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Question 1
Incorrect
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A 65-year-old man, presents to the emergency department. He explains that an hour ago, he experienced central chest pain, which moved down his left arm. On ECG, elevation in the ST-segment was noted in the anterior leads. He undergoes emergency percutaneous coronary intervention (PCI) which requires the cardiologist to access the heart via the femoral artery. Where is the surface marking for identifying the femoral artery?
Your Answer: Midway between the ASIS and the pubic tubercle
Correct Answer: Midway between the ASIS and the pubic symphysis
Explanation:The surface marking for locating the femoral artery is the mid-inguinal point, which is the halfway point between the anterior superior iliac spine (ASIS) and the pubic symphysis.
The other mentioned options are not specific for any landmark.
However, it is important to note the difference between the mid inguinal point and the midpoint of the inguinal ligament, which is travels from the ASIS to the pubic tubercle.
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This question is part of the following fields:
- Anatomy
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Question 2
Incorrect
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All the following statements are false regarding gabapentin except:
Your Answer: Is a potent hepatic enzyme inducer
Correct Answer: Requires dose adjustment in renal disease
Explanation:Therapy with gabapentin requires dose adjustment with renal diseases. However, plasma monitoring of the drug is not necessary.
Gabapentin is not a liver enzyme inducer unlike other anticonvulsants like phenytoin and phenobarbitone
Gabapentin has not been shown to be associated with visual disturbances.
Gabapentin is used for add-on therapy in partial or generalized seizures and used in the management of chronic pain conditions but is of no use in petit mal.
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This question is part of the following fields:
- Pharmacology
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Question 3
Incorrect
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Following a physical assault, a 28-year-old man is admitted to the emergency room. A golf club has struck him in the head. There is a large haematoma on the scalp, as well as a bleeding wound. In response to painful stimuli, he opens his eyes and makes deliberate movements. Because of inappropriate responses, a history is impossible to construct, but words can be discerned. Which of the options below best describes his current Glasgow Coma Scale (GCS)?
Your Answer: E2V4M4=10
Correct Answer: E2V3M5=10
Explanation:The Glasgow Coma Scale (GCS) has been used in outcome models as a measure of physiological derangement and as a tool for assessing head trauma.
Eye opening (E):
4 Spontaneously
3 Responds to voice
2 Responds to painful stimulus
1 No response.Best verbal response (V):
5 Orientated, converses normally
4 Confused, disoriented conversation, but able to answer basic questions
3 Inappropriate responses, words discernible
2 Incomprehensible speech
1 Makes no sounds.Best motor response (M):
6 Obeys commands for movement
5 Purposeful movement to painful stimulus
4 Withdraws from pain
3 Abnormal (spastic) flexor response to painful stimuli, decorticate posture
2 Extensor response to painful stimuli, decerebrate posture
1 No response.In this case, GCS = 2+3+5 = 10.
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This question is part of the following fields:
- Pathophysiology
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Question 4
Incorrect
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The cardiac muscle will primarily utilize which metabolic substrate to produce energy when at rest?
Your Answer: Glucose
Correct Answer: Fatty acids
Explanation:Approximately 70% of the heart’s ATP requirement is met by cardiac mitochondria through beta-oxidation of fatty acids at rest. The remaining 30% is supplied by glucose.
Amino acids and ketones, in the presence of ketoacidosis, may supply at most 10% of the ATP requirement. And, when in high levels, lactate may also contribute to the ATP requirement of the heart, particularly during moments of high muscular activity.
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This question is part of the following fields:
- Pathophysiology
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Question 5
Incorrect
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In an experimental study, a healthy subject was given one litre of 5% dextrose within a 15-minute period. Which of the following mechanisms is expected to affect the urine output?
Your Answer: Osmotic diuresis
Correct Answer: Inhibition of arginine vasopressin (AVP) secretion
Explanation:Changes in the osmolality of body fluids (changes as minor as 1% are sufficient) play the most important role in regulating AVP secretion. The receptors that monitor changes in osmolality of body fluids (termed osmoreceptors) are distinct from the cells that synthesize and secrete AVP, and are located in the organum vasculosum of the lamina terminalis (OVLT) of the hypothalamus. The osmoreceptors sense changes in body osmolality by either shrinking or swelling. When the effective osmolality of the plasma increases, the osmoreceptors send signals to the AVP synthesizing/secreting cells located in the supraoptic and paraventricular nuclei of the hypothalamus, and AVP synthesis and secretion are stimulated. Conversely, when the effective osmolality of the plasma is reduced, secretion is inhibited. Because AVP is rapidly degraded in the plasma, circulating levels can be reduced to zero within minutes after secretion is inhibited.
In this scenario, the osmolality of the plasma will decrease to an estimate of 2.5%, hence inhibition of AVP.
Stimulation of atrial stretch receptors is incorrect because the increase in plasma volume is still below the threshold for its activation.
Osmotic diuresis is incorrect because 5% dextrose is isotonic, hence osmotic diuresis is not probable.
Renin is inhibited when an excess of NaCl in the tubular fluid is sensed by the macula densa.
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This question is part of the following fields:
- Physiology
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Question 6
Incorrect
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What is the name of the space between the vocal cords?
Your Answer: Vestibule
Correct Answer: Rima glottidis
Explanation:The rima glottidis is a narrow, triangle-shaped opening between the true vocal cords.
The vocal folds (true vocal cords) control sound production. The apex of each fold projects medially into the laryngeal cavity.
Each vocal fold includes these vocal ligaments:
Vocalis muscle (most medial part of thyroarytenoid muscle)
The glottis is composed of the vocal folds, processes and rima glottidis.
The rima glottidis is the narrowest potential site within the larynx, as the vocal cords may be completely opposed, forming a complete barrier.
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This question is part of the following fields:
- Anatomy
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Question 7
Correct
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Which of the following drug can be the first-line drug for both broad and narrow complex tachyarrhythmia?
Your Answer: Amiodarone
Explanation:Amiodarone is the longest-acting anti-arrhythmic drug. It possesses the action of all classes of antiarrhythmic drugs (Sodium channel blockade, Beta blockade, Potassium channel blockade, and Calcium channel blockade). Due to this property, it has the widest anti-arrhythmic spectrum and thus can be used in both broad and narrow complex tachyarrhythmia.
Adenosine is shortest acting anti-arrhythmic drug.
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This question is part of the following fields:
- Pharmacology
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Question 8
Incorrect
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One of the non-pharmacologic management of COPD is smoking cessation. Given a case of a 60-year old patient with history of smoking for 30 years and a FEV1 of 70%, what would be the most probable five-year course of his FEV1 if he ceases to smoke?
Your Answer: The FEV1 will return to normal within 5 years
Correct Answer: The FEV1 will decrease at the same rate as a non-smoker
Explanation:For this patient, his forced expiratory volume in 1 second (FEV1) will decrease at the same rate as a non-smoker.
There is a notable, but slow, decline in FEV1 when an individual reaches the age of 26. An average reduction of 30 mls every year in non-smokers, while a more significant reduction of 50-70 mls is observed in approximately 20% of smokers.
Considering the age of the patient, individuals who begin smoking cessation by the age of 60 are far less likely to achieve normal FEV1 levels, even in the next five years. It is expected that their FEV1 will be approximately 14% less than their peers of the same age.
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This question is part of the following fields:
- Physiology
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Question 9
Correct
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About the vagus nerve, which one of these is true ?
Your Answer: Gives off the recurrent laryngeal nerve on the right as it passes anteriorly across the subclavian artery
Explanation:The tenth cranial nerve (vagus nerve) has both sensory and motor divisions.
It emerges from the anterolateral surface of the medulla in a groove between the olive and the inferior cerebellar peduncle as a series of 8-10 rootlets . It leaves the skull through the middle compartment of the jugular foramen and descends within the carotid sheath between the internal carotid artery and internal jugular vein. The right vagus crosses in front of the first part of the subclavian artery. It gives off the right recurrent laryngeal nerve at this point.
The left recurrent laryngeal nerve passes around the ligamentum arteriosum.
The external laryngeal nerve supplies the cricothyroid muscle while the recurrent laryngeal nerve supplies the other laryngeal muscles.
The cranial part of the accessory nerve supplies all the muscles of the palate, via the pharyngeal plexus and the pharyngeal branch of the vagus nerve, except the tensor veli palatini which is supplied by the mandibular branch of the trigeminal nerve.
The Sternothyroid, Sternohyoid, and Omohyoid muscles are supplied by the ansa cervicalis while the thyrohyoid muscle is supplied by the hypoglossal nerve.
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This question is part of the following fields:
- Anatomy
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Question 10
Correct
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What is the number of valves between the superior vena cava and the right atrium?
Your Answer: None
Explanation:The inflow of blood from the superior vena cava is directed towards the right atrioventricular orifice. It returns deoxygenated blood from all structures superior to the diaphragm, except the lungs and heart.
There are no valves in the superior vena cava which is why it is relatively easy to insert a CVP line from the internal jugular vein into the right atrium. The brachiocephalic vein is similar as it also has no valves.
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This question is part of the following fields:
- Anatomy
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Question 11
Correct
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A 40-year old female comes to the GP's office with unexplained weight gain, cold intolerance and fatigue. Her thyroid function tests are performed as there is a suspicion of hypothyroidism. A negative feedback mechanism is incorporated in the control of thyroid hormone release. All of choices below are also controlled by a negative feedback loop except:
Your Answer: Clotting cascade
Explanation:The correct answer is the clotting cascade, which occurs via a positive feedback mechanism. As clotting factors are attracted to a site, their presence attracts further clotting factors. This continues until a functioning clot is formed.
This patient has presented with symptoms of hypothyroidism and symptoms include weight gain, lethargy, cold intolerance, dry skin, coarse hair and constipation. It can be treated by replacing the missing thyroid hormone with levothyroxine which is a synthetic version of thyroxine (T4).
Serum carbon dioxide (CO2) is controlled via a negative feedback mechanism as well. Chemoreceptors can detect when the serum CO2 is high, and send an impulse to the respiratory centre of the brain to increase the respiratory rate. As a result, more CO2 is exhaled which lowers the serum concentration.
Cortisol is also released according to a negative feedback mechanism. Cortisol acts on both the hypothalamus and the anterior pituitary. Its action serve to decrease the formation of corticotrophin releasing hormone (CRH) and adrenocorticotropic hormone (ACTH), respectively. CRH acts on the anterior pituitary to release ACTH. This then acts on the adrenal gland to cause the release of cortisol. Thus, inhibition of CRH and ACTH formation results in high levels of cortisol which inhibit its further release.
Blood pressure (BP) is controlled via a negative feedback mechanism. Low BP results in renin-angiotensin-aldosterone system (RAAS) activation. This leads to vasoconstriction and retention of salt and water which increased BP.
Blood sugar is controlled via a negative feedback mechanism. A rise in blood sugar causes insulin to be released. Insulin acts to transport glucose into the cell which lowers blood sugar. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 12
Correct
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A weakly acidic drug with a pKa of 8.4 is injected intravenously into a patient. At a normal physiological pH, the percentage of this drug unionised in the plasma is?
Your Answer: 90
Explanation:Primary FRCA is concerned with two issues. The first is a working knowledge of the Henderson-Hasselbalch equation, and the second is a working knowledge of logarithms and antilogarithms.
The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.
To calculate the proportion of ionised to unionised form of a drug, use the Henderson-Hasselbalch equation.
pH = pKa + log ([A-]/[HA])
or
pH = pKa + log [(salt)/(acid)]
pH = pKa + log ([ionised]/[unionised])Hence, if the pKa ˆ’ pH = 0, then 50% of drug is ionised and 50% is unionised.
In this example:
7.4 = 8.4 + log ([ionised]/[unionised])
7.4 ˆ’ 8.4 = log ([ionised]/[unionised])
log ˆ’1 = log ([ionised]/[unionised])Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:
y = antilog x = 10x
Antilog to the base 10 of 0 = 1, ˆ’1 = 0.1, ˆ’2 = 0.01, ˆ’3 = 0.001 and, ˆ’4 = 0.0001.
[A-]/[HA] = 0.1
Assuming that we can apply the approximation [A-] << [HA} then this means the acid is 0.1 x 100% = 10% ionised
so the percentage of (non-ionized) acid will be 100% – 10% = 90%
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This question is part of the following fields:
- Pharmacology
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Question 13
Correct
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Which of the following lung parameters can be measured directly using spirometry?
Your Answer: Vital capacity
Explanation:Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).
It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.
During spirometry, the following measurements can be determined:
Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
Forced expiratory volume in one second (FEV1)
FEV1/FVC ratio
Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.
Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution
The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.
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This question is part of the following fields:
- Clinical Measurement
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Question 14
Incorrect
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Regarding the carbon dioxide monitoring, which of the following statements is correct?
Your Answer: Mainstream analysers cause more delay than sidestream analysers
Correct Answer: Carbon dioxide absorbs infrared radiation at 4.28 µm
Explanation:Carbon dioxide (CO2), is a carbonic gas made up of two dissimilar atoms, namely one carbon atom and two oxygen atoms. Capnography is a technique used to measure carbon dioxide during a respiratory cycle, and it consists in calculating the concentration of the partial pressure of CO2, through the absorption of the infrared light, namely that CO2 absorbs infrared radiation at a wavelength of 4.28 µm.
End-tidal CO2 (ETCO2), referring to the level of the carbon dioxide released at the end of an exhaled breath, is required to be continuously monitored, especially in ventilated patients, as it is a sensitive and a non invasive technique that provides immediate information about ventilation, circulation, and metabolism functions. ETCO2 is normally lower than the arterial partial pressure and varies between 0.6 and 0.7 kPa.
There are two methods used to measure carbon dioxide. The sidestream capnometer method samples gases at a set flow rate (150-200 mL/min) from a sampling area through small diameter tubing, and the mainstream analyser method that uses a direct measurement of the patient exhaled CO2 by a relatively large and heavy sensors. Sidestram method allows the analysis of multiple gases and anaesthetic vapours comparing to the mainstream method that does not allow the measurement of other gases.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 15
Correct
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A new volatile anaesthetic agent has been approved for use in clinical testing. It's a non-irritating, sweet-smelling substance. It has a molecular weight of 170, a 0.6 blood:gas partition coefficient, and a 180 oil:gas partition coefficient. An oxidative pathway converts 2% of the substance to trifluoroacetic acid. Which of the following statements best describes this agent's pharmacological profile?
Your Answer: It has a lower molecular weight than isoflurane
Explanation:Because enflurane is much less soluble in blood and has a blood: gas partition coefficient of 1.8, both wash-in and wash-out should be faster.
Sevoflurane’s sweet-smelling, non-irritant nature, combined with a low blood: gas partition coefficient, would result in similar offset and onset characteristics.
Isoflurane and enflurane have a molecular weight of 184.
The oil: gas partition coefficient on a volatile agent is a measure of lipid solubility, potency, and thus MAC. Halothane has an oil: gas partition coefficient of 220 and a MAC of 0.74. One would expect the MAC to be higher with an oil gas partition coefficient of 180 (less lipid soluble).
The conversion of halothane (20%) to trifluoroacetic acid via oxidative metabolism has been linked to the development of hepatitis.
P450 2E1 converts sevoflurane to hexafluoroisopropanol, which results in the release of inorganic fluoride ions. It’s the only fluorinated volatile anaesthetic that doesn’t break down into trifluoracetic acid.
Desflurane is likely to cause airway irritation, which can lead to coughing, apnoea, and laryngospasm, despite its low blood:gas partition coefficient (0.42).
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This question is part of the following fields:
- Pharmacology
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Question 16
Correct
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A 6-year-old child is scheduled for general anaesthesia day surgery. You decide to perform an inhalational induction because he is otherwise medically fit. Which of the following is the most important factor in deciding which volatile anaesthetic agents to use?
Your Answer: The low blood:gas solubility of sevoflurane
Explanation:The ideal volatile agent for a day case surgery inhalational induction should have the following characteristics:
It has a pleasant scent that is not overpowering.
Breathing difficulties, coughing, or laryngeal spasm are not caused by this substance.
The action has a quick onset and a quick reversal.The blood:gas partition coefficient is a physicochemical property of a volatile agent that determines the onset and offset of anaesthesia. The greater an agent’s insolubility in plasma, the faster its alveolar concentration rises.
The blood gas partition coefficients of the most commonly used volatile anaesthetic agents are as follows:
Halothane 2.3
Desflurane 0.45
Sevoflurane 0.6
Nitrous oxide 0.47
Isoflurane 1.4Although halothane has a pleasant odour, it has a slower offset than sevoflurane.
Sevoflurane also has a pleasant odour and is less likely than desflurane to cause airway irritation and breath-holding.
The choice of agent for inhalational induction is unaffected by potency/lipid solubility measures such as the oil: gas partition coefficient and MAC.
In this case, an agent’s saturated vapour pressure is irrelevant.
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This question is part of the following fields:
- Pharmacology
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Question 17
Correct
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All the following statements are false regarding carbamazepine except
Your Answer: Has neurotoxic side effects
Explanation:Phenytoin, Carbamazepine, and Valproate act by inhibiting the sodium channels when these are open. These drugs also prolong the inactivated stage of these channels (Sodium channels are refractory to stimulation till these reach the closed/ resting phase from inactivated phase)
Carbamazepine is the drug of choice for partial seizures and trigeminal neuralgia
It can have neurotoxic side effects. Major neurotoxic effects include dizziness, headache, ataxia, vertigo, and diplopia
The half-life of carbamazepine is about 13-17 years.
It is metabolized in liver into active metabolite, carbamazepine-10,11-epoxide.
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This question is part of the following fields:
- Pharmacology
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Question 18
Incorrect
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A 30-year-old man has been stabbed in an area of the groin that contains the femoral triangle. He will undergo explorative surgery. Which of the following makes the lateral wall of the femoral triangle?
Your Answer: Adductor longus
Correct Answer: Sartorius
Explanation:The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.
Superior: Inguinal ligament
Medial: Adductor longus
Lateral: Sartorius
Floor: Iliopsoas, adductor longus and pectineusThe contents include: (medial to lateral)
Femoral vein
Femoral artery-pulse palpated at the mid inguinal point
Femoral nerve
Deep and superficial inguinal lymph nodes
Lateral cutaneous nerve
Great saphenous vein
Femoral branch of the genitofemoral nerve. -
This question is part of the following fields:
- Anatomy
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Question 19
Incorrect
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A 75-year-old man, visits his general practitioner. He complains of changes to his bowel habit and unexpected weight loss in the last 6 months. He is scheduled for a colonoscopy and biopsy where he is diagnosed with a transverse colon malignancy. The transverse colon is one of many organs tethered to the posterior wall of the abdominal cavity by a double fold of the peritoneum. Which of the listed organs is also tethered to the peritoneum in a similar way?
Your Answer: The aorta
Correct Answer: The stomach
Explanation:The peritoneal cavity is made up of the omentum, the ligaments and the mesentery.
The section of the peritoneum responsible for tethering organs to the posterior abdominal wall is the mesentery.
These tethered organs are classified as intraperitoneal, and these include the stomach, spleen, liver, first and fourth parts of the duodenum, jejunum, ileum, transverse, and sigmoid colon.
Retroperitoneal organs are located posterior to the peritoneum and include: the rest of the duodenum, the ascending colon, the descending colon, the middle third of the rectum, and the remainder of the pancreas.
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This question is part of the following fields:
- Anatomy
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Question 20
Correct
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A 55-year-old woman presents for transsphenoidal surgery following a diagnosis of pituitary macroadenoma. Which of the following is the most common visual field defect caused by such lesions?
Your Answer: Bitemporal hemianopia
Explanation:Pituitary tumours that compress the optic chiasma primarily affect the neurones that decussate at this location. Bitemporal hemianopia is caused by neurones that emerge from the nasal half of the retina and transmit the temporal half of the visual field.
The axons of ganglion cells in the retina form the optic nerve.
It exits the orbit through the optic foramen and projects to the thalamic lateral geniculate body. The optic chiasma forms above the sella turcica as the nasal fibres decussate along the way. The optic radiation travels from the lateral geniculate body to the occipital cortex.
Lesions at various points along this pathway cause the following visual field defects:
Scotoma implies partial retinal or optic nerve damage.
Monocular vision loss occurs when the optic nerve is completely damaged.
Pathology at the optic chiasma causes bitemporal hemianopia.
Cortical blindness with occipital cortex pathology and homonymous hemianopia with lesions compromising the optic radiation. -
This question is part of the following fields:
- Pathophysiology
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Question 21
Correct
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Which of the following statements is true regarding oxygen?
Your Answer: Forms molecules containing either two or three atoms
Explanation:Oxygen is formed by a molecule of oxygen and two molecules of hydrogen with a molecular formula of H2O
The critical temperature is defined as a temperature above which the substance cannot be liquefied, no matter how much pressure is applied.
Water has a critical temperature of -118.6oC. So, it cannot be liquified at room temperature.Medical oxygen cylinder is stored in a cylinder with a white shoulder and black body. Meanwhile, medial air is stored in cylinders with a white and black shoulder and a French grey body.
The partial pressure of air at a high altitude is less but the relative concentration remains constant.
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This question is part of the following fields:
- Basic Physics
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Question 22
Incorrect
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Of the following statements, which is true about the measurements of cardiac output using thermodilution?
Your Answer: A curve of the temperature increase against time is displayed
Correct Answer: Cardiac output should be measured during the end-expiratory pause
Explanation:Thermodilution is the most common dilution method used to measure cardiac output (CO) in a hospital setting.
During the procedure, a Swan-Ganz catheter, which is a specialized catheter with a thermistor-tip, is inserted into the pulmonary artery via the peripheral vein. 5-10mL of a cold saline solution with a known temperature and volume is injected into the right atrium via a proximal catheter port. The solution is cooled as it mixes with the blood during its travel to the pulmonary artery. The temperature of the blood is the measured by the catheter and is profiled using a computer.
The computer also uses the profile to measure cardiac output from the right ventricle, over several measurements until an average is selected.
Cardiac output changes at each point of respiration, therefore to get an accurate measurement, the same point during respiration must be used at each procedure, this is usually the end of expiration, that is the end-expiratory pause.
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This question is part of the following fields:
- Clinical Measurement
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Question 23
Incorrect
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Intracellular effectors are activated by receptors on the cell surface. These receptors receive signals that are relayed by second messenger systems. In the human body, which second messenger is most abundant?
Your Answer: Cyclic AMP (cAMP)
Correct Answer: Calcium ions
Explanation:Second messengers relay signals to target molecules in the cytoplasm or nucleus when an agonist interacts with a receptor on the cell surface. They also amplify the strength of the signal. The most ubiquitous and abundant second messenger is calcium and it regulates multiple cellular functions in the body.
These include:
Muscle contraction (skeletal, smooth and cardiac)
Exocytosis (neurotransmitter release at synapses and insulin secretion)
Apoptosis
Cell adhesion to the extracellular matrix
Lymphocyte activation
Biochemical changes mediated by protein kinase C.cAMP is either inhibited or stimulated by G proteins.
The receptors in the body that stimulate G proteins and increase cAMP include:
Beta (β1, β2, and β3)
Dopamine (D1 and D5)
Histamine (H2)
Glucagon
Vasopressin (V2).The second messenger for the action of nitric oxide (NO) and atrial natriuretic peptide (ANP) is cGMP.
The second messengers for angiotensin and thyroid stimulating hormone are inositol triphosphate (IP3) and diacylglycerol (DAG).
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This question is part of the following fields:
- Physiology
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Question 24
Incorrect
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What does therapeutic index in humans mean?
Your Answer: The LD50 divided by the TD50
Correct Answer: The TD50 divided by the ED50
Explanation:Therapeutic index is a measure which relates the dose of a drug required to produce a desired effect to that which produces an undesired effect.
In humans, it is usually defined as the ratio of the toxic dose for 50% of the population (TD50) to the minimum effective dose for 50% of the population (ED50) for some therapeutically relevant effect. In animal studies, the therapeutic index can be defined as the ratio of the median lethal dose (LD50) to the ED50.
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This question is part of the following fields:
- Pharmacology
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Question 25
Correct
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A 30-year old lady has a sub total thyroidectomy. On the 5th post-operative day, the wound becomes erythematous and there is a purulent discharge. The most likely organism causing this is:
Your Answer: Staphylococcus aureus
Explanation:Staphylococcus aureus infection is the most likely cause.
Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.
SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
The organisms are usually derived from the patient’s own body.Measures that may increase the risk of SSI include:
-Shaving the wound using a single use electrical razor with a disposable head
-Using a non iodine impregnated surgical drape if one is needed
-Tissue hypoxia
-Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.Measures that may decrease the risk of SSI include:
1. Intraoperatively
– Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
-Cover surgical site with dressingIn contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.
2. Post operatively
Tissue viability advice for management of surgical wounds healing by secondary intentionUse of diathermy for skin incisions
In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 26
Incorrect
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A 72-year-old female is diagnosed with acute mesenteric ischemia. On CT angiogram, the origin of the superior mesenteric artery is stenosed. At which vertebra level does the superior mesenteric artery branch from the aorta?
Your Answer: L4
Correct Answer: L1
Explanation:The superior mesenteric artery branches from the abdominal aorta just 1-2 cm below the origin of the celiac trunk. It lies posterior to the body of the pancreas and splenic vein and is separated from the aorta by the left renal vein. It passes forwards and inferiorly, anterior to the uncinate process of the pancreas and the third part of the duodenum, to enter the root of the small bowel mesentery and supply the midgut.
The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:
T10 – oesophageal opening in the diaphragm
T12 – Coeliac trunk, aortic hiatus in the diaphragm
L1 – Left renal artery
L2 – Testicular or ovarian arteries
L3 – Inferior mesenteric artery
L4 – Bifurcation of the abdominal aorta.
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This question is part of the following fields:
- Anatomy
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Question 27
Incorrect
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Of the following, which is NOT a branch of the subclavian artery?
Your Answer: Thyrocervical trunk
Correct Answer: Superior thyroid artery
Explanation:The left subclavian artery originates from the aortic arch, while the right subclavian artery originates from the brachiocephalic artery.
The subclavian artery gives off branches on both sides of the body:
1. Vertebral artery
2. Internal thoracic artery
3. Thyrocervical trunk
4. Costocervical trunk
5. Dorsal scapular arteryThe superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
1. Superior thyroid artery
2. Ascending pharyngeal artery
3. Lingual artery
4. Facial artery
5. Occipital artery
6. Posterior auricular artery
7. Maxillary artery
8. Superficial temporal artery. -
This question is part of the following fields:
- Anatomy
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Question 28
Incorrect
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Drug X, a new intravenous induction drug, is being administered as a bolus at regular time intervals, and the following data were observed: Time following injection (hours) vs Plasma concentration of drug X (mcg/mL) 2 / 400 6 / 100 10 / 25 14 / 6.25 Which of the following values estimate the plasma half-life (T½) of drug X?
Your Answer: 1 hour
Correct Answer: 2 hours
Explanation:Half life (T½) is the time required to change the amount of drug in the body by one-half (or 50%) during elimination. The time course of a drug in the body will depend on both the volume of distribution and the clearance.
Extrapolating the values from the plasma concentration vs time:
Plasma concentration at 0 hours = 800 mcg/mL
Plasma concentration at 2 hours = 400 mcg/mL
Plasma concentration at 4 hours = 200 mcg/mL
Plasma concentration at 6 hours = 100 mcg/mL
Plasma concentration at 8 hours = 50 mcg/mL
Plasma concentration at 10 hours = 25 mcg/mL
Plasma concentration at 12 hours = 12.5 mcg/mL
Plasma concentration at 14 hours = 6.25 mcg/mL -
This question is part of the following fields:
- Statistical Methods
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Question 29
Incorrect
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Which of the following is true regarding a laryngoscope?
Your Answer: The McCoy laryngoscope is based on the standard Robertshaw's blade
Correct Answer: The Wisconsin and Seward are examples of straight blade laryngoscopes
Explanation:Direct laryngoscopy are performed using laryngoscopes and they can be classed according to the shape of the blade as curved or straight.
Miller, Soper, Wisconsin and Seward are examples of straight blade laryngoscopes. Straight blades are commonly used for intubating neonates and infants but can be used in adults too.
The tip of the miller blade is advanced over the epiglottis to the tracheal entrance then lifted in order to view the vocal cords.
The RIGHT-SIDED Macintosh blade is used in adults while the left-sided blade may be used in conditions that make intubation with standard blade difficult e.g. facial deformities.
The McCoy laryngoscope is based on the STANDARD MACINTOSH blade not Robertshaw’s. It has a lever operated hinged tip, which improves the view during laryngoscopy.
Polio blade is mounted at an angle of 120-135 degrees to the handle. Originally designed for use during the polio epidemic €‹in intubation patients within iron lung ventilators, it is now useful in patients with conditions like breast hypertrophy, barrel chest, and restricted neck mobility.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 30
Correct
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An 80-year-old female presents to the emergency department with symptoms consistent with mesenteric ischemia. She is quickly shifted to the operation theatre for an emergency laparotomy. On exploration, the segment of the colon from the splenic flexure down to the rectum is ischemic. The artery blocked in this scenario arises at what vertebral level from the aorta?
Your Answer: L3
Explanation:The hindgut is from the distal third of the transverse colon down to the upper one-third of the anal canal. The inferior mesenteric artery supplies the hindgut.
The inferior mesenteric artery arises from the aorta behind the inferior border of the third part of the duodenum 3€“4 cm above the aortic bifurcation, at the third lumbar vertebra level.
The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:
T12 – Coeliac trunk
L1 – Left renal artery
L2 – Testicular or ovarian arteries
L3 – Inferior mesenteric artery
L4 – Bifurcation of the abdominal aorta.
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This question is part of the following fields:
- Anatomy
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