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Question 1
Incorrect
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A 48-year-old man who was previously diagnosed with prediabetes with an HbA1c of 46 mmol/mol 18 months earlier, has a repeat HbA1c that comes back at 50 mmol/mol despite lifestyle measures and an education programme.
You diagnose him with type 2 diabetes mellitus and discuss the next steps with him. You jointly agree to start an oral anti-hyperglycaemic agent to improve his diabetes control and suggest starting with metformin to increase insulin sensitivity.
How does metformin exert its effect?Your Answer: Binding to GLP-1 receptors in the pancreas
Correct Answer: Activating the AMP-activated protein kinase (AMPK)
Explanation:Metformin activates the AMP-activated protein kinase (AMPK) to improve insulin response and glucose uptake. GLP1 agonists enhance insulin release and reduce glucagon release by binding to GLP-1 receptors in the pancreas. Sulfonylureas close ATP-sensitive potassium (K-ATP) channels on pancreatic beta cells, leading to depolarization. Thiazolidinediones bind to peroxisome proliferator-activated receptor-gamma in adipocytes to promote adipogenesis and fatty acid uptake in peripheral fat. DPP-4 inhibitors block the action of DPP-4, which destroys incretin, a hormone that helps the body produce more insulin when needed and reduce glucose production by the liver when not needed.
Metformin is a medication commonly used to treat type 2 diabetes mellitus, as well as polycystic ovarian syndrome and non-alcoholic fatty liver disease. Unlike other medications, such as sulphonylureas, metformin does not cause hypoglycaemia or weight gain, making it a first-line treatment option, especially for overweight patients. Its mechanism of action involves activating the AMP-activated protein kinase, increasing insulin sensitivity, decreasing hepatic gluconeogenesis, and potentially reducing gastrointestinal absorption of carbohydrates. However, metformin can cause gastrointestinal upsets, reduced vitamin B12 absorption, and in rare cases, lactic acidosis, particularly in patients with severe liver disease or renal failure. It is contraindicated in patients with chronic kidney disease, recent myocardial infarction, sepsis, acute kidney injury, severe dehydration, and those undergoing iodine-containing x-ray contrast media procedures. When starting metformin, it should be titrated up slowly to reduce the incidence of gastrointestinal side-effects, and modified-release metformin can be considered for patients who experience unacceptable side-effects.
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This question is part of the following fields:
- General Principles
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Question 2
Incorrect
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A 75-year-old male visits his GP accompanied by his wife who is anxious about his recent memory decline. The patient's wife is worried as her mother had Alzheimer's disease and she fears her husband may be developing it too. Among the following causes of cognitive decline, which one is potentially reversible?
Your Answer: HIV
Correct Answer: Brain tumour
Explanation:Normal pressure hydrocephalus can be a reversible cause of dementia, while Pick’s disease is a degenerative form of frontotemporal dementia that cannot be reversed. Lewy body dementia is a progressive condition that is linked to parkinson’s and visual hallucinations. Multi-infarct dementia is associated with cardiovascular risk factors like smoking, diabetes, and atrial fibrillation, but the damage caused by infarcts is irreversible. A brain tumor is a potential cause of dementia that can be reversed.
Understanding the Causes of Dementia
Dementia is a condition that affects millions of people worldwide, and it is caused by a variety of factors. The most common causes of dementia include Alzheimer’s disease, cerebrovascular disease, and Lewy body dementia. These conditions account for around 40-50% of all cases of dementia.
However, there are also rarer causes of dementia, which account for around 5% of cases. These include Huntington’s disease, Creutzfeldt-Jakob disease (CJD), Pick’s disease, and HIV (in 50% of AIDS patients). These conditions are less common but can still have a significant impact on those affected.
It is also important to note that there are several potentially treatable causes of dementia that should be ruled out before a diagnosis is made. These include hypothyroidism, Addison’s disease, B12/folate/thiamine deficiency, syphilis, brain tumours, normal pressure hydrocephalus, subdural haematoma, depression, and chronic drug use (such as alcohol or barbiturates).
In conclusion, understanding the causes of dementia is crucial for effective diagnosis and treatment. While some causes are more common than others, it is important to consider all potential factors and rule out treatable conditions before making a final diagnosis.
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This question is part of the following fields:
- Neurological System
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Question 3
Correct
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A 50-year-old male comes to the emergency department complaining of left sided vision loss, headache and scalp tenderness. During the examination, he has a fever of 38.5°C, jaw claudication and a relative afferent pupillary defect is observed. The medical team suspects giant cell arteritis and initiates high dose prednisone treatment.
What structural abnormality is responsible for the relative afferent pupillary defect?Your Answer: Ischaemic optic neuropathy
Explanation:A relative afferent pupillary defect is a sign that there may be an optic nerve lesion or a severe retinal disease. In cases of giant cell arteritis (GCA), an inflammatory process of the blood vessels in the head can lead to ischaemic optic neuropathy, which can cause a RAPD. However, blindness, corneal opacity, and photophobia alone are not enough to cause a RAPD. While optic neuritis can also result in a RAPD, this is not typically seen in GCA and may instead indicate a first presentation of multiple sclerosis.
A relative afferent pupillary defect, also known as the Marcus-Gunn pupil, can be identified through the swinging light test. This condition is caused by a lesion that is located anterior to the optic chiasm, which can be found in the optic nerve or retina. When light is shone on the affected eye, it appears to dilate while the normal eye remains unchanged.
The causes of a relative afferent pupillary defect can vary. For instance, it may be caused by a detachment of the retina or optic neuritis, which is often associated with multiple sclerosis. The pupillary light reflex pathway involves the afferent pathway, which starts from the retina and goes through the optic nerve, lateral geniculate body, and midbrain. The efferent pathway, on the other hand, starts from the Edinger-Westphal nucleus in the midbrain and goes through the oculomotor nerve.
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This question is part of the following fields:
- Neurological System
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Question 4
Incorrect
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As a neurology doctor, you have been requested to assess a 36-year-old woman who was in a car accident and suffered a significant head injury.
Upon arrival, she is unconscious, and there are some minor twitching movements in her right arm and leg. When she wakes up, these movements become more severe, with her right arm and leg repeatedly flinging out with different amplitudes.
Based on the likely diagnosis, where is the lesion most likely located?Your Answer: Left motor cortex
Correct Answer: Left basal ganglia
Explanation:The patient is exhibiting signs of hemiballismus, which is characterized by involuntary and sudden jerking movements on one side of the body. These movements typically occur on the side opposite to the lesion and may decrease in intensity during periods of relaxation or sleep. The most common location for the lesion causing hemiballismus is the basal ganglia, specifically on the contralateral side. A lesion in the left motor cortex would result in decreased function on the right side of the body, and psychosomatic factors are not the cause of this movement disorder. A lesion in the right basal ganglia would cause movement disorders on the left side of the body.
Understanding Hemiballism
Hemiballism is a condition that arises from damage to the subthalamic nucleus. It is characterized by sudden, involuntary, and jerking movements that occur on the side opposite to the lesion. The movements primarily affect the proximal limb muscles, while the distal muscles may display more choreiform-like movements. Interestingly, the symptoms may decrease while the patient is asleep.
The main treatment for hemiballism involves the use of antidopaminergic agents such as Haloperidol. These medications help to reduce the severity of the symptoms and improve the patient’s quality of life. It is important to note that early diagnosis and treatment are crucial in managing this condition. With proper care and management, individuals with hemiballism can lead fulfilling lives.
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This question is part of the following fields:
- Neurological System
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Question 5
Incorrect
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A 67-year-old patient is being evaluated after being admitted for treatment of a persistent Clostridium difficile infection. The patient had received treatment for a previous infection three weeks ago, but the symptoms did not subside, and she continued to experience diarrhoea. The patient was hospitalized three days ago due to a life-threatening Clostridium difficile infection.
The patient has been receiving oral vancomycin and IV metronidazole for the past few days, but there has been no improvement in her symptoms. What would be the venous blood gas results in this case?Your Answer: Normal venous blood gas
Correct Answer: Metabolic acidosis + hypokalaemia
Explanation:If a patient experiences prolonged diarrhoea, they may develop metabolic acidosis and hypokalaemia. This is likely the case for a patient with a history of prolonged Clostridium difficile infection, as the loss of bicarbonate ions from the GI tract during diarrhoea can lead to metabolic acidosis. Prolonged diarrhoea can also result in hypokalaemia due to the direct loss of potassium from the GI tract, which the body may be unable to compensate for. Therefore, metabolic acidosis and hypokalaemia are the expected outcomes in this scenario.
Understanding Metabolic Acidosis
Metabolic acidosis is a condition that can be classified based on the anion gap, which is calculated by subtracting the sum of chloride and bicarbonate from the sum of sodium and potassium. The normal range for anion gap is 10-18 mmol/L. If a question provides the chloride level, it may be an indication to calculate the anion gap.
Hyperchloraemic metabolic acidosis is a type of metabolic acidosis with a normal anion gap. It can be caused by gastrointestinal bicarbonate loss, prolonged diarrhea, ureterosigmoidostomy, fistula, renal tubular acidosis, drugs like acetazolamide, ammonium chloride injection, and Addison’s disease. On the other hand, raised anion gap metabolic acidosis is caused by lactate, ketones, urate, acid poisoning, and other factors.
Lactic acidosis is a type of metabolic acidosis that is caused by high lactate levels. It can be further classified into two types: lactic acidosis type A, which is caused by sepsis, shock, hypoxia, and burns, and lactic acidosis type B, which is caused by metformin. Understanding the different types and causes of metabolic acidosis is important in diagnosing and treating the condition.
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This question is part of the following fields:
- Renal System
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Question 6
Correct
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A 55-year-old man comes in for his regular check-up with his GP. He has a medical history of chronic pancreatitis and diabetes mellitus and is currently taking the maximum doses of metformin and gliclazide. During a random plasma glucose test, his levels show 18.0 mmol/l and his urinalysis reveals glycosuria with minimal ketones. The GP suspects that his body is not producing enough insulin and decides to initiate insulin therapy. Can you identify the location in the body where insulin is produced?
Your Answer: Pancreatic beta cells
Explanation:Diabetes mellitus in this patient is most likely caused by chronic pancreatitis, which has resulted in the destruction of the pancreatic endocrine cells responsible for producing endogenous insulin. These cells are located in the Islets of Langerhans and are known as pancreatic beta cells (β-cells). Other cells in the pancreas, such as alpha cells (which secrete glucagon) and delta cells (which secrete somatostatin), do not produce insulin. Similarly, gastric G cells secrete gastrin and are not involved in insulin production.
Insulin is a hormone produced by the pancreas that plays a crucial role in regulating the metabolism of carbohydrates and fats in the body. It works by causing cells in the liver, muscles, and fat tissue to absorb glucose from the bloodstream, which is then stored as glycogen in the liver and muscles or as triglycerides in fat cells. The human insulin protein is made up of 51 amino acids and is a dimer of an A-chain and a B-chain linked together by disulfide bonds. Pro-insulin is first formed in the rough endoplasmic reticulum of pancreatic beta cells and then cleaved to form insulin and C-peptide. Insulin is stored in secretory granules and released in response to high levels of glucose in the blood. In addition to its role in glucose metabolism, insulin also inhibits lipolysis, reduces muscle protein loss, and increases cellular uptake of potassium through stimulation of the Na+/K+ ATPase pump.
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This question is part of the following fields:
- Endocrine System
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Question 7
Incorrect
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A 62-year-old female visits a medical facility for evaluation after reporting to her doctor about a lump in her right breast. Upon conducting a mammography and biopsy of the breast tissue, it is confirmed that she has invasive ductal carcinoma.
Which oncogene is primarily linked to this condition?Your Answer: BCL-2
Correct Answer: HER2/neu
Explanation:Oncogenes are genes that promote cancer and are derived from normal genes called proto-oncogenes. Proto-oncogenes play a crucial role in cellular growth and differentiation. However, a gain of function in oncogenes increases the risk of cancer. Only one mutated copy of the gene is needed for cancer to occur, making it a dominant effect. Oncogenes are responsible for up to 20% of human cancers and can become oncogenes through mutation, chromosomal translocation, or increased protein expression.
In contrast, tumor suppressor genes restrict or repress cellular proliferation in normal cells. Their inactivation through mutation or germ line incorporation is implicated in various cancers, including renal, colonic, breast, and bladder cancer. Tumor suppressor genes, such as p53, offer protection by causing apoptosis of damaged cells. Other well-known genes include BRCA1 and BRCA2. Loss of function in tumor suppressor genes results in an increased risk of cancer, while gain of function in oncogenes increases the risk of cancer.
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This question is part of the following fields:
- General Principles
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Question 8
Incorrect
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A 65-year-old woman presented with pain, weakness, and numbness in her right arm one day after undergoing surgery on her right shoulder. Upon neurological examination, it was found that the patient had full power in all upper limb movements except for a 4/5 power in right elbow flexion. Sensation was normal throughout the upper limbs except for a specific area on the lateral part of the forearm. The surgeon suspects that the nerve supplying the biceps brachii in the right arm was damaged during the surgical procedure. Which nerve is most likely to have been affected?
Your Answer: Axillary nerve
Correct Answer: Musculocutaneous nerve
Explanation:If a person experiences weakness in elbow flexion, it may be due to an injury to the musculocutaneous nerve. This nerve is responsible for supplying the biceps brachii, coracobrachialis, and brachialis muscles, as well as the skin on the lateral aspect of the forearm.
Other nerves in the arm include the axillary nerve, which supplies the teres minor and deltoid muscles, as well as skin over the lower half of the deltoid and adjacent areas of the arm. The median nerve supplies most of the muscles in the anterior part of the forearm, as well as skin over the lateral portion of the palm, the palmar surface of the thumb, and the lateral two and a half fingers. The radial nerve supplies the supinator and extensor muscles in the forearm, as well as skin on the posterior side of the lateral aspect of the hand, the dorsum of the thumb, and the proximal part of the lateral two and a half fingers. Finally, the ulnar nerve supplies one and a half muscles in the anterior part of the forearm, as well as skin over the medial portion of the palm and the posterior surface of the medial part of the hand.
The shoulder joint is a shallow synovial ball and socket joint that is inherently unstable but capable of a wide range of movement. Stability is provided by the muscles of the rotator cuff. The glenoid labrum is a fibrocartilaginous rim attached to the free edge of the glenoid cavity. The fibrous capsule attaches to the scapula, humerus, and tendons of various muscles. Movements of the shoulder joint are controlled by different muscles. The joint is closely related to important anatomical structures such as the brachial plexus, axillary artery and vein, and various nerves and vessels.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 9
Incorrect
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What is the mechanism of action of rifampicin?
Your Answer: Inhibits protein synthesis
Correct Answer: Inhibits RNA synthesis
Explanation:Rifampicin hinders the process of RNA synthesis.
Antibiotics work in different ways to kill or inhibit the growth of bacteria. The commonly used antibiotics can be classified based on their gross mechanism of action. The first group inhibits cell wall formation by either preventing peptidoglycan cross-linking (penicillins, cephalosporins, carbapenems) or peptidoglycan synthesis (glycopeptides like vancomycin). The second group inhibits protein synthesis by acting on either the 50S subunit (macrolides, chloramphenicol, clindamycin, linezolid, streptogrammins) or the 30S subunit (aminoglycosides, tetracyclines) of the bacterial ribosome. The third group inhibits DNA synthesis (quinolones like ciprofloxacin) or damages DNA (metronidazole). The fourth group inhibits folic acid formation (sulphonamides and trimethoprim), while the fifth group inhibits RNA synthesis (rifampicin). Understanding the mechanism of action of antibiotics is important in selecting the appropriate drug for a particular bacterial infection.
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This question is part of the following fields:
- General Principles
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Question 10
Incorrect
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A 65-year-old male patient undergoes liver resection surgery and encounters uncontrolled hepatic bleeding. To interrupt the blood flow, the surgeon performs the 'Pringle manoeuvre' by clamping the hepatic artery, portal vein, and common bile duct, which form the anterior boundary of the epiploic foramen. What other vessel serves as a boundary in this area?
Your Answer: Right renal vein
Correct Answer: Inferior vena cava
Explanation:The inferior vena cava serves as the posterior boundary of the epiploic foramen. The anterior boundary is formed by the hepatoduodenal ligament, which contains the bile duct, portal vein, and hepatic artery. The first part of the duodenum forms the inferior boundary, while the caudate process of the liver forms the superior boundary.
The Epiploic Foramen and its Boundaries
The epiploic foramen is a small opening in the peritoneum that connects the greater and lesser sacs of the abdomen. It is located posterior to the liver and anterior to the inferior vena cava. The boundaries of the epiploic foramen include the bile duct to the right, the portal vein behind, and the hepatic artery to the left. The inferior boundary is the first part of the duodenum, while the superior boundary is the caudate process of the liver.
During liver surgery, bleeding can be controlled by performing a Pringles manoeuvre. This involves placing a vascular clamp across the anterior aspect of the epiploic foramen, which occludes the common bile duct, hepatic artery, and portal vein. This technique is useful in preventing excessive bleeding during liver surgery and can help to ensure a successful outcome.
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This question is part of the following fields:
- Gastrointestinal System
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Question 11
Incorrect
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Which one of the following relationship descriptions regarding the scalene muscles is incorrect?
Your Answer: The brachial plexus passes anterior to the middle scalene muscle
Correct Answer: The subclavian artery passes posterior to the middle scalene
Explanation:The middle scalene is located posterior to the subclavian artery.
The Scalene Muscles and Thoracic Outlet Syndrome
The scalene muscles are a group of three paired muscles located in the neck that play a role in elevating the ribs and tilting the neck. The scalenus anterior and medius muscles elevate the first rib and laterally flex the neck to the same side, while the scalenus posterior muscle elevates the second rib and tilts the neck to the opposite side. These muscles are innervated by spinal nerves C4-6 and originate from the transverse processes of C2 to C7, inserting into the first and second ribs.
The scalene muscles are important because the brachial plexus and subclavian artery pass between the anterior and middle scalenes through a space called the scalene hiatus or fissure. The subclavian vein and phrenic nerve pass anteriorly to the anterior scalene as it crosses over the first rib. However, the scalenes are at risk of adhering to the fascia surrounding the brachial plexus or shortening, which can cause compression of the brachial plexus when it passes between the clavicle and first rib. This condition is known as thoracic outlet syndrome.
In summary, the scalene muscles play an important role in the neck and chest, but can also cause issues if they become adhered or shortened, leading to thoracic outlet syndrome. It is important to be aware of this condition and seek medical attention if experiencing symptoms such as pain, numbness, or tingling in the arm or hand.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 12
Incorrect
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A patient has been diagnosed with multiple myeloma, and genetic analysis has revealed that a single copy of their p53 gene has been mutated. Usually, two copies of a tumour suppressor gene need to be mutated for cancer to develop. The doctor explains that sometimes having only one copy of TP53 is insufficient to suppress the cancer.
What is this phenomenon known as?Your Answer: Carrier
Correct Answer: Haploinsufficiency
Explanation:Haploinsufficiency occurs when a single allele is unable to produce the typical phenotype in an individual. This happens when one functional allele of a gene is lost due to mutation or deletion, and the remaining normal allele is not enough to carry out its original function. Incomplete penetrance is when an allele may not always be expressed in an individual’s phenotype, and may require an environmental trigger. Codominance is when two different alleles for a trait are expressed equally in the phenotype of heterozygous individuals, such as the AB blood type. Genomic imprinting is an inheritance pattern where a gene has a different effect depending on the gender of the parent from whom it is inherited.
Autosomal Dominant Inheritance: Characteristics and Complicating Factors
Autosomal dominant diseases are genetic disorders that are inherited in an autosomal dominant pattern. This means that both homozygotes and heterozygotes manifest the disease, and there is no carrier state. Both males and females can be affected, and only affected individuals can pass on the disease. The disease is passed on to 50% of children, and it normally appears in every generation. The risk remains the same for each successive pregnancy.
However, there are complicating factors that can affect the inheritance of autosomal dominant diseases. One of these factors is non-penetrance, which refers to the lack of clinical signs and symptoms despite having an abnormal gene. For example, 40% of individuals with otosclerosis may not show any symptoms. Another complicating factor is spontaneous mutation, which occurs when there is a new mutation in one of the gametes. This means that 80% of individuals with achondroplasia have unaffected parents.
In summary, autosomal dominant inheritance is characterized by certain patterns of inheritance, but there are also complicating factors that can affect the expression of the disease. Understanding these factors is important for genetic counseling and for predicting the risk of passing on the disease to future generations.
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This question is part of the following fields:
- General Principles
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Question 13
Incorrect
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A 45-year-old woman visits her doctor complaining of muscle cramps and fatigue. Upon ruling out any musculoskeletal issues, a blood test is conducted which reveals hyperparathyroidism and low serum phosphate levels. It is suspected that the low phosphate levels are due to the inhibitory effect of parathyroid hormone on renal phosphate reabsorption. Which site in the kidney is most likely affected by parathyroid hormone to cause these blood results?
Your Answer: Collecting ducts
Correct Answer: Proximal convoluted tubule
Explanation:The proximal convoluted tubule is responsible for the majority of renal phosphate reabsorption. This occurs through co-transport with sodium and up to two thirds of filtered water. The thin ascending limb of the Loop of Henle is impermeable to water but highly permeable to sodium and chloride, while reabsorption of these ions occurs in the thick ascending limb. Parathyroid hormone is most effective at the proximal convoluted tubule due to its role in regulating phosphate reabsorption.
The Loop of Henle and its Role in Renal Physiology
The Loop of Henle is a crucial component of the renal system, located in the juxtamedullary nephrons and running deep into the medulla. Approximately 60 litres of water containing 9000 mmol sodium enters the descending limb of the loop of Henle in 24 hours. The osmolarity of fluid changes and is greatest at the tip of the papilla. The thin ascending limb is impermeable to water, but highly permeable to sodium and chloride ions. This loss means that at the beginning of the thick ascending limb the fluid is hypo osmotic compared with adjacent interstitial fluid. In the thick ascending limb, the reabsorption of sodium and chloride ions occurs by both facilitated and passive diffusion pathways. The loops of Henle are co-located with vasa recta, which have similar solute compositions to the surrounding extracellular fluid, preventing the diffusion and subsequent removal of this hypertonic fluid. The energy-dependent reabsorption of sodium and chloride in the thick ascending limb helps to maintain this osmotic gradient. Overall, the Loop of Henle plays a crucial role in regulating the concentration of solutes in the renal system.
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This question is part of the following fields:
- Renal System
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Question 14
Incorrect
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A neonatal hearing screening program screened 10,000 newborns by measuring otoacoustic emissions (OAE). Out of these, 200 newborns failed the screening test and were invited for a test of brainstem auditory evoked potential (BAEP), which is considered the gold standard for diagnosing hearing impairment in newborns. Among these 200 newborns, 100 were confirmed to have hearing impairment by BAEP. What is the correct statement regarding this scenario?
Your Answer: The negative predictive value of the screening test is 98%
Correct Answer: The accuracy of the screening test cannot be determined
Explanation:Limitations of Screening Test Results
In the study, 200 out of 10,000 subjects were found to have hearing impairment through a screening test. However, for the 9,800 subjects who tested negative, no further testing was conducted to confirm if they truly did not have hearing impairment. This means that we cannot determine the accuracy of the screening test from the data provided, nor can we calculate the sensitivity, specificity, or negative predictive values. The only value that can be calculated is the positive predictive value, which is 50%. It is important to note the limitations of screening test results and the need for further testing to confirm diagnoses.
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This question is part of the following fields:
- Clinical Sciences
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Question 15
Incorrect
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A 58-year-old woman, previously healthy, visited her doctor complaining of a growing rubbery lump in her neck and night sweats. She was quickly referred to a haematologist who diagnosed her with lymphoma. The patient is currently undergoing chemotherapy for the lymphoma and has come to your clinic with glove-and-stocking distribution paraesthesia.
What medication is the most probable cause of this symptom in this patient?Your Answer: Ondansetron
Correct Answer: Vincristine
Explanation:Cytotoxic agents are drugs that are used to kill cancer cells. There are several types of cytotoxic agents, each with their own mechanism of action and potential adverse effects. Alkylating agents, such as cyclophosphamide, work by causing cross-linking in DNA. However, they can also cause haemorrhagic cystitis, myelosuppression, and transitional cell carcinoma. Cytotoxic antibiotics, like bleomycin and anthracyclines, degrade preformed DNA and stabilize DNA-topoisomerase II complex, respectively. However, they can also cause lung fibrosis and cardiomyopathy. Antimetabolites, such as methotrexate and fluorouracil, inhibit dihydrofolate reductase and thymidylate synthesis, respectively. However, they can also cause myelosuppression, mucositis, and liver or lung fibrosis. Drugs that act on microtubules, like vincristine and docetaxel, inhibit the formation of microtubules and prevent microtubule depolymerisation & disassembly, respectively. However, they can also cause peripheral neuropathy, myelosuppression, and paralytic ileus. Topoisomerase inhibitors, like irinotecan, inhibit topoisomerase I, which prevents relaxation of supercoiled DNA. However, they can also cause myelosuppression. Other cytotoxic drugs, such as cisplatin and hydroxyurea, cause cross-linking in DNA and inhibit ribonucleotide reductase, respectively. However, they can also cause ototoxicity, peripheral neuropathy, hypomagnesaemia, and myelosuppression.
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This question is part of the following fields:
- Haematology And Oncology
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Question 16
Correct
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A 46-year-old man with a history of hypertrophic cardiomyopathy (HOCM) presents for evaluation at the cardiology clinic. During the assessment, a fourth heart sound is detected.
What characteristic is associated with this clinical observation?Your Answer: It coincides with the P wave of the ECG
Explanation:The S4 heart sound occurs simultaneously with the P wave on an ECG. This sound is heard during late diastole when the left ventricle is being actively filled and the atrial contraction is forcing blood into a noncompliant left ventricle. The P wave on the ECG represents the depolarization of the left and right atrium, which results in atrial contraction. Therefore, the S4 heart sound coincides with the P wave on the ECG.
The presence of an S4 heart sound can indicate diastolic heart failure, which is caused by severe left ventricular hypertrophy. This condition can be found in patients with HOCM or can develop as a complication of hypertension or aortic stenosis.
In contrast, the S3 heart sound occurs during early diastole when the left ventricle is being passively filled.
During diastole, the T wave on the ECG represents the repolarization of the ventricles and marks the beginning of ventricular relaxation.
Heart sounds are the sounds produced by the heart during its normal functioning. The first heart sound (S1) is caused by the closure of the mitral and tricuspid valves, while the second heart sound (S2) is due to the closure of the aortic and pulmonary valves. The intensity of these sounds can vary depending on the condition of the valves and the heart. The third heart sound (S3) is caused by the diastolic filling of the ventricle and is considered normal in young individuals. However, it may indicate left ventricular failure, constrictive pericarditis, or mitral regurgitation in older individuals. The fourth heart sound (S4) may be heard in conditions such as aortic stenosis, HOCM, and hypertension, and is caused by atrial contraction against a stiff ventricle. The different valves can be best heard at specific sites on the chest wall, such as the left second intercostal space for the pulmonary valve and the right second intercostal space for the aortic valve.
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This question is part of the following fields:
- Cardiovascular System
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Question 17
Incorrect
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Which statement accurately describes the results of a randomised controlled trial comparing the effectiveness of drug A and drug B in treating diabetes mellitus, where 100 patients were assigned to each group and the HbA1c levels were 72 mmol/mol in group A and 61 mmol/mol in group B with a p-value of 0.08?
Your Answer: Type I error is below 5%
Correct Answer: The 95% confidence intervals of the HbA1c for group A and group B likely overlapped
Explanation:Statistical Significance and Confidence Intervals
When conducting statistical analyses, it is important to understand the concepts of statistical significance and confidence intervals. In general, statistical significance refers to the likelihood that the results of a study are not due to chance. This is typically determined by calculating a p value, which represents the probability of obtaining the observed results if the null hypothesis (i.e., no difference between groups) is true. If the p value is below a predetermined level of significance (usually 0.05 or 0.01), the results are considered statistically significant.
Confidence intervals, on the other hand, provide a range of values within which the true population parameter (e.g., mean, proportion) is likely to fall. The width of the confidence interval is determined by the level of confidence (e.g., 95%, 90%) and the variability of the data. A narrower confidence interval indicates greater precision in the estimate.
In the given statements, it is suggested that the p value and confidence intervals can provide insight into the likelihood of differences between groups. Specifically, if the p value is above 0.05, it is likely that the confidence intervals of the two groups overlap. Additionally, a 90% confidence interval will generally be narrower than a 95% confidence interval. Finally, if the p value is below 0.1, it is suggested that the 90% confidence intervals did not overlap, indicating a greater likelihood of differences between groups. However, it is important to note that the power of the study (i.e., the ability to detect true differences) is not known, so the possibility of a type II error (i.e., failing to detect a true difference) cannot be ruled out.
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This question is part of the following fields:
- Clinical Sciences
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Question 18
Incorrect
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A team of researchers conducts a study to assess the safety of a new medication for lowering cholesterol levels. One thousand participants are randomly divided into two groups, with 500 individuals in each group, and given either the medication or a placebo. The researchers find that acute myositis is more common in those who received the medication than in those who received the placebo, and the difference is statistically significant (p = 0.03).
What is the most precise interpretation of these findings?Your Answer: There is a low chance of developing acute myositis with the drug
Correct Answer: There is a 3% probability that the result is obtained by chance
Explanation:The study found a significant difference between the groups and concluded that the new hypolipidaemic drug increases the risk of developing acute myositis. However, it is unclear what the incidence of this side effect is with the drug as the question did not provide information on how many patients developed acute myositis in each group. The p value of 0.03 indicates that there is a three percent probability of obtaining the observed result by chance, assuming the null hypothesis is true.
Significance tests are used to determine the likelihood of a null hypothesis being true. The null hypothesis states that two treatments are equally effective, while the alternative hypothesis suggests that there is a difference between the two treatments. The p value is the probability of obtaining a result by chance that is at least as extreme as the observed result, assuming the null hypothesis is true. Two types of errors can occur during significance testing: type I, where the null hypothesis is rejected when it is true, and type II, where the null hypothesis is accepted when it is false. The power of a study is the probability of correctly rejecting the null hypothesis when it is false, and it can be increased by increasing the sample size.
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This question is part of the following fields:
- General Principles
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Question 19
Incorrect
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A 65-year-old man with a medical history of obesity, hypertension, type 2 diabetes mellitus, and ischaemic heart disease is hospitalized for SARS-CoV-2 infection. He is started on oxygen therapy and a 10-day course of oral dexamethasone. What is the most crucial monitoring strategy following the initiation of this medication?
Your Answer: Daily urea and electrolytes
Correct Answer: Four times daily capillary blood glucose
Explanation:Regular monitoring of capillary blood glucose is recommended when using corticosteroids as they can worsen diabetic control due to their anti-insulin effects. Dexamethasone, a corticosteroid with a high glucocorticoid effect, carries a high risk of hyperglycaemia in patients with or without diabetes. Monitoring blood sugars is essential for patients with diabetes who are started on glucocorticoids. Monitoring cardiac function, daily amylase levels, daily lying and standing blood pressure, and daily urea and electrolytes are not routinely recommended while on corticosteroids. However, these tests may be necessary if suggestive symptoms develop.
Corticosteroids are commonly prescribed medications that can be taken orally or intravenously, or applied topically. They mimic the effects of natural steroids in the body and can be used to replace or supplement them. However, the use of corticosteroids is limited by their numerous side effects, which are more common with prolonged and systemic use. These side effects can affect various systems in the body, including the endocrine, musculoskeletal, gastrointestinal, ophthalmic, and psychiatric systems. Some of the most common side effects include impaired glucose regulation, weight gain, osteoporosis, and increased susceptibility to infections. Patients on long-term corticosteroids should have their doses adjusted during intercurrent illness, and the medication should not be abruptly withdrawn to avoid an Addisonian crisis. Gradual withdrawal is recommended for patients who have received high doses or prolonged treatment.
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This question is part of the following fields:
- Endocrine System
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Question 20
Correct
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A 42-year-old man has been experiencing mechanical back pain for a few years. Upon waking up one morning, he experiences a sudden onset of pain in his back that travels down his left leg. What is the most probable cause of his symptoms?
Your Answer: Prolapse of nucleus pulposus
Explanation:The cause of the symptoms is likely to be intervertebral disk prolapse, which occurs when the nucleus pulposus herniates.
Intervertebral Discs
Intervertebral discs are composed of two main parts: the outer annulus fibrosus and the inner nucleus pulposus. The annulus fibrosus is made up of multiple layers of fibrocartilage, while the nucleus pulposus contains loose fibers suspended in a mucoprotein gel with a jelly-like consistency. The nucleus of the disc acts as a shock absorber, and pressure on the disc can cause the posterior protrusion of the nucleus pulposus. This is most commonly seen in the lumbrosacral and lower cervical areas.
The discs are separated by hyaline cartilage, and there is one disc between each pair of vertebrae, except for C1/2 and the sacrococcygeal vertebrae. Understanding the structure and function of intervertebral discs is important in the diagnosis and treatment of spinal conditions. By providing support and cushioning to the spine, these discs play a crucial role in maintaining spinal health and mobility.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 21
Incorrect
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A 28-year-old woman presents to her GP with milky discharge from her breasts. Her periods have also become very irregular and she has not menstruated in the past 4 months. On further questioning, she reports not being sexually active since having a miscarriage 9 months ago which required surgical management. On examination, there are no palpable masses in her breasts bilaterally, she demonstrates a small amount of milky white discharge from her left nipple which is collected for microscopy, culture, and sensitivity. She has no focal neurological deficits, cardiac, and respiratory examination is unremarkable, and her abdominal examination is unremarkable.
What is the most likely diagnosis?Your Answer: Pregnancy
Correct Answer: Prolactinoma
Explanation:The likely cause of this patient’s amenorrhoea and galactorrhoea is a prolactinoma, which inhibits the secretion of GnRH and leads to low levels of oestrogen. Further tests, including a urinary pregnancy test and blood tests for various hormones, should be conducted to confirm the diagnosis. Asherman’s syndrome, intraductal papilloma, and pregnancy are less likely causes, as they do not present with the same symptoms or do not fit the patient’s reported history.
Understanding Amenorrhoea: Causes, Investigations, and Management
Amenorrhoea is a condition characterized by the absence of menstrual periods. It can be classified into two types: primary and secondary. Primary amenorrhoea occurs when menstruation fails to start by the age of 15 in girls with normal secondary sexual characteristics or by the age of 13 in girls with no secondary sexual characteristics. On the other hand, secondary amenorrhoea is the cessation of menstruation for 3-6 months in women with previously normal and regular menses or 6-12 months in women with previous oligomenorrhoea.
The causes of amenorrhoea vary depending on the type. Primary amenorrhoea may be caused by gonadal dysgenesis, testicular feminization, congenital malformations of the genital tract, functional hypothalamic amenorrhoea, congenital adrenal hyperplasia, imperforate hymen, hypothalamic amenorrhoea, polycystic ovarian syndrome, hyperprolactinemia, premature ovarian failure, and thyrotoxicosis. Meanwhile, secondary amenorrhoea may be caused by stress, excessive exercise, PCOS, Sheehan’s syndrome, Asherman’s syndrome, and other underlying medical conditions.
To diagnose amenorrhoea, initial investigations may include pregnancy tests, full blood count, urea & electrolytes, coeliac screen, thyroid function tests, gonadotrophins, prolactin, and androgen levels. Management of amenorrhoea involves treating the underlying cause. For primary amenorrhoea, it is important to investigate and treat any underlying cause. For secondary amenorrhoea, it is important to exclude pregnancy, lactation, and menopause and treat the underlying cause accordingly. Women with primary ovarian insufficiency due to gonadal dysgenesis may benefit from hormone replacement therapy to prevent osteoporosis and other complications.
In conclusion, amenorrhoea is a condition that requires proper diagnosis and management. Understanding the causes and appropriate investigations can help in providing the necessary treatment and care for women experiencing this condition.
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This question is part of the following fields:
- Reproductive System
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Question 22
Correct
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What role does the nucleolus play in eukaryotic cells?
Your Answer: To transcribe ribosomal RNA and assemble ribosomes
Explanation:The Nucleolus: Structure and Function
The nucleolus is a non-membrane-bound structure that takes up about a quarter of the nuclear volume. It is composed mainly of proteins and nucleic acids and is responsible for transcribing ribosomal RNA (rRNA) and assembling ribosomes in the cell. Nucleoli are formed in nucleolar organizing regions (NORs), which are also the regions of the genes for three of the four eukaryotic rRNAs.
During ribosome assembly, ribosomal proteins enter the nucleolus from the cytoplasm and begin to assemble on an rRNA precursor. As the pre-rRNA is cleaved to produce 5.8S, 18S, and 28S rRNAs, additional ribosomal proteins and the 5S rRNA (which is synthesized elsewhere in the nucleus) assemble to form preribosomal subunits. These subunits then exit the nucleolus into the cytoplasm and combine to produce the final 40S and 60S ribosomal subunits.
Overall, the nucleolus plays a crucial role in protein synthesis by producing the components necessary for ribosome assembly. Its unique structure and function make it an essential component of the cell’s machinery.
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This question is part of the following fields:
- Basic Sciences
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Question 23
Incorrect
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A 27-year-old female presents to her GP after giving birth 8 months ago. She had planned for a normal vaginal delivery, but due to an umbilical cord prolapse, she had to undergo an emergency caesarean section. Since then, she has experienced several health changes, such as excessive sleep, joint pains, and weight loss. She also reports seeing animals around her that others cannot see and now takes a different route to work to avoid driving past the hospital where the events occurred. Based on her history, what is the most significant feature that supports a diagnosis of post-traumatic stress disorder (PTSD)?
Your Answer: Hallucinations
Correct Answer: Avoidance
Explanation:PTSD is characterized by a set of common features, including re-experiencing, avoidance, and hyperarousal. Patients may experience intrusive flashbacks or nightmares related to the traumatic event. PTSD can develop after exposure to a variety of traumatic events, such as accidents, natural disasters, military exposure, and traumatic births. Healthcare workers during the COVID-19 pandemic have also reported experiencing PTSD. Insomnia is a common symptom associated with PTSD, while excessive sleep is not. Although hallucinations have been reported in some patients with PTSD, they are not as common as flashbacks and should prompt doctors to consider other possible diagnoses. Joint pains may occur in patients with PTSD, but they are not a defining feature of the disease.
Understanding Post-Traumatic Stress Disorder (PTSD)
Post-traumatic stress disorder (PTSD) is a mental health condition that can develop in individuals of any age following a traumatic event. This can include natural disasters, physical or sexual assault, or military combat. PTSD is characterized by a range of symptoms, including re-experiencing the traumatic event through flashbacks or nightmares, avoidance of triggers associated with the event, hyperarousal, emotional numbing, depression, and substance abuse.
Effective management of PTSD involves a range of interventions, including watchful waiting for mild symptoms, trauma-focused cognitive behavioral therapy (CBT), and eye movement desensitization and reprocessing (EMDR) therapy for more severe cases. While drug treatments are not recommended as a first-line treatment for adults, venlafaxine or a selective serotonin reuptake inhibitor (SSRI) such as sertraline may be used. In severe cases, risperidone may be recommended. It is important to note that single-session interventions, also known as debriefing, are not recommended following a traumatic event.
Understanding PTSD and its symptoms is crucial in providing effective support and treatment for those who have experienced trauma. With the right interventions, individuals with PTSD can learn to manage their symptoms and improve their quality of life.
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This question is part of the following fields:
- Psychiatry
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Question 24
Correct
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A 23-year-old man visits a GUM clinic due to painful swelling of lymph nodes in his groin. He has no medical history and is not taking any medications. He admits to having unprotected sex with a casual partner. The diagnosis is LGV. What is the probable pathogen responsible for this condition?
Your Answer: Chlamydia trachomatis serovars L1-3
Explanation:Lymphogranuloma venereum is caused by Chlamydia trachomatis serovars L1, L2 and L3. It presents with three stages, starting with a painless pustule and progressing to painful inguinal lymphadenopathy, and later, proctocolitis may develop. The causative organism is not Chlamydia trachomatis serovars D-K, Treponema pallidum, or Herpes simplex virus.
Understanding Lymphogranuloma Venereum
Lymphogranuloma venereum (LGV) is a sexually transmitted infection caused by Chlamydia trachomatis serovars L1, L2, and L3. This infection is commonly found in men who have sex with men and those who have HIV. While historically it was more prevalent in tropical regions, it is now seen in developed countries as well.
The infection typically progresses through three stages. The first stage involves a small, painless pustule that later forms an ulcer. In the second stage, painful inguinal lymphadenopathy occurs, which may occasionally form fistulating buboes. The third stage involves proctocolitis.
LGV is treated using doxycycline.
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This question is part of the following fields:
- General Principles
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Question 25
Incorrect
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A 79-year-old man arrives at the emergency department with severe, crushing chest pain. His ECG reveals ST-segment elevation in leads V1-4. What electrical state of the heart is likely to be impacted based on his ECG findings?
Your Answer: The start of ventricular depolarisation
Correct Answer: The period when the entire ventricle is depolarised
Explanation:The ST segment on an ECG represents the time when the ventricles are fully depolarized, occurring between the QRS complex and the T wave. The P wave represents atrial depolarization, while the PR interval represents the time between atrial and ventricular depolarization. The QRS complex represents ventricular depolarization, and the T wave represents repolarization. Overall, the ECG reflects the various electrical states of the heart.
Understanding the Normal ECG
The electrocardiogram (ECG) is a diagnostic tool used to assess the electrical activity of the heart. The normal ECG consists of several waves and intervals that represent different phases of the cardiac cycle. The P wave represents atrial depolarization, while the QRS complex represents ventricular depolarization. The ST segment represents the plateau phase of the ventricular action potential, and the T wave represents ventricular repolarization. The Q-T interval represents the time for both ventricular depolarization and repolarization to occur.
The P-R interval represents the time between the onset of atrial depolarization and the onset of ventricular depolarization. The duration of the QRS complex is normally 0.06 to 0.1 seconds, while the duration of the P wave is 0.08 to 0.1 seconds. The Q-T interval ranges from 0.2 to 0.4 seconds depending upon heart rate. At high heart rates, the Q-T interval is expressed as a ‘corrected Q-T (QTc)’ by taking the Q-T interval and dividing it by the square root of the R-R interval.
Understanding the normal ECG is important for healthcare professionals to accurately interpret ECG results and diagnose cardiac conditions. By analyzing the different waves and intervals, healthcare professionals can identify abnormalities in the electrical activity of the heart and provide appropriate treatment.
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This question is part of the following fields:
- Cardiovascular System
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Question 26
Incorrect
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Which organ is the least probable to exhibit cells or glands that secrete mucus?
Your Answer: Cervix
Correct Answer: Vagina
Explanation:Epithelial Tissue in Different Parts of the Body
The lining of the vagina and oesophagus is made up of stratified squamous non-keratinising epithelium. However, mucus glands are present at the lower end of the oesophagus. The intestines, on the other hand, are lined by a simple columnar epithelium throughout the small and large intestine. Lastly, the cervix is lined by simple columnar epithelium.
In summary, the type of epithelial tissue that lines different parts of the body varies. The vagina and oesophagus have a stratified squamous non-keratinising epithelium, while the intestines have a simple columnar epithelium. The cervix is also lined by simple columnar epithelium. It is important to note that mucus glands are present at the lower end of the oesophagus. the different types of epithelial tissue in the body is crucial in identifying and treating various medical conditions.
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This question is part of the following fields:
- Clinical Sciences
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Question 27
Incorrect
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A senior woman with a history of chronic obstructive pulmonary disease (COPD) arrives at the hospital complaining of worsening shortness of breath and a productive cough. As part of the initial evaluation, a chest X-ray is requested.
What radiographic feature would you anticipate observing on her chest X-ray?Your Answer: Pleural effusion
Correct Answer: Flattened diaphragm
Explanation:The diaphragm of patients with COPD often appears flattened on a chest X-ray due to the chronic expiratory airflow obstruction causing dynamic hyperinflation of the lungs. Pleural effusions are commonly associated with infection, malignancy, or heart failure, while empyema is a result of pus accumulation in the pleural space caused by an infection.
Understanding COPD: Symptoms and Diagnosis
Chronic obstructive pulmonary disease (COPD) is a common medical condition that includes chronic bronchitis and emphysema. Smoking is the leading cause of COPD, and patients with mild disease may only need occasional use of a bronchodilator, while severe cases may result in frequent hospital admissions due to exacerbations. Symptoms of COPD include a productive cough, dyspnea, wheezing, and in severe cases, right-sided heart failure leading to peripheral edema.
To diagnose COPD, doctors may recommend post-bronchodilator spirometry to demonstrate airflow obstruction, a chest x-ray to check for hyperinflation, bullae, and flat hemidiaphragm, and to exclude lung cancer. A full blood count may also be necessary to exclude secondary polycythemia, and body mass index (BMI) calculation is important. The severity of COPD is categorized using the FEV1, with a ratio of less than 70% indicating airflow obstruction. The grading system has changed following the 2010 NICE guidelines, with Stage 1 – mild now including patients with an FEV1 greater than 80% predicted but with a post-bronchodilator FEV1/FVC ratio of less than 0.7. Measuring peak expiratory flow is of limited value in COPD, as it may underestimate the degree of airflow obstruction.
In summary, COPD is a common condition caused by smoking that can result in a range of symptoms and severity. Diagnosis involves various tests to check for airflow obstruction, exclude lung cancer, and determine the severity of the disease.
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This question is part of the following fields:
- Respiratory System
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Question 28
Incorrect
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Which interleukin is accountable for the growth of B cells?
Your Answer: IL-2
Correct Answer: IL-4
Explanation:The proliferation and differentiation of B cells is attributed to IL-4. Macrophages produce IL-1, an acute inflammatory protein. T cell proliferation is encouraged by IL-2. Myeloid cells undergo proliferation and differentiation due to IL-3.
Overview of Cytokines and Their Functions
Cytokines are signaling molecules that play a crucial role in the immune system. Interleukins are a type of cytokine that are produced by various immune cells and have specific functions. IL-1, produced by macrophages, induces acute inflammation and fever. IL-2, produced by Th1 cells, stimulates the growth and differentiation of T cell responses. IL-3, produced by activated T helper cells, stimulates the differentiation and proliferation of myeloid progenitor cells. IL-4, produced by Th2 cells, stimulates the proliferation and differentiation of B cells. IL-5, also produced by Th2 cells, stimulates the production of eosinophils. IL-6, produced by macrophages and Th2 cells, stimulates the differentiation of B cells and induces fever. IL-8, produced by macrophages, promotes neutrophil chemotaxis. IL-10, produced by Th2 cells, inhibits Th1 cytokine production and is known as an anti-inflammatory cytokine. IL-12, produced by dendritic cells, macrophages, and B cells, activates NK cells and stimulates the differentiation of naive T cells into Th1 cells.
In addition to interleukins, there are other cytokines with specific functions. Tumor necrosis factor-alpha, produced by macrophages, induces fever and promotes neutrophil chemotaxis. Interferon-gamma, produced by Th1 cells, activates macrophages. Understanding the functions of cytokines is important in developing treatments for various immune-related diseases.
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This question is part of the following fields:
- General Principles
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Question 29
Incorrect
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A 72-year-old male visits his doctor with complaints of decreased and blurry vision. Upon examination with a slit lamp, a nuclear sclerotic cataract is detected in his right eye. The patient has been diagnosed with type 2 diabetes mellitus for 12 years and is currently on insulin therapy.
What is the primary factor that increases the risk of developing this condition?Your Answer: Type 2 diabetes mellitus
Correct Answer: Ageing
Explanation:Ageing is the most significant risk factor for cataracts, although the other factors also contribute to the development of this condition.
Understanding Cataracts
A cataract is a common eye condition that occurs when the lens of the eye becomes cloudy, making it difficult for light to reach the retina and causing reduced or blurred vision. Cataracts are more common in women and increase in incidence with age, affecting 30% of individuals aged 65 and over. The most common cause of cataracts is the normal ageing process, but other possible causes include smoking, alcohol consumption, trauma, diabetes mellitus, long-term corticosteroids, radiation exposure, myotonic dystrophy, and metabolic disorders such as hypocalcaemia.
Patients with cataracts typically experience a gradual onset of reduced vision, faded colour vision, glare, and halos around lights. Signs of cataracts include a defect in the red reflex, which is the reddish-orange reflection seen through an ophthalmoscope when a light is shone on the retina. Diagnosis is made through ophthalmoscopy and slit-lamp examination, which reveal a visible cataract.
In the early stages, age-related cataracts can be managed conservatively with stronger glasses or contact lenses and brighter lighting. However, surgery is the only effective treatment for cataracts, involving the removal of the cloudy lens and replacement with an artificial one. Referral for surgery should be based on the presence of visual impairment, impact on quality of life, patient choice, and the risks and benefits of surgery. Complications following surgery may include posterior capsule opacification, retinal detachment, posterior capsule rupture, and endophthalmitis. Despite these risks, cataract surgery has a high success rate, with 85-90% of patients achieving corrected vision of 6/12 or better on a Snellen chart postoperatively.
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This question is part of the following fields:
- Neurological System
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Question 30
Incorrect
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A 55-year-old man with a BMI of 32 kg/m2 has been experiencing indigestion for a long time. He recently had an endoscopy, during which biopsy samples of his oesophagus were taken. The pathology report revealed abnormal columnar epithelium in the distal samples. Can you identify the best answer that describes this adaptive cellular response to injury?
Your Answer: Hypertrophy
Correct Answer: Metaplasia
Explanation:There are four adaptive cellular responses to injury: atrophy, hypertrophy, hyperplasia, and metaplasia. Metaplasia is the reversible change of one fully differentiated cell type to another, usually in response to irritation. Examples include Barrett’s esophagus, bronchoalveolar epithelium undergoing squamous metaplasia due to cigarette smoke, and urinary bladder transitional epithelium undergoing squamous metaplasia due to a urinary calculi. Atrophy refers to a loss of cells, hypertrophy refers to an increase in cell size, and hyperplasia refers to an increase in cell number. Apoptosis is a specialized form of programmed cell death.
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This question is part of the following fields:
- Clinical Sciences
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