00
Correct
00
Incorrect
00 : 00 : 00
Session Time
00 : 00
Average Question Time ( Mins)
  • Question 1 - A 65-year-old woman with type 2 diabetes mellitus is feeling more fatigued than...

    Correct

    • A 65-year-old woman with type 2 diabetes mellitus is feeling more fatigued than usual. She has not attended the previous three annual check-ups and her blood glucose control has been poor. She has not been compliant with his medications. Blood pressure is 170/90 mmHg. Urinalysis shows microalbuminuria. A blood test reveals her glomerular filtration rate (GFR) is 26mL/min. If a renal biopsy was to be performed in this patient, what would be the expected findings?

      Your Answer: Nodular glomerulosclerosis and hyaline arteriosclerosis

      Explanation:

      This patient has a poorly controlled T2DM with an underlying diabetic nephropathy. The histological findings are Kimmelstiel-Wilson lesions (nodular glomerulosclerosis) and hyaline arteriosclerosis. This is due to nonenzymatic glycosylation.

      Diabetic nephropathy is the chronic loss of kidney function occurring in those with diabetes mellitus. Protein loss in the urine due to damage to the glomeruli may become massive, and cause a low serum albumin with resulting generalized body swelling (edema) and result in the nephrotic syndrome. Likewise, the estimated glomerular filtration rate (eGFR) may progressively fall from a normal of over 90 ml/min/1.73m2 to less than 15, at which point the patient is said to have end-stage kidney disease (ESKD). It usually is slowly progressive over years.

    • This question is part of the following fields:

      • Clinical Sciences
      53.5
      Seconds
  • Question 2 - A 67-year-old man presents with anaemia and weight loss. Upon endoscopy, a gastric...

    Incorrect

    • A 67-year-old man presents with anaemia and weight loss. Upon endoscopy, a gastric tumour is revealed, later established as an adenocarcinoma. The patient refuses any treatment and claims that his condition is not influencing the quality of his life. Clinical examination has nothing particularly interesting to show and the patient seems to be conscious of his decision, regardless of the likely curative nature of surgery. What is the single most appropriate management?

      Your Answer: Ask to speak to his wife alone to find out why he is refusing surgery

      Correct Answer: Respect his wishes and book a follow-up appointment for four weeks

      Explanation:

      The patient seems to be conscious about his decision, which should be respected. According to Mental Capacity Act 2005, a person who makes an unwise decision should not be treated as unable to make a decision.

    • This question is part of the following fields:

      • Clinical Sciences
      61.7
      Seconds
  • Question 3 - A study is carried out to assess the efficacy of a new anti-epileptic...

    Correct

    • A study is carried out to assess the efficacy of a new anti-epileptic drug for children with absence seizures. The total number of the children selected for the study was 400, from which 150 children were assigned to take the new drug and 250 children were assigned in the control group. After a period of four months, only 15 children taking the new drug had a seizure compared to 100 children from the control group who had seizure. What is the correct value regarding the relative risk reduction?

      Your Answer: 75%

      Explanation:

      Relative risk reduction (RRR) tells you by how much the treatment reduced the risk of bad outcomes relative to the control group who did not have the treatment. In the previous example, the relative risk reduction of fever and rash in the group of the children on the intervention was 40 per cent (1 – 0.6 = 0.4 or 40 per cent). RRR = (EER -CER) / CER = (0.1 – 0.4) / 0.4 = -0.75 or 75% reduction.

    • This question is part of the following fields:

      • Clinical Sciences
      44.7
      Seconds
  • Question 4 - A 45-year-old woman with a history of hypothyroidism, presents with ptosis and muscle...

    Incorrect

    • A 45-year-old woman with a history of hypothyroidism, presents with ptosis and muscle weakness. She's noticed that her muscle weakness becomes worse towards the end of the day. Clinical examination reveals fatigable ptosis and proximal limb weakness. Myasthenia gravis is suspected. Which receptor is implicated in the pathophysiology of this condition?

      Your Answer:

      Correct Answer: Nicotinic acetylcholine receptors

      Explanation:

      Myasthenia gravis (MG) is an organ-specific autoimmune disease caused by an antibody-mediated assault on the muscle nicotinic acetylcholine receptor (AChR) at the neuromuscular junction. Binding of antibodies to the AChR leads to loss of functional AChRs and impairs the neuromuscular signal transmission, resulting in muscular weakness.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 5 - What is northern blotting used for? ...

    Incorrect

    • What is northern blotting used for?

      Your Answer:

      Correct Answer: Detect RNA

      Explanation:

      Northern blotting’s purpose is to measure the size and amount of RNA transcribed from a specific gene of interest.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 6 - A 42-year-old patient has been admitted with a very swollen and painful right...

    Incorrect

    • A 42-year-old patient has been admitted with a very swollen and painful right knee. He was unable to walk on it so came into hospital. It is currently being treated as gout with non steroidal anti-inflammatory drugs. You notice he is of short stature, has shortened arms and legs and a flat nasal bridge. A mutation in which gene is responsible for this condition?

      Your Answer:

      Correct Answer: Fibroblast growth factor receptor

      Explanation:

      Achondroplasia is a common cause of dwarfism. It is caused by a mutation in fibroblast growth factor receptor 3 (FGFR3). In normal development FGFR3 has a negative regulatory effect on bone growth. In achondroplasia, the mutated form of the receptor is constitutively active and this leads to severely shortened bones. The effect is genetically dominant, with one mutant copy of the FGFR3 gene being sufficient to cause achondroplasia, while two copies of the mutant gene are invariably fatal. A person with achondroplasia thus has a 50% chance of passing dwarfism to each of their offspring. People with achondroplasia can be born to parents that do not have the condition due to spontaneous mutation. It occurs as a sporadic mutation in approximately 80% of cases (associated with advanced paternal age) or it may be inherited as an autosomal dominant genetic disorder.
      People with achondroplasia have short stature, with an average adult height of 131 centimeters (52 inches) for males and 123 centimeters (48 inches) for females.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 7 - A study is done on 1000 patients to assess the specificity of a...

    Incorrect

    • A study is done on 1000 patients to assess the specificity of a new rapid finger-prick blood test developed to help diagnose deep vein thrombosis (DVT). The new test was positive on 200 patients with DVT and on 100 patients without DVT. It was also negative on 20 patients with DVT and 680 without DVT. What is the specificity of the new test?

      Your Answer:

      Correct Answer: 680/780

      Explanation:

      Specificity (negative in health)
      The ability of a test to correctly classify an individual as disease- free is called the test′s specificity. [Table 2]

      Specificity = d / b+d

      = d (true negative) / b+d (true negative + false positive)

      = Probability of being test negative when disease absent.

      Example: One hundred persons with normal angles (diagnosed by ′gold standard′: gonioscopy) are examined by peripheral angle chamber depth examination. Eighty-five persons had normal peripheral angle chamber depth [Table 3]. The specificity of the peripheral angle chamber depth examination to PACG is therefore –

      85 / 100 = 85%.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 8 - Which one of the following statements regarding nitric oxide is incorrect? ...

    Incorrect

    • Which one of the following statements regarding nitric oxide is incorrect?

      Your Answer:

      Correct Answer: Promotes platelet aggregation

      Explanation:

      Nitric oxide, known as an endothelium-derived relaxing factor (EDRF), is biosynthesized endogenously from L-arginine, oxygen, and NADPH by various nitric oxide synthase (NOS) enzymes and is a signaling molecule in many physiological and pathological processes in humans.
      One of the main enzymatic targets of nitric oxide is guanylyl cyclase. The binding of nitric oxide to the haem region of the enzyme leads to activation, in the presence of iron.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 9 - Choose the correct statement regarding leptin: ...

    Incorrect

    • Choose the correct statement regarding leptin:

      Your Answer:

      Correct Answer: Is produced mainly by the hypothalamus

      Explanation:

      Leptin, a 167–amino acid hormone, was discovered in 1994 and is secreted mainly by adipocytes. Plasma leptin levels are significantly correlated with body mass index (BMI) and the total amount of body fat.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 10 - A 52-year-old man presents with numbness and tingling in his left hand. On...

    Incorrect

    • A 52-year-old man presents with numbness and tingling in his left hand. On examination he has weakness of elbow extension, metacarpophalangeal joint flexion and extension and distal interphalangeal joint flexion. All other movements and reflexes are normal. Sensation is normal apart from reduced pin-prick sensation over the medial aspect of the hand. An MRI scan of the cervical spine is performed due to suspicion of a nerve lesion. Which of the following pathologies is most likely to be found on the scan based on the clinical findings?

      Your Answer:

      Correct Answer: Disc herniation between C7 and T1

      Explanation:

      The C8 nerve forms part of the radial and ulnar nerves via the brachial plexus, and therefore has motor and sensory function in the upper limb. It originates from the spinal column from below the cervical vertebra 7 (C7).
      The C8 nerve receives sensory afferents from the C8 dermatome. This consists of all the skin on the little finger, and continuing up slightly past the wrist on the palmar and dorsal aspects of the hand and forearm.
      The other options available correspond to the C6 or C7 roots and these are unaffected as evidenced by normal elbow flexion and thumb sensation (C6) and normal sensation over the middle finger (C7). Elbow extension is weak as it has roots from both C7 and C8 and so cannot be used alone to decide between the two levels clinically.
      The C8 nerve contributes to the motor innervation of many of the muscles in the trunk and upper limb. Its primary function is the flexion of the fingers, and this is used as the clinical test for C8 integrity, in conjunction with the finger jerk reflex.

      Trunk:
      – Pectoralis major – Medial and lateral pectoral nerves (C5, C6, C7, C8, T1)
      – Pectoralis minor – Medial pectoral nerve (C5, C6, C7,C8, T1)
      – Latissimus dorsi – Thoracodorsal nerve (C6, C7, C8)
      Upper arm:
      – Triceps brachii – Radial nerve (C6, C7,C8)
      Forearm
      – Flexor carpi ulnaris – Ulnar nerve (C7, C8, T1)
      – Palmaris longus – Median nerve (C7,C8)
      – Flexor digitorum superficialis – Median nerve (C8, T1)
      – Flexor digitorum profundus – Median and Ulnar nerves (C8, T1)
      – Flexor pollicis longus – Median nerve (C7,C8)
      – Pronator quadratus – Median nerve (C7,C8)
      – Extensor carpi radialis brevis – Deep branch of the radial nerve (C7,C8)
      – Extensor digitorum – Posterior interosseous nerve (C7,C8)
      – Extensor digiti minimi – Posterior interosseous nerve (C7,C8)
      – Extensor carpi ulnaris – Posterior interosseous nerve (C7,C8)
      – Anconeus – Radial nerve (C6, C7,C8)
      – Abductor pollicis longus – Posterior interosseous nerve (C7,C8)
      – Extensor pollicis brevis – Posterior interosseous nerve (C7,C8)
      – Extensor pollicis longus – Posterior interosseous nerve (C7,C8)
      – Extensor indicis – Posterior interosseous nerve (C7,C8)
      Hand
      – Palmaris brevis – Superficial branch of ulnar nerve (C8, T1)
      – Dorsal interossei – Deep branch of ulnar nerve (C8, T1)
      – Palmar interossei – Deep branch of ulnar nerve (C8, T1)
      – Adductor pollicis – Deep branch of ulnar nerve (C8, T1)
      – Lumbricals – Deep branch of ulnar, Digital branches of median nerve
      – Opponens pollicis – Recurrent branch of median nerve (C8, T1)
      – Abductor pollicis brevis – Recurrent branch of median nerve (C8, T1)
      – Flexor pollicis brevis – Recurrent branch of median nerve (C8, T1)
      – Opponens digiti minimi – Deep branch of ulnar nerve (C8, T1)
      – Abductor digiti minimi – Deep branch of ulnar nerve (C8, T1)
      – Flexor digiti minimi brevis – Deep branch of ulnar nerve (C8, T1)

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 11 - Choose the correct statement regarding hyponatremia: ...

    Incorrect

    • Choose the correct statement regarding hyponatremia:

      Your Answer:

      Correct Answer: Hyperlipidaemia may cause pseudohyponatraemia

      Explanation:

      The Hyperlipidaemia Effect: Pseudohyponatremia in Pancreatic Cancer; Patients who have disorders of cholestasis commonly present with volume depletion due to vomiting and poor oral intake, which, in turn, often leads to hypovolemic hyponatremia. It is less well known that disorders of cholestasis, including tumours of the hepatobiliary system, can be accompanied by hyperlipidaemia.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 12 - Choose the correct statement regarding standard polymerase chain reaction: ...

    Incorrect

    • Choose the correct statement regarding standard polymerase chain reaction:

      Your Answer:

      Correct Answer: A thermostable DNA polymerase is required

      Explanation:

      In the PCR, DNA amplification is performed by thermostable enzymes; invariably either family A DNA polymerases from thermophilic and hyperthermophilic Bacteria or family B DNA polymerases from hyperthermophilic Archaea. Family Y DNA polymerase from the hyperthermophilic archaeon Sulfolobus solfataricus, Sso-polY, is also an enzyme marketed for PCR, but with specialist applications. Each thermostable DNA polymerases has different characteristics and to achieve optimal results, the choice of a PCR enzyme depends on the application itself.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 13 - Choose the molecule that acts as the co-receptor for cells expressing antigens linked...

    Incorrect

    • Choose the molecule that acts as the co-receptor for cells expressing antigens linked with MHC class I molecules:

      Your Answer:

      Correct Answer: CD8

      Explanation:

      CD8+ T cells recognize antigens in the form of short peptide fragments bound to major histocompatibility complex class I (MHCI) molecules on the target cell surface.1 Specific engagement of peptide-MHCI (pMHCI) complexes via the clonotypically expressed αβ T-cell receptor (TCR) triggers a range of effector functions that play a critical role in protective immunity against intracellular infections and various malignancies.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 14 - A clinical trial is conducted to study the benefits of a new oral...

    Incorrect

    • A clinical trial is conducted to study the benefits of a new oral medication to improve the symptoms of patients with asthma. In the trial 400 patients with asthma, half were given the new medication and half a placebo. Three months later they are asked to rate their symptoms using the following scale: much improved, slight improvement, no change, slight worsening, significantly worse. What is the most appropriate statistical test to see whether the new medication is beneficial?

      Your Answer:

      Correct Answer: Mann-Whitney U test

      Explanation:

      The type of significance test used depends on whether the data is parametric (can be measured, usually normally distributed) or non-parametric.
      Parametric tests:
      Student’s t-test – paired or unpaired*
      Pearson’s product-moment coefficient – correlation

      Non-parametric tests:
      Mann-Whitney U test – unpaired data
      Wilcoxon signed-rank test – compares two sets of observations on a single sample
      chi-squared test – used to compare proportions or percentages
      Spearman, Kendall rank – correlation.

      The outcome measured is not normally distributed, i.e. it is non-parametric. This excludes the Student’s t-tests. We are not comparing percentages/proportions so the chi-squared test is excluded. The Mann–Whitney U test is a nonparametric test of the null hypothesis that it is equally likely that a randomly selected value from one sample will be less than or greater than a randomly selected value from a second sample.
      This test can be used to investigate whether two independent samples were selected from populations having the same distribution.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 15 - A 2-day-old girl is admitted by her mother because she gets cyanotic upon...

    Incorrect

    • A 2-day-old girl is admitted by her mother because she gets cyanotic upon feeding and she wouldn't stop crying. The doctors suspect a congenital heart disease. What is the most probable aetiology?

      Your Answer:

      Correct Answer: Transposition of the great arteries

      Explanation:

      Transposition of the great arteries results in a significant hypoxemic status that is observed clinically by central cyanosis. The bluish discoloration of the skin and mucous membranes is therefore the basic pattern of clinical presentation in transposition. Its onset and severity depend on anatomical and functional variants that influence the degree of mixing between the two circulations. Limited intercirculatory mixing, usually present if the ventricular septum is intact or the atrial septal defect is restrictive, is related to progressive and profound central cyanosis evident within the first hours of life. Tachypnoea, tachycardia, diaphoresis, poor weight gain, a gallop rhythm, and eventually hepatomegaly can be then detected later on during infancy. Heart murmurs associated with left outflow tract obstruction, due to a persistent arterial duct or a septal defect may be heard, but they are not a constant finding.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 16 - Intracellular proteins tagged with ubiquitination are destined to which of the following organelles?...

    Incorrect

    • Intracellular proteins tagged with ubiquitination are destined to which of the following organelles?

      Your Answer:

      Correct Answer: Proteasome

      Explanation:

      Delivery of ubiquitinated substrates to the proteasome.
      Ubiquitinated proteins are delivered to the proteasome by various routes and the complete picture of how these pathways fit together has yet to emerge, reviewed in. Some substrates bind directly to the proteasome by interacting with the 19S regulatory particle subunits Rpn1028 or Rpn1329, and probably Rpt530. Alternatively, ubiquitinated substrates can be brought to the proteasome by adaptors that bind both the proteasome and the ubiquitin chain on the substrate to deliver it for degradation.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 17 - Choose the correct statement regarding p53 gene: ...

    Incorrect

    • Choose the correct statement regarding p53 gene:

      Your Answer:

      Correct Answer: Li-Fraumeni syndrome predisposes to the development of sarcomas

      Explanation:

      Li-Fraumeni syndrome (LFS) is a cancer predisposition syndrome associated with the development of the following classic tumours: soft tissue sarcoma, osteosarcoma, pre-menopausal breast cancer, brain tumours, adrenocortical carcinoma (ACC), and leukaemia. LFS is diagnosed in individuals meeting established clinical criteria or in those who have a germline pathogenic variant in TP53 regardless of family cancer history.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 18 - Choose the correct statement regarding relative risk: ...

    Incorrect

    • Choose the correct statement regarding relative risk:

      Your Answer:

      Correct Answer: It is the usual outcome measure of cohort studies

      Explanation:

      Relative Risk = (Probability of event in exposed group) / (Probability of event in not exposed group). The relative risk is mistaken by some, with the odds ratio and absolute risk. Relative risk is the ratio of the probability of an event occurring with an exposure versus the probability of the event occurring without the exposure. Thus to calculate the relative risk, we must know the exposure status of all individuals (either exposed or not exposed). This implies that relative risk is only appropriate for cases where the exposure status and incidence of disease can be accurately determined such as prospective cohort studies.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 19 - A 33-year-old woman has missed her last two periods and has been lactating....

    Incorrect

    • A 33-year-old woman has missed her last two periods and has been lactating. Upon anamnesis, she claims she's lost weight and she's been suffering from vaginal dryness. The endocrinologist suggests that she checks her prolactin levels. Which of the following inhibits prolactin release from the hypophysis?

      Your Answer:

      Correct Answer: Dopamine

      Explanation:

      Dopamine (DA) holds a predominant role in the regulation of prolactin (PRL) secretion. Through a direct effect on anterior pituitary lactotrophs, DA inhibits the basally high-secretory tone of the cell. It accomplishes this by binding to D2 receptors expressed on the cell membrane of the lactotroph, activation of which results in a reduction of PRL exocytosis and gene expression by a variety of intracellular signalling mechanisms.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 20 - Which one of the following occurs during reverse transcriptase polymerase chain reaction? ...

    Incorrect

    • Which one of the following occurs during reverse transcriptase polymerase chain reaction?

      Your Answer:

      Correct Answer: RNA is converted to DNA

      Explanation:

      Reverse transcription polymerase chain reaction is a laboratory technique combining reverse transcription of RNA into DNA and amplification of specific DNA targets using polymerase chain reaction. It is primarily used to measure the amount of a specific RNA. The main advantage of PCR is its sensitivity: only one strand of sample DNA is needed to detect a particular DNA sequence. It now has many uses including prenatal diagnosis, detection of mutated oncogenes and diagnosis of infections.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 21 - Choose the cell organelle involved in the synthesis of lipids: ...

    Incorrect

    • Choose the cell organelle involved in the synthesis of lipids:

      Your Answer:

      Correct Answer: Smooth endoplasmic reticulum

      Explanation:

      The Smooth endoplasmic reticulum (ER) is the major site at which membrane lipids are synthesized in eukaryotic cells. Because they are extremely hydrophobic, lipids are synthesized in association with already existing cellular membranes rather than in the aqueous environment of the cytosol. Although some lipids are synthesized in association with other membranes, most are synthesized in the ER. They are then transported from the ER to their ultimate destinations either in vesicles or by carrier proteins.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 22 - Which one of the following statements regarding the normal distribution is correct? ...

    Incorrect

    • Which one of the following statements regarding the normal distribution is correct?

      Your Answer:

      Correct Answer: Mean = mode = median

      Explanation:

      Normal distribution, also known as the Gaussian distribution, is a probability distribution that is symmetric about the mean. The normal distribution has the following properties:
      – It is symmetric around the mode, the median and the mean of the distribution.
      – It is unimodal
      – The area under the curve and over the x-axis is unity (i.e. equal to one).
      – Its density has two inflection points.
      – Its density is log-concave.
      The standard deviation (SD) is a measure of how much dispersion exists from the mean. SD = square root (variance)

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 23 - A 23-year-old male patient with a downward dislocation of the lens in his...

    Incorrect

    • A 23-year-old male patient with a downward dislocation of the lens in his right eye is experiencing visual problems. The ophthalmologist notes a constellation of symptoms resembling those of Marfan Syndrome. The patient's history reveals learning disabilities and a diagnosis of homocystinuria is suspected. What is the pathophysiology of homocystinuria?

      Your Answer:

      Correct Answer: Deficiency of cystathionine beta synthase

      Explanation:

      Inherited metabolic disorders are often characterized by the lack of an essential enzyme and are currently treated by dietary restriction and other strategies to replace the substrates or products of the missing enzyme. Patients with homocystinuria lack the enzyme cystathionine β-synthase (CBS), and many of these individuals do not respond to current treatment protocols.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 24 - Choose the best source of folic acid: ...

    Incorrect

    • Choose the best source of folic acid:

      Your Answer:

      Correct Answer: Liver

      Explanation:

      Beef liver is one of the best sources of folic acid, amongst others like green vegetables and nuts.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 25 - Which one of the following statements best describes a type II statistical error?...

    Incorrect

    • Which one of the following statements best describes a type II statistical error?

      Your Answer:

      Correct Answer: The null hypothesis is accepted when it is false

      Explanation:

      In statistical hypothesis testing there are 2 types of errors:
      – type I: the null hypothesis is rejected when it is true – i.e. Showing a difference between two groups when it doesn’t exist, a false positive.
      – type II: the null hypothesis is accepted when it is false – i.e. Failing to spot a difference when one really exists, a false negative.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 26 - A 19-year-old female is admitted with a headache, photophobia, fever and confusion. She...

    Incorrect

    • A 19-year-old female is admitted with a headache, photophobia, fever and confusion. She is managed with antibiotics. What is the mechanism of action of the most commonly used first line antibiotic class?

      Your Answer:

      Correct Answer: Inhibition of cell wall synthesis

      Explanation:

      In adults, the most common symptom of meningitis is a severe headache, occurring in almost 90% of cases of bacterial meningitis, followed by nuchal rigidity (the inability to flex the neck forward passively due to increased neck muscle tone and stiffness). Other signs commonly associated with meningitis include photophobia (intolerance to bright light) and phonophobia (intolerance to loud noises).
      In the United Kingdom empirical treatment consists of a third-generation cefalosporin such as cefotaxime or ceftriaxone. In the USA, where resistance to cefalosporins is increasingly found in streptococci, addition of vancomycin to the initial treatment is recommended. Penicillins, cephalosporins, carbapenems and monobactams all act via inhibition of cell wall synthesis.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 27 - What is the correct formula to calculate the positive predictive value? (TP =...

    Incorrect

    • What is the correct formula to calculate the positive predictive value? (TP = true positive; FP = false positive; TN = true negative; FN = false negative)

      Your Answer:

      Correct Answer: TP / (TP + FP)

      Explanation:

      Positive predictive value is the probability that subjects with a positive screening test truly have the disease.

      Positive predictive value = true positive / ( true positive + false positive)

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 28 - Which of the following is not a tumour suppressor gene? ...

    Incorrect

    • Which of the following is not a tumour suppressor gene?

      Your Answer:

      Correct Answer: myc

      Explanation:

      Myc is a family of regulator genes and proto-oncogenes that code for transcription factors.

      A tumor suppressor gene, or antioncogene, is a gene that protects a cell from one step on the path to cancer. When this gene mutates to cause a loss or reduction in its function, the cell can progress to cancer, usually in combination with other genetic changes. Tumor suppressor genes can be grouped into categories including caretaker genes, gatekeeper genes, and landscaper genes; the classification schemes are continually evolving.
      Examples include:
      Gene Associated cancers
      p53 Common to many cancers, Li-Fraumeni syndrome
      APC Colorectal cancer
      BRCA1 Breast and ovarian cancer
      BRCA2 Breast and ovarian cancer
      NF1 Neurofibromatosis
      Rb Retinoblastoma
      WT1 Wilm’s tumour

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 29 - What kind of receptor is the nitric oxide receptor? ...

    Incorrect

    • What kind of receptor is the nitric oxide receptor?

      Your Answer:

      Correct Answer: Guanylate cyclase receptor

      Explanation:

      Soluble guanylyl cyclase (GC-1) is the primary receptor of nitric oxide (NO) in smooth muscle cells and maintains vascular function by inducing vasorelaxation in nearby blood vessels. GC-1 converts guanosine 5′-triphosphate (GTP) into cyclic guanosine 3′,5′-monophosphate (cGMP), which acts as a second messenger to improve blood flow.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 30 - Choose the wrong statement regarding hypocalcaemia: ...

    Incorrect

    • Choose the wrong statement regarding hypocalcaemia:

      Your Answer:

      Correct Answer: Chvostek's sign is more sensitive and specific than Trousseau's sign

      Explanation:

      Chvostek and Trousseau signs can be elicited in patients with hypocalcaemia. Chvostek sign is the twitching of the upper lip with tapping on the cheek 2 cm anterior to the earlobe, below the zygomatic process overlying the facial nerve. Trousseau sign (a more reliable sign present in 94% of hypokalaemic individuals and only 1% to 4% of healthy people) is the presence of carpopedal spasm observed following application of an inflated blood pressure cuff over systolic pressure for 3 minutes in hypokalaemic patients.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Clinical Sciences (2/3) 67%
Passmed