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Question 1
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When there is the presence of distended and engorged veins in the umbilical area, which of the following portosystemic anastomoses has most likely occurred?
Your Answer: Para-umbilical veins and inferior epigastric vein
Explanation:Caput medusae is a condition that consists of collateral veins radiating from the umbilicus and results from recanalization of the umbilical vein.Under normal conditions, the portal venous blood traverses the liver and drains into the inferior vena cava of the systemic venous circulation by way of the hepatic veins. This is the direct route. However, other, smaller communications exist between the portal and systemic systems, and they become important when the direct route becomes blocked. These communications are as follows:At the lower third of the oesophagus, the oesophageal branches of the left gastric vein (portal tributary) anastomose with the oesophageal veins draining the middle third of the oesophagus into the azygos veins (systemic tributary).Halfway down the anal canal, the superior rectal veins (portal tributary) draining the upper half of the anal canal anastomosis with the middle and inferior rectal veins (systemic tributaries), which are tributaries of the internal iliac and internal pudendal veins, respectively.The paraumbilical veins connect the left branch of the portal vein with the superficial veins of the anterior abdominal wall (systemic tributaries). The paraumbilical veins travel in the falciform ligament and accompany the ligamentum teres.The veins of the ascending colon, descending colon, duodenum, pancreas, and liver (portal tributary) anastomose with the renal, lumbar, and phrenic veins (systemic tributaries).
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This question is part of the following fields:
- Abdomen And Pelvis
- Anatomy
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Question 2
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You review a 50-year-old man that is requesting the seasonal influenza vaccination.Which of the following single clinical risk groups is NOT eligible to receive the seasonal influenza vaccination? Select ONE answer only.
Your Answer: Patients over the age of 50
Explanation:Patients with hypertension are only eligible for the seasonal influenza vaccination if they have co-existent cardiac complications.The UK national policy is that the seasonal influenza vaccine should be offered to the following groups:All those aged 65 years and olderChildren aged 2 to 15 yearsResidents of nursing and residential homes for the elderly (and other long-stay facilities)Carers of persons whose welfare may be at risk if the carer falls illAll those aged 6 months or older in a clinical risk groupThe following table outlines the clinical risk groups that are considered eligible for the vaccine:CategoryExamples of eligible groupsRespiratory diseaseCOPDInterstitial lung diseaseCystic fibrosisAsthma (requiring oral or inhaled steroids)Heart diseaseCongenital heart diseaseChronic heart failureCoronary heart disease (requiring medication and/or follow-up)Hypertension with cardiac complicationsKidney diseaseChronic kidney diseaseNephrotic syndromeRenal transplant patientsLiver diseaseLiver cirrhosisChronic hepatitisBiliary atresiaNeurological diseaseCerebrovascular accidentTransient ischaemic attackEndocrine diseaseType 1 and 2 diabetesImmunosuppressionPatients undergoing chemotherapyPatients taking immunosuppressive drug therapy (including systemic steroids)Asplenia or splenic dysfunctionHIV infectionPregnancyAll pregnant women
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This question is part of the following fields:
- Microbiology
- Principles Of Microbiology
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Question 3
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Insulin binds to the insulin receptor (IR) on cell surfaces to exert its action. The IR is a very specific transmembrane receptor belonging to the tyrosine kinase receptor class.One of these also activates the IR:
Your Answer: IGF-I
Explanation:Insulin receptor (IR), in addition to being activated by insulin, is also activated by IGF-I and IGF-II.The IR is a dimer with two identical subunits spanning the cell membrane and are connected by a single disulphide bond. The two sub-units include: The alpha chain situated on the exterior of the cell membrane and the beta chain spanning the cell membrane in a single segment. When insulin is detected, the alpha chains move together folding around the insulin making the beta chains move together, converting them into an active tyrosine kinase. This initiates a phosphorylation cascade increasing the expression of GLUT4 and allowing uptake of glucose by cells.
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This question is part of the following fields:
- Endocrine Physiology
- Physiology
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Question 4
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A dermatological examination on a patient presenting with a lump shows a solid, well circumscribed, lump measuring 0.8 cm in diameter.Which one of these best describes the lump you have found on examination?
Your Answer: Nodule
Explanation:A nodule is a solid, well circumscribed, raised area that lies in or under the skin and measures greater than 0.5 cm in diameter. They are usually painless.A vesicle is a visible collection of fluid measuring less than 0.5 cm in diameter. A macule is a flat, well circumscribed area of discoloured skin less than 1 cm in diameter with no changes in the thickness or texture of the skin.A papule is a solid, well circumscribed, skin elevation measuring less than 0.5 cm in diameter.A plaque is a palpable skin lesion that is elevated and measures >1cm in diameter
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This question is part of the following fields:
- General Pathology
- Pathology
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Question 5
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Which of the following statements regarding the pituitary gland is CORRECT:
Your Answer: Cortisol inhibits release of adrenocorticotropic hormone (ACTH) from the anterior pituitary.
Explanation:Anterior pituitary hormones are released under the control of hypothalamic releasing or inhibiting hormones originating from small neurons with their cell bodies in the hypothalamus and released into the blood at the median eminence. These hypothalamic hormones are transported directly to the anterior pituitary via hypophyseal portal vessels. The anterior pituitary hormones (and the hormones released by their target organs) inhibit further release of hypothalamic and anterior pituitary hormones by negative feedback mechanisms e.g. cortisol inhibits the release of ACTH. Prolactin release from the anterior pituitary is inhibited by dopamine.The posterior pituitary is really a direct extension of the hypothalamus. Oxytocin and ADH are manufactured in the cell bodies of large neurons in the hypothalamus and are transported down the axons of these cells to their terminals on capillaries originating from the inferior hypophyseal artery within the posterior pituitary gland. ADH release is controlled by negative feedback mechanisms based on plasma osmolality and blood volume, oxytocin however is involved in positive feedback mechanisms.
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This question is part of the following fields:
- Endocrine
- Physiology
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Question 6
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Question 7
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What is the primary mode of action of Enoxaparin?
Your Answer: Inhibits factor Xa
Explanation:Heparin acts as an anticoagulant by enhancing the inhibition rate of clotting proteases by antithrombin III impairing normal haemostasis and inhibition of factor Xa. Low molecular weight heparins have a small effect on the activated partial thromboplastin time and strongly inhibit factor Xa. Enoxaparin is derived from porcine heparin that undergoes benzylation followed by alkaline depolymerization.
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This question is part of the following fields:
- Cardiovascular
- Pharmacology
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Question 8
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Which of the following describes the site of a Meckel's diverticulum:
Your Answer: Ileum
Explanation:Meckel’s lies on the antimesenteric surface of the middle-to-distal ileum, approximately 2 feet proximal to the ileocaecal junction. It appears as a blind-ended tubular outpouching of bowel, about 2 inches long, occurring in about 2% of the population, and may contain two types of ectopic tissue (gastric and pancreatic). The rich blood supply to the diverticulum is provided by the superior mesenteric artery.Proximal to the major duodenal papilla the duodenum is supplied by the gastroduodenal artery (branch of the coeliac trunk) and distal to the major duodenal papilla it is supplied by the inferior pancreaticoduodenal artery (branch of superior mesenteric artery). The arterial supply to the jejunoileum is from the superior mesenteric artery.
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This question is part of the following fields:
- Abdomen
- Anatomy
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Question 9
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Urine flow rate = 2 ml/minUrine concentration of creatinine = 18 mg/ml Plasma concentration of creatinine = 0.25 mg/ml What is the estimated glomerular filtration rate (eGFR)?
Your Answer: 144 ml/min
Explanation:GFR can be estimated by:GFR = UCr x V / PCrWhere:UCr = urine concentration of creatininePCr = plasma concentration of creatinineV = rate of urine flowIn this case GFR = (18 x 2) / 0.25 = 144 ml/minNote: Creatinine is used to estimate GFR because it is an organic base naturally produced by muscle breakdown, it is freely filtered at the glomerulus, it is not reabsorbed from the nephron, it is not produced by the kidney, it is not toxic, and it doesn’t alter GFR.
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This question is part of the following fields:
- Physiology
- Renal Physiology
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Question 10
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A 29-year-old woman with anaphylactic reaction to peanuts, had to use her EpiPen on the way to hospital. What percentage of patients with anaphylactic reaction suffer a biphasic response?.
Your Answer: 20%
Explanation:About 20% of patients that suffer an anaphylactic reaction suffer a biphasic response 4-6 hours after the initial response (sometimes up to 72 hours after).
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This question is part of the following fields:
- General Pathology
- Pathology
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Question 11
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A 57-year old man presented himself to the emergency room with persistent cough. During history taking, a record of his previous sputum sample was seen and the report stated that it tested positive for AFB (acid-fast bacilli). What is the most likely pathogen?
Your Answer: Mycobacterium tuberculosis
Explanation:M. tuberculosis is the causative agent of pulmonary tuberculosis (TB). The most commonly used diagnostic test for the diagnosis of pulmonary TB is the direct sputum smear microscopy (DSSM) wherein the presence of acid-fast bacilli (AFB) is tested. The most common method is the hot method or also known as Ziehl-Neelsen method. This is a staining method special for Mycobacteria species because they are known to be acid-fast which means that they are not easily decolorized by acid alcohol. Once the DSSM tests positive for acid-fast bacilli, this indicates possible infection with tuberculosis. The gold standard for diagnosis is still culture but Mycobacteria species are slow-growers that is why DSSM is considered the best diagnostic method. A positive AFB smear and correlation with symptoms is usually used by physicians to create a final diagnosis of pulmonary tuberculosis.
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This question is part of the following fields:
- Microbiology
- Pathogens
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Question 12
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A 50-year-old man presents with headaches, lethargy, hypertension, and electrolyte disturbance. A diagnosis of primary hyperaldosteronism is made.Which biochemical pictures would best support this diagnosis?
Your Answer: Hypokalaemic metabolic alkalosis
Explanation:When there are excessive levels of aldosterone outside of the renin-angiotensin axis, primary hyperaldosteronism occurs. High renin levels will lead to secondary hyperaldosteronism. The classical presentation of hyperaldosteronism when symptoms are present include:HypokalaemiaMetabolic alkalosisHypertensionNormal or slightly raised sodium levels
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This question is part of the following fields:
- Endocrine Physiology
- Physiology
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Question 13
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A 15-year-old male is admitted to a rehabilitation centre with a history of multiple strokes, myopathy and learning disabilities since childhood. He is under the care of a multidisciplinary team, and his genetic testing reports show the presence of a mitochondrial disorder. Which one of the following diseases does this patient most likely have?
Your Answer: MELAS
Explanation:Mitochondrial diseases are a group of disorders caused by dysfunctional mitochondria. Most cases are maternally inherited, as we inherit our mitochondrial DNA from our mothers only, although mutations in nuclear DNA cause some cases.Examples of Mitochondrial Diseases include:1. Mitochondrial encephalomyopathy, lactic acidosis and stroke-like episodes (MELAS)2. Mitochondrial epilepsy with ragged red fibres (MERRF)3. Leber’s hereditary optic neuropathy (LHON)4. Diabetes mellitus and deafness (DAD)5. Neuropathy, ataxia, retinitis pigmentosa, and ptosis (NARP)6. Leigh syndrome (subacute sclerosing encephalopathy). Red-green colour blindness and G6PD deficiency have an X-linked recessive pattern of inheritance. Tay-Sachs Disease and spinal muscular atrophy have an autosomal recessive pattern of inheritance.
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This question is part of the following fields:
- General Pathology
- Pathology
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Question 14
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Which of the following body location is the appropriate site to apply pressure when performing a carotid sinus massage?
Your Answer: Thyroid cartilage
Explanation:The common carotid artery runs through the neck and divides into internal and external carotid arteries on both sides near the upper thyroid cartilage. In emergency situations, carotid sinus massage is also used to diagnose or treat paroxysmal supraventricular tachycardia. During the procedure, to maximize access to the carotid artery, the patient is put in a supine position with the neck extended (i.e. elevating the chin away from the chest). The carotid sinus is normally positioned inferior to the angle of the jaw, near the arterial impulse, at the level of the thyroid cartilage. For 5 to 10 seconds, pressure is administered to one carotid sinus. Although pulsatile pressure applied in a vigorous circular motion may be more effective, continuous pressure is preferred since it is more reproducible. If the predicted reaction is not obtained, the operation is repeated on the opposite side after a one- to two-minute wait.
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This question is part of the following fields:
- Anatomy
- Head And Neck
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Question 15
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In the small intestine, there is a deep gap between each villus that leads to the crypt of Lieberkühn, a tubular intestinal gland.What is the primary function of these glands?
Your Answer: Production of an alkaline intestinal juice
Explanation:In the small intestine, there is a deep gap between each villus that leads to the crypt of Lieberkühn, a tubular intestinal gland. These glands create an alkaline intestinal juice that is a mixture of water and mucus with a pH of 7.4-7.8. Intestinal juice is released in a volume of 1-2 litres per day in response to distention of the small intestine or the irritating effects of chyme on the intestinal mucosa.
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This question is part of the following fields:
- Gastrointestinal Physiology
- Physiology
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Question 16
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A 77 year old lady presents to ED with her left leg shortened and externally rotated following slipping and falling on a wet bathroom floor. There is an intracapsular fracture of the neck of femur seen on imaging studies. She is at risk of avascular necrosis of the head of femur. This is caused by lack of blood supply from which of these arteries?
Your Answer: Medial circumflex artery
Explanation:The primary blood supply to the head of the femur is from branches of the medial femoral circumflex artery. The superior and inferior gluteal arteries supply the hip joint but not the head of femur.The lateral circumflex artery anastomoses with the medial femoral circumflex artery and assists in supplying the head of femur. The obturator artery is an important source of blood supply in children up to about 8 years. It gives rise to the artery of the head of femur which runs in the ligamentum teres and is insufficient to supply the head of femur in adults.
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This question is part of the following fields:
- Anatomy
- Lower Limb
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Question 17
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Which of the following could denote a diagnosis of acquired immunodeficiency syndrome (AIDS) in a patient infected with HIV:
Your Answer: CD4 count < 200 cells/uL
Explanation:A diagnosis of AIDS can be made in a patient infected with HIV if the patient has a CD4 count < 200 cells/uL, or an AIDS-defining illness. Antiretroviral treatment should be considered in patients with CD4 counts < 350 cells/uL. Oral candidiasis is not an AIDS defining illness – candidiasis of the bronchi, trachea or lungs or of the oesophagus is an AIDS defining illness. A positive p24 antigen test seen in early HIV infection and does not indicate the development of AIDS.
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This question is part of the following fields:
- Microbiology
- Pathogens
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Question 18
Correct
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C5 - C9 deficiency increases susceptibility to infection with which of the following:
Your Answer: Neisseria spp.
Explanation:If the complement sequence is completed, an active phospholipase (the membrane attack complex, MAC) is produced, which punches holes in the cell membrane and causes cell lysis. Because the MAC appears to be the sole means to destroy the Neisseria family of bacteria, C5 – C9 deficiency increases susceptibility to Neisseria infections.
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This question is part of the following fields:
- Immune Responses
- Pathology
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Question 19
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A 50-year-old man from Russia presents with a history of cough with blood-stained sputum, fever, night sweats, and weight loss. Suspecting tuberculosis, you begin investigations.All the following statements regarding tuberculosis (TB) are true EXCEPT?
Your Answer: Corticosteroid use is not a risk factor for developing TB
Explanation:Immunosuppressants like corticosteroids may be an important risk factor for developing tuberculosis. All of the other statements are true.
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This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
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Question 20
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When calculating the ventilation over perfusion ratio of a male patient, you should remember the ideal V/Q ratio for this patient to compare with his results. What is the approximate ventilation value for a healthy male patient?
Your Answer: 5 L/min
Explanation:The ventilation/perfusion ratio (V/Q ratio) is a ratio used to assess the efficiency and adequacy of the matching ventilation and perfusion. The ideal V/Q ratio is 1. In an average healthy male, the ventilation value is approximately 5 L/min and the perfusion value is approximately 5 L/min. Any mismatch between ventilation and perfusion will be evident in the V/Q ratio. If perfusion is normal but ventilation is reduced, the V/Q ratio will be less than 1, whereas if ventilation is normal but perfusion is reduced, the V/Q ratio will be greater than 1. If the alveoli were ventilated but not perfused at all, then the V/Q ratio would be infinity.
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This question is part of the following fields:
- Physiology
- Respiratory Physiology
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SESSION STATS - PERFORMANCE PER SPECIALTY
