and behind the concavity, where the structures that form the root of the lung enter and leave the viscus. The right main bronchus is shorter, wider, and more vertical than the left main bronchus. The inferior borders of both lungs are at the 6th rib in the mid clavicular line, 8th rib in the mid axillary line, and 10th rib posteriorly. The pleura runs two ribs lower than the corresponding lung level. The bronchopulmonary segments of the lungs are divided into ten segments, each with a specific function.
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This question is part of the following fields:
- Respiratory System
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Question 27
Incorrect
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Which one of the following does not cause a normal anion gap acidosis?
Your Answer: Renal tubular acidosis
Correct Answer: Uraemia
Explanation:Normal Gap Acidosis can be remembered using the acronym HARDUP, which stands for Hyperalimentation/hyperventilation, Acetazolamide, and R (which is currently blank).
Disorders of Acid-Base Balance
The acid-base nomogram is a useful tool for categorizing the various disorders of acid-base balance. Metabolic acidosis is the most common surgical acid-base disorder, characterized by a reduction in plasma bicarbonate levels. This can be caused by a gain of strong acid or loss of base, and is classified according to the anion gap. A normal anion gap indicates hyperchloraemic metabolic acidosis, which can be caused by gastrointestinal bicarbonate loss, renal tubular acidosis, drugs, or Addison’s disease. A raised anion gap indicates lactate, ketones, urate, or acid poisoning. Metabolic alkalosis, on the other hand, is usually caused by a rise in plasma bicarbonate levels due to a loss of hydrogen ions or a gain of bicarbonate. It is mainly caused by problems of the kidney or gastrointestinal tract. Respiratory acidosis is characterized by a rise in carbon dioxide levels due to alveolar hypoventilation, while respiratory alkalosis is caused by hyperventilation resulting in excess loss of carbon dioxide. These disorders have various causes, such as COPD, sedative drugs, anxiety, hypoxia, and pregnancy.
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This question is part of the following fields:
- Respiratory System
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Question 28
Correct
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A 75-year-old man visits his doctor complaining of a productive cough that has lasted for 5 days. He has also been feeling generally unwell and has had a fever for the past 2 days. The doctor suspects a bacterial respiratory tract infection and orders a blood panel, sputum microscopy, and culture. What is the most likely abnormality to be found in the blood results?
Your Answer: Neutrophils
Explanation:Neutrophils are typically elevated during an acute bacterial infection, while eosinophils are commonly elevated in response to parasitic infections and allergies. Lymphocytes tend to increase during acute viral infections and chronic inflammation. IgE levels are raised in cases of allergic asthma, malaria, and type 1 hypersensitivity reactions. Anti-CCP antibody is a diagnostic tool for Rheumatoid arthritis.
Pneumonia is a common condition that affects the alveoli of the lungs, usually caused by a bacterial infection. Other causes include viral and fungal infections. Streptococcus pneumoniae is the most common organism responsible for pneumonia, accounting for 80% of cases. Haemophilus influenzae is common in patients with COPD, while Staphylococcus aureus often occurs in patients following influenzae infection. Mycoplasma pneumoniae and Legionella pneumophilia are atypical pneumonias that present with dry cough and other atypical symptoms. Pneumocystis jiroveci is typically seen in patients with HIV. Idiopathic interstitial pneumonia is a group of non-infective causes of pneumonia.
Patients who develop pneumonia outside of the hospital have community-acquired pneumonia (CAP), while those who develop it within hospitals are said to have hospital-acquired pneumonia. Symptoms of pneumonia include cough, sputum, dyspnoea, chest pain, and fever. Signs of systemic inflammatory response, tachycardia, reduced oxygen saturations, and reduced breath sounds may also be present. Chest x-ray is used to diagnose pneumonia, with consolidation being the classical finding. Blood tests, such as full blood count, urea and electrolytes, and CRP, are also used to check for infection.
Patients with pneumonia require antibiotics to treat the underlying infection and supportive care, such as oxygen therapy and intravenous fluids. Risk stratification is done using a scoring system called CURB-65, which stands for confusion, respiration rate, blood pressure, age, and is used to determine the management of patients with community-acquired pneumonia. Home-based care is recommended for patients with a CRB65 score of 0, while hospital assessment is recommended for all other patients, particularly those with a CRB65 score of 2 or more. The CURB-65 score also correlates with an increased risk of mortality at 30 days.
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This question is part of the following fields:
- Respiratory System
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Question 29
Correct
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A 65-year-old man visited his family doctor with a persistent cough that has been bothering him for the last six months. He complains of coughing up clear sputum and how it has been affecting his daily life. He has also noticed that he gets short of breath more easily and cannot keep up with his grandchildren. He has a medical history of well-controlled diabetes and dyslipidemia. He attended a smoking cessation program a few months ago, but he finds it challenging to quit smoking after smoking a pack of cigarettes a day for the past 40 years. During the examination, the doctor hears bilateral wheezing with some crackles. The doctor expresses concerns about a possible lung disease due to his long history of smoking and refers him for a pulmonary function test. What is likely to be found during the test?
Your Answer: The FEV1/FVC ratio is lower than normal as there is a larger decrease in FEV1 than FVC
Explanation:The patient’s prolonged smoking history and current symptoms suggest a diagnosis of chronic bronchitis and possibly emphysema, both of which are obstructive lung diseases. These conditions cause air to become trapped in the lungs, making it difficult to breathe out. Pulmonary function tests typically show a greater decrease in FEV1 than FVC in obstructive lung diseases, resulting in a lower FEV1/FVC ratio (also known as the Tiffeneau-Pinelli index). This is different from restrictive lung diseases, which may sometimes show an increase in the FEV1/FVC ratio due to a larger decrease in FVC than FEV1. Chest X-rays may reveal hyperinflated lungs in patients with obstructive lung diseases. An increase in FEV1 may occur in healthy individuals after exercise training or in patients with conditions like asthma after taking medication. Restrictive lung diseases, such as pneumoconioses, hypersensitivity pneumonitis, and idiopathic pulmonary fibrosis, are typically associated with a decrease in the FEV1/FVC ratio.
Understanding Pulmonary Function Tests
Pulmonary function tests are a useful tool in determining whether a respiratory disease is obstructive or restrictive. These tests measure various aspects of lung function, such as forced expiratory volume in one second (FEV1) and forced vital capacity (FVC). By analyzing the results of these tests, doctors can diagnose and monitor conditions such as asthma, COPD, pulmonary fibrosis, and neuromuscular disorders.
In obstructive lung diseases, such as asthma and COPD, the FEV1 is significantly reduced, while the FVC may be reduced or normal. The FEV1% (FEV1/FVC) is also reduced. On the other hand, in restrictive lung diseases, such as pulmonary fibrosis and asbestosis, the FEV1 is reduced, but the FVC is significantly reduced. The FEV1% (FEV1/FVC) may be normal or increased.
It is important to note that there are many conditions that can affect lung function, and pulmonary function tests are just one tool in diagnosing and managing respiratory diseases. However, understanding the results of these tests can provide valuable information for both patients and healthcare providers.
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This question is part of the following fields:
- Respiratory System
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Question 30
Correct
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A 78-year-old man comes to your clinic with a complaint of hoarseness in his voice for the past 2 months. He is unsure if he had a viral infection prior to this and has attempted using over-the-counter remedies with no improvement. How would you approach managing this patient?
Your Answer: Red flag referral to ENT
Explanation:An urgent referral to an ENT specialist is necessary when a person over the age of 45 experiences persistent hoarseness without any apparent cause. In this case, the patient has been suffering from a hoarse voice for 8 weeks, which warrants an urgent referral. A routine referral would not be sufficient as it may not be quick enough to address the issue. Although it could be a viral or bacterial infection, the duration of the hoarseness suggests that there may be an underlying serious condition. Merely informing the patient that their voice may not return is not helpful and may overlook the possibility of a more severe problem.
Hoarseness can be caused by various factors such as overusing the voice, smoking, viral infections, hypothyroidism, gastro-oesophageal reflux, laryngeal cancer, and lung cancer. It is important to investigate the underlying cause of hoarseness, and a chest x-ray may be necessary to rule out any apical lung lesions.
If laryngeal cancer is suspected, it is recommended to refer the patient to an ENT specialist through a suspected cancer pathway. This referral should be considered for individuals who are 45 years old and above and have persistent unexplained hoarseness or an unexplained lump in the neck. Early detection and treatment of laryngeal cancer can significantly improve the patient’s prognosis.
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This question is part of the following fields:
- Respiratory System
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