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Question 1
Correct
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A 29-year-old man with a prolonged history of alcoholism is brought to the emergency department after experiencing a prolonged seizure. Despite a thorough examination, no underlying causes of seizures are found. The attending consultant suspects that the seizure may be due to a deficiency in which vitamin, as a result of the patient's chronic alcohol consumption?
Your Answer: Vitamin B6
Explanation:The Importance of Vitamin B6 in the Body
Vitamin B6 is a type of water-soluble vitamin that belongs to the B complex group. Once it enters the body, it is converted into pyridoxal phosphate (PLP), which acts as a cofactor for various biochemical reactions such as transamination, deamination, and decarboxylation. These reactions are essential for the proper functioning of the body.
However, a deficiency in vitamin B6 can lead to various health problems such as peripheral neuropathy and sideroblastic anemia. One of the common causes of vitamin B6 deficiency is isoniazid therapy, which is used to treat tuberculosis. Therefore, it is important to ensure that the body receives an adequate amount of vitamin B6 to maintain optimal health.
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This question is part of the following fields:
- General Principles
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Question 2
Incorrect
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A patient with a history of peripheral vascular disease visits their GP with essential hypertension. Which of the following medications could worsen their peripheral vascular symptoms?
Your Answer: Spironolactone
Correct Answer: Atenolol
Explanation:Patients with peripheral vascular disease may experience worsened symptoms when taking beta-blockers, and caution should be exercised when prescribing this medication. Additionally, those with Raynaud disease may also experience aggravated symptoms. Monitoring for signs of progressive arterial obstruction is recommended.
Beta-blockers are a class of drugs that are primarily used to manage cardiovascular disorders. They have a wide range of indications, including angina, post-myocardial infarction, heart failure, arrhythmias, hypertension, thyrotoxicosis, migraine prophylaxis, and anxiety. Beta-blockers were previously avoided in heart failure, but recent evidence suggests that certain beta-blockers can improve both symptoms and mortality. They have also replaced digoxin as the rate-control drug of choice in atrial fibrillation. However, their role in reducing stroke and myocardial infarction has diminished in recent years due to a lack of evidence.
Examples of beta-blockers include atenolol and propranolol, which was one of the first beta-blockers to be developed. Propranolol is lipid-soluble, which means it can cross the blood-brain barrier.
Like all drugs, beta-blockers have side-effects. These can include bronchospasm, cold peripheries, fatigue, sleep disturbances (including nightmares), and erectile dysfunction. There are also some contraindications to using beta-blockers, such as uncontrolled heart failure, asthma, sick sinus syndrome, and concurrent use with verapamil, which can precipitate severe bradycardia.
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This question is part of the following fields:
- Cardiovascular System
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Question 3
Incorrect
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A 12-year-old boy comes to his GP complaining of a limp. He has a swollen right knee with clinical synovitis but no effusion. He is growing normally and has been generally healthy, except for experiencing diarrhoea and vomiting last week. There are no signs of joint issues in his other joints.
What condition is most likely causing his symptoms?Your Answer: Septic arthritis
Correct Answer: Reactive arthritis
Explanation:Reactive Arthritis in Children
Reactive arthritis is the most common form of arthritis in children and is often associated with recent illness. In this case, the child presents with large-joint oligoarthritis following gastroenteritis. While it may also be associated with genitourinary infection, treating the infection does not alter the course of the joint disease. The child should be given analgesia and observed for arthritis elsewhere.
Although this may be a new presentation of enteropathic arthritis or JIA, the child’s lack of chronic disease symptoms reduces the likelihood of these diagnoses. Gout is extremely rare in children, except for in rare metabolic conditions. Septic arthritis must also be considered, but the child is likely to be systemically unwell with features of infection.
In summary, reactive arthritis is the most likely diagnosis in this case of paediatric arthritis following recent illness. It is important to monitor the child’s symptoms and consider other potential diagnoses if necessary.
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This question is part of the following fields:
- Rheumatology
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Question 4
Incorrect
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A 55-year-old obese woman presents with a 4-hour history of right upper quadrant abdominal pain that started after a meal. Upon physical examination, tenderness was noted upon palpation of the right upper quadrant. An abdominal ultrasound revealed the presence of gallstones in the gallbladder. The surgeon opted for a cholecystectomy to remove the gallbladder. During the surgery, the surgeon identified the cystic duct and the inferior surface of the liver to locate the hepatobiliary triangle. What is the third border of the hepatobiliary triangle?
Your Answer: Gastroduodenal artery
Correct Answer: Common hepatic duct
Explanation:The area known as the hepatobiliary triangle is defined by three borders: the common hepatic duct on the medial side, the cystic duct on the inferior side, and the inferior edge of the liver on the superior side. This space is particularly important during laparoscopic cholecystectomy, as it allows for safe ligation and division of the cystic duct and cystic artery. It’s worth noting that the common bile duct is formed by the joining of the common hepatic duct and the cystic duct, but it is not considered one of the borders of the hepatobiliary triangle. The cystic artery, on the other hand, is located within this anatomical space. Finally, while the gastroduodenal artery does arise from the common hepatic artery, it is not one of the borders of the hepatobiliary triangle.
The gallbladder is a sac made of fibromuscular tissue that can hold up to 50 ml of fluid. Its lining is made up of columnar epithelium. The gallbladder is located in close proximity to various organs, including the liver, transverse colon, and the first part of the duodenum. It is covered by peritoneum and is situated between the right lobe and quadrate lobe of the liver. The gallbladder receives its arterial supply from the cystic artery, which is a branch of the right hepatic artery. Its venous drainage is directly to the liver, and its lymphatic drainage is through Lund’s node. The gallbladder is innervated by both sympathetic and parasympathetic nerves. The common bile duct originates from the confluence of the cystic and common hepatic ducts and is located in the hepatobiliary triangle, which is bordered by the common hepatic duct, cystic duct, and the inferior edge of the liver. The cystic artery is also found within this triangle.
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This question is part of the following fields:
- Gastrointestinal System
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Question 5
Incorrect
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A 45-year-old woman has varicose veins originating from the short saphenous vein. During mobilization of the vein near its origin, which structure is at the highest risk of injury?
Your Answer: Tibial nerve
Correct Answer: Sural nerve
Explanation:Litigation often arises from damage to the sural nerve, which is closely associated with this structure. While the other structures may also sustain injuries, the likelihood of such occurrences is comparatively lower.
Anatomy of the Popliteal Fossa
The popliteal fossa is a diamond-shaped space located at the back of the knee joint. It is bound by various muscles and ligaments, including the biceps femoris, semimembranosus, semitendinosus, and gastrocnemius. The floor of the popliteal fossa is formed by the popliteal surface of the femur, posterior ligament of the knee joint, and popliteus muscle, while the roof is made up of superficial and deep fascia.
The popliteal fossa contains several important structures, including the popliteal artery and vein, small saphenous vein, common peroneal nerve, tibial nerve, posterior cutaneous nerve of the thigh, genicular branch of the obturator nerve, and lymph nodes. These structures are crucial for the proper functioning of the lower leg and foot.
Understanding the anatomy of the popliteal fossa is important for healthcare professionals, as it can help in the diagnosis and treatment of various conditions affecting the knee joint and surrounding structures.
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This question is part of the following fields:
- Cardiovascular System
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Question 6
Incorrect
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A 49-year-old woman visits her GP complaining of low mood, fatigue, constipation, and urinary frequency. The doctor orders a standard blood test to investigate the possible cause. After reviewing the results, the GP diagnosis the woman with primary hyperparathyroidism.
What blood test results are expected for this patient?Your Answer: Raised calcium, raised phosphate
Correct Answer: Raised calcium, low phosphate
Explanation:Parathyroid hormone (PTH) is responsible for increasing plasma calcium levels and decreasing plasma phosphate levels. Hyperparathyroidism is a condition where there is an excess of PTH, either due to an overactive parathyroid gland (primary) or a low serum calcium level (secondary). Primary hyperparathyroidism results in raised calcium levels and low phosphate levels, while secondary hyperparathyroidism is typically seen in chronic kidney disease. PTH acts by increasing calcium reabsorption in the kidneys and digestive tract, as well as increasing bone resorption. This helps to prevent the formation of calcium phosphate crystals, which can cause renal stones. Symptoms of hyperparathyroidism include constipation and low mood, which are typical of hypercalcaemia.
Hormones Controlling Calcium Metabolism
Calcium metabolism is primarily controlled by two hormones, parathyroid hormone (PTH) and 1,25-dihydroxycholecalciferol (calcitriol). Other hormones such as calcitonin, thyroxine, and growth hormone also play a role. PTH increases plasma calcium levels and decreases plasma phosphate levels. It also increases renal tubular reabsorption of calcium, osteoclastic activity, and renal conversion of 25-hydroxycholecalciferol to 1,25-dihydroxycholecalciferol. On the other hand, 1,25-dihydroxycholecalciferol increases plasma calcium and plasma phosphate levels, renal tubular reabsorption and gut absorption of calcium, osteoclastic activity, and renal phosphate reabsorption. It is important to note that osteoclastic activity is increased indirectly by PTH as osteoclasts do not have PTH receptors. Understanding the actions of these hormones is crucial in maintaining proper calcium metabolism in the body.
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This question is part of the following fields:
- General Principles
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Question 7
Correct
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At which stage does the aorta divide into the left and right common iliac arteries?
Your Answer: L4
Explanation:The point of bifurcation of the aorta is typically at the level of L4, which is a consistent location and is frequently assessed in examinations.
Anatomical Planes and Levels in the Human Body
The human body can be divided into different planes and levels to aid in anatomical study and medical procedures. One such plane is the transpyloric plane, which runs horizontally through the body of L1 and intersects with various organs such as the pylorus of the stomach, left kidney hilum, and duodenojejunal flexure. Another way to identify planes is by using common level landmarks, such as the inferior mesenteric artery at L3 or the formation of the IVC at L5.
In addition to planes and levels, there are also diaphragm apertures located at specific levels in the body. These include the vena cava at T8, the esophagus at T10, and the aortic hiatus at T12. By understanding these planes, levels, and apertures, medical professionals can better navigate the human body during procedures and accurately diagnose and treat various conditions.
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This question is part of the following fields:
- Neurological System
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Question 8
Incorrect
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A 48-year-old woman presents to the clinic with complaints of abdominal pain and constipation. During the examination, you observe blue lines on the gum margin. She also reports experiencing weakness in her legs over the past few days. What is the probable diagnosis?
Your Answer: Guillain Barre syndrome
Correct Answer: Lead poisoning
Explanation:Lead poisoning is a condition that should be considered when a patient presents with abdominal pain and neurological symptoms, along with acute intermittent porphyria. This condition is caused by defective ferrochelatase and ALA dehydratase function. Symptoms of lead poisoning include abdominal pain, peripheral neuropathy (mainly motor), neuropsychiatric features, fatigue, constipation, and blue lines on the gum margin (which is rare in children and only present in 20% of adult patients).
To diagnose lead poisoning, doctors typically measure the patient’s blood lead level, with levels greater than 10 mcg/dl considered significant. A full blood count may also be performed, which can reveal microcytic anemia and red cell abnormalities such as basophilic stippling and clover-leaf morphology. Additionally, raised serum and urine levels of delta aminolaevulinic acid may be seen, which can sometimes make it difficult to differentiate from acute intermittent porphyria. Urinary coproporphyrin is also increased, while urinary porphobilinogen and uroporphyrin levels are normal to slightly increased. In children, lead can accumulate in the metaphysis of the bones, although x-rays are not typically part of the standard work-up.
Various chelating agents are currently used to manage lead poisoning, including dimercaptosuccinic acid (DMSA), D-penicillamine, EDTA, and dimercaprol. These agents work to remove the lead from the body and can help alleviate symptoms.
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This question is part of the following fields:
- Haematology And Oncology
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Question 9
Incorrect
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A 16-year-old girl visits the clinic with concerns about a possible pregnancy. She is provided with a pregnancy test, which indicates a positive result. From which part of her body would the beta-hCG, detected on the pregnancy test, have been secreted?
Your Answer: The anterior pituitary gland
Correct Answer: The placenta
Explanation:During pregnancy, the placenta produces beta-hCG, which helps to sustain the corpus luteum. This, in turn, continues to secrete progesterone and estrogen throughout the pregnancy to maintain the endometrial lining. Eventually, after 6 weeks of gestation, the placenta takes over the production of progesterone.
Endocrine Changes During Pregnancy
During pregnancy, there are several physiological changes that occur in the body, including endocrine changes. Progesterone, which is produced by the fallopian tubes during the first two weeks of pregnancy, stimulates the secretion of nutrients required by the zygote/blastocyst. At six weeks, the placenta takes over the production of progesterone, which inhibits uterine contractions by decreasing sensitivity to oxytocin and inhibiting the production of prostaglandins. Progesterone also stimulates the development of lobules and alveoli.
Oestrogen, specifically oestriol, is another major hormone produced during pregnancy. It stimulates the growth of the myometrium and the ductal system of the breasts. Prolactin, which increases during pregnancy, initiates and maintains milk secretion of the mammary gland. It is essential for the expression of the mammotropic effects of oestrogen and progesterone. However, oestrogen and progesterone directly antagonize the stimulating effects of prolactin on milk synthesis.
Human chorionic gonadotropin (hCG) is secreted by the syncitiotrophoblast and can be detected within nine days of pregnancy. It mimics LH, rescuing the corpus luteum from degenerating and ensuring early oestrogen and progesterone secretion. It also stimulates the production of relaxin and may inhibit contractions induced by oxytocin. Other hormones produced during pregnancy include relaxin, which suppresses myometrial contractions and relaxes the pelvic ligaments and pubic symphysis, and human placental lactogen (hPL), which has lactogenic actions and enhances protein metabolism while antagonizing insulin.
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This question is part of the following fields:
- Reproductive System
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Question 10
Incorrect
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An 82-year-old male patient visits their GP with a swollen and red knee joint that has been hot for the past 3 days. The patient has a medical history of diabetes and osteoarthritis, leading the GP to suspect septic arthritis. During the humoral response to an infection, what receptor is present on Helper T cells that allows them to interact with MHC II molecules on antigen-presenting cells to eliminate pathogens?
Your Answer: CD20
Correct Answer: CD4
Explanation:Helper T cells express CD4, which interacts with MHC II molecules on antigen presenting cells. CD20 is present on B cells from late pro-B cells through memory cells, but not on early pro-B cells or plasma cells. CD8 is expressed on cytotoxic T cells and binds with MHC I molecules.
The adaptive immune response involves several types of cells, including helper T cells, cytotoxic T cells, B cells, and plasma cells. Helper T cells are responsible for the cell-mediated immune response and recognize antigens presented by MHC class II molecules. They express CD4, CD3, TCR, and CD28 and are a major source of IL-2. Cytotoxic T cells also participate in the cell-mediated immune response and recognize antigens presented by MHC class I molecules. They induce apoptosis in virally infected and tumor cells and express CD8 and CD3. Both helper T cells and cytotoxic T cells mediate acute and chronic organ rejection.
B cells are the primary cells of the humoral immune response and act as antigen-presenting cells. They also mediate hyperacute organ rejection. Plasma cells are differentiated from B cells and produce large amounts of antibody specific to a particular antigen. Overall, these cells work together to mount a targeted and specific immune response to invading pathogens or abnormal cells.
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This question is part of the following fields:
- General Principles
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Question 11
Incorrect
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A 65-year-old male with a history of prostate cancer visits the neurology clinic to receive the results of his recent brain MRI. He had been experiencing severe headaches for the past four months, which is unusual for him, and has had five episodes of vomiting in the past month. The MRI scan reveals a lesion in the lateral nucleus of the hypothalamus.
What other symptom is he likely to exhibit?Your Answer: Dysdiadochokinesia
Correct Answer: Anorexia
Explanation:Anorexia can result from lesions in the lateral nucleus of the hypothalamus.
It is likely that the patient in question has a metastatic lesion from her breast in the lateral nucleus of the hypothalamus. Stimulation of this area of the thalamus increases appetite, while a lesion can lead to anorexia.
Lesions in the posterior nucleus of the hypothalamus can cause poikilothermia. This region is responsible for regulating body temperature.
The paraventricular nucleus of the hypothalamus produces oxytocin and antidiuretic hormone. Lesions in this area can result in diabetes insipidus.
Hyperphagia can be caused by lesions in the ventromedial nucleus of the thalamus. This region of the hypothalamus functions as the satiety center.
The hypothalamus is a part of the brain that plays a crucial role in maintaining the body’s internal balance, or homeostasis. It is located in the diencephalon and is responsible for regulating various bodily functions. The hypothalamus is composed of several nuclei, each with its own specific function. The anterior nucleus, for example, is involved in cooling the body by stimulating the parasympathetic nervous system. The lateral nucleus, on the other hand, is responsible for stimulating appetite, while lesions in this area can lead to anorexia. The posterior nucleus is involved in heating the body and stimulating the sympathetic nervous system, and damage to this area can result in poikilothermia. Other nuclei include the septal nucleus, which regulates sexual desire, the suprachiasmatic nucleus, which regulates circadian rhythm, and the ventromedial nucleus, which is responsible for satiety. Lesions in the paraventricular nucleus can lead to diabetes insipidus, while lesions in the dorsomedial nucleus can result in savage behavior.
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This question is part of the following fields:
- Neurological System
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Question 12
Incorrect
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A 25-year-old male suffers a fracture in his left tibia during a sports activity. During which stage of the healing process is the fracture callus expected to be visible on radiographs?
Your Answer: 6 weeks
Correct Answer: 3 weeks
Explanation:The formation of fracture callus involves the production of fibroblasts and chondroblasts, which then synthesize fibrocartilage. This process can usually be observed on X-rays after a certain period of time.
Fracture Healing: Factors and Process
When a bone is fractured, bleeding vessels in the bone and periosteum cause clot and haematoma formation. Over a week, the clot organizes and improves in structure and collagen. Osteoblasts in the periosteum produce new bone, while mesenchymal cells produce cartilage in the soft tissue around the fracture. The connective tissue and hyaline cartilage form a callus, which is bridged by endochondral ossification as new bone approaches. Trabecular bone forms, which is then resorbed by osteoclasts and replaced with compact bone.
Several factors can affect fracture healing, including age, malnutrition, bone disorders like osteoporosis, systemic disorders like diabetes, and drugs like steroids and non-steroidal anti-inflammatory agents. The type of bone, degree of trauma, vascular injury, degree of immobilization, intra-articular fractures, separation of bone ends, and infection can also impact healing.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 13
Incorrect
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As a medical student in general practice, you encounter a 68-year-old female patient who has come in for her routine blood pressure check. She informs you that she has GTN spray at home. Can you explain how nitric oxide leads to vasodilation?
Your Answer: Inhibits the release of Bradykinin
Correct Answer: Activates guanylate cyclase
Explanation:Smooth muscle relaxation and vasodilation are caused by the release of nitric oxide in response to nitrates. Nitric oxide activates guanylate cyclase, which converts GTP to cGMP. This leads to the opening of K+ channels and hyperpolarization of the cell membrane, causing the closure of voltage-gated Ca2+ channels and pumping of Ca2+ out of the smooth muscle. This results in vasodilation. Nitric oxide does not inhibit the release of Bradykinin.
Understanding Nitrates and Their Effects on the Body
Nitrates are a type of medication that can cause blood vessels to widen, which is known as vasodilation. They are commonly used to manage angina and treat heart failure. One of the most frequently prescribed nitrates is sublingual glyceryl trinitrate, which is used to relieve angina attacks in patients with ischaemic heart disease.
The mechanism of action for nitrates involves the release of nitric oxide in smooth muscle, which activates guanylate cyclase. This enzyme then converts GTP to cGMP, leading to a decrease in intracellular calcium levels. In the case of angina, nitrates dilate the coronary arteries and reduce venous return, which decreases left ventricular work and reduces myocardial oxygen demand.
However, nitrates can also cause side effects such as hypotension, tachycardia, headaches, and flushing. Additionally, many patients who take nitrates develop tolerance over time, which can reduce their effectiveness. To combat this, the British National Formulary recommends that patients who develop tolerance take the second dose of isosorbide mononitrate after 8 hours instead of 12 hours. This allows blood-nitrate levels to fall for 4 hours and maintains effectiveness. It’s important to note that this effect is not seen in patients who take modified release isosorbide mononitrate.
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This question is part of the following fields:
- Cardiovascular System
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Question 14
Incorrect
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A 23-year-old male complains of crampy abdominal pain, bloating, and diarrhea. He recently came back from a trip to Egypt where he swam in the local pool a few days ago. He reports having 5 bowel movements per day, and his stool floats in the toilet water without any blood. What is the probable cause of his symptoms?
Your Answer: Chronic pancreatitis
Correct Answer: Giardia lamblia
Explanation:Giardia can lead to the occurrence of greasy stool due to its ability to cause fat malabsorption. Additionally, it is important to note that Giardia is resistant to chlorination, which increases the risk of transmission in swimming pools.
Understanding Diarrhoea: Causes and Characteristics
Diarrhoea is defined as having more than three loose or watery stools per day. It can be classified as acute if it lasts for less than 14 days and chronic if it persists for more than 14 days. Gastroenteritis, diverticulitis, and antibiotic therapy are common causes of acute diarrhoea. On the other hand, irritable bowel syndrome, ulcerative colitis, Crohn’s disease, colorectal cancer, and coeliac disease are some of the conditions that can cause chronic diarrhoea.
Symptoms of gastroenteritis may include abdominal pain, nausea, and vomiting. Diverticulitis is characterized by left lower quadrant pain, diarrhoea, and fever. Antibiotic therapy, especially with broad-spectrum antibiotics, can also cause diarrhoea, including Clostridium difficile infection. Chronic diarrhoea may be caused by irritable bowel syndrome, which is characterized by abdominal pain, bloating, and changes in bowel habits. Ulcerative colitis may cause bloody diarrhoea, crampy abdominal pain, and weight loss. Crohn’s disease may cause crampy abdominal pain, diarrhoea, and malabsorption. Colorectal cancer may cause diarrhoea, rectal bleeding, anaemia, and weight loss. Coeliac disease may cause diarrhoea, abdominal distension, lethargy, and weight loss.
Other conditions associated with diarrhoea include thyrotoxicosis, laxative abuse, appendicitis, and radiation enteritis. It is important to seek medical attention if diarrhoea persists for more than a few days or is accompanied by other symptoms such as fever, severe abdominal pain, or blood in the stool.
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This question is part of the following fields:
- Gastrointestinal System
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Question 15
Correct
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Which one of the following statements related to the coagulation cascade is true?
Your Answer: Tissue factor released by damaged tissue initiates the extrinsic pathway
Explanation:The primary route of coagulation is the extrinsic pathway, which is inhibited by heparin’s ability to prevent the activation of factors 2, 9, 10, and 11. The convergence of both pathways occurs during the activation of factor 10. Fibrinogen is transformed into fibrin by thrombin. Plasminogen is converted to plasmin during fibrinolysis, which breaks down fibrin.
The Coagulation Cascade: Two Pathways to Fibrin Formation
The coagulation cascade is a complex process that leads to the formation of a blood clot. There are two pathways that can lead to fibrin formation: the intrinsic pathway and the extrinsic pathway. The intrinsic pathway involves components that are already present in the blood and has a minor role in clotting. It is initiated by subendothelial damage, such as collagen, which leads to the formation of the primary complex on collagen by high-molecular-weight kininogen (HMWK), prekallikrein, and Factor 12. This complex activates Factor 11, which in turn activates Factor 9. Factor 9, along with its co-factor Factor 8a, forms the tenase complex, which activates Factor 10.
The extrinsic pathway, on the other hand, requires tissue factor released by damaged tissue. This pathway is initiated by tissue damage, which leads to the binding of Factor 7 to tissue factor. This complex activates Factor 9, which works with Factor 8 to activate Factor 10. Both pathways converge at the common pathway, where activated Factor 10 causes the conversion of prothrombin to thrombin. Thrombin hydrolyses fibrinogen peptide bonds to form fibrin and also activates factor 8 to form links between fibrin molecules.
Finally, fibrinolysis occurs, which is the process of clot resorption. Plasminogen is converted to plasmin to facilitate this process. It is important to note that certain factors are involved in both pathways, such as Factor 10, and that some factors are vitamin K dependent, such as Factors 2, 7, 9, and 10. The intrinsic pathway can be assessed by measuring the activated partial thromboplastin time (APTT), while the extrinsic pathway can be assessed by measuring the prothrombin time (PT).
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This question is part of the following fields:
- Haematology And Oncology
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Question 16
Incorrect
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A 65-year-old man arrives at the emergency department with a sudden onset of aphasia lasting for 15 minutes. His partner mentions a similar incident occurred a month ago, but he did not seek medical attention as it resolved on its own.
Upon point of care testing, his capillary blood glucose level is 6.5 mmol/L (3.9 - 7.1). An urgent CT scan of his brain is conducted, which reveals no signs of acute infarct. However, upon returning from the scan, he regains full speech and denies experiencing any other neurological symptoms.
What aspect of the episode suggests a diagnosis of transient ischaemic attack?Your Answer: The patient has had at least one similar previous episode
Correct Answer: There was no evidence of acute infarction on CT imaging, and the episode was brief
Explanation:The definition of a TIA has been updated to focus on tissue-based factors rather than time-based ones. It is now defined as a brief episode of neurological dysfunction caused by focal brain, spinal cord, or retinal ischemia, without acute infarction. The new guidelines emphasize the importance of focal neurology and negative brain imaging in diagnosing a TIA, which typically lasts less than an hour. This is a departure from the previous definition, which focused on symptoms resolving within 24 hours and led to delays in diagnosis and treatment. Patients may have a history of stereotyped episodes preceding a TIA. Focal neurology is a hallmark of TIA, which can affect motor, sensory, aphasic, or visual areas of the brain. In cases where isolated aphasia lasts only 30 minutes and brain imaging shows no infarction, the patient has had a TIA rather than a stroke.
A transient ischaemic attack (TIA) is a brief period of neurological deficit caused by a vascular issue, lasting less than an hour. The original definition of a TIA was based on time, but it is now recognized that even short periods of ischaemia can result in pathological changes to the brain. Therefore, a new ’tissue-based’ definition is now used. The clinical features of a TIA are similar to those of a stroke, but the symptoms resolve within an hour. Possible features include unilateral weakness or sensory loss, aphasia or dysarthria, ataxia, vertigo, or loss of balance, visual problems, sudden transient loss of vision in one eye (amaurosis fugax), diplopia, and homonymous hemianopia.
NICE recommends immediate antithrombotic therapy, giving aspirin 300 mg immediately unless the patient has a bleeding disorder or is taking an anticoagulant. If aspirin is contraindicated, management should be discussed urgently with the specialist team. Specialist review is necessary if the patient has had more than one TIA or has a suspected cardioembolic source or severe carotid stenosis. Urgent assessment within 24 hours by a specialist stroke physician is required if the patient has had a suspected TIA in the last 7 days. Referral for specialist assessment should be made as soon as possible within 7 days if the patient has had a suspected TIA more than a week previously. The person should be advised not to drive until they have been seen by a specialist.
Neuroimaging should be done on the same day as specialist assessment if possible. MRI is preferred to determine the territory of ischaemia or to detect haemorrhage or alternative pathologies. Carotid imaging is necessary as atherosclerosis in the carotid artery may be a source of emboli in some patients. All patients should have an urgent carotid doppler unless they are not a candidate for carotid endarterectomy.
Antithrombotic therapy is recommended, with clopidogrel being the first-line treatment. Aspirin + dipyridamole should be given to patients who cannot tolerate clopidogrel. Carotid artery endarterectomy should only be considered if the patient has suffered a stroke or TIA in the carotid territory and is not severely disabled. It should only be recommended if carotid stenosis is greater
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This question is part of the following fields:
- Neurological System
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Question 17
Incorrect
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A medical research team is analyzing the expression levels of numerous genes concurrently to identify Single Nucleotide Polymorphisms (SNPs) in breast cancer.
Which molecular method would be the most suitable?Your Answer: SDS-PAGE
Correct Answer: Microarray
Explanation:Microarrays are utilized for the simultaneous profiling of gene expression levels of numerous genes to investigate different diseases and treatments. These arrays consist of grids of thousands of DNA sequences arranged on glass or silicon. The chip is then hybridized with DNA or RNA probes, and a scanner is used to detect the relative amounts of complementary binding.
Overview of Molecular Biology Techniques
Molecular biology techniques are essential tools used in the study of biological molecules such as DNA, RNA, and proteins. These techniques are used to detect and analyze these molecules in various biological samples. The most commonly used techniques include Southern blotting, Northern blotting, Western blotting, and enzyme-linked immunosorbent assay (ELISA).
Southern blotting is a technique used to detect DNA, while Northern blotting is used to detect RNA. Western blotting, on the other hand, is used to detect proteins. This technique involves the use of gel electrophoresis to separate native proteins based on their 3-D structure. It is commonly used in the confirmatory HIV test.
ELISA is a biochemical assay used to detect antigens and antibodies. This technique involves attaching a colour-changing enzyme to the antibody or antigen being detected. If the antigen or antibody is present in the sample, the sample changes colour, indicating a positive result. ELISA is commonly used in the initial HIV test.
In summary, molecular biology techniques are essential tools used in the study of biological molecules. These techniques include Southern blotting, Northern blotting, Western blotting, and ELISA. Each technique is used to detect specific molecules in biological samples and is commonly used in various diagnostic tests.
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This question is part of the following fields:
- General Principles
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Question 18
Incorrect
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A 25 year old woman comes to the clinic with a lump in her left breast. She mentions that she has noticed it for about 3 months and is worried because it hasn't disappeared. During the physical examination, a 1.5cm lump is found in the left breast. It is smooth, movable, and not attached to the skin. There are no changes in the nipple or skin. What is the probable diagnosis?
Your Answer: Breast abscess
Correct Answer: Fibroadenoma
Explanation:The most frequent breast lumps in women aged 15-25 are fibroadenomas. These lumps are usually firm, mobile, and less than 3 cm in size. They are not a cause for concern and typically disappear within a few years.
Fat necrosis is a condition that occurs after breast trauma, such as a sports injury or core needle biopsy. The affected area may be tender and show bruising. However, it usually resolves on its own and is unlikely to persist for an extended period.
Overview of Benign Breast Lesions
Benign breast lesions are non-cancerous growths that can occur in the breast tissue. There are several types of benign breast lesions, each with their own unique features and treatment options.
Fibroadenomas are one of the most common types of benign breast lesions, accounting for 12% of all breast masses. They develop from a whole lobule and are typically mobile, firm breast lumps. While they do not increase the risk of malignancy, surgical excision is usually recommended if the lesion is larger than 3 cm. Phyllodes tumors, a rare type of fibroadenoma, should be widely excised or removed with a mastectomy if the lesion is large.
Breast cysts are another common type of benign breast lesion, with 7% of all Western females presenting with one. They usually present as a smooth, discrete lump and may be aspirated. However, if the cyst is blood-stained or persistently refills, it should be biopsied or excised.
Sclerosing adenosis, radial scars, and complex sclerosing lesions can cause mammographic changes that mimic carcinoma. However, they are considered a disorder of involution and do not increase the risk of malignancy. Biopsy is recommended, but excision is not mandatory.
Epithelial hyperplasia is a disorder that consists of increased cellularity of the terminal lobular unit, and atypical features may be present. Those with atypical features and a family history of breast cancer have a greatly increased risk of malignancy and may require surgical resection.
Fat necrosis can occur in up to 40% of cases and usually has a traumatic cause. Physical features may mimic carcinoma, but imaging and core biopsy can help diagnose the lesion.
Duct papillomas usually present with nipple discharge and may require microdochectomy if they are large. However, they do not increase the risk of malignancy.
Overall, benign breast lesions can have varying presentations and treatment options. It is important to consult with a healthcare provider to determine the best course of action for each individual case.
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This question is part of the following fields:
- Reproductive System
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Question 19
Incorrect
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A 22-year-old male arrives at the emergency department with excessive epistaxis. Despite applying pressure on the anterior nares for the past four hours, the bleeding has not stopped. Nasal packing has also failed to control the bleeding. The on-call ENT specialist administers topical tranexamic acid to a visibly bleeding artery, which results in a reduction in bleeding.
What is the mode of action of tranexamic acid?Your Answer: Inhibits anticlotting factors protein C and protein S
Correct Answer: Prevents plasmin from breaking down fibrin clots
Explanation:Tranexamic acid prevents major haemorrhage by binding to plasminogen and preventing plasmin from breaking down fibrin clots. Its mechanism of action is not related to increasing the availability of vitamin K or inhibiting anticlotting factors protein C and S. Similarly, reducing the availability of vitamin K would not be the mechanism of action of tranexamic acid. While stimulating anticlotting factors protein C and S would maintain clots, it is not the mechanism of action of tranexamic acid.
Understanding Tranexamic Acid
Tranexamic acid is a synthetic derivative of lysine that acts as an antifibrinolytic. Its primary function is to bind to lysine receptor sites on plasminogen or plasmin, preventing plasmin from degrading fibrin. This medication is commonly prescribed to treat menorrhagia.
In addition to its use in treating menorrhagia, tranexamic acid has been investigated for its role in trauma. The CRASH 2 trial found that administering tranexamic acid within the first 3 hours of bleeding trauma can be beneficial. In cases of major haemorrhage, tranexamic acid is given as an IV bolus followed by an infusion.
Ongoing research is also exploring the potential of tranexamic acid in treating traumatic brain injury. Overall, tranexamic acid is a medication with important applications in managing bleeding disorders and trauma.
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This question is part of the following fields:
- Haematology And Oncology
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Question 20
Incorrect
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A 16-year-old male presents to the emergency department with a 48-hour history of tachypnea and tachycardia. His blood glucose level is 18mmol/l. While breathing 40% oxygen, an arterial blood sample is taken. The results show a PaO2 of 22kPa, pH of 7.35, PaCO2 of 3.5kPa, and HCO3- of 18.6 mmol/l. How should these blood gas results be interpreted?
Your Answer: Metabolic alkalosis with partial respiratory compensation
Correct Answer: Metabolic acidosis with full respiratory compensation
Explanation:The patient’s blood gas analysis shows a lower oxygen pressure by about 10kPa than the percentage of oxygen. The PaCo2 level is 3.5, indicating respiratory alkalosis or compensation for metabolic acidosis. The HCO3- level is 18.6, which suggests metabolic acidosis or metabolic compensation for respiratory alkalosis. These results indicate that the patient has metabolic acidosis with complete respiratory compensation. Additionally, the patient’s high blood glucose level suggests that the metabolic acidosis is due to diabetic ketoacidosis.
Arterial Blood Gas Interpretation: A 5-Step Approach
Arterial blood gas interpretation is a crucial aspect of patient care, particularly in critical care settings. The Resuscitation Council (UK) recommends a 5-step approach to interpreting arterial blood gas results. The first step is to assess the patient’s overall condition. The second step is to determine if the patient is hypoxaemic, with a PaO2 on air of less than 10 kPa. The third step is to assess if the patient is acidaemic (pH <7.35) or alkalaemic (pH >7.45).
The fourth step is to evaluate the respiratory component of the arterial blood gas results. A PaCO2 level greater than 6.0 kPa suggests respiratory acidosis, while a PaCO2 level less than 4.7 kPa suggests respiratory alkalosis. The fifth step is to assess the metabolic component of the arterial blood gas results. A bicarbonate level less than 22 mmol/l or a base excess less than -2mmol/l suggests metabolic acidosis, while a bicarbonate level greater than 26 mmol/l or a base excess greater than +2mmol/l suggests metabolic alkalosis.
To remember the relationship between pH, PaCO2, and bicarbonate, the acronym ROME can be used. Respiratory acidosis or alkalosis is opposite to the pH level, while metabolic acidosis or alkalosis is equal to the pH level. This 5-step approach and the ROME acronym can aid healthcare professionals in interpreting arterial blood gas results accurately and efficiently.
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This question is part of the following fields:
- Respiratory System
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Question 21
Incorrect
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You are working in the emergency department. A 27-year-old woman comes in with vomiting and abdominal pain. On examination, she is tender on palpation at all lower quadrants of the abdomen. Her temperature is 38ºC. On ultrasound, there is fluid in the rectouterine pouch.
What anatomical structure would a needle be passed via to extract this fluid?Your Answer: Bladder
Correct Answer: Posterior fornix of the vagina
Explanation:To obtain fluid from the rectouterine pouch, a needle is inserted through the posterior fornix of the vagina.
The anterior fornix of the vagina is situated nearer to the bladder than the rectouterine pouch in terms of anatomical position.
Similarly, the bladder is closer to the anterior fornix than the rectouterine pouch.
The round ligament is positioned above the rectouterine pouch.
The urethra connects to the bladder and is not in proximity to the rectouterine pouch.
Anatomy of the Uterus
The uterus is a female reproductive organ that is located within the pelvis and is covered by the peritoneum. It is supplied with blood by the uterine artery, which runs alongside the uterus and anastomoses with the ovarian artery. The uterus is supported by various ligaments, including the central perineal tendon, lateral cervical, round, and uterosacral ligaments. The ureter is located close to the uterus, and injuries to the ureter can occur when there is pathology in the area.
The uterus is typically anteverted and anteflexed in most women. Its topography can be visualized through imaging techniques such as ultrasound or MRI. Understanding the anatomy of the uterus is important for diagnosing and treating various gynecological conditions.
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This question is part of the following fields:
- Reproductive System
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Question 22
Incorrect
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A 69 year old patient is admitted to the emergency department with a suspected digoxin overdose. The individual has a medical history of hypertension, hyperthyroidism, atrial fibrillation, and eczema. The ECG reveals sinus bradycardia. The medical team administers IV digibind and implements measures to safeguard the heart against any electrolyte imbalances.
What is the correct application of digoxin in this scenario?Your Answer: Digoxin has a half-life of 20 hours
Correct Answer: Digoxin overdose can cause hyperkalaemia
Explanation:Hyperkalaemia can be caused by an overdose of digoxin.
Digoxin is known to inhibit the Na+/K+ ATPase, which is responsible for transporting sodium ions out of cells and promoting potassium influx. This inhibition leads to an accumulation of sodium inside the cell, which is then exchanged for calcium via the Na+/Ca2+ exchanger. In the heart, this increased intracellular calcium results in more calcium being released by the sarcoplasmic reticulum, making more calcium available to bind to troponin-C and increasing contractility (inotropy).
However, an overdose of digoxin can cause widespread inhibition of the Na+/K+ ATPase, leading to reduced potassium influx into cells and resulting in hyperkalaemia. This is a common occurrence in cases of acute digoxin toxicity.
In addition, digoxin has been found to increase vagal efferent activity to the heart, which has a parasympathomimetic effect and reduces the firing rate of the sinoatrial node, resulting in a decrease in heart rate (negative chronotropy).
It is important to note that digoxin has a long half-life of 40 hours.
Understanding Digoxin and Its Toxicity
Digoxin is a medication used for rate control in atrial fibrillation and for improving symptoms in heart failure patients. It works by decreasing conduction through the atrioventricular node and increasing the force of cardiac muscle contraction. However, it has a narrow therapeutic index and can cause toxicity even when the concentration is within the therapeutic range.
Toxicity may present with symptoms such as lethargy, nausea, vomiting, confusion, and yellow-green vision. Arrhythmias and gynaecomastia may also occur. Hypokalaemia is a classic precipitating factor as it increases the inhibitory effects of digoxin. Other factors include increasing age, renal failure, myocardial ischaemia, and various electrolyte imbalances. Certain drugs, such as amiodarone and verapamil, can also contribute to toxicity.
If toxicity is suspected, digoxin concentrations should be measured within 8 to 12 hours of the last dose. However, plasma concentration alone does not determine toxicity. Management includes the use of Digibind, correcting arrhythmias, and monitoring potassium levels.
In summary, understanding the mechanism of action, monitoring, and potential toxicity of digoxin is crucial for its safe and effective use in clinical practice.
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This question is part of the following fields:
- General Principles
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Question 23
Incorrect
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A 26-year-old woman comes to your clinic complaining of feeling dizzy for the past two days. She describes a sensation of the room spinning and has been experiencing nausea. The dizziness is relieved when she lies down and has no apparent triggers. She denies any hearing loss or aural fullness and is otherwise healthy. Upon examination, she has no fever and otoscopy reveals no abnormalities. You suspect she may have viral labyrinthitis and prescribe prochlorperazine to alleviate her vertigo symptoms. What class of antiemetic does prochlorperazine belong to?
Your Answer: Antimuscarinic
Correct Answer: Dopamine receptor antagonist
Explanation:Prochlorperazine belongs to a class of drugs known as dopamine receptor antagonists, which work by inhibiting stimulation of the chemoreceptor trigger zone (CTZ) through D2 receptors. Other drugs in this class include domperidone, metoclopramide, and olanzapine.
Antihistamine antiemetics, such as cyclizine and promethazine, are H1 histamine receptor antagonists.
5-HT3 receptor antagonists, such as ondansetron and granisetron, are effective both centrally and peripherally. They work by blocking serotonin receptors in the central nervous system and gastrointestinal tract.
Antimuscarinic antiemetics are anticholinergic drugs, with hyoscine (scopolamine) being a common example.
Vertigo is a condition characterized by a false sensation of movement in the body or environment. There are various causes of vertigo, each with its own unique characteristics. Viral labyrinthitis, for example, is typically associated with a recent viral infection, sudden onset, nausea and vomiting, and possible hearing loss. Vestibular neuronitis, on the other hand, is characterized by recurrent vertigo attacks lasting hours or days, but with no hearing loss. Benign paroxysmal positional vertigo is triggered by changes in head position and lasts for only a few seconds. Meniere’s disease, meanwhile, is associated with hearing loss, tinnitus, and a feeling of fullness or pressure in the ears. Elderly patients with vertigo may be experiencing vertebrobasilar ischaemia, which is accompanied by dizziness upon neck extension. Acoustic neuroma, which is associated with hearing loss, vertigo, and tinnitus, is also a possible cause of vertigo. Other causes include posterior circulation stroke, trauma, multiple sclerosis, and ototoxicity from medications like gentamicin.
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This question is part of the following fields:
- Respiratory System
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Question 24
Incorrect
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A 65-year-old woman presented with pain, weakness, and numbness in her right arm one day after undergoing surgery on her right shoulder. Upon neurological examination, it was found that the patient had full power in all upper limb movements except for a 4/5 power in right elbow flexion. Sensation was normal throughout the upper limbs except for a specific area on the lateral part of the forearm. The surgeon suspects that the nerve supplying the biceps brachii in the right arm was damaged during the surgical procedure. Which nerve is most likely to have been affected?
Your Answer: Ulnar nerve
Correct Answer: Musculocutaneous nerve
Explanation:If a person experiences weakness in elbow flexion, it may be due to an injury to the musculocutaneous nerve. This nerve is responsible for supplying the biceps brachii, coracobrachialis, and brachialis muscles, as well as the skin on the lateral aspect of the forearm.
Other nerves in the arm include the axillary nerve, which supplies the teres minor and deltoid muscles, as well as skin over the lower half of the deltoid and adjacent areas of the arm. The median nerve supplies most of the muscles in the anterior part of the forearm, as well as skin over the lateral portion of the palm, the palmar surface of the thumb, and the lateral two and a half fingers. The radial nerve supplies the supinator and extensor muscles in the forearm, as well as skin on the posterior side of the lateral aspect of the hand, the dorsum of the thumb, and the proximal part of the lateral two and a half fingers. Finally, the ulnar nerve supplies one and a half muscles in the anterior part of the forearm, as well as skin over the medial portion of the palm and the posterior surface of the medial part of the hand.
The shoulder joint is a shallow synovial ball and socket joint that is inherently unstable but capable of a wide range of movement. Stability is provided by the muscles of the rotator cuff. The glenoid labrum is a fibrocartilaginous rim attached to the free edge of the glenoid cavity. The fibrous capsule attaches to the scapula, humerus, and tendons of various muscles. Movements of the shoulder joint are controlled by different muscles. The joint is closely related to important anatomical structures such as the brachial plexus, axillary artery and vein, and various nerves and vessels.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 25
Incorrect
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A 65-year-old man with amyotrophic lateral sclerosis visits his primary care physician complaining of difficulty swallowing and regurgitation. During the examination, the patient's uvula is observed to deviate to the left side of the mouth. The tongue remains unaffected, and taste perception is normal. No other abnormalities are detected upon examination of the oral cavity. Based on these findings, where is the lesion most likely located?
Your Answer: Right trigeminal nerve
Correct Answer: Left vagus nerve
Explanation:The uvula deviating away from the side of the lesion indicates a problem with the left vagus nerve, as this nerve controls the muscles of the soft palate and can cause uvula deviation when damaged. In cases of vagus nerve lesions, the uvula deviates in the opposite direction of the lesion. As the patient’s uvula deviates towards the right, the underlying issue must be with the left vagus nerve.
The left hypoglossal nerve cannot be the cause of the uvula deviation, as this nerve only provides motor innervation to the tongue muscles and cannot affect the uvula.
Similarly, the right hypoglossal nerve and right trigeminal nerve cannot cause uvula deviation, as they do not have any control over the uvula. Trigeminal nerve lesions may cause different clinical signs depending on the location of the lesion, such as masseteric wasting in the case of mandibular nerve damage.
Cranial nerves are a set of 12 nerves that emerge from the brain and control various functions of the head and neck. Each nerve has a specific function, such as smell, sight, eye movement, facial sensation, and tongue movement. Some nerves are sensory, some are motor, and some are both. A useful mnemonic to remember the order of the nerves is Some Say Marry Money But My Brother Says Big Brains Matter Most, with S representing sensory, M representing motor, and B representing both.
In addition to their specific functions, cranial nerves also play a role in various reflexes. These reflexes involve an afferent limb, which carries sensory information to the brain, and an efferent limb, which carries motor information from the brain to the muscles. Examples of cranial nerve reflexes include the corneal reflex, jaw jerk, gag reflex, carotid sinus reflex, pupillary light reflex, and lacrimation reflex. Understanding the functions and reflexes of the cranial nerves is important in diagnosing and treating neurological disorders.
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This question is part of the following fields:
- Neurological System
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Question 26
Incorrect
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Which nerve provides feeling to the nail bed of the middle finger?
Your Answer: Musculocutaneous
Correct Answer: Median
Explanation:Anatomy and Function of the Median Nerve
The median nerve is a nerve that originates from the lateral and medial cords of the brachial plexus. It descends lateral to the brachial artery and passes deep to the bicipital aponeurosis and the median cubital vein at the elbow. The nerve then passes between the two heads of the pronator teres muscle and runs on the deep surface of flexor digitorum superficialis. Near the wrist, it becomes superficial between the tendons of flexor digitorum superficialis and flexor carpi radialis, passing deep to the flexor retinaculum to enter the palm.
The median nerve has several branches that supply the upper arm, forearm, and hand. These branches include the pronator teres, flexor carpi radialis, palmaris longus, flexor digitorum superficialis, flexor pollicis longus, and palmar cutaneous branch. The nerve also provides motor supply to the lateral two lumbricals, opponens pollicis, abductor pollicis brevis, and flexor pollicis brevis muscles, as well as sensory supply to the palmar aspect of the lateral 2 ½ fingers.
Damage to the median nerve can occur at the wrist or elbow, resulting in various symptoms such as paralysis and wasting of thenar eminence muscles, weakness of wrist flexion, and sensory loss to the palmar aspect of the fingers. Additionally, damage to the anterior interosseous nerve, a branch of the median nerve, can result in loss of pronation of the forearm and weakness of long flexors of the thumb and index finger. Understanding the anatomy and function of the median nerve is important in diagnosing and treating conditions that affect this nerve.
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This question is part of the following fields:
- Neurological System
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Question 27
Correct
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A 27-year-old male visits a sexual health clinic due to concerns about a possible sexually transmitted infection. After a swab is taken, the lab results indicate the presence of gram-negative diplococci. What is the probable causative agent?
Your Answer: Neisseria gonorrhoeae
Explanation:gonorrhoeae is caused by Neisseria gonorrhoeae, a gram-negative diplococcus that can be identified on gram staining. Another important gram-negative diplococcus to remember is Neisseria meningitidis. Chlamydia trachomatis is not the causative organism for gonorrhoeae, as it is a rod-shaped intracellular bacteria that is hard to stain. Gardnerella vaginalis is not the causative organism for gonorrhoeae, but is often involved in bacterial vaginosis and has a gram-variable cocco-bacilli shape. Trichomonas vaginalis is also not the causative organism for gonorrhoeae, as it is a parasite that causes trichomoniasis.
Understanding gonorrhoeae: Causes, Symptoms, and Treatment
gonorrhoeae is a sexually transmitted infection caused by the Gram-negative diplococcus Neisseria gonorrhoeae. It can occur on any mucous membrane surface, including the genitourinary tract, rectum, and pharynx. Symptoms in males include urethral discharge and dysuria, while females may experience cervicitis leading to vaginal discharge. However, rectal and pharyngeal infections are usually asymptomatic. Unfortunately, immunisation is not possible, and reinfection is common due to antigen variation of type IV pili and Opa proteins.
If left untreated, gonorrhoeae can lead to local complications such as urethral strictures, epididymitis, and salpingitis, which may result in infertility. Disseminated infection may also occur, with gonococcal infection being the most common cause of septic arthritis in young adults. The pathophysiology of disseminated gonococcal infection is not fully understood but is thought to be due to haematogenous spread from mucosal infection.
Management of gonorrhoeae involves the use of antibiotics. Ciprofloxacin used to be the treatment of choice, but there is now increased resistance to it. Cephalosporins are now more widely used, with a single dose of IM ceftriaxone 1g being the new first-line treatment. If sensitivities are known, a single dose of oral ciprofloxacin 500mg may be given. Disseminated gonococcal infection and gonococcal arthritis may also occur, with symptoms including tenosynovitis, migratory polyarthritis, and dermatitis.
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This question is part of the following fields:
- General Principles
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Question 28
Incorrect
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A 60-year-old man is being seen at the heart failure clinic. Despite being stable, he is bothered by the persistent swelling in his ankles. He is currently on furosemide, but the cardiologist decides to prescribe amiloride to see if it helps. What is the intended target of this new medication?
Your Answer: Carbonic anhydrase enzyme
Correct Answer: Epithelial sodium channel
Explanation:Amiloride is a type of potassium-sparing diuretic that selectively blocks the epithelial sodium transport channels in the distal convoluted tubule. It is often used in combination with thiazide/loop diuretics to counteract potassium loss. Amiloride does not affect the aldosterone receptor, which is targeted by drugs like spironolactone and eplerenone. Carbonic anhydrase inhibitors like dorzolamide and acetazolamide are typically used for glaucoma, while thiazide diuretics like bendroflumethiazide target the sodium-chloride transporter. Loop diuretics like furosemide inhibit the sodium-potassium-chloride cotransporter.
Potassium-sparing diuretics are classified into two types: epithelial sodium channel blockers (such as amiloride and triamterene) and aldosterone antagonists (such as spironolactone and eplerenone). However, caution should be exercised when using these drugs in patients taking ACE inhibitors as they can cause hyperkalaemia. Amiloride is a weak diuretic that blocks the epithelial sodium channel in the distal convoluted tubule. It is usually given with thiazides or loop diuretics as an alternative to potassium supplementation since these drugs often cause hypokalaemia. On the other hand, aldosterone antagonists like spironolactone act in the cortical collecting duct and are used to treat conditions such as ascites, heart failure, nephrotic syndrome, and Conn’s syndrome. In patients with cirrhosis, relatively large doses of spironolactone (100 or 200 mg) are often used to manage secondary hyperaldosteronism.
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This question is part of the following fields:
- General Principles
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Question 29
Incorrect
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A 35-year-old woman visits her doctor suspecting that she might be pregnant as she has missed her last two menstrual cycles. What hormone is expected to be present in the highest amount if her suspicion is true?
Your Answer: Oestrogen
Correct Answer: Human Chorionic Gonadotropin
Explanation:It is important to be aware of the role that hormones play during pregnancy.
Endocrine Changes During Pregnancy
During pregnancy, there are several physiological changes that occur in the body, including endocrine changes. Progesterone, which is produced by the fallopian tubes during the first two weeks of pregnancy, stimulates the secretion of nutrients required by the zygote/blastocyst. At six weeks, the placenta takes over the production of progesterone, which inhibits uterine contractions by decreasing sensitivity to oxytocin and inhibiting the production of prostaglandins. Progesterone also stimulates the development of lobules and alveoli.
Oestrogen, specifically oestriol, is another major hormone produced during pregnancy. It stimulates the growth of the myometrium and the ductal system of the breasts. Prolactin, which increases during pregnancy, initiates and maintains milk secretion of the mammary gland. It is essential for the expression of the mammotropic effects of oestrogen and progesterone. However, oestrogen and progesterone directly antagonize the stimulating effects of prolactin on milk synthesis.
Human chorionic gonadotropin (hCG) is secreted by the syncitiotrophoblast and can be detected within nine days of pregnancy. It mimics LH, rescuing the corpus luteum from degenerating and ensuring early oestrogen and progesterone secretion. It also stimulates the production of relaxin and may inhibit contractions induced by oxytocin. Other hormones produced during pregnancy include relaxin, which suppresses myometrial contractions and relaxes the pelvic ligaments and pubic symphysis, and human placental lactogen (hPL), which has lactogenic actions and enhances protein metabolism while antagonizing insulin.
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This question is part of the following fields:
- Reproductive System
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Question 30
Correct
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You are asked to evaluate a 5-day old cyanotic infant named Benjamin. Benjamin has had a chest x-ray which shows a heart appearance described as 'egg-on-side'. What is the probable underlying diagnosis?
Your Answer: Transposition of the great arteries
Explanation:The ‘egg-on-side’ appearance on x-rays is a characteristic finding of transposition of the great arteries, which is one of the causes of cyanotic heart disease along with tetralogy of Fallot. While the age of the patient can help distinguish between the two conditions, the x-ray provides a clue for diagnosis. Patent ductus arteriosus, coarctation of the aorta, and ventricular septal defect do not typically present with cyanosis.
Understanding Transposition of the Great Arteries
Transposition of the great arteries (TGA) is a type of congenital heart disease that results in cyanosis. This condition occurs when the aorticopulmonary septum fails to spiral during septation, causing the aorta to leave the right ventricle and the pulmonary trunk to leave the left ventricle. Infants born to diabetic mothers are at a higher risk of developing TGA.
The clinical features of TGA include cyanosis, tachypnea, a loud single S2, and a prominent right ventricular impulse. Chest x-rays may show an egg-on-side appearance. To manage TGA, prostaglandins can be used to maintain the ductus arteriosus. However, surgical correction is the definitive treatment for this condition.
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This question is part of the following fields:
- Cardiovascular System
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