-
Question 1
Correct
-
A 16-year old boy is brought to the emergency room after suffering a traffic accident. Upon examination, there is noted ipsilateral loss of proprioception and vibration, ipsilateral motor loss, and contralateral loss of pain and temperature sensation. A spinal cord injury is given as a diagnosis.Which of the following is the most probable cause of this manifestation?
Your Answer: Brown-Séquard syndrome
Explanation:Brown-Sequard Hemicord Syndrome consists of ipsilateral weakness (corticospinal tract) and loss of joint position and vibratory sense (posterior column), with contralateral loss of pain and temperature sense (spinothalamic tract) one or two levels below the lesion. Segmental signs, such as radicular pain, muscle atrophy, or loss of a deep tendon reflex, are unilateral. Partial forms are more common than the fully developed syndrome.
-
This question is part of the following fields:
- Anatomy
- Central Nervous System
-
-
Question 2
Incorrect
-
The causative organism for an infection in a patient you are reviewing is a facultative anaerobe.Which of these is a facultative anaerobic organism?
Your Answer: Mycobacterium tuberculosis
Correct Answer: Staphylococcus aureus
Explanation:Facultative anaerobic bacteria make energy in the form of ATP by aerobic respiration in an oxygen rich environment and can switch to fermentation in an oxygen poor environment.Examples of facultative anaerobes are:Staphylococcus spp.Listeria spp.Streptococcus spp.Escherichia coliMycobacterium tuberculosis, and Pseudomonas aeruginosa are obligate aerobe. They require oxygen to growCampylobacter jejuni and Clostridium spp are obligate anaerobes.They live and grow in the absence of oxygen.
-
This question is part of the following fields:
- Microbiology
- Principles Of Microbiology
-
-
Question 3
Incorrect
-
A 58-year-old man with a long history of depression presents with a deliberate overdose of verapamil tablets, which he is prescribed for a heart condition.What is verapamil's mechanism of action?
Your Answer: N-type calcium channel blockade
Correct Answer: L-type calcium channel blockade
Explanation:Overdosing on calcium-channel blockers should always be taken seriously and regarded as potentially fatal. Verapamil and diltiazem are the two most lethal calcium channel blockers in overdose. These work by binding the alpha-1 subunit of L-type calcium channels, preventing calcium from entering the cell. In cardiac myocytes, vascular smooth muscle cells, and islet beta-cells, these channels play an important role.The standard ABC approach should be used to resuscitate all patients as needed. If life-threatening toxicity is expected, intubation and ventilation should be considered early on. If hypotension and shock are developing, early invasive blood pressure monitoring is recommended.The primary goal of specific treatments is to support the cardiovascular system. These are some of them:1. Fluid resuscitation: Give up to 20 mL of crystalloid per kilogramme of body weight.2. Calcium supplementationThis can be a good way to raise blood pressure and heart rate temporarily.via central venous access: 10% calcium gluconate 60 mL IV (0.6-1.0 mL/kg in children) or 10% calcium chloride 20 mL IV (0.2 mL/kg in children)Boluses can be given up to three times in a row.To keep serum calcium >2.0 mEq/L, consider a calcium infusion.3. Atropine: 0.6 mg every 2 minutes up to 1.8 mg is an option, but it is often ineffective.4. HIET (high-dose insulin-euglycemic therapy):The role of HIET in the step-by-step management of cardiovascular toxicity has changed.5. Vasoactive infusions:This was once thought to be a last-ditch measure, but it is now widely recommended that it be used sooner rather than later.Insulin with a short half-life 50 mL of 50 percent glucose IV bolus plus 1 U/kg bolus (unless marked hyperglycaemia present)Short-acting insulin/dextrose infusions should be continued.Glucose should be checked every 20 minutes for the first hour, then hourly after that.Regularly check potassium levels and replace if they fall below 2.5 mmol/L.Titrate catecholamines to effect (inotropy and chronotropy); options include dopamine, adrenaline, and/or noradrenaline infusions.6. Sodium bicarbonate: Use 50-100 mEq sodium bicarbonate (0.5-1.0 mEq/kg in children) in cases where a severe metabolic acidosis develops.7. Cardiac pacing: It can be difficult to achieve electrical capture, and it may not improve overall perfusion.Bypass AV blockade with ventricular pacing, which is usually done at a rate of less than 60 beats per minute.8. Intralipid transportCalcium channel blockers are lipid-soluble agents, so they should be used in refractory cases.
-
This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
-
-
Question 4
Incorrect
-
After collapsing at home, a 75-year-old man is transported in an ambulance. He is now awake, but he is experiencing palpitations and chest pain. He is transported to resuscitation and placed on a cardiac monitor, which indicates that he is in VT. An amiodarone infusion is set up.Which of the following statements about amiodarone side effects is correct?
Your Answer: It causes shortening of the QT interval
Correct Answer: It can cause jaundice
Explanation:Amiodarone has a lot of potential toxic side effects, so it’s important to get a full clinical evaluation before starting treatment with it.The following are some of the most common amiodarone side effects:ArrhythmiasCorneal microdepositsHepatic disordersHyperthyroidismHypothyroidismHepatic disorders and jaundiceNauseaPeripheral neuropathyRespiratory disorders (including lung fibrosis)Sleep disturbanceSkin reactionsQT prolongationAmiodarone can cause optic neuritis, which is a very rare side effect. If this happens, the amiodarone should be stopped right away because it poses a risk of blindness.Most people who take amiodarone develop corneal microdeposits, which go away once the medication is stopped and rarely cause vision problems.Amiodarone has a chemical structure that is similar to that of thyroxine and can bind to the nuclear thyroid receptor. It can cause both hypothyroidism and hyperthyroidism, though hypothyroidism is far more common, with 5-10% of patients suffering from it.
-
This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
-
-
Question 5
Incorrect
-
A 65-year-old man comes for a visit at the clinic with complaints of abdominal pain. On inquiring about drug history, you find out that he has been taking around 8-10 paracetamol to help relieve the pain. Out of the following, which one is believed to be the main mechanism of action for paracetamol?
Your Answer:
Correct Answer: Selective inhibition of COX-3 receptors
Explanation:The FDA categorizes Paracetamol as an NSAID (nonsteroidal anti-inflammatory drug) as it is believed to selectively inhibit cyclo-oxygenase 3 (COX-3) receptors in the brain and spinal cord. COX-3 is a unique variant of the more known COX-1 and COX-2. It is responsible for the production of prostaglandins in central areas, which sensitizes free nerve endings to the chemical mediators of pain. Therefore, by selectively inhibiting COX-3, paracetamol effectively reduces pain sensation by increasing the pain threshold.Acetaminophen does not inhibit cyclooxygenase in peripheral tissues and, therefore, has no peripheral anti-inflammatory effects.The antipyretic actions of acetaminophen are likely attributed to direct action on heat-regulating centres in the brain, resulting in peripheral vasodilation, sweating, and loss of body heat.
-
This question is part of the following fields:
- CNS Pharmacology
- Pharmacology
-
-
Question 6
Incorrect
-
Which of the following is NOT a common myeloma laboratory finding:
Your Answer:
Correct Answer: Elevated serum Bence-Jones protein
Explanation:Myeloma laboratory findings include:- The presence of a paraprotein in serum or urine (the paraprotein is IgG in 60 percent of cases, IgA in 20 percent, and light chain only in almost all the rest),- Increased serum immunoglobulin-free light chain proteins generated by plasma cells but not coupled with heavy chains – Reduced IgG, IgA, and IgM levels in the blood (immune paresis)- Anaemia, whether normochromic, normocytic, or macrocytic. – On a blood film, a Rouleaux formation has been marked. – In advanced illness, neutropenia and thrombocytopenia are common. – ESR is high. – Plasma cells in the bone marrow are overabundant, typically in aberrant forms. – Hypercalcemia- Creatinine levels are high. – Serum albumin levels are low in advanced illness. 60 percent of patients have osteolytic lesions, osteoporosis, or pathological fractures.
-
This question is part of the following fields:
- Haematology
- Pathology
-
-
Question 7
Incorrect
-
Which of the following is NOT a typical clinical feature of sickle cell disease:
Your Answer:
Correct Answer: Neutropaenia
Explanation:Features of sickle cell disease include:Anaemia (symptoms are usually mild because the O2 dissociation curve of Hb S is shifted to the right)Vaso-occlusive crisisVisceral sequestration crisisAplastic crisisIncreased susceptibility to infectionOther clinical features: Pigment gallstones with cholecystitisChronic leg ulcersAvascular necrosis of the femoral and humeral heads or other bonesCardiomyopathyPulmonary hypertensionProliferative retinopathyPriapismRenal papillary necrosisStroke
-
This question is part of the following fields:
- Haematology
- Pathology
-
-
Question 8
Incorrect
-
Following a decrease in extracellular volume, which of the following is a reaction to enhanced sympathetic innervation of the kidney:
Your Answer:
Correct Answer: Release of renin
Explanation:The RAS pathway begins with renin cleaving its substrate, angiotensinogen (AGT), to produce the inactive peptide, angiotensin I, which is then converted to angiotensin II by endothelial angiotensin-converting enzyme (ACE). ACE activation of angiotensin II occurs most extensively in the lung. Angiotensin II mediates vasoconstriction as well as aldosterone release from the adrenal gland, resulting in sodium retention and increased blood pressure.
-
This question is part of the following fields:
- Physiology
- Renal
-
-
Question 9
Incorrect
-
Which of the following laboratory findings is NOT typical of von Willebrand disease (VWD):
Your Answer:
Correct Answer: Thrombocytopaenia
Explanation:Laboratory findings typically show (although this varies depending on VWD type):Abnormal PFA-100 testLow factor VIII levels (if low a factor VIII/VWF binding assay is performed)Prolonged APTT (or normal)Normal PTLow VWF levelsDefective platelet aggregationNormal platelet count
-
This question is part of the following fields:
- Haematology
- Pathology
-
-
Question 10
Incorrect
-
A diagnosis of acute osteomyelitis was made on a patient with a known history of sickle cell disease. He has no joint prosthesis on in-dwelling metal work and no known drug allergies.Which of the following is most likely the causative agent of the case presented above?
Your Answer:
Correct Answer: Salmonella spp .
Explanation:Patients with sickle cell disease are prone to infection of the bone and bone marrow in areas of infarction and necrosis. Although Staphylococcus aureus is the most common cause of osteomyelitis in the general population, studies have shown that in patients with sickle cell disease, the relative incidence of Salmonella osteomyelitis is twice that of staphylococcal infection.
-
This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
-
-
Question 11
Incorrect
-
The following statements are not true of the flexor digiti minimi brevis, except?
Your Answer:
Correct Answer: It is situated on the radial border of abductor digiti minimi
Explanation:Flexor digiti minimi brevis muscle is located on the ulnar side of the palm, lying on the radial border of the abductor digiti minimi. Together with the abductor digiti minimi and opponens digiti minimi muscles, it forms the hypothenar eminence. The muscle is situated inferior and lateral to adductor digiti minimi muscle and superior and medial to opponens digiti minimi muscle. The proximal parts of flexor digiti minimi brevis and abductor digiti minimi muscles form a gap through which deep branches of the ulnar artery and ulnar nerve pass.
-
This question is part of the following fields:
- Anatomy
- Upper Limb
-
-
Question 12
Incorrect
-
A 23-year-old has a known diagnosis of HIV. Blood is sent to the laboratory for tests.AIDS be diagnosed at a CD4 counts below?
Your Answer:
Correct Answer: 200 cells/mm 3
Explanation:A normal CD4 count ranges from 500-1000 cells/mm3.At CD4 count of less than 350 cells/mm3 treatment with anti-retroviral therapy should be considered.At a CD4 count of >200 cells/mm3 AIDS is diagnosed.
-
This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
-
-
Question 13
Incorrect
-
In patients requiring oxygen, who are at risk of hypercapnic respiratory failure, oxygen saturations should be maintained at:
Your Answer:
Correct Answer: 88 - 92%
Explanation:A lower target of 88 – 92% oxygen saturation is indicated for patients at risk of hypercapnic respiratory failure e.g. patients with COPD. Until blood gases can be measured, initial oxygen should be given using a controlled concentration of 28% or less, titrated towards the SpO2 of 88 – 92%. The aim is to provide the patient with enough oxygen to achieve an acceptable arterial oxygen tension without worsening carbon dioxide retention and respiratory acidosis.
-
This question is part of the following fields:
- Pharmacology
- Respiratory
-
-
Question 14
Incorrect
-
A 5 day old, full term neonate is with a unilateral purulent eye discharge noticed earlier that day is brought in. On gram stain of the exudate, no bacteria are seen. What is the most likely causative pathogen?
Your Answer:
Correct Answer: Chlamydia trachomatis
Explanation:Conjunctivitis occurring in the first 28 days of life (Ophthalmia neonatorum) is most commonly caused by Chlamydia trachomatis in the UK.
-
This question is part of the following fields:
- Microbiology
- Pathogens
-
-
Question 15
Incorrect
-
Which of the following muscles laterally rotates the hip?
Your Answer:
Correct Answer: Gluteus maximus
Explanation:External (lateral) rotation at the hip joint is produced by the gluteus maximus together with a group of 6 small muscles (lateral rotators): piriformis, obturator internus, superior and inferior gemelli, quadratus femoris and obturator externus.
-
This question is part of the following fields:
- Anatomy
- Lower Limb
-
-
Question 16
Incorrect
-
You suspect that your patient with polycystic kidney disease has developed a berry aneurysm as a complication of his disease. The patient complains of a sudden, severe headache. You are guessing subarachnoid haemorrhage secondary to a ruptured berry aneurysm as the cause of his severe headaches. What is the most likely location of his aneurysm?
Your Answer:
Correct Answer: Anterior communicating artery
Explanation:One of the complications that polycystic kidney disease may cause is the development of a brain aneurysm. A berry aneurysm is the most common type of brain aneurysm. The Circle of Willis, where the major blood vessels meet at the base of the brain, is where it usually appears. The most common junctions of the Circle of Willis where an aneurysm may occur include the anterior communicating artery (35%), internal carotid artery (30%), the posterior communicating artery and the middle cerebral artery (22%), and finally, the posterior circulation sites, most commonly the basilar artery tip.
-
This question is part of the following fields:
- Anatomy
- Central Nervous System
-
-
Question 17
Incorrect
-
An analytical study is conducted to compare the risk of stroke between Ticagrelor therapy and Warfarin therapy among patients with atrial fibrillation. The following is obtained from the study:No. of patients who took Ticagrelor: 300No. of patients who took Ticagrelor and suffered a stroke: 30No. of patients who took Warfarin: 500No. of patients who took Warfarin and suffered a stroke: 20Compute for the absolute risk in the Ticagrelor group.
Your Answer:
Correct Answer: 0.1
Explanation:The absolute risk (AR) is the probability or chance of an event. It is computed as the number of events in treated or control groups, divided by the number of people in that group.AR = 30/300 = 0.1
-
This question is part of the following fields:
- Evidence Based Medicine
-
-
Question 18
Incorrect
-
You see a patient in the ED with photophobia, petechial rash, headache and neck stiffness, and suspect a diagnosis of meningococcal meningitis.What is the most appropriate initial management?
Your Answer:
Correct Answer: Give ceftriaxone 2 g IV
Explanation:Treatment should be commenced with antibiotics immediately before laboratory confirmation due to the potentially life-threatening nature of the disease.In a hospital setting, 2g of IV ceftriaxone (80 mg/kg for a child) or IV cefotaxime (2 g adult; 80 mg/kg child) are the drugs of choice. In the prehospital setting, IM benzylpenicillin can be given as an alternative.
-
This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
-
-
Question 19
Incorrect
-
An elderly female has a bacterial infection and you are asked to prescribe an antibiotic to her. This antibiotic is a nucleic acid synthesis inhibitor.Which of the following antimicrobial drugs will be prescribed to this patient?
Your Answer:
Correct Answer: Metronidazole
Explanation:Metronidazole and the other 5-nitroimidazole agents inhibit nucleic acid synthesis by forming toxic free radical metabolites in the bacterial cell that damage DNA. Vancomycin inhibits cell wall peptidoglycan formation by binding the D-Ala-D-Ala portion of cell wall precursors. Erythromycin inhibits protein synthesis and blocks translocation by binding to the 23S rRNA of the 50S ribosomal subunit.Chloramphenicol blocks peptidyl transferase at 50S ribosomal subunit.Gentamicin, an aminoglycoside antibiotic, acts by binding to the 30S subunit of the bacterial ribosome inhibiting the binding of aminoacyl-tRNA and thus preventing initiation of protein synthesis.An overview of the different mechanisms of action of the various types of antimicrobial agents is shown below:1. Inhibition of cell wall synthesis- Penicillins- Cephalosporins- Vancomycin2. Disruption of cell membrane function- Polymyxins- Nystatin- Amphotericin B3. Inhibition of protein synthesis- Macrolides- Aminoglycosides- Tetracyclines- Chloramphenicol4. Inhibition of nucleic acid synthesis- Quinolones- Trimethoprim- 5-nitroimidazoles- Rifampicin5. Anti-metabolic activity- Sulphonamides- Isoniazid
-
This question is part of the following fields:
- Infections
- Pharmacology
-
-
Question 20
Incorrect
-
Regarding fibrinolytics, which of the following statements is INCORRECT:
Your Answer:
Correct Answer: Fibrinolytic drugs act as thrombolytics by directly degrading the fibrin mesh and so breaking up thrombi.
Explanation:Fibrinolytic drugs act as thrombolytics by activating plasminogen to form plasmin, which degrades fibrin and so breaks up thrombi.
-
This question is part of the following fields:
- Cardiovascular
- Pharmacology
-
-
Question 21
Incorrect
-
Question 22
Incorrect
-
A 56-year-old man presents with pneumonia 8 days after being admitted for an open fracture of his tibia and fibula. Upon history taking and observation, it was established that he has no known drug allergies, has coarse left basal crackles and evidence of consolidation in the left lower lobe based on his chest X-ray.Which of the following antibacterial agents would be the most appropriate to prescribe according to the latest NICE guidelines?
Your Answer:
Correct Answer: Ciprofloxacin
Explanation:The current NICE guidelines for hospital-acquired pneumonia are as follow:- First-choice oral antibiotic if non‑severe symptoms or signs, and not at higher risk of resistance (guided by microbiological results when available): co-amoxiclav- Alternative oral antibiotics if non‑severe symptoms or signs, and not at higher risk of resistance, for penicillin allergy or if co‑amoxiclav unsuitable (based on specialist microbiological advice and local resistance data): doxycycline, cefalexin, co-trimoxazole, levofloxacin- First-choice intravenous antibiotics if severe symptoms or signs (for example, symptoms or signs of sepsis) or at higher risk of resistance (based on specialist microbiological advice and local resistance data): piperacillin with tazobactam, ceftazidime, ceftriaxone, cefuroxime, meropenem, ceftazidime with avibactam, levofloxacin- Antibiotics to be added if suspected or confirmed methicillin-resistant Staphylococcus aureus infection (dual therapy with a first-choice intravenous antibiotic): vancomycin, teicoplanin, linezolid
-
This question is part of the following fields:
- Microbiology
- Principles Of Microbiology
-
-
Question 23
Incorrect
-
Vitamin D is a group of secosteroids that play a role in calcium and phosphate control. Vitamin D's hormonally active metabolite is 1,25-dihydroxycholecalciferol.Which of the following actions of 1,25-dihydroxycholecalciferol is a direct action?
Your Answer:
Correct Answer: Increases renal phosphate reabsorption
Explanation:The hormone-active metabolite of vitamin D is 1,25-dihydroxycholecalciferol (commonly known as calcitriol). Its activities raise calcium and phosphate levels in the bloodstream.The following are the primary effects of 1,25-dihydroxycholecalciferol:Calcium and phosphate absorption in the small intestine is increased.Calcium reabsorption in the kidneys is increased.Increases phosphate reabsorption in the kidneys.Increases the action of osteoclastic bacteria (increasing calcium and phosphate resorption from bone)Inhibits the action of 1-alpha-hydroxylase in the kidneys (negative feedback)Thyroid hormone (parathyroid hormone) Calcium reabsorption in the tubules of the kidneys is increased, but renal phosphate reabsorption is decreased.
-
This question is part of the following fields:
- Endocrine Physiology
- Physiology
-
-
Question 24
Incorrect
-
At rest, saliva is produced predominantly by which of the following:
Your Answer:
Correct Answer: Submandibular gland
Explanation:At rest, most saliva is produced by the submandibular gland (65%). When stimulated by the autonomic nervous system, about 50% of saliva is produced by the parotid gland with only 30% produced by the submandibular gland.
-
This question is part of the following fields:
- Gastrointestinal
- Physiology
-
-
Question 25
Incorrect
-
Regarding cytotoxic T cells, which of the following statements is CORRECT:
Your Answer:
Correct Answer: They kill target cells by inducing cell apoptosis.
Explanation:CD8+ T-cells (Cytotoxic T cells)Recognise antigen only in association with HLA Class I molecules (found on all nucleated cells; present endogenous antigens such as those found in cells infected by viruses or intracellular bacteria.)Comprise about 25% of peripheral T-cellsResponsible for cytotoxic killing of target cells
-
This question is part of the following fields:
- Immune Responses
- Pathology
-
-
Question 26
Incorrect
-
The second generation antihistamine, cetirizine is a less-sedating antihistamine than the older antihistamine, chlorphenamine because:
Your Answer:
Correct Answer: It is less lipid-soluble so less able to cross the blood brain barrier.
Explanation:All older antihistamines such as chlorphenamine cause sedation. The newer antihistamines e.g. cetirizine cause less sedation and psychomotor impairment than the older antihistamines because they are much less lipid soluble and penetrate the blood brain barrier only to a slight extent.
-
This question is part of the following fields:
- Pharmacology
- Respiratory
-
-
Question 27
Incorrect
-
In the small intestine, there is a deep gap between each villus that leads to the crypt of Lieberkühn, a tubular intestinal gland.What is the primary function of these glands?
Your Answer:
Correct Answer: Production of an alkaline intestinal juice
Explanation:In the small intestine, there is a deep gap between each villus that leads to the crypt of Lieberkühn, a tubular intestinal gland. These glands create an alkaline intestinal juice that is a mixture of water and mucus with a pH of 7.4-7.8. Intestinal juice is released in a volume of 1-2 litres per day in response to distention of the small intestine or the irritating effects of chyme on the intestinal mucosa.
-
This question is part of the following fields:
- Gastrointestinal Physiology
- Physiology
-
-
Question 28
Incorrect
-
Gastrin release from antral G-cells is inhibited by all but which one of the following:
Your Answer:
Correct Answer: Vagal stimulation
Explanation:Gastrin secretion is inhibited by:Low gastric pH (negative feedback mechanism)SomatostatinSecretinGastric inhibitory polypeptide (GIP)Cholecystokinin
-
This question is part of the following fields:
- Gastrointestinal
- Physiology
-
-
Question 29
Incorrect
-
Which of the following is NOT a function of the commensal intestinal bacterial flora:
Your Answer:
Correct Answer: Breakdown of haem into bilirubin
Explanation:Commensal intestinal bacterial flora have a role in:Keeping pathogenic bacteria at bay by competing for space and nutrientConverting conjugated bilirubin to urobilinogen (some of which is reabsorbed and excreted in urine) and stercobilinogen which is excreted in the faecesThe synthesis of vitamins K, B12, thiamine and riboflavinThe breakdown of primary bile acids to secondary bile acidsThe breakdown of cholesterol, some food additives and drugs
-
This question is part of the following fields:
- Gastrointestinal
- Physiology
-
-
Question 30
Incorrect
-
The juxtacapillary receptors, or J receptors, are sensory cells that play an important role in the control of respiration.At which of the following anatomical sites are the J receptors located? Select ONE answer only.
Your Answer:
Correct Answer: The alveolar walls
Explanation:Juxtacapillary receptors (J receptors) are sensory cells that are located within the alveolar walls in juxtaposition to the pulmonary capillaries of the lung.The J receptors are innervated by the vagus nerve and are activated by physical engorgement of the pulmonary capillaries or increased pulmonary interstitial volume, for example, in the presence of pulmonary oedema, pulmonary embolus, pneumonia and barotraumas. They may also be stimulated by hyperinflation of the lung.Stimulation of the J receptors causes a reflex increase in breathing rate and is also thought to be involved in the sensation of dyspnoea. The reflex response that is produced is apnoea, followed by rapid breathing, bradycardia, and hypotension.
-
This question is part of the following fields:
- Physiology
- Respiratory Physiology
-
00
Correct
00
Incorrect
00
:
00
:
00
Session Time
00
:
00
Average Question Time (
Secs)