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Question 1
Correct
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You review a sick patient in resus who has been prescribed mannitol as part of his treatment protocol.Which SINGLE statement regarding mannitol is true?
Your Answer: It is irritant to veins and causes phlebitis
Explanation:Mannitol is a low molecular weight compound and is therefore freely filtered at the glomerulus and is not reabsorbed. It, therefore, increases the osmolality of the glomerular filtrate and tubular fluid, increasing urinary volume by an osmotic effect. It also does not cross the blood-brain barrier (BBB).Mannitol is primarily used to reduce the pressure and volume of cerebrospinal fluid (CSF). It decreases the volume of CSF by:Decreasing the rate of CSF formation,and;Withdrawing extracellular fluid from the brain across the BBBOther uses of mannitol include:Short-term management of glaucomaTreatment of rhabdomyolysisPreserve renal function in peri-operative jaundiced patientsTo initiate diuresis in transplanted kidneysBowel preparation prior to colorectal proceduresThe recommended dose of mannitol for the reduction of CSF pressure/cerebral oedema is 0.25-2g/kg as an intravenous infusion over 30-60 minutes. This can be repeated 1-2 times after 4-8 hours if needed.Circulatory overload and rebound increases in intracranial pressure may occur following the use of mannitol. It is irritant to tissues and veins and can cause inflammation and phlebitis.Mannitol causes an expansion of the extracellular fluid space, which may worsen congestive cardiac failure. Contraindications to the use of mannitol include:AnuriaIntracranial bleeding (except during craniotomy)Severe cardiac failureSevere dehydrationSevere pulmonary oedema
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This question is part of the following fields:
- Cardiovascular Pharmacology
- Pharmacology
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Question 2
Correct
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A 25-year-old girl just got back from a trip to Northern India. She complains of headaches and intermittent fever. The fever starts with intense chills, then feels very hot, followed by profuse sweating. She is drowsy and is running a fever of 39.0°C. On examination, there are no palpable lymph nodes or rash seen. She has hepatosplenomegaly. Which one of the following is the most likely diagnosis?
Your Answer: Malaria
Explanation:Malaria is a protozoal infection of red blood cells and the liver. It is caused by the parasite belonging to the genus Plasmodium. It is transmitted by the female mosquito Anopheles.Several species with distinct features:P. vivax/P. ovaleP. malariaeP. falciparumThe common symptoms of malaria are:Paroxysms of fever – a cyclical occurrence of:1) a cold phase – the patient experiences intense chills2) a hot stage – the patient feels extremely hot3) a sweating stage – the fever declines and the patient sweats profusely- Fever recurs at regular intervals (48hrs, 72hrs): Variable by species of PlasmodiumAnaemia (RBC infection)- Severity varies by species of Plasmodium- Haemolytic: sometimes jaundiceSplenomegalyAlso nonspecific symptoms:- Sweating- fatigue- malaise- arthralgias- headache- Sometimes cough, vomiting, diarrhoea
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This question is part of the following fields:
- Microbiology
- Specific Pathogen Groups
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Question 3
Correct
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Many of the chemical digestion and absorption takes place in the small intestine. Most digestive enzymes in the small intestine are secreted by the pancreas and enter the small intestine through the pancreatic duct.Which of these digestive enzymes is responsible for breaking down lipids into fatty acid and glycerol?
Your Answer: Pancreatic lipase
Explanation:The principal enzyme involved in lipid digestion is pancreatic lipase. It breaks down triglycerides into free fatty acids and monoglycerides. Pancreatic lipase works with the help of emulsifying agents secreted by the liver and the gallbladder. The main emulsifying agents are the bile acids, cholic acid and chenodeoxycholic acid. These are conjugated with the amino acids glycine and taurine to form bile salts. Bile salts are more soluble than bile acids and act as detergents to emulsify lipids. The free fatty acids and monoglycerides form tiny particles with these bile salts called micelles. The outer region of the micelle is water-attracting (hydrophilic), whereas the inner core is water-repelling (hydrophobic). This arrangement allows the micelles to enter the aqueous layers surrounding the microvilli and free fatty acids and monoglycerides to diffuse passively into the small intestinal cells.Pancreatic amylase breaks down some carbohydrates (notably starch) into oligosaccharides. Chymotrypsin is a proteolytic enzyme that aids in digestion of proteinCarboxypeptidase hydrolyses the first peptide or amide bond at the carboxyl or C-terminal end of proteins and peptides
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This question is part of the following fields:
- Gastrointestinal Physiology
- Physiology
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Question 4
Incorrect
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What type of visual field defect are you most likely to see in a lesion of the parietal optic radiation:
Your Answer: Contralateral homonymous hemianopia
Correct Answer: Contralateral homonymous inferior quadrantanopia
Explanation:A lesion of the parietal optic radiation will result in a contralateral homonymous inferior quadrantanopia.A lesion of the temporal optic radiation will result in a contralateral homonymous superior quadrantanopia.
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This question is part of the following fields:
- Anatomy
- Central Nervous System
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Question 5
Incorrect
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Many of the chemical digestion and absorption takes place in the small intestine. Most digestive enzymes in the small intestine are secreted by the pancreas and enter the small intestine through the pancreatic duct.Which of these digestive enzymes is responsible for breaking down carbohydrates into monosaccharides?
Your Answer: Chymotrypsin
Correct Answer: Glucoamylase
Explanation:Majority of carbohydrates are broken down into monosaccharides (glucose, fructose galactose) and are absorbed by the small intestine. Enzymes released from the brush border break down carbohydrate. Some carbohydrates, such as cellulose, are not digested at all, despite being made of multiple glucose units. This is because the cellulose is made out of beta-glucose that makes the inter-monosaccharide bindings different from the ones present in starch, which consists of alpha-glucose. Humans lack the enzyme for splitting the beta-glucose-bond.The principal brush border enzymes are dextranase and glucoamylase. Other brush border enzymes are maltase, sucrase, and lactase.Pancreatic amylase breaks down some carbohydrates (notably starch) into oligosaccharides. Dextranase and glucoamylase, then further break down oligosaccharides.Trypsin aids in digestion of protein.Chymotrypsin is a proteolytic enzyme that digests proteinCarboxypeptidase hydrolyses the first peptide or amide bond at the carboxyl or C-terminal end of proteins and peptides
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This question is part of the following fields:
- Gastrointestinal Physiology
- Physiology
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Question 6
Correct
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A patient presents to ED complaining of a purulent discharge, urethral discomfort and dysuria. You suspect gonorrhoea. Which of the following cell components produced by Neisseria gonorrhoeae is responsible for attachment to host cells:
Your Answer: Pili
Explanation:Infection of the genital mucosa by Neisseria gonorrhoeae involves attachment to and invasion of epithelial cells. Initial adherence of gonococci to columnar epithelial cells is mediated by type IV pili assembled from pilin subunit PilE proteins and pilus tip-associated PilC proteins, it then invades the epithelial layer, triggering a local acute inflammatory response.
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This question is part of the following fields:
- Microbiology
- Pathogens
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Question 7
Incorrect
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Which of the following best describes a natural killer cell:
Your Answer: A professional antigen presenting cell that is important for normal T helper cell function.
Correct Answer: A large granular lymphocyte that kills by inducing target cell apoptosis.
Explanation:Natural killer (NK) cells are cytotoxic CD8 positive cells that lack the T-cell receptor. They are large cells with cytoplasmic granules. NK cells are designed to kill target cells that have a low level of expression of HLA class I molecules, such as may occur during viral infection or on a malignant cell. NK cells do this by displaying several receptors for HLA molecules on their surface. When HLA is expressed on the target cell these deliver an inhibitory signal into the NK cell. When HLA molecules are absent on the target cell this inhibitory signal is lost and the NK cell can then kill its target. In addition, NK cells display antibody-dependent cell-mediated cytotoxicity. In this, antibody binds to antigen on the surface of the target cell and then NK cells bind to the Fc portion of the bound antibody and kill the target cell.
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This question is part of the following fields:
- Immune Responses
- Pathology
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Question 8
Correct
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Regarding gas exchange at the alveolar-capillary membrane, which of the following statements is CORRECT:
Your Answer: The rate of diffusion in lungs can be estimated by measuring the diffusing capacity of the lungs for carbon monoxide.
Explanation:Gas exchange between alveolar air and blood in the pulmonary capillaries takes place by diffusion across the alveolar-capillary membrane. Diffusion occurs from an area of high partial pressure to an area of low partial pressure, thus the driving force for diffusion is the alveolar-capillary partial pressure gradient. Diffusion occurs across a membrane and is therefore governed by Fick’s law. Although CO2is larger than O2, it is is much more soluble and diffuses 20 times more rapidly. The diffusing capacity for oxygen (DLO2) cannot be measured directly but the rate of diffusion in the lungs can be estimated by measuring the diffusing capacity of the lungs for carbon monoxide (DLCO).
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This question is part of the following fields:
- Physiology
- Respiratory
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Question 9
Incorrect
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Which of the following statements is not true regarding ion channels?
Your Answer: Differences in membrane potential can affect whether voltage-gated ion channels receptors open or close.
Correct Answer: Ion channels provide a charged, hydrophobic pore through which ions can diffuse across the lipid bilayer.
Explanation:Ion channels are pore-forming protein complexes that facilitate the flow of ions across the hydrophobic core of cell membranes. They are present in the plasma membrane and membranes of intracellular organelles of all cells, and perform essential physiological functions. They provide a charged, hydrophilic pore through which ions can move across the lipid bilayer. They are selective for particular ions and their pores may be opened or closed. Because of this ability to open and close, ion channels allow the cell to have the ability to closely control the movement of ions across the membrane. Gating refers to the transition between an open and closed ion channel state, and is brought about by a conformationational change in the protein subunits that open or close the ion-permeable pore. Ion channels can be:1. voltage-gated these are regulated according to the potential difference across the cell membrane or2. ligand-gated – these are regulated by the presence of a specific signal molecule.
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This question is part of the following fields:
- Basic Cellular
- Physiology
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Question 10
Incorrect
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For which of the following infections is phenoxymethylpenicillin (penicillin V) primarily used?
Your Answer: Infective endocarditis
Correct Answer: Streptococcal tonsillitis
Explanation:Phenoxymethylpenicillin (penicillin V) is less active than benzylpenicillin but both have similar antibacterial spectrum. Because penicillin V is gastric-acid stable, it is suitable for oral administration, but should not be used for serious infections as absorption can be unpredictable and plasma concentrations can be variable. Its uses are:1. mainly for respiratory tract infections in children2. for streptococcal tonsillitis 3. for continuing treatment after one or more injections of benzylpenicillin when clinical response has begun. 4. for prophylaxis against streptococcal infections following rheumatic fever and against pneumococcal infections following splenectomy or in sickle-cell disease. It should not be used for meningococcal or gonococcal infections.
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This question is part of the following fields:
- Infections
- Pharmacology
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Question 11
Incorrect
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Langhans giant cells, seen in granulomatous inflammation. are:
Your Answer: Specialised dendritic cells found in skin
Correct Answer: Multinucleated cells formed from fusion of epithelioid cells
Explanation:A granuloma is a collection of five or more epithelioid macrophages, with or without attendant lymphocytes and fibroblasts; epithelioid macrophages are altered macrophages which have turned themselves over to becoming giant phagocytosing and killing machines, they often fuse to become multinucleate (Langhans) giant cells.
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This question is part of the following fields:
- Inflammatory Responses
- Pathology
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Question 12
Correct
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Which type of collagen is initially laid down in early wound healing:
Your Answer: III
Explanation:Fibroblasts migrate to the wound (about 2 – 5 days after wounding), proliferate and secrete extracellular matrix comprising mainly collagen (type III) and fibronectin to plug the gap.
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This question is part of the following fields:
- Pathology
- Wound Healing
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Question 13
Incorrect
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A 30-year-old woman was involved in a road traffic accident and had a class I haemorrhage.Which physiological parameter is consistent with a diagnosis of class I haemorrhage?
Your Answer: 25% of blood volume lost
Correct Answer: Increased pulse pressure
Explanation:There are 4 classes of haemorrhage. Classification is based on clinical signs and physiological parameters.In CLASS I:Blood loss (ml) is < or = 750Blood loss(% blood volume) < or = 15%Pulse rate (bpm) is 30Pulse pressure is normal or increasedSystolic BP is normalCNS/mental status patient is slightly anxious In CLASS II:Blood loss (ml) is 750 – 1500Blood loss(% blood volume) is 15 – 30%Pulse rate (bpm) is 100 – 120Respiratory rate is 20-30Urine output (ml/hr) is 20-30Pulse pressure is decreasedSystolic BP is normalCNS/mental status patient is mildly anxiousIn CLASS III:Blood loss (ml) is 1500 – 2000Blood loss(% blood volume) is 30- 40%Pulse rate (bpm) is 120 – 140Respiratory rate is 30-40Urine output (ml/hr) is 5-15Pulse pressure is decreasedSystolic BP is decreasedCNS/mental status patient is anxious, confusedIn CLASS IV:Blood loss (ml) is >2000Blood loss(% blood volume) is >40%Pulse rate (bpm) is >140Respiratory rate is >40Urine output (ml/hr) is negligiblePulse pressure is decreasedSystolic BP is decreasedCNS/mental status patient is confused, lethargic
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This question is part of the following fields:
- Cardiovascular Physiology
- Physiology
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Question 14
Incorrect
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Which of the following presentations is NOT consistent with the diagnosis of anaphylaxis following exposure to a known allergen:
Your Answer: Hypotension alone
Correct Answer: Generalised urticaria and angioedema alone
Explanation:Anaphylaxis is characterised by sudden onset and rapidly developing, life-threatening airway, breathing and circulation problems associated with skin and/or mucosal changes. Reactions can vary greatly, from hypotension alone, to reactions with predominantly asthmatic features, to cardiac/respiratory arrest. Skin or mucosal changes may be absent or subtle in up to 20% of cases but skin or mucosal changes alone are not a sign of an anaphylactic reaction.
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This question is part of the following fields:
- Pharmacology
- Respiratory
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Question 15
Correct
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A 54-year-old man who is acutely unwell has his blood sent for test and the results come back with a CRP of 115.Which of these statements about C-reactive protein is FALSE?
Your Answer: It is produced in the bone marrow
Explanation:C-reactive protein(CRP) is synthesized in the liver in response to increased interleukin-6 (IL-6) secretion by macrophages and T-cells. Some conditions that cause CRP levels to a rise include: bacterial infection, fungal infection, severe trauma, autoimmune disease, Organ tissue necrosis, malignancy and surgery.It is useful in the clinical setting as a marker of inflammatory activity and can be used to monitor infections. CRP levels start to rise 4-6 hours after an inflammatory trigger and reaches peak levels at 36-50 hours.In the absence of a disease process, the normal plasma concentration is less than 5 mg/l.CRP is useful for monitoring inflammatory conditions (e.g. rheumatoid arthritis and malignancy), can be used as a prognostic marker in acute pancreatitis, and serial measurement can be used to recognize the onset of nosocomial infections in the intensive care settling.
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This question is part of the following fields:
- General Pathology
- Pathology
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Question 16
Incorrect
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Which of the following medications can block the effect of adrenaline?
Your Answer: Tricyclic antidepressants
Correct Answer: Beta-blockers
Explanation:Beta-blockers may reduce the response to adrenaline in the treatment of anaphylactic reactions. Noncardioselective beta-blockers in particular can antagonize the broncho dilating and cardio stimulatory effects of adrenaline by blocking beta-2 adrenergic receptors in the smooth muscles of the bronchial tree and in the heart muscles.
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This question is part of the following fields:
- Pharmacology
- Respiratory
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Question 17
Incorrect
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Injury to which nerve can lead to weakness or paralysis of the brachialis muscle?
Your Answer: The median nerve
Correct Answer: The musculocutaneous nerve
Explanation:The brachialis muscle is a prime flexor of the forearm at the elbow joint. It is fusiform in shape and located in the anterior (flexor) compartment of the arm, deep to the biceps brachii. The brachialis is a broad muscle, with its broadest part located in the middle rather than at either of its extremities. It is sometimes divided into two parts, and may fuse with the fibres of the biceps brachii, coracobrachialis, or pronator teres muscles. It also functions to form part of the floor of the cubital fossa.The brachialis is primarily supplied by the musculocutaneous nerve (C5, C6). In addition, a small lateral portion of the muscle is innervated by the radial nerve (C7).
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This question is part of the following fields:
- Anatomy
- Upper Limb
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Question 18
Incorrect
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The common bile duct drains into the duodenum in which of the following regions:
Your Answer: Duodenojejunal flexure
Correct Answer: Second part of the duodenum
Explanation:As the common bile duct descends, it passes posterior to the first part of the duodenum before joining with the pancreatic duct from the pancreas, forming the hepatopancreatic ampulla (ampulla of Vater) at the major duodenal papilla, located in the second part of the duodenum. Surrounding the ampulla is the sphincter of Oddi, a collection of smooth muscle which can open to allow bile and pancreatic fluid to empty into the duodenum.
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This question is part of the following fields:
- Abdomen
- Anatomy
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Question 19
Incorrect
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In the small intestine, there is a deep gap between each villus that leads to the crypt of Lieberkühn, a tubular intestinal gland.What is the primary function of these glands?
Your Answer: Secretion of cholecystokinin
Correct Answer: Production of an alkaline intestinal juice
Explanation:In the small intestine, there is a deep gap between each villus that leads to the crypt of Lieberkühn, a tubular intestinal gland. These glands create an alkaline intestinal juice that is a mixture of water and mucus with a pH of 7.4-7.8. Intestinal juice is released in a volume of 1-2 litres per day in response to distention of the small intestine or the irritating effects of chyme on the intestinal mucosa.
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This question is part of the following fields:
- Gastrointestinal Physiology
- Physiology
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Question 20
Incorrect
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Regarding the resting membrane potential, which of the following statements is CORRECT:
Your Answer: At rest the inside of the cell is positive relative to the outside.
Correct Answer: The resting cell membrane is more permeable to K + ions than to Na + ions.
Explanation:A membrane potential is a property of all cell membranes, but the ability to generate an action potential is only a property of excitable tissues. The resting membrane is more permeable to K+and Cl-than to other ions (and relatively impermeable to Na+); therefore the resting membrane potential is primarily determined by the K+equilibrium potential. At rest the inside of the cell is negative relative to the outside. In most neurones the resting potential has a value of approximately -70 mV.
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This question is part of the following fields:
- Basic Cellular
- Physiology
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Question 21
Incorrect
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A 20-year-old with type I diabetes mellitus has an episode of hypoglycaemia following inadvertent administration of too much insulin.The mechanism by which insulin causes glucose to be transported into cells is?
Your Answer: Co-transport
Correct Answer: Facilitated diffusion
Explanation:The only mechanism by which insulin facilitates uptake of glucose into cells is by facilitated diffusion through a family of hexose transporters.The major transporter used for glucose uptake is GLUT4. GLUT4 is made available in the plasma membrane by the action of insulin.When insulin concentrations are low, GLUT4 transporters are present in cytoplasmic vesicles, where they are cannot be used for transporting glucose.
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This question is part of the following fields:
- Endocrine Physiology
- Physiology
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Question 22
Incorrect
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Salbutamol should be used with caution in patients with which of the following:
Your Answer: History of tendon rupture
Correct Answer: Susceptibility to QT-interval prolongation
Explanation:Beta-2 agonists should be used with caution in people with: Cardiovascular disease, including arrhythmias and hypertension (beta-2 agonists may cause an increased risk of arrhythmias and significant changes to blood pressure and heart rate)Diabetes(risk of hyperglycaemia and ketoacidosis, especially with intravenous use)Hyperthyroidism(beta-2 agonists may stimulate thyroid activity)Hypokalaemia(potentially serious hypokalaemia may result from beta-2 agonist therapy; this effect may be potentiated in severe asthma by concomitant treatment with theophylline, corticosteroids, diuretics and by hypoxia)Susceptibility to QT-interval prolongationConvulsive disorders
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This question is part of the following fields:
- Pharmacology
- Respiratory
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Question 23
Correct
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A 36 year old man who is overweight with a history of gout, presents to emergency room with an acutely painful big toe which is red, hot and swollen. However, he is apyrexic and otherwise systemically well. He has been diagnosed with acute gout. The most appropriate first line treatment for him is which of the following?
Your Answer: NSAIDs
Explanation:The first line treatment for acute gout includes NSAIDs like diclofenac, indomethacin or naproxen. In patients in whom NSAIDs are contraindicated, not tolerated or ineffective, colchicine is an alternative. In those who cannot tolerate or who are resistant to NSAIDs and colchicine, oral or parenteral corticosteroids are an effective alternative. In acute monoarticular gout, intra-articular injection of a corticosteroid can be used occasionally. In acute gout. allopurinol is not used in the actual treatment, but its use should be continued during an acute attack if the patient is already established on long term therapy.
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This question is part of the following fields:
- Musculoskeletal
- Pharmacology
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Question 24
Incorrect
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Which of the following clinical features would you least expect to see in a lesion of the frontal lobe:
Your Answer: Incontinence
Correct Answer: Contralateral homonymous hemianopia with macular sparing
Explanation:Contralateral homonymous hemianopia with macular sparing results from damage to the primary visual cortex of the occipital lobe. Incontinence may occur due to damage of the cortical micturition centre in the prefrontal cortex. Primitive reflexes and inability to problem solve may occur due to damage to the prefrontal cortex. Motor weakness of the contralateral limb with UMN signs may occur due to damage of the primary motor cortex.
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This question is part of the following fields:
- Anatomy
- Central Nervous System
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Question 25
Incorrect
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Regarding cellular respiration, which of the following statements is CORRECT:
Your Answer: Cellular respiration is the process by which cells obtain energy in the form of AMP.
Correct Answer: When fats are used as the primary energy source, an excess of acetyl-CoA is produced.
Explanation:Cellular respiration is the process by which cells obtain energy in the form of adenosine triphosphate (ATP). ATP transfers chemical energy from the energy rich substances in the cell to the cell’s energy requiring reactions e.g. active transport, DNA replication and muscle contraction.Cellular respiration is essentially a three step process: 1) Glycolysis, 2)The Krebs cycle, 3)The electron transfer system.The main respiratory substrate used by cells is 6-carbon glucose. Fats and proteins can also be used as respiratory substrates. When fats are being used as the primary energy source, in the absence of glucose, an excess amount of acetyl-CoA is produced, and is converted into acetone and ketone bodies. This can occur in starvation, fasting or in diabetic ketoacidosis. Proteins are used as an energy source only if protein intake is very high, or if glucose and fat sources are depleted.
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This question is part of the following fields:
- Basic Cellular
- Physiology
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Question 26
Incorrect
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A 57-year-old woman receives vitamin B12 injections following a gastrectomy.Which of the following cell types, if absent, is responsible for her vitamin B12 deficiency?
Your Answer: Chief cells
Correct Answer: Parietal cells
Explanation:Intrinsic factor, produced by the parietal cells of the stomach, is essential for the absorption of vitamin B12 from the terminal ileum. After a gastrectomy, the absorption of vitamin B12 is markedly reduced, and a deficiency will occur.
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This question is part of the following fields:
- Gastrointestinal Physiology
- Physiology
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Question 27
Incorrect
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If a lesion is observed in Broca's area, which function is expected to become affected?
Your Answer: Comprehension of written language
Correct Answer: Formation of words
Explanation:The primary functions of the Broca area are both language production and comprehension. While the exact role in the production is still unclear, many believe that it directly impacts the motor movements to allow for speech. Although originally thought to only aid in speech production, lesions in the area can rarely be related to impairments in the comprehension of language. Different regions of the Broca area specialize in various aspects of comprehension. The anterior portion helps with semantics, or word meaning, while the posterior is associated with phonology, or how words sound. The Broca area is also necessary for language repetition, gesture production, sentence grammar and fluidity, and the interpretation of others’ actions.Broca’s aphasia is a non-fluent aphasia in which the output of spontaneous speech is markedly diminished and there is a loss of normal grammatical structure. Specifically, small linking words, conjunctions, such as and, or, and but, and the use of prepositions are lost. Patients may exhibit interjectional speech where there is a long latency, and the words that are expressed are produced as if under pressure. The ability to repeat phrases is also impaired in patients with Broca’s aphasia. Despite these impairments, the words that are produced are often intelligible and contextually correct. In pure Broca’s aphasia, comprehension is intact.
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This question is part of the following fields:
- Anatomy
- Central Nervous System
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Question 28
Correct
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Which of the following is NOT a typical clinical feature of diabetic ketoacidosis:
Your Answer: Cheyne–Stokes respiration
Explanation:Clinical features of DKA: Symptoms: Polyuria, polydipsia, thirst, lethargy, weight loss, nausea, vomiting, anorexia, abdominal pain, dehydration, headache, altered mental stateSigns: Dry mucous membranes, ketotic breath, tachycardia, hypotension, Kussmaul breathing, focal signs of precipitant e.g. infection
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This question is part of the following fields:
- Endocrine
- Physiology
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Question 29
Incorrect
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A 45-year-old African American male presents to your clinic complaining of swelling of his feet for the past six months. On examination, there is periorbital and pedal oedema. A 24-hour urine collection is ordered, which shows 8 g of protein. The serum cholesterol is ten mmol/L. You order a renal biopsy to confirm the diagnosis. Which one of the following findings are you most likely to see in this patient's biopsy?
Your Answer: IgA nephropathy
Correct Answer: Focal segmental glomerulosclerosis
Explanation:This patient has Nephrotic Syndrome confirmed by the presence of 1. Heavy proteinuria (greater than 3-3.5 g/24 hours)2. Hypoalbuminemia (serum albumin < 25 g/L)3. Generalised oedema (often with periorbital involvement)4. Severe hyperlipidaemia (total cholesterol is often > 10 mmol/L). Focal Segmental Glomerulosclerosis will be the most likely answer as it is the most common cause of Nephrotic Syndrome in African American adults. Minimal change disease is the most common cause of nephrotic syndrome in children. Membranous glomerulonephritis is the most common cause of Nephrotic Syndrome in Caucasian adults. In IgA nephropathy, patients will complain of cola-coloured urine. Mesangiocapillary glomerulonephritis presents with features of Nephritic Syndrome.
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This question is part of the following fields:
- General Pathology
- Pathology
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Question 30
Incorrect
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Carbamazepine is contraindicated in which of the following:
Your Answer: Pheochromocytoma
Correct Answer: Atrioventricular block
Explanation:Carbamazepine is contraindicated in:- People with known hypersensitivity to carbamazepine or structurally related drugs- People with atrioventricular block (may suppress AV conduction and ventricular automaticity)- People with a history of bone marrow depression (risk of agranulocytosis and aplastic anaemia)- People with a history of acute porphyrias- People taking a monoamine oxidase inhibitor (risk of serotonin syndrome)
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This question is part of the following fields:
- Central Nervous System
- Pharmacology
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SESSION STATS - PERFORMANCE PER SPECIALTY
