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  • Question 1 - All of the following options describes a thermistor for the measurement of temperature...

    Incorrect

    • All of the following options describes a thermistor for the measurement of temperature except:

      Your Answer: Resistance in metals show a linear increase with temperature in a Platinum resistance thermometer

      Correct Answer: Resistance of the bead increases exponentially as the temperature increases

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      49.2
      Seconds
  • Question 2 - Gag reflex was assessed as a part of brain stem death in a...

    Correct

    • Gag reflex was assessed as a part of brain stem death in a 22-year-old man with severe traumatic brain injury. Which of the following nerves forms the afferent limb of this reflex?

      Your Answer: Glossopharyngeal nerve

      Explanation:

      The gag reflex is a protective mechanism that prevents any foreign material to enter the aerodigestive tract.

      This reflex has afferent (sensory) and effect (motor) components.
      – Glossopharyngeal nerve form the afferent limb
      – Vagus nerve form the efferent limb.

    • This question is part of the following fields:

      • Pathophysiology
      25
      Seconds
  • Question 3 - Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart...

    Correct

    • Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart in patients with suspected heart failure. The aim is to measure the ejection fraction, but to do that, the stroke volume must first be measured. How is stroke volume calculated?

      Your Answer: End diastolic volume - end systolic volume

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      71.4
      Seconds
  • Question 4 - Regarding the following induction agents, which one is cleared at the fastest rate...

    Correct

    • Regarding the following induction agents, which one is cleared at the fastest rate from the plasma?

      Your Answer: Propofol

      Explanation:

      Propofol is cleared at the fastest rate at the rate of 60ml/kg/min.

      Clearance rate of other drugs are as follows:
      – Thiopental: 3.5 ml/kg/min
      – Methohexitone: 11 ml/kg/min
      – Ketamine: 17 ml/kg/min
      – Etomidate: 10-20 ml/kg/min

    • This question is part of the following fields:

      • Pharmacology
      4.2
      Seconds
  • Question 5 - Work is underway to devise a new breast cancer screen testing method that...

    Correct

    • Work is underway to devise a new breast cancer screen testing method that doesn't involve mammography which is in contrast to the prevailing standard. The initial numbers look promising and are indicating that the new testing method is better able to pick up early stage cancer. There, however, is not substantial difference in survival rates. Which of the following term can be used to describe this?

      Your Answer: Lead-time bias

      Explanation:

      Work up bias involves comparing the novel diagnostic test with the current standard test. A portion of the patients undergo the standard test while others undergo the new test as the standard test is costly. The result can be alteration in specify and sensitivity.

      Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.

      Not publishing the results of a valid study just because they are negative or uninteresting can be termed as publication bias.

      When information gathering is ill suited with respect to time i.e. collecting the data regarding a fatal disease many years after the death of its patients, it is termed as Late – look bias.

      The case in point is an instance of lead time bias when upon comparing two tests, one is able to detect the condition earlier than the other but the overall outcome doesn’t change. There is a possibility that this will make the survival rates for the newer test look more promising.

    • This question is part of the following fields:

      • Statistical Methods
      8
      Seconds
  • Question 6 - A 20-year-old male student is admitted to ER after sustaining a crush injury...

    Correct

    • A 20-year-old male student is admitted to ER after sustaining a crush injury of the pelvis. Clinical examination is as follows: Airway: Patent Breathing: RR: 25 breaths per minute, breath sounds vesicular, nil added. Circulation: Capillary refill time = 4 seconds, cool peripheries. Pulse: 125 beats per minute, BP: 125/96 mmHg. Disability: Glasgow coma score 15,|Anxious and in pain. Secondary survey does not reveal any other significant injuries. The patient is given high flow oxygen therapy and intravenous access is established. Which one of the following options is the most appropriate initial route of intravenous access?

      Your Answer: Left cephalic vein

      Explanation:

      The clinical signs suggest a class II haemorrhage – 15-30% of circulating blood volume has been lost.

      Pelvic fractures are associated with significant concealed haemorrhage (>2000 ml) and may require aggressive fluid resuscitation. Other priorities include stabilisation of the fracture(s) and pain relief.

      The Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock is as follows:

      Class I haemorrhage (blood loss up to 15%):
      40% blood volume loss):
      Preterminal event patient will die in minutes
      Marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure (or unobtainable diastolic pressure)
      Mental state is markedly depressed
      Skin cold and pale
      Need rapid transfusion and immediate surgical intervention.

      Loss of >50% results in loss of consciousness, pulse and blood pressure.

      The route of choice is an arm vein (cephalic) with one or two large bore cannula. This will enable initial aggressive fluid resuscitation. A central line can be inserted at a later stage if central venous monitoring is deemed necessary. If a suitable peripheral vein cannot be cannulated with a large bore cannula then the internal jugular vein could be accessed rapidly (preferably ultrasound guided).

      Intravenous access below the diaphragm in this case is inadvisable when other routes are available.

    • This question is part of the following fields:

      • Anatomy
      148.1
      Seconds
  • Question 7 - You're summoned to the emergency room, where a 39-year-old man has been admitted...

    Correct

    • You're summoned to the emergency room, where a 39-year-old man has been admitted following a cardiac arrest. He was rescued from a river, but little else is known about him. CPR is being performed on the patient, who has been intubated. He's received three DC shocks and is still in VF. A rectal temperature of 29.5°C is taken with a low-reading thermometer. Which of the following statements about his resuscitation is correct?

      Your Answer: No further DC shocks and no drugs should be given until his core temperature is greater than 30°C

      Explanation:

      The guidelines for the management of cardiac arrest in hypothermic patients published by the UK Resuscitation Council differ slightly from the standard algorithm.

      In a patient with a core temperature of less than 30°C, do the following:

      If you’re on the shockable side of the algorithm (VF/VT), you should give three DC shocks.
      Further shocks are not recommended until the patient has been rewarmed to a temperature of more than 30°C because the rhythm is refractory and unlikely to change.
      There should be no drugs given because they will be ineffective.

      In a patient with a core temperature of 30°C to 35°C, do the following:

      DC shocks are used as usual.
      Because they are metabolised much more slowly, the time between drug doses should be doubled.

      Active rewarming and protection against hyperthermia should be given to the patient.

      Option e is false because there is insufficient information to determine whether resuscitation should be stopped.

    • This question is part of the following fields:

      • Physiology
      11.4
      Seconds
  • Question 8 - A sevoflurane vaporiser with a 2 percent setting and a 200 kPa ambient...

    Incorrect

    • A sevoflurane vaporiser with a 2 percent setting and a 200 kPa ambient pressure is used. At this pressure, which of the following options best represents vaporiser output?

      Your Answer: The output remains at 2% because the splitting ratio remains the same

      Correct Answer: The output is 1% because the saturated pressure of sevoflurane is unaffected by ambient pressure

      Explanation:

      Ambient pressure has no effect on a volatile agent’s saturated vapour pressure (SVP). At a temperature of 20°C, the SVP of sevoflurane is approximately 21 kPa, or 21% of atmospheric pressure (100 kPa).

      The SVP of sevoflurane remains the same when the ambient pressure is doubled to 200 kPa, but the output of the vaporiser is halved, now 21 percent of 200 kPa, equalling 10.5 percent. The vaporiser’s output has increased to 1%, but the partial pressure output has remained unchanged. The splitting ratio will not change because it is determined by temperature changes.

      Calculations can be made as follows:

      Vaporizer output % (ambient pressure) = % volatile (calibrated) x 100 kPa calibrated pressure/ambient pressure
      2% = 2% (dialled) × 100/100
      2% of 100 = 2 kPa

      Altitude, pressure 50 kPa
      4% = 2% (dialled) × 100/50
      4% of 50 = 2 kPa

      High pressure at 200 kPa
      1% = 2% (dialled) × 100/200
      1% of 200 = 2 kPa

      Sevoflurane has a boiling point of 58°C and, unlike desflurane (which has a boiling point of 22.8°C), does not need to be heated and pressurised with a Tec 6 vaporiser.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      27.6
      Seconds
  • Question 9 - Regarding amide local anaesthetics, which one factor has the most significant effect on...

    Correct

    • Regarding amide local anaesthetics, which one factor has the most significant effect on its duration of action?

      Your Answer: Protein binding

      Explanation:

      When drugs are bound to proteins, drugs cannot cross membranes and exert their effect. Only the free (unbound) drug can be absorbed, distributed, metabolized, excreted and exert pharmacologic effect. Thus, when amide local anaesthetics are bound to α1-glycoproteins, their duration of action are reduced.

      The potency of local anaesthetics are affected by lipid solubility. Solubility influences the concentration of the drug in the extracellular fluid surrounding blood vessels. The brain, which is high in lipid content, will dissolve high concentration of lipid soluble drugs. When drugs are non-ionized and non-polarized, they are more lipid-soluble and undergo more extensive distribution. Hence allowing these drugs to penetrate the membrane of the target cells and exert their effect.

      Tissue pKa and pH will determine the degree of ionization.

    • This question is part of the following fields:

      • Physiology
      5.9
      Seconds
  • Question 10 - Which of the following statement is correct regarding the difference between dabigatran and...

    Correct

    • Which of the following statement is correct regarding the difference between dabigatran and other anticoagulants?

      Your Answer: Competitive thrombin inhibitor blocking both free and bound thrombin

      Explanation:

      Dabigatran template is a prodrug and its active metabolite is a direct thrombin inhibitor. It is a synthetic, reversible, non-peptide thrombin inhibitor. This inhibition of thrombin results in a decrease of fibrin and reduces platelet aggregation.

      Drugs like warfarin act by inhibiting the activation of vitamin K-dependent clotting factors. These factors are synthesized by the liver and activated by gamma-carboxylation of glutamate residues with the help of vitamin K. Hydroquinone form of vitamin K is converted to epoxide form in this reaction and regeneration of hydroquinone form by enzyme vitamin K epoxide reductase (VKOR) is required for this activity. Oral anticoagulants prevent this regeneration by inhibiting VKOR, thus vitamin K-dependent factors are not activated. These factors include clotting factors II, VII, IX, and X as well as anti-clotting proteins, protein C and protein S.

    • This question is part of the following fields:

      • Pharmacology
      6.3
      Seconds
  • Question 11 - Which statement is true when describing carbonic anhydrase? ...

    Incorrect

    • Which statement is true when describing carbonic anhydrase?

      Your Answer: Is present in the plasma

      Correct Answer: Isoenzyme IV is found in the brush border of the proximal convoluted tubule

      Explanation:

      Carbonic anhydrase is an enzyme which contains zinc and can be found in:
      1. Erythrocytes
      2. Pulmonary endothelium
      3. The intestine
      4. Pancreas
      5. Cardiac muscle and skeletal muscle.

      To date, there have been seven isoenzymes identified. Of note, isoenzyme IV is found in the brush border of the proximal convoluted tubule and isoenzyme II is found within the luminal cells.

      Acetazolamides a carbonic anhydrase inhibitor and is used as prophylaxis against mountain sickness and in glaucoma management.

      Spironolactone is a potassium diuretic and is an aldosterone antagonist.

    • This question is part of the following fields:

      • Physiology
      10.9
      Seconds
  • Question 12 - A 60-year old male has anaemia and is being investigated. The most common...

    Correct

    • A 60-year old male has anaemia and is being investigated. The most common combination of globin chains in a normal adult is:

      Your Answer: α2β2

      Explanation:

      There are 4 different types of globin chains which surround 4 heme molecules in haemoglobin (Hb) – α, β, γ and δ.
      α chains are essential.
      δ2β2 and β2γ2 are not found in a healthy adult.
      97% of the Hb in a healthy adult is made of α2β2 (2 α chains and 2 β chains).
      α2δ2 accounts for around 1.5-3% of the adult Hb.
      α2γ2 accounts for less than 1%.

      With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.

      Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain.
      There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions.
      The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.

      The oxygen dissociation curve (ODC) describes the relationship between the percentage of saturated haemoglobin and partial pressure of oxygen in the blood.
      Of note, it is not affected by haemoglobin concentration.

      Chronic anaemia causes 2, 3 DPG levels to increase, hence shifting the curve to the right

      Haldane effect – Causes the ODC to shift to the left. For a given oxygen tension there is increased saturation of Hb with oxygen i.e. Decreased oxygen delivery to tissues.
      This can be caused by:
      -HbF, methaemoglobin, carboxyhaemoglobin
      -low [H+] (alkali)
      -low pCO2
      -ow 2,3-DPG
      -ow temperature

      Bohr effect – causes the ODC to shifts to the right = for given oxygen tension there is reduced saturation of Hb with oxygen i.e. Enhanced oxygen delivery to tissues. This can be caused by:
      – raised [H+] (acidic)
      – raised pCO2
      -raised 2,3-DPG
      -raised temperature

    • This question is part of the following fields:

      • Physiology And Biochemistry
      15.9
      Seconds
  • Question 13 - An 81-year old man was admitted to the Pulmonology Ward due to chronic...

    Correct

    • An 81-year old man was admitted to the Pulmonology Ward due to chronic obstructive airway disease (COPD) exacerbation. Upon physical examination, he was hypertensive at 140/90 mmHg, tachycardic at 114 beats per minute, and tachypnoeic at 33 breaths per minute. Arterial blood gas analysis was obtained and showed the following results: pH: 7.25 (Reference range: 7.35-7.45), PaO2: 73 mmHg (9.7 kPa) (Reference range: 11.3-12.6 kPa), PaCO2: 56 mmHg (7.5 kPa) (Reference range: 4.7-6.0 kPa), SaO2: 90%, Standard bicarbonate: 29 mmol/L (Reference range: 20-28), BE: +4 mmol/L (± 2). Which of the following options has the most significant impact on his respiratory rate?

      Your Answer: CSF pH

      Explanation:

      The arterial blood gas analysis indicates presence of acute respiratory acidosis.

      Central chemoreceptors are located in the ventral medulla and respond directly to presence of hydrogen ions in the CSF. When stimulated, it causes an increase in respiratory rate.

      It is believed that hydrogen ions may be the only important direct stimulus for these neurons, however, CO2 is believed to stimulate these neurons secondarily by changing the hydrogen ion concentration.

      Changes in O2 concentration have virtually no direct effect on the respiratory centre itself to alter respiratory drive. Although, O2 changes do have an indirect effect by acting through the peripheral chemoreceptors.

    • This question is part of the following fields:

      • Pathophysiology
      14.2
      Seconds
  • Question 14 - In the fetal circulation, the cerebral and coronary circulations are preferentially supplied by...

    Incorrect

    • In the fetal circulation, the cerebral and coronary circulations are preferentially supplied by oxygen-rich blood over other organs. This is possible because of which phenomenon?

      Your Answer: The pulmonary vascular resistance is very high and therefore a majority of blood passes from the right side of the heart through the ductus arteriosus

      Correct Answer: Well oxygenated blood from the inferior vena cava is preferentially streamed across the patent foramen ovale

      Explanation:

      During fetal development, blood oxygenated by the placenta flows to the foetus through the umbilical vein, bypasses the fetal liver through the ductus venosus, and returns to the fetal heart through the inferior vena cava.

      Blood returning from the inferior vena cava then enters the right atrium and is preferentially shunted to the left atrium through the patent foramen ovale. Blood in the left atrium is then pumped from the left ventricle to the aorta. The oxygenated blood ejected through the ascending aorta is preferentially directed to the fetal coronary and cerebral circulations.

      Deoxygenated blood returns from the superior vena cava to the right atrium and ventricle to be pumped into the pulmonary artery. Fetal pulmonary vascular resistance (PVR), however, is higher than fetal systemic vascular resistance (SVR); this forces deoxygenated blood to mostly bypass the fetal lungs. This poorly oxygenated blood enters the aorta through the patent ductus arteriosus and mixes with the well-oxygenated blood in the descending aorta. The mixed blood in the descending aorta then returns to the placenta for oxygenation through the two umbilical arteries.

    • This question is part of the following fields:

      • Physiology
      57.3
      Seconds
  • Question 15 - Which of the following explains the mode of action of Magnesium sulphate in...

    Incorrect

    • Which of the following explains the mode of action of Magnesium sulphate in preventing eclampsia in susceptible patients?

      Your Answer: Increasing the convulsive threshold by NMDA receptor antagonism

      Correct Answer: Dilatation of cerebral circulation due to calcium channel antagonism reducing cerebral vascular spasm

      Explanation:

      Magnesium is a unique calcium antagonist as it can act on most types of calcium channels in vascular smooth muscle and as such would be expected to decrease intracellular calcium. One major effect of decreased intracellular calcium would be inactivation of calmodulin-dependent myosin light chain kinase activity and decreased contraction, causing arterial relaxation that may subsequently lower peripheral and cerebral vascular resistance, relieve vasospasm, and decrease arterial blood pressure.

      The vasodilatory effect of MgSO4 has been investigated in a wide variety of vessels. For example, both in vivo and in vitro animal studies have shown that it is a vasodilator of large conduit arteries such as the aorta, as well as smaller resistance vessels including mesenteric, skeletal muscle, uterine, and cerebral arteries.

      The theory of cerebrovascular vasospasm as the aetiology of eclampsia seemed to be reinforced by transcranial Doppler (TCD) studies which suggested that MgSO4 treatment caused dilation in the cerebral circulation as well as in animal studies that used large cerebral arteries.

    • This question is part of the following fields:

      • Pathophysiology
      8.8
      Seconds
  • Question 16 - According to the statements given which one is most correct concerning the spinal...

    Correct

    • According to the statements given which one is most correct concerning the spinal cord?

      Your Answer: There are 31 pairs of spinal roots

      Explanation:

      The cylindrical structure(spine), starts from the foramen magnum in medulla oblongata at the skull’s base. Its length varies in gender with men having 45cm and women having up to 43 cm. The spine contains 31 pairs of spinal nerves, named according to the spinal region:
      – 8 cervical nerve pairs ( C1-C8)
      – 12 thoracic nerve pairs ( T1-T12)
      – 5 lumbar nerve pairs (L1-L5)
      – 5 sacral nerves (S1-S5) and
      – 1 coccygeal nerve pair.
      These spinal nerves are classified as the peripheral nervous system though they branch from the spinal cord and central nervous system. They interact directly with the spinal cord to modulate the motor and sensory information from the peripheral’s region. As the nerves emerges form the spinal cords they are known as rootlets. They join to form nerve roots, and depending on their position, we have anterior nerve roots and posterior.

      The spinal cord is supplied by two posterior and one anterior spinal arteries which anastomoses caudally, at the conus medullaris.

      The anterior spinal artery supplies the anterior two-thirds of the spinal cord and medulla. Disruption of the anterior spinal artery supply is characterised by ischaemia or infarction of motor tracts (corticospinal) and loss of pain and temperature sensation below the level of the lesion.

      The posterior spinal arteries supply the posterior columns (posterior third of the spinal cord). Infarction of the posterior columns results in the loss of proprioceptive, vibration and two-point discrimination.

      The spinal cord normally ends at the level of L1 or L2 in an adult and L3 in a newborn.

    • This question is part of the following fields:

      • Anatomy
      10.4
      Seconds
  • Question 17 - The following haemodynamic data is available from a patient with pulmonary artery catheter...

    Correct

    • The following haemodynamic data is available from a patient with pulmonary artery catheter inserted: Pulse rate - 100 beats per minute, Blood pressure - 120/70mmHg, Mean central venous pressure (MCVP) - 10mmHg, Right ventricular pressure (RVP) - 30/4 mmHg, Mean pulmonary artery wedge pressure (MPAWP) - 12mmHg. Which value best approximates the patient's coronary perfusion pressure?

      Your Answer: 58mmHg

      Explanation:

      Coronary perfusion pressure(CPP), the difference between aortic diastolic pressure (Pdiastolic) and the left ventricular end-diastolic pressure (LVEDP), is mainly determined by the formula:

      CPP = Pdiastolic -LVEDP
      where
      Pdiastolic is the lowest pressure in the aorta before left ventricular ejection and
      LVEDP is measured directly during a cardiac catheterisation or indirectly using a pulmonary artery catheter. The pulmonary artery occlusion or wedge pressure approximates best with LVEDP.

      Using this patient’s haemodynamic data:

      CPP = Pdiastolic – MPAWP
      COO = 70 – 12 = 58mmHg.

    • This question is part of the following fields:

      • Clinical Measurement
      5.5
      Seconds
  • Question 18 - Very large SI units are easily expressed using mathematical prefixes. One terabyte is...

    Incorrect

    • Very large SI units are easily expressed using mathematical prefixes. One terabyte is equal to which of the following numbers?

      Your Answer: 1,000,000,000,000,000 bytes

      Correct Answer: 1,000,000,000,000 bytes

      Explanation:

      To denote large measured units, the following SI mathematical prefixes are used:

      1 deca = 10 bytes (101)
      1 hecto (h) = 100 bytes
      1 kilo (k)= 1,000 bytes
      1 mega (M) = 1,000,000 bytes
      1 giga (G) = 1,000,000,000 bytes
      1 Tera (T) = 1,000,000,000,000 bytes
      1 Peta (P) = 1,000,000,000,000,000 bytes.

    • This question is part of the following fields:

      • Basic Physics
      3.5
      Seconds
  • Question 19 - Clearance techniques are used to assess renal glomerular function. Which of the following...

    Correct

    • Clearance techniques are used to assess renal glomerular function. Which of the following is the most accurate marker for glomerular filtration rate measurement?

      Your Answer: Inulin

      Explanation:

      The perfect glomerular filtration marker is:

      The human body is not harmed by it.
      Chemical or physical methods are used to accurately measure
      Extracellular fluid (ECF) compartment is freely and evenly diffusible.
      Inability to access the intracellular fluid (ICF) compartment
      Filtration in the kidney is the only way to remove it from the blood.

      The ideal marker should not be reabsorbed into the bloodstream by the renal tubules or other urinary system components.

      Creatinine is an endogenous substance that is filtered freely by the glomerulus and secreted by the proximal tubule. As a result, creatinine clearance consistently underestimates GFR. In healthy people, this overestimation ranges from 10% to 40%, but it is higher and more unpredictable in patients with chronic kidney disease.

      The gold standard method of inulin clearance necessitates an intravenous infusion and several hours of timed urine collection, making it costly and time-consuming. Inulin is hard to come by and is difficult to mix and keep as a solution.

      Exogenous filtration markers include the following:

      Although plasma clearance of 51chromium EDTA is a widely used method in Europe, tubular reabsorption can occur.
      Because 125I-iothalamate can be excreted by renal tubules in the urine, it cannot be used in patients who have an iodine assay.

      Radioactive substances must be stored, administered, and disposed of according to these methods.

      The glomerulus filters para-aminohippuric acid (PAH) freely, and any that remains in the peritubular capillaries is secreted into the proximal convoluted tubules. This marker is used to determine the amount of blood flowing through the kidneys.

    • This question is part of the following fields:

      • Pathophysiology
      33.7
      Seconds
  • Question 20 - Which statement best describes the bispectral index (BIS)? ...

    Correct

    • Which statement best describes the bispectral index (BIS)?

      Your Answer: It decreases during normal sleep

      Explanation:

      The bispectral index (BIS) is one of several systems used in anaesthesiology as of 2003 to measure the effects of specific anaesthetic drugs on the brain and to track changes in the patient’s level of sedation or hypnosis. It is a complex mathematical algorithm that allows a computer inside an anaesthesia monitor to analyse data from a patient’s electroencephalogram (EEG) during surgery. It is a dimensionless number (0-100) that is a summative measurement of time domain, frequency domain and high order spectral parameters derived from electroencephalogram (EEG) signals.

      Sleep and anaesthesia have similar behavioural characteristics but are physiologically different but BIS monitors can be used to measure sleep depth. With increasing sleep depth during slow-wave sleep, BIS levels decrease. This correlates with changes in regional cerebral blood flow when measured using positron emission tomography (PET).

      BIS shows a dose-response relationship with the intravenous and volatile anaesthetic agents. Opioids produce a clinical change in the depth of sedation or analgesia but fail to produce significant changes in the BIS. Ketamine increases CMRO2 and EEG activity.

      BIS is unable to predict movement in response to a surgical stimulus. Some of these are spinal reflexes and not perceived by the cerebral cortex.

      BIS is used during cardiopulmonary bypass to measure depth of anaesthesia and an index of cerebral perfusion. However, it cannot predict subtle or significant cerebral damage.

    • This question is part of the following fields:

      • Physiology
      6.9
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Clinical Measurement (1/2) 50%
Pathophysiology (3/4) 75%
Physiology And Biochemistry (2/2) 100%
Pharmacology (2/2) 100%
Statistical Methods (1/1) 100%
Anatomy (2/2) 100%
Physiology (3/5) 60%
Anaesthesia Related Apparatus (0/1) 0%
Basic Physics (0/1) 0%
Passmed