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  • Question 1 - A 42 year old lady has acute onset of painless weakness on her...

    Incorrect

    • A 42 year old lady has acute onset of painless weakness on her left side of the face with a drooping mouth and difficulty speaking. With no significant past medical history and after relevant investigations, you rule out stroke as a possible cause. The lady is suspected to have suffered Bell's palsy, an idiopathic paralysis of the facial nerve. What symptoms are you most likely to find on examination in a patient with Bell's palsy?

      Your Answer: Bilateral ptosis

      Correct Answer: Taste impairment of the anterior tongue

      Explanation:

      Bell’s palsy is facial muscle weakness or paralysis that arises from idiopathic damage to the facial nerve. It can occur at any age but is commonly associated with some conditions:
      1. pregnancy
      2. diabetes
      3. upper respiratory ailment
      4. GBS
      5. Toxins

      The common symptoms of Bell’s palsy are:
      1. Abnormal corneal reflex as the facial nerve controls the motor aspect of the corneal reflex.
      2. The loss of control of facial muscles and eyelids leads to decreased tear production.
      3. mild weakness to total paralysis on one side of the face, occurring within hours to days.
      4. Bell’s palsy is a lower motor neuron lesion that usually spares the forehead while the upper motor near lesions, like stroke, involves the entire face.
      5. The anterior two-thirds of the tongue is supplied by the chorda tympani branch of the facial nerve, thus resulting in loss of taste.
      6. Ptosis can be a feature of Bell’s palsy but Bell’s palsy would typically show unilateral symptoms rather than bilateral.

    • This question is part of the following fields:

      • Anatomy
      22.8
      Seconds
  • Question 2 - An 85-year old female is being investigated and treated for pancytopenia of unknown...

    Incorrect

    • An 85-year old female is being investigated and treated for pancytopenia of unknown origin. Her most recent blood test is shown below which shows that he has a low platelet count. Hb-102 g/l, WBC - 2.9* 109/l, Platelets - 7 * 109/l. Which of the following normally stimulates platelet production?

      Your Answer: Granulocyte-colony stimulating factor

      Correct Answer: Thrombopoietin

      Explanation:

      Interleukin-4 is a cytokine which acts to regulate the responses of B and T cells.

      Erythropoietin is responsible for the signal that initiated red blood cell production.

      Granulocyte-colony stimulating factor stimulates the bone marrow to produce granulocytes.

      Interleukin-5 is a cytokine that stimulates the proliferation and activation of eosinophils.

      Thrombopoietin is the primary signal responsible for megakaryocyte and thus platelet production.
      Platelets are also called thrombocytes. They, like red blood cells, are also derived from myeloid stem cells. The process involves a megakaryocyte developing from a common myeloid progenitor cell. A megakaryocyte is a large cell with a multilobulated nucleus, this grows to become massive where it will then break up to form platelets.

      Immune cells are generated from haematopoietic stem cells in bone marrow. They generate two main types of progenitors, myeloid and lymphoid progenitor cells, from which all immune cells are derived.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      2
      Seconds
  • Question 3 - One litre of water at 0°C and a pressure of 1 bar is...

    Incorrect

    • One litre of water at 0°C and a pressure of 1 bar is in a water-bath. A 1 kW element is used in heating it. Given that the specific heat capacity of water is 4181 J/(kg°C) or J/(kg K), how long will it take to raise the temperature of the water by 10°C?

      Your Answer: 7 minutes

      Correct Answer: 42 seconds

      Explanation:

      The amount of energy required to change the temperature of 1 kg of a substance by 1°C is its specific heat capacity.

      Energy required to increase the temperature of any object is given by the equation:

      E = m × c × θ

      Where:
      E = energy required to heat an object
      m = mass of object
      c = specific heat capacity of the substance
      θ = temperature change

      The specific heat capacity of water is 4181 J/(kg°C)

      Therefore the energy required to raise 1kg of water by 10°C is:

      1 kg × 4181 J/(kg°C) × 10°C = 41810 J

      A 1 kW or 1000 W heater would be expected to supply 1000 J/s.

      The approximate time it would take the 1 kW heater to raise the temperature of one Litre of water by 10°C is:

      41810/1000 = 41.8 seconds.

    • This question is part of the following fields:

      • Physiology
      74.8
      Seconds
  • Question 4 - Regarding aldosterone, one of the following is true. ...

    Incorrect

    • Regarding aldosterone, one of the following is true.

      Your Answer: Secretion decreases when sodium intake is reduced

      Correct Answer: Secretion is increased following haematemesis

      Explanation:

      Aldosterone is produced in the zona glomerulosa of the adrenal cortex and acts to increase sodium reabsorption via intracellular mineralocorticoid receptors in the distal tubules and collecting ducts of the nephron.

      Its release is stimulated by hypovolaemia, blood loss ,and low plasma sodium and is inhibited by hypertension and increased sodium. It is regulated by the renin-angiotensin system.

    • This question is part of the following fields:

      • Pathophysiology
      49.9
      Seconds
  • Question 5 - A doctor has recorded the number of times the patient did not attend...

    Incorrect

    • A doctor has recorded the number of times the patient did not attend (DNA) the clinic for a study over a 10 month period. Number of DNAs in 10 Months: 1st Month: 0, 2nd Month: 3, 3rd Month: 1, 4th Month: 45, 5th Month: 2, 6th Month: 0, 7th Month: 1, 8th Month: 4, 9th Month: 4, 10th Month: 2. Which among the following is the most apt way of summarizing mean value?

      Your Answer: Mean

      Correct Answer: Median

      Explanation:

      Variance and standard deviation indicate the dispersion of the plot from mean value and thus are not really helpful in summarizing the mean.

      Range is the difference between maximum and minimum value that is 45 in this case.

      The mean in this case is 6.2 due to the presence of an outlier 45. In the presence of outlier mean can be misleading as it is quite sensitive to skewness in data.

      Mode is the most frequent value. In this case mode has 4 values: 0,1,2,4.

      In case of skewedness, median is the most apt representative of the mean as it is not affected by outliers. In this case since the data set has even values i.e. 10. Median is the average of the 5th & 6th entry after arranging the data in ascending order like that in case of the question (0,0,1,1,2,2,3,4,4,45). This turns out to be 2.

    • This question is part of the following fields:

      • Statistical Methods
      1.4
      Seconds
  • Question 6 - One of the causes of increased pulse pressure is when the aorta becomes...

    Incorrect

    • One of the causes of increased pulse pressure is when the aorta becomes less compliant because of age-related changes. Another cause of increased pulse pressure is which of the following?

      Your Answer: Aortic stenosis

      Correct Answer: Increased stroke volume

      Explanation:

      Impaired ventricular relaxation reduces diastolic filling and therefore preload.

      Decreased blood volume decreases preload due to reduced venous return.

      Heart failure is characterized by reduced ejection fraction and therefore stroke volume.

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume
      Aortic stenosis would decrease stroke volume as end systolic volume would increase.
      This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      18.3
      Seconds
  • Question 7 - A patient under brachial plexus regional block complains of pain under the cuff...

    Incorrect

    • A patient under brachial plexus regional block complains of pain under the cuff after the torniquet is inflated. Which nerve was most probably 'missed' by the local anaesthetic?

      Your Answer:

      Correct Answer: Intercostobrachial nerve

      Explanation:

      The area described in the question is supplied by the intercostobrachial nerve, which provides sensory innervation to the portions of the axilla, tail of the breast, lateral chest wall and medial side of the arm.

      It is a common for it to be ‘missed’ during administration of local anaesthesia because of its very superficial anatomic course. It may be anesthetized by giving an analgesia from the upper border of the biceps at the anterior axillary fold, to the margin of the triceps by the axillary floor.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 8 - An intravenous infusion is started with a 500 mL bag of 0.18 percent...

    Incorrect

    • An intravenous infusion is started with a 500 mL bag of 0.18 percent N. saline and 4% dextrose. Which of the following best describes its make-up?

      Your Answer:

      Correct Answer: Osmolarity 284 mOsmol/L, sodium 15 mequivalents and glucose 20 g

      Explanation:

      30 mmol Na+ and 30 mmol Cl- are found in 1 litre of 0.18 percent N. saline with 4% dextrose. Percent (percent) refers to the number of grammes of a compound per 100 mL, so a litre of 4 percent dextrose solution contains 40 grammes.

      As a result, a 500 mL bag of 1/5th N. saline and 4% dextrose contains approximately 15 mequivalents of sodium and 20 g of glucose. It is hypotonic due to its osmolarity of 284.

      Because of the risk of hyponatraemia, it is no longer considered the crystalloid of choice for fluid maintenance in children.

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 9 - Which compound is secreted only from the adrenal medulla? ...

    Incorrect

    • Which compound is secreted only from the adrenal medulla?

      Your Answer:

      Correct Answer: Adrenaline

      Explanation:

      The adrenal medulla comprises chromaffin cells (pheochromocytes), which are functionally equivalent to postganglionic sympathetic neurons. They synthesize, store and release the catecholamines noradrenaline (norepinephrine) and adrenaline (epinephrine) into the venous sinusoids.
      The majority of the chromaffin cells synthesize adrenaline.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 10 - In the fetal circulation, the cerebral and coronary circulations are preferentially supplied by...

    Incorrect

    • In the fetal circulation, the cerebral and coronary circulations are preferentially supplied by oxygen-rich blood over other organs. This is possible because of which phenomenon?

      Your Answer:

      Correct Answer: Well oxygenated blood from the inferior vena cava is preferentially streamed across the patent foramen ovale

      Explanation:

      During fetal development, blood oxygenated by the placenta flows to the foetus through the umbilical vein, bypasses the fetal liver through the ductus venosus, and returns to the fetal heart through the inferior vena cava.

      Blood returning from the inferior vena cava then enters the right atrium and is preferentially shunted to the left atrium through the patent foramen ovale. Blood in the left atrium is then pumped from the left ventricle to the aorta. The oxygenated blood ejected through the ascending aorta is preferentially directed to the fetal coronary and cerebral circulations.

      Deoxygenated blood returns from the superior vena cava to the right atrium and ventricle to be pumped into the pulmonary artery. Fetal pulmonary vascular resistance (PVR), however, is higher than fetal systemic vascular resistance (SVR); this forces deoxygenated blood to mostly bypass the fetal lungs. This poorly oxygenated blood enters the aorta through the patent ductus arteriosus and mixes with the well-oxygenated blood in the descending aorta. The mixed blood in the descending aorta then returns to the placenta for oxygenation through the two umbilical arteries.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 11 - The half-empty cylinder weighs 4.44 kg. The tare weight of a nitrous oxide...

    Incorrect

    • The half-empty cylinder weighs 4.44 kg. The tare weight of a nitrous oxide cylinder is 4 kg. The molecular weight of nitrous oxide is 44gm. Based on the data, how many litres of nitrous oxide remains in the cylinder for use?

      Your Answer:

      Correct Answer: 224 litres

      Explanation:

      The Tare weight of a cylinder is the weight when it is empty. So,

      Weight of cylinder – tare weight = weight of remaining N2O (g).
      4.44 kg – 4 kg = 0.44 kg
      Here,
      0.44 kg of nitrous oxide remains in the cylinder

      Since the molecular weight of nitrous oxide is 44 g and one mole of an ideal gas will occupy a volume of 22.4 litres at STP
      Therefore amount left in the cylinder is several (gN2O/44) x 22.4 litres of N2O.

      (440/44) x 22.4 = 224 litres.

    • This question is part of the following fields:

      • Basic Physics
      0
      Seconds
  • Question 12 - Which of the following is true in the Kreb's cycle? ...

    Incorrect

    • Which of the following is true in the Kreb's cycle?

      Your Answer:

      Correct Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions to release stored energy through oxidation of acetyl coenzyme A (acetyl-CoA). Some of the products are carbon dioxide and hydrogen atoms.

      The sequence of reactions, known collectively as oxidative phosphorylation, only occurs in the mitochondria (not cytoplasm).

      The Krebs cycle can only take place when oxygen is present, though it does not require oxygen directly, because it relies on the by-products from the electron transport chain, which requires oxygen. It is therefore considered an aerobic process. It is the common pathway for the oxidation of carbohydrate, fat and some amino acids, required for the formation of adenosine triphosphate (ATP).

      Pyruvate enters the mitochondria and is converted into acetyl-CoA. Acetyl-CoA is then condensed with oxaloacetate, to form citrate which is a six carbon molecule. Citrate is subsequently converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only five carbon molecule in the cycle is Alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 13 - A laceration to the upper lateral margin of the popliteal fossa will pose...

    Incorrect

    • A laceration to the upper lateral margin of the popliteal fossa will pose the greatest risk of injury for which nerve?

      Your Answer:

      Correct Answer: Common peroneal nerve

      Explanation:

      The common peroneal (fibular) nerve descends obliquely along the lateral side of the popliteal fossa to the fibular head, medial to biceps femoris.

      The sural nerve exits at the fossa’s lower inferolateral aspect and is more at risk in short saphenous vein surgery.

      The tibial nerve lies more medially and is even less likely to be injured in this location.

      The boundaries of the popliteal fossa are:
      Superolateral – the biceps femoris tendon
      Superomedial – semimembranosus reinforced by semitendinosus
      Inferomedial and inferolateral – medial and lateral heads of gastrocnemius

      The contents of the Popliteal fossa are:

      1. The popliteal artery
      2. The popliteal vein
      3. The Tibial nerve and common Fibular nerve
      4. Posterior femoral cutaneous nerve: descends and pierces the roof
      5. Small saphenous vein
      6. popliteal lymph nodes
      7. fat.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 14 - Which of the following statements is true regarding vecuronium? ...

    Incorrect

    • Which of the following statements is true regarding vecuronium?

      Your Answer:

      Correct Answer: Has a similar structure to rocuronium

      Explanation:

      Vecuronium is used as a part of general anaesthesia to provide skeletal muscle relaxation during surgery or mechanical ventilation. It is a monoquaternary aminosteroid (not quaternary) non- depolarising neuromuscular blocking drug.

      It has a structure similar to both rocuronium and pancuronium. The only difference is the substitution of specific groups on the steroid structure.

      Vecuronium is not associated with the release of norepinephrine from sympathetic nerve endings. However, Pancuronium has norepinephrine releasing the property.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 15 - Which of the following is correct for gas pipeline pressure? ...

    Incorrect

    • Which of the following is correct for gas pipeline pressure?

      Your Answer:

      Correct Answer: 4 bar for oxygen

      Explanation:

      Pipeline gases (in the UK this includes: Oxygen, Nitrous oxide, Medical air, and Entonox) are supplied at 4 bar (or 400 kPa), and compressed air is supplied at 7 bar for power tools.

      Carbon dioxide and nitric oxide are usually only supplied in cylinders.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 16 - The biochemical assessment of malnutrition can be measured by the amount of plasma...

    Incorrect

    • The biochemical assessment of malnutrition can be measured by the amount of plasma proteins. In acute starvation, which of these plasma proteins is the most sensitive indicator?

      Your Answer:

      Correct Answer: Retinol binding globulin

      Explanation:

      The half life of Retinol binding protein (RBP) is 10-12 hours and therefore reflects more acute changes in protein metabolism than any of these proteins. Therefore it is not commonly used as a parameter for nutritional assessment.

      The half life of Transthyretin (thyroxine binding pre-albumin) is only one to two days and so levels are less sensitive and this protein is not an albumin precursor. 15 mg/dL represents early malnutrition and a need for nutritional support.

      Albumin levels have been frequently as a marker of nutrition but this is not a very sensitive marker. It’s half life more than 30 days and significant change takes some time to be noticed. Also, synthesis of albumin is decreased with the onset of the stress response after burns. Unrelated to nutritional status, the synthesis of acute phase proteins increases and that of albumin decreases.

      A more accurate indicator of protein stores is transferrin. It’s response to acute changes in protein status is much faster. The half life of serum transferrin is shorter (8-10 days) and there are smaller body stores than albumin. A low serum transferrin level is below 200 mg/dL and below 100 mg/dL is considered severe. Serum transferrin levels can also affect serum transferrin level.

      Fibronectin is used a nutritional marker but levels decrease after seven days of starvation. It is a glycoprotein which plays a role in enhancing the phagocytosis of foreign particles.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 17 - A 45-year-old woman complains of pain in her upper abdomen to her physician....

    Incorrect

    • A 45-year-old woman complains of pain in her upper abdomen to her physician. The pain comes intermittently in waves and gets worse after eating food. There are no associated complaints of fever or bowel problems. The pain intensity is 6/10, and paracetamol relieves it a little. There is suspicion that part of the biliary tree is blocked. Which area of the duodenum does this blocked tube open into?

      Your Answer:

      Correct Answer: 2nd part of the duodenum

      Explanation:

      The patient is likely suffering from biliary colic since her pain is intermittent and comes and goes in waves. Biliary colic pain gets worse after eating, especially fatty food as bile helps digest fats. Gallstones are the most common cause of biliary colic and are usually located in the cystic duct or common bile duct. But since this patient has no signs of jaundice or steatorrhea, the duct most likely blocked is the cystic duct.

      The cystic duct drains the gallbladder and combines with the common hepatic duct to form the common bile duct. The common bile duct then merges with the pancreatic duct and opens into the second part of the duodenum (major duodenal papilla).

      The duodenojejunal flexure is attached to the diaphragm by the ligament of Treitz and is not associated with any common pathology.
      The fourth part of the duodenum passes very close to the abdominal aorta and can be compressed by an abdominal aortic aneurysm.
      The third part of the duodenum can be affected by superior mesenteric artery syndrome, where the duodenum is compressed between the SMA and the aorta, often in cases of reduced body fat.
      The first part of the duodenum is the most common location for peptic ulcers affecting this organ.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 18 - A 79-year-old female complains of painful legs, especially in her thigh region. The...

    Incorrect

    • A 79-year-old female complains of painful legs, especially in her thigh region. The pain starts after walking and settles with rest. She occasionally has to take paracetamol to relieve the pain. She is a known case of hyperlipidaemia, type 2 diabetes mellitus, hypertension, and depression. Her physician makes a provisional diagnosis of claudication of the femoral artery, which is a continuation of the external iliac artery. Which of the following anatomical landmarks does the external iliac artery cross to become the femoral artery?

      Your Answer:

      Correct Answer: Inguinal ligament

      Explanation:

      The external iliac artery is the larger of the two branches of the common iliac artery. It forms the main blood supply to the lower limbs. The common iliac bifurcates into the internal and external iliac artery anterior to the sacroiliac joint.

      The external iliac artery courses on the medial border of the psoas major muscles and exits the pelvic girdle posterior to the inguinal ligament. Here, midway between the anterior superior iliac spine and the pubic symphysis, the external iliac artery becomes the femoral artery and descends along the anteromedial part of the thigh in the femoral triangle.

      The pectineus forms the posterior border of the femoral canal.
      The femoral vein forms the lateral border of the femoral canal.
      The medial border of the adductor longus muscle forms the medial wall of the femoral triangle.
      The medial border of the sartorius muscle forms the lateral wall of the femoral triangle.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 19 - An 80-year old female was taken to the emergency room for chest pain....

    Incorrect

    • An 80-year old female was taken to the emergency room for chest pain. She has a medical history of coronary artery disease and previous episodes of atrial fibrillation. She was immediately attached to the cardiac monitor, which showed tachycardia at 148 beats per minute. The 12-lead ECG revealed atrial fibrillation. Digoxin was given as an anti-arrhythmic at 500 micrograms, which is higher than the maintenance dose routinely given. Why is this so?

      Your Answer:

      Correct Answer: It has a high volume of distribution

      Explanation:

      When the loading dose of Digoxin is given, the primary thing to consider is the volume of distribution. The volume of distribution is the proportionality factor that relates the total amount of drug in the body to the concentration. LD is computed as:

      LD = Volume of distribution X (desired plasma concentration/bioavailability)

      Digoxin is an anti-arrhythmic drug with a large volume of distribution and high bioavailability, and only a small percentage of Digoxin is bound to plasma proteins (,20%).

      In the case, since the arrhythmia is not life-threatening, there is no need for the medication to work rapidly.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 20 - Calcium homeostasis is regulated by parathormone (PTH). Which of the following PTH actions...

    Incorrect

    • Calcium homeostasis is regulated by parathormone (PTH). Which of the following PTH actions is most likely to cause calcium to be released from bone?

      Your Answer:

      Correct Answer: Indirect stimulation of osteoclasts

      Explanation:

      The hormone parathyroid hormone (PTH) and the receptor parathyroid hormone type 1 (PTH1-Rc) are important regulators of blood calcium homeostasis.

      PTH can cause a rapid release of calcium from the matrix in bone, but it also affects long-term calcium metabolism by acting directly on bone-forming osteoblasts (by binding to PTH1-Rc) and indirectly on bone-resorbing osteoclasts.

      PTH causes changes in the synthesis and/or activity of several proteins, including osteoclast-differentiating factor, also known as TRANCE or RANKL, when it acts on osteoblasts.

      RANK receptors are found on the cell surfaces of osteoclast precursors. The osteoclasts are activated when RANKL binds to the RANK receptors. Osteoclasts lack PTH receptors, whereas osteoblasts do. Osteoclasts are activated indirectly when the RANK receptor binds to the RANKL secreted by osteoblasts, resulting in bone resorption. PTH1 receptors are found in osteoclasts, but they are few.

      PTH activates G-protein coupled receptors in all target cells via adenylate cyclase.

      The PTH2 receptor is most abundant in the nervous system and pancreas, but it is not a calcium metabolism regulator. It is abundant in the septum, midline thalamic nuclei, several hypothalamic nuclei, and the dorsal horn of the spinal cord, as well as the cerebral cortex and basal ganglia. Expression in pancreatic islet somatostatin cells is the most prominent on the periphery.

      The distribution of the receptor is being used to test functional hypotheses. It may play a role in pain modulation and hypothalamic releasing-factor secretion control.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 21 - A 4-year-old boy with status epilepticus was brought to ER and has already...

    Incorrect

    • A 4-year-old boy with status epilepticus was brought to ER and has already received two doses of intravenous lorazepam but is still continuing to have seizures. Which of the following drug would be best for his treatment?

      Your Answer:

      Correct Answer: Phenytoin 20 mg/kg IV

      Explanation:

      When the convulsion lasts for five or more than five minutes, or if there are recurrent episodes of convulsions in a 5 minute period without returning to the baseline, it is termed as Status Epilepticus.
      The first priority in the patient with seizures is maintaining the airway, breathing, and circulation.

      Guideline for the management of Status Epilepticus in children by Advanced Life Support Group is as follow:

      Step 1 (Five minutes after the start of seizures):

      If intravascular access is available start treatment with lorazepam 0.1 mg/kg IV
      If no intravascular access then give buccal midazolam 0.5 mg/kg or rectal diazepam 0.5 mg/kg.

      Step 2 (Ten minutes after the start of seizure):

      If the convulsions continue then a second dose of benzodiazepine should be given. Senior should be called on-site and phenytoin should be prepared.
      No more than two doses or benzodiazepines should be given (including any doses given before arrival at the hospital)
      If still no IV access then obtain intraosseous access (IO).

      Step 3 (Ten minutes after step 2)

      Senior help along with anaesthetic/ICU help should be sought
      Phenytoin 20 mg/kg IV over 20 minutes
      If the seizure stops before the full dose of phenytoin is given then the infusion should be completed as this provides up to 24 hours of anticonvulsant effect
      In children already receiving phenytoin as treatment for epilepsy then an alternative is phenobarbitone 20 mg/kg IV over five minutes
      Once the phenytoin is started, senior staff may wish to give rectal paraldehyde 0.4 mg/kg although this is no longer included in the routine algorithm recommended by APLS.

      Step 4 (20 minutes after step 3)

      If 20 minutes after starting phenytoin the child remains in status epilepticus then rapid sequence induction of anaesthesia with thiopentone and a short acting paralysing agent is needed and the child transferred to paediatric intensive care.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 22 - A patient admitted to the hospital is on oxygen via a venturi mask....

    Incorrect

    • A patient admitted to the hospital is on oxygen via a venturi mask. The air entrainment ratio is 1:9 i.e. 1 litre of 100% oxygen from the source entrains 9 litres of air from the atmosphere). The flow rate of 100% oxygen is 6L/minute. Based on the given data which of the following value approximates the oxygen concentration delivered to the patient?

      Your Answer:

      Correct Answer: 28%

      Explanation:

      The formula for calculating air: oxygen entrainment ratio is given as :
      100% ˆ’ FiO2 = air/oxygen entrainment ratio
      Since FiO2 ˆ’ 21% and the entrainment ratio is already known. Substituting the values in the equation: x = FiO2.

      100 ˆ’ x = 9
      x ˆ’ 21
      100 ˆ’ x = 9(x ˆ’ 21)
      100 ˆ’ x = 9x ˆ’ 189
      10x = 289
      x = 289/10
      x = 28.9%.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 23 - A 2-year old male is admitted to the surgery ward for repair of...

    Incorrect

    • A 2-year old male is admitted to the surgery ward for repair of an inguinal hernia. He weighs 10 kg. To provide post-operative analgesia, levobupivacaine was administered into the epidural space. Given the information above, what is the most appropriate dose for the hernia repair?

      Your Answer:

      Correct Answer: 0.25% 7.5 ml

      Explanation:

      Caudal analgesia using bupivacaine is a widely employed technique for achieving both intraoperative and early postoperative pain relief. 0.5 ml/kg of 0.25% plain bupivacaine is favoured by many practitioners who employ this fixed scheme for procedures involving sacral dermatomes (circumcision, hypospadias repair) as well as lower thoracic dermatomes (orchidopexy). However, there are other dosing regimens for caudal blocks with variable analgesic success rates: These include 0.75 ml/kg, 1.0 ml/kg and 1.25 ml/kg.

      A study indicated that plain bupivacaine 0.25% at a dose of 0.75 ml/kg compared to a dose of 0.5 ml/kg when administered for herniotomies provided improved quality of caudal analgesia with a low side effects profile. There were consistently more patients with favourable objective pain scale (OPS) scores at all timelines, increased the time to the analgesic request with similar postoperative consumption of paracetamol in the group of patients who received 0.75 ml/kg of 0.25% bupivacaine.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 24 - In endurance athletes, which of the following physiological adaptations to exercise is the...

    Incorrect

    • In endurance athletes, which of the following physiological adaptations to exercise is the best predictor of performance?

      Your Answer:

      Correct Answer: Velocity of blood lactate accumulation

      Explanation:

      Multiple regression analysis revealed that velocity of lactate accumulation (VOBLA) accounted for 92 percent of the variation in marathon running velocity (VM), and VOBLA plus training volume prior to the marathon accounted for 96 percent of the variation. Percent ST muscle fibre distribution (r = 0.55-0.69) and capillary density (r = 052-0.63) were found to be positively correlated with all performance variables. As a result, marathon running performance was linked to VOBLA and the ability to run at a pace close to it during the race. The percent ST, capillary density, and training volume were all related to these properties.

      Another metabolic adaptation compared to normal people is the early selection of fat for oxidation by muscle, especially when glucose availability is limited during high-intensity exercise. This helps to delay the onset of muscle fatigue, but it does not prevent VOBLA.

      For a given level of exercise, training can also result in cardiovascular adaptation, such as increased heart size, increased contractility, and a slower heart rate. All of these factors contribute to an increase in maximal oxygen consumption (VO2 max), but genetic factors, despite intensive training, play a large role in an athlete’s performance.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 25 - Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis? ...

    Incorrect

    • Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis?

      Your Answer:

      Correct Answer: Corticosteroids

      Explanation:

      Insulin is the primary anabolic hormone that dominates regulation of metabolism during digestive phase. It promotes glucose uptake in skeletal myocytes and adipocytes, and other insulin-target cells. It promotes glycogenesis and inhibits gluconeogenesis.

      Glucagon is the primary counterregulatory hormone that increases blood glucose levels, primarily through its effects on liver glucose output.

      Similar to glucagon, growth hormone, catecholamines and corticosteroids are also counterregulatory factors released in response to decreased glucose concentrations. Growth hormone promotes glycogenolysis and inhibits gluconeogenesis; catecholamines stimulate glycogenolysis and gluconeogenesis; while corticosteroids stimulate glycogenesis and gluconeogenesis.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 26 - Which of the following is true about the patellar reflex? ...

    Incorrect

    • Which of the following is true about the patellar reflex?

      Your Answer:

      Correct Answer: Is abolished immediately after transection of the spinal cord at T6

      Explanation:

      The patellar (knee jerk) reflex is a monosynaptic stretch reflex arising from L2-L4 nerve roots. It occurs after a tap on the patellar tendon which causes the spindles of the quadriceps muscles to stretch.

      The afferent nerve pathway occurred through A gamma fibres.

      Wesphal’s sign refers to a reduction, or absence of the patellar reflex. It is often indicated of a neurological disease affecting the PNS.

      A transection of the spinal cord results in a degree of shock which causes all reflexes to be reduced or completely absent, and required a period of approximately 6 weeks to recover.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 27 - The passage of glucose into the brain is facilitated by which transport method?...

    Incorrect

    • The passage of glucose into the brain is facilitated by which transport method?

      Your Answer:

      Correct Answer: Facilitated diffusion

      Explanation:

      Glucose transport is a highly regulated process accomplished mostly by facilitated diffusion using carrier proteins to cross cell membranes.

      There are many transporters, but the most important are known as glucose transporters (GLUTs).

      Stresses in various form of acute and chronic forms affect the activity of glucose transporters.
      They are responsive to many types of metabolic stress, including hypoxia, injury, hypoglycaemia, numerous metabolic inhibitors, stress hormones, and other influences such as growth factors.

      Numerous signalling pathways appear to be involved in transporter regulation.

      New evidence suggests that stresses regulating GLUTs are not only acute biological stresses. In addition, chronic low-grade inflammation, and their associated chronic diseases also lead to altered glucose transport. These include obesity, type 2 diabetes, cardiovascular disease, and the growth and spread of many tumours that are affected by altered glucose transporters. Some of these glucose transport effects are compensatory, while others are pathogenic.

      Ultimately, deliberate manipulation of GLUTs could be used as treatment for some of these chronic diseases.

    • This question is part of the following fields:

      • Physiology
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  • Question 28 - During exercise, muscle blood flow can increase by 20 to 50 times. Which...

    Incorrect

    • During exercise, muscle blood flow can increase by 20 to 50 times. Which mechanism is the most important for increased blood flow?

      Your Answer:

      Correct Answer: Local autoregulation

      Explanation:

      Skeletal muscle blood flow is in the range of 1-4 ml/min per 100 g when at rest. Blood flow can reach 50-100 ml/min per 100 g during exercise. With maximal vasodilation, blood flow can increase 20 to 50 times.

      The adrenal medulla releases catecholamines and increases neural sympathetic activity during exercise. Normally, alpha-1 and alpha-2 would cause vasoconstriction in the muscle groups being used, but vasodilatory metabolites override these effects, resulting in a so-called functional sympathectomy. Local hypoxia and hypercarbia, nitric oxide, K+ ions, adenosine, and lactate are some of the stimuli that cause vasodilation.

      However, the splanchnic and cutaneous circulations, which supply inactive muscles, vasoconstrict.

      Sympathetic cholinergic innervation of skeletal muscle arteries is found in some species (such as cats and dogs, but not humans). Vasodilation is induced by stimulating smooth muscle beta-2 adrenoreceptors, but at rest, the alpha-adrenoreceptor effects of adrenaline and noradrenaline predominate. During exercise, the skeletal muscle pump promotes venous emptying, but it does not necessarily increase blood flow.

    • This question is part of the following fields:

      • Physiology
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  • Question 29 - Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the...

    Incorrect

    • Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the most appropriate to establish a platelet dysfunction or disorder?

      Your Answer:

      Correct Answer: Platelet count

      Explanation:

      Decreased platelet concentrations with eclampsia were described as early as 1922 by Stancke. The platelet count is routinely measured in women with any form of gestational hypertension. The frequency and intensity of thrombocytopenia vary and are dependent on the severity and duration of the preeclampsia syndrome and the frequency with which platelet counts are performed.

      Overt thrombocytopenia defined by a platelet count < 100,000/microliter - indicates severe disease. In general, the lower the platelet count, the higher the rates of maternal and fetal morbidity and mortality. In most cases, delivery is advisable because thrombocytopenia usually continues to worsen. After delivery, the platelet count may continue to decline for the first day or so. It then usually increases progressively to reach a normal level within 3-5 days. In some instances with HELLP syndrome, the platelet count continues to fall after delivery. If these do not reach a nadir until 48 to 72 hours, then preeclampsia syndrome may be incorrectly attributed to one of the thrombotic microangiopathies. The following are other severe features associated with preeclampsia: Proteinuria: >/= 300 mg/24 hours; or urine protein: creatinine ratio >/= 0.3; or dipstick 1+

      Renal insufficiency: serum creatinine > 1.1 mg/dL or doubling of creatinine in the absence of other renal disease

      Impaired liver function: two times elevated AST/ALT or unexplained right upper quadrant pain or epigastric pain unresponsive to medications

      Pulmonary oedema

      Cerebral or visual symptoms: headache, visual disturbances.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 30 - A 40-year old gentleman has palpitations and has gone to the emergency department....

    Incorrect

    • A 40-year old gentleman has palpitations and has gone to the emergency department. He is found to have monomorphic ventricular tachycardia. The resting potential of ventricular monocytes is maintained by which electrolyte?

      Your Answer:

      Correct Answer: Potassium

      Explanation:

      Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:

      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms.

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
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SESSION STATS - PERFORMANCE PER SPECIALTY

Physiology And Biochemistry (1/2) 50%
Anatomy (0/1) 0%
Physiology (0/1) 0%
Pathophysiology (0/1) 0%
Statistical Methods (0/1) 0%
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