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  • Question 1 - How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?...

    Incorrect

    • How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?

      Your Answer: Four

      Correct Answer: Three

      Explanation:

      The abdominal arteries are divided into 3 branches;
      – 3 main unpaired trunks (celiac trunk, superior mesenteric, inferior mesenteric arteries)
      – 6 paired branches
      – unpaired median sacral artery.

      We can group the abdominal aorta as follows;
      -Ventral which includes: Coeliac trunk, superior mesenteric and inferior mesenteric arteries
      -Lateral: Inferior phrenic, middle suprarenal, renal and gonadal arteries
      -Dorsal: Lumbar and median sacral arteries
      -Terminal : Right and left common iliac arteries

      The celiac trunk (L1) takes blood the foregut and its found posterior to the stomach. The unpaired superior mesenteric artery supplies blood to the mid-gut.

      The paired renal arteries form the inferior suprarenal arteries. The renal arteries arise around L1/L2 and takes blood to either side of the kidneys.

      The median sacral artery supplies blood to the lumbar vertebrae the L4 and L5.

    • This question is part of the following fields:

      • Anatomy
      8.1
      Seconds
  • Question 2 - An adult and a 7-year-old child are anatomically and physiologically very different. Which...

    Correct

    • An adult and a 7-year-old child are anatomically and physiologically very different. Which of the following physiological characteristics of a 5-year-old most closely resembles those of a healthy adult?

      Your Answer: Dead space ratio

      Explanation:

      Whatever the age, the dead space ratio is 0.3. It’s the dead space (Vd) to tidal volume ratio (Vt).

      The glottis is the narrowest point of the upper airway in an adult, while the cricoid ring is the narrowest point in a child.

      A child’s airway resistance is much higher than an adult’s. The resistance to airflow increases as the diameter of a paediatric airway shrinks. The radius (r) to the power of 4 is inversely proportional to airway resistance (r4). As a result, paediatric patients are more susceptible to changes in airflow caused by a small reduction in airway diameter, such as caused by oedema.

      The compliance of a newborn’s lungs is very low (5 mL/cmH2O), but it gradually improves as lung size and elasticity grow. Lung compliance in an adult is 200 mL/cmH2O.

      In children, minute ventilation (mL/kg/minute) is much higher.

    • This question is part of the following fields:

      • Pathophysiology
      16.2
      Seconds
  • Question 3 - This vertebrae can be easily differentiated from the rest because of its prominent...

    Correct

    • This vertebrae can be easily differentiated from the rest because of its prominent spinous process.

      Your Answer: C7

      Explanation:

      The spinous process is the part of a vertebrae that is directed posteriorly.

      Typical cervical vertebra have spinous processes that are small and bifid, except for C7, which has a long and prominent spinous process.

    • This question is part of the following fields:

      • Anatomy
      3.8
      Seconds
  • Question 4 - The following are the pharmacodynamic properties of a neuromuscular blocking agent: Effective dose...

    Correct

    • The following are the pharmacodynamic properties of a neuromuscular blocking agent: Effective dose 95 (ED95) - 0.3 mg/kg, Time to 95% depression of first twitch of train of four (ToF) - 75 seconds, Time to 25% recovery of first twitch of train of four (ToF) - 33 minutes. Which of the following statements about this neuromuscular blocking agent is the most accurate?

      Your Answer: Can be reversed by a modified gamma-cyclodextrin

      Explanation:

      The aminosteroid rocuronium is the neuromuscular blocking agent in question.

      0.3 mg/kg is the effective dose 95 (ED95) (the dose required to depress the twitch height by 95 percent )
      The dose for intubation is 0.6 mg/kg.
      75 seconds is the time it takes to reach 95 percent depression of the first twitch of the train of four (ToF) or the onset time.
      The clinical duration or time to 25% recovery of the first twitch of the train of four (ToF) is 33 minutes.

      A modified cyclodextrin can quickly reverse both rocuronium and vecuronium (sugammadex).

      It is more fat-soluble than vecuronium, with the liver absorbing the majority of the drug and excreting it in the bile. The only metabolite found in the blood (17-desacetylrocuronium) is 20 times less potent than the parent drug and is unlikely to cause neuromuscular block.

      Despite its quick onset of action (60-90 seconds), suxamethonium arguably is still the neuromuscular blocker of choice for a quick sequence induction. Rocuronium is becoming increasingly popular for this purpose.

    • This question is part of the following fields:

      • Pharmacology
      6.8
      Seconds
  • Question 5 - A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet....

    Correct

    • A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet. On examination, he was found to be hypertensive. Which of the following correctly explains the cause of his visual field defect?

      Your Answer: Pituitary macroadenoma secreting growth hormone (GH)

      Explanation:

      Pituitary macroadenoma is a benign tumour with growth larger than 10mm (those under 10mm are called microadenoma)

      Compression of optic chiasm by pituitary adenoma is responsible for causing visual field defects like bitemporal hemianopia, optic neuropathy.

    • This question is part of the following fields:

      • Pathophysiology
      22.4
      Seconds
  • Question 6 - A new volatile anaesthetic agent has been approved for use in clinical testing....

    Incorrect

    • A new volatile anaesthetic agent has been approved for use in clinical testing. It's a non-irritating, sweet-smelling substance. It has a molecular weight of 170, a 0.6 blood:gas partition coefficient, and a 180 oil:gas partition coefficient. An oxidative pathway converts 2% of the substance to trifluoroacetic acid. Which of the following statements best describes this agent's pharmacological profile?

      Your Answer: It has a slower wash-out than enflurane

      Correct Answer: It has a lower molecular weight than isoflurane

      Explanation:

      Because enflurane is much less soluble in blood and has a blood: gas partition coefficient of 1.8, both wash-in and wash-out should be faster.

      Sevoflurane’s sweet-smelling, non-irritant nature, combined with a low blood: gas partition coefficient, would result in similar offset and onset characteristics.

      Isoflurane and enflurane have a molecular weight of 184.

      The oil: gas partition coefficient on a volatile agent is a measure of lipid solubility, potency, and thus MAC. Halothane has an oil: gas partition coefficient of 220 and a MAC of 0.74. One would expect the MAC to be higher with an oil gas partition coefficient of 180 (less lipid soluble).

      The conversion of halothane (20%) to trifluoroacetic acid via oxidative metabolism has been linked to the development of hepatitis.

      P450 2E1 converts sevoflurane to hexafluoroisopropanol, which results in the release of inorganic fluoride ions. It’s the only fluorinated volatile anaesthetic that doesn’t break down into trifluoracetic acid.

      Desflurane is likely to cause airway irritation, which can lead to coughing, apnoea, and laryngospasm, despite its low blood:gas partition coefficient (0.42).

    • This question is part of the following fields:

      • Pharmacology
      25.7
      Seconds
  • Question 7 - A laceration to the upper lateral margin of the popliteal fossa will pose...

    Incorrect

    • A laceration to the upper lateral margin of the popliteal fossa will pose the greatest risk of injury for which nerve?

      Your Answer: Saphenous nerve

      Correct Answer: Common peroneal nerve

      Explanation:

      The common peroneal (fibular) nerve descends obliquely along the lateral side of the popliteal fossa to the fibular head, medial to biceps femoris.

      The sural nerve exits at the fossa’s lower inferolateral aspect and is more at risk in short saphenous vein surgery.

      The tibial nerve lies more medially and is even less likely to be injured in this location.

      The boundaries of the popliteal fossa are:
      Superolateral – the biceps femoris tendon
      Superomedial – semimembranosus reinforced by semitendinosus
      Inferomedial and inferolateral – medial and lateral heads of gastrocnemius

      The contents of the Popliteal fossa are:

      1. The popliteal artery
      2. The popliteal vein
      3. The Tibial nerve and common Fibular nerve
      4. Posterior femoral cutaneous nerve: descends and pierces the roof
      5. Small saphenous vein
      6. popliteal lymph nodes
      7. fat.

    • This question is part of the following fields:

      • Anatomy
      14.5
      Seconds
  • Question 8 - Out of the following, which is NOT true regarding the external carotid? ...

    Correct

    • Out of the following, which is NOT true regarding the external carotid?

      Your Answer: It ends by bifurcating into the superficial temporal and ascending pharyngeal artery

      Explanation:

      The external carotid artery has eight important branches:
      Anterior surface:
      1. Superior thyroid artery (first branch)
      2. Lingual artery
      3. Facial artery
      Medial branch
      4. Ascending pharyngeal artery
      Posterior branches
      5. Occipital artery
      6. Posterior auricular artery
      Terminal branches
      7. Maxillary artery
      8. Superficial temporal artery

      The external carotid has eight branches, 3 from its anterior surface ; thyroid, lingual and facial. The pharyngeal artery is a medial branch. The posterior auricular and occipital are posterior branches.

    • This question is part of the following fields:

      • Anatomy
      82.2
      Seconds
  • Question 9 - A 60-year-old man, presents to the emergency department with crushing pain in the...

    Correct

    • A 60-year-old man, presents to the emergency department with crushing pain in the central chest area, which radiates to his left arm and jaw. He also reports feelings of nausea with no other symptoms. Elevation of the ST-segment is noted in multiple chest leads upon ECG, leading to a diagnosis of ST-elevation MI. What vessel gives rise to the coronary vessels?

      Your Answer: Ascending aorta

      Explanation:

      The above mentioned patient presentation is one of an acute coronary syndrome.

      The elevations noted in the ST-segments of multiple heart leads on ECG is diagnostic of an ST-elevation myocardial infarction.

      The pulmonary artery branches to give rise to the right and left pulmonary arteries, which supply deoxygenated blood to the right and left lungs from the right ventricle.

      The pulmonary veins do not form any bifurcations, and therefore do not give rise to any vessels. They travel to the left atrium from the lungs, carrying oxygenated blood.

      The descending aorta continues from the aortic arch, and bifurcates to give off many branches, including the right and left common iliac arteries.

      The coronary sinus is formed from the combination of four coronary veins, receiving blood supply from the great, middle, small and posterior cardiac veins, and transporting this venous blood into the right atrium.

      The right and left aortic sinus give rise to the right and left coronary arteries, respectively. They branch of the ascending aorta, in the area just superior to the aortic valve.

    • This question is part of the following fields:

      • Anatomy
      11.5
      Seconds
  • Question 10 - A 27-year-old woman presents to emergency department. She is experiencing generalised seizures. She...

    Correct

    • A 27-year-old woman presents to emergency department. She is experiencing generalised seizures. She is given emergency management of her symptoms before being referred to the neurologist who diagnoses her with new onset of tonic-clonic epilepsy. What is the most appropriate first line of treatment?

      Your Answer: Lamotrigine should be offered as first line of treatment

      Explanation:

      Tonic-clonic (Grand mal) epilepsy is characterised by a general loss of consciousness with violent involuntary muscle contractions.

      The NICE guidelines for treatment indicates the use of sodium valproate and lamotrigine, but sodium valproate unsuitable in this case and she is a woman of reproductive age and it is known to have teratogenic effects. Lamotrigine is a more suitable choice, prescribed as 800mg daily.

      NICE guidelines also advice an additional prescription of 5mg of folic acid daily for women on anticonvulsant therapy looking to get pregnant. It also warns of the need for extra contraceptive precaution as there is a possibly that the anticonvulsant agent can reduce levels of contraceptive agents.

      Stimulation of the vagal nerve stimulation is only necessary in patients who are refractory to medical treatment and not candidates for surgical resection.

    • This question is part of the following fields:

      • Pathophysiology
      15.3
      Seconds
  • Question 11 - An intravenous drug infusion is started at a rate of 20 ml/hour. The...

    Incorrect

    • An intravenous drug infusion is started at a rate of 20 ml/hour. The drug concentration in the syringe is 5 mg/mL. The drug's plasma clearance is 20 L/hour. Which of the following values, assuming that the infusion rate remains constant, best approximates the drug's plasma concentration at steady state?

      Your Answer: 5 mg/mL

      Correct Answer: 5 mcg/mL

      Explanation:

      When a drug is given via intravenous infusion, the plasma concentration rises exponentially as a wash-in curve until it reaches steady-state concentration (the point at which the infusion rate is balanced by the elimination rate or clearance). To reach this steady state, the drug will take 4-5 half-lives.

      Cpss (target plasma concentration at steady state) and clearance (CL) in ml/minute or litre/hour are the two factors that determine the infusion rate or dose (ID) in mg/hour of a drug.

      ID = Cpss × CL

      We know the infusion rate is 20 ml/hour in this case. The drug’s concentration is 5 mg/mL. The patient is receiving 100 mg of the drug per hour, with a 20 L/hour clearance rate.

      ID = Cpss × 20

      Therefore,

      Cpss = 100 mg/20000 ml

      Cpss = 0.005 mg/mL or 5 mcg/mL

    • This question is part of the following fields:

      • Pharmacology
      101.5
      Seconds
  • Question 12 - Regarding amide local anaesthetics, which one factor has the most significant effect on...

    Correct

    • Regarding amide local anaesthetics, which one factor has the most significant effect on its duration of action?

      Your Answer: Protein binding

      Explanation:

      When drugs are bound to proteins, drugs cannot cross membranes and exert their effect. Only the free (unbound) drug can be absorbed, distributed, metabolized, excreted and exert pharmacologic effect. Thus, when amide local anaesthetics are bound to α1-glycoproteins, their duration of action are reduced.

      The potency of local anaesthetics are affected by lipid solubility. Solubility influences the concentration of the drug in the extracellular fluid surrounding blood vessels. The brain, which is high in lipid content, will dissolve high concentration of lipid soluble drugs. When drugs are non-ionized and non-polarized, they are more lipid-soluble and undergo more extensive distribution. Hence allowing these drugs to penetrate the membrane of the target cells and exert their effect.

      Tissue pKa and pH will determine the degree of ionization.

    • This question is part of the following fields:

      • Physiology
      4
      Seconds
  • Question 13 - All of the following statements are false regarding propranolol except: ...

    Correct

    • All of the following statements are false regarding propranolol except:

      Your Answer: Has a plasma half life of 3-6 hours.

      Explanation:

      Propranolol is a nonselective beta-blocker with a half-life of 3 to 6 hours.

      Since it is lipid-soluble it crosses the blood-brain barrier and causes Central Nervous System side effects like sedation, nightmares, and depression.

      They are contraindicated in asthma, Congestive heart failure, and diabetes.

      It has a large volume of distribution with no intrinsic sympathomimetic action.

    • This question is part of the following fields:

      • Pharmacology
      12.3
      Seconds
  • Question 14 - Which measure of central tendency is most useful for a continuous, non-skewed data?...

    Incorrect

    • Which measure of central tendency is most useful for a continuous, non-skewed data?

      Your Answer: Standard deviation

      Correct Answer: Mean

      Explanation:

      Mean, also known as the average, is the most common measure of central tendency. It is the sum of all observed values divided by the number of observation. It is not useful for skewed data, which has an abnormal distribution. It is useful, instead, for numerical data that have symmetric distribution. It reflects the contributions of each data in the group, and are sensitive to outliers.

      The median is the value that falls in the middle position when the observations are ranked in order from the smallest to the largest. If the number of observations is odd, the median is the middle number. If it is even, the median is the average of the two middle numbers. Unlike the mean, the median is useful on skewed data, and can be used for ordinal or numerical data if skewed.

      The mode is the value that occurs with the greatest frequency in a set of observations, and is utilized for bimodal distribution.

      The variance and the standard deviation are not measures of central tendency, but of dispersion.

    • This question is part of the following fields:

      • Statistical Methods
      13.1
      Seconds
  • Question 15 - A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent...

    Incorrect

    • A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent or 1 MET). Which of the following options is linked to the highest VO2 when a person is at rest?

      Your Answer: Thyrotoxicosis

      Correct Answer: Neonate

      Explanation:

      The oxygen consumption rate (VO2) at rest is 3.5 ml/kg/minute (one metabolic equivalent or 1 MET).
      3.86 ml/kg/minute thyrotoxicosis

      Young children consume a lot of oxygen: around 7 ml/kg/min when they are born. The metabolic cost of breathing is higher in children than in adults, and it can account for up to 15% of total oxygen consumption. Similarly, an infant’s metabolic rate is nearly twice that of an adult, resulting in a larger alveolar minute volume and a lower FRC.

      At term, oxygen consumption at rest can increase by as much as 40% (5 ml/kg/minute) and can rise to 60% during labour.

      When compared to normal basal metabolism, sepsis syndrome increases VO2 and resting metabolic rate by 30% (4.55 ml/kg/minute). In septicaemic shock, VO2 decreases.

      Dobutamine hydrochloride was infused into 12 healthy male volunteers at a rate of 2 micrograms per minute per kilogramme, gradually increasing to 4 and 6 micrograms per minute per kilogramme. Dobutamine was infused for 20 minutes for each dose. VO2 increased by 10% to 15%. (3.85-4.0 ml/kg/min).

    • This question is part of the following fields:

      • Physiology
      9.9
      Seconds
  • Question 16 - A 35-year-old male presents to GP presenting an area of erythema which was...

    Incorrect

    • A 35-year-old male presents to GP presenting an area of erythema which was around a recent cut on his right forearm. He was prescribed a short course of antibiotics and after 5 days again presented with progressive fatigue, headaches, and fevers. On clinical examination: Oxygen saturation: 98% on room air, Respiratory rate: 22 per minute, Heart rate: 100 beats per minute, Blood pressure: 105/76 mmHg, Temperature: 38.2 degree Celsius. On physical examination, a dramatic increase in the area of erythema was noted. Blood culture was done in the patient and indicated the presence of bacterium containing beta-lactamase. Which of the following antibiotics was likely prescribed to the patient?

      Your Answer: Co-amoxiclav

      Correct Answer: Amoxicillin

      Explanation:

      Ciprofloxacin belongs to the quinolone group of antibiotics, and doxycycline and minocycline are tetracyclines. So, they are not affected by beta-lactamase.
      However, amoxicillin is a beta-lactam antibiotic and beta-lactamase cleaves the beta-lactam ring present in amoxicillin. This results in the breakdown of the antibiotic and thus the area of erythema dramatically increased.
      Co-amoxiclav contains amoxicillin and clavulanic acid which protects amoxicillin from beta-lactamase.

    • This question is part of the following fields:

      • Pharmacology
      22.1
      Seconds
  • Question 17 - What structure is most critical in providing support for the duodenojejunal flexure? ...

    Incorrect

    • What structure is most critical in providing support for the duodenojejunal flexure?

      Your Answer: Mesentery of the transverse colon

      Correct Answer: Ligament of Treitz

      Explanation:

      The duodenojejunal flexure is the point where the duodenum becomes the jejunum.

      The ligament of Treitz, which arises from the right crus of diaphragm, provides suspension for support.

      Between the ileum and the caecum is the ligament of Treves.

    • This question is part of the following fields:

      • Anatomy
      21.9
      Seconds
  • Question 18 - Which of the following closely estimates the interstitial oncotic pressure acting on a...

    Correct

    • Which of the following closely estimates the interstitial oncotic pressure acting on a pulmonary capillary?

      Your Answer: 17 mmHg

      Explanation:

      The starling forces operate to maintain a homeostatic flow across the pulmonary capillary bed.

      The outward driving force comprises of the capillary hydrostatic pressure (13 mmHg), negative interstitial fluid pressure (zero to slightly negative), and interstitial colloid osmotic pressure (17 mmHg). The inward driving force is controlled by the plasma colloid osmotic pressure (25 mmHg).

    • This question is part of the following fields:

      • Basic Physics
      4.1
      Seconds
  • Question 19 - A 64-year-old man is admitted to the critical care unit. He has a...

    Correct

    • A 64-year-old man is admitted to the critical care unit. He has a recent medical history of faecal peritonitis for which a laparotomy was performed. His vitals have been monitored using an invasive pulmonary artery flotation catheter. His vital readings are: Temperature: 38.1°C. Blood pressure: 79/51 mmHg (mean 58 mmHg), Pulmonary artery pressure: 19/6 mmHg (mean 10 mmHg). Pulmonary capillary occlusion pressure: 5 mmHg, Central venous pressure: 12 mmHg, Cardiac output: 5 L/min, Mixed venous oxygen saturation: 82%. Calculate his approximate pulmonary vascular resistance. Note: A correction factor of 80 is require to convert mmHg to dynes·s·cm-5

      Your Answer: 80 dynes·s·cm-5

      Explanation:

      Pulmonary vascular resistance (PVR) refers to the resistance to blood flow to the left atrium from the pulmonary artery.
      It is derived mathematically by:

      PVR = MPAP – PCWP
      CO
      where,
      MPAP: Mean pulmonary artery pressure
      PCWP: Pulmonary capillary occlusion pressure
      CO: Cardiac output

      For this patient:
      PVR = 10 – 5 = 1mmHg
      5

      Remember, multiply by correction factor 80 to change units:

      PVR = 1mmHg x 80 = 80 dynes·s·cm-5

      Normal values range between 20-130 dynes·s·cm-5.

    • This question is part of the following fields:

      • Clinical Measurement
      32.6
      Seconds
  • Question 20 - Which of the following statement is not true regarding Adrenaline or Epinephrine? ...

    Correct

    • Which of the following statement is not true regarding Adrenaline or Epinephrine?

      Your Answer: Inhibits Glucagon secretion in the pancreas

      Explanation:

      Adrenaline acts on α1, α2, β1, and β2 receptors and also on dopamine receptors (D1, D2) and have sympathomimetic effects.

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

      Adrenaline is a sympathomimetic amine with both alpha and beta-adrenergic stimulating properties.
      Adrenaline is the drug of choice for anaphylactic shock
      Adrenaline is also used in patients with cardiac arrest. The preferred route is i.v. followed by the intra-osseous and endotracheal route.

      Adrenaline is released by the adrenal glands, acts on α 1 and 2, β 1 and 2 receptors, and is responsible for fight or flight response.

      It acts on β 2 receptors in skeletal muscle vessels-causing vasodilation.

      It acts on α adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.

      It acts on β adrenergic receptors to stimulate glucagon secretion in the pancreas. It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue

    • This question is part of the following fields:

      • Pharmacology
      23.5
      Seconds
  • Question 21 - A strain gauge operates on which of the following principles? ...

    Correct

    • A strain gauge operates on which of the following principles?

      Your Answer: Varying resistance of a wire when stretched

      Explanation:

      The principle by which a strain gauge works is that when a wire is stretched, it becomes longer and thinner, and as a result, its resistance increases.

      A strain gauge, which is used in pressure transducers, acts as a resistor. When the pressure in a pressure transducer changes, the diaphragm moves, changing the tension in the resistance wire and thus changing the resistance.

      Changes in current flow through the resistor are amplified and displayed as a pressure change measure.

      A Wheatstone bridge, on the other hand, is frequently used to measure or monitor these changes in resistance.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      33.2
      Seconds
  • Question 22 - Which structure passes through the foramen magnum? ...

    Incorrect

    • Which structure passes through the foramen magnum?

      Your Answer: Accessory nerve

      Correct Answer: Spinal roots of the accessory nerve

      Explanation:

      The structures that pass through the foramen magnum are:

      Meningeal lymphatics
      Spinal cord
      Spinal meninges
      Sympathetic plexus of vertebral arteries
      Vertebral arteries
      Vertebral artery spinal branches
      The spinal roots of the accessory nerve.

      The jugular foramen contains the vagus nerve, the accessory nerve and glossopharyngeal nerve.

      The vertebral veins does not pass into the skull.

    • This question is part of the following fields:

      • Anatomy
      10.5
      Seconds
  • Question 23 - Health workers are at increased risks of anaesthetic exposure. Therefore, The Control of...

    Correct

    • Health workers are at increased risks of anaesthetic exposure. Therefore, The Control of Substances Hazardous to Health (COSHH) regulations require measures implemented to assess and control the risks related to this exposure. Among the following control measures, which one is most likely to limit potentially harmful exposure to anaesthetic agents within an operating theatre?

      Your Answer: Total intravenous anaesthesia (TIVA)

      Explanation:

      Exposure to anaesthetic hazards is one among the occupational exposures in manipulating toxic agents or inhaling toxic gases during anaesthetic practices.

      Toxic gases mainly nitrous oxide, is one of the most gaseous anaesthetic agents that constitutes an important source of pollution. One of the safe and effective technics used in anaesthesia and reducing the amount of pollution is the Total Intravenous Anaesthesia (TIVA) which consists of using opioids in analgesia and propofol for the induction and the maintenance of anaesthesia. It refers to the administration intravenously of an anaesthetic, sedative, and/or tranquilizer. A less polluting but not the best way to get rid of the toxic aesthetic agents is the scavenger system that collects and expels the gas outside the medical environment. Yet, this technique still represents a hazard for the environment and still increase the risk of exposure for the health workers and clinical staff.

      Fume cupboards are also not recommended to use because of their high pollution potency, mainly of the air resulting in a great harm for medical workers.

      Supraglottic airways as well as the Air Changes per Hour technics could be harmful for both patients and health workers, increasing the risks of transmitted diseases, namely nosocomial infections.

      Therefore, the Total Intravenous Anaesthesia technique (TIVA) is most likely to be safe and recommended to use.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      8.5
      Seconds
  • Question 24 - A 20-year old lady has been having excessive bruising and bleeding of her...

    Incorrect

    • A 20-year old lady has been having excessive bruising and bleeding of her gums. She is under investigation for the extrinsic pathway of coagulation. Which is the best investigation to order?

      Your Answer: aPTT time

      Correct Answer: Prothrombin time (PT)

      Explanation:

      The extrinsic pathway is best assessed by the PT time.

      D-dimer is a fibrin degradation product which is raised in the presence of blood clots.

      A 50:50 mixing study is used to assess if a prolonged PT or aPTT is due to factor deficiency or a factor inhibitor.

      The thrombin time is a test used to assess fibrin formation from fibrinogen in plasma. Factors that prolong the thrombin time include heparin, fibrin degradation products, and fibrinogen deficiency.

      Intrinsic pathway – Best assessed by APTT. Factors 8,9,11,12 are involved. Prolonged aPTT can be seen in haemophilia and use of heparin.

      Extrinsic pathway – Best assessed by Increased PT. Factor 7 involved.

      Common pathway – Best assessed by APTT & PT. Factors 2,5,10 involved.

      Vitamin K dependent factors are factors 2,7,9,10

    • This question is part of the following fields:

      • Physiology And Biochemistry
      9.1
      Seconds
  • Question 25 - During 2015 it was reported in the New England Journal of Medicine that...

    Correct

    • During 2015 it was reported in the New England Journal of Medicine that the usage of empagliflozin(a sodium-glucose-co-transporter 2 inhibitor) caused a decrease in the cardiovascular deaths, non fatal heart attacks and strokes in patients suffering from type 2 diabetes. The results were published per 1000 patient years. With the above mentioned drug, the event rate turned out to be 37.3/1000 patient years whereas the placebo had an event rate of 43.9/1000 patient years. How many further patients need to be treated with empagliflozin to avoid any further incidence of cardiovascular death or non fatal myocardial infraction and non fatal stroke?

      Your Answer: 150

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

      where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (43.9-37.3)

      ARR= 6.6

      NNT= 1000/6.6

      NNT=151.5

    • This question is part of the following fields:

      • Statistical Methods
      59.6
      Seconds
  • Question 26 - Tubes for vascular access and body cavity drainage are available in a variety...

    Incorrect

    • Tubes for vascular access and body cavity drainage are available in a variety of sizes. When choosing an intravenous or intra-arterial cannula, which of the following measurements is used?

      Your Answer: French gauge (mm)

      Correct Answer: Standard wire gauge (SWG)

      Explanation:

      Standard wire gauge cannulas for intravenous and intraarterial use are available (SWG or G). The SWG is a former imperial unit (which requires metric conversion). The cross sectional area of wires is becoming more popular as a size measurement.

      The number of wires that will fit into a standard hole template is referred to as SWG.

      This standard sized hole can accommodate 22 thin wires side by side (each wire the diameter of a 22 gauge cannula)
      In the same hole, 14 thicker wires would fit (each wire the diameter of a 14 gauge cannula)

      While the diameter and thus radius of a parallel sided tube are the most important determinants of fluid flow rate, they are not commonly used to compare cannula sizes.

      The circumference of French gauge (FG) catheters (urinary or chest drains) is measured. Sizes of double lumen tracheal tubes are FG. Internal diameter is used to measure single lumen tubes.

    • This question is part of the following fields:

      • Pathophysiology
      15.7
      Seconds
  • Question 27 - A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure,...

    Incorrect

    • A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure, the ileocolic artery is ligated. Which vessel does this artery originate from?

      Your Answer: Coeliac axis

      Correct Answer: Superior mesenteric artery

      Explanation:

      The ileocolic artery is the terminal branch of the superior mesenteric artery. It supplies:
      1. terminal ileum
      2. proximal right colon
      3. cecum
      4. appendix (via its branch of the appendicular artery)

      As veins accompany arteries in the mesentery and are lined by lymphatics, high ligation is the norm in cancer resections€”the ileocolic artery branches off the SMA near the duodenum.

    • This question is part of the following fields:

      • Anatomy
      11.9
      Seconds
  • Question 28 - A 68-year old female is brought to the Emergency Room for abdominal pain....

    Correct

    • A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis. Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2. Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?

      Your Answer: Prothrombin complex

      Explanation:

      Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.

      Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.

      Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.

      Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.

      Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.

    • This question is part of the following fields:

      • Pathophysiology
      99
      Seconds
  • Question 29 - A 30 year old male was the victim of an electrocution injury and...

    Correct

    • A 30 year old male was the victim of an electrocution injury and has been treated. The option that best describes the current levels for this injury is:

      Your Answer: Tonic muscle contraction - 15 mA

      Explanation:

      There are different effects of electrocution and these can be shown in the table below.

      Current Effect
      1 mA Tingling
      5 mA Pain
      15 mA Tonic muscle contraction
      50 mA Respiratory arrest
      100 mA Ventricular fibrillation and cardiac arrest.

    • This question is part of the following fields:

      • Clinical Measurement
      15.5
      Seconds
  • Question 30 - Calculation of the left ventricular ejection fraction is determined by which of the...

    Correct

    • Calculation of the left ventricular ejection fraction is determined by which of the following equations?

      Your Answer: Stroke volume / end diastolic LV volume

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      20.6
      Seconds
  • Question 31 - Regarding anaesthetic breathing circuits, which one would be the best for spontaneous breathing?...

    Correct

    • Regarding anaesthetic breathing circuits, which one would be the best for spontaneous breathing?

      Your Answer: Lack circuit

      Explanation:

      Among the breathing circuits, the Lack circuit is the most efficient for spontaneous breathing.

      An outer coaxial tube is present to deliver fresh air; exhaust air is routed to an inner tube, which is then delivered to a scavenging system. An expiratory valve is seen at the patient end, which is an advantage over other circuits. Moreover, the Lack circuit prevents rebreathing slightly greater than the alveolar minute ventilation at 4-5 litres per minute.

      The Bain circuit prevents rebreathing at 160-200ml/kg per minute, and is a co-axial version of the Mapleson D circuit.

      The Mapleson E circuit prevent rebreathing at a fresh gas flow (FGF) of approximately twice the patient’s normal minute volume. A modification of this, the Mapleson F, has a reservoir bag at the opposite end for the FGF. This circuit is appropriate for paediatric patients with a body weight less than 20 kg.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      3.8
      Seconds
  • Question 32 - Which of the following statement regarding Adrenaline (Epinephrine) is not true? ...

    Incorrect

    • Which of the following statement regarding Adrenaline (Epinephrine) is not true?

      Your Answer: Stimulates lipolysis in adipose tissue

      Correct Answer: Inhibits glycolysis in muscle

      Explanation:

      Adrenaline acts on α1, α2, β1, and β2 receptors and also on dopamine receptors (D1, D2) and have sympathomimetic effects.

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

      Adrenaline is a sympathomimetic amine with both alpha and beta-adrenergic stimulating properties.
      Adrenaline is the drug of choice for anaphylactic shock
      Adrenaline is also used in patients with cardiac arrest. The preferred route is i.v. followed by the intra-osseous and endotracheal route.

      Adrenaline is released by the adrenal glands, acts on α 1 and 2, β 1 and 2 receptors, and is responsible for fight or flight response.

      It acts on β 2 receptors in skeletal muscle vessels-causing vasodilation.

      It acts on α adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.

      It acts on β adrenergic receptors to stimulate glucagon secretion in the pancreas
      It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue

    • This question is part of the following fields:

      • Pharmacology
      6.3
      Seconds
  • Question 33 - Regarding metal wires, which of the following is the most important determinant of...

    Correct

    • Regarding metal wires, which of the following is the most important determinant of their resistance?

      Your Answer: Resistivity

      Explanation:

      Electrical resistivity is a measure of a material’s property to oppose the flow of electric current. This is expressed in Ohm-meters (Ω‹…m). The symbol of resistivity is usually the Greek letter Ï� (rho). A high resistivity means that a material does not conduct electric charge well.

      Electrical resistivity is defined as the relation between the electric field inside a material, and the electric current through it as a consequence:

      � = E/J

      in which Ï� is the resistivity of the material (Ω‹…m),
      E is the magnitude of the electrical field in the material (V/m),
      J is the magnitude of the electric current density in the material (A/m2)

      If the electric field (E) through a material is very large and the flow of current (J) is very small, it means that the material has a high resistivity.

    • This question is part of the following fields:

      • Basic Physics
      6.2
      Seconds
  • Question 34 - About low molecular weight (LMW) heparin, Which of these is true? ...

    Correct

    • About low molecular weight (LMW) heparin, Which of these is true?

      Your Answer: Is excreted in the urine

      Explanation:

      Low molecular weight heparin (LMWH) creates a complex by binding to antithrombin. This complex binds with and inactivates factor Xa.

      There is less risk of bleeding with LMWH because it binds less to platelets, endothelium and von Willebrand factor.

      LMW binds Xa more readily. The shorter chains are less likely to bind both antithrombin and thrombin.

      There is need for monitoring in renal impairment because LMHW is excreted in the urine (and partly by hepatic metabolism)

      LMWH have been shown to be as efficacious as unfractionated heparin. It is also safer and have improved inpatient stay and reduced hospital cost.

    • This question is part of the following fields:

      • Pharmacology
      47.5
      Seconds
  • Question 35 - A 60-year-old man, with a history of excessive alcohol intake, presents for the...

    Incorrect

    • A 60-year-old man, with a history of excessive alcohol intake, presents for the first time in the emergency department with acute abdominal pain in the epigastric region. On examination, the man is sweating and has a high-grade fever. His heart rate is 140/min and a BP of 92/59 mmHg. The patient is diagnosed with acute pancreatitis. Which of the following is a complication you are most likely to see in this patient?

      Your Answer: Bulky, greasy stools

      Correct Answer: Blue discolouration of the flank regions

      Explanation:

      Bulky, greasy stools are associated with improper digestion that can be expected if the pancreas loses its exocrine function. This is common in long-term chronic pancreatitis but since this is the patient’s first presentation with such symptoms, this complication is unlikely.

      Peripheral neuropathy is a common complication of chronic diabetes but has been reported with cases of chronic pancreatitis too.

      Abdominal distention with shifting dullness is a classic symptom of underlying ascites. Ascites is a complication of many diseases but it is not common with the acute first-time presentation of pancreatitis.

      Option E: This points towards abdominal obstruction but in the absence of the more common symptoms, nausea and bilious vomiting, this is unlikely.

      Option A: Grey Turner’s sign is the pooling of blood in the retroperitoneal space between the last rib and the top of the hip. The pancreas is a retroperitoneal organ and inflammation of the pancreas can cause retroperitoneal haemorrhage. The sign takes 24-48 hours to develop and can predict a severe attack of acute pancreatitis. The patient has presented with acute pancreatitis due to his history of high alcohol intake, and acute on chronic is unlikely as this is his first presentation. He also has low blood pressure and an increased heart rate, which suggest blood loss with acute pancreatitis.

    • This question is part of the following fields:

      • Anatomy
      19.7
      Seconds
  • Question 36 - All of the following statements are false regarding salmeterol except: ...

    Incorrect

    • All of the following statements are false regarding salmeterol except:

      Your Answer: Has a short onset time

      Correct Answer: Is more potent than salbutamol at the beta-2 receptor

      Explanation:

      Salmeterol is a long-acting Beta 2 selective agonist. Therefore it is only used for prophylaxis whereas salbutamol is a short-acting Beta 2 agonist and is thus used for the treatment of acute attacks of asthma.

      Salmeterol is 15 times more potent than salbutamol at the Beta 2 receptor but 4 times less potent at the Beta 1 receptor.

      Tachyphylaxis to the unwanted side effects commonly occurs, but not to bronchodilation.

    • This question is part of the following fields:

      • Pharmacology
      12
      Seconds
  • Question 37 - Very small SI units are easily expressed using mathematical prefixes. One femtolitre is...

    Correct

    • Very small SI units are easily expressed using mathematical prefixes. One femtolitre is equal to which of the following volumes?

      Your Answer: 0.000, 000, 000, 000, 001 L

      Explanation:

      Small measurement units are denoted by the following SI mathematical prefixes:

      1 deci = 0.1
      1 milli = 0.001
      1 micro = 0.000001
      1 nano = 0.000000001
      1 pico = 0.000000000001
      1 femto = 0.000000000000001 (used to measure red blood cell volume)
      1 atto = 0.000000000000000001.

    • This question is part of the following fields:

      • Basic Physics
      20.1
      Seconds
  • Question 38 - A 62-year-old woman, presents to emergency department with an ischaemic left colon. Multiple...

    Incorrect

    • A 62-year-old woman, presents to emergency department with an ischaemic left colon. Multiple arteries arise from the aorta at the level of the L3 vertebrae, which is most likely to be involved in this pathology?

      Your Answer: Superior mesenteric artery

      Correct Answer: Inferior mesenteric artery

      Explanation:

      The inferior mesenteric artery arises from the abdominal aorta at the level of the L3 vertebrae and supplies blood to the final third of the transverse colon, the descending colon, the sigmoid colon and the uppermost part of the rectum.

      It is the artery most likely to affect the left colon.

    • This question is part of the following fields:

      • Anatomy
      12.9
      Seconds
  • Question 39 - The following statement is true with regards to the Nernst equation: ...

    Correct

    • The following statement is true with regards to the Nernst equation:

      Your Answer: It is used to calculate the potential difference across a membrane when the individual ions are in equilibrium

      Explanation:

      The Nernst equation is used to calculate the membrane potential at which the ions are in equilibrium across the cell membrane.

      The normal resting membrane potential is -70 mV (not + 70 mV).

      The equation is:
      E = RT/FZ ln {[X]o
      /[X]i}

      Where:
      E is the equilibrium potential
      R is the universal gas constant
      T is the absolute temperature
      F is the Faraday constant
      Z is the valency of the ion
      [X]o is the extracellular concentration of ion X
      [X]i is the intracellular concentration of ion X.

    • This question is part of the following fields:

      • Physiology
      15.9
      Seconds
  • Question 40 - The population incidence of a disease is best described by? ...

    Correct

    • The population incidence of a disease is best described by?

      Your Answer: The number of new cases of a disease per population in a defined period

      Explanation:

      The incidence of a disease is the number of new cases of the disease in a population over a defined time period.

      The prevalence of a disease is the number of cases of the disease in a population over a defined time period describes. It is NOT the number of new cases.

      The number of new cases of a disease only, has no denominator (time period or population) from which to derive an incidence.

      The number of new cases of a disease seeking medical treatment is the incidence of patients seeking medical treatment NOT the incidence of the disease in a population.

      The death rate from a disease is the number of patients dying from the disease in a population.

    • This question is part of the following fields:

      • Statistical Methods
      13.8
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Anatomy (3/10) 30%
Pathophysiology (4/5) 80%
Pharmacology (4/9) 44%
Physiology (2/3) 67%
Statistical Methods (2/3) 67%
Basic Physics (3/3) 100%
Clinical Measurement (2/2) 100%
Anaesthesia Related Apparatus (3/3) 100%
Physiology And Biochemistry (1/2) 50%
Passmed