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Question 1
Correct
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A 25-year-old man is shot in the chest during a robbery. The right lung is lacerated and is bleeding. An emergency thoracotomy is performed. The surgeons place a clamp over the hilum of the right lung. Which one of the following structures lies most anteriorly at this level?
Your Answer: Phrenic nerve
Explanation:At this location, the phrenic nerve is situated in front. The vagus nerve runs in front and then curves backwards just above the base of the left bronchus, releasing the recurrent laryngeal nerve as it curves.
Anatomy of the Lungs
The lungs are a pair of organs located in the chest cavity that play a vital role in respiration. The right lung is composed of three lobes, while the left lung has two lobes. The apex of both lungs is approximately 4 cm superior to the sternocostal joint of the first rib. The base of the lungs is in contact with the diaphragm, while the costal surface corresponds to the cavity of the chest. The mediastinal surface contacts the mediastinal pleura and has the cardiac impression. The hilum is a triangular depression above and behind the concavity, where the structures that form the root of the lung enter and leave the viscus. The right main bronchus is shorter, wider, and more vertical than the left main bronchus. The inferior borders of both lungs are at the 6th rib in the mid clavicular line, 8th rib in the mid axillary line, and 10th rib posteriorly. The pleura runs two ribs lower than the corresponding lung level. The bronchopulmonary segments of the lungs are divided into ten segments, each with a specific function.
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This question is part of the following fields:
- Respiratory System
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Question 2
Incorrect
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An 87-year-old man with a history of interstitial lung disease is admitted with fever, productive cough, and difficulty breathing. His inflammatory markers are elevated, and a chest x-ray reveals focal patchy consolidation in the right lung. He requires oxygen supplementation as his oxygen saturation level is 87% on room air. What factor causes a decrease in haemoglobin's affinity for oxygen?
Your Answer: Decrease in carbon dioxide
Correct Answer: Increase in temperature
Explanation:What effect does pyrexia have on the oxygen dissociation curve?
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 3
Incorrect
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A 33-year-old male presents to the ED with coughing and wheezing following an episode of alcohol intoxication. Upon examination, decreased breath sounds are noted on one side. Imaging reveals a foreign body obstructing an airway structure. What is the most probable location for this foreign body to be lodged?
Your Answer: Right superior lobar bronchus
Correct Answer: Right mainstem bronchus
Explanation:It is rare for a foreign object to become lodged in the left mainstem bronchus due to its greater angle compared to the right mainstem bronchus. A tracheal obstruction would cause reduced breath sounds bilaterally, not just on one side. The right superior lobar bronchus is also unlikely to be affected due to its angle and direction. Therefore, foreign bodies typically get stuck in the right mainstem bronchus in adults because of its wider diameter and lesser angle.
Anatomy of the Lungs
The lungs are a pair of organs located in the chest cavity that play a vital role in respiration. The right lung is composed of three lobes, while the left lung has two lobes. The apex of both lungs is approximately 4 cm superior to the sternocostal joint of the first rib. The base of the lungs is in contact with the diaphragm, while the costal surface corresponds to the cavity of the chest. The mediastinal surface contacts the mediastinal pleura and has the cardiac impression. The hilum is a triangular depression above and behind the concavity, where the structures that form the root of the lung enter and leave the viscus. The right main bronchus is shorter, wider, and more vertical than the left main bronchus. The inferior borders of both lungs are at the 6th rib in the mid clavicular line, 8th rib in the mid axillary line, and 10th rib posteriorly. The pleura runs two ribs lower than the corresponding lung level. The bronchopulmonary segments of the lungs are divided into ten segments, each with a specific function.
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This question is part of the following fields:
- Respiratory System
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Question 4
Incorrect
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Which one of the following is not found in the anterior mediastinum?
Your Answer: Pericardium
Correct Answer: Thoracic duct
Explanation:The posterior and superior mediastinum contain the thoracic duct.
The mediastinum is the area located between the two pulmonary cavities and is covered by the mediastinal pleura. It extends from the thoracic inlet at the top to the diaphragm at the bottom. The mediastinum is divided into four regions: the superior mediastinum, middle mediastinum, posterior mediastinum, and anterior mediastinum.
The superior mediastinum is the area between the manubriosternal angle and T4/5. It contains important structures such as the superior vena cava, brachiocephalic veins, arch of aorta, thoracic duct, trachea, oesophagus, thymus, vagus nerve, left recurrent laryngeal nerve, and phrenic nerve. The anterior mediastinum contains thymic remnants, lymph nodes, and fat. The middle mediastinum contains the pericardium, heart, aortic root, arch of azygos vein, and main bronchi. The posterior mediastinum contains the oesophagus, thoracic aorta, azygos vein, thoracic duct, vagus nerve, sympathetic nerve trunks, and splanchnic nerves.
In summary, the mediastinum is a crucial area in the thorax that contains many important structures and is divided into four regions. Each region contains different structures that are essential for the proper functioning of the body.
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This question is part of the following fields:
- Respiratory System
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Question 5
Correct
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A 59-year-old man comes to you with a dry cough that has been going on for three months and recent episodes of haemoptysis. He stopped smoking five years ago and has had two bouts of pneumonia in his left lower lobe in the last year. On examination, he is apyrexial and there are no notable findings.
What would be your first step in investigating this patient?Your Answer: Chest x ray
Explanation:Diagnosis of Bronchial Carcinoma
The patient’s medical history indicates the possibility of bronchial carcinoma. The most appropriate initial investigation to confirm this diagnosis is a chest x-ray. Other tests such as blood cultures may not be useful for an apyrexial patient. However, additional investigations may be considered after the chest x-ray. It is important to prioritize the chest x-ray as the first line investigation to detect any abnormalities in the lungs. Proper diagnosis is crucial for timely treatment and management of bronchial carcinoma.
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This question is part of the following fields:
- Respiratory System
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Question 6
Incorrect
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You are on call for the pediatric ward at night and are urgently called to a child who is choking on a piece of hot dog visible in their oropharynx. The child is in extremis with saturations of 87% and there is no effective cough.
What is the most appropriate immediate management for this pediatric patient?Your Answer: Finger sweep
Correct Answer: Back blows
Explanation:Resuscitation Council (UK) Recommendations for Choking Emergencies
When faced with a choking emergency, the Resuscitation Council (UK) recommends a specific course of action. If the patient is able to cough effectively, encourage them to do so. If not, but they are conscious, try five back blows followed by five abdominal thrusts (Heimlich manoeuvre) and repeat if necessary. However, if the patient becomes unconscious, begin CPR immediately. It is important to note that a finger sweep is no longer recommended as it can push the obstruction further into the airway. Additionally, high flow oxygen is necessary for breathing, but nasopharyngeal airways will not help in this situation. Removal with forceps is also not recommended as it can be hazardous. If the Heimlich manoeuvre fails, a cricothyroidotomy should be considered. While this procedure is recommended in the US and UK, it is not encouraged in some countries like Australia due to the risk of internal injury from over-vigorous use.
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This question is part of the following fields:
- Respiratory System
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Question 7
Incorrect
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An 80-year-old man with metastatic lung cancer arrives at the acute medical unit with sudden shortness of breath. A chest x-ray shows a malignant pleural effusion encasing the right lung. The medical registrar intends to perform a pleural tap to drain the effusion and send a sample to the lab. The registrar takes into account the effusion's position around the lung. What is the minimum level of the effusion in the mid-axillary line?
Your Answer: 12th rib
Correct Answer: 10th rib
Explanation:The parietal pleura can be found at the 10th rib in the mid-axillary line, while the visceral pleura is closely attached to the lung tissue and can be considered as one. The location of the parietal pleura is more inferior than that of the visceral pleura, with the former being at the 8th rib in the midclavicular line and the 10th rib in the midaxillary line. The location of the parietal pleura in the scapular line is not specified.
Anatomy of the Lungs
The lungs are a pair of organs located in the chest cavity that play a vital role in respiration. The right lung is composed of three lobes, while the left lung has two lobes. The apex of both lungs is approximately 4 cm superior to the sternocostal joint of the first rib. The base of the lungs is in contact with the diaphragm, while the costal surface corresponds to the cavity of the chest. The mediastinal surface contacts the mediastinal pleura and has the cardiac impression. The hilum is a triangular depression above and behind the concavity, where the structures that form the root of the lung enter and leave the viscus. The right main bronchus is shorter, wider, and more vertical than the left main bronchus. The inferior borders of both lungs are at the 6th rib in the mid clavicular line, 8th rib in the mid axillary line, and 10th rib posteriorly. The pleura runs two ribs lower than the corresponding lung level. The bronchopulmonary segments of the lungs are divided into ten segments, each with a specific function.
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This question is part of the following fields:
- Respiratory System
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Question 8
Incorrect
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A 55-year-old Caucasian man presents to the ENT clinic with complaints of gradual hearing loss over the past year. He reports having to turn up the volume on his television to the maximum to hear it comfortably. There are no associated symptoms such as tinnitus or dizziness, and the patient has no significant medical history.
Upon examination, a Weber and Rinne test reveal conductive hearing loss in the left ear. Otoscope examination shows no signs of middle ear effusion or tympanic membrane involvement in either ear. A pure tone audiometry confirms conductive hearing loss in the left ear, with a Carhart's notch present.
The physician diagnoses the patient with otosclerosis and discusses treatment options.
What is the underlying pathology of otosclerosis?Your Answer: Endolymphatic hydrops
Correct Answer: Replacement of normal bone by vascular spongy bone
Explanation:Otosclerosis is a condition where normal bone is replaced by spongy bone with a high vascularity. This leads to progressive conductive hearing loss, without any other neurological impairments. The replacement of the normal endochondral layer of the bony labyrinth by spongy bone affects the ability of the stapes to act as a piston, resulting in the conduction of sound from the middle ear to the inner ear being affected. Caucasians are most commonly affected by this condition.
Benign paroxysmal positional vertigo (BPPV) is caused by the dislodgement of otoliths into the semicircular canals. This condition results in vertiginous dizziness upon positional changes, but does not affect auditory function.
Meniere’s disease is caused by endolymphatic hydrops, which is the accumulation of fluid in the inner ear. The pathophysiology of this condition is not well understood, but it leads to vertigo, tinnitus, hearing loss, and aural fullness.
Cholesteatoma is caused by the accumulation of desquamated, stratified squamous epithelium. This leads to the formation of a mass that can gradually enlarge and erode the ossicle chain, resulting in conductive hearing loss.
Presbycusis is a type of sensorineural hearing loss that occurs as a result of aging. The degeneration of the organ of Corti is one of the underlying pathological mechanisms that causes this condition. This leads to the destruction of outer hair cells and a decrease in hearing sensitivity.
Understanding Otosclerosis: A Progressive Conductive Deafness
Otosclerosis is a medical condition that occurs when normal bone is replaced by vascular spongy bone. This condition leads to a progressive conductive deafness due to the fixation of the stapes at the oval window. It is an autosomal dominant condition that typically affects young adults, with onset usually occurring between the ages of 20-40 years.
The main features of otosclerosis include conductive deafness, tinnitus, a normal tympanic membrane, and a positive family history. In some cases, patients may also experience a flamingo tinge, which is caused by hyperemia and affects around 10% of patients.
Management of otosclerosis typically involves the use of a hearing aid or stapedectomy. A hearing aid can help to improve hearing, while a stapedectomy involves the surgical removal of the stapes bone and replacement with a prosthesis.
Overall, understanding otosclerosis is important for individuals who may be at risk of developing this condition. Early diagnosis and management can help to improve hearing and prevent further complications.
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This question is part of the following fields:
- Respiratory System
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Question 9
Incorrect
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A 67-year-old man has been diagnosed with stage III lung cancer and is concerned about potential complications. What are the risks he may face?
Your Answer: Pulmonary fibrosis
Correct Answer: Pneumothorax
Explanation:Pneumothorax is more likely to occur in individuals with lung cancer.
Pneumothorax: Characteristics and Risk Factors
Pneumothorax is a medical condition characterized by the presence of air in the pleural cavity, which is the space between the lungs and the chest wall. This condition can occur spontaneously or as a result of trauma or medical procedures. There are several risk factors associated with pneumothorax, including pre-existing lung diseases such as COPD, asthma, cystic fibrosis, lung cancer, and Pneumocystis pneumonia. Connective tissue diseases like Marfan’s syndrome and rheumatoid arthritis can also increase the risk of pneumothorax. Ventilation, including non-invasive ventilation, can also be a risk factor.
Symptoms of pneumothorax tend to come on suddenly and can include dyspnoea, chest pain (often pleuritic), sweating, tachypnoea, and tachycardia. In some cases, catamenial pneumothorax can be the cause of spontaneous pneumothoraces occurring in menstruating women. This type of pneumothorax is thought to be caused by endometriosis within the thorax. Early diagnosis and treatment of pneumothorax are crucial to prevent complications and improve outcomes.
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This question is part of the following fields:
- Respiratory System
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Question 10
Correct
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A middle-aged woman who is obese comes in with complaints of polyuria. She has a history of squamous cell lung carcinoma. What could be the possible reason for her polyuria?
Your Answer: Hyperparathyroidism
Explanation:Polyuria is caused by all the options listed above, except for syndrome of inappropriate ADH secretion. However, the patient’s age does not match the typical onset of type 1 diabetes, which usually occurs in young individuals. Furthermore, squamous cell lung carcinoma is commonly associated with a paraneoplastic syndrome that results in the release of excess parathyroid hormone by the tumor, leading to hypercalcemia and subsequent polyuria, along with other symptoms such as renal and biliary stones, bone pain, abdominal discomfort, nausea, vomiting, depression, and anxiety.
Lung cancer can present with paraneoplastic features, which are symptoms caused by the cancer but not directly related to the tumor itself. Small cell lung cancer can cause the secretion of ADH and, less commonly, ACTH, which can lead to hypertension, hyperglycemia, hypokalemia, alkalosis, and muscle weakness. Lambert-Eaton syndrome is also associated with small cell lung cancer. Squamous cell lung cancer can cause the secretion of parathyroid hormone-related protein, leading to hypercalcemia, as well as clubbing and hypertrophic pulmonary osteoarthropathy. Adenocarcinoma can cause gynecomastia and hypertrophic pulmonary osteoarthropathy. Hypertrophic pulmonary osteoarthropathy is a painful condition involving the proliferation of periosteum in the long bones. Although traditionally associated with squamous cell carcinoma, some studies suggest that adenocarcinoma is the most common cause.
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This question is part of the following fields:
- Respiratory System
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Question 11
Incorrect
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A 27-year-old man with a history of epilepsy is admitted to the hospital after experiencing a tonic-clonic seizure. He is currently taking sodium valproate as his only medication. A venous blood gas is obtained immediately.
What are the expected venous blood gas results for this patient?Your Answer: Normal pH, normal lactate, normal SaO2
Correct Answer: Low pH, high lactate, low SaO2
Explanation:Acidosis shifts the oxygen dissociation curve to the right, which enhances oxygen delivery to the tissues by causing more oxygen to dissociate from Hb. postictal lactic acidosis is a common occurrence in patients with tonic-clonic seizures, and it is typically managed by monitoring for spontaneous resolution. During a seizure, tissue hypoxia can cause lactic acidosis. Therefore, a venous blood gas test for this patient should show low pH, high lactate, and low SaO2.
If the venous blood gas test shows a high pH, normal lactate, and low SaO2, it would not be consistent with postictal lactic acidosis. This result indicates alkalosis, which can be caused by gastrointestinal losses, renal losses, or Cushing syndrome.
A high pH, normal lactate, and normal SaO2 would also be inconsistent with postictal lactic acidosis because tissue hypoxia would cause an increase in lactate levels.
Similarly, low pH, high lactate, and normal SaO2 would not be expected in postictal lactic acidosis because acidosis would shift the oxygen dissociation curve to the right, decreasing the oxygen saturation of haemoglobin.
Finally, normal pH, normal lactate, and normal SaO2 are unlikely to be found in this patient shortly after a seizure. However, if the venous blood gas test was taken days after the seizure following an uncomplicated clinical course, these findings would be more plausible.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 12
Incorrect
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A 12-year-old girl is referred to a respiratory specialist due to persistent episodes of shortness of breath. She also suffers from severe hay fever and eczema. After undergoing a peak expiratory flow test, signs of outflow obstruction of her lungs are detected. The doctor prescribes beclomethasone and salbutamol for her and advises her mother to keep her away from dust, as asthma is often linked to hypersensitivity to dust. Which type of hypersensitivity is associated with asthma?
Your Answer: Type 2 hypersensitivity
Correct Answer: Type 1 hypersensitivity
Explanation:Asthma is linked to type 1 hypersensitivity, which is caused by the binding of IgE to Mast cells, resulting in an inflammatory reaction. Other types of hypersensitivity include type 2, which involves the binding of IgG or IgM to cell surface antigens, type 3, which is immune complex-mediated, and type 4, which is T-cell mediated.
Asthma is a common respiratory disorder that affects both children and adults. It is characterized by chronic inflammation of the airways, resulting in reversible bronchospasm and airway obstruction. While asthma can develop at any age, it typically presents in childhood and may improve or resolve with age. However, it can also persist into adulthood and cause significant morbidity, with around 1,000 deaths per year in the UK.
Several risk factors can increase the likelihood of developing asthma, including a personal or family history of atopy, antenatal factors such as maternal smoking or viral infections, low birth weight, not being breastfed, exposure to allergens and air pollution, and the hygiene hypothesis. Patients with asthma may also suffer from other atopic conditions such as eczema and hay fever, and some may be sensitive to aspirin. Occupational asthma is also a concern for those exposed to allergens in the workplace.
Symptoms of asthma include coughing, dyspnea, wheezing, and chest tightness, with coughing often worse at night. Signs may include expiratory wheezing on auscultation and reduced peak expiratory flow rate. Diagnosis is typically made through spirometry, which measures the volume and speed of air during exhalation and inhalation.
Management of asthma typically involves the use of inhalers to deliver drug therapy directly to the airways. Short-acting beta-agonists such as salbutamol are the first-line treatment for relieving symptoms, while inhaled corticosteroids like beclometasone dipropionate and fluticasone propionate are used for daily maintenance therapy. Long-acting beta-agonists like salmeterol and leukotriene receptor antagonists like montelukast may also be used in combination with other medications. Maintenance and reliever therapy (MART) is a newer approach that combines ICS and a fast-acting LABA in a single inhaler for both daily maintenance and symptom relief. Recent guidelines recommend offering a leukotriene receptor antagonist instead of a LABA for patients on SABA + ICS whose asthma is not well controlled, and considering MART for those with poorly controlled asthma.
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This question is part of the following fields:
- Respiratory System
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Question 13
Incorrect
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Which one of the following does not decrease the functional residual capacity?
Your Answer:
Correct Answer: Upright position
Explanation:When a patient is in an upright position, the functional residual capacity (FRC) can increase due to less pressure from the diaphragm and abdominal organs on the lung bases. This increase in FRC can also be caused by emphysema and asthma. On the other hand, factors such as abdominal swelling, pulmonary edema, reduced muscle tone of the diaphragm, and aging can lead to a decrease in FRC. Additionally, laparoscopic surgery, obesity, and muscle relaxants can also contribute to a reduction in FRC.
Understanding Lung Volumes in Respiratory Physiology
In respiratory physiology, lung volumes can be measured to determine the amount of air that moves in and out of the lungs during breathing. The diagram above shows the different lung volumes that can be measured.
Tidal volume (TV) refers to the amount of air that is inspired or expired with each breath at rest. In males, the TV is 500ml while in females, it is 350ml.
Inspiratory reserve volume (IRV) is the maximum volume of air that can be inspired at the end of a normal tidal inspiration. The inspiratory capacity is the sum of TV and IRV. On the other hand, expiratory reserve volume (ERV) is the maximum volume of air that can be expired at the end of a normal tidal expiration.
Residual volume (RV) is the volume of air that remains in the lungs after maximal expiration. It increases with age and can be calculated by subtracting ERV from FRC. Speaking of FRC, it is the volume in the lungs at the end-expiratory position and is equal to the sum of ERV and RV.
Vital capacity (VC) is the maximum volume of air that can be expired after a maximal inspiration. It decreases with age and can be calculated by adding inspiratory capacity and ERV. Lastly, total lung capacity (TLC) is the sum of vital capacity and residual volume.
Physiological dead space (VD) is calculated by multiplying tidal volume by the difference between arterial carbon dioxide pressure (PaCO2) and end-tidal carbon dioxide pressure (PeCO2) and then dividing the result by PaCO2.
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This question is part of the following fields:
- Respiratory System
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Question 14
Incorrect
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A 49-year-old patient presents to the rheumatology clinic with weight loss, fever, and night sweats. The individual is also experiencing shortness of breath. The following blood test results are obtained:
- Hemoglobin (Hb): 140 g/l
- Platelets: 192 * 109/l
- White cell count (WCC): 5.3 * 109/l
- Creatinine: 154 umol/l
- Urea: 9 mmol/l
- cANCA positive
The white cell differential count is reported as normal. What is the most likely diagnosis?Your Answer:
Correct Answer: Granulomatosis with polyangiitis
Explanation:The most likely diagnosis for this patient is granulomatosis with polyangiitis, as indicated by the presence of cANCA and the involvement of multiple organs including the lungs, skin, kidneys, and upper respiratory tract. This condition is known to cause inflammation in the glomeruli, leading to renal impairment. Churg-Strauss disease and Alport’s syndrome are unlikely due to normal eosinophil levels and cANCA positivity, respectively. Goodpasture’s syndrome is also unlikely as the patient does not present with haematuria or haemoptysis.
Granulomatosis with Polyangiitis: An Autoimmune Condition
Granulomatosis with polyangiitis, previously known as Wegener’s granulomatosis, is an autoimmune condition that affects the upper and lower respiratory tract as well as the kidneys. It is characterized by a necrotizing granulomatous vasculitis. The condition presents with various symptoms such as epistaxis, sinusitis, nasal crusting, dyspnoea, haemoptysis, and rapidly progressive glomerulonephritis. Other symptoms include a saddle-shape nose deformity, vasculitic rash, eye involvement, and cranial nerve lesions.
To diagnose granulomatosis with polyangiitis, doctors perform various investigations such as cANCA and pANCA tests, chest x-rays, and renal biopsies. The cANCA test is positive in more than 90% of cases, while the pANCA test is positive in 25% of cases. Chest x-rays show a wide variety of presentations, including cavitating lesions. Renal biopsies reveal epithelial crescents in Bowman’s capsule.
The management of granulomatosis with polyangiitis involves the use of steroids, cyclophosphamide, and plasma exchange. Cyclophosphamide has a 90% response rate. The median survival rate for patients with this condition is 8-9 years.
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This question is part of the following fields:
- Respiratory System
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Question 15
Incorrect
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Sophie, a 4-year-old patient with Down's syndrome, is brought to the general practitioner by her father. He is worried as Sophie has been crying more than usual and has started holding her right ear. She is diagnosed with acute bacterial otitis media.
What is the most probable bacteria responsible for this infection?Your Answer:
Correct Answer: Haemophilus influenzae
Explanation:Haemophilus influenzae is a frequent culprit behind bacterial otitis media, a common ear infection.
The majority of cases of acute bacterial otitis media are caused by Streptococcus pneumoniae, Haemophilus influenzae, or Moraxella.
Genital gonorrhoeae is caused by N. gonorrhoeae, a sexually transmitted infection that presents with discharge and painful urination.
Meningococcal sepsis, a life-threatening condition, is caused by N. meningitides.
Staph. aureus is responsible for superficial skin infections like impetigo.
Syphilis, which typically manifests as a painless genital sore called a chancre, is caused by T. pallidum.
Acute otitis media is a common condition in young children, often caused by bacterial infections following viral upper respiratory tract infections. Symptoms include ear pain, fever, and hearing loss, and diagnosis is based on criteria such as the presence of a middle ear effusion and inflammation of the tympanic membrane. Antibiotics may be prescribed in certain cases, and complications can include perforation of the tympanic membrane, hearing loss, and more serious conditions such as meningitis and brain abscess.
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This question is part of the following fields:
- Respiratory System
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Question 16
Incorrect
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A 26-year-old male is brought to the emergency department by his mother. He is agitated, restless, and anxious.
Upon examination, dilated pupils are observed, and an ECG reveals sinus tachycardia.
The patient has a medical history of chronic asthma and is currently taking modified-release theophylline tablets.
According to his mother, he returned from a trip to Pakistan last night and has been taking antibiotics for bacterial gastroenteritis for the past four days. He has three days left on his antibiotic course.
What could be the cause of his current presentation?Your Answer:
Correct Answer: Ciprofloxacin
Explanation:Terbinafine is frequently prescribed for the treatment of fungal nail infections as an antifungal medication.
Theophylline and its Poisoning
Theophylline is a naturally occurring methylxanthine that is commonly used as a bronchodilator in the management of asthma and COPD. Its exact mechanism of action is still unknown, but it is believed to be a non-specific inhibitor of phosphodiesterase, resulting in an increase in cAMP. Other proposed mechanisms include antagonism of adenosine and prostaglandin inhibition.
However, theophylline poisoning can occur and is characterized by symptoms such as acidosis, hypokalemia, vomiting, tachycardia, arrhythmias, and seizures. In such cases, gastric lavage may be considered if the ingestion occurred less than an hour prior. Activated charcoal is also recommended, while whole-bowel irrigation can be performed if theophylline is in sustained-release form. Charcoal hemoperfusion is preferable to hemodialysis in managing theophylline poisoning.
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This question is part of the following fields:
- Respiratory System
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Question 17
Incorrect
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A 26-year-old man has been referred to ENT by his doctor as he has swallowed a small chicken bone that feels stuck in his throat. During laryngoscopy, a chicken bone is observed lodged in the piriform recess. Which of the following nerves is most likely to be affected by the chicken bone?
Your Answer:
Correct Answer: Internal laryngeal nerve
Explanation:When foreign objects get stuck in the piriform recess, particularly sharp items like bones from fish or chicken, they can harm the internal laryngeal nerve that lies beneath the mucous membrane in that area. Retrieving these objects also poses a risk of damaging the internal laryngeal nerve. However, the other nerves are not likely to be impacted.
Anatomy of the Larynx
The larynx is located in the front of the neck, between the third and sixth cervical vertebrae. It is made up of several cartilaginous segments, including the paired arytenoid, corniculate, and cuneiform cartilages, as well as the single thyroid, cricoid, and epiglottic cartilages. The cricoid cartilage forms a complete ring. The laryngeal cavity extends from the laryngeal inlet to the inferior border of the cricoid cartilage and is divided into three parts: the laryngeal vestibule, the laryngeal ventricle, and the infraglottic cavity.
The vocal folds, also known as the true vocal cords, control sound production. They consist of the vocal ligament and the vocalis muscle, which is the most medial part of the thyroarytenoid muscle. The glottis is composed of the vocal folds, processes, and rima glottidis, which is the narrowest potential site within the larynx.
The larynx is also home to several muscles, including the posterior cricoarytenoid, lateral cricoarytenoid, thyroarytenoid, transverse and oblique arytenoids, vocalis, and cricothyroid muscles. These muscles are responsible for various actions, such as abducting or adducting the vocal folds and relaxing or tensing the vocal ligament.
The larynx receives its arterial supply from the laryngeal arteries, which are branches of the superior and inferior thyroid arteries. Venous drainage is via the superior and inferior laryngeal veins. Lymphatic drainage varies depending on the location within the larynx, with the vocal cords having no lymphatic drainage and the supraglottic and subglottic parts draining into different lymph nodes.
Overall, understanding the anatomy of the larynx is important for proper diagnosis and treatment of various conditions affecting this structure.
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This question is part of the following fields:
- Respiratory System
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Question 18
Incorrect
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During a neck dissection, a nerve is observed to pass behind the medial aspect of the second rib. Which nerve from the list below is the most probable?
Your Answer:
Correct Answer: Phrenic nerve
Explanation:The crucial aspect to note is that the phrenic nerve travels behind the inner side of the first rib. Towards the top, it is situated on the exterior of scalenus anterior.
The Phrenic Nerve: Origin, Path, and Supplies
The phrenic nerve is a crucial nerve that originates from the cervical spinal nerves C3, C4, and C5. It supplies the diaphragm and provides sensation to the central diaphragm and pericardium. The nerve passes with the internal jugular vein across scalenus anterior and deep to the prevertebral fascia of the deep cervical fascia.
The right phrenic nerve runs anterior to the first part of the subclavian artery in the superior mediastinum and laterally to the superior vena cava. In the middle mediastinum, it is located to the right of the pericardium and passes over the right atrium to exit the diaphragm at T8. On the other hand, the left phrenic nerve passes lateral to the left subclavian artery, aortic arch, and left ventricle. It passes anterior to the root of the lung and pierces the diaphragm alone.
Understanding the origin, path, and supplies of the phrenic nerve is essential in diagnosing and treating conditions that affect the diaphragm and pericardium.
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This question is part of the following fields:
- Respiratory System
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Question 19
Incorrect
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A 72-year-old man is admitted to the hospital with symptoms of the flu, confusion, and vomiting. His finger prick glucose levels are within normal range. The physician suspects that the patient's living conditions, which include poor housing and lack of support at home, may have contributed to his symptoms.
What physiological response is expected in this patient?Your Answer:
Correct Answer: An increased affinity of haemoglobin for oxygen
Explanation:Methaemoglobin causes a leftward shift of the oxygen dissociation curve, indicating an increased affinity of haemoglobin for oxygen. This results in reduced offloading of oxygen into the tissues, leading to decreased oxygen delivery. It is important to understand the oxygen-dissociation curve and the effects of carbon monoxide poisoning, which causes increased oxygen binding to methaemoglobin. A rightward shift of the curve indicates increased oxygen delivery to the tissues, which is not the case in methaemoglobinemia.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 20
Incorrect
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A 55-year-old man comes to the hospital complaining of lethargy, headache, and shortness of breath. Upon examination, he is found to be cyanotic and hypoxic, and is admitted to the respiratory ward for oxygen therapy.
Following some initial tests, the consultant informs the patient that his hemoglobin has a high affinity for oxygen, resulting in reduced oxygen delivery to the tissues.
What is the probable reason for this alteration in the oxygen dissociation curve?Your Answer:
Correct Answer: Low 2,3-DPG
Explanation:The correct answer is low 2,3-DPG. The professor’s description refers to a left shift in the oxygen dissociation curve, which indicates that haemoglobin has a high affinity for oxygen and is less likely to release it to the tissues. Factors that cause a left shift include low temperature, high pH, low PCO2, and low 2,3-DPG. 2,3-DPG is a substance that helps release oxygen from haemoglobin, so low levels of it result in less oxygen being released, causing a left shift in the oxygen dissociation curve.
The answer high temperature is incorrect because it causes a right shift in the oxygen dissociation curve, promoting oxygen delivery to the tissues. Hypercapnoea also causes a right shift in the curve, promoting oxygen delivery. Hyperglycaemia has no effect on haemoglobin’s ability to release oxygen, so it is also incorrect.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 21
Incorrect
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A 7-year-old boy is brought to the clinic by his father, who is worried about his son's hearing. The father has noticed that his son frequently asks him to repeat himself and tends to turn up the volume on the TV. During Weber's test, the patient indicates that the sound is louder on the right side. What conclusion can be drawn from this finding?
Your Answer:
Correct Answer: Can not tell which side is affected.
Explanation:The Weber test alone cannot determine which side of the patient’s hearing is affected. The test involves placing a tuning fork on the forehead and asking the patient to report if the sound is symmetrical or louder on one side. If the sound is louder on the left side, it could indicate a conductive hearing loss on the left or a sensorineural hearing loss on the right. To obtain more information, the Weber test should be performed in conjunction with the Rinne test, which involves comparing air conduction and bone conduction.
Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness
Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.
Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.
The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.
Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.
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This question is part of the following fields:
- Respiratory System
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Question 22
Incorrect
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A 26-year-old man is brought to the emergency department after being rescued at sea following a sailing accident. He is currently unresponsive with a Glasgow Coma Score of 9 (E2 V3 M4).
His vital signs include a heart rate of 110 beats per minute, blood pressure of 110/76 mmHg, oxygen saturation of 93%, and temperature of 34.8 ºC. An ECG is unremarkable and venous blood indicates type 2 respiratory failure. The patient's oxygen dissociation curve shows a leftward shift.
What is the cause of the leftward shift in this 26-year-old patient's oxygen dissociation curve?Your Answer:
Correct Answer: Hypothermia
Explanation:The only answer that causes a leftward shift in the oxygen dissociation curve is hypothermia. When tissues undergo aerobic respiration, they generate heat, which changes the shape of the haemoglobin molecule and reduces its affinity for oxygen. This results in the release of oxygen at respiring tissues. In contrast, lower temperatures in the lungs cause a leftward shift in the oxygen dissociation curve, which increases the binding of oxygen to haemoglobin.
Hypercapnia is not the correct answer because it causes a rightward shift in the oxygen dissociation curve. Hypercapnia lowers blood pH, which changes the shape of haemoglobin and reduces its affinity for oxygen.
Hypoxaemia is not the correct answer because the partial pressure of oxygen does not affect the oxygen dissociation curve. The partial pressure of oxygen does not change the affinity of haemoglobin for oxygen.
Increased concentration of 2,3-diphosphoglycerate (2,3-DPG) is not the correct answer because higher concentrations of 2,3-DPG reduce haemoglobin’s affinity for oxygen, causing a right shift in the oxygen dissociation curve.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 23
Incorrect
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A 38-year-old woman visits her GP with a solitary, painless tumour in her left cheek. Upon further examination, she is diagnosed with pleomorphic adenoma. What is the recommended management for this condition?
Your Answer:
Correct Answer: Surgical resection
Explanation:Surgical resection is the preferred treatment for pleomorphic adenoma, a benign tumor of the parotid gland that may undergo malignant transformation. Chemotherapy and radiotherapy are not effective in managing this condition. Additionally, salivary stone removal is not relevant to the treatment of pleomorphic adenoma.
Understanding Pleomorphic Adenoma
Pleomorphic adenoma, also known as a benign mixed tumour, is a non-cancerous growth that commonly affects the parotid gland. This type of tumour usually develops in individuals aged 40 to 60 years old. The condition is characterized by the proliferation of epithelial and myoepithelial cells of the ducts, as well as an increase in stromal components. The tumour is slow-growing, lobular, and not well encapsulated.
The clinical features of pleomorphic adenoma include a gradual onset of painless unilateral swelling of the parotid gland. The swelling is typically movable on examination rather than fixed. The management of pleomorphic adenoma involves surgical excision. The prognosis is generally good, with a recurrence rate of 1-5% with appropriate excision (parotidectomy). However, recurrence may occur due to capsular disruption during surgery. If left untreated, pleomorphic adenoma may undergo malignant transformation, occurring in 2-10% of adenomas observed for long periods. Carcinoma ex-pleomorphic adenoma is the most common type of malignant transformation, occurring most frequently as adenocarcinoma.
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This question is part of the following fields:
- Respiratory System
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Question 24
Incorrect
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An 80-year-old man visits the GP clinic for a routine hearing examination. He reports a decline in hearing ability in his left ear for the past few months. After conducting Rinne and Weber tests, you determine that he has conductive hearing loss in the left ear. Upon otoscopy, you observe cerumen impaction.
What are the test findings for this patient?Your Answer:
Correct Answer: Rinne: bone conduction > air conduction in right ear; Weber: lateralising to right ear
Explanation:Rinne’s and Weber’s Test for Differentiating Conductive and Sensorineural Deafness
Rinne’s and Weber’s tests are used to differentiate between conductive and sensorineural deafness. Rinne’s test involves placing a tuning fork over the mastoid process until the sound is no longer heard, then repositioning it just over the external acoustic meatus. A positive test indicates that air conduction (AC) is better than bone conduction (BC), while a negative test indicates that BC is better than AC, suggesting conductive deafness.
Weber’s test involves placing a tuning fork in the middle of the forehead equidistant from the patient’s ears and asking the patient which side is loudest. In unilateral sensorineural deafness, sound is localized to the unaffected side, while in unilateral conductive deafness, sound is localized to the affected side.
The table below summarizes the interpretation of Rinne and Weber tests. A normal result indicates that AC is greater than BC bilaterally and the sound is midline. Conductive hearing loss is indicated by BC being greater than AC in the affected ear and AC being greater than BC in the unaffected ear, with the sound lateralizing to the affected ear. Sensorineural hearing loss is indicated by AC being greater than BC bilaterally, with the sound lateralizing to the unaffected ear.
Overall, Rinne’s and Weber’s tests are useful tools for differentiating between conductive and sensorineural deafness, allowing for appropriate management and treatment.
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This question is part of the following fields:
- Respiratory System
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Question 25
Incorrect
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A 67-year-old woman presents to the clinic with a gradual onset of dyspnea on exertion over the past 6 months. She has a medical history of severe COPD and is currently receiving long-term oxygen therapy. During the examination, you observe pitting edema up to the mid-thighs, an elevated JVP with a prominent V wave, a precordial heave, and a loud P2. What is the most probable mechanism involved in this diagnosis?
Your Answer:
Correct Answer: Pulmonary arteries vasoconstriction due to hypoxia
Explanation:Hypoxia causes vasoconstriction of pulmonary arteries, leading to a diagnosis of right heart failure secondary to hypoxic lung disease, also known as cor pulmonale.
The Effects of Hypoxia on Pulmonary Arteries
When the partial pressure of oxygen in the blood decreases, the pulmonary arteries undergo vasoconstriction. This means that the blood vessels narrow, allowing blood to be redirected to areas of the lung that are better aerated. This response is a natural mechanism that helps to improve the efficiency of gaseous exchange in the lungs. By diverting blood to areas with more oxygen, the body can ensure that the tissues receive the oxygen they need to function properly. Overall, hypoxia triggers a physiological response that helps to maintain homeostasis in the body.
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This question is part of the following fields:
- Respiratory System
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Question 26
Incorrect
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A 72-year-old woman is brought to the stroke unit with a suspected stroke. She has a medical history of hypertension, type II diabetes, and hypothyroidism. Additionally, she experienced a myocardial infarction 4 years ago. Upon arrival, the patient exhibited a positive FAST result and an irregular breathing pattern. An urgent brain CT scan was performed and is currently under review. What region of the brainstem is responsible for regulating the fundamental breathing rhythm?
Your Answer:
Correct Answer: Medulla oblongata
Explanation:The medullary rhythmicity area in the medullary oblongata controls the basic rhythm of breathing through its inspiratory and expiratory neurons. During quiet breathing, the inspiratory area is active for approximately 2 seconds, causing the diaphragm and external intercostals to contract, followed by a period of inactivity lasting around 3 seconds as the muscles relax and there is elastic recoil. Additional brainstem regions can be stimulated to regulate various aspects of breathing, such as extending inspiration in the apneustic area (refer to the table below).
The Control of Ventilation in the Human Body
The control of ventilation in the human body is a complex process that involves various components working together to regulate the respiratory rate and depth of respiration. The respiratory centres, chemoreceptors, lung receptors, and muscles all play a role in this process. The automatic, involuntary control of respiration occurs from the medulla, which is responsible for controlling the respiratory rate and depth of respiration.
The respiratory centres consist of the medullary respiratory centre, apneustic centre, and pneumotaxic centre. The medullary respiratory centre has two groups of neurons, the ventral group, which controls forced voluntary expiration, and the dorsal group, which controls inspiration. The apneustic centre, located in the lower pons, stimulates inspiration and activates and prolongs inhalation. The pneumotaxic centre, located in the upper pons, inhibits inspiration at a certain point and fine-tunes the respiratory rate.
Ventilatory variables, such as the levels of pCO2, are the most important factors in ventilation control, while levels of O2 are less important. Peripheral chemoreceptors, located in the bifurcation of carotid arteries and arch of the aorta, respond to changes in reduced pO2, increased H+, and increased pCO2 in arterial blood. Central chemoreceptors, located in the medulla, respond to increased H+ in brain interstitial fluid to increase ventilation. It is important to note that the central receptors are not influenced by O2 levels.
Lung receptors also play a role in the control of ventilation. Stretch receptors respond to lung stretching, causing a reduced respiratory rate, while irritant receptors respond to smoke, causing bronchospasm. J (juxtacapillary) receptors are also involved in the control of ventilation. Overall, the control of ventilation is a complex process that involves various components working together to regulate the respiratory rate and depth of respiration.
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This question is part of the following fields:
- Respiratory System
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Question 27
Incorrect
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A 38-year-old man has been admitted to the ICU through the ED with reduced consciousness and cyanosis. Despite an oxygen saturation of 94% in the ED, both peripheral and central cyanosis were present. Arterial blood gas monitoring revealed significant hypoxia, but no evidence of methaemoglobin. The suspected diagnosis is carbon monoxide poisoning, and the patient is intubated and ventilated to prevent further leftward shift of the oxygen dissociation curve. What factors can cause this shift in the oxygen dissociation curve?
Your Answer:
Correct Answer: Hypocapnia
Explanation:The oxygen dissociation curve can be shifted to the left by low pCO2, which increases haemoglobin’s affinity for oxygen and makes it less likely to release oxygen to the tissues. In contrast, acidosis, hypercapnia, and hyperthermia cause a right shift of the curve, making it easier for oxygen to be released to the tissues. Raised levels of 2,3-diphosphoglycerate also shift the curve to the right by inhibiting oxygen binding to haemoglobin.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 28
Incorrect
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Brenda is a 36-year-old woman who presents with tachypnoea. This occurred whilst she was seated. Her only medical history is asthma for which she takes salbutamol. On examination, her respiratory rate is 28 breaths/minute, heart rate 100bpm, Her chest is resonant on percussion and lung sounds are normal. Her chest X-ray is normal. You obtain her arterial blood gas sample results which show the following:
pH 7.55
PaCO2 4.2 kPa
PaO2 10 kPa
HCO3 24 mmol/l
What could have caused the acid-base imbalance in Brenda's case?Your Answer:
Correct Answer: Panic attack
Explanation:Although panic attacks can cause tachypnea and a decrease in partial pressure of carbon dioxide, the acid-base disturbance that would result from this situation is not included as one of the answer choices.
Respiratory Alkalosis: Causes and Examples
Respiratory alkalosis is a condition that occurs when the blood pH level rises above the normal range due to excessive breathing. This can be caused by various factors, including anxiety, pulmonary embolism, CNS disorders, altitude, and pregnancy. Salicylate poisoning can also lead to respiratory alkalosis, but it may also cause metabolic acidosis in the later stages. In this case, the respiratory centre is stimulated early, leading to respiratory alkalosis, while the direct acid effects of salicylates combined with acute renal failure may cause acidosis later on. It is important to identify the underlying cause of respiratory alkalosis to determine the appropriate treatment. Proper management can help prevent complications and improve the patient’s overall health.
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This question is part of the following fields:
- Respiratory System
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Question 29
Incorrect
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During a clinical trial examining oxygen consumption during exercise, participants aged 50 and above engage in high-intensity interval training exercises for 20 minutes while physiological measurements are recorded. What is the primary factor that is likely to restrict oxygen supply to tissues after the training session?
Your Answer:
Correct Answer: Low pCO2
Explanation:When the pCO2 is low, the oxygen dissociation curve shifts to the left, which increases the affinity of haemoglobin for oxygen. This can limit the amount of oxygen available to tissues. On the other hand, high levels of pCO2 (hypercarbia) shift the curve to the right, decreasing the affinity of haemoglobin for oxygen and increasing oxygen availability to tissues.
In acidosis, the concentration of 2,3-diphosphoglycerate (DPG) increases, which binds to deoxyhaemoglobin and shifts the oxygen dissociation curve to the right. This results in increased oxygen release from the blood into tissues.
Hyperthermia also shifts the oxygen dissociation curve to the right, while the performance-enhancing substance myo-inositol trispyrophosphate (ITPP) has a similar effect.
Understanding the Oxygen Dissociation Curve
The oxygen dissociation curve is a graphical representation of the relationship between the percentage of saturated haemoglobin and the partial pressure of oxygen in the blood. It is not influenced by the concentration of haemoglobin. The curve can shift to the left or right, indicating changes in oxygen delivery to tissues. When the curve shifts to the left, there is increased saturation of haemoglobin with oxygen, resulting in decreased oxygen delivery to tissues. Conversely, when the curve shifts to the right, there is reduced saturation of haemoglobin with oxygen, leading to enhanced oxygen delivery to tissues.
The L rule is a helpful mnemonic to remember the factors that cause a shift to the left, resulting in lower oxygen delivery. These factors include low levels of hydrogen ions (alkali), low partial pressure of carbon dioxide, low levels of 2,3-diphosphoglycerate, and low temperature. On the other hand, the mnemonic ‘CADET, face Right!’ can be used to remember the factors that cause a shift to the right, leading to raised oxygen delivery. These factors include carbon dioxide, acid, 2,3-diphosphoglycerate, exercise, and temperature.
Understanding the oxygen dissociation curve is crucial in assessing the oxygen-carrying capacity of the blood and the delivery of oxygen to tissues. By knowing the factors that can shift the curve to the left or right, healthcare professionals can make informed decisions in managing patients with respiratory and cardiovascular diseases.
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This question is part of the following fields:
- Respiratory System
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Question 30
Incorrect
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A 24-year-old man is being evaluated at the respiratory clinic for possible bronchiectasis. He has a history of recurrent chest infections since childhood and has difficulty maintaining a healthy weight. Despite using inhalers, he has not experienced any significant improvement. Genetic testing has been ordered to investigate the possibility of cystic fibrosis.
What is the typical role of the cystic fibrosis transmembrane conductance regulator?Your Answer:
Correct Answer: Chloride channel
Explanation:The chloride channel, specifically a cyclic-AMP regulated chloride channel, is the correct answer. Cystic fibrosis can be caused by various mutations, but they all affect the same gene, the cystic fibrosis transmembrane conductance regulator gene. This gene encodes a chloride channel that, when dysfunctional, results in increased viscosity of secretions and the development of cystic fibrosis.
Understanding Cystic Fibrosis
Cystic fibrosis is a genetic disorder that causes thickened secretions in the lungs and pancreas. It is an autosomal recessive condition that occurs due to a defect in the cystic fibrosis transmembrane conductance regulator gene (CFTR), which regulates a chloride channel. In the UK, 80% of CF cases are caused by delta F508 on chromosome 7, and the carrier rate is approximately 1 in 25.
CF patients are at risk of colonization by certain organisms, including Staphylococcus aureus, Pseudomonas aeruginosa, Burkholderia cepacia (previously known as Pseudomonas cepacia), and Aspergillus. These organisms can cause infections and exacerbate symptoms in CF patients. It is important for healthcare providers to monitor and manage these infections to prevent further complications.
Overall, understanding cystic fibrosis and its associated risks can help healthcare providers provide better care for patients with this condition.
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This question is part of the following fields:
- Respiratory System
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